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Equilibrium — JEE Previous Year Questions

Every Equilibrium question asked in JEE Main and JEE Advanced across the last 186 papers — 199 questions, each with its correct answer. Free to read, no account needed.

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All 199 Equilibrium questions

Most recent papers first.

Q1·ChemistrySingle correctJEE Main 2026
Consider the following reactions in which all the reactants and products are present in gaseous state 2xy⇌x2+y22xy \rightleftharpoons x_2 + y_22xy⇌x2​+y2​ K1=2.5×105K_1 = 2.5 \times 10^5K1​=2.5×105 xy+12z2⇌xyzxy + \frac{1}{2}z_2 \rightleftharpoons xyzxy+21​z2​⇌xyz K2=5×10−3K_2 = 5 \times 10^{-3}K2​=5×10−3 The value of K3K_3K3​ for the equilibrium 12x2+12y2+12z2⇌xyz\frac{1}{2}x_2 + \frac{1}{2}y_2 + \frac{1}{2}z_2 \rightleftharpoons xyz21​x2​+21​y2​+21​z2​⇌xyz is:
  1. (A)2.5×10−32.5 \times 10^{-3}2.5×10−3
  2. (B)2.5×1032.5 \times 10^{3}2.5×103
  3. (C)1.0×10−51.0 \times 10^{-5}1.0×10−5
  4. (D)5×10−35 \times 10^{-3}5×10−3

Correct answer: (C)

Step-by-step solution →
Q2·ChemistryNumericalJEE Main 2026
Solid carbon, CaO and CaCO3CaCO_3CaCO3​ are mixed and allowed to attain equilibrium at T K. CaCO3(s)⇌CaO(s)+CO2(g)CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)CaCO3​(s)⇌CaO(s)+CO2​(g) Kp1=0.08K_{p_1} = 0.08Kp1​​=0.08 atm C(s)+CO2(g)⇌2CO(g)C(s) + CO_2(g) \rightleftharpoons 2CO(g)C(s)+CO2​(g)⇌2CO(g) Kp2=2K_{p_2} = 2Kp2​​=2 atm The partial pressure of CO is __________ ×10−1\times 10^{-1}×10−1 atm

Correct answer: 4

Step-by-step solution →
Q3·ChemistrySingle correctJEE Main 2026
One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium. A(g) ⇌ B(g). KcK_cKc​ for this reaction at 400 K is 4.0. The partial pressures (in atm) of He and B(g) are respectively (at equilibrium) (Assume He, A(g) and B(g) behave as ideal gases) (Given: R = 0.082 L atm K⁻¹ mol⁻¹)
  1. (A)3.28, 2.624
  2. (B)2.624, 3.28
  3. (C)3.28, 0.656
  4. (D)0.656, 6.56

Correct answer: (A)

Step-by-step solution →
Q4·ChemistryNumericalJEE Main 2026
In a closed flask at 600 K, one mole of X2Y4(g)\mathrm{X_{2}Y_{4}(g)}X2​Y4​(g) attains equilibrium as given below : X2Y4(g)⇌2XY2(g)\mathrm{X_{2}Y_{4}}(g) \rightleftharpoons 2\mathrm{XY_{2}}(g)X2​Y4​(g)⇌2XY2​(g) At equilibrium, 75% X2Y4(g)\mathrm{X_{2}Y_{4}(g)}X2​Y4​(g) was dissociated and the total pressure is 1 atm. The magnitude of ΔrG⊖\Delta_{r}G^{\ominus}Δr​G⊖ (in kJ mol−1^{-1}−1) at this temperature is __________. (Nearest Integer) (Given : R = 8.3 J mol−1^{-1}−1 K−1^{-1}−1; ln 10 = 2.3, log 2 = 0.3, log 3 = 0.48, log 5 = 0.69, log 7 = 0.84)

Correct answer: 8

Step-by-step solution →
Q5·ChemistrySingle correctJEE Main 2026
Given is a concentrated solution of a weak electrolyte AxByA_{x}B_{y}Ax​By​ of concentration 'c' and dissociation constant 'K'. The degree of dissociation is given by :
  1. (A)[K×cx+y−1xxyy]x+y\left[K \times c^{x+y-1} x^{x} y^{y}\right]^{x+y}[K×cx+y−1xxyy]x+y
  2. (B)(Kcx+y−1xxyy)1x+y\left(\frac{K}{c^{x+y-1} x^{x} y^{y}}\right)^{\frac{1}{x+y}}(cx+y−1xxyyK​)x+y1​
  3. (C)(cx+y−1xxyyK)x+y\left(\frac{c^{x+y-1} x^{x} y^{y}}{K}\right)^{x+y}(Kcx+y−1xxyy​)x+y
  4. (D)(cx+y−1xxyyK)1x+y\left(\frac{c^{x+y-1} x^{x} y^{y}}{K}\right)^{\frac{1}{x+y}}(Kcx+y−1xxyy​)x+y1​

Correct answer: (B)

Step-by-step solution →
Q6·ChemistrySingle correctJEE Main 2026
M3A2M_3A_2M3​A2​ is a sparingly soluble salt of molar mass yyy g mol−1^{-1}−1 and solubility xxx g L−1^{-1}−1. The ratio of the molar concentration of the anion (A3−A^{3-}A3−) to the solubility product of the salt is
  1. (A)154⋅y4x4\frac{1}{54} \cdot \frac{y^4}{x^4}541​⋅x4y4​
  2. (B)y5108x4\frac{y^5}{108x^4}108x4y5​
  3. (C)108⋅x5y5108 \cdot \frac{x^5}{y^5}108⋅y5x5​
  4. (D)1108⋅y4x4\frac{1}{108} \cdot \frac{y^4}{x^4}1081​⋅x4y4​

Correct answer: (A)

Step-by-step solution →
Q7·ChemistrySingle correctJEE Main 2026
Arrange the following resultant mixtures in increasing order of their pH values A. 10 mL 0.2 M Ca(OH)2_22​ + 25 mL 0.1 M HCl B. 10 mL 0.01 M H2_22​SO4_44​ + 10 mL 0.01 M Ca(OH)2_22​ C. 10 mL 0.1 M H2_22​SO4_44​ + 10 mL 0.1 M KOH Choose the correct answer from the options given below:
  1. (A)B<C<AB < C < AB<C<A
  2. (B)C<A<BC < A < BC<A<B
  3. (C)C<B<AC < B < AC<B<A
  4. (D)A<C<BA < C < BA<C<B

Correct answer: (C)

Step-by-step solution →
Q8·ChemistrySingle correctJEE Main 2026
The reaction A(g) ⇌ B(g) + C(g) was initiated with the amount 'a' of A(g). At equilibrium it is found that the amount of A(g) remaining is (a − x) at a total pressure of p. The equilibrium constant KpK_pKp​ of the reaction can be calculated from the expression :
  1. (A)x2a2+x2×p\frac{x^{2}}{a^{2} + x^{2}} \times pa2+x2x2​×p
  2. (B)x2a2−x2×p\frac{x^{2}}{a^{2} - x^{2}} \times pa2−x2x2​×p
  3. (C)a+x2x2×p\frac{a + x^{2}}{x^{2}} \times px2a+x2​×p
  4. (D)a2−x2x2×p\frac{a^{2} - x^{2}}{x^{2}} \times px2a2−x2​×p

Correct answer: (B)

Step-by-step solution →
Q9·ChemistryNumericalJEE Main 2026
The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below A(g)⇌B(g)+C(g)A(g) \rightleftharpoons B(g) + C(g)A(g)⇌B(g)+C(g) The magnitude of ΔH∘R\frac{\Delta H^\circ}{R}RΔH∘​ calculated from the above data is _____. (Nearest integer)
1T\frac{1}{T}T1​ (K−1^{-1}−1)log⁡10Kp\log_{10} K_plog10​Kp​
0.053.5
0.062.5
0.071.5

Correct answer: 230

Step-by-step solution →
Q10·ChemistryNumericalJEE Main 2026
For the following reaction at 50 °C and at 2 atm pressure, 2N2O5(g)⇌2N2O4(g)+O2(g)2\mathrm{N_{2}O_{5}}(g) \rightleftharpoons 2\mathrm{N_{2}O_{4}}(g) + \mathrm{O_{2}}(g)2N2​O5​(g)⇌2N2​O4​(g)+O2​(g) N2O5\mathrm{N_{2}O_{5}}N2​O5​ is 50% dissociated. The magnitude of standard free energy change at this temperature is xxx. xxx = ______ J mol−1^{-1}−1 [Nearest integer]. Given: RRR = 8.314 J mol−1^{-1}−1 K−1^{-1}−1, log 2 = 0.30, log 3 = 0.48, ln 10 = 2.303, °C + 273 = K

Correct answer: 2474

Step-by-step solution →
Q11·ChemistrySingle correctJEE Main 2026
At T(K)T(K)T(K), the equilibrium constant of A2(g)+B2(g)⇌C(g)A_2(g) + B_2(g) \rightleftharpoons C(g)A2​(g)+B2​(g)⇌C(g) is 2.7×10−52.7 \times 10^{-5}2.7×10−5. What is the equilibrium constant for 13A2(g)+13B2(g)⇌13C(g)\frac{1}{3}A_2(g) + \frac{1}{3}B_2(g) \rightleftharpoons \frac{1}{3}C(g)31​A2​(g)+31​B2​(g)⇌31​C(g) at the same temperature?
  1. (A)(2.7×10−5)3(2.7 \times 10^{-5})^3(2.7×10−5)3
  2. (B)6×10−26 \times 10^{-2}6×10−2
  3. (C)2.7×10−5\sqrt{2.7 \times 10^{-5}}2.7×10−5​
  4. (D)3×10−23 \times 10^{-2}3×10−2

Correct answer: (D)

Step-by-step solution →
Q12·ChemistrySingle correctJEE Main 2026
20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X)? (pKapK_{a}pKa​ value of acetic acid is 4.75).
  1. (A)7.0
  2. (B)4.75
  3. (C)3.5
  4. (D)4.82

Correct answer: (B)

Step-by-step solution →
Q13·ChemistryNumericalJEE Main 2026
The pH of a solution obtained by mixing 5 mL of 0.1 M NH4OHNH_4OHNH4​OH solution with 250 mL of 0.1 M NH4ClNH_4ClNH4​Cl solution is _______ ×10−2\times 10^{-2}×10−2. (Nearest integer) Given: pKb(NH4OH)=4.74pK_b(NH_4OH) = 4.74pKb​(NH4​OH)=4.74 log⁡2=0.30\log 2 = 0.30log2=0.30 log⁡3=0.48\log 3 = 0.48log3=0.48 log⁡5=0.70\log 5 = 0.70log5=0.70

Correct answer: 756

Step-by-step solution →
Q14·ChemistrySingle correctJEE Main 2026
At 25∘C25^{\circ}C25∘C, 20.0 mL of 0.2 M weak monoprotic acid HX is titrated against 0.2 M NaOH. The pH of the solution (a) at the start of the titration (when NaOH has not been added) and (b) when 10 mL of NaOH is added respectively, are: Given: Ka=5×10−4K_a = 5 \times 10^{-4}Ka​=5×10−4, pKa=3.3pK_a = 3.3pKa​=3.3, α<<1\alpha << 1α<<1
  1. (A)(a) 0.7 (b) 2.0
  2. (B)(a) 2.0 (b) 3.3
  3. (C)(a) 1.1 (b) 2.2
  4. (D)(a) 3.0 (b) 2.2

Correct answer: (B)

Step-by-step solution →
Q15·ChemistrySingle correctJEE Main 2026
The first and second ionization constants of a weak dibasic acid H2AH_2AH2​A are 8.1×10−88.1 \times 10^{-8}8.1×10−8 and 1.0×10−131.0 \times 10^{-13}1.0×10−13 respectively. 0.1 mol of H2AH_2AH2​A was dissolved in 1 L of 0.1 M HCl solution. The concentration of HA−HA^-HA− in the resultant solution is:
  1. (A)0.1 M
  2. (B)9.53×10−69.53 \times 10^{-6}9.53×10−6 M
  3. (C)8.1×10−88.1 \times 10^{-8}8.1×10−8 M
  4. (D)1.0×10−131.0 \times 10^{-13}1.0×10−13 M

Correct answer: (C)

Step-by-step solution →
Q16·ChemistrySingle correctJEE Main 2026
The solubility product constants of Ag2CrO4\mathrm{Ag_{2}CrO_{4}}Ag2​CrO4​ and AgBr\mathrm{AgBr}AgBr are 32x32x32x and 4y4y4y respectively at 298 K. The value of (molarity of Ag2CrO4molarity of AgBr)\left(\frac{\text{molarity of } \mathrm{Ag_{2}CrO_{4}}}{\text{molarity of } \mathrm{AgBr}}\right)(molarity of AgBrmolarity of Ag2​CrO4​​) can be expressed as :
  1. (A)2x3y\frac{2\sqrt[3]{x}}{y}y23x​​
  2. (B)2xy2\sqrt{\frac{x}{y}}2yx​​
  3. (C)xy\sqrt{\frac{x}{y}}yx​​
  4. (D)x3y\frac{\sqrt[3]{x}}{\sqrt{y}}y​3x​​

Correct answer: (D)

Step-by-step solution →
Q17·ChemistrySingle correctJEE Main 2026
Consider a weak base 'B' of pKb_{b}b​ = 5.699. 'x' mL of 0.02 M HCl and 'y' mL of 0.02 M weak base 'B' are mixed to make 100 mL of a buffer of pH 9 at 25ºC. The values of 'x' and 'y' respectively are: [Given: log 2 = 0.3010, log 3 = 0.4771, log 5 = 0.699]
  1. (A)x | y 11.1 | 88.9
  2. (B)x | y 42.7 | 57.3
  3. (C)x | y 14.3 | 85.7
  4. (D)x | y 85.7 | 14.3

Correct answer: (C)

Step-by-step solution →
Q18·ChemistryNumericalJEE Main 2026
Consider the dissociation equilibrium of the following weak acid HA ⇌\rightleftharpoons⇌ H+^{+}+(aq) +++ A−^{-}−(aq) If the pKa of the acid is 4, then the pH of 10 mM HA solution is ________. (Nearest integer) [Given : The degree of dissociation can be neglected with respect to unity]

Correct answer: 3

Step-by-step solution →
Q19·ChemistrySingle correctJEE Main 2026
Observe the following equilibrium in a 1 L flask. A(g)⇌B(g)A(g) \rightleftharpoons B(g)A(g)⇌B(g) At T(K), the equilibrium concentrations of A and B are 0.5 M and 0.375 M respectively. 0.1 moles of A is added into the flask and heated to T(K) to establish the equilibrium again. The new equilibrium concentrations (in M) of A and B are respectively.
  1. (A)0.367, 0.275
  2. (B)0.53, 0.4
  3. (C)0.742, 0.557
  4. (D)0.557, 0.418

Correct answer: (D)

Step-by-step solution →
Q20·ChemistrySingle correctJEE Main 2026
Consider the following gaseous equilibrium in a closed container of volume “V” at T(K). P2(g)+Q2(g)⇌2PQ(g)\text{P}_{2}(\text{g}) + \text{Q}_{2}(\text{g}) \rightleftharpoons 2\text{PQ}(\text{g})P2​(g)+Q2​(g)⇌2PQ(g) 2 moles each of P2(g)\text{P}_{2}(\text{g})P2​(g), Q2(g)\text{Q}_{2}(\text{g})Q2​(g) and PQ (g) are present at equilibrium. Now one mole each of ‘P2\text{P}_{2}P2​’ and ‘Q2\text{Q}_{2}Q2​’ are added to the equilibrium keeping the temperature at T(K). The number of moles of P2\text{P}_{2}P2​, Q2\text{Q}_{2}Q2​ and PQ at the new equilibrium, respectively , are -
  1. (A)2.67, 2.67, 2.67
  2. (B)1.21, 2.24, 1.56
  3. (C)1.66, 1.66, 1.66
  4. (D)2.56, 1.62, 2.24

Correct answer: (A)

Step-by-step solution →
Q21·ChemistryNumericalJEE Main 2026
Consider two Group IV metal ions X2+\mathrm{X^{2+}}X2+ and Y2+\mathrm{Y^{2+}}Y2+. A solution containing 0.01 MX2+\mathrm{MX^{2+}}MX2+ and 0.01 MY2+\mathrm{MY^{2+}}MY2+ is saturated with H2S\mathrm{H_2S}H2​S. The pH at which the metal sulphide YS will form as a precipitate is ______ (Nearest integer) (Given : Ksp(XS)=1×10−22\mathrm{K_{sp}\left(XS\right)=1\times10^{-22}}Ksp​(XS)=1×10−22 at 25°C, Ksp(YS)=4×10−16\mathrm{K_{sp}\left(YS\right)=4\times10^{-16}}Ksp​(YS)=4×10−16 at 25°C, [H2S]\mathrm{[H_2S]}[H2​S] = 0.1M in solution, Ka1×Ka2\mathrm{K_{a1} \times K_{a2}}Ka1​×Ka2​ (H2S\mathrm{H_2S}H2​S) = 1.0×10−211.0 \times 10^{-21}1.0×10−21, log 2 = 0.30, log 3 = 0.48, log 5 = 0.70)

Correct answer: 4

Step-by-step solution →
Q22·ChemistrySingle correctJEE Main 2026
Consider the general reaction given below at 400 K xA(g) ⇌ yB(g) The values of Kp_pp​ and Kc_cc​ are studied under the same condition of temperature but variation in x and y. (i) Kp_pp​ = 85.87 and Kc_cc​ = 2.586 appropriate units (ii) Kp_pp​ = 0.862 and Kc_cc​ = 28.62 appropriate units The value of x and y in (i) and (ii) respectively are:
  1. (A)(i) 3, 1 ; (ii) 3, 1
  2. (B)(i) 4, 1 ; (ii) 4, 1
  3. (C)(i) 1, 3 ; (ii) 2, 1
  4. (D)(i) 1, 2 ; (ii) 2, 1

Correct answer: (D)

Step-by-step solution →
Q23·ChemistryNumericalJEE Main 2026
X2_{2}2​(g) + Y2_{2}2​(g) ⇌ 2Z(g) X2_{2}2​(g) and Y2_{2}2​(g) are added to a 1 L flask and it is found that the system attains the above equilibrium at T(K) with the number of moles of X2_{2}2​(g) , Y2_{2}2​(g) and Z(g) being 3, 3 and 9 mol respectively (equilibrium moles). Under this conditions of equilibrium, 10 mol of Z(g) is added to the flask and the temperature is maintained at T(K). Then the number of moles of Z(g) in the flask when the new equilibrium is established is ______. (Nearest integer).

Correct answer: 15

Step-by-step solution →
Q24·ChemistryNumericalJEE Main 2026
For the following gas phase equilibrium reaction at constant temperature, NH3_33​(g) ⇌ 12\frac{1}{2}21​ N2_22​(g) + 32\frac{3}{2}23​ H2_22​(g) If the total pressure is 3\sqrt{3}3​ atm and the pressure equilibrium constant (Kp_pp​) is 9 atm, then the degree of dissociation is given as (x×10−2)−1/2(x \times 10^{-2})^{-1/2}(x×10−2)−1/2. The value of x is ______ (Nearest integer)

Correct answer: 125

Step-by-step solution →
Q25·ChemistryNumericalJEE Main 2026
Dissociation of a gas A2_22​ takes place according to the following chemical reactions. At equilibrium, the total pressure is 1 bar at 300K. A2_22​(g) ⇌ 2A(g) The standard Gibbs energy of formation of the involved substances has been provided below: Substance | ΔGf∘\Delta G_f^{\circ}ΔGf∘​ / kJ mol−1^{-1}−1 A2_22​ | −100.00 A | −50.832 The degree of dissociation of A2_22​(g) is given by (x × 10−2^{-2}−2)1/2^{1/2}1/2 where x = __________. (Nearest integer). [Given : R = 8 J mol−1^{-1}−1 K−1^{-1}−1, log 2 = 0.3010, log 3 = 0.48]

Correct answer: 33

Step-by-step solution →
Q26·ChemistrySingle correctJEE Main 2026
Which of the following mixture gives a buffer solution with pH = 9.25 ? Given : pKbpK_bpKb​ (NH4OHNH_4OHNH4​OH) = 4.75
  1. (A)0.2M NH4OHNH_4OHNH4​OH (0.4 L) + 0.1M HCl (1L)
  2. (B)0.2M NH4OHNH_4OHNH4​OH (0.5 L) + 0.1M HCl (0.5 L)
  3. (C)0.5M NH4OHNH_4OHNH4​OH (0.2 L) + 0.2M HCl (0.5 L)
  4. (D)0.4M NH4OHNH_4OHNH4​OH (1 L) + 0.1M HCl (1L)

Correct answer: (B)

Step-by-step solution →
Q27·ChemistryNumericalJEE Main 2026
The first and second ionization constants of H2X\text{H}_{2}\text{X}H2​X are 2.5×10−82.5 \times 10^{-8}2.5×10−8 and 1.0×10−131.0 \times 10^{-13}1.0×10−13 respectively. The concentration of X2−\text{X}^{2-}X2− in 0.1 M H2X\text{H}_{2}\text{X}H2​X solution is _______ ×10−15\times 10^{-15}×10−15 M. (Nearest Integer)

Correct answer: 100

Step-by-step solution →
Q28·ChemistryNumericalJEE Advanced 2025
At 25°C, the concentration of H+H^+H+ ions in 1.00×10−31.00 \times 10^{-3}1.00×10−3 M aqueous solution of a weak monobasic acid having acid dissociation constant (Ka)(K_a)(Ka​) of 4.00×10−114.00 \times 10^{-11}4.00×10−11 is X×10−7X \times 10^{-7}X×10−7 M. The value of X is ______. Use: Ionic product of water (Kw)=1.00×10−14(K_w) = 1.00 \times 10^{-14}(Kw​)=1.00×10−14 at 25°C.

Correct answer: 2.24

Step-by-step solution →
Q29·ChemistryNumericalJEE Advanced 2025
The solubility of barium iodate in an aqueous solution prepared by mixing 200 mL of 0.010 M barium nitrate with 100 mL of 0.10 M sodium iodate is X ×\times× 10−6^{-6}−6 mol dm−3^{-3}−3. The value of X is _____. Use: Solubility product constant (KspK_{sp}Ksp​) of barium iodate = 1.58 ×\times× 10−9^{-9}−9.

Correct answer: 3.95

Step-by-step solution →
Q30·ChemistryIntegerJEE Main 2025
The equilibrium constant for decomposition of H2O(g)H_2O(g)H2​O(g) (H2O(g)⇌H2(g)+12O2(g), ΔG∘=92.34 kJ mol−1)\left(H_2O(g)\rightleftharpoons H_2(g)+\dfrac{1}{2}O_2(g),\ \Delta G^\circ=92.34\ kJ\,mol^{-1}\right)(H2​O(g)⇌H2​(g)+21​O2​(g), ΔG∘=92.34 kJmol−1) is 8.0×10−38.0\times10^{-3}8.0×10−3 at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation (α\alphaα) of water is ___ ×10−2\times10^{-2}×10−2 (nearest integer value). [Assume α\alphaα is negligible with respect to 1]

Correct answer: 5

Step-by-step solution →
Q31·ChemistryIntegerJEE Main 2025
One litre buffer solution was prepared by adding 0.10 mol each of NH3NH_3NH3​ and NH4ClNH_4ClNH4​Cl in deionised water. The change in pH on addition of 0.05 mol of HCl to the above solution is __________ ×10−2\times 10^{-2}×10−2. (Nearest integer) (Given: pKbpK_bpKb​ of NH3=4.745NH_3=4.745NH3​=4.745 and log⁡103=0.477\log_{10}3=0.477log10​3=0.477)

Correct answer: 48

Step-by-step solution →
Q32·ChemistrySingle correctJEE Main 2025
An aqueous solution of HCl with pH 1.0 is diluted by adding equal volume of water (ignoring dissociation of water). The pH of HCl solution would (Given log⁡2=0.30\log 2=0.30log2=0.30)
  1. (A)reduce to 0.5
  2. (B)increase to 1.3
  3. (C)remain same
  4. (D)increase to 2

Correct answer: (B)

Step-by-step solution →
Q33·ChemistryIntegerJEE Main 2025
The pH of a 0.01 M weak acid HX (Ka=4×10−10K_a=4\times10^{-10}Ka​=4×10−10) is found to be 5. Now the acid solution is diluted with excess of water so that the pH of the solution changes to 6. The new concentration of the diluted weak acid is given as x×10−4x\times10^{-4}x×10−4 M. The value of xxx is ______ (nearest integer).

Correct answer: 25

Step-by-step solution →
Q34·ChemistryIntegerJEE Main 2025
x mg of Mg(OH)2Mg(OH)_2Mg(OH)2​ (molar mass = 58) is required to be dissolved in 1.0 L of water to produce a pH of 10.0 at 298 K. The value of x is ______ mg. (Nearest integer). (Given: Mg(OH)2Mg(OH)_2Mg(OH)2​ is assumed to dissociate completely in H2OH_2OH2​O)

Correct answer: 3

Step-by-step solution →
Q35·ChemistrySingle correctJEE Main 2025
In the following system, PCl5(g)⇌PCl3(g)+Cl2(g)PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)PCl5​(g)⇌PCl3​(g)+Cl2​(g) at equilibrium, upon addition of xenon gas at constant T \& p, the concentration of:
  1. (A)PCl5PCl_5PCl5​ will increase
  2. (B)Cl2Cl_2Cl2​ will decrease
  3. (C)PCl5PCl_5PCl5​, PCl3PCl_3PCl3​ \& Cl2Cl_2Cl2​ remain constant
  4. (D)PCl3PCl_3PCl3​ will increase

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correctJEE Main 2025
Given below are two statements. Statement I: A catalyst cannot alter the equilibrium constant (Keq)(K_{eq})(Keq​) of a reaction, temperature remaining constant. Statement II: A homogenous catalyst can change the equilibrium composition of a system, temperature remaining constant. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is true but Statement II is false

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correctJEE Main 2025
If equal volumes of AB2AB_2AB2​ and XYXYXY (both are salts) aqueous solutions are mixed, which of the following combination will give a precipitate of AY2AY_2AY2​ at 300 K? (Given KspK_{sp}Ksp​ at 300 K for AY2=5.2×10−5AY_2=5.2\times10^{-5}AY2​=5.2×10−5)
  1. (A)3.6×10−33.6\times10^{-3}3.6×10−3 M AB2AB_2AB2​, 5.0×10−45.0\times10^{-4}5.0×10−4 M XYXYXY
  2. (B)2.0×10−42.0\times10^{-4}2.0×10−4 M AB2AB_2AB2​, 0.8×10−40.8\times10^{-4}0.8×10−4 M XYXYXY
  3. (C)2.0×10−22.0\times10^{-2}2.0×10−2 M AB2AB_2AB2​, 2.0×10−22.0\times10^{-2}2.0×10−2 M XYXYXY
  4. (D)1.5×10−41.5\times10^{-4}1.5×10−4 M AB2AB_2AB2​, 1.5×10−31.5\times10^{-3}1.5×10−3 M XYXYXY

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correctJEE Main 2025
Consider the following chemical equilibrium of the gas phase reaction at a constant temperature: A(g)⇌B(g)+C(g)A(g)\rightleftharpoons B(g)+C(g)A(g)⇌B(g)+C(g). If ppp being the total pressure, KpK_pKp​ is the pressure equilibrium constant and α\alphaα is the degree of dissociation, then which of the following is true at equilibrium?
  1. (A)If ppp value is extremely high compared to KpK_pKp​, α≈1\alpha\approx1α≈1
  2. (B)When ppp increases α\alphaα decreases
  3. (C)If KpK_pKp​ value is extremely high compared to ppp, α\alphaα becomes much less than unity
  4. (D)When ppp increases α\alphaα increases

Correct answer: (B)

Step-by-step solution →
Q39·ChemistryIntegerJEE Main 2025
Consider the following equilibrium, CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)CO(g)+2H2​(g)⇌CH3​OH(g). 0.1 mol of CO along with a catalyst is present in a 2 dm3^33 flask maintained at 500 K. Hydrogen is introduced into the flask until the pressure is 5 bar and 0.04 mol of CH3OHCH_3OHCH3​OH is formed. The Kp∘K_p^\circKp∘​ is ______ ×10−3\times10^{-3}×10−3 (nearest integer). (Given R=0.08R=0.08R=0.08 dm3^33 bar K−1^{-1}−1 mol−1^{-1}−1; assume only methanol is formed and the system follows ideal gas behaviour.)

Correct answer: 74

Step-by-step solution →
Q40·ChemistrySingle correctJEE Main 2025
Consider the equilibrium CO(g)+3H2(g)⇌CH4(g)+H2O(g)CO(g)+3H_2(g)\rightleftharpoons CH_4(g)+H_2O(g)CO(g)+3H2​(g)⇌CH4​(g)+H2​O(g). If the pressure applied over the system increases by two fold at constant temperature then (A) Concentration of reactants and products increases. (B) Equilibrium will shift in forward direction. (C) Equilibrium constant increases since concentration of products increases. (D) Equilibrium constant remains unchanged as concentration of reactants and products remain same. Choose the correct answer from the options given below:
  1. (A)(A) and (B) only
  2. (B)(A), (B) and (D) only
  3. (C)(B) and (C) only
  4. (D)(A), (B) and (C) only

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correctJEE Main 2025
At temperature T, compound AB2_22​(g) dissociates as AB2(g)⇌AB(g)+12B2(g)AB_2(g)\rightleftharpoons AB(g)+\dfrac{1}{2}B_2(g)AB2​(g)⇌AB(g)+21​B2​(g) having degree of dissociation x (small compared to unity). The correct expression for x in terms of KpK_pKp​ and p is:
  1. (A)2Kpp3\sqrt[3]{\dfrac{2K_p}{p}}3p2Kp​​​
  2. (B)2Kpp\sqrt{\dfrac{2K_p}{p}}p2Kp​​​
  3. (C)2Kp2p3\sqrt[3]{\dfrac{2K_p^2}{p}}3p2Kp2​​​
  4. (D)Kp\sqrt{K_p}Kp​​

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correctJEE Main 2025
A weak acid HA has degree of dissociation x. Which option gives the correct expression of pH=pKapH=pK_apH=pKa​?
  1. (A)log⁡(1+2x)\log(1+2x)log(1+2x)
  2. (B)log⁡(1−xx)\log\left(\frac{1-x}{x}\right)log(x1−x​)
  3. (C)0
  4. (D)log⁡(x1−x)\log\left(\frac{x}{1-x}\right)log(1−xx​)

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correctJEE Main 2025
Ice and water are placed in a closed container at a pressure of 1 atm and temperature 273.15 K. If pressure of the system is increased 2 times, keeping temperature constant, then identify correct observation from following:
  1. (A)Volume of system increases.
  2. (B)Liquid phase disappears completely.
  3. (C)The amount of ice decreases.
  4. (D)The solid phase (ice) disappears completely.

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correctJEE Main 2025
Arrange the following in increasing order of solubility product: Ca(OH)2_22​, AgBr, PbS, HgS.
  1. (A)PbS < HgS < Ca(OH)2_22​ < AgBr
  2. (B)HgS < PbS < AgBr < Ca(OH)2_22​
  3. (C)Ca(OH)2_22​ < AgBr < HgS < PbS
  4. (D)HgS < AgBr < PbS < Ca(OH)2_22​

Correct answer: (B)

Step-by-step solution →
Q45·ChemistryIntegerJEE Main 2025
37.8 g N₂O₅ was taken in a 1 L reaction vessel and allowed to undergo the following reaction at 500 K: 2N2O5(g)→2N2O4(g)+O2(g)2N_2O_5(g)\to 2N_2O_4(g)+O_2(g)2N2​O5​(g)→2N2​O4​(g)+O2​(g). The total pressure at equilibrium was found to be 18.65 bar. Then, Kp=K_p=Kp​= _______ ×10−2\times10^{-2}×10−2 [nearest integer]. Assume N₂O₅ to behave ideally under these conditions. Given : R = 0.082 bar L mol⁻¹ K⁻¹

Correct answer: 962

Step-by-step solution →
Q46·ChemistrySingle correctJEE Main 2025
For the reaction, H2(g)+I2(g)⇌2HI(g)H_2(g) + I_2(g) \rightleftharpoons 2HI(g)H2​(g)+I2​(g)⇌2HI(g), the attainment of equilibrium is predicted correctly by:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q47·ChemistrySingle correctJEE Main 2025
Ksp for Cr(OH)₃ is 1.6×10−301.6\times10^{-30}1.6×10−30. What is the molar solubility of this salt in water?
  1. (A)1.6×10−30274\sqrt[4]{\dfrac{1.6\times10^{-30}}{27}}4271.6×10−30​​
  2. (B)1.8×10−101.8\times10^{-10}1.8×10−10
  3. (C)1.8×10−303\sqrt[3]{1.8\times10^{-30}}31.8×10−30​
  4. (D)1.6×10−30\sqrt{1.6\times10^{-30}}1.6×10−30​

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correctJEE Main 2025
pH of water is 7 at 25∘25^\circ25∘C. If water is heated to 80∘80^\circ80∘C, it's pH will :
  1. (A)Decrease
  2. (B)Remains the same
  3. (C)H+H^+H+ concentration increases, OH−OH^-OH− concentration decreases
  4. (D)Increase

Correct answer: (A)

Step-by-step solution →
Q49·ChemistryIntegerJEE Main 2025
If 1 mM solution of ethylamine produces pH = 9, then the ionization constant (KbK_bKb​) of ethylamine is 10−x10^{-x}10−x. The value of x is _______ (nearest integer). [The degree of ionization of ethylamine can be neglected with respect to unity.]

Correct answer: 7

Step-by-step solution →
Q50·ChemistrySingle correctJEE Main 2025
Which of the following happens when NH₄OH is added gradually to the solution containing 1M A³⁺ and 1M B³⁺ ions ? Given : Ksp[A(OH)3]=9×10−10K_{sp}[A(OH)_3]=9\times10^{-10}Ksp​[A(OH)3​]=9×10−10 and Ksp[B(OH)3]=27×10−18K_{sp}[B(OH)_3]=27\times10^{-18}Ksp​[B(OH)3​]=27×10−18 at 298 K.
  1. (A)B(OH)₃ will precipitate before A(OH)₃
  2. (B)A(OH)₃ and B(OH)₃ will precipitate together
  3. (C)A(OH)₃ will precipitate before B(OH)₃
  4. (D)Both A(OH)₃ and B(OH)₃ do not show precipitation with NH₄OH

Correct answer: (A)

Step-by-step solution →
Q51·ChemistrySingle correctJEE Main 2025
Consider the reaction X2Y(g)⇌X2(g)+12Y2(g)X_2Y(g)\rightleftharpoons X_2(g)+\tfrac12 Y_2(g)X2​Y(g)⇌X2​(g)+21​Y2​(g). The equation representing correct relationship between the degree of dissociation (x)(x)(x) of X2Y(g)X_2Y(g)X2​Y(g) with its equilibrium constant KpK_pKp​ is __________. Assume xxx to be very very small.
  1. (A)x=2Kppx=\sqrt{\dfrac{2K_p}{p}}x=p2Kp​​​
  2. (B)x=2Kp2p3x=\sqrt[3]{\dfrac{2K_p^2}{p}}x=3p2Kp2​​​
  3. (C)x=Kp2px=\sqrt{\dfrac{K_p}{2p}}x=2pKp​​​
  4. (D)x=Kpp3x=\sqrt[3]{\dfrac{K_p}{p}}x=3pKp​​​

Correct answer: (B)

Step-by-step solution →
Q52·ChemistrySingle correctJEE Main 2025
The molar solubility(s) of zirconium phosphate with molecular formula (Zr4+)3(PO43−)4(Zr^{4+})_3(PO_4^{3-})_4(Zr4+)3​(PO43−​)4​ is given by relation:
  1. (A)(Ksp6912)1/7\left(\frac{K_{sp}}{6912}\right)^{1/7}(6912Ksp​​)1/7
  2. (B)(Ksp5348)1/6\left(\frac{K_{sp}}{5348}\right)^{1/6}(5348Ksp​​)1/6
  3. (C)(Ksp8435)1/7\left(\frac{K_{sp}}{8435}\right)^{1/7}(8435Ksp​​)1/7
  4. (D)(Ksp9612)1/3\left(\frac{K_{sp}}{9612}\right)^{1/3}(9612Ksp​​)1/3

Correct answer: (A)

Step-by-step solution →
Q53·ChemistrySingle correctJEE Main 2025
A vessel at 1000 K contains CO₂ at a pressure of 0.5 atm. Some of the CO₂ is converted into CO on addition of graphite. If the total pressure at equilibrium is 0.8 atm, then Kp is:
  1. (A)0.18 atm
  2. (B)1.8 atm
  3. (C)0.3 atm
  4. (D)3 atm

Correct answer: (B)

Step-by-step solution →
Q54·ChemistrySingle correctJEE Main 2024
For a sparingly soluble salt AB2AB_2AB2​, the equilibrium concentrations of A2+A^{2+}A2+ ions and B−B^{-}B− ions are 1.2×10−41.2\times10^{-4}1.2×10−4 M and 0.24×10−30.24\times10^{-3}0.24×10−3 M, respectively. The solubility product of AB2AB_2AB2​ is:
  1. (A)0.069×10−120.069\times10^{-12}0.069×10−12
  2. (B)6.91×10−126.91\times10^{-12}6.91×10−12
  3. (C)0.276×10−120.276\times10^{-12}0.276×10−12
  4. (D)27.65×10−1227.65\times10^{-12}27.65×10−12

Correct answer: (B)

Step-by-step solution →
Q55·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement (I): A buffer solution is the mixture of a salt and an acid or a base mixed in any particular quantities. Statement (II): Blood is naturally occurring buffer solution whose pH is maintained by H2CO3/HCO3−\text{H}_2\text{CO}_3/\text{HCO}_3^-H2​CO3​/HCO3−​ concentrations. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II is true
  3. (C)Both Statement I and Statement II is false
  4. (D)Statement I is true but Statement II is false

Correct answer: (A)

Step-by-step solution →
Q56·ChemistrySingle correctJEE Main 2024
For the given hypothetical reactions, the equilibrium constants are as follows: X⇌YX\rightleftharpoons YX⇌Y; K1=1.0K_1=1.0K1​=1.0; Y⇌ZY\rightleftharpoons ZY⇌Z; K2=2.0K_2=2.0K2​=2.0; Z⇌WZ\rightleftharpoons WZ⇌W; K3=4.0K_3=4.0K3​=4.0. The equilibrium constant for the reaction X⇌WX\rightleftharpoons WX⇌W is:
  1. (A)6.06.06.0
  2. (B)12.012.012.0
  3. (C)8.08.08.0
  4. (D)7.07.07.0

Correct answer: (C)

Step-by-step solution →
Q57·ChemistrySingle correctJEE Main 2024
At −20 ∘-20\,^{\circ}−20∘C and 1 atm pressure, a cylinder is filled with equal number of H2H_2H2​, I2I_2I2​ and HIHIHI molecules for the reaction H2(g)+I2(g)⇌2HI(g)H_2(g) + I_2(g) \rightleftharpoons 2HI(g)H2​(g)+I2​(g)⇌2HI(g). The KPK_PKP​ for the process is x×10−1x\times10^{-1}x×10−1. The value of xxx is: (Given: R=0.082R=0.082R=0.082 L atm K−1^{-1}−1 mol−1^{-1}−1)
  1. (A)2
  2. (B)1
  3. (C)10
  4. (D)0.01

Correct answer: (C)

Step-by-step solution →
Q58·ChemistrySingle correctJEE Main 2024
The ratio KPKC\dfrac{K_P}{K_C}KC​KP​​ for the reaction: CO(g)+12O2(g)⇌CO2(g)CO_{(g)} + \dfrac{1}{2}O_{2(g)} \rightleftharpoons CO_{2(g)}CO(g)​+21​O2(g)​⇌CO2(g)​ is:
  1. (A)(RT)1/2(RT)^{1/2}(RT)1/2
  2. (B)RTRTRT
  3. (C)111
  4. (D)1RT\dfrac{1}{\sqrt{RT}}RT​1​

Correct answer: (D)

Step-by-step solution →
Q59·ChemistrySingle correctJEE Main 2024
The following reaction occurs in the blast furnace where iron ore is reduced to iron metal: Fe2O3(s)+3CO(g)→2Fe(l)+3CO2(g)\text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g)Fe2​O3​(s)+3CO(g)→2Fe(l)+3CO2​(g). Using Le Chatelier’s principle, predict which one of the following will not disturb the equilibrium.
  1. (A)Addition of Fe2O3\text{Fe}_2\text{O}_3Fe2​O3​
  2. (B)Addition of CO2\text{CO}_2CO2​
  3. (C)Removal of CO
  4. (D)Removal of CO2\text{CO}_2CO2​

Correct answer: (A)

Step-by-step solution →
Q60·ChemistrySingle correctJEE Main 2024
The equilibrium constant for the reaction SO3(g)⇌SO2(g)+12O2(g)\text{SO}_3(g)\rightleftharpoons\text{SO}_2(g)+\tfrac{1}{2}\text{O}_2(g)SO3​(g)⇌SO2​(g)+21​O2​(g) is KC=4.9×10−2K_C=4.9\times10^{-2}KC​=4.9×10−2. The value of KCK_CKC​ for the reaction 2SO2(g)+O2(g)⇌2SO3(g)2\text{SO}_2(g)+\text{O}_2(g)\rightleftharpoons 2\text{SO}_3(g)2SO2​(g)+O2​(g)⇌2SO3​(g) given below is
  1. (A)4.9
  2. (B)41.6
  3. (C)49
  4. (D)416

Correct answer: (D)

Step-by-step solution →
Q61·ChemistryNumericalJEE Main 2024
KaK_aKa​ for CH3COOHCH_3COOHCH3​COOH is 1.8×10−51.8\times10^{-5}1.8×10−5 and KbK_bKb​ for NH4OHNH_4OHNH4​OH is 1.8×10−51.8\times10^{-5}1.8×10−5. The pH of ammonium acetate solution will be ___

Correct answer: 7

Step-by-step solution →
Q62·ChemistrySingle correctJEE Main 2024
Solubility of calcium phosphate (molecular mass, M) in water is WgW_gWg​ per 100 mL at 25∘25^{\circ}25∘ C. Its solubility product at 25∘25^{\circ}25∘C will be approximately:
  1. (A)107(WM)310^7\left(\dfrac{W}{M}\right)^3107(MW​)3
  2. (B)107(WM)510^7\left(\dfrac{W}{M}\right)^5107(MW​)5
  3. (C)103(WM)510^3\left(\dfrac{W}{M}\right)^5103(MW​)5
  4. (D)105(WM)510^5\left(\dfrac{W}{M}\right)^5105(MW​)5

Correct answer: (B)

Step-by-step solution →
Q63·ChemistrySingle correctJEE Main 2024
A(g)⇌B(g)+C2(g)A_{(g)}\rightleftharpoons B_{(g)}+\dfrac{C}{2}_{(g)}A(g)​⇌B(g)​+2C​(g)​. The correct relationship between KPK_PKP​ and equilibrium pressure P is
  1. (A)KP=α3/2P1/2(2+α)1/2K_P=\dfrac{\alpha^{3/2}P^{1/2}}{(2+\alpha)^{1/2}}KP​=(2+α)1/2α3/2P1/2​
  2. (B)KP=α3/2P1/2(2+α)1/2(1−α)K_P=\dfrac{\alpha^{3/2}P^{1/2}}{(2+\alpha)^{1/2}(1-\alpha)}KP​=(2+α)1/2(1−α)α3/2P1/2​
  3. (C)KP=α1/2P3/2(2+α)3/2K_P=\dfrac{\alpha^{1/2}P^{3/2}}{(2+\alpha)^{3/2}}KP​=(2+α)3/2α1/2P3/2​
  4. (D)KP=α1/2P1/2(2+α)3/2K_P=\dfrac{\alpha^{1/2}P^{1/2}}{(2+\alpha)^{3/2}}KP​=(2+α)3/2α1/2P1/2​

Correct answer: (B)

Step-by-step solution →
Q64·ChemistryNumericalJEE Main 2024
Consider the following reaction at 298 K. 32O2(g)⇌O3(g)\dfrac{3}{2}O_{2(g)}\rightleftharpoons O_{3(g)}23​O2(g)​⇌O3(g)​. KP=2.47×10−29K_P=2.47\times10^{-29}KP​=2.47×10−29. ΔrG⊖\Delta_r G^\ominusΔr​G⊖ for the reaction is ______ kJ. (Given R = 8.314 JK−1^{-1}−1 mol−1^{-1}−1)

Correct answer: 163

Step-by-step solution →
Q65·ChemistrySingle correctJEE Main 2024
For the given reaction, choose the correct expression of KCK_CKC​ from the following :- Fe(aq)3++SCN(aq)−⇌(FeSCN)(aq)2+Fe^{3+}_{(aq)}+SCN^-_{(aq)}\rightleftharpoons (FeSCN)^{2+}_{(aq)}Fe(aq)3+​+SCN(aq)−​⇌(FeSCN)(aq)2+​
  1. (A)KC=[FeSCN2+][Fe3+][SCN−]K_C=\dfrac{[FeSCN^{2+}]}{[Fe^{3+}][SCN^-]}KC​=[Fe3+][SCN−][FeSCN2+]​
  2. (B)KC=[Fe3+][SCN−][FeSCN2+]K_C=\dfrac{[Fe^{3+}][SCN^-]}{[FeSCN^{2+}]}KC​=[FeSCN2+][Fe3+][SCN−]​
  3. (C)KC=[FeSCN2+][Fe3+]2[SCN−]2K_C=\dfrac{[FeSCN^{2+}]}{[Fe^{3+}]^2[SCN^-]^2}KC​=[Fe3+]2[SCN−]2[FeSCN2+]​
  4. (D)KC=[FeSCN2+]2[Fe3+][SCN−]K_C=\dfrac{[FeSCN^{2+}]^2}{[Fe^{3+}][SCN^-]}KC​=[Fe3+][SCN−][FeSCN2+]2​

Correct answer: (A)

Step-by-step solution →
Q66·ChemistryNumericalJEE Main 2024
The pH at which Mg(OH)2Mg(OH)_2Mg(OH)2​ [Ksp=1×10−11][K_{sp}=1\times10^{-11}][Ksp​=1×10−11] begins to precipitate from a solution containing 0.10 M0.10\,M0.10M Mg2+Mg^{2+}Mg2+ ions is ___

Correct answer: 9

Step-by-step solution →
Q67·ChemistryNumericalJEE Main 2024
The pH of an aqueous solution containing 1M benzoic acid (pKa=4.20pK_a=4.20pKa​=4.20) and 1M sodium benzoate is 4.5. The volume of benzoic acid solution in 300 mL of this buffer solution is ______ mL.

Correct answer: 100

Step-by-step solution →
Q68·ChemistryNumericalJEE Main 2024
For the reaction N2O4(g)⇌2NO2(g)N_2O_4(g)\rightleftharpoons 2NO_2(g)N2​O4​(g)⇌2NO2​(g), Kp=0.492K_p=0.492Kp​=0.492 atm at 300 K. KcK_cKc​ for the reaction at same temperature is ______ ×10−2\times10^{-2}×10−2. (Given : R = 0.082 L atm mol−1^{-1}−1 K−1^{-1}−1)

Correct answer: 2

Step-by-step solution →
Q69·ChemistryNumericalJEE Main 2024
The following concentrations were observed at 500 K for the formation of NH3NH_3NH3​ from N2N_2N2​ and H2H_2H2​. At equilibrium [N2]=2×10−2[N_2]=2\times10^{-2}[N2​]=2×10−2 M, [H2]=3×10−2[H_2]=3\times10^{-2}[H2​]=3×10−2 M and [NH3]=1.5×10−3[NH_3]=1.5\times10^{-3}[NH3​]=1.5×10−3 M. Equilibrium constant for the reaction is ___ ×10−2\times10^{-2}×10−2.

Correct answer: 417

Step-by-step solution →
Q70·ChemistrySingle correctJEE Main 2024
Given below are two statements: Statement (I): Aqueous solution of ammonium carbonate is basic. Statement (II): Acidic/basic nature of salt solution of a salt of weak acid and weak base depends on KaK_aKa​ and KbK_bKb​ value of acid and the base forming it. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (A)

Step-by-step solution →
Q71·ChemistrySingle correctJEE Advanced 2023
On decreasing the pH from 7 to 2, the solubility of a sparingly soluble salt (MX) of a weak acid (HX) increased from 10−4 mol L−110^{-4}\ \mathrm{mol\ L^{-1}}10−4 mol L−1 to 10−3 mol L−110^{-3}\ \mathrm{mol\ L^{-1}}10−3 mol L−1. The pKa\mathrm{pK_a}pKa​ of HX is
  1. (A)3
  2. (B)4
  3. (C)5
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q72·ChemistrySingle correctJEE Main 2023
Which of the following statement(s) is/are correct? (A) The pH of 1×10−81 \times 10^{-8}1×10−8 M HCl solution is 8. (B) The conjugate base H2PO4−H_2PO_4^-H2​PO4−​ is HPO42−HPO_4^{2-}HPO42−​. (C) KwK_wKw​ increases with increase in temperature. (D) When a solution of weak monoprotic acid is titrated against a strong base at half neutralisation point, pH=12pKapH = \frac{1}{2}pK_apH=21​pKa​. Choose the correct answer from the option given below.
  1. (A)(B), (C), (D)
  2. (B)(A), (D)
  3. (C)(A), (B), (C)
  4. (D)(B), (C)

Correct answer: (D)

Step-by-step solution →
Q73·ChemistryNumericalJEE Main 2023
20 mL of 0.1 M NaOH is added to 50 mL of 0.1 M acetic acid solution. The pH of the resulting solution is ____ ×10−2\times 10^{-2}×10−2 (Nearest integer). Given: pKa (CH3COOH)=4.76(CH_3COOH) = 4.76(CH3​COOH)=4.76.

Correct answer: 448

Step-by-step solution →
Q74·ChemistryNumericalJEE Main 2023
25.0 mL25.0\,mL25.0mL of 0.050 M Ba(NO3)20.050\,M\,Ba(NO_{3})_{2}0.050MBa(NO3​)2​ is mixed with 25.0 mL25.0\,mL25.0mL of 0.020 M NaF0.020\,M\,NaF0.020MNaF. KspK_{sp}Ksp​ of BaF2BaF_{2}BaF2​ is 0.5×10−60.5\times10^{-6}0.5×10−6 at 298 K298\,K298K. The ratio of [Ba2+][F−]2[Ba^{2+}][F^{-}]^{2}[Ba2+][F−]2 and KspK_{sp}Ksp​ is _____ (Nearest integer).

Correct answer: 5

Step-by-step solution →
Q75·ChemistryNumericalJEE Main 2023
An analyst wants to convert 1L HCl of pH = 1 to a solution of HCl at pH 2. The volume of water needed to do this dilution is _________ mL. (Nearest Integer)

Correct answer: 9000

Step-by-step solution →
Q76·ChemistryNumericalJEE Main 2023
One mole of an ideal gas at 350K is in a 2.0 L vessel of thermally conducting walls, which are in contact with the surroundings. It undergoes isothermal reversible expansion from 2.0L to 3.0L against a constant pressure of 4 atm. The change in entropy of the surroundings (ΔS)(\Delta S)(ΔS) is _________ J K−1^{-1}−1 (Nearest integer). Given: R = 8.314 J K−1^{-1}−1 mol−1^{-1}−1.

Correct answer: 3

Step-by-step solution →
Q77·ChemistryNumericalJEE Main 2023
A mixture of 1 mole of H2OH_2OH2​O and 1 mole of CO is taken in a 10 litre container and heated to 725 K. At equilibrium 40% of water by mass reacts with carbon monoxide according to the equation: CO(g)+H2O(g)⇌CO2(g)+H2(g)CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g)CO(g)+H2​O(g)⇌CO2​(g)+H2​(g). The equilibrium constant KC×102K_C \times 10^2KC​×102 for the reaction is __________. (Nearest integer)

Correct answer: 44

Step-by-step solution →
Q78·ChemistryNumericalJEE Main 2023
4.5 moles each of hydrogen and iodine are heated in a sealed ten litre vessel. At equilibrium, 3 moles of HI were found. The equilibrium constant for H2(g)+I2(g)⇌2HI(g)H_2(g)+I_2(g)\rightleftharpoons 2HI(g)H2​(g)+I2​(g)⇌2HI(g) is ____.

Correct answer: 1

Step-by-step solution →
Q79·ChemistryNumericalJEE Main 2023
A(g)⇌2B(g)+C(g)\text{A}(g)\rightleftharpoons 2\text{B}(g)+\text{C}(g)A(g)⇌2B(g)+C(g). For the given reaction, if the initial pressure was 450450450 mm Hg and the pressure at time t is 720720720 mm Hg at constant temperature T and constant volume V, the fraction of A(g)\text{A}(g)A(g) decomposed under these conditions is x×10−1x\times10^{-1}x×10−1. The value of x is _______ (nearest integer).

Correct answer: 3

Step-by-step solution →
Q80·ChemistryNumericalJEE Main 2023
The number of incorrect statement/s involving equilibria in physical process from the following is _________. (A) Equilibrium is possible only in a closed system at a given temperature. (B) Both the opposing processes occur at the same rate. (C) When equilibrium is attained at a given temperature, the value of all its parameters becomes equal. (D) For dissolution of solids in liquids, the solubility is constant at a given temperature.

Correct answer: 3

Step-by-step solution →
Q81·ChemistryNumericalJEE Main 2023
The titration curve of weak acid vs. strong base with phenolphthalein as indicator) is shown below. The Kphenolphthalein=4×10−10K_{phenolphthalein} = 4 \times 10^{-10}Kphenolphthalein​=4×10−10. Given: log⁡2=0.3\log 2 = 0.3log2=0.3. The number of following statements which is/are correct about phenolphthalein is ____ A. It can be used as an indicator for the titration of weak acid with weak base. B. It begins to change colour at pH=8.4pH = 8.4pH=8.4 C. It is a weak organic base D. It is colourless in acidic medium

Correct answer: 2

Step-by-step solution →
Q82·ChemistryNumericalJEE Main 2023
The solubility product of BaSO4BaSO_4BaSO4​ is 1×10−101\times10^{-10}1×10−10 at 298 K. The solubility of BaSO4BaSO_4BaSO4​ in 0.10.10.1 M K2SO4(aq)K_2SO_4(aq)K2​SO4​(aq) solution is ____ ×10−9\times10^{-9}×10−9 g L−1^{-1}−1 (nearest integer). Given: Molar mass of BaSO4BaSO_4BaSO4​ is 233233233 g mol−1^{-1}−1.

Correct answer: 233

Step-by-step solution →
Q83·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: Methyl orange is a weak acid. Statement II: The benzenoid form of methyl orange is more intense/deeply coloured than the quinonoid form. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but Statement II is incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (C)

Step-by-step solution →
Q84·ChemistrySingle correctJEE Main 2023
Given below are two statements: Statement I: In redox titration, the indicators used are sensitive to change in pH of the solution. Statement II: In acid-base titration, the indicators used are sensitive to change in oxidation potential. In the light of the above statements, choose the most appropriate answer from the options given below.
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are incorrect

Correct answer: (D)

Step-by-step solution →
Q85·ChemistryNumericalJEE Main 2023
The equilibrium composition for the reaction PCl3+Cl2⇌PCl5PCl_3 + Cl_2 \rightleftharpoons PCl_5PCl3​+Cl2​⇌PCl5​ at 298 K is given below. [PCl3]eq=0.2[PCl_3]_{eq} = 0.2[PCl3​]eq​=0.2 mol L−1L^{-1}L−1, [Cl2]eq=0.1[Cl_2]_{eq} = 0.1[Cl2​]eq​=0.1 mol L−1L^{-1}L−1, [PCl5]eq=0.40[PCl_5]_{eq} = 0.40[PCl5​]eq​=0.40 mol L−1L^{-1}L−1. If 0.2 mol of Cl2Cl_2Cl2​ is added at the same temperature, the equilibrium concentration of PCl5PCl_5PCl5​ is ____ ×10−2\times 10^{-2}×10−2 mol L−1L^{-1}L−1. (Given: KcK_cKc​ for the reaction at 298 K is 20)

Correct answer: 48

Step-by-step solution →
Q86·ChemistrySingle correctJEE Main 2023
For a concentrated solution of a weak electrolyte (Keq=(K_{eq}=(Keq​= equilibrium constant))) A2B3A_2B_3A2​B3​ of concentration ccc, the degree of dissociation α\alphaα is:
  1. (A)(Keq108c4)1/5\left(\dfrac{K_{eq}}{108c^{4}}\right)^{1/5}(108c4Keq​​)1/5
  2. (B)(Keq6c2)1/2\left(\dfrac{K_{eq}}{6c^{2}}\right)^{1/2}(6c2Keq​​)1/2
  3. (C)(Keq5c4)1/5\left(\dfrac{K_{eq}}{5c^{4}}\right)^{1/5}(5c4Keq​​)1/5
  4. (D)(Keq25c4)1/3\left(\dfrac{K_{eq}}{25c^{4}}\right)^{1/3}(25c4Keq​​)1/3

Correct answer: (A)

Step-by-step solution →
Q87·ChemistryNumericalJEE Main 2023
The value of log⁡K\log KlogK for the reaction A⇌BA\rightleftharpoons BA⇌B at 298 K298\,K298K is _____. (Nearest integer) Given: ΔH∘=−54.07 kJ mol−1, ΔS∘=10 J K−1 mol−1\Delta H^\circ=-54.07\,kJ\,mol^{-1},\,\Delta S^\circ=10\,J\,K^{-1}\,mol^{-1}ΔH∘=−54.07kJmol−1,ΔS∘=10JK−1mol−1. (Take 2.303×8.314×298=57052.303\times8.314\times298=57052.303×8.314×298=5705)

Correct answer: 10

Step-by-step solution →
Q88·ChemistrySingle correctJEE Main 2023
The effect of addition of helium gas to the following reaction in equilibrium state, is: PCl5(g)⇌PCl3(g)+Cl2(g)PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)PCl5​(g)⇌PCl3​(g)+Cl2​(g)
  1. (A)helium will deactivate PCl5PCl_5PCl5​ and reaction will stop.
  2. (B)the equilibrium will shift in the forward direction and more of Cl2Cl_2Cl2​ and PCl3PCl_3PCl3​ gases will be produced.
  3. (C)the equilibrium will go backward due to suppression of dissociation of PCl5PCl_5PCl5​.
  4. (D)addition of helium will not affect the equilibrium.

Correct answer: (B)

Step-by-step solution →
Q89·ChemistryNumericalJEE Main 2023
For the equilibria (i) X(g)⇌Y(g)+Z(g)\text{X(g)}\rightleftharpoons \text{Y(g)}+\text{Z(g)}X(g)⇌Y(g)+Z(g), Kp1=3K_{p_1}=3Kp1​​=3 and (ii) A(g)⇌2B(g)\text{A(g)}\rightleftharpoons 2\text{B(g)}A(g)⇌2B(g), Kp2=1K_{p_2}=1Kp2​​=1. If the degree of dissociation and initial concentration of both the reactants X(g)\text{X(g)}X(g) and A(g)\text{A(g)}A(g) are equal, then the ratio of the total pressure at equilibrium (p1p2)\left(\tfrac{p_1}{p_2}\right)(p2​p1​​) is equal to x:1x:1x:1. The value of xxx is _______ (Nearest integer).

Correct answer: 12

Step-by-step solution →
Q90·ChemistryNumericalJEE Main 2023
For reaction: SO2(g)+12O2(g)⇌SO3(g)SO_2(g) + \frac{1}{2}O_2(g) \rightleftharpoons SO_3(g)SO2​(g)+21​O2​(g)⇌SO3​(g), Kp=2×1012K_p = 2 \times 10^{12}Kp​=2×1012 at 27∘C27^{\circ}C27∘C and 1 atm pressure. The KcK_cKc​ for the same reaction is ___ ×1013\times 10^{13}×1013. (Nearest integer) (Given R=0.082 L atm K−1 mol−1R = 0.082\ L\,atm\,K^{-1}\,mol^{-1}R=0.082 LatmK−1mol−1)

Correct answer: 1

Step-by-step solution →
Q91·ChemistrySingle correctJEE Main 2023
Incorrect statement for the use of indicators in acid-base titration is:
  1. (A)Methyl orange may be used for a weak acid vs weak base titration.
  2. (B)Phenolphthalein is a suitable indicator for a weak acid vs strong base titration.
  3. (C)Methyl orange is a suitable indicator for a strong acid vs weak base titration.
  4. (D)Phenolphthalein may be used for a strong acid vs strong base titration.

Correct answer: (A)

Step-by-step solution →
Q92·ChemistryNumericalJEE Main 2023
At 298 K, the solubility of silver chloride in water is 1.434×10−31.434\times10^{-3}1.434×10−3 g L−1^{-1}−1. The value of −log⁡Ksp-\log K_{sp}−logKsp​ for silver chloride is _________ (Given mass of Ag is 107.9 g mol−1^{-1}−1 and mass of Cl is 35.5 g mol−1^{-1}−1)

Correct answer: 10

Step-by-step solution →
Q93·ChemistryNumericalJEE Main 2023
Consider the equilibrium 2SO2(g)+O2(g)⇌2SO3(g)2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)2SO2​(g)+O2​(g)⇌2SO3​(g), ΔH=−190\Delta H=-190ΔH=−190 kJ. The number of factors from the following which will increase the yield of SO3SO_3SO3​ at equilibrium is _______: A. Increasing temperature, B. Increasing pressure, C. Adding more SO2SO_2SO2​, D. Adding more O2O_2O2​, E. Addition of catalyst.

Correct answer: 3

Step-by-step solution →
Q94·ChemistryNumericalJEE Main 2023
600600600 mL of 0.010.010.01 M HCl is mixed with 400400400 mL of 0.010.010.01 M H2_22​SO4_44​. The pH of the mixture is _________ ×10−2\times10^{-2}×10−2. (Nearest integer) [Given log 2 = 0.30, log 3 = 0.48, log 5 = 0.69, log 7 = 0.84, log 11 = 1.04]

Correct answer: 186

Step-by-step solution →
Q95·ChemistryNumericalJEE Main 2023
At 298 K298\,K298K N2(g)+3H2(g)⇌2NH3(g), K1=4×105N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g),\,K_1=4\times10^5N2​(g)+3H2​(g)⇌2NH3​(g),K1​=4×105 N2(g)+O2(g)⇌2NO(g), K2=1.6×1012N_2(g)+O_2(g)\rightleftharpoons 2NO(g),\,K_2=1.6\times10^{12}N2​(g)+O2​(g)⇌2NO(g),K2​=1.6×1012 H2(g)+12O2(g)⇌H2O(g), K3=1.0×10−13H_2(g)+\dfrac12 O_2(g)\rightleftharpoons H_2O(g),\,K_3=1.0\times10^{-13}H2​(g)+21​O2​(g)⇌H2​O(g),K3​=1.0×10−13 Based on above equilibria, the equilibrium constant of the reaction, 2NH3(g)+52O2(g)⇌2NO(g)+3H2O(g)2NH_3(g)+\dfrac52 O_2(g)\rightleftharpoons 2NO(g)+3H_2O(g)2NH3​(g)+25​O2​(g)⇌2NO(g)+3H2​O(g) is _____ ×10−33\times10^{-33}×10−33 (Nearest integer).

Correct answer: 4

Step-by-step solution →
Q96·ChemistryNumericalJEE Main 2023
Water decomposes at 2300 K: H2_22​O(g) →\rightarrow→ H2_22​(g) + 12\dfrac{1}{2}21​O2_22​(g). The percent of water decomposing at 2300 K and 1 bar is ________ (Nearest integer). Equilibrium constant for the reaction is 2×10−32 \times 10^{-3}2×10−3 at 2300 K.

Correct answer: 2

Step-by-step solution →
Q97·ChemistryNumericalJEE Main 2023
Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is x×10−1x \times 10^{-1}x×10−1. The value of xxx is ________ (Nearest integer). Assume complete dissociation.

Correct answer: 5

Step-by-step solution →
Q98·ChemistrySingle correctJEE Main 2023
When the hydrogen ion concentration [H+][H^+][H+] changes by a factor of 100010001000, the value of pH of the solution
  1. (A)increases by 2 units
  2. (B)increases by 1000 units
  3. (C)decreases by 2 units
  4. (D)decreases by 3 units

Correct answer: (D)

Step-by-step solution →
Q99·ChemistryNumericalJEE Main 2023
A litre of buffer solution contains 0.1 mole of each of NH3NH_3NH3​ and NH4ClNH_4ClNH4​Cl. On the addition of 0.02 mole of HCl by dissolving gaseous HCl, the pH of the solution is found to be _______ ×10−3\times10^{-3}×10−3 (nearest integer). (Given: pKb(NH3)=4.745pK_b(NH_3)=4.745pKb​(NH3​)=4.745, log⁡2=0.301\log 2=0.301log2=0.301, log⁡3=0.477\log 3=0.477log3=0.477, T = 298 K)

Correct answer: 9

Step-by-step solution →
Q100·ChemistryNumericalJEE Main 2023
If the pKapK_apKa​ of lactic acid is 555, then the pH of 0.0050.0050.005 M calcium lactate solution at 25 ∘C25\,^\circ C25∘C is _________ ×10−1\times10^{-1}×10−1 (Nearest integer)

Correct answer: 85

Step-by-step solution →
Q101·ChemistryNumericalJEE Main 2023
The dissociation constant of acetic acid is x×10−5x\times10^{-5}x×10−5. When 25 mL of 0.2 M CH3COONa\text{CH}_3\text{COONa}CH3​COONa solution is mixed with 25 mL of 0.02 M CH3COOH\text{CH}_3\text{COOH}CH3​COOH solution, the pH of the resultant solution is found to be equal to 5. The value of xxx is _______ .

Correct answer: 10

Step-by-step solution →
Q102·ChemistryIntegerJEE Advanced 2022
Concentration of H2SO4\mathrm{H_2SO_4}H2​SO4​ and Na2SO4\mathrm{Na_2SO_4}Na2​SO4​ in a solution is 1 M and 1.8×10−21.8 \times 10^{-2}1.8×10−2 M, respectively. Molar solubility of PbSO4\mathrm{PbSO_4}PbSO4​ in the same solution is X×10−Y\mathrm{X} \times 10^{-\mathrm{Y}}X×10−Y M (expressed in scientific notation). The value of Y is____. [Given : Solubility product of PbSO4(Ksp)=1.6×10−8\mathrm{PbSO_4}\left(\mathrm{K_{sp}}\right) = 1.6 \times 10^{-8}PbSO4​(Ksp​)=1.6×10−8. For H2SO4\mathrm{H_2SO_4}H2​SO4​, Ka1\mathrm{K_{a_1}}Ka1​​ is very large and Ka2=1.2×10−2\mathrm{K_{a_2}} = 1.2 \times 10^{-2}Ka2​​=1.2×10−2]

Correct answer: 6

Step-by-step solution →
Q103·ChemistryNumericalJEE Advanced 2022
A solution is prepared by mixing 0.01 mol each of H2CO3\mathrm{H_2CO_3}H2​CO3​, NaHCO3\mathrm{NaHCO_3}NaHCO3​, Na2CO3\mathrm{Na_2CO_3}Na2​CO3​, and NaOH in 100 mL of water. pH of the resulting solution is ________. [Given: pKa1p\mathrm{Ka_1}pKa1​ and pKa2p\mathrm{Ka_2}pKa2​ of H2CO3\mathrm{H_2CO_3}H2​CO3​ are 6.37 and 10.32, respectively; log⁡2=0.30\log 2 = 0.30log2=0.30]

Correct answer: 10.02

Step-by-step solution →
Q104·ChemistrySingle correctJEE Main 2022
200 mL of 0.01 M HCl is mixed with 400 mL of 0.01M H2_{2}2​SO4_{4}4​. The pH of the mixture is ____.
  1. (A)1.14
  2. (B)1.78
  3. (C)2.34
  4. (D)3.02

Correct answer: (B)

Step-by-step solution →
Q105·ChemistrySingle correctJEE Main 2022
A compound 'X' is a weak acid and it exhibits colour change at pH close to the equivalence point during neutralization of NaOH with CH3_{3}3​COOH. Compound 'X' exists in ionized form in basic medium. The compound 'X' is :
  1. (A)methyl orange
  2. (B)methyl red
  3. (C)phenolphthalein
  4. (D)erichrome Black T

Correct answer: (C)

Step-by-step solution →
Q106·ChemistryNumericalJEE Main 2022
If the solubility product of PbS is 8 × 10−2810^{-28}10−28, then the solubility of PbS in pure water at 298 K is x × 10−1610^{-16}10−16 mol L−1L^{-1}L−1. The value of x is ________. (Nearest Integer) [Given 2\sqrt{2}2​ = 1.41]

Correct answer: 282

Step-by-step solution →
Q107·ChemistryNumericalJEE Main 2022
Ka_aa​ for butyric acid (C3_33​H7_77​COOH) is 2 × 10−5^{-5}−5. The pH of 0.2 M solution of butyric acid is ___ × 10−1^{-1}−1. (Nearest integer) [Given log 2 = 0.30]

Correct answer: 27

Step-by-step solution →
Q108·ChemistryNumericalJEE Main 2022
At 600K, 2 mol of NO are mixed with 1 mol of O2\mathrm{O_2}O2​. 2NO(g)+O2(g)⇌2NO2(g)2\mathrm{NO_{(g)}} + \mathrm{O_2(g)} \rightleftharpoons 2\mathrm{NO_2(g)}2NO(g)​+O2​(g)⇌2NO2​(g) The reaction occurring as above comes to equilibrium under a total pressure of 1 atom. Analysis of the system shows that 0.6 mol of oxygen are present at equilibrium. The equilibrium constant for the reaction is _____. (Nearest integer).

Correct answer: 2

Step-by-step solution →
Q109·ChemistryNumericalJEE Main 2022
At 310 K, the solubility of CaF2CaF_{2}CaF2​ in water is 2.34×10−32.34 \times 10^{-3}2.34×10−3 g /100 mL. The solubility product of CaF2CaF_{2}CaF2​ is ___ ×10−8\times 10^{-8}×10−8 (mol/L)3(mol/L)^{3}(mol/L)3. (Given molar mass : CaF2CaF_{2}CaF2​ = 78 g mol−1mol^{-1}mol−1)

Correct answer: 0

Step-by-step solution →
Q110·ChemistrySingle correctJEE Main 2022
The Plot of pH-metric titration of weak base NH4_{4}4​OH vs strong acid HCl looks like:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q111·ChemistrySingle correctJEE Main 2022
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A :Phenolphthalein is a pH dependent indicator, remains colourless in acidic solution and gives pink colour in basic medium Reason R : Phenolphthalein is a weak acid. It doesn't dissociate in basic medium. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (C)

Step-by-step solution →
Q112·ChemistryNumericalJEE Main 2022
At 298 K, the equilibrium constant is 2 × 1015^{15}15 for the reaction : Cu(s) + 2Ag+^{+}+(aq) ⇌ Cu2+^{2+}2+(aq) + 2Ag(s) The equilibrium constant for the reaction 12\frac{1}{2}21​Cu2+^{2+}2+(aq) + Ag(s) ⇌ 12\frac{1}{2}21​Cu(s) + Ag+^{+}+(aq) is x × 10−8^{-8}−8. The value of x is________. (Nearest Integer)

Correct answer: 2

Step-by-step solution →
Q113·ChemistrySingle correctJEE Main 2022
Class XII students were asked to prepare one litre of buffer solution of pH 8.26 by their chemistry teacher. The amount of ammonium chloride to be dissolved by the student in 0.2 M ammonia solution to make one litre of the buffer is (Given pKbpK_{b}pKb​ (NH3NH_{3}NH3​) = 4.74; Molar mass of NH3NH_{3}NH3​ = 17 g mol−1mol^{-1}mol−1; Molar mass of NH4ClNH_{4}ClNH4​Cl = 53.5 g mol−1mol^{-1}mol−1)
  1. (A)53.5 g
  2. (B)72.3 g
  3. (C)107.0 g
  4. (D)126.0 g

Correct answer: (C)

Step-by-step solution →
Q114·ChemistrySingle correctJEE Main 2022
20 mL of 0.1 M NH4OHNH_{4}OHNH4​OH is mixed with 40 mL of 0.05 M HCl. The pH of the mixture is nearest to: (Given: Kb(NH4OH)=1×10−5K_{b}(NH_{4}OH) = 1 \times 10^{-5}Kb​(NH4​OH)=1×10−5, log 2 = 0.30, log 3 = 0.48, log 5 = 0.69, log 7 = 0.84, log 11 =1.04)
  1. (A)3.2
  2. (B)4.2
  3. (C)5.2
  4. (D)6.2

Correct answer: (C)

Step-by-step solution →
Q115·ChemistrySingle correctJEE Main 2022
The solubility of AgCl will be maximum in which of the following ?
  1. (A)0.01 M KCl
  2. (B)0.01 M HCl
  3. (C)0.01 M AgNO3AgNO_3AgNO3​
  4. (D)Deionised water

Correct answer: (D)

Step-by-step solution →
Q116·ChemistrySingle correctJEE Main 2022
4.0 moles of argon and 5.0 moles of PCl5_55​ are introduced into an evacuated flask of 100 litre capacity at 610 K. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be 6.0 atm. The Kp_pp​ for the reaction is [Given : R = 0.082L atm K−1^{-1}−1 mol−1^{-1}−1]
  1. (A)2.25
  2. (B)6.24
  3. (C)12.13
  4. (D)15.24

Correct answer: (A)

Step-by-step solution →
Q117·ChemistrySingle correctJEE Main 2022
A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH 4. The ratio of [CH3CH2COO−][CH3CH2COOH]\frac{[CH_3CH_2COO^-]}{[CH_3CH_2COOH]}[CH3​CH2​COOH][CH3​CH2​COO−]​ required to make buffer is ………. Given : Ka_aa​(CH3_33​CH2_22​COOH) = 1.3 × 10−5^{-5}−5
  1. (A)0.03
  2. (B)0.13
  3. (C)0.23
  4. (D)0.33

Correct answer: (B)

Step-by-step solution →
Q118·ChemistryNumericalJEE Main 2022
pH value of 0.001 M NaOH solution is_______.

Correct answer: 11

Step-by-step solution →
Q119·ChemistryNumericalJEE Main 2022
2NOCl(g) ⇌ 2NO(g) + Cl2Cl_{2}Cl2​(g) In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol/L. The equilibrium constant at 30°C is _______ × 10−410^{-4}10−4.

Correct answer: 125

Step-by-step solution →
Q120·ChemistryNumericalJEE Main 2022
40° of HI undergoes decomposition to H2H_2H2​ and I2I_2I2​ at 300 K. ΔG⊖\Delta G^{\ominus}ΔG⊖ for this decompostion reaction at one atmosphere pressure is_________ J mol−1mol^{-1}mol−1. [nearest integer] (Use R = 8.31 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1; log 2 = 0.3010. In 10 = 2.3, log 3 = 0.477)

Correct answer: 2735

Step-by-step solution →
Q121·ChemistryNumericalJEE Main 2022
50 mL of 0.1 M CH3COOHCH_{3}COOHCH3​COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be ______ ×10−2\times 10^{-2}×10−2. (Nearest integer) (Given : pKapK_{a}pKa​ (CH3COOHCH_{3}COOHCH3​COOH) = 4.76) log 2 = 0.30 log 3 = 0.48 log 5 = 0.69 log 7 = 0.84 log 11 = 1.04

Correct answer: 476

Step-by-step solution →
Q122·ChemistrySingle correctJEE Main 2022
Given below are two statements one is labelled as Assertion A and the other is labelled as Reason R: Assertion A : The amphoteric nature of water is explained by using Lewis acid/base concept. Reason R : Water acts as an acid with NH3_33​ and as a base with H2_22​S. In the light of the above statements choose the correct answer from the options given below :
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false.
  4. (D)A is false but R is true.

Correct answer: (D)

Step-by-step solution →
Q123·ChemistryNumericalJEE Main 2022
The standard free energy change (ΔG°) for 50% dissociation of N2O4N_2O_4N2​O4​ into NO2NO_2NO2​ at 27°C and 1 atm pressure is −x J mol−1mol^{-1}mol−1. The value of x is _________. (Nearest Integer) [Given : R = 8.31 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1, log 1.33 = 0.1239 ln 10 = 2.3]

Correct answer: 710

Step-by-step solution →
Q124·ChemistrySingle correctJEE Main 2022
The Ksp_{sp}sp​ for bismuth sulphide (Bi2_22​S3_33​) is 1.08 ×\times× 10−73^{-73}−73. The solubility of Bi2_22​S3_33​ in mol L−1^{-1}−1 at 298 K is
  1. (A)1.0 ×\times× 10−15^{-15}−15
  2. (B)2.7 ×\times× 10−12^{-12}−12
  3. (C)3.2 ×\times× 10−10^{-10}−10
  4. (D)4.2 ×\times× 10−8^{-8}−8

Correct answer: (A)

Step-by-step solution →
Q125·ChemistryNumericalJEE Main 2022
PCl5_55​ dissociates as PCl5_55​(g) ⇌\rightleftharpoons⇌ PCl3_33​(g) + Cl2_22​(g) 5 moles of PCl5_55​ are placed in a 200 litre vessel which contains 2 moles of N2_22​ and is maintained at 600 K. The equilibrium pressure is 2.46 atm. The equilibrium constant Kp_pp​ for the dissociation of PCl5_55​ is_____ ×\times× 10−3^{-3}−3. (nearest integer) (Given: R = 0.082 L atm K−1^{-1}−1 mol−1^{-1}−1 : Assume ideal gas behaviour)

Correct answer: 1107

Step-by-step solution →
Q126·ChemistrySingle correctJEE Main 2022
For a reaction at equilibrium A(g)⇌B(g)+12C(g)A(g)\rightleftharpoons B(g)+\dfrac{1}{2}C(g)A(g)⇌B(g)+21​C(g) the relation between dissociation constant (K), degree of dissociation (α\alphaα) and equilibrium pressure (p) is given by :
  1. (A)K=α12p32(1+32α)12(1−α)K=\dfrac{\alpha^{\frac{1}{2}}p^{\frac{3}{2}}}{\left(1+\dfrac{3}{2}\alpha\right)^{\frac{1}{2}}(1-\alpha)}K=(1+23​α)21​(1−α)α21​p23​​
  2. (B)K=α32p12(2+α)12(1−α)K=\dfrac{\alpha^{\frac{3}{2}}p^{\frac{1}{2}}}{(2+\alpha)^{\frac{1}{2}}(1-\alpha)}K=(2+α)21​(1−α)α23​p21​​
  3. (C)K=(αp)32(1+32α)12(1−α)K=\dfrac{(\alpha p)^{\frac{3}{2}}}{\left(1+\dfrac{3}{2}\alpha\right)^{\frac{1}{2}}(1-\alpha)}K=(1+23​α)21​(1−α)(αp)23​​
  4. (D)K=(αp)32(1+α)(1−α)12K=\dfrac{(\alpha p)^{\frac{3}{2}}}{(1+\alpha)(1-\alpha)^{\frac{1}{2}}}K=(1+α)(1−α)21​(αp)23​​

Correct answer: (B)

Step-by-step solution →
Q127·ChemistryNumericalJEE Main 2021
The molar solubility of Zn(OH)2_{2}2​ in 0.1 M NaOH solution is x × 10−18^{-18}−18 M. The value of x is ______ (Nearest integer) (Given : The solubility product of Zn(OH)2_{2}2​ is 2 × 10−20^{-20}−20)

Correct answer: 2

Step-by-step solution →
Q128·ChemistryNumericalJEE Main 2021
A3B2\mathrm{A_3B_2}A3​B2​ is a sparingly soluble salt of molar mass M (g mol−1^{-1}−1) and solubility x g L−1^{-1}−1 . The solubility product satisfies Ksp=a(xM)5\mathrm{K_{sp}} = a\left(\dfrac{\mathrm{x}}{\mathrm{M}}\right)^{5}Ksp​=a(Mx​)5 . The value of aaa is ____. (Integer answer)

Correct answer: 108

Step-by-step solution →
Q129·ChemistryNumericalJEE Main 2021
The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 mL of 1 M NaOH is x ×\times× 10−4^{-4}−4. The value of x is __________. (Nearest integer) [log⁡2.5=0.3979\log 2.5 = 0.3979log2.5=0.3979]

Correct answer: 6021

Step-by-step solution →
Q130·ChemistryNumericalJEE Main 2021
When 5.1 g of solid NH4_{4}4​HS is introduced into a two litre evacuated flask at 27°C, 20% of the solid decomposes into gaseous ammonia and hydrogen sulphide. The Kp_{p}p​ for the reaction at 27°C is x × 10−2^{-2}−2. The value of x is _____ . (Integer answer) [Given R = 0.082 L atm K−1^{-1}−1 mol−1^{-1}−1]

Correct answer: 6

Step-by-step solution →
Q131·ChemistryNumericalJEE Main 2021
The number of moles of NH3NH_3NH3​, that must be added to 2 L of 0.80 M AgNO3AgNO_3AgNO3​ in order to reduce the concentration of Ag+Ag^+Ag+ ions to 5.0×10−85.0 \times 10^{-8}5.0×10−8 M (KformationK_{formation}Kformation​ for [Ag(NH3)2]+=1.0×108[Ag(NH_3)_2]^+ = 1.0 \times 10^8[Ag(NH3​)2​]+=1.0×108) is ________ . (Nearest integer) [Assume no volume change on adding NH3NH_3NH3​]

Correct answer: 4

Step-by-step solution →
Q132·ChemistryNumericalJEE Main 2021
The equilibrium constant KcK_cKc​ at 298 K for the reaction A+B⇌C+DA + B \rightleftharpoons C + DA+B⇌C+D is 100. Starting with an equimolar solution with concentrations of A, B, C and D all equal to 1M, the equilibrium concentration of D is ______ ×10−2\times 10^{-2}×10−2 M. (Nearest integer)

Correct answer: 182

Step-by-step solution →
Q133·ChemistryNumericalJEE Main 2021
The OH−OH^-OH− concentration in a mixture of 5.0 mL of 0.0504 M NH4Cl0.0504\ M\ NH_4Cl0.0504 M NH4​Cl and 2 mL of 0.0210 M NH30.0210\ M\ NH_30.0210 M NH3​ solution is x×10−6x \times 10^{-6}x×10−6 M. The value of x is ________. (Nearest integer) [Given Kw=1×10−14K_w = 1 \times 10^{-14}Kw​=1×10−14 and Kb=1.8×10−5K_b = 1.8 \times 10^{-5}Kb​=1.8×10−5]

Correct answer: 3

Step-by-step solution →
Q134·ChemistrySingle correctJEE Main 2021
Given below are two statements. Statement I: In the titration between strong acid and weak base methyl orange is suitable as an indicator. Statement II: For titration of acetic acid with NaOH phenolphthalein is not a suitable indicator. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are true
  4. (D)Both Statement I and Statement II are false

Correct answer: (B)

Step-by-step solution →
Q135·ChemistryNumericalJEE Main 2021
PCl5⇌PCl3+Cl2PCl_5 \rightleftharpoons PCl_3 + Cl_2PCl5​⇌PCl3​+Cl2​ KCK_CKC​ = 1.844 3.0 moles of PCl5PCl_5PCl5​ is introduced in a 1L closed reaction vessel at 380K. The number of moles of PCl5PCl_5PCl5​ at equilibrium is_________ ×10−3\times 10^{-3}×10−3. (Round off to the Nearest integer)

Correct answer: 1396

Step-by-step solution →
Q136·ChemistryNumericalJEE Main 2021
The conductivity of a weak acid HA of concentration 0.001 mol L−1^{-1}−1 is 2.0×10−52.0 \times 10^{-5}2.0×10−5 S cm−1^{-1}−1. If Λmo\Lambda_m^oΛmo​(HA) = 190 S cm2^22 mol−1^{-1}−1, the ionization constant (KaK_aKa​) of HA is equal to ________ ×10−6\times 10^{-6}×10−6 (Round off to the nearest integer)

Correct answer: 12

Step-by-step solution →
Q137·ChemistryNumericalJEE Main 2021
Assuming that Ba(OH)2_22​ is completely ionized in aqueous solution under the given conditions the concentration of H3_33​O+^{+}+ ions in 0.005 M aqueous solution of Ba(OH)2_22​ at 298 K is ___________ ×\times× 10−1210^{-12}10−12 mol L−1^{-1}−1. (nearest integer)

Correct answer: 1

Step-by-step solution →
Q138·ChemistryNumericalJEE Main 2021
For the reaction A + B ⇌\rightleftharpoons⇌ 2C The value of equilibrium constant is 100 at 298K. If the initial concentration of all the three species is 1M each, then the equilibrium concentration of C is x×10−1\times 10^{-1}×10−1M. The value of x is__________. (Nearest integer)

Correct answer: 25

Step-by-step solution →
Q139·ChemistryNumericalJEE Main 2021
Value of KpK_pKp​ for the equilibrium reaction N2O4(g)⇌2NO2(g)\mathrm{N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}}N2​O4(g)​⇌2NO2(g)​ at 288 K is 47.9. The KcK_cKc​ for this reaction at same temperature is __________. (Nearest integer) (R = 0.083 L bar K−1^{-1}−1 mol−1^{-1}−1)

Correct answer: 2

Step-by-step solution →
Q140·ChemistryNumericalJEE Main 2021
2SO2_22​(g) + O2_22​(g) ⇌ 2SO3_33​(g) In an equilibrium mixture, the partial pressures are PSO3P_{SO_3}PSO3​​ = 43kPa ; PO2P_{O_2}PO2​​ = 530 Pa and PSO2P_{SO_2}PSO2​​ = 45kPa . The equilibrium constant KpK_pKp​ = ______________ ×10−2\times 10^{-2}×10−2 (Nearest integer)

Correct answer: 172

Step-by-step solution →
Q141·ChemistrySingle correctJEE Main 2021
A solution is 0.1 M in Cl−\mathrm{Cl}^-Cl− and 0.001 M in CrO42−\mathrm{CrO_4^{2-}}CrO42−​. Solid AgNO3\mathrm{AgNO_3}AgNO3​ is gradually added to it. Assuming that the addition does not change in volume and Ksp(AgCl)=1.7×10−10 M2\mathrm{K_{sp}}\left(\mathrm{AgCl}\right) = 1.7 \times 10^{-10}\ \mathrm{M^2}Ksp​(AgCl)=1.7×10−10 M2 and Ksp(Ag2CrO4)=1.9×10−12 M3\mathrm{K_{sp}}\left(\mathrm{Ag_2CrO_4}\right) = 1.9 \times 10^{-12}\ \mathrm{M^3}Ksp​(Ag2​CrO4​)=1.9×10−12 M3. Select correct statement from the following :
  1. (A)Ag2CrO4\mathrm{Ag_2CrO_4}Ag2​CrO4​ precipitates first because the amount of Ag+\mathrm{Ag}^+Ag+ needed is low.
  2. (B)Ag2CrO4\mathrm{Ag_2CrO_4}Ag2​CrO4​ precipitates first as its Ksp\mathrm{K_{sp}}Ksp​ is low.
  3. (C)AgCl\mathrm{AgCl}AgCl will precipitate first as the amount of Ag+\mathrm{Ag}^+Ag+ needed to precipitate is low.
  4. (D)AgCl\mathrm{AgCl}AgCl precipitates first because its Ksp\mathrm{K_{sp}}Ksp​ is high.

Correct answer: (C)

Step-by-step solution →
Q142·ChemistryNumericalJEE Main 2021
In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is ________ M. (Round off to the Nearest Integer). [Given : pKa (acetic acid) = 4.74]

Correct answer: 10

Step-by-step solution →
Q143·ChemistryNumericalJEE Main 2021
The solubility of CdSO4_{4}4​ in water is 8.0 × 10−4^{-4}−4 mol L−1^{-1}−1. Its solubility in 0.01 M H2_{2}2​SO4_{4}4​ solution is ______ × 10−6^{-6}−6 mol L−1^{-1}−1. (Round off to the Nearest integer) (Assume that solubility is much less than 0.01 M)

Correct answer: 64

Step-by-step solution →
Q144·ChemistryNumericalJEE Main 2021
0.01 moles of a weak acid HA(Ka=2.0×10−6)\mathrm{HA}(\mathrm{K_a} = 2.0 \times 10^{-6})HA(Ka​=2.0×10−6) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is ________ ×10−5\times 10^{-5}×10−5 (Round off to the Nearest Integer). [Neglect volume change on adding HA. Assume degree of dissociation <<1]

Correct answer: 2

Step-by-step solution →
Q145·ChemistryNumericalJEE Main 2021
Consider the reaction N2_{2}2​O4_{4}4​(g) ⇌\rightleftharpoons⇌ 2NO2_{2}2​(g). The temperature at which KC_{C}C​ = 20.4 and KP_{P}P​ = 600.1, is_____K. (Round off to the Nearest Integer). [Assume all gases are ideal and R = 0.0831 L bar K−1^{-1}−1 mol−1^{-1}−1]

Correct answer: 354

Step-by-step solution →
Q146·ChemistryNumericalJEE Main 2021
Two salts A2_{2}2​X and MX have the same value of solubility product of 4.0 × 10−12^{-12}−12. The ratio of their molar solubilities i.e. S(A2X)S(MX)\frac{S(A_{2}X)}{S(MX)}S(MX)S(A2​X)​ = _______. (Round off to the Nearest Integer).

Correct answer: 50

Step-by-step solution →
Q147·ChemistryNumericalJEE Main 2021
Sulphurous acid (H2_{2}2​SO3_{3}3​) has Ka1_{1}1​ = 1.7 × 10−2^{-2}−2 and Ka2_{2}2​ = 6.4 × 10−8^{-8}−8. The pH of 0.588 M H2_{2}2​SO3_{3}3​ is _________. (Round off to the Nearest Integer)

Correct answer: 1

Step-by-step solution →
Q148·ChemistryNumericalJEE Main 2021
A homogeneous ideal gaseous reaction AB2(g)_{2(g)}2(g)​ ⇌ A(g)_{(g)}(g)​ + 2B(g)_{(g)}(g)​ is carried out in a 25 litre flask at 27°C. The initial amount of AB2_22​ was 1 mole and the equilibrium pressure was 1.9 atm. The value of Kp_pp​ is x × 10−2^{-2}−2. The value of x is ________. [R = 0.08206 dm3^33 atm K−1^{-1}−1 mol−1^{-1}−1]

Correct answer: 74

Step-by-step solution →
Q149·ChemistryNumericalJEE Main 2021
The pH of ammonium phosphate solution, if pkapk_apka​ of phosphoric acid and pkbpk_bpkb​ of ammonium hydroxide are 5.23 and 4.75 respectively, is_______________.

Correct answer: 7

Step-by-step solution →
Q150·ChemistrySingle correctJEE Main 2021
The solubility of Ca(OH)2 in water is : [Given : The solubility product of Ca(OH)2 in water = 5.5×10−6^{-6}−6]
  1. (A)1.11 ×10−6^{-6}−6
  2. (B)1.77 ×10−6^{-6}−6
  3. (C)1.77×10−2^{-2}−2
  4. (D)1.11×10−2^{-2}−2

Correct answer: (D)

Step-by-step solution →
Q151·ChemistrySingle correctJEE Main 2021
The solubility of AgCN in a buffer solution of pH = 3 is x. The value of x is: [Assume: No cyano complex is formed; Ksp_{sp}sp​(AgCN) = 2.2 × 10−16^{-16}−16 and Ka_{a}a​ (HCN) = 6.2 × 10−10^{-10}−10]
  1. (A)0.625 × 10−6^{-6}−6
  2. (B)1.6 × 10−6^{-6}−6
  3. (C)2.2 × 10−16^{-16}−16
  4. (D)1.9 × 10−5^{-5}−5

Correct answer: (D)

Step-by-step solution →
Q152·ChemistryNumericalJEE Main 2021
At 1990 K and 1 atrm pressure, there are equal number of Cl2\mathrm{Cl_2}Cl2​ molecules and Cl\mathrm{Cl}Cl atoms in the reaction mixture. The value of Kp\mathrm{K_p}Kp​ for the reaction Cl2(g)⇌2Cl(g)\mathrm{Cl_{2(g)}} \rightleftharpoons \mathrm{2Cl_{(g)}}Cl2(g)​⇌2Cl(g)​ under the above conditions is x×10−1x \times 10^{-1}x×10−1. The value of x is _________. (Rounded off to the nearest integer)

Correct answer: 5

Step-by-step solution →
Q153·ChemistryNumericalJEE Main 2021
The solubility product of PbI2PbI_{2}PbI2​ is 8.0 × 10−910^{-9}10−9 . The solubility of lead iodide in 0.1 molar solution of lead nitrate is x × 10−610^{-6}10−6 mol/L. The value of x is _________(Rounded off to the nearest integer) [Given 2=1.41\sqrt{2} = 1.412​=1.41]

Correct answer: 141

Step-by-step solution →
Q154·ChemistryNumericalJEE Advanced 2020
A solution of 0.1 M weak base (B) is titrated with 0.1 M of a strong acid (HA). The variation of pH of the solution with the volume of HA added is shown in the figure below. What is the pKbpK_{b}pKb​ of the base? The neutralization reaction is given by B+HA→BH++A−B + HA \rightarrow BH^{+} + A^{-}B+HA→BH++A−.

Correct answer: 2.80 TO 3.20

Step-by-step solution →
Q155·ChemistryNumericalJEE Advanced 2020
Consider the reaction A ⇌ B at 1000 K. At time t', the temperature of the system was increased to 2000 K and the system was allowed to reach equilibrium. Throughout this experiment the partial pressure of A was maintained at 1 bar. Given below is the plot of the partial pressure of B with time. What is the ratio of the standard Gibbs energy of the reaction at 1000 K to that at 2000 K?

Correct answer: 0.25

Step-by-step solution →
Q156·ChemistryNumericalJEE Advanced 2020
An acidified solution of 0.05 M Zn2+Zn^{2+}Zn2+ is saturated with 0.1 M H2SH_{2}SH2​S. What is the minimum molar concentration (M) of H+H^{+}H+ required to prevent the precipitation of ZnS ? Use KspK_{sp}Ksp​ (ZnS) = 1.25×10−221.25 \times 10^{-22}1.25×10−22 and Overall dissociation constant of H2SH_{2}SH2​S, KNET=K1K2=1×10−21K_{NET} = K_{1}K_{2} = 1 \times 10^{-21}KNET​=K1​K2​=1×10−21

Correct answer: 0.20

Step-by-step solution →
Q157·ChemistrySingle correctJEE Main 2020
Arrange the following solutions in the decreasing order of pOH (1) 0.01 M HCl (2) 0.01 M NaOH (3) 0.01 M CH3COONaCH_3COONaCH3​COONa (4) 0.01 M NaCl
  1. (A)(1) > (3) > (4) > (2)
  2. (B)(1) > (4) > (3) > (2)
  3. (C)(2) > (3) > (4) > (1)
  4. (D)(2) > (4) > (3) > (1)

Correct answer: (B)

Step-by-step solution →
Q158·ChemistrySingle correctJEE Main 2020
The value of KC_CC​ is 64 at 800 K for the reaction N2_22​(g) + 3H2_22​(g) ⇌ 2NH3_33​(g) The value of KC_CC​ for the following reaction is: NH3_33​(g) ⇌ 12\frac{1}{2}21​N2_22​(g) + 32\frac{3}{2}23​H2_22​(g)
  1. (A)164\frac{1}{64}641​
  2. (B)8
  3. (C)14\frac{1}{4}41​
  4. (D)18\frac{1}{8}81​

Correct answer: (D)

Step-by-step solution →
Q159·ChemistrySingle correctJEE Main 2020
For the reaction Fe2N(s)+32H2(g)=2Fe(s)+NH3(g)Fe_2N(s) + \dfrac{3}{2}H_2(g) = 2Fe(s) + NH_3(g)Fe2​N(s)+23​H2​(g)=2Fe(s)+NH3​(g)
  1. (A)Kc=Kp(RT)K_c = K_p(RT)Kc​=Kp​(RT)
  2. (B)Kc=KP(RT)−1/2K_c = K_P(RT)^{-1/2}Kc​=KP​(RT)−1/2
  3. (C)Kc=KP(RT)1/2K_c = K_P(RT)^{1/2}Kc​=KP​(RT)1/2
  4. (D)Kc=KP(RT)3/2K_c = K_P(RT)^{3/2}Kc​=KP​(RT)3/2

Correct answer: (C)

Step-by-step solution →
Q160·ChemistryNumericalJEE Main 2020
If the solubility product of AB2_22​ is 3.20 × 10−11^{-11}−11 M3^33, then the solubility of AB2_22​ in pure water is __________ × 10−4^{-4}−4 mol L−1^{-1}−1. [Assuming that neither kind of ion reacts with water]

Correct answer: 02.00

Step-by-step solution →
Q161·ChemistryNumericalJEE Main 2020
For a reaction X + Y = 2Z, 1.0 mol of X, 1.5 mol of Y and 0.5 mol of Z were taken in a 1 L vessel and allowed to react. At equilibrium, the concentration of Z was 1.0 mol L−1^{-1}−1. The equilibrium constant of the reaction is __________ x15\dfrac{x}{15}15x​. The value of x is __________.

Correct answer: 16.00

Step-by-step solution →
Q162·ChemistrySingle correctJEE Main 2020
For the equilibrium A ⇌\rightleftharpoons⇌ B, the variation of the rate of the forward (a) and reverse (B) reaction with time is given by:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q163·ChemistrySingle correctJEE Main 2020
If the equilibrium constant for A⇌B+CA \rightleftharpoons B + CA⇌B+C is K(eq)(1)K^{(1)}_{(eq)}K(eq)(1)​ and that of B+C⇌PB + C \rightleftharpoons PB+C⇌P is K(eq)(2)K^{(2)}_{(eq)}K(eq)(2)​, the equilibrium constant for A⇌PA \rightleftharpoons PA⇌P is:
  1. (A)K(eq)(1)K(eq)(2)K^{(1)}_{(eq)}K^{(2)}_{(eq)}K(eq)(1)​K(eq)(2)​
  2. (B)K(eq)(1)/K(eq)(1)K^{(1)}_{(eq)} / K^{(1)}_{(eq)}K(eq)(1)​/K(eq)(1)​
  3. (C)K(eq)(1)+K(eq)(2)K^{(1)}_{(eq)} + K^{(2)}_{(eq)}K(eq)(1)​+K(eq)(2)​
  4. (D)K(eq)(2)−K(eq)(1)K^{(2)}_{(eq)} - K^{(1)}_{(eq)}K(eq)(2)​−K(eq)(1)​

Correct answer: (A)

Step-by-step solution →
Q164·ChemistrySingle correctJEE Main 2020
100 mL of 0.1 M HCl is taken in a beaker and to it 100 mL of 0.1 M NaOH is added in steps of 2 mL and the pH is continuously measured. Which of the following graphs correctly depicts the change in pH?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q165·ChemistrySingle correctJEE Main 2020
An acidic buffer is obtained on mixing:
  1. (A)100 mL of 0.1 M HCl and 200 mL of 0.1 M NaCl
  2. (B)100 mL of 0.1 M HCl and 200 mL of 0.1 M CH3_33​COONa
  3. (C)100 mL of 0.1 M CH3_33​COOH and 100 mL of 0.1 M NaOH
  4. (D)100 mL of 0.1 M CH3_33​COOH and 200 mL of 0.1 M NaOH

Correct answer: (B)

Step-by-step solution →
Q166·ChemistrySingle correctJEE Main 2020
The solubility product of Cr(OH)3_33​ at 298 K is 6.0×10−316.0 \times 10^{-31}6.0×10−31. The concentration of hydroxide ions in a saturated solution of Cr(OH)3_33​ will be :
  1. (A)(18×10−31)1/4(18 \times 10^{-31})^{1/4}(18×10−31)1/4
  2. (B)(4.86×10−29)1/4(4.86 \times 10^{-29})^{1/4}(4.86×10−29)1/4
  3. (C)(18×10−31)1/2(18 \times 10^{-31})^{1/2}(18×10−31)1/2
  4. (D)(2.22×10−31)1/4(2.22 \times 10^{-31})^{1/4}(2.22×10−31)1/4

Correct answer: (A)

Step-by-step solution →
Q167·ChemistrySingle correctJEE Main 2020
The Ksp_{sp}sp​ for the following dissociation is 1.6 ×\times× 10−5^{-5}−5 PbCl2_{2}2​ (s) ⇌\rightleftharpoons⇌ Pb2+^{2+}2+ (aq) + 2Cl−^{-}− (aq) Which of the following choices is correct for a mixture of 300 mL 0.134 M Pb(NO3_{3}3​)2_{2}2​ and 100 mL 0.4 M NaCl?
  1. (A)Not enough data provided
  2. (B)Q > Ksp_{sp}sp​
  3. (C)Q < Ksp_{sp}sp​
  4. (D)Q = Ksp_{sp}sp​

Correct answer: (B)

Step-by-step solution →
Q168·ChemistrySingle correctJEE Main 2020
The stoichiometry and solubility product of a salt with the solubility curve given below is, respectively:
  1. (A)XY, 2 ×\times× 10−5^{-5}−5 M3^{3}3
  2. (B)XY3_{3}3​, 1 ×\times× 10−9^{-9}−9 M3^{3}3
  3. (C)XY2_{2}2​, 4 ×\times× 10−9^{-9}−9 M3^{3}3
  4. (D)X2_{2}2​Y, 2 ×\times× 10−9^{-9}−9 M3^{3}3

Correct answer: (C)

Step-by-step solution →
Q169·ChemistryNumericalJEE Main 2020
Two solutions A and B, each of 100 L was made by dissolution of 4g of NaOH and 9.8 g of H2_22​SO4_44​ in water, respectively. The pH of the resultant solution obtained from mixing 40 L of solution A and 10 L of solution B is

Correct answer: 10.60

Step-by-step solution →
Q170·ChemistryNumericalJEE Main 2020
3 g of acetic acid is added to 250 mL of 0.1 M HCl and the solution made up to 500 mL. To 20 mL of this solution ½ mL of 5 M NaOH is added. The pH of the solution is __________ [Given: pKaK_aKa​ of acetic acid = 4.75, molar mass of acetic acid = 60 g/mol, log 3 = 0.4771] Neglect any changes in volume.

Correct answer: 5.2271

Step-by-step solution →
Q171·ChemistryNumericalJEE Advanced 2019
For the following reaction, the equilibrium constant Kc_{c}c​ at 298 K is 1.6 ×\times× 1017^{17}17 Fe2+^{2+}2+(aq) + S2−^{2-}2−(aq) ⇌\rightleftharpoons⇌ FeS(s) When equal volumes of 0.06 M Fe2+^{2+}2+(aq) and 0.2 M S2−^{2-}2−(aq) solutions are mixed, the equilibrium concentration of Fe2+^{2+}2+(aq) is found to be Y ×\times× 10−17^{-17}−17 M. The value of Y is ……… .

Correct answer: 8.92 or 8.93

Step-by-step solution →
Q172·ChemistrySingle correctJEE Main 2019
The molar solubility of Cd(OH)2_22​ is 1.84 ×\times× 10−5^{-5}−5 M in water. The expected solubility of Cd(OH)2_22​ in a buffer solution of pH = 12 is :
  1. (A)6.23 ×\times× 10−11^{-11}−11 M
  2. (B)1.84 ×\times× 10−9^{-9}−9 M
  3. (C)2.491.84×10−9\frac{2.49}{1.84} \times 10^{-9}1.842.49​×10−9 M
  4. (D)2.49 ×\times× 10−10^{-10}−10 M

Correct answer: (D)

Step-by-step solution →
Q173·ChemistrySingle correctJEE Main 2019
What is the molar solubility of Al(OH)3_33​ in 0.2 M NaOH solution? Given that, solubility product of Al(OH)3_33​ = 2.4 ×\times× 10−24^{-24}−24 :
  1. (A)3×\times×10−19^{-19}−19
  2. (B)12×\times×10−21^{-21}−21
  3. (C)12×\times×10−23^{-23}−23
  4. (D)3×\times×10−22^{-22}−22

Correct answer: (D)

Step-by-step solution →
Q174·ChemistrySingle correctJEE Main 2019
In which one of the following equilibria, Kp_pp​ ≠ Kc_cc​?
  1. (A)2NO(g) ⇌ N2_22​(g) + O2_22​(g)
  2. (B)2C(s) + O2_22​(g) ⇌ 2CO(g)
  3. (C)NO2_22​(g) + SO2_22​(g) ⇌ NO(g) + SO3_33​(g)
  4. (D)2HI(g) ⇌ H2_22​(g) + I2_22​(g)

Correct answer: (B)

Step-by-step solution →
Q175·ChemistrySingle correctJEE Main 2019
Consider the following statements (a) The pH of a mixture containing 400 mL of 0.1 M H2SO4H_2SO_4H2​SO4​ and 400 mL of 0.1 M NaOH will be approximately 1.3. (b) Ionic product of water is temperature dependent. (c) A monobasic acid with Ka=10−5K_a = 10^{-5}Ka​=10−5 has a pH = 5. the degree of dissociation of this acid is 50%. (d) The Le Chatelier's principle is not applicable to common-ion effect. The correct statements are:
  1. (A)(a) and (b)
  2. (B)(a), (b) and (c)
  3. (C)(b) and (c)
  4. (D)(a), (b) and (d)

Correct answer: (B)

Step-by-step solution →
Q176·ChemistrySingle correctJEE Main 2019
The pH of a 0.02 M NH4_44​Cl solution will be [given Kb_bb​ (NH4_44​OH) = 10−5^{-5}−5 and log 2 = 0.301]
  1. (A)2.65
  2. (B)5.35
  3. (C)4.35
  4. (D)4.65

Correct answer: (B)

Step-by-step solution →
Q177·ChemistrySingle correctJEE Main 2019
For the reaction, 2SO2(g)+O2(g)⟶2SO3(g)2\mathrm{SO}_2(\mathrm{g}) + \mathrm{O}_2(\mathrm{g}) \longrightarrow 2\mathrm{SO}_3(\mathrm{g})2SO2​(g)+O2​(g)⟶2SO3​(g) ΔH=−57.2\Delta_H = -57.2ΔH​=−57.2 kJ mol−1^{-1}−1 and KC=1.7×1016\mathrm{K}_\mathrm{C} = 1.7 \times 10^{16}KC​=1.7×1016 Which of the following statement is INCORRECT?
  1. (A)The equilibrium constant is large suggestive of reaction going to completion and so no catalyst is required.
  2. (B)The equilibrium will shift in forward direction as the pressure increase.
  3. (C)The equilibrium constant decreases as the temperature increases.
  4. (D)The addition of inert gas at constant volume will not affect the equilibrium constant.

Correct answer: (A)

Step-by-step solution →
Q178·ChemistrySingle correctJEE Main 2019
In an acid – base titration, 0.1 M HCl solution was added to the NaOH solution of unknown strength. Which of the following correctly shows the change of pH of the titration mixture in this experiment?
  1. (A)(a)
  2. (B)(c)
  3. (C)(d)
  4. (D)(b)

Correct answer: (A)

Step-by-step solution →
Q179·ChemistrySingle correctJEE Main 2019
If solubility product of Zr3(PO4)4Zr_3(PO_4)_4Zr3​(PO4​)4​ is denoted by KSPK_{SP}KSP​ and its molar solubility is denoted by S, then which of the following relation between S and KSPK_{SP}KSP​ is correct?
  1. (A)S=(KSP6912)1/7S = \left(\dfrac{K_{SP}}{6912}\right)^{1/7}S=(6912KSP​​)1/7
  2. (B)S=(KSP144)1/6S = \left(\dfrac{K_{SP}}{144}\right)^{1/6}S=(144KSP​​)1/6
  3. (C)S=(KSp929)1/9S = \left(\dfrac{K_{Sp}}{929}\right)^{1/9}S=(929KSp​​)1/9
  4. (D)S=(KSP216)1/7S = \left(\dfrac{K_{SP}}{216}\right)^{1/7}S=(216KSP​​)1/7

Correct answer: (A)

Step-by-step solution →
Q180·ChemistrySingle correctJEE Main 2019
For the following reactions, equilibrium constants are given: S(s)+O2(g)⇌SO2(g);K1=1052S(s)+O_{2}(g)\rightleftharpoons SO_{2}(g);K_{1}=10^{52}S(s)+O2​(g)⇌SO2​(g);K1​=1052 2S(s)+3O2(g)⇌2SO3(g);K2=101292S(s)+3O_{2}(g)\rightleftharpoons 2SO_{3}(g);K_{2}=10^{129}2S(s)+3O2​(g)⇌2SO3​(g);K2​=10129 The equilibrium constant for the reaction 2SO2(g)+O2(g)⇌2SO3(g)2SO_{2}(g)+O_{2}(g)\rightleftharpoons 2SO_{3}(g)2SO2​(g)+O2​(g)⇌2SO3​(g) is:
  1. (A)107710^{77}1077
  2. (B)102510^{25}1025
  3. (C)1018110^{181}10181
  4. (D)1015410^{154}10154

Correct answer: (B)

Step-by-step solution →
Q181·ChemistrySingle correctJEE Main 2019
In a chemical reaction A+2B⇌K2C+DA + 2B \underset{}{\overset{K}{\rightleftharpoons}} 2C + DA+2B⇌K​​2C+D, the initial concentration of B was 1.5 times of A but the equilibrium concentrations of A and B were found to be equal. The equilibrium, constant(K) for the aforesaid chemical reaction is
  1. (A)4
  2. (B)16
  3. (C)1/4
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q182·ChemistrySingle correctJEE Main 2019
Two solids dissociate as follows A(s)⇌B(g)+C(g);Kp1=x atm2A(s)\rightleftharpoons B(g)+C(g); K_{p_1}=x\ atm^2A(s)⇌B(g)+C(g);Kp1​​=x atm2 D(s)⇌C(g)+E(g);Kp2=y atm2D(s)\rightleftharpoons C(g)+E(g); K_{p_2}=y\ atm^2D(s)⇌C(g)+E(g);Kp2​​=y atm2 The total pressure when both the solids dissociate simultaneously is
  1. (A)x+y\sqrt{x+y}x+y​ atm
  2. (B)2(x+y)2(\sqrt{x+y})2(x+y​) atm
  3. (C)(x+y)(x+y)(x+y) atm
  4. (D)x2+y2x^2+y^2x2+y2 atm

Correct answer: (B)

Step-by-step solution →
Q183·ChemistrySingle correctJEE Main 2019
If Ksp of Ag2CO3 is 8×10−128\times10^{-12}8×10−12, the molar solubility of Ag2CO3 in 0.1 M AgNO3 is :
  1. (A)8×10−128\times10^{-12}8×10−12 M
  2. (B)8×10−118\times10^{-11}8×10−11 M
  3. (C)8×10−108\times10^{-10}8×10−10 M
  4. (D)8×10−138\times10^{-13}8×10−13 M

Correct answer: (C)

Step-by-step solution →
Q184·ChemistrySingle correctJEE Main 2019
Consider the reaction N2(g)+3H2(g)⇌2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)N2​(g)+3H2​(g)⇌2NH3​(g) The equilibrium constant of the above reaction is K3K_3K3​. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that PNH3≪PtotalP_{NH_3} \ll P_{total}PNH3​​≪Ptotal​ at equilibrium)
  1. (A)33/2Kp1/2P216\dfrac{3^{3/2}K_p^{1/2}P^2}{16}1633/2Kp1/2​P2​
  2. (B)Kp1/2P216\dfrac{K_p^{1/2}P^2}{16}16Kp1/2​P2​
  3. (C)Kp1/2P24\dfrac{K_p^{1/2}P^2}{4}4Kp1/2​P2​
  4. (D)33/2Kp1/2P24\dfrac{3^{3/2}K_p^{1/2}P^2}{4}433/2Kp1/2​P2​

Correct answer: (A)

Step-by-step solution →
Q185·ChemistrySingle correctJEE Main 2019
For the equilibrium 2H2_22​O ⇌\rightleftharpoons⇌ H3_33​O+^++ + OH−^-−, the value of ΔG0\Delta G^0ΔG0 at 298 K is approximately:
  1. (A)100 kJ mol−1^{-1}−1
  2. (B)−-−80 kJ mol−1^{-1}−1
  3. (C)80 kJ mol−1^{-1}−1
  4. (D)−-−100 kJ mol−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q186·ChemistrySingle correctJEE Main 2019
The values of Kp_{p}p​/Kc_{c}c​ for the following reactions at 300 K are respectively: (At 300 K, Rt = 24.62 dm3^{3}3 atm mol−1^{-1}−1) N2_{2}2​(g) + O2_{2}2​(g) = 2NO(g) N2_{2}2​O4_{4}4​(g) = 2NO2_{2}2​(g) N2_{2}2​(g) + 3H2_{2}2​(g) = 2NH3_{3}3​(g)
  1. (A)1, 24.62 dm3^{3}3 atm mol−1^{-1}−1, 606.0 dm6^{6}6 atm2^{2}2 mol−2^{-2}−2
  2. (B)1, 24.62 dm3^{3}3 atm mol−1^{-1}−1, 1.65 ×\times× 10−3^{-3}−3 dm−6^{-6}−6 atm−2^{-2}−2 mol2^{2}2
  3. (C)1, 4.1 ×\times× 10−2^{-2}−2 dm−3^{-3}−3 atm−1^{-1}−1 mol, 606.0 dm6^{6}6 atm2^{2}2 mol−2^{-2}−2
  4. (D)24.62 dm3^{3}3 atm mol−1^{-1}−1, 606.0 dm6^{6}6 atm2^{2}2 atm2^{2}2 mol−2^{-2}−2, 1.65 ×\times× 10−3^{-3}−3 dm−6^{-6}−6 atm−2^{-2}−2 mol2^{2}2

Correct answer: (B)

Step-by-step solution →
Q187·ChemistrySingle correctJEE Main 2019
A mixture of 100 m mol of Ca(OH)2_{2}2​ and 2 g of sodium sulphate was dissolved in water and the volume was made upto 100 mL. The mass of calcium sulphate formed and the concentration of OH−^{-}− in resulting solution, respectively are (Molar mass of Ca(OH)2_{2}2​, Na2_{2}2​SO4_{4}4​ and CaSO4_{4}4​ are 74, 143 and 136 g mol−1^{-1}−1 respectively; Ksp_{sp}sp​ of Ca(OH)2_{2}2​ is 5.5 ×\times× 10−6^{-6}−6)
  1. (A)1.9 g, 0.28 mol L−1^{-1}−1
  2. (B)13.6 g, 0.28 mol L−1^{-1}−1
  3. (C)1.9g, 0.14 mol L−1^{-1}−1
  4. (D)13.6 g, 0.14 mol L−1^{-1}−1

Correct answer: (A)

Step-by-step solution →
Q188·ChemistrySingle correctJEE Main 2019
Consider the following reversible chemical reactions: A2(g)+B2(g)⇌K12AB(g)A_2(g) + B_2(g) \underset{}{\overset{K_1}{\rightleftharpoons}} 2AB(g)A2​(g)+B2​(g)⇌K1​​​2AB(g) .......(1) 6AB(g)⇌K23A2(g)+3B2(g)6AB(g) \underset{}{\overset{K_2}{\rightleftharpoons}} 3A_2(g) + 3B_2(g)6AB(g)⇌K2​​​3A2​(g)+3B2​(g) .......(2) The relation between K1_11​ and K2_22​ is
  1. (A)K1K2=13K_1K_2 = \frac{1}{3}K1​K2​=31​
  2. (B)K2=K13K_2 = K_1^{3}K2​=K13​
  3. (C)K2=K1−3K_2 = K_1^{-3}K2​=K1−3​
  4. (D)K1K2=3K_1K_2 = 3K1​K2​=3

Correct answer: (C)

Step-by-step solution →
Q189·ChemistrySingle correctJEE Main 2019
20 mL of 0.1 M H2_{2}2​SO4_{4}4​ is added to 30 mL of 0.2 M NH4_{4}4​OH solution. The pH of the resultant mixture is [pkb_{b}b​ of NH4_{4}4​OH = 4.7]
  1. (A)5.2
  2. (B)9.0
  3. (C)5.0
  4. (D)9.4

Correct answer: (B)

Step-by-step solution →
Q190·ChemistrySingle correctJEE Advanced 2018
Dilution processes of different aqueous solutions, with water, are given in LIST-I. The effects of dilution of the solutions on [H+][H^{+}][H+] are given in LIST-II. (Note: Degree of dissociation (α\alphaα) of weak acid and weak base is << 1; degree of hydrolysis of salt <<1; [H+][H^{+}][H+] represents the concentration of H+H^{+}H+ ions) Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is
LIST-ILIST-II
P.(10 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 60 mL1.the value of [H+][H^{+}][H+] does not change on dilution
Q.(20 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 80 mL2.the value of [H+][H^{+}][H+] changes to half of its initial value on dilution
R.(20 mL of 0.1 M HCl + 20 mL of 0.1 M ammonia solution) diluted to 80 mL3.the value of [H+][H^{+}][H+] changes to two times of its initial value on dilution
S.10 mL saturated solution of Ni(OH)2Ni(OH)_{2}Ni(OH)2​ in equilibrium with excess solid Ni(OH)2Ni(OH)_{2}Ni(OH)2​ is diluted to 20 mL (solid Ni(OH)2Ni(OH)_{2}Ni(OH)2​ is still present after dilution).4.the value of [H+][H^{+}][H+] changes to 12\frac{1}{\sqrt{2}}2​1​ times of its initial value on dilution
5.the value of [H+][H^{+}][H+] changes to 2\sqrt{2}2​ times of its initial value on dilution
  1. (A)P →\rightarrow→ 4; Q →\rightarrow→ 2; R →\rightarrow→ 3; S →\rightarrow→ 1
  2. (B)P →\rightarrow→ 4; Q →\rightarrow→ 3; R →\rightarrow→ 2; S →\rightarrow→ 3
  3. (C)P →\rightarrow→ 1; Q →\rightarrow→ 4; R →\rightarrow→ 5; S →\rightarrow→ 3
  4. (D)P →\rightarrow→ 1; Q →\rightarrow→ 5; R →\rightarrow→ 4; S →\rightarrow→ 1

Correct answer: (D)

Step-by-step solution →
Q191·ChemistryNumericalJEE Advanced 2018
The solubility of a salt of weak acid (AB) at pH 3 is Y×10−3Y \times 10^{-3}Y×10−3 mol L−1L^{-1}L−1. The value of Y is ___. (Given that the value of solubility product of AB (KspK_{sp}Ksp​) =2×10−10= 2 \times 10^{-10}=2×10−10 and the value of ionization constant of HB (KaK_{a}Ka​) =1×10−8= 1 \times 10^{-8}=1×10−8)

Correct answer: 4.47

Step-by-step solution →
Q192·ChemistryMultiple correctJEE Advanced 2017
For a reaction taking place in a container in equilibrium with its surroundings, the effect of temperature on its equilibrium constant KKK in terms of change in entropy is described by
  1. (A)With increase in temperature, the value of KKK for exothermic reaction decreases because entropy change of the system is positive
  2. (B)With increase in temperature, the value of KKK for endothermic reaction increases because unfavourable change in entropy of the surroundings decreases
  3. (C)With increase in temperature, the value of KKK for endothermic reaction increases because the entropy change of the system is negative
  4. (D)With increase in temperature, the value of KKK for exothermic reaction decreases because favourable change in entropy of the surrounding decreases

Correct answer: (B), (D)

Step-by-step solution →
Q193·ChemistrySingle correctJEE Advanced 2016
Thermal decomposition of gaseous X2X_{2}X2​ to gaseous X at 298 K takes place according to the following equation: X2(g)⇌2X(g)X_{2}(g) \rightleftharpoons 2X(g)X2​(g)⇌2X(g) The standard reaction Gibbs energy, ΔrG0\Delta_{r}G^{0}Δr​G0, of this reaction is positive. At the start of the reaction, there is one mole of X2X_{2}X2​ and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium\beta_{equilibrium}βequilibrium​ is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given: R = 0.083 L bar K−1K^{-1}K−1 mol−1mol^{-1}mol−1) The equilibrium constant KpK_{p}Kp​ for this reaction at 298 K, in terms of βequilibrium\beta_{equilibrium}βequilibrium​, is
  1. (A)8βequilibrium22−βequilibrium\dfrac{8\beta_{equilibrium}^{2}}{2-\beta_{equilibrium}}2−βequilibrium​8βequilibrium2​​
  2. (B)8βequilibrium24−βequilibrium2\dfrac{8\beta_{equilibrium}^{2}}{4-\beta_{equilibrium}^{2}}4−βequilibrium2​8βequilibrium2​​
  3. (C)4βequilibrium22−βequilibrium\dfrac{4\beta_{equilibrium}^{2}}{2-\beta_{equilibrium}}2−βequilibrium​4βequilibrium2​​
  4. (D)4βequilibrium24−βequilibrium2\dfrac{4\beta_{equilibrium}^{2}}{4-\beta_{equilibrium}^{2}}4−βequilibrium2​4βequilibrium2​​

Correct answer: (B)

Step-by-step solution →
Q194·ChemistrySingle correctJEE Advanced 2016
Thermal decomposition of gaseous X2X_{2}X2​ to gaseous X at 298 K takes place according to the following equation: X2(g)⇌2X(g)X_{2}(g) \rightleftharpoons 2X(g)X2​(g)⇌2X(g) The standard reaction Gibbs energy, ΔrG0\Delta_{r}G^{0}Δr​G0, of this reaction is positive. At the start of the reaction, there is one mole of X2X_{2}X2​ and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium\beta_{equilibrium}βequilibrium​ is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given: R = 0.083 L bar K−1K^{-1}K−1 mol−1mol^{-1}mol−1) The INCORRECT statement among the following, for this reaction is
  1. (A)Decrease in the total pressure will result in formation of more moles of gaseous X
  2. (B)At the start of the reaction, dissociation of gaseous X2X_{2}X2​ takes place spontaneously
  3. (C)βequilibrium=0.7\beta_{equilibrium} = 0.7βequilibrium​=0.7
  4. (D)Kc<1K_{c} < 1Kc​<1

Correct answer: (C)

Step-by-step solution →
Q195·ChemistryMultiple correctJEE Advanced 2015
When 100 mL of 1.0 M HCl was mixed with 100 mL of 1.0 M NaOH in an insulated beaker at constant pressure, a temperature increase of 5.7 ∘5.7\,^{\circ}5.7∘C was measured for the beaker and its contents (Expt. 1\mathbf{Expt.\ 1}Expt. 1). Because the enthalpy of neutralization of a strong acid with a strong base is a constant (−57.0-57.0−57.0 kJ mol−1^{-1}−1), this experiment could be used to measure the calorimeter constant. In a second experiment (Expt. 2\mathbf{Expt.\ 2}Expt. 2), 100 mL of 2.0 M acetic acid (Ka=2.0×10−5K_{a} = 2.0 \times 10^{-5}Ka​=2.0×10−5) was mixed with 100 mL of 1.0 M NaOH (under identical conditions to Expt. 1\mathbf{Expt.\ 1}Expt. 1) where a temperature rise of 5.6 ∘5.6\,^{\circ}5.6∘C was measured. (Consider heat capacity of all solutions as 4.2 J g−1^{-1}−1 K−1^{-1}−1 and density of all solutions as 1.0 g mL−1^{-1}−1) The pH of the solution after Expt. 2\mathbf{Expt.\ 2}Expt. 2 is
  1. (A)2.8
  2. (B)4.7
  3. (C)5.0
  4. (D)7.0

Correct answer: (B)

Step-by-step solution →
Q196·ChemistryMultiple correctJEE Advanced 2015
The % yield of ammonia as a function of time in the reaction N2(g)+3H2(g)⇌2NH3(g)\mathrm{N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g)}N2​(g)+3H2​(g)⇌2NH3​(g), ΔH<0\Delta H < 0ΔH<0 at (P, T1T_{1}T1​) is given below: If this reaction is conducted at (P, T2T_{2}T2​), with T2>T1T_{2} > T_{1}T2​>T1​, the % yield of ammonia as a function of time is represented by
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q197·ChemistryMultiple correctJEE Advanced 2013
The initial rate of hydrolysis of methyl acetate (1 M) by a weak acid (HA, 1M) is 1/100th^{th}th of that of a strong acid (HX, 1M), at 25∘^{\circ}∘C. The KaK_aKa​ of HA is
  1. (A)1×10−41 \times 10^{-4}1×10−4
  2. (B)1×10−51 \times 10^{-5}1×10−5
  3. (C)1×10−61 \times 10^{-6}1×10−6
  4. (D)1×10−31 \times 10^{-3}1×10−3

Correct answer: (A)

Step-by-step solution →
Q198·ChemistryMultiple correctJEE Advanced 2013
The KspK_{sp}Ksp​ of Ag2CrO4\mathrm{Ag_2CrO_4}Ag2​CrO4​ is 1.1×10−121.1 \times 10^{-12}1.1×10−12 at 298K. The solubility (in mol/L) of Ag2CrO4\mathrm{Ag_2CrO_4}Ag2​CrO4​ in a 0.1M AgNO3\mathrm{AgNO_3}AgNO3​ solution is
  1. (A)1.1×10−111.1 \times 10^{-11}1.1×10−11
  2. (B)1.1×10−101.1 \times 10^{-10}1.1×10−10
  3. (C)1.1×10−121.1 \times 10^{-12}1.1×10−12
  4. (D)1.1×10−91.1 \times 10^{-9}1.1×10−9

Correct answer: (B)

Step-by-step solution →
Q199·ChemistryMultiple correctJEE Advanced 2013
The thermal dissociation equilibrium of CaCO3(s)\mathrm{CaCO_3(s)}CaCO3​(s) is studied under different conditions. CaCO3(s)⇌CaO(s)+CO2(g)\mathrm{CaCO_3(s)} \rightleftharpoons \mathrm{CaO(s)} + \mathrm{CO_2(g)}CaCO3​(s)⇌CaO(s)+CO2​(g) For this equilibrium, the correct statement(s) is(are)
  1. (A)ΔH\Delta HΔH is dependent on T
  2. (B)K is independent of the initial amount of CaCO3\mathrm{CaCO_3}CaCO3​
  3. (C)K is dependent on the pressure of CO2\mathrm{CO_2}CO2​ at a given T
  4. (D)ΔH\Delta HΔH is independent of the catalyst, if any

Correct answer: (A), (B), (D)

Step-by-step solution →

Equilibrium — frequently asked

How many questions from Equilibrium appear in JEE?

Equilibrium has appeared in 163 of the last 186 JEE Main and JEE Advanced papers — about 88% of them — contributing 199 questions in total across those papers.

Is Equilibrium an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 88% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Equilibrium questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Chemistry chapters

  • Coordination Compounds 318
  • p-Block Elements 276
  • Redox Reactions and Electrochemistry 265
  • Chemical Bonding and Molecular Structure 207
  • d- and f-Block Elements 202
  • Aldehydes and Ketones 199
  • Solutions 198
  • Chemical Thermodynamics 195

All 36 Chemistry chapters →

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