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p-Block Elements — JEE Previous Year Questions

Every p-Block Elements question asked in JEE Main and JEE Advanced across the last 186 papers — 276 questions, each with its correct answer. Free to read, no account needed.

Questions

276

Papers it appeared in

164/186

Appearance rate

88%

All 276 p-Block Elements questions

Most recent papers first.

Q1·ChemistryMultiple correctJEE Advanced 2026
Correct statement(s) about the compounds P, Q and R is(are)
  1. (A)P has two lone pairs of electrons on the central atom.
  2. (B)Q has a perfect octahedral geometry.
  3. (C)Q can act as a fluorinating agent.
  4. (D)The molecular structure of R is trigonal pyramidal.

Correct answer: (A), (C), (D)

Step-by-step solution →
Q2·ChemistryMultiple correctJEE Advanced 2026
Reaction of PtF6\mathrm{PtF_6}PtF6​ with oxygen (O2\mathrm{O_2}O2​) gas results in the formation of an ionic compound, X+Y−\mathrm{X^+Y^-}X+Y−. Correct statement(s) is(are)
  1. (A)The bond order of X+\mathrm{X^+}X+ is 1.5.
  2. (B)Valence ddd-orbitals of the metal ion in X+Y−\mathrm{X^+Y^-}X+Y− has 5 electrons.
  3. (C)PtF6\mathrm{PtF_6}PtF6​ acts as an oxidant in this reaction.
  4. (D)PtF6\mathrm{PtF_6}PtF6​ acts as a fluorinating agent in this reaction.

Correct answer: (B), (C)

Step-by-step solution →
Q3·ChemistryMultiple correctJEE Advanced 2026
Correct statement(s) about the compounds X, Y and Z is(are)
  1. (A)X is used for sterilizing drinking water.
  2. (B)Y has a planar structure.
  3. (C)Z is used in the enrichment of 235U^{235}\mathrm{U}235U.
  4. (D)Y is a stronger Lewis base than ammonia.

Correct answer: (A), (C)

Step-by-step solution →
Q4·ChemistrySingle correctJEE Main 2026
Find the correct statements related to group 15 hydrides. A. Reducing nature increases from NH3_33​ to BiH3_33​ B. Tendency to donate lone pair of electrons decreases from NH3_33​ to BiH3_33​ C. The stability of hydrides decreases from NH3_33​ to BiH3_33​ D. HEH bond angle decreases from NH3_33​ to SbH3_33​ (E = Elements of group 15) Choose the correct answer from the options given below:
  1. (A)A and B only
  2. (B)B and C only
  3. (C)A, B, C and D
  4. (D)A, C and D Only

Correct answer: (C)

Step-by-step solution →
Q5·ChemistrySingle correctJEE Main 2026
Given below are two statements: Statement I: Aluminium is more electropositive than thallium as the standard electrode potential value of EAl3+/Al∘E^\circ_{Al^{3+}/Al}EAl3+/Al∘​ is negative and ETl3+/Tl∘E^\circ_{Tl^{3+}/Tl}ETl3+/Tl∘​ is positive. Statement II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms Al³⁺ ion. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q6·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I : F2O<H2O<Cl2O\mathrm{F_{2}O} < \mathrm{H_{2}O} < \mathrm{Cl_{2}O}F2​O<H2​O<Cl2​O is the correct trend in terms of bond angle. Statement II : SiF4\mathrm{SiF_{4}}SiF4​, SnF4\mathrm{SnF_{4}}SnF4​ and PbF4\mathrm{PbF_{4}}PbF4​ are ionic in nature. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q7·ChemistrySingle correctJEE Main 2026
Treatment of a gas 'XXX' with a freshly prepared ferrous sulphate solution gives a compound 'YYY' as a brown ring. The compounds XXX and YYY are.
  1. (A)NO and [Fe(NO)]SO4[\mathrm{Fe(NO)}]\mathrm{SO_{4}}[Fe(NO)]SO4​
  2. (B)NO2\mathrm{NO_{2}}NO2​ and [Fe(NO2)]SO4[\mathrm{Fe(NO_{2})}]\mathrm{SO_{4}}[Fe(NO2​)]SO4​
  3. (C)N2O\mathrm{N_{2}O}N2​O and [Fe(N2O)]SO4[\mathrm{Fe(N_{2}O)}]\mathrm{SO_{4}}[Fe(N2​O)]SO4​
  4. (D)N2O4\mathrm{N_{2}O_{4}}N2​O4​ and [Fe(N2O4)]SO4[\mathrm{Fe(N_{2}O_{4})}]\mathrm{SO_{4}}[Fe(N2​O4​)]SO4​

Correct answer: (A)

Step-by-step solution →
Q8·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I: Aluminium upon reaction with NaOH forms [Al(OH)₆]³⁻ ion. Statement II: The geometry of ICl₄⁻, ClO₃⁻ and IBr₂⁻ is square planar, pyramidal and linear respectively. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q9·ChemistrySingle correctJEE Main 2026
Correct statements from the following are: A. Nitrogen in oxidation states from +1+1+1 to +4+4+4 disproportionates in acid medium. B. Nitrogen has the ability to form dπ−pπd\pi - p\pidπ−pπ multiple bonds with itself and other elements with small size and high electronegativity. C. N-N single bond is stronger than P-P single bond. D. Nitrogen has highest density in its group due to small size. E. The maximum covalency of nitrogen is four since it has only four valence orbitals for bonding. Choose the correct answer from the options given below:
  1. (A)B, C and D Only
  2. (B)C, D and E Only
  3. (C)A, C and E Only
  4. (D)A and E Only

Correct answer: (D)

Step-by-step solution →
Q10·ChemistryNumericalJEE Main 2026
According to Lewis theory, the total number of σ\sigmaσ bond-pairs and lone pair of electrons around the central atom of XeO64−XeO_6^{4-}XeO64−​ ion is _______.

Correct answer: 6

Step-by-step solution →
Q11·ChemistrySingle correctJEE Main 2026
Given below are two statements: Statement I: The covalency of oxygen is generally two but it can exceed upto four. The oxidation state of oxygen in SO2SO_2SO2​ is −2-2−2 and in OF2OF_2OF2​ it is +2+2+2. Statement II: The anomalous behaviour of oxygen when compared to the other elements of group 16 is due to its small size and high electronegativity. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q12·ChemistrySingle correctJEE Main 2026
The electronegativity of a group 13 element 'E' is same as that of Ge (on Pauling scale and upto one decimal point). The CORRECT statements about E3+E^{3+}E3+ are A. It can act as a reducing agent. B. It can act as an oxidizing agent. C. E3+E^{3+}E3+ is more stable than E+E^{+}E+. D. The standard electrode potential value for E3+/EE^{3+}/EE3+/E is positive. Choose the correct answer from the options given below:
  1. (A)A and C Only
  2. (B)B and C Only
  3. (C)B and D Only
  4. (D)A and D Only

Correct answer: (C)

Step-by-step solution →
Q13·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement (I) : Oxidising power of halogens decreases in the order F2>Cl2>Br2>I2\mathrm{F_{2}} > \mathrm{Cl_{2}} > \mathrm{Br_{2}} > \mathrm{I_{2}}F2​>Cl2​>Br2​>I2​, which is the basis of "Layer test". Statement (II) : "Layer test" to identify Br2\mathrm{Br_{2}}Br2​ and I2\mathrm{I_{2}}I2​ in aqueous solution involves the oxidation of bromide or iodide into Br2\mathrm{Br_{2}}Br2​ or I2\mathrm{I_{2}}I2​ respectively with Cl2\mathrm{Cl_{2}}Cl2​, which is a type of displacement redox reaction. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q14·ChemistrySingle correctJEE Main 2026
Given below are two statements: Statement I: The second ionization enthalpy of B, Al and Ga is in the order of B>Al>GaB > Al > GaB>Al>Ga. Statement II: The correct order in terms of first ionization enthalpy is Si<Ge<Pb<SnSi < Ge < Pb < SnSi<Ge<Pb<Sn. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (B)

Step-by-step solution →
Q15·ChemistrySingle correctJEE Main 2026
Consider the following reactions. Na2B4O7→Δ2X+YNa_2B_4O_7 \xrightarrow{\Delta} 2X + YNa2​B4​O7​Δ​2X+Y CuSO4+Y→Non−Luminous flameZ+SO3CuSO_4 + Y \xrightarrow{Non-Luminous\ flame} Z + SO_3CuSO4​+YNon−Luminous flame​Z+SO3​ 2Z+2X+Carbon→Luminous flame2Q+Na2B4O7+CO2Z+2X+Carbon \xrightarrow{Luminous\ flame} 2Q+Na_2B_4O_7+CO2Z+2X+CarbonLuminous flame​2Q+Na2​B4​O7​+CO The oxidation states of Cu in Z and Q, respectively are :
  1. (A)+2 and +2
  2. (B)+2 and +1
  3. (C)+1 and +2
  4. (D)+1 and +1

Correct answer: (B)

Step-by-step solution →
Q16·ChemistrySingle correctJEE Main 2026
Regarding the hydrides of group 15 elements EH3_{3}3​ (E = N, P, As, Sb), select the correct statement from the following: A. The stability of hydrides decreases down the group. B. The basicity of hydrides decreases down the group. C. The reducing character increases down the group. D. The boiling point increases down the group. Choose the correct answer from the options given below:
  1. (A)A, B & C only
  2. (B)A & D only
  3. (C)A, B, C & D
  4. (D)B & C only

Correct answer: (A)

Step-by-step solution →
Q17·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I : The increasing order of boiling point of hydrogen halides is HCl < HBr < HI < HF. Statement II : The increasing order of melting point of hydrogen halides is HCl < HBr < HF < HI. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q18·ChemistrySingle correctJEE Main 2026
Match List-I with List-II according to shape. Choose the correct answer from the options given below :
List-IList-II
A.XeO3_{3}3​I.BrF5_{5}5​
B.XeF2_{2}2​II.NH3_{3}3​
C.XeO2_{2}2​F2_{2}2​III.[I3_{3}3​]–^{–}–
D.XeOF4_{4}4​IV.SF4_{4}4​
  1. (A)A-II, B-I, C-III, D-IV
  2. (B)A-II, B-III, C-IV, D-I
  3. (C)A-II, B-III, C-I, D-IV
  4. (D)A-III, B-II, C-IV, D-I

Correct answer: (B)

Step-by-step solution →
Q19·ChemistrySingle correctJEE Main 2026
Among the following, the CORRECT combinations are : A. IF3IF_3IF3​ → T-shaped (sp3dsp^3dsp3d) B. IF5IF_5IF5​ → Square pyramidal (sp3d2sp^3d^2sp3d2) C. IF7IF_7IF7​ → Pentagonal bipyramidal (sp3d3sp^3d^3sp3d3) D. ClO4−ClO_4^-ClO4−​ → Square planar (sp2dsp^2dsp2d) Choose the correct answer from the options given below :
  1. (A)A, B and C only
  2. (B)A and B only
  3. (C)A, B, C and D
  4. (D)B, C and D Only

Correct answer: (A)

Step-by-step solution →
Q20·ChemistrySingle correctJEE Main 2026
One mole of Cl2\text{Cl}_{2}Cl2​ (g) was passed into 2 L of cold 2M KOH solution. After the reaction, the concentrations of Cl−\text{Cl}^{-}Cl−, ClO−\text{ClO}^{-}ClO− and OH−\text{OH}^{-}OH− are respectively (assume volume remains constant)
  1. (A)0.75 M , 0.75 M , 1 M
  2. (B)0.5 M , 0.5 M , 0.5 M
  3. (C)0.5 M , 0.5 M , 1 M
  4. (D)1 M , 1M , 1 M

Correct answer: (C)

Step-by-step solution →
Q21·ChemistrySingle correctJEE Main 2026
Choose the INCORRECT statement
  1. (A)Among the isotopes of carbon, 13C^{13}\text{C}13C is a radioactive isotope.
  2. (B)Carbon exhibits negative oxidation states along with +4 and +2.
  3. (C)Carbon cannot exceed its covalency more than four.
  4. (D)CO2\text{CO}_{2}CO2​ is the most acidic oxide among the dioxides of group of 14 elements.

Correct answer: (A)

Step-by-step solution →
Q22·ChemistrySingle correctJEE Main 2026
Which statements are NOT TRUE about XeO2_{2}2​F2_{2}2​? A. It has a see-saw shape. B. Xe has 5 electron pairs in its valence shell in XeO2_{2}2​F2_{2}2​. C. The O–Xe–O bond angle is close to 180°. D. The F–Xe–F bond angle is close to 180° E. Xe has 16 valence electrons in XeO2_{2}2​F2_{2}2​. Choose the correct answer from the options given below.
  1. (A)B, C and E only
  2. (B)B and D only
  3. (C)A and D only
  4. (D)B, D and E only

Correct answer: (A)

Step-by-step solution →
Q23·ChemistrySingle correctJEE Main 2026
Elements X and Y belong to Group 15. The difference between the electronegativity values of ‘X’ and phosphorus is higher than that of the difference between phosphorus and ‘Y’. ‘X’ & ‘Y’ are respectively
  1. (A)N & As
  2. (B)As & Bi
  3. (C)Bi & N
  4. (D)As & Sb

Correct answer: (A)

Step-by-step solution →
Q24·ChemistrySingle correctJEE Main 2026
The correct statements from the following are : (A) Ionic radii of trivalent cations of group 13 elements decreases down the group. (B) Electronegativity of group 13 elements decreases down the group. (C) Among the group 13 elements, Boron has highest first ionisation enthalpy. (D) The trichloride and triiodide of group 13 elements are covalent in nature. Choose the correct answer from the otpions given below :
  1. (A)A and C only
  2. (B)A and D only
  3. (C)C and D only
  4. (D)B and D only

Correct answer: (C)

Step-by-step solution →
Q25·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement-I : Element 'X' and 'Y' are the most and least electronegative elements, respectively among N, As, Sb and P. The nature of the oxides X2O3X_2O_3X2​O3​ and Y2O3Y_2O_3Y2​O3​ is acidic and amphoteric, respectively. Statement-II : BCl3BCl_3BCl3​ is covalent in nature and gets hydrolysed in water. It produces [B(OH)4]−[B(OH)_4]^-[B(OH)4​]− and [B(H2O)6]3+[B(H_2O)_6]^{3+}[B(H2​O)6​]3+ in aqueous medium. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement-I and Statement-II are true.
  2. (B)Statement-I is true but Statement-II is false.
  3. (C)Both Statement-I and Statement-II are false.
  4. (D)Statement-I is false but Statement-II is true.

Correct answer: (B)

Step-by-step solution →
Q26·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I : The halogen that makes longest bond with hydrogen in HX, has the smallest covalent radius in its group. Statement II : A group 15 element's hydride EH3_33​ has the lowest boiling point among corresponding hydrides of other group 15 elements. The maximum covalency of that element E is 4. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Both Statement I and Statement II are true.
  2. (B)Statement I is false but Statement II is true.
  3. (C)Both Statement I and Statement II are false.
  4. (D)Statement I is true but Statement II is false.

Correct answer: (C)

Step-by-step solution →
Q27·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I : The correct order in terms of bond dissociation enthalpy is Cl2>Br2>F2>I2\text{Cl}_{2} > \text{Br}_{2} > \text{F}_{2} > \text{I}_{2}Cl2​>Br2​>F2​>I2​ Statement II : The correct trend in the covalent character of the metal halides is [SnCl4>SnCl2][\text{SnCl}_{4} > \text{SnCl}_{2}][SnCl4​>SnCl2​], [PbCl4>PbCl2][\text{PbCl}_{4} > \text{PbCl}_{2}][PbCl4​>PbCl2​] and [UF4>UF6][\text{UF}_{4} > \text{UF}_{6}][UF4​>UF6​] In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are false

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I : The number of pairs among [SiO2,CO2][SiO_2, CO_2][SiO2​,CO2​], [SnO,SnO2][SnO, SnO_2][SnO,SnO2​], [PbO,PbO2][PbO, PbO_2][PbO,PbO2​] and [GeO,GeO2][GeO, GeO_2][GeO,GeO2​], which contain oxides that are both amphoteric is 2. Statement II : BF3BF_3BF3​ is an electron deficient molecule can act as a lewis acid, forms adduct with NH3NH_3NH3​ and has a trigonal planar geometry. In the light of the above statement, choose the correct answer from the option given below.
  1. (A)Both Statement I and Statement II are true.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Statement I is false Statement II is true.

Correct answer: (A)

Step-by-step solution →
Q29·ChemistrySingle correctJEE Main 2026
Consider the following reactions. PbCl2+K2CrO4→A+2KClPbCl_2 + K_2CrO_4 \rightarrow A + 2KClPbCl2​+K2​CrO4​→A+2KCl (Hot solution) A+NaOH⇌B+Na2CrO4A + NaOH \rightleftharpoons B + Na_2CrO_4A+NaOH⇌B+Na2​CrO4​ PbSO4+4CH3COONH4→(NH4)2SO4+XPbSO_4 + 4CH_3COONH_4 \rightarrow (NH_4)_2SO_4 + XPbSO4​+4CH3​COONH4​→(NH4​)2​SO4​+X In the above reactions, A, B and X are respectively.
  1. (A)Na2[Pb(OH)2],PbCrO4Na_2[Pb(OH)_2], PbCrO_4Na2​[Pb(OH)2​],PbCrO4​ and (NH4)2[Pb(CH3COO)4](NH_4)_2[Pb(CH_3COO)_4](NH4​)2​[Pb(CH3​COO)4​]
  2. (B)PbCrO4PbCrO_4PbCrO4​, Na2[Pb(OH)4]Na_2[Pb(OH)_4]Na2​[Pb(OH)4​] and [Pb(NH3)4]SO4[Pb(NH_3)_4]SO_4[Pb(NH3​)4​]SO4​
  3. (C)Na2[Pb(OH)2]Na_2[Pb(OH)_2]Na2​[Pb(OH)2​], PbCrO4PbCrO_4PbCrO4​ and [Pb(NH3)4]SO4[Pb(NH_3)_4]SO_4[Pb(NH3​)4​]SO4​
  4. (D)PbCrO4PbCrO_4PbCrO4​, Na2[Pb(OH)4]Na_2[Pb(OH)_4]Na2​[Pb(OH)4​] and (NH4)2[Pb(CH3COO)4](NH_4)_2[Pb(CH_3COO)_4](NH4​)2​[Pb(CH3​COO)4​]

Correct answer: (D)

Step-by-step solution →
Q30·ChemistrySingle correctJEE Advanced 2025
The heating of NH4NO2NH_4NO_2NH4​NO2​ at 60–70°C and NH4NO3NH_4NO_3NH4​NO3​ at 200–250°C is associated with the formation of nitrogen containing compounds X and Y, respectively. X and Y, respectively, are
  1. (A)N2N_2N2​ and N2ON_2ON2​O
  2. (B)NH3NH_3NH3​ and NO2NO_2NO2​
  3. (C)NONONO and N2ON_2ON2​O
  4. (D)N2N_2N2​ and NH3NH_3NH3​

Correct answer: (A)

Step-by-step solution →
Q31·ChemistryMultiple correctJEE Advanced 2025
The compound(s) with P −-− H bond(s) is(are)
  1. (A)H3_{3}3​PO4_{4}4​
  2. (B)H3_{3}3​PO3_{3}3​
  3. (C)H4_{4}4​P2_{2}2​O7_{7}7​
  4. (D)H3_{3}3​PO2_{2}2​

Correct answer: (B), (D)

Step-by-step solution →
Q32·ChemistrySingle correctJEE Advanced 2025
The complete hydrolysis of ICl, ClF3_{3}3​ and BrF5_{5}5​, respectively, gives
  1. (A)IO−^{-}−, ClO2−_{2}^{-}2−​ and BrO3−_{3}^{-}3−​
  2. (B)IO3−_{3}^{-}3−​, ClO2−_{2}^{-}2−​ and BrO3−_{3}^{-}3−​
  3. (C)IO−^{-}−, ClO−^{-}− and BrO2−_{2}^{-}2−​
  4. (D)IO3−_{3}^{-}3−​, ClO4−_{4}^{-}4−​ and BrO2−_{2}^{-}2−​

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement I: H2SeH_2SeH2​Se is more acidic than H2TeH_2TeH2​Te. Statement II: H2SeH_2SeH2​Se has higher bond enthalpy for dissociation than H2TeH_2TeH2​Te. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are false.
  2. (B)Both statement I and Statement II are true.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Statement I is false but Statement II is true.

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correctJEE Main 2025
The correct statements from the following are: (A) Tl3+Tl^{3+}Tl3+ is a powerful oxidising agent (B) Al3+Al^{3+}Al3+ does not get reduced easily (C) Both Al3+Al^{3+}Al3+ and Tl3+Tl^{3+}Tl3+ are very stable in solution (D) Tl+Tl^+Tl+ is more stable than Tl3+Tl^{3+}Tl3+ (E) Al3+Al^{3+}Al3+ and Tl+Tl^+Tl+ are highly stable Choose the correct answer from the options given below:
  1. (A)(A), (B), (C), (D) and (E)
  2. (B)(A), (B), (D) and (E) only
  3. (C)(B), (D) and (E) only
  4. (D)(A), (C) and (D) only

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correctJEE Main 2025
The group 14 elements A and B have the first ionisation enthalpy values of 708 and 715 kJ mol−1^{-1}−1 respectively. The above values are lowest among their group members. The nature of their ions A2+A^{2+}A2+, B4+B^{4+}B4+ respectively is
  1. (A)both reducing
  2. (B)both oxidising
  3. (C)reducing and oxidising
  4. (D)oxidising and reducing

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correctJEE Main 2025
The elements of Group 13 with highest and lowest first ionisation enthalpies are respectively:
  1. (A)B & Ga
  2. (B)B & Tl
  3. (C)Tl & B
  4. (D)B & In

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement (I): The first ionisation enthalpy of group 14 elements is higher than the corresponding elements of group 13. Statement (II): Melting points and boiling points of group 13 elements are in general much higher than the corresponding elements of group 14. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but Statement II is incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement I: Nitrogen forms oxides with +1+1+1 to +5+5+5 oxidation states due to the formation of pπ−pπp\pi-p\pipπ−pπ bond with oxygen. Statement II: Nitrogen does not form halides with +5+5+5 oxidation state due to the absence of d-orbital in it. In the light of given statements, choose the correct answer from the options below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are true

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correctJEE Main 2025
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. (B<Al)(B<Al)(B<Al), (Al<Ga)(Al<Ga)(Al<Ga), (Ga<In)(Ga<In)(Ga<In) and (In<Tl)(In<Tl)(In<Tl). Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius (M3+M^{3+}M3+) than the other one. The atomic number of the element (X) is
  1. (A)31
  2. (B)49
  3. (C)13
  4. (D)81

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correctJEE Main 2025
The correct orders among the following are: A. Atomic radius: B<Al<Ga<In<TlB < Al < Ga < In < TlB<Al<Ga<In<Tl B. Electronegativity: Al<Ga<In<Tl<BAl < Ga < In < Tl < BAl<Ga<In<Tl<B C. Density: Tl<In<Ga<Al<BTl < In < Ga < Al < BTl<In<Ga<Al<B D. 1st Ionisation Energy: In<Al<Ga<Tl<BIn < Al < Ga < Tl < BIn<Al<Ga<Tl<B Choose the correct answer from the options given below:
  1. (A)B and D Only
  2. (B)A and C Only
  3. (C)C and D Only
  4. (D)A and B Only

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correctJEE Main 2025
Given below are two statements. Statement I: The N-N single bond is weaker and longer than that of P-P single bond. Statement II: Compounds of group 15 elements in +3 oxidation states readily undergo disproportionation reactions. In the light of above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but statement II is false
  2. (B)Both statement I and statement II are false
  3. (C)Statement I is false but Statement II is true
  4. (D)Both statement I and Statement II are true

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correctJEE Main 2025
The nature of oxide (TeO2)(TeO_2)(TeO2​) and hydride (TeH2)(TeH_2)(TeH2​) formed by Te, respectively are:
  1. (A)Oxidising and acidic
  2. (B)Reducing and basic
  3. (C)Reducing and acidic
  4. (D)Oxidising and basic

Correct answer: (A)

Step-by-step solution →
Q43·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement (I): The metallic radius of Al is less than that of Ga. Statement (II): The ionic radius of Al3+Al^{3+}Al3+ is less than that of Ga3+Ga^{3+}Ga3+. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correctJEE Main 2025
The property/properties that show irregularity in the first four elements of group-17 is/are: (A) Covalent radius (B) Electron affinity (C) Ionic radius (D) First ionization energy. Choose the correct answer from the options given below:
  1. (A)B and D only
  2. (B)A and C only
  3. (C)B only
  4. (D)A, B, C and D

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correctJEE Main 2025
A molecule with the formula AX4YAX_4YAX4​Y has all its elements from the p-block. Element A is rarest, monoatomic, non-radioactive and has the lowest ionization enthalpy value among A, X and Y. Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is:
  1. (A)Square pyramidal
  2. (B)Octahedral
  3. (C)Pentagonal planar
  4. (D)Trigonal bipyramidal

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correctJEE Main 2025
The standard reduction potential values of some of the p-block ions are given below. Predict the one with the strongest oxidising capacity.
  1. (A)ESn4+/Sn2+∘=+1.15E^\circ_{Sn^{4+}/Sn^{2+}}=+1.15ESn4+/Sn2+∘​=+1.15 V
  2. (B)ETl3+/Tl+∘=+1.26E^\circ_{Tl^{3+}/Tl^{+}}=+1.26ETl3+/Tl+∘​=+1.26 V
  3. (C)EAl3+/Al∘=−1.66E^\circ_{Al^{3+}/Al}=-1.66EAl3+/Al∘​=−1.66 V
  4. (D)EPb4+/Pb2+∘=+1.67E^\circ_{Pb^{4+}/Pb^{2+}}=+1.67EPb4+/Pb2+∘​=+1.67 V

Correct answer: (D)

Step-by-step solution →
Q47·ChemistrySingle correctJEE Main 2025
First ionisation enthalpy values of first four group 15 elements are given below. Choose the correct value for the element that is a main component of apatite family:
  1. (A)1012 kJ mol⁻¹
  2. (B)1402 kJ mol⁻¹
  3. (C)834 kJ mol⁻¹
  4. (D)947 kJ mol⁻¹

Correct answer: (A)

Step-by-step solution →
Q48·ChemistryIntegerJEE Main 2025
A group 15 element forms dπ\piπ-dπ\piπ bond with transition metals. It also forms hydride, which is a strongest base among the hydrides of other group members that form dπ\piπ-dπ\piπ bond. The atomic number of this element is ______.

Correct answer: 15

Step-by-step solution →
Q49·ChemistrySingle correctJEE Main 2025
The large difference between the melting and boiling points of oxygen and sulphur may be explained on the basis of
  1. (A)Atomic size
  2. (B)Atomicity
  3. (C)Electronegativity
  4. (D)Electron gain enthalpy

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correctJEE Main 2025
The incorrect statement among the following is
  1. (A)PH₃ shows lower proton affinity than NH₃.
  2. (B)PF₃ exists but NF₅ does not.
  3. (C)NO₂ can dimerise easily.
  4. (D)SO₂ can act as an oxidizing agent, but not as a reducing agent.

Correct answer: (D)

Step-by-step solution →
Q51·ChemistrySingle correctJEE Main 2025
Given below are the atomic numbers of some group 14 elements. The atomic number of the element with lowest melting point is :
  1. (A)14
  2. (B)6
  3. (C)82
  4. (D)50

Correct answer: (D)

Step-by-step solution →
Q52·ChemistrySingle correctJEE Main 2025
The species which does not undergo disproportionation reaction is:
  1. (A)ClO2−ClO_2^-ClO2−​
  2. (B)ClO4−ClO_4^-ClO4−​
  3. (C)ClO−ClO^-ClO−
  4. (D)ClO3−ClO_3^-ClO3−​

Correct answer: (B)

Step-by-step solution →
Q53·ChemistrySingle correctJEE Main 2025
The maximum covalency of a non-metallic group 15 element 'E' with weakest E−-−E bond is:
  1. (A)5
  2. (B)3
  3. (C)6
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q54·ChemistrySingle correctJEE Advanced 2024
The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are
  1. (A)[PF4]+[PF6]−[PF_4]^+[PF_6]^-[PF4​]+[PF6​]− and [PCl4]+[PF6]−[PCl_4]^+[PF_6]^-[PCl4​]+[PF6​]−
  2. (B)[PCl4]+[PCl4F2]−[PCl_4]^+[PCl_4F_2]^-[PCl4​]+[PCl4​F2​]− and [PCl4]+[PF6]−[PCl_4]^+[PF_6]^-[PCl4​]+[PF6​]−
  3. (C)PF3PF_3PF3​ and PCl3PCl_3PCl3​
  4. (D)PF5PF_5PF5​ and PCl3PCl_3PCl3​

Correct answer: (B)

Step-by-step solution →
Q55·ChemistryMultiple correctJEE Advanced 2024
The compound(s) having peroxide linkage is(are)
  1. (A)H2S2O7H_2S_2O_7H2​S2​O7​
  2. (B)H2S2O8H_2S_2O_8H2​S2​O8​
  3. (C)H2S2O5H_2S_2O_5H2​S2​O5​
  4. (D)H2SO5H_2SO_5H2​SO5​

Correct answer: (B), (D)

Step-by-step solution →
Q56·ChemistrySingle correctJEE Advanced 2024
At room temperature, disproportionation of an aqueous solution of in situ\textit{in situ}in situ generated nitrous acid (HNO2_{2}2​) gives the species
  1. (A)H3_{3}3​O+^{+}+, NO3−_{3}^{-}3−​ and NO
  2. (B)H3_{3}3​O+^{+}+, NO3−_{3}^{-}3−​ and NO2_{2}2​
  3. (C)H3_{3}3​O+^{+}+, NO−^{-}− and NO2_{2}2​
  4. (D)H3_{3}3​O+^{+}+, NO3−_{3}^{-}3−​ and N2_{2}2​O

Correct answer: (A)

Step-by-step solution →
Q57·ChemistrySingle correctJEE Main 2024
Given below are two statements : one is labelled as Assertion (A) : and the other is labelled as Reason (R). Assertion (A) : Both rhombic and monoclinic sulphur exist as S8S_8S8​ while oxygen exists as O2O_2O2​. Reason (R) : Oxygen forms pπp\pipπ-pπp\pipπ multiple bonds with itself and other elements having small size and high electronegativity like C, N, which is not possible for sulphur. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Both (A) and (R) are correct and (R) is the correct explanation of (A).
  2. (B)Both (A) and (R) are correct but (R) is not the correct explanation of (A).
  3. (C)(A) is correct but (R) is not correct.
  4. (D)(A) is not correct but (R) is correct.

Correct answer: (A)

Step-by-step solution →
Q58·ChemistrySingle correctJEE Main 2024
The F−F^-F− ions make the enamel on teeth much harder by converting hydroxyapatite (the enamel on the surface of teeth) into much harder fluoroapatite having the formula.
  1. (A)[3(Ca3(PO4)2).CaF2][3(Ca_3(PO_4)_2).CaF_2][3(Ca3​(PO4​)2​).CaF2​]
  2. (B)[3(Ca2(PO4)2).Ca(OH)2][3(Ca_2(PO_4)_2).Ca(OH)_2][3(Ca2​(PO4​)2​).Ca(OH)2​]
  3. (C)[3(Ca3(PO4)3).CaF2][3(Ca_3(PO_4)_3).CaF_2][3(Ca3​(PO4​)3​).CaF2​]
  4. (D)[3(Ca3(PO4)2).Ca(OH)2][3(Ca_3(PO_4)_2).Ca(OH)_2][3(Ca3​(PO4​)2​).Ca(OH)2​]

Correct answer: (A)

Step-by-step solution →
Q59·ChemistryNumericalJEE Main 2024
Number of oxygen atoms present in the chemical formula of fuming sulphuric acid is _______.

Correct answer: 7

Step-by-step solution →
Q60·ChemistrySingle correctJEE Main 2024
On reaction of Lead Sulphide with dilute nitric acid which of the following is notnotnot formed?
  1. (A)Lead nitrate
  2. (B)Sulphur
  3. (C)Nitric oxide
  4. (D)Nitrous oxide

Correct answer: (D)

Step-by-step solution →
Q61·ChemistrySingle correctJEE Main 2024
Identify the incorrect statements about group 15 elements: (A) Dinitrogen is a diatomic gas which acts like an inert gas at room temperature. (B) The common oxidation states of these elements are −3-3−3, +3+3+3 and +5+5+5. (C) Nitrogen has unique ability to form pπ−pπp\pi-p\pipπ−pπ multiple bonds. (D) The stability of +5+5+5 oxidation states increases down the group. (E) Nitrogen shows a maximum covalency of 6. Choose the correct answer from the options given below.
  1. (A)(A), (B), (D) only
  2. (B)(A), (C), (E) only
  3. (C)(B), (D), (E) only
  4. (D)(D) and (E) only

Correct answer: (D)

Step-by-step solution →
Q62·ChemistrySingle correctJEE Main 2024
Among the following halogens F2F_2F2​, Cl2Cl_2Cl2​, Br2Br_2Br2​ and I2I_2I2​, which can undergo disproportionation reaction?
  1. (A)Only I2I_2I2​
  2. (B)Cl2Cl_2Cl2​, Br2Br_2Br2​ and I2I_2I2​
  3. (C)F2F_2F2​, Cl2Cl_2Cl2​ and Br2Br_2Br2​
  4. (D)F2F_2F2​ and Cl2Cl_2Cl2​

Correct answer: (B)

Step-by-step solution →
Q63·ChemistrySingle correctJEE Main 2024
Identify the correct statements about p-block elements and their compounds. (A) Non metals have higher electronegativity than metals. (B) Non metals have lower ionisation enthalpy than metals. (C) Compounds formed between highly reactive nonmetals and highly reactive metals are generally ionic. (D) The non-metal oxides are generally basic in nature. (E) The metal oxides are generally acidic or neutral in nature.
  1. (A)(D) and (E) only
  2. (B)(A) and (C) only
  3. (C)(B) and (E) only
  4. (D)(B) and (D) only

Correct answer: (B)

Step-by-step solution →
Q64·ChemistrySingle correctJEE Main 2024
Given below are two statements: Assertion A: The stability order of +1+1+1 oxidation state of Ga, In and Tl is Ga < In < Tl. Reason R: The inert pair effect stabilizes the lower oxidation state down the group. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)A is true but R is false.
  3. (C)Both A and R are true but R is NOT the correct explanation of A.
  4. (D)A is false but R is true.

Correct answer: (A)

Step-by-step solution →
Q65·ChemistrySingle correctJEE Main 2024
The number of ions from the following that are expected to behave as oxidising agent is: Sn4+Sn^{4+}Sn4+, Sn2+Sn^{2+}Sn2+, Pb2+Pb^{2+}Pb2+, Tl3+Tl^{3+}Tl3+, Pb4+Pb^{4+}Pb4+, Tl+Tl^+Tl+
  1. (A)3
  2. (B)4
  3. (C)1
  4. (D)2

Correct answer: (D)

Step-by-step solution →
Q66·ChemistrySingle correctJEE Main 2024
Evaluate the following statements related to group 14 elements for their correctness. (A) Covalent radius decreases down the group from C to Pb in a regular manner. (B) Electronegativity decreases from C to Pb down the group gradually. (C) Maximum covalence of C is 4 whereas other elements can expand their covalence due to presence of d orbitals. (D) Heavier elements do not form pπ−pπp\pi-p\pipπ−pπ bonds. (E) Carbon can exhibit negative oxidation states. Choose the correct answer from the options given below:
  1. (A)(C), (D) and (E) Only
  2. (B)(A) and (B) Only
  3. (C)(A), (B) and (C) Only
  4. (D)(C) and (D) Only

Correct answer: (A)

Step-by-step solution →
Q67·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement I: Gallium is used in the manufacturing of thermometers. Statement II: A thermometer containing gallium is useful for measuring the freezing point (256 K) of brine solution. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are false.
  2. (B)Statement I is false but Statement II is true.
  3. (C)Both Statement I and Statement II are true.
  4. (D)Statement I is true but Statement II is false.

Correct answer: (D)

Step-by-step solution →
Q68·ChemistrySingle correctJEE Main 2024
The correct statements from the following are: (A) The decreasing order of atomic radii of group 13 elements is Tl > In > Ga > Al > B. (B) Down group 13, electronegativity decreases from top to bottom. (C) Al dissolves in dil. HCl and liberates H2\text{H}_2H2​, but conc. HNO3\text{HNO}_3HNO3​ renders Al passive by forming a protective oxide layer on the surface. (D) All elements of group 13 exhibit a highly stable +1 oxidation state. (E) The hybridisation of Al in [Al(H2O)6]3+[\text{Al}(\text{H}_2\text{O})_6]^{3+}[Al(H2​O)6​]3+ ion is sp3d2sp^3d^2sp3d2. Choose the correct answer from the options given below:
  1. (A)(C) and (E) only
  2. (B)(A), (C) and (E) only
  3. (C)(A), (B), (C) and (E) only
  4. (D)(A) and (C) only

Correct answer: (A)

Step-by-step solution →
Q69·ChemistrySingle correctJEE Main 2024
The number of neutrons present in the more abundant isotope of boron is 'x'. Amorphous boron upon heating with air forms a product in which the oxidation state of boron is 'y'. The value of x+yx + yx+y is:
  1. (A)4
  2. (B)6
  3. (C)3
  4. (D)9

Correct answer: (D)

Step-by-step solution →
Q70·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement I: In group 13, the stability of the +1 oxidation state increases down the group. Statement II: The atomic size of gallium is greater than that of aluminium. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Both Statement I and Statement II are correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Statement I is correct but Statement II is incorrect

Correct answer: (D)

Step-by-step solution →
Q71·ChemistrySingle correctJEE Main 2024
When MnO2\text{MnO}_2MnO2​ and H2SO4\text{H}_2\text{SO}_4H2​SO4​ is added to a salt (A), greenish yellow gas liberated as salt (A) is
  1. (A)NaBr\text{NaBr}NaBr
  2. (B)CaI2\text{CaI}_2CaI2​
  3. (C)KNO3\text{KNO}_3KNO3​
  4. (D)NH4Cl\text{NH}_4\text{Cl}NH4​Cl

Correct answer: (D)

Step-by-step solution →
Q72·ChemistryNumericalJEE Main 2024
Among the following oxides of p-block elements, number of oxides having amphoteric nature is ___. Cl2O7Cl_2O_7Cl2​O7​, COCOCO, PbO2PbO_2PbO2​, N2ON_2ON2​O, NONONO, Al2O3Al_2O_3Al2​O3​, SiO2SiO_2SiO2​, SnO2SnO_2SnO2​

Correct answer: 3

Step-by-step solution →
Q73·ChemistrySingle correctJEE Main 2024
The strongest reducing agent among the following is:
  1. (A)NH3\text{NH}_3NH3​
  2. (B)SbH3\text{SbH}_3SbH3​
  3. (C)BiH3\text{BiH}_3BiH3​
  4. (D)PH3\text{PH}_3PH3​

Correct answer: (C)

Step-by-step solution →
Q74·ChemistrySingle correctJEE Main 2024
Given below are two statements: Assertion (A): PH3PH_3PH3​ has lower boiling point than NH3NH_3NH3​. Reason (R): In liquid state NH3NH_3NH3​ molecules are associated through vander waal's forces, but PH3PH_3PH3​ molecules are associated through hydrogen bonding. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  2. (B)(A) is not correct but (R) is correct
  3. (C)Both (A) and (R) are correct but (R) is not the correct explanation of (A)
  4. (D)(A) is correct but (R) is not correct

Correct answer: (D)

Step-by-step solution →
Q75·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement (I): SiO2\text{SiO}_2SiO2​ and GeO2\text{GeO}_2GeO2​ are acidic while SnO and PbO are amphoteric in nature. Statement (II): Allotropic forms of carbon are due to property of catenation and pπ\piπ–dπ\piπ bond formation. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q76·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement-I : Noble gases have very high boiling points. Statement-II : Noble gases are monoatomic gases. They are held together by strong dispersion forces. Because of this they are liquefied at very low temperature. Hence, they have very high boiling points. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true.
  2. (B)Both Statement I and Statement II are true.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Both Statement I and Statement II are false.

Correct answer: (D)

Step-by-step solution →
Q77·ChemistryNumericalJEE Main 2024
Molar mass of the salt from NaBr, NaNO3NaNO_3NaNO3​, KI and CaF2CaF_2CaF2​ which does not evolve coloured vapours on heating with concentrated H2SO4H_2SO_4H2​SO4​ is ______ g mol−1^{-1}−1. (Molar mass in g mol−1^{-1}−1 : Na : 23, N : 14, K : 39, O : 16, Br : 80, I : 127, F : 19, Ca : 40)

Correct answer: 78

Step-by-step solution →
Q78·ChemistrySingle correctJEE Main 2024
Consider the oxides of group 14 elements SiO2SiO_2SiO2​, GeO2GeO_2GeO2​, SnO2SnO_2SnO2​, PbO2PbO_2PbO2​, CO and GeO. The amphoteric oxides are
  1. (A)GeO,GeO2GeO, GeO_2GeO,GeO2​
  2. (B)SiO2,GeO2SiO_2, GeO_2SiO2​,GeO2​
  3. (C)SnO2,PbO2SnO_2, PbO_2SnO2​,PbO2​
  4. (D)SnO2,COSnO_2, COSnO2​,CO

Correct answer: (C)

Step-by-step solution →
Q79·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement-I: Group 13 trivalent halides easily get hydrolyzed by water due to their covalent nature. Statement-II: AlCl3AlCl_3AlCl3​ upon hydrolysis in acidified aqueous solution forms octahedral [Al(H2O)6]3+[Al(H_2O)_6]^{3+}[Al(H2​O)6​]3+ ion. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Statement I is false but Statement II is true
  3. (C)Both statement I and statement II are false
  4. (D)Both statement I and statement II are true

Correct answer: (D)

Step-by-step solution →
Q80·ChemistrySingle correctJEE Main 2024
Choose the correct statements from the following A. All group 16 elements form oxides of general formula EO2EO_2EO2​ and EO3EO_3EO3​ where E = S, Se, Te and Po. Both the types of oxides are acidic in nature. B. TeO2TeO_2TeO2​ is an oxidising agent while SO2SO_2SO2​ is reducing in nature. C. The reducing property decreases from H2SH_2SH2​S to H2TeH_2TeH2​Te down the group. D. The ozone molecule contains five lone pairs of electrons. Choose the correct answer from the options given below:
  1. (A)A and D only
  2. (B)B and C only
  3. (C)C and D only
  4. (D)A and B only

Correct answer: (D)

Step-by-step solution →
Q81·ChemistrySingle correctJEE Main 2024
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: H2TeH_2TeH2​Te is more acidic than H2SH_2SH2​S. Reason R: Bond dissociation enthalpy of H2TeH_2TeH2​Te is lower than H2SH_2SH2​S. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both A and R are true but R is NOT the correct explanation of A.
  2. (B)Both A and R are true and R is the correct explanation of A.
  3. (C)A is false but R is true.
  4. (D)A is true but R is false.

Correct answer: (B)

Step-by-step solution →
Q82·ChemistrySingle correctJEE Main 2024
Choose the correct statements about the hydrides of group 15 elements. A. The stability of the hydrides decreases in the order NH3>PH3>AsH3>SbH3>BiH3NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3NH3​>PH3​>AsH3​>SbH3​>BiH3​. B. The reducing ability of the hydrides increases in the order NH3<PH3<AsH3<SbH3<BiH3NH_3 < PH_3 < AsH_3 < SbH_3 < BiH_3NH3​<PH3​<AsH3​<SbH3​<BiH3​. C. Among the hydrides, NH3NH_3NH3​ is strong reducing agent while BiH3BiH_3BiH3​ is mild reducing agent. D. The basicity of the hydrides increases in the order NH3<PH3<AsH3<SbH3<BiH3NH_3 < PH_3 < AsH_3 < SbH_3 < BiH_3NH3​<PH3​<AsH3​<SbH3​<BiH3​. Choose the most appropriate answer from the option given below:
  1. (A)B and C only
  2. (B)C and D only
  3. (C)A and B only
  4. (D)A and D only

Correct answer: (C)

Step-by-step solution →
Q83·ChemistrySingle correctJEE Main 2024
On passing a gas 'X' through Nessler's reagent, a brown precipitate is obtained. The gas 'X' is:
  1. (A)H2SH_2SH2​S
  2. (B)CO2CO_2CO2​
  3. (C)NH3NH_3NH3​
  4. (D)Cl2Cl_2Cl2​

Correct answer: (C)

Step-by-step solution →
Q84·ChemistrySingle correctJEE Main 2024
Given below are two statements : Statement I : The electronegativity of group 14 elements from Si to Pb gradually decreases. Statement II : Group 14 contains non-metallic, metallic, as well as metalloid elements. In the light of the above statements, choose the most appropriate from the options given below :
  1. (A)Statement I is false but Statement II is true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are true
  4. (D)Both Statement I and Statement II are false

Correct answer: (A)

Step-by-step solution →
Q85·ChemistryNumericalJEE Main 2024
The oxidation number of iron in the compound formed during brown ring test for NO3−NO_3^-NO3−​ ion is ___.

Correct answer: 1

Step-by-step solution →
Q86·ChemistrySingle correctJEE Main 2024
Anomalous behaviour of oxygen is due to its:
  1. (A)Large size and high electronegativity
  2. (B)Small size and low electronegativity
  3. (C)Small size and high electronegativity
  4. (D)Large size and low electronegativity

Correct answer: (C)

Step-by-step solution →
Q87·ChemistrySingle correctJEE Main 2024
Which of the following cannot function as an oxidising agent ?
  1. (A)N3−N^{3-}N3−
  2. (B)SO42−SO_4^{2-}SO42−​
  3. (C)BrO3−BrO_3^-BrO3−​
  4. (D)MnO4−MnO_4^-MnO4−​

Correct answer: (A)

Step-by-step solution →
Q88·ChemistrySingle correctJEE Main 2024
Element not showing variable oxidation state is:
  1. (A)Bromine
  2. (B)Iodine
  3. (C)Chlorine
  4. (D)Fluorine

Correct answer: (D)

Step-by-step solution →
Q89·ChemistryNumericalJEE Main 2024
From the given list, the number of compounds with +4 oxidation state of Sulphur __________: SO3,  H2SO3,  SOCl2,  SF4,  BaSO4,  H2S2O7\text{SO}_3,\;\text{H}_2\text{SO}_3,\;\text{SOCl}_2,\;\text{SF}_4,\;\text{BaSO}_4,\;\text{H}_2\text{S}_2\text{O}_7SO3​,H2​SO3​,SOCl2​,SF4​,BaSO4​,H2​S2​O7​.

Correct answer: 3

Step-by-step solution →
Q90·ChemistrySingle correctJEE Main 2024
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): Melting point of Boron (2453 K) is unusually high in group 13 elements. Reason (R): Solid Boron has very strong crystalline lattice. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both (A) and (R) are correct but (R) is Not the correct explanation of (A)
  2. (B)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  3. (C)(A) is true but (R) is false
  4. (D)(A) is false but (R) is true

Correct answer: (B)

Step-by-step solution →
Q91·ChemistrySingle correctJEE Main 2024
Yellow compound of lead chromate gets dissolved on treatment with hot NaOH solution. The product of lead formed is a:
  1. (A)Tetraanionic complex with coordination number six
  2. (B)Neutral complex with coordination number four
  3. (C)Dianionic complex with coordination number six
  4. (D)Dianionic complex with coordination number four

Correct answer: (D)

Step-by-step solution →
Q92·ChemistrySingle correctJEE Main 2024
Given below are two statements : Statement (I) : Oxygen being the first member of group 16 exhibits only −2-2−2 oxidation state. Statement (II) : Down the group 16 stability of +4+4+4 oxidation state decreases and +6+6+6 oxidation state increases. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Statement I is correct but Statement II is incorrect
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Both Statement I and Statement II are correct
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (B)

Step-by-step solution →
Q93·ChemistryNumericalJEE Advanced 2023
The stoichiometric reaction of 516 g of dimethyldichlorosilane with water results in a tetrameric cyclic product X in 75% yield. The weight (in g) of X obtained is___. [Use, molar mass (g mol−1\mathrm{g\ mol^{-1}}g mol−1): H = 1, C = 12, O = 16, Si = 28, Cl = 35.5]

Correct answer: 222

Step-by-step solution →
Q94·ChemistrySingle correctJEE Advanced 2023
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option.
List-IList-II
P.P2O3+3H2O→\mathrm{P_2O_3 + 3H_2O} \rightarrowP2​O3​+3H2​O→1.P(O)(OCH3)Cl2\mathrm{P(O)(OCH_3)Cl_2}P(O)(OCH3​)Cl2​
Q.P4+3NaOH+3H2O→\mathrm{P_4 + 3NaOH + 3H_2O} \rightarrowP4​+3NaOH+3H2​O→2.H3PO3\mathrm{H_3PO_3}H3​PO3​
R.PCl5+CH3COOH→\mathrm{PCl_5 + CH_3COOH} \rightarrowPCl5​+CH3​COOH→3.PH3\mathrm{PH_3}PH3​
S.H3PO2+2H2O+4AgNO3→\mathrm{H_3PO_2 + 2H_2O + 4AgNO_3} \rightarrowH3​PO2​+2H2​O+4AgNO3​→4.POCl3\mathrm{POCl_3}POCl3​
5.H3PO4\mathrm{H_3PO_4}H3​PO4​
  1. (A)P →\rightarrow→ 2; Q →\rightarrow→ 3; R →\rightarrow→ 1; S →\rightarrow→ 5
  2. (B)P →\rightarrow→ 3; Q →\rightarrow→ 5; R →\rightarrow→ 4; S →\rightarrow→ 2
  3. (C)P →\rightarrow→ 5; Q →\rightarrow→ 2; R →\rightarrow→ 1; S →\rightarrow→ 3
  4. (D)P →\rightarrow→ 2; Q →\rightarrow→ 3; R →\rightarrow→ 4; S →\rightarrow→ 5

Correct answer: (D)

Step-by-step solution →
Q95·ChemistrySingle correctJEE Main 2023
The number of P-O-P bonds in H4P2O7H_4P_2O_7H4​P2​O7​, (HPO3)3(HPO_3)_3(HPO3​)3​ and P4O10P_4O_{10}P4​O10​ are respectively.
  1. (A)1, 3, 6
  2. (B)0, 3, 6
  3. (C)0, 3, 4
  4. (D)1, 2, 4

Correct answer: (A)

Step-by-step solution →
Q96·ChemistrySingle correctJEE Main 2023
The covalency and oxidation state respectively of boron in [BF4]−[BF_4]^-[BF4​]− are
  1. (A)4 and 3
  2. (B)4 and 4
  3. (C)3 and 4
  4. (D)3 and 5

Correct answer: (A)

Step-by-step solution →
Q97·ChemistrySingle correctJEE Main 2023
The correct group of halide ions which can be oxidised by oxygen in acidic medium is
  1. (A)Br−Br^-Br− only
  2. (B)Cl−,Br−Cl^-, Br^-Cl−,Br− and I−I^-I− only
  3. (C)Br−Br^-Br− and I−I^-I− only
  4. (D)I−I^-I− only

Correct answer: (D)

Step-by-step solution →
Q98·ChemistrySingle correctJEE Main 2023
The incorrect statement from the following for borazine is:
  1. (A)It has electronic delocalization
  2. (B)It contains banana bonds
  3. (C)It can react with water
  4. (D)It is a cyclic compound

Correct answer: (C)

Step-by-step solution →
Q99·ChemistryNumericalJEE Main 2023
If the formula of Borax is Na2B4Ox(OH)y⋅zH2ONa_2B_4O_x(OH)_y \cdot zH_2ONa2​B4​Ox​(OH)y​⋅zH2​O, then x+y+z=x + y + z =x+y+z= ____.

Correct answer: 17

Step-by-step solution →
Q100·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: Boron is extremely hard indicating its high lattice energy. Statement II: Boron has highest melting and boiling point compared to its other group members. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Both Statement I and Statement II are correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are incorrect

Correct answer: (B)

Step-by-step solution →
Q101·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: SbCl5_55​ is more covalent than SbCl3_33​. Statement II: The higher oxides of halogens also tend to be more stable than the lower ones. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (A)

Step-by-step solution →
Q102·ChemistrySingle correctJEE Main 2023
For compound having the formula GaAlCl4GaAlCl_4GaAlCl4​, the correct option from the following is
  1. (A)Ga is more electronegative than Al and is present as a cationic part of the salt GaAlCl4GaAlCl_4GaAlCl4​
  2. (B)Oxidation state of Ga in the salt GaAlCl4GaAlCl_4GaAlCl4​ is +3.
  3. (C)Cl forms bond with both Al and Ga in GaAlCl4GaAlCl_4GaAlCl4​
  4. (D)Ga is coordinated with Cl in GaAlCl4GaAlCl_4GaAlCl4​

Correct answer: (A)

Step-by-step solution →
Q103·ChemistrySingle correctJEE Main 2023
One mole of P4P_4P4​ reacts with 8 moles of SOCl2SOCl_2SOCl2​ to give 4 moles of A, x moles of SO2SO_2SO2​ and 2 moles of B. A, B and x respectively are
  1. (A)PCl3, S2Cl2PCl_3,\ S_2Cl_2PCl3​, S2​Cl2​ and 4
  2. (B)POCl3, S2Cl2POCl_3,\ S_2Cl_2POCl3​, S2​Cl2​ and 4
  3. (C)PCl3, S2Cl2PCl_3,\ S_2Cl_2PCl3​, S2​Cl2​ and 2
  4. (D)POCl3, S2Cl2POCl_3,\ S_2Cl_2POCl3​, S2​Cl2​ and 2

Correct answer: (A)

Step-by-step solution →
Q104·ChemistrySingle correctJEE Main 2023
For elements B, C, N, Li, Be, O and F the correct order of first ionization enthalpy is
  1. (A)Li < Be < B < C < N < O < F
  2. (B)B > Li > Be > C > N > O > F
  3. (C)Li < B < Be < C < O < N < F
  4. (D)Li < Be < B < C < O < N < F

Correct answer: (C)

Step-by-step solution →
Q105·ChemistrySingle correctJEE Main 2023
The compound which does not exist is
  1. (A)NaO2_22​
  2. (B)(NH4_44​)2_22​BeF4_44​
  3. (C)BeH2_22​
  4. (D)PbI4_44​

Correct answer: (D)

Step-by-step solution →
Q106·ChemistryNumericalJEE Main 2023
In the following reactions, the total number of oxygen atoms in X and Y is _________. Na2O+H2O→2XNa_2O+H_2O\rightarrow2XNa2​O+H2​O→2X; Cl2O7+H2O→2YCl_2O_7+H_2O\rightarrow2YCl2​O7​+H2​O→2Y

Correct answer: 5

Step-by-step solution →
Q107·ChemistryNumericalJEE Main 2023
In the complete hydrolysis of XeF4\text{XeF}_4XeF4​, the difference in the oxidation state of Xe between the oxidised product of XeF4\text{XeF}_4XeF4​ and XeF4\text{XeF}_4XeF4​ is _______ .

Correct answer: 2

Step-by-step solution →
Q108·ChemistryNumericalJEE Main 2023
The sum of lone pairs present on the central atom of the interhalogen IF5_55​ and IF7_77​ is _________.

Correct answer: 1

Step-by-step solution →
Q109·ChemistrySingle correctJEE Main 2023
The correct order of electronegativity for given elements is:
  1. (A)C > P > At > Br
  2. (B)Br > P > At > C
  3. (C)P > Br > C > At
  4. (D)Br > C > At > P

Correct answer: (D)

Step-by-step solution →
Q110·ChemistrySingle correctJEE Main 2023
Which halogen is known to cause the reaction given below: 2Cu2++4X−→Cu2X2(s)+X22Cu^{2+} + 4X^- \rightarrow Cu_2X_2(s) + X_22Cu2++4X−→Cu2​X2​(s)+X2​
  1. (A)Only Iodine
  2. (B)Only Bromine
  3. (C)All halogens
  4. (D)Only Chlorine

Correct answer: (A)

Step-by-step solution →
Q111·ChemistryNumericalJEE Main 2023
XeF4XeF_4XeF4​ reacts with SbF5SbF_5SbF5​ to form [XeFm]n+[SbFy]z−[XeF_m]^{n+}[SbF_y]^{z-}[XeFm​]n+[SbFy​]z−. m+n+y+z=m + n + y + z =m+n+y+z= ____

Correct answer: 11

Step-by-step solution →
Q112·ChemistrySingle correctJEE Main 2023
Which one of the following elements will remain as liquid inside pure boiling water?
  1. (A)Cs
  2. (B)Ga
  3. (C)Li
  4. (D)Br

Correct answer: (B)

Step-by-step solution →
Q113·ChemistrySingle correctJEE Main 2023
Group-13 elements react with O2O_2O2​ in amorphous form to form oxides of type M2O3M_2O_3M2​O3​ (MMM = element). Which among the following is the most basic oxide?
  1. (A)Al2O3Al_2O_3Al2​O3​
  2. (B)Ga2O3Ga_2O_3Ga2​O3​
  3. (C)Tl2O3Tl_2O_3Tl2​O3​
  4. (D)B2O3B_2O_3B2​O3​

Correct answer: (C)

Step-by-step solution →
Q114·ChemistryAssertion & ReasonJEE Main 2023
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Amongst He, Ne, Ar and Kr; 1 g of activated charcoal adsorbs more of Kr. Reason R: The critical volume VcV_cVc​ (cm3 mol−1\text{cm}^3\,\text{mol}^{-1}cm3mol−1) and critical pressure PcP_cPc​ (atm) is highest for Krypton but the compressibility factor at critical point ZcZ_cZc​ is lowest for Krypton. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is true but R is false
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)A is false but R is true
  4. (D)Both A and R are true but R is NOT the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q115·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: Chlorine can easily combine with oxygen to form oxides; and the product has a tendency to explode. Statement II: Chemical reactivity of an element can be determined by its reaction with oxygen and halogens. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both the Statements I and II are true
  2. (B)Both the Statements I and II are false
  3. (C)Statement I is false but Statement II is true
  4. (D)Statement I is true but Statement II is false

Correct answer: (A)

Step-by-step solution →
Q116·ChemistrySingle correctJEE Main 2023
O−OO-OO−O bond length in H2O2H_2O_2H2​O2​ is X‾\underline{X}X​ than the O−OO-OO−O bond length in F2O2F_2O_2F2​O2​. The O−HO-HO−H bond length in H2O2H_2O_2H2​O2​ is Y‾\underline{Y}Y​ than the O−FO-FO−F bond in F2O2F_2O_2F2​O2​. Choose the correct option for X and Y from those given below
  1. (A)X-shorter, Y-longer
  2. (B)X-shorter, Y-shorter
  3. (C)X-longer, Y-shorter
  4. (D)X-longer, Y-longer

Correct answer: (C)

Step-by-step solution →
Q117·ChemistrySingle correctJEE Main 2023
The correct order of bond enthalpy (kJmol−1^{-1}−1) is:
  1. (A)C−C>Si−Si>Sn−Sn>Ge−GeC-C>Si-Si>Sn-Sn>Ge-GeC−C>Si−Si>Sn−Sn>Ge−Ge
  2. (B)C−C>Si−Si>Ge−Ge>Sn−SnC-C>Si-Si>Ge-Ge>Sn-SnC−C>Si−Si>Ge−Ge>Sn−Sn
  3. (C)Si−Si>C−C>Sn−Sn>Ge−GeSi-Si>C-C>Sn-Sn>Ge-GeSi−Si>C−C>Sn−Sn>Ge−Ge
  4. (D)Si−Si>C−C>Ge−Ge>Sn−SnSi-Si>C-C>Ge-Ge>Sn-SnSi−Si>C−C>Ge−Ge>Sn−Sn

Correct answer: (B)

Step-by-step solution →
Q118·ChemistrySingle correctJEE Main 2023
The Lewis acid character of boron tri halides follows the order:
  1. (A)BI3>BBr3>BCl3>BF3BI_3>BBr_3>BCl_3>BF_3BI3​>BBr3​>BCl3​>BF3​
  2. (B)BBr3>BI3>BCl3>BF3BBr_3>BI_3>BCl_3>BF_3BBr3​>BI3​>BCl3​>BF3​
  3. (C)BCl3>BF3>BBr3>BI3BCl_3>BF_3>BBr_3>BI_3BCl3​>BF3​>BBr3​>BI3​
  4. (D)BF3>BCl3>BBr3>BI3BF_3>BCl_3>BBr_3>BI_3BF3​>BCl3​>BBr3​>BI3​

Correct answer: (A)

Step-by-step solution →
Q119·ChemistrySingle correctJEE Main 2023
Identify X, Y and Z in the following reaction. (Equation not balanced) ClO+NO2→X→H2OY+ZClO + NO_2 \rightarrow X \xrightarrow{H_2O} Y + ZClO+NO2​→XH2​O​Y+Z
  1. (A)X = ClONO2ClONO_2ClONO2​, Y = HOCl, Z = HNO3HNO_3HNO3​
  2. (B)X = ClONO2ClONO_2ClONO2​, Y = HOCl, Z = NO2NO_2NO2​
  3. (C)X = ClNO2ClNO_2ClNO2​, Y = HCl, Z = HNO3HNO_3HNO3​
  4. (D)X = ClNO3ClNO_3ClNO3​, Y = Cl2Cl_2Cl2​, Z = NO2NO_2NO2​

Correct answer: (A)

Step-by-step solution →
Q120·ChemistryNumericalJEE Main 2023
The oxidation state of phosphorus in hypophosphoric acid is +++ ___ .

Correct answer: 4

Step-by-step solution →
Q121·ChemistrySingle correctJEE Main 2023
The correct increasing order of the ionic radii is
  1. (A)S2−<Cl−<Ca2+<K+S^{2-} < Cl^- < Ca^{2+} < K^+S2−<Cl−<Ca2+<K+
  2. (B)K+<S2−<Ca2+<Cl−K^+ < S^{2-} < Ca^{2+} < Cl^-K+<S2−<Ca2+<Cl−
  3. (C)Ca2+<K+<Cl−<S2−Ca^{2+} < K^+ < Cl^- < S^{2-}Ca2+<K+<Cl−<S2−
  4. (D)Cl−<Ca2+<K+<S2−Cl^- < Ca^{2+} < K^+ < S^{2-}Cl−<Ca2+<K+<S2−

Correct answer: (C)

Step-by-step solution →
Q122·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green. Statement II: The green colour observed is due to the formation of copper(I) metaborate. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Statement I is true but Statement II is false
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are false

Correct answer: (D)

Step-by-step solution →
Q123·ChemistrySingle correctJEE Main 2023
Boric acid is solid, whereas BF3BF_3BF3​ is gas at room temperature because of:
  1. (A)Strong van der Waal's interaction in Boric acid
  2. (B)Strong covalent bond in BF3BF_3BF3​
  3. (C)Strong ionic bond in Boric acid
  4. (D)Strong hydrogen bond in Boric acid

Correct answer: (D)

Step-by-step solution →
Q124·ChemistrySingle correctJEE Main 2023
The bond dissociation energy of the "E-H" bond of the "H2EH_2EH2​E" hydrides of group 16 elements (A. O, B. S, C. Se, D. Te) follows the order. Choose the correct one from the options given below:
  1. (A)B>A>C>DB>A>C>DB>A>C>D
  2. (B)A>B>D>CA>B>D>CA>B>D>C
  3. (C)A>B>C>DA>B>C>DA>B>C>D
  4. (D)D>C>B>AD>C>B>AD>C>B>A

Correct answer: (C)

Step-by-step solution →
Q125·ChemistryNumericalJEE Main 2023
Total number of acidic oxides among N2O3, NO2, N2O, Cl2O7, SO2, CO, CaO, Na2ON_2O_3,\,NO_2,\,N_2O,\,Cl_2O_7,\,SO_2,\,CO,\,CaO,\,Na_2ON2​O3​,NO2​,N2​O,Cl2​O7​,SO2​,CO,CaO,Na2​O and NONONO is _____.

Correct answer: 4

Step-by-step solution →
Q126·ChemistrySingle correctJEE Main 2023
"A" obtained by Ostwald's method involving air oxidation of NH3_33​, upon further air oxidation produces "B". "B" on hydration forms an oxoacid of Nitrogen along with evolution of "A". The oxoacid also produces "A" and gives positive brown ring test. Identify A and B, respectively.
  1. (A)N2_22​O3_33​, NO2_22​
  2. (B)NO2_22​, N2_22​O4_44​
  3. (C)NO2_22​, N2_22​O5_55​
  4. (D)NO, NO2_22​

Correct answer: (D)

Step-by-step solution →
Q127·ChemistrySingle correctJEE Main 2023
The bond dissociation energy is highest for:
  1. (A)F2_22​
  2. (B)Br2_22​
  3. (C)I2_22​
  4. (D)Cl2_22​

Correct answer: (D)

Step-by-step solution →
Q128·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: The decrease in first ionization enthalpy from B to Al is much larger than that from Al to Ga. Statement II: The d orbitals in Ga are completely filled. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but statement II is correct
  2. (B)Both the statements I and II are correct
  3. (C)Both the statements I and II are incorrect
  4. (D)Statement I is correct but statement II is incorrect

Correct answer: (A)

Step-by-step solution →
Q129·ChemistrySingle correctJEE Main 2023
Inert gases have positive electron gain enthalpy. Its correct order is:
  1. (A)He<Kr<Xe<NeHe < Kr < Xe < NeHe<Kr<Xe<Ne
  2. (B)He<Xe<Kr<NeHe < Xe < Kr < NeHe<Xe<Kr<Ne
  3. (C)He<Ne<Kr<XeHe < Ne < Kr < XeHe<Ne<Kr<Xe
  4. (D)Xe<Kr<Ne<HeXe < Kr < Ne < HeXe<Kr<Ne<He

Correct answer: (B)

Step-by-step solution →
Q130·ChemistrySingle correctJEE Main 2023
Which of the following represents the correct order of metallic character of the given elements ?
  1. (A)Si<Be<Mg<KSi < Be < Mg < KSi<Be<Mg<K
  2. (B)Be<Si<K<MgBe < Si < K < MgBe<Si<K<Mg
  3. (C)Be<Si<Mg<KBe < Si < Mg < KBe<Si<Mg<K
  4. (D)K<Mg<Be<SiK < Mg < Be < SiK<Mg<Be<Si

Correct answer: (A)

Step-by-step solution →
Q131·ChemistrySingle correctJEE Main 2023
Reaction of thionyl chloride with white phosphorus forms a compound [A], which on hydrolysis gives [B], a dibasic acid. [A] and [B] are respectively:
  1. (A)P4O6P_4O_6P4​O6​ and H3PO3H_3PO_3H3​PO3​
  2. (B)PCl3PCl_3PCl3​ and H3PO4H_3PO_4H3​PO4​
  3. (C)POCl3POCl_3POCl3​ and H3PO4H_3PO_4H3​PO4​
  4. (D)PCl3PCl_3PCl3​ and H3PO3H_3PO_3H3​PO3​

Correct answer: (D)

Step-by-step solution →
Q132·ChemistrySingle correctJEE Main 2023
Match List I with List II (industrial processes/catalysts and their applications) and choose the correct answer from the options given below.
LIST ILIST II
A.Cobalt catalystI.(H2+Cl2)(H_2 + Cl_2)(H2​+Cl2​) production
B.SyngasII.Water gas production
C.Nickel catalystIII.Coal gasification
D.Brine solutionIV.Methanol production
  1. (A)A-IV, B-I, C-II, D-III
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-II, B-III, C-IV, D-I
  4. (D)A-IV, B-III, C-I, D-II

Correct answer: (B)

Step-by-step solution →
Q133·ChemistrySingle correctJEE Main 2023
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Carbon forms two important oxides - CO and CO2CO_2CO2​. CO is neutral whereas CO2CO_2CO2​ is acidic in nature. Reason R : CO2CO_2CO2​ can combine with water in a limited way to form carbonic acid, while CO is sparingly soluble in water. In the light of the above statements, choose the most appropriate answer from the options given below
  1. (A)Both A and R are correct but R is NOT the correct explanation of A
  2. (B)A is correct but R is not correct
  3. (C)Both A and R are correct and R is the correct explanation of A
  4. (D)A is not correct but R is correct

Correct answer: (C)

Step-by-step solution →
Q134·ChemistryNumericalJEE Main 2023
Sum of π\piπ-bonds present in peroxodisulphuric acid and pyrosulphuric acid is:

Correct answer: 8

Step-by-step solution →
Q135·ChemistrySingle correctJEE Main 2023
Which of the Phosphorus oxoacid can create silver mirror from AgNO3\text{AgNO}_3AgNO3​ solution?
  1. (A)(HPO3)n(\text{HPO}_3)_n(HPO3​)n​
  2. (B)H4P2O6\text{H}_4\text{P}_2\text{O}_6H4​P2​O6​
  3. (C)H4P2O5\text{H}_4\text{P}_2\text{O}_5H4​P2​O5​
  4. (D)H4P2O7\text{H}_4\text{P}_2\text{O}_7H4​P2​O7​

Correct answer: (C)

Step-by-step solution →
Q136·ChemistryIntegerJEE Advanced 2022
The reaction of Xe and O2F2\mathrm{O_2F_2}O2​F2​ gives a Xe compound P\mathbf{P}P. The number of moles of HF produced by the complete hydrolysis of 1 mol of P\mathbf{P}P is____.

Correct answer: 2

Step-by-step solution →
Q137·ChemistryMultiple correctJEE Advanced 2022
The compound(s) which react(s) with NH3\mathrm{NH_3}NH3​ to give boron nitride (BN) is(are)
  1. (A)B
  2. (B)B2H6\mathrm{B_2H_6}B2​H6​
  3. (C)B2O3\mathrm{B_2O_3}B2​O3​
  4. (D)HBF4\mathrm{HBF_4}HBF4​

Correct answer: (B), (C) or (A), (B), (C)

Step-by-step solution →
Q138·ChemistrySingle correctJEE Advanced 2022
The reaction of Pb(NO3)2\mathrm{Pb\left(NO_3\right)_2}Pb(NO3​)2​ and NaCl in water produces a precipitate that dissolves upon the addition of HCl of appropriate concentration. The dissolution of the precipitate is due to the formation of
  1. (A)PbCl2\mathrm{PbCl_2}PbCl2​
  2. (B)PbCl4\mathrm{PbCl_4}PbCl4​
  3. (C)[PbCl4]2−\left[\mathrm{PbCl_4}\right]^{2-}[PbCl4​]2−
  4. (D)[PbCl6]2−\left[\mathrm{PbCl_6}\right]^{2-}[PbCl6​]2−

Correct answer: (C)

Step-by-step solution →
Q139·ChemistryMultiple correctJEE Advanced 2022
The treatment of galena with HNO3\mathrm{HNO_3}HNO3​ produces a gas that is
  1. (A)paramagnetic
  2. (B)bent in geometry
  3. (C)an acidic oxide
  4. (D)colorless

Correct answer: (A), (D)

Step-by-step solution →
Q140·ChemistryNumericalJEE Advanced 2022
Dissolving 1.24 g of white phosphorous in boiling NaOH solution in an inert atmosphere gives a gas Q\mathbf{Q}Q. The amount of CuSO4\mathrm{CuSO_4}CuSO4​ (in g) required to completely consume the gas Q\mathbf{Q}Q is ________. [Given: Atomic mass of H = 1, O = 16, Na = 23, P = 31, S = 32, Cu = 63]

Correct answer: 2.38

Step-by-step solution →
Q141·ChemistrySingle correctJEE Advanced 2022
The reaction of HClO3\mathrm{HClO_3}HClO3​ with HCl gives a paramagnetic gas, which upon reaction with O3\mathrm{O_3}O3​ produces
  1. (A)Cl2O\mathrm{Cl_2O}Cl2​O
  2. (B)ClO2\mathrm{ClO_2}ClO2​
  3. (C)Cl2O6\mathrm{Cl_2O_6}Cl2​O6​
  4. (D)Cl2O7\mathrm{Cl_2O_7}Cl2​O7​

Correct answer: (C)

Step-by-step solution →
Q142·ChemistrySingle correctJEE Main 2022
When borax is heated with CoO on a platinum loop, blue coloured bead formed is largely due to :
  1. (A)B2_{2}2​O3_{3}3​
  2. (B)Co(BO2_{2}2​)2_{2}2​
  3. (C)CoB4_{4}4​O7_{7}7​
  4. (D)Co[B4_{4}4​O5_{5}5​(OH)4_{4}4​]

Correct answer: (B)

Step-by-step solution →
Q143·ChemistryNumericalJEE Main 2022
Consider the following sulphure based oxoacids. H2_{2}2​SO3_{3}3​, H2_{2}2​SO4_{4}4​, H2_{2}2​S2_{2}2​O8_{8}8​ and H2_{2}2​S2_{2}2​O7_{7}7​. Amongst these oxoacids, the number of those with peroxo(O-O) bond is______.

Correct answer: 1

Step-by-step solution →
Q144·ChemistryNumericalJEE Main 2022
The number of interhalogens from the following having square pyramidal structure is : ClF3_33​, IF7_77​, BrF5_55​, BrF3_33​, I2_22​Cl6_66​, IF5_55​, ClF, ClF5_55​

Correct answer: 3

Step-by-step solution →
Q145·ChemistrySingle correctJEE Main 2022
Dinitrogen and dioxygen. the main constituents of air do not react with each other in atmosphere to form oxides of nitrogen because
  1. (A)N2\mathrm{N_2}N2​ is unreactive in the condition of atmosphere.
  2. (B)Oxides of nitrogen are unstable.
  3. (C)Reaction between them can occur in the presence of a catalyst.
  4. (D)The reaction is endothermic and require very high temperature.

Correct answer: (D)

Step-by-step solution →
Q146·ChemistrySingle correctJEE Main 2022
Match List-I with List-II, match the gas evolved during each reaction. Choose the correct answer from the options given below :
List-IList-II
A.(NH4_44​)2_22​Cr2_22​O7_77​ →Δ\xrightarrow{\Delta}Δ​I.H2_22​
B.KMnO4_44​ + HCl →II.N2_22​
C.Al + NaOH + H2_22​O →III.O2_22​
D.NaNO3_33​ →Δ\xrightarrow{\Delta}Δ​IV.Cl2_22​
  1. (A)(A) – (II), (B) – (III), (C) – (I), (D) – (IV)
  2. (B)(A) – (III), (B) – (I), (C) – (IV), (D) – (II)
  3. (C)(A) – (II), (B) – (IV), (C) – (I), (D) – (III)
  4. (D)(A) – (III), (B) – (IV), (C) – (I), (D) – (II)

Correct answer: (C)

Step-by-step solution →
Q147·ChemistrySingle correctJEE Main 2022
Concentrated HNO3\mathrm{HNO_3}HNO3​ reacts with Iodine to give
  1. (A)HI\mathrm{HI}HI, NO2\mathrm{NO_2}NO2​ and H2O\mathrm{H_2O}H2​O
  2. (B)HIO2\mathrm{HIO_2}HIO2​, N2O\mathrm{N_2O}N2​O and H2O\mathrm{H_2O}H2​O
  3. (C)HIO3\mathrm{HIO_3}HIO3​, NO2\mathrm{NO_2}NO2​ and H2O\mathrm{H_2O}H2​O
  4. (D)HIO4\mathrm{HIO_4}HIO4​, N2O\mathrm{N_2O}N2​O and H2O\mathrm{H_2O}H2​O

Correct answer: (C)

Step-by-step solution →
Q148·ChemistrySingle correctJEE Main 2022
White phosphorus reacts with thionyl chloride to give
  1. (A)PCl5\mathrm{PCl_5}PCl5​, SO2\mathrm{SO_2}SO2​ and S2Cl2\mathrm{S_2Cl_2}S2​Cl2​
  2. (B)PCl3\mathrm{PCl_3}PCl3​. SO2\mathrm{SO_2}SO2​ and S2Cl2\mathrm{S_2Cl_2}S2​Cl2​
  3. (C)PCl3\mathrm{PCl_3}PCl3​, SO2\mathrm{SO_2}SO2​ and Cl2\mathrm{Cl_2}Cl2​
  4. (D)PCl5\mathrm{PCl_5}PCl5​, SO2\mathrm{SO_2}SO2​ and Cl2\mathrm{Cl_2}Cl2​

Correct answer: (B)

Step-by-step solution →
Q149·ChemistrySingle correctJEE Main 2022
Which oxoacid of phosphorous has the highest number of oxygen atoms present in its chemical formula?
  1. (A)Pyrophosphorous acid
  2. (B)Hypophosphoric acid
  3. (C)Phosphoric acid
  4. (D)Pyrophosphoric acid

Correct answer: (D)

Step-by-step solution →
Q150·ChemistrySingle correctJEE Main 2022
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R) Assertion (A) : Boron is unable to form BF63−_{6}^{3-}63−​ Reason (R) : Size of B is very small. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. (B)Both (A) and (R) are true but (R) is not the correct explanation of (A)
  3. (C)(A) is true but (R) is false
  4. (D)(A) is false but (R) is true

Correct answer: (B)

Step-by-step solution →
Q151·ChemistrySingle correctJEE Main 2022
The metal that has very low melting point and its periodic position is closer to a metalloid is :
  1. (A)Al
  2. (B)Ga
  3. (C)Se
  4. (D)In

Correct answer: (B)

Step-by-step solution →
Q152·ChemistrySingle correctJEE Main 2022
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Boric acid is a weak acid Reason R : Boric acid is not able to release H+H^{+}H+ ion on its own. It receives OH−OH^{-}OH− ion from water and releases H+H^{+}H+ ion. In the light of the above statements, choose the most appropriate answer from the options given below.
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)Both A and R are correct but R is NOT the correct explanation of A
  3. (C)A is correct but R is not correct
  4. (D)A is not correct but R is correct

Correct answer: (A)

Step-by-step solution →
Q153·ChemistrySingle correctJEE Main 2022
Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of "X" with 6-equivalents of "Y". "X" and "Y", respectively are :
  1. (A)B(OH)3_33​ and NH3_33​
  2. (B)B2_22​H6_66​ and NH3_33​
  3. (C)B2_22​H6_66​ and HN3_33​
  4. (D)NH3_33​ and B2_22​O3_33​

Correct answer: (B)

Step-by-step solution →
Q154·ChemistryNumericalJEE Main 2022
The number of non-ionisable protons present in the product B obtained from the following reaction is ______. C2H5OHC_{2}H_{5}OHC2​H5​OH + PCl3PCl_{3}PCl3​ → C2H5ClC_{2}H_{5}ClC2​H5​Cl + A A + PCl3PCl_{3}PCl3​ → B

Correct answer: 2

Step-by-step solution →
Q155·ChemistrySingle correctJEE Main 2022
The geometry around boron in the product 'B' formed from the following reaction is BF3+NaH→450KA+NaFBF_{3} + NaH \xrightarrow{450K} A + NaFBF3​+NaH450K​A+NaF A+NMe3→BA + NMe_{3} \rightarrow BA+NMe3​→B
  1. (A)trigonal planar
  2. (B)tetrahedral
  3. (C)pyramidal
  4. (D)square planar

Correct answer: (B)

Step-by-step solution →
Q156·ChemistrySingle correctJEE Main 2022
The interhalogen compound formed from the reaction of bromine with excess of fluorine is a :
  1. (A)hypohalite
  2. (B)halate
  3. (C)perhalate
  4. (D)halite

Correct answer: (B)

Step-by-step solution →
Q157·ChemistrySingle correctJEE Main 2022
The oxoacid of phosphorus that is easily obtained from a reaction of alkali and white phosphorus and has two P-H bonds, is :
  1. (A)Phosphonic acid
  2. (B)Phosphinic acid
  3. (C)Pyrophosphorus acid
  4. (D)Hypophosphoric acid

Correct answer: (B)

Step-by-step solution →
Q158·ChemistrySingle correctJEE Main 2022
Match the List-I with List- II. Choose the most appropriate answer from the option given below:
List-I (Metal)List-II Application
A.CsI.High temperature thermometer
B.GaII.Water repellent sprays
C.BIII.Photoelectric cells
D.SiIV.Bullet proof vest
  1. (A)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. (B)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  3. (C)(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  4. (D)(A)-(I), (B)-(IV), (C)-(II), (D)-(III)

Correct answer: (A)

Step-by-step solution →
Q159·ChemistrySingle correctJEE Main 2022
Aqueous solution of which of the following boron compounds will be strongly basic in nature?
  1. (A)NaBH4_44​
  2. (B)LiBH4_44​
  3. (C)B2_22​H6_66​
  4. (D)Na2_22​B4_44​O7_77​

Correct answer: (D)

Step-by-step solution →
Q160·ChemistrySingle correctJEE Main 2022
Which of the following oxoacids of sulphur contains “S” in two different oxidation states?
  1. (A)H2_22​S2_22​O3_33​
  2. (B)H2_22​S2_22​O6_66​
  3. (C)H2_22​S2_22​O7_77​
  4. (D)H2_22​S2_22​O8_88​

Correct answer: (A)

Step-by-step solution →
Q161·ChemistrySingle correctJEE Main 2022
Given below are two statements : Statement -I :The pentavalent oxide of group- 15 element. E2O5E_2O_5E2​O5​. is less acidic than trivalent oxide. E2O3E_2O_3E2​O3​. of the same element. Statement -II :The acidic character of trivalent oxide of group 15 elements. E2O3E_2O_3E2​O3​. decreases down the group. In light of the above statements. choose most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are true.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I true. but statement II is false.
  4. (D)Statement I is false but statement II is true.

Correct answer: (D)

Step-by-step solution →
Q162·ChemistrySingle correctJEE Main 2022
Among the given oxides of nitrogen; N2_22​O, N2_22​O3_33​, N2_22​O4_44​ and N2_22​O5_55​, the number of compound/(s) having N–N bond is :
  1. (A)1
  2. (B)2
  3. (C)3
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q163·ChemistrySingle correctJEE Main 2022
Nitrogen gas is obtained by thermal decomposition of
  1. (A)Ba(NO3)2Ba(NO_3)_2Ba(NO3​)2​
  2. (B)Ba(N3)2Ba(N_3)_2Ba(N3​)2​
  3. (C)NaNO2NaNO_2NaNO2​
  4. (D)NaNO3NaNO_3NaNO3​

Correct answer: (B)

Step-by-step solution →
Q164·ChemistrySingle correctJEE Main 2022
Heating white phosphorus with conc. NaOH solution gives mainly
  1. (A)Na3PNa_{3}PNa3​P and H2OH_{2}OH2​O
  2. (B)H3POH_{3}POH3​PO and NaH
  3. (C)P(OH)3P(OH)_{3}P(OH)3​ and NaH2PO4NaH_{2}PO_{4}NaH2​PO4​
  4. (D)PH3PH_{3}PH3​ and NaH2PO2NaH_{2}PO_{2}NaH2​PO2​

Correct answer: (D)

Step-by-step solution →
Q165·ChemistrySingle correctJEE Main 2022
Match List-I with List-II List-I (Si-Compounds) (A) (CH3)4Si(CH_{3})_{4}Si(CH3​)4​Si (B) (CH3)Si(OH)3(CH_{3})Si(OH)_{3}(CH3​)Si(OH)3​ (C) (CH3)2Si(OH)2(CH_{3})_{2}Si(OH)_{2}(CH3​)2​Si(OH)2​ (D) (CH3)3Si(OH)(CH_{3})_{3}Si(OH)(CH3​)3​Si(OH) List-II (Si-Polymeric/other products) (I) Chain silicone (II) Dimeric silicone (III) Silane (IV) 2D – Silicone Choose the correct answer from the options given below:
  1. (A)(A) – (III), (B) – (II), (C) – (I), (D) – (IV)
  2. (B)(A) – (IV), (B) – (I), (C) – (II), (D) – (III)
  3. (C)(A) – (II), (B) – (I), (C) – (IV), (D) – (III)
  4. (D)(A) – (III), (B) – (IV), (C) – (I), (D) – (II)

Correct answer: (D)

Step-by-step solution →
Q166·ChemistrySingle correctJEE Main 2022
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Flourine forms one oxoacid. Reason R : Flourine has smallest size amongst all halogens and is highly electronegative In the light of the above statements, choose the most appropriate answer from the options given below.
  1. (A)Both A and R are correct and R is the correct explanation of A.
  2. (B)Both A and R are correct but R is NOT the correct explanation of A.
  3. (C)A is correct but R is not correct.
  4. (D)A is not correct but R is correct

Correct answer: (A)

Step-by-step solution →
Q167·ChemistrySingle correctJEE Main 2022
The gas produced by treating an aqueous solution of ammonium chloride with sodium nitrite is
  1. (A)NH3_33​
  2. (B)N2_22​
  3. (C)N2_22​O
  4. (D)Cl2_22​

Correct answer: (B)

Step-by-step solution →
Q168·ChemistrySingle correctJEE Main 2022
Consider the following reaction : A + alkali → B (Major Product) If B is an oxoacid of phosphorus with no P–H bond, then A is :
  1. (A)White P4P_{4}P4​
  2. (B)Red P4P_{4}P4​
  3. (C)P2O3P_{2}O_{3}P2​O3​
  4. (D)H3PO3H_{3}PO_{3}H3​PO3​

Correct answer: (B)

Step-by-step solution →
Q169·ChemistrySingle correctJEE Main 2022
Choose the correct stability order of group 13 elements in their +1 oxidation state.
  1. (A)Al < Ga < In < Tl
  2. (B)Tl < In < Ga < Al
  3. (C)Al < Ga < Tl < In
  4. (D)Al < Tl < Ga < In

Correct answer: (A)

Step-by-step solution →
Q170·ChemistrySingle correctJEE Main 2022
The correct order of melting points of hydrides of group 16 elements is :
  1. (A)H2S<H2Se<H2Te<H2OH_{2}S < H_{2}Se < H_{2}Te < H_{2}OH2​S<H2​Se<H2​Te<H2​O
  2. (B)H2O<H2S<H2Se<H2TeH_{2}O < H_{2}S < H_{2}Se < H_{2}TeH2​O<H2​S<H2​Se<H2​Te
  3. (C)H2S<H2Te<H2Se<H2OH_{2}S < H_{2}Te < H_{2}Se < H_{2}OH2​S<H2​Te<H2​Se<H2​O
  4. (D)H2Se<H2S<H2Te<H2OH_{2}Se < H_{2}S < H_{2}Te < H_{2}OH2​Se<H2​S<H2​Te<H2​O

Correct answer: (A)

Step-by-step solution →
Q171·ChemistrySingle correctJEE Main 2022
The oxide which contains an odd electron at the nitrogen atom is
  1. (A)N2ON_2ON2​O
  2. (B)NO2NO_2NO2​
  3. (C)N2O3N_2O_3N2​O3​
  4. (D)N2O5N_2O_5N2​O5​

Correct answer: (B)

Step-by-step solution →
Q172·ChemistrySingle correctJEE Main 2022
The number of bridged oxygen atoms present in compound B formed from the following reactions is Pb(NO3_33​)2_22​ →673 K\xrightarrow{673\ K}673 K​ A + PbO + O2_22​ A →Dimerise\xrightarrow{Dimerise}Dimerise​ B
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q173·ChemistryNumericalJEE Main 2022
Consider the following reactions : PCl3_33​ + H2_22​O ⟶\longrightarrow⟶ A + HCl A + H2_22​O ⟶\longrightarrow⟶ B + HCl number of ionisable protons present in the product B_________.

Correct answer: 2

Step-by-step solution →
Q174·ChemistrySingle correctJEE Main 2022
PCl5_55​ is well known. but NCl5_55​ is not. Because.
  1. (A)nitrogen is less reactive than phosphorous.
  2. (B)nitrogen doesn't have d-orbitals in its valence shell.
  3. (C)catenation tendency is weaker in nitrogen than phosphorous.
  4. (D)size of phosphorous is larger than nitrogen.

Correct answer: (B)

Step-by-step solution →
Q175·ChemistrySingle correctJEE Main 2022
Which one of the following elemental forms is not present in the enamel of the teeth?
  1. (A)Ca2+^{2+}2+
  2. (B)P3+^{3+}3+
  3. (C)F−^-−
  4. (D)P5+^{5+}5+

Correct answer: (B)

Step-by-step solution →
Q176·ChemistrySingle correctJEE Main 2022
The most stable trihalide of nitrogen is:
  1. (A)NF3_33​
  2. (B)NCl3_33​
  3. (C)NBr3_33​
  4. (D)NI3_33​

Correct answer: (A)

Step-by-step solution →
Q177·ChemistrySingle correctJEE Main 2022
Identify the correct statement for B2_22​H6_66​ from those given below. (A) In B2_22​H6_66​, all B-H bonds are equivalent. (B) In B2_22​H6_66​ there are four 3-centre-2-electron bonds. (C) B2_22​H6_66​ is a Lewis acid. (D) B2_22​H6_66​ can be synthesized form both BF3_33​ and NaBH4_44​. (E) B2_22​H6_66​ is a planar molecule. Choose the most appropriate answer from the options given below :
  1. (A)(A) and (E) only
  2. (B)(B), (C) and (E) only
  3. (C)(C) and (D) only
  4. (D)(C) and (E) only

Correct answer: (C)

Step-by-step solution →
Q178·ChemistryIntegerJEE Advanced 2021
Ozonolysis of ClO2_{2}2​ produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is ___.

Correct answer: 6

Step-by-step solution →
Q179·ChemistryMultiple correctJEE Advanced 2021
The correct statement(s) related to oxoacids of phosphorous is(are)
  1. (A)Upon heating, H3_{3}3​PO3_{3}3​ undergoes disproportionation reaction to produce H3_{3}3​PO4_{4}4​ and PH3_{3}3​.
  2. (B)While H3_{3}3​PO3_{3}3​ can act as reducing agent, H3_{3}3​PO4_{4}4​ cannot.
  3. (C)H3_{3}3​PO3_{3}3​ is a monobasic acid.
  4. (D)The H atom of P–H bond in H3_{3}3​PO3_{3}3​ is not ionizable in water.

Correct answer: (A), (B), (D)

Step-by-step solution →
Q180·ChemistrySingle correctJEE Main 2021
The oxide without nitrogen-nitrogen bond is :
  1. (A)N2_{2}2​O
  2. (B)N2_{2}2​O4_{4}4​
  3. (C)N2_{2}2​O3_{3}3​
  4. (D)N2_{2}2​O5_{5}5​

Correct answer: (D)

Step-by-step solution →
Q181·ChemistryNumericalJEE Main 2021
The number of halogen/(s) forming halic (V) acid is ______.

Correct answer: 3

Step-by-step solution →
Q182·ChemistrySingle correctJEE Main 2021
Which one of the following correctly represents the order of stability of oxides, X2O\mathrm{X_2O}X2​O; (X = halogen) ?
  1. (A)Br > Cl > I
  2. (B)Br > I > Cl
  3. (C)Cl > I > Br
  4. (D)I > Cl > Br

Correct answer: (D)

Step-by-step solution →
Q183·ChemistrySingle correctJEE Main 2021
The number of S=O\mathrm{S=O}S=O bonds present in sulphurous acid, peroxodisulphuric acid and pyrosulphuric acid, respectively are :
  1. (A)2, 3 and 4
  2. (B)1, 4 and 3
  3. (C)2, 4 and 3
  4. (D)1, 4 and 4

Correct answer: (D)

Step-by-step solution →
Q184·ChemistrySingle correctJEE Main 2021
Which one of the following is used to remove most of plutonium from spent nuclear fuel?
  1. (A)ClF3_{3}3​
  2. (B)O2_{2}2​F2_{2}2​
  3. (C)I2_{2}2​O5_{5}5​
  4. (D)BrO3_{3}3​

Correct answer: (B)

Step-by-step solution →
Q185·ChemistrySingle correctJEE Main 2021
Match List-I with List-II : List-I (Species) List-II (Number of lone pairs of electrons on the central atom) (a) XeF2\mathrm{XeF_2}XeF2​ (b) XeO2F2\mathrm{XeO_2F_2}XeO2​F2​ (c) XeO3F2\mathrm{XeO_3F_2}XeO3​F2​ (d) XeF4\mathrm{XeF_4}XeF4​ (i) 0 (ii) 1 (iii) 2 (iv) 3 Choose the most appropriate answer from the options given below :
  1. (A)(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
  2. (B)(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
  3. (C)(a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)
  4. (D)(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

Correct answer: (D)

Step-by-step solution →
Q186·ChemistrySingle correctJEE Main 2021
In which one of the following molecules strongest back donation of an electron pair from halide to boron is expected?
  1. (A)BCl3\mathrm{BCl_3}BCl3​
  2. (B)BF3\mathrm{BF_3}BF3​
  3. (C)BBr3\mathrm{BBr_3}BBr3​
  4. (D)BI3\mathrm{BI_3}BI3​

Correct answer: (B)

Step-by-step solution →
Q187·ChemistrySingle correctJEE Main 2021
Which one of the following is formed (mainly) when red phosphorus is heated in a sealed tube at 803 K ?
  1. (A)White phosphorus
  2. (B)Yellow phosphorus
  3. (C)β-Black phosphorus
  4. (D)α-Black phosphorus

Correct answer: (D)

Step-by-step solution →
Q188·ChemistrySingle correctJEE Main 2021
The incorrect statement is:
  1. (A)Cl2\mathrm{Cl_2}Cl2​ is more reactive than ClF.
  2. (B)F2\mathrm{F_2}F2​ is more reactive than ClF.
  3. (C)On hydrolysis ClF froms HOCl and HF.
  4. (D)F2\mathrm{F_2}F2​ is a stronger oxidizing agent than Cl2\mathrm{Cl_2}Cl2​ in aqueous solution

Correct answer: (A)

Step-by-step solution →
Q189·ChemistrySingle correctJEE Main 2021
The number of non-ionisable hydrogen atoms present in the final product obtained from the hydrolysis of PCl5\mathrm{PCl_5}PCl5​ is :
  1. (A)0
  2. (B)2
  3. (C)1
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q190·ChemistrySingle correctJEE Main 2021
The conversion of hydroxyapatite occurs due to presence of F−\mathrm{F^-}F− ions in water. The correct formula of hydroxyapatite is:
  1. (A)[3Ca3(PO4)2⋅Ca(OH)2][3\mathrm{Ca_3(PO_4)_2} \cdot \mathrm{Ca(OH)_2}][3Ca3​(PO4​)2​⋅Ca(OH)2​]
  2. (B)[3Ca(OH)2⋅CaF2][3\mathrm{Ca(OH)_2} \cdot \mathrm{CaF_2}][3Ca(OH)2​⋅CaF2​]
  3. (C)[Ca3(PO4)2⋅CaF2][\mathrm{Ca_3(PO_4)_2} \cdot \mathrm{CaF_2}][Ca3​(PO4​)2​⋅CaF2​]
  4. (D)[3Ca3(PO4)2⋅CaF2][3\mathrm{Ca_3(PO_4)_2} \cdot \mathrm{CaF_2}][3Ca3​(PO4​)2​⋅CaF2​]

Correct answer: (A)

Step-by-step solution →
Q191·ChemistrySingle correctJEE Main 2021
Chalcogen group elements are :
  1. (A)Se, Tb and Pu.
  2. (B)Se, Te and Po.
  3. (C)S, Te and Pm.
  4. (D)O, Ti and Po.

Correct answer: (B)

Step-by-step solution →
Q192·ChemistrySingle correctJEE Main 2021
Number of Cl=O bonds in chlorous acid, chloric acid and perchloric acid respectively are:
  1. (A)4,1 and 0
  2. (B)1,1 and 3
  3. (C)1,2 and 3
  4. (D)3,1 and 1

Correct answer: (C)

Step-by-step solution →
Q193·ChemistrySingle correctJEE Main 2021
The oxidation states of 'P' in H4P2O7H_4P_2O_7H4​P2​O7​, H4P2O5H_4P_2O_5H4​P2​O5​ and H4P2O6H_4P_2O_6H4​P2​O6​, respectively are:
  1. (A)5,3 and 4
  2. (B)5,4 and 3
  3. (C)6,4 and 5
  4. (D)7,5 and 6

Correct answer: (A)

Step-by-step solution →
Q194·ChemistrySingle correctJEE Main 2021
Which one of the following compounds of Group-14 elements is not known?
  1. (A)[GeCl6]2−[GeCl_6]^{2-}[GeCl6​]2−
  2. (B)[Sn(OH)6]2−[Sn(OH)_6]^{2-}[Sn(OH)6​]2−
  3. (C)[SiF6]2−[SiF_6]^{2-}[SiF6​]2−
  4. (D)[SiCl6]2−[SiCl_6]^{2-}[SiCl6​]2−

Correct answer: (D)

Step-by-step solution →
Q195·ChemistrySingle correctJEE Main 2021
Which one of the following group − 15 hydride is the strongest reducing agent ?
  1. (A)AsH3AsH_{3}AsH3​
  2. (B)SbH3SbH_{3}SbH3​
  3. (C)BiH3BiH_{3}BiH3​
  4. (D)PH3PH_{3}PH3​

Correct answer: (C)

Step-by-step solution →
Q196·ChemistrySingle correctJEE Main 2021
Given below are the statements about diborane. (a) Diborane is prepared by the oxidation of NaBH4NaBH_{4}NaBH4​ With I2I_{2}I2​. (b) Each boron atom is in sp2sp^{2}sp2 hybridized state. (c) Diborane has one bridged 3 centre − 2 − electron bond. (d) Diborane is a planar molecule. The option with correct statement(s) is :
  1. (A)(a) only
  2. (B)(c) only
  3. (C)(a) and (b) only
  4. (D)(c) and (d) only

Correct answer: (A)

Step-by-step solution →
Q197·ChemistrySingle correctJEE Main 2021
Chemical nature of the nitrogen oxide compound obtained from a reaction of concentrated nitric acid and P4O10P_4O_{10}P4​O10​ (in 4:1 ratio) is:
  1. (A)basic
  2. (B)neutral
  3. (C)amphoteric
  4. (D)acidic

Correct answer: (D)

Step-by-step solution →
Q198·ChemistrySingle correctJEE Main 2021
The set in which compounds have different nature is:
  1. (A)B(OH)3B(OH)_{3}B(OH)3​ and Al (OH)3(OH)_{3}(OH)3​
  2. (B)B(OH)3B(OH)_{3}B(OH)3​ and H3PO3H_{3}PO_{3}H3​PO3​
  3. (C)NaOH and Ca(OH)2Ca(OH)_{2}Ca(OH)2​
  4. (D)Be(OH)2Be(OH)_{2}Be(OH)2​ and Al(OH)3Al(OH)_{3}Al(OH)3​

Correct answer: (A)

Step-by-step solution →
Q199·ChemistryNumericalJEE Main 2021
A xenon compound 'A' upon partial hydrolysis gives XeO2_{2}2​F2_{2}2​. The number of lone pair of electrons present in compound A is _______ (Round off to the Nearest integer)

Correct answer: 19

Step-by-step solution →
Q200·ChemistrySingle correctJEE Main 2021
The number of ionisable hydrogens present in the product obtained from a reaction of phosphorus trichloride and phosphonic acid is:
  1. (A)3
  2. (B)0
  3. (C)2
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q201·ChemistryNumericalJEE Main 2021
The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction 1 mol of 'A' with excess of AgNO3\mathrm{AgNO_3}AgNO3​ in aqueous medium gives ________ mol(s) of Ag. (Round off to the Nearest Integer).

Correct answer: 4

Step-by-step solution →
Q202·ChemistrySingle correctJEE Main 2021
The set that represents the pair of neutral oxides of nitrogen is :
  1. (A)NO and N2_{2}2​O
  2. (B)N2_{2}2​O and N2_{2}2​O3_{3}3​
  3. (C)N2_{2}2​O and NO2_{2}2​
  4. (D)NO and NO2_{2}2​

Correct answer: (A)

Step-by-step solution →
Q203·ChemistrySingle correctJEE Main 2021
A group 15 element, which is a metal and forms a hydride with strongest reducing power among group 15 hydrides. The element is :
  1. (A)Sb
  2. (B)P
  3. (C)As
  4. (D)Bi

Correct answer: (D)

Step-by-step solution →
Q204·ChemistrySingle correctJEE Main 2021
Match List-I (Name of oxo acid) with List-II (Oxidation state of 'P') : Choose the correct answer from the options given below :
List-I (Name of oxo acid)List-II (Oxidation state of 'P')
a.Hypophosphorous acidi.+5
b.Orthophosphoric acidii.+4
c.Hypophosphoric acidiii.+3
d.Orthophosphorous acidiv.+2
v.+1
  1. (A)(a)-(v), (b)-(i), (c)-(ii), (d)-(iii)
  2. (B)(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
  3. (C)(a)-(iv), (b)-(v), (c)-(ii), (d)-(iii)
  4. (D)(a)-(v), (b)-(iv), (c)-(ii), (d)-(iii)

Correct answer: (A)

Step-by-step solution →
Q205·ChemistrySingle correctJEE Main 2021
The INCORRECT statement regarding the structure of C60_{60}60​ is :
  1. (A)The six-membered rings are fused to both six and five-membered rings.
  2. (B)Each carbon atom forms three sigma bonds.
  3. (C)The five-membered rings are fused only to six-membered rings.
  4. (D)It contains 12 six-membered rings and 24 five-membered rings.

Correct answer: (D)

Step-by-step solution →
Q206·ChemistrySingle correctJEE Main 2021
Match List-I (Industrial process) with List-II (Application) : Choose the correct answer from the options given below :
List-I (Industrial process)List-II (Application)
a.Haber's processi.HNO3_{3}3​ synthesis
b.Ostwald's processii.Aluminium extraction
c.Contact processiii.NH3_{3}3​ synthesis
d.Hall-Heroult processiv.H2_{2}2​SO4_{4}4​ synthesis
  1. (A)(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
  2. (B)(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
  3. (C)(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
  4. (D)(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

Correct answer: (C)

Step-by-step solution →
Q207·ChemistrySingle correctJEE Main 2021
The exact volumes of 1 M NaOH solution required to neutralise 50 mL of 1 M H3_{3}3​PO3_{3}3​ solution and 100 mL of 2 M H3_{3}3​PO2_{2}2​ solution, respectively, are :
  1. (A)100 mL and 100 mL
  2. (B)100 mL and 50 mL
  3. (C)100 mL and 200 mL
  4. (D)50 mL and 50 mL

Correct answer: (C)

Step-by-step solution →
Q208·ChemistrySingle correctJEE Main 2021
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: In TlI3_33​, isomorphous to CsI3_33​, the metal is present in +1 oxidation state. Reason R: Tl metals has fourteen f electrons in its electronic configuration. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)A is not correct but R is correct
  3. (C)Both A and R are correct R is NOT the correct explanation of A
  4. (D)A is correct but R is not correct

Correct answer: (C)

Step-by-step solution →
Q209·ChemistrySingle correctJEE Main 2021
Which pair of oxides is acidic in nature?
  1. (A)N2_22​O, BaO
  2. (B)CaO, SiO2_22​
  3. (C)B2_22​O3_33​, CaO
  4. (D)B2_22​O3_33​, SiO2_22​

Correct answer: (D)

Step-by-step solution →
Q210·ChemistrySingle correctJEE Main 2021
Compound A used as a strong oxidizing agent is amphoteric in nature. It is the part of lead storage batteries. Compound A is :
  1. (A)Pb3_33​O4_44​
  2. (B)PbO2_22​
  3. (C)PbSO4_44​
  4. (D)PbO

Correct answer: (B)

Step-by-step solution →
Q211·ChemistrySingle correctJEE Main 2021
Given below are two statements : Statement I : α and β forms of sulphur can change reversibly between themselves with slow heating or slow cooling. Statement II : At room temperature the stable crystalline form of sulphur is monoclinic sulphur. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Both statement I and statement II are false
  2. (B)Statement I is true but statement II is false
  3. (C)Both statement I and statement II are true
  4. (D)Statement I is false but statement II is true

Correct answer: (B)

Step-by-step solution →
Q212·ChemistryNumericalJEE Main 2021
Among the following, the number of halide(s) which is/are inert to hydrolysis is _______. (A) BF3_{3}3​ (B) SiCl4_{4}4​ (C) PCl5_{5}5​ (D) SF6_{6}6​

Correct answer: 1

Step-by-step solution →
Q213·ChemistrySingle correctJEE Main 2021
The correct statement about B2_{2}2​H6_{6}6​ is:
  1. (A)All B−H−B angles are of 120°.
  2. (B)Its fragment, BH3_{3}3​, behaves as a Lewis base.
  3. (C)Terminal B−H bonds have less p-character when compared to bridging bonds.
  4. (D)The two B−H−B bonds are not of same length.

Correct answer: (C)

Step-by-step solution →
Q214·ChemistrySingle correctJEE Main 2021
The correct order of bond dissociation enthalpy of halogen is :
  1. (A)F2>Cl2>Br2>I2
  2. (B)Cl2>F2>Br2>I2
  3. (C)Cl2>Br2>F2>I2
  4. (D)I2>Br2>Cl2>F2

Correct answer: (C)

Step-by-step solution →
Q215·ChemistryNumericalJEE Main 2021
Among the following allotropic forms of sulphur, the number of allotropic forms, which will show paramagnetism is _______. (1) α\alphaα-sulphur (2) β\betaβ-sulphur (3) S2S_{2}S2​-form

Correct answer: 1

Step-by-step solution →
Q216·ChemistryMultiple correctJEE Advanced 2020
Choose the correct statement(s) among the following.
  1. (A)SnCl2.2H2OSnCl_{2}.2H_{2}OSnCl2​.2H2​O is a reducing agent.
  2. (B)SnO2SnO_{2}SnO2​ reacts with KOH to form K2[Sn(OH)6]K_{2}[Sn(OH)_{6}]K2​[Sn(OH)6​].
  3. (C)A solution of PbCl2PbCl_{2}PbCl2​ in HCl contains Pb2+Pb^{2+}Pb2+ and Cl−Cl^{-}Cl− ions.
  4. (D)The reaction of Pb3O4Pb_{3}O_{4}Pb3​O4​ with hot dilute nitric acid to give PbO2PbO_{2}PbO2​ is a redox reaction.

Correct answer: (A), (B)

Step-by-step solution →
Q217·ChemistryMultiple correctJEE Advanced 2020
With respect to hypochlorite, chlorate and perchlorate ions, choose the correct statement(s).
  1. (A)The hypochlorite ion is the strongest conjugate base.
  2. (B)The molecular shape of only chlorate ion is influenced by the lone pair of electrons of Cl.
  3. (C)The hypochlorite and chlorate ions disproportionate to give rise to identical set of ions.
  4. (D)The hypochlorite ion oxidizes the sulfite ion.

Correct answer: (A), (B), (D)

Step-by-step solution →
Q218·ChemistrySingle correctJEE Main 2020
The reaction of NO with N2_22​O4_44​ at 250 K gives:
  1. (A)N2_22​O
  2. (B)NO2_22​
  3. (C)N2_22​O3_33​
  4. (D)N2_22​O5_55​

Correct answer: (C)

Step-by-step solution →
Q219·ChemistrySingle correctJEE Main 2020
The correct statement with respect to dinitrogen is:
  1. (A)N2N_2N2​ is paramagnetic in nature
  2. (B)It can combine with dioxygen at 25∘25^\circ25∘ C.
  3. (C)Liquid dinitrogen is not used in cryosurgery
  4. (D)It can be used as an inert diluent for reactive chemicals

Correct answer: (D)

Step-by-step solution →
Q220·ChemistrySingle correctJEE Main 2020
Reaction of an inorganic sulphite X with dilute H2_22​SO4_44​ generates compound Y. Reaction of Y with NaOH gives X. Further, the reaction of X. Further, the reaction of X with Y and water affords compound Z. Y and Z respectively, are:
  1. (A)SO2_22​ and Na2_22​SO3_33​
  2. (B)SO3_33​ and NaHSO3_33​
  3. (C)SO2_22​ and NaHSO3_33​
  4. (D)S and Na2_22​SO3_33​

Correct answer: (C)

Step-by-step solution →
Q221·ChemistrySingle correctJEE Main 2020
On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is:
  1. (A)+4
  2. (B)+3
  3. (C)+2
  4. (D)+5

Correct answer: (B)

Step-by-step solution →
Q222·ChemistryNumericalJEE Main 2020
The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is ______.

Correct answer: 10

Step-by-step solution →
Q223·ChemistrySingle correctJEE Main 2020
If the boiling point of H2_22​O is 373 K, the boiling point of H2_22​S will be:
  1. (A)more than 373 K
  2. (B)less than 300 K
  3. (C)greater than 300 K but less than 373 K
  4. (D)equal to 373 K

Correct answer: (B)

Step-by-step solution →
Q224·ChemistrySingle correctJEE Main 2020
Aqua regia is used for dissolving noble metals (Au, Pt, etc.). The gas evolved in this process is:
  1. (A)NO
  2. (B)N2_22​O3_33​
  3. (C)N2_22​
  4. (D)N2_22​O5_55​

Correct answer: (A)

Step-by-step solution →
Q225·ChemistrySingle correctJEE Main 2020
In a molecule of pyrophosphoric acid, the number of P −-− OH, P === O and P −-− O −-− P bonds/ moiety(ies) respectively are
  1. (A)4, 2 and 1
  2. (B)4, 2 and 0
  3. (C)2, 4 and 1
  4. (D)3, 3 and 3

Correct answer: (A)

Step-by-step solution →
Q226·ChemistrySingle correctJEE Main 2020
The reaction of H3_33​N3_33​B3_33​Cl3_33​(A) with LiBH4_44​ in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H3_33​N3_33​B3_33​(Me)3_33​. Compounds (B) and (C) respectively, are:
  1. (A)Borazine and MeBr
  2. (B)Boron nitride and MeBr
  3. (C)Diborane and MeMgBr
  4. (D)Borazine and MeMgBr

Correct answer: (D)

Step-by-step solution →
Q227·ChemistrySingle correctJEE Main 2020
The number of bonds between sulphur and oxygen atoms in S2_22​O8−_8^{-}8−​ and the number of bonds between sulphur and sulphur atoms in rhombic sulphur, respectively, are :
  1. (A)4 and 8
  2. (B)4 and 6
  3. (C)8 and 6
  4. (D)8 and 8

Correct answer: (D)

Step-by-step solution →
Q228·ChemistrySingle correctJEE Main 2020
White phosphorus on reaction with concentrated NaOH solution in an inert atmosphere of CO2_22​ gives phosphine and compound (X). (X) on acidification with HCl gives compound (Y). The basicity of compound (Y) is:
  1. (A)2
  2. (B)4
  3. (C)3
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q229·ChemistrySingle correctJEE Main 2020
In the following reactions, products(A) and (B) respectively are NaOH+Cl2→Hot and Conc(A)+side products\mathrm{NaOH + Cl_2} \xrightarrow{\text{Hot and Conc}} (A) + \text{side products}NaOH+Cl2​Hot and Conc​(A)+side products Ca(OH)2 Cl2→Dry(B)+side products\mathrm{Ca(OH)_2\,Cl_2} \xrightarrow{\text{Dry}} (B) + \text{side products}Ca(OH)2​Cl2​Dry​(B)+side products
  1. (A)NaClO3\mathrm{NaClO_3}NaClO3​ and Ca(OCl)2\mathrm{Ca(OCl)_2}Ca(OCl)2​
  2. (B)NaOCl\mathrm{NaOCl}NaOCl and Ca(OCl)2\mathrm{Ca(OCl)_2}Ca(OCl)2​
  3. (C)NaOCl\mathrm{NaOCl}NaOCl and Ca(ClO3)2\mathrm{Ca(ClO_3)_2}Ca(ClO3​)2​
  4. (D)NaClO3\mathrm{NaClO_3}NaClO3​ and Ca(ClO3)2\mathrm{Ca(ClO_3)_2}Ca(ClO3​)2​

Correct answer: (A)

Step-by-step solution →
Q230·ChemistryNumericalJEE Main 2020
Chlorine reacts with hot and concentrated NaOH and produces compound(X) and (Y). Compound(X) gives white precipitate with silver nitrate solution. The average bond order between Cl and O atoms in (Y) is

Correct answer: 1.67

Step-by-step solution →
Q231·ChemistryMultiple correctJEE Advanced 2019
A tin chloride Q undergoes the following reactions (not balanced) Q + Cl−^{-}− ⟶\longrightarrow⟶ X Q + Me3_{3}3​N ⟶\longrightarrow⟶ Y Q + CuCl2_{2}2​ ⟶\longrightarrow⟶ Z + CuCl X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the correct option(s)
  1. (A)The central atom in Z has one lone pair of electrons
  2. (B)The central atom in X is sp3^{3}3 hybridized
  3. (C)There is a coordinate bond in Y
  4. (D)The oxidation state of the central atom in Z is +2

Correct answer: (B), (C)

Step-by-step solution →
Q232·ChemistryMultiple correctJEE Advanced 2019
With reference to \textit{aqua regia}, choose the correct option(s)
  1. (A)The yellow colour of \textit{aqua regia} is due to the presence of NOCl and Cl2_{2}2​
  2. (B)\textit{Aqua regia} is prepared by mixing conc. HCl and conc. HNO3_{3}3​ in 3 : 1 (\textit{v/v}) ratio
  3. (C)Reaction of gold with \textit{aqua regia} produces an anion having Au in +3 oxidation state
  4. (D)Reaction of gold with \textit{aqua regia} produces NO2_{2}2​ in the absence of air

Correct answer: (A), (C)

Step-by-step solution →
Q233·ChemistryNumericalJEE Advanced 2019
At 143 K, the reaction of XeF4_{4}4​ with O2_{2}2​F2_{2}2​ produces xenon compound Y. The total number of lone Pair(s) of electrons present on the whole molecule of Y is ……… .

Correct answer: 19.00

Step-by-step solution →
Q234·ChemistrySingle correctJEE Main 2019
The basic structural unit of feldspar, zeolites, mica and asbestos is :
  1. (A){SiRR−O}n\left\{\overset{R}{\underset{R}{\text{Si}}}-\text{O}\right\}_n{RSi​R​−O}n​ (R = Me)
  2. (B)(SiO3)2−(SiO_3)^{2-}(SiO3​)2−
  3. (C)SiO2SiO_2SiO2​
  4. (D)(SiO4)4−(SiO_4)^{4-}(SiO4​)4−

Correct answer: (D)

Step-by-step solution →
Q235·ChemistrySingle correctJEE Main 2019
The C–C bond length is maximum in
  1. (A)graphite
  2. (B)C70_{70}70​
  3. (C)diamond
  4. (D)C60_{60}60​

Correct answer: (C)

Step-by-step solution →
Q236·ChemistrySingle correctJEE Main 2019
The oxoacid of sulphur that does not contain bond between sulphur atoms is:
  1. (A)H2S2O3H_2S_2O_3H2​S2​O3​
  2. (B)H2S2O4H_2S_2O_4H2​S2​O4​
  3. (C)H2S2O7H_2S_2O_7H2​S2​O7​
  4. (D)H2S4O6H_2S_4O_6H2​S4​O6​

Correct answer: (C)

Step-by-step solution →
Q237·ChemistrySingle correctJEE Main 2019
The number of pentagons in C60_{60}60​ and trigons (triangles) in white phosphorus, respectively, are:
  1. (A)12 and 3
  2. (B)20 and 4
  3. (C)12 and 4
  4. (D)20 and 3

Correct answer: (C)

Step-by-step solution →
Q238·ChemistrySingle correctJEE Main 2019
The noble gas that does NOT occur in the atmosphere is:
  1. (A)He
  2. (B)Ra
  3. (C)Ne
  4. (D)Kr

Correct answer: (B)

Step-by-step solution →
Q239·ChemistrySingle correctJEE Main 2019
The correct order of catenation is:
  1. (A)C > Sn > Si ≈ Ge
  2. (B)Ge > Sn > Si > C
  3. (C)Si > Sn > C > Ge
  4. (D)C > Si > Ge ≈ Sn

Correct answer: (D)

Step-by-step solution →
Q240·ChemistrySingle correctJEE Main 2019
C60C_{60}C60​, an allotrope of carbon contains:
  1. (A)20 hexagons and 12 pentagons.
  2. (B)12 hexagons and 20 pentagons.
  3. (C)18 hexagons and 14 pentagons.
  4. (D)16 hexagons and 16 pentagons

Correct answer: (A)

Step-by-step solution →
Q241·ChemistrySingle correctJEE Main 2019
HF has highest boiling point among hydrogen halides, because it has:
  1. (A)lowest dissociation enthalpy
  2. (B)strongest van der Waals' interactions
  3. (C)strongest hydrogen bonding
  4. (D)lowest ionic character

Correct answer: (C)

Step-by-step solution →
Q242·ChemistrySingle correctJEE Main 2019
The correct order of the oxidation states of nitrogen in NO, N2ON_2ON2​O, NO2NO_2NO2​ and N2O3N_2O_3N2​O3​ is:
  1. (A)N2O<N2O3<NO<NO2N_2O < N_2O_3 < NO < NO_2N2​O<N2​O3​<NO<NO2​
  2. (B)NO2<NO<N2O3<N2ONO_2 < NO < N_2O_3 < N_2ONO2​<NO<N2​O3​<N2​O
  3. (C)NO2<N2O3<NO<N2ONO_2 < N_2O_3 < NO < N_2ONO2​<N2​O3​<NO<N2​O
  4. (D)N2O<NO<N2O3<NO2N_2O < NO < N_2O_3 < NO_2N2​O<NO<N2​O3​<NO2​

Correct answer: (D)

Step-by-step solution →
Q243·ChemistrySingle correctJEE Main 2019
The amorphous form of silica is:
  1. (A)quartz
  2. (B)kieselguhr
  3. (C)cristobalite
  4. (D)tridymite

Correct answer: (B)

Step-by-step solution →
Q244·ChemistrySingle correctJEE Main 2019
The correct statements among I to III regarding group 13 element oxides are, I. Boron trioxide is acidic II. Oxides of aluminium and gallium are amphoteric III. Oxides of indium and thallium are basic
  1. (A)I, II and III
  2. (B)II and III only
  3. (C)I and III only
  4. (D)I and II only

Correct answer: (A)

Step-by-step solution →
Q245·ChemistrySingle correctJEE Main 2019
Diborane (B2H6B_2H_6B2​H6​) reacts independently with O2O_2O2​ and H2OH_2OH2​O to produce, respectively:
  1. (A)H3BO3H_3BO_3H3​BO3​ and B2O3B_2O_3B2​O3​
  2. (B)B2O3B_2O_3B2​O3​ and H3BO3H_3BO_3H3​BO3​
  3. (C)HBO2HBO_2HBO2​ and H3BO3H_3BO_3H3​BO3​
  4. (D)B2O3B_2O_3B2​O3​ and [BH4]−[BH_4]^-[BH4​]−

Correct answer: (B)

Step-by-step solution →
Q246·ChemistrySingle correctJEE Main 2019
The correct statement about ICl5ICl_5ICl5​ and ICl4−ICl_4^-ICl4−​ is:
  1. (A)ICl5ICl_5ICl5​ is trigonal bipyramidal and ICl4−ICl_4^-ICl4−​ is tetrahedral
  2. (B)ICl5ICl_5ICl5​ is square pyramidal and ICl4−ICl_4^-ICl4−​ is square planar
  3. (C)ICl5ICl_5ICl5​ is square pyramidal and ICl4−ICl_4^-ICl4−​ is tetrahedral
  4. (D)Both are isostructural

Correct answer: (B)

Step-by-step solution →
Q247·ChemistrySingle correctJEE Main 2019
The element that shows greater ability to form pπ\piπ-pπ\piπ multiple bonds, is:
  1. (A)Sn
  2. (B)C
  3. (C)Ge
  4. (D)Si

Correct answer: (B)

Step-by-step solution →
Q248·ChemistrySingle correctJEE Main 2019
Chlorine on reaction with hot and concentrated sodium hydroxide gives :
  1. (A)Cl−^{-}− and ClO3−_{3}^{-}3−​
  2. (B)Cl−^{-}− and ClO−^{-}−
  3. (C)ClO3−_{3}^{-}3−​ and ClO2−_{2}^{-}2−​
  4. (D)Cl−^{-}− and ClO2−_{2}^{-}2−​

Correct answer: (A)

Step-by-step solution →
Q249·ChemistrySingle correctJEE Main 2019
The element that does NOT show catenation is :
  1. (A)Ge
  2. (B)Si
  3. (C)Sn
  4. (D)Pb

Correct answer: (D)

Step-by-step solution →
Q250·ChemistrySingle correctJEE Main 2019
The relative stability of +1 oxidation state of group 13 elements follows the order:
  1. (A)Al < Ga < Tl < In
  2. (B)Tl < In < Ga < Al
  3. (C)Ga < Al < In < Tl
  4. (D)Al < Ga < In < Tl

Correct answer: (D)

Step-by-step solution →
Q251·ChemistrySingle correctJEE Main 2019
The hydride that is NOT electron deficient is:
  1. (A)SiH4SiH_{4}SiH4​
  2. (B)B2H6B_{2}H_{6}B2​H6​
  3. (C)GaH3GaH_{3}GaH3​
  4. (D)AlH3AlH_{3}AlH3​

Correct answer: (A)

Step-by-step solution →
Q252·ChemistrySingle correctJEE Main 2019
The chloride that CANNOT get hydrolysed is
  1. (A)PbCl4PbCl_4PbCl4​
  2. (B)CCl4CCl_4CCl4​
  3. (C)SnCl4SnCl_4SnCl4​
  4. (D)SiCl4SiCl_4SiCl4​

Correct answer: (B)

Step-by-step solution →
Q253·ChemistrySingle correctJEE Main 2019
Good reducing nature of H3_33​PO2_22​ is attributed to the presence of
  1. (A)Two P – OH bonds
  2. (B)One P – H bond
  3. (C)Two P – H bonds
  4. (D)One P – OH bond

Correct answer: (C)

Step-by-step solution →
Q254·ChemistrySingle correctJEE Main 2019
Correct statements among a to d regarding silicones are (i) they are polymers with hydrophobic character (ii) they are biocompatible (iii) in general, they have high thermal stability and low dielectric strength (iv) usually they are resistant to oxidation and used as greases.
  1. (A)(i), (ii), (iii) and (iv)
  2. (B)(i), (ii) and (iii)
  3. (C)(i) and (ii) only
  4. (D)(i), (ii) and (iv)

Correct answer: (D)

Step-by-step solution →
Q255·ChemistrySingle correctJEE Main 2019
Aluminium is usually found in +3 oxidation state. In contrast, thallium exists in +1 and +3 oxidation states. This is due to
  1. (A)inert pair effect
  2. (B)diagonal relationship
  3. (C)lattice effect
  4. (D)lanthanoid contraction

Correct answer: (A)

Step-by-step solution →
Q256·ChemistryMultiple correctJEE Advanced 2018
Based on the compounds of group 15 elements, the correct statement(s) is (are)
  1. (A)Bi2O5Bi_{2}O_{5}Bi2​O5​ is more basic than N2O5N_{2}O_{5}N2​O5​
  2. (B)NF3NF_{3}NF3​ is more covalent than BiF3BiF_{3}BiF3​
  3. (C)PH3PH_{3}PH3​ boils at lower temperature than NH3NH_{3}NH3​
  4. (D)The N−N single bond is stronger than the P−P single bond

Correct answer: (A), (B), (C)

Step-by-step solution →
Q257·ChemistryNumericalJEE Advanced 2018
The total number of compounds having at least one bridging oxo group among the molecules given below is ____. N2O3N_{2}O_{3}N2​O3​, N2O5N_{2}O_{5}N2​O5​, P4O6P_{4}O_{6}P4​O6​, P4O7P_{4}O_{7}P4​O7​, H4P2O5H_{4}P_{2}O_{5}H4​P2​O5​, H5P3O10H_{5}P_{3}O_{10}H5​P3​O10​, H2S2O3H_{2}S_{2}O_{3}H2​S2​O3​, H2S2O5H_{2}S_{2}O_{5}H2​S2​O5​

Correct answer: 6

Step-by-step solution →
Q258·ChemistryMultiple correctJEE Advanced 2018
The compound(s) which generate(s) N2N_{2}N2​ gas upon thermal decomposition below 300°C is (are)
  1. (A)NH4NO3NH_{4}NO_{3}NH4​NO3​
  2. (B)(NH4)2Cr2O7(NH_{4})_{2}Cr_{2}O_{7}(NH4​)2​Cr2​O7​
  3. (C)Ba(N3)2Ba(N_{3})_{2}Ba(N3​)2​
  4. (D)Mg3N2Mg_{3}N_{2}Mg3​N2​

Correct answer: (B), (C)

Step-by-step solution →
Q259·ChemistryMultiple correctJEE Advanced 2017
The colour of the X2X_{2}X2​ molecules of group 17 elements changes gradually from yellow to violet down the group. This is due to
  1. (A)the physical state of X2X_{2}X2​ at atom temperature changes from gas to solid down the group
  2. (B)decrease in HOMO-LUMO gap down the group
  3. (C)decrease in π∗\pi^{*}π∗-σ∗\sigma^{*}σ∗ gap down the group
  4. (D)decrease in ionization energy down the group

Correct answer: (B), (C)

Step-by-step solution →
Q260·ChemistrySingle correctJEE Advanced 2017
PARAGRAPH 1 Upon heating KClO3\mathrm{KClO_{3}}KClO3​ in the presence of catalytic amount of MnO2\mathrm{MnO_{2}}MnO2​, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with HNO3\mathrm{HNO_{3}}HNO3​ gives Y and Z. W and X are, respectively
  1. (A)O3\mathrm{O_{3}}O3​ and P4O6\mathrm{P_{4}O_{6}}P4​O6​
  2. (B)O2\mathrm{O_{2}}O2​ and P4O6\mathrm{P_{4}O_{6}}P4​O6​
  3. (C)O2\mathrm{O_{2}}O2​ and P4O10\mathrm{P_{4}O_{10}}P4​O10​
  4. (D)O3\mathrm{O_{3}}O3​ and P4O10\mathrm{P_{4}O_{10}}P4​O10​

Correct answer: (C)

Step-by-step solution →
Q261·ChemistrySingle correctJEE Advanced 2017
The order of the oxidation state of the phosphorus atom in H3PO2\mathrm{H_{3}PO_{2}}H3​PO2​, H3PO4\mathrm{H_{3}PO_{4}}H3​PO4​, H3PO3\mathrm{H_{3}PO_{3}}H3​PO3​, and H4P2O6\mathrm{H_{4}P_{2}O_{6}}H4​P2​O6​ is
  1. (A)H3PO3>H3PO2>H3PO4>H4P2O6\mathrm{H_{3}PO_{3}} > \mathrm{H_{3}PO_{2}} > \mathrm{H_{3}PO_{4}} > \mathrm{H_{4}P_{2}O_{6}}H3​PO3​>H3​PO2​>H3​PO4​>H4​P2​O6​
  2. (B)H3PO4>H3PO2>H3PO3>H4P2O6\mathrm{H_{3}PO_{4}} > \mathrm{H_{3}PO_{2}} > \mathrm{H_{3}PO_{3}} > \mathrm{H_{4}P_{2}O_{6}}H3​PO4​>H3​PO2​>H3​PO3​>H4​P2​O6​
  3. (C)H3PO4>H4P2O6>H3PO3>H3PO2\mathrm{H_{3}PO_{4}} > \mathrm{H_{4}P_{2}O_{6}} > \mathrm{H_{3}PO_{3}} > \mathrm{H_{3}PO_{2}}H3​PO4​>H4​P2​O6​>H3​PO3​>H3​PO2​
  4. (D)H3PO2>H3PO3>H4P2O6>H3PO4\mathrm{H_{3}PO_{2}} > \mathrm{H_{3}PO_{3}} > \mathrm{H_{4}P_{2}O_{6}} > \mathrm{H_{3}PO_{4}}H3​PO2​>H3​PO3​>H4​P2​O6​>H3​PO4​

Correct answer: (C)

Step-by-step solution →
Q262·ChemistryMultiple correctJEE Advanced 2017
The correct statement(s) about the oxoacids, HClO4HClO_{4}HClO4​ and HClOHClOHClO, is(are)
  1. (A)HClO4HClO_{4}HClO4​ is more acidic than HClOHClOHClO because of the resonance stabilization of its anion
  2. (B)HClO4HClO_{4}HClO4​ is formed in the reaction between Cl2Cl_{2}Cl2​ and H2OH_{2}OH2​O
  3. (C)The central atom in both HClO4HClO_{4}HClO4​ and HClOHClOHClO is sp3sp^{3}sp3 hybridized
  4. (D)The conjugate base of HClO4HClO_{4}HClO4​ is weaker base than H2OH_{2}OH2​O

Correct answer: (A), (C), (D)

Step-by-step solution →
Q263·ChemistrySingle correctJEE Advanced 2017
PARAGRAPH 1 Upon heating KClO3\mathrm{KClO_{3}}KClO3​ in the presence of catalytic amount of MnO2\mathrm{MnO_{2}}MnO2​, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with HNO3\mathrm{HNO_{3}}HNO3​ gives Y and Z. Y and Z are, respectively
  1. (A)N2O3\mathrm{N_{2}O_{3}}N2​O3​ and H3PO4\mathrm{H_{3}PO_{4}}H3​PO4​
  2. (B)N2O5\mathrm{N_{2}O_{5}}N2​O5​ and HPO3\mathrm{HPO_{3}}HPO3​
  3. (C)N2O4\mathrm{N_{2}O_{4}}N2​O4​ and HPO3\mathrm{HPO_{3}}HPO3​
  4. (D)N2O4\mathrm{N_{2}O_{4}}N2​O4​ and H3PO3\mathrm{H_{3}PO_{3}}H3​PO3​

Correct answer: (B)

Step-by-step solution →
Q264·ChemistryMultiple correctJEE Advanced 2016
The crystalline form of borax has
  1. (A)tetranuclear [B4O5(OH)4]2−[B_{4}O_{5}(OH)_{4}]^{2-}[B4​O5​(OH)4​]2− unit
  2. (B)all boron atoms in the same plane
  3. (C)equal number of sp2sp^{2}sp2 and sp3sp^{3}sp3 hybridized boron atoms
  4. (D)one terminal hydroxide per boron atom

Correct answer: (A), (C), (D)

Step-by-step solution →
Q265·ChemistryMultiple correctJEE Advanced 2016
The nitrogen containing compound produced in the reaction of HNO3HNO_{3}HNO3​ with P4O10P_{4}O_{10}P4​O10​
  1. (A)can also be prepared by reaction of P4P_{4}P4​ and HNO3HNO_{3}HNO3​
  2. (B)is diamagnetic
  3. (C)contains one N – N bond
  4. (D)reacts with Na metal producing a brown gas

Correct answer: (B), (D)

Step-by-step solution →
Q266·ChemistrySingle correctJEE Advanced 2016
The increasing order of atomic radii of the following Group 13 elements is
  1. (A)Al < Ga < In < Tl
  2. (B)Ga < Al < In < Tl
  3. (C)Al < In < Ga < Tl
  4. (D)Al < Ga < Tl < In

Correct answer: (B)

Step-by-step solution →
Q267·ChemistryMultiple correctJEE Advanced 2015
The correct statement(s) regarding, (i) HClO\mathrm{HClO}HClO, (ii) HClO2\mathrm{HClO_{2}}HClO2​, (iii) HClO3\mathrm{HClO_{3}}HClO3​ and (iv) HClO4\mathrm{HClO_{4}}HClO4​, is (are)
  1. (A)The number of Cl=O\mathrm{Cl = O}Cl=O bonds in (ii) and (iii) together is two
  2. (B)The number of lone pairs of electrons on Cl in (ii) and (iii) together is three
  3. (C)The hybridization of Cl in (iv) is sp3sp^{3}sp3
  4. (D)Amongst (i) to (iv), the strongest acid is (i)

Correct answer: (B), (C)

Step-by-step solution →
Q268·ChemistryIntegerJEE Advanced 2015
Three moles of B2H6\mathrm{B_{2}H_{6}}B2​H6​ are completely reacted with methanol. The number of moles of boron containing product formed is

Correct answer: 6

Step-by-step solution →
Q269·ChemistrySingle correctJEE Advanced 2014
The product formed in the reaction of SOCl2\mathrm{SOCl}_2SOCl2​ with white phosphorous is
  1. (A)PCl3\mathrm{PCl}_3PCl3​
  2. (B)SO2Cl2\mathrm{SO_2Cl_2}SO2​Cl2​
  3. (C)SCl2\mathrm{SCl}_2SCl2​
  4. (D)POCl3\mathrm{POCl}_3POCl3​

Correct answer: (A)

Step-by-step solution →
Q270·ChemistryMultiple correctJEE Advanced 2014
The correct statement(s) for orthoboric acid is/are
  1. (A)It behaves as a weak acid in water due to self ionization.
  2. (B)Acidity of its aqueous solution increases upon addition of ethylene glycol.
  3. (C)It has a three dimensional structure due to hydrogen bonding.
  4. (D)It is a weak electrolyte in water.

Correct answer: (B), (D)

Step-by-step solution →
Q271·ChemistrySingle correctJEE Advanced 2014
Under ambient conditions, the total number of gases released as products in the final step of the reaction scheme shown below is
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q272·ChemistrySingle correctJEE Advanced 2013
The unbalanced chemical reactions given in List – I show missing reagent or condition (?) which are provided in List – II. Match List – I with List – II and select the correct answer using the code given below the lists:
List – IList – II
P.PbO2+H2SO4→?PbSO4+O2+other product\mathrm{PbO_2} + \mathrm{H_2SO_4} \xrightarrow{?} \mathrm{PbSO_4} + \mathrm{O_2} + \text{other product}PbO2​+H2​SO4​?​PbSO4​+O2​+other product1.NO\mathrm{NO}NO
Q.Na2S2O3+H2O→?NaHSO4+other product\mathrm{Na_2S_2O_3} + \mathrm{H_2O} \xrightarrow{?} \mathrm{NaHSO_4} + \text{other product}Na2​S2​O3​+H2​O?​NaHSO4​+other product2.I2\mathrm{I_2}I2​
R.N2H4→?N2+other product\mathrm{N_2H_4} \xrightarrow{?} \mathrm{N_2} + \text{other product}N2​H4​?​N2​+other product3.Warm
S.XeF2→?Xe+other product\mathrm{XeF_2} \xrightarrow{?} \mathrm{Xe} + \text{other product}XeF2​?​Xe+other product4.Cl2\mathrm{Cl_2}Cl2​
  1. (A)P-4, Q-2, R-3, S-1
  2. (B)P-3, Q-2, R-1, S-4
  3. (C)P-1, Q-4, R-2, S-3
  4. (D)P-3, Q-4, R-2, S-1

Correct answer: (D)

Step-by-step solution →
Q273·ChemistrySingle correctJEE Advanced 2013
The reactions of Cl2\mathrm{Cl_2}Cl2​ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2\mathrm{Cl_2}Cl2​ gas reacts with SO2\mathrm{SO_2}SO2​ gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T. R, S and T, respectively, are
  1. (A)SO2Cl2\mathrm{SO_2Cl_2}SO2​Cl2​, PCl5\mathrm{PCl_5}PCl5​ and H3PO4\mathrm{H_3PO_4}H3​PO4​
  2. (B)SO2Cl2\mathrm{SO_2Cl_2}SO2​Cl2​, PCl3\mathrm{PCl_3}PCl3​ and H3PO3\mathrm{H_3PO_3}H3​PO3​
  3. (C)SOCl2\mathrm{SOCl_2}SOCl2​, PCl3\mathrm{PCl_3}PCl3​ and H3PO2\mathrm{H_3PO_2}H3​PO2​
  4. (D)SOCl2\mathrm{SOCl_2}SOCl2​, PCl5\mathrm{PCl_5}PCl5​ and H3PO4\mathrm{H_3PO_4}H3​PO4​

Correct answer: (A)

Step-by-step solution →
Q274·ChemistryMultiple correctJEE Advanced 2013
The correct statement(s) about O3\mathrm{O_3}O3​ is(are)
  1. (A)O–O bond lengths are equal.
  2. (B)Thermal decomposition of O3\mathrm{O_3}O3​ is endothermic.
  3. (C)O3\mathrm{O_3}O3​ is diamagnetic in nature.
  4. (D)O3\mathrm{O_3}O3​ has a bent structure.

Correct answer: (A), (C), (D)

Step-by-step solution →
Q275·ChemistrySingle correctJEE Advanced 2013
The reactions of Cl2\mathrm{Cl_2}Cl2​ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2\mathrm{Cl_2}Cl2​ gas reacts with SO2\mathrm{SO_2}SO2​ gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T. P and Q, respectively, are the sodium salts of
  1. (A)hypochlorus and chloric acids
  2. (B)hypochlorus and chlorus acids
  3. (C)chloric and perchloric acids
  4. (D)chloric and hypochlorus acids

Correct answer: (A)

Step-by-step solution →
Q276·ChemistrySingle correctJEE Advanced 2013
Concentrated nitric acid, upon long standing, turns yellow–brown due to the formation of
  1. (A)NONONO
  2. (B)NO2NO_2NO2​
  3. (C)N2ON_2ON2​O
  4. (D)N2O4N_2O_4N2​O4​

Correct answer: (B)

Step-by-step solution →

p-Block Elements — frequently asked

How many questions from p-Block Elements appear in JEE?

p-Block Elements has appeared in 164 of the last 186 JEE Main and JEE Advanced papers — about 88% of them — contributing 276 questions in total across those papers.

Is p-Block Elements an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 88% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these p-Block Elements questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Chemistry chapters

  • Coordination Compounds 318
  • Redox Reactions and Electrochemistry 265
  • Chemical Bonding and Molecular Structure 207
  • d- and f-Block Elements 202
  • Aldehydes and Ketones 199
  • Equilibrium 199
  • Solutions 198
  • Chemical Thermodynamics 195

All 36 Chemistry chapters →

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