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Hyperbola — JEE Previous Year Questions

Every Hyperbola question asked in JEE Main and JEE Advanced across the last 186 papers — 80 questions, each with its correct answer. Free to read, no account needed.

Questions

80

Papers it appeared in

77/186

Appearance rate

41%

All 80 Hyperbola questions

Most recent papers first.

Q1·MathematicsNumericalJEE Advanced 2026
Consider the ellipse EEE given by x218+y212=1\dfrac{x^{2}}{18} + \dfrac{y^{2}}{12} = 118x2​+12y2​=1. Let HHH be the hyperbola whose eccentricity is the reciprocal of the eccentricity of EEE and whose foci are the same as that of EEE. Let PPP and QQQ be the points of intersection of HHH and the parabola 5 y=x2\sqrt{5}\, y = x^{2}5​y=x2 in the first quadrant. Let ddd be the distance between PPP and QQQ. If aaa and bbb are the integers such that d2=a+b5d^{2} = a + b\sqrt{5}d2=a+b5​, then the value of a−ba - ba−b is _____.

Correct answer: 18

Step-by-step solution →
Q2·MathematicsSingle correctJEE Main 2026
The eccentricity of an ellipse EEE with centre at the origin OOO is 32\frac{\sqrt{3}}{2}23​​ and its directrices are x=±463x = \pm\frac{4\sqrt{6}}{3}x=±346​​. Let H:x2a2−y2b2=1H : \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1H:a2x2​−b2y2​=1 be a hyperbola whose eccentricity is equal to the length of semi-major axis of EEE, and whose length of latus rectum is equal to the length of minor axis of EEE. Then the distance between the foci of HHH is :
  1. (A)427\frac{4\sqrt{2}}{\sqrt{7}}7​42​​
  2. (B)427\frac{4\sqrt{2}}{7}742​​
  3. (C)47\frac{4}{\sqrt{7}}7​4​
  4. (D)87\frac{8}{7}78​

Correct answer: (D)

Step-by-step solution →
Q3·MathematicsSingle correctJEE Main 2026
If the eccentricity e of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1a2x2​−b2y2​=1, passing through (6, 4√3), satisfies 15(e2^22 + 1) = 34e, then the length of the latus rectum of the hyperbola x2b2−y22(a2+1)=1\frac{x^2}{b^2} - \frac{y^2}{2(a^2 + 1)} = 1b2x2​−2(a2+1)y2​=1 is:
  1. (A)10
  2. (B)20
  3. (C)25
  4. (D)30

Correct answer: (A)

Step-by-step solution →
Q4·MathematicsSingle correctJEE Main 2026
Let the eccentricity e of a hyperbola satisfy the equation 6e2−11e+3=06e^2 - 11e + 3 = 06e2−11e+3=0. If the foci of the hyperbola are (3, 5) and (3, −4), then the length of its latus rectum is :
  1. (A)113\frac{11}{3}311​
  2. (B)173\frac{17}{3}317​
  3. (C)152\frac{15}{2}215​
  4. (D)172\frac{17}{2}217​

Correct answer: (C)

Step-by-step solution →
Q5·MathematicsSingle correctJEE Main 2026
Let H:x2a2−y2b2=1H : \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1H:a2x2​−b2y2​=1 be a hyperbola such that the distance between its foci is 6 and the distance between its directrices is 83\frac{8}{3}38​. If the line x=αx = \alphax=α intersects the hyperbola HHH at the points AAA and BBB such that the area of the triangle AOBAOBAOB is 4154\sqrt{15}415​, where OOO is the origin, then α2\alpha^{2}α2 equals
  1. (A)12
  2. (B)16
  3. (C)24
  4. (D)25

Correct answer: (B)

Step-by-step solution →
Q6·MathematicsSingle correctJEE Main 2026
Let O be the origin, and P and Q be two points on the rectangular hyperbola xy=12xy = 12xy=12 such that the mid point of the line segment PQ is (12,−12)\left(\frac{1}{2}, -\frac{1}{2}\right)(21​,−21​). Then the area of the triangle OPQ equals:
  1. (A)32\frac{3}{2}23​
  2. (B)52\frac{5}{2}25​
  3. (C)72\frac{7}{2}27​
  4. (D)92\frac{9}{2}29​

Correct answer: (C)

Step-by-step solution →
Q7·MathematicsSingle correctJEE Main 2026
Let the ellipse E:x2144+y2169=1E : \dfrac{x^{2}}{144} + \dfrac{y^{2}}{169} = 1E:144x2​+169y2​=1 and the hyperbola H:x216−y2λ2=−1H : \dfrac{x^{2}}{16} - \dfrac{y^{2}}{\lambda^{2}} = -1H:16x2​−λ2y2​=−1 have the same foci. If e and L respectively denote the eccentricity and the length of the latus rectum of H, then the value of 24(e + L) is :
  1. (A)296
  2. (B)126
  3. (C)148
  4. (D)67

Correct answer: (A)

Step-by-step solution →
Q8·MathematicsNumericalJEE Main 2026
For some θ∈(0,π2)\theta \in \left(0, \dfrac{\pi}{2}\right)θ∈(0,2π​), let the eccentricity and the length of the latus rectum of the hyperbola x2−y2sec⁡2θ=8x^{2} - y^{2}\sec^{2}\theta = 8x2−y2sec2θ=8 be e1e_1e1​ and ℓ1\ell_1ℓ1​, respectively, and let the eccentricity and the length of the latus rectum of the ellipse x2sec⁡2θ+y2=6x^{2}\sec^{2}\theta + y^{2} = 6x2sec2θ+y2=6 be e2e_2e2​ and ℓ2\ell_2ℓ2​, respectively. If e12=e22(sec⁡2θ+1)e_1^{2} = e_2^{2}\left(\sec^{2}\theta + 1\right)e12​=e22​(sec2θ+1), then (ℓ1ℓ2e1e2)tan⁡2θ\left(\dfrac{\ell_1\ell_2}{e_1e_2}\right)\tan^{2}\theta(e1​e2​ℓ1​ℓ2​​)tan2θ is equal to _____.

Correct answer: 8

Step-by-step solution →
Q9·MathematicsSingle correctJEE Main 2026
Let PQ be a chord of the hyperbola x24−y2b2=1\dfrac{x^2}{4} - \dfrac{y^2}{b^2} = 14x2​−b2y2​=1, perpendicular to the x-axis such that OPQ is an equilateral triangle, O being the centre of the hyperbola. If the eccentricity of the hyperbola is 3\sqrt{3}3​, then the area of the triangle OPQ is :
  1. (A)232\sqrt{3}23​
  2. (B)835\dfrac{8\sqrt{3}}{5}583​​
  3. (C)115\dfrac{11}{5}511​
  4. (D)95\dfrac{9}{5}59​

Correct answer: (B)

Step-by-step solution →
Q10·MathematicsSingle correctJEE Main 2026
Let the domain of the function f(x)=log⁡3log⁡5log⁡7(9x−x2−13)f(x) = \log_3\log_5\log_7 (9x - x^2 - 13)f(x)=log3​log5​log7​(9x−x2−13) be the interval (m, n). Let the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1a2x2​−b2y2​=1 have eccentricity n3\frac{n}{3}3n​ and the length of the latus rectum 8m3\frac{8m}{3}38m​. Then b2−a2b^2 - a^2b2−a2 is equal to :
  1. (A)5
  2. (B)11
  3. (C)9
  4. (D)7

Correct answer: (D)

Step-by-step solution →
Q11·MathematicsSingle correctJEE Main 2026
Let P (10, 215)\left(10,\ 2\sqrt{15}\right)(10, 215​) be a point on the hyperbola x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1, whose foci are S and S'. If the length of its latus rectum is 8, then the square of the area of ΔPSS′\Delta PSS'ΔPSS′ is equal to :
  1. (A)4200
  2. (B)900
  3. (C)1462
  4. (D)2700

Correct answer: (D)

Step-by-step solution →
Q12·MathematicsSingle correctJEE Main 2026
If the line αx + 2y = 1, where α ∈ ℝ, does not meet the hyperbola x2−9y2=9x^2 - 9y^2 = 9x2−9y2=9, then a possible value of α is :
  1. (A)0.6
  2. (B)0.8
  3. (C)0.5
  4. (D)0.7

Correct answer: (B)

Step-by-step solution →
Q13·MathematicsSingle correctJEE Main 2026
Let the foci of hyperbola coincide with the foci of the ellipse x236+y216=1\frac{x^{2}}{36} + \frac{y^{2}}{16} = 136x2​+16y2​=1. If the eccentricity of the hyperbola is 5, then the length of its latus rectum is:
  1. (A)12
  2. (B)16
  3. (C)965\frac{96}{\sqrt{5}}5​96​
  4. (D)24524\sqrt{5}245​

Correct answer: (C)

Step-by-step solution →
Q14·MathematicsSingle correctJEE Advanced 2025
Let S denote the locus of the point of intersection of the pair of lines 4x−3y=12α4x - 3y = 12\alpha4x−3y=12α, 4αx+3αy=124\alpha x + 3\alpha y = 124αx+3αy=12, where α varies over the set of non-zero real numbers. Let T be the tangent to S passing through the points (p, 0) and (0, q), q > 0, and parallel to the line 4x−32y=04x - \frac{3}{\sqrt{2}}y = 04x−2​3​y=0. Then the value of pq is
  1. (A)−62-6\sqrt{2}−62​
  2. (B)−32-3\sqrt{2}−32​
  3. (C)−92-9\sqrt{2}−92​
  4. (D)−122-12\sqrt{2}−122​

Correct answer: (A)

Step-by-step solution →
Q15·MathematicsIntegerJEE Main 2025
Let the lengths of the transverse and conjugate axes of a hyperbola in standard form be 2a2a2a and 2b2b2b, respectively, and one focus and the corresponding directrix of this hyperbola be (−5,0)(-5,0)(−5,0) and 5x+9=05x+9=05x+9=0, respectively. If the product of the focal distances of a point (α,25)\left(\alpha,2\sqrt{5}\right)(α,25​) on the hyperbola is ppp, then 4p4p4p is equal to __________.

Correct answer: 189

Step-by-step solution →
Q16·MathematicsIntegerJEE Main 2025
Consider the hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1a2x2​−b2y2​=1 having one of its focus at P(−3,0)P(-3,0)P(−3,0). If the latus rectum through its other focus subtends a right angle at PPP and a2b2=α2−βa^2b^2=\alpha\sqrt{2}-\betaa2b2=α2​−β, α,β∈N\alpha,\beta\in\mathbb{N}α,β∈N. Then α+β=\alpha+\beta=α+β= ______.

Correct answer: 1944

Step-by-step solution →
Q17·MathematicsSingle correctJEE Main 2025
Let the sum of the focal distances of the point P(4,3)P(4,3)P(4,3) on the hyperbola H:x2a2−y2b2=1H:\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1H:a2x2​−b2y2​=1 be 8538\sqrt{\dfrac{5}{3}}835​​. If for HHH, the length of the latus rectum is lll and the product of the focal distances of the point PPP is mmm, then 9l2+6m9l^2+6m9l2+6m is equal to:
  1. (A)184
  2. (B)186
  3. (C)185
  4. (D)187

Correct answer: (C)

Step-by-step solution →
Q18·MathematicsIntegerJEE Main 2025
Let the product of the focal distances of the point P(4,23)P(4,2\sqrt3)P(4,23​) on the hyperbola H:x2a2−y2b2=1H:\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1H:a2x2​−b2y2​=1 be 32. Let the length of the conjugate axis of HHH be ppp and the length of its latus rectum be qqq. Then p2+q2p^2+q^2p2+q2 is equal to __________.

Correct answer: 120

Step-by-step solution →
Q19·MathematicsIntegerJEE Main 2025
If the equation of the hyperbola with foci (4,2)(4,2)(4,2) and (8,2)(8,2)(8,2) is 3x2−y2−αx+βy+γ=03x^2-y^2-\alpha x+\beta y+\gamma=03x2−y2−αx+βy+γ=0, then α+β+γ\alpha+\beta+\gammaα+β+γ is equal to __________.

Correct answer: 141

Step-by-step solution →
Q20·MathematicsSingle correctJEE Main 2025
If A and B are the points of intersection of the circle x2+y2−8x=0x^2+y^2-8x=0x2+y2−8x=0 and the hyperbola x29−y24=1\frac{x^2}{9}-\frac{y^2}{4}=19x2​−4y2​=1 and a point P moves on the line 2x−3y+4=02x-3y+4=02x−3y+4=0, then the centroid of △PAB\triangle PAB△PAB lies on the line:
  1. (A)4x−9y=124x-9y=124x−9y=12
  2. (B)x+9y=36x+9y=36x+9y=36
  3. (C)9x−9y=329x-9y=329x−9y=32
  4. (D)6x−9y=206x-9y=206x−9y=20

Correct answer: (D)

Step-by-step solution →
Q21·MathematicsIntegerJEE Main 2025
Let H1:x2a2−y2b2=1H_1:\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1H1​:a2x2​−b2y2​=1 and H2:−x2A2+y2B2=1H_2:-\dfrac{x^2}{A^2}+\dfrac{y^2}{B^2}=1H2​:−A2x2​+B2y2​=1 be two hyperbolas having length of latus rectums 15215\sqrt2152​ and 12512\sqrt5125​ respectively. Let their eccentricities be e1=52e_1=\sqrt{\dfrac{5}{2}}e1​=25​​ and e2e_2e2​ respectively. If the product of the lengths of their transverse axes is 10010100\sqrt{10}10010​, then 25e2225e_2^225e22​ is equal to __________.

Correct answer: 55

Step-by-step solution →
Q22·MathematicsSingle correctJEE Main 2025
The foci of a hyperbola are (1,14)(1,14)(1,14) and (1,−12)(1,-12)(1,−12), and it passes through (1,6)(1,6)(1,6). The length of its latus rectum is:
  1. (A)256\tfrac{25}{6}625​
  2. (B)245\tfrac{24}{5}524​
  3. (C)2885\tfrac{288}{5}5288​
  4. (D)1445\tfrac{144}{5}5144​

Correct answer: (C)

Step-by-step solution →
Q23·MathematicsSingle correctJEE Main 2024
Let the foci of a hyperbola H coincide with the foci of the ellipse E:(x−1)2100+(y−1)275=1E:\dfrac{(x-1)^{2}}{100}+\dfrac{(y-1)^{2}}{75}=1E:100(x−1)2​+75(y−1)2​=1 and the eccentricity of the hyperbola H be the reciprocal of the eccentricity of the ellipse E. If the length of the transverse axis of H is α\alphaα and the length of its conjugate axis is β\betaβ, then 3α2+2β23\alpha^{2}+2\beta^{2}3α2+2β2 is equal to:
  1. (A)242242242
  2. (B)225225225
  3. (C)237237237
  4. (D)205205205

Correct answer: (B)

Step-by-step solution →
Q24·MathematicsSingle correctJEE Main 2024
Let H:−x2a2+y2b2=1H:\dfrac{-x^2}{a^2}+\dfrac{y^2}{b^2}=1H:a2−x2​+b2y2​=1 be the hyperbola, whose eccentricity is 3\sqrt33​ and the length of the latus rectum is 434\sqrt343​. Suppose the point (α,6)(\alpha,6)(α,6), α>0\alpha>0α>0 lies on HHH. If β\betaβ is the product of the focal distances of the point (α,6)(\alpha,6)(α,6), then α2+β\alpha^2+\betaα2+β is equal to:
  1. (A)170170170
  2. (B)171171171
  3. (C)169169169
  4. (D)172172172

Correct answer: (B)

Step-by-step solution →
Q25·MathematicsNumericalJEE Main 2024
Let S be the focus of the hyperbola x23−y25=1\dfrac{x^2}{3}-\dfrac{y^2}{5}=13x2​−5y2​=1, on the positive x-axis. Let C be the circle with its centre at A(6,5)A(\sqrt{6},\sqrt{5})A(6​,5​) and passing through the point S. If O is the origin and SAB is a diameter of C, then the square of the area of the triangle OSB is equal to _______ .

Correct answer: 40

Step-by-step solution →
Q26·MathematicsNumericalJEE Main 2024
The length of the latus rectum and directrices of a hyperbola with eccentricity eee are 999 and x=±43x=\pm\frac{4}{\sqrt{3}}x=±3​4​, respectively. Let the line y−3x+3=0y-\sqrt{3}x+\sqrt{3}=0y−3​x+3​=0 touch this hyperbola at (x0,y0)(x_{0},y_{0})(x0​,y0​). If mmm is the product of the focal distances of the point (x0,y0)(x_{0},y_{0})(x0​,y0​), then 4e2+m4e^{2}+m4e2+m is equal to ______.

Correct answer: 61

Step-by-step solution →
Q27·MathematicsSingle correctJEE Main 2024
Consider the hyperbola H having centre at the origin and foci on the x-axis. Let C1C_1C1​ be the circle touching the hyperbola H and having the centre at the origin. Let C2C_2C2​ be the circle touching the hyperbola H at its vertex and having the centre at one of its foci. If areas (in sq. units) of C1C_1C1​ and C2C_2C2​ are 36π36\pi36π and 4π4\pi4π, respectively, then the length (in units) of latus rectum of H is
  1. (A)283\tfrac{28}{3}328​
  2. (B)143\tfrac{14}{3}314​
  3. (C)103\tfrac{10}{3}310​
  4. (D)113\tfrac{11}{3}311​

Correct answer: (A)

Step-by-step solution →
Q28·MathematicsSingle correctJEE Main 2024
Let PPP be a point on the hyperbola H:x29−y24=1H:\dfrac{x^2}{9}-\dfrac{y^2}{4}=1H:9x2​−4y2​=1, in the first quadrant such that the area of triangle formed by PPP and the two foci of HHH is 2132\sqrt{13}213​. Then, the square of the distance of PPP from the origin is:
  1. (A)181818
  2. (B)262626
  3. (C)222222
  4. (D)202020

Correct answer: (C)

Step-by-step solution →
Q29·MathematicsNumericalJEE Main 2024
Let the latus rectum of the hyperbola x29−y2b2=1\dfrac{x^2}{9}-\dfrac{y^2}{b^2}=19x2​−b2y2​=1 subtend an angle of π3\dfrac\pi33π​ at the centre of the hyperbola. If b2b^2b2 is equal to lm(1+n)\dfrac{l}{m}(1+\sqrt n)ml​(1+n​), where lll and mmm are co-prime numbers, then l2+m2+n2l^2+m^2+n^2l2+m2+n2 is equal to ___

Correct answer: 182

Step-by-step solution →
Q30·MathematicsNumericalJEE Main 2023
Let m1m_{1}m1​ and m2m_{2}m2​ be the slopes of the tangents drawn from the point P(4,1)P(4,1)P(4,1) to the hyperbola H:y225−x216=1H:\dfrac{y^{2}}{25}-\dfrac{x^{2}}{16}=1H:25y2​−16x2​=1. If QQQ is the point from which the tangents drawn to HHH have slopes ∣m1∣|m_{1}|∣m1​∣ and ∣m2∣|m_{2}|∣m2​∣ and they make positive intercepts α\alphaα and β\betaβ on the xxx-axis, then (PQ)2αβ\dfrac{(PQ)^{2}}{\alpha\beta}αβ(PQ)2​ is equal to _____.

Correct answer: 8

Step-by-step solution →
Q31·MathematicsNumericalJEE Main 2023
The foci of a hyperbola are (±2,0)(\pm 2, 0)(±2,0) and its eccentricity is 32\dfrac{3}{2}23​. A tangent, perpendicular to the line 2x+3y=62x + 3y = 62x+3y=6, is drawn at a point in the first quadrant on the hyperbola. If the intercepts made by the tangent on the x- and y-axes are aaa and bbb respectively, then ∣6a∣+∣5b∣|6a| + |5b|∣6a∣+∣5b∣ is equal to

Correct answer: 12

Step-by-step solution →
Q32·MathematicsNumericalJEE Main 2023
Let the tangent to the parabola y2=12xy^2=12xy2=12x at the point (3,α)(3,\alpha)(3,α) be perpendicular to the line 2x+2y=32x+2y=32x+2y=3. Then the square of the distance of the point (6,−4)(6,-4)(6,−4) from the normal to the hyperbola α2x2−9y2=9α2\alpha^2 x^2-9y^2=9\alpha^2α2x2−9y2=9α2 at its point (α−1,α+2)(\alpha-1,\alpha+2)(α−1,α+2) is equal to

Correct answer: 116

Step-by-step solution →
Q33·MathematicsNumericalJEE Main 2023
Let Hn=x21+n−y23+n=1H_n = \frac{x^2}{1 + n} - \frac{y^2}{3 + n} = 1Hn​=1+nx2​−3+ny2​=1, n∈Nn \in \mathbb{N}n∈N. Let kkk be the smallest even value of nnn such that the eccentricity of HkH_kHk​ is a rational number. If lll is length of the latus rectum of HkH_kHk​, then 21l21l21l is equal to _______ .

Correct answer: 306

Step-by-step solution →
Q34·MathematicsSingle correctJEE Main 2023
Let P(x0,y0)P(x_0,y_0)P(x0​,y0​) be the point on the hyperbola 3x2−4y2=363x^2-4y^2=363x2−4y2=36, which is nearest to the line 3x+2y=13x+2y=13x+2y=1. Then 2(y0−x0)\sqrt2(y_0-x_0)2​(y0​−x0​) is equal to:
  1. (A)−9-9−9
  2. (B)−3-3−3
  3. (C)333
  4. (D)999

Correct answer: (A)

Step-by-step solution →
Q35·MathematicsSingle correctJEE Main 2023
Let H be the hyperbola, whose foci are (1±2,0)(1\pm\sqrt2,0)(1±2​,0) and eccentricity is 2\sqrt22​. Then the length of its latus rectum is
  1. (A)32\dfrac3223​
  2. (B)222
  3. (C)333
  4. (D)52\dfrac5225​

Correct answer: (B)

Step-by-step solution →
Q36·MathematicsNumericalJEE Main 2023
The vertices of a hyperbola HHH are (±6,0)(\pm 6,0)(±6,0) and its eccentricity is 52\dfrac{\sqrt{5}}{2}25​​. Let NNN be the normal to HHH at a point in the first quadrant and parallel to the line 2x+y=22\sqrt{2}x+y=2\sqrt{2}2​x+y=22​. If ddd is the length of the line segment of NNN between HHH and the yyy-axis, then d2d^2d2 is equal to _______.

Correct answer: 216

Step-by-step solution →
Q37·MathematicsSingle correctJEE Main 2023
Let TTT and CCC respectively be the transverse and conjugate axes of the hyperbola 16x2−y2+64x+4y+44=016x^2 - y^2 + 64x + 4y + 44 = 016x2−y2+64x+4y+44=0. Then the area of the region above the parabola x2=y+4x^2 = y + 4x2=y+4, below the transverse axis TTT and on the right of the conjugate axis CCC is:
  1. (A)46+2834\sqrt{6} + \dfrac{28}{3}46​+328​
  2. (B)46−4434\sqrt{6} - \dfrac{44}{3}46​−344​
  3. (C)46+4434\sqrt{6} + \dfrac{44}{3}46​+344​
  4. (D)46−2834\sqrt{6} - \dfrac{28}{3}46​−328​

Correct answer: (A)

Step-by-step solution →
Q38·MathematicsIntegerJEE Advanced 2022
Consider the hyperbola x2100−y264=1\frac{x^{2}}{100} - \frac{y^{2}}{64} = 1100x2​−64y2​=1 with foci at S and S1_{1}1​, where S lies on the positive x-axis. Let P be a point on the hyperbola, in the first quadrant. Let ∠SPS1=α\angle SPS_{1} = \alpha∠SPS1​=α, with α<π2\alpha < \frac{\pi}{2}α<2π​. The straight line passing through the point S and having the same slope as that of the tangent at P to the hyperbola, intersects the straight line S1_{1}1​P at P1_{1}1​. Let δ be the distance of P from the straight line SP1_{1}1​, and β = S1_{1}1​P. Then the greatest integer less than or equal to βδ9sin⁡α2\frac{\beta\delta}{9}\sin\frac{\alpha}{2}9βδ​sin2α​ is ________.

Correct answer: 7

Step-by-step solution →
Q39·MathematicsSingle correctJEE Main 2022
Let the hyperbola H:x2a2−y2b2=1H: \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1H:a2x2​−b2y2​=1 pass through the point (22,−22)\left(2\sqrt{2},-2\sqrt{2}\right)(22​,−22​). A parabola is drawn whose focus is same as the focus of H with positive abscissa and the directrix of the parabola passes through the other focus of H. If the length of the latus rectum of the parabola is e times the length of the latus rectum of H, where e is the eccentricity of H, then which of the following points lies on the parabola?
  1. (A)(23,32)\left(2\sqrt{3},3\sqrt{2}\right)(23​,32​)
  2. (B)(33,−62)\left(3\sqrt{3},-6\sqrt{2}\right)(33​,−62​)
  3. (C)(3,−6)\left(\sqrt{3},-\sqrt{6}\right)(3​,−6​)
  4. (D)(36,62)\left(3\sqrt{6},6\sqrt{2}\right)(36​,62​)

Correct answer: (B)

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Q40·MathematicsNumericalJEE Main 2022
A common tangent T to the curves C1:x24+y29=1C_{1} : \frac{x^{2}}{4} + \frac{y^{2}}{9} = 1C1​:4x2​+9y2​=1 and C2:x242−y2143=1C_{2} : \frac{x^{2}}{42} - \frac{y^{2}}{143} = 1C2​:42x2​−143y2​=1 does not pass through the fourth quadrant. If T touches C1C_{1}C1​ at (x1,y1)(x_{1}, y_{1})(x1​,y1​) and C2C_{2}C2​ at (x2,y2)(x_{2}, y_{2})(x2​,y2​), then ∣2x1+x2∣|2x_{1} + x_{2}|∣2x1​+x2​∣ is equal to ________.

Correct answer: 20

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Q41·MathematicsSingle correctJEE Main 2022
If the line x−1=0x-1 = 0x−1=0, is a directrix of the hyperbola kx2−y2=6kx^{2}-y^{2}=6kx2−y2=6, then the hyperbola passes through the point
  1. (A)(−25,6)\left(-2\sqrt{5},6\right)(−25​,6)
  2. (B)(−5,3)\left(-\sqrt{5},3\right)(−5​,3)
  3. (C)(5,−2)\left(\sqrt{5},-2\right)(5​,−2)
  4. (D)(25,36)\left(2\sqrt{5},3\sqrt{6}\right)(25​,36​)

Correct answer: (C)

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Q42·MathematicsSingle correctJEE Main 2022
Let the tangent drawn to the parabola y2=24xy^{2} = 24xy2=24x at the point (α,β)(\alpha, \beta)(α,β) is perpendicular to the line 2x +2y = 5. Then the normal to the hyperbola x2α2−y2β2=1\dfrac{x^{2}}{\alpha^{2}} - \dfrac{y^{2}}{\beta^{2}} = 1α2x2​−β2y2​=1 at the point (α+4,β+4)(\alpha+4,\beta+4)(α+4,β+4) does NOT pass through the point :
  1. (A)(25, 10)
  2. (B)(20, 12)
  3. (C)(30, 8)
  4. (D)(15, 13)

Correct answer: (D)

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Q43·MathematicsNumericalJEE Main 2022
Let the equation of two diameters of a circle x2+y2−2x+2fy+1=0x^{2} + y^{2} - 2x + 2fy + 1 = 0x2+y2−2x+2fy+1=0 be 2px−y=12px - y = 12px−y=1 and 2x+py=4p2x + py = 4p2x+py=4p. Then the slope m∈(0,∞)m \in (0, \infty)m∈(0,∞) of the tangent to the hyperbola 3x2−y2=33x^{2} - y^{2} = 33x2−y2=3 passing through the centre of the circle is equal to ________.

Correct answer: 2

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Q44·MathematicsNumericalJEE Main 2022
Let H:x2a2−y2b2=1H : \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1H:a2x2​−b2y2​=1, a > 0, b > 0, be a hyperbola such that the sum of lengths of the transverse and the conjugate axes is 4(22+14)4\left(2\sqrt{2} + \sqrt{14}\right)4(22​+14​). If the eccentricity H is 112\frac{\sqrt{11}}{2}211​​, then value of a2+b2a^2 + b^2a2+b2 is equal to __________.

Correct answer: 88

Step-by-step solution →
Q45·MathematicsSingle correctJEE Main 2022
Let the eccentricity of the hyperbola H:x2a2−y2b2=1\mathrm{H}:\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1H:a2x2​−b2y2​=1 be 52\sqrt{\frac{5}{2}}25​​ and length of its latus rectum be 62,6\sqrt{2},62​, If y=2x+cy = 2x + cy=2x+c is a tangent to the hyperbola H, then the value of c2c^{2}c2 is equal to
  1. (A)18
  2. (B)20
  3. (C)24
  4. (D)32

Correct answer: (B)

Step-by-step solution →
Q46·MathematicsSingle correctJEE Main 2022
Let a>0a > 0a>0, b>0b > 0b>0. Let e and ℓ\ellℓ respectively be the eccentricity and length of the latus rectum of the hyperbola x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1. Let e′e'e′ and ℓ′\ell'ℓ′ respectively the eccentricity and length of the latus rectum of its conjugate hyperbola. If e2=1114ℓe^{2} = \frac{11}{14}\elle2=1411​ℓ and (e′)2=118ℓ′\left(e'\right)^{2} = \frac{11}{8}\ell'(e′)2=811​ℓ′, then the value of 77a+44b77a + 44b77a+44b is equal to
  1. (A)100
  2. (B)110
  3. (C)120
  4. (D)130

Correct answer: (D)

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Q47·MathematicsNumericalJEE Main 2022
Let a line L1L_{1}L1​ be tangent to the hyperbola x216−y24=1\frac{x^{2}}{16}-\frac{y^{2}}{4}=116x2​−4y2​=1 and let L2L_{2}L2​ be the line passing through the origin and perpendicular to L1L_{1}L1​. If the locus of the point of intersection of L1L_{1}L1​ and L2L_{2}L2​ is (x2+y2)2=αx2+βy2(x^{2}+y^{2})^{2}=\alpha x^{2}+\beta y^{2}(x2+y2)2=αx2+βy2, then α+β\alpha+\betaα+β is equal to ______ .

Correct answer: 12

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Q48·MathematicsSingle correctJEE Main 2022
The normal to the hyperbola x2a2−y29=1\frac{x^2}{a^2}-\frac{y^2}{9}=1a2x2​−9y2​=1 at the point (8,33)\left(8,3\sqrt{3}\right)(8,33​) on it passes through the point :
  1. (A)(15,−23)\left(15,-2\sqrt{3}\right)(15,−23​)
  2. (B)(9,23)\left(9,2\sqrt{3}\right)(9,23​)
  3. (C)(−1,93)\left(-1,9\sqrt{3}\right)(−1,93​)
  4. (D)(−1,63)\left(-1,6\sqrt{3}\right)(−1,63​)

Correct answer: (C)

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Q49·MathematicsNumericalJEE Main 2022
Let the eccentricity of the hyperbola x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1 be 54\frac{5}{4}45​. If the equation of the normal at the point (85,125)\left(\frac{8}{\sqrt{5}}, \frac{12}{5}\right)(5​8​,512​) on the hyperbola is 85x+βy=λ8\sqrt{5}x + \beta y = \lambda85​x+βy=λ, then λ−β\lambda - \betaλ−β is equal to

Correct answer: 85

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Q50·MathematicsNumericalJEE Main 2022
Let the hyperbola H:x2a2−y2=1H : \dfrac{x^{2}}{a^{2}} - y^{2} = 1H:a2x2​−y2=1 and the ellipse E:3x2+4y2=12E : 3x^{2} + 4y^{2} = 12E:3x2+4y2=12 be such that the length of latus rectum of H is equal to the length of latus rectum of E. If eHe_{H}eH​ and eEe_{E}eE​ are the eccentricities of H and E respectively, then the value of 12(eH2+eE2)12\left(e_{H}^{2} + e_{E}^{2}\right)12(eH2​+eE2​) is equal to ______.

Correct answer: 42

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Q51·MathematicsSingle correctJEE Main 2022
Let λx−2y=μ\lambda x-2y=\muλx−2y=μ be a tangent to the hyperbola a2x2−y2=b2a^{2}x^{2}-y^{2}=b^{2}a2x2−y2=b2. Then (λa)2−(μb)2\left(\dfrac{\lambda}{a}\right)^{2}-\left(\dfrac{\mu}{b}\right)^{2}(aλ​)2−(bμ​)2 is equal to:
  1. (A)−2-2−2
  2. (B)−4-4−4
  3. (C)2
  4. (D)4

Correct answer: (D)

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Q52·MathematicsNumericalJEE Advanced 2021
Consider the lines L1L_1L1​ and L2L_2L2​ defined by L1:x2+y−1=0L_1 : x\sqrt{2} + y - 1 = 0L1​:x2​+y−1=0 and L2:x2−y+1=0L_2 : x\sqrt{2} - y + 1 = 0L2​:x2​−y+1=0 For a fixed constant λ\lambdaλ, let C be the locus of a point P such that the product of the distance of P from L1L_1L1​ and the distance of P from L2L_2L2​ is λ2\lambda^2λ2. The line y=2x+1y = 2x + 1y=2x+1 meets C at two points R and S, where the distance between R and S is 270\sqrt{270}270​. Let the perpendicular bisector of RS meet C at two distinct points R' and S'. Let D be the square of the distance between R' and S'. The value of λ2\lambda^2λ2 is ________.

Correct answer: 9.00

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Q53·MathematicsNumericalJEE Advanced 2021
Consider the lines L1L_1L1​ and L2L_2L2​ defined by L1:x2+y−1=0L_1 : x\sqrt{2} + y - 1 = 0L1​:x2​+y−1=0 and L2:x2−y+1=0L_2 : x\sqrt{2} - y + 1 = 0L2​:x2​−y+1=0 For a fixed constant λ\lambdaλ, let C be the locus of a point P such that the product of the distance of P from L1L_1L1​ and the distance of P from L2L_2L2​ is λ2\lambda^2λ2. The line y=2x+1y = 2x + 1y=2x+1 meets C at two points R and S, where the distance between R and S is 270\sqrt{270}270​. Let the perpendicular bisector of RS meet C at two distinct points R' and S'. Let D be the square of the distance between R' and S'. The value of D is ________.

Correct answer: 77.14

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Q54·MathematicsSingle correctJEE Main 2021
The point P(−26,3)P\left(-2\sqrt{6}, \sqrt{3}\right)P(−26​,3​) lies on the hyperbola x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1 having eccentricity 52\frac{\sqrt{5}}{2}25​​. If the tangent and normal at P to the hyperbola intersect its conjugate axis at the point Q and R respectively, then QR is equal to :
  1. (A)434\sqrt{3}43​
  2. (B)666
  3. (C)636\sqrt{3}63​
  4. (D)363\sqrt{6}36​

Correct answer: (C)

Step-by-step solution →
Q55·MathematicsSingle correctJEE Main 2021
The locus of the mid points of the chords of the hyperbola x2−y2=4x^{2} - y^{2} = 4x2−y2=4, which touch the parabola y2=8xy^{2} = 8xy2=8x, is :
  1. (A)y3(x−2)=x2y^{3}(x - 2) = x^{2}y3(x−2)=x2
  2. (B)x3(x−2)=y2x^{3}(x - 2) = y^{2}x3(x−2)=y2
  3. (C)y2(x−2)=x3y^{2}(x - 2) = x^{3}y2(x−2)=x3
  4. (D)x2(x−2)=y3x^{2}(x - 2) = y^{3}x2(x−2)=y3

Correct answer: (C)

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Q56·MathematicsSingle correctJEE Main 2021
The locus of the centroid of the triangle formed by any point P on this hyperbola 16x2−9y2+32x+36y−164=016x^{2}-9y^{2}+32x+36y-164=016x2−9y2+32x+36y−164=0, and its foci is :
  1. (A)16x2−9y2+32x+36y−144=016x^{2}-9y^{2}+32x+36y-144=016x2−9y2+32x+36y−144=0
  2. (B)16x2−9y2+32x+36y−36=016x^{2}-9y^{2}+32x+36y-36=016x2−9y2+32x+36y−36=0
  3. (C)9x2−16y2+36x+32y−144=09x^{2}-16y^{2}+36x+32y-144=09x2−16y2+36x+32y−144=0
  4. (D)9x2−16y2+36x+32y−36=09x^{2}-16y^{2}+36x+32y-36=09x2−16y2+36x+32y−36=0

Correct answer: (B)

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Q57·MathematicsSingle correctJEE Main 2021
Let a line L : 2x+y=k2x + y = k2x+y=k, k>0k > 0k>0 be a tangent to the hyperbola x2−y2=3x^2 - y^2 = 3x2−y2=3. If L is also a tangent to the parabola y2=αxy^2 = \alpha xy2=αx, then α\alphaα is equal to :
  1. (A)242424
  2. (B)−24-24−24
  3. (C)−12-12−12
  4. (D)121212

Correct answer: (B)

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Q58·MathematicsNumericalJEE Main 2021
A square ABCD has all its vertices on the curve x2y2=1x^{2}y^{2} = 1x2y2=1. The midpoints of its sides also lie on the same curve. Then, the square of area of ABCD is

Correct answer: 80

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Q59·MathematicsSingle correctJEE Main 2021
Consider a hyperbola H : x2−2y2=4x^{2} - 2y^{2} = 4x2−2y2=4. Let the tangent at a point P(4,6)P\left(4, \sqrt{6}\right)P(4,6​) meet the x-axis at Q and latus rectum at R(x1,y1)R(x_{1}, y_{1})R(x1​,y1​), x1>0x_{1} > 0x1​>0. If F is a focus of H which is nearer to the point P, then the area of ΔQFR is equal to
  1. (A)464\sqrt{6}46​
  2. (B)6−1\sqrt{6}-16​−1
  3. (C)76−2\frac{7}{\sqrt{6}}-26​7​−2
  4. (D)46−14\sqrt{6}-146​−1

Correct answer: (C)

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Q60·MathematicsSingle correctJEE Main 2021
The locus of the midpoints of the chord of the circle, x2+y2=25x^{2} + y^{2} = 25x2+y2=25 which is tangent to the hyperbola, x29−y216=1\frac{x^{2}}{9} - \frac{y^{2}}{16} = 19x2​−16y2​=1 is :
  1. (A)(x2+y2)2−16x2+9y2=0(x^{2} + y^{2})^{2} - 16x^{2} + 9y^{2} = 0(x2+y2)2−16x2+9y2=0
  2. (B)(x2+y2)2−9x2+144y2=0(x^{2} + y^{2})^{2} - 9x^{2} + 144y^{2} = 0(x2+y2)2−9x2+144y2=0
  3. (C)(x2+y2)2−9x2−16y2=0(x^{2} + y^{2})^{2} - 9x^{2} - 16y^{2} = 0(x2+y2)2−9x2−16y2=0
  4. (D)(x2+y2)2−9x2+16y2=0(x^{2} + y^{2})^{2} - 9x^{2} + 16y^{2} = 0(x2+y2)2−9x2+16y2=0

Correct answer: (D)

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Q61·MathematicsSingle correctJEE Main 2021
A hyperbola passes through the foci of the ellipse x2^{2}2+y2^{2}2=1 and its transverse and conjugate 2516 axes coincide with major and minor axes of the ellipse, respectively. If the product of their eccentricities is one, then the equation of the hyperbola is:
  1. (A)x2^{2}2–y2^{2}2=1 94
  2. (B)x2^{2}2–y2^{2}2=1 916
  3. (C)x2^{2}2 – y2^{2}2 = 9
  4. (D)x2^{2}2–y2^{2}2=1 925

Correct answer: (B)

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Q62·MathematicsNumericalJEE Main 2021
The locus of the point of intersection of the lines (3)kx+ky−43=0(\sqrt{3})kx + ky - 4\sqrt{3} = 0(3​)kx+ky−43​=0 and 3x−y−4(3)k=0\sqrt{3}x - y - 4(\sqrt{3})k = 03​x−y−4(3​)k=0 is a conic, whose eccentricity is __________.

Correct answer: 2

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Q63·MathematicsMultiple correctJEE Advanced 2020
Let aaa and bbb be positive real numbers such that a>1a > 1a>1 and b<ab < ab<a. Let PPP be a point in the first quadrant that lies on the hyperbola x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1. Suppose the tangent to the hyperbola at PPP passes through the point (1,0)(1,0)(1,0), and suppose the normal to the hyperbola at PPP cuts off equal intercepts on the coordinate axes. Let Δ\DeltaΔ denote the area of the triangle formed by the tangent at PPP, the normal at PPP and the xxx-axis. If eee denotes the eccentricity of the hyperbola, then which of the following statements is/are TRUE?
  1. (A)1<e<21 < e < \sqrt{2}1<e<2​
  2. (B)2<e<2\sqrt{2} < e < 22​<e<2
  3. (C)Δ=a4\Delta = a^{4}Δ=a4
  4. (D)Δ=b4\Delta = b^{4}Δ=b4

Correct answer: (A), (D)

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Q64·MathematicsSingle correctJEE Main 2020
If the line y = mx + c is a common tangent to the hyperbola x2100−y264=1\dfrac{x^2}{100} - \dfrac{y^2}{64} = 1100x2​−64y2​=1 and the circle x2+y2=36x^2 + y^2 = 36x2+y2=36, then which one of the following is true?
  1. (A)4c2=3694c^2 = 3694c2=369
  2. (B)c2=369c^2 = 369c2=369
  3. (C)5m=45m = 45m=4
  4. (D)8m+5=08m + 5 = 08m+5=0

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correctJEE Main 2020
Let P (3, 3) be a point on the hyperbola, x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1. If the normal to it at P intersects the x-axis at (9, 0) and e is its eccentricity, then the ordered pair (a2,e2)(a^{2}, e^{2})(a2,e2) is equal to:
  1. (A)(32, 2)\left( \frac{3}{2},\, 2 \right)(23​,2)
  2. (B)(92, 2)\left( \frac{9}{2},\, 2 \right)(29​,2)
  3. (C)(9, 3)(9,\, 3)(9,3)
  4. (D)(92, 3)\left( \frac{9}{2},\, 3 \right)(29​,3)

Correct answer: (D)

Step-by-step solution →
Q66·MathematicsSingle correctJEE Main 2020
A hyperbola having the transverse axis of length 2\sqrt{2}2​ has the same foci as that of the ellipse 3x2+4y2=123x^{2}+4y^{2}=123x2+4y2=12, then this hyperbola does not pass through which of the following points?
  1. (A)(1,−12)\left(1,-\frac{1}{\sqrt{2}}\right)(1,−2​1​)
  2. (B)(32,12)\left(\sqrt{\frac{3}{2}},\frac{1}{\sqrt{2}}\right)(23​​,2​1​)
  3. (C)(−32,1)\left(-\sqrt{\frac{3}{2}},1\right)(−23​​,1)
  4. (D)(12,0)\left(\frac{1}{\sqrt{2}},0\right)(2​1​,0)

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correctJEE Main 2020
If a hyperbola passes through the point P (10, 16) and it has vertices at (±6,0)(\pm 6, 0)(±6,0) then the equation of the normal to it at P is:
  1. (A)2x+5y=1002x+5y=1002x+5y=100
  2. (B)x+3y=58x+3y=58x+3y=58
  3. (C)3x+4y=943x+4y=943x+4y=94
  4. (D)x+2y=42x+2y=42x+2y=42

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correctJEE Main 2019
Let P be the point of intersection of the common tangents to the parabola y2=12xy^{2}=12xy2=12x and the hyperbola 8x2−y2=88x^{2}-y^{2}=88x2−y2=8. If S and S' denote the foci of the hyperbola where S lies on the positive x-axis then P divides SS' in a ratio:
  1. (A)2:1
  2. (B)13:11
  3. (C)5:4
  4. (D)14:13

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correctJEE Main 2019
If a directrix of a hyperbola centered at the origin and passing through the point (4,−23)(4,-2\sqrt{3})(4,−23​) is 5x=455x=4\sqrt{5}5x=45​ and its eccentricity is e, then
  1. (A)4e4+8e2−35=04e^{4}+8e^{2}-35=04e4+8e2−35=0
  2. (B)4e4−24e2+35=04e^{4}-24e^{2}+35=04e4−24e2+35=0
  3. (C)4e4−12e2−27=04e^{4}-12e^{2}-27=04e4−12e2−27=0
  4. (D)4e4−24e2+27=04e^{4}-24e^{2}+27=04e4−24e2+27=0

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correctJEE Main 2019
If 5x + 9 = 0 is the directrix of the hyperbola 16x2−9y2=14416x^{2} - 9y^{2} = 14416x2−9y2=144, then its corresponding focus is
  1. (A)(5, 0)
  2. (B)(53,0)\left(\dfrac{5}{3}, 0\right)(35​,0)
  3. (C)(-5, 0)
  4. (D)(−53,0)\left(-\dfrac{5}{3}, 0\right)(−35​,0)

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correctJEE Main 2019
If the line y=mx+73y=mx+7\sqrt{3}y=mx+73​ is normal to the hyperbola x224−y218=1\dfrac{x^{2}}{24}-\dfrac{y^{2}}{18}=124x2​−18y2​=1, then a value of m is:
  1. (A)25\dfrac{2}{\sqrt{5}}5​2​
  2. (B)52\dfrac{\sqrt{5}}{2}25​​
  3. (C)152\dfrac{\sqrt{15}}{2}215​​
  4. (D)35\dfrac{3}{\sqrt{5}}5​3​

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correctJEE Main 2019
If the eccentricity of the standard hyperbola passing, through the point (4, 6) is 2, then the equation of the tangent to the hyperbola at (4, 6) is:
  1. (A)2x−3y+10=02x-3y+10=02x−3y+10=0
  2. (B)x−2y+8=0x-2y+8=0x−2y+8=0
  3. (C)2x−y−2=02x-y-2=02x−y−2=0
  4. (D)3x−2y=03x-2y=03x−2y=0

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correctJEE Main 2019
If the vertices of a hyperbola be at (−2,0)(-2, 0)(−2,0) and (2,0)(2, 0)(2,0) and one of its foci be at (−3,0)(-3, 0)(−3,0), then which one of the following points does not lie on this hyperbola?
  1. (A)(−6,210)\left(-6,2\sqrt{10}\right)(−6,210​)
  2. (B)(26,5)\left(2\sqrt{6},5\right)(26​,5)
  3. (C)(4,15)\left(4,\sqrt{15}\right)(4,15​)
  4. (D)(6,52)\left(6,5\sqrt{2}\right)(6,52​)

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correctJEE Main 2019
If a hyperbola has length of its conjugate axis equal to 5 and the distance between its foci is 13, then the eccentricity of the hyperbola is:
  1. (A)1312\dfrac{13}{12}1213​
  2. (B)2
  3. (C)136\dfrac{13}{6}613​
  4. (D)138\dfrac{13}{8}813​

Correct answer: (A)

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Q75·MathematicsSingle correctJEE Main 2019
The equation of a tangent to the hyperbola 4x2−5y2=204x^2 - 5y^2 = 204x2−5y2=20 parallel to the line x−y=2x - y = 2x−y=2 is:
  1. (A)x − y + 1 = 0
  2. (B)x − y + 7 = 0
  3. (C)x − y + 9 = 0
  4. (D)x − y − 3 = 0

Correct answer: (A)

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Q76·MathematicsSingle correctJEE Main 2019
Let 0<θ<π20 < \theta < \dfrac{\pi}{2}0<θ<2π​. If the eccentricity of the hyperbola x2cos⁡2θ−y2sin⁡2θ=1\dfrac{x^2}{\cos^2\theta} - \dfrac{y^2}{\sin^2\theta} = 1cos2θx2​−sin2θy2​=1 is greater than 2, then the length of its latus rectum lies in the interval:
  1. (A)(3,∞)(3, \infty)(3,∞)
  2. (B)(32,2]\left(\dfrac{3}{2}, 2\right](23​,2]
  3. (C)(2,3](2, 3](2,3]
  4. (D)(1,32]\left(1, \dfrac{3}{2}\right](1,23​]

Correct answer: (A)

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Q77·MathematicsSingle correctJEE Main 2019
A hyperbola has its centre at the origin, passes through the point (4, 2) and has transverse axis of length 4 along the x - axis. Then the eccentricity of the hyperbola is:
  1. (A)23\dfrac{2}{\sqrt{3}}3​2​
  2. (B)32\dfrac{3}{2}23​
  3. (C)3\sqrt{3}3​
  4. (D)2

Correct answer: (A)

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Q78·MathematicsSingle correctJEE Advanced 2018
Let H : x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1, where a>b>0a > b > 0a>b>0, be a hyperbola in the xy-plane whose conjugate axis LM subtends an angle of 60∘60^{\circ}60∘ at one of its vertices N. Let the area of the triangle LMN be 434\sqrt{3}43​. The correct option is :
LIST-ILIST-II
P.The length of the conjugate axis of H is1.8
Q.The eccentricity of H is2.43\frac{4}{\sqrt{3}}3​4​
R.The distance between the foci of H is3.23\frac{2}{\sqrt{3}}3​2​
S.The length of the latus rectum of H is4.4
  1. (A)P →\to→ 4; Q →\to→ 2; R →\to→ 1; S →\to→ 3
  2. (B)P →\to→ 4; Q →\to→ 3; R →\to→ 1; S →\to→ 2
  3. (C)P →\to→ 4; Q →\to→ 1; R →\to→ 3; S →\to→ 2
  4. (D)P →\to→ 3; Q →\to→ 4; R →\to→ 2; S →\to→ 1

Correct answer: (B)

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Q79·MathematicsMultiple correctJEE Advanced 2017
If 2x−y+1=02x - y + 1 = 02x−y+1=0 is a tangent to the hyperbola x2a2−y216=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{16} = 1a2x2​−16y2​=1, then which of the following CANNOT be sides of a right angled triangle ?
  1. (A)2a2a2a, 444, 111
  2. (B)2a2a2a, 888, 111
  3. (C)aaa, 444, 111
  4. (D)aaa, 444, 222

Correct answer: (B), (C), (D)

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Q80·MathematicsMultiple correctJEE Advanced 2015
Consider the hyperbola H:x2−y2=1H : x^{2} - y^{2} = 1H:x2−y2=1 and a circle S with center N(x2,0)N(x_{2}, 0)N(x2​,0). Suppose that H and S touch each other at a point P(x1,y1)P(x_{1}, y_{1})P(x1​,y1​) with x1>1x_{1} > 1x1​>1 and y1>0y_{1} > 0y1​>0. The common tangent to H and S at P intersects the x-axis at point M. If (l,m)(l, m)(l,m) is the centroid of the triangle ΔPMN\Delta PMNΔPMN, then the correct expression(s) is(are)
  1. (A)dldx1=1−13x12\dfrac{dl}{dx_{1}} = 1 - \dfrac{1}{3x_{1}^{2}}dx1​dl​=1−3x12​1​ for x1>1x_{1} > 1x1​>1
  2. (B)dmdx1=x13(x12−1)\dfrac{dm}{dx_{1}} = \dfrac{x_{1}}{3\left(\sqrt{x_{1}^{2} - 1}\right)}dx1​dm​=3(x12​−1​)x1​​ for x1>1x_{1} > 1x1​>1
  3. (C)dldx1=1+13x12\dfrac{dl}{dx_{1}} = 1 + \dfrac{1}{3x_{1}^{2}}dx1​dl​=1+3x12​1​ for x1>1x_{1} > 1x1​>1
  4. (D)dmdy1=13\dfrac{dm}{dy_{1}} = \dfrac{1}{3}dy1​dm​=31​ for y1>0y_{1} > 0y1​>0

Correct answer: (A), (B), (D)

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Hyperbola — frequently asked

How many questions from Hyperbola appear in JEE?

Hyperbola has appeared in 77 of the last 186 JEE Main and JEE Advanced papers — about 41% of them — contributing 80 questions in total across those papers.

Is Hyperbola an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 41% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Hyperbola questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Mathematics chapters

  • Three Dimensional Geometry 344
  • Matrices and Determinants 342
  • Sets, Relations and Functions 313
  • Sequence and Series 287
  • Definite Integration 267
  • Vector Algebra 245
  • Differential Equations 240
  • Probability 226

All 26 Mathematics chapters →

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