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Chemical Bonding and Molecular Structure — JEE Previous Year Questions

Every Chemical Bonding and Molecular Structure question asked in JEE Main and JEE Advanced across the last 186 papers — 207 questions, each with its correct answer. Free to read, no account needed.

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207

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81%

All 207 Chemical Bonding and Molecular Structure questions

Most recent papers first.

Q1·ChemistrySingle correctJEE Advanced 2026
The correct order of ONO bond angle in the given species is
  1. (A)NO2+<NO2<NO3−<NO2−NO_{2}^{+} < NO_{2} < NO_{3}^{-} < NO_{2}^{-}NO2+​<NO2​<NO3−​<NO2−​
  2. (B)NO2−<NO3−<NO2<NO2+NO_{2}^{-} < NO_{3}^{-} < NO_{2} < NO_{2}^{+}NO2−​<NO3−​<NO2​<NO2+​
  3. (C)NO3−<NO2−<NO2<NO2+NO_{3}^{-} < NO_{2}^{-} < NO_{2} < NO_{2}^{+}NO3−​<NO2−​<NO2​<NO2+​
  4. (D)NO2−<NO3−<NO2+<NO2NO_{2}^{-} < NO_{3}^{-} < NO_{2}^{+} < NO_{2}NO2−​<NO3−​<NO2+​<NO2​

Correct answer: (B)

Step-by-step solution →
Q2·ChemistrySingle correctJEE Advanced 2026
Consider the following species: SOCl2\mathrm{SOCl_2}SOCl2​, XeOF4\mathrm{XeOF_4}XeOF4​, ClF3\mathrm{ClF_3}ClF3​, ClF5\mathrm{ClF_5}ClF5​, XeF5+\mathrm{XeF_5^+}XeF5+​, SO32−\mathrm{SO_3^{2-}}SO32−​, XeF3+\mathrm{XeF_3^+}XeF3+​, SF4\mathrm{SF_4}SF4​ List-I contains different molecular shapes and List-II contains total number of species with the same molecular shapes from the given species. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
List-IList-II
P.See-saw1.one
Q.T-Shaped2.two
R.Trigonal Planar3.three
S.Square Pyramidal4.four
5.zero
  1. (A)P → 1; Q → 2; R → 5; S → 3
  2. (B)P → 5; Q → 4; R → 2; S → 3
  3. (C)P → 3; Q → 2; R → 1; S → 4
  4. (D)P → 1; Q → 3; R → 5; S → 4

Correct answer: (A)

Step-by-step solution →
Q3·ChemistrySingle correctJEE Advanced 2026
The correct order of dipole moments for the given species is
  1. (A)BF3=NH4+<NF3<NH3\mathrm{BF_3} = \mathrm{NH_4^+} < \mathrm{NF_3} < \mathrm{NH_3}BF3​=NH4+​<NF3​<NH3​
  2. (B)BF3<NH4+<NF3<NH3\mathrm{BF_3} < \mathrm{NH_4^+} < \mathrm{NF_3} < \mathrm{NH_3}BF3​<NH4+​<NF3​<NH3​
  3. (C)NH4+<BF3<NH3<NF3\mathrm{NH_4^+} < \mathrm{BF_3} < \mathrm{NH_3} < \mathrm{NF_3}NH4+​<BF3​<NH3​<NF3​
  4. (D)BF3<NH4+<NH3<NF3\mathrm{BF_3} < \mathrm{NH_4^+} < \mathrm{NH_3} < \mathrm{NF_3}BF3​<NH4+​<NH3​<NF3​

Correct answer: (A)

Step-by-step solution →
Q4·ChemistrySingle correctJEE Main 2026
Bromine trifluoride autoionizes to form BrF2⊕BrF_2^{\oplus}BrF2⊕​ and BrF4⊖BrF_4^{\ominus}BrF4⊖​. The shapes of the cation and anion are respectively ________, and ________.
  1. (A)bent, square planar
  2. (B)linear, square planar
  3. (C)bent, see-saw
  4. (D)linear, tetrahedral

Correct answer: (A)

Step-by-step solution →
Q5·ChemistrySingle correctJEE Main 2026
The pairs among A = [SO₃²⁻, CO₃²⁻], B = [O₂²⁻, F₂], C = [CN⁻, CO], D = [NH₃, H₃O⁺] and E = [MnO₄²⁻, CrO₄²⁻] that do not have similar Lewis dot structure are
  1. (A)A, B and E
  2. (B)A and E
  3. (C)B, C and D
  4. (D)C and D

Correct answer: (B)

Step-by-step solution →
Q6·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I : The number of compounds among SO2\mathrm{SO_{2}}SO2​, SO3\mathrm{SO_{3}}SO3​, SF4\mathrm{SF_{4}}SF4​, SF6\mathrm{SF_{6}}SF6​ and H2S\mathrm{H_{2}S}H2​S in which sulphur does not obey the Octet rule is 3. Statement II : Among [H2O[\mathrm{H_{2}O}[H2​O, ClF3\mathrm{ClF_{3}}ClF3​, SF4]\mathrm{SF_{4}}]SF4​], [NH3[\mathrm{NH_{3}}[NH3​, BrF5\mathrm{BrF_{5}}BrF5​, SF4]\mathrm{SF_{4}}]SF4​], [BrF5[\mathrm{BrF_{5}}[BrF5​, ClF3\mathrm{ClF_{3}}ClF3​, XeF4]\mathrm{XeF_{4}}]XeF4​] and [XeF4[\mathrm{XeF_{4}}[XeF4​, ClF3\mathrm{ClF_{3}}ClF3​, H2O]\mathrm{H_{2}O}]H2​O], the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q7·ChemistryNumericalJEE Main 2026
Consider the following species: BrF5_55​, XeF5−_5^-5−​, BF4−_4^-4−​, ICl4−_4^-4−​, XeF4_44​, SF4_44​, NH4+_4^+4+​, ClF3_33​, XeF2_22​, ICl2−_2^-2−​ Number of species having sp3^33d hybridized central atom is __________.

Correct answer: 4

Step-by-step solution →
Q8·ChemistrySingle correctJEE Main 2026
Which of the following pictorial diagram most correctly represents the π* (π-antibonding) molecular orbital between two atoms if the internuclear axis is taken to be in the z-direction (→z-axis\xrightarrow{\text{z-axis}}z-axis​)?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q9·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement (I) : The correct sequence of bond lengths in the following species is : O2+<O2<O2−<O22−\mathrm{O_{2}^{+}} < \mathrm{O_{2}} < \mathrm{O_{2}^{-}} < \mathrm{O_{2}^{2-}}O2+​<O2​<O2−​<O22−​ Statement (II) : The correct sequence of number of unpaired electrons in the following species is : O2>O2+>O2−>O22−\mathrm{O_{2}} > \mathrm{O_{2}^{+}} > \mathrm{O_{2}^{-}} > \mathrm{O_{2}^{2-}}O2​>O2+​>O2−​>O22−​ In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q10·ChemistrySingle correctJEE Main 2026
SF4SF_4SF4​ is isostructural with: A. BrF4⊖BrF_4^{\ominus}BrF4⊖​ B. CH4CH_4CH4​ C. IF4⊕IF_4^{\oplus}IF4⊕​ D. XeF4XeF_4XeF4​ E. XeO2F2XeO_2F_2XeO2​F2​ Choose the correct answer from the options given below:
  1. (A)C Only
  2. (B)C and E Only
  3. (C)A and D Only
  4. (D)B and E Only

Correct answer: (B)

Step-by-step solution →
Q11·ChemistrySingle correctJEE Main 2026
Given below are two statements: Statement I: The number of species among BF4−_{4}^{-}4−​, SiF4_{4}4​, XeF4_{4}4​ and SF4_{4}4​, that have unequal E–F bond lengths is two. Here, E is the central atom. Statement II: Among O2−_{2}^{-}2−​, O22−_{2}^{2-}22−​, F2_{2}2​ and O2+_{2}^{+}2+​, O2−_{2}^{-}2−​ has the highest bond order. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q12·ChemistrySingle correctJEE Main 2026
Pair of species among the following having same bond order as well as paramagnetic character will be-
  1. (A)O2+,N22−\text{O}_{2}^{+}, \text{N}_{2}^{2-}O2+​,N22−​
  2. (B)O2−,N2+\text{O}_{2}^{-}, \text{N}_{2}^{+}O2−​,N2+​
  3. (C)O2+,N2−\text{O}_{2}^{+}, \text{N}_{2}^{-}O2+​,N2−​
  4. (D)O2−,N2−\text{O}_{2}^{-}, \text{N}_{2}^{-}O2−​,N2−​

Correct answer: (C)

Step-by-step solution →
Q13·ChemistrySingle correctJEE Main 2026
Given below are statements about some molecules/ions. Identify the CORRECT statements. A. The dipole moment value of NF3NF_3NF3​ is higher than that of NH3NH_3NH3​. B. The dipole moment value of BeH2BeH_2BeH2​ is zero. C. The bond order of O22−O_2^{2-}O22−​ and F2F_2F2​ is same. D. The formal charge on the central oxygen atom of ozone is –1. E. In NO2NO_2NO2​, all the three atoms satisfy the octet rule, hence it is very stable. Choose the correct answer from the options given below :
  1. (A)A, B, C, D & E
  2. (B)B & C only
  3. (C)B, C & D only
  4. (D)A, C & D only

Correct answer: (B)

Step-by-step solution →
Q14·ChemistrySingle correctJEE Main 2026
Identify the molecule(X) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among HNO3_33​, H2_22​SO4_44​, NF3_33​ and O3_33​. Choose the correct bond angle made by the central atom of the molecule (X).
  1. (A)120°
  2. (B)107°
  3. (C)102°
  4. (D)116°

Correct answer: (C)

Step-by-step solution →
Q15·ChemistrySingle correctJEE Main 2026
Two p-block elements X and Y form fluroides of the type EF3_33​. The fluoride compound XF3_33​ is a Lewis acid and YF3_33​ is a Lewis base. The hybridization of the central atoms of XF3_33​ and YF3_33​ respectively are
  1. (A)Both sp3^33
  2. (B)sp2^22 and sp3^33
  3. (C)sp3^33 and sp2^22
  4. (D)Both sp2^22

Correct answer: (B)

Step-by-step solution →
Q16·ChemistrySingle correctJEE Main 2026
The formal changes on the atoms marked as (1) to (4) in the Lewis representation of HnO3_33​ molecule respectively are
  1. (A)+1, 0, 0, –1
  2. (B)0, –1, 0, +1
  3. (C)0, +1, 0, –1
  4. (D)0, 0, –1, +1

Correct answer: (C)

Step-by-step solution →
Q17·ChemistrySingle correctJEE Main 2026
Among H2SH_2SH2​S, H2OH_2OH2​O, NF3NF_3NF3​, NH3NH_3NH3​ and CHCl3CHCl_3CHCl3​, identify the molecule (X) with lowest dipole moment value. The number of lone pairs of electrons present on the central atom of the molecule (X) is :
  1. (A)2
  2. (B)0
  3. (C)1
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q18·ChemistrySingle correctJEE Main 2026
The correct increasing order of C−H(A)\text{C}-\text{H}(\text{A})C−H(A), C−O(B)\text{C}-\text{O}(\text{B})C−O(B), C=O(C)\text{C}=\text{O}(\text{C})C=O(C) and C≡N(D)\text{C}\equiv \text{N}(\text{D})C≡N(D) bonds in terms of covalent bond length is:
  1. (A)A<B<C<D\text{A} < \text{B} < \text{C} < \text{D}A<B<C<D
  2. (B)A<D<C<B\text{A} < \text{D} < \text{C} < \text{B}A<D<C<B
  3. (C)D<C<B<A\text{D} < \text{C} < \text{B} < \text{A}D<C<B<A
  4. (D)D<C<A<B\text{D} < \text{C} < \text{A} < \text{B}D<C<A<B

Correct answer: (B)

Step-by-step solution →
Q19·ChemistrySingle correctJEE Main 2026
Given below are two statements: Statement I: The number of species among SF4_44​, NH4+_4^+4+​, [NiCl4_44​], XeF4_44​, [PtC14_44​]2−^{2-}2−, SeF4_44​ and [Ni(CN)4_44​]2−^{2-}2−, that have tetrahedral geometry is 3. Statement II: In the set [NO2_22​, BeH2_22​, BF3_33​, AIC13_33​], all the molecules have incomplete octet around central atom. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are true

Correct answer: (C)

Step-by-step solution →
Q20·ChemistryMultiple correctJEE Advanced 2025
Regarding the molecular orbital (MO) energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is(are)
  1. (A)Bond order of Ne2Ne_2Ne2​ is zero.
  2. (B)The highest occupied molecular orbital (HOMO) of F2F_2F2​ is σ-type.
  3. (C)Bond energy of O2+O_2^+O2+​ is smaller than the bond energy of O2O_2O2​.
  4. (D)Bond length of Li2Li_2Li2​ is larger than the bond length of B2B_2B2​.

Correct answer: (B), (C)

Step-by-step solution →
Q21·ChemistryIntegerJEE Main 2025
Resonance in X2YX_2YX2​Y can be represented as shown in the figure. The enthalpy of formation of X2YX_2YX2​Y (X≡X(g)+12Y=Y(g)→X2Y(g))\left(X\equiv X(g)+\dfrac{1}{2}Y=Y(g)\to X_2Y(g)\right)(X≡X(g)+21​Y=Y(g)→X2​Y(g)) is 80 kJ mol−1^{-1}−1. The magnitude of resonance energy of X2YX_2YX2​Y is ___ kJ mol−1^{-1}−1 (nearest integer value). Given: Bond energies of X≡XX\equiv XX≡X, X=XX=XX=X, Y=YY=YY=Y and X=YX=YX=Y are 940, 410, 500 and 602 kJ mol−1^{-1}−1 respectively. valence X : 3, Y : 2

Correct answer: 98

Step-by-step solution →
Q22·ChemistrySingle correctJEE Main 2025
In SO2SO_2SO2​, NO2−NO_2^-NO2−​ and N3−N_3^-N3−​ the hybridizations at the central atom are respectively:
  1. (A)sp2sp^2sp2, sp2sp^2sp2 and spspsp
  2. (B)sp2sp^2sp2, spspsp and spspsp
  3. (C)sp2sp^2sp2, sp2sp^2sp2 and sp2sp^2sp2
  4. (D)spspsp, sp2sp^2sp2 and spspsp

Correct answer: (A)

Step-by-step solution →
Q23·ChemistrySingle correctJEE Main 2025
Match the List-I (molecule/ion) with List-II (bond pair : lone pair on the central atom). Choose the correct answer from the options given below:
List-I (Molecule/ion)List-II (Bond pair : lone pair on the central atom)
A.ICl2−ICl_2^-ICl2−​I.4 : 2
B.H2OH_2OH2​OII.4 : 1
C.SO2SO_2SO2​III.2 : 3
D.XeF4XeF_4XeF4​IV.2 : 2
  1. (A)A-IV, B-III, C-II, D-I
  2. (B)A-III, B-IV, C-II, D-I
  3. (C)A-III, B-IV, C-I, D-II
  4. (D)A-IV, B-I, C-IV, D-III

Correct answer: (B)

Step-by-step solution →
Q24·ChemistrySingle correctJEE Main 2025
Which of the following molecules(s) show/s paramagnetic behavior? (A) O2O_2O2​ (B) N2N_2N2​ (C) F2F_2F2​ (D) S2S_2S2​ (E) Cl2Cl_2Cl2​. Choose the correct answer from the options given below:
  1. (A)B only
  2. (B)A & C only
  3. (C)A & E only
  4. (D)A & D only

Correct answer: (D)

Step-by-step solution →
Q25·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement (I): for ClF3ClF_3ClF3​, all three possible structures may be drawn as follows. Statement (II): Structure III is most stable, as the orbitals having the lone pairs are axial, where the lp–bp repulsion is minimum. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but statement II is correct
  2. (B)Statement I is correct but statement II is incorrect
  3. (C)Both Statement I and statement II are correct
  4. (D)Both Statement I and statement II are incorrect

Correct answer: (B)

Step-by-step solution →
Q26·ChemistrySingle correctJEE Main 2025
Match the LIST-I (Molecules/ion) with LIST-II (Hybridisation of central atom). Choose the correct answer from the options given below:
LIST-I (Molecules/ion)LIST-II (Hybridisation of central atom)
A.PF5PF_5PF5​I.dsp2dsp^2dsp2
B.SF6SF_6SF6​II.sp3dsp^3dsp3d
C.Ni(CO)4Ni(CO)_4Ni(CO)4​III.sp3d2sp^3d^2sp3d2
D.[PtCl4]2−[PtCl_4]^{2-}[PtCl4​]2−IV.sp3sp^3sp3
  1. (A)(A)-II, (B)-III, (C)-IV, (D)-I
  2. (B)(A)-IV, (B)-I, (C)-II, (D)-III
  3. (C)(A)-I, (B)-II, (C)-III, (D)-IV
  4. (D)(A)-III, (B)-I, (C)-IV, (D)-II

Correct answer: (A)

Step-by-step solution →
Q27·ChemistrySingle correctJEE Main 2025
Which among the following molecules is (a) involved in sp3dsp^3dsp3d hybridization, (b) has different bond lengths and (c) has lone pair of electrons on the central atom?
  1. (A)PF5PF_5PF5​
  2. (B)XeF4XeF_4XeF4​
  3. (C)SF4SF_4SF4​
  4. (D)XeF2XeF_2XeF2​

Correct answer: (C)

Step-by-step solution →
Q28·ChemistrySingle correctJEE Main 2025
Among SO2SO_2SO2​, NF3NF_3NF3​, NH3NH_3NH3​, XeF2XeF_2XeF2​, ClF3ClF_3ClF3​ and SF4SF_4SF4​, the hybridization of the molecule with non-zero dipole moment and highest number of lone-pairs of electrons on the central atom is:
  1. (A)sp3sp^3sp3
  2. (B)dsp2dsp^2dsp2
  3. (C)sp3d2sp^3d^2sp3d2
  4. (D)sp3dsp^3dsp3d

Correct answer: (D)

Step-by-step solution →
Q29·ChemistryIntegerJEE Main 2025
Total number of non bonded electrons present in NO2−NO_2^-NO2−​ ion based on Lewis theory is ______.

Correct answer: 12

Step-by-step solution →
Q30·ChemistrySingle correctJEE Main 2025
The molecules having square pyramidal geometry are:
  1. (A)BrF5_55​ & XeOF4_44​
  2. (B)SbF5_55​ & XeOF4_44​
  3. (C)SbF5_55​ & PCl5_55​
  4. (D)BrF5_55​ & PCl5_55​

Correct answer: (A)

Step-by-step solution →
Q31·ChemistryIntegerJEE Main 2025
Total number of molecules/species from following which will be paramagnetic is ______. O2_22​, O2+_2^+2+​, O2−_2^-2−​, NO, NO2_22​, CO, K2_22​[NiCl4_44​], [Co(NH3_33​)6_66​]Cl3_33​, K2_22​[Ni(CN)4_44​]

Correct answer: 6

Step-by-step solution →
Q32·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement (I): Experimentally determined oxygen-oxygen bond lengths in O3_33​ are found to be same and the bond length is greater than that of a O=O (double bond) but less than that of a single bond (O–O). Statement (II): The strong lone pair-lone pair repulsion between oxygen atoms is solely responsible for the fact about the bond length in ozone. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Statement I is true but Statement II is false
  2. (B)Statement I is true and Statement II is true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correctJEE Main 2025
Which of the following linear combination of atomic orbitals will lead to formation of molecular orbitals in homonuclear diatomic molecules [internuclear axis in z-direction] ? A. 2pz2p_z2pz​ and 2px2p_x2px​ B. 2s and 2px2p_x2px​ C. 3dxy3d_{xy}3dxy​ and 3dx2−y23d_{x^2-y^2}3dx2−y2​ D. 2s and 2pz2p_z2pz​ E. 2pz2p_z2pz​ and 3dz23d_{z^2}3dz2​. Choose the correct answer from the options given below :
  1. (A)E Only
  2. (B)A and B Only
  3. (C)D Only
  4. (D)C and D Only

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correctJEE Main 2025
Which of the following statement is true with respect to H₂O, NH₃ and CH₄? A. The central atoms of all the molecules are sp³ hybridized. B. The H-O-H, H-N-H and H-C-H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively. C. The increasing order of dipole moment is CH₄ < NH₃ < H₂O. D. Both H₂O and NH₃ are Lewis acids and CH₄ a Lewis base. E. A solution of NH₃ in H₂O is basic. In this solution NH₃ and H₂O act as Lowry-Bronsted acid and base respectively. Choose the correct answer from the options given below :
  1. (A)A, B and C only
  2. (B)C, D and E only
  3. (C)A, D and E only
  4. (D)A, B, C and E only

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correctJEE Main 2025
Match List-I (Octet Behaviour) with List-II (Example Molecules). Choose the correct answer from the options given below:
List-I (Octet Behaviour)List-II (Example Molecules)
A.Molecules obeying octet ruleI.NO, NO₂
B.Molecules with incomplete octetII.BCl₃, AlCl₃
C.Molecules with incomplete octet with odd electronIII.H₂SO₄, PCl₅
D.Molecules with expanded octetIV.CCl₄, CO₂
  1. (A)A-IV, B-II, C-I, D-III
  2. (B)A-III, B-II, C-I, D-IV
  3. (C)A-IV, B-I, C-III, D-II
  4. (D)A-II, B-IV, C-III, D-I

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correctJEE Main 2025
Arrange the following compounds in increasing order of their dipole moment: HBr, H2_22​S, NF3_33​ and CHCl3_33​
  1. (A)NF3<HBr<H2S<CHCl3NF_3 < HBr < H_2S < CHCl_3NF3​<HBr<H2​S<CHCl3​
  2. (B)HBr<H2S<NF3<CHCl3HBr < H_2S < NF_3 < CHCl_3HBr<H2​S<NF3​<CHCl3​
  3. (C)H2S<HBr<NF3<CHCl3H_2S < HBr < NF_3 < CHCl_3H2​S<HBr<NF3​<CHCl3​
  4. (D)CHCl3<NF3<HBr<H2SCHCl_3 < NF_3 < HBr < H_2SCHCl3​<NF3​<HBr<H2​S

Correct answer: (A)

Step-by-step solution →
Q37·ChemistryIntegerJEE Main 2025
The number of molecules/ions that show linear geometry among the following is ______: SO₂, BeCl₂, CO₂, N₃⁻, NO₂, F₂O, XeF₂, NO₂⁺, I₃⁻, O₃.

Correct answer: 6

Step-by-step solution →
Q38·ChemistryMultiple correctJEE Advanced 2024
The option(s) in which at least three molecules follow Octet Rule is(are)
  1. (A)CO2_{2}2​, C2_{2}2​H4_{4}4​, NO and HCl
  2. (B)NO2_{2}2​, O3_{3}3​, HCl and H2_{2}2​SO4_{4}4​
  3. (C)BCl3_{3}3​, NO, NO2_{2}2​ and H2_{2}2​SO4_{4}4​
  4. (D)CO2_{2}2​, BCl3_{3}3​, O3_{3}3​ and C2_{2}2​H4_{4}4​

Correct answer: (A), (D)

Step-by-step solution →
Q39·ChemistrySingle correctJEE Advanced 2024
Based on VSEPR\mathbf{VSEPR}VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.
List-IList-II
P.XeF2_{2}2​1.Trigonal bipyramidal and two lone pair of electrons
Q.XeF4_{4}4​2.Tetrahedral and one lone pair of electrons
R.XeO3_{3}3​3.Octahedral and two lone pair of electrons
S.XeO3_{3}3​F2_{2}2​4.Trigonal bipyramidal and no lone pair of electrons
5.Trigonal bipyramidal and three lone pair of electrons
  1. (A)(P) →\to→ (5), (Q) →\to→ (2), (R) →\to→ (3), (S) →\to→ (1)
  2. (B)(P) →\to→ (5), (Q) →\to→ (3), (R) →\to→ (2), (S) →\to→ (4)
  3. (C)(P) →\to→ (4), (Q) →\to→ (3), (R) →\to→ (2), (S) →\to→ (1)
  4. (D)(P) →\to→ (4), (Q) →\to→ (2), (R) →\to→ (5), (S) →\to→ (3)

Correct answer: (B)

Step-by-step solution →
Q40·ChemistryNumericalJEE Main 2024
Total number of electrons present in (π∗)(\pi^{*})(π∗) molecular orbitals of O2O_2O2​, O2+O_2^{+}O2+​ and O2−O_2^{-}O2−​ is _______.

Correct answer: 6

Step-by-step solution →
Q41·ChemistryNumericalJEE Main 2024
The total number of species from the following in which one unpaired electron is present, is _____. N2,O2,C2−,O2−,O22−,H2+,CN−,He2+N_2, O_2, C_2^-, O_2^-, O_2^{2-}, H_2^+, CN^-, He_2^+N2​,O2​,C2−​,O2−​,O22−​,H2+​,CN−,He2+​

Correct answer: 4

Step-by-step solution →
Q42·ChemistrySingle correctJEE Main 2024
In which one of the following pairs the central atoms exhibit sp2sp^2sp2 hybridization ?
  1. (A)BF3BF_3BF3​ and NO2−NO_2^-NO2−​
  2. (B)NH2−NH_2^-NH2−​ and H2OH_2OH2​O
  3. (C)H2OH_2OH2​O and NO2NO_2NO2​
  4. (D)NH2−NH_2^-NH2−​ and BF3BF_3BF3​

Correct answer: (A)

Step-by-step solution →
Q43·ChemistrySingle correctJEE Main 2024
The correct increasing order for bond angles among BF3BF_3BF3​, PF3PF_3PF3​ and ClF3ClF_3ClF3​ is:
  1. (A)PF3<ClF3<BF3PF_3 < ClF_3 < BF_3PF3​<ClF3​<BF3​
  2. (B)BF3<PF3<ClF3BF_3 < PF_3 < ClF_3BF3​<PF3​<ClF3​
  3. (C)ClF3<PF3<BF3ClF_3 < PF_3 < BF_3ClF3​<PF3​<BF3​
  4. (D)BF3=PF3=ClF3BF_3 = PF_3 = ClF_3BF3​=PF3​=ClF3​

Correct answer: (C)

Step-by-step solution →
Q44·ChemistryNumericalJEE Main 2024
Number of molecules having bond order 2 from the following molecules is _______. C2\text{C}_2C2​, O2\text{O}_2O2​, Be2\text{Be}_2Be2​, Li2\text{Li}_2Li2​, Ne2\text{Ne}_2Ne2​, N2\text{N}_2N2​, He2\text{He}_2He2​

Correct answer: 2

Step-by-step solution →
Q45·ChemistrySingle correctJEE Main 2024
Match List-I (molecules) with List-II (their shapes). Choose the correct answer from the options given below:
List-I (Molecule)List-II (Shape)
A.NH3NH_3NH3​I.Square pyramidal
B.BrF5BrF_5BrF5​II.Tetrahedral
C.PCl5PCl_5PCl5​III.Trigonal pyramidal
D.CH4CH_4CH4​IV.Trigonal bipyramidal
  1. (A)A-IV, B-III, C-I, D-II
  2. (B)A-II, B-IV, C-I, D-III
  3. (C)A-III, B-I, C-IV, D-II
  4. (D)A-III, B-I, C-I, D-II

Correct answer: (C)

Step-by-step solution →
Q46·ChemistryNumericalJEE Main 2024
Number of molecules from the following which are exceptions to octet rule is ___. CO2CO_2CO2​, NO2NO_2NO2​, H2SO4H_2SO_4H2​SO4​, BF3BF_3BF3​, CH4CH_4CH4​, SiF4SiF_4SiF4​, ClO2ClO_2ClO2​, PCl5PCl_5PCl5​, BeF2BeF_2BeF2​, C2H6C_2H_6C2​H6​, CHCl3CHCl_3CHCl3​, CBr4CBr_4CBr4​

Correct answer: 6

Step-by-step solution →
Q47·ChemistrySingle correctJEE Main 2024
When ψA\psi_AψA​ and ψB\psi_BψB​ are the wave functions of atomic orbitals, then ψ∗\psi^*ψ∗ is represented by:
  1. (A)ψA−2ψB\psi_A-2\psi_BψA​−2ψB​
  2. (B)ψA−ψB\psi_A-\psi_BψA​−ψB​
  3. (C)ψA+2ψB\psi_A+2\psi_BψA​+2ψB​
  4. (D)ψA+ψB\psi_A+\psi_BψA​+ψB​

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correctJEE Main 2024
Match List-I (Compound / Species) with List-II (Shape / Geometry). Choose the correct answer from the options given below:
List-I (Compound / Species)List-II (Shape / Geometry)
A.SF4SF_4SF4​I.Tetrahedral
B.BrF3BrF_3BrF3​II.Pyramidal
C.BrO3−BrO_3^{-}BrO3−​III.See saw
D.NH4+NH_4^{+}NH4+​IV.Bent T-shape
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-III, B-IV, C-II, D-I
  3. (C)A-II, B-IV, C-III, D-I
  4. (D)A-III, B-II, C-IV, D-I

Correct answer: (B)

Step-by-step solution →
Q49·ChemistrySingle correctJEE Main 2024
Match List-I (Molecule / Species) with List-II (Property / Shape). Choose the correct answer from the options given below:
List-I (Molecule / Species)List-II (Property / Shape)
A.SO2Cl2SO_2Cl_2SO2​Cl2​I.Paramagnetic
B.NONONOII.Diamagnetic
C.NO2−NO_2^{-}NO2−​III.Tetrahedral
D.I3−I_3^{-}I3−​IV.Linear
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-III, B-I, C-II, D-IV
  3. (C)A-II, B-III, C-I, D-IV
  4. (D)A-III, B-IV, C-II, D-I

Correct answer: (B)

Step-by-step solution →
Q50·ChemistryNumericalJEE Main 2024
Total number of species from the following with central atom utilising 2p22p^22p2 hybrid orbitals for bonding is _______. NH3NH_3NH3​, SO2SO_2SO2​, SiO2SiO_2SiO2​, BeCl2BeCl_2BeCl2​, C2H2C_2H_2C2​H2​, C2H4C_2H_4C2​H4​, BCl3BCl_3BCl3​, HCHOHCHOHCHO, C6H6C_6H_6C6​H6​, BF3BF_3BF3​, C2H4Cl2C_2H_4Cl_2C2​H4​Cl2​

Correct answer: 6

Step-by-step solution →
Q51·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement I: PF5PF_5PF5​ and BrF5BrF_5BrF5​ both exhibit sp3dsp^3dsp3d hybridisation. Statement II: Both SF6SF_6SF6​ and [Co(NH3)6]3+[Co(NH_3)_6]^{3+}[Co(NH3​)6​]3+ exhibit sp3d2sp^3d^2sp3d2 hybridisation. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q52·ChemistryNumericalJEE Main 2024
The number of molecules from the following which can exhibit hydrogen bonding is _______ (nearest integer): CH3OHCH_3OHCH3​OH, H2OH_2OH2​O, C2H6C_2H_6C2​H6​, C6H6C_6H_6C6​H6​, (the compound shown in the figure), HFHFHF, NH3NH_3NH3​.

Correct answer: 5

Step-by-step solution →
Q53·ChemistrySingle correctJEE Main 2024
Match List-I (Hybridization) with List-II (Orientation in Space). Choose the correct answer from the options given below:
List-I (Hybridization)List-II (Orientation in Space)
A.sp3sp^3sp3I.Trigonal bipyramidal
B.dsp2dsp^2dsp2II.Octahedral
C.sp3dsp^3dsp3dIII.Tetrahedral
D.sp3d2sp^3d^2sp3d2IV.Square planar
  1. (A)A-III, B-I, C-IV, D-II
  2. (B)A-II, B-I, C-IV, D-III
  3. (C)A-IV, B-III, C-I, D-II
  4. (D)A-III, B-IV, C-I, D-II

Correct answer: (D)

Step-by-step solution →
Q54·ChemistryNumericalJEE Main 2024
The number of compounds from the following with zero dipole moment is __________. HF\text{HF}HF, H2\text{H}_2H2​, H2S\text{H}_2\text{S}H2​S, CO2\text{CO}_2CO2​, NH3\text{NH}_3NH3​, BF3\text{BF}_3BF3​, CH4\text{CH}_4CH4​, CHCl3\text{CHCl}_3CHCl3​, SiF4\text{SiF}_4SiF4​, H2O\text{H}_2\text{O}H2​O, BeF2\text{BeF}_2BeF2​.

Correct answer: 6

Step-by-step solution →
Q55·ChemistryNumericalJEE Main 2024
In the Lewis dot structure for NO2−\text{NO}_2^-NO2−​, the total number of valence electrons around nitrogen is ___.

Correct answer: 8

Step-by-step solution →
Q56·ChemistrySingle correctJEE Main 2024
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): NH3\text{NH}_3NH3​ and NF3\text{NF}_3NF3​ molecules have a pyramidal shape with a lone pair of electrons on the nitrogen atom. The resultant dipole moment of NH3\text{NH}_3NH3​ is greater than that of NF3\text{NF}_3NF3​. Reason (R): In NH3\text{NH}_3NH3​, the orbital dipole due to the lone pair is in the same direction as the resultant dipole moment of the N–H bonds; F is the most electronegative element. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. (B)(A) is false but (R) is true
  3. (C)(A) is true but (R) is false
  4. (D)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

Correct answer: (A)

Step-by-step solution →
Q57·ChemistrySingle correctJEE Main 2024
Match List-I (interhalogen / halogen species) with List-II (molecular shape). Choose the correct answer from the options given below:
List-IList-II
A.ICl\text{ICl}IClI.T-Shape
B.ICl3\text{ICl}_3ICl3​II.Square pyramidal
C.ClF5\text{ClF}_5ClF5​III.Pentagonal bipyramidal
D.IF7\text{IF}_7IF7​IV.Linear
  1. (A)(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  2. (B)(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  3. (C)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  4. (D)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Correct answer: (C)

Step-by-step solution →
Q58·ChemistrySingle correctJEE Main 2024
The number of σ\sigmaσ and π\piπ bonds present in an ethylene molecule is respectively:
  1. (A)3 and 1
  2. (B)5 and 2
  3. (C)4 and 1
  4. (D)5 and 1

Correct answer: (D)

Step-by-step solution →
Q59·ChemistrySingle correctJEE Main 2024
The number of species from the following that have pyramidal geometry around the central atom is: S2O32−\text{S}_2\text{O}_3^{2-}S2​O32−​, SO42−\text{SO}_4^{2-}SO42−​, SO32−\text{SO}_3^{2-}SO32−​, S2O72−\text{S}_2\text{O}_7^{2-}S2​O72−​
  1. (A)4
  2. (B)3
  3. (C)1
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q60·ChemistryNumericalJEE Main 2024
Number of compounds/species from the following with non-zero dipole moment is ______: BeCl2\text{BeCl}_2BeCl2​, BCl3\text{BCl}_3BCl3​, NF3\text{NF}_3NF3​, XeF4\text{XeF}_4XeF4​, CCl4\text{CCl}_4CCl4​, H2O\text{H}_2\text{O}H2​O, H2S\text{H}_2\text{S}H2​S, HBr\text{HBr}HBr, CO2\text{CO}_2CO2​, H2\text{H}_2H2​, HCl\text{HCl}HCl.

Correct answer: 5

Step-by-step solution →
Q61·ChemistrySingle correctJEE Main 2024
Which one of the following molecules has maximum dipole moment?
  1. (A)NF3NF_3NF3​
  2. (B)CH4CH_4CH4​
  3. (C)NH3NH_3NH3​
  4. (D)PF3PF_3PF3​

Correct answer: (C)

Step-by-step solution →
Q62·ChemistrySingle correctJEE Main 2024
The correct statement/s about Hydrogen bonding is/are: A. Hydrogen bonding exists when H is covalently bonded to the highly electro negative atom. B. Intermolecular H bonding is present in o-nitro phenol. C. Intramolecular H bonding is present in HF. D. The magnitude of H bonding depends on the physical state of the compound. E. H-bonding has powerful effect on the structure and properties of compounds. Choose the correct answer from the options given below:
  1. (A)A only
  2. (B)A, D, E only
  3. (C)A, B, D only
  4. (D)A, B, C only

Correct answer: (B)

Step-by-step solution →
Q63·ChemistrySingle correctJEE Main 2024
Number of molecules/ions from the following in which the central atom is involved in sp3sp^3sp3 hybridization is ___. NO3−NO_3^-NO3−​, BCl3BCl_3BCl3​, ClO2−ClO_2^-ClO2−​, ClO3−ClO_3^-ClO3−​
  1. (A)222
  2. (B)444
  3. (C)333
  4. (D)111

Correct answer: (A)

Step-by-step solution →
Q64·ChemistryNumericalJEE Main 2024
Number of molecules/species from the following having one unpaired electron is ___. O2O_2O2​, O2−O_2^-O2−​, NONONO, CN−CN^-CN−, O22−O_2^{2-}O22−​

Correct answer: 2

Step-by-step solution →
Q65·ChemistryNumericalJEE Main 2024
Lowest Oxidation number of an atom in a compound A2BA_2BA2​B is −2-2−2. The number of an electron in its valence shell is ___

Correct answer: 6

Step-by-step solution →
Q66·ChemistrySingle correctJEE Main 2024
Arrange the bonds in order of increasing ionic character in the molecules. LiFLiFLiF, K2OK_2OK2​O, N2N_2N2​, SO2SO_2SO2​ and ClF3ClF_3ClF3​.
  1. (A)ClF3<N2<SO2<K2O<LiFClF_3<N_2<SO_2<K_2O<LiFClF3​<N2​<SO2​<K2​O<LiF
  2. (B)LiF<K2O<ClF3<SO2<N2LiF<K_2O<ClF_3<SO_2<N_2LiF<K2​O<ClF3​<SO2​<N2​
  3. (C)N2<SO2<ClF3<K2O<LiFN_2<SO_2<ClF_3<K_2O<LiFN2​<SO2​<ClF3​<K2​O<LiF
  4. (D)N2<ClF3<SO2<K2O<LiFN_2<ClF_3<SO_2<K_2O<LiFN2​<ClF3​<SO2​<K2​O<LiF

Correct answer: (C)

Step-by-step solution →
Q67·ChemistryNumericalJEE Main 2024
The number of molecules/ion/s having trigonal bipyramidal geometry among the following is ___. PF5PF_5PF5​, BrF5BrF_5BrF5​, PCl5PCl_5PCl5​, [PtCl4]2−[PtCl_4]^{2-}[PtCl4​]2−, BF3BF_3BF3​, Fe(CO)5Fe(CO)_5Fe(CO)5​

Correct answer: 3

Step-by-step solution →
Q68·ChemistrySingle correctJEE Main 2024
Select the compound from the following that will show intramolecular hydrogen bonding.
  1. (A)H2O\text{H}_2\text{O}H2​O
  2. (B)NH3\text{NH}_3NH3​
  3. (C)C2H5OH\text{C}_2\text{H}_5\text{OH}C2​H5​OH
  4. (D)o-nitrophenol

Correct answer: (D)

Step-by-step solution →
Q69·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement (I): A π\piπ bonding MO has lower electron density above and below the inter-nuclear axis. Statement (II): The π∗\pi^*π∗ antibonding MO has a node between the nuclei. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is false but Statement II is true
  4. (D)Statement I is true but Statement II is false

Correct answer: (C)

Step-by-step solution →
Q70·ChemistryNumericalJEE Main 2024
A diatomic molecule has a dipole moment of 1.2 D. If the bond distance is 1 A˚1\,\text{\AA}1A˚, then fractional charge on each atom is ______ ×10−1\times10^{-1}×10−1 esu. (Given 1 D=10−181\,D=10^{-18}1D=10−18 esu cm)

Correct answer: 0

Step-by-step solution →
Q71·ChemistrySingle correctJEE Main 2024
Which of the following is least ionic?
  1. (A)BaCl2BaCl_2BaCl2​
  2. (B)AgClAgClAgCl
  3. (C)KClKClKCl
  4. (D)CoCl2CoCl_2CoCl2​

Correct answer: (B)

Step-by-step solution →
Q72·ChemistrySingle correctJEE Main 2024
The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals A. have the same energy B. have the minimum overlap C. have same symmetry about the molecular axis D. have different symmetry about the molecular axis Choose the most appropriate from the options given below:
  1. (A)A, B, C only
  2. (B)A and C only
  3. (C)B, C, D only
  4. (D)B and D only

Correct answer: (B)

Step-by-step solution →
Q73·ChemistryNumericalJEE Main 2024
The number of species from the following in which the central atom uses sp3sp^3sp3 hybrid orbitals in its bonding is ______. NH3NH_3NH3​, SO2SO_2SO2​, SiO2SiO_2SiO2​, BeCl2BeCl_2BeCl2​, CO2CO_2CO2​, H2OH_2OH2​O, CH4CH_4CH4​, BF3BF_3BF3​

Correct answer: 4

Step-by-step solution →
Q74·ChemistrySingle correctJEE Main 2024
The molecule/ion with square pyramidal shape is:
  1. (A)[Ni(CN)4]2−[Ni(CN)_4]^{2-}[Ni(CN)4​]2−
  2. (B)PCl5PCl_5PCl5​
  3. (C)BrF5BrF_5BrF5​
  4. (D)PF5PF_5PF5​

Correct answer: (C)

Step-by-step solution →
Q75·ChemistryNumericalJEE Main 2024
The total number of molecular orbitals formed from 2s and 2p atomic orbitals of a diatomic molecule is ___

Correct answer: 8

Step-by-step solution →
Q76·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement-I: Since fluorine is more electronegative than nitrogen, the net dipole moment of NF3NF_3NF3​ is greater than NH3NH_3NH3​. Statement-II: In NH3NH_3NH3​ the orbital dipole due to lone pair and the dipole moment of NH bonds are in opposite direction, but in NF3NF_3NF3​ the orbital dipole due to lone pair and dipole moments of N-F bonds are in same direction. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is true but Statement II is false.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Both Statement I and Statement II are true.
  4. (D)Statement I is false but Statement II is true.

Correct answer: (B)

Step-by-step solution →
Q77·ChemistrySingle correctJEE Main 2024
Match List-I (molecules) with List-II (their shapes). Choose the correct answer:
List-I (Molecule)List-II (Shape)
A.BrF5BrF_5BrF5​I.T-shape
B.H2OH_2OH2​OII.See saw
C.ClF3ClF_3ClF3​III.Bent
D.SF4SF_4SF4​IV.Square pyramidal
  1. (A)(A)-I, (B)-II, (C)-IV, (D)-III
  2. (B)(A)-II, (B)-I, (C)-III, (D)-IV
  3. (C)(A)-III, (B)-IV, (C)-I, (D)-II
  4. (D)(A)-IV, (B)-III, (C)-I, (D)-II

Correct answer: (D)

Step-by-step solution →
Q78·ChemistryNumericalJEE Main 2024
The total number of anti bonding molecular orbitals, formed from 2s and 2p atomic orbitals in a diatomic molecule is ___.

Correct answer: 4

Step-by-step solution →
Q79·ChemistryNumericalJEE Main 2024
Number of compounds with one lone pair of electrons on central atom amongst following is ______ . O3O_3O3​, H2OH_2OH2​O, SF4SF_4SF4​, ClF3ClF_3ClF3​, NH3NH_3NH3​, BrF5BrF_5BrF5​, XeF4XeF_4XeF4​

Correct answer: 4

Step-by-step solution →
Q80·ChemistryNumericalJEE Main 2024
The total number of molecules with zero dipole moment among CH4CH_4CH4​, BF3BF_3BF3​, H2OH_2OH2​O, HFHFHF, NH3NH_3NH3​, CO2CO_2CO2​ and SO2SO_2SO2​ is ___.

Correct answer: 3

Step-by-step solution →
Q81·ChemistryNumericalJEE Main 2024
The total number of ‘Sigma’ and Pi bonds in 2-formylhex-4-enoic acid is ___.

Correct answer: 22

Step-by-step solution →
Q82·ChemistryNumericalJEE Main 2024
The number of species from the following which are paramagnetic and with bond order equal to one is ______ . H2H_2H2​, He2+He_2^+He2+​, O2+O_2^+O2+​, N22−N_2^{2-}N22−​, O22−O_2^{2-}O22−​, F2F_2F2​, Ne2+Ne_2^+Ne2+​, B2B_2B2​

Correct answer: 1

Step-by-step solution →
Q83·ChemistryNumericalJEE Main 2024
The number of non-polar molecules from the following is __________. HF, H2OH_2OH2​O, SO2SO_2SO2​, H2H_2H2​, CO2CO_2CO2​, CH4CH_4CH4​, HCl, CHCl3CHCl_3CHCl3​, BF3BF_3BF3​.

Correct answer: 4

Step-by-step solution →
Q84·ChemistryNumericalJEE Main 2024
Sum of bond order of CO and NO+^++ is __________.

Correct answer: 6

Step-by-step solution →
Q85·ChemistrySingle correctJEE Main 2024
Choose the polar molecule from the following:
  1. (A)CCl4\text{CCl}_4CCl4​
  2. (B)CO2\text{CO}_2CO2​
  3. (C)CH2=CH2\text{CH}_2=\text{CH}_2CH2​=CH2​
  4. (D)CHCl3\text{CHCl}_3CHCl3​

Correct answer: (D)

Step-by-step solution →
Q86·ChemistrySingle correctJEE Advanced 2023
The correct molecular orbital diagram for F2\mathrm{F_2}F2​ molecule in the ground state is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q87·ChemistryIntegerJEE Advanced 2023
Among [I3]+[\mathrm{I_3}]^{+}[I3​]+, [SiO4]4−[\mathrm{SiO_4}]^{4-}[SiO4​]4−, SO2Cl2\mathrm{SO_2Cl_2}SO2​Cl2​, XeF2\mathrm{XeF_2}XeF2​, SF4\mathrm{SF_4}SF4​, ClF3\mathrm{ClF_3}ClF3​, Ni(CO)4\mathrm{Ni(CO)_4}Ni(CO)4​, XeO2F2\mathrm{XeO_2F_2}XeO2​F2​, [PtCl4]2−[\mathrm{PtCl_4}]^{2-}[PtCl4​]2−, XeF4\mathrm{XeF_4}XeF4​, and SOCl2\mathrm{SOCl_2}SOCl2​, the total number of species having sp3sp^3sp3 hybridised central atom is ______.

Correct answer: 5

Step-by-step solution →
Q88·ChemistrySingle correctJEE Main 2023
Consider the following statements: (A) NF3NF_3NF3​ molecule has a trigonal planar structure. (B) Bond length of N2N_2N2​ is shorter than O2O_2O2​. (C) Isoelectronic molecules or ions have identical bond order. (D) Dipole moment of H2SH_2SH2​S is higher than that of water molecule. Choose the correct answer from the option below:
  1. (A)(A) and (D) are correct
  2. (B)(C) and (D) are correct
  3. (C)(A) and (B) are correct
  4. (D)(B) and (C) are correct

Correct answer: (D)

Step-by-step solution →
Q89·ChemistrySingle correctJEE Main 2023
ClF5ClF_{5}ClF5​ at room temperature is a:
  1. (A)Colourless gas with trigonal bipyramidal geometry
  2. (B)Colourless gas with square pyramidal geometry
  3. (C)Colourless liquid with square pyramidal geometry
  4. (D)Colourless liquid with trigonal bipyramidal geometry

Correct answer: (C)

Step-by-step solution →
Q90·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: SO2SO_2SO2​ and H2OH_2OH2​O both possess V-shaped structure. Statement II: The bond angle of SO2SO_2SO2​ is less than that of H2OH_2OH2​O. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (B)

Step-by-step solution →
Q91·ChemistrySingle correctJEE Main 2023
In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?
  1. (A)O2→O2+O_{2}\to O_{2}^{+}O2​→O2+​
  2. (B)NO→NO+NO\to NO^{+}NO→NO+
  3. (C)N2→N2+N_{2}\to N_{2}^{+}N2​→N2+​
  4. (D)O2→O2−O_{2}\to O_{2}^{-}O2​→O2−​

Correct answer: (B)

Step-by-step solution →
Q92·ChemistrySingle correctJEE Main 2023
The bond order and magnetic property of acetylide ion are same as that of
  1. (A)NO+^++
  2. (B)O2+_2^+2+​
  3. (C)O2−_2^-2−​
  4. (D)N2+_2^+2+​

Correct answer: (A)

Step-by-step solution →
Q93·ChemistryNumericalJEE Main 2023
The maximum number of lone pairs of electrons on the central atom from the following species is ____. ClO3−, XeF4, SF4ClO_3^-,\ XeF_4,\ SF_4ClO3−​, XeF4​, SF4​ and I3−I_3^-I3−​.

Correct answer: 3

Step-by-step solution →
Q94·ChemistrySingle correctJEE Main 2023
Match List-I (Species) with List-II (Geometry/Shape) and choose the correct answer.
List-I SpeciesList-II Geometry/Shape
A.H3O+H_3O^+H3​O+I.Tetrahedral
B.Acetylide anionII.Linear
C.NH4+NH_4^+NH4+​III.Pyramidal
D.ClO2−ClO_2^-ClO2−​IV.Bent
  1. (A)A-III, B-II, C-I, D-IV
  2. (B)A-III, B-I, C-II, D-IV
  3. (C)A-III, B-IV, C-I, D-II
  4. (D)A-III, B-IV, C-II, D-I

Correct answer: (A)

Step-by-step solution →
Q95·ChemistryNumericalJEE Main 2023
The number of bent-shaped molecule/s from the following is _________: N3−N_3^-N3−​, NO2+NO_2^+NO2+​, I3−I_3^-I3−​, SO2SO_2SO2​

Correct answer: 3

Step-by-step solution →
Q96·ChemistryNumericalJEE Main 2023
The number of molecules from the following which contain only lone pairs of electrons (in addition to bond pairs) is _______ : H2O,N2,CO,XeF4,NH3,NO,CO2,F2\text{H}_2\text{O}, \text{N}_2, \text{CO}, \text{XeF}_4, \text{NH}_3, \text{NO}, \text{CO}_2, \text{F}_2H2​O,N2​,CO,XeF4​,NH3​,NO,CO2​,F2​.

Correct answer: 4

Step-by-step solution →
Q97·ChemistrySingle correctJEE Main 2023
The pair from the following pairs having both compounds with net non-zero dipole moment is
  1. (A)Benzene, anisidine
  2. (B)1,4-Dichlorobenzene, 1,3-Dichlorobenzene
  3. (C)CH2_22​Cl2_22​, CHCl3_33​
  4. (D)cis-butene, trans-butene

Correct answer: (C)

Step-by-step solution →
Q98·ChemistryNumericalJEE Main 2023
The number of following factors which affect the percent covalent character of the ionic bond is ____ (a) Polarising power of cation (b) Extent of distortion of anion (c) Polarisability of the anion (d) Polarising power of anion

Correct answer: 3

Step-by-step solution →
Q99·ChemistryNumericalJEE Main 2023
The ratio of sigma and π\piπ bonds present in pyrophosphoric acid is ____.

Correct answer: 6

Step-by-step solution →
Q100·ChemistryNumericalJEE Main 2023
The number of species from the following carrying a single lone pair on the central atom xenon is ____. XeF5+XeF_5^+XeF5+​, XeO3XeO_3XeO3​, XeO2F2XeO_2F_2XeO2​F2​, XeF5−XeF_5^-XeF5−​, XeO3F2XeO_3F_2XeO3​F2​, XeOF4XeOF_4XeOF4​, XeF4XeF_4XeF4​

Correct answer: 4

Step-by-step solution →
Q101·ChemistryNumericalJEE Main 2023
In an ice crystal, each water molecule is hydrogen bonded to ____ neighbouring molecules.

Correct answer: 4

Step-by-step solution →
Q102·ChemistryNumericalJEE Main 2023
The number of species from the following which have square pyramidal structure is _____. PF5, BrF4−, IF5, BrF5, XeOF4, ICl4−PF_5,\,BrF_4^{-},\,IF_5,\,BrF_5,\,XeOF_4,\,ICl_4^{-}PF5​,BrF4−​,IF5​,BrF5​,XeOF4​,ICl4−​

Correct answer: 3

Step-by-step solution →
Q103·ChemistrySingle correctJEE Main 2023
Match List I with List II. Choose the correct answer from the options given below:
List I (Oxide)List II (Type of Bond)
A.N2O5N_2O_5N2​O5​I.1 N=O1\,N=O1N=O bond
B.NO2NO_2NO2​II.1 N−O−N1\,N-O-N1N−O−N bond
C.N2O3N_2O_3N2​O3​III.1 N−N1\,N-N1N−N bond
D.N2ON_2ON2​OIV.1 N=N/1 N≡N1\,N=N/1\,N\equiv N1N=N/1N≡N bond
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-II, B-II, C-III, D-I
  3. (C)A-III, B-II, C-I, D-IV
  4. (D)A-II, B-I, C-III, D-IV

Correct answer: (D)

Step-by-step solution →
Q104·ChemistryNumericalJEE Main 2023
The number of species having a square planar shape from the following is ____. XeF4XeF_4XeF4​, SF4SF_4SF4​, SiF4SiF_4SiF4​, BF4−BF_4^-BF4−​, BrF4−BrF_4^-BrF4−​, [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}[Cu(NH3​)4​]2+, [FeCl4]2−[FeCl_4]^{2-}[FeCl4​]2−, [PtCl4]2−[PtCl_4]^{2-}[PtCl4​]2−

Correct answer: 4

Step-by-step solution →
Q105·ChemistrySingle correctJEE Main 2023
Resonance structures of the carbonate ion (CO32−)(\text{CO}_3^{2-})(CO32−​) are shown in the figure. Which of the following is true?
  1. (A)All these structures are in dynamic equilibrium with each other.
  2. (B)It is possible to identify each structure individually by some physical or chemical method.
  3. (C)Each structure exists for equal amount of time.
  4. (D)CO32−\text{CO}_3^{2-}CO32−​ has a single structure i.e., resonance hybrid of the above three structures.

Correct answer: (D)

Step-by-step solution →
Q106·ChemistryNumericalJEE Main 2023
Amongst the following, the number of species having the linear shape is _________ XeF2,I3+,C2O2,I3−,CO2,SO2,BeCl2XeF_2, I_3^+, C_2O_2, I_3^-, CO_2, SO_2, BeCl_2XeF2​,I3+​,C2​O2​,I3−​,CO2​,SO2​,BeCl2​ and BCl3BCl_3BCl3​

Correct answer: 5

Step-by-step solution →
Q107·ChemistrySingle correctJEE Main 2023
Match List I (molecule/ion) with List II (shape/geometry).
List IList II
A.XeF4XeF_4XeF4​I.See-saw
B.SF4SF_4SF4​II.Square planar
C.NH4+NH_4^+NH4+​III.Bent T-shaped
D.BrF3BrF_3BrF3​IV.Tetrahedral
  1. (A)A-IV, B-III, C-II, D-I
  2. (B)A-IV, B-I, C-II, D-III
  3. (C)A-II, B-I, C-III, D-IV
  4. (D)A-II, B-I, C-IV, D-III

Correct answer: (D)

Step-by-step solution →
Q108·ChemistrySingle correctJEE Main 2023
Match List I (molecules/ions) with List II (number of lone pairs of electrons on the central atom). Choose the correct answer from the options given below:
List I (molecules/ions)List II (No. of lone pairs of e⁻ on central atom)
A.IF7_77​I.Three
B.ICl4−_4^-4−​II.One
C.XeF6_66​III.Two
D.XeF2_22​IV.Zero
  1. (A)A-II, B-III, C-II, D-I
  2. (B)A-II, B-I, C-IV, D-III
  3. (C)A-IV, B-I, C-II, D-III
  4. (D)A-IV, B-III, C-II, D-I

Correct answer: (D)

Step-by-step solution →
Q109·ChemistrySingle correctJEE Main 2023
For OF2OF_2OF2​ molecule consider the following: A. Number of lone pairs on oxygen is 2. B. FOF angle is less than 104.5°104.5°104.5°. C. Oxidation state of O is −2-2−2. D. Molecule is bent 'V' shaped. E. Molecular geometry is linear. correct options are:
  1. (A)A, C, D only
  2. (B)C, D, E only
  3. (C)A, B, D only
  4. (D)B, E, A only

Correct answer: (C)

Step-by-step solution →
Q110·ChemistrySingle correctJEE Main 2023
According to MO theory the bond orders for O22−O_2^{2-}O22−​, CO and NO+NO^+NO+ respectively, are:
  1. (A)1,21,21,2 and 333
  2. (B)1,31,31,3 and 222
  3. (C)2,32,32,3 and 333
  4. (D)1,31,31,3 and 333

Correct answer: (D)

Step-by-step solution →
Q111·ChemistryNumericalJEE Main 2023
The number of molecules or ions from the following, which do not have odd number of electrons are ________ . (A) NO2_22​ (B) ICl4−_4^-4−​ (C) BrF3_33​ (D) ClO2_22​ (E) NO2+_2^+2+​ (F) NO

Correct answer: 3

Step-by-step solution →
Q112·ChemistryNumericalJEE Main 2023
The total number of lone pairs of electrons on oxygen atoms of ozone is _______.

Correct answer: 6

Step-by-step solution →
Q113·ChemistrySingle correctJEE Main 2023
Statement I : Dipole moment is a vector quantity and by convention it is depicted by a small arrow with tail on the negative centre and head pointing towards the positive centre. Statement II : The crossed arrow of the dipole moment symbolizes the direction of the shift of charges in the molecules. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (B)

Step-by-step solution →
Q114·ChemistrySingle correctJEE Main 2023
Order of Covalent bond: A. KF > KI; LiF > KF. B. KF < KI; LiF > KF. C. SnCl4\text{SnCl}_4SnCl4​ > SnCl2\text{SnCl}_2SnCl2​; CuCl > NaCl. D. LiF > KF; CuCl < NaCl. E. KF < KI; CuCl > NaCl. Choose the correct answer from the options given below:
  1. (A)C, E only
  2. (B)B, C, E only
  3. (C)A, B only
  4. (D)B, C only

Correct answer: (B)

Step-by-step solution →
Q115·ChemistrySingle correctJEE Main 2023
Decreasing order of the hydrogen bonding in following forms of water is correctly represented by: A. Liquid water B. Ice C. Impure water. Choose the correct answer from the options given below:
  1. (A)B > A > C
  2. (B)A>B>CA>B>CA>B>C
  3. (C)A=B>CA=B>CA=B>C
  4. (D)C > B > A

Correct answer: (A)

Step-by-step solution →
Q116·ChemistrySingle correctJEE Main 2023
What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species: N2N_2N2​; N2+N_2^+N2+​; O2O_2O2​; O2+O_2^+O2+​?
  1. (A)2,1,0,1
  2. (B)0,1,2,1
  3. (C)0,1,0,1
  4. (D)2,1,2,1

Correct answer: (B)

Step-by-step solution →
Q117·ChemistryMultiple correctJEE Advanced 2022
For diatomic molecules, the correct statement(s) about the molecular orbitals formed by the overlap of two 2pz\mathrm{2p_z}2pz​ orbitals is(are)
  1. (A)σ\sigmaσ orbital has a total of two nodal planes
  2. (B)σ∗\sigma^*σ∗ orbital has one node in the xz-plane containing the molecular axis.
  3. (C)π\piπ orbital has one node in the plane which is perpendicular to the molecular axis and goes through the center of the molecule.
  4. (D)π∗\pi^*π∗ orbital has one node in the xy-plane containing the molecular axis.

Correct answer: (A), (D)

Step-by-step solution →
Q118·ChemistryIntegerJEE Advanced 2022
Thermal decomposition of AgNO3\mathrm{AgNO_3}AgNO3​ produces two paramagnetic gases. The total number of electrons present in the antibonding molecular orbitals of the gas that has the higher number of unpaired electrons is____.

Correct answer: 6

Step-by-step solution →
Q119·ChemistryNumericalJEE Main 2022
Consider, PF5_{5}5​, BrF5_{5}5​, PCl3_{3}3​, SF6_{6}6​, [ICl4_{4}4​]−^{-}−, ClF3_{3}3​ and IF5_{5}5​. Amongst the above molecule(s)/ion(s), the number of molecule(s)/ion(s) having sp3^{3}3d2^{2}2 hybridisation is____.

Correct answer: 4

Step-by-step solution →
Q120·ChemistrySingle correctJEE Main 2022
Which of the following pair of molecules contain odd electron molecule and an expanded octet molecule?
  1. (A)BCl3BCl_{3}BCl3​ and SF6SF_{6}SF6​
  2. (B)NO and H2SO4H_{2}SO_{4}H2​SO4​
  3. (C)SF6SF_{6}SF6​ and H2SO4H_{2}SO_{4}H2​SO4​
  4. (D)BCl3BCl_{3}BCl3​ and NO

Correct answer: (B)

Step-by-step solution →
Q121·ChemistryNumericalJEE Main 2022
The number of paramagnetic species among the following is __________. B2_22​, Li2_22​, C2_22​, C2−_2^-2−​, O22−_2^{2-}22−​, O2+_2^+2+​ and He2+_2^+2+​

Correct answer: 4

Step-by-step solution →
Q122·ChemistrySingle correctJEE Main 2022
Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R Assertion A : Zero orbital overlap is an out of phase overlap. Reason : It results due to different orientation/direction of approach of orbitals. In the light of the above statements. Choose the correct answer from the options given below
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (A)

Step-by-step solution →
Q123·ChemistrySingle correctJEE Main 2022
Match List-I with List-II List-I (A) ΨMO=ΨA−ΨB\Psi_{MO} = \Psi_{A} - \Psi_{B}ΨMO​=ΨA​−ΨB​ (B) μ=Q×r\mu = Q \times rμ=Q×r (C) Nb−Na2\frac{N_{b} - N_{a}}{2}2Nb​−Na​​ (D) ΨMO=ΨA+ΨB\Psi_{MO} = \Psi_{A} + \Psi_{B}ΨMO​=ΨA​+ΨB​ List-II (I) Dipole moment (II) Bonding molecular orbital (III) Anti-bonding molecualr orbital (IV) Bond order
  1. (A)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  2. (B)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  3. (C)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  4. (D)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Correct answer: (C)

Step-by-step solution →
Q124·ChemistryNumericalJEE Main 2022
Amongst the following the number of oxide(s) which are paramagnetic in nature is Na2ONa_{2}ONa2​O, KO2KO_{2}KO2​, NO2NO_{2}NO2​, N2ON_{2}ON2​O, ClO2ClO_{2}ClO2​, NO, SO2SO_{2}SO2​, Cl2OCl_{2}OCl2​O

Correct answer: 4

Step-by-step solution →
Q125·ChemistryNumericalJEE Main 2022
According to MO theory, number of species/ions from the following having identical bond order is______: CN−CN^{-}CN−, NO+NO^{+}NO+, O2O_{2}O2​, O2+O_{2}^{+}O2+​, O22+O_{2}^{2+}O22+​

Correct answer: 3

Step-by-step solution →
Q126·ChemistrySingle correctJEE Main 2022
Given below are two statements. Statement I : O2O_{2}O2​ , Cu2+Cu^{2+}Cu2+ and Fe3+Fe^{3+}Fe3+ are weakly attracted by magnetic field and are magnetized in the same direction as magnetic field. Statement II : NaCl and H2OH_{2}OH2​O are weakly magnetized in opposite direction to magnetic field. In the light of the above statements, choose the most appropriate answer form the options given below :
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (A)

Step-by-step solution →
Q127·ChemistryNumericalJEE Main 2022
The number of molecule(s) or ion(s) from the following having non-planar structure is______. NO3−_{3}^{-}3−​, H2_{2}2​O2_{2}2​, BF3_{3}3​, PCl3_{3}3​, XeF4_{4}4​, SF4_{4}4​, XeO3_{3}3​, PH4+_{4}^{+}4+​, SO3_{3}3​, [Al(OH)4_{4}4​]−^{-}−

Correct answer: 6

Step-by-step solution →
Q128·ChemistrySingle correctJEE Main 2022
Match List - I with List - II. Choose the correct answer from the options given below :
List - I (Compound)List - II (Shape)
A.BrF5_55​I.bent
B.[CrF6_66​]3−^{3-}3−II.square pyramidal
C.O3_33​III.trigonal bipyramidal
D.PCl5_55​IV.octahedral
  1. (A)(A) – (I), (B) - (II), (C) - (III), (D) - (IV)
  2. (B)(A) - (IV), (B) - (III), (C) - (II), (D) - (I)
  3. (C)(A) - (II), (B) - (IV), (C) - (I), (D) - (III)
  4. (D)(A) - (III), (B) - (IV), (C) - (II), (D) - (I)

Correct answer: (C)

Step-by-step solution →
Q129·ChemistrySingle correctJEE Main 2022
Arrange the following in increasing order of their covalent character. (A) CaF2CaF_{2}CaF2​ (B) CaCl2CaCl_{2}CaCl2​ (C) CaBr2CaBr_{2}CaBr2​ (D) CaI2CaI_{2}CaI2​ Choose the correct answer from the options given below.
  1. (A)B < A < C < D
  2. (B)A < B < C < D
  3. (C)A < B < D < C
  4. (D)A < C < B < D

Correct answer: (B)

Step-by-step solution →
Q130·ChemistryNumericalJEE Main 2022
Among the following species N2N_{2}N2​, N2+N_{2}^{+}N2+​, N2−N_{2}^{-}N2−​, N22−N_{2}^{2-}N22−​, O2O_{2}O2​, O2+O_{2}^{+}O2+​, O2−O_{2}^{-}O2−​, O22−O_{2}^{2-}O22−​ the number of species showing diamagnetism is

Correct answer: 2

Step-by-step solution →
Q131·ChemistrySingle correctJEE Main 2022
Consider the species CH4_44​, NH4+_4^+4+​ and BH4−_4^-4−​. Choose the correct option with respect to the there species:
  1. (A)They are isoelectronic and only two have tetrahedral structures
  2. (B)They are isoelectronic and all have tetrahedral structures
  3. (C)Only two are isoelectronic and all have tetrahedral structures
  4. (D)Only two are isoelectronic and only two have tetrahedral structures

Correct answer: (B)

Step-by-step solution →
Q132·ChemistrySingle correctJEE Main 2022
Number of lone pair (s) of electrons on central atom and the shape of BrF3_33​ molecule respectively, are :
  1. (A)0, triangular planar.
  2. (B)1, pyramidal.
  3. (C)2, bent T-shape.
  4. (D)1, bent T-shape

Correct answer: (C)

Step-by-step solution →
Q133·ChemistrySingle correctJEE Main 2022
Arrange the following in the decreasing order of their covalent character : (A) LiCl (B) NaCl (C) KCl (D) CsCl Question: Choose the most appropriate answer from the options given below :
  1. (A)(A) > (C) > (B) > (D)
  2. (B)(B) > (A) > (C) > (D)
  3. (C)(A) > (B) > (C) > (D)
  4. (D)(A) > (B) > (D) > (C)

Correct answer: (C)

Step-by-step solution →
Q134·ChemistrySingle correctJEE Main 2022
In the structure of SF4_44​, the lone pair of electrons on S is in.
  1. (A)equatorial position and there are two lone pair-bond pair repulsions at 90°
  2. (B)equatorial position and there are three lone pair-bond pair repulsions at 90°
  3. (C)axial position and there are three lone pair – bond pair repulsion at 90°.
  4. (D)axial position and there are two lone pair – bond pair repulsion at 90°.

Correct answer: (A)

Step-by-step solution →
Q135·ChemistryNumericalJEE Main 2022
The hybridization of P exhibited in PF5PF_5PF5​ is spxdysp^{x}d^{y}spxdy. The value of y is __________.

Correct answer: 1

Step-by-step solution →
Q136·ChemistrySingle correctJEE Main 2022
The correct order of increasing intermolecular hydrogen bond strength is
  1. (A)HCN < H2_22​O < NH3_33​
  2. (B)HCN < CH4_44​ < NH3_33​
  3. (C)CH4_44​ < HCN < NH3_33​
  4. (D)CH4_44​ < NH3_33​ < HCN

Correct answer: (C)

Step-by-step solution →
Q137·ChemistrySingle correctJEE Main 2022
Based upon VSEPR theory, match the shape (geometry) of the molecules in List-I with the molecules in List-II and select the most appropriate option List-I (Shape) (A) T-shaped (B) Trigonal planar (C) Square planar (D) See-saw List-II (Molecules) (I) XeF4XeF_{4}XeF4​ (II) SF4SF_{4}SF4​ (III) ClF3ClF_{3}ClF3​ (IV) BF3BF_{3}BF3​
  1. (A)(A) – I, (B) – (II), (C) – (III), (D) – (IV)
  2. (B)(A) – (III), (B) – (IV), (C) – (I), (D) – (II)
  3. (C)(A) – (III), (B) – (IV), (C) – (II), (D) – (I)
  4. (D)(A) – (IV), (B) – (III), (C) – (I), (D) – (II)

Correct answer: (B)

Step-by-step solution →
Q138·ChemistrySingle correctJEE Main 2022
Identify the incorrect statement for PCl5_55​ from the following.
  1. (A)In this molecule, orbitals of phosphorous are assumed to undergo sp3^{3}3d hybridization.
  2. (B)The geometry of PCl5_55​ is trigonal bipyramidal.
  3. (C)PCl5_55​ has two axial bonds stronger than three equatorial bonds.
  4. (D)The three equatorial bonds of PCl5_55​ lie in a plane.

Correct answer: (C)

Step-by-step solution →
Q139·ChemistrySingle correctJEE Main 2022
Consider the ions/molecule O2+O_{2}^{+}O2+​, O2O_{2}O2​, O2−O_{2}^{-}O2−​, O22−O_{2}^{2-}O22−​ For increasing bond order the correct option is :
  1. (A)O22−<O2−<O2<O2+O_{2}^{2-} < O_{2}^{-} < O_{2} < O_{2}^{+}O22−​<O2−​<O2​<O2+​
  2. (B)O2−<O22−<O2<O2+O_{2}^{-} < O_{2}^{2-} < O_{2} < O_{2}^{+}O2−​<O22−​<O2​<O2+​
  3. (C)O2−<O22−<O2+<O2O_{2}^{-} < O_{2}^{2-} < O_{2}^{+} < O_{2}O2−​<O22−​<O2+​<O2​
  4. (D)O2−<O2+<O22−<O2O_{2}^{-} < O_{2}^{+} < O_{2}^{2-} < O_{2}O2−​<O2+​<O22−​<O2​

Correct answer: (A)

Step-by-step solution →
Q140·ChemistryNumericalJEE Main 2022
Amongst SF4SF_4SF4​, XeF4XeF_4XeF4​, CF4CF_4CF4​ and H2OH_2OH2​O, the number of species with two lone pairs of electrons _______ .

Correct answer: 2

Step-by-step solution →
Q141·ChemistrySingle correctJEE Main 2022
Number of electron deficient molecules among the following PH3PH_3PH3​, B2H6B_2H_6B2​H6​, CCl4CCl_4CCl4​, NH3NH_3NH3​, LiH and BCl3BCl_3BCl3​ is
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q142·ChemistryNumericalJEE Main 2022
Amongst BeF2_22​, BF3_33​, H2_22​O, NH3_33​, CCl4_44​ and HCl, the number of molecules with non-zero net dipole moment is __________.

Correct answer: 3

Step-by-step solution →
Q143·ChemistrySingle correctJEE Main 2022
Bonding in which of the following diatomic molecule(s) become(s) stronger, on the basis of MO Theory, by removal of an electron ? (A) NO (B) N2N_2N2​ (C) O2O_2O2​ (D) C2C_2C2​ (E) B2B_2B2​ Choose the most appropriate answer from the options given below :-
  1. (A)(A), (B), (C) only
  2. (B)(B), (C), (E) only
  3. (C)(A), (C) only
  4. (D)(D) only

Correct answer: (C)

Step-by-step solution →
Q144·ChemistrySingle correctJEE Main 2022
Match List – I with List - II
List-IList-II
A.[PtCl4_44​]2−^{2-}2−I.sp3^33d
B.BrF5_55​II.d2^22sp3^33
C.PCl5_55​III.dsp2^22
D.[Co(NH3_33​)6_66​]3+^{3+}3+IV.sp3^33d2^22
  1. (A)(A)→(II), (B)→(IV), (C)→(I), (D)→(III)
  2. (B)(A)→(III), (B)→(IV), (C)→(I), (D)→(II)
  3. (C)(A)→(III), (B)→(I), (C)→(IV), (D)→(II)
  4. (D)(A)→(II), (B)→(I), (C)→(IV), (D)→(III)

Correct answer: (B)

Step-by-step solution →
Q145·ChemistrySingle correctJEE Main 2022
The correct order of bound orders of C22−_2^{2-}22−​, N22−_2^{2-}22−​ and O22−_2^{2-}22−​ is, respectively.
  1. (A)C22−_2^{2-}22−​ < N22−_2^{2-}22−​ < O22−_2^{2-}22−​
  2. (B)O22−_2^{2-}22−​ < N22−_2^{2-}22−​ < C22−_2^{2-}22−​
  3. (C)C22−_2^{2-}22−​ < O22−_2^{2-}22−​ < N22−_2^{2-}22−​
  4. (D)N22−_2^{2-}22−​ < C22−_2^{2-}22−​ < O22−_2^{2-}22−​

Correct answer: (B)

Step-by-step solution →
Q146·ChemistryNumericalJEE Main 2021
The spin-only magnetic moment value of B2+_{2}^{+}2+​ species is ______ ×10−2^{-2}−2 BM. (Nearest integer) [Given : 3\sqrt{3}3​ = 1.73 ]

Correct answer: 173

Step-by-step solution →
Q147·ChemistryNumericalJEE Main 2021
According to molecular orbital theory, the number of unpaired electron(s) in O22−\mathrm{O_2^{2-}}O22−​ is :

Correct answer: 0

Step-by-step solution →
Q148·ChemistryNumericalJEE Main 2021
The number of species having non–pyramidal shape among the following is _____ . (A) SO3_{3}3​ (B) NO3−_{3}^{-}3−​ (C) PCl3_{3}3​ (D) CO32−_{3}^{2-}32−​

Correct answer: 3

Step-by-step solution →
Q149·ChemistryNumericalJEE Main 2021
AB3AB_3AB3​ is an interhalogen T-shaped molecule. The number of lone pairs of electrons on A is ________. (Integer answer)

Correct answer: 2

Step-by-step solution →
Q150·ChemistrySingle correctJEE Main 2021
The bond order and magnetic behaviour of O2−\mathrm{O_2^-}O2−​ ion are, respectively :
  1. (A)1.5 and paramagnetic
  2. (B)1.5 and diamagnetic
  3. (C)2 and diamagnetic
  4. (D)1 and paramagnetic

Correct answer: (A)

Step-by-step solution →
Q151·ChemistryNumericalJEE Main 2021
The total number of electrons in all bonding molecular orbitals of O22−_2^{2-}22−​ is ____________. (Round off to the Nearest Integer).

Correct answer: 10

Step-by-step solution →
Q152·ChemistryNumericalJEE Main 2021
The difference between bond orders of CO and NO⊕NO^{\oplus}NO⊕ is x2\dfrac{x}{2}2x​ where x _________ (Round off to the Nearest integer)

Correct answer: 0

Step-by-step solution →
Q153·ChemistrySingle correctJEE Main 2021
In the following the correct bond order sequence is:
  1. (A)O2>O2−>O22−>O2+O_2 > O_2^- > O_2^{2-} > O_2^+O2​>O2−​>O22−​>O2+​
  2. (B)O2+>O2>O2−>O22−O_2^+ > O_2 > O_2^- > O_2^{2-}O2+​>O2​>O2−​>O22−​
  3. (C)O22−>O2+>O2−>O2O_2^{2-} > O_2^+ > O_2^- > O_2O22−​>O2+​>O2−​>O2​
  4. (D)O2+>O2−>O22−>O2O_2^+ > O_2^- > O_2^{2-} > O_2O2+​>O2−​>O22−​>O2​

Correct answer: (B)

Step-by-step solution →
Q154·ChemistrySingle correctJEE Main 2021
Identify the species having one π-bond and maximum number of canonical forms from the following:
  1. (A)SO2SO_2SO2​
  2. (B)CO32−CO_3^{2-}CO32−​
  3. (C)O2O_2O2​
  4. (D)SO3SO_3SO3​

Correct answer: (B)

Step-by-step solution →
Q155·ChemistrySingle correctJEE Main 2021
Match List − I with List − II : Choose the correct answer from the options given below :
List-I (Species)List-II (Hybrid Orbitals)
a.SF4SF_4SF4​i.sp3d2sp^3d^2sp3d2
b.IF5IF_5IF5​ii.d2sp3d^2sp^3d2sp3
c.NO2+NO_2^+NO2+​iii.sp3dsp^3dsp3d
d.NH4+NH_4^+NH4+​iv.sp3sp^3sp3
v.sp
  1. (A)(a) −(iii) , (b) −(i), (c) −(v) and (d) −(iv)
  2. (B)(a) −(ii), (b) −(i), (c) −(iv) and (d) −(v)
  3. (C)(a) −(i), (b) −(ii), (c) −(v) and (d) −(iii)
  4. (D)(a) −(iv), (b) −(iii), (c) −(ii) and (d) −(v)

Correct answer: (A)

Step-by-step solution →
Q156·ChemistrySingle correctJEE Main 2021
The hybridisations of the atomic orbitals of nitrogen in NO2−\mathrm{NO_2^-}NO2−​, NO2+\mathrm{NO_2^+}NO2+​ and NH4+\mathrm{NH_4^+}NH4+​ respectively are :
  1. (A)sp3\mathrm{sp^3}sp3, sp\mathrm{sp}sp and sp2\mathrm{sp^2}sp2
  2. (B)sp\mathrm{sp}sp, sp2\mathrm{sp^2}sp2 and sp3\mathrm{sp^3}sp3
  3. (C)sp2\mathrm{sp^2}sp2, sp\mathrm{sp}sp and sp3\mathrm{sp^3}sp3
  4. (D)sp3\mathrm{sp^3}sp3, sp2\mathrm{sp^2}sp2 and sp\mathrm{sp}sp

Correct answer: (C)

Step-by-step solution →
Q157·ChemistryNumericalJEE Main 2021
The number of lone pairs of electrons on the central I atom in I3−I_3^-I3−​ is______________.

Correct answer: 3

Step-by-step solution →
Q158·ChemistrySingle correctJEE Main 2021
In the following molecules, Hybridisation of carbon a, b and c respectively are :
  1. (A)sp3^{3}3, sp, sp
  2. (B)sp3^{3}3, sp2^{2}2, sp
  3. (C)sp3^{3}3, sp2^{2}2, sp2^{2}2
  4. (D)sp3^{3}3, sp, sp2^{2}2

Correct answer: (C)

Step-by-step solution →
Q159·ChemistryNumericalJEE Main 2021
The number of species below that have two lone pairs of electrons in their central atom is ____ (Round off to the Nearest integer) SF4_{4}4​, BF4−_{4}^{-}4−​ , ClF3_{3}3​, AsF3_{3}3​, PCl5_{5}5​, BrF5_{5}5​, XeF4_{4}4​, SF6_{6}6​

Correct answer: 2

Step-by-step solution →
Q160·ChemistrySingle correctJEE Main 2021
Amongst the following, the linear species is :
  1. (A)NO2_{2}2​
  2. (B)Cl2_{2}2​O
  3. (C)O3_{3}3​
  4. (D)N3−_{3}^{-}3−​

Correct answer: (D)

Step-by-step solution →
Q161·ChemistrySingle correctJEE Main 2021
Which of the following compound CANNOT act as a Lewis base?
  1. (A)NF3\mathrm{NF_3}NF3​
  2. (B)PCl5\mathrm{PCl_5}PCl5​
  3. (C)SF4\mathrm{SF_4}SF4​
  4. (D)ClF3\mathrm{ClF_3}ClF3​

Correct answer: (B)

Step-by-step solution →
Q162·ChemistrySingle correctJEE Main 2021
A central atom in a molecule has two lone pairs of electrons and forms three single bonds. The shape of this molecule is:
  1. (A)see-saw
  2. (B)planar triangular
  3. (C)T-shaped
  4. (D)trigonal pyramidal

Correct answer: (C)

Step-by-step solution →
Q163·ChemistrySingle correctJEE Main 2021
Given below are two statement : one is labelled as Assertion A and the other is labelled as Reason R : Assertion A : The H–O–H bond angle in water molecule is 104.5°. Reason R : The lone pair – lone pair repulsion of electrons is higher than the bond pair - bond pair repulsion.
  1. (A)A is false but R is true
  2. (B)Both A and R are true, but R is not the correct correct explanation of A
  3. (C)A is true but R is false
  4. (D)Both A and R are true, and R is the correct explanation of A

Correct answer: (D)

Step-by-step solution →
Q164·ChemistrySingle correctJEE Main 2021
Match List-I with List-II. List-I (Molecule) List-II (Bond order) (a) Ne2Ne_2Ne2​ (i) 1 (b) N2N_2N2​ (ii) 2 (c) F2F_2F2​ (iii) 0 (d) O2O_2O2​ (iv) 3 Choose the correct answer from the options given below:
  1. (A)(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
  2. (B)(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
  3. (C)(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
  4. (D)(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

Correct answer: (A)

Step-by-step solution →
Q165·ChemistrySingle correctJEE Main 2021
In CH2_22​ = C = CH–CH3_33​ molecule, the hybridization of carbon 1, 2, 3 and 4 respectively are:
  1. (A)sp2^22, sp, sp2^22, sp3^33
  2. (B)sp2^22, sp2^22, sp2^22, sp3^33
  3. (C)sp2^22, sp3^33, sp2^22, sp3^33
  4. (D)sp3^33, sp, sp3^33, sp3^33

Correct answer: (A)

Step-by-step solution →
Q166·ChemistrySingle correctJEE Main 2021
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Dipole-dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation Reason R : Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)A is false but R is true
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)A is true but R is false
  4. (D)Both A and R are true and R is not the correct explanation of A

Correct answer: (C)

Step-by-step solution →
Q167·ChemistrySingle correctJEE Main 2021
According to molecular orbital theory, the species among the following that does not exist is:
  1. (A)He2−_{2}^{-}2−​
  2. (B)He2+_{2}^{+}2+​
  3. (C)O22−_{2}^{2-}22−​
  4. (D)Be2_{2}2​

Correct answer: (D)

Step-by-step solution →
Q168·ChemistrySingle correctJEE Main 2021
Which among the following species has unequal bond lengths ?
  1. (A)XeF4
  2. (B)SiF4
  3. (C)BF4^{4}4 −^{-}−
  4. (D)SF4

Correct answer: (D)

Step-by-step solution →
Q169·ChemistrySingle correctJEE Main 2021
Which of the following are isostructural pairs ? (A) SO42−\mathrm{SO_4^{2-}}SO42−​ and CrO42−\mathrm{CrO_4^{2-}}CrO42−​ (B) SiCl4\mathrm{SiCl_4}SiCl4​ and TiCl4\mathrm{TiCl_4}TiCl4​ (c) NH3\mathrm{NH_3}NH3​ and NO3−\mathrm{NO_3^{-}}NO3−​ (D) BCl3\mathrm{BCl_3}BCl3​ and BrCl3\mathrm{BrCl_3}BrCl3​
  1. (A)A and C only
  2. (B)A and B only
  3. (C)B and C only
  4. (D)C and D only

Correct answer: (B)

Step-by-step solution →
Q170·ChemistrySingle correctJEE Main 2021
The correct shape and I-I-I bond angles respectively in I3−I_{3}^{-}I3−​ ion are :
  1. (A)Trigonal planar; 120º
  2. (B)Distorted trigonal planar; 135º and 90º
  3. (C)Linear; 180º
  4. (D)T-shaped; 180º and 90º

Correct answer: (C)

Step-by-step solution →
Q171·ChemistrySingle correctJEE Main 2021
The Correct set from the following in which both pairs are in correct order of melting point is :
  1. (A)LiF > LiCl ; NaCl > MgO
  2. (B)LiF > LiCl ; MgO > NaCl
  3. (C)LiCl > LiF ; NaCl > MgO
  4. (D)LiCl > LiF ; MgO > NaCl

Correct answer: (B)

Step-by-step solution →
Q172·ChemistryIntegerJEE Advanced 2020
Consider the following compounds in the liquid form : O2O_{2}O2​, HF, H2OH_{2}OH2​O, NH3NH_{3}NH3​, H2O2H_{2}O_{2}H2​O2​, CCl4CCl_{4}CCl4​, CHCl3CHCl_{3}CHCl3​, C6H6C_{6}H_{6}C6​H6​, C6H5ClC_{6}H_{5}ClC6​H5​Cl. When a charged comb is brought near their flowing stream, how many of them show deflection as per the following figure?

Correct answer: 6

Step-by-step solution →
Q173·ChemistryNumericalJEE Main 2020
The number of Cl = O bonds in perchloric acid is," ______________".

Correct answer: 3

Step-by-step solution →
Q174·ChemistrySingle correctJEE Main 2020
The compound that has the largest H – M – H bond angle (M = N, O, S, C), is
  1. (A)H2OH_2OH2​O
  2. (B)CH4CH_4CH4​
  3. (C)H2SH_2SH2​S
  4. (D)NH3NH_3NH3​

Correct answer: (B)

Step-by-step solution →
Q175·ChemistrySingle correctJEE Main 2020
The potential energy curve for the H2H_2H2​ molecule as a function of internuclear distance is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q176·ChemistrySingle correctJEE Main 2020
The molecule in which hybrid MOs involve only one d-orbital of the central atom is :
  1. (A)XeF4_44​
  2. (B)[CrF6_66​]3−^{3-}3−
  3. (C)[Ni(CN)4_44​]2−^{2-}2−
  4. (D)BrF5_55​

Correct answer: (C)

Step-by-step solution →
Q177·ChemistrySingle correctJEE Main 2020
The intermolecular potential energy for the molecules A, B, C and D given below suggest that:
  1. (A)A – A has the largest bond enthalpy
  2. (B)A – D has the shortest bond length
  3. (C)D is more electronegative than other atoms
  4. (D)A – B has the stiffest bond.

Correct answer: (D)

Step-by-step solution →
Q178·ChemistrySingle correctJEE Main 2020
The reaction in which hybridization of the underlined atom is affected is:
  1. (A)Xe‾F4+SbF5→\underline{Xe}F_4 + SbF_5 \rightarrowXe​F4​+SbF5​→
  2. (B)H2S‾O4+NaCl→420 KH_2\underline{S}O_4 + NaCl \xrightarrow{420\ K}H2​S​O4​+NaCl420 K​
  3. (C)H3P‾O2→DisproportionationH_3\underline{P}O_2 \xrightarrow{\text{Disproportionation}}H3​P​O2​Disproportionation​
  4. (D)N‾H3→H+\underline{N}H_3 \xrightarrow{H^+}N​H3​H+​

Correct answer: (A)

Step-by-step solution →
Q179·ChemistrySingle correctJEE Main 2020
Of the species, NO, NO+^++, NO2+^{2+}2+ and NO−^-−, the one with minimum bond strength is
  1. (A)NO+^++
  2. (B)NO
  3. (C)NO2+^{2+}2+
  4. (D)NO−^-−

Correct answer: (D)

Step-by-step solution →
Q180·ChemistrySingle correctJEE Main 2020
If the magnetic moment of a dioxygen species is 1.73 B.M, it may be:
  1. (A)O2_22​, O2−_2^{-}2−​ or O2+_2^{+}2+​
  2. (B)O2_22​ or O2−_2^{-}2−​
  3. (C)O2_22​ + O2+_2^{+}2+​
  4. (D)O2−_2^{-}2−​ or O2+_2^{+}2+​

Correct answer: (D)

Step-by-step solution →
Q181·ChemistrySingle correctJEE Main 2020
The number of sp2^22 hybrid orbitals in a molecule of benzene is
  1. (A)18
  2. (B)6
  3. (C)12
  4. (D)24

Correct answer: (A)

Step-by-step solution →
Q182·ChemistrySingle correctJEE Main 2020
Arrange the following bonds according to their average bond energies in descending order: C–Cl, C–Br, C–F, C–I
  1. (A)C–F > C–Cl > C–Br > C–I
  2. (B)C–I > C–Br > C–Cl > C–F
  3. (C)C–Cl > C–Br > C–I > C–F
  4. (D)C–Br > C–I > C–Cl > C–F

Correct answer: (A)

Step-by-step solution →
Q183·ChemistrySingle correctJEE Main 2020
The dipole moments of CCl4_44​, CHCl3_33​ ad CH4_44​ are in the order
  1. (A)CHCl3_33​ < CH4_44​ = CCl4_44​
  2. (B)CCl4_44​ < CH4_44​ < CHCl3_33​
  3. (C)CH4_44​ = CCl4_44​ < CHCl3_33​
  4. (D)CH4_44​ < CCl4_44​ < CHCl3_33​

Correct answer: (C)

Step-by-step solution →
Q184·ChemistrySingle correctJEE Main 2020
The bond order and the magnetic characteristics of CN−CN^-CN− are
  1. (A)3, paramagnetic
  2. (B)2½, diamagnetic
  3. (C)3, diamagnetic
  4. (D)2½, paramagnetic

Correct answer: (C)

Step-by-step solution →
Q185·ChemistryMultiple correctJEE Advanced 2019
Each of the following options contains a set of four molecules, Identify the option(s) where all four molecules possess permanent dipole moment at room temperature.
  1. (A)SO2_{2}2​, C6_{6}6​H5_{5}5​Cl, H2_{2}2​Se, BrF5_{5}5​
  2. (B)BeCl2_{2}2​, CO2_{2}2​, BCl3_{3}3​, CHCl3_{3}3​
  3. (C)BF3_{3}3​, O3_{3}3​, SF6_{6}6​, XeF6_{6}6​
  4. (D)NO2_{2}2​, NH3_{3}3​, POCl3_{3}3​, CH3_{3}3​Cl

Correct answer: (A), (D)

Step-by-step solution →
Q186·ChemistryNumericalJEE Advanced 2019
Among B2_{2}2​H6_{6}6​, B3_{3}3​N3_{3}3​H6_{6}6​, N2_{2}2​O, N2_{2}2​O4_{4}4​, H2_{2}2​S2_{2}2​O3_{3}3​ and H2_{2}2​S2_{2}2​O8_{8}8​, the total number of molecules containing covalent bond between two atoms of the same kind is

Correct answer: 4.00

Step-by-step solution →
Q187·ChemistrySingle correctJEE Main 2019
The correct statement among the following is
  1. (A)(SiH3)3N(SiH_3)_3N(SiH3​)3​N is planar and less basic than (CH3)3N(CH_3)_3N(CH3​)3​N.
  2. (B)(SiH3)3N(SiH_3)_3N(SiH3​)3​N is planar and more basic than (CH3)3N(CH_3)_3N(CH3​)3​N.
  3. (C)(SiH3)3N(SiH_3)_3N(SiH3​)3​N is pyramidal and less basic than (CH3)3N(CH_3)_3N(CH3​)3​N.
  4. (D)(SiH3)3N(SiH_3)_3N(SiH3​)3​N is pyramidal and more basic than (CH3)3N(CH_3)_3N(CH3​)3​N.

Correct answer: (A)

Step-by-step solution →
Q188·ChemistrySingle correctJEE Main 2019
Among the following, the molecule expected to be stabilized by anion formation is:
  1. (A)F2F_2F2​
  2. (B)C2C_2C2​
  3. (C)O2O_2O2​
  4. (D)NO

Correct answer: (B)

Step-by-step solution →
Q189·ChemistrySingle correctJEE Main 2019
Among the following species, the diamagnetic molecule is
  1. (A)O2_22​
  2. (B)NO
  3. (C)B2_22​
  4. (D)CO

Correct answer: (D)

Step-by-step solution →
Q190·ChemistrySingle correctJEE Main 2019
Among the following molecules / ions C22−,N22−,O22−,O2C_2^{2-},N_2^{2-},O_2^{2-},O_2C22−​,N22−​,O22−​,O2​ which one is diamagnetic and has the shortest bond length?
  1. (A)O22−O_2^{2-}O22−​
  2. (B)C22−C_2^{2-}C22−​
  3. (C)O2O_2O2​
  4. (D)N22−N_2^{2-}N22−​

Correct answer: (B)

Step-by-step solution →
Q191·ChemistrySingle correctJEE Main 2019
The ion that has sp3d2sp^{3}d^{2}sp3d2 hybridization for the central atom is:
  1. (A)[IF6]−[IF_{6}]^{-}[IF6​]−
  2. (B)[ICl4]−[ICl_{4}]^{-}[ICl4​]−
  3. (C)[ICl2]−[ICl_{2}]^{-}[ICl2​]−
  4. (D)[BrF2]−[BrF_{2}]^{-}[BrF2​]−

Correct answer: (B)

Step-by-step solution →
Q192·ChemistrySingle correctJEE Main 2019
Two pi and half sigma bonds are present in
  1. (A)O2+_{2}^{+}2+​
  2. (B)N2_{2}2​
  3. (C)O2_{2}2​
  4. (D)N2+_{2}^{+}2+​

Correct answer: (D)

Step-by-step solution →
Q193·ChemistrySingle correctJEE Main 2019
The type of hybridisation and number of lone pair(s) of electrons of Xe in XeOF4_{4}4​ respectively are
  1. (A)sp3^{3}3d2^{2}2 and 1
  2. (B)sp3^{3}3d and 2
  3. (C)sp3^{3}3d2^{2}2 and 2
  4. (D)sp3^{3}3d and 1

Correct answer: (A)

Step-by-step solution →
Q194·ChemistrySingle correctJEE Main 2019
According to molecular orbital theory, which of the following is true with respect to Li2+_{2}^{+}2+​ and Li2−_{2}^{-}2−​?
  1. (A)Li2+_{2}^{+}2+​ is unstable and Li2−_{2}^{-}2−​ is stable
  2. (B)Li2+_{2}^{+}2+​ is stable and Li2−_{2}^{-}2−​ is unstable
  3. (C)Both are stable
  4. (D)Both are unstable

Correct answer: (C)

Step-by-step solution →
Q195·ChemistrySingle correctJEE Main 2019
In which of the following processes, the bond order has increased and paramagnetic character has changed to diamagnetic?
  1. (A)NO →\rightarrow→ NO+^{+}+
  2. (B)N2_22​ →\rightarrow→ N2+_2^{+}2+​
  3. (C)O2_22​ →\rightarrow→ O2+_2^{+}2+​
  4. (D)O2_22​ →\rightarrow→ O22−_2^{2-}22−​

Correct answer: (A)

Step-by-step solution →
Q196·ChemistryNumericalJEE Advanced 2018
Among the species given below, the total number of diamagnetic species is ___. H atom, NO2NO_{2}NO2​ monomer, O2−O_{2}^{-}O2−​ (superoxide), dimeric sulphur in vapour phase, Mn3O4Mn_{3}O_{4}Mn3​O4​, (NH4)2[FeCl4](NH_{4})_{2}[FeCl_{4}](NH4​)2​[FeCl4​], (NH4)2[NiCl4](NH_{4})_{2}[NiCl_{4}](NH4​)2​[NiCl4​], K2MnO4K_{2}MnO_{4}K2​MnO4​, K2CrO4K_{2}CrO_{4}K2​CrO4​

Correct answer: 1

Step-by-step solution →
Q197·ChemistryIntegerJEE Advanced 2017
Among H2,He2+,Li2,Be2,B2,C2,N2,O2−H_{2}, He_{2}^{+}, Li_{2}, Be_{2}, B_{2}, C_{2}, N_{2}, O_{2}^{-}H2​,He2+​,Li2​,Be2​,B2​,C2​,N2​,O2−​, and F2F_{2}F2​ , the number of diamagnetic species is (Atomic numbers: H = 1, He = 2, Li = 3, Be = 4, B = 5, C = 6, N = 7, O = 8, F = 9)

Correct answer: 6

Step-by-step solution →
Q198·ChemistryMultiple correctJEE Advanced 2017
Among the following, the correct statement(s) is(are)
  1. (A)Al(CH3)3\mathrm{Al(CH_{3})_{3}}Al(CH3​)3​ has the three-centre two-electron bonds in its dimeric structure
  2. (B)BH3\mathrm{BH_{3}}BH3​ has the three-centre two-electron bonds in its dimeric structure
  3. (C)AlCl3\mathrm{AlCl_{3}}AlCl3​ has the three-centre two-electron bonds in its dimeric structure
  4. (D)The Lewis acidity of BCl3\mathrm{BCl_{3}}BCl3​ is greater than that of AlCl3\mathrm{AlCl_{3}}AlCl3​

Correct answer: (A), (B), (D)

Step-by-step solution →
Q199·ChemistryIntegerJEE Advanced 2017
The sum of the number of lone pairs of electrons on each central atom in the following species is [TeBr6]2−,[BrF2]+,SNF3\left[TeBr_{6}\right]^{2-}, \left[BrF_{2}\right]^{+}, SNF_{3}[TeBr6​]2−,[BrF2​]+,SNF3​, and [XeF3]−\left[XeF_{3}\right]^{-}[XeF3​]− (Atomic numbers : N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54)

Correct answer: 6

Step-by-step solution →
Q200·ChemistryMultiple correctJEE Advanced 2016
The compound(s) with TWO lone pairs of electrons on the central atom is(are)
  1. (A)BrF5BrF_{5}BrF5​
  2. (B)ClF3ClF_{3}ClF3​
  3. (C)XeF4XeF_{4}XeF4​
  4. (D)SF4SF_{4}SF4​

Correct answer: (B), (C)

Step-by-step solution →
Q201·ChemistryMultiple correctJEE Advanced 2016
According to Molecular Orbital Theory
  1. (A)C22−C_{2}^{2-}C22−​ is expected to be diamagnetic
  2. (B)O22+O_{2}^{2+}O22+​ expected to have a longer bond length than O2O_{2}O2​
  3. (C)N2+N_{2}^{+}N2+​ and N2−N_{2}^{-}N2−​ have the same bond order
  4. (D)He2+He_{2}^{+}He2+​ has the same energy as two isolated He atoms

Correct answer: (A), (C)

Step-by-step solution →
Q202·ChemistryIntegerJEE Advanced 2015
The total number of lone pairs of electrons in N2O3\mathrm{N_{2}O_{3}}N2​O3​ is

Correct answer: 8

Step-by-step solution →
Q203·ChemistryIntegerJEE Advanced 2015
Among the triatomic molecules/ions, BeCl2\mathrm{BeCl_{2}}BeCl2​, N3−\mathrm{N_{3}^{-}}N3−​, N2O\mathrm{N_{2}O}N2​O, NO2+\mathrm{NO_{2}^{+}}NO2+​, O3\mathrm{O_{3}}O3​, SCl2\mathrm{SCl_{2}}SCl2​, ICl2−\mathrm{ICl_{2}^{-}}ICl2−​, I3−\mathrm{I_{3}^{-}}I3−​ and XeF2\mathrm{XeF_{2}}XeF2​, the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the ddd-orbital(s) is [Atomic number: S = 16, Cl = 17, I = 53 and Xe = 54]

Correct answer: 4

Step-by-step solution →
Q204·ChemistryMultiple correctJEE Advanced 2014
Hydrogen bonding plays a central role in the following phenomena:
  1. (A)Ice floats in water.
  2. (B)Higher Lewis basicity of primary amines than tertiary amines in aqueous solutions.
  3. (C)Formic acid is more acidic than acetic acid.
  4. (D)Dimerisation of acetic acid in benzene.

Correct answer: (A), (B), (D)

Step-by-step solution →
Q205·ChemistrySingle correctJEE Advanced 2014
Match the orbital overlap figures shown in List-I with the description given in List-II and select the correct answer using the code given below the lists.
List-IList-II
P.see figure1.p−dp - dp−d π\piπ antibonding
Q.see figure2.d−dd - dd−d σ\sigmaσ bonding
R.see figure3.p−dp - dp−d π\piπ bonding
S.see figure4.d−dd - dd−d σ\sigmaσ antibonding
  1. (A)P-2, Q-1, R-3, S-4
  2. (B)P-4, Q-3, R-1, S-2
  3. (C)P-2, Q-3, R-1, S-4
  4. (D)P-4, Q-1, R-3, S-2

Correct answer: (C)

Step-by-step solution →
Q206·ChemistrySingle correctJEE Advanced 2014
Assuming 2s−2p2s - 2p2s−2p mixing is NOT operative, the paramagnetic species among the following is
  1. (A)Be2\mathrm{Be}_2Be2​
  2. (B)B2\mathrm{B}_2B2​
  3. (C)C2\mathrm{C}_2C2​
  4. (D)N2\mathrm{N}_2N2​

Correct answer: (C)

Step-by-step solution →
Q207·ChemistryIntegerJEE Advanced 2013
The total number of lone-pairs of electrons in melamine is

Correct answer: 6

Step-by-step solution →

Chemical Bonding and Molecular Structure — frequently asked

How many questions from Chemical Bonding and Molecular Structure appear in JEE?

Chemical Bonding and Molecular Structure has appeared in 151 of the last 186 JEE Main and JEE Advanced papers — about 81% of them — contributing 207 questions in total across those papers.

Is Chemical Bonding and Molecular Structure an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 81% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Chemical Bonding and Molecular Structure questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Chemistry chapters

  • Coordination Compounds 318
  • p-Block Elements 276
  • Redox Reactions and Electrochemistry 265
  • d- and f-Block Elements 202
  • Aldehydes and Ketones 199
  • Equilibrium 199
  • Solutions 198
  • Chemical Thermodynamics 195

All 36 Chemistry chapters →

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