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Straight Lines — JEE Previous Year Questions

Every Straight Lines question asked in JEE Main and JEE Advanced across the last 186 papers — 137 questions, each with its correct answer. Free to read, no account needed.

Questions

137

Papers it appeared in

114/186

Appearance rate

61%

All 137 Straight Lines questions

Most recent papers first.

Q1·MathematicsSingle correctJEE Main 2026
If a straight line drawn through the point of intersection of the lines 4x+3y−1=04x + 3y - 1 = 04x+3y−1=0 and 3x+4y−1=03x + 4y - 1 = 03x+4y−1=0, meets the co-ordinate axes at the points P and Q, then the locus of the mid point of PQ is:
  1. (A)x+y−7=0x + y - 7 = 0x+y−7=0
  2. (B)x+y−14xy=0x + y - 14xy = 0x+y−14xy=0
  3. (C)2x+y+14xy=02x + y + 14xy = 02x+y+14xy=0
  4. (D)x+2y−14xy=0x + 2y - 14xy = 0x+2y−14xy=0

Correct answer: (B)

Step-by-step solution →
Q2·MathematicsNumericalJEE Main 2026
From the point (−1, −1), two rays are sent making angles of 45° with the line x + y = 0. These rays get reflected from the mirror x + 2y = 1. If the equations of the reflected rays are ax + by = 9 and cx + dy = 7, a, b, c, d ∈ ℤ, then the value of ad + bc is _______.

Correct answer: 7

Step-by-step solution →
Q3·MathematicsSingle correctJEE Main 2026
In an equilateral triangle PQRPQRPQR, let the vertex PPP be at (3,5)(3,5)(3,5) and the side QRQRQR be along the line x+y=4x + y = 4x+y=4. If the orthocentre of the triangle PQRPQRPQR is (α,β)(\alpha, \beta)(α,β), then 9(α+β)9(\alpha + \beta)9(α+β) is equal to:
  1. (A)16
  2. (B)27
  3. (C)36
  4. (D)48

Correct answer: (D)

Step-by-step solution →
Q4·MathematicsNumericalJEE Main 2026
Let A,BA, BA,B be points on the two half-lines x−3∣y∣=αx - \sqrt{3}|y| = \alphax−3​∣y∣=α, α>0\alpha > 0α>0 at a distance of α from their point of intersection PPP. The line segment ABABAB meets the angle bisector of the given half-lines at the point QQQ. If PQ=92PQ = \frac{9}{2}PQ=29​ and RRR is the radius of the circumcircle of △PAB\triangle PAB△PAB, then α2R\frac{\alpha^{2}}{R}Rα2​ is equal to ______

Correct answer: 9

Step-by-step solution →
Q5·MathematicsSingle correctJEE Main 2026
Let the line L1:x+3=0L_1 : x + 3 = 0L1​:x+3=0 intersect the lines L2:x−y=0L_2 : x - y = 0L2​:x−y=0 and L3:3x+y=0L_3 : 3x + y = 0L3​:3x+y=0 at the points AAA and BBB, respectively. Let the bisector of the obtuse angle between the lines L2L_2L2​ and L3L_3L3​ intersect the line L1L_1L1​ at the point CCC. Then BC2:AC2BC^2 : AC^2BC2:AC2 is equal to:
  1. (A)5:15 : 15:1
  2. (B)1:51 : 51:5
  3. (C)2:32 : 32:3
  4. (D)3:23 : 23:2

Correct answer: (A)

Step-by-step solution →
Q6·MathematicsSingle correctJEE Main 2026
Let the vertex AAA of a triangle ABCABCABC be (1,2)(1, 2)(1,2), and the mid-point of the side ABABAB be (5,−1)(5, -1)(5,−1). If the centroid of this triangle is (3,4)(3, 4)(3,4) and its circumcenter is (α,β)(\alpha, \beta)(α,β), then 21(α+β)21(\alpha + \beta)21(α+β) is equal to:
  1. (A)309309309
  2. (B)403403403
  3. (C)497497497
  4. (D)524524524

Correct answer: (C)

Step-by-step solution →
Q7·MathematicsSingle correctJEE Main 2026
Let the mid points of the sides of a triangle ABC be (52,7)\left(\frac{5}{2},7\right)(25​,7), (52,3)\left(\frac{5}{2},3\right)(25​,3) and (4,5)(4,5)(4,5). If its incentre is (h,k)(h,k)(h,k), then 3h+k3h+k3h+k is equal to :
  1. (A)11
  2. (B)12
  3. (C)13
  4. (D)14

Correct answer: (C)

Step-by-step solution →
Q8·MathematicsSingle correctJEE Main 2026
Let ABC be an equilateral triangle with orthocenter at the origin and the side BC on the line x+22 y=4x + 2\sqrt{2}\,y = 4x+22​y=4. If the co-ordinates of the vertex A are (α,β)(\alpha, \beta)(α,β), then the greatest integer less than or equal to ∣α+2 β∣\left|\alpha + \sqrt{2}\,\beta\right|​α+2​β​ is
  1. (A)2
  2. (B)3
  3. (C)5
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q9·MathematicsSingle correctJEE Main 2026
Let the angles made with the positive x-axis by two straight lines drawn from the point P(2, 3) and meeting the line x+y=6x + y = 6x+y=6 at a distance 23\sqrt{\frac{2}{3}}32​​ from the point P be θ1\theta_{1}θ1​ and θ2\theta_{2}θ2​. Then the value of (θ1+θ2)(\theta_{1} + \theta_{2})(θ1​+θ2​) is :
  1. (A)π12\frac{\pi}{12}12π​
  2. (B)π6\frac{\pi}{6}6π​
  3. (C)π2\frac{\pi}{2}2π​
  4. (D)π3\frac{\pi}{3}3π​

Correct answer: (C)

Step-by-step solution →
Q10·MathematicsSingle correctJEE Main 2026
Let A(1, 0), B(2, −1) and C(73,43)C\left(\frac{7}{3},\frac{4}{3}\right)C(37​,34​) be three points. If the equation of the bisector of the angle ABC is αx+βy=5\alpha x+\beta y=5αx+βy=5, then the value of α2+β2\alpha^{2}+\beta^{2}α2+β2 is
  1. (A)888
  2. (B)555
  3. (C)131313
  4. (D)101010

Correct answer: (D)

Step-by-step solution →
Q11·MathematicsSingle correctJEE Main 2026
Let A(1, 2) and C(−3, −6) be two diagonally opposite vertices of a rhombus, whose sides AD an BC are parallel to the line 7x−y=147x - y = 147x−y=14. If B (α\alphaα, β\betaβ) and D(γ\gammaγ, δ\deltaδ) are the other two vertices, then ∣α+β+γ+δ∣|\alpha + \beta + \gamma + \delta|∣α+β+γ+δ∣ is equal to :
  1. (A)9
  2. (B)3
  3. (C)6
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q12·MathematicsSingle correctJEE Main 2026
A rectangle is formed by the lines x = 0, y = 0, x = 3 and y = 4. Let the line L be perpendicular to 3x + y + 6 = 0 and divide the area of the rectangle into two equal parts. Then the distance of the point (12,−5)\left(\frac{1}{2}, -5\right)(21​,−5) from the line L is equal to :
  1. (A)252\sqrt{5}25​
  2. (B)3103\sqrt{10}310​
  3. (C)10\sqrt{10}10​
  4. (D)2102\sqrt{10}210​

Correct answer: (D)

Step-by-step solution →
Q13·MathematicsSingle correctJEE Main 2026
Among the statements (S1) : If A(5, -1) and B(-2, 3) are two vertices of a triangle, whose orthocentre is (0, 0), then its third vertex is (-4, -7) and (S2) : If positive numbers 2a, b, c are three consecutive terms of an A.P., then the lines ax+by+c=0ax + by + c = 0ax+by+c=0 are concurrent at (2, -2),
  1. (A)Only (S1) is correct
  2. (B)Only (S2) is correct
  3. (C)Both are incorrect
  4. (D)Both are correct

Correct answer: (D)

Step-by-step solution →
Q14·MathematicsSingle correctJEE Main 2026
Let a point A lie between the parallel lines L1L_{1}L1​ and L2L_{2}L2​ such that its distances from L1L_{1}L1​ and L2L_{2}L2​ are 6 and 3 units, respectively. Then the area (in sq. units) of the equilateral triangle ABC, where the points B and C lie on the lines L1L_{1}L1​ and L2L_{2}L2​ respectively, is :
  1. (A)15615\sqrt{6}156​
  2. (B)27
  3. (C)21321\sqrt{3}213​
  4. (D)12212\sqrt{2}122​

Correct answer: (C)

Step-by-step solution →
Q15·MathematicsSingle correctJEE Main 2025
A line passing through the point P(a,0)P(a,0)P(a,0) makes an acute angle α\alphaα with the positive x-axis. Let this line be rotated about the point PPP through an angle α2\dfrac{\alpha}{2}2α​ in the clock-wise direction. If in the new position, the slope of the line is 2−32-\sqrt32−3​ and its distance from the origin is 12\dfrac{1}{\sqrt2}2​1​, then the value of 3a2tan⁡2α−233a^2\tan^2\alpha-2\sqrt33a2tan2α−23​ is:
  1. (A)444
  2. (B)666
  3. (C)555
  4. (D)888

Correct answer: (A)

Step-by-step solution →
Q16·MathematicsSingle correctJEE Main 2025
Let aaa be the length of a side of a square OABCOABCOABC with OOO being the origin. Its side OAOAOA makes an acute angle α\alphaα with the positive x-axis and the equations of its diagonals are (3+1)x+(3−1)y=0(\sqrt3+1)x+(\sqrt3-1)y=0(3​+1)x+(3​−1)y=0 and (3−1)x−(3+1)y+83=0(\sqrt3-1)x-(\sqrt3+1)y+8\sqrt3=0(3​−1)x−(3​+1)y+83​=0. Then a2a^2a2 is equal to:
  1. (A)484848
  2. (B)323232
  3. (C)161616
  4. (D)242424

Correct answer: (A)

Step-by-step solution →
Q17·MathematicsSingle correctJEE Main 2025
Let ABC be the triangle such that the equations of lines AB and AC be 3y−x=23y-x=23y−x=2 and x+y=2x+y=2x+y=2, respectively, and the points B and C lie on x-axis. If P is the orthocentre of the triangle ABC, then the area of the triangle PBC is equal to
  1. (A)4
  2. (B)10
  3. (C)8
  4. (D)6

Correct answer: (D)

Step-by-step solution →
Q18·MathematicsSingle correctJEE Main 2025
Consider the lines x(3λ+1)+y(7λ+2)=17λ+5x(3\lambda+1)+y(7\lambda+2)=17\lambda+5x(3λ+1)+y(7λ+2)=17λ+5, λ\lambdaλ being a parameter, and passing through a point PPP. One of these lines (say LLL) is farthest from the origin. If the distance of LLL from the point (3,6)(3,6)(3,6) is ddd, then the value of d2d^2d2 is:
  1. (A)20
  2. (B)30
  3. (C)10
  4. (D)15

Correct answer: (A)

Step-by-step solution →
Q19·MathematicsSingle correctJEE Main 2025
A line passes through the origin and makes equal angles with the positive coordinate axes. It intersects the lines L1:2x+y+6=0L_1:2x+y+6=0L1​:2x+y+6=0 and L2:4x+2y−p=0L_2:4x+2y-p=0L2​:4x+2y−p=0, at the points AAA and BBB, respectively. If AB=92AB=\dfrac{9}{\sqrt2}AB=2​9​ and the foot of the perpendicular from the point AAA on the line L2L_2L2​ is MMM, then AMBM\dfrac{AM}{BM}BMAM​ is equal to:
  1. (A)5
  2. (B)4
  3. (C)2
  4. (D)3

Correct answer: (D)

Step-by-step solution →
Q20·MathematicsIntegerJEE Main 2025
Let A(4,−2)A(4,-2)A(4,−2), B(1,1)B(1,1)B(1,1) and C(9,−3)C(9,-3)C(9,−3) be the vertices of a triangle. Then the maximum area of the parallelogram AFDE, formed with vertices D, E and F on the sides BC, CA and AB of the triangle ABC respectively, is ______.

Correct answer: 3

Step-by-step solution →
Q21·MathematicsSingle correctJEE Main 2025
Let the area of the triangle formed by a straight line L:x+by+c=0L:x+by+c=0L:x+by+c=0 with the co-ordinate axes be 48 square units. If the perpendicular drawn from the origin to the line LLL makes an angle of 45∘45^\circ45∘ with the positive x-axis, then the value of b2+c2b^2+c^2b2+c2 is:
  1. (A)90
  2. (B)93
  3. (C)97
  4. (D)83

Correct answer: (C)

Step-by-step solution →
Q22·MathematicsSingle correctJEE Main 2025
Let ABC be a triangle formed by the lines 7x−6y+3=07x-6y+3=07x−6y+3=0, x+2y−31=0x+2y-31=0x+2y−31=0 and 9x−2y−19=09x-2y-19=09x−2y−19=0. Let the point (h,k) be the image of the centroid of △ABC\triangle ABC△ABC in the line 3x+6y−53=03x+6y-53=03x+6y−53=0. Then h2+k2+hkh^2+k^2+hkh2+k2+hk is equal to
  1. (A)37
  2. (B)47
  3. (C)40
  4. (D)36

Correct answer: (A)

Step-by-step solution →
Q23·MathematicsSingle correctJEE Main 2025
Let the line x+y=1x+y=1x+y=1 meet the axes of x and y at A and B, respectively. A right angled triangle AMN is inscribed in the triangle OAB, where O is the origin and the points M and N lie on the lines OB and AB, respectively. If the area of the triangle AMN is 49\dfrac{4}{9}94​ of the area of the triangle OAB and AN:NB=λ:1AN:NB=\lambda:1AN:NB=λ:1, then the sum of all possible value(s) of λ\lambdaλ is:
  1. (A)12\dfrac{1}{2}21​
  2. (B)136\dfrac{13}{6}613​
  3. (C)52\dfrac{5}{2}25​
  4. (D)2

Correct answer: (D)

Step-by-step solution →
Q24·MathematicsSingle correctJEE Main 2025
Two equal sides of an isosceles triangle are along −x+2y=4-x+2y=4−x+2y=4 and x+y=4x+y=4x+y=4. If m is the slope of its third side, then the sum, of all possible distinct values of m, is:
  1. (A)-6
  2. (B)12
  3. (C)6
  4. (D)−210-2\sqrt{10}−210​

Correct answer: (C)

Step-by-step solution →
Q25·MathematicsSingle correctJEE Main 2025
Let nCr−1=28^nC_{r-1}=28nCr−1​=28, nCr=56^nC_r=56nCr​=56 and nCr+1=70^nC_{r+1}=70nCr+1​=70. Let A(4cos⁡t,4sin⁡t)A(4\cos t, 4\sin t)A(4cost,4sint), B(2sin⁡t,−2cos⁡t)B(2\sin t, -2\cos t)B(2sint,−2cost) and C(3r−n,r2−n−1)C(3r-n, r^2-n-1)C(3r−n,r2−n−1) be the vertices of a triangle ABC, where t is a parameter. If (3x−1)2+(3y)2=α(3x-1)^2+(3y)^2=\alpha(3x−1)2+(3y)2=α, is the locus of the centroid of triangle ABC, then α\alphaα equals:
  1. (A)20
  2. (B)8
  3. (C)6
  4. (D)18

Correct answer: (A)

Step-by-step solution →
Q26·MathematicsSingle correctJEE Main 2025
Let ABCD be a trapezium whose vertices lie on the parabola y2=4xy^2=4xy2=4x. Let the sides AD and BC of the trapezium be parallel to y-axis. If the diagonal AC is of length 254\frac{25}{4}425​ and it passes through the point (1,0)(1, 0)(1,0), then the area of ABCD is:
  1. (A)754\frac{75}{4}475​
  2. (B)252\frac{25}{2}225​
  3. (C)1258\frac{125}{8}8125​
  4. (D)758\frac{75}{8}875​

Correct answer: (A)

Step-by-step solution →
Q27·MathematicsSingle correctJEE Main 2025
Let the points (112,α)\left(\dfrac{11}{2},\alpha\right)(211​,α) lie on or inside the triangle with sides x+y=11x+y=11x+y=11, x+2y=16x+2y=16x+2y=16 and 2x+3y=292x+3y=292x+3y=29. Then the product of the smallest and the largest values of α\alphaα is equal to:
  1. (A)22
  2. (B)44
  3. (C)33
  4. (D)55

Correct answer: (C)

Step-by-step solution →
Q28·MathematicsSingle correctJEE Main 2025
Let the lines 3x−4y−α=03x-4y-\alpha=03x−4y−α=0, 8x−11y−33=08x-11y-33=08x−11y−33=0, and 2x−3y+λ=02x-3y+\lambda=02x−3y+λ=0 be concurrent. If the image of the point (1,2)(1,2)(1,2) in the line 2x−3y+λ=02x-3y+\lambda=02x−3y+λ=0 is (5713,−4013)\left(\dfrac{57}{13},\dfrac{-40}{13}\right)(1357​,13−40​), then ∣αλ∣|\alpha\lambda|∣αλ∣ is equal to :
  1. (A)848484
  2. (B)919191
  3. (C)113113113
  4. (D)101101101

Correct answer: (B)

Step-by-step solution →
Q29·MathematicsSingle correctJEE Main 2025
A rod of length eight units moves such that its ends AAA and BBB always lie on the lines x−y+2=0x-y+2=0x−y+2=0 and y+2=0y+2=0y+2=0, respectively. If the locus of the point PPP, that divides the rod ABABAB internally in the ratio 2:12:12:1 is 9(x2+αy2+βxy+γx+28y)−76=09(x^2+\alpha y^2+\beta xy+\gamma x+28y)-76=09(x2+αy2+βxy+γx+28y)−76=0, then α−β−γ\alpha-\beta-\gammaα−β−γ is equal to :
  1. (A)24
  2. (B)23
  3. (C)21
  4. (D)22

Correct answer: (B)

Step-by-step solution →
Q30·MathematicsSingle correctJEE Main 2025
Let the area of a △PQR\triangle PQR△PQR with vertices P(5,4)P(5,4)P(5,4), Q(−2,4)Q(-2,4)Q(−2,4) and R(a,b)R(a,b)R(a,b) be 35 square units. If its orthocenter and centroid are O(2,145)O\left(2,\dfrac{14}{5}\right)O(2,514​) and C(c,d)C(c,d)C(c,d) respectively, then c+2dc+2dc+2d is equal to
  1. (A)73\dfrac{7}{3}37​
  2. (B)333
  3. (C)222
  4. (D)83\dfrac{8}{3}38​

Correct answer: (B)

Step-by-step solution →
Q31·MathematicsSingle correctJEE Main 2025
Let triangle PQR be the image of the triangle with vertices (1,3),(3,1),(2,4)(1,3),(3,1),(2,4)(1,3),(3,1),(2,4) in the line x+2y=2x+2y=2x+2y=2. If the centroid of △PQR\triangle PQR△PQR is (α,β)(\alpha,\beta)(α,β), then 15(α−β)15(\alpha-\beta)15(α−β) equals:
  1. (A)24
  2. (B)19
  3. (C)21
  4. (D)22

Correct answer: (D)

Step-by-step solution →
Q32·MathematicsIntegerJEE Main 2025
Let A(6,8)A(6,8)A(6,8), B(10cos⁡α,−10sin⁡α)B(10\cos\alpha,-10\sin\alpha)B(10cosα,−10sinα) and C(−10sin⁡α,10cos⁡α)C(-10\sin\alpha,10\cos\alpha)C(−10sinα,10cosα) be the vertices of a triangle. If L(a,9)L(a,9)L(a,9) and G(h,k)G(h,k)G(h,k) be its orthocenter and centroid respectively, then (5a−3h+6k+100sin⁡2α)(5a-3h+6k+100\sin2\alpha)(5a−3h+6k+100sin2α) is equal to ______.

Correct answer: 145

Step-by-step solution →
Q33·MathematicsIntegerJEE Main 2025
Let the distance between two parallel lines be 5 units and a point PPP lie between the lines at a unit distance from one of them. An equilateral triangle PQRPQRPQR is formed such that QQQ lies on one of the parallel lines, while RRR lies on the other. Then (QR)2(QR)^2(QR)2 is equal to ______.

Correct answer: 28

Step-by-step solution →
Q34·MathematicsSingle correctJEE Main 2024
A variable line L passes through the point (3,5)(3, 5)(3,5) and intersects the positive coordinate axes at the points A and B. The minimum area of the triangle OAB, where O is the origin, is:
  1. (A)30
  2. (B)25
  3. (C)40
  4. (D)35

Correct answer: (A)

Step-by-step solution →
Q35·MathematicsSingle correctJEE Main 2024
A ray of light coming from the point P(1,2)P(1, 2)P(1,2) gets reflected from the point Q on the x-axis and then passes through the point R(4,3)R(4, 3)R(4,3). If the point S(h,k)S(h, k)S(h,k) is such that PQRS is a parallelogram, then hk2hk^2hk2 is equal to:
  1. (A)80
  2. (B)90
  3. (C)60
  4. (D)70

Correct answer: (D)

Step-by-step solution →
Q36·MathematicsSingle correctJEE Main 2024
Two vertices of a triangle ABC are A(3,−1)A(3, -1)A(3,−1) and B(−2,3)B(-2, 3)B(−2,3), and its orthocentre is P(1,1)P(1, 1)P(1,1). If the coordinates of the point C are (α,β)(\alpha, \beta)(α,β) and the centre of the circle circumscribing the triangle PAB is (h,k)(h, k)(h,k), then the value of (α+β)+2(h+k)(\alpha+\beta)+2(h+k)(α+β)+2(h+k) equals:
  1. (A)515151
  2. (B)818181
  3. (C)555
  4. (D)151515

Correct answer: (C)

Step-by-step solution →
Q37·MathematicsSingle correctJEE Main 2024
If the line segment joining the points (5,2)(5,2)(5,2) and (2,a)(2,a)(2,a) subtends an angle π4\dfrac{\pi}{4}4π​ at the origin, then the absolute value of the product of all possible values of aaa is
  1. (A)666
  2. (B)888
  3. (C)222
  4. (D)444

Correct answer: (D)

Step-by-step solution →
Q38·MathematicsNumericalJEE Main 2024
Let a ray of light passing through the point (3,10)(3,10)(3,10) reflect on the line 2x+y=62x+y=62x+y=6 and the reflected ray pass through the point (7,2)(7,2)(7,2). If the equation of the incident ray is ax+by+1=0ax+by+1=0ax+by+1=0, then a2+b2+3aba^2+b^2+3aba2+b2+3ab is equal to _______ .

Correct answer: 1

Step-by-step solution →
Q39·MathematicsNumericalJEE Main 2024
If the orthocentre of the triangle formed by the lines 2x+3y−1=02x+3y-1=02x+3y−1=0, x+2y−1=0x+2y-1=0x+2y−1=0 and ax+by−1=0ax+by-1=0ax+by−1=0, is the centroid of another triangle, whose circumcentre and orthocentre respectively are (3,4)(3,4)(3,4) and (−6,−8)(-6,-8)(−6,−8), then the value of ∣a−b∣|a-b|∣a−b∣ is ___

Correct answer: 16

Step-by-step solution →
Q40·MathematicsSingle correctJEE Main 2024
The equations of two sides ABABAB and ACACAC of a triangle ABCABCABC are 4x+y=144x+y=144x+y=14 and 3x−2y=53x-2y=53x−2y=5, respectively. The point (2,−43)\left(2,-\dfrac43\right)(2,−34​) divides the third side BCBCBC internally in the ratio 2:12:12:1. The equation of the side BCBCBC is:
  1. (A)x−6y−10=0x-6y-10=0x−6y−10=0
  2. (B)x−3y−6=0x-3y-6=0x−3y−6=0
  3. (C)x+3y+2=0x+3y+2=0x+3y+2=0
  4. (D)x+6y+6=0x+6y+6=0x+6y+6=0

Correct answer: (C)

Step-by-step solution →
Q41·MathematicsSingle correctJEE Main 2024
If the image of the point (−4,5)(-4,5)(−4,5) in the line x+2y=2x+2y=2x+2y=2 lies on the circle (x+4)2+(y−3)2=r2(x+4)^2+(y-3)^2=r^2(x+4)2+(y−3)2=r2, then rrr is equal to
  1. (A)111
  2. (B)222
  3. (C)5\sqrt{5}5​
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q42·MathematicsSingle correctJEE Main 2024
If P(6,1)P(6, 1)P(6,1) be the orthocentre of the triangle whose vertices are A(5,−2)A(5, -2)A(5,−2), B(8,3)B(8, 3)B(8,3) and C(h,k)C(h, k)C(h,k), then the point C lies on the circle.
  1. (A)x2+y2−65=0x^2 + y^2 - 65 = 0x2+y2−65=0
  2. (B)x2+y2−74=0x^2 + y^2 - 74 = 0x2+y2−74=0
  3. (C)x2+y2−61=0x^2 + y^2 - 61 = 0x2+y2−61=0
  4. (D)x2+y2−52=0x^2 + y^2 - 52 = 0x2+y2−52=0

Correct answer: (A)

Step-by-step solution →
Q43·MathematicsSingle correctJEE Main 2024
Let a variable line of slope m>0m>0m>0 passing through the point (4,−9)(4,-9)(4,−9) intersect the coordinate axes at the points AAA and BBB. The minimum value of the sum of the distances of AAA and BBB from the origin is
  1. (A)252525
  2. (B)303030
  3. (C)151515
  4. (D)101010

Correct answer: (A)

Step-by-step solution →
Q44·MathematicsSingle correctJEE Main 2024
Let two straight lines drawn from the origin O intersect the line 3x+4y=123x + 4y = 123x+4y=12 at the points P and Q such that ΔOPQ\Delta OPQΔOPQ is an isosceles triangle and ∠POQ=90∘\angle POQ = 90^\circ∠POQ=90∘. If l=OP2+PQ2+QO2l = OP^2 + PQ^2 + QO^2l=OP2+PQ2+QO2, then the greatest integer less than or equal to lll is:
  1. (A)444444
  2. (B)484848
  3. (C)464646
  4. (D)424242

Correct answer: (C)

Step-by-step solution →
Q45·MathematicsSingle correctJEE Main 2024
Let A(−1,1)A(-1,1)A(−1,1) and B(2,3)B(2,3)B(2,3) be two points and PPP be a variable point above the line ABABAB such that the area of △PAB\triangle PAB△PAB is 10. If the locus of PPP is ax+by=15ax+by=15ax+by=15, then 5a+2b5a+2b5a+2b is:
  1. (A)−125-\dfrac{12}{5}−512​
  2. (B)−65-\dfrac{6}{5}−56​
  3. (C)4
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q46·MathematicsSingle correctJEE Main 2024
Let ABCD and AEFG be squares of side 4 and 2 units, respectively. The point E is on the line segment AB and the point F is on the diagonal AC. Then the radius rrr of the circle passing through the point F and touching the line segments BC and CD satisfies:
  1. (A)r=1r=1r=1
  2. (B)r2−8r+8=0r^2-8r+8=0r2−8r+8=0
  3. (C)2r2−4r+1=02r^2-4r+1=02r2−4r+1=0
  4. (D)2r2−8r+7=02r^2-8r+7=02r2−8r+7=0

Correct answer: (B)

Step-by-step solution →
Q47·MathematicsSingle correctJEE Main 2024
The vertices of a triangle are A(−1,3)A(-1,3)A(−1,3), B(−2,2)B(-2,2)B(−2,2) and C(3,−1)C(3,-1)C(3,−1). A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is:
  1. (A)x−y−(2+2)=0x-y-(2+\sqrt2)=0x−y−(2+2​)=0
  2. (B)−x+y−(2−2)=0-x+y-(2-\sqrt2)=0−x+y−(2−2​)=0
  3. (C)x+y−(2−2)=0x+y-(2-\sqrt2)=0x+y−(2−2​)=0
  4. (D)x+y+(2−2)=0x+y+(2-\sqrt2)=0x+y+(2−2​)=0

Correct answer: (C)

Step-by-step solution →
Q48·MathematicsNumericalJEE Main 2024
Consider a triangle ABC having the vertices A(1,2)A(1,2)A(1,2), B(α,β)B(\alpha,\beta)B(α,β) and C(γ,δ)C(\gamma,\delta)C(γ,δ) and angles ∠ABC=π6\angle ABC=\dfrac{\pi}{6}∠ABC=6π​ and ∠BAC=2π3\angle BAC=\dfrac{2\pi}{3}∠BAC=32π​. If the points B and C lie on the line y=x+4y=x+4y=x+4, then α2+γ2\alpha^2+\gamma^2α2+γ2 is equal to

Correct answer: 14

Step-by-step solution →
Q49·MathematicsNumericalJEE Main 2024
The lines L1,L2,…,L20L_1,L_2,\ldots,L_{20}L1​,L2​,…,L20​ are distinct. For n=1,2,3,…,10n=1,2,3,\ldots,10n=1,2,3,…,10 all the lines L2n−1L_{2n-1}L2n−1​ are parallel to each other and all the lines L2nL_{2n}L2n​ pass through a given point P. The maximum number of points of intersection of pairs of lines from the set {L1,L2,…,L20}\{L_1,L_2,\ldots,L_{20}\}{L1​,L2​,…,L20​} is equal to __________.

Correct answer: 101

Step-by-step solution →
Q50·MathematicsSingle correctJEE Main 2024
Let α,β,γ,δ∈Z\alpha,\beta,\gamma,\delta\in Zα,β,γ,δ∈Z and let A(α,β)A(\alpha,\beta)A(α,β), B(1,0)B(1,0)B(1,0), C(γ,δ)C(\gamma,\delta)C(γ,δ) and D(1,2)D(1,2)D(1,2) be the vertices of a parallelogram ABCD. If AB=10AB=\sqrt{10}AB=10​ and the points A and C lie on the line 3y=2x+13y=2x+13y=2x+1, then 2(α+β+γ+δ)2(\alpha+\beta+\gamma+\delta)2(α+β+γ+δ) is equal to
  1. (A)101010
  2. (B)555
  3. (C)121212
  4. (D)888

Correct answer: (D)

Step-by-step solution →
Q51·MathematicsSingle correctJEE Main 2024
Let A(aaa, bbb), B(3, 4) and C(−6-6−6, −8-8−8) respectively denote the centroid, circumcentre and orthocentre of a triangle. Then, the distance of the point P(2a+32a+32a+3, 7b+57b+57b+5) from the line 2x+3y−4=02x+3y-4=02x+3y−4=0 measured parallel to the line x−2y−1=0x-2y-1=0x−2y−1=0 is
  1. (A)1557\dfrac{15\sqrt{5}}{7}7155​​
  2. (B)1756\dfrac{17\sqrt{5}}{6}6175​​
  3. (C)1757\dfrac{17\sqrt{5}}{7}7175​​
  4. (D)4517\dfrac{4\sqrt{5}}{17}1745​​

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsNumericalJEE Main 2024
Let A(−2,−1)A(-2,-1)A(−2,−1), B(1,0)B(1,0)B(1,0), C(α,β)C(\alpha,\beta)C(α,β) and D(γ,δ)D(\gamma,\delta)D(γ,δ) be the vertices of a parallelogram ABCD. If the point C lies on 2x−y=52x-y=52x−y=5 and the point D lies on 3x−2y=63x-2y=63x−2y=6, then the value of ∣α+β+γ+δ∣|\alpha+\beta+\gamma+\delta|∣α+β+γ+δ∣ is equal to ______.

Correct answer: 32

Step-by-step solution →
Q53·MathematicsSingle correctJEE Main 2024
A line passing through the point A(9,0)A(9,0)A(9,0) makes an angle of 30∘30^\circ30∘ with the positive direction of x-axis. If this line is rotated about AAA through an angle of 15∘15^\circ15∘ in the clockwise direction, then its equation in the new position is:
  1. (A)y3−2+x=9\dfrac{y}{\sqrt3-2}+x=93​−2y​+x=9
  2. (B)x3−2+y=9\dfrac{x}{\sqrt3-2}+y=93​−2x​+y=9
  3. (C)x3+2+y=9\dfrac{x}{\sqrt3+2}+y=93​+2x​+y=9
  4. (D)y3+2+x=9\dfrac{y}{\sqrt3+2}+x=93​+2y​+x=9

Correct answer: (A)

Step-by-step solution →
Q54·MathematicsSingle correctJEE Main 2024
If x2−y2+2hxy+2gx+2fy+c=0x^2-y^2+2hxy+2gx+2fy+c=0x2−y2+2hxy+2gx+2fy+c=0 is the locus of a point, which moves such that it is always equidistant from the lines x+2y+7=0x+2y+7=0x+2y+7=0 and 2x−y+8=02x-y+8=02x−y+8=0, then the value of g+c+h−fg+c+h-fg+c+h−f equals:
  1. (A)141414
  2. (B)666
  3. (C)888
  4. (D)292929

Correct answer: (A)

Step-by-step solution →
Q55·MathematicsSingle correctJEE Main 2024
Let AAA be the point of intersection of the lines 3x+2y=143x+2y=143x+2y=14, 5x−y=65x-y=65x−y=6 and BBB be the point of intersection of the lines 4x+3y=84x+3y=84x+3y=8, 6x+y=56x+y=56x+y=5. The distance of the point P(5,−2)P(5,-2)P(5,−2) from the line ABABAB is:
  1. (A)132\dfrac{13}{2}213​
  2. (B)8
  3. (C)52\dfrac{5}{2}25​
  4. (D)6

Correct answer: (D)

Step-by-step solution →
Q56·MathematicsSingle correctJEE Main 2024
In a △ABC\triangle ABC△ABC, suppose y=xy=xy=x is the equation of the bisector of the angle B and the equation of the side AC is 2x−y=22x-y=22x−y=2. If 2AB=BC2AB=BC2AB=BC and the point A and B are respectively (4,6)(4,6)(4,6) and (α,β)(\alpha,\beta)(α,β), then α+2β\alpha+2\betaα+2β is equal to
  1. (A)424242
  2. (B)393939
  3. (C)484848
  4. (D)454545

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correctJEE Main 2024
The distance of the point (2,3)(2,3)(2,3) from the line 2x−3y+28=02x-3y+28=02x−3y+28=0, measured parallel to the line 3x−y+1=0\sqrt{3}x-y+1=03​x−y+1=0, is equal to:
  1. (A)424\sqrt{2}42​
  2. (B)636\sqrt{3}63​
  3. (C)3+423+4\sqrt{2}3+42​
  4. (D)4+634+6\sqrt{3}4+63​

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsSingle correctJEE Main 2024
Let R be the interior region between the lines 3x−y+1=03x-y+1=03x−y+1=0 and x+2y−5=0x+2y-5=0x+2y−5=0 containing the origin. The set of all values of aaa, for which the points (a2,a+1)(a^2,a+1)(a2,a+1) lie in R, is :
  1. (A)(−3,−1)∪(−13,1)(-3,-1)\cup\left(-\dfrac13,1\right)(−3,−1)∪(−31​,1)
  2. (B)(−3,0)∪(13,1)(-3,0)\cup\left(\dfrac13,1\right)(−3,0)∪(31​,1)
  3. (C)(−3,0)∪(23,1)(-3,0)\cup\left(\dfrac23,1\right)(−3,0)∪(32​,1)
  4. (D)(−3,−1)∪(13,1)(-3,-1)\cup\left(\dfrac13,1\right)(−3,−1)∪(31​,1)

Correct answer: (B)

Step-by-step solution →
Q59·MathematicsSingle correctJEE Main 2024
The portion of the line 4x+5y=204x+5y=204x+5y=20 in the first quadrant is trisected by the lines L1L_1L1​ and L2L_2L2​ passing through the origin. The tangent of an angle between the lines L1L_1L1​ and L2L_2L2​ is:
  1. (A)85\dfrac{8}{5}58​
  2. (B)2541\dfrac{25}{41}4125​
  3. (C)25\dfrac{2}{5}52​
  4. (D)3041\dfrac{30}{41}4130​

Correct answer: (D)

Step-by-step solution →
Q60·MathematicsNumericalJEE Main 2024
If the sum of squares of all real values of α\alphaα, for which the lines 2x−y+3=02x-y+3=02x−y+3=0, 6x+3y+1=06x+3y+1=06x+3y+1=0 and αx+2y−2=0\alpha x+2y-2=0αx+2y−2=0 do not form a triangle is ppp, then the greatest integer less than or equal to ppp is __________.

Correct answer: 32

Step-by-step solution →
Q61·MathematicsNumericalJEE Main 2023
Consider the triangles with vertices A(2,1)A(2, 1)A(2,1), B(0,0)B(0, 0)B(0,0) and C(t,4)C(t, 4)C(t,4), t∈[0,4]t \in [0, 4]t∈[0,4]. If the maximum and the minimum perimeters of such triangles are obtained at t=αt = \alphat=α and t=βt = \betat=β respectively, then 6α+21β6\alpha + 21\beta6α+21β is equal to____

Correct answer: 48

Step-by-step solution →
Q62·MathematicsSingle correctJEE Main 2023
If (α,β)(\alpha,\beta)(α,β) is the orthocentre of the triangle ABC with vertices A(3,−7)A(3,-7)A(3,−7), B(−1,2)B(-1,2)B(−1,2) and C(4,5)C(4,5)C(4,5), then 9α−6β+609\alpha-6\beta+609α−6β+60 is equal to:
  1. (A)30
  2. (B)25
  3. (C)40
  4. (D)35

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correctJEE Main 2023
Let (α,β)(\alpha, \beta)(α,β) be the centroid of the triangle formed by the lines 15x−y=8215x - y = 8215x−y=82, 6x−5y=−46x - 5y = -46x−5y=−4 and 9x+4y=179x + 4y = 179x+4y=17. Then α+β\alpha + \betaα+β and 9α−β9\alpha - \beta9α−β are the roots of the equation
  1. (A)x2−7x+12=0x^2 - 7x + 12 = 0x2−7x+12=0
  2. (B)x2−13x+42=0x^2 - 13x + 42 = 0x2−13x+42=0
  3. (C)x2−14x+48=0x^2 - 14x + 48 = 0x2−14x+48=0
  4. (D)x2−10x+25=0x^2 - 10x + 25 = 0x2−10x+25=0

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correctJEE Main 2023
If the point (α,733)\left(\alpha,\dfrac{7\sqrt3}{3}\right)(α,373​​) lies on the curve traced by the mid-points of the line segments of the lines xcos⁡θ+ysin⁡θ=7x\cos\theta+y\sin\theta=7xcosθ+ysinθ=7, θ∈(0,π2)\theta\in\left(0,\dfrac{\pi}{2}\right)θ∈(0,2π​) between the co-ordinate axes, then α\alphaα is equal to
  1. (A)7
  2. (B)-7
  3. (C)−73-7\sqrt3−73​
  4. (D)737\sqrt373​

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsNumericalJEE Main 2023
If the line ℓ1:3y−2x=3\ell_1:3y-2x=3ℓ1​:3y−2x=3 is the angular bisector of the lines ℓ2:x−y+1=0\ell_2:x-y+1=0ℓ2​:x−y+1=0 and ℓ3:αx+βy+17=0\ell_3:\alpha x+\beta y+17=0ℓ3​:αx+βy+17=0, then α2+β2−α−β\alpha^2+\beta^2-\alpha-\betaα2+β2−α−β is equal to

Correct answer: 348

Step-by-step solution →
Q66·MathematicsNumericalJEE Main 2023
Let the equations of two adjacent sides of a parallelogram ABCD be 2x−3y=−232x-3y=-232x−3y=−23 and 5x+4y=235x+4y=235x+4y=23. If the equation of one diagonal AC is 3x+7y=233x+7y=233x+7y=23 and the distance of A from the other diagonal is ddd, then 50 d250\,d^250d2 is equal to _______ .

Correct answer: 529

Step-by-step solution →
Q67·MathematicsSingle correctJEE Main 2023
Let C(α,β)C(\alpha,\beta)C(α,β) be the circumcenter of the triangle formed by the lines 4x+3y=694x+3y=694x+3y=69, 4y−3x=174y-3x=174y−3x=17 and x+7y=61x+7y=61x+7y=61. Then (α−β)2+α+β(\alpha-\beta)^{2}+\alpha+\beta(α−β)2+α+β is equal to
  1. (A)18
  2. (B)17
  3. (C)16
  4. (D)15

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correctJEE Main 2023
The straight lines l1l_1l1​ and l2l_2l2​ pass through the origin and trisect the line segment of the line L:9x+5y=45L:9x+5y=45L:9x+5y=45 between the axes. If m1m_1m1​ and m2m_2m2​ are the slopes of the lines l1l_1l1​ and l2l_2l2​, then the point of intersection of the line y=(m1+m2)xy=(m_1+m_2)xy=(m1​+m2​)x with LLL lies on:
  1. (A)y−x=5y-x=5y−x=5
  2. (B)y−2x=5y-2x=5y−2x=5
  3. (C)6x+y=106x+y=106x+y=10
  4. (D)2y−x=52y-x=52y−x=5

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correctJEE Main 2023
The combined equation of the two lines ax+by+c=0ax+by+c=0ax+by+c=0 and a′x+b′y+c′=0a'x+b'y+c'=0a′x+b′y+c′=0 can be written as (ax+by+c)(a′x+b′y+c′)=0(ax+by+c)(a'x+b'y+c')=0(ax+by+c)(a′x+b′y+c′)=0. The equation of the angle bisectors of the lines represented by the equation 2x2+xy−3y2=02x^2+xy-3y^2=02x2+xy−3y2=0 is
  1. (A)x2−y2−10xy=0x^2-y^2-10xy=0x2−y2−10xy=0
  2. (B)x2−y2+10xy=0x^2-y^2+10xy=0x2−y2+10xy=0
  3. (C)3x2+5xy+2y2=03x^2+5xy+2y^2=03x2+5xy+2y2=0
  4. (D)3x2+xy−2y2=03x^2+xy-2y^2=03x2+xy−2y2=0

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correctJEE Main 2023
If the orthocentre of the triangle, whose vertices are (1,2)(1,2)(1,2), (2,3)(2,3)(2,3) and (3,1)(3,1)(3,1) is (α,β)(\alpha,\beta)(α,β), then the quadratic equation whose roots are α+4β\alpha+4\betaα+4β and 4α+β4\alpha+\beta4α+β, is
  1. (A)x2−20x+99=0x^2-20x+99=0x2−20x+99=0
  2. (B)x2−19x+90=0x^2-19x+90=0x2−19x+90=0
  3. (C)x2−22x+120=0x^2-22x+120=0x2−22x+120=0
  4. (D)x2−18x+80=0x^2-18x+80=0x2−18x+80=0

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correctJEE Main 2023
A straight line cuts off the intercepts OA=aOA=aOA=a and OB=bOB=bOB=b on the positive directions of x-axis and y-axis respectively. If the perpendicular from origin O to this line makes an angle of π6\dfrac{\pi}{6}6π​ with positive direction of y-axis and the area of △OAB\triangle OAB△OAB is 9833\dfrac{98}{3}\sqrt3398​3​, then a2−b2a^2-b^2a2−b2 is equal to:
  1. (A)3923\dfrac{392}{3}3392​
  2. (B)1963\dfrac{196}{3}3196​
  3. (C)989898
  4. (D)196196196

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correctJEE Main 2023
A light ray emits from the origin making an angle 30∘30^\circ30∘ with the positive x-axis. After getting reflected by the line x+y=1x + y = 1x+y=1, if this ray intersects x-axis at QQQ, then the abscissa of QQQ is
  1. (A)32(3+1)\dfrac{\sqrt{3}}{2(\sqrt{3}+1)}2(3​+1)3​​
  2. (B)23+3\dfrac{2}{3+\sqrt{3}}3+3​2​
  3. (C)23−1\dfrac{2}{\sqrt{3}-1}3​−12​
  4. (D)23−3\dfrac{2}{3-\sqrt{3}}3−3​2​

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correctJEE Main 2023
Let BBB and CCC be the two points on the line y+x=0y + x = 0y+x=0 such that BBB and CCC are symmetric with respect to the origin. Suppose AAA is a point on y−2x=2y - 2x = 2y−2x=2 such that △ABC\triangle ABC△ABC is an equilateral triangle. Then, the area of the △ABC\triangle ABC△ABC is
  1. (A)103\dfrac{10}{\sqrt{3}}3​10​
  2. (B)333\sqrt{3}33​
  3. (C)232\sqrt{3}23​
  4. (D)83\dfrac{8}{\sqrt{3}}3​8​

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsNumericalJEE Main 2023
A triangle is formed by the X-axis, the Y-axis and the line 3x+4y=603x+4y=603x+4y=60. Then the number of points P(a,b)P(a,b)P(a,b) which lie strictly inside the triangle, where aaa is an integer and bbb is a multiple of aaa, is

Correct answer: 31

Step-by-step solution →
Q75·MathematicsSingle correctJEE Main 2023
The equations of two sides of a variable triangle are x=0x = 0x=0 and y=3y = 3y=3, and its third side is a tangent to parabola y2=6xy^2 = 6xy2=6x. The locus of its circumcentre is:
  1. (A)4y2−18y−3x−18=04y^2 - 18y - 3x - 18 = 04y2−18y−3x−18=0
  2. (B)4y2−18y−3x+18=04y^2 - 18y - 3x + 18 = 04y2−18y−3x+18=0
  3. (C)4y2−18y+3x+18=04y^2 - 18y + 3x + 18 = 04y2−18y+3x+18=0
  4. (D)4y2+18y+3x+18=04y^2 + 18y + 3x + 18 = 04y2+18y+3x+18=0

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsNumericalJEE Main 2023
The equations of the sides AB, BC and CA of a triangle ABC are: 2x+y=02x+y=02x+y=0, x+py=21ax+py=21ax+py=21a (a≠0)(a\neq0)(a=0) and x−y=3x-y=3x−y=3 respectively. Let P(2,a)P(2,a)P(2,a) be the centroid of △ABC\triangle ABC△ABC. Then (BC)2(BC)^2(BC)2 is equal to

Correct answer: 122

Step-by-step solution →
Q77·MathematicsSingle correctJEE Main 2023
The equations of the sides AB and AC of a triangle ABC are (λ+1)x+λy=4(\lambda+1)x+\lambda y=4(λ+1)x+λy=4 and λx+(1−λ)y+λ=0\lambda x+(1-\lambda)y+\lambda=0λx+(1−λ)y+λ=0 respectively. Its vertex A is on the y-axis and its orthocentre is (1,2)(1,2)(1,2). The length of the tangent from the point C to the part of the parabola y2=6xy^2=6xy2=6x in the first quadrant is:
  1. (A)444
  2. (B)222
  3. (C)6\sqrt66​
  4. (D)222\sqrt222​

Correct answer: (D)

Step-by-step solution →
Q78·MathematicsSingle correctJEE Main 2022
Let the circumcentre of a triangle with vertices A(a,3)A(a, 3)A(a,3), B(b,5)B(b, 5)B(b,5) and C(a,b)C(a, b)C(a,b), ab>0ab > 0ab>0 be P(1,1)P(1, 1)P(1,1). If the line AP intersects the line BC at the point Q(k1,k2)Q(k_{1}, k_{2})Q(k1​,k2​), then k1+k2k_{1} + k_{2}k1​+k2​ is equal to :
  1. (A)2
  2. (B)47\frac{4}{7}74​
  3. (C)27\frac{2}{7}72​
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correctJEE Main 2022
Let A(α,−2)A(\alpha, -2)A(α,−2), B(α,6)B(\alpha, 6)B(α,6) and C(α4,−2)C\left( \frac{\alpha}{4}, -2 \right)C(4α​,−2) be vertices of a △ABC\triangle ABC△ABC. If (5,α4)\left( 5, \frac{\alpha}{4} \right)(5,4α​) is the circumcentre of △ABC\triangle ABC△ABC, then which of the following is NOT correct about △ABC\triangle ABC△ABC:
  1. (A)ares is 24
  2. (B)perimeter is 25
  3. (C)circumradius is 5
  4. (D)inradius is 2

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsSingle correctJEE Main 2022
Let m1m_1m1​, m2m_2m2​ be the slopes of two adjacent sides of a square of side aaa such that a2+11a+3(m22+m22)=220a^2 + 11a + 3\left( m_2^2 + m_2^2 \right) = 220a2+11a+3(m22​+m22​)=220. If one vertex of the square is (10(cos⁡α−sin⁡α), 10(sin⁡α+cos⁡α))(10(\cos\alpha - \sin\alpha),\ 10(\sin\alpha + \cos\alpha))(10(cosα−sinα), 10(sinα+cosα)), where α∈(0,π2)\alpha \in \left( 0, \frac{\pi}{2} \right)α∈(0,2π​) and the equation of one diagonal is (cos⁡α−sin⁡α)x+(sin⁡α+cos⁡α)y=10(\cos\alpha - \sin\alpha)x + (\sin\alpha + \cos\alpha)y = 10(cosα−sinα)x+(sinα+cosα)y=10, then 72(sin⁡4α+cos⁡4α)+a2−3a+1372(\sin^4\alpha + \cos^4\alpha) + a^2 - 3a + 1372(sin4α+cos4α)+a2−3a+13 is equal to:
  1. (A)119119119
  2. (B)128128128
  3. (C)145145145
  4. (D)155155155

Correct answer: (B)

Step-by-step solution →
Q81·MathematicsSingle correctJEE Main 2022
For t∈(0,2π)t \in (0, 2\pi)t∈(0,2π), if ABC is an equilateral triangle with vertices A(sint, −cost), B(cost, sint) and C(a, b) such that its orthocentre lies on a circle with centre (1,13)\left(1, \frac{1}{3}\right)(1,31​), then (a2−b2)(a^{2} - b^{2})(a2−b2) is equal to :
  1. (A)83\frac{8}{3}38​
  2. (B)8
  3. (C)779\frac{77}{9}977​
  4. (D)809\frac{80}{9}980​

Correct answer: (B)

Step-by-step solution →
Q82·MathematicsSingle correctJEE Main 2022
Let A(1, 1), B(-4, 3) C(-2, -5) be vertices of a triangle ABC, P be a point on side BC, and Δ1\Delta_{1}Δ1​ and Δ2\Delta_{2}Δ2​ be the areas of triangle APB and ABC. Respectively. If Δ1:Δ2=4:7\Delta_{1}:\Delta_{2}=4:7Δ1​:Δ2​=4:7, then the area enclosed by the lines AP, AC and the x-axis is
  1. (A)14\frac{1}{4}41​
  2. (B)34\frac{3}{4}43​
  3. (C)12\frac{1}{2}21​
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q83·MathematicsSingle correctJEE Main 2022
The equations of the sides AB, BC and CA of a triangle ABC are 2x+y=02x + y = 02x+y=0, x+py=39x + py = 39x+py=39 and x−y=3x - y = 3x−y=3 respectively and P(2,3)P(2, 3)P(2,3) is its circumcentre. Then which of the following is NOT true :
  1. (A)(AC)2=9p(AC)^{2} = 9p(AC)2=9p
  2. (B)(AC)2+p2=136(AC)^{2} + p^{2} = 136(AC)2+p2=136
  3. (C)32<area (ΔABC)<3632 < \text{area } (\Delta ABC) < 3632<area (ΔABC)<36
  4. (D)34<area (ΔABC)<3834 < \text{area } (\Delta ABC) < 3834<area (ΔABC)<38

Correct answer: (D)

Step-by-step solution →
Q84·MathematicsNumericalJEE Main 2022
The equations of the sides AB, BC and CA of a triangle ABC are 2x + y = 0, x + py = 15a and x − y = 3 respectively. If its orthocentre is (2, a), −12-\frac{1}{2}−21​ < a < 2, then p is equal to

Correct answer: 3

Step-by-step solution →
Q85·MathematicsSingle correctJEE Main 2022
A line, with the slope greater than one, passes through the point A(4, 3) and intersects the line x−y−2=0x - y - 2 = 0x−y−2=0 at the point B. If the length of the line segment AB is 293\frac{\sqrt{29}}{3}329​​, then B also lies on the line :
  1. (A)2x+y=92x + y = 92x+y=9
  2. (B)3x−2y=73x - 2y = 73x−2y=7
  3. (C)x+2y=6x + 2y = 6x+2y=6
  4. (D)2x−3y=32x - 3y = 32x−3y=3

Correct answer: (C)

Step-by-step solution →
Q86·MathematicsSingle correctJEE Main 2022
The distance of the origin from the centroid of the triangle whose two sides have the equations x−2y+1=0x - 2y + 1 = 0x−2y+1=0 and 2x−y−1=02x - y - 1 = 02x−y−1=0 and whose orthocenter is (73,73)\left(\frac{7}{3}, \frac{7}{3}\right)(37​,37​) is:
  1. (A)2\sqrt{2}2​
  2. (B)222
  3. (C)222\sqrt{2}22​
  4. (D)444

Correct answer: (C)

Step-by-step solution →
Q87·MathematicsSingle correctJEE Main 2022
The distance between the two points A and A′A'A′ which lie on y=2y = 2y=2 such that both the line segments AB and A′BA'BA′B (where B is the point (2, 3)) subtend angle π4\frac{\pi}{4}4π​ at the origin, is equal to :
  1. (A)10
  2. (B)485\frac{48}{5}548​
  3. (C)525\frac{52}{5}552​
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q88·MathematicsNumericalJEE Main 2022
A ray of light passing through the point P(2, 3) reflects on the x-axis at point A and the reflected ray passes through the point Q(5, 4). Let R be the point that divides the line segment AQ internally into the ratio 2 : 1. Let the co-ordinates of the foot of the perpendicular M from R on the bisector of the angle PAQ be (α, β). Then, the value of 7α+3β7\alpha + 3\beta7α+3β is equal to ______.

Correct answer: 31

Step-by-step solution →
Q89·MathematicsSingle correctJEE Main 2022
Let a triangle be bounded by the lines L1:2x+5y=10L_1 : 2x + 5y = 10L1​:2x+5y=10; L2:−4x+3y=12L_2 : -4x + 3y = 12L2​:−4x+3y=12 and the line L3L_3L3​, which passes through the point P(2,3)P(2, 3)P(2,3), intersect L2L_2L2​ at A and L1L_1L1​ at B. If the point P divides the line-segment AB, internally in the ratio 1:31 : 31:3, then the area of the triangle is equal to
  1. (A)11013\frac{110}{13}13110​
  2. (B)13213\frac{132}{13}13132​
  3. (C)14213\frac{142}{13}13142​
  4. (D)15113\frac{151}{13}13151​

Correct answer: (B)

Step-by-step solution →
Q90·MathematicsSingle correctJEE Main 2022
In an isosceles triangle ABC, the vertex A is (6, 1) and the equation of the base BC is 2x+y=42x + y = 42x+y=4. Let the point B lie on the line x+3y=7x + 3y = 7x+3y=7. If (α,β)(\alpha, \beta)(α,β) is the centroid ΔABC\Delta ABCΔABC, then 15(α+β)15\left(\alpha + \beta\right)15(α+β) is equal to :
  1. (A)39
  2. (B)41
  3. (C)51
  4. (D)63

Correct answer: (C)

Step-by-step solution →
Q91·MathematicsSingle correctJEE Main 2022
Let R be the point (3, 7) and let P and Q be two points on the line x + y = 5 such that PQR is an equilateral triangle. Then the area of Δ\DeltaΔPQR is :
  1. (A)2543\frac{25}{4\sqrt{3}}43​25​
  2. (B)2532\frac{25\sqrt{3}}{2}2253​​
  3. (C)253\frac{25}{\sqrt{3}}3​25​
  4. (D)2523\frac{25}{2\sqrt{3}}23​25​

Correct answer: (D)

Step-by-step solution →
Q92·MathematicsNumericalJEE Main 2022
Let A(3a,a)A\left(\dfrac{3}{\sqrt{a}},\sqrt{a}\right)A(a​3​,a​) a>0a > 0a>0, be a fixed point in the xy-plane. The image of A in y-axis be B and the image of B in x-axis be C. If D(3 cos θ\thetaθ, a sin θ\thetaθ) is a point in the fourth quadrant such that the maximum area of △ACD\triangle ACD△ACD is 12 square units, then a is equal to ________ .

Correct answer: 8

Step-by-step solution →
Q93·MathematicsSingle correctJEE Main 2022
Let the area of the triangle with vertices A(1,α)A(1, \alpha)A(1,α), B(α,0)B(\alpha, 0)B(α,0) and C(0,α)C(0, \alpha)C(0,α) be 4 sq. units. If the point (α,−α)(\alpha, -\alpha)(α,−α), (−α,α)(-\alpha, \alpha)(−α,α) and (α2,β)(\alpha^{2}, \beta)(α2,β) are collinear, then β\betaβ is equal to
  1. (A)64
  2. (B)-8
  3. (C)-64
  4. (D)512

Correct answer: (C)

Step-by-step solution →
Q94·MathematicsNumericalJEE Main 2021
Let the points of intersections of the lines x − y + 1 = 0, x − 2y + 3 = 0 and 2x − 5y + 11 = 0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is ________ .

Correct answer: 6

Step-by-step solution →
Q95·MathematicsNumericalJEE Main 2021
A man starts walking from the point P(−3,4), touches the x-axis at R, and then turns to reach at the point Q(0, 2). The man is walking at a constant speed. If the man reaches the point Q in the minimum time, then 50((PR)2+(RQ)2)50\left((PR)^{2} + (RQ)^{2}\right)50((PR)2+(RQ)2) is equal to ______ .

Correct answer: 1250

Step-by-step solution →
Q96·MathematicsSingle correctJEE Main 2021
Let A be the set of all points (α,β)(\alpha, \beta)(α,β) such that the area of triangle formed by the points (5,6)(5, 6)(5,6), (3,2)(3, 2)(3,2) and (α,β)(\alpha, \beta)(α,β) is 12 square units. Then the least possible length of a line segment joining the origin to a point in A, is :
  1. (A)45\frac{4}{\sqrt{5}}5​4​
  2. (B)165\frac{16}{\sqrt{5}}5​16​
  3. (C)85\frac{8}{\sqrt{5}}5​8​
  4. (D)125\frac{12}{\sqrt{5}}5​12​

Correct answer: (C)

Step-by-step solution →
Q97·MathematicsSingle correctJEE Main 2021
If p and q are the lengths of the perpendiculars from the origin on the lines, xcosec⁡α−ysec⁡α=kcot⁡2αx \operatorname{cosec} \alpha - y \sec \alpha = k \cot 2\alphaxcosecα−ysecα=kcot2α and xsin⁡α+ycos⁡α=ksin⁡2αx \sin \alpha + y \cos \alpha = k \sin 2\alphaxsinα+ycosα=ksin2α respectively, then k2k^{2}k2 is equal to :
  1. (A)4p2+q24p^{2} + q^{2}4p2+q2
  2. (B)2p2+q22p^{2} + q^{2}2p2+q2
  3. (C)p2+2q2p^{2} + 2q^{2}p2+2q2
  4. (D)p2+4q2p^{2} + 4q^{2}p2+4q2

Correct answer: (A)

Step-by-step solution →
Q98·MathematicsSingle correctJEE Main 2021
Let A be a fixed point (0,6)(0, 6)(0,6) and B be a moving point (2t,0)(2t, 0)(2t,0). Let M be the mid-point of AB and the perpendicular bisector of AB meets the y-axis at C. The locus of the mid-point P of MC is :
  1. (A)3x2−2y−6=03x^2 - 2y - 6 = 03x2−2y−6=0
  2. (B)3x2+2y−6=03x^2 + 2y - 6 = 03x2+2y−6=0
  3. (C)2x2+3y−9=02x^2 + 3y - 9 = 02x2+3y−9=0
  4. (D)2x2−3y+9=02x^2 - 3y + 9 = 02x2−3y+9=0

Correct answer: (C)

Step-by-step solution →
Q99·MathematicsSingle correctJEE Main 2021
Let A(a, 0), B(b, 2b +1) and C(0, b), b ≠ 0, |b| ≠ 1, be points such that the area of triangle ABC is 1 sq. unit, then the sum of all possible values of a is :
  1. (A)−2bb+1\frac{-2b}{b+1}b+1−2b​
  2. (B)2bb+1\frac{2b}{b+1}b+12b​
  3. (C)2b2b+1\frac{2b^{2}}{b+1}b+12b2​
  4. (D)−2b2b+1\frac{-2b^{2}}{b+1}b+1−2b2​

Correct answer: (D)

Step-by-step solution →
Q100·MathematicsSingle correctJEE Main 2021
A 10 inches long pencil AB with mid point C and a small eraser P are placed on the horizontal top of a table such that PC=5PC = \sqrt{5}PC=5​ inches and ∠PCB=tan⁡−1(2)\angle PCB = \tan^{-1}(2)∠PCB=tan−1(2). The acute angle through which the pencil must be rotated about C so that the perpendicular distance between eraser and pencil becomes exactly 1 inch is :
  1. (A)tan⁡−1(34)\tan^{-1}\left(\frac{3}{4}\right)tan−1(43​)
  2. (B)tan⁡−1(1)\tan^{-1}(1)tan−1(1)
  3. (C)tan⁡−1(43)\tan^{-1}\left(\frac{4}{3}\right)tan−1(34​)
  4. (D)tan⁡−1(12)\tan^{-1}\left(\frac{1}{2}\right)tan−1(21​)

Correct answer: (A)

Step-by-step solution →
Q101·MathematicsSingle correctJEE Main 2021
Two sides of a parallelogram are along the lines 4x + 5y = 0 and 7x + 2y = 0. If the equation of one of the diagonals of the parallelogram is 11x + 7y = 9, then other diagonal passes through the point :
  1. (A)(2,1)(2,1)(2,1)
  2. (B)(2,2)(2,2)(2,2)
  3. (C)(1,3)(1,3)(1,3)
  4. (D)(1,2)(1,2)(1,2)

Correct answer: (B)

Step-by-step solution →
Q102·MathematicsSingle correctJEE Main 2021
The point P(a, b) undergoes the following three transformations successively : (a) reflection about the line y = x (b) translation through 2 units along the positive direction of x-axis. (c) rotation through angle π4\frac{\pi}{4}4π​ about the origin in the anti-clockwise direction. If the co-ordinates of the final position of the point P are (−12,72)\left( -\frac{1}{\sqrt{2}}, \frac{7}{\sqrt{2}} \right)(−2​1​,2​7​), then the value of 2a + b is equal to :
  1. (A)5
  2. (B)7
  3. (C)13
  4. (D)9

Correct answer: (D)

Step-by-step solution →
Q103·MathematicsSingle correctJEE Main 2021
Let the equation of the pair of lines, y = px and y = qx, can be written as (y−px)(y−qx)=0\left( y - px \right)\left( y - qx \right) = 0(y−px)(y−qx)=0. Then the equation of the pair of the angle bisectors of the lines x2−4xy−5y2=0x^2 - 4xy - 5y^2 = 0x2−4xy−5y2=0 is :
  1. (A)x2−3xy+y2=0x^2 - 3xy + y^2 = 0x2−3xy+y2=0
  2. (B)x2+3xy−y2=0x^2 + 3xy - y^2 = 0x2+3xy−y2=0
  3. (C)x2−3xy−y2=0x^2 - 3xy - y^2 = 0x2−3xy−y2=0
  4. (D)x2+4xy−y2=0x^2 + 4xy - y^2 = 0x2+4xy−y2=0

Correct answer: (B)

Step-by-step solution →
Q104·MathematicsNumericalJEE Main 2021
Consider a triangle having vertices A(−2,3)A(-2,3)A(−2,3), B(1,9)B(1,9)B(1,9) and C(3,8)C(3,8)C(3,8). If a line L passing through the circum-center of triangle ABC, bisects line BC, and intersects y-axis at point (0,α2)\left(0,\frac{\alpha}{2}\right)(0,2α​), then the value of real number α\alphaα is…………

Correct answer: 9

Step-by-step solution →
Q105·MathematicsSingle correctJEE Main 2021
Let the centroid of an equilateral triangle ABC be at the origin. Let one of the sides of the equilateral triangle be along the straight line x + y = 3. If R and r be the radius of circumcircle and incircle respectively of ΔABC, then (R + r) is equal to :
  1. (A)92\frac{9}{\sqrt{2}}2​9​
  2. (B)727\sqrt{2}72​
  3. (C)222\sqrt{2}22​
  4. (D)323\sqrt{2}32​

Correct answer: (A)

Step-by-step solution →
Q106·MathematicsSingle correctJEE Main 2021
The equation of one of the straight lines which passes through the point (1,3)(1,3)(1,3) and makes an angles tan⁡−1(2)\tan^{-1}\left(\sqrt{2}\right)tan−1(2​) with the straight line, y+1=32 xy + 1 = 3\sqrt{2}\,xy+1=32​x is
  1. (A)42x+5y−(15+42)=04\sqrt{2}x + 5y - \left(15 + 4\sqrt{2}\right) = 042​x+5y−(15+42​)=0
  2. (B)52x+4y−(15+42)=05\sqrt{2}x + 4y - \left(15 + 4\sqrt{2}\right) = 052​x+4y−(15+42​)=0
  3. (C)42x+5y−42=04\sqrt{2}x + 5y - 4\sqrt{2} = 042​x+5y−42​=0
  4. (D)42x−5y−(5+42)=04\sqrt{2}x - 5y - \left(5 + 4\sqrt{2}\right) = 042​x−5y−(5+42​)=0

Correct answer: (A)

Step-by-step solution →
Q107·MathematicsSingle correctJEE Main 2021
The number of integral values of m so that the abscissa of point of intersection of lines 3x+4y=93x + 4y = 93x+4y=9 and y=mx+1y = mx + 1y=mx+1 is also an integer, is :
  1. (A)111
  2. (B)222
  3. (C)333
  4. (D)000

Correct answer: (B)

Step-by-step solution →
Q108·MathematicsSingle correctJEE Main 2021
Let A(-1, 1), B(3, 4) and C(2, 0) be given three points. A line y=mxy = mxy=mx, m>0m > 0m>0, intersects lines AC and BC at point P and Q respectively. Let A1A_{1}A1​ and A2A_{2}A2​ be the areas of ΔABC\Delta ABCΔABC and ΔPQC\Delta PQCΔPQC respectively, such that A1=3A2A_{1}=3A_{2}A1​=3A2​, then the value of m is equal to :
  1. (A)415\frac{4}{15}154​
  2. (B)111
  3. (C)222
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q109·MathematicsSingle correctJEE Main 2021
The intersection of three lines x−y = 0, x + 2y = 3 and 2x + y = 6 is a:
  1. (A)Equilateral triangle
  2. (B)None of the above
  3. (C)Isosceles triangle
  4. (D)Right angled triangle

Correct answer: (C)

Step-by-step solution →
Q110·MathematicsSingle correctJEE Main 2021
The image of the point (3,5) in the line x−y+1=0x - y + 1 = 0x−y+1=0, lies on :
  1. (A)(x−2)2+(y−4)2=4(x - 2)^{2} + (y - 4)^{2} = 4(x−2)2+(y−4)2=4
  2. (B)(x−4)2+(y+2)2=16(x - 4)^{2} + (y + 2)^{2} = 16(x−4)2+(y+2)2=16
  3. (C)(x−4)2+(y−4)2=8(x - 4)^{2} + (y - 4)^{2} = 8(x−4)2+(y−4)2=8
  4. (D)(x−2)2+(y−2)2=12(x - 2)^{2} + (y - 2)^{2} = 12(x−2)2+(y−2)2=12

Correct answer: (A)

Step-by-step solution →
Q111·MathematicsSingle correctJEE Main 2021
If the curve x2^{2}2 + 2y2^{2}2 = 2 intersects the line x + y = 1 at two points P and Q, then the angle subtended by the line segment PQ at the origin is:
  1. (A)2π+tan–1^{–1}–1 (14 )
  2. (B)2π– tan–1^{–1}–1 (14 )
  3. (C)2π+tan–1^{–1}–1 (13 )
  4. (D)2π– tan–1^{–1}–1 (13 )

Correct answer: (A)

Step-by-step solution →
Q112·MathematicsSingle correctJEE Main 2021
A man is walking on a straight line. The arithmetic mean of the reciprocals of the intercepts of this line on the coordinate axes is 14\frac{1}{4}41​. Three stones A, B and C are placed at the points (1,1)(1, 1)(1,1), (2,2)(2, 2)(2,2) and (4,4)(4, 4)(4,4) respectively. Then which of these stones is/are on the path of the man?
  1. (A)B only
  2. (B)A only
  3. (C)All the three
  4. (D)C only

Correct answer: (A)

Step-by-step solution →
Q113·MathematicsSingle correctJEE Main 2020
A ray of light coming from the point (2,23)(2, 2\sqrt{3})(2,23​) is incident at an angle 30∘30^\circ30∘ on the line x=1x=1x=1 at the point A. The ray gets reflected on the line x=1x=1x=1 and meets xxx-axis at the point B. Then, the line AB passes through the point:
  1. (A)(3,−13)\left(3, -\dfrac{1}{\sqrt{3}}\right)(3,−3​1​)
  2. (B)(4,−32)\left(4, -\dfrac{\sqrt{3}}{2}\right)(4,−23​​)
  3. (C)(3,−3)\left(3, -\sqrt{3}\right)(3,−3​)
  4. (D)(4,−3)\left(4, -\sqrt{3}\right)(4,−3​)

Correct answer: (C)

Step-by-step solution →
Q114·MathematicsSingle correctJEE Main 2020
Let L denote the line in the xy-plane with x and y intercepts as 3 and 1 respectively. Then the image of the point (−1,−4)(-1, -4)(−1,−4) in this line is:
  1. (A)(115,285)\left(\frac{11}{5}, \frac{28}{5}\right)(511​,528​)
  2. (B)(295,85)\left(\frac{29}{5}, \frac{8}{5}\right)(529​,58​)
  3. (C)(85,295)\left(\frac{8}{5}, \frac{29}{5}\right)(58​,529​)
  4. (D)(295,115)\left(\frac{29}{5}, \frac{11}{5}\right)(529​,511​)

Correct answer: (A)

Step-by-step solution →
Q115·MathematicsNumericalJEE Main 2020
If the line, 2x−y+3=02x-y+3=02x−y+3=0 is at a distance 15\dfrac{1}{\sqrt{5}}5​1​ and 25\dfrac{2}{\sqrt{5}}5​2​ from the lines 4x−2y+α=04x-2y+\alpha=04x−2y+α=0 and 6x−3y+β=06x-3y+\beta=06x−3y+β=0, respectively, then the sum of all possible values of α\alphaα and β\betaβ is ____.

Correct answer: 30.00

Step-by-step solution →
Q116·MathematicsSingle correctJEE Main 2020
If the perpendicular bisector of the line segment joining the points P(1, 4) and Q(k, 3) has y-intercept equal to –4, then a value of k is:
  1. (A)14\sqrt{14}14​
  2. (B)15\sqrt{15}15​
  3. (C)– 4
  4. (D)– 2

Correct answer: (C)

Step-by-step solution →
Q117·MathematicsSingle correctJEE Main 2020
A triangle ABC lying in the first quadrant has two vertices as A(1, 2) and B(3, 1). If ∠BAC=90°\angle BAC = 90°∠BAC=90°, and ar(ΔABC)=55\mathrm{ar}\left( \Delta ABC \right) = 5\sqrt{5}ar(ΔABC)=55​ sq. units, then the abscissa of the vertex C is:
  1. (A)1+251 + 2\sqrt{5}1+25​
  2. (B)1+51 + \sqrt{5}1+5​
  3. (C)25−12\sqrt{5} - 125​−1
  4. (D)2+52 + \sqrt{5}2+5​

Correct answer: (A)

Step-by-step solution →
Q118·MathematicsSingle correctJEE Main 2020
If a ΔABC\Delta ABCΔABC have vertices A (−1,7)(-1, 7)(−1,7), B (−7,1)(-7, 1)(−7,1) and C (5,−5)(5, -5)(5,−5), then its orthocenter has coordinates:
  1. (A)(35,−35)\left( \frac{3}{5}, -\frac{3}{5} \right)(53​,−53​)
  2. (B)(−3,3)(-3, 3)(−3,3)
  3. (C)(3,−3)(3, -3)(3,−3)
  4. (D)(−35,35)\left( -\frac{3}{5}, \frac{3}{5} \right)(−53​,53​)

Correct answer: (B)

Step-by-step solution →
Q119·MathematicsSingle correctJEE Main 2020
Let C be the centroid of the triangle with vertices (3,−1)(3,-1)(3,−1), (1,3)(1,3)(1,3) AND (2,4)(2,4)(2,4). Let P be the point of intersection of the lines x+3y−1=0x+3y-1=0x+3y−1=0 and 3x−y+1=03x-y+1=03x−y+1=0. Then the line passing through the points C and P also passes through the point:
  1. (A)(−9,−7)(-9,-7)(−9,−7)
  2. (B)(−9,−6)(-9,-6)(−9,−6)
  3. (C)(7,6)(7,6)(7,6)
  4. (D)(9,7)(9,7)(9,7)

Correct answer: (B)

Step-by-step solution →
Q120·MathematicsSingle correctJEE Main 2020
Let two points be A(1, -1) and B(0, 2). If a point P(x′,y′)P(x', y')P(x′,y′) be such that the area of △PAB=5\triangle PAB = 5△PAB=5 sq. units and it lies on the line, 3x+y−4λ=03x+y-4\lambda=03x+y−4λ=0, then a value of λ\lambdaλ is:
  1. (A)3
  2. (B)4
  3. (C)1
  4. (D)-3

Correct answer: (A)

Step-by-step solution →
Q121·MathematicsNumericalJEE Main 2020
Let A(1,0),B(6,2)A(1,0), B(6,2)A(1,0),B(6,2) and C(32,6)C\left(\frac{3}{2}, 6\right)C(23​,6) be the vertices of a triangle ABC. If P is a point inside the triangle ABC such that the triangles APC, APB and BPC have equal areas, then the length of the line segment PQ, where Q is the point (−76,−13)\left(-\frac{7}{6}, -\frac{1}{3}\right)(−67​,−31​) is _________

Correct answer: 5

Step-by-step solution →
Q122·MathematicsSingle correctJEE Main 2020
The locus of the mid-points of the perpendiculars drawn from points on the line, x=2yx=2yx=2y to the line x=yx=yx=y is:
  1. (A)7x−5y=07x-5y=07x−5y=0
  2. (B)3x−2y=03x-2y=03x−2y=0
  3. (C)2x−3y=02x-3y=02x−3y=0
  4. (D)5x−7y=05x-7y=05x−7y=0

Correct answer: (D)

Step-by-step solution →
Q123·MathematicsSingle correctJEE Main 2019
A triangle has a vertex at (1, 2) and the mid points of the two sides through it are (−1, 1) and (2,3). Then the centroid of this triangle is :
  1. (A)(1,73)\left(1,\dfrac{7}{3}\right)(1,37​)
  2. (B)(13,1)\left(\dfrac{1}{3},1\right)(31​,1)
  3. (C)(13,2)\left(\dfrac{1}{3},2\right)(31​,2)
  4. (D)(13,53)\left(\dfrac{1}{3},\dfrac{5}{3}\right)(31​,35​)

Correct answer: (C)

Step-by-step solution →
Q124·MathematicsSingle correctJEE Main 2019
The equation y=sin⁡xsin⁡(x+2)−sin⁡2(x+1)y = \sin x \sin(x + 2) - \sin^{2}(x+1)y=sinxsin(x+2)−sin2(x+1) represents a straight line lying in :
  1. (A)first, third and fourth quadrants
  2. (B)first, second and fourth quadrants
  3. (C)third and fourth quadrants only
  4. (D)second and third quadrants only

Correct answer: (C)

Step-by-step solution →
Q125·MathematicsSingle correctJEE Main 2019
Lines are drawn parallel to the line 4x − 3y + 2 = 0 at a distance 35\dfrac{3}{5}53​ from the origin. Then which one of the following points lies on any of these lines?
  1. (A)(−14,23)\left(-\dfrac{1}{4}, \dfrac{2}{3}\right)(−41​,32​)
  2. (B)(14,13)\left(\dfrac{1}{4}, \dfrac{1}{3}\right)(41​,31​)
  3. (C)(14,−13)\left(\dfrac{1}{4}, -\dfrac{1}{3}\right)(41​,−31​)
  4. (D)(−14,−23)\left(-\dfrac{1}{4}, -\dfrac{2}{3}\right)(−41​,−32​)

Correct answer: (A)

Step-by-step solution →
Q126·MathematicsSingle correctJEE Main 2019
The region represented by ∣x−y∣≤2|x-y|\le 2∣x−y∣≤2 and ∣x+y∣≤2|x+y|\le 2∣x+y∣≤2 is bounded by a:
  1. (A)rhombus of area 828\sqrt{2}82​ sq. units
  2. (B)square of area 16 sq. units
  3. (C)rhombus of side length 2 units
  4. (D)square of side length 222\sqrt{2}22​ units

Correct answer: (D)

Step-by-step solution →
Q127·MathematicsSingle correctJEE Main 2019
If the two lines x+(a−1)y=1x + (a-1)y = 1x+(a−1)y=1 and 2x+a2y=1 (a∈R−{0,1})2x + a^{2}y = 1\ (a \in R - \{0,1\})2x+a2y=1 (a∈R−{0,1}) are perpendicular, then the distance of their point of intersection from the origin is:
  1. (A)25\dfrac{2}{5}52​
  2. (B)25\dfrac{\sqrt{2}}{5}52​​
  3. (C)25\dfrac{2}{\sqrt{5}}5​2​
  4. (D)25\sqrt{\dfrac{2}{5}}52​​

Correct answer: (D)

Step-by-step solution →
Q128·MathematicsSingle correctJEE Main 2019
A rectangle is inscribed in a circle with a diameter lying along the line 3y=x+73y=x+73y=x+7. If the two adjacent vertices of the rectangle are (−8,5)\left(-8,5\right)(−8,5) and (6,5)\left(6,5\right)(6,5) then the area of the rectangle (in sq. units) is
  1. (A)72
  2. (B)84
  3. (C)98
  4. (D)56

Correct answer: (B)

Step-by-step solution →
Q129·MathematicsSingle correctJEE Main 2019
A point on the straight line, 3x+5y=153x+5y=153x+5y=15 which is equidistant from the coordinate, axes will lie only in:
  1. (A)4th quadrant
  2. (B)1st, 2nd and 4th quadrants
  3. (C)1st quadrant
  4. (D)1st and 2nd quadrants

Correct answer: (D)

Step-by-step solution →
Q130·MathematicsSingle correctJEE Main 2019
Suppose that the points (h,k)(h,k)(h,k), (1,2)(1,2)(1,2) and (−3,4)(-3,4)(−3,4) lie on the line L1L_{1}L1​. If a line L2L_{2}L2​ passing through the points (h,k)(h,k)(h,k) and (4,3)(4,3)(4,3) is perpendicular to L1L_{1}L1​, then kh\frac{k}{h}hk​ equals:
  1. (A)−17-\frac{1}{7}−71​
  2. (B)13\frac{1}{3}31​
  3. (C)3
  4. (D)0

Correct answer: (B)

Step-by-step solution →
Q131·MathematicsSingle correctJEE Main 2019
If the straight line, 2x−3y+17=02x - 3y + 17 = 02x−3y+17=0 is perpendicular to the line passing through the points (7, 17) and (15,β)(15, \beta)(15,β), then β\betaβ equals:
  1. (A)353\dfrac{35}{3}335​
  2. (B)-5
  3. (C)−353-\dfrac{35}{3}−335​
  4. (D)5

Correct answer: (D)

Step-by-step solution →
Q132·MathematicsSingle correctJEE Main 2019
If a straight line passing through the point P(−3, 4) is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is :
  1. (A)3x−4y+25=03x - 4y + 25 = 03x−4y+25=0
  2. (B)4x−3y+24=04x - 3y + 24 = 04x−3y+24=0
  3. (C)x−y+7=0x - y + 7 = 0x−y+7=0
  4. (D)4x+3y=04x + 3y = 04x+3y=0

Correct answer: (B)

Step-by-step solution →
Q133·MathematicsSingle correctJEE Main 2019
If in a parallelogram ABDC, the coordinates of A, B and C are respectively (1, 2), (3, 4) and (2, 5), then the equation of the diagonal AD is:
  1. (A)5x−3y+1=05x-3y+1=05x−3y+1=0
  2. (B)5x+3y−11=05x+3y-11=05x+3y−11=0
  3. (C)3x−5y+7=03x-5y+7=03x−5y+7=0
  4. (D)3x+5y−13=03x+5y-13=03x+5y−13=0

Correct answer: (A)

Step-by-step solution →
Q134·MathematicsSingle correctJEE Main 2019
A point P moves on the line 2x−3y+4=02x - 3y + 4 = 02x−3y+4=0. If Q(1, 4) and R(3, −2-2−2) are fixed points, then the locus of the centroid of △\triangle△PQR is a line:
  1. (A)with slope 32\dfrac{3}{2}23​
  2. (B)parallel to x-axis
  3. (C)with slope 23\dfrac{2}{3}32​
  4. (D)parallel to y-axis

Correct answer: (C)

Step-by-step solution →
Q135·MathematicsSingle correctJEE Main 2019
Let the equation of two sides of a triangle be 3x−2y+6=03x - 2y + 6 = 03x−2y+6=0 and 4x+5y−20=04x + 5y - 20 = 04x+5y−20=0. If the orthocentre of this triangle is at (1, 1), then the equation of its third side is:
  1. (A)122y−26x−1675=0122y - 26x - 1675 = 0122y−26x−1675=0
  2. (B)26x+61y+1675=026x + 61y + 1675 = 026x+61y+1675=0
  3. (C)122y+26x+1675=0122y + 26x + 1675 = 0122y+26x+1675=0
  4. (D)26x−122y−1675=026x - 122y - 1675 = 026x−122y−1675=0

Correct answer: (D)

Step-by-step solution →
Q136·MathematicsSingle correctJEE Main 2019
Consider the set of all lines px+qy+r=0px + qy + r = 0px+qy+r=0 such that 3p+2q+4r=03p + 2q + 4r = 03p+2q+4r=0. Which one of the following statements is true?
  1. (A)The lines are concurrent at the point (34,12)\left(\dfrac{3}{4}, \dfrac{1}{2}\right)(43​,21​).
  2. (B)Each line passes through the origin.
  3. (C)The lines are all parallel
  4. (D)The lines are not concurrent

Correct answer: (A)

Step-by-step solution →
Q137·MathematicsSingle correctJEE Advanced 2013
For a>b>c>0a>b>c>0a>b>c>0, the distance between (1,1)(1,1)(1,1) and the point of intersection of the lines ax+by+c=0ax+by+c=0ax+by+c=0 and bx+ay+c=0bx+ay+c=0bx+ay+c=0 is less than 222\sqrt{2}22​, then
  1. (A)a+b−c>0a+b-c>0a+b−c>0
  2. (B)a−b+c<0a-b+c<0a−b+c<0
  3. (C)a−b+c>0a-b+c>0a−b+c>0
  4. (D)a+b−c<0a+b-c<0a+b−c<0

Correct answer: (A)

Step-by-step solution →

Straight Lines — frequently asked

How many questions from Straight Lines appear in JEE?

Straight Lines has appeared in 114 of the last 186 JEE Main and JEE Advanced papers — about 61% of them — contributing 137 questions in total across those papers.

Is Straight Lines an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 61% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Straight Lines questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Mathematics chapters

  • Three Dimensional Geometry 344
  • Matrices and Determinants 342
  • Sets, Relations and Functions 313
  • Sequence and Series 287
  • Definite Integration 267
  • Vector Algebra 245
  • Differential Equations 240
  • Probability 226

All 26 Mathematics chapters →

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