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Nuclei — JEE Previous Year Questions

Every Nuclei question asked in JEE Main and JEE Advanced across the last 186 papers — 140 questions, each with its correct answer. Free to read, no account needed.

Questions

140

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116/186

Appearance rate

62%

All 140 Nuclei questions

Most recent papers first.

Q1·PhysicsSingle correctJEE Advanced 2026
A nuclear reactor starts producing a radioactive nuclide XXX from t=0t = 0t=0, at a constant rate of α\alphaα per second. Each decay of XXX produces energy E0E_{0}E0​, which is utilized to heat a liquid of mass mmm and specific heat sss. Assuming no heat loss from the liquid and taking λ\lambdaλ as the decay constant of XXX, the rate of increase in the temperature of the liquid is:
  1. (A)αE0ms(1−e−λt)\frac{\alpha E_{0}}{ms}\left(1 - e^{-\lambda t}\right)msαE0​​(1−e−λt)
  2. (B)αE0ms(eλt−1)\frac{\alpha E_{0}}{ms}\left(e^{\lambda t} - 1\right)msαE0​​(eλt−1)
  3. (C)λE0ms(1−e−λt)\frac{\lambda E_{0}}{ms}\left(1 - e^{-\lambda t}\right)msλE0​​(1−e−λt)
  4. (D)E0ms(α−λe−λt)\frac{E_{0}}{ms}\left(\alpha - \lambda e^{-\lambda t}\right)msE0​​(α−λe−λt)

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correctJEE Main 2026
Two radioactive substances A and B of mass numbers 200 and 212 respectively, shows spontaneous α\alphaα-decay with same QQQ value of 1 MeV. The ratio of energies of α\alphaα-rays produced by A and B is ________.
  1. (A)25482650\dfrac{2548}{2650}26502548​
  2. (B)27062646\dfrac{2706}{2646}26462706​
  3. (C)25972600\dfrac{2597}{2600}26002597​
  4. (D)28622499\dfrac{2862}{2499}24992862​

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsNumericalJEE Main 2026
The energy released when 717.13\frac{7}{17.13}17.137​ kg of 37^{7}_{3}37​Li is converted into 24^{4}_{2}24​He by proton bombardment is α×1032\alpha \times 10^{32}α×1032 eV. The value of α\alphaα is _______. (Nearest integer) (Mass of 37^{7}_{3}37​Li = 7.0183 u, mass of 24^{4}_{2}24​He = 4.004 u, mass of proton = 1.008 u and 1 u = 931 MeV/c2^{2}2 and Avogadro number = 6.0×10236.0 \times 10^{23}6.0×1023)

Correct answer: 6

Step-by-step solution →
Q4·PhysicsSingle correctJEE Main 2026
The energy released if hydrogen atoms are combined to form 24{}^{4}_{2}24​He is __________ MeV. (Take binding energies per nucleon of 12{}^{2}_{1}12​H and 24{}^{4}_{2}24​He as 1.1 MeV and 7.2 MeV, respectively)
  1. (A)6.1
  2. (B)24.4
  3. (C)26.6
  4. (D)5

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correctJEE Main 2026
Assuming the experimental mass of 612C^{12}_{6}C612​C as 12 u, the mass defect of 612C^{12}_{6}C612​C atom is ________ MeV/c2c^2c2. (Mass of proton =1.00727= 1.00727=1.00727 u, mass of neutron =1.00866= 1.00866=1.00866 u, 1 u =931.5= 931.5=931.5 MeV/c2c^2c2 and ccc is the speed of the light in vacuum).
  1. (A)127.5
  2. (B)89.03
  3. (C)272.0
  4. (D)92.0

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correctJEE Main 2026
Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10 . If the binding energy per nucleon for the mass numbers 3, 4 and 10 are 5.6 MeV, 7.4 MeV and 6.1 MeV, respectively, then in the process, ΔMc2=\Delta Mc^2 =ΔMc2= _____ MeV.
  1. (A)6.9
  2. (B)7.9
  3. (C)2.2
  4. (D)4.3

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correctJEE Main 2026
The binding energy per nucleon of 83209Bi^{209}_{83}Bi83209​Bi is ________ MeV. [[[Take m(83209Bi)=208.980388 um(^{209}_{83}Bi) = 208.980388\,um(83209​Bi)=208.980388u, mp=1.007825 um_p = 1.007825\,ump​=1.007825u, mn=1.008665 um_n = 1.008665\,umn​=1.008665u, 1 u=931 MeV/c2]1\,u = 931\,\mathrm{MeV}/c^2]1u=931MeV/c2]
  1. (A)7.48
  2. (B)7.84
  3. (C)8.79
  4. (D)6.94

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correctJEE Main 2026
A nucleus has mass number α and radius RαR_{\alpha}Rα​. Another nucleus has mass number β and radius RβR_{\beta}Rβ​. If β = 8α then Rα/RβR_{\alpha}/R_{\beta}Rα​/Rβ​ is :
  1. (A)2
  2. (B)8
  3. (C)1
  4. (D)0.5

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correctJEE Main 2026
Given below are two statements: Statement I : For all elements, greater the mass of the nucleus, greater is the binding energy per nucleon. Statement II : For all elements, nuclei with less binding energy per nucleon transforms to nuclei with greater binding energy per nucleon. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correctJEE Main 2026
The binding energy for the following nuclear reactions are expressed in MeV. 2He3+0n1→2He4+20_2\text{He}^3 + _0\text{n}^1 \rightarrow _2\text{He}^4 + 202​He3+0​n1→2​He4+20 MeV 2He4+0n1→2He5−0.9_2\text{He}^4 + _0\text{n}^1 \rightarrow _2\text{He}^5 - 0.92​He4+0​n1→2​He5−0.9 MeV If X3X_3X3​, X4X_4X4​, X5X_5X5​ denote the stability of 2He3_2\text{He}^32​He3, 2He4_2\text{He}^42​He4 and 2He5_2\text{He}^52​He5, respectively, then the correct order is :
  1. (A)X4>X5>X3X_4 > X_5 > X_3X4​>X5​>X3​
  2. (B)X4=X5=X3X_4 = X_5 = X_3X4​=X5​=X3​
  3. (C)X4>X5<X3X_4 > X_5 < X_3X4​>X5​<X3​
  4. (D)X4<X5<X3X_4 < X_5 < X_3X4​<X5​<X3​

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsNumericalJEE Main 2026
The average energy released per fission for the nucleus of 92235^{235}_{92}92235​U is 190 MeV. When all the atoms of 47 g pure 92235^{235}_{92}92235​U undergo fission process, the energy released is α×1023\alpha \times 10^{23}α×1023 MeV. The value of α is ________. (Avogadro Number = 6×10236 \times 10^{23}6×1023 per mole)

Correct answer: 228

Step-by-step solution →
Q12·PhysicsSingle correctJEE Main 2026
Which of the following pair of nuclei are isobars of the element ?
  1. (A)12H^{2}_{1}\mathrm{H}12​H and 13H^{3}_{1}\mathrm{H}13​H
  2. (B)92236U^{236}_{92}\mathrm{U}92236​U and 92238U^{238}_{92}\mathrm{U}92238​U
  3. (C)80198Hg^{198}_{80}\mathrm{Hg}80198​Hg and 79197Au^{197}_{79}\mathrm{Au}79197​Au
  4. (D)13H^{3}_{1}\mathrm{H}13​H and 23H^{3}_{2}\mathrm{H}23​H

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correctJEE Main 2026
The minimum frequency of photon required to break a particle of mass 15.348 amu into 4α particles is ____ kHz. [mass of He nucleus = 4.002 amu, 1 amu = 1.66×10−271.66 \times 10^{-27}1.66×10−27 kg, h = 6.6×10−346.6 \times 10^{-34}6.6×10−34 J.s and c = 3×1083 \times 10^{8}3×108 m/s]
  1. (A)9×10199 \times 10^{19}9×1019
  2. (B)9×10209 \times 10^{20}9×1020
  3. (C)14.94×102014.94 \times 10^{20}14.94×1020
  4. (D)14.94×101914.94 \times 10^{19}14.94×1019

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correctJEE Main 2025
For a nucleus of mass number AAA and radius RRR, the mass density of nucleus can be represented as:
  1. (A)A3A^{3}A3
  2. (B)A1/3A^{1/3}A1/3
  3. (C)A2/3A^{2/3}A2/3
  4. (D)Independent of AAA

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correctJEE Main 2025
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The density of the copper (2964Cu)\left({}^{64}_{29}\mathrm{Cu}\right)(2964​Cu) nucleus is greater than that of the carbon (612C)\left({}^{12}_{6}\mathrm{C}\right)(612​C) nucleus. Reason (R): The nucleus of mass number A has a radius proportional to A1/3A^{1/3}A1/3. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)(A) is correct but (R) is not correct
  2. (B)(A) is not correct but (R) is correct
  3. (C)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  4. (D)Both (A) and (R) are correct but (R) is not the correct explanation of (A)

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correctJEE Main 2025
A radioactive material P first decays into Q and then Q decays to non-radioactive material R. Which of the following figure represents the time dependent mass of P, Q and R?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correctJEE Main 2025
Match the LIST-I (Nuclear / chemical reaction) with LIST-II (Type of reaction). Choose the correct answer from the options given below:
LIST-I (Nuclear / chemical reaction)LIST-II (Type of reaction)
A.01n+92235U→54140Xe+3894Sr+201n{}^{1}_{0}n+{}^{235}_{92}U\to{}^{140}_{54}Xe+{}^{94}_{38}Sr+2{}^{1}_{0}n01​n+92235​U→54140​Xe+3894​Sr+201​nI.Chemical reaction
B.2H2+O2→2H2O2H_2+O_2\to 2H_2O2H2​+O2​→2H2​OII.Fusion with +ve Q value
C.12H+12H→23He+01n{}^{2}_{1}H+{}^{2}_{1}H\to{}^{3}_{2}He+{}^{1}_{0}n12​H+12​H→23​He+01​nIII.Fission
D.11H+13H→12H+12H{}^{1}_{1}H+{}^{3}_{1}H\to{}^{2}_{1}H+{}^{2}_{1}H11​H+13​H→12​H+12​HIV.Fusion with -ve Q value
  1. (A)(A)-II, (B)-I, (C)-III, (D)-IV
  2. (B)(A)-III, (B)-I, (C)-II, (D)-IV
  3. (C)(A)-II, (B)-I, (C)-IV, (D)-III
  4. (D)(A)-III, (B)-I, (C)-IV, (D)-II

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correctJEE Main 2025
Energy released when two deuterons (1H2)(_1H^2)(1​H2) fuse to form a helium nucleus (2He4)(_2He^4)(2​He4) is: (Given: Binding energy per nucleon of 1H2=1.1_1H^2=1.11​H2=1.1 MeV and binding energy per nucleon of 2He4=7.0_2He^4=7.02​He4=7.0 MeV)
  1. (A)8.1 MeV
  2. (B)5.9 MeV
  3. (C)23.6 MeV
  4. (D)26.8 MeV

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correctJEE Main 2025
Choose the correct nuclear process from the below options [p: proton, n: neutron, e−e^-e−: electron, e+e^+e+: positron, ν\nuν: neutrino, νˉ\bar{\nu}νˉ: antineutrino]
  1. (A)n→p+e−+νˉn\to p+e^-+\bar{\nu}n→p+e−+νˉ
  2. (B)n→p+e−+νn\to p+e^-+\nun→p+e−+ν
  3. (C)n→p+e++νˉn\to p+e^++\bar{\nu}n→p+e++νˉ
  4. (D)n→p+e++νn\to p+e^++\nun→p+e++ν

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correctJEE Main 2025
A radioactive nucleus n2n_2n2​ has 3 times the decay constant as compared to the decay constant of another radioactive nucleus n1n_1n1​. If initial number of both nuclei are the same, what is the ratio of number of nuclei of n2n_2n2​ to the number of nuclei of n1n_1n1​, after one half-life of n1n_1n1​?
  1. (A)14\dfrac{1}{4}41​
  2. (B)18\dfrac{1}{8}81​
  3. (C)4
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsSingle correctJEE Main 2025
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : The binding energy per nucleon is found to be practically independent of the atomic number A, for nuclei with mass numbers between 30 and 170. Reason (R) : Nuclear force is long range. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)(A) is false but (R) is true
  2. (B)(A) is true but (R) is false
  3. (C)Both (A) and (R) are true and (R) is the correct explanation of (A)
  4. (D)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

Correct answer: (B)

Step-by-step solution →
Q22·PhysicsSingle correctJEE Main 2024
The energy released in the fusion of 2 kg of hydrogen deep in the sun is EHE_{H}EH​ and the energy released in the fission of 2 kg of 235^{235}235U is EUE_{U}EU​. The ratio EHEU\dfrac{E_{H}}{E_{U}}EU​EH​​ is approximately: (Consider the fusion reaction as 4 11H+2e−→ 24He+2ν+6γ+26.74\,^{1}_{1}H+2e^{-}\rightarrow\,^{4}_{2}He+2\nu+6\gamma+26.7411​H+2e−→24​He+2ν+6γ+26.7 MeV; energy released in the fission reaction of 235^{235}235U is 200 MeV per fission and NA=6.023×1023N_{A}=6.023\times10^{23}NA​=6.023×1023)
  1. (A)9.13
  2. (B)5.04
  3. (C)7.62
  4. (D)25.6

Correct answer: (C)

Step-by-step solution →
Q23·PhysicsSingle correctJEE Main 2024
The energy equivalent of 1g of substance is:
  1. (A)11.2×102411.2 \times 10^{24}11.2×1024 MeV
  2. (B)5.6×10125.6 \times 10^{12}5.6×1012 MeV
  3. (C)5.6 eV
  4. (D)5.6×10265.6 \times 10^{26}5.6×1026 MeV

Correct answer: (D)

Step-by-step solution →
Q24·PhysicsNumericalJEE Main 2024
A star has 100% helium composition. It starts to convert three 4He^{4}\mathrm{He}4He into one 12C^{12}\mathrm{C}12C via triple alpha process as 4He+4He+4He→12C+Q^{4}\mathrm{He}+{}^{4}\mathrm{He}+{}^{4}\mathrm{He}\to{}^{12}\mathrm{C}+Q4He+4He+4He→12C+Q. The mass of the star is 2.0×10322.0\times10^{32}2.0×1032 kg and it generates energy at the rate of 5.808×10305.808\times10^{30}5.808×1030 W. The rate of converting these 4He^{4}\mathrm{He}4He to 12C^{12}\mathrm{C}12C is n×1042 s−1n\times10^{42}\ \mathrm{s^{-1}}n×1042 s−1, where nnn is ______. [Take, mass of 4He=4.0026^{4}\mathrm{He}=4.00264He=4.0026 u, mass of 12C=12^{12}\mathrm{C}=1212C=12 u]

Correct answer: 5

Step-by-step solution →
Q25·PhysicsSingle correctJEE Main 2024
In a hypothetical fission reaction 92X236→ 56Y141+ 36Z92+3R_{92}X^{236}\to\,_{56}Y^{141}+\,_{36}Z^{92}+3R92​X236→56​Y141+36​Z92+3R. The identity of emitted particles (R) is:
  1. (A)Proton
  2. (B)Electron
  3. (C)Neutron
  4. (D)γ\gammaγ-radiations

Correct answer: (C)

Step-by-step solution →
Q26·PhysicsSingle correctJEE Main 2024
If MoM_oMo​ is the mass of isotope 512B_5^{12}B512​B, MpM_pMp​ and MnM_nMn​ are the masses of proton and neutron, then nuclear binding energy of the isotope is:
  1. (A)(5Mp+7Mn−Mo)C2(5M_p+7M_n-M_o)C^2(5Mp​+7Mn​−Mo​)C2
  2. (B)(Mo−5Mp)C2(M_o-5M_p)C^2(Mo​−5Mp​)C2
  3. (C)(Mo−12Mn)C2(M_o-12M_n)C^2(Mo​−12Mn​)C2
  4. (D)(Mo−5Mp−7Mn)C2(M_o-5M_p-7M_n)C^2(Mo​−5Mp​−7Mn​)C2

Correct answer: (A)

Step-by-step solution →
Q27·PhysicsSingle correctJEE Main 2024
Binding energy of a certain nucleus is 18×10818\times10^818×108 J. How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus:
  1. (A)0.02 μg0.02\,\mu g0.02μg
  2. (B)20 μg20\,\mu g20μg
  3. (C)2 μg2\,\mu g2μg
  4. (D)10 μg10\,\mu g10μg

Correct answer: (B)

Step-by-step solution →
Q28·PhysicsNumericalJEE Main 2024
If three helium nuclei combine to form a carbon nucleus, then the energy released in this reaction is ___ ×10−2\times10^{-2}×10−2 MeV. (Given 1 u=931 MeV/c21\ \text{u} = 931\ \text{MeV}/c^21 u=931 MeV/c2; atomic mass of helium = 4.002603 u; mass of carbon-12 = 12 u.)

Correct answer: 727

Step-by-step solution →
Q29·PhysicsNumericalJEE Main 2024
The disintegration energy Q for the nuclear fission of 235U→140Ce+94Zr+2n^{235}\text{U}\to{}^{140}\text{Ce}+{}^{94}\text{Zr}+2n235U→140Ce+94Zr+2n is ______ MeV. Given atomic masses are: 235U:235.0439 u^{235}\text{U}:235.0439\,u235U:235.0439u, 140Ce:139.9054 u^{140}\text{Ce}:139.9054\,u140Ce:139.9054u, 94Zr:93.9063 u^{94}\text{Zr}:93.9063\,u94Zr:93.9063u, n:1.00866 un:1.00866\,un:1.00866u. Value of c2=931 MeV/uc^2=931\ \text{MeV/u}c2=931 MeV/u.

Correct answer: 208

Step-by-step solution →
Q30·PhysicsSingle correctJEE Main 2024
Which of the following nuclear fragments corresponding to nuclear fission between neutron (01n)({}^1_0n)(01​n) and uranium isotope (92235U)({}^{235}_{92}U)(92235​U) is correct:
  1. (A)56144Ba+3689Kr+401n{}^{144}_{56}Ba+{}^{89}_{36}Kr+4{}^1_0n56144​Ba+3689​Kr+401​n
  2. (B)54140Xe+3894Sr+301n{}^{140}_{54}Xe+{}^{94}_{38}Sr+3{}^1_0n54140​Xe+3894​Sr+301​n
  3. (C)51153Sb+4199Nb+301n{}^{153}_{51}Sb+{}^{99}_{41}Nb+3{}^1_0n51153​Sb+4199​Nb+301​n
  4. (D)56144Ba+3689Kr+301n{}^{144}_{56}Ba+{}^{89}_{36}Kr+3{}^1_0n56144​Ba+3689​Kr+301​n

Correct answer: (D)

Step-by-step solution →
Q31·PhysicsNumericalJEE Main 2024
The radius of a nucleus of mass number 646464 is 4.84.84.8 fermi. Then the mass number of another nucleus having radius of 444 fermi is 1000x\dfrac{1000}{x}x1000​, where xxx is ___

Correct answer: 27

Step-by-step solution →
Q32·PhysicsSingle correctJEE Main 2024
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is:
  1. (A)24
  2. (B)32
  3. (C)40
  4. (D)20

Correct answer: (A)

Step-by-step solution →
Q33·PhysicsNumericalJEE Main 2024
The mass defect in a particular reaction is 0.4 g. The amount of energy liberated is n×107n\times10^7n×107 kWh, where n=n=n= ______. (speed of light = 3×1083\times10^83×108 m/s)

Correct answer: 1

Step-by-step solution →
Q34·PhysicsNumericalJEE Main 2024
A nucleus has mass number A1A_1A1​ and volume V1V_1V1​. Another nucleus has mass number A2A_2A2​ and volume V2V_2V2​. If relation between mass number is A2=4A1A_2=4A_1A2​=4A1​, then V2V1=\dfrac{V_2}{V_1}=V1​V2​​= ______.

Correct answer: 4

Step-by-step solution →
Q35·PhysicsSingle correctJEE Main 2024
In a nuclear fission reaction of an isotope of mass M, three similar daughter nuclei of same mass are formed. The speed of a daughter nuclei in terms of mass defect ΔM\Delta MΔM will be:
  1. (A)2cΔMM\sqrt{\dfrac{2c\Delta M}{M}}M2cΔM​​
  2. (B)ΔMc23\dfrac{\Delta Mc^2}{3}3ΔMc2​
  3. (C)c2ΔMMc\sqrt{\dfrac{2\Delta M}{M}}cM2ΔM​​
  4. (D)c3ΔMMc\sqrt{\dfrac{3\Delta M}{M}}cM3ΔM​​

Correct answer: (C)

Step-by-step solution →
Q36·PhysicsSingle correctJEE Main 2024
The explosive in a Hydrogen bomb is a mixture of 1H2_1H^21​H2, 1H3_1H^31​H3 and 3Li6_3Li^63​Li6 in some condensed form. The chain reaction is given by 3Li6+0n1→2He4+1H3_3Li^6+_0n^1\to{}_2He^4+_1H^33​Li6+0​n1→2​He4+1​H3 ; 1H2+1H3→2He4+0n1_1H^2+_1H^3\to{}_2He^4+_0n^11​H2+1​H3→2​He4+0​n1. During the explosion the energy released is approximately [Given : M(3Li6_3Li^63​Li6) = 6.01690 amu. M(1H2_1H^21​H2) = 2.01471 amu. M(2He4_2He^42​He4) = 4.00388 amu, and 1 amu = 931.5 MeV]
  1. (A)28.1228.1228.12 MeV
  2. (B)12.6412.6412.64 MeV
  3. (C)16.4816.4816.48 MeV
  4. (D)22.2222.2222.22 MeV

Correct answer: (D)

Step-by-step solution →
Q37·PhysicsNumericalJEE Main 2024
In a nuclear fission process, a high mass nuclide (A≈236A\approx 236A≈236) with binding energy 7.6 MeV/Nucleon dissociated into middle mass nuclides (A≈118A\approx 118A≈118), having binding energy of 8.6 MeV/Nucleon. The energy released in the process would be __________ MeV.

Correct answer: 236

Step-by-step solution →
Q38·PhysicsSingle correctJEE Main 2024
The atomic mass of 6C12_6\text{C}^{12}6​C12 is 12.000000 u and that of 6C13_6\text{C}^{13}6​C13 is 13.003354 u. The required energy to remove a neutron from 6C13_6\text{C}^{13}6​C13, if mass of neutron is 1.008665 u, will be :
  1. (A)62.5 MeV
  2. (B)6.25 MeV
  3. (C)4.95 MeV
  4. (D)49.5 MeV

Correct answer: (C)

Step-by-step solution →
Q39·PhysicsIntegerJEE Advanced 2023
In a radioactive decay process, the activity is defined as A=−dNdtA = -\frac{dN}{dt}A=−dtdN​, where N(t) is the number of radioactive nuclei at time t. Two radioactive sources, S1S_1S1​ and S2S_2S2​ have same activity at time ttt = 0. At a later time, the activities of S1S_1S1​ and S2S_2S2​ are A1A_1A1​ and A2A_2A2​, respectively. When S1S_1S1​ and S2S_2S2​ have just completed their 3rd^{rd}rd and 7th^{th}th half-lives, respectively, the ratio A1/A2A_1/A_2A1​/A2​ is ___________.

Correct answer: 16

Step-by-step solution →
Q40·PhysicsSingle correctJEE Advanced 2023
List-I shows different radioactive decay processes and List-II provides possible emitted particles. Match each entry in List-I with an appropriate entry from List-II, and choose the correct option.
List-IList-II
P.92238U→91234Pa{}^{238}_{92}\mathrm{U} \rightarrow {}^{234}_{91}\mathrm{Pa}92238​U→91234​Pa1.one α\alphaα particle and one β+\beta^{+}β+ particle
Q.82214Pb→82210Pb{}^{214}_{82}\mathrm{Pb} \rightarrow {}^{210}_{82}\mathrm{Pb}82214​Pb→82210​Pb2.three β−\beta^{-}β− particles and one α\alphaα particle
R.81210Tℓ→82206Pb{}^{210}_{81}\mathrm{T}\ell \rightarrow {}^{206}_{82}\mathrm{Pb}81210​Tℓ→82206​Pb3.two β−\beta^{-}β− particles and one α\alphaα particle
S.91228Pa→88224Ra{}^{228}_{91}\mathrm{Pa} \rightarrow {}^{224}_{88}\mathrm{Ra}91228​Pa→88224​Ra4.one α\alphaα particle and one β−\beta^{-}β− particle
5.one α\alphaα particle and two β+\beta^{+}β+ particles
  1. (A)P →\rightarrow→ 4, Q →\rightarrow→ 3, R →\rightarrow→ 2, S →\rightarrow→ 1
  2. (B)P →\rightarrow→ 4, Q →\rightarrow→ 1, R →\rightarrow→ 2, S →\rightarrow→ 5
  3. (C)P →\rightarrow→ 5, Q →\rightarrow→ 3, R →\rightarrow→ 1, S →\rightarrow→ 4
  4. (D)P →\rightarrow→ 5, Q →\rightarrow→ 1, R →\rightarrow→ 3, S →\rightarrow→ 2

Correct answer: (A)

Step-by-step solution →
Q41·PhysicsSingle correctJEE Main 2023
The half-life of a radioactive nucleus is 5 years, The fraction of the original sample that would decay in 15 years is :
  1. (A)18\frac{1}{8}81​
  2. (B)14\frac{1}{4}41​
  3. (C)78\frac{7}{8}87​
  4. (D)34\frac{3}{4}43​

Correct answer: (C)

Step-by-step solution →
Q42·PhysicsSingle correctJEE Main 2023
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The binding energy per nucleon is practically independent of the atomic number for nuclei of mass number in the range 30 to 170. Reason R: Nuclear force is short ranged. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both A and R are true but R is NOT the correct explanation of A
  2. (B)A is true but R is false
  3. (C)A is false but R is true
  4. (D)Both A and R are true and R is the correct explanation of A

Correct answer: (D)

Step-by-step solution →
Q43·PhysicsSingle correctJEE Main 2023
92238U→90234 ⁣Th+24 ⁣D+Q^{238}_{92}U\to ^{234}_{90}\!Th+^{4}_{2}\!D+Q92238​U→90234​Th+24​D+Q. In the above nuclear reaction, the approximate amount of energy released will be: [Given, mass of 92238U=238.05079×931.5 MeV/c2^{238}_{92}U=238.05079\times 931.5\,MeV/c^{2}92238​U=238.05079×931.5MeV/c2, mass of 90234Th=234.04363×931.5 MeV/c2^{234}_{90}Th=234.04363\times 931.5\,MeV/c^{2}90234​Th=234.04363×931.5MeV/c2, mass of 24D=4.00260×931.5 MeV/c2^{4}_{2}D=4.00260\times 931.5\,MeV/c^{2}24​D=4.00260×931.5MeV/c2]
  1. (A)3.82 MeV3.82\,MeV3.82MeV
  2. (B)5.9 MeV5.9\,MeV5.9MeV
  3. (C)2.12 MeV2.12\,MeV2.12MeV
  4. (D)4.25 MeV4.25\,MeV4.25MeV

Correct answer: (D)

Step-by-step solution →
Q44·PhysicsNumericalJEE Main 2023
Consider an example of alpha decay 92238U→90234Th+24He+Q_{92}^{238}U\rightarrow{}_{90}^{234}Th+{}_2^4He+Q92238​U→90234​Th+24​He+Q. Given: 92238U=238.05060u_{92}^{238}U=238.05060u92238​U=238.05060u, 90234Th=234.04360u_{90}^{234}Th=234.04360u90234​Th=234.04360u, 24He=4.00260u_2^4He=4.00260u24​He=4.00260u, and 1u=931.5 MeVc21u=931.5\,\dfrac{MeV}{c^2}1u=931.5c2MeV​. The energy released (Q) during the alpha decay of 92238U_{92}^{238}U92238​U is _________ MeV.

Correct answer: 4

Step-by-step solution →
Q45·PhysicsSingle correctJEE Main 2023
Two radioactive elements A and B initially have same number of atoms. The half life of A is same as the average life of B. If λA\lambda_AλA​ and λB\lambda_BλB​ are decay constants of A and B respectively, then choose the correct relation from the given options.
  1. (A)λA=λB\lambda_A = \lambda_BλA​=λB​
  2. (B)λA=2λB\lambda_A = 2\lambda_BλA​=2λB​
  3. (C)λA=λBln⁡2\lambda_A = \lambda_B \ln 2λA​=λB​ln2
  4. (D)λAln⁡2=λB\lambda_A \ln 2 = \lambda_BλA​ln2=λB​

Correct answer: (C)

Step-by-step solution →
Q46·PhysicsNumericalJEE Main 2023
A nucleus disintegrates into two nuclear parts, in such a way that the ratio of their nuclear sizes is 1:21/31:2^{1/3}1:21/3. Their respective speeds have a ratio of n:1n:1n:1. The value of n is ____.

Correct answer: 2

Step-by-step solution →
Q47·PhysicsSingle correctJEE Main 2023
The half-life of a radioactive substance is T. The time taken for disintegrating 78\tfrac{7}{8}87​th part of its original mass will be:
  1. (A)3T3T3T
  2. (B)8T8T8T
  3. (C)TTT
  4. (D)2T2T2T

Correct answer: (A)

Step-by-step solution →
Q48·PhysicsNumericalJEE Main 2023
The decay constant for a radioactive nuclide is 1.5×10−51.5\times10^{-5}1.5×10−5 s−1^{-1}−1. Atomic weight of the substance is 60 g mole−1^{-1}−1, (NA=6×1023)(N_A=6\times10^{23})(NA​=6×1023). The activity of 1.0 µg of the substance is _________ ×1010\times10^{10}×1010 Bq.

Correct answer: 15

Step-by-step solution →
Q49·PhysicsSingle correctJEE Main 2023
A radioactive material is reduced to 18\dfrac{1}{8}81​ of its original amount in 3 days. If 8×10−38\times10^{-3}8×10−3 kg of the material is left after 5 days, the initial amount of the material is
  1. (A)64 g
  2. (B)40 g
  3. (C)32 g
  4. (D)256 g

Correct answer: (D)

Step-by-step solution →
Q50·PhysicsNumericalJEE Main 2023
A nucleus with mass number 242 and binding energy per nucleon as 7.6 MeV7.6\,\text{MeV}7.6MeV breaks into fragment each with mass number 121. If each fragment nucleus has binding energy per nucleon as 8.1 MeV8.1\,\text{MeV}8.1MeV, the total gain in binding energy is ______ MeV\text{MeV}MeV

Correct answer: 121

Step-by-step solution →
Q51·PhysicsSingle correctJEE Main 2023
For a nucleus ZAX^{A}_{Z}XZA​X having mass number A and atomic number Z: A. The surface energy per nucleon (bs)=a1A2/3(b_{s}) = a_{1}A^{2/3}(bs​)=a1​A2/3. B. The Coulomb contribution to the binding energy bc=−a2Z(Z−1)A4/3b_{c} = -a_{2}\dfrac{Z(Z-1)}{A^{4/3}}bc​=−a2​A4/3Z(Z−1)​. C. The volume energy bv=a3Ab_{v} = a_{3}Abv​=a3​A. D. Decrease in the binding energy is proportional to surface area. E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons, (a1,a2(a_{1}, a_{2}(a1​,a2​ and a3a_{3}a3​ are constants). Choose the most appropriate answer from the options given below:
  1. (A)C, D only
  2. (B)B, C, E only
  3. (C)A, B, C, D only
  4. (D)B, C only

Correct answer: (A)

Step-by-step solution →
Q52·PhysicsSingle correctJEE Main 2023
The mass of proton, neutron and helium nucleus are respectively 1.0073u1.0073u1.0073u, 1.0087u1.0087u1.0087u and 4.0015u4.0015u4.0015u. The binding energy of helium nucleus is:
  1. (A)28.428.428.4 MeV
  2. (B)56.856.856.8 MeV
  3. (C)14.214.214.2 MeV
  4. (D)7.17.17.1 MeV

Correct answer: (A)

Step-by-step solution →
Q53·PhysicsNumericalJEE Main 2023
Nucleus A having Z=17Z=17Z=17 and equal number of protons and neutrons has 1.21.21.2 MeV binding energy per nucleon. Another nucleus B of Z=12Z=12Z=12 has total 262626 nucleons and 1.81.81.8 MeV binding energy per nucleons. The difference of binding energy of B and A will be _________ MeV.

Correct answer: 6

Step-by-step solution →
Q54·PhysicsSingle correctJEE Main 2023
A free neutron decays into a proton but a free proton does not decay into neutron. This is because
  1. (A)proton is a charged particle
  2. (B)neutron is an uncharged particle
  3. (C)neutron is a composite particle made of a proton and an electron
  4. (D)neutron has larger rest mass than proton

Correct answer: (D)

Step-by-step solution →
Q55·PhysicsNumericalJEE Main 2023
A radioactive nucleus decays by two different processes. The half life of the first process is 5 minutes and that of the second process is 30 s. The effective half-life of the nucleus is calculated to be α11\dfrac{\alpha}{11}11α​ s. The value of α\alphaα is _______.

Correct answer: 300

Step-by-step solution →
Q56·PhysicsSingle correctJEE Main 2023
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The nuclear density of nuclides 510B^{10}_{5}B510​B, 36Li^{6}_{3}Li36​Li, 2656Fe^{56}_{26}Fe2656​Fe, 1020Ne^{20}_{10}Ne1020​Ne and 83209Bi^{209}_{83}Bi83209​Bi can be arranged as ρBiN>ρFeN>ρNeN>ρBN>ρLiN\rho^{N}_{Bi}>\rho^{N}_{Fe}>\rho^{N}_{Ne}>\rho^{N}_{B}>\rho^{N}_{Li}ρBiN​>ρFeN​>ρNeN​>ρBN​>ρLiN​. Reason R: The radius R of a nucleus is related to its mass number A as R=R0A1/3R=R_0 A^{1/3}R=R0​A1/3, where R0R_0R0​ is a constant. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is false but R is true
  2. (B)A is true but R is false
  3. (C)Both A and R are true but R is NOT the correct explanation of A
  4. (D)Both A and R are true and R is the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q57·PhysicsNumericalJEE Main 2023
A radioactive element 92242X_{92}^{242}X92242​X emits two α\alphaα-particles, one electron and two positrons. The product nucleus is represented by P234Y_{P}^{234}YP234​Y. The value of PPP is ________ .

Correct answer: 87

Step-by-step solution →
Q58·PhysicsSingle correctJEE Main 2023
If a radioactive element having half-life of 30 min is undergoing beta decay, the fraction of radioactive element remains undecayed after 90 min will be:
  1. (A)18\dfrac{1}{8}81​
  2. (B)12\dfrac{1}{2}21​
  3. (C)14\dfrac{1}{4}41​
  4. (D)116\dfrac{1}{16}161​

Correct answer: (A)

Step-by-step solution →
Q59·PhysicsSingle correctJEE Main 2023
Substance AAA has atomic mass number 161616 and half-life of 111 day. Another substance BBB has atomic mass number 323232 and half life of 12\dfrac1221​ day. If both AAA and BBB simultaneously start undergo radio activity at the same time with initial mass 320 g320\,g320g each, how many total atoms of AAA and BBB combined would be left after 222 days.
  1. (A)3.38×10243.38\times10^{24}3.38×1024
  2. (B)1.69×10241.69\times10^{24}1.69×1024
  3. (C)6.76×10246.76\times10^{24}6.76×1024
  4. (D)6.76×10236.76\times10^{23}6.76×1023

Correct answer: (A)

Step-by-step solution →
Q60·PhysicsSingle correctJEE Main 2023
The ratio of the density of oxygen nucleus (816O^{16}_{8}O816​O) and helium nucleus (24He^{4}_{2}He24​He) is:
  1. (A)4:14:14:1
  2. (B)2:12:12:1
  3. (C)1:11:11:1
  4. (D)8:18:18:1

Correct answer: (C)

Step-by-step solution →
Q61·PhysicsNumericalJEE Main 2023
A nucleus disintegrates into two smaller parts, which have their velocities in the ratio 3:23:23:2. The ratio of their nuclear sizes will be (x3)13\left(\frac{x}{3}\right)^{\frac{1}{3}}(3x​)31​. The value of 'xxx' is:

Correct answer: 2

Step-by-step solution →
Q62·PhysicsSingle correctJEE Main 2023
Consider the following radioactive decay process: 84218A→αA1→β−A2→γA3→αA4→β+A5→γA6{}^{218}_{84}A \xrightarrow{\alpha} A_1 \xrightarrow{\beta^-} A_2 \xrightarrow{\gamma} A_3 \xrightarrow{\alpha} A_4 \xrightarrow{\beta^+} A_5 \xrightarrow{\gamma} A_684218​Aα​A1​β−​A2​γ​A3​α​A4​β+​A5​γ​A6​. The mass number and the atomic number of A6A_6A6​ are given by:
  1. (A)210 and 84
  2. (B)210 and 82
  3. (C)211 and 80
  4. (D)210 and 80

Correct answer: (D)

Step-by-step solution →
Q63·PhysicsNumericalJEE Main 2023
Assume that protons and neutrons have equal masses. Mass of a nucleon is 1.6×10−271.6\times10^{-27}1.6×10−27 kg and radius of nucleus is 1.5×10−15A1/31.5\times10^{-15}A^{1/3}1.5×10−15A1/3 m. The approximate ratio of the nuclear density and water density is n×1013n\times10^{13}n×1013. The value of nnn is _______ .

Correct answer: 11

Step-by-step solution →
Q64·PhysicsNumericalJEE Main 2023
The energy released per fission of nucleus of 240X^{240}X240X is 200200200 MeV. The energy released if all the atoms in 120120120 g of pure 240X^{240}X240X undergo fission is _________ ×1025\times10^{25}×1025 MeV (Given NA=6×1023N_A=6\times10^{23}NA​=6×1023)

Correct answer: 6

Step-by-step solution →
Q65·PhysicsNumericalJEE Advanced 2022
The minimum kinetic energy needed by an alpha particle to cause the nuclear reaction 716N+24He→11H+819O^{16}_{7}N + ^{4}_{2}He \rightarrow ^{1}_{1}H + ^{19}_{8}O716​N+24​He→11​H+819​O in a laboratory frame is n (in MeV). Assume that 716N^{16}_{7}N716​N is at rest in the laboratory frame. The masses of 716N^{16}_{7}N716​N, 24He^{4}_{2}He24​He, 11H^{1}_{1}H11​H and 819O^{19}_{8}O819​O can be taken to be 16.006 u, 4.003 u, 1.008 u and 19.003 u, respectively, where 1 u = 930 MeVc−2^{-2}−2. The value of n is __________.

Correct answer: 2.32

Step-by-step solution →
Q66·PhysicsIntegerJEE Advanced 2022
In a radioactive decay chain reaction, 90230Th^{230}_{90}Th90230​Th nucleus decays into 84214Po^{214}_{84}Po84214​Po nucleus. The ratio of the number of α to number of β−^{-}− particles emitted in this process is__________

Correct answer: 2

Step-by-step solution →
Q67·PhysicsMultiple correctJEE Advanced 2022
The binding energy of nucleons in a nucleus can be affected by the pairwise Coulomb repulsion. Assume that all nucleons are uniformly distributed inside the nucleus. Let the binding energy of a proton be EbpE_b^pEbp​ and the binding energy of a neutron be EbnE_b^nEbn​ in the nucleus. Which of the following statement(s) is(are) correct?
  1. (A)Ebp−EbnE_b^p - E_b^nEbp​−Ebn​ is proportional to Z(Z−1)Z(Z-1)Z(Z−1) where Z is the atomic number of the nucleus.
  2. (B)Ebp−EbnE_b^p - E_b^nEbp​−Ebn​ is proportional to A−13A^{-\frac{1}{3}}A−31​ where A is the mass number of the nucleus.
  3. (C)Ebp−EbnE_b^p - E_b^nEbp​−Ebn​ is positive.
  4. (D)EbpE_b^pEbp​ increases if the nucleus undergoes a beta decay emitting a positron.

Correct answer: (A), (B), (D)

Step-by-step solution →
Q68·PhysicsSingle correctJEE Main 2022
Read the following statements: (A) Volume of the nucleus is directly proportional to the mass number. (B) Volume of the nucleus is independent of mass number. (C) Density of the nucleus is directly proportional to the mass number. (D) Density of the nucleus is directly proportional to the cube root of the mass number. (E) Density of the nucleus is independent of the mass number. Choose the correct option from the following options.
  1. (A)(A) and (D) only.
  2. (B)(A) and (E) only.
  3. (C)(B) and (E) only.
  4. (D)(A) and (C) only

Correct answer: (B)

Step-by-step solution →
Q69·PhysicsNumericalJEE Main 2022
Two radioactive materials A and B have decay constants 25λ and 16λ respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of B to that of A will be "e" after a time 1aλ\frac{1}{a\lambda}aλ1​. The value of a is________.

Correct answer: 9

Step-by-step solution →
Q70·PhysicsNumericalJEE Main 2022
A freshly prepared radioactive source of half life 2 hours 30 minutes emits radiation which is 64 times the permissible safe level. The minimum time, after which it would be possible to work safely with source, will be ________ hours.

Correct answer: 15

Step-by-step solution →
Q71·PhysicsSingle correctJEE Main 2022
The half life period of a radioactive substance is 60 days. The time taken for 78\frac{7}{8}87​th of its original mass to disintegrate will be :
  1. (A)120 days
  2. (B)130 days
  3. (C)180 days
  4. (D)20 days

Correct answer: (C)

Step-by-step solution →
Q72·PhysicsSingle correctJEE Main 2022
What is the half-life period of a radioactive material if its activity drops to 1/16th1/16^{\text{th}}1/16th of its initial value of 30 years ?
  1. (A)9.5 years
  2. (B)8.5 years
  3. (C)7.5 years
  4. (D)10.5 years

Correct answer: (C)

Step-by-step solution →
Q73·PhysicsSingle correctJEE Main 2022
The activity of a radioactive material is 6.4×10−46.4 \times 10^{-4}6.4×10−4 curie. Its half life is 5 days. The activity will become 5×10−65 \times 10^{-6}5×10−6 curie after :
  1. (A)7 days
  2. (B)15 days
  3. (C)25 days
  4. (D)35 days

Correct answer: (D)

Step-by-step solution →
Q74·PhysicsSingle correctJEE Main 2022
Mass numbers of two nuclei are in the ratio of 4:3. Their nuclear densities will be in the ratio of
  1. (A)4:3
  2. (B)(34)13\left(\frac{3}{4}\right)^{\frac{1}{3}}(43​)31​
  3. (C)1 : 1
  4. (D)(43)13\left(\frac{4}{3}\right)^{\frac{1}{3}}(34​)31​

Correct answer: (C)

Step-by-step solution →
Q75·PhysicsNumericalJEE Main 2022
Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: 12X+12X=24Y^{2}_{1}X + {}^{2}_{1}X = {}^{4}_{2}Y12​X+12​X=24​Y The binding energies per nucleon 12X^{2}_{1}X12​X and 24Y^{4}_{2}Y24​Y are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is________ . MeV.

Correct answer: 26

Step-by-step solution →
Q76·PhysicsSingle correctJEE Main 2022
The disintegration rate of a certain radioactive sample at any instant is 4250 disintegrations per minute. 10 minutes later, the rate becomes 2250 disintegrations per minute. The approximate decay constant is : (Take log10_{10}10​1.88 = 0.274)
  1. (A)0.02 min−1^{-1}−1
  2. (B)2.7 min−1^{-1}−1
  3. (C)0.063 min−1^{-1}−1
  4. (D)6.3 min−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q77·PhysicsSingle correctJEE Main 2022
The activity of a radioactive material is 2.56×10−32.56 \times 10^{-3}2.56×10−3 Ci. If the half life of the material is 5 days, after how many days the activity will become 2×10−52 \times 10^{-5}2×10−5 Ci?
  1. (A)30 days
  2. (B)35 days
  3. (C)40 days
  4. (D)25 days

Correct answer: (B)

Step-by-step solution →
Q78·PhysicsSingle correctJEE Main 2022
In the following nuclear rection, D→ α D1→ β− D2→ α D3→ γ D4D \xrightarrow{\ \alpha\ } D_1 \xrightarrow{\ \beta^-\ } D_2 \xrightarrow{\ \alpha\ } D_3 \xrightarrow{\ \gamma\ } D_4D α ​D1​ β− ​D2​ α ​D3​ γ ​D4​ Mass number of D is 182 and atomic number is 74. Mass number and atomic number of D4D_4D4​ respectively will be____.
  1. (A)174 and 71
  2. (B)174 and 69
  3. (C)172 and 69
  4. (D)172 and 71

Correct answer: (A)

Step-by-step solution →
Q79·PhysicsNumericalJEE Main 2022
The half life of a radioactive substance is 5 years. After x years a given sample of the radioactive substance gest reduced to 6.25% of its initial value of x is ________.

Correct answer: 20

Step-by-step solution →
Q80·PhysicsSingle correctJEE Main 2022
The Q-value of a nuclear reaction and kinetic energy of the projectile particle, KpK_{p}Kp​ are related as :
  1. (A)Q=KpQ = K_{p}Q=Kp​
  2. (B)(Kp+Q)<O(K_{p} + Q) < O(Kp​+Q)<O
  3. (C)Q<KpQ < K_{p}Q<Kp​
  4. (D)(Kp+Q)>0(K_{p} + Q) > 0(Kp​+Q)>0

Correct answer: (D)

Step-by-step solution →
Q81·PhysicsSingle correctJEE Main 2022
Following statements related to radioactivity are given below: (A) Radioactivity is a random and spontaneous process and is dependent on physical and chemical conditions. (B) The number of un–decayed nuclei in the radioactive sample decays exponentially with time. (C) Slope of the graph of loge_ee​(no. of undecayed nuclei) Vs. time represents the reciprocal of mean life time (τ). (D) Product of decay constant (λ) and half–life time (T1/2_{1/2}1/2​) is not constant. Choose the most appropriate answer from the options given below:
  1. (A)(A) and (B) only
  2. (B)(B) and (D) only
  3. (C)(B) and (C) only
  4. (D)(C) and (D) only

Correct answer: (C)

Step-by-step solution →
Q82·PhysicsSingle correctJEE Main 2022
A radioactive nucleus can decay by two different processes. Half-life for the first process is 3.0 hours while it is 4.5 hours for the second process. The effective half- life of the nucleus will be :
  1. (A)3.75 hours
  2. (B)0.56 hours
  3. (C)0.26 hours
  4. (D)1.80 hours

Correct answer: (D)

Step-by-step solution →
Q83·PhysicsSingle correctJEE Main 2022
How many alpha and beta particles are emitted when Uranium 92U238_{92}U^{238}92​U238 decays to lead 82Pb206_{82}Pb^{206}82​Pb206 ?
  1. (A)3 alpha particles and 5 beta particles
  2. (B)6 alpha particles and 4 beta particles
  3. (C)4 alpha particles and 5 beta particles
  4. (D)8 alpha particles and 6 beta particles

Correct answer: (D)

Step-by-step solution →
Q84·PhysicsSingle correctJEE Main 2022
Which of the following figure represents the variation of ln⁡(RR0)\ln\left(\frac{R}{R_0}\right)ln(R0​R​) with ln A(If R = radius of a nucleus and A = its mass number)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q85·PhysicsSingle correctJEE Main 2022
Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments 'B' and 'C' of mass numbers 105 and 115. The binding energy of nucleons in 'B' and 'C' is 6.4 MeV per nucleon. The energy Q released per fission will be :
  1. (A)0.8 MeV
  2. (B)275 MeV
  3. (C)220 MeV
  4. (D)176 MeV

Correct answer: (D)

Step-by-step solution →
Q86·PhysicsNumericalJEE Main 2022
A sample contains 10−2^{-2}−2 kg each of two substances A and B with half lives 4 s and 8 s respectively. The ratio of then atomic weights is 1 : 2. The ratio of the amounts of A and B after 16 s is x100\dfrac{x}{100}100x​. the value of x is ______.

Correct answer: 25

Step-by-step solution →
Q87·PhysicsMultiple correctJEE Advanced 2021
A heavy nucleus NNN, at rest, undergoes fission N→P+QN \rightarrow P + QN→P+Q, where PPP and QQQ are two lighter nuclei. Let δ=MN−MP−MQ\delta = M_N - M_P - M_Qδ=MN​−MP​−MQ​, where MPM_PMP​, MQM_QMQ​ and MNM_NMN​ are the masses of PPP, QQQ and NNN, respectively. EPE_PEP​ and EQE_QEQ​ are the kinetic energies of PPP and QQQ, respectively. The speed of PPP and QQQ are vPv_PvP​ and vQv_QvQ​, respectively. If ccc is the speed of light, which of the following statement(s) is(are) correct ?
  1. (A)EP+EQ=c2δE_P + E_Q = c^2 \deltaEP​+EQ​=c2δ
  2. (B)EP=(MPMP+MQ)c2δE_P = \left( \frac{M_P}{M_P + M_Q} \right) c^2 \deltaEP​=(MP​+MQ​MP​​)c2δ
  3. (C)vPvQ=MQMP\frac{v_P}{v_Q} = \frac{M_Q}{M_P}vQ​vP​​=MP​MQ​​
  4. (D)The magnitude of momentum for PPP as well as QQQ is c2μδc\sqrt{2\mu\delta}c2μδ​, where μ=MPMQ(MP+MQ)\mu = \frac{M_P M_Q}{\left( M_P + M_Q \right)}μ=(MP​+MQ​)MP​MQ​​

Correct answer: (A), (C), (D)

Step-by-step solution →
Q88·PhysicsSingle correctJEE Advanced 2021
A heavy nucleus Q of half-life 20 minutes undergoes alpha-decay with probability of 60% and beta-decay with probability of 40%. Initially, the number of Q nuclei is 1000. The number of alpha-decays of Q in the first one hour is
  1. (A)50
  2. (B)75
  3. (C)350
  4. (D)525

Correct answer: (D)

Step-by-step solution →
Q89·PhysicsSingle correctJEE Main 2021
The half life period of radioactive element x is same as the mean life time of another radioactive element y. Initially they have the same number of atoms. Then :
  1. (A)x–will decay faster than y.
  2. (B)y– will decay faster than x.
  3. (C)x and y have same decay rate initially and later on different decay rate.
  4. (D)x and y decay at the same rate always.

Correct answer: (B)

Step-by-step solution →
Q90·PhysicsSingle correctJEE Main 2021
A sample of a radioactive nucleus A disintegrates to another radioactive nucleus B, which in turn disintegrates to some other stable nucleus C. Plot of a graph showing the variation of number of atoms of nucleus B vesus time is : (Assume that at t = 0, there are no B atoms in the sample)
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q91·PhysicsSingle correctJEE Main 2021
There are 101010^{10}1010 radioactive nuclei in a given radioactive element, Its half-life time is 1 minute. How many nuclei will remain after 30 seconds ? (2=1.414)\left(\sqrt{2} = 1.414\right)(2​=1.414)
  1. (A)2×10102 \times 10^{10}2×1010
  2. (B)7×1097 \times 10^{9}7×109
  3. (C)10510^{5}105
  4. (D)4×10104 \times 10^{10}4×1010

Correct answer: (B)

Step-by-step solution →
Q92·PhysicsSingle correctJEE Main 2021
At time t = 0, a material is composed of two radioactive atoms A and B, where NA(0)=2NB(0)N_{A}(0) = 2N_{B}(0)NA​(0)=2NB​(0). The decay constant of both kind of radioactive atoms is λ\lambdaλ. However, A disintegrates to B and B disintegrates to C. Which of the following figures represents the evolution of NB(t)N_{B}(t)NB​(t) / NB(0)N_{B}(0)NB​(0) with respect to time t ? [NA(0)=No. of A atoms at t=0NB(0)=No. of B atoms at t=0]\left[\begin{array}{l} N_{A}\left(0\right) = \text{No. of A atoms at } t = 0 \\\\ N_{B}\left(0\right) = \text{No. of B atoms at } t = 0 \end{array}\right]​NA​(0)=No. of A atoms at t=0NB​(0)=No. of B atoms at t=0​​
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q93·PhysicsNumericalJEE Main 2021
A radioactive sample has an average life of 30ms and is decaying. A capacitor of capacitance 200 μF is first charged and later connected with resistor 'R'. If the ratio of charge on capacitor to the activity of radioactive sample is fixed with respect to time then the value of 'R' should be ____ Ω .

Correct answer: 150

Step-by-step solution →
Q94·PhysicsSingle correctJEE Main 2021
If 'f' denotes the ratio of the number of nuclei decayed (NdN_dNd​) to the number of nuclei at t = 0 (N0N_0N0​) then for a collection of radioactive nuclei, the rate of change of 'f' with respect to time is given as : [ λ is the radioactive decay constant ]
  1. (A)λe−λt\lambda e^{-\lambda t}λe−λt
  2. (B)λ(1−e−λt)\lambda\left(1-e^{-\lambda t}\right)λ(1−e−λt)
  3. (C)−λ(1−e−λt)-\lambda\left(1-e^{-\lambda t}\right)−λ(1−e−λt)
  4. (D)−λe−λt-\lambda e^{-\lambda t}−λe−λt

Correct answer: (A)

Step-by-step solution →
Q95·PhysicsSingle correctJEE Main 2021
Consider the following statements : (A) Atoms of each element emit characteristics spectrum. (B) According to Bohr's Postulate, an electron in a hydrogen atom, revolves in a certain stationary orbit. (C) The density of nuclear matter depends on the size of the nucleus. (D) A free neutron is stable but a free proton decay is possible. (E) Radioactivity is an indication of the instability of nuclei. Choose the correct answer from the options given below :
  1. (A)B and D only
  2. (B)A, C and E only
  3. (C)A, B, C, D and E
  4. (D)A, B and E only

Correct answer: (D)

Step-by-step solution →
Q96·PhysicsNumericalJEE Main 2021
The nuclear activity of a radioactive element becomes (18)th\left(\frac{1}{8}\right)^{\text{th}}(81​)th of its initial value in 30 years. The half –life of radioactive element is ________ years.

Correct answer: 10

Step-by-step solution →
Q97·PhysicsNumericalJEE Main 2021
From the given data, the amount of energy required to break the nucleus of aluminium 1327Al^{27}_{13}\text{Al}1327​Al is ________ x×10−3x \times 10^{-3}x×10−3 J. Mass of neutron = 1.00866u Mass of proton = 1.00726 u Mass of Aluminium nucleus = 27.18846 u (Assume 1 u corresponds to x J of energy) (Round off to the nearest integer)

Correct answer: 27

Step-by-step solution →
Q98·PhysicsSingle correctJEE Main 2021
The half-life of 198^{198}198Au is 3 days. If atomic weight of 198^{198}198Au is 198 g /mol then the activity of 2 mg of 198^{198}198Au is [ in disintegration / second ] :
  1. (A)6.06×10186.06 \times 10^{18}6.06×1018
  2. (B)2.67×10122.67 \times 10^{12}2.67×1012
  3. (C)16.18×101216.18 \times 10^{12}16.18×1012
  4. (D)32.36×101232.36 \times 10^{12}32.36×1012

Correct answer: (C)

Step-by-step solution →
Q99·PhysicsSingle correctJEE Main 2021
Some nuclei of a radioactive material are undergoing radioactive decay. The time gap between the instances when a quarter of the nuclei have decayed and when half of the nuclei have decayed is given as : (where λ\lambdaλ is the decay constant)
  1. (A)ℓn32λ\frac{\ell n \frac{3}{2}}{\lambda}λℓn23​​
  2. (B)ℓn2λ\frac{\ell n 2}{\lambda}λℓn2​
  3. (C)2ℓn2λ\frac{2 \ell n 2}{\lambda}λ2ℓn2​
  4. (D)12 ℓn2λ\frac{1}{2}\ \frac{\ell n 2}{\lambda}21​ λℓn2​

Correct answer: (A)

Step-by-step solution →
Q100·PhysicsSingle correctJEE Main 2021
A nucleus with number 184 initially at rest emits an α−\alpha-α−particle. If the Q value of the reaction is 5.5 MeV, calculate the kinetic energy of the α−\alpha-α−particle.
  1. (A)5.5 MeV
  2. (B)5.38 MeV
  3. (C)5.0 MeV
  4. (D)0.12 MeV

Correct answer: (B)

Step-by-step solution →
Q101·PhysicsSingle correctJEE Main 2021
For a certain radioactive process the graph between ℓn(R)\ell n(R)ℓn(R) and t(sec) is obtained as shown in the figure. Then the value of half life for the unknown radioactive material is approximately :
  1. (A)2.62 sec
  2. (B)9.15 sec
  3. (C)4.62 sec
  4. (D)6.93 sec

Correct answer: (C)

Step-by-step solution →
Q102·PhysicsNumericalJEE Main 2021
A radioactive substance decays to (116)th\left(\frac{1}{16}\right)^{th}(161​)th of this initial activity in 80 days. The half life of the radioactive substance expressed in days is ____________.

Correct answer: 20

Step-by-step solution →
Q103·PhysicsSingle correctJEE Main 2021
A nucleus of mass M emits γ − ray photon of frequency 'ν'. The loss of internal energy by the nucleus is : [Take 'c' as the speed of electromagnetic wave ]
  1. (A)hν[1+hν2Mc2]h\nu\left[1+\frac{h\nu}{2Mc^2}\right]hν[1+2Mc2hν​]
  2. (B)0
  3. (C)hν[1−hν2Mc2]h\nu\left[1-\frac{h\nu}{2Mc^2}\right]hν[1−2Mc2hν​]
  4. (D)hνh\nuhν

Correct answer: (A)

Step-by-step solution →
Q104·PhysicsSingle correctJEE Main 2021
A radioactive material decays by simultaneous emissions of two particles with half lives of 1400 years and 700 years respectively. What will be the time after which one third of the material remains? (Take ln 3 = 1.1)
  1. (A)340 years
  2. (B)1110 years
  3. (C)700 years
  4. (D)740 years

Correct answer: (D)

Step-by-step solution →
Q105·PhysicsSingle correctJEE Main 2021
The decay of a proton to neutron is :
  1. (A)not possible as proton mass is less than the neutron mass
  2. (B)possible only inside the nucleus
  3. (C)not possible but neutron to proton conversion is possible
  4. (D)always possible as it is associated only with β+^{+}+ decay

Correct answer: (B)

Step-by-step solution →
Q106·PhysicsSingle correctJEE Main 2021
A radioactive sample disintegrates via two independent decay processes having half lives T1/2(1)T_{1/2}^{(1)}T1/2(1)​ and T1/2(2)T_{1/2}^{(2)}T1/2(2)​ respectively. The effective half-life T1/2T_{1/2}T1/2​ of the nuclei is :
  1. (A)None of the above
  2. (B)T1/2=T1/2(1)+T1/2(2)T_{1/2} = T_{1/2}^{(1)} + T_{1/2}^{(2)}T1/2​=T1/2(1)​+T1/2(2)​
  3. (C)T1/2=T1/2(1)T1/2(2)T1/2(1)+T1/2(2)T_{1/2} = \dfrac{T_{1/2}^{(1)}T_{1/2}^{(2)}}{T_{1/2}^{(1)} + T_{1/2}^{(2)}}T1/2​=T1/2(1)​+T1/2(2)​T1/2(1)​T1/2(2)​​
  4. (D)T1/2=T1/2(1)+T1/2(2)T1/2(1)−T1/2(2)T_{1/2} = \dfrac{T_{1/2}^{(1)} + T_{1/2}^{(2)}}{T_{1/2}^{(1)} - T_{1/2}^{(2)}}T1/2​=T1/2(1)​−T1/2(2)​T1/2(1)​+T1/2(2)​​

Correct answer: (C)

Step-by-step solution →
Q107·PhysicsSingle correctJEE Main 2021
Calculate the time interval between 33% decay and 67% decay if half-life of a substance is 20 minutes.
  1. (A)60 minutes
  2. (B)20 minutes
  3. (C)40 minutes
  4. (D)13 minutes

Correct answer: (B)

Step-by-step solution →
Q108·PhysicsSingle correctJEE Main 2021
The half-life of Au198^{198}198 is 2.7 days. The activity of 1.50 mg of Au198^{198}198 if its atomic weight is 198 g mol−1^{-1}−1 is, (NA_{A}A​ = 6 × 1023^{23}23/mol)
  1. (A)240 Ci
  2. (B)357 Ci
  3. (C)535 Ci
  4. (D)252 Ci

Correct answer: (B)

Step-by-step solution →
Q109·PhysicsSingle correctJEE Main 2021
A radioactive sample is undergoing α decay. At any time t1_{1}1​, its activity is A and another time t2_{2}2​, the activity is A5\frac{A}{5}5A​. What is the average life time for the sample?
  1. (A)t2−t1ln⁡5\frac{t_{2}-t_{1}}{\ln 5}ln5t2​−t1​​
  2. (B)ln⁡(t2+t1)2\frac{\ln\left(t_{2}+t_{1}\right)}{2}2ln(t2​+t1​)​
  3. (C)t1−t2ln⁡5\frac{t_{1}-t_{2}}{\ln 5}ln5t1​−t2​​
  4. (D)ln⁡5t2−t1\frac{\ln 5}{t_{2}-t_{1}}t2​−t1​ln5​

Correct answer: (A)

Step-by-step solution →
Q110·PhysicsSingle correctJEE Main 2021
Two radioactive substances X and Y originally have N1N_1N1​ and N2N_2N2​nuclei respectively. Half life of X is half of the half life of Y. After there half lives of Y, number of nuclei of both are equal. The ratio N1N2\dfrac{N_1}{N_2}N2​N1​​ will be equal to :
  1. (A)81\dfrac{8}{1}18​
  2. (B)18\dfrac{1}{8}81​
  3. (C)31\dfrac{3}{1}13​
  4. (D)13\dfrac{1}{3}31​

Correct answer: (A)

Step-by-step solution →
Q111·PhysicsSingle correctJEE Main 2020
Given the masses of various atomic particles mpm_{p}mp​ = 1.0072 u, mnm_{n}mn​ = 1.0087 u, mem_{e}me​ = 0.000548 u, mvˉm_{\bar{v}}mvˉ​ = 0, mdm_{d}md​ = 2.0141 u, where p ≡ proton, n ≡ neutron, e ≡ electron, vˉ\bar{v}vˉ ≡ antineutrino and d ≡ deuteron. Which of the following process is allowed by momentum and energy conservation?
  1. (A)n + n → deuterium atom (electron bound to the nucleus)
  2. (B)p→n+e++vˉp → n + e^{+} + \bar{v}p→n+e++vˉ
  3. (C)n+p→d+γn + p → d + γn+p→d+γ
  4. (D)e++e−→γe^{+} + e^{-} → γe++e−→γ

Correct answer: (C)

Step-by-step solution →
Q112·PhysicsSingle correctJEE Main 2020
You are given that Mass of 27Li=7.0160u^7_2\text{Li} = 7.0160\text{u}27​Li=7.0160u Mass of 24He=4.0026u^4_2\text{He} = 4.0026\text{u}24​He=4.0026u and 11H=1.0079u^1_1\text{H} = 1.0079\text{u}11​H=1.0079u. When 20 g of 37Li^7_3\text{Li}37​Li is converted into 24He^4_2\text{He}24​He by proton capture, the energy liberated, (in kWh), is [Mass of nucleon =1Gevc2=\dfrac{1\text{Gev}}{c^2}=c21Gev​]
  1. (A)4.5×1054.5\times10^54.5×105
  2. (B)8×1068\times10^68×106
  3. (C)6.82×1056.82\times10^56.82×105
  4. (D)1.33×1061.33\times10^61.33×106

Correct answer: (D)

Step-by-step solution →
Q113·PhysicsSingle correctJEE Main 2020
Activities of three radioactive substances A, B and C are represented by the curves A, B and C in the figure. Then their half lives T1/2(A):T1/2(B):T1/2(C)T_{1/2}(A) : T_{1/2}(B) : T_{1/2}(C)T1/2​(A):T1/2​(B):T1/2​(C) are in the radio:
  1. (A)3:2:1
  2. (B)2:1:3
  3. (C)4:3:1
  4. (D)2:1:1

Correct answer: (B)

Step-by-step solution →
Q114·PhysicsSingle correctJEE Main 2020
A radioactive nucleus decays by two difference processes. The half life for the first process is 10 s and that for the second is 100 s. The effective half life of the nucleus is closes to:
  1. (A)6 sec.
  2. (B)9 sec.
  3. (C)12 sec.
  4. (D)55 sec.

Correct answer: (B)

Step-by-step solution →
Q115·PhysicsSingle correctJEE Main 2020
In a radioactive material, fraction of active material remaining after time t is 9/16. The fraction that was remaining after t/2 is
  1. (A)35\frac{3}{5}53​
  2. (B)34\frac{3}{4}43​
  3. (C)78\frac{7}{8}87​
  4. (D)45\frac{4}{5}54​

Correct answer: (B)

Step-by-step solution →
Q116·PhysicsSingle correctJEE Main 2020
The radius R of a nucleus of mass number A can be estimated by the formula R=(1.3×10−15)A1/3mR=\left(1.3\times 10^{-15}\right)A^{1/3}mR=(1.3×10−15)A1/3m. It follows that the mass density of a nucleus is of the order of: (Mprot=Mneut.≃1.67×10−27 kg)\left(M_{prot}=M_{neut.}\simeq 1.67\times 10^{-27}\,kg\right)(Mprot​=Mneut.​≃1.67×10−27kg)
  1. (A)103kg m−310^{3}kg\ m^{-3}103kg m−3
  2. (B)1017 kg m−310^{17}\,kg\ m^{-3}1017kg m−3
  3. (C)1010 kg m−310^{10}\,kg\ m^{-3}1010kg m−3
  4. (D)1024 kg m−310^{24}\,kg\ m^{-3}1024kg m−3

Correct answer: (B)

Step-by-step solution →
Q117·PhysicsSingle correctJEE Main 2020
The activity of a radioactive sample falls from 700 s−1^{-1}−1 to 500 s−1^{-1}−1 in 30 minutes. Its half life is close to
  1. (A)66 min
  2. (B)52 min
  3. (C)62 min
  4. (D)72 min

Correct answer: (C)

Step-by-step solution →
Q118·PhysicsSingle correctJEE Advanced 2019
In a radioactive sample 1940^{40}_{19}1940​K nuclei either decay into stable 2040^{40}_{20}2040​Ca nuclei with decay constant 4.5 × 10−1010^{-10}10−10 per year or into stable 1840^{40}_{18}1840​Ar nuclei with decay constant 0.5×10−100.5 \times 10^{-10}0.5×10−10 per year. Given that in this sample all the stable 2040^{40}_{20}2040​Ca and 1840^{40}_{18}1840​Ar nuclei are produced by the 1940^{40}_{19}1940​K nuclei only. In time t × 10910^9109 years, if the ratio of the sum of stable 2040^{40}_{20}2040​Ca and 1840^{40}_{18}1840​Ar nuclei to the radioactive 1940^{40}_{19}1940​K nuclei is 99, the value of t will be [Given : ln10 = 2.3]
  1. (A)1.15
  2. (B)4.6
  3. (C)9.2
  4. (D)2.3

Correct answer: (C)

Step-by-step solution →
Q119·PhysicsNumericalJEE Advanced 2019
Suppose a 88226Ra^{226}_{88}\mathrm{Ra}88226​Ra nucleus at rest and in ground state undergoes α\alphaα-decay to a 86222Rn^{222}_{86}\mathrm{Rn}86222​Rn nucleus in its excited state. The kinetic energy of the emitted α\alphaα particle is found to be 4.44 MeV. 86222Rn^{222}_{86}\mathrm{Rn}86222​Rn nucleus then goes to its ground state by γ\gammaγ-decay. The energy of the emitted γ\gammaγ photon is ______keV. [Given: atomic mass of 88226Ra^{226}_{88}\mathrm{Ra}88226​Ra = 226.005 u, atomic mass of 86222Rn^{222}_{86}\mathrm{Rn}86222​Rn = 222.000 u, atomic mass of α\alphaα particle = 4.000 u, 1 u = 931 MeV/c2c^2c2, c is speed of the light]

Correct answer: 135.00

Step-by-step solution →
Q120·PhysicsSingle correctJEE Main 2019
Half lives of two radioactive nuclei A and B are 10 minutes and 20 minutes, respectively. If, initially a sample has equal number of nuclei, then after 60 minutes, the ratio of decayed numbers of nuclei A and B will be :
  1. (A)9 : 8
  2. (B)1 : 8
  3. (C)8 : 1
  4. (D)3 : 8

Correct answer: (A)

Step-by-step solution →
Q121·PhysicsSingle correctJEE Main 2019
Two radioactive materials A and B have decay constants 10λ10\lambda10λ and λ\lambdaλ, respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of a to that of B will be 1/e after a time:
  1. (A)111λ\dfrac{1}{11\lambda}11λ1​
  2. (B)110λ\dfrac{1}{10\lambda}10λ1​
  3. (C)19λ\dfrac{1}{9\lambda}9λ1​
  4. (D)1110λ\dfrac{11}{10\lambda}10λ11​

Correct answer: (C)

Step-by-step solution →
Q122·PhysicsSingle correctJEE Main 2019
Two radioactive substances A and B have decay constants 5λ and λ respectively. At t = 0, a sample has the same number of the two nuclei. The time taken for the ratio of the number of nuclei to become (1e)2\left(\dfrac{1}{e}\right)^{2}(e1​)2 will be
  1. (A)1/λ
  2. (B)1/4λ
  3. (C)2/λ
  4. (D)1/2λ

Correct answer: (D)

Step-by-step solution →
Q123·PhysicsSingle correctJEE Main 2019
The ratio of mass densities of nuclei of 40Ca^{40}C_a40Ca​ and 16O^{16}O16O is close to:
  1. (A)0.1
  2. (B)5
  3. (C)2
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q124·PhysicsSingle correctJEE Main 2019
In a radioactive decay chain, the initial nucleus is 90232Th_{90}^{232}\text{Th}90232​Th. At the end there are 6 α-particles and 4 β-particles with are emitted. If the end nucleus is ZAX_{Z}^{A}XZA​X, A and Z are given by :
  1. (A)A = 208; Z = 80
  2. (B)A = 202; Z = 80
  3. (C)A = 208; Z = 82
  4. (D)A = 200; Z = 81

Correct answer: (C)

Step-by-step solution →
Q125·PhysicsSingle correctJEE Main 2019
Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:
  1. (A)200
  2. (B)150
  3. (C)400
  4. (D)360

Correct answer: (A)

Step-by-step solution →
Q126·PhysicsSingle correctJEE Main 2019
A sample of radioactive material A, that has an activity of 10 mCi (1 Ci = 3.7×10103.7 \times 10^{10}3.7×1010 decays/s), has twice the number of nuclei as another sample of different radioactive material B which has an activity of 20 mCi. The correct choices for half-lives of A and B would then be respectively:
  1. (A)5 days and 10 days
  2. (B)10 days and 40 days
  3. (C)20 days and 5 days
  4. (D)20 days and 10 days

Correct answer: (C)

Step-by-step solution →
Q127·PhysicsSingle correctJEE Main 2019
At a given instant, say t = 0, two radioactive substances A and B have equal activates. The ratio RBRA\frac{R_B}{R_A}RA​RB​​ of their activities. The ratio RBRA\frac{R_B}{R_A}RA​RB​​ of their activates after time t itself decays with time t as e−3te^{-3t}e−3t. If the half-life of A is ℓn2\ell n2ℓn2, the half-life of B is:
  1. (A)4ℓn24\ell n24ℓn2
  2. (B)ℓn22\frac{\ell n2}{2}2ℓn2​
  3. (C)ℓn24\frac{\ell n2}{4}4ℓn2​
  4. (D)2ℓn22\ell n22ℓn2

Correct answer: (C)

Step-by-step solution →
Q128·PhysicsMultiple correctJEE Advanced 2018
In a radioactive decay chain, 90232^{232}_{90}90232​Th nucleus decays to 82212^{212}_{82}82212​Pb nucleus. Let NαN_{\alpha}Nα​ and NβN_{\beta}Nβ​ be the number of α\alphaα and β−\beta^{-}β− particles, respectively, emitted in this decay process. Which of the following statements is (are) true?
  1. (A)Nα=5N_{\alpha} = 5Nα​=5
  2. (B)Nα=6N_{\alpha} = 6Nα​=6
  3. (C)Nβ=2N_{\beta} = 2Nβ​=2
  4. (D)Nβ=4N_{\beta} = 4Nβ​=4

Correct answer: (A), (C)

Step-by-step solution →
Q129·PhysicsIntegerJEE Advanced 2017
131I^{131}I131I is an isotope of Iodine that β\betaβ decays to an isotope of Xenon with a half-life of 8 days. A small amount of a serum labelled with 131I^{131}I131I is injected into the blood of a person. The activity of the amount of 131I^{131}I131I injected was 2.4 ×\times× 10510^{5}105 Becquerel (Bq). It is known that the injected serum will get distributed uniformly in the blood stream in less than half an hour. After 11.5 hours, 2.5 ml of blood is drawn from the person's body, and gives an activity of 115 Bq. The total volume of blood in the person's body, in liters is approximately (you may use ex≈1+xe^{x} \approx 1 + xex≈1+x for ∣x∣≪1|x| \ll 1∣x∣≪1 and ln 2 ≈\approx≈ 0.7).

Correct answer: 5

Step-by-step solution →
Q130·PhysicsSingle correctJEE Advanced 2016
The electrostatic energy of Z protons uniformly distributed throughout a spherical nucleus of radius R is given by E=35 Z(Z−1)e24πε0RE = \frac{3}{5}\,\frac{Z(Z-1)e^{2}}{4\pi\varepsilon_{0}R}E=53​4πε0​RZ(Z−1)e2​ The measured masses of the neutron, 11H^{1}_{1}\text{H}11​H, 715N^{15}_{7}\text{N}715​N and 815O^{15}_{8}\text{O}815​O are 1.008665 u, 1.007825 u, 15.000109 u and 15.003065u, respectively. Given that the radii of both the 715N^{15}_{7}\text{N}715​N and 815O^{15}_{8}\text{O}815​O nuclei are same, 1 u = 931.5 MeV/c2c^{2}c2 ( c is the speed of light) and e2/(4πε0)e^{2}/(4\pi\varepsilon_{0})e2/(4πε0​) = 1.44 MeV fm. Assuming that the difference between the binding energies of 715N^{15}_{7}\text{N}715​N and 815O^{15}_{8}\text{O}815​O is purely due to the electrostatic energy, the radius of either of the nuclei is (1 fm = 10−1510^{-15}10−15m)
  1. (A)2.85 fm
  2. (B)3.03 fm
  3. (C)3.42 fm
  4. (D)3.80 fm

Correct answer: (C)

Step-by-step solution →
Q131·PhysicsIntegerJEE Advanced 2016
The isotope 512B^{12}_{5}\text{B}512​B having a mass 12.014 u undergoes β-decay to 612C^{12}_{6}\text{C}612​C. 612C^{12}_{6}\text{C}612​C has an excited state of the nucleus (612C∗^{12}_{6}\text{C}^*612​C∗) at 4.041 MeV above its ground state. If 512B^{12}_{5}\text{B}512​B decays to 612C∗^{12}_{6}\text{C}^*612​C∗, the maximum kinetic energy of the β-particle in units of MeV is (1 u = 931.5 MeV/c2c^{2}c2, where ccc is the speed of light in vacuum).

Correct answer: 9

Step-by-step solution →
Q132·PhysicsSingle correctJEE Advanced 2016
An accident in a nuclear laboratory resulted in deposition of a certain amount of radioactive material of half-life 18 days inside the laboratory. Tests revealed that the radiation was 64 times more than the permissible level required for safe operation of the laboratory. What is the minimum number of days after which the laboratory can be considered safe for use?
  1. (A)64
  2. (B)90
  3. (C)108
  4. (D)120

Correct answer: (C)

Step-by-step solution →
Q133·PhysicsIntegerJEE Advanced 2015
A nuclear power plant supplying electrical power to a village uses a radioactive material of half life T years as the fuel. The amount of fuel at the beginning is such that the total power requirement of the village is 12.5 % of the electrical power available form the plant at that time. If the plant is able to meet the total power needs of the village for a maximum period of nTnTnT years, then the value of nnn is

Correct answer: 3

Step-by-step solution →
Q134·PhysicsMatrix matchJEE Advanced 2015
Match the nuclear processes given in column I with the appropriate option(s) in column II
Column IColumn II
A.Nuclear fusionP.Absorption of thermal neutrons by 92235U^{235}_{92}\mathrm{U}92235​U
B.Fission in a nuclear reactorQ.2760Co^{60}_{27}\mathrm{Co}2760​Co nucleus
C.β\betaβ-decayR.Energy production in stars via hydrogen conversion to helium
D.γ\gammaγ-ray emissionS.Heavy water
T.Neutrino emission

Correct answer: A-(R,T); B-(P,S); C-(P,Q,R,T); D-(P,Q,R,T)

Step-by-step solution →
Q135·PhysicsIntegerJEE Advanced 2015
For a radioactive material, its activity A and rate of change of its activity R are defined as A=−dNdtA = -\dfrac{dN}{dt}A=−dtdN​ and R=−dAdtR = -\dfrac{dA}{dt}R=−dtdA​, where N(t) is the number of nuclei at time t. Two radioactive sources P (mean life τ\tauτ) and Q (mean life 2τ2\tau2τ) have the same activity at t=0t = 0t=0. Their rates of change of activities at t=2τt = 2\taut=2τ are RPR_{P}RP​ and RQR_{Q}RQ​, respectively. If RPRQ=ne\dfrac{R_{P}}{R_{Q}} = \dfrac{n}{e}RQ​RP​​=en​, then the value of n is

Correct answer: 2

Step-by-step solution →
Q136·PhysicsMultiple correctJEE Advanced 2015
A fission reaction is given by 92236U→54140Xe+3894Sr+x+y^{236}_{92}\mathrm{U} \to {}^{140}_{54}\mathrm{Xe} + {}^{94}_{38}\mathrm{Sr} + x + y92236​U→54140​Xe+3894​Sr+x+y, where x and y are two particles. Considering 92236U^{236}_{92}\mathrm{U}92236​U to be at rest, the kinetic energies of the products are denoted by KXeK_{Xe}KXe​, KSrK_{Sr}KSr​, KxK_{x}Kx​(2MeV) and KyK_{y}Ky​(2MeV), respectively. Let the binding energies per nucleon of 92236U^{236}_{92}\mathrm{U}92236​U, 54140Xe^{140}_{54}\mathrm{Xe}54140​Xe and 3894Sr^{94}_{38}\mathrm{Sr}3894​Sr be 7.5 MeV, 8.5 MeV and 8.5 MeV respectively. Considering different conservation laws, the correct option(s) is(are)
  1. (A)x=nx = nx=n, y=ny = ny=n, KSr=129K_{Sr} = 129KSr​=129 MeV, KXe=86K_{Xe} = 86KXe​=86 MeV
  2. (B)x=px = px=p, y=e−y = e^{-}y=e−, KSr=129K_{Sr} = 129KSr​=129 MeV, KXe=86K_{Xe} = 86KXe​=86 MeV
  3. (C)x=px = px=p, y=ny = ny=n, KSr=129K_{Sr} = 129KSr​=129 MeV, KXe=86K_{Xe} = 86KXe​=86 MeV
  4. (D)x=nx = nx=n, y=ny = ny=n, KSr=86K_{Sr} = 86KSr​=86 MeV, KXe=129K_{Xe} = 129KXe​=129 MeV

Correct answer: (A)

Step-by-step solution →
Q137·PhysicsSingle correctJEE Advanced 2013
The mass of nucleus ZAX^{A}_{Z}\mathrm{X}ZA​X is less than the sum of the masses of (A−Z)(A-Z)(A−Z) number of neutrons and ZZZ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass MMM can break into two light nuclei of mass m1m_{1}m1​ and m2m_{2}m2​ only if (m1+m2)<M(m_{1} + m_{2}) < M(m1​+m2​)<M. Also two light nuclei of masses m3m_{3}m3​ and m4m_{4}m4​ can undergo complete fusion and form a heavy nucleus of mass M′M'M′ only if (m3+m4)>M′(m_{3} + m_{4}) > M'(m3​+m4​)>M′. The masses of some neutral atoms are given in the table below: The kinetic energy (in keV) of the alpha particle, when the nucleus 84210Po^{210}_{84}\mathrm{Po}84210​Po at rest undergoes alpha decay, is
NuclideMass
11H^{1}_{1}\mathrm{H}11​H1.007825 u
12H^{2}_{1}\mathrm{H}12​H2.014102 u
13H^{3}_{1}\mathrm{H}13​H3.016050 u
24He^{4}_{2}\mathrm{He}24​He4.002603 u
36Li^{6}_{3}\mathrm{Li}36​Li6.015123 u
37Li^{7}_{3}\mathrm{Li}37​Li7.016004 u
3070Zn^{70}_{30}\mathrm{Zn}3070​Zn69.925325 u
3482Se^{82}_{34}\mathrm{Se}3482​Se81.916709 u
64152Gd^{152}_{64}\mathrm{Gd}64152​Gd151.919803 u
82206Pb^{206}_{82}\mathrm{Pb}82206​Pb205.974455 u
83209Bi^{209}_{83}\mathrm{Bi}83209​Bi208.980388 u
84210Po^{210}_{84}\mathrm{Po}84210​Po209.982876 u
  1. (A)5319
  2. (B)5422
  3. (C)5707
  4. (D)5818

Correct answer: (A)

Step-by-step solution →
Q138·PhysicsSingle correctJEE Advanced 2013
The mass of nucleus ZAX^{A}_{Z}\mathrm{X}ZA​X is less than the sum of the masses of (A−Z)(A-Z)(A−Z) number of neutrons and ZZZ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass MMM can break into two light nuclei of mass m1m_{1}m1​ and m2m_{2}m2​ only if (m1+m2)<M(m_{1} + m_{2}) < M(m1​+m2​)<M. Also two light nuclei of masses m3m_{3}m3​ and m4m_{4}m4​ can undergo complete fusion and form a heavy nucleus of mass M′M'M′ only if (m3+m4)>M′(m_{3} + m_{4}) > M'(m3​+m4​)>M′. The masses of some neutral atoms are given in the table below: The correct statement is
NuclideMass
11H^{1}_{1}\mathrm{H}11​H1.007825 u
12H^{2}_{1}\mathrm{H}12​H2.014102 u
13H^{3}_{1}\mathrm{H}13​H3.016050 u
24He^{4}_{2}\mathrm{He}24​He4.002603 u
36Li^{6}_{3}\mathrm{Li}36​Li6.015123 u
37Li^{7}_{3}\mathrm{Li}37​Li7.016004 u
3070Zn^{70}_{30}\mathrm{Zn}3070​Zn69.925325 u
3482Se^{82}_{34}\mathrm{Se}3482​Se81.916709 u
64152Gd^{152}_{64}\mathrm{Gd}64152​Gd151.919803 u
82206Pb^{206}_{82}\mathrm{Pb}82206​Pb205.974455 u
83209Bi^{209}_{83}\mathrm{Bi}83209​Bi208.980388 u
84210Po^{210}_{84}\mathrm{Po}84210​Po209.982876 u
  1. (A)The nucleus 36Li^{6}_{3}\mathrm{Li}36​Li can emit an alpha particle
  2. (B)The nucleus 84210Po^{210}_{84}\mathrm{Po}84210​Po can emit a proton.
  3. (C)Deuteron and alpha particle can undergo complete fusion.
  4. (D)The nuclei 3070Zn^{70}_{30}\mathrm{Zn}3070​Zn and 3482Se^{82}_{34}\mathrm{Se}3482​Se can undergo complete fusion.

Correct answer: (C)

Step-by-step solution →
Q139·PhysicsSingle correctJEE Advanced 2013
Match List I of the nuclear processes with List II containing parent nucleus and one of the end products of each process and then select the correct answer using the codes given below the lists:
List IList II
P.Alpha decay1.815O→715N+.....^{15}_{8}\mathrm{O} \to {}^{15}_{7}\mathrm{N} + .....815​O→715​N+.....
Q.β+\beta^{+}β+ decay2.92238U→90234Th+.....^{238}_{92}\mathrm{U} \to {}^{234}_{90}\mathrm{Th} + .....92238​U→90234​Th+.....
R.Fission3.83185Bi→82184Pb+.....^{185}_{83}\mathrm{Bi} \to {}^{184}_{82}\mathrm{Pb} + .....83185​Bi→82184​Pb+.....
S.Proton emission4.94239Pu→57140La+.....^{239}_{94}\mathrm{Pu} \to {}^{140}_{57}\mathrm{La} + .....94239​Pu→57140​La+.....
  1. (A)P-4, Q-2, R-1, S-3
  2. (B)P-1, Q-3, R-2, S-4
  3. (C)P-2, Q-1, R-4, S-3
  4. (D)P-4, Q-3, R-2, S-1

Correct answer: (C)

Step-by-step solution →
Q140·PhysicsIntegerJEE Advanced 2013
A freshly prepared sample of a radioisotope of half-life 1386 s has activity 10310^{3}103 disintegrations per second. Given that ln⁡2=0.693\ln 2 = 0.693ln2=0.693, the fraction of the initial number of nuclei (expressed in nearest integer percentage) that will decay in the first 80 s after preparation of the sample is

Correct answer: 4

Step-by-step solution →

Nuclei — frequently asked

How many questions from Nuclei appear in JEE?

Nuclei has appeared in 116 of the last 186 JEE Main and JEE Advanced papers — about 62% of them — contributing 140 questions in total across those papers.

Is Nuclei an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 62% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Nuclei questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Physics chapters

  • Properties of Solids and Liquids 344
  • Current Electricity 309
  • Rotational Motion 266
  • Geometrical Optics 259
  • Kinematics 255
  • Magnetic Field of Current 211
  • Electromagnetic Waves 208
  • Thermodynamics 201

All 28 Physics chapters →

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