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Atoms — JEE Previous Year Questions

Every Atoms question asked in JEE Main and JEE Advanced across the last 186 papers — 130 questions, each with its correct answer. Free to read, no account needed.

Questions

130

Papers it appeared in

112/186

Appearance rate

60%

All 130 Atoms questions

Most recent papers first.

Q1·PhysicsMultiple correctJEE Advanced 2026
Consider a hydrogen atom with vkv_kvk​, rkr_krk​, and KkK_kKk​ denoting the velocity, orbital radius and kinetic energy of the electron in the kthk^{\text{th}}kth orbit, respectively. The electron undergoes a transition from the nthn^{\text{th}}nth orbit, emitting radiation corresponding to the Lyman series. Considering hhh to be the Planck's constant and ϵ0\epsilon_0ϵ0​ the permittivity of the free space, the correct statement(s) is/are:
  1. (A)Magnitude of change in kinetic energy of electron can be expressed as h4π∣nvnrn−v1r1∣\frac{h}{4\pi}\left|\frac{nv_n}{r_n} - \frac{v_1}{r_1}\right|4πh​​rn​nvn​​−r1​v1​​​.
  2. (B)Magnitude of change in de Broglie wavelength of the electron can be expressed as e24ϵ0∣1Kn−1K1∣\frac{e^2}{4\epsilon_0}\left|\frac{1}{K_n} - \frac{1}{K_1}\right|4ϵ0​e2​​Kn​1​−K1​1​​.
  3. (C)Frequency of the radiation emitted can be expressed as e28πϵ0h(1r1−1rn)\frac{e^2}{8\pi\epsilon_0 h}\left(\frac{1}{r_1} - \frac{1}{r_n}\right)8πϵ0​he2​(r1​1​−rn​1​).
  4. (D)Magnitude of change in total energy of the electron can be expressed as h2π∣v1r1−nvnrn∣\frac{h}{2\pi}\left|\frac{v_1}{r_1} - \frac{nv_n}{r_n}\right|2πh​​r1​v1​​−rn​nvn​​​.

Correct answer: (A), (C)

Step-by-step solution →
Q2·PhysicsSingle correctJEE Main 2026
The ratio of momentum of the photons of the 1st^{st}st and 2nd^{nd}nd line of Balmer series of Hydrogen atoms is α/β\alpha/\betaα/β. The possible values of α\alphaα and β\betaβ are:-
  1. (A)27 and 20
  2. (B)3 and 16
  3. (C)5 and 36
  4. (D)20 and 27

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correctJEE Main 2026
In the hydrogen atom, the electron makes a transition from the higher orbit (i)(i)(i) to a lower orbit (f)(f)(f). The ratio of the radius of the orbits in given by ri:rf=16:4r_i : r_f = 16 : 4ri​:rf​=16:4. The wavelength of photon emitted due to this transition is ______ nm. (Given Rydberg constant =1.0973×107= 1.0973 \times 10^7=1.0973×107 /m)
  1. (A)121
  2. (B)242
  3. (C)486
  4. (D)974

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correctJEE Main 2026
In Rutherford's alpha-particle scattering experiment, only a few alpha particles rebound back because A. The size of gold nucleus is very small as compared to the size of gold atom. B. Alpha particle and gold nucleus have equal charge. C. The impact parameter is minimum for a few alpha particles. D. A few alpha particles have very high kinetic energy. E. Only a few alpha particles undergo head-on collision with the nuclei. Choose the correct answer from the options given below:
  1. (A)A, B Only
  2. (B)B, E Only
  3. (C)C, D Only
  4. (D)A, C, E Only

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsNumericalJEE Main 2026
Using Bohr's model, calculate the ratio of the magnetic fields generated due to the motion of the electrons in the 2nd2^{nd}2nd and 4th4^{th}4th orbits of hydrogen atom ________.

Correct answer: 32

Step-by-step solution →
Q6·PhysicsSingle correctJEE Main 2026
Angular momentum of an electron in a hydrogen atom is 3hπ\frac{3h}{\pi}π3h​, then the energy of the electron is ________ eV.
  1. (A)−1.51
  2. (B)−0.85
  3. (C)−0.38
  4. (D)−0.28

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correctJEE Main 2026
Two electrons are moving in orbits of two hydrogen like atoms with speeds 3×1053 \times 10^{5}3×105 m/s and 2.5×1052.5 \times 10^{5}2.5×105 m/s respectively. If the radii of these orbits are nearly same then the possible order of energy states are______ respectively.
  1. (A)6 and 5
  2. (B)9 and 8
  3. (C)8 and 10
  4. (D)10 and 12

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correctJEE Main 2026
In hydrogen atom spectrum, (R → Rydberg's constant) A. the maximum wavelength of the radiation of Lyman series is 43R\frac{4}{3R}3R4​ B. the Balmer series lies in the visible region of the spectrum C. the minimum wavelength of the radiation of Paschen series is 9R\frac{9}{R}R9​ D. the minimum wavelength of Lyman series is 54R\frac{5}{4R}4R5​ Choose the correct answer from the options given below :
  1. (A)B, D Only
  2. (B)A, B and C Only
  3. (C)A, B and D Only
  4. (D)A, B Only

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correctJEE Main 2026
7.9 MeV α−particle scatters from a target material of atomic number 79. From the given data the estimated diameter of nuclei of the target material is (approximately)_________m. [14π∈o=9×109 Nm2/C2\frac{1}{4\pi \in_{o}} = 9\times 10^{9}\,\mathrm{Nm}^{2}/\mathrm{C}^{2}4π∈o​1​=9×109Nm2/C2 and electron charge =1.6×10−19C=1.6\times 10^{-19}\mathrm{C}=1.6×10−19C]
  1. (A)5.76×10−145.76 \times 10^{-14}5.76×10−14
  2. (B)1.44×10−131.44 \times 10^{-13}1.44×10−13
  3. (C)2.88×10−142.88 \times 10^{-14}2.88×10−14
  4. (D)1.69×10−121.69 \times 10^{-12}1.69×10−12

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correctJEE Main 2026
The smallest wavelength of Lyman series is 91 nm. The difference between the largest wavelengths of Paschen and Balmer series is nearly ____ nm.
  1. (A)1875
  2. (B)1550
  3. (C)1217
  4. (D)1784

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correctJEE Main 2026
The energy of an electron in an orbit of the Bohr's atom is −0.04E0-0.04\text{E}_0−0.04E0​ eV where E0\text{E}_0E0​ is the ground state energy. If L is the angular momentum of the electron in this orbit and h is the Planck's constant, then 2πLh\dfrac{2\pi\text{L}}{\text{h}}h2πL​ is __________ :
  1. (A)2
  2. (B)4
  3. (C)5
  4. (D)6

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correctJEE Main 2026
If an alpha particle with energy 7.7 MeV is bombarded on a thin gold foil, the closest distance from nucleus it can reach is _________ m. (Atomic number of gold = 79 and 14πϵ0=9×109\frac{1}{4\pi \epsilon_{0}} = 9 \times 10^{9}4πϵ0​1​=9×109 in SI units)
  1. (A)2.95×10−142.95 \times 10^{-14}2.95×10−14
  2. (B)2.95×10−162.95 \times 10^{-16}2.95×10−16
  3. (C)3.85×10−163.85 \times 10^{-16}3.85×10−16
  4. (D)3.85×10−143.85 \times 10^{-14}3.85×10−14

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsNumericalJEE Advanced 2025
A hydrogen atom, initially at rest in its ground state, absorbs a photon of frequency ν1\nu_1ν1​ and ejects the electron with a kinetic energy of 10 eV. The electron then combines with a positron at rest to form a positronium atom in its ground state and simultaneously emits a photon of frequency ν2\nu_2ν2​. The center of mass of the resulting positronium atom moves with a kinetic energy of 5 eV. It is given that positron has the same mass as that of electron and the positronium atom can be considered as a Bohr atom, in which the electron and the positron orbit around their center of mass. Considering no other energy loss during the whole process, the difference between the two photon energies (in eV) is ______

Correct answer: 11.8

Step-by-step solution →
Q14·PhysicsNumericalJEE Advanced 2025
Consider an electron in the n = 3 orbit of a hydrogen-like atom with atomic number Z. At absolute temperature T, a neutron having thermal energy kBTk_{B}TkB​T has the same de Broglie wavelength as that of this electron. If this temperature is given by T=z2h2απ2a02mNkBT = \frac{z^{2}h^{2}}{\alpha\pi^{2}a_{0}^{2}m_{N}k_{B}}T=απ2a02​mN​kB​z2h2​, (where h is the Planck's constant, kBk_{B}kB​ is the Boltzmann constant, mNm_{N}mN​ is the mass of the neutron and a0a_{0}a0​ is the first Bohr radius of hydrogen atom) then the value of α\alphaα is

Correct answer: 72

Step-by-step solution →
Q15·PhysicsSingle correctJEE Main 2025
In a hydrogen like ion, the energy difference between the 2nd2^{nd}2nd excitation energy state and ground is 108.8 eV. The atomic number of the ion is
  1. (A)4
  2. (B)2
  3. (C)1
  4. (D)3

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correctJEE Main 2025
For a hydrogen atom, the ratio of the largest wavelength of Lyman series to that of the Balmer series is.
  1. (A)5:365:365:36
  2. (B)5:275:275:27
  3. (C)3:43:43:4
  4. (D)27:527:527:5

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correctJEE Main 2025
Given below are two statements: Statement (I): The dimensions of Planck's constant and angular momentum are same. Statement (II): In Bohr's model electron revolve around the nucleus only in those orbits for which angular momentum is integral multiple of Planck's constant. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are incorrect

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correctJEE Main 2025
Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius 5th5^{\text{th}}5th orbit of the electron in Li2+Li^{2+}Li2+ and He+He^{+}He+ is
  1. (A)32\dfrac{3}{2}23​
  2. (B)49\dfrac{4}{9}94​
  3. (C)94\dfrac{9}{4}49​
  4. (D)23\dfrac{2}{3}32​

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsIntegerJEE Main 2025
An electron in the hydrogen atom initially in the fourth excited state makes a transition to nthn^{th}nth energy state by emitting a photon of energy 2.86 eV. The integer value of nnn will be __________.

Correct answer: 2

Step-by-step solution →
Q20·PhysicsSingle correctJEE Main 2025
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The Bohr model is applicable to hydrogen and hydrogen-like atoms only. Reason R: The formulation of Bohr model does not include repulsive force between electrons. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true but R is NOT the correct explanation of A.
  2. (B)A is false but R is true.
  3. (C)Both A and R are true and R is the correct explanation of A.
  4. (D)A is true but R is false.

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsSingle correctJEE Main 2025
Considering Bohr’s atomic model for hydrogen atom: (A) the energy of H atom in ground state is same as energy of He+^++ ion in its first excited state. (B) The energy of H atom in ground state is same as that for Li2+^{2+}2+ ion in its second excited state. (C) The energy of H atom in its ground state is same as that of He+^++ ion for its ground state. (D) the energy of He+^++ ion in its first excited state is same as that for Li2+^{2+}2+ ion in its ground state. Choose the correct answer from the options given below:
  1. (A)(B), (D) only
  2. (B)(A), (B) only
  3. (C)(A), (D) only
  4. (D)(A), (C) only

Correct answer: (B)

Step-by-step solution →
Q22·PhysicsSingle correctJEE Main 2025
Assuming the validity of Bohr's atomic model for hydrogen like ions, the radius of Li++Li^{++}Li++ ion in its ground state is given by 1Xa0\dfrac{1}{X}a_0X1​a0​, where X=X=X= ______. (Where a0a_0a0​ is the first Bohr's radius.)
  1. (A)2
  2. (B)1
  3. (C)3
  4. (D)9

Correct answer: (C)

Step-by-step solution →
Q23·PhysicsSingle correctJEE Main 2025
The number of spectral lines emitted by atomic hydrogen that is in the 4th4^{\text{th}}4th energy level, is
  1. (A)6
  2. (B)0
  3. (C)3
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q24·PhysicsSingle correctJEE Main 2025
The frequency of revolution of the electron in Bohr's orbit varies with n, the principal quantum number as
  1. (A)1n\frac{1}{n}n1​
  2. (B)1n3\frac{1}{n^3}n31​
  3. (C)1n4\frac{1}{n^4}n41​
  4. (D)1n2\frac{1}{n^2}n21​

Correct answer: (B)

Step-by-step solution →
Q25·PhysicsSingle correctJEE Main 2025
During the transition of electron from state A to state C of a Bohr atom, the wavelength of emitted radiation is 2000 Å and it becomes 6000 Å when the electron jumps from state B to state C. Then the wavelength of the radiation emitted during the transition of electrons from state A to state B is :-
  1. (A)3000 Å
  2. (B)6000 Å
  3. (C)4000 Å
  4. (D)2000 Å

Correct answer: (A)

Step-by-step solution →
Q26·PhysicsSingle correctJEE Main 2025
An electron projected perpendicular to a uniform magnetic field B moves in a circle. If Bohr's quantization is applicable, then the radius of electronic orbit in the first excited state is:
  1. (A)2hπeB\sqrt{\frac{2h}{\pi eB}}πeB2h​​
  2. (B)4hπeB\sqrt{\frac{4h}{\pi eB}}πeB4h​​
  3. (C)h2πeB\sqrt{\frac{h}{2\pi eB}}2πeBh​​
  4. (D)hπeB\sqrt{\frac{h}{\pi eB}}πeBh​​

Correct answer: (D)

Step-by-step solution →
Q27·PhysicsSingle correctJEE Main 2025
An electron is in the orbital radius 5.3×10⁻¹¹ m (ground state) of a hydrogen atom. The ratio of the de Broglie wavelength of the electron in the 3rd excited state to that in the ground state is:
  1. (A)4
  2. (B)9
  3. (C)3
  4. (D)16

Correct answer: (A)

Step-by-step solution →
Q28·PhysicsSingle correctJEE Advanced 2024
A metal target with atomic number Z=46Z = 46Z=46 is bombarded with a high energy electron beam. The emission of X-rays from the target is analyzed. The ratio r of the wavelengths of the KαK_\alphaKα​ -line and the cut-off is found to be r = 2 . If the same electron beam bombards another metal target with Z = 41 , the value of r will be
  1. (A)2.53
  2. (B)1.27
  3. (C)2.24
  4. (D)1.58

Correct answer: (A)

Step-by-step solution →
Q29·PhysicsMultiple correctJEE Advanced 2024
A particle of mass mmm is moving in a circular orbit under the influence of the central force F(r)=−krF(r) = -krF(r)=−kr, corresponding to the potential energy V(r)=kr2/2V(r) = kr^{2}/2V(r)=kr2/2, where kkk is a positive force constant and rrr is the radial distance from the origin. According to the Bohr's quantization rule, the angular momentum of the particle is given by L=nℏL = n\hbarL=nℏ, where ℏ=h/(2π)\hbar = h/(2\pi)ℏ=h/(2π), hhh is the Planck's constant, and nnn a positive integer. If vvv and EEE are the speed and total energy of the particle, respectively, then which of the following expression(s) is(are) correct?
  1. (A)r2=nℏ1mkr^{2} = n\hbar\sqrt{\frac{1}{mk}}r2=nℏmk1​​
  2. (B)v2=nℏkm3v^{2} = n\hbar\sqrt{\frac{k}{m^{3}}}v2=nℏm3k​​
  3. (C)Lmr2=km\frac{L}{mr^{2}} = \sqrt{\frac{k}{m}}mr2L​=mk​​
  4. (D)E=nℏ2kmE = \frac{n\hbar}{2}\sqrt{\frac{k}{m}}E=2nℏ​mk​​

Correct answer: (A), (B), (C)

Step-by-step solution →
Q30·PhysicsSingle correctJEE Main 2024
A hydrogen atom in ground state is given an energy of 10.2 eV. How many spectral lines will be emitted due to transition of electrons?
  1. (A)6
  2. (B)3
  3. (C)10
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q31·PhysicsNumericalJEE Main 2024
In an alpha particle scattering experiment distance of closest approach for the α\alphaα particle is 4.5×10−144.5\times10^{-14}4.5×10−14 m. If target nucleus has atomic number 808080, then maximum velocity of α\alphaα-particle is ___ ×105\times10^5×105 m/s approximately. (14πε0=9×109 SI unit, mass of α particle=6.72×10−27 kg)\left(\dfrac{1}{4\pi\varepsilon_0}=9\times10^9\text{ SI unit, mass of }\alpha\text{ particle}=6.72\times10^{-27}\text{ kg}\right)(4πε0​1​=9×109 SI unit, mass of α particle=6.72×10−27 kg)

Correct answer: 156

Step-by-step solution →
Q32·PhysicsSingle correctJEE Main 2024
The ratio of the shortest wavelength of the Balmer series to the shortest wavelength of the Lyman series for hydrogen atom is:
  1. (A)4:14:14:1
  2. (B)1:21:21:2
  3. (C)1:41:41:4
  4. (D)2:12:12:1

Correct answer: (A)

Step-by-step solution →
Q33·PhysicsSingle correctJEE Main 2024
The longest wavelength associated with Paschen series is : (Given RH=1.097×107R_H = 1.097 \times 10^7RH​=1.097×107 SI unit)
  1. (A)1.094×10−61.094 \times 10^{-6}1.094×10−6 m
  2. (B)2.973×10−62.973 \times 10^{-6}2.973×10−6 m
  3. (C)3.646×10−63.646 \times 10^{-6}3.646×10−6 m
  4. (D)1.876×10−61.876 \times 10^{-6}1.876×10−6 m

Correct answer: (D)

Step-by-step solution →
Q34·PhysicsNumericalJEE Main 2024
In Franck-Hertz experiment, the first dip in the current-voltage graph for hydrogen is observed at 10.210.210.2 V. The wavelength of light emitted by hydrogen atom when excited to the first excitation level is ______ nm. (Given hc=1245hc = 1245hc=1245 eV nm, e=1.6×10−19e = 1.6 \times 10^{-19}e=1.6×10−19 C).

Correct answer: 122

Step-by-step solution →
Q35·PhysicsNumericalJEE Main 2024
Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of the electron in this orbit is Ex\tfrac{E}{x}xE​, then x=x=x= _______. (Given a0=0.529a_{0}=0.529a0​=0.529 Å, E=E=E= energy of electron in the ground state)

Correct answer: 16

Step-by-step solution →
Q36·PhysicsSingle correctJEE Main 2024
In a hydrogen-like system the ratio of the Coulomb force and the gravitational force between an electron and a proton is of the order of:
  1. (A)103910^{39}1039
  2. (B)101910^{19}1019
  3. (C)102910^{29}1029
  4. (D)103610^{36}1036

Correct answer: (A)

Step-by-step solution →
Q37·PhysicsNumericalJEE Main 2024
The shortest wavelength of the spectral lines in the Lyman series of the hydrogen spectrum is 915 Å. The longest wavelength of the spectral lines in the Balmer series will be __________ Å.

Correct answer: 6588

Step-by-step solution →
Q38·PhysicsSingle correctJEE Main 2024
The angular momentum of an electron in a hydrogen atom is proportional to: (where rrr is the radius of the orbit of the electron)
  1. (A)r\sqrt{r}r​
  2. (B)1r\dfrac{1}{r}r1​
  3. (C)rrr
  4. (D)1r\dfrac{1}{\sqrt{r}}r​1​

Correct answer: (A)

Step-by-step solution →
Q39·PhysicsSingle correctJEE Main 2024
An electron rotates in a circle around a nucleus having positive charge ZeZeZe. The correct relation between the total energy (E) of the electron and its potential energy (U) is:
  1. (A)E=2UE = 2UE=2U
  2. (B)2E=3U2E = 3U2E=3U
  3. (C)E=UE = UE=U
  4. (D)2E=U2E = U2E=U

Correct answer: (D)

Step-by-step solution →
Q40·PhysicsSingle correctJEE Main 2024
According to Bohr's theory, the moment of momentum of an electron revolving in 4th4^{\text{th}}4th orbit of hydrogen atom is
  1. (A)8hπ\tfrac{8h}{\pi}π8h​
  2. (B)hπ\tfrac{h}{\pi}πh​
  3. (C)2hπ\tfrac{2h}{\pi}π2h​
  4. (D)h2π\tfrac{h}{2\pi}2πh​

Correct answer: (C)

Step-by-step solution →
Q41·PhysicsNumericalJEE Main 2024
A hydrogen atom changes its state from n=3n=3n=3 to n=2n=2n=2. Due to recoil, the percentage change in the wave length of emitted light is approximately 1×10−n1\times10^{-n}1×10−n. The value of nnn is ___. (Given Rhc=13.6 eVRhc=13.6\,eVRhc=13.6eV, hc=1242 eV nmhc=1242\,eV\,nmhc=1242eVnm, h=6.6×10−34 J sh=6.6\times10^{-34}\,J\,sh=6.6×10−34Js, mass of hydrogen atom =1.6×10−27 kg=1.6\times10^{-27}\,kg=1.6×10−27kg)

Correct answer: 7

Step-by-step solution →
Q42·PhysicsNumericalJEE Main 2024
A particular hydrogen-like ion emits the radiation of frequency 3×10153\times 10^{15}3×1015 Hz when it makes transition from n=2n=2n=2 to n=1n=1n=1. The frequency of radiation emitted in transition from n=3n=3n=3 to n=1n=1n=1 is X9×1015\dfrac{X}{9}\times 10^{15}9X​×1015 Hz, when X=X=X= __________.

Correct answer: 32

Step-by-step solution →
Q43·PhysicsSingle correctJEE Main 2024
The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly:
  1. (A)1.5 eV1.5\,eV1.5eV
  2. (B)13.6 eV13.6\,eV13.6eV
  3. (C)1.9 eV1.9\,eV1.9eV
  4. (D)12.1 eV12.1\,eV12.1eV

Correct answer: (D)

Step-by-step solution →
Q44·PhysicsSingle correctJEE Main 2024
From the statements given below: (A) The angular momentum of an electron in nthn^{\text{th}}nth orbit is an integral multiple of hhh. (B) Nuclear forces do not obey inverse square law. (C) Nuclear forces are spin dependent. (D) Nuclear forces are central and charge independent. (E) Stability of nucleus is inversely proportional to the value of packing fraction. Choose the correct answer from the options given below:
  1. (A)(A), (B), (C), (D) only
  2. (B)(A), (C), (D), (E) only
  3. (C)(A), (B), (C), (E) only
  4. (D)(B), (C), (D), (E) only

Correct answer: (C)

Step-by-step solution →
Q45·PhysicsSingle correctJEE Main 2024
If the wavelength of the first member of Lyman series of hydrogen is λ\lambdaλ. The wavelength of the second member will be :
  1. (A)2732λ\dfrac{27}{32}\lambda3227​λ
  2. (B)3227λ\dfrac{32}{27}\lambda2732​λ
  3. (C)275λ\dfrac{27}{5}\lambda527​λ
  4. (D)527λ\dfrac{5}{27}\lambda275​λ

Correct answer: (A)

Step-by-step solution →
Q46·PhysicsNumericalJEE Main 2024
A electron of hydrogen atom on an excited state is having energy En=−0.85 eVE_n=-0.85\,eVEn​=−0.85eV. The maximum number of allowed transitions to lower energy level is ___

Correct answer: 6

Step-by-step solution →
Q47·PhysicsSingle correctJEE Main 2024
An electron revolving in nthn^{\text{th}}nth Bohr orbit has magnetic moment μn\mu_nμn​. If μn∝nx\mu_n\propto n^xμn​∝nx, then the value of xxx is:
  1. (A)2
  2. (B)1
  3. (C)3
  4. (D)0

Correct answer: (B)

Step-by-step solution →
Q48·PhysicsSingle correctJEE Main 2024
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th5^{th}5th excited state of a hydrogen atom is:
  1. (A)444
  2. (B)14\dfrac1441​
  3. (C)12\dfrac1221​
  4. (D)111

Correct answer: (C)

Step-by-step solution →
Q49·PhysicsNumericalJEE Main 2024
Hydrogen atom is bombarded with electrons accelerated through a potential difference of V, which causes excitation of hydrogen atoms. If the experiment is being performed at T=0T=0T=0 K, the minimum potential difference needed to observe any Balmer series lines in the emission spectra will be α10\dfrac{\alpha}{10}10α​ V, where α=\alpha=α= ___.

Correct answer: 121

Step-by-step solution →
Q50·PhysicsSingle correctJEE Main 2024
Given below are two statements: Statement I: Most of the mass of the atom and all its positive charge are concentrated in a tiny nucleus and the electrons revolve around it, is Rutherford’s model. Statement II: An atom is a spherical cloud of positive charges with electrons embedded in it, is a special case of Rutherford’s model. In the light of the above statements, choose the most appropriate from the options given below.
  1. (A)Both statement I and statement II are false
  2. (B)Statement I is false but statement II is true
  3. (C)Statement I is true but statement II is false
  4. (D)Both statement I and statement II are true

Correct answer: (C)

Step-by-step solution →
Q51·PhysicsNumericalJEE Main 2024
When a hydrogen atom going from n=2n=2n=2 to n=1n=1n=1 emits a photon, its recoil speed is x5\dfrac{x}{5}5x​ m/s. Where x=x=x= ______ . (Use : mass of hydrogen atom =1.6×10−27=1.6\times10^{-27}=1.6×10−27 kg)

Correct answer: 17

Step-by-step solution →
Q52·PhysicsSingle correctJEE Main 2024
The radius of third stationary orbit of electron for Bohr’s atom is RRR. The radius of fourth stationary orbit will be:
  1. (A)43R\dfrac{4}{3}R34​R
  2. (B)169R\dfrac{16}{9}R916​R
  3. (C)34R\dfrac{3}{4}R43​R
  4. (D)916R\dfrac{9}{16}R169​R

Correct answer: (B)

Step-by-step solution →
Q53·PhysicsNumericalJEE Main 2024
If Rydberg's constant is R, the longest wavelength of radiation in Paschen series will be α7R\dfrac{\alpha}{7R}7Rα​, where α\alphaα is ________.

Correct answer: 144.00

Step-by-step solution →
Q54·PhysicsNumericalJEE Advanced 2023
A Hydrogen-like atom has atomic number Z. Photons emitted in the electronic transitions from level n = 4 to level n = 3 in these atoms are used to perform photoelectric effect experiment on a target metal. The maximum kinetic energy of the photoelectrons generated is 1. 95 eV. If the photoelectric threshold wavelength for the target metal is 310 nm, the value of Z is ________. [Given: hc = 1240 eV-nm and Rhc = 13.6 eV, where R is the Rydberg constant, h is the Planck's constant and c is the speed of light in vacuum]

Correct answer: 3

Step-by-step solution →
Q55·PhysicsNumericalJEE Main 2023
As per given figure A, B and C are the first, second and third excited energy level of hydrogen atom respectively. If the ratio of the two wavelengths (i.e. λ1λ2\frac{\lambda_1}{\lambda_2}λ2​λ1​​) is 74n\frac{7}{4n}4n7​, then the value of n will be __________.

Correct answer: 5

Step-by-step solution →
Q56·PhysicsNumericalJEE Main 2023
An electron in a hydrogen atom revolves around its nucleus with a speed of 6.76×1066.76 \times 10^66.76×106 ms−1^{-1}−1 in an orbit of radius 0.520.520.52 A∘^\circ∘. The magnetic field produced at the nucleus of the hydrogen atom is __________ T.

Correct answer: 40

Step-by-step solution →
Q57·PhysicsNumericalJEE Main 2023
An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 600 nm. The net energy absorbed by the atom in this process is n×10−4n \times 10^{-4}n×10−4 eV. The value of n is ____. [Assume the atom to be stationary during the absorption and emission process] (Take h=6.6×10−34h = 6.6 \times 10^{-34}h=6.6×10−34 Js and c=3×108c = 3 \times 10^8c=3×108 m/s)

Correct answer: 4125

Step-by-step solution →
Q58·PhysicsNumericalJEE Main 2023
The radius of 2nd2^{nd}2nd orbit of He+He^{+}He+ of Bohr's model is r1r_{1}r1​ and that of fourth orbit of Be+3Be^{+3}Be+3 is represented as r2r_{2}r2​. Now the ratio r2r1\dfrac{r_{2}}{r_{1}}r1​r2​​ is x:1x:1x:1. The value of xxx is _____.

Correct answer: 2

Step-by-step solution →
Q59·PhysicsSingle correctJEE Main 2023
A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. The number of spectral lines emitted will be:
  1. (A)2
  2. (B)1
  3. (C)3
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q60·PhysicsNumericalJEE Main 2023
A monochromatic light is incident on a hydrogen sample in ground state. Hydrogen atoms absorb a fraction of light and subsequently emit radiation of six different wavelengths. The frequency of incident light is x×1015x \times 10^{15}x×1015 Hz. The value of x is ________. (Given h=4.25×10−15h = 4.25 \times 10^{-15}h=4.25×10−15 eVs)

Correct answer: 3

Step-by-step solution →
Q61·PhysicsSingle correctJEE Main 2023
The energy of the He+^++ ion in the first excited state is (the ground state energy for the hydrogen atom is −13.6-13.6−13.6 eV):
  1. (A)−3.4-3.4−3.4 eV
  2. (B)−54.4-54.4−54.4 eV
  3. (C)−13.6-13.6−13.6 eV
  4. (D)−27.2-27.2−27.2 eV

Correct answer: (C)

Step-by-step solution →
Q62·PhysicsNumericalJEE Main 2023
If 917917917 Å is the lowest wavelength of the Lyman series, then the lowest wavelength of the Balmer series will be _______ Å.

Correct answer: 3668

Step-by-step solution →
Q63·PhysicsSingle correctJEE Main 2023
The angular momentum for the electron in Bohr's orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be:
  1. (A)L2\dfrac{L}{2}2L​
  2. (B)zero
  3. (C)L
  4. (D)2L

Correct answer: (C)

Step-by-step solution →
Q64·PhysicsNumericalJEE Main 2023
The ratio of the wavelengths of the spectral lines HαH_\alphaHα​ and HβH_\betaHβ​ in the Balmer series is x20\dfrac{x}{20}20x​. The value of x is ____.

Correct answer: 27

Step-by-step solution →
Q65·PhysicsSingle correctJEE Main 2023
A small particle of mass mmm moves in such a way that its potential energy U=12mω2r2U = \dfrac{1}{2}m\omega^2 r^2U=21​mω2r2 where ω\omegaω is constant and rrr is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of nthn^{th}nth orbit will be proportional to:
  1. (A)n\sqrt{n}n​
  2. (B)nnn
  3. (C)n2n^2n2
  4. (D)1n\dfrac{1}{n}n1​

Correct answer: (A)

Step-by-step solution →
Q66·PhysicsSingle correctJEE Main 2023
The energy levels of an hydrogen atom are shown below. The transition corresponding to emission of shortest wavelength is:
  1. (A)C
  2. (B)D
  3. (C)B
  4. (D)A

Correct answer: (B)

Step-by-step solution →
Q67·PhysicsNumericalJEE Main 2023
The radius of the fifth orbit of the Li++Li^{++}Li++ is _____ ×10−12 m\times10^{-12}\,m×10−12m. (radius of hydrogen atom =0.51 A˚=0.51\,\mathring{A}=0.51A˚)

Correct answer: 425

Step-by-step solution →
Q68·PhysicsNumericalJEE Main 2023
Experimentally it is found that 12.8 eV energy is required to separate a hydrogen atom into a proton and an electron. The orbital radius of the electron in a hydrogen atom is 9x×10−10\dfrac{9}{x}\times10^{-10}x9​×10−10 m. The value of xxx is (14πε0=9×109\dfrac{1}{4\pi\varepsilon_0}=9\times10^94πε0​1​=9×109 Nm2^22/C2^22 and electronic charge =1.6×10−19=1.6\times10^{-19}=1.6×10−19 C)

Correct answer: 16

Step-by-step solution →
Q69·PhysicsNumericalJEE Main 2023
A light of energy 12.7512.7512.75 eV is incident on a hydrogen atom in its ground state. The atom absorbs the radiation and reaches to one of its excited states. The angular momentum of the atom in the excited state is xπ×10−17\tfrac{x}{\pi}\times10^{-17}πx​×10−17 eVs. The value of xxx is _______ (use h=4.14×10−15h=4.14\times10^{-15}h=4.14×10−15 eVs, c=3×108c=3\times10^8c=3×108 ms−1^{-1}−1).

Correct answer: 828

Step-by-step solution →
Q70·PhysicsSingle correctJEE Main 2023
An electron of a hydrogen like atom, having Z=4Z=4Z=4, jumps from 4th4^{th}4th energy state to 2nd2^{nd}2nd energy state. The energy released in this process, will be: (Given Rch=13.6Rch=13.6Rch=13.6 eV) where RRR = Rydberg constant, ccc = Speed of light in vacuum, hhh = Planck's constant
  1. (A)40.8 eV40.8\,eV40.8eV
  2. (B)3.4 eV3.4\,eV3.4eV
  3. (C)10.5 eV10.5\,eV10.5eV
  4. (D)13.6 eV13.6\,eV13.6eV

Correct answer: (A)

Step-by-step solution →
Q71·PhysicsSingle correctJEE Main 2023
The radius of electron's second stationary orbit in Bohr's atom is R. The radius of 3rd orbit will be
  1. (A)R3\dfrac{R}{3}3R​
  2. (B)3R3R3R
  3. (C)2.25R2.25R2.25R
  4. (D)9R9R9R

Correct answer: (C)

Step-by-step solution →
Q72·PhysicsNumericalJEE Main 2023
For hydrogen atom, λ1\lambda_1λ1​ and λ2\lambda_2λ2​ are the wavelengths corresponding to the transitions 1 and 2 respectively as shown in figure. The ratio of λ1\lambda_1λ1​ and λ2\lambda_2λ2​ is x32\frac{x}{32}32x​. The value of xxx is __________.

Correct answer: 27

Step-by-step solution →
Q73·PhysicsNumericalJEE Main 2023
If the binding energy of ground state electron in a hydrogen atom is 13.613.613.6 eV, then, the energy required to remove the electron from the second excited state of Li2+Li^{2+}Li2+ will be x×10−1x\times10^{-1}x×10−1 eV. The value of xxx is _________.

Correct answer: 136

Step-by-step solution →
Q74·PhysicsSingle correctJEE Main 2023
Speed of an electron in Bohr's 7th7^{th}7th orbit for Hydrogen atom is 3.6×1063.6\times10^63.6×106 m/s. The corresponding speed of the electron in 3rd3^{rd}3rd orbit, in m/s is:
  1. (A)1.8×1061.8\times10^61.8×106
  2. (B)3.6×1063.6\times10^63.6×106
  3. (C)7.5×1067.5\times10^67.5×106
  4. (D)8.4×1068.4\times10^68.4×106

Correct answer: (D)

Step-by-step solution →
Q75·PhysicsSingle correctJEE Main 2023
The energy levels of an atom is shown in figure. Which one of these transitions will result in the emission of a photon of wavelength 124.1124.1124.1 nm? Given h=6.62×10−34h = 6.62\times10^{-34}h=6.62×10−34 Js.
  1. (A)D
  2. (B)B
  3. (C)C
  4. (D)A

Correct answer: (A)

Step-by-step solution →
Q76·PhysicsNumericalJEE Main 2023
The wavelength of the radiation emitted is λ0\lambda_0λ0​ when an electron jumps from the second excited state to the first excited state of a hydrogen atom. If the electron jumps from the third excited state to the second excited state of the hydrogen atom, the wavelength of the radiation emitted will be 20xλ0\dfrac{20}{x}\lambda_0x20​λ0​. The value of xxx is _______.

Correct answer: 7

Step-by-step solution →
Q77·PhysicsSingle correctJEE Main 2023
A photon is emitted in transition from n=4n=4n=4 to n=1n=1n=1 level in hydrogen atom. The corresponding wavelength for this transition is (given, h=4×10−15h=4\times10^{-15}h=4×10−15 eVs):
  1. (A)99.399.399.3 nm
  2. (B)941941941 nm
  3. (C)974974974 nm
  4. (D)94.194.194.1 nm

Correct answer: (D)

Step-by-step solution →
Q78·PhysicsSingle correctJEE Main 2022
Find the ratio of energies of photons produced due to transition of an election of hydrogen atom from its(i) second permitted energy level to the first level, and (ii) the highest permitted energy level to the first permitted level.
  1. (A)3 : 4
  2. (B)4 : 3
  3. (C)1 : 4
  4. (D)4 : 1

Correct answer: (A)

Step-by-step solution →
Q79·PhysicsNumericalJEE Main 2022
In a hydrogen spectrum ,λ be the wavelength of first transition line of Lyman series. The wavelength difference will be "aλ" between the wavelength of 3rd^{rd}rd transition line of Paschen series and that of 2nd^{nd}nd transition line of Balmer Series where a = ________

Correct answer: 5

Step-by-step solution →
Q80·PhysicsSingle correctJEE Main 2022
The momentum of an electron revolving in nthn^{th}nth orbit is given by : (Symbols have their usual meanings)
  1. (A)nh2πr\frac{nh}{2\pi r}2πrnh​
  2. (B)nh2r\frac{nh}{2r}2rnh​
  3. (C)nh2π\frac{nh}{2\pi}2πnh​
  4. (D)2πrnh\frac{2\pi r}{nh}nh2πr​

Correct answer: (A)

Step-by-step solution →
Q81·PhysicsNumericalJEE Main 2022
d1\sqrt{d_1}d1​​ and d2\sqrt{d_2}d2​​ are the impact parameters corresponding to scattering angles 60° and 90° respectively, when an α particle is approaching a gold nucleus. For d1=x d2d_1 = x\, d_2d1​=xd2​, the value of x will be________.

Correct answer: 3

Step-by-step solution →
Q82·PhysicsSingle correctJEE Main 2022
Given below are two statements: Statement I : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E1)(E_{1})(E1​) to higher energy orbit (E2)(E_{2})(E2​), is given as hf=E1−E2hf = E_{1} - E_{2}hf=E1​−E2​. Statement-II : The jumping of electron from higher energy orbit (E2)(E_{2})(E2​) to lower energy orbit (E1)(E_{1})(E1​) is associated with frequency of radiation given as f=(E2−E1)/hf = (E_{2} - E_{1})/hf=(E2​−E1​)/h This condition is Bohr's frequency condition. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both statement I and statement II are true.
  2. (B)Both statement I and statement II are false
  3. (C)Statement I is correct but statement II is false
  4. (D)Statement I is incorrect but statement II is true.

Correct answer: (D)

Step-by-step solution →
Q83·PhysicsNumericalJEE Main 2022
A beam of monochromatic light is used to excite the electron in Li++Li^{++}Li++ from the first orbit to the third orbit. The wavelength of monochromatic light is found to be x×10−10mx \times 10^{-10} mx×10−10m . The value of x is _______ . [Given hc = 1242 eV nm]

Correct answer: 114

Step-by-step solution →
Q84·PhysicsSingle correctJEE Main 2022
A hydrogen atom in is ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of : (Given, Plank's constant =6.6×10−34= 6.6 \times 10^{-34}=6.6×10−34 Js)
  1. (A)2.10×10−34 Js2.10 \times 10^{-34}\ Js2.10×10−34 Js
  2. (B)1.05×10−34 Js1.05 \times 10^{-34}\ Js1.05×10−34 Js
  3. (C)3.15×10−34 Js3.15 \times 10^{-34}\ Js3.15×10−34 Js
  4. (D)4.2×10−34 Js4.2 \times 10^{-34}\ Js4.2×10−34 Js

Correct answer: (B)

Step-by-step solution →
Q85·PhysicsSingle correctJEE Main 2022
The ratio for the speed of the electron in the 3rd orbit of He+^{+}+ to the speed of the electron in the 3rd orbit of hydrogen atom will be :-
  1. (A)1 : 1
  2. (B)1 : 2
  3. (C)4 : 1
  4. (D)2 : 1

Correct answer: (D)

Step-by-step solution →
Q86·PhysicsSingle correctJEE Main 2022
Choose the correct option from the following options given below :
  1. (A)In the ground state of Rutherford's model electrons are in stable equilibrium. While in Thomson's model electrons always experience a net-force.
  2. (B)An atom has a nearly continuous mass distribution in a Rutherford's model but has a highly non-uniform mass distribution in Thomson's model
  3. (C)A classical atom based on Rutherford's model is doomed to collapse.
  4. (D)The positively charged part of the atom possesses most of the mass in Rutherford's model but not in Thomson's model.

Correct answer: (C)

Step-by-step solution →
Q87·PhysicsSingle correctJEE Main 2022
In Bohr's atomic model of hydrogen, let K. P and E are the kinetic energy, potential energy and total energy of the electron respectively. Choose the correct option when the electron undergoes transitions to a higher level :
  1. (A)All K. P and E increase.
  2. (B)K decreases. P and E increase.
  3. (C)P decreases. K and E increase.
  4. (D)K increases. P and E decrease.

Correct answer: (B)

Step-by-step solution →
Q88·PhysicsMultiple correctJEE Advanced 2021
Which of the following statement(s) is(are) correct about the spectrum of hydrogen atom ?
  1. (A)The ratio of the longest wavelength to the shortest wavelength in Balmer series is 9/5
  2. (B)There is an overlap between the wavelength ranges of Balmer and Paschen series.
  3. (C)The wavelengths of Lyman series are given by (1+1m2)λ0\left(1 + \frac{1}{m^2}\right)\lambda_0(1+m21​)λ0​ , where λ0\lambda_0λ0​ is the shortest wavelength of Lyman series and m is an integer
  4. (D)The wavelength ranges of Lyman and Balmer series do not overlap

Correct answer: (A), (D)

Step-by-step solution →
Q89·PhysicsSingle correctJEE Main 2021
A free electron of 2.6 eV energy collides with a H+^++ ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon. (h=6.6×10−34(h = 6.6 \times 10^{-34}(h=6.6×10−34 Js)))
  1. (A)1.45×10161.45 \times 10^{16}1.45×1016 MHz
  2. (B)0.19×10150.19 \times 10^{15}0.19×1015 MHz
  3. (C)1.45×1091.45 \times 10^{9}1.45×109 MHz
  4. (D)9.0×10279.0 \times 10^{27}9.0×1027 MHz

Correct answer: (C)

Step-by-step solution →
Q90·PhysicsNumericalJEE Main 2021
X different wavelengths may be observed in the spectrum from a hydrogen sample if the atoms are exited to states with principal quantum number n = 6 ? The value of X is ________ .

Correct answer: 15

Step-by-step solution →
Q91·PhysicsSingle correctJEE Main 2021
A particular hydrogen like ion emits radiation of frequency 2.92 ×\times× 101510^{15}1015 Hz when it makes transition from n = 3 to n = 1. The frequency in Hz of radiation emitted in transition from n = 2 to n = 1 will be :
  1. (A)0.44 ×\times× 101510^{15}1015
  2. (B)6.57 ×\times× 101510^{15}1015
  3. (C)4.38 ×\times× 101510^{15}1015
  4. (D)2.46 ×\times× 101510^{15}1015

Correct answer: (D)

Step-by-step solution →
Q92·PhysicsNumericalJEE Main 2021
In Bohr's atomic model, the electron is assumed to revolve in a circular orbit of radius 0.5 Å. If the speed of electron is 2.2×10610^{6}106 m /s, then the current associated with the electron will be ____ × 10−210^{-2}10−2 mA. [ Take π as 227\frac{22}{7}722​ ]

Correct answer: 112

Step-by-step solution →
Q93·PhysicsNumericalJEE Main 2021
The Kα_\alphaα​ - X ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atom with a K electron knocked out is 27.5 ke V, the energy of this atom when an L electron is knocked out will be ________ ke V. (Round off to the nearest integer) [ h = 4.14×10−15^{-15}−15 eVs,c = 3×108^88 ms−1^{-1}−1 ]

Correct answer: 10

Step-by-step solution →
Q94·PhysicsSingle correctJEE Main 2021
Imagine that the electron in a hydrogen atom is replaced by a muon (µ). The mass of muon particle is 207 times that of an electron and charge is equal to the charge of an electron. The ionization potential of this hydrogen atom will be :-
  1. (A)13.6 eV
  2. (B)2815.2 eV
  3. (C)331.2 eV
  4. (D)27.2 eV

Correct answer: (B)

Step-by-step solution →
Q95·PhysicsNumericalJEE Main 2021
A particle of mass m moves in a circular orbit in a central potential field U(r) = U0_{0}0​r4^{4}4 . If Bohr's quantization conditions are applied, radii of possible orbitals rn_{n}n​ vary with n1/α^{1/\alpha}1/α , where α is___________.

Correct answer: 3

Step-by-step solution →
Q96·PhysicsSingle correctJEE Main 2021
Which level of the single ionized carbon has the same energy as the ground state energy of hydrogen atom?
  1. (A)1
  2. (B)6
  3. (C)4
  4. (D)8

Correct answer: (B)

Step-by-step solution →
Q97·PhysicsSingle correctJEE Main 2021
If an electron is moving in the nthn^{th}nth orbit of the hydrogen atom, then its velocity (vn)(v_n)(vn​) for the nthn^{th}nth orbit is given as :
  1. (A)vn∝nv_n \propto nvn​∝n
  2. (B)vn∝1nv_n \propto \frac{1}{n}vn​∝n1​
  3. (C)vn∝n2v_n \propto n^2vn​∝n2
  4. (D)vn∝1n2v_n \propto \frac{1}{n^2}vn​∝n21​

Correct answer: (B)

Step-by-step solution →
Q98·PhysicsSingle correctJEE Main 2021
The atomic hydrogen emits a line spectrum consisting of various series.Which series of hydrogen atomic spectra is lying in the visible region ?
  1. (A)Brackett series
  2. (B)Paschen series
  3. (C)Lyman series
  4. (D)Balmer series

Correct answer: (D)

Step-by-step solution →
Q99·PhysicsNumericalJEE Main 2021
The first three spectral lines of H-atom in the Balmer series are given λ1_{1}1​, λ2_{2}2​, λ3_{3}3​ considering the Bohr atomic model, the wave lengths of first and third spectral lines (λ1λ3)\left(\dfrac{\lambda_{1}}{\lambda_{3}}\right)(λ3​λ1​​) are related by a factor of approximately 'x' × 10−1^{-1}−1. The value of x, to the nearest integer, is ________.

Correct answer: 15

Step-by-step solution →
Q100·PhysicsSingle correctJEE Main 2021
The recoil speed of a hydrogen atom after it emits a photon in going from n = 5 state to n = 1 state will be:
  1. (A)4.17 m/s
  2. (B)4.34 m/s
  3. (C)219 m/s
  4. (D)3.25 m/s

Correct answer: (A)

Step-by-step solution →
Q101·PhysicsSingle correctJEE Main 2021
If λ1_11​ and λ2_22​ are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of λ1_11​ : λ2_22​ is :
  1. (A)1 : 3
  2. (B)1 : 9
  3. (C)7 : 135
  4. (D)7 : 108

Correct answer: (C)

Step-by-step solution →
Q102·PhysicsSingle correctJEE Main 2021
The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n = 2 to n = 1 state is:
  1. (A)194.8 nm
  2. (B)490.7 nm
  3. (C)913.3 nm
  4. (D)121.8 nm

Correct answer: (D)

Step-by-step solution →
Q103·PhysicsSingle correctJEE Main 2021
In the given figure, the energy levels of hydrogen atom have been shown along with some transitions marked A,B,C,D and E. The transitions A,B and C respectively represents –
  1. (A)The series limit of Lyman series, third member of balmer series and second member of paschen series
  2. (B)The first member of the Lyman series, third member of Balmer series and second member of paschen series
  3. (C)The ionization potential of hydrogen, second member of Balmer series and third member of Paschen series
  4. (D)The series limit of Lyman series, second memebr of Balmer series and second member of Paschen series.

Correct answer: (A)

Step-by-step solution →
Q104·PhysicsSingle correctJEE Main 2021
According to Bohr atom model, in which of the following transitions will the frequency be maximum?
  1. (A)n=2 to n=1
  2. (B)n=4 to n =3
  3. (C)n=5 to n=4
  4. (D)n=3 to n=2

Correct answer: (A)

Step-by-step solution →
Q105·PhysicsMultiple correctJEE Advanced 2020
In an X-ray tube, electrons emitted from a filament (cathode) carrying current I hit a target (anode) at a distance ddd from the cathode. The target is kept at a potential VVV higher than the cathode resulting in emission of continuous and characteristic X-rays. If the filament current III is decreased to I2\frac{I}{2}2I​, the potential difference VVV is increased to 2V2V2V, and the separation distance ddd is reduced to d2\frac{d}{2}2d​, then
  1. (A)the cut-off wavelength will reduce to half, and the wavelengths of the characteristic X-rays will remain the same
  2. (B)the cut-off wavelength as well as the wavelengths of the characteristic X-rays will remain the same
  3. (C)the cut-off wavelength will reduce to half, and the intensities of all the X-rays will decrease
  4. (D)the cut-off wavelength will become two times larger, and the intensity of all the X-rays will decrease

Correct answer: (A), (C)

Step-by-step solution →
Q106·PhysicsMultiple correctJEE Advanced 2020
A particle of mass m moves in circular orbits with potential energy V(r)=FrV(r) = FrV(r)=Fr, where F is a positive constant and r is its distance from the origin. Its energies are calculated using the Bohr model. If the radius of the particle's orbit is denoted by R and its speed and energy are denoted by v and E, respectively, then for the nthn^{th}nth orbit (here h is the Planck's constant)-
  1. (A)R∝n1/3R \propto n^{1/3}R∝n1/3 and v∝n2/3v \propto n^{2/3}v∝n2/3
  2. (B)R∝n2/3R \propto n^{2/3}R∝n2/3 and v∝n1/3v \propto n^{1/3}v∝n1/3
  3. (C)E=32(n2h2F24π2m)1/3E = \frac{3}{2}\left(\frac{n^2h^2F^2}{4\pi^2m}\right)^{1/3}E=23​(4π2mn2h2F2​)1/3
  4. (D)E=2(n2h2F24π2m)1/3E = 2\left(\frac{n^2h^2F^2}{4\pi^2m}\right)^{1/3}E=2(4π2mn2h2F2​)1/3

Correct answer: (B), (C)

Step-by-step solution →
Q107·PhysicsNumericalJEE Main 2020
A particle of mass 200 MeV/c2^22 collides with a hydrogen atom at rest. Soon after the collision the particle comes to rest, and the atom recoils and goes to its first excited state. The initial kinetic energy of the particle (in eV) is N4\dfrac{N}{4}4N​. The value of N is: (Given the mass of the hydrogen atom to be 1 GeV / c2^22).

Correct answer: 51.00

Step-by-step solution →
Q108·PhysicsSingle correctJEE Main 2020
The energy required to ionize a hydrogen like ion in its ground state is 9 Rydbergs. What is the wavelength of the radiation emitted when the electron in this ion jumps from the second excited state to the ground state?
  1. (A)11.4 nm
  2. (B)35.8 nm
  3. (C)24.2 nm
  4. (D)8.6 nm

Correct answer: (A)

Step-by-step solution →
Q109·PhysicsNumericalJEE Main 2020
The first member of the Balmer series of hydrogen atom has a wavelength of 6561 Å. The wavelength of the second member of the Balmer series (in nm) is ____.

Correct answer: 486

Step-by-step solution →
Q110·PhysicsSingle correctJEE Main 2020
The graph which depicts the results of Rutherford gold foil experiment with α-particles is θ : Scattering angle Y : Number of scattered α-particles detected (Plots are schematic and not to scale)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q111·PhysicsSingle correctJEE Main 2020
The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6×10−161.6 \times 10^{-16}1.6×10−16 s. The frequency of revolution of the electron is its first excited state (in s−1^{-1}−1) is
  1. (A)7.8×10147.8 \times 10^{14}7.8×1014
  2. (B)1.6×10141.6 \times 10^{14}1.6×1014
  3. (C)6.2×10156.2 \times 10^{15}6.2×1015
  4. (D)5.6×10125.6 \times 10^{12}5.6×1012

Correct answer: (A)

Step-by-step solution →
Q112·PhysicsMultiple correctJEE Advanced 2019
A free hydrogen atom after absorbing a photon of wavelength λa\lambda_aλa​ gets excited from the state n = 1 to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon of wavelength λe\lambda_eλe​. Let the change in momentum of atom due to the absorption and the emission are Δpa\Delta p_aΔpa​ and Δpe\Delta p_eΔpe​. respectively. If λaλe=15\frac{\lambda_a}{\lambda_e} = \frac{1}{5}λe​λa​​=51​, which of the option(s) is /are correct ? [Use hc = 1242 eV nm; 1 nm = 10−910^{-9}10−9m, h and c are Planck's constant and speed of light, respectively]
  1. (A)ΔpaΔpe=12\frac{\Delta p_a}{\Delta p_e} = \frac{1}{2}Δpe​Δpa​​=21​
  2. (B)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 14\frac{1}{4}41​
  3. (C)λe=418\lambda_e = 418λe​=418 nm
  4. (D)m = 2

Correct answer: (B), (D)

Step-by-step solution →
Q113·PhysicsSingle correctJEE Main 2019
The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ1/λ2\lambda_{1}/\lambda_{2}λ1​/λ2​, of the photons emitted in this process is :
  1. (A)20/7
  2. (B)7/5
  3. (C)9/7
  4. (D)27/5

Correct answer: (A)

Step-by-step solution →
Q114·PhysicsSingle correctJEE Main 2019
An excited He+^++ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength λ\lambdaλ, energy E=1240 eVλ(in nm)E=\dfrac{1240\ \text{eV}}{\lambda(\text{in nm})}E=λ(in nm)1240 eV​ :)
  1. (A)n = 4
  2. (B)n = 6
  3. (C)n = 5
  4. (D)n = 7

Correct answer: (C)

Step-by-step solution →
Q115·PhysicsSingle correctJEE Main 2019
Consider an electron in a hydrogen atom, revolving in its second excited state (having radius 4.65 Å). The de-Broglie wavelength of this electron is :
  1. (A)12.9 Å
  2. (B)9.7 Å
  3. (C)6.6 Å
  4. (D)3.5 Å

Correct answer: (B)

Step-by-step solution →
Q116·PhysicsSingle correctJEE Main 2019
In Li++^{++}++, electron in first Bohr orbit is excited to a level by a radiation of wavelength λ. When the ion gets deexcited to the ground state in all possible ways(including intermediate emission) a total of six spectral lines are observed. What is the value of λ? (Given: h = 6.63×10346.63 \times 10^{34}6.63×1034 js; e = 3×1083 \times 10^{8}3×108 ms−1^{-1}−1)
  1. (A)10.8 nm
  2. (B)11.4 nm
  3. (C)9.4 nm
  4. (D)12.3 nm

Correct answer: (A)

Step-by-step solution →
Q117·PhysicsSingle correctJEE Main 2019
A He+ ion is in its first excited state. Its ionization energy is:
  1. (A)6.04 eV
  2. (B)13.60 eV
  3. (C)54.40 eV
  4. (D)48.36 eV

Correct answer: (B)

Step-by-step solution →
Q118·PhysicsSingle correctJEE Main 2019
Radiation coming from transition n = 2 to n = 1 of hydrogen atoms fall of He+He^{+}He+ ions in n = 1 and n = 2 states. The possible. Transition of helium ions as they absorb energy from the radiation is:
  1. (A)n=2→n=4n=2\rightarrow n=4n=2→n=4
  2. (B)n=2→n=5n=2\rightarrow n=5n=2→n=5
  3. (C)n=2→n=3n=2\rightarrow n=3n=2→n=3
  4. (D)n=1→n=4n=1\rightarrow n=4n=1→n=4

Correct answer: (A)

Step-by-step solution →
Q119·PhysicsSingle correctJEE Main 2019
In a Frank-hertz experiment, an electron of energy 5.6 eV passes through mercury vapour and emerges with an energy 0.7 eV. The minimum wavelength of photons emitted by mercury atoms is close to :
  1. (A)1700 nm
  2. (B)2020 nm
  3. (C)220 nm
  4. (D)250 nm

Correct answer: (D)

Step-by-step solution →
Q120·PhysicsSingle correctJEE Main 2019
A particle of mass m moves in a circular orbit in a central potential field U(r)=12kr2U(r)=\dfrac{1}{2}kr^2U(r)=21​kr2. If Bohr's quantization conditions are applied, radii of possible orbits and energy levels vary with quantum number n as:
  1. (A)rn∝nr_n \propto \sqrt{n}rn​∝n​, En∝nE_n \propto nEn​∝n
  2. (B)rn∝nr_n \propto \sqrt{n}rn​∝n​, En∝1nE_n \propto \dfrac{1}{n}En​∝n1​
  3. (C)rn∝nr_n \propto nrn​∝n, En∝nE_n \propto nEn​∝n
  4. (D)rn∝n2r_n \propto n^2rn​∝n2, En∝1n2E_n \propto \dfrac{1}{n^2}En​∝n21​

Correct answer: (A)

Step-by-step solution →
Q121·PhysicsSingle correctJEE Main 2019
A hydrogen atom, initially in the ground state is excited by absorbing a photon of wavelength 980 Å. The radius of the atom in the excited state, in terms of Bohr radius a0a_0a0​, will be: (hc = 12500 eV- Å)
  1. (A)25a025a_025a0​
  2. (B)9a09a_09a0​
  3. (C)16a016a_016a0​
  4. (D)4a04a_04a0​

Correct answer: (C)

Step-by-step solution →
Q122·PhysicsSingle correctJEE Main 2019
In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell the wavelength of emitted radiation is λ\lambdaλ. If an electron jumps from N-shell to the L-shell the wavelength of emitted radiation will be:
  1. (A)2720λ\frac{27}{20}\lambda2027​λ
  2. (B)1625λ\frac{16}{25}\lambda2516​λ
  3. (C)2516λ\frac{25}{16}\lambda1625​λ
  4. (D)2027λ\frac{20}{27}\lambda2720​λ

Correct answer: (D)

Step-by-step solution →
Q123·PhysicsNumericalJEE Advanced 2018
Consider a hydrogen-like ionized atom with atomic number Z with a single electron. In the emission spectrum of this atom, the photon emitted in the n = 2 to n = 1 transition has energy 74.8 eV higher than the photon emitted in the n = 3 to n = 2 transition. The ionization energy of the hydrogen atom is 13.6 eV. The value of Z is ___________.

Correct answer: 3.00

Step-by-step solution →
Q124·PhysicsIntegerJEE Advanced 2017
An electron in a hydrogen atom undergoes a transition from an orbit with quantum numebr nin_{i}ni​ to another with quantum number nfn_{f}nf​. ViV_{i}Vi​ and VfV_{f}Vf​ are respectively the initial and final potential energies of the electon. If ViVf=6.25\frac{V_{i}}{V_{f}} = 6.25Vf​Vi​​=6.25, then the smallest possible nfn_{f}nf​ is

Correct answer: 5

Step-by-step solution →
Q125·PhysicsMultiple correctJEE Advanced 2016
Highly excited states for hydrogen-like atoms (also called Rydberg states) with nuclear charge ZeZeZe are defined by their principal quantum number nnn, where n>>1n >> 1n>>1. Which of the following statement(s) is (are) true?
  1. (A)Relative change in the radii of two consecutive orbitals does not depend on ZZZ
  2. (B)Relative change in the radii of two consecutive orbitals varies as 1/n1/n1/n
  3. (C)Relative change in the energy of two consecutive orbitals varies as 1/n31/n^{3}1/n3
  4. (D)Relative change in the angular momenta of two consecutive orbitals varies as 1/n1/n1/n

Correct answer: (A), (B), (D)

Step-by-step solution →
Q126·PhysicsIntegerJEE Advanced 2016
A hydrogen atom in its ground state is irradiated by light of wavelength 970 Å. Taking hc/e=1.237×10−6hc/e = 1.237 \times 10^{-6}hc/e=1.237×10−6 eV m and the ground state energy of hydrogen atom as −13.6 eV, the number of lines present in the emission spectrum is

Correct answer: 6

Step-by-step solution →
Q127·PhysicsIntegerJEE Advanced 2015
An electron in an excited state of Li2+\mathrm{Li^{2+}}Li2+ ion has angular momentum 3h/2π3h/2\pi3h/2π. The de Broglie wavelength of the electron in this state is pπa0p\pi a_{0}pπa0​ (where a0a_{0}a0​ is the Bohr radius). The value of ppp is

Correct answer: 2

Step-by-step solution →
Q128·PhysicsIntegerJEE Advanced 2015
Consider a hydrogen atom with its electron in the nthn^{\text{th}}nth orbital. An electromagnetic radiation of wavelength 90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of nnn is (hc = 1242 eV nm)

Correct answer: 2

Step-by-step solution →
Q129·PhysicsSingle correctJEE Advanced 2014
If λcu\lambda_{cu}λcu​ is the wavelength of KαK_{\alpha}Kα​ X-ray line of copper (atomic number 29) and λMo\lambda_{Mo}λMo​ is the wavelength of the KαK_{\alpha}Kα​ X-ray line of molybdenum (atomic number 42), then the ratio λcu/λMo\lambda_{cu}/\lambda_{Mo}λcu​/λMo​ is close to
  1. (A)1.99
  2. (B)2.14
  3. (C)0.50
  4. (D)0.48

Correct answer: (B)

Step-by-step solution →
Q130·PhysicsMultiple correctJEE Advanced 2013
The radius of the orbit of an electron in a Hydrogen-like atom is 4.5a04.5a_{0}4.5a0​ where a0a_{0}a0​ is the Bohr radius. Its orbital angular momentum is 3h2π\frac{3h}{2\pi}2π3h​. It is given that hhh is Planck's constant and RRR is Rydberg constant. The possible wavelength(s), when the atom de-excites, is (are)
  1. (A)932R\frac{9}{32R}32R9​
  2. (B)916R\frac{9}{16R}16R9​
  3. (C)95R\frac{9}{5R}5R9​
  4. (D)43R\frac{4}{3R}3R4​

Correct answer: (A), (C)

Step-by-step solution →

Atoms — frequently asked

How many questions from Atoms appear in JEE?

Atoms has appeared in 112 of the last 186 JEE Main and JEE Advanced papers — about 60% of them — contributing 130 questions in total across those papers.

Is Atoms an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 60% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Atoms questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Physics chapters

  • Properties of Solids and Liquids 344
  • Current Electricity 309
  • Rotational Motion 266
  • Geometrical Optics 259
  • Kinematics 255
  • Magnetic Field of Current 211
  • Electromagnetic Waves 208
  • Thermodynamics 201

All 28 Physics chapters →

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