Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Physics PYQs
  3. /Thermodynamics

Thermodynamics — JEE Previous Year Questions

Every Thermodynamics question asked in JEE Main and JEE Advanced across the last 186 papers — 201 questions, each with its correct answer. Free to read, no account needed.

Questions

201

Papers it appeared in

154/186

Appearance rate

83%

All 201 Thermodynamics questions

Most recent papers first.

Q1·PhysicsMultiple correctJEE Advanced 2026
A quasi-static cycle of a monoatomic ideal gas contains an isothermal process (ab)(ab)(ab), followed by an isochoric process (bc)(bc)(bc) and an adiabatic process (ca)(ca)(ca) as shown in the figure. The volumes of the gas are V1V_1V1​ and V2V_2V2​ at aaa and bbb, respectively. If the cycle has heat input QinQ_{\text{in}}Qin​ and output QoutQ_{\text{out}}Qout​, then the efficiency of the cycle is defined as η=Qin−QoutQin\eta = \frac{Q_{\text{in}} - Q_{\text{out}}}{Q_{\text{in}}}η=Qin​Qin​−Qout​​. The correct statement(s) is/are: [Given: ln⁡2≈0.7\ln 2 \approx 0.7ln2≈0.7]
  1. (A)If V2/V1=8V_2/V_1 = 8V2​/V1​=8, the heat released in the process bcbcbc is smaller than the heat absorbed in the process ababab.
  2. (B)For a given value of V2/V1V_2/V_1V2​/V1​, η\etaη does not depend on the temperature of the isothermal process.
  3. (C)If V2/V1=8V_2/V_1 = 8V2​/V1​=8, then the temperature of the gas at aaa is 4 times the temperature of the gas at ccc.
  4. (D)If V2/V1=8V_2/V_1 = 8V2​/V1​=8, then the pressure of the gas at aaa is 4 times the pressure of the gas at bbb.

Correct answer: (A), (B), (C)

Step-by-step solution →
Q2·PhysicsNumericalJEE Advanced 2026
As shown in the figure, an insulated container is fitted with a thermally conducting but immovable partition (P1)(P_1)(P1​) and a freely movable but thermally insulated piston (P2)(P_2)(P2​). The partition P1P_1P1​ with thermal conductivity KKK, cross sectional area AAA and width xxx divides the container into two sections, S1S_1S1​ and S2S_2S2​, each containing one mole of a monoatomic gas. The piston P2P_2P2​ moves freely such that the gas in S2S_2S2​ is always at the atmospheric pressure. Initially, the difference between the temperatures of S1S_1S1​ and S2S_2S2​ is ΔT0\Delta T_0ΔT0​. The time it takes for the temperature difference to become ΔT02\frac{\Delta T_0}{2}2ΔT0​​ is nxR/KAnxR/KAnxR/KA, where RRR is the universal gas constant. The value of nnn is: [Given: ln⁡2≈0.7\ln 2 \approx 0.7ln2≈0.7]

Correct answer: 0.66

Step-by-step solution →
Q3·PhysicsMultiple correctJEE Advanced 2026
Ten moles of an ideal monoatomic gas, initially in state a\boldsymbol{a}a at atmospheric pressure and temperature Ta=27T_{a} = 27Ta​=27°C, is enclosed in a metal cylinder of volume V0V_{0}V0​ fitted with a frictionless piston. The gas is suddenly compressed to state b\boldsymbol{b}b with volume V0/3V_{0}/3V0​/3. Now, keeping the piston stationary, the cylinder is submerged in a water bath of temperature 11°C until the gas reaches the temperature of the water bath, which is denoted as state c\boldsymbol{c}c. Finally, while still in the water bath, the piston is brought slowly to its initial position, which is denoted as state f\boldsymbol{f}f. If RRR is universal gas constant, then the correct option(s) is/are: [Given: 91/3=2.089^{1/3} = 2.0891/3=2.08]
  1. (A)The schematic P-V diagram of the processes described above is:
  2. (B)The change in internal energy in going from state a\boldsymbol{a}a to b\boldsymbol{b}b is 4860R4860R4860R.
  3. (C)The net change in the internal energy in the whole process is −240R-240R−240R.
  4. (D)The pressure and temperature of the state b\boldsymbol{b}b are 2.08 times the atmospheric pressure and 624 K, respectively.

Correct answer: (A), (B), (C)

Step-by-step solution →
Q4·PhysicsNumericalJEE Advanced 2026
As shown in the figure, five Carnot engines, each with efficiency η\etaη and same number of cycles per unit time, are operating between six heat reservoirs. The amount of heat released per cycle by one engine is completely absorbed by the next engine. Consider Q0Q_0Q0​ to be the amount of heat absorbed per cycle by the first engine and WWW as the amount of total work done by all the engines per cycle, then the net efficiency of the system is found to be ηnet=WQ0=211243\eta_{\text{net}} = \frac{W}{Q_0} = \frac{211}{243}ηnet​=Q0​W​=243211​. The value of η\etaη is:

Correct answer: 0.33

Step-by-step solution →
Q5·PhysicsSingle correctJEE Main 2026
Initial pressure and volume of a monoatomic ideal gas are PPP and VVV. The change in internal energy of this gas in adiabatic expansion to volume Vfinal=27VV_{final} = 27VVfinal​=27V is ________ J.
  1. (A)−2PV(33−1)-2PV(3\sqrt{3}-1)−2PV(33​−1)
  2. (B)43PV\dfrac{4}{3}PV34​PV
  3. (C)−43PV-\dfrac{4}{3}PV−34​PV
  4. (D)34PV\dfrac{3}{4}PV43​PV

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsNumericalJEE Main 2026
A certain gas is isothermally compressed to (13)rd\left(\frac{1}{3}\right)^{rd}(31​)rd of its initial volume (Vo=3V_o = 3Vo​=3 litre) by applying required pressure. If the bulk modulus of the gas is 3×1053 \times 10^{5}3×105 N/m2^{2}2, the magnitude of work done on the gas is _______ J.

Correct answer: 989

Step-by-step solution →
Q7·PhysicsSingle correctJEE Main 2026
A cylinder with adiabatic walls is closed at both ends and is divided into two compartments by a frictionless adiabatic piston. Ideal gas is filled in both (left and right) the compartments at same P,V,TP, V, TP,V,T. Heating is started from left side until pressure changes to 27P8\frac{27P}{8}827P​. If initial volume of each compartment was 9 litres then the final volume in right-hand side compartment is __________ litres. (for this ideal gas CP/CV=1.5C_{P}/C_{V} = 1.5CP​/CV​=1.5)
  1. (A)3
  2. (B)4
  3. (C)14
  4. (D)9

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correctJEE Main 2026
Consider the following statements: A. Zeroth law of thermodynamics gives concept of temperature B. First law of thermodynamics gives concept of internal energy C. In isothermal expansion of ideal gas, ΔQ≠ΔW\Delta Q \neq \Delta WΔQ=ΔW D. Product of intensive and extensive variables is extensive E. The ratio of any extensive variable to mass will be an extensive variable Choose the correct combination of statements from the options given below:
  1. (A)C, D and E Only
  2. (B)A, B and C Only
  3. (C)A, B and D Only
  4. (D)B, C and D Only

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correctJEE Main 2026
An ideal gas undergoes a process maintaining relation between pressure (P)(P)(P) and volume (V)(V)(V) as P=Po(1+(VoV)2)−1P = P_o\left(1 + \left(\frac{V_o}{V}\right)^2\right)^{-1}P=Po​(1+(VVo​​)2)−1 , where PoP_oPo​ and VoV_oVo​ are constants. If two samples AAA and BBB (two moles each) with initial volumes VoV_oVo​ and 3Vo3V_o3Vo​ respectively undergo above mentioned process and attain same pressure, then the difference at the temperatures of these samples, TB−TAT_B - T_ATB​−TA​ is _____. (R=R =R= gas constant)
  1. (A)9PoVo8R\frac{9P_oV_o}{8R}8R9Po​Vo​​
  2. (B)11PoVo10R\frac{11P_oV_o}{10R}10R11Po​Vo​​
  3. (C)7PoVo6R\frac{7P_oV_o}{6R}6R7Po​Vo​​
  4. (D)13PoVo11R\frac{13P_oV_o}{11R}11R13Po​Vo​​

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correctJEE Main 2026
Heat is supplied to a diatomic gas at constant pressure. Then the ratio of ΔQ:ΔU:ΔW\Delta Q : \Delta U : \Delta WΔQ:ΔU:ΔW is ______.
  1. (A)2 : 3 : 5
  2. (B)5 : 3 : 2
  3. (C)2 : 5 : 7
  4. (D)7 : 5 : 2

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsNumericalJEE Main 2026
A vessel contains 0.150.150.15 m3^{3}3 of a gas at pressure 8 bar and temperature 140 °C with cp=3Rc_{p} = 3Rcp​=3R and cv=2Rc_{v} = 2Rcv​=2R. It is expanded adiabatically till pressure falls to 1 bar. The work done during this process is ________ kJ. (RRR is gas constant)

Correct answer: 120

Step-by-step solution →
Q12·PhysicsNumericalJEE Main 2026
5 moles of unknown gas is heated at constant volume from 10 ∘C10\,^\circ C10∘C to 20 ∘C20\,^\circ C20∘C. The molar specific heat of this gas at constant pressure cp=8c_p = 8cp​=8 cal/mol.∘^\circ∘C and R=8.36R = 8.36R=8.36 J/mol.∘^\circ∘C. The change in the internal energy of the gas is ________ calorie.

Correct answer: 300

Step-by-step solution →
Q13·PhysicsNumericalJEE Main 2026
A thermodynamic system is taken through the cyclic process ABC as shown in the figure. The total work done by the system during the cycle ABC is _______ J.

Correct answer: 300

Step-by-step solution →
Q14·PhysicsSingle correctJEE Main 2026
In the following ppp-VVV diagram the equation of state along the curved path is given by (V−2)2=4ap(V - 2)^{2} = 4ap(V−2)2=4ap where aaa is a constant. The total work done in the closed path is
  1. (A)−1a-\frac{1}{a}−a1​
  2. (B)+13a+\frac{1}{3a}+3a1​
  3. (C)12a\frac{1}{2a}2a1​
  4. (D)−13a-\frac{1}{3a}−3a1​

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correctJEE Main 2026
Density of water at 4°C and 20°C are 1000 kg/m3\mathrm{kg/m^{3}}kg/m3 and respectively. The increase in internal energy of 4 kg water when it is heated from 4 °C to 20°C is____J. (Specific heat capacity of water = 4.2 J/kg. and 1 atmospheric pressure = 10510^{5}105 Pa)
  1. (A)315826.2
  2. (B)234699.2
  3. (C)258700.8
  4. (D)268799.2

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correctJEE Main 2026
10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P1\text{P}_1P1​ to P2\text{P}_2P2​ is α\alphaα Joule (P1=21.7\text{P}_1 = 21.7P1​=21.7 Pa and P2=30\text{P}_2 = 30P2​=30 Pa, Cv=21\text{C}_\text{v} = 21Cv​=21 J/K.mol, R=8.3R = 8.3R=8.3 J/mol.K). The value of α\alphaα is _____.
  1. (A)24
  2. (B)15
  3. (C)21
  4. (D)28

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correctJEE Main 2026
One mole of an ideal diatomic gas expands from volume V to 2V isothermally at a temperature 27°C and does W joule of work. If the gas undergoes same magnitude of expansion adiabatically from 27°C doing the same amount of work W, then its final temperature will be (close to) __________ °C.
  1. (A)−189
  2. (B)−56
  3. (C)−30
  4. (D)−117

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correctJEE Main 2026
The internal energy of a monoatomic gas is 3nRT. One mole of helium is kept in a cylinder having internal cross section area of 17 cm2^{2}2 and fitted with a light movable frictionless piston. The gas is heated slowly by suppling 126 J heat. If the temperature rises by 4 °C, then the piston will move______cm. (atmospheric pressure = 10510^{5}105 Pa)
  1. (A)14.5
  2. (B)1.55
  3. (C)15.5
  4. (D)1.45

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correctJEE Main 2026
The volume of an ideal gas increases 8 times and temperature becomes (1/4)th(1/4)^{th}(1/4)th of initial temperature during a reversible change. If there is no exchange of heat in this process (ΔQ = 0) then identify the gas from the following options (Assuming the gases given in the options are ideal gases) :
  1. (A)CO2CO_2CO2​
  2. (B)O2O_2O2​
  3. (C)NH3NH_3NH3​
  4. (D)He

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsNumericalJEE Main 2026
10 mole of oxygen is heated at constant volume from 30°C to 40°C. The change in the internal energy of the gas is _______ cal. (The molecular specific heat of oxygen at constant pressure, CpC_pCp​ = 7 cal./mol °C and R = 2 cal./mol °C.)

Correct answer: 500

Step-by-step solution →
Q21·PhysicsNumericalJEE Main 2026
A diatomic gas (γ=1.4\gamma = 1.4γ=1.4) does 100 J of work when it is expanded isobarically. Then the heat given to the gas __________ J.

Correct answer: 350

Step-by-step solution →
Q22·PhysicsNumericalJEE Advanced 2025
An ideal monatomic gas of n moles is taken through a cycle WXYZW consisting of consecutive adiabatic and isobaric quasi-static processes, as shown in the schematic V-T diagram. The volume of the gas at W, X and Y points are, 64 cm3^33, 125 cm3^33 and 250 cm3^33 respectively. If the absolute temperature of the gas TWT_WTW​ at the point W is such that nRTW=1nRT_W = 1nRTW​=1 J (R is the universal gas constant), then the amount of heat absorbed (in J) by the gas along the path XY is ______

Correct answer: 1.6

Step-by-step solution →
Q23·PhysicsMultiple correctJEE Advanced 2025
The efficiency of a Carnot engine operating with a hot reservoir kept at a temperature of 1000 K is 0.4. It extracts 150 J of heat per cycle from the hot reservoir. The work extracted from this engine is being fully used to run a heat pump which has a coefficient of performance 10. The hot reservoir of the heat pump is at a temperature of 300 K. Which of the following statements is/are correct:
  1. (A)Work extracted from the Carnot engine in one cycle is 60 J .
  2. (B)Temperature of the cold reservoir of the Carnot engine is 600 K .
  3. (C)Temperature of the cold reservoir of the heat pump is 270 K .
  4. (D)Heat supplied to the hot reservoir of the heat pump in one cycle is 540 J .

Correct answer: (A), (B), (C)

Step-by-step solution →
Q24·PhysicsSingle correctJEE Main 2025
A monoatomic gas having γ=53\gamma=\dfrac{5}{3}γ=35​ is stored in a thermally insulated container and the gas is suddenly compressed to (18)th\left(\dfrac{1}{8}\right)^{th}(81​)th of its initial volume. The ratio of final pressure and initial pressure is: (γ\gammaγ is the ratio of specific heats of the gas at constant pressure and at constant volume)
  1. (A)161616
  2. (B)404040
  3. (C)323232
  4. (D)282828

Correct answer: (C)

Step-by-step solution →
Q25·PhysicsSingle correctJEE Main 2025
Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool. (Take g=10 m/s2g=10\ m/s^2g=10 m/s2, specific heat of water =4200 J/(kg⋅K)=4200\ J/(kg\cdot K)=4200 J/(kg⋅K))
  1. (A)0.23 K0.23\ K0.23 K
  2. (B)0.36 K0.36\ K0.36 K
  3. (C)0.14 K0.14\ K0.14 K
  4. (D)0.48 K0.48\ K0.48 K

Correct answer: (D)

Step-by-step solution →
Q26·PhysicsIntegerJEE Main 2025
An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ______ ×10−1\times10^{-1}×10−1 J. (Take π=3.14\pi=3.14π=3.14)

Correct answer: 314

Step-by-step solution →
Q27·PhysicsSingle correctJEE Main 2025
Match the LIST-I (Thermodynamic process) with LIST-II (Characteristic). Choose the correct answer from the options given below:
LIST-I (Thermodynamic process)LIST-II (Characteristic)
A.IsothermalI.ΔW\Delta WΔW (work done) =0=0=0
B.AdiabaticII.ΔQ\Delta QΔQ (supplied heat) =0=0=0
C.IsobaricIII.ΔU\Delta UΔU (change in internal energy) ≠0\ne 0=0
D.IsochoricIV.ΔU=0\Delta U=0ΔU=0
  1. (A)(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  2. (B)(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  3. (C)(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  4. (D)(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct answer: (C)

Step-by-step solution →
Q28·PhysicsSingle correctJEE Main 2025
Match List-I (Process) with List-II (First-law relation). Choose the correct answer from the options given below:
List-I (Process)List-II (First-law relation)
A.IsobaricI.ΔQ=ΔW\Delta Q=\Delta WΔQ=ΔW
B.IsochoricII.ΔQ=ΔU\Delta Q=\Delta UΔQ=ΔU
C.AdiabaticIII.ΔQ=\Delta Q=ΔQ= zero
D.IsothermalIV.ΔQ=ΔU+PΔV\Delta Q=\Delta U+P\Delta VΔQ=ΔU+PΔV
  1. (A)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  2. (B)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  3. (C)(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  4. (D)(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Correct answer: (C)

Step-by-step solution →
Q29·PhysicsSingle correctJEE Main 2025
A piston of mass M is hung from a massless spring whose restoring force law goes as F=−kx3F=-kx^3F=−kx3, where kkk is the spring constant of appropriate dimension. The piston separates the vertical chamber into two parts, where the bottom part is filled with nnn moles of an ideal gas. An external work is done on the gas isothermally (at a constant temperature T) with the help of a heating filament (with negligible volume) mounted in the lower part of the chamber, so that the piston goes up from a height L0L_0L0​ to L1L_1L1​. The total energy delivered by the filament is (assume the spring to be at its natural length before heating):
  1. (A)3nRTln⁡ ⁣(L1L0)+2Mg(L1−L0)+k3(L13−L03)3nRT\ln\!\left(\dfrac{L_1}{L_0}\right)+2Mg(L_1-L_0)+\dfrac{k}{3}(L_1^3-L_0^3)3nRTln(L0​L1​​)+2Mg(L1​−L0​)+3k​(L13​−L03​)
  2. (B)nRTln⁡ ⁣(L12L02)+Mg2(L1−L0)+k4(L14−L04)nRT\ln\!\left(\dfrac{L_1^2}{L_0^2}\right)+\dfrac{Mg}{2}(L_1-L_0)+\dfrac{k}{4}(L_1^4-L_0^4)nRTln(L02​L12​​)+2Mg​(L1​−L0​)+4k​(L14​−L04​)
  3. (C)nRTln⁡ ⁣(L1L0)+Mg(L1−L0)+k4(L14−L04)nRT\ln\!\left(\dfrac{L_1}{L_0}\right)+Mg(L_1-L_0)+\dfrac{k}{4}(L_1^4-L_0^4)nRTln(L0​L1​​)+Mg(L1​−L0​)+4k​(L14​−L04​)
  4. (D)nRTln⁡ ⁣(L1L0)+Mg(L1−L0)+3k4(L14−L04)nRT\ln\!\left(\dfrac{L_1}{L_0}\right)+Mg(L_1-L_0)+\dfrac{3k}{4}(L_1^4-L_0^4)nRTln(L0​L1​​)+Mg(L1​−L0​)+43k​(L14​−L04​)

Correct answer: (C)

Step-by-step solution →
Q30·PhysicsSingle correctJEE Main 2025
A gas is kept in a container having walls which are thermally non-conducting. Initially the gas has a volume of 800 cm3800\,\text{cm}^3800cm3 and temperature 27∘27^\circ27∘C. The change in temperature when the gas is adiabatically compressed to 200 cm3200\,\text{cm}^3200cm3 is: (Take γ=1.5\gamma=1.5γ=1.5; γ\gammaγ is the ratio of specific heats at constant pressure and at constant volume)
  1. (A)327 K
  2. (B)600 K
  3. (C)522 K
  4. (D)300 K

Correct answer: (D)

Step-by-step solution →
Q31·PhysicsSingle correctJEE Main 2025
An ideal gas exists in a state with pressure P0P_0P0​, volume V0V_0V0​. It is isothermally expanded to 4 times of its initial volume (V0)(V_0)(V0​), then isobarically compressed to its original volume. Finally the system is heated isochorically to bring it to its initial state. The amount of heat exchanged in this process is:
  1. (A)P0V0(2ln⁡2−0.75)P_0V_0(2\ln 2-0.75)P0​V0​(2ln2−0.75)
  2. (B)P0V0(ln⁡2−0.75)P_0V_0(\ln 2-0.75)P0​V0​(ln2−0.75)
  3. (C)P0V0(2ln⁡2−0.25)P_0V_0(2\ln 2-0.25)P0​V0​(2ln2−0.25)
  4. (D)P0V0(2ln⁡2+0.25)P_0V_0(2\ln 2+0.25)P0​V0​(2ln2+0.25)

Correct answer: (A)

Step-by-step solution →
Q32·PhysicsSingle correctJEE Main 2025
During the melting of a slab of ice at 273 K at atmospheric pressure:
  1. (A)Internal energy of ice-water system remains unchanged.
  2. (B)Positive work is done by the ice-water system on the atmosphere.
  3. (C)Internal energy of the ice-water system decreases.
  4. (D)Positive work is done on the ice-water system by the atmosphere.

Correct answer: (D)

Step-by-step solution →
Q33·PhysicsSingle correctJEE Main 2025
Identify the characteristics of an adiabatic process in a monoatomic gas. (A) Internal energy is constant. (B) Work done in the process is equal to the change in internal energy. (C) The product of temperature and volume is a constant. (D) The product of pressure and volume is a constant. (E) The work done to change the temperature from T1T_1T1​ to T2T_2T2​ is proportional to (T2−T1)(T_2-T_1)(T2​−T1​). Choose the correct answer from the options given below:
  1. (A)(A), (C), (D) only
  2. (B)(A), (C), (E) only
  3. (C)(B), (E) only
  4. (D)(B), (D) only

Correct answer: (C)

Step-by-step solution →
Q34·PhysicsSingle correctJEE Main 2025
In an adiabatic process, which of the following statements is true?
  1. (A)The molar heat capacity is infinite
  2. (B)Work done by the gas equals the increase in internal energy
  3. (C)The molar heat capacity is zero
  4. (D)The internal energy of the gas decreases as the temperature increases

Correct answer: (C)

Step-by-step solution →
Q35·PhysicsSingle correctJEE Main 2025
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): With the increase in the pressure of an ideal gas, the volume falls off more rapidly in an isothermal process in comparison to the adiabatic process. Reason (R): In isothermal process, PV = constant, while in adiabatic process PVγPV^{\gamma}PVγ = constant. Here γ\gammaγ is the ratio of specific heats, P is the pressure and V is the volume of the ideal gas. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
  2. (B)(A) is true but (R) is false
  3. (C)Both (A) and (R) are true and (R) is the correct explanation of (A)
  4. (D)(A) is false but (R) is true

Correct answer: (C)

Step-by-step solution →
Q36·PhysicsSingle correctJEE Main 2025
The workdone in an adiabatic change in an ideal gas depends upon only:
  1. (A)change in its pressure
  2. (B)change in its specific heat
  3. (C)change in its volume
  4. (D)change in its temperature

Correct answer: (D)

Step-by-step solution →
Q37·PhysicsSingle correctJEE Main 2025
A cup of coffee cools from 90°C to 80°C in t minutes when the room temperature is 20°C. The time taken by the similar cup of coffee to cool from 80°C to 60°C at the same room temperature is:
  1. (A)135t\dfrac{13}{5}t513​t
  2. (B)1013t\dfrac{10}{13}t1310​t
  3. (C)1310t\dfrac{13}{10}t1013​t
  4. (D)513t\dfrac{5}{13}t135​t

Correct answer: (A)

Step-by-step solution →
Q38·PhysicsSingle correctJEE Main 2025
A Carnot engine (E) is working between two temperatures 473K and 273K. In a new system two engines – engine E1E_1E1​ works between 473K to 373K and engine E2E_2E2​ works between 373K to 273K. If η12\eta_{12}η12​, η1\eta_1η1​ and η2\eta_2η2​ are the efficiencies of the engines E, E1E_1E1​ and E2E_2E2​, respectively, then
  1. (A)η12<η1+η2\eta_{12}<\eta_1+\eta_2η12​<η1​+η2​
  2. (B)η12=η1η2\eta_{12}=\eta_1\eta_2η12​=η1​η2​
  3. (C)η12=η1+η2\eta_{12}=\eta_1+\eta_2η12​=η1​+η2​
  4. (D)η12≥η1+η2\eta_{12}\ge\eta_1+\eta_2η12​≥η1​+η2​

Correct answer: (A)

Step-by-step solution →
Q39·PhysicsSingle correctJEE Main 2025
The temperature of a body in air falls from 40∘40^\circ40∘C to 24∘24^\circ24∘C in 4 minutes. The temperature of the air is 16∘16^\circ16∘C. The temperature of the body in the next 4 minutes will be :
  1. (A)143 ∘\dfrac{14}{3}\,^\circ314​∘C
  2. (B)283 ∘\dfrac{28}{3}\,^\circ328​∘C
  3. (C)563 ∘\dfrac{56}{3}\,^\circ356​∘C
  4. (D)423 ∘\dfrac{42}{3}\,^\circ342​∘C

Correct answer: (C)

Step-by-step solution →
Q40·PhysicsSingle correctJEE Main 2025
Given below are two statements. Assertion (A) : In an insulated container, a gas is adiabatically shrunk to half of its initial volume. The temperature of the gas decreases. Reason (R) : Free expansion of an ideal gas is an irreversible and an adiabatic process. In the light of the above statement, choose the correct answer from the options given below :
  1. (A)Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. (B)(A) is true but (R) is false
  3. (C)(A) is false but (R) is true
  4. (D)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

Correct answer: (C)

Step-by-step solution →
Q41·PhysicsSingle correctJEE Main 2025
The magnitude of heat exchanged by a system for the given cyclic process ABCA (as shown in figure, a semicircular loop in the P-V plane with P in kPa and V in cc) is (in SI unit):
  1. (A)10π10\pi10π
  2. (B)5π5\pi5π
  3. (C)zero
  4. (D)40π40\pi40π

Correct answer: (B)

Step-by-step solution →
Q42·PhysicsSingle correctJEE Main 2025
An ideal gas goes from an initial state to final state. During the process, the pressure of gas increases linearly with temperature. A. The work done by gas during the process is zero. B. The heat added to gas is different from change in its internal energy. C. The volume of the gas is increased. D. The internal energy of the gas is increased. E. The process is isochoric (constant volume process). Choose the correct answer from the options given below :-
  1. (A)A, B, C, D Only
  2. (B)A, D, E Only
  3. (C)E Only
  4. (D)A, C Only

Correct answer: (B)

Step-by-step solution →
Q43·PhysicsSingle correctJEE Main 2025
Which of the following figure represents the relation between Celsius and Fahrenheit temperatures? (Choose the correct C vs F graph.)
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q44·PhysicsSingle correctJEE Main 2025
Water of mass m gram is slowly heated to increase the temperature from T1T_1T1​ to T2T_2T2​. The change in entropy of the water, given specific heat of water is 1 Jkg−1K−11\ \mathrm{Jkg^{-1}K^{-1}}1 Jkg−1K−1, is :
  1. (A)zero
  2. (B)m(T2−T1)m(T_2-T_1)m(T2​−T1​)
  3. (C)mln⁡ ⁣(T1T2)m\ln\!\left(\dfrac{T_1}{T_2}\right)mln(T2​T1​​)
  4. (D)mln⁡ ⁣(T2T1)m\ln\!\left(\dfrac{T_2}{T_1}\right)mln(T1​T2​​)

Correct answer: (D)

Step-by-step solution →
Q45·PhysicsSingle correctJEE Main 2025
Match List-I (Thermodynamic Process) with List-II (Process Name). Choose the correct answer from the options given below:
List-I (Thermodynamic Process)List-II (Process Name)
A.Pressure varies inversely with volume of an ideal gasI.Adiabatic process
B.Heat absorbed goes partly to increase internal energy and partly to do workII.Isochoric process
C.Heat is neither absorbed nor released by a systemIII.Isothermal process
D.No work is done on or by a gasIV.Isobaric process
  1. (A)A-II, B-IV, C-II, D-III
  2. (B)A-III, B-I, C-IV, D-II
  3. (C)A-I, B-III, C-II, D-IV
  4. (D)A-III, B-IV, C-I, D-II

Correct answer: (D)

Step-by-step solution →
Q46·PhysicsSingle correctJEE Main 2025
Using the given P-V diagram, the work done by an ideal gas along the path ABCD is :
  1. (A)4 P0V04\,P_0V_04P0​V0​
  2. (B)3 P0V03\,P_0V_03P0​V0​
  3. (C)−4 P0V0-4\,P_0V_0−4P0​V0​
  4. (D)−3 P0V0-3\,P_0V_0−3P0​V0​

Correct answer: (D)

Step-by-step solution →
Q47·PhysicsSingle correctJEE Main 2025
A gun fires a lead bullet of temperature 300K into a wooden block. The bullet having melting temperature of 600 K penetrates into the block and melts down. If the total heat required for the process is 625 J, then the mass of the bullet is _______ grams. (Latent heat of fusion of lead =2.5×104=2.5\times10^4=2.5×104 JKg−1^{-1}−1 and specific heat capacity of lead =125=125=125 JKg−1^{-1}−1K−1^{-1}−1)
  1. (A)20
  2. (B)15
  3. (C)10
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q48·PhysicsSingle correctJEE Main 2025
Given are statements for certain thermodynamic variables, (A) Internal energy, volume (V) and mass (M) are extensive variables. (B) Pressure (P), temperature (T) and density (ρ\rhoρ) are intensive variables. (C) Volume (V), temperature (T) and density (ρ\rhoρ) are intensive variables. (D) Mass (M), temperature (T) and internal energy are extensive variables. Choose the correct answer from the points given below:
  1. (A)(C) and (D) only
  2. (B)(D) and (A) only
  3. (C)(A) and (B) only
  4. (D)(B) and (C) only

Correct answer: (C)

Step-by-step solution →
Q49·PhysicsIntegerJEE Main 2025
Three conductors of the same length having thermal conductivities k₁, k₂ and k₃ are connected as shown in the figure (a 100°C end joined through the 1st conductor to a junction, then the 2nd conductor to a 0°C end, with the 3rd conductor also bridging the junction to 0°C). The area of cross-section of the 1st and 2nd conductors is A and that of the 3rd conductor is 2A. With k₁ = 60 J s⁻¹m⁻¹K⁻¹, k₂ = 120 J s⁻¹m⁻¹K⁻¹ and k₃ = 135 J s⁻¹m⁻¹K⁻¹, the temperature θ (°C) of the junction is ______.

Correct answer: 40

Step-by-step solution →
Q50·PhysicsSingle correctJEE Main 2025
Two spherical bodies of the same material having radii 0.2 m and 0.8 m are placed in the same atmosphere. The temperature of the smaller body is 800 K and that of the bigger body is 400 K. If the energy radiated from the bigger body is E, the energy radiated from the smaller body (effect of the surroundings being negligible) is:
  1. (A)256E
  2. (B)E
  3. (C)64E
  4. (D)16E

Correct answer: (B)

Step-by-step solution →
Q51·PhysicsIntegerJEE Advanced 2024
The specific heat capacity of a substance is temperature dependent and is given by the formula C=kTC = kTC=kT, where kkk is a constant of suitable dimensions in SI units, and TTT is the absolute temperature. If the heat required to raise the temperature of 1 kg of the substance from −73∘-73^{\circ}−73∘C to 27∘27^{\circ}27∘C is nknknk, the value of nnn is ______. [Given: 0 K =−273∘= -273^{\circ}=−273∘C]

Correct answer: 25000

Step-by-step solution →
Q52·PhysicsSingle correctJEE Advanced 2024
One mole of a monatomic ideal gas undergoes the cyclic process J→K→L→M→JJ \to K \to L \to M \to JJ→K→L→M→J, as shown in the P-T diagram. Match the quantities mentioned in List-I with their values in List-II and choose the correct option. [R is the gas constant.]
List-IList-II
P.Work done in the complete cyclic process1.RT0−4RT0ln⁡2RT_{0} - 4RT_{0}\ln 2RT0​−4RT0​ln2
Q.Change in the internal energy of the gas in the process JK2.0
R.Heat given to the gas in the process KL3.3RT03RT_{0}3RT0​
S.Change in the internal energy of the gas in the process MJ4.−2RT0ln⁡2-2RT_{0}\ln 2−2RT0​ln2
5.−3RT0ln⁡2-3RT_{0}\ln 2−3RT0​ln2
  1. (A)P →\to→ 1; Q →\to→ 3; R →\to→ 5; S →\to→ 4
  2. (B)P →\to→ 4; Q →\to→ 3; R →\to→ 5; S →\to→ 2
  3. (C)P →\to→ 4; Q →\to→ 1; R →\to→ 2; S →\to→ 2
  4. (D)P →\to→ 2; Q →\to→ 5; R →\to→ 3; S →\to→ 4

Correct answer: (B)

Step-by-step solution →
Q53·PhysicsSingle correctJEE Main 2024
A real gas within a closed chamber at 27 ∘27\,^{\circ}27∘C undergoes the cyclic process as shown in the figure. The gas obeys PV3=RTPV^{3}=RTPV3=RT equation for the path A to B. The net work done in the complete cycle is (assuming R=8R=8R=8 J/mol K):
  1. (A)225 J
  2. (B)205 J
  3. (C)20 J
  4. (D)−20-20−20 J

Correct answer: (B)

Step-by-step solution →
Q54·PhysicsSingle correctJEE Main 2024
The volume of an ideal gas (γ=1.5\gamma = 1.5γ=1.5) is changed adiabatically from 5 litres to 4 litres. The ratio of initial pressure to final pressure is:
  1. (A)45\dfrac{4}{5}54​
  2. (B)1625\dfrac{16}{25}2516​
  3. (C)855\dfrac{8}{5\sqrt{5}}55​8​
  4. (D)25\dfrac{2}{\sqrt{5}}5​2​

Correct answer: (C)

Step-by-step solution →
Q55·PhysicsSingle correctJEE Main 2024
A sample of 1 mole gas at temperature TTT is adiabatically expanded to double its volume. If adiabatic constant for the gas is γ=32\gamma=\frac{3}{2}γ=23​, then the work done by the gas in the process is:
  1. (A)RT[2−2]RT\left[2-\sqrt{2}\right]RT[2−2​]
  2. (B)RT[2−2]\frac{R}{T}\left[2-\sqrt{2}\right]TR​[2−2​]
  3. (C)RT[2+2]RT\left[2+\sqrt{2}\right]RT[2+2​]
  4. (D)TR[2+2]\frac{T}{R}\left[2+\sqrt{2}\right]RT​[2+2​]

Correct answer: (A)

Step-by-step solution →
Q56·PhysicsSingle correctJEE Main 2024
Two different adiabatic paths for the same gas intersect two isothermal curves as shown in P-V diagram. The relation between the ratio VaVd\dfrac{V_a}{V_d}Vd​Va​​ and the ratio VbVc\dfrac{V_b}{V_c}Vc​Vb​​ is:
  1. (A)VaVd=(VbVc)γ−1\dfrac{V_a}{V_d}=\left(\dfrac{V_b}{V_c}\right)^{\gamma-1}Vd​Va​​=(Vc​Vb​​)γ−1
  2. (B)VaVd=VbVc\dfrac{V_a}{V_d}=\dfrac{V_b}{V_c}Vd​Va​​=Vc​Vb​​
  3. (C)VaVd=(VbVc)1/2\dfrac{V_a}{V_d}=\left(\dfrac{V_b}{V_c}\right)^{1/2}Vd​Va​​=(Vc​Vb​​)1/2
  4. (D)VaVd=(VbVc)2\dfrac{V_a}{V_d}=\left(\dfrac{V_b}{V_c}\right)^2Vd​Va​​=(Vc​Vb​​)2

Correct answer: (B)

Step-by-step solution →
Q57·PhysicsSingle correctJEE Main 2024
A diatomic gas (γ=1.4\gamma=1.4γ=1.4) does 100 J of work in an isobaric expansion. The heat given to the gas is:
  1. (A)350 J
  2. (B)490 J
  3. (C)150 J
  4. (D)250 J

Correct answer: (A)

Step-by-step solution →
Q58·PhysicsSingle correctJEE Main 2024
The specific heat at constant pressure of a real gas obeying PV2=RTPV^{2}=RTPV2=RT equation is:
  1. (A)Cv+RC_{v}+RCv​+R
  2. (B)R3+Cv\tfrac{R}{3}+C_{v}3R​+Cv​
  3. (C)RRR
  4. (D)Cv+R2VC_{v}+\tfrac{R}{2V}Cv​+2VR​

Correct answer: (D)

Step-by-step solution →
Q59·PhysicsSingle correctJEE Main 2024
A total of 48 J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2∘2^\circ2∘C. The work done by the gas is : (Given, R=8.3R = 8.3R=8.3 J K−1^{-1}−1mol−1^{-1}−1.)
  1. (A)72.9 J
  2. (B)24.9 J
  3. (C)48 J
  4. (D)23.1 J

Correct answer: (D)

Step-by-step solution →
Q60·PhysicsSingle correctJEE Main 2024
During an adiabatic process, if the pressure of a gas is found to be proportional to the cube of its absolute temperature, then the ratio CPCV\dfrac{C_P}{C_V}CV​CP​​ for the gas is:
  1. (A)53\dfrac{5}{3}35​
  2. (B)97\dfrac{9}{7}79​
  3. (C)32\dfrac{3}{2}23​
  4. (D)75\dfrac{7}{5}57​

Correct answer: (C)

Step-by-step solution →
Q61·PhysicsSingle correctJEE Main 2024
The heat absorbed by a system in going through the given cyclic process is:
  1. (A)61.6 J
  2. (B)431.2 J
  3. (C)616 J
  4. (D)19.6 J

Correct answer: (A)

Step-by-step solution →
Q62·PhysicsSingle correctJEE Main 2024
A sample of gas at temperature T is adiabatically expanded to double its volume. Adiabatic constant for the gas is γ=32\gamma=\tfrac{3}{2}γ=23​. The work done by the gas in the process is (μ=1\mu=1μ=1 mole)
  1. (A)RT[2−2]RT\left[\sqrt{2}-2\right]RT[2​−2]
  2. (B)RT[1−22]RT\left[1-2\sqrt{2}\right]RT[1−22​]
  3. (C)RT[22−1]RT\left[2\sqrt{2}-1\right]RT[22​−1]
  4. (D)RT[2−2]RT\left[2-\sqrt{2}\right]RT[2−2​]

Correct answer: (D)

Step-by-step solution →
Q63·PhysicsSingle correctJEE Main 2024
A diatomic gas (γ=1.4)(\gamma=1.4)(γ=1.4) does 200 J of work when it is expanded isobarically. The heat given to the gas in the process is:
  1. (A)850 J
  2. (B)800 J
  3. (C)600 J
  4. (D)700 J

Correct answer: (D)

Step-by-step solution →
Q64·PhysicsSingle correctJEE Main 2024
The pressure and volume of an ideal gas are related as PV5/2=KPV^{5/2}=KPV5/2=K (Constant). The work done when the gas is taken from state A(P1,V1,T1)A(P_1,V_1,T_1)A(P1​,V1​,T1​) to state B(P2,V2,T2)B(P_2,V_2,T_2)B(P2​,V2​,T2​) is:
  1. (A)2(P1V1−P2V2)2(P_1V_1-P_2V_2)2(P1​V1​−P2​V2​)
  2. (B)2(P2V2−P1V1)2(P_2V_2-P_1V_1)2(P2​V2​−P1​V1​)
  3. (C)2(P1V1−P2V2)2\left(\sqrt{P_1V_1}-\sqrt{P_2V_2}\right)2(P1​V1​​−P2​V2​​)
  4. (D)2(P2V2−P1V1)2\left(P_2\sqrt{V_2}-P_1\sqrt{V_1}\right)2(P2​V2​​−P1​V1​​)

Correct answer: (A)

Step-by-step solution →
Q65·PhysicsSingle correctJEE Main 2024
The given figure represents two isobaric processes for the same mass of an ideal gas, then
  1. (A)P2≥P1P_2\ge P_1P2​≥P1​
  2. (B)P2>P1P_2>P_1P2​>P1​
  3. (C)P1=P2P_1=P_2P1​=P2​
  4. (D)P1>P2P_1>P_2P1​>P2​

Correct answer: (D)

Step-by-step solution →
Q66·PhysicsMultiple correctJEE Main 2024
Choose the correct statement for processes A & B shown in figure.
  1. (A)PVγ=kPV^\gamma=kPVγ=k for process B and PV=kPV=kPV=k for process A.
  2. (B)PV=kPV=kPV=k for process B and A.
  3. (C)Pγ−1Tγ=k\dfrac{P^{\gamma-1}}{T^\gamma}=kTγPγ−1​=k for process B and T=kT=kT=k for process A.
  4. (D)TγPγ−1=k\dfrac{T^\gamma}{P^{\gamma-1}}=kPγ−1Tγ​=k for process A and PV=kPV=kPV=k for process B.

Correct answer: (A), (C)

Step-by-step solution →
Q67·PhysicsSingle correctJEE Main 2024
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio CPCV\dfrac{C_P}{C_V}CV​CP​​ for the gas is :
  1. (A)53\dfrac5335​
  2. (B)73\dfrac7337​
  3. (C)75\dfrac7557​
  4. (D)97\dfrac9779​

Correct answer: (B)

Step-by-step solution →
Q68·PhysicsSingle correctJEE Main 2024
0.08 kg air is heated at constant volume through 5∘5^{\circ}5∘C. The specific heat of air at constant volume is 0.17 kcal/kg·∘^{\circ}∘C and J=4.18J=4.18J=4.18 joule/cal. The change in its internal energy is approximately:
  1. (A)318 J
  2. (B)298 J
  3. (C)284 J
  4. (D)142 J

Correct answer: (C)

Step-by-step solution →
Q69·PhysicsIntegerJEE Advanced 2023
One mole of an ideal gas undergoes two different cyclic processes I and II, as shown in the P-V diagrams below. In cycle I, processes a, b, c and d are isobaric, isothermal, isobaric and isochoric, respectively. In cycle II, processes a′'′, b′'′, c′'′ and d′'′ are isothermal, isochoric, isobaric and isochoric, respectively. The total work done during cycle I is WIW_IWI​ and that during cycle II is WIIW_{II}WII​. The ratio WI/WIIW_I / W_{II}WI​/WII​ is ________.

Correct answer: 2

Step-by-step solution →
Q70·PhysicsSingle correctJEE Advanced 2023
One mole of an ideal gas expands adiabatically from an initial state (TA,V0)(T_A, V_0)(TA​,V0​) to final state (Tf,5V0)(T_f, 5V_0)(Tf​,5V0​). Another mole of the same gas expands isothermally from a different initial state (TB,V0)(T_B, V_0)(TB​,V0​) to the same final state (Tf,5V0)(T_f, 5V_0)(Tf​,5V0​). The ratio of the specific heats at constant pressure and constant volume of this ideal gas is γ\gammaγ. What is the ratio TA/TBT_A/T_BTA​/TB​?
  1. (A)5γ−15^{\gamma-1}5γ−1
  2. (B)51−γ5^{1-\gamma}51−γ
  3. (C)5γ5^{\gamma}5γ
  4. (D)51+γ5^{1+\gamma}51+γ

Correct answer: (A)

Step-by-step solution →
Q71·PhysicsNumericalJEE Advanced 2023
A closed container contains a homogeneous mixture of two moles of an ideal monatomic gas (γ=5/3\gamma = 5/3γ=5/3) and one mole of an ideal diatomic gas (γ=7/5\gamma = 7/5γ=7/5). Here, γ\gammaγ is the ratio of the specific heats at constant pressure and constant volume of an ideal gas. The gas mixture does a work of 66 Joule when heated at constant pressure. The change in its internal energy is ________ Joule.

Correct answer: 121

Step-by-step solution →
Q72·PhysicsSingle correctJEE Main 2023
A thermodynamic system is taken through cyclic process. The total work done in the process is :
  1. (A)100100100 J
  2. (B)300300300 J
  3. (C)Zero
  4. (D)200200200 J

Correct answer: (B)

Step-by-step solution →
Q73·PhysicsSingle correctJEE Main 2023
The initial pressure and volume of an ideal gas are P0P_0P0​ and V0V_0V0​. The final pressure of the gas when the gas is suddenly compressed to volume V04\dfrac{V_0}{4}4V0​​ will be: (Given γ\gammaγ = ratio of specific heats at constant pressure and at constant volume)
  1. (A)P0(4)1−γP_0(4)^{1-\gamma}P0​(4)1−γ
  2. (B)P0(4)γP_0(4)^{\gamma}P0​(4)γ
  3. (C)P0P_0P0​
  4. (D)4P04P_04P0​

Correct answer: (B)

Step-by-step solution →
Q74·PhysicsNumericalJEE Main 2023
Two plates A and B have thermal conductivities 84 Wm−1^{-1}−1K−1^{-1}−1 and 126 Wm−1^{-1}−1K−1^{-1}−1 respectively. They have same surface area and same thickness. They are placed in contact along their surfaces. If the temperatures of the outer surfaces of A and B are kept at 100 °C and 0 °C respectively, then the temperature of the surface of contact in steady state is ____ °C.

Correct answer: 40

Step-by-step solution →
Q75·PhysicsSingle correctJEE Main 2023
A body cools from 80°C to 60°C in 5 minutes. The temperature of the surrounding is 20°C. The time it takes to cool from 60°C to 40°C is:
  1. (A)500 s
  2. (B)253\dfrac{25}{3}325​ s
  3. (C)450 s
  4. (D)420 s

Correct answer: (A)

Step-by-step solution →
Q76·PhysicsSingle correctJEE Main 2023
An engine operating between the boiling and freezing points of water will have 1. efficiency more than 27% 2. efficiency less than the efficiency of a Carnot engine operating between the same two temperatures 3. efficiency equal to 27% 4. efficiency less than 27%. Choose the correct answer from the options given below:
  1. (A)2, 3 and 4 only
  2. (B)2 and 3 only
  3. (C)2 and 4 only
  4. (D)1 and 2 only

Correct answer: (C)

Step-by-step solution →
Q77·PhysicsSingle correctJEE Main 2023
On a temperature scale 'X'. The boiling point of water is 65∘65^{\circ}65∘ X and the freezing point is −15∘-15^{\circ}−15∘ X. Assume that the X scale is linear. The equivalent temperature corresponding to −95∘-95^{\circ}−95∘ X on the Farenheit scale would be:
  1. (A)−63∘-63^{\circ}−63∘F
  2. (B)−112∘-112^{\circ}−112∘F
  3. (C)−48∘-48^{\circ}−48∘F
  4. (D)−148∘-148^{\circ}−148∘F

Correct answer: (D)

Step-by-step solution →
Q78·PhysicsSingle correctJEE Main 2023
The thermodynamic process in which the internal energy of the system remains constant is:
  1. (A)Isochoric
  2. (B)Isothermal
  3. (C)Adiabatic
  4. (D)Isobaric

Correct answer: (B)

Step-by-step solution →
Q79·PhysicsSingle correctJEE Main 2023
1 kg of water at 100∘^\circ∘C is converted into steam at 100∘^\circ∘C by boiling at atmospheric pressure. The volume of water changes from 1.00×10−3 m31.00 \times 10^{-3} \, \text{m}^31.00×10−3m3 as a liquid to 1.671 m31.671 \, \text{m}^31.671m3 as steam. The change in internal energy of the system during the process will be (Given latent heat of vaporisaiton = 2257 kJ/kg. Atmospheric pressure = 1×1051 \times 10^51×105 Pa)
  1. (A)+2090+ 2090+2090 kJ
  2. (B)−2090- 2090−2090 kJ
  3. (C)−2426- 2426−2426 kJ
  4. (D)+2476+ 2476+2476 kJ

Correct answer: (A)

Step-by-step solution →
Q80·PhysicsSingle correctJEE Main 2023
A gas is compressed adiabatically. Which one of the following statements is NOT true?
  1. (A)There is no heat supplied to the system
  2. (B)The temperature of the gas increases
  3. (C)The change in the internal energy is equal to the work done on the gas
  4. (D)There is no change in the internal energy

Correct answer: (D)

Step-by-step solution →
Q81·PhysicsSingle correctJEE Main 2023
Consider two containers A and B containing monoatomic gases at the same Pressure (P), Volume (V) and Temperature (T). The gas in A is compressed isothermally to 18\dfrac1881​ of its original volume while the gas in B is compressed adiabatically to 18\dfrac1881​ of its original volume. The ratio of final pressure of gas in B to that of gas in A is:
  1. (A)8
  2. (B)18\dfrac1881​
  3. (C)14\dfrac1441​
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q82·PhysicsSingle correctJEE Main 2023
Work done by a Carnot engine operating between temperatures 127∘127^{\circ}127∘C and 27∘27^{\circ}27∘C is 2 kJ. The amount of heat transferred to the engine by the reservoir is:
  1. (A)4 kJ
  2. (B)2 kJ
  3. (C)8 kJ
  4. (D)2.67 kJ

Correct answer: (C)

Step-by-step solution →
Q83·PhysicsSingle correctJEE Main 2023
Given below are two statements: Statement I: If heat is added to a system, its temperature must increase. Statement II: If positive work is done by a system in a thermodynamic process, its volume must increase. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q84·PhysicsSingle correctJEE Main 2023
A body cools in 7 minutes from 60 °C to 40 °C. The temperature of the surrounding is 10 °C. The temperature of the body after the next 7 minutes will be:
  1. (A)32 °C32\,°C32°C
  2. (B)30 °C30\,°C30°C
  3. (C)28 °C28\,°C28°C
  4. (D)34 °C34\,°C34°C

Correct answer: (C)

Step-by-step solution →
Q85·PhysicsSingle correctJEE Main 2023
A source supplies heat to a system at the rate of 1000 W1000\,W1000W. If the system performs work at a rate of 200 W200\,W200W. The rate at which internal energy of the system increases is:
  1. (A)1200 W1200\,W1200W
  2. (B)600 W600\,W600W
  3. (C)500 W500\,W500W
  4. (D)800 W800\,W800W

Correct answer: (D)

Step-by-step solution →
Q86·PhysicsSingle correctJEE Main 2023
A Carnot engine operating between two reservoirs has efficiency 13\dfrac1331​. When the temperature of cold reservoir raised by xxx, its efficiency decreases to 16\dfrac1661​. The value of xxx, if the temperature of hot reservoir is 99°C99°C99°C, will be:
  1. (A)666666 K
  2. (B)626262 K
  3. (C)333333 K
  4. (D)16.516.516.5 K

Correct answer: (B)

Step-by-step solution →
Q87·PhysicsSingle correctJEE Main 2023
A sample of gas at temperature TTT is adiabatically expanded to double its volume. The work done by the gas in the process is (given, γ=32)\left(\text{given},\ \gamma=\tfrac{3}{2}\right)(given, γ=23​):
  1. (A)W=TR[2−2]W=\tfrac{T}{R}[\sqrt{2}-2]W=RT​[2​−2]
  2. (B)W=RT[2−2]W=RT[2-\sqrt{2}]W=RT[2−2​]
  3. (C)W=TR[2−2]W=TR[\sqrt{2}-2]W=TR[2​−2]
  4. (D)W=RT[2−2]W=\tfrac{R}{T}[2-\sqrt{2}]W=TR​[2−2​]

Correct answer: (B)

Step-by-step solution →
Q88·PhysicsNumericalJEE Main 2023
A water heater of power 200020002000 W is used to heat water. The specific heat capacity of water is 420042004200 J kg−1^{-1}−1 K−1^{-1}−1. The efficiency of heater is 70%70\%70%. Time required to heat 222 kg of water from 10°C10°C10°C to 60°C60°C60°C is _________ s. (Assume that the specific heat capacity of water remains constant over the temperature range of the water).

Correct answer: 300

Step-by-step solution →
Q89·PhysicsSingle correctJEE Main 2023
The pressure of a gas changes linearly with volume from AAA to BBB as shown in figure. If no heat is supplied to or extracted from the gas then change in the internal energy of the gas will be
  1. (A)−4.5-4.5−4.5 J
  2. (B)zero
  3. (C)4.54.54.5 J
  4. (D)666 J

Correct answer: (C)

Step-by-step solution →
Q90·PhysicsSingle correctJEE Main 2023
A hypothetical gas expands adiabatically such that its volume changes from 888 litres to 272727 litres. If the ratio of final pressure of the gas to initial pressure of the gas is 1681\dfrac{16}{81}8116​, then the ratio of CpCv\dfrac{C_p}{C_v}Cv​Cp​​ will be:
  1. (A)12\dfrac1221​
  2. (B)45\dfrac4554​
  3. (C)32\dfrac3223​
  4. (D)34\dfrac3443​

Correct answer: (B)

Step-by-step solution →
Q91·PhysicsSingle correctJEE Main 2023
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Efficiency of a reversible heat engine will be highest at −273 ∘-273\,^{\circ}−273∘C temperature of the cold reservoir. Reason R: The efficiency of Carnot's engine depends not only on temperature of the cold reservoir but it depends on the temperature of the hot reservoir too and is given as η=(1−T2T1)\eta=\left(1-\dfrac{T_2}{T_1}\right)η=(1−T1​T2​​). In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (A)

Step-by-step solution →
Q92·PhysicsSingle correctJEE Main 2023
Heat is given to an ideal gas in an isothermal process. A. Internal energy of the gas will decrease. B. Internal energy of the gas will increase. C. Internal energy of the gas will not change. D. The gas will do positive work. E. The gas will do negative work. Choose the correct answer from the options given below:
  1. (A)C and D only
  2. (B)C and E only
  3. (C)A and E only
  4. (D)B and D only

Correct answer: (A)

Step-by-step solution →
Q93·PhysicsSingle correctJEE Main 2023
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: If dQdQdQ and dWdWdW represent the heat supplied to the system and the work done on the system respectively, then according to the first law of thermodynamics dQ=dU−dWdQ = dU - dWdQ=dU−dW. Reason R: First law of thermodynamics is based on law of conservation of energy. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)A is not correct but R is correct
  3. (C)A is correct but R is not correct
  4. (D)Both A and R are correct but R is not the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q94·PhysicsNumericalJEE Main 2023
A body cools from 60∘60^\circ60∘C to 40∘40^\circ40∘C in 6 minutes. If the temperature of surroundings is 10∘10^\circ10∘C, then after the next 6 minutes its temperature will be ________ ∘^\circ∘C.

Correct answer: 28

Step-by-step solution →
Q95·PhysicsSingle correctJEE Main 2023
Match List I with List II: LIST I: (A) Isothermal Process, (B) Adiabatic Process, (C) Isochoric Process, (D) Isobaric Process. LIST II: (I) Work done by the gas decreases internal energy, (II) No change in internal energy, (III) The heat absorbed goes partly to increase internal energy and partly to do work, (IV) No work is done on or by the gas. Choose the correct answer from the options given below:
List-IList-II
A.Isothermal ProcessI.Work done by the gas decreases internal energy
B.Adiabatic ProcessII.No change in internal energy
C.Isochoric ProcessIII.The heat absorbed goes partly to increase internal energy and partly to do work
D.Isobaric ProcessIV.No work is done on or by the gas
  1. (A)A-I, B-II, C-III, D-IV
  2. (B)A-II, B-I, C-IV, D-III
  3. (C)A-II, B-I, C-III, D-IV
  4. (D)A-I, B-II, C-IV, D-III

Correct answer: (B)

Step-by-step solution →
Q96·PhysicsSingle correctJEE Main 2023
A Carnot engine with efficiency 50% takes heat from a source at 600 K. In order to increase the efficiency to 70%, keeping the temperature of sink same, the new temperature of the source will be:
  1. (A)130013001300 K
  2. (B)900900900 K
  3. (C)100010001000 K
  4. (D)360360360 K

Correct answer: (C)

Step-by-step solution →
Q97·PhysicsSingle correctJEE Main 2023
In an Isothermal change, the change in pressure and volume of a gas can be represented for three different temperature; T3>T2>T1T_3>T_2>T_1T3​>T2​>T1​ as:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q98·PhysicsSingle correctJEE Main 2023
1 g of a liquid is converted to vapour at 3×1053\times10^53×105 Pa pressure. If 10% of the heat supplied is used for increasing the volume by 1600 cm3^33 during this phase change, then the increase in internal energy in the process will be:
  1. (A)432000 J
  2. (B)4320 J
  3. (C)4800 J
  4. (D)4.32×1084.32\times10^84.32×108 J

Correct answer: (B)

Step-by-step solution →
Q99·PhysicsMultiple correctJEE Advanced 2022
In the given P-V diagram, a monoatomic gas (γ=53)\left(\gamma = \frac{5}{3}\right)(γ=35​) is first compressed adiabatically from state A to state B. Then it expands isothermally from state B to state C. [Given : (13)0.6≃0.5\left(\frac{1}{3}\right)^{0.6} \simeq 0.5(31​)0.6≃0.5, ln⁡2≃0.7\ln 2 \simeq 0.7ln2≃0.7 ]. Which of the following statement(s) is(are) correct?
  1. (A)The magnitude of the total work done in the process A→B→CA \rightarrow B \rightarrow CA→B→C is 144kJ .
  2. (B)The magnitude of the work done in the process B→CB \rightarrow CB→C is 84kJ .
  3. (C)The magnitude of the work done in the process A→BA \rightarrow BA→B is 60kJ .
  4. (D)The magnitude of the work done in the process C→AC \rightarrow AC→A is zero.

Correct answer: (B), (C), (D)

Step-by-step solution →
Q100·PhysicsMultiple correctJEE Advanced 2022
An ideal gas of density ρ=0.2\rho = 0.2ρ=0.2 kg m−3^{-3}−3 enters a chimney of height h at the rate of α=0.8\alpha = 0.8α=0.8 kg s−1^{-1}−1 from its lower end, and escapes through the upper end as shown in the figure. The cross-sectional area of the lower end is A1=0.1A_1 = 0.1A1​=0.1 m2^22 and the upper end is A2=0.4A_2 = 0.4A2​=0.4 m2^22. The pressure and the temperature of the gas at the lower end are 600 Pa and 300 K, respectively, while its temperature at the upper end is 150 K. The chimney is heat insulated so that the gas undergoes adiabatic expansion. Take g = 10 ms−2^{-2}−2 and the ratio of specific heats of the gas γ=2\gamma = 2γ=2. Ignore atmospheric pressure. Which of the following statement(s) is(are) correct?
  1. (A)The pressure of the gas at the upper end of the chimney is 300 Pa.
  2. (B)The velocity of the gas at the lower end of the chimney is 40 ms−1^{-1}−1 and at the upper end is 20 ms−1^{-1}−1.
  3. (C)The height of the chimney is 590m.
  4. (D)The density of the gas at the upper end is 0.05 kg m−3^{-3}−3

Correct answer: (B)

Step-by-step solution →
Q101·PhysicsMultiple correctJEE Advanced 2022
A bubble has surface tension S. The ideal gas inside the bubble has ratio of specific heats γ=53\gamma = \frac{5}{3}γ=35​ . The bubble is exposed to the atmosphere and it always retains its spherical shape. When the atmospheric pressure is Pα1P_{\alpha 1}Pα1​, the radius of the bubble is found to be r1r_1r1​ and the temperature of the enclosed gas is T1T_1T1​. When the atmospheric pressure is Pα2P_{\alpha 2}Pα2​, the radius of the bubble and the temperature of the enclosed gas are r2r_2r2​ and T2T_2T2​ , respectively. Which of the following statement(s) is(are) correct?
  1. (A)If the surface of the bubble is a perfect heat insulator, then (r1r2)5=Pα2+2Sr2Pα1+2Sr1\left(\frac{r_1}{r_2}\right)^5 = \frac{P_{\alpha 2} + \frac{2S}{r_2}}{P_{\alpha 1} + \frac{2S}{r_1}}(r2​r1​​)5=Pα1​+r1​2S​Pα2​+r2​2S​​
  2. (B)If the surface of the bubble is a perfect heat insulator, then the total internal energy of the bubble including its surface energy does not change with the external atmospheric pressure.
  3. (C)If the surface of the bubble is a perfect heat conductor and the change in atmospheric temperature is negligible, then (r1r2)3=Pα2+4Sr2Pα1+4Sr1\left(\frac{r_1}{r_2}\right)^3 = \frac{P_{\alpha 2} + \frac{4S}{r_2}}{P_{\alpha 1} + \frac{4S}{r_1}}(r2​r1​​)3=Pα1​+r1​4S​Pα2​+r2​4S​​
  4. (D)If the surface of the bubble is a perfect heat insulator, then (T2T1)52=Pα2+4Sr2Pα1+4Sr1\left(\frac{T_2}{T_1}\right)^{\frac{5}{2}} = \frac{P_{\alpha 2} + \frac{4S}{r_2}}{P_{\alpha 1} + \frac{4S}{r_1}}(T1​T2​​)25​=Pα1​+r1​4S​Pα2​+r2​4S​​

Correct answer: (C), (D)

Step-by-step solution →
Q102·PhysicsSingle correctJEE Advanced 2022
List I describes thermodynamic processes in four different systems. List II gives the magnitudes (either exactly or as a close approximation) of possible changes in the internal energy of the system due to the process. Which one of the following options is correct ?
List-IList-II
I.10−310^{-3}10−3 kg of water at 100∘^\circ∘C is converted to steam at the same temperature, at a pressure of 10510^{5}105 Pa. The volume of the system changes from 10−610^{-6}10−6 m3^33 to 10−310^{-3}10−3 m3^33 in the process. Latent heat of water = 2250 kJ/kg.P.2 kJ
II.0.2 moles of a rigid diatomic ideal gas with volume V at temperature 500 K undergoes an isobaric expansion to volume 3 V. Assume R = 8.0 J mol−1^{-1}−1 K−1^{-1}−1.Q.7 kJ
III.One mole of a monatomic ideal gas is compressed adiabatically from volume V=13m3V = \frac{1}{3}m^3V=31​m3 and pressure 2 kPa to volume V8\frac{V}{8}8V​.R.4 kJ
IV.Three moles of a diatomic ideal gas whose molecules can vibrate, is given 9 kJkJkJ of heat and undergoes isobaric expansion.S.5 kJ
T.3 kJ
  1. (A)I →\rightarrow→ T, II →\rightarrow→ R, III →\rightarrow→ S, IV →\rightarrow→ Q
  2. (B)I →\rightarrow→ S, II →\rightarrow→ P, III →\rightarrow→ T, IV →\rightarrow→ P
  3. (C)I →\rightarrow→ P, II →\rightarrow→ R, III →\rightarrow→ T, IV →\rightarrow→ Q
  4. (D)I →\rightarrow→ Q, II →\rightarrow→ R, III →\rightarrow→ S, IV →\rightarrow→ T

Correct answer: (C)

Step-by-step solution →
Q103·PhysicsSingle correctJEE Main 2022
A thermodynamic system is taken from an original state D to an intermediate state E by the linear process shown in the figure. Its volume is then reduced to the original volume from E to F by an isobaric process. The total work done by the gas from D to E to F will be
  1. (A)−450 J
  2. (B)450 J
  3. (C)900 J
  4. (D)1350 J

Correct answer: (B)

Step-by-step solution →
Q104·PhysicsNumericalJEE Main 2022
The pressure P1P_1P1​ and density d1d_1d1​ of diatomic gas (γ=75)\left(\gamma = \frac{7}{5}\right)(γ=57​) changes suddenly to P2(>P1)P_2(>P_1)P2​(>P1​) and d2d_2d2​ respectively during an adiabatic process. The temperature of the gas increases and becomes __________ times of its initial temperature. (given d2d1\frac{d_2}{d_1}d1​d2​​ = 32)

Correct answer: 4

Step-by-step solution →
Q105·PhysicsNumericalJEE Main 2022
At a certain temperature, the degrees of freedom per molecule for gas is 8. The gas performs 150 J of work when it expands under constant pressure. The amount of heat absorbed by the gas will be ........ J.

Correct answer: 750

Step-by-step solution →
Q106·PhysicsSingle correctJEE Main 2022
A Carnot engine has efficiency of 50%. If the temperature of sink is reduced by 40°C, its efficiency increases by 30%. The temperature of the source will be :
  1. (A)166.7 K
  2. (B)255.1 K
  3. (C)266.7 K
  4. (D)367.7 K

Correct answer: (C)

Step-by-step solution →
Q107·PhysicsSingle correctJEE Main 2022
In 1st^{st}st case, Carnot engine operates between temperatures 300 K and 100 K. In 2nd^{nd}nd case, as shown in the figure, a combination of two engines is used. The efficiency of this combination (in 2nd^{nd}nd case) will be :
  1. (A)same as the 1st^{st}st case
  2. (B)always greater than the 1st^{st}st case
  3. (C)always less than the 1st^{st}st case
  4. (D)may increase or decrease with respect to the 1st^{st}st case

Correct answer: (A)

Step-by-step solution →
Q108·PhysicsSingle correctJEE Main 2022
A monoatomic gas at pressure P and volume V is suddenly compressed to one eighth of its original volume. The final pressure at constant entropy will be:
  1. (A)P
  2. (B)8P
  3. (C)32P
  4. (D)64 P

Correct answer: (C)

Step-by-step solution →
Q109·PhysicsSingle correctJEE Main 2022
7 mole of certain monoatomic ideal gas undergoes a temperature increase of 40K at constant pressure. The increase in the internal energy of the gas in this process is (Given R = 8.3 JK−1^{-1}−1mol−1^{-1}−1)
  1. (A)5810 J
  2. (B)3486 J
  3. (C)11620J
  4. (D)6972 J

Correct answer: (B)

Step-by-step solution →
Q110·PhysicsSingle correctJEE Main 2022
A certain amount of gas of volume V at 27∘27^\circ27∘C temperature and pressure 2×1072 \times 10^{7}2×107 Nm−2^{-2}−2 expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use γ=1.5\gamma = 1.5γ=1.5)
  1. (A)3.536×1053.536 \times 10^{5}3.536×105 Pa
  2. (B)3.536×1063.536 \times 10^{6}3.536×106 Pa
  3. (C)1.25×1061.25 \times 10^{6}1.25×106 Pa
  4. (D)1.25×1051.25 \times 10^{5}1.25×105 Pa

Correct answer: (B)

Step-by-step solution →
Q111·PhysicsSingle correctJEE Main 2022
Starting with the same initial conditions, an ideal gas expands from volume V1V_1V1​ to V2V_2V2​ in three different ways. The work done by the gas is W1W_1W1​ if the process is purely isothermal. W2W_2W2​. if the process is purely adiabatic and W3W_3W3​ if the process is purely isobaric. Then, choose the coned option
  1. (A)W1<W2<W3W_1 < W_2 < W_3W1​<W2​<W3​
  2. (B)W2<W3<W1W_2 < W_3 < W_1W2​<W3​<W1​
  3. (C)W3<W1<W2W_3 < W_1 < W_2W3​<W1​<W2​
  4. (D)W2<W1<W3W_2 < W_1 < W_3W2​<W1​<W3​

Correct answer: (D)

Step-by-step solution →
Q112·PhysicsNumericalJEE Main 2022
300 cal. of heat is given to a heat engine and it rejects 225 cal. of heat. If source temperature is 227°C, then the temperature of sink will be __ ∘^{\circ}∘C.

Correct answer: 102

Step-by-step solution →
Q113·PhysicsSingle correctJEE Main 2022
Given below are two statement : Statement – I : What μ amount of an ideal gas undergoes adiabatic change from state (P1,V1,T1)\left(P_{1}, V_{1}, T_{1}\right)(P1​,V1​,T1​) to state (P2,V2,T2)\left(P_{2}, V_{2}, T_{2}\right)(P2​,V2​,T2​), the work done is W=1R(T2−T1)1−γW = \frac{1R\left(T_{2} - T_{1}\right)}{1 - \gamma}W=1−γ1R(T2​−T1​)​, where γ=CPCV\gamma = \frac{C_{P}}{C_{V}}γ=CV​CP​​ and R = universal gas constant, Statement — II: In the above case. when work is done on the gas. the temperature of the gas would rise. Choose the correct answer from the options given below:
  1. (A)Both statement—I and statement-II are true.
  2. (B)Both statement—I and statement-II are false.
  3. (C)Statement-I is true but statement-II is false.
  4. (D)Statement-I is false but statement-II is true.

Correct answer: (A)

Step-by-step solution →
Q114·PhysicsSingle correctJEE Main 2022
A sample of an ideal gas is taken through the cyclic process ABCA as shown in figure. It absorbs, 40 J of heat during the part AB, no heat during BC and rejects 60J of heat during CA. A work 50J is done on the gas during the part BC. The internal energy of the gas at A is 1560J. The work done by the gas during the part CA is:
  1. (A)20 J
  2. (B)30 J
  3. (C)–30J
  4. (D)–60 J

Correct answer: (B)

Step-by-step solution →
Q115·PhysicsNumericalJEE Main 2022
A diatomic gas (γ=1.4)(\gamma = 1.4)(γ=1.4) does 400 J of work when it is expanded isobarically. The heat given to the gas in the process is ________ J.

Correct answer: 1400

Step-by-step solution →
Q116·PhysicsNumericalJEE Main 2022
In a carnot engine, the temperature of reservoir is 527∘^{\circ}∘C and that of sink is 200 K. If the workdone by the engine when it transfers heat from reservoir to sink is 12000 kJ, the quantity of heat absorbed by the engine from reservoir is ________ ×106\times 10^{6}×106 J.

Correct answer: 16

Step-by-step solution →
Q117·PhysicsSingle correctJEE Main 2022
The efficiency of a Carnot's engine, working between steam point and ice point, will be :
  1. (A)26.81%
  2. (B)37.81%
  3. (C)47.81%
  4. (D)57.81%

Correct answer: (A)

Step-by-step solution →
Q118·PhysicsNumericalJEE Main 2022
A heat engine operates with the cold reservoir at temperature 324 K. The minimum temperature of the hot reservoir, if the heat engine takes 300 J heat from the hot reservoir and delivers 180 J heat to the cold reservoir per cycle, is ____________K.

Correct answer: 540

Step-by-step solution →
Q119·PhysicsSingle correctJEE Main 2022
A Carnot engine take 5000 kcal of heat from a reservoir at 727∘727^{\circ}727∘C and gives heat to a sink at 127∘127^{\circ}127∘C. The work done by the engine is :
  1. (A)3×1063\times10^{6}3×106 J
  2. (B)Zero
  3. (C)12.6×10612.6\times10^{6}12.6×106 J
  4. (D)8.4×1068.4\times10^{6}8.4×106 J

Correct answer: (C)

Step-by-step solution →
Q120·PhysicsSingle correctJEE Main 2022
A Carnot engine whose heat sinks at 27∘27^{\circ}27∘C, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency ?
  1. (A)Increases by 18∘18^{\circ}18∘C
  2. (B)Increase by 200∘200^{\circ}200∘C
  3. (C)Increase by 120∘120^{\circ}120∘C
  4. (D)Increase by 73∘73^{\circ}73∘

Correct answer: (B)

Step-by-step solution →
Q121·PhysicsNumericalJEE Main 2022
A monoatomic gas performs a work of Q4\dfrac{Q}{4}4Q​ where Q is the heat supplied to it. The molar heat capaticy of the gas will be ______R during this transformation. Where R is the gas constant.

Correct answer: 2

Step-by-step solution →
Q122·PhysicsSingle correctJEE Advanced 2021
A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, Cv=2RC_v = 2RCv​=2R. Here, RRR is the gas constant. Initially, each side has a volume V0V_0V0​ and temperature T0T_0T0​. The left side has an electric heater, which is turned on at very low power to transfer heat QQQ to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2V_0/2V0​/2. Consequently, the gas temperatures on the left and the right sides become TLT_LTL​ and TRT_RTR​, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition. The value of QRT0\frac{Q}{RT_0}RT0​Q​ is
  1. (A)4(22+1)4\left( 2\sqrt{2} + 1 \right)4(22​+1)
  2. (B)4(22−1)4\left( 2\sqrt{2} - 1 \right)4(22​−1)
  3. (C)(52+1)\left( 5\sqrt{2} + 1 \right)(52​+1)
  4. (D)(52−1)\left( 5\sqrt{2} - 1 \right)(52​−1)

Correct answer: (B)

Step-by-step solution →
Q123·PhysicsSingle correctJEE Advanced 2021
An ideal gas undergoes a four step cycle as shown in the P−VP - VP−V diagram below. During this cycle, heat is absorbed by the gas in
  1. (A)steps 1 and 2
  2. (B)steps 1 and 3
  3. (C)steps 1 and 4
  4. (D)steps 2 and 4

Correct answer: (C)

Step-by-step solution →
Q124·PhysicsSingle correctJEE Advanced 2021
A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, Cv=2RC_v = 2RCv​=2R. Here, RRR is the gas constant. Initially, each side has a volume V0V_0V0​ and temperature T0T_0T0​. The left side has an electric heater, which is turned on at very low power to transfer heat QQQ to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2V_0/2V0​/2. Consequently, the gas temperatures on the left and the right sides become TLT_LTL​ and TRT_RTR​, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition. The value of TRT0\frac{T_R}{T_0}T0​TR​​ is
  1. (A)2\sqrt{2}2​
  2. (B)3\sqrt{3}3​
  3. (C)2
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q125·PhysicsNumericalJEE Main 2021
The temperature of 3.00 mol of an ideal diatomic gas is increased by 40.0 °C without changing the pressure of the gas. The molecules in the gas rotate but do not oscillate. If the ratio of change in internal energy of the gas to the amount of workdone by the gas is x10\frac{x}{10}10x​. Then the value of x (round off to the nearest integer) is ________ . (Given R = 8.31 J mol−1^{-1}−1 K−1^{-1}−1)

Correct answer: 25

Step-by-step solution →
Q126·PhysicsNumericalJEE Main 2021
A sample of gas with γ\gammaγ = 1.5 is taken through an adiabatic process in which the volume is compressed from 1200 cm3^{3}3 to 300 cm3^{3}3. If the initial pressure is 200 kPa. The absolute value of the workdone by the gas in the process =______J.

Correct answer: 480

Step-by-step solution →
Q127·PhysicsSingle correctJEE Main 2021
The height of victoria falls is 63 m. What is the difference in temperature of water at the top and at the bottom of fall ? [Given 1 cal = 4.2 J and specific heat of water = 1 cal g−1^{-1}−1 °C−1^{-1}−1]
  1. (A)0.147° C
  2. (B)14.76° C
  3. (C)1.476°
  4. (D)0.014° C

Correct answer: (A)

Step-by-step solution →
Q128·PhysicsNumericalJEE Main 2021
A heat engine operates between a cold reservoir at temperature T2T_2T2​ = 400 K and a hot reservoir at temperature T1T_1T1​. It takes 300 J of heat from the hot reservoir and delivers 240 J of heat to the cold reservoir in a cycle. The minimum temperature of the hot reservoir has to be __________ K.

Correct answer: 500

Step-by-step solution →
Q129·PhysicsSingle correctJEE Main 2021
An ideal gas is expanding such that PT3PT^3PT3 = constant. The coefficient of volume expansion of the gas is :
  1. (A)1T\frac{1}{T}T1​
  2. (B)2T\frac{2}{T}T2​
  3. (C)4T\frac{4}{T}T4​
  4. (D)3T\frac{3}{T}T3​

Correct answer: (C)

Step-by-step solution →
Q130·PhysicsSingle correctJEE Main 2021
An electric appliance supplies 6000 J/min heat to the system. If the system delivers a power of 90W. How long it would take to increase the internal energy by 2.5 ×\times× 10310^{3}103 J ?
  1. (A)2.5 ×\times× 10210^{2}102 s
  2. (B)4.1 ×\times× 10110^{1}101s
  3. (C)2.4 ×\times× 10310^{3}103 s
  4. (D)2.5 ×\times× 10110^{1}101s

Correct answer: (A)

Step-by-step solution →
Q131·PhysicsSingle correctJEE Main 2021
A refrigerator consumes an average 35 W power to operate between temperature –10°C to 25°C. If there is no loss of energy then how much average heat per second does it transfer ?
  1. (A)263 J/s
  2. (B)298 J/s
  3. (C)350 J/s
  4. (D)35 J/s

Correct answer: (A)

Step-by-step solution →
Q132·PhysicsSingle correctJEE Main 2021
One mole of an ideal gas is taken through an adiabatic process where the temperature rises from 27°C to 37°C. If the ideal gas is composed of polyatomic molecule that has 4 vibrational modes, which of the following of the following is true ? [R = 8.314 J mol−1^{-1}−1 K−1^{-1}−1]
  1. (A)Work done by the gas is close to 582 J
  2. (B)Work done on the gas in close to 582 J
  3. (C)Work done on the gas is close to 332 J
  4. (D)Work done by the gas is close to 332 J

Correct answer: (B)

Step-by-step solution →
Q133·PhysicsSingle correctJEE Main 2021
A body takes 4 min. to cool from 61°C to 59°C.If the temperature of the surroundings is 30°C, the time taken by the body to cool from 51°C to 49°C is :
  1. (A)6 min.
  2. (B)3 min.
  3. (C)4 min.
  4. (D)8 min.

Correct answer: (A)

Step-by-step solution →
Q134·PhysicsSingle correctJEE Main 2021
Two Carnot engines A and operate in series such that engine A absorbs heat at T1_11​ and rejects heat to a sink at temperature T. Engine B absorbs half of the heat rejected by Engine A and rejects heat to the sink at T3_33​ . When work done in both the cases is equal, the value of T is :
  1. (A)32T1+13T3\frac{3}{2}T_1+\frac{1}{3}T_323​T1​+31​T3​
  2. (B)23T1+32T3\frac{2}{3}T_1+\frac{3}{2}T_332​T1​+23​T3​
  3. (C)23T1+13T3\frac{2}{3}T_1+\frac{1}{3}T_332​T1​+31​T3​
  4. (D)13T1+23T3\frac{1}{3}T_1+\frac{2}{3}T_331​T1​+32​T3​

Correct answer: (C)

Step-by-step solution →
Q135·PhysicsSingle correctJEE Main 2021
In the reported figure, there is a cyclic process ABCDA on a sample of 1mol of a diatomic gas. The temperature of the gas during the process A → B and C → D are T1T_1T1​ and T2T_2T2​ (T1>T2T_1 > T_2T1​>T2​) respectively. Choose the correct option out of the following for work done if processes BC and DA are adiabatic.
  1. (A)WAB=WDCW_{AB} = W_{DC}WAB​=WDC​
  2. (B)WAD=WBCW_{AD} = W_{BC}WAD​=WBC​
  3. (C)WAB<WCDW_{AB} < W_{CD}WAB​<WCD​
  4. (D)WBC+WDA>0W_{BC} + W_{DA} > 0WBC​+WDA​>0

Correct answer: (B)

Step-by-step solution →
Q136·PhysicsSingle correctJEE Main 2021
A heat engine has an efficiency of 16\frac{1}{6}61​. When the temperature of sink is reduced by 62∘62^\circ62∘ C, its efficiency get doubled. The temperature of the source is :
  1. (A)124∘^\circ∘C
  2. (B)99∘^\circ∘C
  3. (C)37∘^\circ∘C
  4. (D)62∘^\circ∘C

Correct answer: (B)

Step-by-step solution →
Q137·PhysicsSingle correctJEE Main 2021
A monoatomic ideal gas, initially at temperature T1T_1T1​ is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature T2T_2T2​ by releasing the piston suddenly. If ℓ1\ell_1ℓ1​ and ℓ2\ell_2ℓ2​ are the lengths of the gas column, before and after the expansion respectively, then the value of T1T2\frac{T_1}{T_2}T2​T1​​ will be :
  1. (A)ℓ2ℓ1\frac{\ell_2}{\ell_1}ℓ1​ℓ2​​
  2. (B)(ℓ1ℓ2)23\left(\frac{\ell_1}{\ell_2}\right)^{\frac{2}{3}}(ℓ2​ℓ1​​)32​
  3. (C)ℓ1ℓ2\frac{\ell_1}{\ell_2}ℓ2​ℓ1​​
  4. (D)(ℓ2ℓ1)23\left(\frac{\ell_2}{\ell_1}\right)^{\frac{2}{3}}(ℓ1​ℓ2​​)32​

Correct answer: (D)

Step-by-step solution →
Q138·PhysicsNumericalJEE Main 2021
In 5 minutes, a body cools from 75°C to 65°C at room temperature of 25°C. The temperature of body at the end of next 5 minutes is ________ °C.

Correct answer: 57

Step-by-step solution →
Q139·PhysicsNumericalJEE Main 2021
In the reported figure, heat energy absorbed by a system in going through a cyclic process is ________ π\piπ J.

Correct answer: 100

Step-by-step solution →
Q140·PhysicsNumericalJEE Main 2021
One mole of an ideal gas at 27∘C27^{\circ}\mathrm{C}27∘C is taken from A to B as shown in the given PV indicator diagram. The work done by the system will be ________ ×10−1\times 10^{-1}×10−1 J. [Given : R=8.3 J/mole K\mathrm{R} = 8.3\,\mathrm{J/mole\ K}R=8.3J/mole K, ℓn 2=0.6931\ell\mathrm{n}\,2 = 0.6931ℓn2=0.6931 ] (Round off to the nearest integer)

Correct answer: 17258

Step-by-step solution →
Q141·PhysicsSingle correctJEE Main 2021
For an adiabatic expansion of an ideal gas, the fractional change in its pressure is equal to (where γ is the ratio of specific heats):
  1. (A)−γdVV-\gamma\frac{dV}{V}−γVdV​
  2. (B)−γVdV-\gamma\frac{V}{dV}−γdVV​
  3. (C)−1γdVV-\frac{1}{\gamma}\frac{dV}{V}−γ1​VdV​
  4. (D)dVV\frac{dV}{V}VdV​

Correct answer: (A)

Step-by-step solution →
Q142·PhysicsSingle correctJEE Main 2021
The P-V diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The work done during an adiabatic process CD is (use γ = 1.4) :
  1. (A)–500 J
  2. (B)–400 J
  3. (C)400 J
  4. (D)200 J

Correct answer: (A)

Step-by-step solution →
Q143·PhysicsSingle correctJEE Main 2021
An ideal gas in a cylinder is separated by a piston in such a way that the entropy of one part is S1S_1S1​ and that of the other part is S2S_2S2​. Given that S1>S2S_1 > S_2S1​>S2​. If the piston is removed then the total entropy of the system will be :
  1. (A)S1×S2S_1 \times S_2S1​×S2​
  2. (B)S1−S2S_1 - S_2S1​−S2​
  3. (C)S1S2\frac{S_1}{S_2}S2​S1​​
  4. (D)S1+S2S_1 + S_2S1​+S2​

Correct answer: (D)

Step-by-step solution →
Q144·PhysicsSingle correctJEE Main 2021
A Carnot's engine working between 400 K and 800 K has a work output of 1200 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is :
  1. (A)3200 J
  2. (B)1800 J
  3. (C)1600 J
  4. (D)2400 J

Correct answer: (D)

Step-by-step solution →
Q145·PhysicsSingle correctJEE Main 2021
Which one is the correct option for the two different thermodynamic processes ?
  1. (A)(c) and (a)
  2. (B)(c) and (d)
  3. (C)(a) only
  4. (D)(b) and (c)

Correct answer: (B)

Step-by-step solution →
Q146·PhysicsSingle correctJEE Main 2021
In thermodynamics, heat and work are :
  1. (A)Path functions
  2. (B)Intensive thermodynamic state variables
  3. (C)Extensive thermodynamic state variables
  4. (D)Point functions

Correct answer: (A)

Step-by-step solution →
Q147·PhysicsNumericalJEE Main 2021
For an ideal heat engine, the temperature of the source is 127°C. In order to have 60% efficiency the temperature of the sink should be _______°C. (Round off to the Nearest Integer)

Correct answer: -113

Step-by-step solution →
Q148·PhysicsNumericalJEE Main 2021
1 mole of rigid diatomic gas performs a work of Q5\frac{Q}{5}5Q​ when heat Q is supplied to it. The molar heat capacity of the gas during this transformation is xR8\frac{xR}{8}8xR​. The value of x is __________.

Correct answer: 25

Step-by-step solution →
Q149·PhysicsNumericalJEE Main 2021
The volume V of a given mass of monatomic gas changes with temperature T according to the relation V=KT23V = KT^{\frac{2}{3}}V=KT32​. The work done when temperature changes by 90 K will be xR. The value of x is ____________________. [R =universal gas constant]

Correct answer: 60

Step-by-step solution →
Q150·PhysicsNumericalJEE Main 2021
A reversible heat engine converts one- fourth of the heat input into work. When the temperature of the sink is reduced by 52K, its efficiency is doubled. The temperature in Kelvin of the source will be_______.

Correct answer: 208

Step-by-step solution →
Q151·PhysicsNumericalJEE Main 2021
In a certain themodynamical process, the pressure ofa gas depends on its volume as kV3kV^3kV3 . The work done when the temperature changes from 100ºC to 300ºC will be _____ nR, where n denotes number of moles of a gas.

Correct answer: 50

Step-by-step solution →
Q152·PhysicsSingle correctJEE Main 2021
thermodynamic process is shown below on a P-V diagram for one mole of an ideal gas. If V2 = 2V1 then the ratio of temperature T2/T1 is: P1(P1^{1}1V1^{1}1T1^{1}1)PV1/2^{1/2}1/2=constant 2(P2V2T2) V V1_{1}1​V2_{2}2​
  1. (A)12\dfrac{1}{\sqrt{2}}2​1​
  2. (B)12\dfrac{1}{2}21​
  3. (C)222
  4. (D)2\sqrt{2}2​

Correct answer: (D)

Step-by-step solution →
Q153·PhysicsSingle correctJEE Main 2021
A diatomic gas, having Cp=72RC_p = \dfrac{7}{2}RCp​=27​R and Cv=52RC_v = \dfrac{5}{2}RCv​=25​R, is heated at constant pressure. The ratio dU : dQ : dW
  1. (A)3 : 7 : 2
  2. (B)5 : 7 : 2
  3. (C)5 : 7 : 3
  4. (D)3 : 5 : 2

Correct answer: (B)

Step-by-step solution →
Q154·PhysicsSingle correctJEE Main 2021
match List I with List II List-I (a) Isothermal (b) Isochoric (c) Adiabatic (d) Isobaric List-II (i) Pressure constant (ii) Temperature constant (iii) Volume constant (iv) Heat content is constant Choose the correct answer from the options given below –
  1. (A)(a) – (ii), (b) – (iv), (c) – (iii), (d) – (i)
  2. (B)(a) – (ii), (b) – (iii), (c) – (iv), (d) – (i)
  3. (C)(a) – (i), (b) – (iii), (c) – (ii), (d) – (iv)
  4. (D)(a) – (iii), (b) – (ii), (c) – (i), (d) – (iv)

Correct answer: (B)

Step-by-step solution →
Q155·PhysicsSingle correctJEE Main 2021
n mole of a perfect gas undergoes a cyclic process ABCA (see figure) consisting of the following processes – A→\rightarrow→B : Isothermal expansion at temperature T so that the volume is doubled from V1V_1V1​ to V2=2V1V_2 = 2V_1V2​=2V1​ and pressure changes from P1P_1P1​ to P2P_2P2​. B →\rightarrow→ C : Isobaric compression at pressure P2P_2P2​ to initial volume V1V_1V1​. C →\rightarrow→ A : Isochoric change leading to change of pressure from P2P_2P2​ to P1P_1P1​. Total workdone in the complete cycle ABCA is –
  1. (A)0
  2. (B)nRT(ln⁡2+12)nRT\left(\ln 2 + \frac{1}{2}\right)nRT(ln2+21​)
  3. (C)nRTln⁡2nRT\ln 2nRTln2
  4. (D)nRT(ln⁡2−12)nRT\left(\ln 2 - \frac{1}{2}\right)nRT(ln2−21​)

Correct answer: (D)

Step-by-step solution →
Q156·PhysicsSingle correctJEE Main 2021
If one mole of an ideal gas at (P1P_1P1​, V1V_1V1​) is allowed to expand reversibly and isothermally (A to B) its pressure is reduced to one-half of the original pressure (see figure). This is followed by a constant volume cooling till its pressure is reduced to one-fourth of the initial value (B→\rightarrow→C). Then it is restored to its initial state by a reversible adiabatic compression (C to A). The net workdone by the gas is equal to :
  1. (A)0
  2. (B)−RT2(γ−1)-\frac{RT}{2(\gamma-1)}−2(γ−1)RT​
  3. (C)RT[ln⁡2−12(γ−1)]RT\left[\ln 2-\frac{1}{2(\gamma-1)}\right]RT[ln2−2(γ−1)1​]
  4. (D)RTln⁡2RT\ln 2RTln2

Correct answer: (C)

Step-by-step solution →
Q157·PhysicsNumericalJEE Advanced 2020
A spherical bubble inside water has radius RRR. Take the pressure inside the bubble and the water pressure to be p0p_0p0​. The bubble now gets compressed radially in an adiabatic manner so that its radius becomes (R−a)(R - a)(R−a). For a≪Ra \ll Ra≪R the magnitude of the work done in the process is given by (4πp0Ra2)X(4\pi p_0 R a^2)X(4πp0​Ra2)X, where XXX is a constant and γ=Cp/CV=41/30\gamma = C_p/C_V = 41/30γ=Cp​/CV​=41/30. The value of XXX is _________.

Correct answer: 2.05

Step-by-step solution →
Q158·PhysicsNumericalJEE Advanced 2020
Consider one mole of helium gas enclosed in a container at initial pressure P1P_1P1​ and volume V1V_1V1​. It expands isothermally to volume 4V14V_14V1​. After this, the gas expands adiabatically and its volume becomes 32V132V_132V1​. The work done by the gas during isothermal and adiabatic expansion processes are WisoW_{iso}Wiso​ and WadiaW_{adia}Wadia​, respectively. If the ratio WisoWadia=fln⁡2\frac{W_{iso}}{W_{adia}} = f\ln2Wadia​Wiso​​=fln2, then fff is _________.

Correct answer: 1.77 to 1.79

Step-by-step solution →
Q159·PhysicsSingle correctJEE Main 2020
In adiabatic process, the density of a diatomic gas becomes 32 times its initial value. The final pressure of the gas is found to be n times the initial pressure. The value of n is:
  1. (A)128
  2. (B)132\dfrac{1}{32}321​
  3. (C)32
  4. (D)326

Correct answer: (A)

Step-by-step solution →
Q160·PhysicsSingle correctJEE Main 2020
Match the thermodynamics processes taking place in a system with the correct conditions. In the table: ΔQ is the heat supplied, ΔW is the work done and ΔU is change in internal energy of the system. Match the following:
ProcessCondition
I.AidabaticA.ΔW = 0
II.IsothermalB.ΔQ = 0
III.IsochoricC.ΔU ≠ 0, ΔW ≠ 0, ΔQ ≠ 0
IV.IsobaricD.ΔU = 0
  1. (A)(I)→(B); (II)→(D); (III)→(A); (IV)→(C)
  2. (B)(I)→(A); (II)→(A); (III)→(B); (IV)→(C)
  3. (C)(I)→(A); (II)→(B); (III)→(D); (IV)→(D)
  4. (D)(I)→(B); (II)→(A); (III)→(D); (IV)→(C)

Correct answer: (A)

Step-by-step solution →
Q161·PhysicsSingle correctJEE Main 2020
A balloon filled with helium (32°C and 1.7 atm.) bursts. Immediately afterwards the expansion of helium can be considered as:
  1. (A)irreversible adiabatic
  2. (B)reversible isothermal
  3. (C)reversible adiabatic
  4. (D)irreversible isothermal

Correct answer: (A)

Step-by-step solution →
Q162·PhysicsNumericalJEE Main 2020
If minimum possible work is done by a refrigerator in converting 100 grams of water at 0∘C0^{\circ}C0∘C to ice, how much heat (in calories) is released to the surroundings at temperature 27∘C27^{\circ}C27∘C (Latent heat of ice = 80 Cal/gram) to the nearest integer?

Correct answer: 8791

Step-by-step solution →
Q163·PhysicsSingle correctJEE Main 2020
Which of the following is an equivalent cyclic process corresponding to the thermodynamic cyclic given in the figure? Where, 1→21 \to 21→2 is adiabatic. (Graphs are schematic and are not to scale)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q164·PhysicsSingle correctJEE Main 2020
A Carnot engine having an efficiency of 110\frac{1}{10}101​ is being used as a refrigerator. If the work done on the refrigerator is 10 J, the amount of heat absorbed from the reservoir at lower temperature is:
  1. (A)99 J
  2. (B)100 J
  3. (C)1 J
  4. (D)90 J

Correct answer: (D)

Step-by-step solution →
Q165·PhysicsSingle correctJEE Main 2020
A thermodynamic cycle xyzx is shown on a V-T diagram. The P-V diagram that best describes this cycle is: (diagrams are schematic and not to scale)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q166·PhysicsSingle correctJEE Main 2020
A litre of dry air at STP expands adiabatically to a volume of 3 litres. If γ = 1.40, the work done by air is: (31.43^{1.4}31.4 = 4.6555) [Take air to be an ideal gas]
  1. (A)48 J
  2. (B)90.5 J
  3. (C)100.8 J
  4. (D)60.7 J

Correct answer: (B)

Step-by-step solution →
Q167·PhysicsNumericalJEE Main 2020
A Carnot engine operates between two reservoirs of temperatures 900 K and 300 K. The engine performs 1200 J of work per cycle. The heat energy (in J) delivered by the engine to the low temperature reservoir, in a cycle is _________.

Correct answer: 600

Step-by-step solution →
Q168·PhysicsSingle correctJEE Main 2020
Two ideal Carnot engines operate in cascade (all heat given up by one engine is used by the other engine to produce work) between temperatures, T1_11​ and T2_22​. The temperature of the hot reservoir of the first engine is T1_11​ and the temperature of the cold reservoir of the second engine is T2_22​. T is temperature of the sink of first engine which is also the source for the second engine. How is T related to T1_11​ and T2_22​, if both the engines perform equal amount of work?
  1. (A)T = T1T2\sqrt{T_1T_2}T1​T2​​
  2. (B)T = T1+T22\dfrac{T_1+T_2}{2}2T1​+T2​​
  3. (C)T = 2T1T2T1+T2\dfrac{2T_1T_2}{T_1+T_2}T1​+T2​2T1​T2​​
  4. (D)T = 0

Correct answer: (B)

Step-by-step solution →
Q169·PhysicsSingle correctJEE Advanced 2019
Answer the following by appropriately matching the list based on the information given in the paragraph. In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔXT\Delta XTΔX, where T is temperature of the system and ΔX\Delta XΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=32Rln⁡(TTA)+Rln⁡(VVA)X = \frac{3}{2}R\ln\left(\frac{T}{T_A}\right) + R\ln\left(\frac{V}{V_A}\right)X=23​Rln(TA​T​)+Rln(VA​V​). Here, R is gas constant, V is volume of gas. TAT_ATA​ and VAV_AVA​ are constants. The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities. If the process on one mole of monatomic ideal gas is as shown in the TV-diagram with P0V0=13RT0P_0V_0 = \frac{1}{3}RT_0P0​V0​=31​RT0​, the correct match is,
List-IList-II
I.Work done by the system in process 1→2→31 \to 2 \to 31→2→3P.13RT0ln⁡2\frac{1}{3}RT_0\ln 231​RT0​ln2
II.Change in internal energy in process 1→2→31 \to 2 \to 31→2→3Q.13RT0\frac{1}{3}RT_031​RT0​
III.Heat absorbed by the system in process 1→2→31 \to 2 \to 31→2→3R.RT0RT_0RT0​
IV.Heat absorbed by the system in process 1→21 \to 21→2S.43RT0\frac{4}{3}RT_034​RT0​
T.13RT0(3+ln⁡2)\frac{1}{3}RT_0(3+\ln 2)31​RT0​(3+ln2)
U.56RT0\frac{5}{6}RT_065​RT0​
  1. (A)I →\to→ P, II →\to→ T, III →\to→ Q, IV →\to→ T
  2. (B)I →\to→ S, II →\to→ T, III →\to→ Q, IV →\to→ U
  3. (C)I →\to→ P, II →\to→ R, III →\to→ T, IV →\to→ S
  4. (D)I →\to→ P, II →\to→ R, III →\to→ T, IV →\to→ P

Correct answer: (D)

Step-by-step solution →
Q170·PhysicsSingle correctJEE Advanced 2019
A current carrying wire heats a metal rod. The wire provides a constant power (P) to the rod. The metal rod is enclosed in an insulated container. It is observed that the temperature (T) in the metal rod changes with time (t) as T(t)=T0(1+βt1/4)T (t) = T_0 (1 + \beta t^{1/4})T(t)=T0​(1+βt1/4) where β is a constant with appropriate dimension while T0T_0T0​ is a constant with dimension of temperature. The heat capacity of the metal is
  1. (A)4P(T(t)−T0)4β4T05\frac{4P(T(t)-T_0)^4}{\beta^4 T_0^5}β4T05​4P(T(t)−T0​)4​
  2. (B)4P(T(t)−T0)β4T02\frac{4P(T(t)-T_0)}{\beta^4 T_0^2}β4T02​4P(T(t)−T0​)​
  3. (C)4P(T(t)−T0)2β4T02\frac{4P(T(t)-T_0)^2}{\beta^4 T_0^2}β4T02​4P(T(t)−T0​)2​
  4. (D)4P(T(t)−T0)3β4T04\frac{4P(T(t)-T_0)^3}{\beta^4 T_0^4}β4T04​4P(T(t)−T0​)3​

Correct answer: (D)

Step-by-step solution →
Q171·PhysicsMultiple correctJEE Advanced 2019
A mixture of ideal gas contains 5 moles of monatomic gas and 1 mole of rigid diatomic gas is initially at pressure P0P_0P0​, volume V0V_0V0​, and temperature T0T_0T0​. If the gas mixture is adiabatically compressed to a volume V04\frac{V_0}{4}4V0​​, then the correct statement(s) is /are, (Given 21.2=2.32^{1.2} = 2.321.2=2.3; 23.2=9.22^{3.2} = 9.223.2=9.2; R is gas constant)
  1. (A)Adiabatic constant of the gas mixture is 1.6
  2. (B)The final pressure of the gas mixture after compression is in between 9P09P_09P0​ and 10P010P_010P0​
  3. (C)The work ∣W∣|W|∣W∣ done during the process is 13RT013RT_013RT0​
  4. (D)The average kinetic energy of the gas mixture after compression is in between 18RT018RT_018RT0​ and 19RT019RT_019RT0​.

Correct answer: (A), (B), (C)

Step-by-step solution →
Q172·PhysicsSingle correctJEE Advanced 2019
Answer the following by appropriately matching the list based on the information given in the paragraph. In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔXT\Delta XTΔX, where T is temperature of the system and ΔX\Delta XΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=32Rln⁡(TTA)+Rln⁡(VVA)X = \frac{3}{2}R\ln\left(\frac{T}{T_A}\right) + R\ln\left(\frac{V}{V_A}\right)X=23​Rln(TA​T​)+Rln(VA​V​). Here, R is gas constant, V is volume of gas. TAT_ATA​ and VAV_AVA​ are constants. The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities. If the process carried out on one mole of monatomic ideal gas is as shown in figure in the PV-diagram with P0V0=13RT0P_0V_0 = \frac{1}{3}RT_0P0​V0​=31​RT0​, the correct match is,
List-IList-II
I.Work done by the system in process 1→2→31 \to 2 \to 31→2→3P.13RT0ln⁡2\frac{1}{3}RT_0\ln 231​RT0​ln2
II.Change in internal energy in process 1→2→31 \to 2 \to 31→2→3Q.13RT0\frac{1}{3}RT_031​RT0​
III.Heat absorbed by the system in process 1→2→31 \to 2 \to 31→2→3R.RT0RT_0RT0​
IV.Heat absorbed by the system in process 1→21 \to 21→2S.43RT0\frac{4}{3}RT_034​RT0​
T.13RT0(3+ln⁡2)\frac{1}{3}RT_0(3+\ln 2)31​RT0​(3+ln2)
U.56RT0\frac{5}{6}RT_065​RT0​
  1. (A)I →\to→ Q, II →\to→ R, III →\to→ S, IV →\to→ U
  2. (B)I →\to→ Q, II →\to→ S, III →\to→ R, IV →\to→ U
  3. (C)I →\to→ Q, II →\to→ R, III →\to→ P, IV →\to→ U
  4. (D)I →\to→ S, II →\to→ R, III →\to→ Q, IV →\to→ T

Correct answer: (A)

Step-by-step solution →
Q173·PhysicsMultiple correctJEE Advanced 2019
One mole of a monatomic ideal gas goes through a thermodynamic cycle, as shown in the volume versus temperature (V – T) diagram. The correct statement(s) is/are: [R is the gas constant]
  1. (A)Work done in this thermodynamic cycle (1 → 2 → 3 → 4 → 1) is ∣W∣=12RT0|W| = \frac{1}{2}RT_0∣W∣=21​RT0​
  2. (B)The ratio of heat transfer during processes 1 → 2 and 2 → 3 is ∣Q1→2Q2→3∣=53\left|\frac{Q_{1\to 2}}{Q_{2\to 3}}\right| = \frac{5}{3}​Q2→3​Q1→2​​​=35​
  3. (C)The above thermodynamic cycle exhibits only isochoric and adiabatic processes.
  4. (D)The ratio of heat transfer during processes 1 → 2 and 3 → 4 is ∣Q1→2Q3→4∣=12\left|\frac{Q_{1\to 2}}{Q_{3\to 4}}\right| = \frac{1}{2}​Q3→4​Q1→2​​​=21​

Correct answer: (A), (B)

Step-by-step solution →
Q174·PhysicsSingle correctJEE Main 2019
A diatomic gas with rigid molecules does 10 J of work when expanded at constant pressure. What would be the heat energy absorbed by the gas, in this process?
  1. (A)40 J
  2. (B)30 J
  3. (C)35 J
  4. (D)25 J

Correct answer: (C)

Step-by-step solution →
Q175·PhysicsSingle correctJEE Main 2019
A Carnot engine has an efficiency of 1/6. When the temperature of the sink is reduced by 62ºC, its efficiency is doubled. The temperatures of the source and the sink are, respectively
  1. (A)62ºC, 124ºC
  2. (B)99ºC, 37ºC
  3. (C)37ºC, 99ºC
  4. (D)124ºC, 62ºC

Correct answer: (B)

Step-by-step solution →
Q176·PhysicsSingle correctJEE Main 2019
A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal energy of the gas along the path ca is −-−180 J. The gas absorbs 250 J of heat along the path ab and 60 J along the path bc. The work done by the gas along the path abc is :
  1. (A)120 J
  2. (B)100 J
  3. (C)140 J
  4. (D)130 J

Correct answer: (D)

Step-by-step solution →
Q177·PhysicsSingle correctJEE Main 2019
n-moles of an ideal gas with constant volume heat capacity CVC_{V}CV​ undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is
  1. (A)nRCV−nR\dfrac{nR}{C_{V} - nR}CV​−nRnR​
  2. (B)nRCV+nR\dfrac{nR}{C_{V} + nR}CV​+nRnR​
  3. (C)4nRCV+nR\dfrac{4nR}{C_{V} + nR}CV​+nR4nR​
  4. (D)4nRCV−nR\dfrac{4nR}{C_{V} - nR}CV​−nR4nR​

Correct answer: (B)

Step-by-step solution →
Q178·PhysicsSingle correctJEE Main 2019
One mole of an ideal gas passes through a process where pressure and volume obey the relation P=P0[1−12(V0V)2]P = P_{0}\left[1 - \dfrac{1}{2}\left(\dfrac{V_{0}}{V}\right)^{2}\right]P=P0​[1−21​(VV0​​)2]. Here P0P_{0}P0​ and V0V_{0}V0​ are constants. Calculate the change in the temperature of the gas if its volume change from V0V_{0}V0​ to 2V02V_{0}2V0​
  1. (A)14P0V0R\dfrac{1}{4}\dfrac{P_{0}V_{0}}{R}41​RP0​V0​​
  2. (B)12P0V0R\dfrac{1}{2}\dfrac{P_{0}V_{0}}{R}21​RP0​V0​​
  3. (C)54P0V0R\dfrac{5}{4}\dfrac{P_{0}V_{0}}{R}45​RP0​V0​​
  4. (D)34P0V0R\dfrac{3}{4}\dfrac{P_{0}V_{0}}{R}43​RP0​V0​​

Correct answer: (C)

Step-by-step solution →
Q179·PhysicsSingle correctJEE Main 2019
Following figure shows two processes A and B for a gas. If ΔQA\Delta Q_AΔQA​ and ΔQB\Delta Q_BΔQB​ are the amount of heat absorbed by the system in two cases, and ΔUA\Delta U_AΔUA​ and ΔUB\Delta U_BΔUB​ are changes in internal energies, respectively, then:
  1. (A)ΔQA=ΔQB;ΔUA=ΔUB\Delta Q_A=\Delta Q_B; \Delta U_A=\Delta U_BΔQA​=ΔQB​;ΔUA​=ΔUB​
  2. (B)ΔQA>ΔQB;ΔUA=ΔUB\Delta Q_A>\Delta Q_B; \Delta U_A=\Delta U_BΔQA​>ΔQB​;ΔUA​=ΔUB​
  3. (C)ΔQA<ΔQB;ΔUA<ΔUB\Delta Q_A<\Delta Q_B; \Delta U_A<\Delta U_BΔQA​<ΔQB​;ΔUA​<ΔUB​
  4. (D)ΔQA>ΔQB;ΔUA>ΔUB\Delta Q_A>\Delta Q_B; \Delta U_A>\Delta U_BΔQA​>ΔQB​;ΔUA​>ΔUB​

Correct answer: (B)

Step-by-step solution →
Q180·PhysicsSingle correctJEE Main 2019
For the given cyclic process CAB as shown for a gas, the work done is:
  1. (A)30 J
  2. (B)10 J
  3. (C)1 J
  4. (D)5 J

Correct answer: (B)

Step-by-step solution →
Q181·PhysicsSingle correctJEE Main 2019
In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = K, where I is a constant. In this process the temperature of the gas is increased by ΔT\Delta TΔT. The amount of heat absorbed by gas is (R is gas constant)
  1. (A)12RΔT\frac{1}{2}R\Delta T21​RΔT
  2. (B)12KRΔT\frac{1}{2}KR\Delta T21​KRΔT
  3. (C)32RΔT\frac{3}{2}R\Delta T23​RΔT
  4. (D)2K3ΔT\frac{2K}{3}\Delta T32K​ΔT

Correct answer: (A)

Step-by-step solution →
Q182·PhysicsSingle correctJEE Main 2019
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The rational between temperature and volume for the process is TVxTV^{x}TVx = constant, then x is:
  1. (A)3/5
  2. (B)2/5
  3. (C)2/3
  4. (D)5/3

Correct answer: (B)

Step-by-step solution →
Q183·PhysicsSingle correctJEE Main 2019
A gas can be taken from A to B via two different processes ACB and ADB. When path ACB is used 60 J of heat flows into the system and 30 J of work is done by the system. If path ADB is used work down by the system is 10 J. the heat flow into the system in path ADB is
  1. (A)40 J
  2. (B)80 J
  3. (C)100 J
  4. (D)20 J

Correct answer: (A)

Step-by-step solution →
Q184·PhysicsSingle correctJEE Main 2019
Two Carnot engines A and B are operated in series. The first one, A, receives heat at T1(=600T_1(= 600T1​(=600 K))) and rejects to a reservoir at temperature T2T_2T2​. The second engine B receives heat rejected by the first engine and, in turns, rejects to a heat reservoir at T3(=400T_3 (=400T3​(=400 K))). Calculate the temperature T2T_2T2​ if the work outputs of the two engines are equal:
  1. (A)600 K
  2. (B)400 K
  3. (C)300 K
  4. (D)500 K

Correct answer: (D)

Step-by-step solution →
Q185·PhysicsSingle correctJEE Advanced 2018
One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV-diagram below. Among these four processes, one is isobaric, one is isochoric, one is isothermal and one is adiabatic. Match the processes mentioned in List-1 with the corresponding statements in List-II.
LIST-ILIST-II
P.In process I1.Work done by the gas is zero
Q.In process II2.Temperature of the gas remains unchanged
R.In process III3.No heat is exchanged between the gas and its surroundings
S.In process IV4.Work done by the gas is 6P0V06P_{0}V_{0}6P0​V0​
  1. (A)P →\rightarrow→ 4; Q →\rightarrow→ 3; R →\rightarrow→ 1; S →\rightarrow→ 2
  2. (B)P →\rightarrow→ 1; Q →\rightarrow→ 3; R →\rightarrow→ 2; S →\rightarrow→ 4
  3. (C)P →\rightarrow→ 3; Q →\rightarrow→ 4; R →\rightarrow→ 1; S →\rightarrow→ 2
  4. (D)P →\rightarrow→ 3; Q →\rightarrow→ 4; R →\rightarrow→ 2; S →\rightarrow→ 1

Correct answer: (C)

Step-by-step solution →
Q186·PhysicsMultiple correctJEE Advanced 2018
One mole of a monatomic ideal gas undergoes a cyclic process as shown in the figure (where VVV is the volume and TTT is the temperature). Which of the statements below is (are) true?
  1. (A)Process I is an isochoric process
  2. (B)In process II, gas absorbs heat
  3. (C)In process IV, gas releases heat
  4. (D)Processes I and III are not isobaric

Correct answer: (B), (C), (D)

Step-by-step solution →
Q187·PhysicsNumericalJEE Advanced 2018
One mole of a monatomic ideal gas undergoes an adiabatic expansion in which its volume becomes eight times its initial value. If the initial temperature of the gas is 100 K and the universal gas constant R = 8.0 J mol−1^{-1}−1K−1^{-1}−1, the decrease in its internal energy, in Joule, is___________.

Correct answer: 900.00

Step-by-step solution →
Q188·PhysicsSingle correctJEE Advanced 2017
An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P−VP-VP−V diagrams in column 3 of the table. Consider only the path from state 1 to 2. WWW denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic processes. Here γ\gammaγ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is nnn. Which one of the following options is the correct combination?
Column IColumn 2Column 3
(I) W1−2=1γ−1(P2V2−P1V2)W_{1-2} = \frac{1}{\gamma-1}\left(P_{2}V_{2}-P_{1}V_{2}\right)W1−2​=γ−11​(P2​V2​−P1​V2​)(i) Isothermal(P)
(II) W1→2=−PV2+PV1W_{1\rightarrow 2} = -PV_{2}+PV_{1}W1→2​=−PV2​+PV1​(ii) isochoric(Q)
(III) W1→2=0W_{1\rightarrow 2} = 0W1→2​=0(iii) Isobaric(R)
(IV) W1→2=−nRTln⁡(V2V1)W_{1\rightarrow 2} = -nRT\ln\left(\frac{V_{2}}{V_{1}}\right)W1→2​=−nRTln(V1​V2​​)(iv) Adiabatic(S)
  1. (A)(III) (ii) (S)
  2. (B)(II) (iv) (R)
  3. (C)(II) (iv) (P)
  4. (D)(IV) (ii) (S)

Correct answer: (A)

Step-by-step solution →
Q189·PhysicsSingle correctJEE Advanced 2017
An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P−VP-VP−V diagrams in column 3 of the table. Consider only the path from state 1 to 2. WWW denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic processes. Here γ\gammaγ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is nnn. Which one of the following options correctly represents a thermodynamic process that is used as a correction in the determination of the speed of sound in an ideal gas?
Column IColumn 2Column 3
(I) W1−2=1γ−1(P2V2−P1V2)W_{1-2} = \frac{1}{\gamma-1}\left(P_{2}V_{2}-P_{1}V_{2}\right)W1−2​=γ−11​(P2​V2​−P1​V2​)(i) Isothermal(P)
(II) W1→2=−PV2+PV1W_{1\rightarrow 2} = -PV_{2}+PV_{1}W1→2​=−PV2​+PV1​(ii) isochoric(Q)
(III) W1→2=0W_{1\rightarrow 2} = 0W1→2​=0(iii) Isobaric(R)
(IV) W1→2=−nRTln⁡(V2V1)W_{1\rightarrow 2} = -nRT\ln\left(\frac{V_{2}}{V_{1}}\right)W1→2​=−nRTln(V1​V2​​)(iv) Adiabatic(S)
  1. (A)(III) (iv) (R)
  2. (B)(I) (ii) (Q)
  3. (C)(IV) (ii) (R)
  4. (D)(I) (iv) (Q)

Correct answer: (D)

Step-by-step solution →
Q190·PhysicsSingle correctJEE Advanced 2017
An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P−VP-VP−V diagrams in column 3 of the table. Consider only the path from state 1 to 2. WWW denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic processes. Here γ\gammaγ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is nnn. Which of the following options is the only correct representation of a process in which ΔU=ΔQ−PΔV\Delta U = \Delta Q - P\Delta VΔU=ΔQ−PΔV ?
Column IColumn 2Column 3
(I) W1−2=1γ−1(P2V2−P1V2)W_{1-2} = \frac{1}{\gamma-1}\left(P_{2}V_{2}-P_{1}V_{2}\right)W1−2​=γ−11​(P2​V2​−P1​V2​)(i) Isothermal(P)
(II) W1→2=−PV2+PV1W_{1\rightarrow 2} = -PV_{2}+PV_{1}W1→2​=−PV2​+PV1​(ii) isochoric(Q)
(III) W1→2=0W_{1\rightarrow 2} = 0W1→2​=0(iii) Isobaric(R)
(IV) W1→2=−nRTln⁡(V2V1)W_{1\rightarrow 2} = -nRT\ln\left(\frac{V_{2}}{V_{1}}\right)W1→2​=−nRTln(V1​V2​​)(iv) Adiabatic(S)
  1. (A)(II) (iv) (R)
  2. (B)(II) (iii) (P)
  3. (C)(II) (iii) (S)
  4. (D)(III) (iii) (P)

Correct answer: (B)

Step-by-step solution →
Q191·PhysicsSingle correctJEE Advanced 2016
A water cooler of storage capacity 120 litres can cool water at a constant rate of PPP watts. In a closed circulation system (as shown schematically in the figure), the water from the cooler is used to cool an external device that generates constantly 3 kW of heat (thermal load). The temperature of water fed into the device cannot exceed 30 0C30\ ^{0}\text{C}30 0C and the entire stored 120 litres of water is initially cooled to 10 0C10\ ^{0}\text{C}10 0C. The entire system is thermally insulated. The minimum value of PPP (in watts) for which the device can be operated for 3 hours is (Specific heat of water is 4.2 kJ kg−1 K−14.2\ \text{kJ kg}^{-1}\ \text{K}^{-1}4.2 kJ kg−1 K−1 and the density of water is 1000 kg m−31000\ \text{kg m}^{-3}1000 kg m−3)
  1. (A)1600
  2. (B)2067
  3. (C)2533
  4. (D)3933

Correct answer: (B)

Step-by-step solution →
Q192·PhysicsIntegerJEE Advanced 2016
A metal is heated in a furnace where a sensor is kept above the metal surface to read the power radiated (PPP) by the metal. The sensor has a scale that displays log⁡2(P/P0)\log_2 (P/P_0)log2​(P/P0​), where P0P_0P0​ is a constant. When the metal surface is at a temperature of 487°C, the sensor shows a value 1. Assume that the emissivity of the metallic surface remains constant. What is the value displayed by the sensor when the temperature of the metal surface is raised to 2767 °C?

Correct answer: 9

Step-by-step solution →
Q193·PhysicsSingle correctJEE Advanced 2016
A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi=105P_{i} = 10^{5}Pi​=105 Pa and volume Vi=10−3 m3V_{i} = 10^{-3}\ \text{m}^{3}Vi​=10−3 m3 changes to a final state at Pf=(1/32)×105P_{f} = (1/32) \times 10^{5}Pf​=(1/32)×105 Pa and Vf=8×10−3 m3V_{f} = 8 \times 10^{-3}\ \text{m}^{3}Vf​=8×10−3 m3 in an adiabatic quasi-static process, such that P3V5P^{3}V^{5}P3V5 = constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at PiP_{i}Pi​ followed by an isochoric (isovolumetric) process at volume VfV_{f}Vf​. The amount of heat supplied to the system in the two-step process is approximately
  1. (A)112 J
  2. (B)294 J
  3. (C)588 J
  4. (D)813 J

Correct answer: (C)

Step-by-step solution →
Q194·PhysicsMultiple correctJEE Advanced 2015
An ideal monoatomic gas is confined in a horizontal cylinder by a spring loaded piston (as shown in the figure). Initially the gas is at temperature T1T_{1}T1​, pressure P1P_{1}P1​ and volume V1V_{1}V1​ and the spring is in its relaxed state. The gas is then heated very slowly to temperature T2T_{2}T2​, pressure P2P_{2}P2​ and volume V2V_{2}V2​. During this process the piston moves out by a distance x. Ignoring the friction between the piston and the cylinder, the correct statement(s) is(are)
  1. (A)If V2=2V1V_{2} = 2V_{1}V2​=2V1​ and T2=3T1T_{2} = 3T_{1}T2​=3T1​, then the energy stored in the spring is 14P1V1\dfrac{1}{4}P_{1}V_{1}41​P1​V1​
  2. (B)If V2=2V1V_{2} = 2V_{1}V2​=2V1​ and T2=3T1T_{2} = 3T_{1}T2​=3T1​, then the change in internal energy is 3P1V13P_{1}V_{1}3P1​V1​
  3. (C)If V2=3V1V_{2} = 3V_{1}V2​=3V1​ and T2=4T1T_{2} = 4T_{1}T2​=4T1​, then the work done by the gas is 73P1V1\dfrac{7}{3}P_{1}V_{1}37​P1​V1​
  4. (D)If V2=3V1V_{2} = 3V_{1}V2​=3V1​ and T2=4T1T_{2} = 4T_{1}T2​=4T1​, then the heat supplied to the gas is 176P1V1\dfrac{17}{6}P_{1}V_{1}617​P1​V1​

Correct answer: (B) or (A), (B), (C)

Step-by-step solution →
Q195·PhysicsIntegerJEE Advanced 2015
Two spherical stars A and B emit blackbody radiation. The radius of A is 400 times that of B and A emits 10410^{4}104 times the power emitted from B. The ratio (λA/λB)\left(\lambda_{A}/\lambda_{B}\right)(λA​/λB​) of their wavelengths λA\lambda_{A}λA​ and λB\lambda_{B}λB​ at which the peaks occur in their respective radiation curves is

Correct answer: 2

Step-by-step solution →
Q196·PhysicsIntegerJEE Advanced 2014
A thermodynamic system is taken from an initial state iii with internal energy Ui=100 JU_i = 100 \text{ J}Ui​=100 J to the final state fff along two different paths iafiafiaf and ibfibfibf, as schematically shown in the figure. The work done by the system along the paths afafaf, ibibib and bfbfbf are Waf=200 JW_{af} = 200 \text{ J}Waf​=200 J, Wib=50 JW_{ib} = 50 \text{ J}Wib​=50 J and Wbf=100 JW_{bf} = 100 \text{ J}Wbf​=100 J respectively. The heat supplied to the system along the path iafiafiaf, ibibib and bfbfbf are QiafQ_{iaf}Qiaf​, QibQ_{ib}Qib​ and QbfQ_{bf}Qbf​ respectively. If the internal energy of the system in the state bbb is Ub=200 JU_b = 200 \text{ J}Ub​=200 J and Qiaf=500 JQ_{iaf} = 500 \text{ J}Qiaf​=500 J, the ratio Qbf/QibQ_{bf} / Q_{ib}Qbf​/Qib​ is

Correct answer: 2

Step-by-step solution →
Q197·PhysicsSingle correctJEE Advanced 2014
In the figure a container is shown to have a movable (without friction) piston on top. The container and the piston are all made of perfectly insulating material allowing no heat transfer between outside and inside the container. The container is divided into two compartments by a rigid partition made of a thermally conducting material that allows slow transfer of heat. The lower compartment of the container is filled with 2 moles of an ideal monatomic gas at 700 K and the upper compartment is filled with 2 moles of an ideal diatomic gas at 400 K. The heat capacities per mole of an ideal monatomic gas are CV=32RC_{V} = \frac{3}{2}RCV​=23​R, CP=52RC_{P} = \frac{5}{2}RCP​=25​R, and those for an ideal diatomic gas are CV=52RC_{V} = \frac{5}{2}RCV​=25​R, CP=72RC_{P} = \frac{7}{2}RCP​=27​R. Now consider the partition to be free to move without friction so that the pressure of gases in both compartments is the same. Then total work done by the gases till the time they achieve equilibrium will be
  1. (A)250R250R250R
  2. (B)200R200R200R
  3. (C)100R100R100R
  4. (D)−100R-100R−100R

Correct answer: (D)

Step-by-step solution →
Q198·PhysicsSingle correctJEE Advanced 2014
In the figure a container is shown to have a movable (without friction) piston on top. The container and the piston are all made of perfectly insulating material allowing no heat transfer between outside and inside the container. The container is divided into two compartments by a rigid partition made of a thermally conducting material that allows slow transfer of heat. The lower compartment of the container is filled with 2 moles of an ideal monatomic gas at 700 K and the upper compartment is filled with 2 moles of an ideal diatomic gas at 400 K. The heat capacities per mole of an ideal monatomic gas are CV=32RC_{V} = \frac{3}{2}RCV​=23​R, CP=52RC_{P} = \frac{5}{2}RCP​=25​R, and those for an ideal diatomic gas are CV=52RC_{V} = \frac{5}{2}RCV​=25​R, CP=72RC_{P} = \frac{7}{2}RCP​=27​R. Consider the partition to be rigidly fixed so that it does not move. When equilibrium is achieved, the final temperature of the gases will be
  1. (A)550 K
  2. (B)525 K
  3. (C)513 K
  4. (D)490 K

Correct answer: (D)

Step-by-step solution →
Q199·PhysicsSingle correctJEE Advanced 2013
Two rectangular blocks, having identical dimensions, can be arranged either in configuration I or in configuration II as shown in the figure. One of the blocks has thermal conductivity κ\kappaκ and the other 2κ2\kappa2κ. The temperature difference between the ends along the x-axis is the same in both the configurations. It takes 9 s to transport a certain amount of heat from the hot end to the cold end in the configuration I. The time to transport the same amount of heat in the configuration II is
  1. (A)2.0 s
  2. (B)3.0 s
  3. (C)4.5 s
  4. (D)6.0 s

Correct answer: (A)

Step-by-step solution →
Q200·PhysicsSingle correctJEE Advanced 2013
One mole of mono-atomic ideal gas is taken along two cyclic processes E→F→G→EE \to F \to G \to EE→F→G→E and E→F→H→EE \to F \to H \to EE→F→H→E as shown in the PV diagram. The processes involved are purely isochoric, isobaric, isothermal or adiabatic. Match the paths in List I with the magnitudes of the work done in List II and select the correct answer using the codes given below the lists.
List IList II
P.G→EG \to EG→E1.160 P0V0ln⁡2160\,P_{0}V_{0}\ln 2160P0​V0​ln2
Q.G→HG \to HG→H2.36 P0V036\,P_{0}V_{0}36P0​V0​
R.F→HF \to HF→H3.24 P0V024\,P_{0}V_{0}24P0​V0​
S.F→GF \to GF→G4.31 P0V031\,P_{0}V_{0}31P0​V0​
  1. (A)P-4, Q-3, R-2, S-1
  2. (B)P-4, Q-3, R-1, S-2
  3. (C)P-3, Q-1, R-2, S-4
  4. (D)P-1, Q-3, R-2, S-4

Correct answer: (A)

Step-by-step solution →
Q201·PhysicsMultiple correctJEE Advanced 2013
The figure shows the variation of specific heat capacity (CCC) of a solid as a function of temperature (TTT). The temperature is increased continuously from 000 to 500 K500\ \mathrm{K}500 K at a constant rate. Ignoring any volume change, the following statement(s) is (are) correct to a reasonable approximation.
  1. (A)the rate at which heat is absorbed in the range 000-100 K100\ \mathrm{K}100 K varies linearly with temperature TTT.
  2. (B)heat absorbed in increasing the temperature from 000-100 K100\ \mathrm{K}100 K is less than the heat required for increasing the temperature from 400400400 – 500 K500\ \mathrm{K}500 K.
  3. (C)there is no change in the rate of heat absorption in range 400400400 – 500 K500\ \mathrm{K}500 K.
  4. (D)the rate of heat absorption increases in the range 200200200 – 300 K300\ \mathrm{K}300 K.

Correct answer: (A), (B), (C), (D)

Step-by-step solution →

Thermodynamics — frequently asked

How many questions from Thermodynamics appear in JEE?

Thermodynamics has appeared in 154 of the last 186 JEE Main and JEE Advanced papers — about 83% of them — contributing 201 questions in total across those papers.

Is Thermodynamics an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 83% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Thermodynamics questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Physics chapters

  • Properties of Solids and Liquids 344
  • Current Electricity 309
  • Rotational Motion 266
  • Geometrical Optics 259
  • Kinematics 255
  • Magnetic Field of Current 211
  • Electromagnetic Waves 208
  • Laws of Motion 196

All 28 Physics chapters →

Practise Thermodynamics until it stops costing you marks.

Build a timed test from these 201 questions in one click. Jarvis marks it, names the specific misconception behind each wrong answer, and brings the ones you failed back at the right interval.

Practise Thermodynamics freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS