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Area Under Curves — JEE Previous Year Questions

Every Area Under Curves question asked in JEE Main and JEE Advanced across the last 186 papers — 149 questions, each with its correct answer. Free to read, no account needed.

Questions

149

Papers it appeared in

139/186

Appearance rate

75%

All 149 Area Under Curves questions

Most recent papers first.

Q1·MathematicsNumericalJEE Advanced 2026
Passage: Consider the ellipses given by x2+4y2=1x^{2} + 4y^{2} = 1x2+4y2=1 and 4x2+y2=14x^{2} + y^{2} = 14x2+y2=1. Question: If α\alphaα is the area of the common region that lies inside both the given ellipses, then the value of cot⁡α\cot\alphacotα is _____.

Correct answer: 0.75

Step-by-step solution →
Q2·MathematicsNumericalJEE Advanced 2026
Passage: Consider the curve C1C_{1}C1​ given by y=e−xy = e^{-x}y=e−x for x∈[0,10π]x \in [0, 10\pi]x∈[0,10π], and the curve C2C_{2}C2​ given by y=e−x(sin⁡x+cos⁡x)y = e^{-x}(\sin x + \cos x)y=e−x(sinx+cosx) for x∈[0,10π]x \in [0, 10\pi]x∈[0,10π]. Let nnn be the total number of points of intersection of the curves C1C_{1}C1​ and C2C_{2}C2​. Suppose that α1,α2,…,αn∈[0,10π]\alpha_{1}, \alpha_{2}, \ldots, \alpha_{n} \in [0, 10\pi]α1​,α2​,…,αn​∈[0,10π] are the xxx-coordinates of the points of intersection of the curves C1C_{1}C1​ and C2C_{2}C2​ such that α1<α2<⋯<αn\alpha_{1} < \alpha_{2} < \cdots < \alpha_{n}α1​<α2​<⋯<αn​. Question: Let β\betaβ be the area of the region enclosed between the curves C1C_{1}C1​, C2C_{2}C2​, and the lines x=α1x = \alpha_{1}x=α1​ and x=α4x = \alpha_{4}x=α4​. Then the value of −1πlog⁡e(β−2e−π2)-\dfrac{1}{\pi}\log_{e}\left(\beta - 2e^{-\frac{\pi}{2}}\right)−π1​loge​(β−2e−2π​) is _____.

Correct answer: 2.5

Step-by-step solution →
Q3·MathematicsSingle correctJEE Main 2026
Let f:(1,∞)→Rf : (1, \infty) \to \mathbb{R}f:(1,∞)→R be a function defined as f(x)=x−1x+1f(x) = \dfrac{x-1}{x+1}f(x)=x+1x−1​. Let fi+1(x)=f(fi(x))f^{i+1}(x) = f(f^{i}(x))fi+1(x)=f(fi(x)), i=1,2,…,25i = 1, 2, \ldots, 25i=1,2,…,25, where f1(x)=f(x)f^{1}(x) = f(x)f1(x)=f(x). If g(x)+f26(x)=0g(x) + f^{26}(x) = 0g(x)+f26(x)=0, x∈(1,∞)x \in (1, \infty)x∈(1,∞), then the area of the region bounded by the curves y=g(x)y = g(x)y=g(x), 2y=2x−32y = 2x - 32y=2x−3, y=0y = 0y=0 and x=4x = 4x=4 is:
  1. (A)18+log⁡e2\dfrac{1}{8} + \log_e 281​+loge​2
  2. (B)14+log⁡e2\dfrac{1}{4} + \log_e 241​+loge​2
  3. (C)56+3log⁡e2\dfrac{5}{6} + 3\log_e 265​+3loge​2
  4. (D)56+log⁡e2\dfrac{5}{6} + \log_e 265​+loge​2

Correct answer: (A)

Step-by-step solution →
Q4·MathematicsSingle correctJEE Main 2026
The area of the region {(x,y):x2−8x≤y≤−x}\{(x, y) : x^{2} - 8x \le y \le -x\}{(x,y):x2−8x≤y≤−x} is :
  1. (A)3436\frac{343}{6}6343​
  2. (B)6376\frac{637}{6}6637​
  3. (C)4376\frac{437}{6}6437​
  4. (D)5236\frac{523}{6}6523​

Correct answer: (A)

Step-by-step solution →
Q5·MathematicsSingle correctJEE Main 2026
The area of the region {(x, y) : 0 ≤ y ≤ 6 − x, y2^22 ≥ 4x − 3, x ≥ 0} is:
  1. (A)8
  2. (B)9
  3. (C)12
  4. (D)15

Correct answer: (B)

Step-by-step solution →
Q6·MathematicsSingle correctJEE Main 2026
Let e be the base of natural logarithm and let f : {1, 2, 3, 4} → {1, e, e2^22, e3^33} and g : {1, e, e2^22, e3^33} → {1,12,13,14}\left\{1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}\right\}{1,21​,31​,41​} be two bijective functions such that f is strictly decreasing and g is strictly increasing. If ϕ(x)=[f−1{g−1(12)}]x\phi(x) = \left[f^{-1}\left\{g^{-1}\left(\frac{1}{2}\right)\right\}\right]^{x}ϕ(x)=[f−1{g−1(21​)}]x, then the area of the region R = {(x, y) : x2^22 ≤ y ≤ φ(x), 0 ≤ x ≤ 1} is:
  1. (A)3−log⁡e(2)3log⁡e(2)\frac{3 - \log_e(2)}{3\log_e(2)}3loge​(2)3−loge​(2)​
  2. (B)13log⁡e(2)\frac{1}{3\log_e(2)}3loge​(2)1​
  3. (C)3 + loge_ee​(2)
  4. (D)3+log⁡e(2)2+log⁡e(3)\frac{3 + \log_e(2)}{2 + \log_e(3)}2+loge​(3)3+loge​(2)​

Correct answer: (A)

Step-by-step solution →
Q7·MathematicsNumericalJEE Main 2026
Let f : ℝ → ℝ be a function such that f(x)+3f(π2−x)=sin⁡xf(x) + 3f\left(\frac{\pi}{2} - x\right) = \sin xf(x)+3f(2π​−x)=sinx, x ∈ ℝ. Let the maximum value of f on ℝ be α. If the area of the region bounded by the curves g(x)=x2g(x) = x^{2}g(x)=x2 and h(x)=βx3h(x) = \beta x^{3}h(x)=βx3, β > 0, is α2\alpha^{2}α2, then 30β330\beta^{3}30β3 is equal to _______.

Correct answer: 16

Step-by-step solution →
Q8·MathematicsSingle correctJEE Main 2026
The area of the region bounded by the curves x+3y2=0x + 3y^{2} = 0x+3y2=0 and x+4y2=1x + 4y^{2} = 1x+4y2=1 is equal to:
  1. (A)13\frac{1}{3}31​
  2. (B)23\frac{2}{3}32​
  3. (C)43\frac{4}{3}34​
  4. (D)53\frac{5}{3}35​

Correct answer: (C)

Step-by-step solution →
Q9·MathematicsSingle correctJEE Main 2026
The area of the region {(x,y):y≤π−∣x∣, y≤∣xsin⁡x∣, y≥0}\{(x, y) : y \leq \pi - |x|,\ y \leq |x \sin x|,\ y \geq 0\}{(x,y):y≤π−∣x∣, y≤∣xsinx∣, y≥0} is:
  1. (A)1+π281 + \frac{\pi^2}{8}1+8π2​
  2. (B)2+π242 + \frac{\pi^2}{4}2+4π2​
  3. (C)π28−1\frac{\pi^2}{8} - 18π2​−1
  4. (D)4+π224 + \frac{\pi^2}{2}4+2π2​

Correct answer: (B)

Step-by-step solution →
Q10·MathematicsNumericalJEE Main 2026
If the area of the region bounded by 16x2−9y2=14416x^2 - 9y^2 = 14416x2−9y2=144 and 8x−3y=248x - 3y = 248x−3y=24 is A, then 3(A+6log⁡e(3))3(A + 6\log_e(3))3(A+6loge​(3)) is equal to ________.

Correct answer: 24

Step-by-step solution →
Q11·MathematicsSingle correctJEE Main 2026
The area of the region R={(x,y):xy≤8,1≤y≤x2,x≥0}R = \{(x, y) : xy \le 8, 1 \le y \le x^2, x \ge 0\}R={(x,y):xy≤8,1≤y≤x2,x≥0} is
  1. (A)13(49log⁡e(2)−15)\dfrac{1}{3}\left(49\log_e(2) - 15\right)31​(49loge​(2)−15)
  2. (B)23(20log⁡e(2)+9)\dfrac{2}{3}\left(20\log_e(2) + 9\right)32​(20loge​(2)+9)
  3. (C)23(24log⁡e(2)−7)\dfrac{2}{3}\left(24\log_e(2) - 7\right)32​(24loge​(2)−7)
  4. (D)13(40log⁡e(2)+27)\dfrac{1}{3}\left(40\log_e(2) + 27\right)31​(40loge​(2)+27)

Correct answer: (C)

Step-by-step solution →
Q12·MathematicsSingle correctJEE Main 2026
Let P1:y=4x2P_{1} : y = 4x^{2}P1​:y=4x2 and P2:y=x2+27P_{2} : y = x^{2} + 27P2​:y=x2+27 be two parabolas. If the area of the bounded region enclosed between P1P_{1}P1​ and P2P_{2}P2​ is six times the area of the bounded region enclosed between the line y=αxy = \alpha xy=αx, α > 0 and P1P_{1}P1​, then α is equal to :
  1. (A)8
  2. (B)15
  3. (C)12
  4. (D)6

Correct answer: (C)

Step-by-step solution →
Q13·MathematicsSingle correctJEE Main 2026
Let A1\mathrm{A}_{1}A1​ be the bounded area enclosed by the curves y=x2+2y = x^{2} + 2y=x2+2, x+y=8x + y = 8x+y=8 and y-axis that lies in the first quadrant. Let A2\mathrm{A}_{2}A2​ be the bounded area enclosed by the curves y=x2+2y = x^{2} + 2y=x2+2, y2=xy^{2} = xy2=x, x=2x = 2x=2, and y-axis that lies in the first quadrant. Then A1−A2\mathrm{A}_{1} - \mathrm{A}_{2}A1​−A2​ is equal to
  1. (A)23(22+1)\frac{2}{3}\left(2\sqrt{2} + 1\right)32​(22​+1)
  2. (B)23(42+1)\frac{2}{3}\left(4\sqrt{2} + 1\right)32​(42​+1)
  3. (C)23(2+1)\frac{2}{3}\left(\sqrt{2} + 1\right)32​(2​+1)
  4. (D)23(32+1)\frac{2}{3}\left(3\sqrt{2} + 1\right)32​(32​+1)

Correct answer: (A)

Step-by-step solution →
Q14·MathematicsSingle correctJEE Main 2026
Let f(α)f(\alpha)f(α) denote the area of the region in the first quadrant bounded by x=0x = 0x=0, x=1x = 1x=1, y2=xy^{2} = xy2=x and y=∣αx−5∣−∣1−αx∣+αx2y = |\alpha x - 5| - |1 - \alpha x| + \alpha x^{2}y=∣αx−5∣−∣1−αx∣+αx2. Then (f(0)+f(1))(f(0) + f(1))(f(0)+f(1)) is equal to
  1. (A)9
  2. (B)14
  3. (C)7
  4. (D)12

Correct answer: (C)

Step-by-step solution →
Q15·MathematicsNumericalJEE Main 2026
Let the area of the region bounded by the curve y=max⁡ {sin⁡x,cos⁡x}y = \max\ \{\sin x, \cos x\}y=max {sinx,cosx}, lines x=0x = 0x=0, x=3π2x = \frac{3\pi}{2}x=23π​, and the x-axis be A. Then, A+A2A + A^{2}A+A2 is equal to

Correct answer: 12

Step-by-step solution →
Q16·MathematicsSingle correctJEE Main 2026
The area of the region enclosed between the circles x2+y2=4x^2 + y^2 = 4x2+y2=4 and x2+(y−2)2=4x^2 + (y-2)^2 = 4x2+(y−2)2=4 is :
  1. (A)23(2π−33)\dfrac{2}{3}(2\pi - 3\sqrt{3})32​(2π−33​)
  2. (B)43(2π−33)\dfrac{4}{3}(2\pi - 3\sqrt{3})34​(2π−33​)
  3. (C)43(2π−3)\dfrac{4}{3}(2\pi - \sqrt{3})34​(2π−3​)
  4. (D)23(4π−33)\dfrac{2}{3}(4\pi - 3\sqrt{3})32​(4π−33​)

Correct answer: (D)

Step-by-step solution →
Q17·MathematicsSingle correctJEE Main 2026
The area of the region A={(x, y):4x2+y2≤8 and y2≤4x}A = \{(x,\ y) : 4x^{2} + y^{2} \le 8 \text{ and } y^{2} \le 4x\}A={(x, y):4x2+y2≤8 and y2≤4x} is :
  1. (A)π2+2\frac{\pi}{2} + 22π​+2
  2. (B)π+23\pi + \frac{2}{3}π+32​
  3. (C)π+4\pi + 4π+4
  4. (D)π2+13\frac{\pi}{2} + \frac{1}{3}2π​+31​

Correct answer: (B)

Step-by-step solution →
Q18·MathematicsSingle correctJEE Main 2026
Let the line x = −1 divide the area of the region {(x,y):1+x2≤y≤3−x}\left\{(x,y) : 1 + x^2 \le y \le 3 - x\right\}{(x,y):1+x2≤y≤3−x} in the ratio m : n, gcd (m, n) = 1. Then m + n is equal to
  1. (A)25
  2. (B)28
  3. (C)26
  4. (D)27

Correct answer: (D)

Step-by-step solution →
Q19·MathematicsSingle correctJEE Main 2026
If the area of the region {(x,y):1−2x≤y≤4−x2,x≥0,y≥0}\{(x, y) : 1 - 2x \le y \le 4 - x^2, x \ge 0, y \ge 0\}{(x,y):1−2x≤y≤4−x2,x≥0,y≥0} is αβ\frac{\alpha}{\beta}βα​, α, β, ∈ N, gcd (α, β) = 1, then the value of (α + β) is :
  1. (A)73
  2. (B)85
  3. (C)91
  4. (D)67

Correct answer: (A)

Step-by-step solution →
Q20·MathematicsSingle correctJEE Main 2026
The area of the region, inside the ellipse x2+4y2=4x^{2} + 4y^{2} = 4x2+4y2=4 and outside the region bounded by the curves y=∣x∣−1y = |x| - 1y=∣x∣−1 and y=1−∣x∣y = 1 - |x|y=1−∣x∣, is :
  1. (A)2(π−1)2(\pi - 1)2(π−1)
  2. (B)2π−122\pi - \frac{1}{2}2π−21​
  3. (C)3(π−1)3(\pi - 1)3(π−1)
  4. (D)2π−12\pi - 12π−1

Correct answer: (A)

Step-by-step solution →
Q21·MathematicsSingle correctJEE Advanced 2025
Let R denote the set of all real numbers. Then the area of the region {(x,y)∈R×R:x>0, y>1x, 5x−4y−1>0, 4x+4y−17<0}\left\{ (x, y) \in R \times R : x > 0,\, y > \frac{1}{x},\, 5x - 4y - 1 > 0,\, 4x + 4y - 17 < 0 \right\}{(x,y)∈R×R:x>0,y>x1​,5x−4y−1>0,4x+4y−17<0} is
  1. (A)1716−log⁡e4\frac{17}{16} - \log_e 41617​−loge​4
  2. (B)338−log⁡e4\frac{33}{8} - \log_e 4833​−loge​4
  3. (C)578−log⁡e4\frac{57}{8} - \log_e 4857​−loge​4
  4. (D)172−log⁡e4\frac{17}{2} - \log_e 4217​−loge​4

Correct answer: (B)

Step-by-step solution →
Q22·MathematicsMultiple correctJEE Advanced 2025
Let S denote the locus of mid-points of those chords of the parabola y2=xy^2 = xy2=x, such that area of the region enclosed between the parabola and the chord is 43\frac{4}{3}34​. Let R denote the region lying in the first quadrant, enclosed by the parabola y2=xy^2 = xy2=x, the curve S , and the lines x = 1 and x = 4. Then which of the following statements is (are) TRUE?
  1. (A)(4,3)∈S\left( 4, \sqrt{3} \right) \in S(4,3​)∈S
  2. (B)(5,2)∈S\left( 5, \sqrt{2} \right) \in S(5,2​)∈S
  3. (C)Area of R is 143−23\frac{14}{3} - 2\sqrt{3}314​−23​
  4. (D)Area of R is 143−3\frac{14}{3} - \sqrt{3}314​−3​

Correct answer: (A), (C)

Step-by-step solution →
Q23·MathematicsIntegerJEE Main 2025
Let the area of the bounded region {(x,y):0≤9x≤y2, y≥3x−6}\{(x,y):0\le9x\le y^2,\ y\ge3x-6\}{(x,y):0≤9x≤y2, y≥3x−6} be AAA. Then 6A6A6A is equal to ___

Correct answer: 15

Step-by-step solution →
Q24·MathematicsSingle correctJEE Main 2025
If the area of the region {(x,y):1+x2≤y≤min⁡{x+7, 11−3x}}\{(x,y):1+x^2\le y\le \min\{x+7,\ 11-3x\}\}{(x,y):1+x2≤y≤min{x+7, 11−3x}} is AAA, then 3A3A3A is equal to:
  1. (A)50
  2. (B)49
  3. (C)46
  4. (D)47

Correct answer: (A)

Step-by-step solution →
Q25·MathematicsSingle correctJEE Main 2025
If the area of the region bounded by the curves y=4−x24y=4-\dfrac{x^2}{4}y=4−4x2​ and y=x−42y=\dfrac{x-4}{2}y=2x−4​ is equal to α\alphaα, then 6α6\alpha6α equals
  1. (A)250
  2. (B)210
  3. (C)240
  4. (D)220

Correct answer: (A)

Step-by-step solution →
Q26·MathematicsIntegerJEE Main 2025
If the area of the region {(x,y):∣x−5∣≤y≤4x}\{(x,y):|x-5|\le y\le4\sqrt{x}\}{(x,y):∣x−5∣≤y≤4x​} is AAA, then 3A3A3A is equal to ______.

Correct answer: 368

Step-by-step solution →
Q27·MathematicsSingle correctJEE Main 2025
Let f:[0,∞)→Rf:[0,\infty)\to\mathbb{R}f:[0,∞)→R be differentiable function such that f(x)=1−2x+∫0xex−tf(t) dtf(x)=1-2x+\displaystyle\int_0^x e^{x-t}f(t)\,dtf(x)=1−2x+∫0x​ex−tf(t)dt for all x∈[0,∞)x\in[0,\infty)x∈[0,∞). Then the area of the region bounded by y=f(x)y=f(x)y=f(x) and the coordinate axes is
  1. (A)5\sqrt{5}5​
  2. (B)12\dfrac{1}{2}21​
  3. (C)2\sqrt{2}2​
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q28·MathematicsIntegerJEE Main 2025
The area of the region bounded by the curve y=max⁡{∣x∣, x∣x−2∣}y=\max\{|x|,\,x|x-2|\}y=max{∣x∣,x∣x−2∣}, the x-axis and the lines x=−2x=-2x=−2 and x=4x=4x=4 is equal to __________.

Correct answer: 12

Step-by-step solution →
Q29·MathematicsSingle correctJEE Main 2025
The area of the region {(x,y):∣x−y∣≤y≤4x}\{(x,y):|x-y|\le y\le 4\sqrt{x}\}{(x,y):∣x−y∣≤y≤4x​} is:
  1. (A)512
  2. (B)10243\dfrac{1024}{3}31024​
  3. (C)5123\dfrac{512}{3}3512​
  4. (D)20483\dfrac{2048}{3}32048​

Correct answer: (B)

Step-by-step solution →
Q30·MathematicsIntegerJEE Main 2025
If the area of the region {(x,y):∣4−x2∣≤y≤x2, y≤4, x≥0}\{(x,y):|4-x^2|\le y\le x^2,\ y\le4,\ x\ge0\}{(x,y):∣4−x2∣≤y≤x2, y≤4, x≥0} is (802α−β)\left(\dfrac{80\sqrt{2}}{\alpha}-\beta\right)(α802​​−β), α,β∈N\alpha,\beta\in Nα,β∈N, then α+β\alpha+\betaα+β is equal to ______.

Correct answer: 22

Step-by-step solution →
Q31·MathematicsSingle correctJEE Main 2025
Let the area enclosed between the curves ∣y∣=1−x2|y|=1-x^2∣y∣=1−x2 and x2+y2=1x^2+y^2=1x2+y2=1 be α\alphaα. If 9α=βπ+γ9\alpha=\beta\pi+\gamma9α=βπ+γ; β,γ\beta,\gammaβ,γ are integers, then the value of ∣β−γ∣|\beta-\gamma|∣β−γ∣ equals
  1. (A)27
  2. (B)18
  3. (C)15
  4. (D)33

Correct answer: (D)

Step-by-step solution →
Q32·MathematicsSingle correctJEE Main 2025
Let the area of the region {(x,y):2y≤x2+3, y+∣x∣≤3, y≥∣x−1∣}\{(x,y): 2y\le x^2+3,\ y+|x|\le 3,\ y\ge|x-1|\}{(x,y):2y≤x2+3, y+∣x∣≤3, y≥∣x−1∣} be A. Then 6A is equal to:
  1. (A)16
  2. (B)12
  3. (C)18
  4. (D)14

Correct answer: (D)

Step-by-step solution →
Q33·MathematicsSingle correctJEE Main 2025
The area of the region bounded by the curves x(1+y2)=1x(1+y^2)=1x(1+y2)=1 and y2=2xy^2=2xy2=2x is:
  1. (A)2(π2−13)2\left(\frac{\pi}{2}-\frac{1}{3}\right)2(2π​−31​)
  2. (B)π4−13\frac{\pi}{4}-\frac{1}{3}4π​−31​
  3. (C)π2−13\frac{\pi}{2}-\frac{1}{3}2π​−31​
  4. (D)12(π2−13)\frac{1}{2}\left(\frac{\pi}{2}-\frac{1}{3}\right)21​(2π​−31​)

Correct answer: (C)

Step-by-step solution →
Q34·MathematicsSingle correctJEE Main 2025
The area (in sq. units) of the region {(x,y):0≤y≤2∣x∣+1,0≤y≤x2+1,∣x∣≤3}\{(x, y): 0\le y\le 2|x|+1, 0\le y\le x^2+1, |x|\le 3\}{(x,y):0≤y≤2∣x∣+1,0≤y≤x2+1,∣x∣≤3} is
  1. (A)803\frac{80}{3}380​
  2. (B)643\frac{64}{3}364​
  3. (C)173\frac{17}{3}317​
  4. (D)323\frac{32}{3}332​

Correct answer: (B)

Step-by-step solution →
Q35·MathematicsSingle correctJEE Main 2025
The area of the region {(x,y):x2+4x+2≤y≤∣x+2∣}\{(x,y):x^2+4x+2\le y\le|x+2|\}{(x,y):x2+4x+2≤y≤∣x+2∣} is equal to
  1. (A)777
  2. (B)245\dfrac{24}{5}524​
  3. (C)203\dfrac{20}{3}320​
  4. (D)555

Correct answer: (C)

Step-by-step solution →
Q36·MathematicsSingle correctJEE Main 2025
The area of the region enclosed by the curves y=exy=e^xy=ex, y=∣ex−1∣y=|e^x-1|y=∣ex−1∣ and y-axis is:
  1. (A)1+log⁡e21+\log_e 21+loge​2
  2. (B)2log⁡e22\log_e 22loge​2
  3. (C)2log⁡e2−12\log_e 2-12loge​2−1
  4. (D)1−log⁡e21-\log_e 21−loge​2

Correct answer: (D)

Step-by-step solution →
Q37·MathematicsSingle correctJEE Main 2025
If the area of the region {(x,y):−1≤x≤1, 0≤y≤a+e∣x∣−e−x, a>0}\{(x,y):-1\le x\le 1,\ 0\le y\le a+e^{|x|}-e^{-x},\ a>0\}{(x,y):−1≤x≤1, 0≤y≤a+e∣x∣−e−x, a>0} is e2+8e+1e\dfrac{e^2+8e+1}{e}ee2+8e+1​, then the value of aaa is :
  1. (A)7
  2. (B)6
  3. (C)8
  4. (D)5

Correct answer: (D)

Step-by-step solution →
Q38·MathematicsSingle correctJEE Main 2025
The area of the region inside the circle (x−23)2+y2=12(x-2\sqrt3)^2+y^2=12(x−23​)2+y2=12 and outside the parabola y2=23 xy^2=2\sqrt3\,xy2=23​x is:
  1. (A)6π−86\pi-86π−8
  2. (B)3π−83\pi-83π−8
  3. (C)6π−166\pi-166π−16
  4. (D)5π+85\pi+85π+8

Correct answer: (C)

Step-by-step solution →
Q39·MathematicsSingle correctJEE Main 2025
Let f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R be twice differentiable with f(x+y)=f(x)f(y)f(x+y)=f(x)f(y)f(x+y)=f(x)f(y) for all x,yx,yx,y. If f′(0)=4af'(0)=4af′(0)=4a and f′′(x)−3a f′(x)−f(x)=0 (a>0)f''(x)-3a\,f'(x)-f(x)=0\,(a>0)f′′(x)−3af′(x)−f(x)=0(a>0), then the area of R={(x,y):0≤y≤f(ax), 0≤x≤2}R=\{(x,y):0\le y\le f(ax),\,0\le x\le 2\}R={(x,y):0≤y≤f(ax),0≤x≤2} is:
  1. (A)e4−1e^{4}-1e4−1
  2. (B)e2+1e^{2}+1e2+1
  3. (C)e4+1e^{4}+1e4+1
  4. (D)e2−1e^{2}-1e2−1

Correct answer: (D)

Step-by-step solution →
Q40·MathematicsSingle correctJEE Main 2025
The area of the region enclosed by the curves y=x2−4x+4y=x^2-4x+4y=x2−4x+4 and y2=16−8xy^2=16-8xy2=16−8x is:
  1. (A)83\dfrac{8}{3}38​
  2. (B)43\dfrac{4}{3}34​
  3. (C)5
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q41·MathematicsSingle correctJEE Advanced 2024
Let S={(x,y)∈R×R:x≥0,y≥0,y2≤4x,y2≤12−2x and 3y+8x≤58}S = \left\{(x, y) \in \mathbb{R} \times \mathbb{R} : x \geq 0, y \geq 0, y^2 \leq 4x, y^2 \leq 12 - 2x \text{ and } 3y + \sqrt{8}x \leq 5\sqrt{8}\right\}S={(x,y)∈R×R:x≥0,y≥0,y2≤4x,y2≤12−2x and 3y+8​x≤58​}. If the area of the region SSS is α2\alpha\sqrt{2}α2​, then α\alphaα is equal to
  1. (A)172\frac{17}{2}217​
  2. (B)173\frac{17}{3}317​
  3. (C)174\frac{17}{4}417​
  4. (D)175\frac{17}{5}517​

Correct answer: (B)

Step-by-step solution →
Q42·MathematicsSingle correctJEE Main 2024
The area (in square units) of the region enclosed by the ellipse x2+3y2=18x^{2}+3y^{2}=18x2+3y2=18 in the first quadrant below the line y=xy=xy=x is:
  1. (A)3π+34\sqrt{3}\pi+\dfrac{3}{4}3​π+43​
  2. (B)3π\sqrt{3}\pi3​π
  3. (C)3π−34\sqrt{3}\pi-\dfrac{3}{4}3​π−43​
  4. (D)3π+1\sqrt{3}\pi+13​π+1

Correct answer: (B)

Step-by-step solution →
Q43·MathematicsSingle correctJEE Main 2024
The parabola y2=4xy^2 = 4xy2=4x divides the area of the circle x2+y2=5x^2 + y^2 = 5x2+y2=5 in two parts. The area of the smaller part is equal to:
  1. (A)23+5sin⁡−1(25)\frac{2}{3} + 5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)32​+5sin−1(5​2​)
  2. (B)13+5sin⁡−1(25)\frac{1}{3} + 5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)31​+5sin−1(5​2​)
  3. (C)13+5sin⁡−1(25)\frac{1}{3} + \sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)31​+5​sin−1(5​2​)
  4. (D)23+5sin⁡−1(25)\frac{2}{3} + \sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)32​+5​sin−1(5​2​)

Correct answer: (A)

Step-by-step solution →
Q44·MathematicsSingle correctJEE Main 2024
The area of the region in the first quadrant inside the circle x2+y2=8x^2+y^2=8x2+y2=8 and outside the parabola y2=2xy^2=2xy2=2x is equal to
  1. (A)π2−13\tfrac{\pi}{2}-\tfrac{1}{3}2π​−31​
  2. (B)π−23\pi-\tfrac{2}{3}π−32​
  3. (C)π2−23\tfrac{\pi}{2}-\tfrac{2}{3}2π​−32​
  4. (D)π−13\pi-\tfrac{1}{3}π−31​

Correct answer: (B)

Step-by-step solution →
Q45·MathematicsNumericalJEE Main 2024
Let the area of the region enclosed by the curve y=min⁡{sin⁡x,cos⁡x}y=\min\{\sin x,\cos x\}y=min{sinx,cosx} and the x-axis between x=−πx=-\pix=−π to x=πx=\pix=π be AAA. Then A2A^2A2 is equal to ___

Correct answer: 16

Step-by-step solution →
Q46·MathematicsSingle correctJEE Main 2024
If the area of the region {(x,y):ax2≤y≤1x, 1≤x≤2, 0<a<1}\left\{(x,y):\frac{a}{x^{2}}\le y\le\frac{1}{x},\,1\le x\le 2,\,0<a<1\right\}{(x,y):x2a​≤y≤x1​,1≤x≤2,0<a<1} is (log⁡e2)−17(\log_{e}2)-\frac{1}{7}(loge​2)−71​ then the value of 7a−37a-37a−3 is equal to:
  1. (A)222
  2. (B)000
  3. (C)−1-1−1
  4. (D)111

Correct answer: (C)

Step-by-step solution →
Q47·MathematicsSingle correctJEE Main 2024
Let the area of the region enclosed by the curves y=3xy=3xy=3x, 2y=27−3x2y=27-3x2y=27−3x and y=3x−xxy=3x-x\sqrt{x}y=3x−xx​ be AAA. Then 10A10A10A is equal to
  1. (A)184184184
  2. (B)154154154
  3. (C)172172172
  4. (D)162162162

Correct answer: (D)

Step-by-step solution →
Q48·MathematicsSingle correctJEE Main 2024
The area enclosed between the curves y=x∣x∣y=x|x|y=x∣x∣ and y=x−∣x∣y=x-|x|y=x−∣x∣ is:
  1. (A)83\dfrac{8}{3}38​
  2. (B)23\dfrac{2}{3}32​
  3. (C)1
  4. (D)43\dfrac{4}{3}34​

Correct answer: (D)

Step-by-step solution →
Q49·MathematicsNumericalJEE Main 2024
The area of the region enclosed by the parabolas y=x2−5xy = x^2 - 5xy=x2−5x and y=7x−x2y = 7x - x^2y=7x−x2 is ___.

Correct answer: 72

Step-by-step solution →
Q50·MathematicsSingle correctJEE Main 2024
The area (in sq. units) of the region described by {(x,y):y2≤2x and y≥4x−1}\{(x,y):y^2\le 2x \text{ and } y\ge 4x-1\}{(x,y):y2≤2x and y≥4x−1} is
  1. (A)1132\tfrac{11}{32}3211​
  2. (B)83\tfrac{8}{3}38​
  3. (C)1112\tfrac{11}{12}1211​
  4. (D)932\tfrac{9}{32}329​

Correct answer: (D)

Step-by-step solution →
Q51·MathematicsSingle correctJEE Main 2024
One of the points of intersection of the curves y=1+3x−2x2y=1+3x-2x^2y=1+3x−2x2 and y=1xy=\dfrac1xy=x1​ is (12,2)\left(\dfrac12,2\right)(21​,2). Let the area of the region bounded by these curves be 124(ℓ5+m)−nlog⁡e(1+5)\dfrac{1}{24}(\ell\sqrt5+m)-n\log_e(1+\sqrt5)241​(ℓ5​+m)−nloge​(1+5​), where ℓ,m,n∈N\ell,m,n\in\mathbb{N}ℓ,m,n∈N. Then ℓ+m+n\ell+m+nℓ+m+n is equal to:
  1. (A)323232
  2. (B)303030
  3. (C)292929
  4. (D)313131

Correct answer: (B)

Step-by-step solution →
Q52·MathematicsSingle correctJEE Main 2024
The area (in sq. units) of the region S={z=x+iy:∣z−1∣≤2,  (z+zˉ)+i(z−zˉ)≤2,  Im⁡(z)≥0}S=\{z=x+iy:|z-1|\le 2,\;(z+\bar{z})+i(z-\bar{z})\le 2,\;\operatorname{Im}(z)\ge 0\}S={z=x+iy:∣z−1∣≤2,(z+zˉ)+i(z−zˉ)≤2,Im(z)≥0} is
  1. (A)3π2\tfrac{3\pi}{2}23π​
  2. (B)3π3\pi3π
  3. (C)17π6\tfrac{17\pi}{6}617π​
  4. (D)7π4\tfrac{7\pi}{4}47π​

Correct answer: (A)

Step-by-step solution →
Q53·MathematicsSingle correctJEE Main 2024
The area enclosed by the curves xy+4y=16xy+4y=16xy+4y=16 and x+y=6x+y=6x+y=6 is equal to:
  1. (A)28−30log⁡e228-30\log_e 228−30loge​2
  2. (B)30−28log⁡e230-28\log_e 230−28loge​2
  3. (C)30−32log⁡e230-32\log_e 230−32loge​2
  4. (D)32−30log⁡e232-30\log_e 232−30loge​2

Correct answer: (C)

Step-by-step solution →
Q54·MathematicsNumericalJEE Main 2024
The sum of squares of all possible values of kkk, for which area of the region bounded by the parabolas 2y2=kx2y^2=kx2y2=kx and ky2=2(y−x)ky^2=2(y-x)ky2=2(y−x) is maximum, is equal to __________.

Correct answer: 8

Step-by-step solution →
Q55·MathematicsNumericalJEE Main 2024
Three points O(0,0)O(0,0)O(0,0), P(a,a2)P(a,a^2)P(a,a2), Q(−b,b2)Q(-b,b^2)Q(−b,b2), a>0,b>0a>0,b>0a>0,b>0, are on the parabola y=x2y=x^2y=x2. Let S1S_1S1​ be the area of the region bounded by the line PQ and the parabola, and S2S_2S2​ be the area of the triangle OPQ. If the minimum value of S1S2\dfrac{S_1}{S_2}S2​S1​​ is mn\dfrac{m}{n}nm​, gcd⁡(m,n)=1\gcd(m,n)=1gcd(m,n)=1, then m+nm+nm+n is equal to __________.

Correct answer: 7

Step-by-step solution →
Q56·MathematicsSingle correctJEE Main 2024
The area of the region {(x,y):y2≤4x, x<4, xy(x−1)(x−2)(x−3)(x−4)>0, x≠3}\left\{(x,y): y^2\le 4x,\ x<4,\ \dfrac{xy(x-1)(x-2)}{(x-3)(x-4)}>0,\ x\ne 3\right\}{(x,y):y2≤4x, x<4, (x−3)(x−4)xy(x−1)(x−2)​>0, x=3} is
  1. (A)163\dfrac{16}{3}316​
  2. (B)643\dfrac{64}{3}364​
  3. (C)83\dfrac{8}{3}38​
  4. (D)323\dfrac{32}{3}332​

Correct answer: (D)

Step-by-step solution →
Q57·MathematicsSingle correctJEE Main 2024
The area of the region enclosed by the parabola y=4x−x2y=4x-x^2y=4x−x2 and 3y=(x−4)23y=(x-4)^23y=(x−4)2 is equal to
  1. (A)329\dfrac{32}{9}932​
  2. (B)4
  3. (C)6
  4. (D)143\dfrac{14}{3}314​

Correct answer: (C)

Step-by-step solution →
Q58·MathematicsNumericalJEE Main 2024
The area of the region enclosed by the parabola (y−2)2=x−1(y-2)^2=x-1(y−2)2=x−1, the line x−2y+4=0x-2y+4=0x−2y+4=0 and the positive coordinate axes is ______.

Correct answer: 5

Step-by-step solution →
Q59·MathematicsSingle correctJEE Main 2024
The area (in square units) of the region bounded by the parabola y2=4(x−2)y^2=4(x-2)y2=4(x−2) and the line y=2x−8y=2x-8y=2x−8 is:
  1. (A)888
  2. (B)999
  3. (C)666
  4. (D)777

Correct answer: (B)

Step-by-step solution →
Q60·MathematicsNumericalJEE Main 2024
Let the area of the region {(x,y):0≤x≤3, 0≤y≤min⁡{x2+2, 2x+2}}\{(x,y):0\le x\le 3,\ 0\le y\le\min\{x^2+2,\,2x+2\}\}{(x,y):0≤x≤3, 0≤y≤min{x2+2,2x+2}} be AAA. Then 12A12A12A is equal to ___.

Correct answer: 164

Step-by-step solution →
Q61·MathematicsNumericalJEE Main 2024
The area (in sq. units) of the part of circle x2+y2=169x^2+y^2=169x2+y2=169 which is below the line 5x−y=135x-y=135x−y=13 is πα2β−652+αβsin⁡−1(1213)\dfrac{\pi\alpha}{2\beta}-\dfrac{65}{2}+\dfrac{\alpha}{\beta}\sin^{-1}\left(\dfrac{12}{13}\right)2βπα​−265​+βα​sin−1(1312​) where α,β\alpha,\betaα,β are coprime numbers. Then α+β\alpha+\betaα+β is equal to ______.

Correct answer: 171

Step-by-step solution →
Q62·MathematicsNumericalJEE Main 2024
If the area of the region {(x,y):0≤y≤min⁡{2x,6x−x2}}\{(x,y):0\le y\le\min\{2x,6x-x^2\}\}{(x,y):0≤y≤min{2x,6x−x2}} is A, then 12A12A12A is equal to __________.

Correct answer: 304

Step-by-step solution →
Q63·MathematicsNumericalJEE Main 2024
Let the area of the region {(x,y):x−2y+4≥0, x+2y2≥0, x+4y2≤8, y≥0}\{(x,y):x-2y+4\ge 0,\,x+2y^2\ge 0,\,x+4y^2\le 8,\,y\ge 0\}{(x,y):x−2y+4≥0,x+2y2≥0,x+4y2≤8,y≥0} be mn\dfrac{m}{n}nm​, where mmm and nnn are coprime numbers. Then m+nm+nm+n is equal to __________.

Correct answer: 119

Step-by-step solution →
Q64·MathematicsNumericalJEE Advanced 2023
Let n≥2n \geq 2n≥2 be a natural number and f:[0,1]→Rf : [0, 1] \rightarrow Rf:[0,1]→R be the function defined by f(x)={n(1−2nx)if 0≤x≤12n2n(2nx−1)if 12n≤x≤34n4n(1−nx)if 34n≤x≤1nnn−1(nx−1)if 1n≤x≤1f(x) = \begin{cases} n(1 - 2nx) & \text{if } 0 \leq x \leq \frac{1}{2n} \\ 2n(2nx - 1) & \text{if } \frac{1}{2n} \leq x \leq \frac{3}{4n} \\ 4n(1 - nx) & \text{if } \frac{3}{4n} \leq x \leq \frac{1}{n} \\ \frac{n}{n-1}(nx - 1) & \text{if } \frac{1}{n} \leq x \leq 1 \end{cases}f(x)=⎩⎨⎧​n(1−2nx)2n(2nx−1)4n(1−nx)n−1n​(nx−1)​if 0≤x≤2n1​if 2n1​≤x≤4n3​if 4n3​≤x≤n1​if n1​≤x≤1​ If n is such that the area of the region bounded by the curves x=0x = 0x=0 , x=1x = 1x=1 , y=0y = 0y=0 and y=f(x)y = f(x)y=f(x) is 4 , then the maximum value of the function f is

Correct answer: 8

Step-by-step solution →
Q65·MathematicsMultiple correctJEE Advanced 2023
Let f:[0,1]→[0,1]f : [0, 1] \rightarrow [0, 1]f:[0,1]→[0,1] be the function defined by f(x)=x33−x2+59x+1736f(x) = \frac{x^3}{3} - x^2 + \frac{5}{9}x + \frac{17}{36}f(x)=3x3​−x2+95​x+3617​ . Consider the square region S=[0,1]×[0,1]S = [0, 1] \times [0, 1]S=[0,1]×[0,1]. Let G={(x,y)∈S:y>f(x)}G = \{(x, y) \in S : y > f(x)\}G={(x,y)∈S:y>f(x)} be called the green region and R={(x,y)∈S:y<f(x)}R = \{(x, y) \in S : y < f(x)\}R={(x,y)∈S:y<f(x)} be called the red region. Let Lh={(x,h)∈S:x∈[0,1]}L_h = \{(x, h) \in S : x \in [0, 1]\}Lh​={(x,h)∈S:x∈[0,1]} be the horizontal line drawn at a height h∈[0,1]h \in [0, 1]h∈[0,1]. Then which of the following statements is(are) true?
  1. (A)There exists an h∈[14,23]h \in \left[\frac{1}{4}, \frac{2}{3}\right]h∈[41​,32​] such that the area of the green region above the line LhL_hLh​ equals the area of the green region below the line LhL_hLh​
  2. (B)There exists an h∈[14,23]h \in \left[\frac{1}{4}, \frac{2}{3}\right]h∈[41​,32​] such that the area of the red region above the line LhL_hLh​ equals the area of the red region below the line LhL_hLh​
  3. (C)There exists an h∈[14,23]h \in \left[\frac{1}{4}, \frac{2}{3}\right]h∈[41​,32​] such that the area of the green region above the line LhL_hLh​ equals the area of the red region below the line LhL_hLh​
  4. (D)There exists an h∈[14,23]h \in \left[\frac{1}{4}, \frac{2}{3}\right]h∈[41​,32​] such that the area of the red region above the line LhL_hLh​ equals the area of the green region below the line LhL_hLh​

Correct answer: (B), (C), (D)

Step-by-step solution →
Q66·MathematicsNumericalJEE Main 2023
If the area bounded by the curve 2y2=3x2y^2 = 3x2y2=3x, lines x+y=3x + y = 3x+y=3, y=0y = 0y=0 and outside the circle (x−3)2+y2=2(x - 3)^2 + y^2 = 2(x−3)2+y2=2 is AAA, then 4(π+4A)4(\pi + 4A)4(π+4A) is equal to____

Correct answer: 42

Step-by-step solution →
Q67·MathematicsSingle correctJEE Main 2023
The area of the region enclosed by the curve f(x)=max⁡{sin⁡x,cos⁡x}, −π≤x≤πf(x)=\max\{\sin x,\cos x\},\,-\pi\le x\le\pif(x)=max{sinx,cosx},−π≤x≤π and the xxx-axis is:
  1. (A)2(2+1)2(\sqrt2+1)2(2​+1)
  2. (B)22(2+1)2\sqrt2(\sqrt2+1)22​(2​+1)
  3. (C)4(2)4(\sqrt2)4(2​)
  4. (D)444

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correctJEE Main 2023
The area of the region {(x,y):x2≤y≤∣x2−4∣, y≥1}\left\{(x, y) : x^2 \le y \le \left|x^2 - 4\right|,\ y \ge 1\right\}{(x,y):x2≤y≤​x2−4​, y≥1} is
  1. (A)34(42−1)\dfrac{3}{4}\left(4\sqrt{2} - 1\right)43​(42​−1)
  2. (B)43(42−1)\dfrac{4}{3}\left(4\sqrt{2} - 1\right)34​(42​−1)
  3. (C)43(42+1)\dfrac{4}{3}\left(4\sqrt{2} + 1\right)34​(42​+1)
  4. (D)34(42+1)\dfrac{3}{4}\left(4\sqrt{2} + 1\right)43​(42​+1)

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correctJEE Main 2023
The area of the region enclosed by the curve y=x3y=x^3y=x3 and its tangent at the point (−1,−1)(-1,-1)(−1,−1) is
  1. (A)274\dfrac{27}{4}427​
  2. (B)194\dfrac{19}{4}419​
  3. (C)234\dfrac{23}{4}423​
  4. (D)314\dfrac{31}{4}431​

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsNumericalJEE Main 2023
If AAA is the area in the first quadrant enclosed by the curve C:2x2−y+1=0C:2x^2-y+1=0C:2x2−y+1=0, the tangent to CCC at the point (1,3)(1,3)(1,3) and the line x+y=1x+y=1x+y=1, then the value of 60A60A60A is

Correct answer: 16

Step-by-step solution →
Q71·MathematicsSingle correctJEE Main 2023
Area of the region {(x,y):x2+(y−2)2≤4, x2≥2y}\{ (x, y) : x^2 + (y - 2)^2 \le 4,\ x^2 \ge 2y \}{(x,y):x2+(y−2)2≤4, x2≥2y} is
  1. (A)2π−1632\pi - \frac{16}{3}2π−316​
  2. (B)π−83\pi - \frac{8}{3}π−38​
  3. (C)π+83\pi + \frac{8}{3}π+38​
  4. (D)2π+1632\pi + \frac{16}{3}2π+316​

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsNumericalJEE Main 2023
If the area of the region {(x,y):∣x2−2∣≤y≤x}\{(x,y):|x^2-2|\le y\le x\}{(x,y):∣x2−2∣≤y≤x} is A, then 6A+1626A+16\sqrt{2}6A+162​ is equal to _______ .

Correct answer: 27

Step-by-step solution →
Q73·MathematicsNumericalJEE Main 2023
Let y=p(x)y=p(x)y=p(x) be the parabola passing through the points (−1,0),(0,1)(-1,0),(0,1)(−1,0),(0,1) and (1,0)(1,0)(1,0). If the area of the region {(x,y):(x+1)2+(y−1)2≤1, y≤p(x)}\{(x,y):(x+1)^2+(y-1)^2\le1,\ y\le p(x)\}{(x,y):(x+1)2+(y−1)2≤1, y≤p(x)} is A, then 12(π−4A)12(\pi-4A)12(π−4A) is equal to _________.

Correct answer: 16

Step-by-step solution →
Q74·MathematicsSingle correctJEE Main 2023
The area of the region {(x,y):x2≤y≤8−x2, y≤7}\{(x,y):x^{2}\le y\le 8-x^{2},\, y\le 7\}{(x,y):x2≤y≤8−x2,y≤7} is
  1. (A)21
  2. (B)18
  3. (C)24
  4. (D)20

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsNumericalJEE Main 2023
Let the area enclosed by the lines x+y=2x+y=2x+y=2, y=0y=0y=0, x=0x=0x=0 and the curve f(x)=min⁡{x2+34, 1+[x]}f(x)=\min\left\{x^{2}+\dfrac{3}{4},\,1+[x]\right\}f(x)=min{x2+43​,1+[x]}, where [x][x][x] denotes the greatest integer ≤x\leq x≤x, be A. Then the value of 12A12A12A is

Correct answer: 17

Step-by-step solution →
Q76·MathematicsSingle correctJEE Main 2023
The area bounded by the curves y=∣x−1∣+∣x−2∣y=|x-1|+|x-2|y=∣x−1∣+∣x−2∣ and y=3y=3y=3 is equal to
  1. (A)3
  2. (B)4
  3. (C)5
  4. (D)6

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsNumericalJEE Main 2023
If the area of the region S={(x,y):2y−y2≤x2≤2y, x≥y}S=\{(x,y):2y-y^{2}\le x^{2}\le 2y,\,x\ge y\}S={(x,y):2y−y2≤x2≤2y,x≥y} is equal to n+2n+1−πn−1\dfrac{n+2}{n+1}-\dfrac{\pi}{n-1}n+1n+2​−n−1π​, then the natural number nnn is equal to _____.

Correct answer: 5

Step-by-step solution →
Q78·MathematicsNumericalJEE Main 2023
Let AAA be the area bounded by the curve y=x∣x−3∣y=x|x-3|y=x∣x−3∣, the xxx-axis and the ordinates x=−1x=-1x=−1 and x=2x=2x=2. Then 12A12A12A is equal to _______ .

Correct answer: 62

Step-by-step solution →
Q79·MathematicsSingle correctJEE Main 2023
The area of the region given by {(x,y):xy≤8, 1≤y≤x2}\{(x,y):xy\leq 8,\,1\leq y\leq x^2\}{(x,y):xy≤8,1≤y≤x2} is:
  1. (A)16log⁡e2+7316\log_e 2+\dfrac7316loge​2+37​
  2. (B)16log⁡e2−14316\log_e 2-\dfrac{14}{3}16loge​2−314​
  3. (C)8log⁡e2−1338\log_e 2-\dfrac{13}{3}8loge​2−313​
  4. (D)8log⁡e2+768\log_e 2+\dfrac768loge​2+67​

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsNumericalJEE Main 2023
Let the area of the region {(x,y):∣2x−1∣≤y≤∣x2−x∣, 0≤x≤1}\{(x,y):|2x-1|\le y\le|x^2-x|,\ 0\le x\le1\}{(x,y):∣2x−1∣≤y≤∣x2−x∣, 0≤x≤1} be AAA. Then (6A+11)2(6A+11)^2(6A+11)2 is equal to

Correct answer: 125

Step-by-step solution →
Q81·MathematicsSingle correctJEE Main 2023
Let qqq be the maximum integral value of ppp in [0,10][0, 10][0,10] for which the roots of the equation x2−px+54p=0x^2 - px + \dfrac{5}{4}p=0x2−px+45​p=0 are rational. Then the area of the region {(x,y):0≤y≤(x−q)2, 0≤x≤q}\{(x, y): 0 \le y \le (x - q)^2,\ 0 \le x \le q\}{(x,y):0≤y≤(x−q)2, 0≤x≤q} is:
  1. (A)243243243
  2. (B)164164164
  3. (C)1253\dfrac{125}{3}3125​
  4. (D)252525

Correct answer: (A)

Step-by-step solution →
Q82·MathematicsNumericalJEE Main 2023
Let AAA be the area of the region {(x,y):y≥x2, y≥(1−x)2, y≤2x(1−x)}\{(x, y): y \ge x^2,\ y \ge (1 - x)^2,\ y \le 2x(1 - x)\}{(x,y):y≥x2, y≥(1−x)2, y≤2x(1−x)}. Then 540 A540\,A540A is equal to _______.

Correct answer: 25

Step-by-step solution →
Q83·MathematicsNumericalJEE Main 2023
Let α\alphaα be the area of the larger region bounded by the curve y2=8xy^2=8xy2=8x and the lines y=xy=xy=x and x=2x=2x=2, which lies in the first quadrant. Then the value of 3α3\alpha3α is equal to

Correct answer: 22

Step-by-step solution →
Q84·MathematicsSingle correctJEE Main 2023
The area of the region A={(x,y):∣cos⁡x−sin⁡x∣≤y≤sin⁡x, 0≤x≤π2}A=\{(x,y):|\cos x-\sin x|\le y\le\sin x,\,0\le x\le\dfrac{\pi}{2}\}A={(x,y):∣cosx−sinx∣≤y≤sinx,0≤x≤2π​} is:
  1. (A)5+22−4.5\sqrt5+2\sqrt2-4.55​+22​−4.5
  2. (B)1−32+451-\dfrac{3}{\sqrt2}+\dfrac{4}{\sqrt5}1−2​3​+5​4​
  3. (C)35−32+1\dfrac{3}{\sqrt5}-\dfrac{3}{\sqrt2}+15​3​−2​3​+1
  4. (D)5−22+1\sqrt5-2\sqrt2+15​−22​+1

Correct answer: (D)

Step-by-step solution →
Q85·MathematicsSingle correctJEE Main 2023
Let Δ\DeltaΔ be the area of the region {(x,y)∈R2:x2+y2≤21,y2≤4x,x≥1}\{(x, y) \in \mathbb{R}^2 : x^2 + y^2 \leq 21, y^2 \leq 4x, x \geq 1\}{(x,y)∈R2:x2+y2≤21,y2≤4x,x≥1}. Then 12(Δ−21sin⁡−127)\dfrac{1}{2}\left(\Delta - 21\sin^{-1}\dfrac{2}{\sqrt{7}}\right)21​(Δ−21sin−17​2​) is equal to
  1. (A)23−232\sqrt{3} - \dfrac{2}{3}23​−32​
  2. (B)3−43\sqrt{3} - \dfrac{4}{3}3​−34​
  3. (C)3−23\sqrt{3} - \dfrac{2}{3}3​−32​
  4. (D)23−132\sqrt{3} - \dfrac{1}{3}23​−31​

Correct answer: (B)

Step-by-step solution →
Q86·MathematicsSingle correctJEE Main 2023
Let A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2}A = \{(x, y) \in \mathbb{R}^2 : y \geq 0, 2x \leq y \leq \sqrt{4 - (x - 1)^2}\}A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2​} and B={(x,y)∈R×R:0≤y≤min⁡{2x,4−(x−1)2}}B = \{(x, y) \in \mathbb{R} \times \mathbb{R} : 0 \leq y \leq \min\{2x, \sqrt{4 - (x - 1)^2}\}\}B={(x,y)∈R×R:0≤y≤min{2x,4−(x−1)2​}}. Then the ratio of the area of AAA to the area of BBB is
  1. (A)π+1π−1\dfrac{\pi + 1}{\pi - 1}π−1π+1​
  2. (B)ππ−1\dfrac{\pi}{\pi - 1}π−1π​
  3. (C)π−1π+1\dfrac{\pi - 1}{\pi + 1}π+1π−1​
  4. (D)ππ+1\dfrac{\pi}{\pi + 1}π+1π​

Correct answer: (C)

Step-by-step solution →
Q87·MathematicsNumericalJEE Main 2023
If the area enclosed by the parabolas P1:2y=5x2P_1:2y=5x^2P1​:2y=5x2 and P2:x2−y+6=0P_2:x^2-y+6=0P2​:x2−y+6=0 is equal to the area enclosed by P1P_1P1​ and y=αxy=\alpha xy=αx, α>0\alpha>0α>0, then α3\alpha^3α3 is equal to _______.

Correct answer: 600

Step-by-step solution →
Q88·MathematicsNumericalJEE Main 2023
If the area of the region bounded by the curves y2−2y=−x, x+y=0y^2-2y=-x,\ x+y=0y2−2y=−x, x+y=0 is A, then 8A8A8A is equal to

Correct answer: 36

Step-by-step solution →
Q89·MathematicsSingle correctJEE Main 2023
The area enclosed by the curves y2+4x=4y^2+4x=4y2+4x=4 and y−2x=2y-2x=2y−2x=2 is:
  1. (A)999
  2. (B)223\tfrac{22}{3}322​
  3. (C)233\tfrac{23}{3}323​
  4. (D)253\tfrac{25}{3}325​

Correct answer: (A)

Step-by-step solution →
Q90·MathematicsIntegerJEE Advanced 2022
Consider the function f, g : R → R defined by f(x)=x2+512f\left(x\right) = x^{2} + \frac{5}{12}f(x)=x2+125​ and g(x)={2(1−4∣x∣3),∣x∣≤34,0,∣x∣>34.g(x) = \begin{cases} 2\left(1 - \frac{4|x|}{3}\right), & |x| \leq \frac{3}{4}, \\ 0, & |x| > \frac{3}{4}. \end{cases}g(x)={2(1−34∣x∣​),0,​∣x∣≤43​,∣x∣>43​.​ If α is the area of the region {(x,y)∈R×R:∣x∣≤34,0≤y≤min⁡{f(x),g(x)}}\left\{\left(x, y\right) \in R \times R : |x| \leq \frac{3}{4}, 0 \leq y \leq \min\left\{f\left(x\right), g\left(x\right)\right\}\right\}{(x,y)∈R×R:∣x∣≤43​,0≤y≤min{f(x),g(x)}}, then the value of 9α is __________.

Correct answer: 6

Step-by-step solution →
Q91·MathematicsSingle correctJEE Main 2022
The area of the region {(x, y):∣ x−1 ∣≤y≤5−x2}\left\{(x,\,y) : |\,x-1\,| \le y \le \sqrt{5-x^{2}}\right\}{(x,y):∣x−1∣≤y≤5−x2​} is equal to :
  1. (A)52sin⁡−1(35)−12\frac{5}{2}\sin^{-1}\left(\frac{3}{5}\right)-\frac{1}{2}25​sin−1(53​)−21​
  2. (B)5π4−32\frac{5\pi}{4}-\frac{3}{2}45π​−23​
  3. (C)3π4+32\frac{3\pi}{4}+\frac{3}{2}43π​+23​
  4. (D)5π4−12\frac{5\pi}{4}-\frac{1}{2}45π​−21​

Correct answer: (D)

Step-by-step solution →
Q92·MathematicsSingle correctJEE Main 2022
The area enclosed by the curves y=log⁡e(x+e2)y=\log_{e}\left(x+e^{2}\right)y=loge​(x+e2), x=log⁡e(2y)x=\log_{e}\left(\frac{2}{y}\right)x=loge​(y2​) and x=log⁡e2x=\log_{e}2x=loge​2, above the line y=1y=1y=1 is
  1. (A)2+e−log⁡e22+e-\log_{e}22+e−loge​2
  2. (B)1+e−log⁡e21+e-\log_{e}21+e−loge​2
  3. (C)e−log⁡e2e-\log_{e}2e−loge​2
  4. (D)1+log⁡e21+\log_{e}21+loge​2

Correct answer: (B)

Step-by-step solution →
Q93·MathematicsSingle correctJEE Main 2022
The area of the smaller region enclosed by the curves y2=8x+4y^2 = 8x + 4y2=8x+4 and x2+y2+43x−4=0x^2 + y^2 + 4\sqrt{3}x - 4 = 0x2+y2+43​x−4=0 is equal to
  1. (A)13(2−123+8π)\frac{1}{3}\left(2 - 12\sqrt{3} + 8\pi\right)31​(2−123​+8π)
  2. (B)13(2−123+6π)\frac{1}{3}\left(2 - 12\sqrt{3} + 6\pi\right)31​(2−123​+6π)
  3. (C)13(4−123+8π)\frac{1}{3}\left(4 - 12\sqrt{3} + 8\pi\right)31​(4−123​+8π)
  4. (D)13(4−123+6π)\frac{1}{3}\left(4 - 12\sqrt{3} + 6\pi\right)31​(4−123​+6π)

Correct answer: (C)

Step-by-step solution →
Q94·MathematicsSingle correctJEE Main 2022
The area of the region enclosed by y≤4x2,x2≤9yy \le 4x^{2}, x^{2} \le 9yy≤4x2,x2≤9y and y≤4y \le 4y≤4, is equal to :
  1. (A)403\frac{40}{3}340​
  2. (B)563\frac{56}{3}356​
  3. (C)1123\frac{112}{3}3112​
  4. (D)803\frac{80}{3}380​

Correct answer: (D)

Step-by-step solution →
Q95·MathematicsSingle correctJEE Main 2022
The odd natural number a, such that the area of the region bounded by y= 1, y = 3, x = 0, x = ya^{a}a is 3643\dfrac{364}{3}3364​, equal to :
  1. (A)3
  2. (B)5
  3. (C)7
  4. (D)9

Correct answer: (B)

Step-by-step solution →
Q96·MathematicsSingle correctJEE Main 2022
The area bounded by the curves y=∣x2−1∣y=|x^{2}-1|y=∣x2−1∣ and y=1y=1y=1 is
  1. (A)23(2+1)\frac{2}{3}\left(\sqrt{2}+1\right)32​(2​+1)
  2. (B)43(2−1)\frac{4}{3}\left(\sqrt{2}-1\right)34​(2​−1)
  3. (C)2(2−1)2\left(\sqrt{2}-1\right)2(2​−1)
  4. (D)83(2−1)\frac{8}{3}\left(\sqrt{2}-1\right)38​(2​−1)

Correct answer: (D)

Step-by-step solution →
Q97·MathematicsSingle correctJEE Main 2022
The area of the region given by A={(x,y):x2≤y≤min⁡{x+2,4−3x}}A = \{(x, y) : x^{2} \le y \le \min \{x + 2, 4 - 3x\}\}A={(x,y):x2≤y≤min{x+2,4−3x}} is :
  1. (A)318\frac{31}{8}831​
  2. (B)176\frac{17}{6}617​
  3. (C)196\frac{19}{6}619​
  4. (D)278\frac{27}{8}827​

Correct answer: (B)

Step-by-step solution →
Q98·MathematicsSingle correctJEE Main 2022
The area enclosed by y2=8xy^{2} = 8xy2=8x and y=2 xy = \sqrt{2}\,xy=2​x that lies outside the triangle formed by y=2xy = \sqrt{2}xy=2​x, x=1x = 1x=1, y=22y = 2\sqrt{2}y=22​, is equal to :
  1. (A)1626\frac{16\sqrt{2}}{6}6162​​
  2. (B)1126\frac{11\sqrt{2}}{6}6112​​
  3. (C)1326\frac{13\sqrt{2}}{6}6132​​
  4. (D)526\frac{5\sqrt{2}}{6}652​​

Correct answer: (C)

Step-by-step solution →
Q99·MathematicsNumericalJEE Main 2022
For real numbers aaa, b (a>b>0a > b > 0a>b>0), let Area{(x,y):x2+y2≤a2andx2a2+y2b2≥1}=30πArea\left\{(x,y) : x^2 + y^2 \leq a^2 \text{and} \frac{x^2}{a^2} + \frac{y^2}{b^2} \geq 1\right\} = 30\piArea{(x,y):x2+y2≤a2anda2x2​+b2y2​≥1}=30π and Area{(x,y):x2+y2≥b2andx2a2+y2b2≤1}=18πArea\left\{(x,y) : x^2 + y^2 \geq b^2 \text{and} \frac{x^2}{a^2} + \frac{y^2}{b^2} \leq 1\right\} = 18\piArea{(x,y):x2+y2≥b2anda2x2​+b2y2​≤1}=18π Then the value of (a−b)2(a - b)^2(a−b)2 is equal to____.

Correct answer: 12

Step-by-step solution →
Q100·MathematicsSingle correctJEE Main 2022
The area of the region S={(x,y):y2≤8x,y≥2x,x≥1}\mathrm{S}=\{(x,y):y^{2} \le 8x, y \ge \sqrt{2}x, x \ge 1\}S={(x,y):y2≤8x,y≥2​x,x≥1} is
  1. (A)1326\frac{13\sqrt{2}}{6}6132​​
  2. (B)1126\frac{11\sqrt{2}}{6}6112​​
  3. (C)526\frac{5\sqrt{2}}{6}652​​
  4. (D)1926\frac{19\sqrt{2}}{6}6192​​

Correct answer: (B)

Step-by-step solution →
Q101·MathematicsSingle correctJEE Main 2022
The area of the bounded region enclosed by the curve y=3−∣x−12∣−∣x+1∣y = 3 - \left|x - \frac{1}{2}\right| - |x + 1|y=3−​x−21​​−∣x+1∣ and the x-axis is
  1. (A)94\frac{9}{4}49​
  2. (B)4516\frac{45}{16}1645​
  3. (C)278\frac{27}{8}827​
  4. (D)6316\frac{63}{16}1663​

Correct answer: (C)

Step-by-step solution →
Q102·MathematicsNumericalJEE Main 2022
If the area of the region {(x,y):x23+y23≤1 x+y≥0, y≥0}\left\{(x,y):x^{\frac{2}{3}}+y^{\frac{2}{3}}\le 1\, x+y\ge 0,\ y\ge 0\right\}{(x,y):x32​+y32​≤1x+y≥0, y≥0} is A, then 256 Aπ\dfrac{256\,A}{\pi}π256A​ is

Correct answer: 36

Step-by-step solution →
Q103·MathematicsNumericalJEE Main 2022
Let A1={(x,y):∣x∣≤y2,∣x∣+2y≤8}A_1=\left\{(x,y):|x|\le y^2, |x|+2y\le 8\right\}A1​={(x,y):∣x∣≤y2,∣x∣+2y≤8} and A2={(x,y):∣x∣+∣y∣≤k}A_2=\left\{(x,y):|x|+|y|\le k\right\}A2​={(x,y):∣x∣+∣y∣≤k}. If 27 (Area A1A_1A1​) = 5 (Area A2A_2A2​), then k is equal to :

Correct answer: 6

Step-by-step solution →
Q104·MathematicsSingle correctJEE Main 2022
The area of the region bounded by y2=8xy^2=8xy2=8x and y2=16(3−x)y^2=16(3-x)y2=16(3−x) is equal to :-
  1. (A)323\frac{32}{3}332​
  2. (B)403\frac{40}{3}340​
  3. (C)16
  4. (D)19

Correct answer: (C)

Step-by-step solution →
Q105·MathematicsSingle correctJEE Main 2022
The area of the region enclosed between the parabolas y2=2x−1y^2 = 2x - 1y2=2x−1 and y2=4x−3y^2 = 4x - 3y2=4x−3 is
  1. (A)13\frac{1}{3}31​
  2. (B)16\frac{1}{6}61​
  3. (C)23\frac{2}{3}32​
  4. (D)34\frac{3}{4}43​

Correct answer: (A)

Step-by-step solution →
Q106·MathematicsNumericalJEE Main 2022
Let S be the region bounded by the curves y=x3y=x^{3}y=x3 and y2=xy^{2}=xy2=x. The curve y=2∣x∣y=2|x|y=2∣x∣ divides S into two regions of areas R1R_{1}R1​ and R2R_{2}R2​. If max {R1,R2}=R2\{R_{1},R_{2}\}=R_{2}{R1​,R2​}=R2​, then R2R1\dfrac{R_{2}}{R_{1}}R1​R2​​ is equal to ____ .

Correct answer: 19

Step-by-step solution →
Q107·MathematicsNumericalJEE Main 2022
The area (in sq. units) of the region enclosed between the parabola y2=2xy^{2} = 2xy2=2x and the line x+y=4x + y = 4x+y=4 is ______.

Correct answer: 18

Step-by-step solution →
Q108·MathematicsSingle correctJEE Advanced 2021
The area of the region {(x,y):0≤x≤94, 0≤y≤1, x≥3y, x+y≥2}\left\{(x, y) : 0 \le x \le \frac{9}{4},\ 0 \le y \le 1,\ x \ge 3y,\ x + y \ge 2\right\}{(x,y):0≤x≤49​, 0≤y≤1, x≥3y, x+y≥2} is
  1. (A)1132\frac{11}{32}3211​
  2. (B)3596\frac{35}{96}9635​
  3. (C)3796\frac{37}{96}9637​
  4. (D)1332\frac{13}{32}3213​

Correct answer: (A)

Step-by-step solution →
Q109·MathematicsSingle correctJEE Main 2021
The area, enclosed by the curves y = sin x + cos x and y=∣cos⁡x−sin⁡x∣y = \left|\cos x - \sin x\right|y=∣cosx−sinx∣ and the lines x = 0, x=π2x = \frac{\pi}{2}x=2π​, is :
  1. (A)22(2−1)2\sqrt{2}\left(\sqrt{2} - 1\right)22​(2​−1)
  2. (B)2(2+1)2\left(\sqrt{2} + 1\right)2(2​+1)
  3. (C)4(2−1)4\left(\sqrt{2} - 1\right)4(2​−1)
  4. (D)22(2+1)2\sqrt{2}\left(\sqrt{2} + 1\right)22​(2​+1)

Correct answer: (A)

Step-by-step solution →
Q110·MathematicsNumericalJEE Main 2021
If the line y=mxy = mxy=mx bisects the area enclosed by the lines x=0x = 0x=0, y=0y = 0y=0, x=32x = \frac{3}{2}x=23​ and the curve y=1+4x−x2y = 1 + 4x - x^{2}y=1+4x−x2, then 12 m is equal to ______.

Correct answer: 26

Step-by-step solution →
Q111·MathematicsSingle correctJEE Main 2021
The area of the region bounded by the parabola (y−2)2=(x−1)(y - 2)^{2} = (x - 1)(y−2)2=(x−1), the tangent to it at the point whose ordinate is 3 and the x-axis is :
  1. (A)9
  2. (B)10
  3. (C)4
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q112·MathematicsNumericalJEE Main 2021
The area of the region S={(x,y):3x2≤4y≤6x+24}S = \{(x, y) : 3x^{2} \leq 4y \leq 6x + 24\}S={(x,y):3x2≤4y≤6x+24} is ________.

Correct answer: 27

Step-by-step solution →
Q113·MathematicsNumericalJEE Main 2021
Let a and b respectively be the points of local maximum and local minimum of the function f(x)=2x3−3x2−12xf(x) = 2x^{3} - 3x^{2} - 12xf(x)=2x3−3x2−12x. If A is the total area of the region bounded by y=f(x)y = f(x)y=f(x), the x-axis and the lines x=ax = ax=a and x=bx = bx=b, then 4A is equal to ________.

Correct answer: 114

Step-by-step solution →
Q114·MathematicsSingle correctJEE Main 2021
If the area of the bounded region R={(x,y):max⁡{0,log⁡ex}≤y≤2x,12≤x≤2}R = \left\{ (x, y) : \max\left\{0, \log_e x\right\} \le y \le 2^x, \frac{1}{2} \le x \le 2 \right\}R={(x,y):max{0,loge​x}≤y≤2x,21​≤x≤2} is,  α(log⁡e2)−1+β(log⁡e2)+γ\ \alpha\left(\log_e 2\right)^{-1} + \beta\left(\log_e 2\right) + \gamma α(loge​2)−1+β(loge​2)+γ, then the value of (α+β−2γ)2\left(\alpha + \beta - 2\gamma\right)^2(α+β−2γ)2 is equal to :
  1. (A)4
  2. (B)8
  3. (C)2
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q115·MathematicsSingle correctJEE Main 2021
The area of the region bounded by y − x = 2 and x2^22 = y is equal to :
  1. (A)23\frac{2}{3}32​
  2. (B)92\frac{9}{2}29​
  3. (C)163\frac{16}{3}316​
  4. (D)43\frac{4}{3}34​

Correct answer: (B)

Step-by-step solution →
Q116·MathematicsSingle correctJEE Main 2021
The area (in sq. units) of the region, given by the set {(x,y)∈R×R∣x≥0,2x2≤y≤4−2x}\left\{(x, y) \in R \times R \mid x \geq 0, 2x^{2} \leq y \leq 4 - 2x\right\}{(x,y)∈R×R∣x≥0,2x2≤y≤4−2x} is :
  1. (A)173\frac{17}{3}317​
  2. (B)83\frac{8}{3}38​
  3. (C)73\frac{7}{3}37​
  4. (D)133\frac{13}{3}313​

Correct answer: (C)

Step-by-step solution →
Q117·MathematicsNumericalJEE Main 2021
The area (in sq. units) of the region bounded by the curves x2+2y−1=0x^2 + 2y - 1 = 0x2+2y−1=0, y2+4x−4=0y^2 + 4x - 4 = 0y2+4x−4=0 and y2−4x−4=0y^2 - 4x - 4 = 0y2−4x−4=0, in the upper half plane is.........

Correct answer: 2

Step-by-step solution →
Q118·MathematicsSingle correctJEE Main 2021
The area bounded by the curve 4y2=x2(4−x)(x−2)4y^{2} = x^{2}(4-x)(x-2)4y2=x2(4−x)(x−2) is equal to :
  1. (A)π8\frac{\pi}{8}8π​
  2. (B)3π8\frac{3\pi}{8}83π​
  3. (C)3π2\frac{3\pi}{2}23π​
  4. (D)π16\frac{\pi}{16}16π​

Correct answer: (C)

Step-by-step solution →
Q119·MathematicsNumericalJEE Main 2021
Let f:[−3,1]→Rf : [-3, 1] \rightarrow Rf:[−3,1]→R be given as f(x)={min⁡{(x+6),x2},−3≤x≤0max⁡{x,x2},0≤x≤1.f(x) = \begin{cases} \min\left\{(x+6), x^{2}\right\}, & -3 \le x \le 0 \\ \max\left\{\sqrt{x}, x^{2}\right\}, & 0 \le x \le 1. \end{cases}f(x)={min{(x+6),x2},max{x​,x2},​−3≤x≤00≤x≤1.​ If the area bounded by y=f(x)y = f(x)y=f(x) and x-axis is A, then the value of 6A6A6A is equal to ______.

Correct answer: 41

Step-by-step solution →
Q120·MathematicsNumericalJEE Main 2021
Let the curve y = y(x) be the solution of the differential equation, dydx=2(x+1)\frac{dy}{dx} = 2(x+1)dxdy​=2(x+1). If the numerical value of area bounded by the curve y = y(x) and x-axis is 483\frac{4\sqrt{8}}{3}348​​, then the value of y(1) is equal to _______ .

Correct answer: 2

Step-by-step solution →
Q121·MathematicsSingle correctJEE Main 2021
Let A1A_{1}A1​ be the area of the region bounded by the curves y = sinx, y = cos x and y-axis in the first quadrant. Also, let A2A_{2}A2​ be the area of the region bounded by the curves y = sin x, y = cos x, x-axis and x= π2\frac{\pi}{2}2π​ in the first quadrant. Then,
  1. (A)A1=A2A_{1} = A_{2}A1​=A2​ and A1+A2=2A_{1} + A_{2} = \sqrt{2}A1​+A2​=2​
  2. (B)A1:A2=1:2A_{1} : A_{2} = 1 : 2A1​:A2​=1:2 and A1+A2=1A_{1} + A_{2} = 1A1​+A2​=1
  3. (C)2A1=A22A_{1} = A_{2}2A1​=A2​ and A1+A2=1+2A_{1} + A_{2} = 1 + \sqrt{2}A1​+A2​=1+2​
  4. (D)A1:A2=1:2A_{1} : A_{2} = 1 : \sqrt{2}A1​:A2​=1:2​ and A1+A2=1A_{1} + A_{2} = 1A1​+A2​=1

Correct answer: (D)

Step-by-step solution →
Q122·MathematicsNumericalJEE Main 2021
The graphs of sine and cosine functions, intersect each other at a number of points and between two consecutive points of intersection, the two graphs enclose the same area A. Then A4A^4A4 is equal to __________

Correct answer: 64

Step-by-step solution →
Q123·MathematicsSingle correctJEE Main 2021
The area (in sq. units) of the part of the circle x2+y2=36x^2+y^2=36x2+y2=36, which is outside the parabola y2=9xy^2=9xy2=9x, is :
  1. (A)24π+3324\pi + 3\sqrt{3}24π+33​
  2. (B)12π+3312\pi + 3\sqrt{3}12π+33​
  3. (C)12π−3312\pi - 3\sqrt{3}12π−33​
  4. (D)24π−3324\pi - 3\sqrt{3}24π−33​

Correct answer: (D)

Step-by-step solution →
Q124·MathematicsSingle correctJEE Main 2021
The area of the region : R={(x, y):5x2≤y≤2x2+9}R=\left\{(x,\,y):5x^{2}\le y\le 2x^{2}+9\right\}R={(x,y):5x2≤y≤2x2+9} is:
  1. (A)939\sqrt{3}93​ square units
  2. (B)12312\sqrt{3}123​ square units
  3. (C)11311\sqrt{3}113​ square units
  4. (D)636\sqrt{3}63​ square units

Correct answer: (B)

Step-by-step solution →
Q125·MathematicsSingle correctJEE Advanced 2020
Let the functions f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R and g:R→Rg : \mathbb{R} \to \mathbb{R}g:R→R be defined by f(x)=ex−1−e−∣x−1∣f(x) = e^{x-1} - e^{-|x-1|}f(x)=ex−1−e−∣x−1∣ and g(x)=12(ex−1+e1−x)g(x) = \frac{1}{2}\left(e^{x-1} + e^{1-x}\right)g(x)=21​(ex−1+e1−x). Then the area of the region in the first quadrant bounded by the curves y=f(x)y = f(x)y=f(x), y=g(x)y = g(x)y=g(x) and x=0x = 0x=0 is
  1. (A)(2−3)+12(e−e−1)\left(2 - \sqrt{3}\right) + \frac{1}{2}\left(e - e^{-1}\right)(2−3​)+21​(e−e−1)
  2. (B)(2+3)+12(e−e−1)\left(2 + \sqrt{3}\right) + \frac{1}{2}\left(e - e^{-1}\right)(2+3​)+21​(e−e−1)
  3. (C)(2−3)+12(e+e−1)\left(2 - \sqrt{3}\right) + \frac{1}{2}\left(e + e^{-1}\right)(2−3​)+21​(e+e−1)
  4. (D)(2+3)+12(e+e−1)\left(2 + \sqrt{3}\right) + \frac{1}{2}\left(e + e^{-1}\right)(2+3​)+21​(e+e−1)

Correct answer: (A)

Step-by-step solution →
Q126·MathematicsSingle correctJEE Main 2020
The area (in sq. units) of the region enclosed by the curves y=x2−1y = x^{2} - 1y=x2−1 and y=1−x2y = 1 - x^{2}y=1−x2 is equal to
  1. (A)43\frac{4}{3}34​
  2. (B)83\frac{8}{3}38​
  3. (C)72\frac{7}{2}27​
  4. (D)163\frac{16}{3}316​

Correct answer: (B)

Step-by-step solution →
Q127·MathematicsSingle correctJEE Main 2020
The area (in sq. units) of the region A={(x,y):∣x∣+∣y∣≤1, 2y2≥∣x∣}A = \{(x,y) : |x| + |y| \le 1,\ 2y^2 \ge |x|\}A={(x,y):∣x∣+∣y∣≤1, 2y2≥∣x∣} is:
  1. (A)13\dfrac{1}{3}31​
  2. (B)76\dfrac{7}{6}67​
  3. (C)16\dfrac{1}{6}61​
  4. (D)56\dfrac{5}{6}65​

Correct answer: (D)

Step-by-step solution →
Q128·MathematicsSingle correctJEE Main 2020
The area (in sq. units) of the region {(x,y):0≤y≤x2+1, 0≤y≤x+1, 12≤x≤2}\{(x, y) : 0 \leq y \leq x^{2} + 1,\ 0 \leq y \leq x + 1,\ \frac{1}{2} \leq x \leq 2\}{(x,y):0≤y≤x2+1, 0≤y≤x+1, 21​≤x≤2} is:
  1. (A)7916\frac{79}{16}1679​
  2. (B)2316\frac{23}{16}1623​
  3. (C)7924\frac{79}{24}2479​
  4. (D)236\frac{23}{6}623​

Correct answer: (C)

Step-by-step solution →
Q129·MathematicsSingle correctJEE Main 2020
Given : f(x)={x,0≤x<1212,x=121−x,12<x≤1f(x) = \begin{cases} x, & 0 \leq x < \dfrac{1}{2} \\[4pt] \dfrac{1}{2}, & x = \dfrac{1}{2} \\[4pt] 1 - x, & \dfrac{1}{2} < x \leq 1 \end{cases}f(x)=⎩⎨⎧​x,21​,1−x,​0≤x<21​x=21​21​<x≤1​ and g(x)=(x−12)2,x∈Rg(x) = \left(x - \dfrac{1}{2}\right)^{2}, x \in Rg(x)=(x−21​)2,x∈R. Then the area (in sq. units) of the region bounded by the curves, y=f(x)y = f(x)y=f(x) and y=g(x)y = g(x)y=g(x) between the lines 2x=12x = 12x=1 and 2x=32x = \sqrt{3}2x=3​, is:
  1. (A)13+34\dfrac{1}{3} + \dfrac{\sqrt{3}}{4}31​+43​​
  2. (B)12+34\dfrac{1}{2} + \dfrac{\sqrt{3}}{4}21​+43​​
  3. (C)34−13\dfrac{\sqrt{3}}{4} - \dfrac{1}{3}43​​−31​
  4. (D)12−34\dfrac{1}{2} - \dfrac{\sqrt{3}}{4}21​−43​​

Correct answer: (C)

Step-by-step solution →
Q130·MathematicsSingle correctJEE Main 2020
The area of the region, enclosed by the circle x2+y2=2x^{2} + y^{2} = 2x2+y2=2, which is not common to the region bounded by the parabola y2=xy^{2} = xy2=x and the straight line y=xy = xy=x, is :
  1. (A)13(12π−1)\frac{1}{3}(12\pi - 1)31​(12π−1)
  2. (B)13(6π−1)\frac{1}{3}(6\pi - 1)31​(6π−1)
  3. (C)16(12π−1)\frac{1}{6}(12\pi - 1)61​(12π−1)
  4. (D)16(24π−1)\frac{1}{6}(24\pi - 1)61​(24π−1)

Correct answer: (C)

Step-by-step solution →
Q131·MathematicsSingle correctJEE Main 2020
The area (in sq. units of the region {(x,y)∈R2 ∣ 4x2≤y≤8x+12}\{(x,y)\in R^{2}\,|\,4x^{2}\le y\le 8x+12\}{(x,y)∈R2∣4x2≤y≤8x+12} is:
  1. (A)1243\dfrac{124}{3}3124​
  2. (B)1253\dfrac{125}{3}3125​
  3. (C)1283\dfrac{128}{3}3128​
  4. (D)1273\dfrac{127}{3}3127​

Correct answer: (C)

Step-by-step solution →
Q132·MathematicsSingle correctJEE Advanced 2019
The area of the region {(x,y):xy≤8,1≤y≤x2}\{(x, y) : xy \le 8, 1 \le y \le x^2\}{(x,y):xy≤8,1≤y≤x2} is
  1. (A)16log⁡e2−616\log_e 2 - 616loge​2−6
  2. (B)8log⁡e2−1438\log_e 2 - \frac{14}{3}8loge​2−314​
  3. (C)16log⁡e2−14316\log_e 2 - \frac{14}{3}16loge​2−314​
  4. (D)8log⁡e2−738\log_e 2 - \frac{7}{3}8loge​2−37​

Correct answer: (C)

Step-by-step solution →
Q133·MathematicsSingle correctJEE Main 2019
If the area (in sq. units) bounded by the parabola y2=4λxy^{2} = 4\lambda xy2=4λx and the line y=λxy = \lambda xy=λx, λ>0\lambda > 0λ>0, is 19\dfrac{1}{9}91​, then λ\lambdaλ is equal to :
  1. (A)48
  2. (B)434\sqrt{3}43​
  3. (C)262\sqrt{6}26​
  4. (D)24

Correct answer: (D)

Step-by-step solution →
Q134·MathematicsSingle correctJEE Main 2019
If the area (in sq. units) of the region {(x,y):y2≤4x,x+y≤1,x≥0,y≥0}\{(x,y): y^{2} \le 4x, x+y \le 1, x \ge 0, y \ge 0\}{(x,y):y2≤4x,x+y≤1,x≥0,y≥0} is a2+ba\sqrt{2}+ba2​+b, then a −-− b is equal to :
  1. (A)103\frac{10}{3}310​
  2. (B)6
  3. (C)83\frac{8}{3}38​
  4. (D)−23-\frac{2}{3}−32​

Correct answer: (B)

Step-by-step solution →
Q135·MathematicsSingle correctJEE Main 2019
The area(in sq. units) of the region bounded by the curves y=2xy = 2^{x}y=2x and y=∣x+1∣y = |x + 1|y=∣x+1∣ in the first quadrant is
  1. (A)32\dfrac{3}{2}23​
  2. (B)log⁡e2+32\log_{e} 2 + \dfrac{3}{2}loge​2+23​
  3. (C)32−1log⁡e2\dfrac{3}{2} - \dfrac{1}{\log_{e} 2}23​−loge​21​
  4. (D)12\dfrac{1}{2}21​

Correct answer: (C)

Step-by-step solution →
Q136·MathematicsSingle correctJEE Main 2019
The area (in sq. units) of the region A={(x,y):y22≤x≤y+4}A=\left\{\left(x,y\right):\dfrac{y^{2}}{2}\leq x\leq y+4\right\}A={(x,y):2y2​≤x≤y+4} is:
  1. (A)533\dfrac{53}{3}353​
  2. (B)18
  3. (C)30
  4. (D)16

Correct answer: (B)

Step-by-step solution →
Q137·MathematicsSingle correctJEE Main 2019
The area (in sq. units) of the region A={(x,y):x2≤y≤x+2}A=\{(x, y) : x^{2}\leq y\leq x+2\}A={(x,y):x2≤y≤x+2} is:
  1. (A)316\dfrac{31}{6}631​
  2. (B)136\dfrac{13}{6}613​
  3. (C)92\dfrac{9}{2}29​
  4. (D)103\dfrac{10}{3}310​

Correct answer: (C)

Step-by-step solution →
Q138·MathematicsSingle correctJEE Main 2019
The area (in sq. units) of the region A={(x,y)∈R×R∣0≤x≤3,0≤y≤4,y≤x2+3x}A=\{(x,y)\in R\times R \mid 0\le x\le 3, 0\le y\le 4, y\le x^{2}+3x\}A={(x,y)∈R×R∣0≤x≤3,0≤y≤4,y≤x2+3x} is:
  1. (A)263\dfrac{26}{3}326​
  2. (B)596\dfrac{59}{6}659​
  3. (C)536\dfrac{53}{6}653​
  4. (D)8

Correct answer: (B)

Step-by-step solution →
Q139·MathematicsSingle correctJEE Main 2019
The area (in sq. units) of the region bounded by the parabola, y=x2+2y = x^{2} + 2y=x2+2 and the lines, y=x+1y = x + 1y=x+1, x=0x = 0x=0 and x=3x = 3x=3, is:
  1. (A)154\dfrac{15}{4}415​
  2. (B)212\dfrac{21}{2}221​
  3. (C)174\dfrac{17}{4}417​
  4. (D)152\dfrac{15}{2}215​

Correct answer: (D)

Step-by-step solution →
Q140·MathematicsSingle correctJEE Main 2019
The area (in sq. units) in the first quadrant bounded by the parabola, y=x2+1y=x^{2}+1y=x2+1, the tangent to it at the point (2, 5) and the coordinate axes is:
  1. (A)83\frac{8}{3}38​
  2. (B)3724\frac{37}{24}2437​
  3. (C)18724\frac{187}{24}24187​
  4. (D)143\frac{14}{3}314​

Correct answer: (B)

Step-by-step solution →
Q141·MathematicsSingle correctJEE Main 2019
The area (in sq. units) of the region bounded by the curve x2=4yx^{2}=4yx2=4y and the straight line x=4y−2x=4y-2x=4y−2 is:
  1. (A)5/45/45/4
  2. (B)9/89/89/8
  3. (C)7/87/87/8
  4. (D)3/43/43/4

Correct answer: (B)

Step-by-step solution →
Q142·MathematicsSingle correctJEE Main 2019
If the area enclosed between the curves y=kx2y = kx^2y=kx2 and x=ky2x = ky^2x=ky2, (k>0k > 0k>0), is 1 square unit. Then k is:
  1. (A)32\dfrac{\sqrt{3}}{2}23​​
  2. (B)13\dfrac{1}{\sqrt{3}}3​1​
  3. (C)3\sqrt{3}3​
  4. (D)23\dfrac{2}{\sqrt{3}}3​2​

Correct answer: (B)

Step-by-step solution →
Q143·MathematicsSingle correctJEE Main 2019
The area (in sq. units) bounded by the parabola y=x2−1y=x^{2}-1y=x2−1, the tangent at the point (2, 3) to it and the y – axis is:
  1. (A)83\dfrac{8}{3}38​
  2. (B)323\dfrac{32}{3}332​
  3. (C)533\dfrac{53}{3}353​
  4. (D)143\dfrac{14}{3}314​

Correct answer: (A)

Step-by-step solution →
Q144·MathematicsSingle correctJEE Main 2019
The area of the region A{(x,y):0≤y≤x∣x∣+1A\{(x,y):0\leq y\leq x|x|+1A{(x,y):0≤y≤x∣x∣+1 and −1≤x≤1}-1\leq x\leq 1\}−1≤x≤1} in sq. units, is:
  1. (A)23\frac{2}{3}32​
  2. (B)13\frac{1}{3}31​
  3. (C)2
  4. (D)43\frac{4}{3}34​

Correct answer: (C)

Step-by-step solution →
Q145·MathematicsNumericalJEE Advanced 2018
A farmer F1F_{1}F1​ has a land in the shape of a triangle with vertices at P(0,0)P(0, 0)P(0,0), Q(1,1)Q(1, 1)Q(1,1) and R(2,0)R(2, 0)R(2,0). From this land, a neighbouring farmer F2F_{2}F2​ takes away the region which lies between the side PQ and a curve of the form y=xny = x^{n}y=xn (n>1)(n > 1)(n>1). If the area of the region taken away by the farmer F2F_{2}F2​ is exactly 30% of the area of Δ\DeltaΔPQR, then the value of n is ______ .

Correct answer: 4

Step-by-step solution →
Q146·MathematicsMultiple correctJEE Advanced 2017
If the line x=αx = \alphax=α divides the area of region R={(x,y)∈R2:x3≤y≤x, 0≤x≤1}R = \{(x, y) \in \mathbb{R}^{2} : x^{3} \le y \le x,\ 0 \le x \le 1\}R={(x,y)∈R2:x3≤y≤x, 0≤x≤1} into two equal parts, then
  1. (A)0<α≤120 < \alpha \le \dfrac{1}{2}0<α≤21​
  2. (B)12<α<1\dfrac{1}{2} < \alpha < 121​<α<1
  3. (C)2α4−4α2+1=02\alpha^{4} - 4\alpha^{2} + 1 = 02α4−4α2+1=0
  4. (D)α4+4α2−1=0\alpha^{4} + 4\alpha^{2} - 1 = 0α4+4α2−1=0

Correct answer: (B), (C)

Step-by-step solution →
Q147·MathematicsSingle correctJEE Advanced 2016
Area of the region {(x,y)∈R2:y≥∣x+3∣,5y≤x+9≤15}\left\{ (x, y) \in \mathbb{R}^{2} : y \geq \sqrt{|x + 3|}, 5y \leq x + 9 \leq 15 \right\}{(x,y)∈R2:y≥∣x+3∣​,5y≤x+9≤15} is equal to
  1. (A)16\frac{1}{6}61​
  2. (B)43\frac{4}{3}34​
  3. (C)32\frac{3}{2}23​
  4. (D)53\frac{5}{3}35​

Correct answer: (C)

Step-by-step solution →
Q148·MathematicsIntegerJEE Advanced 2014
For a point PPP in the plane, let d1(P)d_1(P)d1​(P) and d2(P)d_2(P)d2​(P) be the distances of the point PPP from the lines x−y=0x - y = 0x−y=0 and x+y=0x + y = 0x+y=0 respectively. The area of the region RRR consisting of all points PPP lying in the first quadrant of the plane and satisfying 2≤d1(P)+d2(P)≤42 \le d_1(P) + d_2(P) \le 42≤d1​(P)+d2​(P)≤4, is __________

Correct answer: 6

Step-by-step solution →
Q149·MathematicsSingle correctJEE Advanced 2013
The area enclosed by the curves y=sin⁡x+cos⁡xy=\sin x+\cos xy=sinx+cosx and y=∣cos⁡x−sin⁡x∣y=|\cos x-\sin x|y=∣cosx−sinx∣ over the interval [0,π2][0,\frac{\pi}{2}][0,2π​] is
  1. (A)4(2−1)4(\sqrt{2}-1)4(2​−1)
  2. (B)22(2−1)2\sqrt{2}(\sqrt{2}-1)22​(2​−1)
  3. (C)2(2+1)2(\sqrt{2}+1)2(2​+1)
  4. (D)22(2+1)2\sqrt{2}(\sqrt{2}+1)22​(2​+1)

Correct answer: (B)

Step-by-step solution →

Area Under Curves — frequently asked

How many questions from Area Under Curves appear in JEE?

Area Under Curves has appeared in 139 of the last 186 JEE Main and JEE Advanced papers — about 75% of them — contributing 149 questions in total across those papers.

Is Area Under Curves an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 75% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Area Under Curves questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Mathematics chapters

  • Three Dimensional Geometry 344
  • Matrices and Determinants 342
  • Sets, Relations and Functions 313
  • Sequence and Series 287
  • Definite Integration 267
  • Vector Algebra 245
  • Differential Equations 240
  • Probability 226

All 26 Mathematics chapters →

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