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Kinetic Theory of Gases — JEE Previous Year Questions

Every Kinetic Theory of Gases question asked in JEE Main and JEE Advanced across the last 186 papers — 146 questions, each with its correct answer. Free to read, no account needed.

Questions

146

Papers it appeared in

135/186

Appearance rate

73%

All 146 Kinetic Theory of Gases questions

Most recent papers first.

Q1·PhysicsSingle correctJEE Main 2026
Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure 90 kPa and temperature 400 K. Keeping the temperature of one vessel constant at 400 K the second vessel temperature is raised to 500 K. The final pressure in the vessels is ________ kPa.
  1. (A)100
  2. (B)120
  3. (C)90
  4. (D)105

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correctJEE Main 2026
If 2 mole of an ideal monoatomic gas at temperature TTT, is mixed with 6 mole of another ideal monoatomic gas at temperature 2T2T2T then the temperature of mixture is :
  1. (A)52T\frac{5}{2}T25​T
  2. (B)54T\frac{5}{4}T45​T
  3. (C)72T\frac{7}{2}T27​T
  4. (D)74T\frac{7}{4}T47​T

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correctJEE Main 2026
An ideal gas at pressure P and temperature T is expanding such that PT³ = constant. The coefficient of volume expansion of the gas is ________.
  1. (A)2T\dfrac{2}{T}T2​
  2. (B)1T\dfrac{1}{T}T1​
  3. (C)4T\dfrac{4}{T}T4​
  4. (D)3T\dfrac{3}{T}T3​

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correctJEE Main 2026
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: If the average kinetic energy of H2H_{2}H2​ and O2O_{2}O2​ molecules, kept in two different sized containers are same, then their temperatures will be same. Reason R: The r.m.s. speed of H2H_{2}H2​ and O2O_{2}O2​ molecules are same at same temperature. Choose the correct answer from the options given below
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correctJEE Main 2026
One gas of n1n_1n1​ mole of molecules at temperature T1T_1T1​, volume V1V_1V1​, and pressure P1P_1P1​, and another gas of n2n_2n2​ mole of molecules at temperature T2T_2T2​, volume V2V_2V2​, and pressure P2P_2P2​, are mixed resulting in pressure PPP and volume VVV of the mixture. The temperature of the mixture is _____.
  1. (A)(T1+T2)/2(T_1 + T_2)/2(T1​+T2​)/2
  2. (B)T1T2PV/(T2P1V1+T1P2V2)T_1T_2PV/(T_2P_1V_1 + T_1P_2V_2)T1​T2​PV/(T2​P1​V1​+T1​P2​V2​)
  3. (C)(T2P1V1+T1P2V2)/(T1T2PV)(T_2P_1V_1 + T_1P_2V_2)/(T_1T_2PV)(T2​P1​V1​+T1​P2​V2​)/(T1​T2​PV)
  4. (D)∣T1−T2∣/2|T_1 - T_2|/2∣T1​−T2​∣/2

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correctJEE Main 2026
A mixture of carbon dioxide and oxygen has volume 8310 cm3^{3}3, temperature 300 K, pressure 100 kPa and mass 13.2 g. The number of moles of carbon dioxide and oxygen gases in the mixture respectively are ______. (Assume both carbon dioxide and oxygen gases behave like ideal gases) [R=8.31[R = 8.31[R=8.31 J/mol.K]]]
  1. (A)0.15 and 0.18
  2. (B)0.25 and 0.08
  3. (C)0.21 and 0.12
  4. (D)0.13 and 0.20

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correctJEE Main 2026
The mean free path of a molecule of diameter 5×10−105 \times 10^{-10}5×10−10 m at the temperature 41°C and pressure 1.38×1051.38 \times 10^{5}1.38×105 Pa, is given as ____m. (Given kB=1.38×10−23k_{B} = 1.38 \times 10^{-23}kB​=1.38×10−23 J/K).
  1. (A)22×10−102\sqrt{2} \times 10^{-10}22​×10−10
  2. (B)102×10−810\sqrt{2} \times 10^{-8}102​×10−8
  3. (C)22×10−82\sqrt{2} \times 10^{-8}22​×10−8
  4. (D)2×10−82 \times 10^{-8}2×10−8

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correctJEE Main 2026
An air bubble of volume 2.9 cm3^{3}3 rises from the bottom of a swimming pool of 5 m deep. At the bottom of the pool water temperature is 17 °C. The volume of the bubble when it reaches the surface, where the water temperature is 27 °C, is____ cm3^{3}3. (g = 10 m/s2^{2}2, density of water = 10310^{3}103 kg/m3^{3}3, and 1 atm pressure is 10510^{5}105 Pa)
  1. (A)4.2
  2. (B)2.0
  3. (C)3.0
  4. (D)4.5

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correctJEE Main 2026
A cylindrical tube ABABAB of length lll, closed at both ends contains an ideal gas of 1 mol having molecular weight MMM. The tube is rotated in a horizontal plane with constant angular velocity ω\omegaω about an axis perpendicular to ABABAB and passing through the edge at end A, as shown in the figure. If PAP_{A}PA​ and PBP_{B}PB​ are the pressures at AAA and BBB respectively, then (Consider the temperature is same at all points in the tube)
  1. (A)PB=PAexp⁡(Mω2l2/2RT)P_{B} = P_{A} \exp (M\omega^{2}l^{2} / 2RT)PB​=PA​exp(Mω2l2/2RT)
  2. (B)PB=PAP_{B} = P_{A}PB​=PA​
  3. (C)PB=PAexp⁡(Mω2l2/3RT)P_{B} = P_{A} \exp (M\omega^{2}l^{2} / 3RT)PB​=PA​exp(Mω2l2/3RT)
  4. (D)PB=PAexp⁡(Mω2l2/RT)P_{B} = P_{A} \exp (M\omega^{2}l^{2} / RT)PB​=PA​exp(Mω2l2/RT)

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsNumericalJEE Main 2026
An insulated cylinder of volume 60 cm3^33 is filled with a gas at 27°C and 2 atmospheric pressure. Then the gas is compressed making the final volume as 20 cm3^33 while allowing the temperature to rise to 77°C. The final pressure is ________ atmospheric pressure.

Correct answer: 7

Step-by-step solution →
Q11·PhysicsSingle correctJEE Main 2026
The r.m.s speed of oxygen molecules at 47∘47^\circ47∘C is equal to that of the hydrogen molecules kept at______∘^\circ∘C. (Mass of oxygen molecule/mass of hydrogen molecule=32/2)
  1. (A)−235
  2. (B)−100
  3. (C)−253
  4. (D)−20

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsNumericalJEE Advanced 2025
The left and right compartments of a thermally isolated container of length L are separated by a thermally conducting, movable piston of area A. The left and right compartments are filled with 32\frac{3}{2}23​ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant k and natural length 2L5\frac{2L}{5}52L​. In thermodynamic equilibrium, the piston is at a distance L2\frac{L}{2}2L​ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is P=kLAαP = \frac{kL}{A}\alphaP=AkL​α, then the value of α\alphaα is ____

Correct answer: 0.20

Step-by-step solution →
Q13·PhysicsSingle correctJEE Main 2025
The helium and argon are put in the flask at the same room temperature (300 K). The ratio of average kinetic energies (per molecule) of helium and argon is: (Given: Molar mass of helium = 4 g/mol, Molar mass of argon = 40 g/mol)
  1. (A)1 : 10
  2. (B)10 : 1
  3. (C)1:101:\sqrt{10}1:10​
  4. (D)1 : 1

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correctJEE Main 2025
Match the List-I (type of gas) with List-II (ratio of specific heats CPCV\dfrac{C_P}{C_V}CV​CP​​). Choose the correct answer from the options given below:
List-I (Type of gas)List-II ($C_P/C_V$)
A.Triatomic rigid gasI.CPCV=53\dfrac{C_P}{C_V}=\dfrac{5}{3}CV​CP​​=35​
B.Diatomic non-rigid gasII.CPCV=75\dfrac{C_P}{C_V}=\dfrac{7}{5}CV​CP​​=57​
C.Monoatomic gasIII.CPCV=43\dfrac{C_P}{C_V}=\dfrac{4}{3}CV​CP​​=34​
D.Diatomic rigid gasIV.CPCV=97\dfrac{C_P}{C_V}=\dfrac{9}{7}CV​CP​​=79​
  1. (A)A-III, B-IV, C-I, D-II
  2. (B)A-III, B-II, C-IV, D-I
  3. (C)A-II, B-IV, C-I, D-III
  4. (D)A-IV, B-II, C-III, D-I

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correctJEE Main 2025
There are two vessels filled with an ideal gas where volume of one is double the volume of other. The large vessel contains the gas at 8 kPa at 1000 K while the smaller vessel contains the gas at 7 kPa at 500 K. If the vessels are connected to each other by a thin tube allowing the gas to flow and the temperature of both vessels is maintained at 600 K, at steady state the pressure in the vessels will be (in kPa):
  1. (A)4.4
  2. (B)6
  3. (C)24
  4. (D)18

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correctJEE Main 2025
The mean free path and the average speed of oxygen molecules at 300 K and 1 atm are 3×10−73\times10^{-7}3×10−7 m and 600 m/s, respectively. Find the frequency of its collisions.
  1. (A)2×10102\times10^{10}2×1010/s
  2. (B)9×1099\times10^{9}9×109/s
  3. (C)2×1092\times10^{9}2×109/s
  4. (D)5×1095\times10^{9}5×109/s

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correctJEE Main 2025
Pressure of an ideal gas, contained in a closed vessel, is increased by 0.4% when heated by 1∘1^\circ1∘C. Its initial temperature must be:
  1. (A)25∘25^\circ25∘C
  2. (B)2500 K
  3. (C)250 K
  4. (D)250∘250^\circ250∘C

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsIntegerJEE Main 2025
The internal energy of air in a 4 m×4 m×3 m4\,m\times4\,m\times3\,m4m×4m×3m sized room at 1 atmospheric pressure will be ______ ×106 J\times10^6\,J×106J. (Consider air as a diatomic molecule)

Correct answer: 12

Step-by-step solution →
Q19·PhysicsIntegerJEE Main 2025
γA\gamma_AγA​ is the specific heat ratio of monoatomic gas A having 3 translational degrees of freedom. γB\gamma_BγB​ is the specific heat ratio of polyatomic gas B having 3 translational, 3 rotational degrees of freedom and 1 vibrational mode. If γAγB=(1+1n)\dfrac{\gamma_A}{\gamma_B}=\left(1+\dfrac{1}{n}\right)γB​γA​​=(1+n1​), then the value of nnn is ______.

Correct answer: 3

Step-by-step solution →
Q20·PhysicsIntegerJEE Main 2025
A container of fixed volume contains a gas at 27∘27^\circ27∘C. To double the pressure of the gas, the temperature of gas should be raised to ______ ∘^\circ∘C.

Correct answer: 327

Step-by-step solution →
Q21·PhysicsSingle correctJEE Main 2025
The kinetic energy of translation of the molecules in 50 g of CO2_22​ gas at 17∘17^\circ17∘C is:
  1. (A)3986.3 J
  2. (B)4102.8 J
  3. (C)4205.5 J
  4. (D)3582.7 J

Correct answer: (B)

Step-by-step solution →
Q22·PhysicsSingle correctJEE Main 2025
For a particular ideal gas which of the following graphs represents the variation of mean squared velocity of the gas molecules with temperature?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q23·PhysicsSingle correctJEE Main 2025
The ratio of vapour densities of two gases at the same temperature is 425\frac{4}{25}254​, then the ratio of r.m.s. velocities will be:
  1. (A)254\frac{25}{4}425​
  2. (B)25\frac{2}{5}52​
  3. (C)52\frac{5}{2}25​
  4. (D)425\frac{4}{25}254​

Correct answer: (C)

Step-by-step solution →
Q24·PhysicsIntegerJEE Main 2025
The temperature of 1 mole of an ideal monoatomic gas is increased by 50°C at constant pressure. The total heat added and change in internal energy are E1E_1E1​ and E2E_2E2​, respectively. If E1E2=x9\dfrac{E_1}{E_2}=\dfrac{x}{9}E2​E1​​=9x​ then the value of x is _______.

Correct answer: 15

Step-by-step solution →
Q25·PhysicsSingle correctJEE Main 2025
For a diatomic gas, if γ1=(CpCv)\gamma_1=\left(\frac{C_p}{C_v}\right)γ1​=(Cv​Cp​​) for rigid molecules and γ2=(CpCv)\gamma_2=\left(\frac{C_p}{C_v}\right)γ2​=(Cv​Cp​​) for another diatomic molecules, but also having vibrational modes. Then, which one of the following options is correct? (CpC_pCp​ and CvC_vCv​ are specific heats of the gas at constant pressure and volume)
  1. (A)γ2>γ1\gamma_2>\gamma_1γ2​>γ1​
  2. (B)γ2=γ1\gamma_2=\gamma_1γ2​=γ1​
  3. (C)2γ2=γ12\gamma_2=\gamma_12γ2​=γ1​
  4. (D)γ2<γ1\gamma_2<\gamma_1γ2​<γ1​

Correct answer: (D)

Step-by-step solution →
Q26·PhysicsSingle correctJEE Main 2024
The temperature of a gas is −78 ∘-78\,^{\circ}−78∘C and the average translational kinetic energy of its molecules is K. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes 2K is:
  1. (A)−39 ∘-39\,^{\circ}−39∘C
  2. (B)117 ∘117\,^{\circ}117∘C
  3. (C)127 ∘127\,^{\circ}127∘C
  4. (D)−78 ∘-78\,^{\circ}−78∘C

Correct answer: (B)

Step-by-step solution →
Q27·PhysicsSingle correctJEE Main 2024
A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature (27∘C27^\circ C27∘C). The ratio of specific heat of gases at constant volume respectively is:
  1. (A)75\dfrac7557​
  2. (B)32\dfrac3223​
  3. (C)35\dfrac3553​
  4. (D)53\dfrac5335​

Correct answer: (C)

Step-by-step solution →
Q28·PhysicsSingle correctJEE Main 2024
Given below are two statements: Statement (I): The mean free path of gas molecules is inversely proportional to square of molecular diameter. Statement (II): Average kinetic energy of gas molecules is directly proportional to absolute temperature of gas. In the light of the above statements, choose the correct answer from the option given below:
  1. (A)Statement I is false but Statement II is true.
  2. (B)Statement I is true but Statement II is false.
  3. (C)Both Statement I and Statement II are false
  4. (D)Both Statement I and Statement II are true.

Correct answer: (D)

Step-by-step solution →
Q29·PhysicsSingle correctJEE Main 2024
A sample contains a mixture of helium and oxygen gas. The ratio of the root mean square speed of helium to that of oxygen in the sample is:
  1. (A)132\tfrac{1}{\sqrt{32}}32​1​
  2. (B)222\sqrt{2}22​
  3. (C)14\tfrac{1}{4}41​
  4. (D)122\tfrac{1}{2\sqrt{2}}22​1​

Correct answer: (B)

Step-by-step solution →
Q30·PhysicsSingle correctJEE Main 2024
Energy of 10 non rigid diatomic molecules at temperature T is :
  1. (A)72\frac{7}{2}27​ RT
  2. (B)70KBT70 K_B T70KB​T
  3. (C)35 RT
  4. (D)35KBT35 K_B T35KB​T

Correct answer: (D)

Step-by-step solution →
Q31·PhysicsSingle correctJEE Main 2024
If the collision frequency of hydrogen molecules in a closed chamber at 27∘C27^{\circ}\text{C}27∘C is ZZZ, then the collision frequency of the same system at 127∘C127^{\circ}\text{C}127∘C is:
  1. (A)32Z\dfrac{\sqrt{3}}{2}Z23​​Z
  2. (B)43Z\dfrac{4}{3}Z34​Z
  3. (C)23Z\dfrac{2}{\sqrt{3}}Z3​2​Z
  4. (D)34Z\dfrac{3}{4}Z43​Z

Correct answer: (C)

Step-by-step solution →
Q32·PhysicsSingle correctJEE Main 2024
If nnn is the number density and ddd is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by:
  1. (A)12nπd2\dfrac{1}{\sqrt{2n\pi d^2}}2nπd2​1​
  2. (B)2 nπd2\sqrt{2}\,n\pi d^22​nπd2
  3. (C)12 nπd2\dfrac{1}{\sqrt{2}\,n\pi d^2}2​nπd21​
  4. (D)12 n2π2d2\dfrac{1}{\sqrt{2}\,n^2\pi^2 d^2}2​n2π2d21​

Correct answer: (C)

Step-by-step solution →
Q33·PhysicsSingle correctJEE Main 2024
P-T diagram of an ideal gas having three different densities ρ1,ρ2,ρ3\rho_1,\rho_2,\rho_3ρ1​,ρ2​,ρ3​ (in three different cases) is shown in the figure. Which of the following is correct:
  1. (A)ρ2<ρ1\rho_2<\rho_1ρ2​<ρ1​
  2. (B)ρ1>ρ2\rho_1>\rho_2ρ1​>ρ2​
  3. (C)ρ1<ρ2\rho_1<\rho_2ρ1​<ρ2​
  4. (D)ρ1=ρ2=ρ3\rho_1=\rho_2=\rho_3ρ1​=ρ2​=ρ3​

Correct answer: (B)

Step-by-step solution →
Q34·PhysicsSingle correctJEE Main 2024
The translational degrees of freedom (ftf_tft​) and rotational degrees of freedom (frf_rfr​) of CH4\text{CH}_4CH4​ molecule are
  1. (A)ft=2f_t=2ft​=2 and fr=2f_r=2fr​=2
  2. (B)ft=3f_t=3ft​=3 and fr=3f_r=3fr​=3
  3. (C)ft=3f_t=3ft​=3 and fr=2f_r=2fr​=2
  4. (D)ft=2f_t=2ft​=2 and fr=3f_r=3fr​=3

Correct answer: (B)

Step-by-step solution →
Q35·PhysicsSingle correctJEE Main 2024
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km/s, the root mean square velocity of oxygen at the same condition in km/s is:
  1. (A)2.0
  2. (B)0.5
  3. (C)1.5
  4. (D)1.0

Correct answer: (B)

Step-by-step solution →
Q36·PhysicsSingle correctJEE Main 2024
Two moles of a monoatomic gas is mixed with six moles of a diatomic gas. The molar specific heat of the mixture at constant volume is:
  1. (A)94R\dfrac94 R49​R
  2. (B)74R\dfrac74 R47​R
  3. (C)32R\dfrac32 R23​R
  4. (D)52R\dfrac52 R25​R

Correct answer: (A)

Step-by-step solution →
Q37·PhysicsSingle correctJEE Main 2024
The parameter that remains the same for molecules of all gases at a given temperature is :
  1. (A)kinetic energy
  2. (B)momentum
  3. (C)mass
  4. (D)speed

Correct answer: (A)

Step-by-step solution →
Q38·PhysicsSingle correctJEE Main 2024
A gas mixture consists of 8 moles of argon and 6 moles of oxygen at temperature T. Neglecting all vibrational modes, the total internal energy of the system is
  1. (A)29 RT
  2. (B)20 RT
  3. (C)27 RT
  4. (D)21 RT

Correct answer: (C)

Step-by-step solution →
Q39·PhysicsSingle correctJEE Main 2024
At which temperature the r.m.s. velocity of a hydrogen molecule equal to that of an oxygen molecule at 47∘C47^\circ C47∘C?
  1. (A)80 K80\,K80K
  2. (B)−73 K-73\,K−73K
  3. (C)4 K4\,K4K
  4. (D)20 K20\,K20K

Correct answer: (D)

Step-by-step solution →
Q40·PhysicsSingle correctJEE Main 2024
If three moles of monoatomic gas (γ=53)\left(\gamma=\dfrac{5}{3}\right)(γ=35​) is mixed with two moles of a diatomic gas (γ=75)\left(\gamma=\dfrac{7}{5}\right)(γ=57​), the value of adiabatic exponent γ\gammaγ for the mixture is:
  1. (A)1.75
  2. (B)1.40
  3. (C)1.52
  4. (D)1.35

Correct answer: (C)

Step-by-step solution →
Q41·PhysicsSingle correctJEE Main 2024
N moles of a polyatomic gas (f=6f=6f=6) must be mixed with two moles of a monoatomic gas so that the mixture behaves as a diatomic gas. The value of N is:
  1. (A)6
  2. (B)3
  3. (C)4
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q42·PhysicsSingle correctJEE Main 2024
Two vessels A and B are of the same size and are at same temperature. A contains 1 g of hydrogen and B contains 1 g of oxygen. PAP_APA​ and PBP_BPB​ are the pressures of the gases in A and B respectively, then PAPB\dfrac{P_A}{P_B}PB​PA​​ is :
  1. (A)161616
  2. (B)888
  3. (C)444
  4. (D)323232

Correct answer: (A)

Step-by-step solution →
Q43·PhysicsSingle correctJEE Main 2024
The temperature of a gas having 2.0×10252.0\times10^{25}2.0×1025 molecules per cubic meter at 1.38 atm (Given, k=1.38×10−23k=1.38\times10^{-23}k=1.38×10−23 JK−1^{-1}−1) is:
  1. (A)500 K
  2. (B)200 K
  3. (C)100 K
  4. (D)300 K

Correct answer: (A)

Step-by-step solution →
Q44·PhysicsSingle correctJEE Main 2024
The equation of state of a real gas is given by (P+aV2)(V−b)=RT\left(P+\dfrac{a}{V^2}\right)(V-b)=RT(P+V2a​)(V−b)=RT, where P, V and T are pressure, volume and temperature respectively and R is the universal gas constant. The dimensions of ab2\dfrac{a}{b^2}b2a​ is similar to that of :
  1. (A)PV
  2. (B)P
  3. (C)RT
  4. (D)R

Correct answer: (B)

Step-by-step solution →
Q45·PhysicsSingle correctJEE Main 2024
The total kinetic energy of 1 mole of oxygen at 27∘27^\circ27∘C is : [Use universal gas constant (R) = 8.31 J/mole K]
  1. (A)6845.5 J
  2. (B)5942.0 J
  3. (C)6232.5 J
  4. (D)5670.5 J

Correct answer: (C)

Step-by-step solution →
Q46·PhysicsSingle correctJEE Main 2024
The average kinetic energy of a monatomic molecule is 0.414 eV at temperature (Use KB=1.38×10−23K_B=1.38\times 10^{-23}KB​=1.38×10−23 J/mol-K):
  1. (A)3000 K
  2. (B)3200 K
  3. (C)1600 K
  4. (D)1500 K

Correct answer: (B)

Step-by-step solution →
Q47·PhysicsSingle correctJEE Advanced 2023
An ideal gas is in thermodynamic equilibrium. The number of degrees of freedom of a molecule of the gas is n. The internal energy of one mole of the gas is UnU_nUn​ and the speed of sound in the gas is vnv_nvn​. At a fixed temperature and pressure, which of the following is the correct option ?
  1. (A)v3<v6v_3 < v_6v3​<v6​ and U3>U6U_3 > U_6U3​>U6​
  2. (B)v5>v3v_5 > v_3v5​>v3​ and U3>U5U_3 > U_5U3​>U5​
  3. (C)v5>v7v_5 > v_7v5​>v7​ and U5<U7U_5 < U_7U5​<U7​
  4. (D)v6<v7v_6 < v_7v6​<v7​ and U6<U7U_6 < U_7U6​<U7​

Correct answer: (C)

Step-by-step solution →
Q48·PhysicsSingle correctJEE Main 2023
A flask contains Hydrogen and Argon in the ratio 2:1 by mass. The temperature of the mixture is 30∘^{\circ}∘C. The ratio of average kinetic energy per molecule of the two gases (K argon/K hydrogen) is: (Given: Atomic Weight of Ar = 39.9)
  1. (A)1
  2. (B)2
  3. (C)39.92\frac{39.9}{2}239.9​
  4. (D)39.9

Correct answer: (A)

Step-by-step solution →
Q49·PhysicsSingle correctJEE Main 2023
The rmsrmsrms speed of oxygen molecules in a vessel at particular temperature is (1+5x)1/2 v\left(1+\dfrac{5}{x}\right)^{1/2}\,v(1+x5​)1/2v, where vvv is the average speed of the molecule. The value of xxx will be: (Take π=227\pi=\dfrac{22}{7}π=722​)
  1. (A)282828
  2. (B)272727
  3. (C)888
  4. (D)444

Correct answer: (A)

Step-by-step solution →
Q50·PhysicsSingle correctJEE Main 2023
The mean free path of molecules of a certain gas at STP is 1500d, where d is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at 373 K is approximately:
  1. (A)1098d
  2. (B)2049d
  3. (C)750d
  4. (D)1500d

Correct answer: (B)

Step-by-step solution →
Q51·PhysicsSingle correctJEE Main 2023
If the r.m.s. speed of chlorine molecule is 490 m/s at 27°C, the r.m.s. speed of argon molecules at the same temperature will be (Atomic mass of argon = 39.9u, molecular mass of chlorine = 70.9u)
  1. (A)751.7 m/s
  2. (B)451.7 m/s
  3. (C)651.7 m/s
  4. (D)551.7 m/s

Correct answer: (C)

Step-by-step solution →
Q52·PhysicsSingle correctJEE Main 2023
The root mean square speed of molecules of nitrogen gas at 27∘27^\circ27∘C is: (Given mass of a nitrogen molecule =4.6×10−26=4.6\times10^{-26}=4.6×10−26 kg and take Boltzmann constant kB=1.4×10−23k_B=1.4\times10^{-23}kB​=1.4×10−23 JK−1^{-1}−1)
  1. (A)523523523 m/s
  2. (B)126012601260 m/s
  3. (C)919191 m/s
  4. (D)27.427.427.4 m/s

Correct answer: (A)

Step-by-step solution →
Q53·PhysicsSingle correctJEE Main 2023
Three vessels of equal volume contain gases at the same temperature and pressure. The first vessel contains neon (monoatomic), the second contains chlorine (diatomic) and third contains uranium hexafloride (polyatomic). Arrange these on the basis of their root mean square speed (vrmsv_{rms}vrms​) and choose the correct answer from the options given below:
  1. (A)vrms(mono)=vrms(dia)=vrms(poly)v_{rms}(\text{mono}) = v_{rms}(\text{dia}) = v_{rms}(\text{poly})vrms​(mono)=vrms​(dia)=vrms​(poly)
  2. (B)vrms(mono)>vrms(dia)>vrms(poly)v_{rms}(\text{mono}) > v_{rms}(\text{dia}) > v_{rms}(\text{poly})vrms​(mono)>vrms​(dia)>vrms​(poly)
  3. (C)vrms(dia)<vrms(poly)<vrms(mono)v_{rms}(\text{dia}) < v_{rms}(\text{poly}) < v_{rms}(\text{mono})vrms​(dia)<vrms​(poly)<vrms​(mono)
  4. (D)vrms(mono)<vrms(dia)<vrms(poly)v_{rms}(\text{mono}) < v_{rms}(\text{dia}) < v_{rms}(\text{poly})vrms​(mono)<vrms​(dia)<vrms​(poly)

Correct answer: (B)

Step-by-step solution →
Q54·PhysicsSingle correctJEE Main 2023
Match List I (degrees of freedom) with List II (type of gas). Choose the correct answer from the options given below:
List IList II
A.3 Translational degrees of freedomI.Monoatomic gases
B.3 Translational, 2 rotational degrees of freedomII.Polyatomic gases
C.3 Translational, 2 rotational and 1 vibrational degrees of freedomIII.Rigid diatomic gases
D.3 Translational, 3 rotational and more than one vibrational degrees of freedomIV.Nonrigid diatomic gases
  1. (A)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  2. (B)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  3. (C)(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
  4. (D)(A)-(I), (B)-(IV), (C)-(III), (D)-(II)

Correct answer: (C)

Step-by-step solution →
Q55·PhysicsSingle correctJEE Main 2023
A gas mixture consists of 222 moles of oxygen and 444 moles of neon at temperature T. Neglecting all vibrational modes, the total internal energy of the system will be:
  1. (A)8 RT8\,RT8RT
  2. (B)16 RT16\,RT16RT
  3. (C)4 RT4\,RT4RT
  4. (D)11 RT11\,RT11RT

Correct answer: (D)

Step-by-step solution →
Q56·PhysicsSingle correctJEE Main 2023
The temperature at which the kinetic energy of oxygen molecules becomes double of its value at 27∘27^{\circ}27∘C is
  1. (A)1227∘1227^{\circ}1227∘C
  2. (B)927∘927^{\circ}927∘C
  3. (C)327∘327^{\circ}327∘C
  4. (D)627∘627^{\circ}627∘C

Correct answer: (C)

Step-by-step solution →
Q57·PhysicsSingle correctJEE Main 2023
The temperature of an ideal gas is increased from 200 K to 800 K. If r.m.s. speed of gas at 200 K is v0v_0v0​, then r.m.s. speed of the gas at 800 K will be:
  1. (A)v0v_0v0​
  2. (B)4v04v_04v0​
  3. (C)v04\dfrac{v_0}{4}4v0​​
  4. (D)2v02v_02v0​

Correct answer: (D)

Step-by-step solution →
Q58·PhysicsSingle correctJEE Main 2023
The number of air molecules per cm3cm^3cm3 increased from 3×10193\times10^{19}3×1019 to 12×101912\times10^{19}12×1019. The ratio of collision frequency of air molecules before and after the increase in number respectively is:
  1. (A)1.251.251.25
  2. (B)0.250.250.25
  3. (C)0.750.750.75
  4. (D)0.500.500.50

Correct answer: (B)

Step-by-step solution →
Q59·PhysicsSingle correctJEE Main 2023
For three low density gases A, B, C pressure versus temperature graphs are plotted while keeping them at constant volume, as shown in the figure. The temperature corresponding to the point 'K' is:
  1. (A)−273°C-273°C−273°C
  2. (B)−100°C-100°C−100°C
  3. (C)−40°C-40°C−40°C
  4. (D)−373°C-373°C−373°C

Correct answer: (A)

Step-by-step solution →
Q60·PhysicsSingle correctJEE Main 2023
The average kinetic energy of a molecule of the gas is:
  1. (A)proportional to absolute temperature
  2. (B)proportional to pressure
  3. (C)proportional to volume
  4. (D)dependent on the nature of gas

Correct answer: (A)

Step-by-step solution →
Q61·PhysicsSingle correctJEE Main 2023
Heat energy of 735735735 J is given to a diatomic gas allowing the gas to expand at constant pressure. Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal energy of the gas will be:
  1. (A)525525525 J
  2. (B)441441441 J
  3. (C)572572572 J
  4. (D)735735735 J

Correct answer: (A)

Step-by-step solution →
Q62·PhysicsSingle correctJEE Main 2023
The correct relation between γ=CpCv\gamma=\frac{C_p}{C_v}γ=Cv​Cp​​ and temperature TTT is :
  1. (A)γα T0\gamma \alpha\, T^0γαT0
  2. (B)γα T\gamma \alpha\, TγαT
  3. (C)γα 1T\gamma \alpha\, \frac{1}{\sqrt{T}}γαT​1​
  4. (D)γα 1T\gamma \alpha\, \frac{1}{T}γαT1​

Correct answer: (A)

Step-by-step solution →
Q63·PhysicsSingle correctJEE Main 2023
A flask contains hydrogen and oxygen in the ratio of 2:1 by mass at temperature 27 ∘27\,^{\circ}27∘C. The ratio of average kinetic energy per molecule of hydrogen and oxygen respectively is:
  1. (A)2:12:12:1
  2. (B)1:11:11:1
  3. (C)1:41:41:4
  4. (D)4:14:14:1

Correct answer: (B)

Step-by-step solution →
Q64·PhysicsSingle correctJEE Main 2023
The pressure (P) and temperature (T) relationship of an ideal gas obeys the equation PT2=PT^2=PT2= constant. The volume expansion coefficient of the gas will be:
  1. (A)3T2\dfrac{3}{T^2}T23​
  2. (B)3T3\dfrac{3}{T^3}T33​
  3. (C)3T23T^23T2
  4. (D)3T\dfrac{3}{T}T3​

Correct answer: (D)

Step-by-step solution →
Q65·PhysicsSingle correctJEE Main 2023
A bicycle tyre is filled with air having pressure of 270 kPa at 27 °C. The approximate pressure of the air in the tyre when the temperature increases to 36 °C is:
  1. (A)270 kPa
  2. (B)262 kPa
  3. (C)360 kPa
  4. (D)278 kPa

Correct answer: (D)

Step-by-step solution →
Q66·PhysicsSingle correctJEE Main 2023
At 300 K300\,K300K the rms speed of oxygen molecules is α+5α\sqrt{\dfrac{\alpha+5}{\alpha}}αα+5​​ times to that of its average speed in the gas. Then, the value of α\alphaα will be: (used π=227)\left(\text{used }\pi=\dfrac{22}{7}\right)(used π=722​)
  1. (A)282828
  2. (B)242424
  3. (C)323232
  4. (D)272727

Correct answer: (A)

Step-by-step solution →
Q67·PhysicsSingle correctJEE Main 2023
According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is:
  1. (A)52R\frac{5}{2}R25​R
  2. (B)92R\frac{9}{2}R29​R
  3. (C)72R\frac{7}{2}R27​R
  4. (D)32R\frac{3}{2}R23​R

Correct answer: (C)

Step-by-step solution →
Q68·PhysicsSingle correctJEE Main 2023
The root mean square velocity of molecules of a gas is:
  1. (A)Inversely proportional to square root of temperature (1T)\left(\dfrac{1}{\sqrt{T}}\right)(T​1​)
  2. (B)Proportional to square of temperature (T2)(T^2)(T2)
  3. (C)Proportional to temperature (T)(T)(T)
  4. (D)Proportional to square root of temperature (T)(\sqrt{T})(T​)

Correct answer: (D)

Step-by-step solution →
Q69·PhysicsSingle correctJEE Main 2023
Given below are two statements: Statement I: The temperature of a gas is −73∘-73^{\circ}−73∘C. When the gas is heated to 527∘527^{\circ}527∘C, the root mean square speed of the molecules is doubled. Statement II: The product of pressure and volume of an ideal gas will be equal to translational kinetic energy of the molecules. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are true

Correct answer: (C)

Step-by-step solution →
Q70·PhysicsSingle correctJEE Main 2023
Let γ1\gamma_1γ1​ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ2\gamma_2γ2​ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio γ1γ2\dfrac{\gamma_1}{\gamma_2}γ2​γ1​​ is:
  1. (A)2521\dfrac{25}{21}2125​
  2. (B)2527\dfrac{25}{27}2725​
  3. (C)2125\dfrac{21}{25}2521​
  4. (D)2735\dfrac{27}{35}3527​

Correct answer: (A)

Step-by-step solution →
Q71·PhysicsNumericalJEE Main 2022
One mole of a monoatomic gas is mixed with three moles of a diatomic gas. The molecular specific heat of mixture at constant volume is α24\frac{\alpha^2}{4}4α2​R J/mol K; then the value of α\alphaα will be ________. (Assume that the given diatomic gas has no vibrational mode.)

Correct answer: 3

Step-by-step solution →
Q72·PhysicsSingle correctJEE Main 2022
The root mean square speed of smoke particles of mass 5×10−175 \times 10^{-17}5×10−17 kg in their Brownian motion in air at NTP is approximately. [Given k =1.38×10−23= 1.38 \times 10^{-23}=1.38×10−23 JK−1^{-1}−1]
  1. (A)60 mm s−1^{-1}−1
  2. (B)12 mm s−1^{-1}−1
  3. (C)15 mm s−1^{-1}−1
  4. (D)36 mm s−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q73·PhysicsSingle correctJEE Main 2022
A vessel contains 14 g of nitrogen gas at a temperature of 27∘^\circ∘C. The amount of heat to be transferred to the gap to double the r.m.s. speed of its molecules will be : (Take R = 8.32 J mol−1k−1mol^{-1}k^{-1}mol−1k−1)
  1. (A)2229 J
  2. (B)5616 J
  3. (C)9360 J
  4. (D)13,104 J

Correct answer: (C)

Step-by-step solution →
Q74·PhysicsSingle correctJEE Main 2022
Given below are two statements : Statement I :The average momentum of a molecule in a sample of an ideal gas depends on temperature. Statement II : The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become 2v. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q75·PhysicsSingle correctJEE Main 2022
Which statements are correct about degrees of freedom? A. A molecule with n degrees of freedom has n2^{2}2 different ways of storing energy. B. Each degree of freedom is associated with 12RT\frac{1}{2}RT21​RT average energy per mole. C. A monoatomic gas molecule has 1 rotational degree of freedom where as diatomic molecule has 2 rotational degrees of freedom D. CH4_44​ has a total to 6 degrees of freedom Choose the correct answer from the option given below:
  1. (A)B and C only
  2. (B)B and D only
  3. (C)A and B only
  4. (D)C and D only

Correct answer: (B)

Step-by-step solution →
Q76·PhysicsSingle correctJEE Main 2022
Same gas is filled in two vessels of the same volume at the same temperature. If the ratio of the number of molecules is 1:4, then A. The r.m.s. velocity of gas molecules in two vessels will be the same. B. The ratio of pressure in these vessels will be 1 : 4 C. The ratio of pressure will be 1 : 1 D. The r.m.s. velocity of gas molecules in two vessels will be in the ratio of 1 : 4
  1. (A)A and C only
  2. (B)B and D only
  3. (C)A and B only
  4. (D)C and D only

Correct answer: (C)

Step-by-step solution →
Q77·PhysicsSingle correctJEE Main 2022
A gas has n degrees of freedom. The ratio of specific heat of gas at constant volume to the specific heat of gas at constant pressure will be :
  1. (A)nn+2\frac{n}{n+2}n+2n​
  2. (B)n+2n\frac{n+2}{n}nn+2​
  3. (C)n2n+2\frac{n}{2n+2}2n+2n​
  4. (D)nn−2\frac{n}{n-2}n−2n​

Correct answer: (A)

Step-by-step solution →
Q78·PhysicsSingle correctJEE Main 2022
Following statements are given : (1) The average kinetic energy of a gas molecule decreases when the temperature is reduced. (2) The average kinetic energy of a gas molecule increases with increase in pressure at constant temperature. (3) The average kinetic energy of a gas molecule decreases with increases in volume. (4) Pressure of a gas increases with increase in temperature at constant pressure. (5) The volume of gas decreases with increase in temperature. Choose the correct answer from the options given below :
  1. (A)(1) and (4) only
  2. (B)(1), (2) and (4) only
  3. (C)(2) and (4) only
  4. (D)(1), (2) and (5) only

Correct answer: (A)

Step-by-step solution →
Q79·PhysicsSingle correctJEE Main 2022
A vessel contains 16g of hydrogen and 128 g of oxygen at standard temperature and pressure. The volume of the vessel in cm3\mathrm{cm}^3cm3 is :
  1. (A)72×10572 \times 10^{5}72×105
  2. (B)32×10532 \times 10^{5}32×105
  3. (C)27×10427 \times 10^{4}27×104
  4. (D)54×10454 \times 10^{4}54×104

Correct answer: (C)

Step-by-step solution →
Q80·PhysicsSingle correctJEE Main 2022
A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0°C will be : (Given gas constant R = 8.3 JK−1JK^{-1}JK−1-mol−1mol^{-1}mol−1)
  1. (A)249 J
  2. (B)415 J
  3. (C)498 J
  4. (D)830 J

Correct answer: (C)

Step-by-step solution →
Q81·PhysicsSingle correctJEE Main 2022
What will be the effect on the root mean square velocity of oxygen molecules if the temperature is doubled and oxygen molecule dissociates into atomic oxygen?
  1. (A)The velocity of atomic oxygen remains same
  2. (B)The velocity of atomic oxygen doubles
  3. (C)The velocity of atomic oxygen becomes half
  4. (D)The velocity of atomic oxygen becomes four times

Correct answer: (B)

Step-by-step solution →
Q82·PhysicsNumericalJEE Main 2022
The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be J. (Given R = 8.31 J/mol.K)

Correct answer: 7479

Step-by-step solution →
Q83·PhysicsSingle correctJEE Main 2022
For a perfect gas, two pressures P1P_{1}P1​ and P2P_{2}P2​ are shown in figure. The graph shows:
  1. (A)P1>P2P_{1}>P_{2}P1​>P2​
  2. (B)P1<P2P_{1}<P_{2}P1​<P2​
  3. (C)P1=P2P_{1}=P_{2}P1​=P2​
  4. (D)Insufficient data to draw any conclusion

Correct answer: (A)

Step-by-step solution →
Q84·PhysicsSingle correctJEE Main 2022
A mixture of hydrogen and oxygen has volume 2000 cm3cm^{3}cm3, temperature 300 K, pressure 100 kPa and mass 0.76 g The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be :
  1. (A)13\frac{1}{3}31​
  2. (B)31\frac{3}{1}13​
  3. (C)116\frac{1}{16}161​
  4. (D)161\frac{16}{1}116​

Correct answer: (B)

Step-by-step solution →
Q85·PhysicsSingle correctJEE Main 2022
According to kinetic theory of gases, A. The motion of the gas molecules freezes at 0∘0^{\circ}0∘C B. The mean free path of gas molecules decreases if the density of molecules is increased. C. The mean free path of gas molecules increases if temperature is increased keeping pressure constant. D. Average kinetic energy per molecule per degree of freedom is 32kBT\dfrac{3}{2}k_{B}T23​kB​T (for monoatomic gases) Choose the most appropriate answer from the options given below:
  1. (A)A and C only
  2. (B)B and C only
  3. (C)A and B only
  4. (D)C and D only

Correct answer: (B)

Step-by-step solution →
Q86·PhysicsSingle correctJEE Main 2022
A thermally insulated vessel contains an ideal gas of molecular mass M and ratio of specific heats 1.4. Vessel is moving with speed v and is suddenly brought to rest. Assuming no heat is lost to the surrounding and vessel temperature of the gas increases by : (R = universal gas constant)
  1. (A)Mv27R\frac{Mv^{2}}{7R}7RMv2​
  2. (B)Mv25R\frac{Mv^{2}}{5R}5RMv2​
  3. (C)2Mv27R2\frac{Mv^{2}}{7R}27RMv2​
  4. (D)7Mv25R7\frac{Mv^{2}}{5R}75RMv2​

Correct answer: (B)

Step-by-step solution →
Q87·PhysicsSingle correctJEE Main 2022
A flask contains argon and oxygen in the ratio of 3:2 in mass and the mixture is kept at 27°C. The ratio of their average kinetic energy per molecule respectively will be :
  1. (A)3 : 2
  2. (B)9 : 4
  3. (C)2 : 3
  4. (D)1 : 1

Correct answer: (D)

Step-by-step solution →
Q88·PhysicsSingle correctJEE Main 2022
The ratio of specific heats (CPCV)\left(\frac{C_P}{C_V}\right)(CV​CP​​) in terms of degree of freedom (f) is given by:
  1. (A)(1+f3)\left(1 + \frac{f}{3}\right)(1+3f​)
  2. (B)(1+2f)\left(1 + \frac{2}{f}\right)(1+f2​)
  3. (C)(1+f2)\left(1 + \frac{f}{2}\right)(1+2f​)
  4. (D)(1+1f)\left(1 + \frac{1}{f}\right)(1+f1​)

Correct answer: (B)

Step-by-step solution →
Q89·PhysicsNumericalJEE Main 2022
When a gas filled in a closed vessel is heated by raising the temperature by 1°C, its pressure increase by 0.4%. The initial temperature of the gas is_______ K.

Correct answer: 250

Step-by-step solution →
Q90·PhysicsSingle correctJEE Main 2022
The relation between root mean square speed (vrms)(v_{rms})(vrms​) and most probable speed (vp)(v_p)(vp​) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :-
  1. (A)vrms=23vpv_{rms}=\sqrt{\frac{2}{3}}v_pvrms​=32​​vp​
  2. (B)vrms=32vpv_{rms}=\sqrt{\frac{3}{2}}v_pvrms​=23​​vp​
  3. (C)vrms=vpv_{rms}=v_pvrms​=vp​
  4. (D)vrms=13vpv_{rms}=\sqrt{\frac{1}{3}}v_pvrms​=31​​vp​

Correct answer: (B)

Step-by-step solution →
Q91·PhysicsNumericalJEE Main 2022
0.056 kg of Nitrogen is enclosed in a vessel at a temperature of 127∘127^{\circ}127∘C. The amount of heat required to double the speed of its molecules is ______ k cal. (Take R = 2 cal mole−1^{-1}−1K−1^{-1}−1)

Correct answer: 12

Step-by-step solution →
Q92·PhysicsNumericalJEE Advanced 2021
A soft plastic bottle, filled with water of density 1 gm/cc, carries an inverted glass test-tube with some air (ideal gas) trapped as shown in the figure. The test-tube has a mass of 5 gm, and it is made of a thick glass of density 2.5 gm/cc. Initially the bottle is sealed at atmospheric pressure p0=105p_0 = 10^5p0​=105 Pa so that the volume of the trapped air is v0v_0v0​ = 3.3 cc. When the bottle is squeezed from outside at constant temperature, the pressure inside rises and the volume of the trapped air reduces. It is found that the test tube begins to sink at pressure P0+ΔpP_0 + \Delta pP0​+Δp without changing its orientation. At this pressure, the volume of the trapped air is v0−Δvv_0 - \Delta vv0​−Δv. Let Δv=X\Delta v = XΔv=X cc and Δp=Y×103\Delta p = Y \times 10^3Δp=Y×103 Pa. The value of YYY is ____.

Correct answer: 10.00

Step-by-step solution →
Q93·PhysicsNumericalJEE Main 2021
The average translational kinetic energy of N2_{2}2​ gas molecules at ..........°C becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1 volt. (Given kB_{B}B​ = 1.38 × 10−23^{-23}−23 J/K) (Fill the nearest integer).

Correct answer: 500

Step-by-step solution →
Q94·PhysicsSingle correctJEE Main 2021
For an ideal gas the instantaneous change in pressure 'p' with volume 'v' is given by the equation dpdv=−ap\frac{dp}{dv}=-apdvdp​=−ap. If p = p0p_{0}p0​ at v = 0 is the given boundary condition, then the maximum temperature one mole of gas can attain is : (Here R is the gas constant)
  1. (A)p0a e R\frac{p_{0}}{a\,e\,R}aeRp0​​
  2. (B)ap0e R\frac{ap_{0}}{e\,R}eRap0​​
  3. (C)infinity
  4. (D)0∘^\circ∘C

Correct answer: (A)

Step-by-step solution →
Q95·PhysicsSingle correctJEE Main 2021
A mixture of hydrogen and oxygen has volume 500 cm3^33, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be :-
  1. (A)3 : 8
  2. (B)3 : 16
  3. (C)16 : 3
  4. (D)8 : 3

Correct answer: (C)

Step-by-step solution →
Q96·PhysicsSingle correctJEE Main 2021
If the rms speed of oxygen molecules at 0°C is 160 m/s, find the rms speed of hydrogen molecules at 0°C.
  1. (A)640 m/s
  2. (B)40 m/s
  3. (C)80 m/s
  4. (D)332 m/s

Correct answer: (A)

Step-by-step solution →
Q97·PhysicsSingle correctJEE Main 2021
A balloon carries a total load of 185 kg at normal pressure and temperature of 27∘^\circ∘C. What load will the balloon carry on rising to a height at which the barometric pressure is 45 cm of Hg and the temperature is −7∘-7^\circ−7∘C. Assuming the volume constant ?
  1. (A)181.46 kg
  2. (B)214.15 kg.
  3. (C)219.07 kg
  4. (D)123.54 kg

Correct answer: (D)

Step-by-step solution →
Q98·PhysicsSingle correctJEE Main 2021
The rms speeds of the molecules of Hydrogen, Oxygen and Carbondioxide at the same temperature are VHV_HVH​, VOV_OVO​ and VCV_CVC​ respectively then :
  1. (A)VH>VO>VCV_H > V_O > V_CVH​>VO​>VC​
  2. (B)VC>VO>VHV_C > V_O > V_HVC​>VO​>VH​
  3. (C)VH=VO>VCV_H = V_O > V_CVH​=VO​>VC​
  4. (D)VH=VO=VCV_H = V_O = V_CVH​=VO​=VC​

Correct answer: (A)

Step-by-step solution →
Q99·PhysicsSingle correctJEE Main 2021
A cylindrical container of volume 4.0×10−34.0 \times 10^{-3}4.0×10−3 m3^{3}3 contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400 K. The pressure of the mixture of gases is : [Take gas constant as 8.3 J mol−1^{-1}−1 K−1^{-1}−1]
  1. (A)249×101249 \times 10^{1}249×101 Pa
  2. (B)24.9×10324.9 \times 10^{3}24.9×103 Pa
  3. (C)24.9×10524.9 \times 10^{5}24.9×105 Pa
  4. (D)24.9 Pa

Correct answer: (C)

Step-by-step solution →
Q100·PhysicsSingle correctJEE Main 2021
The number of molecules in one litre of an ideal gas at 300K and 2 atmospheric pressure with mean kinetic energy 2×10−92 \times 10^{-9}2×10−9 J per molecule is :
  1. (A)0.75×10110.75 \times 10^{11}0.75×1011
  2. (B)3×10113 \times 10^{11}3×1011
  3. (C)6×10116 \times 10^{11}6×1011
  4. (D)1.5×10111.5 \times 10^{11}1.5×1011

Correct answer: (D)

Step-by-step solution →
Q101·PhysicsNumericalJEE Main 2021
A system consists of two types of gas molecules A and B having same number density 2×10252 \times 10^{25}2×1025 / m³. The diameter of A and B are 10 Å and 5 Å respectively. They suffer collision at room temperature. The ratio of average distance covered by the molecule A to that of B between two successive collision is ________ ×10−2\times 10^{-2}×10−2.

Correct answer: 25

Step-by-step solution →
Q102·PhysicsSingle correctJEE Main 2021
For a gas CP−CV=C_P - C_V = CP​−CV​= R in a state P and CP−CV=C_P - C_V = CP​−CV​= 1.10 R in a state Q, TPT_PTP​ and TQT_QTQ​ are the temperatures in two different states P and Q respectively. Then
  1. (A)TP<TQT_P < T_QTP​<TQ​
  2. (B)TP=0.9 TQT_P = 0.9\ T_QTP​=0.9 TQ​
  3. (C)TP>TQT_P > T_QTP​>TQ​
  4. (D)TP=TQT_P = T_QTP​=TQ​

Correct answer: (C)

Step-by-step solution →
Q103·PhysicsSingle correctJEE Main 2021
What will be the average value of energy for a monoatomic gas in thermal equilibrium at temperature T ?
  1. (A)32kBT\frac{3}{2}k_B T23​kB​T
  2. (B)12kBT\frac{1}{2}k_B T21​kB​T
  3. (C)kBTk_B TkB​T
  4. (D)23kBT\frac{2}{3}k_B T32​kB​T

Correct answer: (A)

Step-by-step solution →
Q104·PhysicsSingle correctJEE Main 2021
Consider a mixture of gas molecule of types A, B and C having masses mA<mB<mCm_A < m_B < m_CmA​<mB​<mC​. The ratio of their root mean square speeds at normal temperature and pressure is :
  1. (A)1υA>1υB>1υC\frac{1}{\upsilon_A} > \frac{1}{\upsilon_B} > \frac{1}{\upsilon_C}υA​1​>υB​1​>υC​1​
  2. (B)υA=υB=υC=0\upsilon_A = \upsilon_B = \upsilon_C = 0υA​=υB​=υC​=0
  3. (C)1υA<1υB<1υC\frac{1}{\upsilon_A} < \frac{1}{\upsilon_B} < \frac{1}{\upsilon_C}υA​1​<υB​1​<υC​1​
  4. (D)υA=υB≠υC\upsilon_A = \upsilon_B \neq \upsilon_CυA​=υB​=υC​

Correct answer: (C)

Step-by-step solution →
Q105·PhysicsSingle correctJEE Main 2021
Which of the following graphs represent the behaviour of an ideal gas? Symbols have their usual meaning.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q106·PhysicsSingle correctJEE Main 2021
The correct relation between the degrees of freedom f and the ratio of specific heat γ\gammaγ is :
  1. (A)f=2γ+1f = \dfrac{2}{\gamma + 1}f=γ+12​
  2. (B)f=2γ−1f = \dfrac{2}{\gamma - 1}f=γ−12​
  3. (C)f=1γ+1f = \dfrac{1}{\gamma + 1}f=γ+11​
  4. (D)f=γ+12f = \dfrac{\gamma + 1}{2}f=2γ+1​

Correct answer: (B)

Step-by-step solution →
Q107·PhysicsSingle correctJEE Main 2021
The amount of heat needed to raise the temperature of 4 moles of a rigid diatomic gas from 0°C to 50°C when no work is done is ________. (R is the universal gas constant)
  1. (A)175 R
  2. (B)750 R
  3. (C)250 R
  4. (D)500 R

Correct answer: (D)

Step-by-step solution →
Q108·PhysicsSingle correctJEE Main 2021
What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T ? (kB_{B}B​ is Boltzmann constant)
  1. (A)12kBT\dfrac{1}{2}k_{B}T21​kB​T
  2. (B)23kBT\dfrac{2}{3}k_{B}T32​kB​T
  3. (C)32kBT\dfrac{3}{2}k_{B}T23​kB​T
  4. (D)kBTk_{B}TkB​T

Correct answer: (A)

Step-by-step solution →
Q109·PhysicsSingle correctJEE Main 2021
Two ideal polyatomic gases at temperatures T1T_1T1​ and T2T_2T2​ are mixed so that there is no loss of energy. If F1F_1F1​ and F2F_2F2​, m1m_1m1​ and m2m_2m2​, n1n_1n1​ and n2n_2n2​ be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is :
  1. (A)n1T1+n2T2n1+n2\frac{n_1 T_1 + n_2 T_2}{n_1 + n_2}n1​+n2​n1​T1​+n2​T2​​
  2. (B)n1F1T1+n2F2T2n1F1+n2F2\frac{n_1 F_1 T_1 + n_2 F_2 T_2}{n_1 F_1 + n_2 F_2}n1​F1​+n2​F2​n1​F1​T1​+n2​F2​T2​​
  3. (C)n1F1T1+n2F2T2F1+F2\frac{n_1 F_1 T_1 + n_2 F_2 T_2}{F_1 + F_2}F1​+F2​n1​F1​T1​+n2​F2​T2​​
  4. (D)n1F1T1+n2F2T2n1+n2\frac{n_1 F_1 T_1 + n_2 F_2 T_2}{n_1 + n_2}n1​+n2​n1​F1​T1​+n2​F2​T2​​

Correct answer: (B)

Step-by-step solution →
Q110·PhysicsSingle correctJEE Main 2021
If one mole of the polyatomic gas is having two vibrational modes and β is the ratio of molar specific heats for polyatomic gas (β=CPCV)\left(\beta = \frac{C_{P}}{C_{V}}\right)(β=CV​CP​​) then the value of β is :
  1. (A)1.02
  2. (B)1.2
  3. (C)1.25
  4. (D)1.35

Correct answer: (B)

Step-by-step solution →
Q111·PhysicsSingle correctJEE Main 2021
A polyatomic ideal gas has 24 vibrational modes. What is the value of γ\gammaγ ?
  1. (A)1.03
  2. (B)1.30
  3. (C)1.37
  4. (D)10.3

Correct answer: (A)

Step-by-step solution →
Q112·PhysicsSingle correctJEE Main 2021
The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :
  1. (A)88RTV\frac{88RT}{V}V88RT​
  2. (B)3RTV\frac{3RT}{V}V3RT​
  3. (C)52RTV\frac{5}{2}\frac{RT}{V}25​VRT​
  4. (D)4RTV\frac{4RT}{V}V4RT​

Correct answer: (C)

Step-by-step solution →
Q113·PhysicsSingle correctJEE Main 2021
Calculate the value of mean free path (λ) for oxygen molecules at temperature 27°C and pressure 1.01 × 105^{5}5 Pa. Assume the molecular diameter 0.3 nm and the gas is ideal. (k = 1.38 × 10−23^{-23}−23 JK−1^{-1}−1)
  1. (A)58 nm
  2. (B)32 nm
  3. (C)86 nm
  4. (D)102 nm

Correct answer: (D)

Step-by-step solution →
Q114·PhysicsNumericalJEE Main 2021
A container is divided into two chambers by a partition. The volume of first chamber is 4.5 litre and second chamber is 5.5 litre. The first chamber contain 3.0 moles of gas at pressure 2.0 atm and second chamber contain 4.0 moles of gas at pressure 3.0 atm. After the partition is removed and the mixture attains equilibrium, then, the common equilibrium pressure existing in the mixture is x × 10−1^{-1}−1 atm. Value of x is _________.

Correct answer: 25

Step-by-step solution →
Q115·PhysicsSingle correctJEE Main 2021
The internal energy (U), pressure (P) and volume (V) of an ideal gas are related as U = 3PV + 4. The gas is :
  1. (A)polyatomic only
  2. (B)monoatomic only
  3. (C)either monoatomic or diatomic
  4. (D)diatomic only.

Correct answer: (A)

Step-by-step solution →
Q116·PhysicsNumericalJEE Main 2021
A monoatomic gas of mass 4.0 u is kept in an insulated container. Container is moving with velocity 30 m/s. If container is suddenly stopped then change in temperature of the gas (R=gas constant) is x3R\dfrac{x}{3R}3Rx​. Value of x is ________ .

Correct answer: 3600

Step-by-step solution →
Q117·PhysicsSingle correctJEE Main 2021
Given below are two statements: Statement I: In a diatomic molecule, the rotational energy at a given temperature obeys Maxwell's distribution. Statement II: in a diatomic molecule, the rotational energy at a given temperature equals the translational kinetic energy for each molecule. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both statement I and statement II are false.
  2. (B)Both statement I and statement II are true.
  3. (C)Statement I is false but statement II is true
  4. (D)Statement I is true but statement II is false.

Correct answer: (D)

Step-by-step solution →
Q118·PhysicsNumericalJEE Main 2021
The root mean square speed of molecules of a given mass of a gas at 27°C and 1 atmosphere pressure is 200 ms−1^{-1}−1. The root mean square speed of molecules of the gas at 127°C and 2 atmosphere pressure is x3\dfrac{x}{\sqrt{3}}3​x​ ms−1^{-1}−1. The value of x will be ____________.

Correct answer: 400

Step-by-step solution →
Q119·PhysicsSingle correctJEE Main 2021
On the basis of kinetic theory of gases, the gas exerts pressure because its molecules:
  1. (A)suffer change in momentum when impinge on the walls of container.
  2. (B)continuously stick to the walls of container.
  3. (C)continuously lose their energy till it reaches wall.
  4. (D)are attracted by the walls of container.

Correct answer: (A)

Step-by-step solution →
Q120·PhysicsMultiple correctJEE Advanced 2020
As shown schematically in the figure, two vessels contain water solutions (at temperature TTT) of potassium permanganate (KMnO4KMnO_4KMnO4​) of different concentrations n1n_1n1​ and n2n_2n2​ (n1>n2n_1 > n_2n1​>n2​) molecules per unit volume with Δn=(n1−n2)≪n1\Delta n = (n_1 - n_2) \ll n_1Δn=(n1​−n2​)≪n1​. When they are connected by a tube of small length ℓ\ellℓ and cross-sectional area S, KMnO4KMnO_4KMnO4​ starts to diffuse from the left to the right vessel through the tube. Consider the collection of molecules to behave as dilute ideal gases and the difference in their partial pressure in the two vessels causing the diffusion. The speed v of the molecules is limited by the viscous force −βv-\beta v−βv on each molecule, where β is a constant. Neglecting all terms of the order (Δn)2(\Delta n)^2(Δn)2, which of the following is/are correct? (kBk_BkB​ is the Boltzmann constant)-
  1. (A)the force causing the molecules to move across the tube is ΔnkBTS\Delta nk_BTSΔnkB​TS
  2. (B)force balance implies n1βvℓ=ΔnkBTn_1\beta v\ell = \Delta nk_BTn1​βvℓ=ΔnkB​T
  3. (C)total number of molecules going across the tube per sec is (Δnℓ)(kBTβ)S\left(\frac{\Delta n}{\ell}\right)\left(\frac{k_BT}{\beta}\right)S(ℓΔn​)(βkB​T​)S
  4. (D)rate of molecules getting transferred through the tube does not change with time

Correct answer: (A), (B), (C)

Step-by-step solution →
Q121·PhysicsNumericalJEE Main 2020
Initially a gas of diatomic molecules is contained in a cylinder of volume V1V_1V1​ at a pressure P1P_1P1​ and temperature 250 K. Assuming that 25% of the molecules get dissociated causing a change in number of moles. The pressure of the resulting gas at temperature 2000 K, when contained in a volume 2V12V_12V1​ is given by P2P_2P2​. The ratio P2P1\dfrac{P_2}{P_1}P1​P2​​ is __________.

Correct answer: 05.00

Step-by-step solution →
Q122·PhysicsSingle correctJEE Main 2020
Molecules of an ideal gas are known to have three translational degrees of freedom and two rotational degrees of freedom. The gas is maintained at a temperature of T. The total internal energy, U of a mole of this gas, and the value of γ(=CPCv)\gamma\left(=\dfrac{C_P}{C_v}\right)γ(=Cv​CP​​) are given, respectively, by:
  1. (A)U=52RTU=\dfrac{5}{2}RTU=25​RT and γ=65\gamma=\dfrac{6}{5}γ=56​
  2. (B)U=5RTU=5RTU=5RT and γ=75\gamma=\dfrac{7}{5}γ=57​
  3. (C)U=52RTU=\dfrac{5}{2}RTU=25​RT and γ=75\gamma=\dfrac{7}{5}γ=57​
  4. (D)U=5RTU=5RTU=5RT and γ=65\gamma=\dfrac{6}{5}γ=56​

Correct answer: (C)

Step-by-step solution →
Q123·PhysicsSingle correctJEE Main 2020
Number of molecules in a volume of 4 cm3^33 of a perfect monoatomic gas at some temperature T and at a pressure of 2 cm of mercury is close to? (Given, mean kinetic energy of a molecule (at T) is 4×10−144 \times 10^{-14}4×10−14 erg, g = 980 cm / s2^22, density of mercury = 13.6 g / cm3^33)
  1. (A)5.8×10185.8 \times 10^{18}5.8×1018
  2. (B)4.0×10164.0 \times 10^{16}4.0×1016
  3. (C)5.8×10165.8 \times 10^{16}5.8×1016
  4. (D)4.0×10184.0 \times 10^{18}4.0×1018

Correct answer: (D)

Step-by-step solution →
Q124·PhysicsSingle correctJEE Main 2020
Match the CP/CVC_{P}/C_{V}CP​/CV​ ratio for ideal gases with different type of molecules: Match the correct option?
Molecule Type$C_{P}/C_{V}$
A.MonatomicI.75\frac{7}{5}57​
B.Diatomic rigid moleculesII.97\frac{9}{7}79​
C.Diatomic non-rigid moleculesIII.43\frac{4}{3}34​
D.Triatomic rigid moleculesIV.53\frac{5}{3}35​
  1. (A)A → III; B → IV; C → II; D → I
  2. (B)A → IV; B → I; C → II; D → III
  3. (C)A → II; B → III; C → I; D → IV
  4. (D)A → IV; B → II; C → I; D → III

Correct answer: (B)

Step-by-step solution →
Q125·PhysicsNumericalJEE Main 2020
The change in the magnitude of the volume of an ideal gas when a small additional pressure ΔP is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity ΔT at constant pressure. The initial temperature and pressure of the gas were 300 K and 2 atm. respectively. If |ΔT| = C|ΔP| then value of C in (K/atm) is ….

Correct answer: 150

Step-by-step solution →
Q126·PhysicsSingle correctJEE Main 2020
To raise the temperature of a certain mass of gas by 50∘50^{\circ}50∘ C at a constant pressure, 160 calories of heat is required. When the same mass of gas is cooled by 100∘C100^{\circ}C100∘C at constant volume, 240 calories of heat is released. How many degrees of freedom does each molecule of this gas have (assume gas to be ideal)?
  1. (A)7
  2. (B)5
  3. (C)3
  4. (D)6

Correct answer: (D)

Step-by-step solution →
Q127·PhysicsSingle correctJEE Main 2020
Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is:
  1. (A)52RT\dfrac{5}{2}RT25​RT
  2. (B)32RT\dfrac{3}{2}RT23​RT
  3. (C)3RT3RT3RT
  4. (D)92RT\dfrac{9}{2}RT29​RT

Correct answer: (C)

Step-by-step solution →
Q128·PhysicsSingle correctJEE Main 2020
Consider two ideal diatomic gases A and B at some temperature T. Molecules of the gas A are rigid, and have a mass m. Molecules of the gas B have an additional vibrational mode and have mass m4\dfrac{m}{4}4m​. The ratio of the specific heats (CVAC_{V}^{A}CVA​ and CVBC_{V}^{B}CVB​) of gas A and B, respectively is
  1. (A)3 : 5
  2. (B)5 : 7
  3. (C)7 : 9
  4. (D)5 : 9

Correct answer: (B)

Step-by-step solution →
Q129·PhysicsSingle correctJEE Main 2020
The plot that depicts the behavior of the mean free time τ\tauτ (time between two successive collisions) for the molecules of an ideal gas, as a function of temperature (T), qualitatively, is: (Graphs are schematic and not drawn to scale)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q130·PhysicsSingle correctJEE Main 2020
Consider a mixture of n moles of helium gas and 2n moles of oxygen gas (molecules taken to be rigid) as an ideal gas. It CP_{P}P​/CV_{V}V​ value will be
  1. (A)19/13
  2. (B)40/27
  3. (C)67/45
  4. (D)23/15

Correct answer: (A)

Step-by-step solution →
Q131·PhysicsSingle correctJEE Main 2020
Two moles of an ideal gas with CPCV=53\dfrac{C_P}{C_V}=\dfrac{5}{3}CV​CP​​=35​ are mixed with 3 moles of another ideal gas with CPCV=43\dfrac{C_P}{C_V}=\dfrac{4}{3}CV​CP​​=34​. The value of CPCV\dfrac{C_P}{C_V}CV​CP​​ for the mixture is:
  1. (A)1.42
  2. (B)1.47
  3. (C)1.45
  4. (D)1.50

Correct answer: (A)

Step-by-step solution →
Q132·PhysicsMultiple correctJEE Advanced 2019
A small particle of mass m moving inside a heavy, hollow and straight tube along the tube axis undergoes elastic collision at two ends. The tube has no friction and it is closed at one end by a flat surface while the other end is fitted with a heavy movable flat piston as shown in figure. When the distance of the piston from closed end is L=L0L = L_0L=L0​ the particle speed is v=v0v = v_0v=v0​. The piston is moved inward at a very low speed V such that V<<dLLv0V << \frac{dL}{L}v_0V<<LdL​v0​, where dL is the infinitesimal displacement of the piston. which of the following statement(s) is/are correct ?
  1. (A)The particle's kinetic energy increases by a factor of 4 when the piston is moved inward from L0L_0L0​ to 12L0\frac{1}{2}L_021​L0​.
  2. (B)After each collision with the piston, the particle speed increases by 2V.
  3. (C)If the piston moves inward by dL, the particle speed increases by 2vdLL2v\frac{dL}{L}2vLdL​
  4. (D)The rate at which the particle strikes the piston is v/L

Correct answer: (A), (B)

Step-by-step solution →
Q133·PhysicsSingle correctJEE Main 2019
Two moles of helium gas is mixed with three moles of hydrogen molecules (taken to be rigid). What is the molar specific heat of mixture at constant volume? (R = 8.3 J/mol K)
  1. (A)17.4 J/mol K
  2. (B)15.7 J/mol K
  3. (C)19.7 J/mol K
  4. (D)21.6 J/mol K

Correct answer: (A)

Step-by-step solution →
Q134·PhysicsSingle correctJEE Main 2019
The number density of molecules of a gas depends on their distance r from the origin as, n(r)=n0e−αr4n(r) = n_{0}e^{-\alpha r^{4}}n(r)=n0​e−αr4. Then the total number of molecules is proportional to :
  1. (A)n0α−3/4n_{0}\alpha^{-3/4}n0​α−3/4
  2. (B)n0α−3n_{0}\alpha^{-3}n0​α−3
  3. (C)n0α1/4n_{0}\alpha^{1/4}n0​α1/4
  4. (D)n0 α1/2\sqrt{n_{0}}\,\alpha^{1/2}n0​​α1/2

Correct answer: (A)

Step-by-step solution →
Q135·PhysicsSingle correctJEE Main 2019
A cylinder with fixed capacity of 67.2 lit contains helium gas at STP. The amount of heat needed to raise the temperature of the gas by 20°C is: [Given that R = 8.31 J mol−1^{-1}−1 K−1^{-1}−1]
  1. (A)350 J
  2. (B)700 J
  3. (C)748 J
  4. (D)374 J

Correct answer: (C)

Step-by-step solution →
Q136·PhysicsSingle correctJEE Main 2019
When heat Q is supplied to a diatomic gas of rigid molecules at constant volume its temperature increases by ΔT. The heat required to produce the same change in temperature, at constant pressure is
  1. (A)32Q\dfrac{3}{2}Q23​Q
  2. (B)53Q\dfrac{5}{3}Q35​Q
  3. (C)75Q\dfrac{7}{5}Q57​Q
  4. (D)23Q\dfrac{2}{3}Q32​Q

Correct answer: (C)

Step-by-step solution →
Q137·PhysicsSingle correctJEE Main 2019
For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at 127°C. At 2 atm pressure and at 227°C, the rms speed of the molecules will be:
  1. (A)80 m/s
  2. (B)80580\sqrt{5}805​ m / s
  3. (C)100 m/s
  4. (D)1005100\sqrt{5}1005​ m / s

Correct answer: (D)

Step-by-step solution →
Q138·PhysicsSingle correctJEE Main 2019
The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth is closest to: [Boltzmans Constant kB=1.38×10−23k_B = 1.38 \times 10^{-23}kB​=1.38×10−23 J/K Avogadro number NA=6.02×1026N_A = 6.02 \times 10^{26}NA​=6.02×1026 /kg Radius of Earth: 6.4×1066.4 \times 10^{6}6.4×106 m Gravitation acceleration on Earth = 10 ms−2^{-2}−2]
  1. (A)800k
  2. (B)10410^{4}104 K
  3. (C)3×1053\times 10^{5}3×105
  4. (D)650 K

Correct answer: (B)

Step-by-step solution →
Q139·PhysicsSingle correctJEE Main 2019
A vertical closed cylinder is separated into two parts by a frictionless piston of mass m and of negligible thickness. The piston is free to move along the length of the cylinder .The length of the cylinder above the piston is l1_11​, and that below the piston is l2_22​, such that l1_11​ > l2_22​. Each part of the cylinder contains n moles of an ideal gas at equal temperature T. If the piston is stationary, its mass, m, will be given by: (R is universal gas constant and g is the acceleration due to gravity)
  1. (A)RTng[l1−3l2l1l2]\frac{RT}{ng}\left[\frac{l_1-3l_2}{l_1l_2}\right]ngRT​[l1​l2​l1​−3l2​​]
  2. (B)RTg[2l1+l2l1l2]\frac{RT}{g}\left[\frac{2l_1+l_2}{l_1l_2}\right]gRT​[l1​l2​2l1​+l2​​]
  3. (C)nRTng[1l2+1l1]\frac{nRT}{ng}\left[\frac{1}{l_2}+\frac{1}{l_1}\right]ngnRT​[l2​1​+l1​1​]
  4. (D)nRTg[l1−l2l1l2]\frac{nRT}{g}\left[\frac{l_1-l_2}{l_1l_2}\right]gnRT​[l1​l2​l1​−l2​​]

Correct answer: (D)

Step-by-step solution →
Q140·PhysicsSingle correctJEE Main 2019
An ideal gas is enclosed in a cylinder at pressure of 2 atm and temperature, 300 K. The mean time between two successive collisions is 6×10−86\times10^{-8}6×10−8s. If the pressure is doubled and temperature is increased to 500 K, the mean time between two successive collisions will be close to :
  1. (A)2×10−72\times10^{-7}2×10−7s
  2. (B)4×10−84\times10^{-8}4×10−8s
  3. (C)0.5×10−80.5\times10^{-8}0.5×10−8s
  4. (D)3×10−63\times10^{-6}3×10−6s

Correct answer: (B)

Step-by-step solution →
Q141·PhysicsSingle correctJEE Main 2019
A gas mixture consists of 3 moles of oxygen and 5 moles or argon at temperature T. Considering only translational and rotational modes, the total internal energy of the system is:
  1. (A)15 RT
  2. (B)12 RT
  3. (C)4 RT
  4. (D)20 RT

Correct answer: (A)

Step-by-step solution →
Q142·PhysicsSingle correctJEE Main 2019
A 15 g mass of nitrogen gas is enclosed in a vessel at a temperature 27°C. Amount of heat transferred to the gas, so that rms velocity of molecules is doubled, is about: [Take R = 8.3 J/K mole]
  1. (A)0.9 kJ
  2. (B)6 kJ
  3. (C)10 kJ
  4. (D)14 kJ

Correct answer: (C)

Step-by-step solution →
Q143·PhysicsSingle correctJEE Main 2019
A mixture of 2 moles of helium gas (atomic mass = 4 u), and 1 mole of argon gas (atomic mass = 40 u) is kept at 300 K in a container. The ratio of their rms speeds [Vrms(helium)Vrms(argon)]\left[\dfrac{V_{rms}(helium)}{V_{rms}(argon)}\right][Vrms​(argon)Vrms​(helium)​], is close to:
  1. (A)3.16
  2. (B)0.32
  3. (C)0.45
  4. (D)2.24

Correct answer: (A)

Step-by-step solution →
Q144·PhysicsMultiple correctJEE Advanced 2017
A flat plate is moving normal to its plane through a gas under the action of constant force FFF. The gas is kept at a very low pressure. The speed of the plate v is much less than the average speed u of the gas molecules. Which of the following options is/are true?
  1. (A)The resistive force experienced by the plate is proportional to v
  2. (B)The pressure difference between the leading and trailing faces of the plate is proportional to uv
  3. (C)The plate will continue to move with constant non-zero acceleration, at all times
  4. (D)At a later time the external force FFF balances the resistive force.

Correct answer: (A), (B), (D)

Step-by-step solution →
Q145·PhysicsMultiple correctJEE Advanced 2015
A container of fixed volume has a mixture of one mole of hydrogen and one mole of helium in equilibrium at temperature T. Assuming the gases are ideal, the correct statement(s) is(are)
  1. (A)The average energy per mole of the gas mixture is 2RT.
  2. (B)The ratio of speed of sound in the gas mixture to that in helium gas is 6/5\sqrt{6/5}6/5​.
  3. (C)The ratio of the rms speed of helium atoms to that of hydrogen molecules is 1/21/21/2.
  4. (D)The ratio of the rms speed of helium atoms to that of hydrogen molecules is 1/21/\sqrt{2}1/2​.

Correct answer: (A), (B), (D)

Step-by-step solution →
Q146·PhysicsSingle correctJEE Advanced 2013
Two non-reactive monoatomic ideal gases have their atomic masses in the ratio 2 : 3. The ratio of their partial pressures, when enclosed in a vessel kept at a constant temperature, is 4 : 3. The ratio of their densities is
  1. (A)1 : 4
  2. (B)1 : 2
  3. (C)6 : 9
  4. (D)8 : 9

Correct answer: (D)

Step-by-step solution →

Kinetic Theory of Gases — frequently asked

How many questions from Kinetic Theory of Gases appear in JEE?

Kinetic Theory of Gases has appeared in 135 of the last 186 JEE Main and JEE Advanced papers — about 73% of them — contributing 146 questions in total across those papers.

Is Kinetic Theory of Gases an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 73% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Kinetic Theory of Gases questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Physics chapters

  • Properties of Solids and Liquids 344
  • Current Electricity 309
  • Rotational Motion 266
  • Geometrical Optics 259
  • Kinematics 255
  • Magnetic Field of Current 211
  • Electromagnetic Waves 208
  • Thermodynamics 201

All 28 Physics chapters →

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