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Quadratic Equations — JEE Previous Year Questions

Every Quadratic Equations question asked in JEE Main and JEE Advanced across the last 186 papers — 170 questions, each with its correct answer. Free to read, no account needed.

Questions

170

Papers it appeared in

148/186

Appearance rate

80%

All 170 Quadratic Equations questions

Most recent papers first.

Q1·MathematicsSingle correctJEE Advanced 2026
Match each entry in List-I to the correct entry in List-II and choose the correct option.
List-IList-II
P.If α\alphaα and β\betaβ are the distinct roots of the equation x2+x+1=0x^2 + x + 1 = 0x2+x+1=0, then the quadratic equation with roots 1(α+1)2026\frac{1}{(\alpha + 1)^{2026}}(α+1)20261​ and 1(β+1)2026\frac{1}{(\beta + 1)^{2026}}(β+1)20261​ is1.x2+x+1=0x^2 + x + 1 = 0x2+x+1=0
Q.If α\alphaα and β\betaβ are the distinct roots of the equation x2+x+1=0x^2 + x + 1 = 0x2+x+1=0, then the quadratic equation with roots 1(α+1)2027\frac{1}{(\alpha + 1)^{2027}}(α+1)20271​ and 1(β+1)2027\frac{1}{(\beta + 1)^{2027}}(β+1)20271​ is2.x2−x+1=0x^2 - x + 1 = 0x2−x+1=0
R.If γ\gammaγ and δ\deltaδ are the distinct roots of the equation x2−x+1=0x^2 - x + 1 = 0x2−x+1=0, then the value of 1(γ−1)2026+1(δ−1)2026\frac{1}{(\gamma - 1)^{2026}} + \frac{1}{(\delta - 1)^{2026}}(γ−1)20261​+(δ−1)20261​ is3.x2+x−1=0x^2 + x - 1 = 0x2+x−1=0
S.If ppp and rrr are the distinct roots of the equation x2+x−1=0x^2 + x - 1 = 0x2+x−1=0, then the value of 1(p+1)3+1(r+1)3\frac{1}{(p + 1)^3} + \frac{1}{(r + 1)^3}(p+1)31​+(r+1)31​ is4.−1-1−1
5.−4-4−4
  1. (A)(P) → (1), (Q) → (2), (R) → (5), (S) → (4)
  2. (B)(P) → (3), (Q) → (1), (R) → (4), (S) → (5)
  3. (C)(P) → (1), (Q) → (2), (R) → (4), (S) → (5)
  4. (D)(P) → (2), (Q) → (3), (R) → (5), (S) → (4)

Correct answer: (C)

Step-by-step solution →
Q2·MathematicsMultiple correctJEE Advanced 2026
Let a,b,ca, b, ca,b,c be positive integers in arithmetic progression such that the equation ax2+bx+c=0ax^{2} + bx + c = 0ax2+bx+c=0 has only integer solutions. Then which of the following statements is (are) TRUE ?
  1. (A)c−bc - bc−b is an integer multiple of aaa
  2. (B)Both the roots of the equation ax2+bx+c=0ax^{2} + bx + c = 0ax2+bx+c=0 are odd integers
  3. (C)If c=15c = 15c=15, then ab=8ab = 8ab=8
  4. (D)If b=8b = 8b=8, then x=3x = 3x=3 is a root of the equation ax2+bx+c=0ax^{2} + bx + c = 0ax2+bx+c=0

Correct answer: (A), (B), (C)

Step-by-step solution →
Q3·MathematicsNumericalJEE Main 2026
The sum of squares of all the real solutions of the equation log⁡(x+1)(2x2+5x+3)=4−log⁡(2x+3)(x2+2x+1)\log_{(x+1)}(2x^2 + 5x + 3) = 4 - \log_{(2x+3)}(x^2 + 2x + 1)log(x+1)​(2x2+5x+3)=4−log(2x+3)​(x2+2x+1) is equal to ________.

Correct answer: 2

Step-by-step solution →
Q4·MathematicsSingle correctJEE Main 2026
Let e1_11​ and e2_22​ be two distinct roots of the equation x2^22 − ax + 2 = 0. Let the sets {a ∈ ℝ : e1_11​ and e2_22​ are the eccentricities of hyperbolas} = (α, β), and {a ∈ ℝ : e1_11​ and e2_22​ are the eccentricities of an ellipse and a hyperbola, respectively} = (γ, ∞). Then α2^22 + β2^22 + γ2^22 is equal to:
  1. (A)18
  2. (B)22
  3. (C)26
  4. (D)34

Correct answer: (C)

Step-by-step solution →
Q5·MathematicsSingle correctJEE Main 2026
Let one root of the quadratic equation in x: (k2^22 − 15k + 27)x2^22 + 9(k − 1)x + 18 = 0 be twice the other. Then the length of the latus rectum of the parabola y2^22 = 6kx is equal to:
  1. (A)4
  2. (B)6
  3. (C)8
  4. (D)12

Correct answer: (D)

Step-by-step solution →
Q6·MathematicsSingle correctJEE Main 2026
Let lim⁡x→2(tan⁡(x−2))(rx2+(p−2)x−2p)(x−2)2=5\lim_{x \to 2} \frac{(\tan(x-2))(rx^{2} + (p-2)x - 2p)}{(x-2)^{2}} = 5limx→2​(x−2)2(tan(x−2))(rx2+(p−2)x−2p)​=5 for some r,p∈Rr, p \in \mathbb{R}r,p∈R. If the set of all possible values of qqq, such that the roots of the equation rx2−px+q=0rx^{2} - px + q = 0rx2−px+q=0 lie in (0,2)(0, 2)(0,2), be the interval (α,β](\alpha, \beta](α,β], then 4(α+β)4(\alpha + \beta)4(α+β) equals :
  1. (A)11
  2. (B)13
  3. (C)17
  4. (D)21

Correct answer: (C)

Step-by-step solution →
Q7·MathematicsSingle correctJEE Main 2026
Let α, β be the roots of the equation x2−x+p=0x^2 - x + p = 0x2−x+p=0 and γ, δ be the roots the equation x2−4x+q=0x^2 - 4x + q = 0x2−4x+q=0; p, q ∈ Z. If α, β, γ, δ are in G.P., then ∣p+q∣|p + q|∣p+q∣ equals :
  1. (A)16
  2. (B)32
  3. (C)34
  4. (D)38

Correct answer: (C)

Step-by-step solution →
Q8·MathematicsSingle correctJEE Main 2026
Let a,b∈Ca, b \in \mathbb{C}a,b∈C. Let α,β\alpha, \betaα,β be the roots of the equation x2+ax+b=0x^2 + ax + b = 0x2+ax+b=0. If β−α=11\beta - \alpha = \sqrt{11}β−α=11​ and β2−α2=3i11\beta^2 - \alpha^2 = 3i\sqrt{11}β2−α2=3i11​, then (β3−α3)2(\beta^3 - \alpha^3)^2(β3−α3)2 is equal to:
  1. (A)160
  2. (B)176
  3. (C)194
  4. (D)187

Correct answer: (B)

Step-by-step solution →
Q9·MathematicsSingle correctJEE Main 2026
If the quadratic equation (λ+2)x2−3λx+4λ=0(\lambda + 2)x^{2} - 3\lambda x + 4\lambda = 0(λ+2)x2−3λx+4λ=0, λ≠−2\lambda \neq -2λ=−2, has two positive roots, then the number of possible integral values of λ\lambdaλ is:
  1. (A)1
  2. (B)2
  3. (C)3
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q10·MathematicsSingle correctJEE Main 2026
If the set of all solutions of ∣x2+x−9∣=∣x∣+∣x2−9∣|x^2 + x - 9| = |x| + |x^2 - 9|∣x2+x−9∣=∣x∣+∣x2−9∣ is [α,β]∪[γ,∞)[\alpha, \beta] \cup [\gamma, \infty)[α,β]∪[γ,∞), then (α2+β2+γ2)(\alpha^2 + \beta^2 + \gamma^2)(α2+β2+γ2) is equal to:
  1. (A)999
  2. (B)181818
  3. (C)363636
  4. (D)727272

Correct answer: (B)

Step-by-step solution →
Q11·MathematicsSingle correctJEE Main 2026
Let α,β\alpha, \betaα,β be the roots of the equation x2−3x+r=0x^2 - 3x + r = 0x2−3x+r=0, and α2,2β\frac{\alpha}{2}, 2\beta2α​,2β be the roots of the equation x2+3x+r=0x^2 + 3x + r = 0x2+3x+r=0. If the roots of the equation x2+6x=mx^2 + 6x = mx2+6x=m are 2α+β+2r2\alpha + \beta + 2r2α+β+2r and α−2β−r2\alpha - 2\beta - \frac{r}{2}α−2β−2r​, then mmm is equal to:
  1. (A)−135-135−135
  2. (B)−567-567−567
  3. (C)135135135
  4. (D)567567567

Correct answer: (D)

Step-by-step solution →
Q12·MathematicsSingle correctJEE Main 2026
Let α, α + 2, α ∈ ℤ, be the roots of the quadratic equation x(x+2)+(x+1)(x+3)+(x+2)(x+4)+…+(x+n−1)(x+n+1)=4nx(x+2)+(x+1)(x+3)+(x+2)(x+4)+\ldots+(x+n-1)(x+n+1)=4nx(x+2)+(x+1)(x+3)+(x+2)(x+4)+…+(x+n−1)(x+n+1)=4n for some n ∈ ℕ. Then n + α is equal to :
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q13·MathematicsSingle correctJEE Main 2026
Let S={x3+ax2+bx+c:a,b,c∈NS = \{x^3 + ax^2 + bx + c : a, b, c \in NS={x3+ax2+bx+c:a,b,c∈N and a,b,c≤20}a, b, c \le 20\}a,b,c≤20} be a set of polynomials. Then the number of polynomials in S, which are divisible by x2+2x^2 + 2x2+2, is
  1. (A)20
  2. (B)6
  3. (C)120
  4. (D)10

Correct answer: (D)

Step-by-step solution →
Q14·MathematicsSingle correctJEE Main 2026
If α\alphaα, β\betaβ, where α<β\alpha < \betaα<β, are the roots of the equation λx2−(λ+3)x+3=0\lambda x^2 - (\lambda + 3)x + 3 = 0λx2−(λ+3)x+3=0 such that 1α−1β=13\dfrac{1}{\alpha} - \dfrac{1}{\beta} = \dfrac{1}{3}α1​−β1​=31​, then the sum of all possible values of λ\lambdaλ is :
  1. (A)6
  2. (B)2
  3. (C)4
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q15·MathematicsSingle correctJEE Main 2026
Let the arithmetic mean of 1a\dfrac{1}{a}a1​ and 1b\dfrac{1}{b}b1​ be 516\dfrac{5}{16}165​, a > 2. If α is such that a, 4, α, b are in A.P., then the equation αx2−ax+2(α−2b)=0\alpha x^{2} - ax + 2(\alpha - 2b) = 0αx2−ax+2(α−2b)=0 has :
  1. (A)One root in (1,4) and another in (–2,0)
  2. (B)One root in (0,2) and another in (– 4, –2)
  3. (C)Complex roots of magnitude less than 2
  4. (D)Both roots in the interval (–2, 0)

Correct answer: (A)

Step-by-step solution →
Q16·MathematicsSingle correctJEE Main 2026
The number of the real solutions of the equation : x∣x+3∣+∣x−1∣−2=0\mathrm{x}\left|\mathrm{x} + 3\right| + \left|\mathrm{x} - 1\right| - 2 = 0x∣x+3∣+∣x−1∣−2=0 is
  1. (A)3
  2. (B)2
  3. (C)5
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q17·MathematicsSingle correctJEE Main 2026
The smallest positive integral value of a, for which all the roots of x4−ax2+9=0x^{4} - ax^{2} + 9 = 0x4−ax2+9=0 are real and distinct, is equal to
  1. (A)9
  2. (B)3
  3. (C)4
  4. (D)7

Correct answer: (D)

Step-by-step solution →
Q18·MathematicsSingle correctJEE Main 2026
A building construction work can be completed by two masons A and B together in 22.5 days. Mason A alone can complete the construction work in 24 days less than mason B alone. Then mason A alone will complete the construction work in:
  1. (A)24 days
  2. (B)42 days
  3. (C)30 days
  4. (D)36 days

Correct answer: (D)

Step-by-step solution →
Q19·MathematicsSingle correctJEE Main 2026
The sum of all the real solutions of the equation log⁡(x+3)(6x2+28x+30)=5−2log⁡(6x+10)(x2+6x+9)\log_{(x+3)}(6x^2 + 28x + 30) = 5 - 2\log_{(6x+10)}(x^2 + 6x + 9)log(x+3)​(6x2+28x+30)=5−2log(6x+10)​(x2+6x+9) is equal to :
  1. (A)2
  2. (B)1
  3. (C)0
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q20·MathematicsSingle correctJEE Main 2026
If α\alphaα and β\betaβ (α<β\alpha < \betaα<β) are the roots of the equation (−2+3)(∣x−3∣)+(x−6x)+(9−23)=0\left(-2 + \sqrt{3}\right)\left(\left|\sqrt{x} - 3\right|\right) + \left(x - 6\sqrt{x}\right) + \left(9 - 2\sqrt{3}\right) = 0(−2+3​)(∣x​−3∣)+(x−6x​)+(9−23​)=0, x≥0x \ge 0x≥0, then βα+αβ\sqrt{\frac{\beta}{\alpha}} + \sqrt{\alpha\beta}αβ​​+αβ​ is equal to :
  1. (A)8
  2. (B)9
  3. (C)10
  4. (D)11

Correct answer: (C)

Step-by-step solution →
Q21·MathematicsSingle correctJEE Main 2026
The number of distinct real solutions of the equation x∣x+4∣+3∣x+2∣+10=0x|x + 4| + 3|x + 2| + 10 = 0x∣x+4∣+3∣x+2∣+10=0 is
  1. (A)3
  2. (B)1
  3. (C)0
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q22·MathematicsSingle correctJEE Main 2026
Let α\alphaα, β\betaβ be the roots of the quadratic equation 12x2−20x+3λ=012x^{2} - 20x + 3\lambda = 012x2−20x+3λ=0, λ∈Z\lambda \in \mathbb{Z}λ∈Z. If 12≤∣β−α∣≤32\frac{1}{2} \le |\beta - \alpha| \le \frac{3}{2}21​≤∣β−α∣≤23​, then the sum of all possible values of λ\lambdaλ is :
  1. (A)6
  2. (B)1
  3. (C)3
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q23·MathematicsSingle correctJEE Main 2026
The sum of all the roots of the equation (x−1)2−5∣x−1∣+6=0(x-1)^{2}-5|x-1|+6=0(x−1)2−5∣x−1∣+6=0, is:
  1. (A)4
  2. (B)3
  3. (C)1
  4. (D)5

Correct answer: (A)

Step-by-step solution →
Q24·MathematicsSingle correctJEE Main 2026
Let α and β be the roots of equation x2+2ax+(3a+10)=0x^2 + 2ax + (3a + 10) = 0x2+2ax+(3a+10)=0 such that α < 1 < β. Then the set of all possible values of a is :
  1. (A)(−∞,−115)∪(5,∞)\left(-\infty, \frac{-11}{5}\right) \cup (5, \infty)(−∞,5−11​)∪(5,∞)
  2. (B)(−∞,−2)∪(5,∞)(-\infty, -2) \cup (5, \infty)(−∞,−2)∪(5,∞)
  3. (C)(−∞,−3)(-\infty, -3)(−∞,−3)
  4. (D)(−∞,−115)\left(-\infty, \frac{-11}{5}\right)(−∞,5−11​)

Correct answer: (D)

Step-by-step solution →
Q25·MathematicsSingle correctJEE Main 2026
The positive integer n, for which the solutions of the equation x(x+2)+(x+2)(x+4)+…+(x+2n−2)(x+2n)=8n3x(x+2) + (x + 2)(x + 4) + \ldots + (x + 2n - 2)(x+2n) = \frac{8n}{3}x(x+2)+(x+2)(x+4)+…+(x+2n−2)(x+2n)=38n​ are two consecutive even integers, is :-
  1. (A)3
  2. (B)6
  3. (C)12
  4. (D)9

Correct answer: (A)

Step-by-step solution →
Q26·MathematicsSingle correctJEE Advanced 2025
Let R denote the set of all real numbers. Let ai,bi∈Ra_i, b_i \in Rai​,bi​∈R for i∈{1,2,3}i \in \{1, 2, 3\}i∈{1,2,3}. Define the function f: R → R, g : R → R, and h : R → R by f(x)=a1+10x+a2x2+a3x3+x4f(x) = a_1 + 10x + a_2x^2 + a_3x^3 + x^4f(x)=a1​+10x+a2​x2+a3​x3+x4, g(x)=b1+3x+b2x2+b3x3+x4g(x) = b_1 + 3x + b_2x^2 + b_3x^3 + x^4g(x)=b1​+3x+b2​x2+b3​x3+x4, h(x)=f(x+1)−g(x+2)h(x) = f(x + 1) - g(x + 2)h(x)=f(x+1)−g(x+2). If f(x)≠g(x)f(x) \neq g(x)f(x)=g(x) for every x∈Rx \in Rx∈R, then the coefficient of x3x^3x3 in h(x) is
  1. (A)8
  2. (B)2
  3. (C)− 4
  4. (D)− 6

Correct answer: (C)

Step-by-step solution →
Q27·MathematicsSingle correctJEE Main 2025
The sum of the squares of the roots of ∣x+2∣2+∣x−2∣−2=0|x+2|^2+|x-2|-2=0∣x+2∣2+∣x−2∣−2=0 and the squares of the roots of x2−2∣x−3∣−5=0x^2-2|x-3|-5=0x2−2∣x−3∣−5=0, is:
  1. (A)262626
  2. (B)363636
  3. (C)303030
  4. (D)242424

Correct answer: (B)

Step-by-step solution →
Q28·MathematicsSingle correctJEE Main 2025
Let the set of all values of p∈Rp\in\mathbb{R}p∈R, for which both the roots of the equation x2−(p+2)x+(2p+9)=0x^2-(p+2)x+(2p+9)=0x2−(p+2)x+(2p+9)=0 are negative real numbers, be the interval (α,β](\alpha,\beta](α,β]. Then β−2α\beta-2\alphaβ−2α is equal to:
  1. (A)0
  2. (B)9
  3. (C)5
  4. (D)20

Correct answer: (C)

Step-by-step solution →
Q29·MathematicsSingle correctJEE Main 2025
The number of real roots of the equation x∣x−2∣+3∣x−3∣+1=0x|x-2|+3|x-3|+1=0x∣x−2∣+3∣x−3∣+1=0 is:
  1. (A)4
  2. (B)2
  3. (C)1
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q30·MathematicsSingle correctJEE Main 2025
Consider the equation x2+4x−n=0x^2+4x-n=0x2+4x−n=0, where n∈[20,100]n\in[20,100]n∈[20,100] is a natural number. Then the number of all distinct values of nnn, for which the given equation has integral roots, is equal to
  1. (A)7
  2. (B)8
  3. (C)6
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q31·MathematicsSingle correctJEE Main 2025
Let the product of ω1=(8+i)sin⁡θ+(7+4i)cos⁡θ\omega_1=(8+i)\sin\theta+(7+4i)\cos\thetaω1​=(8+i)sinθ+(7+4i)cosθ and ω2=(1+8i)sin⁡θ+(4+7i)cos⁡θ\omega_2=(1+8i)\sin\theta+(4+7i)\cos\thetaω2​=(1+8i)sinθ+(4+7i)cosθ be α+iβ\alpha+i\betaα+iβ, i=−1i=\sqrt{-1}i=−1​. Let ppp and qqq be the maximum and minimum values of α+β\alpha+\betaα+β respectively. Then p+qp+qp+q is equal to:
  1. (A)140
  2. (B)130
  3. (C)160
  4. (D)150

Correct answer: (B)

Step-by-step solution →
Q32·MathematicsSingle correctJEE Main 2025
Let the equation x(x+2)(12−k)=2x(x+2)(12-k)=2x(x+2)(12−k)=2 have equal roots. Then the distance of the point (k,k2)\left(k,\dfrac{k}{2}\right)(k,2k​) from the line 3x+4y+5=03x+4y+5=03x+4y+5=0 is:
  1. (A)15
  2. (B)535\sqrt353​
  3. (C)15515\sqrt5155​
  4. (D)12

Correct answer: (A)

Step-by-step solution →
Q33·MathematicsSingle correctJEE Main 2025
Let α\alphaα and β\betaβ be the roots of x2+3 x−16=0x^2+\sqrt3\,x-16=0x2+3​x−16=0, and γ\gammaγ and δ\deltaδ be the roots of x2+3x−1=0x^2+3x-1=0x2+3x−1=0. If Pn=αn+βnP_n=\alpha^n+\beta^nPn​=αn+βn and Qn=γn+δnQ_n=\gamma^n+\delta^nQn​=γn+δn, then P25+3 P242P23+Q25−Q23Q24\dfrac{P_{25}+\sqrt3\,P_{24}}{2P_{23}}+\dfrac{Q_{25}-Q_{23}}{Q_{24}}2P23​P25​+3​P24​​+Q24​Q25​−Q23​​ is equal to:
  1. (A)3
  2. (B)4
  3. (C)5
  4. (D)7

Correct answer: (C)

Step-by-step solution →
Q34·MathematicsSingle correctJEE Main 2025
Let Pn=αn+βnP_n=\alpha^n+\beta^nPn​=αn+βn, n∈Nn\in Nn∈N. If P10=123P_{10}=123P10​=123, P9=76P_9=76P9​=76, P8=47P_8=47P8​=47 and P1=1P_1=1P1​=1, then the quadratic equation having roots 1α\dfrac{1}{\alpha}α1​ and 1β\dfrac{1}{\beta}β1​ is:
  1. (A)x2−x+1=0x^2-x+1=0x2−x+1=0
  2. (B)x2+x−1=0x^2+x-1=0x2+x−1=0
  3. (C)x2−x−1=0x^2-x-1=0x2−x−1=0
  4. (D)x2+x+1=0x^2+x+1=0x2+x+1=0

Correct answer: (B)

Step-by-step solution →
Q35·MathematicsIntegerJEE Main 2025
If the set of all a∈R−{1}a\in\mathbb{R}-\{1\}a∈R−{1}, for which the roots of the equation (1−a)x2+2(a−3)x+9=0(1-a)x^2+2(a-3)x+9=0(1−a)x2+2(a−3)x+9=0 are positive is (−∞,−α]∪[β,γ)(-\infty,-\alpha]\cup[\beta,\gamma)(−∞,−α]∪[β,γ), then 2α+β+γ2\alpha+\beta+\gamma2α+β+γ is equal to ______.

Correct answer: 7

Step-by-step solution →
Q36·MathematicsSingle correctJEE Main 2025
If the set of all a∈Ra\in Ra∈R, for which the equation 2x2+(a−5)x+15=3a2x^2+(a-5)x+15=3a2x2+(a−5)x+15=3a has no real root, is the interval (α,β)(\alpha,\beta)(α,β), and X={x∈Z:α<x<β}X=\{x\in Z:\alpha<x<\beta\}X={x∈Z:α<x<β}, then ∑x∈Xx2\displaystyle\sum_{x\in X}x^2x∈X∑​x2 is equal to
  1. (A)2109
  2. (B)2129
  3. (C)2139
  4. (D)2119

Correct answer: (C)

Step-by-step solution →
Q37·MathematicsSingle correctJEE Main 2025
The number of solutions of the equation (9x−9x+2)(2x−7x+3)=0\left(\dfrac{9}{x}-\dfrac{9}{\sqrt{x}}+2\right)\left(\dfrac{2}{x}-\dfrac{7}{\sqrt{x}}+3\right)=0(x9​−x​9​+2)(x2​−x​7​+3)=0 is:
  1. (A)2
  2. (B)4
  3. (C)1
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q38·MathematicsSingle correctJEE Main 2025
The sum, of the squares of all the roots of the equation x2+∣2x−3∣−4=0x^2+|2x-3|-4=0x2+∣2x−3∣−4=0, is:
  1. (A)3(3−2)3(3-\sqrt{2})3(3−2​)
  2. (B)6(3−2)6(3-\sqrt{2})6(3−2​)
  3. (C)6(2−2)6(2-\sqrt{2})6(2−2​)
  4. (D)3(2−2)3(2-\sqrt{2})3(2−2​)

Correct answer: (C)

Step-by-step solution →
Q39·MathematicsSingle correctJEE Main 2025
If α+iβ\alpha+i\betaα+iβ and γ+iδ\gamma+i\deltaγ+iδ are the roots of x2−(3−2i)x−(2i−2)=0x^2-(3-2i)x-(2i-2)=0x2−(3−2i)x−(2i−2)=0, i=−1i=\sqrt{-1}i=−1​, then αγ+βδ\alpha\gamma+\beta\deltaαγ+βδ is equal to:
  1. (A)6
  2. (B)2
  3. (C)-2
  4. (D)-6

Correct answer: (B)

Step-by-step solution →
Q40·MathematicsSingle correctJEE Main 2025
The product of all the rational roots of the equation (x2−9x+11)2−(x−4)(x−5)=3(x^2-9x+11)^2-(x-4)(x-5)=3(x2−9x+11)2−(x−4)(x−5)=3, is equal to :
  1. (A)141414
  2. (B)777
  3. (C)282828
  4. (D)212121

Correct answer: (A)

Step-by-step solution →
Q41·MathematicsSingle correctJEE Main 2025
The number of real solution(s) of the equation x2+3x+2=min⁡{∣x−3∣,∣x+2∣}x^2+3x+2=\min\{|x-3|,|x+2|\}x2+3x+2=min{∣x−3∣,∣x+2∣} is :
  1. (A)2
  2. (B)0
  3. (C)3
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q42·MathematicsIntegerJEE Main 2025
If the equation a(b−c)x2+b(c−a)x+c(a−b)=0a(b-c)x^2+b(c-a)x+c(a-b)=0a(b−c)x2+b(c−a)x+c(a−b)=0 has equal roots, where a+c=15a+c=15a+c=15 and b=365b=\dfrac{36}{5}b=536​, then a2+c2a^2+c^2a2+c2 is equal to _______

Correct answer: 117

Step-by-step solution →
Q43·MathematicsIntegerJEE Main 2025
Let α,β\alpha,\betaα,β be the roots of the equation x2−ax−b=0x^2-ax-b=0x2−ax−b=0 with Im⁡(α)<Im⁡(β)\operatorname{Im}(\alpha)<\operatorname{Im}(\beta)Im(α)<Im(β). Let Pn=αn−βnP_n=\alpha^n-\beta^nPn​=αn−βn. If P3=−57 i, P4=−37 i, P5=117 iP_3=-5\sqrt7\,i,\ P_4=-3\sqrt7\,i,\ P_5=11\sqrt7\,iP3​=−57​i, P4​=−37​i, P5​=117​i and P6=457 iP_6=45\sqrt7\,iP6​=457​i, then ∣α4+β4∣|\alpha^4+\beta^4|∣α4+β4∣ is equal to __________.

Correct answer: 31

Step-by-step solution →
Q44·MathematicsSingle correctJEE Main 2025
The product of all solutions of e5(log⁡ex)2+3=x8 (x>0)e^{5(\log_e x)^2+3}=x^{8}\,(x>0)e5(loge​x)2+3=x8(x>0) is:
  1. (A)e8/5e^{8/5}e8/5
  2. (B)e6/5e^{6/5}e6/5
  3. (C)e
  4. (D)e2e^{2}e2

Correct answer: (A)

Step-by-step solution →
Q45·MathematicsSingle correctJEE Main 2025
Let α0\alpha_0α0​ and β0\beta_0β0​ be the distinct roots of 2x2+(cos⁡θ)x−1=02x^2+(\cos\theta)x-1=02x2+(cosθ)x−1=0, θ∈(0,2π)\theta\in(0,2\pi)θ∈(0,2π). If mmm and MMM are the minimum and the maximum values of α04+β04\alpha_0^4+\beta_0^4α04​+β04​, then 16(M+m)16(M+m)16(M+m) equals:
  1. (A)24
  2. (B)25
  3. (C)27
  4. (D)17

Correct answer: (B)

Step-by-step solution →
Q46·MathematicsMultiple correctJEE Advanced 2024
Let R2R^{2}R2 denote R×RR \times RR×R. Let S={(a,b,c):a,b,c∈R and ax2+2bxy+cy2>0 for all (x,y)∈R2−{(0,0)}}S = \left\{(a, b, c) : a, b, c \in R \text{ and } ax^{2} + 2bxy + cy^{2} > 0 \text{ for all } (x, y) \in R^{2} - \{(0,0)\}\right\}S={(a,b,c):a,b,c∈R and ax2+2bxy+cy2>0 for all (x,y)∈R2−{(0,0)}} Then which of the following statements is (are) TRUE?
  1. (A)(2,72,6)∈S\left(2, \frac{7}{2}, 6\right) \in S(2,27​,6)∈S
  2. (B)If (3,b,112)∈S\left(3, b, \frac{1}{12}\right) \in S(3,b,121​)∈S, then ∣2b∣<1|2b| < 1∣2b∣<1
  3. (C)For any given (a,b,c)∈S(a, b, c) \in S(a,b,c)∈S, then the system of linear equations ax+by=1ax + by = 1ax+by=1 bx+cy=−1bx + cy = -1bx+cy=−1 has a unique solution.
  4. (D)For any given (a,b,c)∈S(a, b, c) \in S(a,b,c)∈S, then the system of linear equations (a+1)x+by=0(a + 1)x + by = 0(a+1)x+by=0 bx+(c+1)y=0bx + (c + 1)y = 0bx+(c+1)y=0 has a unique solution.

Correct answer: (B), (C), (D)

Step-by-step solution →
Q47·MathematicsIntegerJEE Advanced 2024
Let f(x)=x4+ax3+bx2+cf(x) = x^{4} + ax^{3} + bx^{2} + cf(x)=x4+ax3+bx2+c be a polynomial with real coefficients such that f(1)=−9f(1) = -9f(1)=−9. Suppose that i3i\sqrt{3}i3​ is a root of the equation 4x3+3ax2+2bx=04x^{3} + 3ax^{2} + 2bx = 04x3+3ax2+2bx=0, where i=−1i = \sqrt{-1}i=−1​. If α1,α2,α3,\alpha_{1}, \alpha_{2}, \alpha_{3},α1​,α2​,α3​, and α4\alpha_{4}α4​ are all the roots of the equation f(x)=0f(x) = 0f(x)=0, then ∣α1∣2+∣α2∣2+∣α3∣2+∣α4∣2\left|\alpha_{1}\right|^{2} + \left|\alpha_{2}\right|^{2} + \left|\alpha_{3}\right|^{2} + \left|\alpha_{4}\right|^{2}∣α1​∣2+∣α2​∣2+∣α3​∣2+∣α4​∣2 is equal to ______ .

Correct answer: 20

Step-by-step solution →
Q48·MathematicsSingle correctJEE Main 2024
Let α,β\alpha, \betaα,β be the roots of the equation x2+22 x−1=0x^2 + 2\sqrt{2}\,x - 1 = 0x2+22​x−1=0. The quadratic equation, whose roots are α4+β4\alpha^4 + \beta^4α4+β4 and 110(α6+β6)\frac{1}{10}(\alpha^6 + \beta^6)101​(α6+β6), is :
  1. (A)x2−190x+9466=0x^2 - 190x + 9466 = 0x2−190x+9466=0
  2. (B)x2−195x+9466=0x^2 - 195x + 9466 = 0x2−195x+9466=0
  3. (C)x2−195x+9506=0x^2 - 195x + 9506 = 0x2−195x+9506=0
  4. (D)x2−180x+9506=0x^2 - 180x + 9506 = 0x2−180x+9506=0

Correct answer: (C)

Step-by-step solution →
Q49·MathematicsSingle correctJEE Main 2024
Let α,β\alpha, \betaα,β (α>β\alpha>\betaα>β) be the roots of the equation x2−2x−3=0x^{2}-\sqrt{2}x-\sqrt{3}=0x2−2​x−3​=0. Let Pn=αn−βnP_{n}=\alpha^{n}-\beta^{n}Pn​=αn−βn, n∈Nn\in\mathbb{N}n∈N. Then (113−102)P10+(112+10)P11−11P12\left(11\sqrt{3}-10\sqrt{2}\right)P_{10}+\left(11\sqrt{2}+10\right)P_{11}-11P_{12}(113​−102​)P10​+(112​+10)P11​−11P12​ is equal to:
  1. (A)102 P910\sqrt{2}\,P_{9}102​P9​
  2. (B)103 P910\sqrt{3}\,P_{9}103​P9​
  3. (C)112 P911\sqrt{2}\,P_{9}112​P9​
  4. (D)113 P911\sqrt{3}\,P_{9}113​P9​

Correct answer: (B)

Step-by-step solution →
Q50·MathematicsNumericalJEE Main 2024
The number of distinct real roots of the equation ∣x+1∣ ∣x+3∣−4 ∣x+2∣+5=0|x+1|\,|x+3|-4\,|x+2|+5=0∣x+1∣∣x+3∣−4∣x+2∣+5=0, is _______ .

Correct answer: 2

Step-by-step solution →
Q51·MathematicsSingle correctJEE Main 2024
The sum of all the solutions of the equation (8)2x−16⋅(8)x+48=0(8)^{2x}-16\cdot(8)^x+48=0(8)2x−16⋅(8)x+48=0 is:
  1. (A)1+log⁡6(8)1+\log_6(8)1+log6​(8)
  2. (B)log⁡8(6)\log_8(6)log8​(6)
  3. (C)1+log⁡8(6)1+\log_8(6)1+log8​(6)
  4. (D)log⁡8(4)\log_8(4)log8​(4)

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correctJEE Main 2024
Let α,β\alpha,\betaα,β be the distinct roots of the equation x2−(t2−5t+6)x+1=0x^{2}-(t^{2}-5t+6)x+1=0x2−(t2−5t+6)x+1=0, t∈Rt\in\mathbb{R}t∈R and an=αn+βna_{n}=\alpha^{n}+\beta^{n}an​=αn+βn. Then the minimum value of a2023+a2025a2024\dfrac{a_{2023}+a_{2025}}{a_{2024}}a2024​a2023​+a2025​​ is
  1. (A)14\tfrac{1}{4}41​
  2. (B)−12-\tfrac{1}{2}−21​
  3. (C)−14-\tfrac{1}{4}−41​
  4. (D)12\tfrac{1}{2}21​

Correct answer: (C)

Step-by-step solution →
Q53·MathematicsNumericalJEE Main 2024
Let x1,x2,x3,x4x_{1},x_{2},x_{3},x_{4}x1​,x2​,x3​,x4​ be the solution of the equation 4x4+8x3−17x2−12x+9=04x^{4}+8x^{3}-17x^{2}-12x+9=04x4+8x3−17x2−12x+9=0 and (4+x12)(4+x22)(4+x32)(4+x42)=12516m(4+x_{1}^{2})(4+x_{2}^{2})(4+x_{3}^{2})(4+x_{4}^{2})=\dfrac{125}{16}m(4+x12​)(4+x22​)(4+x32​)(4+x42​)=16125​m. Then the value of mmm is _______.

Correct answer: 221

Step-by-step solution →
Q54·MathematicsNumericalJEE Main 2024
Let α,β\alpha,\betaα,β be roots of x2+2x−8=0x^{2}+\sqrt{2}x-8=0x2+2​x−8=0. If Un=αn+βnU_{n}=\alpha^{n}+\beta^{n}Un​=αn+βn, then U10+12 U92U8\frac{U_{10}+\sqrt{12}\,U_{9}}{2U_{8}}2U8​U10​+12​U9​​ is equal to ______.

Correct answer: 4

Step-by-step solution →
Q55·MathematicsNumericalJEE Main 2024
The number of distinct real roots of the equation ∣x∣ ∣x+2∣−5∣x+1∣−1=0|x|\,|x + 2| - 5|x + 1| - 1 = 0∣x∣∣x+2∣−5∣x+1∣−1=0 is ___.

Correct answer: 3

Step-by-step solution →
Q56·MathematicsNumericalJEE Main 2024
The number of real solutions of the equation x ∣x+5∣+2∣x+7∣−2=0x\,|x+5|+2|x+7|-2=0x∣x+5∣+2∣x+7∣−2=0 is __________.

Correct answer: 3

Step-by-step solution →
Q57·MathematicsSingle correctJEE Main 2024
If 222 and 666 are the roots of the equation ax2+bx+1=0ax^2+bx+1=0ax2+bx+1=0, then the quadratic equation, whose roots are 12a+b\dfrac{1}{2a+b}2a+b1​ and 16a+b\dfrac{1}{6a+b}6a+b1​, is:
  1. (A)2x2+11x+12=02x^2+11x+12=02x2+11x+12=0
  2. (B)4x2+14x+12=04x^2+14x+12=04x2+14x+12=0
  3. (C)x2+10x+16=0x^2+10x+16=0x2+10x+16=0
  4. (D)x2+8x+12=0x^2+8x+12=0x2+8x+12=0

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsNumericalJEE Main 2024
Let S={sin⁡22θ:(sin⁡4θ+cos⁡4θ)x2+(sin⁡2θ)x+(sin⁡6θ+cos⁡6θ)=0 has real roots}S=\{\sin^2 2\theta:(\sin^4\theta+\cos^4\theta)x^2+(\sin 2\theta)x+(\sin^6\theta+\cos^6\theta)=0 \text{ has real roots}\}S={sin22θ:(sin4θ+cos4θ)x2+(sin2θ)x+(sin6θ+cos6θ)=0 has real roots}. If α\alphaα and β\betaβ be the smallest and largest elements of the set S, respectively, then 3((α−2)2+(β−1)2)3\left((\alpha-2)^2+(\beta-1)^2\right)3((α−2)2+(β−1)2) equals

Correct answer: 4

Step-by-step solution →
Q59·MathematicsSingle correctJEE Main 2024
Let S={x∈R:(3+2)x+(3−2)x=10}S=\{x\in\mathbb{R}:(\sqrt3+\sqrt2)^x+(\sqrt3-\sqrt2)^x=10\}S={x∈R:(3​+2​)x+(3​−2​)x=10}. Then the number of elements in SSS is:
  1. (A)444
  2. (B)000
  3. (C)222
  4. (D)111

Correct answer: (C)

Step-by-step solution →
Q60·MathematicsNumericalJEE Main 2024
Let P={z∈C:∣z+2−3i∣≤11}P=\{z\in\mathbb{C}:|z+2-3i|\le\sqrt{11}\}P={z∈C:∣z+2−3i∣≤11​} and Q={z∈C:z(1+i)+zˉ(1−i)≤−8}Q=\{z\in\mathbb{C}:z(1+i)+\bar z(1-i)\le-8\}Q={z∈C:z(1+i)+zˉ(1−i)≤−8}. Let in P∩QP\cap QP∩Q, ∣z−3+2i∣|z-3+2i|∣z−3+2i∣ be the maximum and minimum at z1z_1z1​ and z2z_2z2​ respectively. If ∣z1∣2+2∣z2∣2=α+β2|z_1|^2+2|z_2|^2=\alpha+\beta\sqrt2∣z1​∣2+2∣z2​∣2=α+β2​, where α,β\alpha,\betaα,β are integers, then α+β\alpha+\betaα+β equals ___

Correct answer: 36

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Q61·MathematicsSingle correctJEE Main 2024
Let α\alphaα and β\betaβ be the roots of the equation px2+qx−r=0px^2+qx-r=0px2+qx−r=0, where p≠0p\neq 0p=0. If ppp, qqq and rrr be the consecutive terms of a non-constant GP and 1α+1β=34\dfrac{1}{\alpha}+\dfrac{1}{\beta}=\dfrac{3}{4}α1​+β1​=43​, then the value of (α−β)2(\alpha-\beta)^2(α−β)2 is:
  1. (A)809\dfrac{80}{9}980​
  2. (B)9
  3. (C)203\dfrac{20}{3}320​
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correctJEE Main 2024
For 0<c<b<a0<c<b<a0<c<b<a, let (a+b−2c)x2+(b+c−2a)x+(c+a−2b)=0(a+b-2c)x^2+(b+c-2a)x+(c+a-2b)=0(a+b−2c)x2+(b+c−2a)x+(c+a−2b)=0 and α≠1\alpha\ne 1α=1 be one of its root. Then, among the two statements (I) If α∈(−1,0)\alpha\in(-1,0)α∈(−1,0), then b cannot be the geometric mean of a and c (II) If α∈(0,1)\alpha\in(0,1)α∈(0,1), then b may be the geometric mean of a and c
  1. (A)Both (I) and (II) are true
  2. (B)Neither (I) nor (II) is true
  3. (C)Only (II) is true
  4. (D)Only (I) is true

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsNumericalJEE Main 2024
Let aaa, bbb, ccc be the length of three sides of a triangle satisfying the condition (a2+b2)x2−2b(a+c)x+(b2+c2)=0(a^2+b^2)x^2-2b(a+c)x+(b^2+c^2)=0(a2+b2)x2−2b(a+c)x+(b2+c2)=0. If the set of all possible values of xxx is the interval (α,β)(\alpha,\beta)(α,β), then 12(α2+β2)12(\alpha^2+\beta^2)12(α2+β2) is equal to ______.

Correct answer: 36

Step-by-step solution →
Q64·MathematicsSingle correctJEE Main 2024
Let a be the sum of all coefficients in the expansion of (1−2x+2x2)2023(3−4x2+2x3)2024\left(1-2x+2x^2\right)^{2023}\left(3-4x^2+2x^3\right)^{2024}(1−2x+2x2)2023(3−4x2+2x3)2024 and b=lim⁡x→0(∫0xlog⁡(1+t)t2024+1dtx2)b=\displaystyle\lim_{x\to 0}\left(\dfrac{\int_0^x \frac{\log(1+t)}{t^{2024}+1}dt}{x^2}\right)b=x→0lim​(x2∫0x​t2024+1log(1+t)​dt​). If the equations cx2+dx+e=0cx^2+dx+e=0cx2+dx+e=0 and 2bx2+ax+4=02bx^2+ax+4=02bx2+ax+4=0 have a common root, where c,d,e∈Rc,d,e\in Rc,d,e∈R, then d:c:ed:c:ed:c:e equals
  1. (A)2:1:42:1:42:1:4
  2. (B)4:1:44:1:44:1:4
  3. (C)1:2:41:2:41:2:4
  4. (D)1:1:41:1:41:1:4

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correctJEE Main 2024
Let S be the set of positive integral values of a for which ax2+2(a+1)x+9a+4x2−8x+32<0\dfrac{ax^2+2(a+1)x+9a+4}{x^2-8x+32}<0x2−8x+32ax2+2(a+1)x+9a+4​<0, ∀x∈R\forall x\in R∀x∈R. Then, the number of elements in S is
  1. (A)111
  2. (B)000
  3. (C)∞\infty∞
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsNumericalJEE Main 2024
The number of real solutions of the equation x(x2+3∣x∣+5∣x−1∣+6∣x−2∣)=0x\left(x^2+3|x|+5|x-1|+6|x-2|\right)=0x(x2+3∣x∣+5∣x−1∣+6∣x−2∣)=0 is ______.

Correct answer: 1

Step-by-step solution →
Q67·MathematicsNumericalJEE Main 2024
Let α,β∈N\alpha,\beta\in\mathbb{N}α,β∈N be roots of the equation x2−70x+λ=0x^2-70x+\lambda=0x2−70x+λ=0, where λ2,λ3∉N\dfrac\lambda2,\dfrac\lambda3\notin\mathbb{N}2λ​,3λ​∈/N. If λ\lambdaλ assumes the minimum possible value, then (α−1+β−1)(λ+35)∣α−β∣\dfrac{(\sqrt{\alpha-1}+\sqrt{\beta-1})(\lambda+35)}{|\alpha-\beta|}∣α−β∣(α−1​+β−1​)(λ+35)​ is equal to ___

Correct answer: 60

Step-by-step solution →
Q68·MathematicsNumericalJEE Main 2024
Let α,β\alpha,\betaα,β be the roots of the equation x2−6 x+3=0x^2-\sqrt6\,x+3=0x2−6​x+3=0 such that Im(α)>Im(β)\text{Im}(\alpha)>\text{Im}(\beta)Im(α)>Im(β). Let a,ba,ba,b be integers not divisible by 3 and nnn be a natural number such that α99β+α98=3n(a+ib), i=−1\dfrac{\alpha^{99}}{\beta}+\alpha^{98}=3^n(a+ib),\ i=\sqrt{-1}βα99​+α98=3n(a+ib), i=−1​. Then n+a+bn+a+bn+a+b is equal to ___.

Correct answer: 49

Step-by-step solution →
Q69·MathematicsNumericalJEE Main 2024
Let α,β\alpha,\betaα,β be the roots of the equation x2−x+2=0x^2-x+2=0x2−x+2=0 with Im⁡(α)>Im⁡(β)\operatorname{Im}(\alpha)>\operatorname{Im}(\beta)Im(α)>Im(β). Then α6+α4+β4−5α2\alpha^6+\alpha^4+\beta^4-5\alpha^2α6+α4+β4−5α2 is equal to ______.

Correct answer: 13

Step-by-step solution →
Q70·MathematicsSingle correctJEE Main 2023
The number of real roots of the equation x∣x∣−5∣x+2∣+6=0x|x|-5|x+2|+6=0x∣x∣−5∣x+2∣+6=0, is
  1. (A)5
  2. (B)3
  3. (C)6
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correctJEE Main 2023
The set of all a∈Ra\in\mathbb{R}a∈R for which the equation x∣x−1∣+∣x+2∣+a=0x|x-1|+|x+2|+a=0x∣x−1∣+∣x+2∣+a=0 has exactly one real root is:
  1. (A)(−6,−3)(-6,-3)(−6,−3)
  2. (B)(−∞,∞)(-\infty,\infty)(−∞,∞)
  3. (C)(−6,∞)(-6,\infty)(−6,∞)
  4. (D)(−∞,−3)(-\infty,-3)(−∞,−3)

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correctJEE Main 2023
Let α,β\alpha,\betaα,β be the roots of the quadratic equation x2+6 x+3=0x^2+\sqrt6\,x+3=0x2+6​x+3=0. Then α23+β23+α14+β14α15+β15+α10+β10\dfrac{\alpha^{23}+\beta^{23}+\alpha^{14}+\beta^{14}}{\alpha^{15}+\beta^{15}+\alpha^{10}+\beta^{10}}α15+β15+α10+β10α23+β23+α14+β14​ is equal to
  1. (A)729
  2. (B)72
  3. (C)81
  4. (D)9

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correctJEE Main 2023
The number of integral solutions xxx of log⁡(x+72)(x−72x−3)2≥0\log_{\left( x + \frac{7}{2} \right)} \left( \frac{x - 7}{2x - 3} \right)^2 \ge 0log(x+27​)​(2x−3x−7​)2≥0 is
  1. (A)6
  2. (B)8
  3. (C)5
  4. (D)7

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsNumericalJEE Main 2023
If aaa and bbb are the roots of equation x2−7x−1=0x^2 - 7x - 1 = 0x2−7x−1=0, then the value of a21+b21+a17+b17a19+b19\frac{a^{21} + b^{21} + a^{17} + b^{17}}{a^{19} + b^{19}}a19+b19a21+b21+a17+b17​ is equal to _______ .

Correct answer: 51

Step-by-step solution →
Q75·MathematicsNumericalJEE Main 2023
Let a, b, c be three distinct positive real numbers such that (2a)log⁡ea=(bc)log⁡eb(2a)^{\log_e a}=(bc)^{\log_e b}(2a)loge​a=(bc)loge​b and blog⁡e2=alog⁡ecb^{\log_e 2}=a^{\log_e c}bloge​2=aloge​c. Then 6a+5bc6a+5bc6a+5bc is equal to _________.

Correct answer: 8

Step-by-step solution →
Q76·MathematicsNumericalJEE Main 2023
The number of elements in the set {n∈Z:∣n2−10n+19∣<6}\{n\in\mathbb{Z}:|n^2-10n+19|<6\}{n∈Z:∣n2−10n+19∣<6} is _________.

Correct answer: 6

Step-by-step solution →
Q77·MathematicsSingle correctJEE Main 2023
Let α,β,γ\alpha,\beta,\gammaα,β,γ be the three roots of the equation x3+bx+c=0x^{3}+bx+c=0x3+bx+c=0. If βγ=1=−α\beta\gamma=1=-\alphaβγ=1=−α, then b3+2c3−3α3−6β3−8γ3b^{3}+2c^{3}-3\alpha^{3}-6\beta^{3}-8\gamma^{3}b3+2c3−3α3−6β3−8γ3 is equal to
  1. (A)21
  2. (B)1698\frac{169}{8}8169​
  3. (C)19
  4. (D)1558\frac{155}{8}8155​

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsNumericalJEE Main 2023
Let m and n be the numbers of real roots of the quadratic equations x2−12x+[x]+31=0x^{2}-12x+[x]+31=0x2−12x+[x]+31=0 and x2−5∣x+2∣−4=0x^{2}-5|x+2|-4=0x2−5∣x+2∣−4=0 respectively, where [x][x][x] denotes the greatest integer ≤x\leq x≤x. Then m2+mn+n2m^{2}+mn+n^{2}m2+mn+n2 is equal to

Correct answer: 9

Step-by-step solution →
Q79·MathematicsSingle correctJEE Main 2023
The sum of all the roots of the equation ∣x2−8x+15∣−2x+7=0|x^{2}-8x+15|-2x+7=0∣x2−8x+15∣−2x+7=0 is:
  1. (A)9+39+\sqrt39+3​
  2. (B)11+311+\sqrt311+3​
  3. (C)9−39-\sqrt39−3​
  4. (D)11−311-\sqrt311−3​

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsSingle correctJEE Main 2023
The number of integral values of k, for which one root of the equation 2x2−8x+k=02x^2-8x+k=02x2−8x+k=0 lies in the interval (1,2)(1,2)(1,2) and its other root lies in the interval (2,3)(2,3)(2,3), is:
  1. (A)333
  2. (B)000
  3. (C)222
  4. (D)111

Correct answer: (D)

Step-by-step solution →
Q81·MathematicsSingle correctJEE Main 2023
Let S={x:x∈R and (3+2)x2−4+(3−2)x2−4=10}S=\{x:x\in\mathbb{R}\text{ and }(\sqrt{3}+\sqrt{2})^{x^2-4}+(\sqrt{3}-\sqrt{2})^{x^2-4}=10\}S={x:x∈R and (3​+2​)x2−4+(3​−2​)x2−4=10}. Then n(S)n(S)n(S) is equal to
  1. (A)444
  2. (B)000
  3. (C)666
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q82·MathematicsSingle correctJEE Main 2023
The number of real roots of the equation x2−4x+3+x2−9=4x2−14x+6\sqrt{x^2 - 4x + 3} + \sqrt{x^2 - 9} = \sqrt{4x^2 - 14x + 6}x2−4x+3​+x2−9​=4x2−14x+6​, is :
  1. (A)333
  2. (B)111
  3. (C)222
  4. (D)000

Correct answer: (B)

Step-by-step solution →
Q83·MathematicsSingle correctJEE Main 2023
The equation e4x+8e3x+13e2x−8ex+1=0, x∈Re^{4x}+8e^{3x}+13e^{2x}-8e^{x}+1=0,\ x\in\mathbb{R}e4x+8e3x+13e2x−8ex+1=0, x∈R has:
  1. (A)four solutions two of which are negative
  2. (B)two solutions and only one of them is negative
  3. (C)two solutions and both are negative
  4. (D)no solution

Correct answer: (C)

Step-by-step solution →
Q84·MathematicsNumericalJEE Main 2023
If the value of the real number a>0a > 0a>0 for which x2−5ax+1=0x^2 - 5ax + 1=0x2−5ax+1=0 and x2−ax−5=0x^2 - ax - 5=0x2−ax−5=0 have a common real root is 32β\dfrac{3}{\sqrt{2\beta}}2β​3​, then β\betaβ is equal to _______.

Correct answer: 13

Step-by-step solution →
Q85·MathematicsSingle correctJEE Main 2023
Let λ≠0\lambda \neq 0λ=0 be a real number. Let α,β\alpha, \betaα,β be the roots of the equation 14x2−31x+3λ=014x^2 - 31x + 3\lambda = 014x2−31x+3λ=0 and α,γ\alpha, \gammaα,γ be the roots of the equation 35x2−53x+4λ=035x^2 - 53x + 4\lambda = 035x2−53x+4λ=0. Then 3αβ\dfrac{3\alpha}{\beta}β3α​ and 4αγ\dfrac{4\alpha}{\gamma}γ4α​ are the roots of the equation
  1. (A)49x2−245x+250=049x^2 - 245x + 250 = 049x2−245x+250=0
  2. (B)7x2+245x−250=07x^2 + 245x - 250 = 07x2+245x−250=0
  3. (C)7x2−245x+250=07x^2 - 245x + 250 = 07x2−245x+250=0
  4. (D)49x2+245x+250=049x^2 + 245x + 250 = 049x2+245x+250=0

Correct answer: (A)

Step-by-step solution →
Q86·MathematicsNumericalJEE Main 2023
Let a∈Ra\in\mathbb{R}a∈R and let α,β\alpha,\betaα,β be the roots of the equation x2+6014x+a=0x^{2}+60^{\frac{1}{4}}x+a=0x2+6041​x+a=0. If α4+β4=−30\alpha^{4}+\beta^{4}=-30α4+β4=−30, then the product of all possible values of aaa is

Correct answer: 45

Step-by-step solution →
Q87·MathematicsNumericalJEE Main 2023
Let S={α:log⁡2(92α−4+13)−log⁡2(52⋅32α−4+1)=2}S=\Big\{\alpha:\log_2(9^{2\alpha-4}+13)-\log_2\big(\tfrac{5}{2}\cdot 3^{2\alpha-4}+1\big)=2\Big\}S={α:log2​(92α−4+13)−log2​(25​⋅32α−4+1)=2}. Then the maximum value of β\betaβ for which the equation x2−2(∑α∈Sα)2x+∑α∈S(α+1)2 β=0x^2-2\left(\displaystyle\sum_{\alpha\in S}\alpha\right)^2 x+\sum_{\alpha\in S}(\alpha+1)^2\,\beta=0x2−2(α∈S∑​α)2x+∑α∈S​(α+1)2β=0 has real roots, is _______.

Correct answer: 25

Step-by-step solution →
Q88·MathematicsSingle correctJEE Main 2023
The number of real solutions of the equation 3(x2+1x2)−2(x+1x)+5=03\left(x^2+\dfrac{1}{x^2}\right)-2\left(x+\dfrac{1}{x}\right)+5=03(x2+x21​)−2(x+x1​)+5=0, is
  1. (A)000
  2. (B)333
  3. (C)444
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q89·MathematicsNumericalJEE Main 2023
Let λ∈R\lambda\in\mathbb{R}λ∈R and let the equation EEE be ∣x∣2−2∣x∣+∣λ−3∣=0|x|^2-2|x|+|\lambda-3|=0∣x∣2−2∣x∣+∣λ−3∣=0. Then the largest element in the set S={x+λ:x is an integer solution of E}S=\{x+\lambda:x \text{ is an integer solution of } E\}S={x+λ:x is an integer solution of E} is _______ .

Correct answer: 5

Step-by-step solution →
Q90·MathematicsIntegerJEE Advanced 2022
The product of all positive real values of x satisfying the equation x(16(log⁡5x)3−68log⁡5x)=5−16x^{\left(16\left(\log_{5}x\right)^{3} - 68\log_{5}x\right)} = 5^{-16}x(16(log5​x)3−68log5​x)=5−16 is ________.

Correct answer: 1

Step-by-step solution →
Q91·MathematicsNumericalJEE Main 2022
Let α,β\alpha, \betaα,β (α>β)(\alpha > \beta)(α>β) be the roots of the quadratic equation x2−x−4=0x^2 - x - 4 = 0x2−x−4=0. If Pn=αn−βnP_n = \alpha^n - \beta^nPn​=αn−βn, n∈Nn \in \mathbb{N}n∈N, then P15P16−P14P16−P152+P14P15P13P14\frac{P_{15}P_{16} - P_{14}P_{16} - P_{15}^2 + P_{14}P_{15}}{P_{13}P_{14}}P13​P14​P15​P16​−P14​P16​−P152​+P14​P15​​ is equal to ______.

Correct answer: 16

Step-by-step solution →
Q92·MathematicsNumericalJEE Main 2022
The sum of all real values of x for which 3x2−9x+17x2+3x+10=5x2−7x+193x2+5x+12\frac{3x^{2} - 9x + 17}{x^{2} + 3x + 10} = \frac{5x^{2} - 7x + 19}{3x^{2} + 5x + 12}x2+3x+103x2−9x+17​=3x2+5x+125x2−7x+19​ is equal to ____.

Correct answer: 6

Step-by-step solution →
Q93·MathematicsNumericalJEE Main 2022
For p,q∈Rp, q \in Rp,q∈R, consider the real valued function f(x)=(x−p)2−qf(x) = (x - p)^{2} - qf(x)=(x−p)2−q, x∈Rx \in Rx∈R and q > 0. Let a1a_{1}a1​, a2a_{2}a2​, a3a_{3}a3​ and a4a_{4}a4​ be in an arithmetic progression with mean p and positive common difference. If ∣f(ai)∣=500\left| f\left(a_{i}\right) \right| = 500∣f(ai​)∣=500 for all i = 1, 2, 3, 4, then the absolute difference between the roots of f(x) = 0 is ______.

Correct answer: 50

Step-by-step solution →
Q94·MathematicsSingle correctJEE Main 2022
Let f(x)=ax2+bx+cf(x)=ax^{2}+bx+cf(x)=ax2+bx+c be such that f(1)=3f(1)=3f(1)=3, f(−2)=λf(-2)=\lambdaf(−2)=λ and f(3)=4f(3)=4f(3)=4. If f(0)+f(1)+f(−2)+f(3)=14f(0)+f(1)+f(-2)+f(3)=14f(0)+f(1)+f(−2)+f(3)=14, then λ\lambdaλ is equal to
  1. (A)−4-4−4
  2. (B)132\frac{13}{2}213​
  3. (C)232\frac{23}{2}223​
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q95·MathematicsSingle correctJEE Main 2022
Let α\alphaα, β\betaβ be the roots of the equation x2−2x+6=0x^{2}-\sqrt{2}x+\sqrt{6}=0x2−2​x+6​=0 and 1α2+1,1β2+1\frac{1}{\alpha^{2}}+1, \frac{1}{\beta^{2}}+1α21​+1,β21​+1 be the roots of the equation x2+ax+b=0x^{2}+ax+b=0x2+ax+b=0. Then the roots of the equation x2−(a+b−2)x+(a+b+2)=0x^{2}-(a+b-2)x+(a+b+2)=0x2−(a+b−2)x+(a+b+2)=0 are :
  1. (A)non-real complex numbers
  2. (B)real and both negative
  3. (C)real and both positive
  4. (D)real and exactly one of them is positive

Correct answer: (B)

Step-by-step solution →
Q96·MathematicsNumericalJEE Main 2022
Let f(x)=2x2−x−1f\left(x\right)=2x^{2}-x-1f(x)=2x2−x−1 and S={n∈Z:∣f(n)∣≤800}S=\left\{n\in\mathbb{Z}:\left|f\left(n\right)\right|\le 800\right\}S={n∈Z:∣f(n)∣≤800}. Then, the value of ∑n∈Sf(n)\sum_{n\in S}f\left(n\right)∑n∈S​f(n) is equal to ________.

Correct answer: 10620

Step-by-step solution →
Q97·MathematicsSingle correctJEE Main 2022
If α,β\alpha, \betaα,β are the roots of the equation x2−(5+3log⁡35−5log⁡53)+3(3(log⁡35)13−5(log⁡53)23−1)=0x^{2}-\left(5+3^{\sqrt{\log_{3}5}}-5^{\sqrt{\log_{5}3}}\right)+3\left(3^{(\log_{3}5)^{\frac{1}{3}}}-5^{(\log_{5}3)^{\frac{2}{3}}}-1\right)=0x2−(5+3log3​5​−5log5​3​)+3(3(log3​5)31​−5(log5​3)32​−1)=0 then the equation, whose roots are α+1β\alpha+\frac{1}{\beta}α+β1​ and β+1α\beta+\frac{1}{\alpha}β+α1​,
  1. (A)3x2−20x−12=03x^{2}-20x-12=03x2−20x−12=0
  2. (B)3x2−10x−4=03x^{2}-10x-4=03x2−10x−4=0
  3. (C)3x2−10x+2=03x^{2}-10x+2=03x2−10x+2=0
  4. (D)3x2−20x+16=03x^{2}-20x+16=03x2−20x+16=0

Correct answer: (B)

Step-by-step solution →
Q98·MathematicsNumericalJEE Main 2022
The number of distinct real roots of the equation x5^{5}5(x3^{3}3 − x2^{2}2 − x +1) +x (3x3^{3}3 − 4x2^{2}2 − 2x + 4) − 1 = 0 is

Correct answer: 3

Step-by-step solution →
Q99·MathematicsNumericalJEE Main 2022
If for some p, q, r ∈ R, not all have same sign, one of the roots of the equation (p2^{2}2 + q2^{2}2)x2^{2}2 − 2q(p + r)x + q2^{2}2 + r2^{2}2 = 0 is also a root of the equation x2^{2}2 + 2x − 8 = 0, then q2+r2p2\frac{q^{2}+r^{2}}{p^{2}}p2q2+r2​ is equal to-

Correct answer: 272

Step-by-step solution →
Q100·MathematicsSingle correctJEE Main 2022
The minimum value of the sum of the squares of the roots of x2+(3−a)x+1=2ax^{2}+(3-a)x+1=2ax2+(3−a)x+1=2a is:
  1. (A)4
  2. (B)5
  3. (C)6
  4. (D)8

Correct answer: (C)

Step-by-step solution →
Q101·MathematicsNumericalJEE Main 2022
Let a, b be two non-zero real numbers. If p and r are the roots of the equation x2−8ax+2a=0x^{2} - 8ax + 2a = 0x2−8ax+2a=0 and q and s are the roots of the equation x2+12bx+6b=0x^{2} + 12bx + 6b = 0x2+12bx+6b=0, such that 1p,1q,1r,1s\frac{1}{p}, \frac{1}{q}, \frac{1}{r}, \frac{1}{s}p1​,q1​,r1​,s1​ are in A.P., then a−1−b−1a^{-1} - b^{-1}a−1−b−1 is equal to ________.

Correct answer: 38

Step-by-step solution →
Q102·MathematicsNumericalJEE Main 2022
The number of real solutions of the equation e4x+4e3x−58e2x+4ex+1=0e^{4x} + 4e^{3x} - 58e^{2x} + 4e^{x} + 1 = 0e4x+4e3x−58e2x+4ex+1=0 is ______.

Correct answer: 2

Step-by-step solution →
Q103·MathematicsSingle correctJEE Main 2022
Let f(x)f(x)f(x) be a quadratic polynomial such that f(−2)+f(3)=0f(-2) + f(3) = 0f(−2)+f(3)=0. If one of the roots of f(x)=0f(x) = 0f(x)=0 is −1-1−1, then the sum of the roots of f(x)=0f(x) = 0f(x)=0 is equal to :
  1. (A)113\frac{11}{3}311​
  2. (B)73\frac{7}{3}37​
  3. (C)133\frac{13}{3}313​
  4. (D)143\frac{14}{3}314​

Correct answer: (A)

Step-by-step solution →
Q104·MathematicsNumericalJEE Main 2022
Let α\alphaα, β\betaβ be the roots of the equation x2−4λx+5=0x^{2}-4\lambda x+5=0x2−4λx+5=0 and α\alphaα, γ\gammaγ be the roots of the equation x2−(32+23)x+7+3λ3=0x^{2}-\left(3\sqrt{2}+2\sqrt{3}\right)x+7+3\lambda\sqrt{3}=0x2−(32​+23​)x+7+3λ3​=0. If β+γ=32\beta+\gamma=3\sqrt{2}β+γ=32​, then (α+2β+γ)2(\alpha+2\beta+\gamma)^{2}(α+2β+γ)2 is equal to :

Correct answer: 98

Step-by-step solution →
Q105·MathematicsNumericalJEE Main 2022
If the sum of all the roots of the equation e2x−11ex−45e−x+812=0e^{2x}-11e^{x}-45e^{-x}+\frac{81}{2}=0e2x−11ex−45e−x+281​=0 is log⁡e\log_eloge​ P, then p is equal to ________.

Correct answer: 45

Step-by-step solution →
Q106·MathematicsSingle correctJEE Main 2022
The number of distinct real roots of x4−4x+1=0x^{4} - 4x + 1 = 0x4−4x+1=0 is :
  1. (A)4
  2. (B)2
  3. (C)1
  4. (D)0

Correct answer: (B)

Step-by-step solution →
Q107·MathematicsNumericalJEE Main 2022
Let p and q be two real numbers such that p+q=3p+q=3p+q=3 and p4+q4=369p^{4}+q^{4}=369p4+q4=369. Then (1p+1q)−2\left(\frac{1}{p}+\frac{1}{q}\right)^{-2}(p1​+q1​)−2 is equal to ________.

Correct answer: 4

Step-by-step solution →
Q108·MathematicsNumericalJEE Main 2022
The sum of the cubes of all the roots of the equation x4−3x3−2x2+3x+1=10x^{4} - 3x^{3} - 2x^{2} + 3x + 1 = 10x4−3x3−2x2+3x+1=10 is ______.

Correct answer: 36

Step-by-step solution →
Q109·MathematicsSingle correctJEE Main 2022
Let a,b∈Ra, b \in Ra,b∈R be such that the equation ax2−2bx+15=0ax^2 - 2bx + 15 = 0ax2−2bx+15=0 has a repeated root α\alphaα. If α\alphaα and β\betaβ are the roots of the equation x2−2bx+21=0x^2 - 2bx + 21 = 0x2−2bx+21=0, then α2+β2\alpha^2 + \beta^2α2+β2 is equal to:
  1. (A)37
  2. (B)58
  3. (C)68
  4. (D)92

Correct answer: (B)

Step-by-step solution →
Q110·MathematicsSingle correctJEE Main 2022
If the sum of the squares of the reciprocals of the roots α\alphaα and β\betaβ of the equation 3x2+λx−1=03x^{2}+\lambda x-1=03x2+λx−1=0 is 15, then 6(α3+β3)26(\alpha^{3}+\beta^{3})^{2}6(α3+β3)2 is equal to :
  1. (A)18
  2. (B)24
  3. (C)36
  4. (D)96

Correct answer: (B)

Step-by-step solution →
Q111·MathematicsSingle correctJEE Main 2022
The sum of all the real roots of the equation (e2x−4)(6e2x−5ex+1)=0(e^{2x} - 4)(6e^{2x} - 5e^{x} + 1) = 0(e2x−4)(6e2x−5ex+1)=0 is
  1. (A)log⁡e3\log_e 3loge​3
  2. (B)−log⁡e3-\log_e 3−loge​3
  3. (C)log⁡e6\log_e 6loge​6
  4. (D)−log⁡e6-\log_e 6−loge​6

Correct answer: (B)

Step-by-step solution →
Q112·MathematicsIntegerJEE Advanced 2021
For x∈Rx \in \mathbb{R}x∈R , then number of real roots of the equation 3x2−4∣x2−1∣+x−1=03x^2 - 4\left|x^2 - 1\right| + x - 1 = 03x2−4​x2−1​+x−1=0 is ____.

Correct answer: 4

Step-by-step solution →
Q113·MathematicsNumericalJEE Main 2021
Let f(x) be a polynomial of degree 3 such that f(k)=−2kf(k) = -\frac{2}{k}f(k)=−k2​ for k = 2, 3, 4, 5. Then the value of 52 − 10 f(10) is equal to :

Correct answer: 26

Step-by-step solution →
Q114·MathematicsSingle correctJEE Main 2021
The numbers of pairs (a, b) of real numbers, such that whenever α is a root of the equation x2+ax+b=0x^{2} + ax + b = 0x2+ax+b=0 , α2−2\alpha^{2} - 2α2−2 is also a root of this equation, is :
  1. (A)6
  2. (B)2
  3. (C)4
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q115·MathematicsSingle correctJEE Main 2021
The number of real roots of the equation e4x+2e3x−ex−6=0e^{4x} + 2e^{3x} - e^{x} - 6 = 0e4x+2e3x−ex−6=0 is :
  1. (A)2
  2. (B)4
  3. (C)1
  4. (D)0

Correct answer: (C)

Step-by-step solution →
Q116·MathematicsSingle correctJEE Main 2021
The sum of the roots of the equation x+1−2log⁡2(3+2x)+2log⁡4(10−2−x)=0x + 1 - 2\log_2(3 + 2^x) + 2\log_4(10 - 2^{-x}) = 0x+1−2log2​(3+2x)+2log4​(10−2−x)=0, is :
  1. (A)log⁡214\log_2 14log2​14
  2. (B)log⁡211\log_2 11log2​11
  3. (C)log⁡212\log_2 12log2​12
  4. (D)log⁡213\log_2 13log2​13

Correct answer: (B)

Step-by-step solution →
Q117·MathematicsSingle correctJEE Main 2021
The set of all values of k > −1, for which the equation (3x2+4x+3)2−(k+1)(3x2+4x+3)(3x2+4x+2)+k(3x2+4x+2)2=0(3x^{2} + 4x + 3)^{2} - (k+1)(3x^{2} + 4x + 3)(3x^{2} + 4x + 2) + k(3x^{2} + 4x + 2)^{2} = 0(3x2+4x+3)2−(k+1)(3x2+4x+3)(3x2+4x+2)+k(3x2+4x+2)2=0 has real roots, is :
  1. (A)(1,52]\left(1, \frac{5}{2}\right](1,25​]
  2. (B)[2, 3)
  3. (C)[−12,1)\left[-\frac{1}{2}, 1\right)[−21​,1)
  4. (D)(12,32]−{1}\left(\frac{1}{2}, \frac{3}{2}\right] - \{1\}(21​,23​]−{1}

Correct answer: (A)

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Q118·MathematicsNumericalJEE Main 2021
The number of distinct real roots of the equation 3x4+4x3−12x2+4=03x^{4} + 4x^{3} - 12x^{2} + 4 = 03x4+4x3−12x2+4=0 is _________.

Correct answer: 4

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Q119·MathematicsSingle correctJEE Main 2021
If x2+9y2−4x+3=0x^2 + 9y^2 - 4x + 3 = 0x2+9y2−4x+3=0, x,y∈Rx, y \in \mathbb{R}x,y∈R , then x and y respectively lie in the intervals:
  1. (A)[−13,13]\left[-\frac{1}{3}, \frac{1}{3}\right][−31​,31​] and [−13,13]\left[-\frac{1}{3}, \frac{1}{3}\right][−31​,31​]
  2. (B)[−13,13]\left[-\frac{1}{3}, \frac{1}{3}\right][−31​,31​] and [1,3][1, 3][1,3]
  3. (C)[1,3][1, 3][1,3] and [1,3][1, 3][1,3]
  4. (D)[1,3][1, 3][1,3] and [−13,13]\left[-\frac{1}{3}, \frac{1}{3}\right][−31​,31​]

Correct answer: (D)

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Q120·MathematicsNumericalJEE Main 2021
Let λ≠0\lambda \ne 0λ=0 be in R\mathbf{R}R. If α\alphaα and β\betaβ are the roots of the equation x2−x+2λ=0x^{2} - x + 2\lambda = 0x2−x+2λ=0, and α\alphaα and γ\gammaγ are the roots of equation 3x2−10x+27λ=03x^{2} - 10x + 27\lambda = 03x2−10x+27λ=0, then βγλ\frac{\beta\gamma}{\lambda}λβγ​ is equal to ________.

Correct answer: 18

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Q121·MathematicsNumericalJEE Main 2021
The sum of all integral values of k (k≠0)(k \neq 0)(k=0) for which the equation 2x−1−1x−2=2k\frac{2}{x-1} - \frac{1}{x-2} = \frac{2}{k}x−12​−x−21​=k2​ in x has no real roots, is ________.

Correct answer: 66

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Q122·MathematicsSingle correctJEE Main 2021
Let α=max⁡x∈R{82sin⁡3x.44cos⁡3x}\alpha = \max_{x \in R} \left\{ 8^{2\sin 3x} . 4^{4\cos 3x} \right\}α=maxx∈R​{82sin3x.44cos3x} and β=min⁡x∈R{82sin⁡3x.44cos⁡3x}\beta = \min_{x \in R} \left\{ 8^{2\sin 3x} . 4^{4\cos 3x} \right\}β=minx∈R​{82sin3x.44cos3x}. If 8x2+bx+c=08x^2 + bx + c = 08x2+bx+c=0 is a quadratic equation whose roots are α1/5\alpha^{1/5}α1/5 and β1/5\beta^{1/5}β1/5, then the value of c − b is equal to :
  1. (A)42
  2. (B)43
  3. (C)47
  4. (D)50

Correct answer: (A)

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Q123·MathematicsSingle correctJEE Main 2021
Let α,β\alpha,\betaα,β be two roots of the equation x2+(20)14x+(5)12=0x^2+\left(20\right)^{\frac{1}{4}}x+\left(5\right)^{\frac{1}{2}}=0x2+(20)41​x+(5)21​=0 Then α8+β8\alpha^8+\beta^8α8+β8 is equal to :
  1. (A)50
  2. (B)100
  3. (C)10
  4. (D)160

Correct answer: (A)

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Q124·MathematicsNumericalJEE Main 2021
The number of real roots of the equation e4xe^{4x}e4x − e3xe^{3x}e3x − 4e2x4e^{2x}4e2x − exe^{x}ex + 1 = 0 is equal to…………

Correct answer: 2

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Q125·MathematicsNumericalJEE Main 2021
If α,β\alpha, \betaα,β are roots of the equation x2+5(2)x+10=0x^2 + 5\left( \sqrt{2} \right)x + 10 = 0x2+5(2​)x+10=0, α>β\alpha > \betaα>β and Pn=αn−βnP_n = \alpha^n - \beta^nPn​=αn−βn for each positive integer n, then the value of (P17P20+52P17P19P18P19+52P182)\left( \frac{P_{17}P_{20} + 5\sqrt{2}P_{17}P_{19}}{P_{18}P_{19} + 5\sqrt{2}P_{18}^2} \right)(P18​P19​+52​P182​P17​P20​+52​P17​P19​​) is equal to..........

Correct answer: 1

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Q126·MathematicsSingle correctJEE Main 2021
The number of real solutions of the equation, x2−∣x∣−12=0x^2 - \left|x\right| - 12 = 0x2−∣x∣−12=0 is :
  1. (A)1
  2. (B)4
  3. (C)3
  4. (D)2

Correct answer: (D)

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Q127·MathematicsNumericalJEE Main 2021
If a + b + c = 1, ab + bc + ca = 2 and abc = 3, then the value of a4+b4+c4a^{4} + b^{4} + c^{4}a4+b4+c4 is equal to.....

Correct answer: 13

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Q128·MathematicsSingle correctJEE Main 2021
The number of real roots of the equation e6x−e4x−2e3x−12e2x+ex+1=0e^{6x} - e^{4x} - 2e^{3x} - 12e^{2x} + e^{x} + 1 = 0e6x−e4x−2e3x−12e2x+ex+1=0 is :
  1. (A)1
  2. (B)4
  3. (C)2
  4. (D)6

Correct answer: (C)

Step-by-step solution →
Q129·MathematicsSingle correctJEE Main 2021
If α\alphaα and β\betaβ are the distinct roots of the equation x2+(3)14x+312=0x^2+\left(3\right)^{\frac{1}{4}}x+3^{\frac{1}{2}} = 0x2+(3)41​x+321​=0, then the value of α96(α12−1)+β96(β12−1)\alpha^{96}\left(\alpha^{12}-1\right)+\beta^{96}\left(\beta^{12}-1\right)α96(α12−1)+β96(β12−1) is equal to :
  1. (A)56×32556 \times 3^{25}56×325
  2. (B)28×32528 \times 3^{25}28×325
  3. (C)52×32452 \times 3^{24}52×324
  4. (D)56×32456 \times 3^{24}56×324

Correct answer: (C)

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Q130·MathematicsNumericalJEE Main 2021
The number of solutions of the equation log⁡(x+1)(2x2+7x+5)+log⁡(2x+5)(x+1)2−4=0\log_{(x+1)}\left(2x^{2}+7x+5\right)+\log_{(2x+5)}(x+1)^{2}-4=0log(x+1)​(2x2+7x+5)+log(2x+5)​(x+1)2−4=0, x>0x>0x>0, is………

Correct answer: 1

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Q131·MathematicsSingle correctJEE Main 2021
The probability of selecting integers a∈[−5,30]a \in [-5, 30]a∈[−5,30] such that x2+2(a+4)x−5a+64>0x^2+2(a+4)x-5a+64 > 0x2+2(a+4)x−5a+64>0, for all x∈Rx \in Rx∈R is :
  1. (A)29\frac{2}{9}92​
  2. (B)16\frac{1}{6}61​
  3. (C)736\frac{7}{36}367​
  4. (D)14\frac{1}{4}41​

Correct answer: (A)

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Q132·MathematicsSingle correctJEE Main 2021
The value of 3+14+13+14+13+...∞3 + \cfrac{1}{4 + \cfrac{1}{3 + \cfrac{1}{4 + \cfrac{1}{3 + ...\infty}}}}3+4+3+4+3+...∞1​1​1​1​ is equal to
  1. (A)1.5+31.5 + \sqrt{3}1.5+3​
  2. (B)2+32 + \sqrt{3}2+3​
  3. (C)3+233 + 2\sqrt{3}3+23​
  4. (D)4+34 + \sqrt{3}4+3​

Correct answer: (A)

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Q133·MathematicsSingle correctJEE Main 2021
The number of elements in the set {x ∈ ℝ : (|x| − 3) |x + 4| = 6} is equal to
  1. (A)3
  2. (B)2
  3. (C)4
  4. (D)1

Correct answer: (B)

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Q134·MathematicsSingle correctJEE Main 2021
Let P(x)=x2+bx+cP(x)=x^{2}+bx+cP(x)=x2+bx+c be a quadratic polynomial with real coefficients such that ∫01P(x)dx=1\int\limits_{0}^{1}P(x)dx=10∫1​P(x)dx=1 and P(x) leaves remainder 5 when it is divided by (x−2)(x - 2)(x−2). Then the value of 9(b+c)9(b + c)9(b+c) is equal to:
  1. (A)999
  2. (B)151515
  3. (C)777
  4. (D)111111

Correct answer: (C)

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Q135·MathematicsNumericalJEE Main 2021
The number of solutions of the equation log⁡4(x−1)=log⁡2(x−3)\log_{4}(x-1)=\log_{2}(x-3)log4​(x−1)=log2​(x−3) is _______.

Correct answer: 1

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Q136·MathematicsNumericalJEE Main 2021
Let α\alphaα and β\betaβ be two real numbers such that α+β=1\alpha + \beta = 1α+β=1 and αβ=−1\alpha\beta = -1αβ=−1. Let Pn=(α)n+(β)nP_{n} = (\alpha)^{n} + (\beta)^{n}Pn​=(α)n+(β)n, Pn−1=11P_{n-1} = 11Pn−1​=11 and Pn+1=29P_{n+1} = 29Pn+1​=29 for some integer n≥1n \geq 1n≥1. Then, the value of Pn2P_{n}^{2}Pn2​ is ________________.

Correct answer: 324

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Q137·MathematicsSingle correctJEE Main 2021
Let α and β be the roots of x2^{2}2 – 6x – 2 = 0. If an = αn^{n}n – βn^{n}n for n ≥ 1, then the value of a10^{10}10– 2a8^{8}8 3a9_{9}9​ is:
  1. (A)4
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q138·MathematicsSingle correctJEE Main 2021
The integer 'k', for which the inequality x2−2(3k−1)x+8k2−7>0x^{2} - 2(3k - 1)x + 8k^{2} - 7 > 0x2−2(3k−1)x+8k2−7>0 is valid for every x in R is :
  1. (A)333
  2. (B)222
  3. (C)444
  4. (D)000

Correct answer: (A)

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Q139·MathematicsSingle correctJEE Main 2021
Let a, b, c be in arithmetic progression. Let the centroid of the triangle with vertices (a,c),(2,b)(a,c),(2,b)(a,c),(2,b) and (a,b)(a,b)(a,b) be (103,73)\left(\frac{10}{3},\frac{7}{3}\right)(310​,37​). If α,β\alpha,\betaα,β are the roots of the equation ax2+bx+1=0ax^{2}+bx+1=0ax2+bx+1=0, then the value of α2+β2−αβ\alpha^{2}+\beta^{2}-\alpha\betaα2+β2−αβ is:
  1. (A)71256\frac{71}{256}25671​
  2. (B)−69256-\frac{69}{256}−25669​
  3. (C)69256\frac{69}{256}25669​
  4. (D)−71256-\frac{71}{256}−25671​

Correct answer: (D)

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Q140·MathematicsSingle correctJEE Main 2021
Let p and q be two positive number such that p+q=2p + q = 2p+q=2 and p4+q4=272p^4 + q^4 = 272p4+q4=272. Then p and q are roots of the equation :
  1. (A)x2−2x+2=0x^2 - 2x + 2 = 0x2−2x+2=0
  2. (B)x2−2x+8=0x^2 - 2x + 8 = 0x2−2x+8=0
  3. (C)x2−2x+136=0x^2 - 2x + 136 = 0x2−2x+136=0
  4. (D)x2−2x+16=0x^2 - 2x + 16 = 0x2−2x+16=0

Correct answer: (D)

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Q141·MathematicsNumericalJEE Main 2021
The number of the real roots of the equation (x+1)2+∣x−5∣=274(x+1)^{2}+|x-5|=\frac{27}{4}(x+1)2+∣x−5∣=427​ is________.

Correct answer: 2

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Q142·MathematicsSingle correctJEE Advanced 2020
Suppose a, b denote the distinct real roots of the quadratic polynomial x2+20x−2020x^{2} + 20x - 2020x2+20x−2020 and suppose c,d denote the distinct complex roots of the quadratic polynomial x2−20x+2020x^{2} - 20x + 2020x2−20x+2020. Then the value of ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d)ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d) is
  1. (A)000
  2. (B)800080008000
  3. (C)808080808080
  4. (D)160001600016000

Correct answer: (D)

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Q143·MathematicsSingle correctJEE Main 2020
If α\alphaα and β\betaβ are the roots of the equation 2x(2x+1)=12x(2x + 1) = 12x(2x+1)=1, then β\betaβ is equal to:
  1. (A)2α(α+1)2\alpha(\alpha + 1)2α(α+1)
  2. (B)−2α(α+1)-2\alpha(\alpha + 1)−2α(α+1)
  3. (C)2α(α−1)2\alpha(\alpha - 1)2α(α−1)
  4. (D)2α22\alpha^{2}2α2

Correct answer: (B)

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Q144·MathematicsSingle correctJEE Main 2020
If α\alphaα and β\betaβ are the roots of the equation, 7x2−3x−2=07x^2-3x-2=07x2−3x−2=0, then the value of α1−α2+β1−β2\dfrac{\alpha}{1-\alpha^2}+\dfrac{\beta}{1-\beta^2}1−α2α​+1−β2β​ is equal to:
  1. (A)2732\dfrac{27}{32}3227​
  2. (B)2716\dfrac{27}{16}1627​
  3. (C)38\dfrac{3}{8}83​
  4. (D)124\dfrac{1}{24}241​

Correct answer: (B)

Step-by-step solution →
Q145·MathematicsSingle correctJEE Main 2020
The product of the roots of the equation 9x2−18∣x∣+5=09x^{2} - 18|x| + 5 = 09x2−18∣x∣+5=0, is:
  1. (A)59\dfrac{5}{9}95​
  2. (B)259\dfrac{25}{9}925​
  3. (C)527\dfrac{5}{27}275​
  4. (D)2581\dfrac{25}{81}8125​

Correct answer: (D)

Step-by-step solution →
Q146·MathematicsSingle correctJEE Main 2020
Let λ≠0\lambda \neq 0λ=0 be in R. If α\alphaα and β\betaβ are the roots of the equation, x2−x+2λ=0x^{2} - x + 2\lambda = 0x2−x+2λ=0 and α\alphaα and γ\gammaγ are the roots of the equation, 3x2−10x+27λ=03x^{2} - 10x + 27\lambda = 03x2−10x+27λ=0, then βγλ\frac{\beta\gamma}{\lambda}λβγ​ is equal to:
  1. (A)18
  2. (B)36
  3. (C)9
  4. (D)27

Correct answer: (A)

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Q147·MathematicsSingle correctJEE Main 2020
Let α\alphaα and β\betaβ be roots of x2−3x+p=0x^{2} - 3x + p = 0x2−3x+p=0 and γ\gammaγ and δ\deltaδ be the roots of x2−6x+q=0x^{2} - 6x + q = 0x2−6x+q=0. If α\alphaα, β\betaβ, γ\gammaγ, δ\deltaδ, form a geometric progression. Then ratio (2q+p):(2q−p)(2q + p) : (2q - p)(2q+p):(2q−p) is:
  1. (A)33:3133 : 3133:31
  2. (B)5:35 : 35:3
  3. (C)3:13 : 13:1
  4. (D)9:79 : 79:7

Correct answer: (D)

Step-by-step solution →
Q148·MathematicsSingle correctJEE Main 2020
The set of all real values of λ\lambdaλ for which the quadratic equations, (λ2+1)x2−4λx+2=0\left(\lambda^2 + 1\right)x^2 - 4\lambda x + 2 = 0(λ2+1)x2−4λx+2=0 always have exactly one root in the interval (0, 1) is:
  1. (A)(0,2)(0, 2)(0,2)
  2. (B)(2,4](2, 4](2,4]
  3. (C)(−3,−1)(-3, -1)(−3,−1)
  4. (D)(1,3](1, 3](1,3]

Correct answer: (D)

Step-by-step solution →
Q149·MathematicsSingle correctJEE Main 2020
Let a,b∈R,a≠0a, b \in R, a \neq 0a,b∈R,a=0 be such that the equation ax2−2bx+5=0ax^{2} - 2bx + 5 = 0ax2−2bx+5=0 has a repeated root α\alphaα, which is also a root of the equation, x2−2bx−10=0x^{2} - 2bx - 10 = 0x2−2bx−10=0. If β\betaβ is the other root of this equation, then α2+β2\alpha^{2} + \beta^{2}α2+β2 is equal to:
  1. (A)28
  2. (B)24
  3. (C)26
  4. (D)25

Correct answer: (D)

Step-by-step solution →
Q150·MathematicsSingle correctJEE Main 2020
The number of real roots of the equation, e4x+e3x−4e2x+ex+1=0e^{4x}+e^{3x}-4e^{2x}+e^{x}+1=0e4x+e3x−4e2x+ex+1=0 is:
  1. (A)2
  2. (B)4
  3. (C)3
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q151·MathematicsNumericalJEE Main 2020
The least positive value of 'a' for which the equation, 2x2+(a−10)x+332=2a2x^{2}+(a-10)x+\dfrac{33}{2}=2a2x2+(a−10)x+233​=2a has real root is

Correct answer: 8

Step-by-step solution →
Q152·MathematicsSingle correctJEE Main 2020
Let S be the set of all real roots of the equation, 3x(3x−1)+2=∣3x−1∣+∣3x−2∣3^{x}\left(3^{x}-1\right)+2=\left|3^{x}-1\right|+\left|3^{x}-2\right|3x(3x−1)+2=∣3x−1∣+∣3x−2∣. Then S:
  1. (A)contains at least four elements
  2. (B)is a singleton
  3. (C)is an empty set
  4. (D)contains exactly two elements

Correct answer: (B)

Step-by-step solution →
Q153·MathematicsSingle correctJEE Main 2020
Let α\alphaα and β\betaβ be two real roots of the equation (k+1)tan⁡2x−2.λtan⁡x=(1−k)(k+1)\tan^{2}x - \sqrt{2}.\lambda \tan x = (1-k)(k+1)tan2x−2​.λtanx=(1−k), where k(≠−1)k(\ne -1)k(=−1) and λ\lambdaλ are real numbers. If tan⁡2(α+β)=50\tan^{2}(\alpha+\beta) = 50tan2(α+β)=50, then a value of λ\lambdaλ is:
  1. (A)10
  2. (B)5
  3. (C)525\sqrt{2}52​
  4. (D)10210\sqrt{2}102​

Correct answer: (A)

Step-by-step solution →
Q154·MathematicsSingle correctJEE Main 2020
Let α\alphaα and β\betaβ be the roots of the equation x2−x−1=0x^{2}-x-1=0x2−x−1=0. If Pk=(α)k+(β)k,k≥1P_{k}=(\alpha)^{k}+(\beta)^{k}, k \ge 1Pk​=(α)k+(β)k,k≥1, then which one of the following statements is not true?
  1. (A)p5=11p_{5}=11p5​=11
  2. (B)(p1+p2+p3+p4+p5)=26(p_{1}+p_{2}+p_{3}+p_{4}+p_{5})=26(p1​+p2​+p3​+p4​+p5​)=26
  3. (C)p3=p5−p4p_{3}=p_{5}-p_{4}p3​=p5​−p4​
  4. (D)p5=p2.p3p_{5}=p_{2}.p_{3}p5​=p2​.p3​

Correct answer: (D)

Step-by-step solution →
Q155·MathematicsSingle correctJEE Main 2019
If α\alphaα, β\betaβ and γ\gammaγ are three consecutive terms of a non-constant G.P. such that the equations αx2+2βx+γ=0\alpha x^{2} + 2\beta x + \gamma = 0αx2+2βx+γ=0 and x2+x−1=0x^{2} + x - 1 = 0x2+x−1=0 have a common root, then α(β+γ)\alpha(\beta+\gamma)α(β+γ) is equal to :
  1. (A)αγ\alpha\gammaαγ
  2. (B)0
  3. (C)αβ\alpha\betaαβ
  4. (D)βγ\beta\gammaβγ

Correct answer: (D)

Step-by-step solution →
Q156·MathematicsSingle correctJEE Main 2019
If α and β are the roots of the quadratic equation, x2^{2}2 + x sinθ − 2sinθ = 0, θ ∈ (0, π2\frac{\pi}{2}2π​) then α12+β12(α−12+β−12)(α−β)24\frac{\alpha^{12}+\beta^{12}}{(\alpha^{-12}+\beta^{-12})(\alpha-\beta)^{24}}(α−12+β−12)(α−β)24α12+β12​ is equal to:
  1. (A)212(sin⁡θ+8)12\frac{2^{12}}{(\sin\theta+8)^{12}}(sinθ+8)12212​
  2. (B)212(sin⁡θ−4)12\frac{2^{12}}{(\sin\theta-4)^{12}}(sinθ−4)12212​
  3. (C)212(sin⁡θ−8)6\frac{2^{12}}{(\sin\theta-8)^{6}}(sinθ−8)6212​
  4. (D)26(sin⁡θ+8)12\frac{2^{6}}{(\sin\theta+8)^{12}}(sinθ+8)1226​

Correct answer: (A)

Step-by-step solution →
Q157·MathematicsSingle correctJEE Main 2019
The number of real roots of the equation 5+∣2x−1∣=2x(2x−2)5 + |2^{x} - 1| = 2^{x}(2^{x} - 2)5+∣2x−1∣=2x(2x−2) is
  1. (A)4
  2. (B)3
  3. (C)2
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q158·MathematicsSingle correctJEE Main 2019
If m is chosen in the quadratic equation (m2+1)x2−3x+(m2+1)2=0\left(m^{2}+1\right)x^{2}-3x+\left(m^{2}+1\right)^{2}=0(m2+1)x2−3x+(m2+1)2=0 such that the sum of its roots is greatest, then the absolute difference of the cubes of its roots is:
  1. (A)838\sqrt{3}83​
  2. (B)434\sqrt{3}43​
  3. (C)10510\sqrt{5}105​
  4. (D)858\sqrt{5}85​

Correct answer: (D)

Step-by-step solution →
Q159·MathematicsSingle correctJEE Main 2019
The number of integral values of m for which the equation (1+m2)x2−2(1+3m)x+(1+8m)=0\left(1+m^{2}\right)x^{2}-2(1+3m)x+(1+8m)=0(1+m2)x2−2(1+3m)x+(1+8m)=0 has no real root is:
  1. (A)infinitely many
  2. (B)2
  3. (C)3
  4. (D)1

Correct answer: (A)

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Q160·MathematicsSingle correctJEE Main 2019
The sum of the solutions of the equation ∣x−2∣+x(x−4)+2=0\left|\sqrt{x}-2\right|+\sqrt{x}\left(\sqrt{x}-4\right)+2=0∣x​−2∣+x​(x​−4)+2=0, (x>0)(x>0)(x>0) is equal to:
  1. (A)999
  2. (B)444
  3. (C)101010
  4. (D)121212

Correct answer: (C)

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Q161·MathematicsSingle correctJEE Main 2019
If λ\lambdaλ be the ratio of the roots of the quadratic equation in x, 3m2x2+m(m−4)x+2=03m^{2}x^{2}+m(m-4)x+2=03m2x2+m(m−4)x+2=0, then the least value of m for which λ+1λ=1\lambda+\frac{1}{\lambda}=1λ+λ1​=1, is:
  1. (A)2−32-\sqrt{3}2−3​
  2. (B)4−324-3\sqrt{2}4−32​
  3. (C)−2+2-2+\sqrt{2}−2+2​
  4. (D)4−234-2\sqrt{3}4−23​

Correct answer: (B)

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Q162·MathematicsSingle correctJEE Main 2019
The number of integral values of m for which the quadratic expression, (1+2m)x2−2(1+3m)x+4(1+m)(1 + 2m)x^{2} - 2(1 + 3m)x + 4(1 + m)(1+2m)x2−2(1+3m)x+4(1+m), x∈Rx \in Rx∈R, is always positive, is :
  1. (A)3
  2. (B)8
  3. (C)7
  4. (D)6

Correct answer: (C)

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Q163·MathematicsSingle correctJEE Main 2019
If one real root of the quadratic equation 81x2+kx+256=081x^{2}+kx+256=081x2+kx+256=0 is cube of the other root, then a value of k is:
  1. (A)− 81
  2. (B)100
  3. (C)144
  4. (D)− 300

Correct answer: (D)

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Q164·MathematicsSingle correctJEE Main 2019
Let α and β be the roots of the quadratic equation x2sin⁡θ−x(sin⁡θcos⁡θ+1)+cos⁡θ=0  (0<θ<450)x^{2}\sin\theta-x\left(\sin\theta\cos\theta+1\right)+\cos\theta=0\;\left(0<\theta<45^{0}\right)x2sinθ−x(sinθcosθ+1)+cosθ=0(0<θ<450), and α < β. Then ∑n=0∞(αn+(−1)nβn)\displaystyle\sum_{n=0}^{\infty}\left(\alpha^{n}+\dfrac{(-1)^{n}}{\beta^{n}}\right)n=0∑∞​(αn+βn(−1)n​) is equal to:
  1. (A)11−cos⁡θ−11+sin⁡θ\dfrac{1}{1-\cos\theta}-\dfrac{1}{1+\sin\theta}1−cosθ1​−1+sinθ1​
  2. (B)11+cos⁡θ+11−sin⁡θ\dfrac{1}{1+\cos\theta}+\dfrac{1}{1-\sin\theta}1+cosθ1​+1−sinθ1​
  3. (C)11−cos⁡θ+11+sin⁡θ\dfrac{1}{1-\cos\theta}+\dfrac{1}{1+\sin\theta}1−cosθ1​+1+sinθ1​
  4. (D)11+cos⁡θ−11−sin⁡θ\dfrac{1}{1+\cos\theta}-\dfrac{1}{1-\sin\theta}1+cosθ1​−1−sinθ1​

Correct answer: (C)

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Q165·MathematicsSingle correctJEE Main 2019
The number of all possible positive integral values of α\alphaα for which the roots of the quadratic equation, 6x2−11x+α=06x^{2} - 11x + \alpha = 06x2−11x+α=0 are rational numbers is:
  1. (A)2
  2. (B)5
  3. (C)3
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q166·MathematicsSingle correctJEE Advanced 2017
PARAGRAPH 2 Let ppp, qqq be integers and let α\alphaα, β\betaβ be the roots of the equation x2−x−1=0x^{2} - x - 1 = 0x2−x−1=0, where α≠β\alpha \ne \betaα=β. For n=0,1,2,…n = 0, 1, 2, \dotsn=0,1,2,…, let an=pαn+qβna_{n} = p\alpha^{n} + q\beta^{n}an​=pαn+qβn. FACT: If aaa and bbb are rational numbers and a+b5=0a + b\sqrt{5} = 0a+b5​=0, then a=0=ba = 0 = ba=0=b. If a4=28a_{4} = 28a4​=28, then p+2q=p + 2q =p+2q=
  1. (A)212121
  2. (B)141414
  3. (C)777
  4. (D)121212

Correct answer: (D)

Step-by-step solution →
Q167·MathematicsSingle correctJEE Advanced 2016
Let −π6<θ<−π12-\frac{\pi}{6} < \theta < -\frac{\pi}{12}−6π​<θ<−12π​. Suppose α1\alpha_1α1​ and β1\beta_1β1​ are the roots of the equation x2−2xsec⁡θ+1=0x^{2} - 2x\sec\theta + 1 = 0x2−2xsecθ+1=0 and α2\alpha_2α2​ and β2\beta_2β2​ are the roots of the equation x2+2xtan⁡θ−1=0x^{2} + 2x\tan\theta - 1 = 0x2+2xtanθ−1=0. If α1>β1\alpha_1 > \beta_1α1​>β1​ and α2>β2\alpha_2 > \beta_2α2​>β2​, then α1+β2\alpha_1 + \beta_2α1​+β2​ equals
  1. (A)2(sec⁡θ−tan⁡θ)2(\sec\theta - \tan\theta)2(secθ−tanθ)
  2. (B)2sec⁡θ2\sec\theta2secθ
  3. (C)−2tan⁡θ-2\tan\theta−2tanθ
  4. (D)000

Correct answer: (C)

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Q168·MathematicsMultiple correctJEE Advanced 2015
Let SSS be the set of all non-zero real numbers α\alphaα such that the quadratic equation αx2−x+α=0\alpha x^{2} - x + \alpha = 0αx2−x+α=0 has two distinct real roots x1x_{1}x1​ and x2x_{2}x2​ satisfying the inequality ∣x1−x2∣<1\left|x_{1} - x_{2}\right| < 1∣x1​−x2​∣<1. Which of the following intervals is(are) a subset(s) of SSS ?
  1. (A)(−12,−15)\left(-\dfrac{1}{2}, -\dfrac{1}{\sqrt{5}}\right)(−21​,−5​1​)
  2. (B)(−15,0)\left(-\dfrac{1}{\sqrt{5}}, 0\right)(−5​1​,0)
  3. (C)(0,15)\left(0, \dfrac{1}{\sqrt{5}}\right)(0,5​1​)
  4. (D)(15,12)\left(\dfrac{1}{\sqrt{5}}, \dfrac{1}{2}\right)(5​1​,21​)

Correct answer: (A), (D)

Step-by-step solution →
Q169·MathematicsMultiple correctJEE Advanced 2014
Let a∈Ra \in \mathbb{R}a∈R and let f:R→Rf: \mathbb{R} \to \mathbb{R}f:R→R be given by f(x)=x5−5x+af(x) = x^5 - 5x + af(x)=x5−5x+a, then
  1. (A)f(x)f(x)f(x) has three real roots if a>4a > 4a>4
  2. (B)f(x)f(x)f(x) has only one real roots if a>4a > 4a>4
  3. (C)f(x)f(x)f(x) has three real roots if a<−4a < -4a<−4
  4. (D)f(x)f(x)f(x) has three real roots if −4<a<4-4 < a < 4−4<a<4

Correct answer: (B), (D)

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Q170·MathematicsSingle correctJEE Advanced 2014
The quadratic equation p(x)=0p(x) = 0p(x)=0 with real coefficients has purely imaginary roots. Then the equation p(p(x))=0p(p(x)) = 0p(p(x))=0 has
  1. (A)only purely imaginary roots
  2. (B)all real roots
  3. (C)two real and two purely imaginary roots
  4. (D)neither real nor purely imaginary roots

Correct answer: (D)

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Quadratic Equations — frequently asked

How many questions from Quadratic Equations appear in JEE?

Quadratic Equations has appeared in 148 of the last 186 JEE Main and JEE Advanced papers — about 80% of them — contributing 170 questions in total across those papers.

Is Quadratic Equations an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 80% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Quadratic Equations questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Mathematics chapters

  • Three Dimensional Geometry 344
  • Matrices and Determinants 342
  • Sets, Relations and Functions 313
  • Sequence and Series 287
  • Definite Integration 267
  • Vector Algebra 245
  • Differential Equations 240
  • Probability 226

All 26 Mathematics chapters →

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