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Solutions — JEE Previous Year Questions

Every Solutions question asked in JEE Main and JEE Advanced across the last 186 papers — 198 questions, each with its correct answer. Free to read, no account needed.

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198

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85%

All 198 Solutions questions

Most recent papers first.

Q1·ChemistryNumericalJEE Advanced 2026
Passage: Two volatile liquids A and B form an ideal solution. Consider a 5 molal solution of B in A inside a closed container having a total vapour pressure of 100 mm Hg at 300 K. The vapour pressure of pure A at 300 K is 105 mm Hg. Assume that A and B behave as ideal gases in the vapour phase. Given: The gas constant R=0.08R = 0.08R=0.08 L atm K−1K^{-1}K−1 mol−1mol^{-1}mol−1 Molar mass of A is 50 g mol−1mol^{-1}mol−1 Molar mass of B is 57 g mol−1mol^{-1}mol−1 Density of liquid B at 300 K is 0.5 g/mL 1 atm === 760 mm Hg Question: The mole fraction of B in vapour phase which is in equilibrium with this solution is ____.

Correct answer: 0.16

Step-by-step solution →
Q2·ChemistryNumericalJEE Advanced 2026
Passage: Two volatile liquids A and B form an ideal solution. Consider a 5 molal solution of B in A inside a closed container having a total vapour pressure of 100 mm Hg at 300 K. The vapour pressure of pure A at 300 K is 105 mm Hg. Assume that A and B behave as ideal gases in the vapour phase. Given: The gas constant R=0.08R = 0.08R=0.08 L atm K−1K^{-1}K−1 mol−1mol^{-1}mol−1 Molar mass of A is 50 g mol−1mol^{-1}mol−1 Molar mass of B is 57 g mol−1mol^{-1}mol−1 Density of liquid B at 300 K is 0.5 g/mL 1 atm === 760 mm Hg Question: At 300 K, the ratio of the molar volume of pure B in vapour phase to its molar volume in liquid phase is ____.

Correct answer: 2000

Step-by-step solution →
Q3·ChemistryNumericalJEE Advanced 2026
In a solvent S, a compound B is partially dissociated into C and D as given below: B⇌2C+2DB \rightleftharpoons 2C + 2DB⇌2C+2D B, C and D are non-volatile in nature. The molar mass of B is 10 times the molar mass of S. The standard boiling point and the standard enthalpy of vaporization of S are 400 K and 10R10R10R J mol−1mol^{-1}mol−1, respectively (RRR is the gas constant in J K−1K^{-1}K−1 mol−1mol^{-1}mol−1). A solution of B in S with an initial concentration of B as 0.25% (mass/mass) has a boiling point of 408 K at 1 bar pressure. In this solution, the mole percent of B that has been dissociated is ____.

Correct answer: 33.33

Step-by-step solution →
Q4·ChemistrySingle correctJEE Main 2026
Given below are two statements: Given: Molar mass of C, H, O, Cl are 12, 1, 16 and 35.5 g mol−1^{-1}−1, respectively. Statement I: In 30% (w/w) solution of methanol in CCl4_44​ (at T K), the mole fraction of CCl4_44​ is equal to 0.33. Statement II: Mixture of methanol and CCl4_44​ shows positive deviation from Raoult's law. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q5·ChemistrySingle correctJEE Main 2026
Given below are two statements : Statement I : H2O\mathrm{H_{2}O}H2​O molecules move from the chamber 1 to chamber 2. Statement II : The osmotic pressure of a solution prepared by dissolving 50 mg of potassium sulphate (molar mass = 174 g/mol) in 2 L of water (at 27 °C) is 0.0107 bar. (Given : R = 0.083 dm3^{3}3 bar K−1^{-1}−1 mol−1^{-1}−1 and assume complete dissociation of electrolyte) In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q6·ChemistrySingle correctJEE Main 2026
When 0.25 moles of a non-volatile, non-ionizable solute was dissolved in 1 mole of a solvent the vapor pressure of solution was x%x\%x% of vapor pressure of pure solvent. What is x%x\%x%?
  1. (A)50%
  2. (B)60%
  3. (C)70%
  4. (D)80%

Correct answer: (D)

Step-by-step solution →
Q7·ChemistrySingle correctJEE Main 2026
What is the mole fraction of water in 10% by weight (w/w) of aqueous urea solution? [Given: Molar mass of H, O, C and N are 1, 16, 12 and 14 g mol−1^{-1}−1 respectively.]
  1. (A)0.825
  2. (B)0.032
  3. (C)0.867
  4. (D)0.967

Correct answer: (D)

Step-by-step solution →
Q8·ChemistryNumericalJEE Main 2026
20 g hemoglobin in a 1 L aqueous solution (A) at 300 K is separated from pure water by semi permeable membrane. At equilibrium the height of solution in a tube dipped in a solution (A) is found to be 80.0 mm higher than the tube dipped in water. The molar mass of hemoglobin is _______ kg mol⁻¹. (Nearest integer) (Given : g = 10 m s⁻², R = 8.3 kPa dm³ K⁻¹mol⁻¹, density of solution = 1000 kg m⁻³)

Correct answer: 62

Step-by-step solution →
Q9·ChemistryNumericalJEE Main 2026
A non-volatile, non-electrolyte solid solute when dissolved in 40 g of a solvent, the vapour pressure of the solvent decreased from 760 mm Hg to 750 mm Hg. If the same solution boils at 320 K, then the number of moles of the solvent present in the solution is _______. (Nearest integer) [Given: boiling point of the pure solvent =319.5= 319.5=319.5 K, KbK_bKb​ of the solvent =0.3= 0.3=0.3 K kg mol−1mol^{-1}mol−1]

Correct answer: 5

Step-by-step solution →
Q10·ChemistrySingle correctJEE Main 2026
At 27°C, 0.1 M, 1 L K4[Fe(CN)6]\mathrm{K_{4}[Fe(CN)_{6}]}K4​[Fe(CN)6​] aqueous solution and 0.1 M, 1 L FeCl3\mathrm{FeCl_{3}}FeCl3​ aqueous solution are placed in a container separated by a semi permeable membrane AB. Assume complete dissociation of both the solutes. Which of the following statement is correct?
  1. (A)Blue color is formed on both sides.
  2. (B)Ionic solutes in aqueous solution can pass through semi-permeable membrane.
  3. (C)Solution on side 'y' is hypotonic.
  4. (D)To cause the reverse flow of solvent during osmosis, external pressure (any value) should be applied to side 'x'.

Correct answer: (C)

Step-by-step solution →
Q11·ChemistrySingle correctJEE Main 2026
Solution A is prepared by dissolving 1 g of a protein (molar mass = 50000 g mol−1^{-1}−1) in 0.5 L of water at 300 K. Its osmotic pressure is xxx bar. Solution B is made by dissolving 2 g of same protein in 1 L of water at 300 K. Osmotic pressure of solution B is yyy bar. Entire solution of A is mixed with entire solution of B at same temperature. The osmotic pressure of resultant solution is zzz bar. x,yx, yx,y and zzz respectively are: (R=0.083(R = 0.083(R=0.083 L bar mol−1^{-1}−1 K−1)^{-1})−1)
  1. (A)9.96×10−49.96 \times 10^{-4}9.96×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4
  2. (B)9.96×10−49.96 \times 10^{-4}9.96×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4; 19.92×10−419.92 \times 10^{-4}19.92×10−4
  3. (C)4.98×10−44.98 \times 10^{-4}4.98×10−4; 4.98×10−44.98 \times 10^{-4}4.98×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4
  4. (D)4.98×10−44.98 \times 10^{-4}4.98×10−4; 4.98×10−44.98 \times 10^{-4}4.98×10−4; 4.98×10−44.98 \times 10^{-4}4.98×10−4

Correct answer: (A)

Step-by-step solution →
Q12·ChemistrySingle correctJEE Main 2026
19.5 g of fluoro acetic acid (molar mass = 78 g mol−1\mathrm{mol^{-1}}mol−1) is dissolved in 500 g of water at 298 K. The depression in the freezing point of water was 1 °C. What is KaK_{a}Ka​ of fluoro acetic acid? (For water, Kf=1.86K_{f} = 1.86Kf​=1.86 K kg mol−1\mathrm{mol^{-1}}mol−1). Assume molarity and molality to have same values.
  1. (A)10−610^{-6}10−6
  2. (B)4×10−44 \times 10^{-4}4×10−4
  3. (C)3×10−53 \times 10^{-5}3×10−5
  4. (D)3×10−33 \times 10^{-3}3×10−3

Correct answer: (D)

Step-by-step solution →
Q13·ChemistrySingle correctJEE Main 2026
Consider the following aqueous solutions. I. 2.2 g Glucose in 125 mL of solution. II. 1.9 g Calcium chloride in 250 mL of solution. III. 9.0 g Urea in 500 mL of solution. IV. 20.5 g Aluminium sulphate in 750 mL of solution. The correct increasing order of boiling point of these solutions will be: [Given: Molar mass in g mol−1mol^{-1}mol−1: H=1, C=12, N=14, O=16, Cl=35.5, Ca=40, Al=27 and S=32]
  1. (A)I < II < III < IV
  2. (B)III < I < II < IV
  3. (C)II < III < I < IV
  4. (D)II < III < IV < I

Correct answer: (A)

Step-by-step solution →
Q14·ChemistrySingle correctJEE Main 2026
At T(K), 2 moles of liquid A and 3 moles of liquid B are mixed. The vapour pressure of ideal solution formed is 320 mm Hg. At this stage, one mole of A and one mole of B are added to the solution. The vapour pressure is now measured as 328.6 mm Hg. The vapour pressure (in mm Hg) of A and B are respectively:
  1. (A)300, 200
  2. (B)600, 400
  3. (C)400, 300
  4. (D)500, 200

Correct answer: (D)

Step-by-step solution →
Q15·ChemistrySingle correctJEE Main 2026
Two liquids A and B form an ideal solution at temperature T K. At T K , the vapour pressures of pure A and B are 55 and 15 kNm−2\text{kNm}^{-2}kNm−2 respectively. What is the mole fraction of A in solution of A and B in equilibrium with a vapour in which the mole fraction of A is 0.8 ?
  1. (A)0.5217
  2. (B)0.480
  3. (C)0.663
  4. (D)0.340

Correct answer: (A)

Step-by-step solution →
Q16·ChemistrySingle correctJEE Main 2026
A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute 'A' of molar mass 60 g mol−1^{-1}−1 and 0.9 g of a non-volatile non-electrolyte solute 'B' of molar mass 180 g mol−1^{-1}−1 in 100 mL H2OH_2OH2​O at 27°C. Osmotic pressure of the solution will be [Given : R = 0.082 L atm K−1^{-1}−1 mol−1^{-1}−1]
  1. (A)1.23 atm
  2. (B)2.46 atm
  3. (C)0.82 atm
  4. (D)1.47 atm

Correct answer: (B)

Step-by-step solution →
Q17·ChemistrySingle correctJEE Main 2026
'W' g of a non-volatile electrolyte solid solute of molar mass 'M' g mol−1^{-1}−1 when dissolved in 100 mL water, decreases vapour pressure of water from 640 mm Hg to 600 mm Hg. If aqueous solution of the electrolyte boils at 375 K and KbK_bKb​ for water is 0.52 K kg mol−1^{-1}−1, then the mole fraction of the electrolyte solute (x2)(x_2)(x2​) in the solution can be expressed as (Given : density of water = 1 g/mL and boiling point of water = 373 K)
  1. (A)1.38×WM\frac{1.3}{8} \times \frac{W}{M}81.3​×MW​
  2. (B)162.6×WM\frac{16}{2.6} \times \frac{W}{M}2.616​×MW​
  3. (C)2.616×MW\frac{2.6}{16} \times \frac{M}{W}162.6​×WM​
  4. (D)1.38×MW\frac{1.3}{8} \times \frac{M}{W}81.3​×WM​

Correct answer: (A)

Step-by-step solution →
Q18·ChemistrySingle correctJEE Main 2026
At 298 K, the mole percentage of N2(g)\text{N}_{2}(\text{g})N2​(g) in air is 80%. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of N2(g)\text{N}_{2}(\text{g})N2​(g) in water at 298 K ? (KH\text{K}_{\text{H}}KH​ for N2\text{N}_{2}N2​ is 6.5×1076.5 \times 10^{7}6.5×107 mm Hg )
  1. (A)1.23×10−71.23 \times 10^{-7}1.23×10−7
  2. (B)1.17×10−41.17 \times 10^{-4}1.17×10−4
  3. (C)9.35×1059.35 \times 10^{5}9.35×105
  4. (D)9.35×10−59.35 \times 10^{-5}9.35×10−5

Correct answer: (D)

Step-by-step solution →
Q19·ChemistryNumericalJEE Main 2026
Two liquids A and B form an ideal solution. At 320 K, the vapour pressure of the solution, containing 3 mol of A and 1 mol of B is 500mm Hg. At the same temperature, if 1 mol of A is further added to this solution, vapour pressure of the solution increases by 20 mm Hg. Vapour pressure (in mm Hg) of B in the pure state is ________. (Nearest integer)

Correct answer: 200

Step-by-step solution →
Q20·ChemistrySingle correctJEE Main 2026
Which one of the following graphs accurately represents the plot of partial pressure of CS2_22​ vs its mole fraction in a mixture of acetone and CS2_22​ at constant temperature ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q21·ChemistrySingle correctJEE Main 2026
Given below are two statements: Statement I : The Henry's law constant KH_HH​ is constant with respect to variations in solution's concentration over the range for which the solutions is ideally dilute. Statement II : KH_HH​ does not differ for the same solute in different solvents. In the light of the above statements, choose the correct answer from the options.
  1. (A)Statement I is false but Statement II is true.
  2. (B)Statement I is true but Statement II is false.
  3. (C)Both Statement I and Statement II are true.
  4. (D)Both Statement I and Statement II are false.

Correct answer: (B)

Step-by-step solution →
Q22·ChemistrySingle correctJEE Main 2026
Consider a solution of CO2_22​(g) dissolved in water in a closed container. Which one of the following plots correctly represents variation of log (partial pressure of CO2_22​ in vapour phase above water) [y-axis] with log (mole fraction of CO2_22​ in water) [x-axis] at 25°C ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q23·ChemistrySingle correctJEE Main 2026
Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and PQ2PQ_2PQ2​. When 1 g of PQ is dissolved in 50 g of solvent 'A'. ΔTb\Delta T_bΔTb​ was 1.176 K while when 1 g of PQ2PQ_2PQ2​ is dissolved in 50 g of solvent 'A', ΔTb\Delta T_bΔTb​ was 0.689 K. (KbK_bKb​ of 'A' = 5 K kg mol−1mol^{-1}mol−1). The molar masses of elements P and Q (in g mol−1mol^{-1}mol−1) respectively, are :
  1. (A)70, 110
  2. (B)65, 145
  3. (C)60, 25
  4. (D)25, 60

Correct answer: (D)

Step-by-step solution →
Q24·ChemistryNumericalJEE Main 2026
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass =300= 300=300 g mol−1\text{g mol}^{-1}g mol−1) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is _________ ×10−2\times 10^{-2}×10−2. (Nearest integer) [Given : Kb\text{K}_{\text{b}}Kb​ of the solvent =5.0= 5.0=5.0 K kg mol−1\text{mol}^{-1}mol−1] Assume the solution to be dilute and no association or dissociation of X takes place in solution.

Correct answer: 3

Step-by-step solution →
Q25·ChemistryNumericalJEE Main 2026
The osmotic pressure of a living cell in 12 atm at 300 K. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is ________ g L−1\text{g L}^{-1}g L−1. (Nearest integer) Given : R=0.08\text{R} = 0.08R=0.08 L atm K−1\text{K}^{-1}K−1 mol−1\text{mol}^{-1}mol−1 Assume complete dissociation of NaCl (Given : Molar mass of Na and Cl are 23 and 35.5 g mol−1\text{g mol}^{-1}g mol−1 respectively.)

Correct answer: 15

Step-by-step solution →
Q26·ChemistryNumericalJEE Advanced 2025
At 300 K, an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height (h) of the solution (density = 1.00 g cm−3^{-3}−3) where h is equal to 2.00 cm. If the concentration of the dilute solution of the macromolecule is 2.00 g dm−3^{-3}−3, the molar mass of the macromolecule is calculated to be X ×\times× 104^{4}4 g mol−1^{-1}−1. The value of X is ________. Use: Universal gas constant (R) = 8.3 J K−1^{-1}−1 mol−1^{-1}−1 and acceleration due to gravity (ggg) = 10 m s−2^{-2}−2.

Correct answer: 2.49

Step-by-step solution →
Q27·ChemistrySingle correctJEE Main 2025
HA(aq)⇌H+(aq)+A−(aq)HA(aq)\rightleftharpoons H^+(aq)+A^-(aq)HA(aq)⇌H+(aq)+A−(aq). The freezing point depression of a 0.1 m aqueous solution of a monobasic weak acid HA is 0.20∘C0.20^\circ C0.20∘C. The dissociation constant for the acid is: Given: Kf(H2O)=1.8 K kg mol−1K_f(H_2O)=1.8\ K\,kg\,mol^{-1}Kf​(H2​O)=1.8 Kkgmol−1, molality === molarity.
  1. (A)1.38×10−31.38\times10^{-3}1.38×10−3
  2. (B)1.1×10−21.1\times10^{-2}1.1×10−2
  3. (C)1.90×10−31.90\times10^{-3}1.90×10−3
  4. (D)1.89×10−11.89\times10^{-1}1.89×10−1

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correctJEE Main 2025
Which of the following binary mixture does not show the behaviour of minimum boiling azeotropes?
  1. (A)H2O+CH3COC2H5H_2O+CH_3COC_2H_5H2​O+CH3​COC2​H5​
  2. (B)C2H5OH+C2H5NH2C_2H_5OH+C_2H_5NH_2C2​H5​OH+C2​H5​NH2​
  3. (C)CS2+CH3COCH3CS_2+CH_3COCH_3CS2​+CH3​COCH3​
  4. (D)CH3OH+CHCl3CH_3OH+CHCl_3CH3​OH+CHCl3​

Correct answer: (B)

Step-by-step solution →
Q29·ChemistrySingle correctJEE Main 2025
Liquid A and B form an ideal solution. The vapour pressure of pure liquids A and B are 350 and 750 mm Hg respectively at the same temperature. If xAx_AxA​ and xBx_BxB​ are the mole fraction of A and B in solution while yAy_AyA​ and yBy_ByB​ are the mole fraction of A and B in vapour phase then:
  1. (A)xAxB<yAyB\dfrac{x_A}{x_B}<\dfrac{y_A}{y_B}xB​xA​​<yB​yA​​
  2. (B)xAxB=yAyB\dfrac{x_A}{x_B}=\dfrac{y_A}{y_B}xB​xA​​=yB​yA​​
  3. (C)xAxB>yAyB\dfrac{x_A}{x_B}>\dfrac{y_A}{y_B}xB​xA​​>yB​yA​​
  4. (D)(xA−yA)<(xB−yB)(x_A-y_A)<(x_B-y_B)(xA​−yA​)<(xB​−yB​)

Correct answer: (C)

Step-by-step solution →
Q30·ChemistryIntegerJEE Main 2025
The percentage dissociation of a salt (MX3MX_3MX3​) solution at given temperature (van't Hoff factor i=2i=2i=2) is ______ % (Nearest integer)

Correct answer: 33

Step-by-step solution →
Q31·ChemistrySingle correctJEE Main 2025
Match the LIST-I (Binary solution) with LIST-II (Property). Choose the correct answer from the options given below:
LIST-I (Binary solution)LIST-II (Property)
A.Solution of chloroform and acetoneI.Minimum boiling azeotrope
B.Solution of ethanol and waterII.Dimerizes
C.Solution of benzene and tolueneIII.Maximum boiling azeotrope
D.Solution of acetic acid in benzeneIV.ΔVmix=0\Delta V_{mix}=0ΔVmix​=0
  1. (A)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. (B)(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  3. (C)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. (D)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement (I): Molal depression constant KfK_fKf​ is given by M1RTfΔSfus\dfrac{M_1 R T_f}{\Delta S_{fus}}ΔSfus​M1​RTf​​, where symbols have their usual meaning. Statement (II): KfK_fKf​ for benzene is less than the KfK_fKf​ for water. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Both Statement I and Statement II are correct
  4. (D)Statement I is correct but Statement II is incorrect

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correctJEE Main 2025
XY is the membrane / partition between two chambers 1 and 2 containing sugar solutions of concentration c1c_1c1​ and c2c_2c2​ (c1>c2c_1>c_2c1​>c2​) mol L−1^{-1}−1 (shown in the figure). For the reverse osmosis to take place identify the correct condition. (Here p1p_1p1​ and p2p_2p2​ are pressures applied on chamber 1 and 2) (A) Membrane/Partition; Cellophane, p1>πp_1>\pip1​>π (B) Membrane/Partition; Porous, p2>πp_2>\pip2​>π (C) Membrane/Partition; Parchment paper, p1>πp_1>\pip1​>π (D) Membrane/Partition; Cellophane, p2>πp_2>\pip2​>π. Choose the correct answer from the option given below:
  1. (A)B and D only
  2. (B)A and D only
  3. (C)A and C only
  4. (D)C only

Correct answer: (C)

Step-by-step solution →
Q34·ChemistryIntegerJEE Main 2025
Sea water, which can be considered as a 6 molar (6 M) solution of NaCl, has a density of 2 g mL−12\ g\,mL^{-1}2 gmL−1. The concentration of dissolved oxygen (O2)(O_2)(O2​) in sea water is 5.8 ppm. Then the concentration of dissolved oxygen (O2)(O_2)(O2​) in sea water, is x×10−4 mx \times 10^{-4}\ mx×10−4 m. x=x = x= ______ (Nearest integer). (Given: Molar mass of NaCl is 58.5 g mol−158.5\ g\,mol^{-1}58.5 gmol−1; Molar mass of O2O_2O2​ is 32 g mol−132\ g\,mol^{-1}32 gmol−1)

Correct answer: 2

Step-by-step solution →
Q35·ChemistrySingle correctJEE Main 2025
2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is: (Given: Ebullioscopic constant of water =0.52=0.52=0.52 K kg mol−1^{-1}−1)
  1. (A)379.2 K
  2. (B)377.3 K
  3. (C)375.3 K
  4. (D)277.3 K

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correctJEE Main 2025
Which of the following properties will change when system containing solution 1 will become solution 2? (Solution 1: 10 mol of solute x + 10 L of water; Solution 2: 1 L of solution 1 + 1 mol of solute x + 1 L of water.)
  1. (A)Molar heat capacity
  2. (B)Density
  3. (C)Concentration
  4. (D)Gibbs free energy

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correctJEE Main 2025
'X' g of NaCl is added to water in a beaker with a lid. The temperature of the system is raised from 1∘C1^\circ C1∘C to 25∘C25^\circ C25∘C. Which of the following graphs is best suited for the change in the molarity (M) of the solution with respect to temperature? [Consider the solubility of NaCl remains unchanged over the temperature range]
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correctJEE Main 2025
A solution is made by mixing one mole of volatile liquid A with 3 moles of volatile liquid B. The vapour pressure of pure A is 200 mm Hg and that of the solution is 500 mm Hg. The vapour pressure of pure B and the least volatile component of the solution, respectively, are:
  1. (A)1400 mm Hg, A
  2. (B)1400 mm Hg, B
  3. (C)600 mm Hg, B
  4. (D)600 mm Hg, A

Correct answer: (D)

Step-by-step solution →
Q39·ChemistryIntegerJEE Main 2025
When 1 g each of compounds AB and AB2AB_2AB2​ are dissolved in 15 g of water separately, they increased the boiling point of water by 2.7 K and 1.5 K respectively. The atomic mass of A (in amu) is ______ ×10−1\times10^{-1}×10−1 (Nearest integer). (Given: Molal boiling point elevation constant is 0.5 K kg mol−10.5\ K\,kg\,mol^{-1}0.5 Kkgmol−1)

Correct answer: 25

Step-by-step solution →
Q40·ChemistrySingle correctJEE Main 2025
Which of the following graph (shown in the figure) correctly represents the plots of KHK_HKH​ at 1 bar of gases in water versus temperature?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correctJEE Main 2025
Given below are two statements: Statement (I): NaCl is added to the ice at 0°C, present in the ice cream box to prevent the melting of ice cream. Statement (II): On addition of NaCl to ice at 0°C, there is a depression in freezing point. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is true but Statement II is false

Correct answer: (B)

Step-by-step solution →
Q42·ChemistryIntegerJEE Main 2025
If A2_22​B is 30% ionised in an aqueous solution, then the value of van’t Hoff factor (i) is ______ ×10−1\times 10^{-1}×10−1.

Correct answer: 16

Step-by-step solution →
Q43·ChemistrySingle correctJEE Main 2025
1.24 g of AX2_22​ (molar mass 124 g mol−1^{-1}−1) is dissolved in 1 kg of water to form a solution with boiling point of 100.0156∘100.0156^\circ100.0156∘C, while 25.4 g of AY2_22​ (molar mass 250 g mol−1^{-1}−1) in 2 kg of water constitutes a solution with a boiling point of 100.0260∘100.0260^\circ100.0260∘C. Kb(H2O)=0.52K_b(H_2O)=0.52Kb​(H2​O)=0.52 K kg mol−1^{-1}−1. Which of the following is correct?
  1. (A)AX2_22​ and AY2_22​ (both) are completely unionised.
  2. (B)AX2_22​ and AY2_22​ (both) are fully ionised.
  3. (C)AX2_22​ is completely unionised while AY2_22​ is fully ionised.
  4. (D)AX2_22​ is fully ionised while AY2_22​ is completely unionised.

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correctJEE Main 2025
Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is: (Given: Density of nitric acid solution is 1.25 g mL−1^{-1}−1)
  1. (A)45
  2. (B)55
  3. (C)32
  4. (D)40

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correctJEE Main 2025
What is the freezing point depression constant of a solvent, 50 g of which contain 1 g non volatile solute (molar mass 256 g mol−1^{-1}−1) and the decrease in freezing point is 0.40 K?
  1. (A)5.12 K kg mol−1^{-1}−1
  2. (B)4.43 K kg mol−1^{-1}−1
  3. (C)1.86 K kg mol−1^{-1}−1
  4. (D)3.72 K kg mol−1^{-1}−1

Correct answer: (A)

Step-by-step solution →
Q46·ChemistryIntegerJEE Main 2025
The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is _______ ×10−1\times 10^{-1}×10−1 M (Nearest integer). [Given: Density of aqueous solution of (X) is 1.25 g mL−1^{-1}−1. Molar mass of the acid is 70 g mol−1^{-1}−1]

Correct answer: 125

Step-by-step solution →
Q47·ChemistryIntegerJEE Main 2025
The observed and normal molar masses of compound MX2MX_2MX2​ are 65.6 and 164 respectively. The percent degree of ionisation of MX2MX_2MX2​ is __________ %. (Nearest integer)

Correct answer: 75

Step-by-step solution →
Q48·ChemistrySingle correctJEE Main 2025
Consider the given plots of vapour pressure (VP) vs temperature (T/K). Which amongst the following options is correct graphical representation showing ΔTf\Delta T_fΔTf​, depression in the freezing point of solvent in a solution ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q49·ChemistrySingle correctJEE Main 2025
When a non-volatile solute is added to the solvent, the vapour pressure of the solvent decreases by 10 mm of Hg. The mole fraction of the solute in the solution is 0.2. What would be the mole fraction of the solvent if decrease in vapour pressure is 20 mm of Hg ?
  1. (A)0.6
  2. (B)0.4
  3. (C)0.2
  4. (D)0.8

Correct answer: (A)

Step-by-step solution →
Q50·ChemistrySingle correctJEE Main 2025
Consider a binary solution of two volatile liquid components 1 and 2. x1x_1x1​ and y1y_1y1​ are the mole fractions of component 1 in liquid and vapour phase, respectively. The slope and intercept of the linear plot of 1x1\dfrac{1}{x_1}x1​1​ vs 1y1\dfrac{1}{y_1}y1​1​ are given respectively as :
  1. (A)P10P20, P20−P10P20\dfrac{P_1^0}{P_2^0},\ \dfrac{P_2^0-P_1^0}{P_2^0}P20​P10​​, P20​P20​−P10​​
  2. (B)P20P10, P10−P20P20\dfrac{P_2^0}{P_1^0},\ \dfrac{P_1^0-P_2^0}{P_2^0}P10​P20​​, P20​P10​−P20​​
  3. (C)P10P20, P10−P20P20\dfrac{P_1^0}{P_2^0},\ \dfrac{P_1^0-P_2^0}{P_2^0}P20​P10​​, P20​P10​−P20​​
  4. (D)P20P10, P20−P10P20\dfrac{P_2^0}{P_1^0},\ \dfrac{P_2^0-P_1^0}{P_2^0}P10​P20​​, P20​P20​−P10​​

Correct answer: (A)

Step-by-step solution →
Q51·ChemistrySingle correctJEE Main 2025
Arrange the following solutions in order of their increasing boiling points: (i) 10⁻⁴ M NaCl, (ii) 10⁻⁴ M Urea, (iii) 10⁻³ M NaCl, (iv) 10⁻² M NaCl.
  1. (A)(ii) < (i) < (iii) < (iv)
  2. (B)(i) < (ii) < (iii) < (iv)
  3. (C)(iv) < (iii) < (i) < (ii)
  4. (D)(iv) < (iii) < (ii) < (i)

Correct answer: (A)

Step-by-step solution →
Q52·ChemistrySingle correctJEE Main 2025
Density of 3 M NaCl solution is 1.25 g/mL. The molality of the solution is:
  1. (A)1.79 m
  2. (B)2 m
  3. (C)3 m
  4. (D)2.79 m

Correct answer: (D)

Step-by-step solution →
Q53·ChemistryIntegerJEE Main 2025
20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is ______ ×10−2\times 10^{-2}×10−2 M. (Nearest integer)

Correct answer: 57

Step-by-step solution →
Q54·ChemistryNumericalJEE Advanced 2024
Vessel-1 contains w2w_2w2​ g of a non-volatile solute X dissolved in w1w_1w1​ g of water. Vessel-2 contains w2w_2w2​ g of another non-volatile solute Y dissolved in w1w_1w1​ g of water. Both the vessels are at the same temperature and pressure. The molar mass of X is 80% of that of Y. The van't Hoff factor for X is 1.2 times of that of Y for their respective concentrations. The elevation of boiling point for solution in Vessel-1 is ________ % of the solution in Vessel-2.

Correct answer: 150

Step-by-step solution →
Q55·ChemistryNumericalJEE Main 2024
Molarity (M) of an aqueous solution containing x g of anhyd. CuSO4CuSO_4CuSO4​ in 500 mL solution at 32 ∘^\circ∘C is 2×10−12 \times 10^{-1}2×10−1 M. Its molality will be _____ ×10−3\times 10^{-3}×10−3 m. (nearest integer). [Given density of the solution = 1.25 g/mL.]

Correct answer: 164

Step-by-step solution →
Q56·ChemistryNumericalJEE Main 2024
The vapour pressure of pure benzene and methyl benzene at 27 ∘27\,^{\circ}27∘C is given as 80 Torr and 24 Torr, respectively. The mole fraction of methyl benzene in vapour phase, in equilibrium with an equimolar mixture of these two liquids (ideal solution) at the same temperature is _______ ×10−2\times10^{-2}×10−2 (nearest integer).

Correct answer: 23

Step-by-step solution →
Q57·ChemistrySingle correctJEE Main 2024
0.05M CuSO4CuSO_4CuSO4​ when treated with 0.01M K2Cr2O7K_2Cr_2O_7K2​Cr2​O7​ gives green colour solution of Cu2Cr2O7Cu_2Cr_2O_7Cu2​Cr2​O7​. [SPM : Semi Permeable Membrane]. A container is divided by a semi-permeable membrane (SPM): Side X contains K2Cr2O7K_2Cr_2O_7K2​Cr2​O7​ and Side Y contains CuSO4CuSO_4CuSO4​. Due to osmosis:
  1. (A)Green colour formation observed on side Y.
  2. (B)Green colour formation observed on side X.
  3. (C)Molarity of K2Cr2O7K_2Cr_2O_7K2​Cr2​O7​ solution is lowered.
  4. (D)Molarity of CuSO4CuSO_4CuSO4​ solution is lowered.

Correct answer: (D)

Step-by-step solution →
Q58·ChemistryNumericalJEE Main 2024
A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is _______ . (Integer Answer) (Given: Molar mass in g mol−1^{-1}−1 — Ethyl alcohol: 46, water: 18)

Correct answer: 22

Step-by-step solution →
Q59·ChemistryNumericalJEE Main 2024
A solution containing 10 g10\,g10g of an electrolyte AB2AB_2AB2​ in 100 g100\,g100g of water boils at 100.52∘C100.52^\circ C100.52∘C. The degree of ionization of the electrolyte (α)(\alpha)(α) is ___ ×10−1\times10^{-1}×10−1 (nearest integer). [Given: Molar mass of AB2=200 g mol−1AB_2=200\,g\,mol^{-1}AB2​=200gmol−1, Kb=0.52 K kg mol−1K_b=0.52\,K\,kg\,mol^{-1}Kb​=0.52Kkgmol−1, boiling point of water =100∘C=100^\circ C=100∘C; AB2AB_2AB2​ ionises as AB2→A2++2B−AB_2\to A^{2+}+2B^-AB2​→A2++2B−]

Correct answer: 5

Step-by-step solution →
Q60·ChemistryNumericalJEE Main 2024
Molality of an aqueous solution of urea is 4.44 m. Mole fraction of urea in solution is x×10−3x\times10^{-3}x×10−3. Value of x is _______ . (integer answer)

Correct answer: 74

Step-by-step solution →
Q61·ChemistrySingle correctJEE Main 2024
The density of 'x' M (x molar) solution of NaOH is 1.12 g mL−1^{-1}−1, while in molality, the concentration of the solution is 3 m (3 molal). Then x is: (Given: Molar mass of NaOH is 40 g/mol)
  1. (A)3.5
  2. (B)3.0
  3. (C)3.8
  4. (D)2.8

Correct answer: (B)

Step-by-step solution →
Q62·ChemistrySingle correctJEE Main 2024
Molality (m) of 3 M aqueous solution of NaCl is: (Given : Density of solution = 1.25 g mL−1mL^{-1}mL−1, Molar mass in g mol−1mol^{-1}mol−1 : Na-23, Cl-35.5)
  1. (A)2.90 m
  2. (B)2.79 m
  3. (C)1.90 m
  4. (D)3.85 m

Correct answer: (B)

Step-by-step solution →
Q63·ChemistryNumericalJEE Main 2024
Consider the dissociation of the weak acid HX as given below: HX(aq)⇌H+(aq)+X−(aq)HX(aq) \rightleftharpoons H^{+}(aq) + X^{-}(aq)HX(aq)⇌H+(aq)+X−(aq), Ka=1.2×10−5K_a = 1.2\times10^{-5}Ka​=1.2×10−5. The osmotic pressure of 0.03 M aqueous solution of HX at 300 K is _______ ×10−2\times10^{-2}×10−2 bar (nearest integer). (Given: R=0.083R=0.083R=0.083 L bar mol−1^{-1}−1 K−1^{-1}−1)

Correct answer: 76

Step-by-step solution →
Q64·ChemistryNumericalJEE Main 2024
When 'x' ×10−2\times 10^{-2}×10−2 mL methanol (molar mass = 32 g; density = 0.792 g/cm3^33) is added to 100 mL water (density = 1 g/cm3^33), the following diagram is obtained. x = _______ (nearest integer). [Given: Molal freezing point depression constant of water at 273.15 K is 1.86 K kg mol−1^{-1}−1]

Correct answer: 543

Step-by-step solution →
Q65·ChemistryNumericalJEE Main 2024
An artificial cell is made by encapsulating a 0.2 M glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a 0.05 M solution of NaCl at 300 K is ___ ×10−1\times10^{-1}×10−1 bar (nearest integer). [Given R=0.083 L bar mol−1K−1R = 0.083\ \text{L bar mol}^{-1}\text{K}^{-1}R=0.083 L bar mol−1K−1; assume complete dissociation of NaCl.]

Correct answer: 25

Step-by-step solution →
Q66·ChemistryNumericalJEE Main 2024
Acetic acid dissociates in water with a dissociation constant of 6.25×10−56.25 \times 10^{-5}6.25×10−5. If 5 mL of acetic acid is dissolved in 1 litre of water, the solution will freeze at −x×10−2-x \times 10^{-2}−x×10−2 °C, provided pure water freezes at 0 °C. The value of xxx is __________. (Nearest integer) Given: (Kf)water=1.86(K_f)_{water} = 1.86(Kf​)water​=1.86 K kg mol−1^{-1}−1; density of acetic acid = 1.2 g mL−1^{-1}−1; molar mass of water = 18 g mol−1^{-1}−1; molar mass of acetic acid = 60 g mol−1^{-1}−1; density of water = 1 g cm−3^{-3}−3.

Correct answer: 19

Step-by-step solution →
Q67·ChemistrySingle correctJEE Main 2024
Molar ionic conductivities of a divalent cation and anion are 57 S cm2mol−157\ \text{S cm}^2\text{mol}^{-1}57 S cm2mol−1 and 73 S cm2mol−173\ \text{S cm}^2\text{mol}^{-1}73 S cm2mol−1 respectively. The molar conductivity of a solution of an electrolyte with the above cation and anion will be:
  1. (A)65 S cm2mol−165\ \text{S cm}^2\text{mol}^{-1}65 S cm2mol−1
  2. (B)130 S cm2mol−1130\ \text{S cm}^2\text{mol}^{-1}130 S cm2mol−1
  3. (C)187 S cm2mol−1187\ \text{S cm}^2\text{mol}^{-1}187 S cm2mol−1
  4. (D)260 S cm2mol−1260\ \text{S cm}^2\text{mol}^{-1}260 S cm2mol−1

Correct answer: (B)

Step-by-step solution →
Q68·ChemistryNumericalJEE Main 2024
2.5 g2.5\,g2.5g of a non-volatile, non-electrolyte is dissolved in 100 g100\,g100g of water at 25∘C25^\circ C25∘C. The solution showed a boiling point elevation by 2∘C2^\circ C2∘C. Assuming the solute concentration is negligible with respect to the solvent concentration, the vapour pressure of the resulting aqueous solution is ___ mm of Hg (nearest integer). [Given: Molal boiling point elevation constant of water (Kb)=0.52 K kg mol−1(K_b)=0.52\,K\,kg\,mol^{-1}(Kb​)=0.52Kkgmol−1, 111 atm pressure =760 mm=760\,mm=760mm of Hg, molar mass of water =18 g mol−1=18\,g\,mol^{-1}=18gmol−1]

Correct answer: 707

Step-by-step solution →
Q69·ChemistryNumericalJEE Main 2024
2.7 kg of each of water and acetic acid are mixed. The freezing point of the solution will be −x ∘-x\ ^{\circ}−x ∘C. Consider the acetic acid does not dimerise in water, nor dissociates in water; x=x=x= ______ (nearest integer). [Given: Molar mass of water =18 g mol−1=18\ \text{g mol}^{-1}=18 g mol−1, acetic acid =60 g mol−1=60\ \text{g mol}^{-1}=60 g mol−1, KfK_fKf​ of water =1.86 ∘C/m=1.86\ ^{\circ}\text{C/m}=1.86 ∘C/m, acetic acid =3.90 K/m=3.90\ \text{K/m}=3.90 K/m; freezing point: H2O=273\text{H}_2\text{O}=273H2​O=273 K, acetic acid =290=290=290 K]

Correct answer: 31

Step-by-step solution →
Q70·ChemistryNumericalJEE Main 2024
Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at −24∘-24^{\circ}−24∘C is __________ kg (Molar mass in g mol−1^{-1}−1 for ethylene glycol 62, KfK_fKf​ of water =1.86=1.86=1.86 K kg mol−1^{-1}−1).

Correct answer: 15

Step-by-step solution →
Q71·ChemistrySingle correctJEE Main 2024
We have three aqueous solutions of NaCl labelled as AAA, BBB and CCC with concentration 0.1 M0.1\,M0.1M, 0.01 M0.01\,M0.01M & 0.001 M0.001\,M0.001M, respectively. The value of van't Hoff factor (i)(i)(i) for these solutions will be in the order:
  1. (A)iA<iB<iCi_A<i_B<i_CiA​<iB​<iC​
  2. (B)iA>iB>iCi_A>i_B>i_CiA​>iB​>iC​
  3. (C)iA=iB=iCi_A=i_B=i_CiA​=iB​=iC​
  4. (D)iA>iB=iCi_A>i_B=i_CiA​>iB​=iC​

Correct answer: (A)

Step-by-step solution →
Q72·ChemistrySingle correctJEE Main 2024
Identify the mixture that shows positive deviations from Raoult's Law
  1. (A)(CH3)2CO+C6H5NH2(CH_3)_2CO+C_6H_5NH_2(CH3​)2​CO+C6​H5​NH2​
  2. (B)CHCl3+C6H6CHCl_3+C_6H_6CHCl3​+C6​H6​
  3. (C)CHCl3+(CH3)2COCHCl_3+(CH_3)_2COCHCl3​+(CH3​)2​CO
  4. (D)(CH3)2CO+CS2(CH_3)_2CO+CS_2(CH3​)2​CO+CS2​

Correct answer: (D)

Step-by-step solution →
Q73·ChemistrySingle correctJEE Main 2024
The solution from the following with highest depression in freezing point/lowest freezing point is:
  1. (A)180 g of acetic acid dissolved in water
  2. (B)180 g of acetic acid dissolved in benzene
  3. (C)180 g of benzoic acid dissolved in benzene
  4. (D)180 g of glucose dissolved in water

Correct answer: (A)

Step-by-step solution →
Q74·ChemistrySingle correctJEE Main 2024
What happens to freezing point of benzene when small quantity of naphthalene is added to benzene?
  1. (A)Increases
  2. (B)Remains unchanged
  3. (C)First decreases and then increases
  4. (D)Decreases

Correct answer: (D)

Step-by-step solution →
Q75·ChemistryNumericalJEE Main 2024
Molality of 0.8 M H2SO4H_2SO_4H2​SO4​ solution (density 1.06 g cm−3^{-3}−3) is ___ ×10−3\times10^{-3}×10−3 m.

Correct answer: 815

Step-by-step solution →
Q76·ChemistryNumericalJEE Main 2024
The osmotic pressure of a dilute solution is 7×1057\times10^57×105 Pa at 273 K. Osmotic pressure of the same solution at 283 K is ______ ×104\times10^4×104 Nm−2^{-2}−2.

Correct answer: 72.56

Step-by-step solution →
Q77·ChemistryNumericalJEE Main 2024
Volume of 3 M NaOH (formula weight 40 g mol−1^{-1}−1) which can be prepared from 84 g of NaOH is __________ ×10−1\times10^{-1}×10−1 dm3^33.

Correct answer: 7

Step-by-step solution →
Q78·ChemistrySingle correctJEE Main 2024
A solution of two miscible liquids showing negative deviation from Raoult's law will have:
  1. (A)increased vapour pressure, increased boiling point
  2. (B)increased vapour pressure, decreased boiling point
  3. (C)decreased vapour pressure, decreased boiling point
  4. (D)decreased vapour pressure, increased boiling point

Correct answer: (D)

Step-by-step solution →
Q79·ChemistrySingle correctJEE Main 2024
Which among the following changes with temperature is :
  1. (A)Molarity
  2. (B)Mass percentage
  3. (C)Molality
  4. (D)Mole fraction

Correct answer: (A)

Step-by-step solution →
Q80·ChemistryIntegerJEE Advanced 2023
50 mL of 0.2 molal urea solution (density = 1.012 g mL−1^{-1}−1 at 300 K) is mixed with 250 mL of a solution containing 0.06 g of urea. Both the solutions were prepared in the same solvent. The osmotic pressure (in Torr) of the resulting solution at 300 K is ___. [Use: Molar mass of urea = 60 g mol−1^{-1}−1; gas constant, R = 62 L Torr K−1^{-1}−1 mol−1^{-1}−1 ; Assume, ΔmixH=0\Delta_{\mathrm{mix}} H = 0Δmix​H=0, ΔmixV=0\Delta_{\mathrm{mix}} V = 0Δmix​V=0]

Correct answer: 682

Step-by-step solution →
Q81·ChemistryNumericalJEE Main 2023
The vapour pressure of 30% (w/v) aqueous solution of glucose is _______ mm Hg at 25 C. [Given : The density of 30% (w/v), aqueous solution of glucose is 1.2 g cm−3cm^{-3}cm−3 and vapour pressure of pure water is 24 mm Hg.] (Molar mass of glucose is 180 g mol−1mol^{-1}mol−1.)

Correct answer: 23

Step-by-step solution →
Q82·ChemistryNumericalJEE Main 2023
Solution of 12 g12\,g12g of non-electrolyte (A) prepared by dissolving it in 1000 mL1000\,mL1000mL of water exerts the same osmotic pressure as that of 0.05 M0.05\,M0.05M glucose solution at the same temperature. The empirical formula of AAA is CH2OCH_{2}OCH2​O. The molecular mass of A is _____ ggg. (Nearest integer)

Correct answer: 240

Step-by-step solution →
Q83·ChemistryNumericalJEE Main 2023
Sea water contains 29.25% NaCl and 19% MgCl2MgCl_2MgCl2​ by weight of solution. The normal boiling point of the sea water is ____ °C (Nearest integer). Assume 100% ionization for both NaCl and MgCl2MgCl_2MgCl2​. Given: Kb(H2O)=0.52K_b(H_2O) = 0.52Kb​(H2​O)=0.52 K kg mol−1^{-1}−1. Molar mass of NaCl and MgCl2MgCl_2MgCl2​ is 58.5 and 95 g mol−1^{-1}−1 respectively.

Correct answer: 116

Step-by-step solution →
Q84·ChemistryNumericalJEE Main 2023
80 mole percent of MgCl2_22​ is dissociated in aqueous solution. The vapour pressure of 1.0 molal aqueous solution of MgCl2_22​ at 38°C is _________ mm Hg. (Nearest integer) Given: Vapour pressure of water at 38°C is 50 mm Hg.

Correct answer: 48

Step-by-step solution →
Q85·ChemistrySingle correctJEE Main 2023
A solution is prepared by adding 2 g of "X" to 1 mole of water. The mass percent of "X" in the solution is:
  1. (A)20%
  2. (B)5%
  3. (C)2%
  4. (D)10%

Correct answer: (D)

Step-by-step solution →
Q86·ChemistryNumericalJEE Main 2023
0.004 M K2SO4K_2SO_4K2​SO4​ solution is isotonic with 0.01 M glucose solution. Percentage dissociation of K2SO4K_2SO_4K2​SO4​ is __________ (Nearest integer)

Correct answer: 75

Step-by-step solution →
Q87·ChemistrySingle correctJEE Main 2023
What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg? (Assume a dilute solution is being formed.) Given: Vapour pressure of pure water is 54.2 mm Hg at room temperature; molar mass of glucose is 180 g mol−1^{-1}−1.
  1. (A)4.69 g
  2. (B)3.59 g
  3. (C)2.59 g
  4. (D)3.69 g

Correct answer: (D)

Step-by-step solution →
Q88·ChemistryNumericalJEE Main 2023
The degree of dissociation of aqueous solution of weak monobasic acid is determined to be 0.3, then the observed freezing point will be _________ % higher than the expected/theoretical freezing point. (Nearest integer)

Correct answer: 30

Step-by-step solution →
Q89·ChemistryNumericalJEE Main 2023
An aqueous solution of volume 300300300 cm3^33 contains 0.630.630.63 g of protein. The osmotic pressure of the solution at 300300300 K is 1.291.291.29 mbar. The molar mass of the protein is _______ g mol−1^{-1}−1. (Given R =0.083=0.083=0.083 L bar K−1^{-1}−1 mol−1^{-1}−1).

Correct answer: 40535

Step-by-step solution →
Q90·ChemistryNumericalJEE Main 2023
If the boiling points of two solvents X and Y (having the same molecular weights) are in the ratio 2:12:12:1 and their enthalpies of vaporization are in the ratio 1:21:21:2, then the boiling point elevation constant of X is m times the boiling point elevation constant of Y. The value of m is ____ (nearest integer).

Correct answer: 8

Step-by-step solution →
Q91·ChemistryNumericalJEE Main 2023
The vapour pressure vs. temperature curve for a solution solvent system is shown below. The boiling point of the solvent is ____ ∘C^\circ C∘C

Correct answer: 82

Step-by-step solution →
Q92·ChemistryNumericalJEE Main 2023
Mass of Urea (NH2CONH2)(NH_2CONH_2)(NH2​CONH2​) required to be dissolved in 1000 g1000\,g1000g of water to reduce the vapour pressure of water by 25%25\%25% is _____ ggg. (Nearest integer) Given: Molar mass of N, C, ON,\,C,\,ON,C,O and HHH are 14, 12, 1614,\,12,\,1614,12,16 and 1 g mol−11\,g\,mol^{-1}1gmol−1 respectively.

Correct answer: 1111

Step-by-step solution →
Q93·ChemistryNumericalJEE Main 2023
Consider the following pairs of solutions which will be isotonic at the same temperature. The number of pairs of solutions is/are ____. A. 1 M aq. NaCl and 2 M aq. Urea. B. 1 M aq. CaCl2CaCl_2CaCl2​ and 1.5 M aq. KCl. C. 1.5 M aq. AlCl3AlCl_3AlCl3​ and 2 M aq. Na2SO4Na_2SO_4Na2​SO4​. D. 2.5 M aq. KCl and 1 M aq. Al2(SO4)3Al_2(SO_4)_3Al2​(SO4​)3​.

Correct answer: 4

Step-by-step solution →
Q94·ChemistryNumericalJEE Main 2023
The density of 3 M solution of NaCl\text{NaCl}NaCl is 1.01.01.0 g mL−1^{-1}−1. Molality of the solution is _______ ×10−2\times10^{-2}×10−2 m (Nearest integer). (Given: molar mass of Na\text{Na}Na and Cl\text{Cl}Cl is 23 and 35.535.535.5 g mol−1^{-1}−1 respectively).

Correct answer: 364

Step-by-step solution →
Q95·ChemistryNumericalJEE Main 2023
The molality of a 10%10\%10%(v/v) solution of di-bromine solution in CCl4CCl_4CCl4​ (carbon tetrachloride) is 'x'. x=x=x= _________ ×10−2\times10^{-2}×10−2 M. (Nearest integer) [Given: molar mass of Br2=160Br_2=160Br2​=160 g mol−1^{-1}−1, atomic mass of C =12=12=12, Cl =35.5=35.5=35.5 g mol−1^{-1}−1, density of dibromine =3.2=3.2=3.2 g cm−3^{-3}−3, density of CCl4=1.6CCl_4=1.6CCl4​=1.6 g cm−3^{-3}−3]

Correct answer: 139

Step-by-step solution →
Q96·ChemistryNumericalJEE Main 2023
25 mL of an aqueous solution of KCl was found to require 20 mL of 1 M AgNO3\text{AgNO}_3AgNO3​ solution when titrated using K2CrO4\text{K}_2\text{CrO}_4K2​CrO4​ as an indicator. What is the depression in freezing point of KCl solution of the given concentration? _______ (Nearest integer). (Given: Kf=2.0K_f=2.0Kf​=2.0 K kg mol−1^{-1}−1) Assume (1) 100% ionization and (2) density of the aqueous solution as 111 g mL−1^{-1}−1.

Correct answer: 3

Step-by-step solution →
Q97·ChemistryNumericalJEE Main 2023
20%20\%20% of acetic acid is dissociated when its 555 g is added to 500500500 mL of water. The depression in freezing point of such water is _________ ×10−3\times10^{-3}×10−3 °C. Atomic mass of C, H and O are 12,112,112,1 and 161616 a.m.u. respectively. [Given: Molal depression constant and density of water are 1.861.861.86 K kg mol−1^{-1}−1 and 111 g cm−3^{-3}−3 respectively.]

Correct answer: 372

Step-by-step solution →
Q98·ChemistryNumericalJEE Main 2023
At 27∘C27^{\circ}C27∘C, a solution containing 2.52.52.5 g of solute in 250.0250.0250.0 mL of solution exerts an osmotic pressure of 400400400 Pa. The molar mass of the solute is ___ g mol−1\,mol^{-1}mol−1 (Nearest integer) (Given : R=0.083 L bar K−1 mol−1R = 0.083\ L\,bar\,K^{-1}\,mol^{-1}R=0.083 LbarK−1mol−1)

Correct answer: 62250

Step-by-step solution →
Q99·ChemistrySingle correctJEE Main 2023
Evaluate the following statements for their correctness. A. The elevation in boiling point temperature of water will be same for 0.1M NaCl and 0.1M urea. B. Azeotropic mixtures boil without change in their composition. C. Osmosis always takes place from hypertonic to hypotonic. D. The density of 32% H2SO432\%\,H_2SO_432%H2​SO4​ solution having molarity 4.09M is approximately 1.26 g mL−1^{-1}−1. E. A negatively charged sol is obtained when KI solution is added to silver nitrate solution. Choose the correct answer from the options given below:
  1. (A)A, B and D only
  2. (B)B and D only
  3. (C)B, D and E only
  4. (D)A and C only

Correct answer: (B)

Step-by-step solution →
Q100·ChemistryNumericalJEE Main 2023
A solution containing 222 g of a non-volatile solute in 202020 g of water boils at 373.52373.52373.52 K. The molecular mass of the solute is _________ g mol−1^{-1}−1. (Nearest integer) Given, Water boils at 373373373 K, Kb_bb​ for water = 0.520.520.52 K kg mol−1^{-1}−1

Correct answer: 100

Step-by-step solution →
Q101·ChemistryNumericalJEE Main 2023
Some amount of dichloromethane (CH2_22​Cl2_22​) is added to 671.141671.141671.141 mL of chloroform (CHCl3_33​) to prepare 2.6×10−32.6\times10^{-3}2.6×10−3 M solution of CH2_22​Cl2_22​ (DCM). The concentration of DCM is _________ ppm (by mass). Given: atomic mass C = 12, H = 1, Cl = 35.5, density of CHCl3_33​ = 1.49 g cm−3^{-3}−3

Correct answer: 148.322

Step-by-step solution →
Q102·ChemistryNumericalJEE Main 2023
A lead storage battery contains a 38% by weight solution of H2SO4H_2SO_4H2​SO4​. The van't Hoff factor is 2.67 at this concentration. The temperature in Kelvin at which the solution in the battery will freeze is _______ (nearest integer). (Given Kf=1.8K_f=1.8Kf​=1.8 K kg mol−1^{-1}−1)

Correct answer: 243

Step-by-step solution →
Q103·ChemistrySingle correctJEE Main 2023
Match List I with List II. Choose the correct answer from the options given below:
List IList II
A.van't Hoff factor, iiiI.Cryoscopic constant
B.kfk_fkf​II.Isotonic solutions
C.Solution with same osmotic pressureIII.Normal molar massAbnormal molar mass\dfrac{\text{Normal molar mass}}{\text{Abnormal molar mass}}Abnormal molar massNormal molar mass​
D.AzeotropesIV.Solutions with same composition of vapour above it
  1. (A)A-I, B-III, C-II, D-IV
  2. (B)A-III, B-I, C-IV, D-II
  3. (C)A-III, B-I, C-II, D-IV
  4. (D)A-III, B-II, C-I, D-IV

Correct answer: (C)

Step-by-step solution →
Q104·ChemistryNumericalJEE Main 2023
Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15 °C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at −0.8-0.8−0.8 °C. The solubility product of PbCl2_22​ formed is ________ ×10−6\times 10^{-6}×10−6 at 298 K. (Nearest integer) (Given: Kb_bb​ = 0.5 K kg mol−1^{-1}−1 and Kf_ff​ = 1.8 K kg mol−1^{-1}−1. Assume molality to be equal to molarity in all cases.)

Correct answer: 13

Step-by-step solution →
Q105·ChemistryNumericalJEE Main 2023
The osmotic pressure of solutions of PVC in cyclohexanone at 300 K are plotted on the graph shown in the figure. The molar mass of PVC is _______ g mol−1^{-1}−1 (nearest integer). (Given: R=0.083R=0.083R=0.083 L atm K−1^{-1}−1 mol−1^{-1}−1)

Correct answer: 41500

Step-by-step solution →
Q106·ChemistryNumericalJEE Main 2023
The number of pairs of the solutions having the same value of the osmotic pressure from the following is (Assume 100% ionization) A. 0.500 M C2H5OHC_2H_5OHC2​H5​OH (aq) and 0.25 M KBr (aq) B. 0.100 M K4[Fe(CN)6]K_4[Fe(CN)_6]K4​[Fe(CN)6​] (aq) and 0.100 M FeSO4(NH4)2SO4FeSO_4(NH_4)_2SO_4FeSO4​(NH4​)2​SO4​ (aq) C. 0.05 M K4[Fe(CN)6]K_4[Fe(CN)_6]K4​[Fe(CN)6​] (aq) and 0.25 M NaCl (aq) D. 0.15 M NaCl(aq) and 0.1 M BaCl2BaCl_2BaCl2​(aq) E. 0.02 M KCl⋅MgCl2⋅6H2OKCl\cdot MgCl_2\cdot 6H_2OKCl⋅MgCl2​⋅6H2​O(aq) and 0.05 M KCl(aq)

Correct answer: 4

Step-by-step solution →
Q107·ChemistrySingle correctJEE Main 2023
What is the mass ratio of ethylene glycol (C2H6O2C_2H_6O_2C2​H6​O2​, molar mass =62= 62=62 g/mol) required for making 500500500 g of 0.250.250.25 molal aqueous solution and 250250250 mL of 0.250.250.25 molal aqueous solution?
  1. (A)1 : 1
  2. (B)2 : 1
  3. (C)1 : 2
  4. (D)3 : 1

Correct answer: (B)

Step-by-step solution →
Q108·ChemistryNumericalJEE Main 2023
Number of units, which are used to express concentration of solutions from the following is _________. Mass percentage, Mole, Mole fraction, Molarity, ppm, Molality

Correct answer: 5

Step-by-step solution →
Q109·ChemistrySingle correctJEE Main 2023
In the depression of freezing point experiment: A. Vapour pressure of the solution is less than that of pure solvent. B. Vapour pressure of the solution is more than that of pure solvent. C. Only solute molecules solidify at the freezing point. D. Only solvent molecules solidify at the freezing point. Choose the most appropriate answer from the options given below:
  1. (A)A and C only
  2. (B)A only
  3. (C)A and D only
  4. (D)B and C only

Correct answer: (C)

Step-by-step solution →
Q110·ChemistryNumericalJEE Main 2023
The total pressure observed by mixing two liquids A and B is 350350350 mmHg when their mole fractions are 0.70.70.7 and 0.30.30.3 respectively. The total pressure become 410410410 mmHg if the mole fractions are changed to 0.20.20.2 and 0.80.80.8 respectively for A and B. The vapour pressure of pure A is _________ mmHg. (Nearest integer) Consider the liquids and solutions behave ideally.

Correct answer: 314

Step-by-step solution →
Q111·ChemistryIntegerJEE Advanced 2022
An aqueous solution is prepared by dissolving 0.1 mol of an ionic salt in 1.8 kg of water at 35∘C35^\circ\mathrm{C}35∘C. The salt remains 90% dissociated in the solution. The vapour pressure of the solution is 59.724 mm of Hg. Vapor pressure of water at 35∘C35^\circ\mathrm{C}35∘C is 60.000 mm of Hg. The number of ions present per formula unit of the ionic salt is____.

Correct answer: 5

Step-by-step solution →
Q112·ChemistryNumericalJEE Main 2022
If O2O_{2}O2​ gas is bubbled through water at 303 K, the number of millimoles of O2O_{2}O2​ gas that dissolve in 1 litre of water is________. (Nearest Integer) (Given : Henry's Law constant for O2O_{2}O2​ at 303 K is 46.82 k bar and partial pressure of O2O_{2}O2​ = 0.920 bar) (Assume solubility of O2O_{2}O2​ in water is too small, nearly negligible)

Correct answer: 1

Step-by-step solution →
Q113·ChemistryNumericalJEE Main 2022
1.80 g of solute A was dissolved in 62.5 cm3^{3}3 of ethanol and freezing point of the solution was found to be 155.1 K. The molar mass of solute A is __g mol−1^{-1}−1. [Given: Freezing point of ethanol is 156.0 K. Density of ethanol is 0.80 g cm−3^{-3}−3. Freezing point depression constant of ethanol is 2.00 K kg mol−1^{-1}−1]

Correct answer: 80

Step-by-step solution →
Q114·ChemistryNumericalJEE Main 2022
150 g of acetic acid was contaminated with 10.2 g ascorbic acid (C6_66​H8_88​O6_66​) to lower down its freezing point by (x × 10−1^{-1}−1)°C. The value of x is _________. (Nearest integer) [Given Kf_ff​ = 3.9 K kg mol−1^{-1}−1; Molar mass of ascorbic acid = 176 g mol−1^{-1}−1]

Correct answer: 15

Step-by-step solution →
Q115·ChemistryNumericalJEE Main 2022
A gaseous mixture of two substances A and B, under a total pressure of 0.8 atm is in equilibrium with an ideal liquid solution. The mole fraction of substance A is 0.5 in the vapour phase and 0.2 in the liquid phase. The vapour pressure of pure liquid A is _____ atm. (Nearest integer)

Correct answer: 2

Step-by-step solution →
Q116·ChemistrySingle correctJEE Main 2022
Boiling point of a 2% aqueous solution of a non-volatile solute A is equal to the boiling point of 8% aqueous solution of a non-volatile solute B. The relation between molecular weights of A and B is.
  1. (A)MA=4MBM_{A} = 4M_{B}MA​=4MB​
  2. (B)MB=4MAM_{B} = 4M_{A}MB​=4MA​
  3. (C)MA=8MBM_{A} = 8M_{B}MA​=8MB​
  4. (D)MB=8MAM_{B} = 8M_{A}MB​=8MA​

Correct answer: (B)

Step-by-step solution →
Q117·ChemistrySingle correctJEE Main 2022
250 g solution of D-glucose in water contains 10.8% of carbon by weight. The molality of the solution is nearest to (Given: Atomic Weights are H, 1u ; C, 12u ; O, 16u)
  1. (A)1.03
  2. (B)2.06
  3. (C)3.09
  4. (D)5.40

Correct answer: (B)

Step-by-step solution →
Q118·ChemistryNumericalJEE Main 2022
The elevation in boiling point for 1 molal solution of non-volatile solute A is 3K. The depression in freezing point for 2 molal solution of A in the same solvent is 6 K. The ratio of KbK_{b}Kb​ and KfK_{f}Kf​ i.e., Kb/KfK_{b}/K_{f}Kb​/Kf​ is 1 : X. The value of X is [nearest integer]

Correct answer: 1

Step-by-step solution →
Q119·ChemistrySingle correctJEE Main 2022
The depression in freezing point observed for a formic acid solution of concentration 0.5 mL L−1L^{-1}L−1 is 0.0405°C. Density of formic acid is 1.05 g mL−1mL^{-1}mL−1. The Van't Hoff factor of the formic acid solution is nearly : (Given for water kfk_{f}kf​= 1.86 K kg mol−1mol^{-1}mol−1)
  1. (A)0.8
  2. (B)1.1
  3. (C)1.9
  4. (D)2.4

Correct answer: (C)

Step-by-step solution →
Q120·ChemistryNumericalJEE Main 2022
Elevation in boiling point for 1.5 molal solution of glucose in water is 4K. The depression in freezing point for 4.5 molal solution of glucose in water is 4K. The ratio of molal elevation constant to molal depression constant (Kb_bb​/Kf_ff​) is______.

Correct answer: 3

Step-by-step solution →
Q121·ChemistryNumericalJEE Main 2022
1.2 mL of acetic acid is dissolved in water to make 2.0 L of solution. The depression in freezing point observed for this strength of acid is 0.0198°C. The percentage of dissociation of the acid is _______ . (Nearest integer) [Given : Density of acetic acid is 1.02 g mL−1mL^{-1}mL−1 Molar mass of acetic acid is 60 g mol−1mol^{-1}mol−1 KfK_fKf​ (H2OH_2OH2​O) = 1.85 K kg mol−1mol^{-1}mol−1]

Correct answer: 5

Step-by-step solution →
Q122·ChemistryNumericalJEE Main 2022
2.5 g of protein containing only glycine (C2_22​H5_55​NO2_22​) is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be 5.03 × 10−3^{-3}−3 bar. The total number of glycine units present in the protein is ______ (Given : R = 0.083 L bar K−1^{-1}−1 mol−1^{-1}−1)

Correct answer: 330

Step-by-step solution →
Q123·ChemistryNumericalJEE Main 2022
The vapour pressures of two volatile liquids A and B at 25°C are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0.3 mole fraction of A, then the mole fraction of liquid B in the vapour phase is x17\frac{x}{17}17x​. The value of x is ________.

Correct answer: 14

Step-by-step solution →
Q124·ChemistrySingle correctJEE Main 2022
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R) Assertion (A) : At 10°C, the density of a 5M solution of KCl [atomic masses of K and Cl are 39 & 35.5 g mol−1mol^{-1}mol−1]. The solution is cooled to -21°C. The molality of the solution will remain unchanged. Reason (R) : The molality of a solution does not change with temperature as mass remains unaffected with temperature. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. (B)Both (A) and (R) are true but (R) is not the correct explanation of (A)
  3. (C)(A) is true but (R) is false
  4. (D)(A) is false but (R) is true

Correct answer: (A)

Step-by-step solution →
Q125·ChemistryNumericalJEE Main 2022
2g of a non-volatile non-electrolyte solute is dissolved in 200 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 8. The elevation in boiling points of A and B are in the ratio xy\frac{x}{y}yx​ (x : y). The value of y is__________ (Nearest integer)

Correct answer: 8

Step-by-step solution →
Q126·ChemistryNumericalJEE Main 2022
A solution containing 2.5 ×\times× 10−3^{-3}−3 kg of a solute dissolved in 75 ×\times× 10−3^{-3}−3 kg of water boils at 373.535 K. The molar mass of the solute is _______ g mol−1^{-1}−1. [nearest integer] (Given: Kb_bb​ (H2_22​O) = 0.52 K Kg mol−1^{-1}−1 , boiling point of water = 373.15K)

Correct answer: 45

Step-by-step solution →
Q127·ChemistryNumericalJEE Main 2022
The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol−1mol^{-1}mol−1 in 200 mL of water at 27°C is ________ Pa. [integer value] (use R = 0.083 L bar mol−1mol^{-1}mol−1 K−1K^{-1}K−1)

Correct answer: 415

Step-by-step solution →
Q128·ChemistryNumericalJEE Main 2022
A 0.5 percent solution of potassium chloride was found to freeze at –0.24°C. The percentage dissociation of potassium chloride is ______. (Nearest integer) (Molal depression constant for water is 1.80 K kg mol−1mol^{-1}mol−1 and molar mass of KCl is 74.6 g mol−1mol^{-1}mol−1)

Correct answer: 98

Step-by-step solution →
Q129·ChemistrySingle correctJEE Main 2022
Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 g of water, it depresses the freezing point by 0.2∘^{\circ}∘C. The percentage association of solute A in water, is [Given : Molar mass of A = 93 g mol−1^{-1}−1. Molal depression constant of water is 1.86 K kg mol−1^{-1}−1]
  1. (A)50 %
  2. (B)60 %
  3. (C)70 %
  4. (D)80 %

Correct answer: (D)

Step-by-step solution →
Q130·ChemistryNumericalJEE Main 2022
The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL−1^{-1}−1 is _____(Molar mass of glucose = 180 g mol−1^{-1}−1 R = 0.083 L bar K−1^{-1}−1 mol−1^{-1}−1) (Nearest integer)

Correct answer: 54

Step-by-step solution →
Q131·ChemistryNumericalJEE Advanced 2021
The boiling point of water in a 0.1 molal silver nitrate solution (solution A\mathbf{A}A) is x\mathbf{x}x ∘^\circ∘C. To this solution A\mathbf{A}A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B\mathbf{B}B. The difference in the boiling points of water in the two solutions A\mathbf{A}A and B\mathbf{B}B is y×10−2\mathbf{y} \times 10^{-2}y×10−2 ∘^\circ∘C. (Assume : Densities of the solutions A\mathbf{A}A and B\mathbf{B}B are the same as that of water and the soluble salts dissociate completely.) Use: Molal elevation constant (Ebullioscopic Constant), Kb=0.5K_b = 0.5Kb​=0.5 K kg mol−1^{-1}−1; Boiling point of pure water as 100∘^\circ∘C.) The value of x\mathbf{x}x is _______.

Correct answer: 100.10

Step-by-step solution →
Q132·ChemistryNumericalJEE Advanced 2021
The boiling point of water in a 0.1 molal silver nitrate solution (solution A\mathbf{A}A) is x\mathbf{x}x ∘^\circ∘C. To this solution A\mathbf{A}A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B\mathbf{B}B. The difference in the boiling points of water in the two solutions A\mathbf{A}A and B\mathbf{B}B is y×10−2\mathbf{y} \times 10^{-2}y×10−2 ∘^\circ∘C. (Assume : Densities of the solutions A\mathbf{A}A and B\mathbf{B}B are the same as that of water and the soluble salts dissociate completely.) Use: Molal elevation constant (Ebullioscopic Constant), Kb=0.5K_b = 0.5Kb​=0.5 K kg mol−1^{-1}−1; Boiling point of pure water as 100∘^\circ∘C.) The value of ∣y∣|\mathbf{y}|∣y∣ is _____ .

Correct answer: 2.50

Step-by-step solution →
Q133·ChemistrySingle correctJEE Main 2021
Which one of the following 0.10 M aqueous solutions will exhibit the largest freezing point depression ?
  1. (A)hydrazine
  2. (B)glucose
  3. (C)glycine
  4. (D)KHSO4\mathrm{KHSO_4}KHSO4​

Correct answer: (D)

Step-by-step solution →
Q134·ChemistryNumericalJEE Main 2021
1.22 g of an organic acid is separately dissolved in 100 g of benzene (Kb\mathrm{K_b}Kb​ = 2.6 K kg mol−1^{-1}−1) and 100 g of acetone (Kb\mathrm{K_b}Kb​ = 1.7 K kg mol−1^{-1}−1). The acid is known to dimerize in benzene but remain as a monomer in acetone. The boiling point of the solution in acetone increases by 0.17°C. The increase in boiling point of solution in benzene in °C is x ×\times× 10−2^{-2}−2. The value of x is ________.(Nearest integer) [Atomic mass : C = 12.0, H = 1.0, O= 16.0]

Correct answer: 13

Step-by-step solution →
Q135·ChemistryNumericalJEE Main 2021
40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is _____ K. (Nearest integer) [Given : Kf_{f}f​ = 1.86 K kg mol−1^{-1}−1 ; Density of water = 1.00 g cm−3^{-3}−3; Freezing point of water = 273.15 K]

Correct answer: 271

Step-by-step solution →
Q136·ChemistryNumericalJEE Main 2021
1 kg of 0.75 molal aqueous solution of sucrose can be cooled up to −4∘C-4^\circ C−4∘C before freezing. The amount of ice (in g) that will be separated out is ________ . (Nearest integer) [Given : Kf(H2O)=1.86K_f(H_2O) = 1.86Kf​(H2​O)=1.86 K kg mol−1mol^{-1}mol−1]

Correct answer: 518

Step-by-step solution →
Q137·ChemistryNumericalJEE Main 2021
83 g of ethylene glycol dissolved in 625 g of water. The freezing point of the solution is ________K. (Nearest integer) [Use : Molal Freezing point depression constant of water = 1.86 K kg mol−1^{-1}−1] Freezing Point of water = 273 K Atomic masses : C : 12.0 u, O : 16.0 u, H : 1.0 u]

Correct answer: 269

Step-by-step solution →
Q138·ChemistryNumericalJEE Main 2021
An aqueous KCl solution of density 1.20 g mL−11.20\ g\ mL^{-1}1.20 g mL−1 has a molality of 3.30 mol kg−13.30\ mol\ kg^{-1}3.30 mol kg−1. The molarity of the solution in mol L−1mol\ L^{-1}mol L−1 is ________ (Nearest integer) [Molar mass of KCl = 74.5]

Correct answer: 3

Step-by-step solution →
Q139·ChemistryNumericalJEE Main 2021
Of the following four aqueous solutions, total number of those solutions whose freezing point is lower than that of 0.10 M C2H5OH0.10\ M\ C_2H_5OH0.10 M C2​H5​OH is ________ (Integer answer) (i) 0.10 M Ba3(PO4)20.10\ M\ Ba_3(PO_4)_20.10 M Ba3​(PO4​)2​ (ii) 0.10 M Na2SO40.10\ M\ Na_2SO_40.10 M Na2​SO4​ (iii) 0.10 M KCl0.10\ M\ KCl0.10 M KCl (iv) 0.10 M Li3PO40.10\ M\ Li_3PO_40.10 M Li3​PO4​

Correct answer: 4

Step-by-step solution →
Q140·ChemistryNumericalJEE Main 2021
1.46 g of a biopolymer dissolved in a 100 mL water at 300 K exerted an osmotic pressure of 2.42×10−32.42 \times 10^{-3}2.42×10−3 bar. The molar mass of the biopolymer is ____________ ×104\times 10^4×104 g mol−1^{-1}−1. (Round off to the Nearest integer) [ Use : R = 0.083 L bar mol−1^{-1}−1 K−1^{-1}−1 ]

Correct answer: 15

Step-by-step solution →
Q141·ChemistryNumericalJEE Main 2021
In a solvent 50% of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is ______________ ×10−2^{-2}−2. (Round off to the Nearest Integer).

Correct answer: 125

Step-by-step solution →
Q142·ChemistryNumericalJEE Main 2021
When 3.00 g of substance ‘X” is dissolved in 100 g of CCl4_44​, it raises the boiling point by 0.60K. The molar mass of the substance ‘X” is __________ g mol−1^{-1}−1. (nearest integer) [Given Kb_bb​ for CCl4_44​ is 5.0 K kg mol−1^{-1}−1]

Correct answer: 250

Step-by-step solution →
Q143·ChemistryNumericalJEE Main 2021
CO2_22​ gas is bubbled through water during a soft drink manufacturing process at 298 K. If CO2_22​ exerts a partial pressure of 0.835 bar then x m mol of CO2_22​ would dissolve in 0.9 L of water. The value of x is__________(Nearest integer) (Henry's law constant for CO2_22​ at 298 K is 1.67×103\times 10^{3}×103 bar)

Correct answer: 25

Step-by-step solution →
Q144·ChemistrySingle correctJEE Main 2021
Which one of the following 0.06 M aqueous solutions has lowest freezing point ?
  1. (A)KI
  2. (B)C6H12O6C_6H_{12}O_6C6​H12​O6​
  3. (C)K2SO4K_2SO_4K2​SO4​
  4. (D)Al2(SO4)3Al_2(SO_4)_3Al2​(SO4​)3​

Correct answer: (D)

Step-by-step solution →
Q145·ChemistryNumericalJEE Main 2021
At 20°C, the vapour pressure of benzene is 70 torr and that of methyl benzene is 20 torr. The mole fraction of benzene in the vapour phase at 20°C above an equimolar mixture of benzene and methyl benzene is ______________ ×10−2\times 10^{-2}×10−2. (Nearest integer)

Correct answer: 78

Step-by-step solution →
Q146·ChemistryNumericalJEE Main 2021
The vapour pressures of A and B at 25∘C25^\circ \mathrm{C}25∘C are 90 mm Hg and 15 mm Hg respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x×10−1x \times 10^{-1}x×10−1. The value xxx is ________. (Nearest Integer)

Correct answer: 1

Step-by-step solution →
Q147·ChemistryNumericalJEE Main 2021
A solute a dimerizes in water. The boiling point of a 2 molar solution of A is 100.52°C. The percentage association of A is. ____ . (Round off to the Nearest integer) [Use : Kb_{b}b​ for water = 0.52 K kg mol−1^{-1}−1 Boiling point of water = 100°C]

Correct answer: 100

Step-by-step solution →
Q148·ChemistryNumericalJEE Main 2021
The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is ________ ×10−5\times 10^{-5}×10−5 mol dm−3\mathrm{dm^{-3}}dm−3. (Round off to the Nearest Integer). [Given : Henry's law constant =KH=8.0×104= \mathrm{K_H} = 8.0 \times 10^{4}=KH​=8.0×104 kPa for O2\mathrm{O_2}O2​. Density of water with dissolved oxygen =1.0= 1.0=1.0 kg dm−3\mathrm{dm^{-3}}dm−3]

Correct answer: 1389

Step-by-step solution →
Q149·ChemistryNumericalJEE Main 2021
A 1 molal K4_{4}4​Fe(CN)6_{6}6​ solution has a degree of dissociation of 0.4. Its boiling point is equal to that of another solution which contains 18.1 weight percent of a non electrolytic solute A. The molar mass of A is____ u. (Round off to the Nearest Integer). [Density of water = 1.0 g cm−3^{-3}−3]

Correct answer: 85

Step-by-step solution →
Q150·ChemistryNumericalJEE Main 2021
The mole fraction of a solute in a 100 molal aqueous solution ________ ×10−2\times 10^{-2}×10−2. (Round off to the Nearest Integer). [Given : Atomic masses : H : 1.0 u, O : 16.0 u]

Correct answer: 64

Step-by-step solution →
Q151·ChemistryNumericalJEE Main 2021
At 363 K, the vapour pressure of A is 21 kPa and that of B is 18 kPa. One mole of A and 2 moles of B are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is ________ kPa. (Round of to the Nearest Integer).

Correct answer: 19

Step-by-step solution →
Q152·ChemistryNumericalJEE Main 2021
A 6.50 molal solution of KOH (aq.) has a density of 1.89 g cm−3^{-3}−3. The molarity of the solution is ________ mol dm−3^{-3}−3. (Round off to the Nearest Integer). [Atomic masses: K :39.0 u; O :16.0 u; H :1.0 u]

Correct answer: 9

Step-by-step solution →
Q153·ChemistryNumericalJEE Main 2021
AB2_{2}2​ is 10% dissociated in water to A2+^{2+}2+ and B−^{-}−. The boiling point of a 10.0 molal aqueous solution of AB2_{2}2​ is _______ °C. (Round off to the Nearest Integer). [Given : Molal elevation constant of water Kb_{b}b​ = 0.5 K kg mol−1^{-1}−1 boiling point of pure water = 100°C]

Correct answer: 106

Step-by-step solution →
Q154·ChemistryNumericalJEE Main 2021
When 12.2 g of benzoic acid is dissolved in 100g of water, the freezing point of solution was found to be −0.93°C (KfK_fKf​ (H2OH_2OH2​O) = 1.86 K kg mol−1mol^{-1}mol−1). The number (n) of benzoic acid molecules associated (assuming 100% association ) is_______________.

Correct answer: 2

Step-by-step solution →
Q155·ChemistryNumericalJEE Main 2021
If a compound AB dissociates to the extent of 75% in an aqueous solution, the molality of the solution which shows a 2.5 K rise in the boiling point of the solution is ______molal. (Rounded-off to the nearest integer) [Kb=0.52 K kg mol−1^{-1}−1]

Correct answer: 3

Step-by-step solution →
Q156·ChemistryNumericalJEE Main 2021
1 molal aqueous solution of an electrolyte A2_{2}2​B3_{3}3​ is 60% ionised. The boiling point of the solution at 1 atm is _______ K. (Rounded-off to the nearest integer) [Given Kb_{b}b​ for (H2_{2}2​O) = 0.52 K kg mol−1^{-1}−1]

Correct answer: 375

Step-by-step solution →
Q157·ChemistryNumericalJEE Main 2021
C6H6C_{6}H_{6}C6​H6​ freezes at 5.5ºC. The temperature at which a solution of 10 g of C4H10C_{4}H_{10}C4​H10​ in 200 g of C6H6C_{6}H_{6}C6​H6​ freeze is ________ºC. (The molal freezing point depression constant of C6H6C_{6}H_{6}C6​H6​ is) 5.12ºC/m)

Correct answer: 1

Step-by-step solution →
Q158·ChemistryNumericalJEE Main 2021
When 9.45g of ClCH2COOH\mathrm{ClCH_2COOH}ClCH2​COOH is added to 500 mL of water, its freezing point drops by 0.5°C. The dissociation constant of ClCH2COOH\mathrm{ClCH_2COOH}ClCH2​COOH is x×10−3x \times 10^{-3}x×10−3. The value of x is ________. (Rounded off to the nearest integer) [Kf(H2O)=1.86 K kg mol−1][\mathrm{K_{f(H_2O)}} = 1.86\,\mathrm{K\,kg\,mol^{-1}}][Kf(H2​O)​=1.86Kkgmol−1]

Correct answer: 35

Step-by-step solution →
Q159·ChemistryNumericalJEE Advanced 2020
Liquids A and B form ideal solution for all compositions of A and B at 25°C. Two such solutions with 0.25 and 0.50 mole fractions of A have the total vapor pressures of 0.3 and 0.4 bar, respectively. What is the vapor pressure of pure liquid B in bar?

Correct answer: 0.20

Step-by-step solution →
Q160·ChemistrySingle correctJEE Main 2020
A solution of two components containing n1n_1n1​ moles of the 1st1^{st}1st component and n2n^2n2 moles of the 2nd2^{nd}2nd component is prepared. M1M_1M1​ and M2M_2M2​ are the molecular weights of component 1 and 2 respectively. If d is the density of the solution in gmL−1gmL^{-1}gmL−1, C2C_2C2​ is the molarity and x2x_2x2​ is the mole fraction of the 2nd2^{nd}2nd component, then C2C_2C2​ can be expressed as:
  1. (A)C2=1000x2M1+x2(M2−M1)C_2 = \dfrac{1000x_2}{M_1+x_2(M_2-M_1)}C2​=M1​+x2​(M2​−M1​)1000x2​​
  2. (B)C2=dx2M2+x2(M2−M1)C_2 = \dfrac{dx_2}{M_2+x_2(M_2-M_1)}C2​=M2​+x2​(M2​−M1​)dx2​​
  3. (C)C2=1000dx2M1+x2(M2−M1)C_2 = \dfrac{1000dx_2}{M_1+x_2(M_2-M_1)}C2​=M1​+x2​(M2​−M1​)1000dx2​​
  4. (D)C2=dx1M2+x2(M2−M1)C_2 = \dfrac{dx_1}{M_2+x_2(M_2-M_1)}C2​=M2​+x2​(M2​−M1​)dx1​​

Correct answer: (C)

Step-by-step solution →
Q161·ChemistrySingle correctJEE Main 2020
A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C. The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A = 100 g mol−1^{-1}−1 ; B = 200 g mol−1^{-1}−1 ; C = 10,000 g mol−1^{-1}−1]
  1. (A)B > C > A
  2. (B)C > B > A
  3. (C)A > B > C
  4. (D)A > C > B

Correct answer: (C)

Step-by-step solution →
Q162·ChemistryNumericalJEE Main 2020
A soft drink was bottled with a partial pressure of CO2CO_2CO2​ of 3 bar over the liquid at room temperature. The partial pressure of CO2CO_2CO2​ over the solution approaches a value of 30 bar when 44 g of CO2CO_2CO2​ is dissolved in 1 kg of water at room temperature. The approximate pH of the soft drink is ___ x 10−110^{-1}10−1/ (First dissociation constant of H2CO3H_2CO_3H2​CO3​ = 4.0×10−74.0\times10^{-7}4.0×10−7;log 2 = 0.3; density of the soft drink = 1 g mL−1mL^{-1}mL−1)

Correct answer: 37

Step-by-step solution →
Q163·ChemistryNumericalJEE Main 2020
At 300K, the vapour pressure of a solution containing 1 mole of n-hexane and 3 moles of n-heptane is 550 mm of Hg. At the same temperature, if one more mole of n-heptane is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. What is the vapour pressure in mm Hg of n-heptane in its pure state ________?

Correct answer: 600

Step-by-step solution →
Q164·ChemistryNumericalJEE Main 2020
The osmotic pressure of a solution of NaCl is 0.10 atm and that of a glucose solution is 0.20 atm. The osmotic pressure of a solution formed by mixing 1 L of the sodium chloride solution with 2 L of the glucose solution is x×10−3x \times 10^{-3}x×10−3 atm. x is ………….. (nearest integer)

Correct answer: 167

Step-by-step solution →
Q165·ChemistryNumericalJEE Main 2020
The mole fraction of glucose (C6_66​H12_{12}12​O6_66​) in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is __________.

Correct answer: 47

Step-by-step solution →
Q166·ChemistrySingle correctJEE Main 2020
Henry's constant (in kbar) for four gases α, β, γ and δ in water at 298 K is given below: (density of water = 103^33 kg m−3^{-3}−3 at 298 K) This table implies that:
αβγδ
KH_HH​5022 ×\times× 10−5^{-5}−50.5
  1. (A)α has the highest solubility in water at a given pressure
  2. (B)solubility of γ at 308 K is lower than at 298 K.
  3. (C)The pressure of a 55.5 molal solution of δ is 250 bar.
  4. (D)The pressure of a 55.5 molal solution of γ is 1 bar.

Correct answer: (C)

Step-by-step solution →
Q167·ChemistryNumericalJEE Main 2020
If 250 cm3^{3}3 of an aqueous solution containing 0.73 g of a protein A is isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ______ ×10−2\times 10^{-2}×10−2 (to the nearest integer).

Correct answer: 177

Step-by-step solution →
Q168·ChemistrySingle correctJEE Main 2020
At 35°C, the vapour pressure of CS2_22​ is 512 mm of Hg and that of acetone is 344 mm of Hg. A solution of CS2_22​ in acetone has a total vapour pressure of 600 mm of Hg. The false statement among the following is
  1. (A)CS2_22​ and acetone are less attracted to each other than to themselves
  2. (B)Heat must be absorbed in order to produce the solution at 35°C
  3. (C)Raoult's law is not obeyed by this system
  4. (D)a mixture of 100 mL CS2_22​ and 100 mL acetone has a volume of < 200 mL

Correct answer: (D)

Step-by-step solution →
Q169·ChemistrySingle correctJEE Main 2020
Two open beakers one containing a solvent and the other containing a mixture of that solvent with a non-volatile solute are together sealed in a container. Over time
  1. (A)the volume of the solution increases and the volume of the solvent decreases
  2. (B)the volume of the solution and the solvent does not change
  3. (C)the volume of the solution does not change and the volume of the solvent decreases
  4. (D)the volume of the solution decreases and the volume of the solvent increases

Correct answer: (A)

Step-by-step solution →
Q170·ChemistryNumericalJEE Advanced 2019
The mole fraction of urea in an aqueous urea solution containing 900 g of water is 0.05. If the density of the solution is 1.2 g cm−3^{-3}−3, the molarity of urea solution is_______ (Given data: Molar masses of urea and water are 60 g mol−1^{-1}−1 and 18 g mol−1^{-1}−1, respectively)

Correct answer: 2.98

Step-by-step solution →
Q171·ChemistryNumericalJEE Advanced 2019
On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapour pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is (Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol−1^{-1}−1 and 5.12 K kg mol−1^{-1}−1, respectively)

Correct answer: 1.02 or 1.03

Step-by-step solution →
Q172·ChemistrySingle correctJEE Main 2019
A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol−1^{-1}−1) and 1.8 g of glucose (molar mass = 180 g mol−1^{-1}−1) in 100 mL of water at 27°C. The osmotic pressure of the solution is : (R = 0.08206 L atm K−1^{-1}−1 mol−1^{-1}−1)
  1. (A)8.2 atm
  2. (B)1.64 atm
  3. (C)4.92 atm
  4. (D)2.46 atm

Correct answer: (C)

Step-by-step solution →
Q173·ChemistrySingle correctJEE Main 2019
The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg−1^{-1}−1) of the aqueous solution is
  1. (A)13.88×10−213.88 \times 10^{-2}13.88×10−2
  2. (B)13.88×10−113.88 \times 10^{-1}13.88×10−1
  3. (C)13.8813.8813.88
  4. (D)13.88×10−313.88 \times 10^{-3}13.88×10−3

Correct answer: (C)

Step-by-step solution →
Q174·ChemistrySingle correctJEE Main 2019
At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea = 60 g mol−1^{-1}−1)
  1. (A)0.027 mmHg
  2. (B)0.031 mmHg
  3. (C)0.028 mmHg
  4. (D)0.017 mmHg

Correct answer: (D)

Step-by-step solution →
Q175·ChemistrySingle correctJEE Main 2019
1 g of non-volatile non-electrolyte solute is dissolved in 100g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, ΔTb(A)ΔTb(B)\dfrac{\Delta T_b(A)}{\Delta T_b(B)}ΔTb​(B)ΔTb​(A)​ is :
  1. (A)5 : 1
  2. (B)10 : 1
  3. (C)1 : 5
  4. (D)1 : 0.2

Correct answer: (C)

Step-by-step solution →
Q176·ChemistrySingle correctJEE Main 2019
What would be the molality of 20% (mass/mass) aqueous solution of KI? (molar mass of KI = 166 g mol−1^{-1}−1)
  1. (A)1.08
  2. (B)1.48
  3. (C)1.51
  4. (D)1.35

Correct answer: (C)

Step-by-step solution →
Q177·ChemistrySingle correctJEE Main 2019
The osmotic pressure of a dilute solution of an ionic compound XY in water is four times that of a solution of 0.01 M BaCl2BaCl_2BaCl2​ in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of XY (in mol L−1L^{-1}L−1) in solution is
  1. (A)4×10−44 \times 10^{-4}4×10−4
  2. (B)6×10−26 \times 10^{-2}6×10−2
  3. (C)16×10−416 \times 10^{-4}16×10−4
  4. (D)4×10−24 \times 10^{-2}4×10−2

Correct answer: (B)

Step-by-step solution →
Q178·ChemistrySingle correctJEE Main 2019
Molal depression constant for a solvent is 4.0 K Kg mol−1^{-1}−1. The depression in the freezing point of the solvent for 0.03 mol kg−1^{-1}−1 solution of K2_22​SO4_44​ is: (Assume complete dissociation of the electrolyte)
  1. (A)0.12 K
  2. (B)0.36 K
  3. (C)0.18 K
  4. (D)0.24 K

Correct answer: (B)

Step-by-step solution →
Q179·ChemistrySingle correctJEE Main 2019
The vapour pressures of pure liquids A and B are 400 and 600 mm Hg, respectively at 298 K. On mixing the two liquids, the sum of their initial volumes is equal to the volume of the final mixture. The mole fraction of liquid B is 0.5 in the mixture. The vapour pressure of the final solution, the mole fractions of components A and B in vapour phase, respectively are:
  1. (A)500 mmHg, 0.4, 0.6
  2. (B)500 mmHg, 0.5, 0.5
  3. (C)450 mmHg, 0.5, 0.5
  4. (D)450 mmHg, 0.4, 0.6

Correct answer: (A)

Step-by-step solution →
Q180·ChemistrySingle correctJEE Main 2019
Molecules of benzoic acid (C6_{6}6​H5_{5}5​COOH) dimerise in benzene. 'w' g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is : (Given that Kf_{f}f​ = 5 K kg mol−1^{-1}−1, Molar mass of benzoic acid = 122 g mol−1^{-1}−1)
  1. (A)2.4 g
  2. (B)1.0 g
  3. (C)1.5 g
  4. (D)1.8 g

Correct answer: (A)

Step-by-step solution →
Q181·ChemistrySingle correctJEE Main 2019
Freezing point of a 4% aqueous solution of X is equal to freezing point of 12% aqueous solution of Y. If molecular weight of X is A then molecular weight of Y is
  1. (A)3A
  2. (B)2A
  3. (C)A
  4. (D)4A

Correct answer: (A)

Step-by-step solution →
Q182·ChemistrySingle correctJEE Main 2019
8 g of NaOH is dissolved in 18 g of H2_{2}2​O. Mole fraction of NaOH in solution and molality (in mol kg−1^{-1}−1) of the solution respectively are :
  1. (A)0.2, 22.20
  2. (B)0.2, 11.11
  3. (C)0.167, 11.11
  4. (D)0.167, 22.20

Correct answer: (C)

Step-by-step solution →
Q183·ChemistrySingle correctJEE Main 2019
K2_22​HgI4_44​ is 40% ionized in aqueous solution. The value of its van't Hoff factor (i) is:
  1. (A)1.6
  2. (B)1.8
  3. (C)2.0
  4. (D)2.2

Correct answer: (B)

Step-by-step solution →
Q184·ChemistrySingle correctJEE Main 2019
The freezing point of diluted milk sample is found to be −0.2∘C-0.2^{\circ}C−0.2∘C, while it should have been 0.5∘C0.5^{\circ}C0.5∘C for pure milk. How much water been added to pure milk to make the diluted sample?
  1. (A)1 cup of water to 2 cups of pure milk
  2. (B)3 cups of water to 2 cups of pure milk
  3. (C)1 cup of water to 3 cups of pure milk
  4. (D)2 cups of water to 3 cups of pure milk

Correct answer: (B)

Step-by-step solution →
Q185·ChemistrySingle correctJEE Main 2019
Liquids A and B form and ideal solution in the entire composition range. At 350 K, the vapour pressures of pure A and pure B are 7 ×\times× 103^{3}3 Pa and 12 ×\times× 103^{3}3 Pa, respectively. The composition of the vapour in equilibrium with a solution containing 40 mole percent of A at this temperature is
  1. (A)xA_{A}A​ = 0.37; xB_{B}B​ = 0.63
  2. (B)xA_{A}A​ = 0.28; xB_{B}B​ = 0.72
  3. (C)xA_{A}A​ = 0.4; xB_{B}B​ = 0.6
  4. (D)xA_{A}A​ = 0.76; xB_{B}B​ = 0.24

Correct answer: (B)

Step-by-step solution →
Q186·ChemistrySingle correctJEE Main 2019
A solution of sodium sulphate contains 92 g of Na+^{+}+ ions per kilogram of water. The Molality of Na+^{+}+ ions in that solution in mol kg−1^{-1}−1 is
  1. (A)12
  2. (B)4
  3. (C)8
  4. (D)16

Correct answer: (B)

Step-by-step solution →
Q187·ChemistrySingle correctJEE Main 2019
Which one of the following statements regarding Henry's law is not correct?
  1. (A)Higher the value of KH_{H}H​ at a given pressure, higher is the solubility of the gas in the liquids
  2. (B)Different gases have different KH_{H}H​(Henry's law constant) values at the same temperature
  3. (C)The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution
  4. (D)The value of KH_{H}H​ increases with increase of temperature and KH_{H}H​ is function of the nature of the gas.

Correct answer: (A)

Step-by-step solution →
Q188·ChemistrySingle correctJEE Main 2019
A solution containing 62 g ethylene glycol in 250 g water is cooled to -10°C. If Kf_ff​ for water is 1.86 K kg mol−1^{-1}−1, the amount of water(in g) separated as ice is
  1. (A)48
  2. (B)32
  3. (C)64
  4. (D)16

Correct answer: (C)

Step-by-step solution →
Q189·ChemistryNumericalJEE Advanced 2018
Liquids A and B form ideal solution over the entire range of composition. At temperature T, equimolar binary solution of liquids A and B has vapour pressure 45 Torr. At the same temperature, a new solution of A and B having mole fractions xAx_{A}xA​ and xBx_{B}xB​, respectively, has vapour pressure of 22.5 Torr. The value of xA/xBx_{A}/x_{B}xA​/xB​ in the new solution is ___. (given that the vapour pressure of pure liquid A is 20 Torr at temperature T)

Correct answer: 19

Step-by-step solution →
Q190·ChemistryNumericalJEE Advanced 2018
The plot given below shows P—T curves (where PPP is the pressure and TTT is the temperature) for two solvents X and Y and isomolal solutions of NaCl in these solvents. NaCl completely dissociates in both the solvents. On addition of equal number of moles of a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is ___.

Correct answer: 0.05

Step-by-step solution →
Q191·ChemistryMultiple correctJEE Advanced 2017
For a solution formed by mixing liquids L and M, the vapour pressure of L plotted against the mole fraction of M in solution is shown in the following figure. Here xLx_{L}xL​ and xMx_{M}xM​ represent mole fractions of L and M, respectively, in the solution. The correct statement(s) applicable to this system is(are)
  1. (A)Attractive intermolecular interactions between L-L in pure liquid L and M-M in pure liquid M are stronger than those between L-M when mixed in solution
  2. (B)The point Z represents vapour pressure of pure liquid M and Raoult's law is obeyed when xL→0x_{L} \rightarrow 0xL​→0
  3. (C)The point Z represents vapour pressure of pure liquid L and Raoult's law is obeyed when xL→1x_{L} \rightarrow 1xL​→1
  4. (D)The point Z represents vapour pressure of pure liquid M and Raoult's law is obeyed from xL=0x_{L} = 0xL​=0 to xL=1x_{L} = 1xL​=1

Correct answer: (A), (C)

Step-by-step solution →
Q192·ChemistrySingle correctJEE Advanced 2017
Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water changes the freezing point of the solution. Use the freezing point depression constant of water as 2 K kg mol−1^{-1}−1. The figures shown below represent plots of vapour pressure (V.P.) versus temperature (T). [molecular weight of ethanol is 46 g mol−1^{-1}−1] Among the following, the option representing change the freezing point is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q193·ChemistryIntegerJEE Advanced 2016
The mole fraction of a solute in a solution is 0.1. At 298 K, molarity of this solution is the same as its molality. Density of this solution at 298 K is 2.0 g cm−3cm^{-3}cm−3. The ratio of the molecular weights of the solute and solvent, (MWsoluteMWsolvent)\left(\dfrac{MW_{solute}}{MW_{solvent}}\right)(MWsolvent​MWsolute​​), is

Correct answer: 9

Step-by-step solution →
Q194·ChemistryMultiple correctJEE Advanced 2016
Mixture (s) showing positive deviation from Raoult’s law at 35°C is (are)
  1. (A)carbon tetrachloride + methanol
  2. (B)carbon disulphide + acetone
  3. (C)benzene + toluene
  4. (D)phenol + aniline

Correct answer: (A), (B)

Step-by-step solution →
Q195·ChemistryIntegerJEE Advanced 2015
If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex (which behaves as a strong electrolyte) is −0.0558 0-0.0558\,^{0}−0.05580C, the number of chloride(s) in the coordination sphere of the complex is [KfK_{f}Kf​ of water = 1.86 K kg mol−1^{-1}−1]

Correct answer: 1

Step-by-step solution →
Q196·ChemistryIntegerJEE Advanced 2014
A compound H2XH_2XH2​X with molar weight of 80 g80 \text{ g}80 g is dissolved in a solvent having density of 0.4 g mL−10.4 \text{ g mL}^{-1}0.4 g mL−1. Assuming no change in volume upon dissolution, the molality of a 3.23.23.2 molar solution is

Correct answer: 8

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Q197·ChemistryIntegerJEE Advanced 2014
MX2MX_2MX2​ dissociates in M2+M^{2+}M2+ and X−X^-X− ions in an aqueous solution, with a degree of dissociation (α)(\alpha)(α) of 0.50.50.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

Correct answer: 2

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Q198·ChemistryMultiple correctJEE Advanced 2013
Benzene and naphthalene form an ideal solution at room temperature. For this process, the true statement(s) is(are)
  1. (A)ΔG\Delta GΔG is positive
  2. (B)ΔSsystem\Delta S_{system}ΔSsystem​ is positive
  3. (C)ΔSsurroundings=0\Delta S_{surroundings} = 0ΔSsurroundings​=0
  4. (D)ΔH=0\Delta H = 0ΔH=0

Correct answer: (B), (C), (D)

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Solutions — frequently asked

How many questions from Solutions appear in JEE?

Solutions has appeared in 158 of the last 186 JEE Main and JEE Advanced papers — about 85% of them — contributing 198 questions in total across those papers.

Is Solutions an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 85% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Solutions questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Chemistry chapters

  • Coordination Compounds 318
  • p-Block Elements 276
  • Redox Reactions and Electrochemistry 265
  • Chemical Bonding and Molecular Structure 207
  • d- and f-Block Elements 202
  • Aldehydes and Ketones 199
  • Equilibrium 199
  • Chemical Thermodynamics 195

All 36 Chemistry chapters →

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