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Carboxylic Acids and Derivatives — JEE Previous Year Questions

Every Carboxylic Acids and Derivatives question asked in JEE Main and JEE Advanced across the last 186 papers — 64 questions, each with its correct answer. Free to read, no account needed.

Questions

64

Papers it appeared in

54/186

Appearance rate

29%

All 64 Carboxylic Acids and Derivatives questions

Most recent papers first.

Q1·ChemistryNumericalJEE Advanced 2026
The sum of total number of carbonyl groups (>C=O>\mathrm{C}=\mathrm{O}>C=O) present in the major products X and Y in the following reactions is ____.

Correct answer: 4

Step-by-step solution →
Q2·ChemistrySingle correctJEE Main 2026
Consider the following reaction. The major product (P) formed is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q3·ChemistrySingle correctJEE Main 2026
Complete the following reaction sequence and give the name of major product 'P'. CH₃ − CH₂ − C ≡ N →(ii) H3O+(i) OH−/H2O/Δ\xrightarrow[\text{(ii) } H_3O^+]{\text{(i) } OH^-/H_2O/\Delta}(i) OH−/H2​O/Δ(ii) H3​O+​ →(iv) H2O(iii) Cl2/Red P\xrightarrow[\text{(iv) } H_2O]{\text{(iii) } Cl_2/\text{Red P}}(iii) Cl2​/Red P(iv) H2​O​ P (Major product)
  1. (A)2-Chloropropanoic acid
  2. (B)3-Chloropropanoic acid
  3. (C)1-Chloropropane
  4. (D)2-Chloropropane

Correct answer: (A)

Step-by-step solution →
Q4·ChemistrySingle correctJEE Main 2026
The correct order of acidic strength of the major products formed in the given reactions, is : A. PhNH2→(1) NaNO2+HCl (<5∘C)  (2) CuCN  (3) H3O+/Δ[A]PhNH_2 \xrightarrow{(1)\ NaNO_2+HCl\,(<5^\circ C)\ \ (2)\ CuCN\ \ (3)\ H_3O^+/\Delta} [A]PhNH2​(1) NaNO2​+HCl(<5∘C)  (2) CuCN  (3) H3​O+/Δ​[A] B. CH3CH2CHO→Δ[Ag(NH3)2]+, OH−[B]CH_3CH_2CHO \xrightarrow[\Delta]{[Ag(NH_3)_2]^+,\ OH^-} [B]CH3​CH2​CHO[Ag(NH3​)2​]+, OH−Δ​[B] C. CH4+O2→(ii) Na2Cr2O7/H+(i) Mo2O3[C]CH_4 + O_2 \xrightarrow[(ii)\ Na_2Cr_2O_7/H^+]{(i)\ Mo_2O_3} [C]CH4​+O2​(i) Mo2​O3​(ii) Na2​Cr2​O7​/H+​[C] D. PhCH2MgBr+CO2→H3O+Dry ether[D]PhCH_2MgBr + CO_2 \xrightarrow[H_3O^+]{Dry\ ether} [D]PhCH2​MgBr+CO2​Dry etherH3​O+​[D] Choose the correct answer from the options given below :
  1. (A)C > B > A > D
  2. (B)A > D > C > B
  3. (C)A > D > B > C
  4. (D)C > A > D > B

Correct answer: (D)

Step-by-step solution →
Q5·ChemistryNumericalJEE Main 2026
Grignard reagent RMgBr(P) reacts with water and forms a gas (Q). One gram of Q occupies 1.4 dm3\text{dm}^{3}dm3 at STP. (P) on reaction with dry ice in dry ether followed by H3O+\text{H}_{3}\text{O}^{+}H3​O+ forms a compound (Z). 0.1 mole of (Z) will weigh _______ g. (Nearest integer)

Correct answer: 6

Step-by-step solution →
Q6·ChemistryMultiple correctJEE Advanced 2025
For the reaction sequence given below, the correct statement(s) is(are)
  1. (A)P is optically active.
  2. (B)S gives Bayer's test.
  3. (C)Q gives effervescence with aq. NaHCO3_{3}3​.
  4. (D)R is an alkyne.

Correct answer: (B), (C)

Step-by-step solution →
Q7·ChemistrySingle correctJEE Advanced 2025
The correct reaction/reaction sequence that would produce a dicarboxylic acid as the major product is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q8·ChemistrySingle correctJEE Main 2025
A→(i) NaOH (ii) H3O+B→(i) EtOH (ii) H2SO4, ΔCA\xrightarrow{\text{(i) NaOH (ii) }H_3O^+}B\xrightarrow{\text{(i) EtOH (ii) }H_2SO_4,\,\Delta}CA(i) NaOH (ii) H3​O+​B(i) EtOH (ii) H2​SO4​,Δ​C. 'A' shows positive Lassaigne's test for N and its molar mass is 121. 'B' gives effervescence with aq. NaHCO3NaHCO_3NaHCO3​. 'C' gives fruity smell. Identify A, B and C from the following:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q9·ChemistrySingle correctJEE Main 2025
A toxic compound "A" when reacted with NaCN in aqueous acidic medium yields an edible cooking component and food preservative "B". "B" is converted to "C" by diborane and can be used as an additive to petrol to reduce emission. "C" upon reaction with oleum at 140∘C140^\circ C140∘C yields an inhalable anaesthetic "D". Identify "A", "B", "C" and "D", respectively.
  1. (A)Methanol; formaldehyde; methyl chloride; chloroform
  2. (B)Ethanol; acetonitrile; ethylamine; ethylene
  3. (C)Methanol; acetic acid; ethanol; diethyl ether
  4. (D)Acetaldehyde; 2-hydroxypropanoic acid; propanoic acid; dipropyl ether

Correct answer: (C)

Step-by-step solution →
Q10·ChemistrySingle correctJEE Main 2025
Consider the following molecules: (p) CH3CH2COClCH_3CH_2COClCH3​CH2​COCl (acyl chloride), (q) CH3CH2CO−O−COCH3CH_3CH_2CO-O-COCH_3CH3​CH2​CO−O−COCH3​ (anhydride), (r) CH3CH2CO−O−CH2CH3CH_3CH_2CO-O-CH_2CH_3CH3​CH2​CO−O−CH2​CH3​ (ester), (s) CH3CH2CONH2CH_3CH_2CONH_2CH3​CH2​CONH2​ (amide). The correct order of rate of hydrolysis is:
  1. (A)r > q > p > s
  2. (B)q > p > r > s
  3. (C)p > r > q > s
  4. (D)p > q > r > s

Correct answer: (D)

Step-by-step solution →
Q11·ChemistrySingle correctJEE Main 2025
Consider the following reactions. From these reactions which reaction will give carboxylic acid as a major product? (A) R−C≡N→(i) H+/H2O, mildR{-}C\equiv N \xrightarrow{\text{(i) }H^+/H_2O,\ \text{mild}}R−C≡N(i) H+/H2​O, mild​ (B) R−MgX→(i) CO2 (ii) H3O+R{-}MgX \xrightarrow{\text{(i) }CO_2\ \text{(ii) }H_3O^+}R−MgX(i) CO2​ (ii) H3​O+​ (C) R−C≡N→(i) SnCl2⋅3HCl (ii) H3O+R{-}C\equiv N \xrightarrow{\text{(i) }SnCl_2\cdot3HCl\ \text{(ii) }H_3O^+}R−C≡N(i) SnCl2​⋅3HCl (ii) H3​O+​ (D) R−CH2−OH→PCCR{-}CH_2{-}OH \xrightarrow{PCC}R−CH2​−OHPCC​ (E) C6H5COCl→H2/Pd-BaSO4C6H5CHOC_6H_5COCl \xrightarrow{H_2/Pd\text{-}BaSO_4} C_6H_5CHOC6​H5​COClH2​/Pd-BaSO4​​C6​H5​CHO. Choose the correct answer from the options given below:
  1. (A)A and D only
  2. (B)A, B and E only
  3. (C)B, C and E only
  4. (D)B, D and E only

Correct answer: (D)

Step-by-step solution →
Q12·ChemistrySingle correctJEE Main 2025
The compounds that produce CO2_22​ with aqueous NaHCO3_33​ solution are (compounds A-E are shown in the figure). Choose the correct answer from the options given below:
  1. (A)A and C only
  2. (B)A, B and E only
  3. (C)A, C and D only
  4. (D)A and B only

Correct answer: (C)

Step-by-step solution →
Q13·ChemistryIntegerJEE Advanced 2024
In the following reaction sequence, major product P\mathbf{P}P is formed. Glycerol reacts completely with excess P\mathbf{P}P in the presence of an acid catalyst to form Q\mathbf{Q}Q. Reaction of Q\mathbf{Q}Q with excess NaOH followed by the treatment with CaCl2_{2}2​ yields Ca – soap R\mathbf{R}R, quantitatively. Starting with one mole of Q\mathbf{Q}Q, the amount of R\mathbf{R}R produced in gram is ___________. [Given, atomic weight: H = 1, C = 12, N = 14, O = 16, Na = 23, Cl = 35, Ca = 40]

Correct answer: 909

Step-by-step solution →
Q14·ChemistrySingle correctJEE Main 2024
Identify the major product (P)(P)(P) in the following reaction: cyclopentane carboxylic acid →i) Br2/Red P→ii) H2O(P)\xrightarrow{\text{i) }Br_2/\text{Red P}}\xrightarrow{\text{ii) }H_2O}(P)i) Br2​/Red P​ii) H2​O​(P)
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q15·ChemistrySingle correctJEE Main 2024
The correct sequence of acidic strength of the following aliphatic acids in their decreasing order is: CH3CH2COOH\text{CH}_3\text{CH}_2\text{COOH}CH3​CH2​COOH, CH3COOH\text{CH}_3\text{COOH}CH3​COOH, CH3CH2CH2COOH\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}CH3​CH2​CH2​COOH, HCOOH\text{HCOOH}HCOOH
  1. (A)HCOOH>CH3COOH>CH3CH2COOH>CH3CH2CH2COOH\text{HCOOH}>\text{CH}_3\text{COOH}>\text{CH}_3\text{CH}_2\text{COOH}>\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}HCOOH>CH3​COOH>CH3​CH2​COOH>CH3​CH2​CH2​COOH
  2. (B)HCOOH>CH3CH2CH2COOH>CH3CH2COOH>CH3COOH\text{HCOOH}>\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}>\text{CH}_3\text{CH}_2\text{COOH}>\text{CH}_3\text{COOH}HCOOH>CH3​CH2​CH2​COOH>CH3​CH2​COOH>CH3​COOH
  3. (C)CH3CH2CH2COOH>CH3CH2COOH>CH3COOH>HCOOH\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}>\text{CH}_3\text{CH}_2\text{COOH}>\text{CH}_3\text{COOH}>\text{HCOOH}CH3​CH2​CH2​COOH>CH3​CH2​COOH>CH3​COOH>HCOOH
  4. (D)CH3COOH>CH3CH2COOH>CH3CH2CH2COOH>HCOOH\text{CH}_3\text{COOH}>\text{CH}_3\text{CH}_2\text{COOH}>\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}>\text{HCOOH}CH3​COOH>CH3​CH2​COOH>CH3​CH2​CH2​COOH>HCOOH

Correct answer: (A)

Step-by-step solution →
Q16·ChemistryNumericalJEE Main 2024
Major product BBB of the following reaction has ___ π\piπ-bonds. Ethylbenzene →KMnO4−KOH, Δ(A)→HNO3/H2SO4(B)\xrightarrow{KMnO_4-KOH,\ \Delta}(A)\xrightarrow{HNO_3/H_2SO_4}(B)KMnO4​−KOH, Δ​(A)HNO3​/H2​SO4​​(B)

Correct answer: 5

Step-by-step solution →
Q17·ChemistrySingle correctJEE Main 2024
Consider the given reaction, identify the major product P. CH3−COOHCH_3-COOHCH3​−COOH undergoes (i) LiAlH4LiAlH_4LiAlH4​ (ii) PCC (iii) HCN/−OHHCN/^{-}OHHCN/−OH (iv) H2O/−OH,ΔH_2O/^{-}OH, \DeltaH2​O/−OH,Δ to give "P".
  1. (A)CH3−CH2−CH2−OHCH_3-CH_2-CH_2-OHCH3​−CH2​−CH2​−OH
  2. (B)CH3−CH2−CO−NH2CH_3-CH_2-CO-NH_2CH3​−CH2​−CO−NH2​
  3. (C)CH3−CO−CH2CH3CH_3-CO-CH_2CH_3CH3​−CO−CH2​CH3​
  4. (D)CH3−CH(OH)−COOHCH_3-CH(OH)-COOHCH3​−CH(OH)−COOH

Correct answer: (D)

Step-by-step solution →
Q18·ChemistrySingle correctJEE Main 2024
CH3CH2OH\text{CH}_3\text{CH}_2\text{OH}CH3​CH2​OH is treated successively with (i) Jones' reagent, (ii) KMnO4\text{KMnO}_4KMnO4​, (iii) NaOH, CaO, Δ\DeltaΔ. Consider the above reaction sequence and identify the major product P.
  1. (A)Methane
  2. (B)Methanal
  3. (C)Methoxymethane
  4. (D)Methanoic acid

Correct answer: (A)

Step-by-step solution →
Q19·ChemistryNumericalJEE Main 2024
The product C in the following sequence of reactions has __________ π\piπ bonds. Toluene →KMnO4−KOH, Δ\xrightarrow{\text{KMnO}_4-\text{KOH},\,\Delta}KMnO4​−KOH,Δ​ A →H3O+\xrightarrow{\text{H}_3\text{O}^+}H3​O+​ B →Br2/FeBr3\xrightarrow{\text{Br}_2/\text{FeBr}_3}Br2​/FeBr3​​ C.

Correct answer: 4

Step-by-step solution →
Q20·ChemistrySingle correctJEE Main 2024
Benzene reacts with succinic anhydride in the presence of anhydrous AlCl3\text{AlCl}_3AlCl3​ (Friedel-Crafts acylation) to give (A). Compound (A), on Clemmensen reduction (Zn-Hg/HCl) followed by acidic work-up (H+\text{H}^+H+), gives (B). Identify (A) and (B) from the structures shown:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q21·ChemistrySingle correctJEE Main 2024
The molecular formula of second homologue in the homologous series of mono carboxylic acids is _________.
  1. (A)C2H4O2C_2H_4O_2C2​H4​O2​
  2. (B)C4H8O2C_4H_8O_2C4​H8​O2​
  3. (C)CH2O2CH_2O_2CH2​O2​
  4. (D)C3H6O2C_3H_6O_2C3​H6​O2​

Correct answer: (A)

Step-by-step solution →
Q22·ChemistryMultiple correctJEE Advanced 2023
In the following reactions, P\mathbf{P}P, Q\mathbf{Q}Q, R\mathbf{R}R, and S\mathbf{S}S are the major products. The correct statement(s) about P\mathbf{P}P, Q\mathbf{Q}Q, R\mathbf{R}R, and S\mathbf{S}S is(are)
  1. (A)P\mathbf{P}P and Q\mathbf{Q}Q are monomers of polymers dacron and glyptal, respectively.
  2. (B)P\mathbf{P}P, Q\mathbf{Q}Q, and R\mathbf{R}R are dicarboxylic acids.
  3. (C)Compounds Q\mathbf{Q}Q and R\mathbf{R}R are the same.
  4. (D)R\mathbf{R}R does not undergo aldol condensation and S\mathbf{S}S does not undergo Cannizzaro reaction.

Correct answer: (C), (D)

Step-by-step solution →
Q23·ChemistryMultiple correctJEE Advanced 2023
Consider the following reaction scheme and choose the correct option(s) for the major products Q, R and S.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q24·ChemistrySingle correctJEE Main 2023
The major product 'P' formed in the following sequence of reactions (on the substrate shown) is: (i) SOCl2_22​; (ii) Benzene/AlCl3_33​; (iii) LiAlH4_44​; (iv) H3_33​O+^++
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q25·ChemistrySingle correctJEE Main 2023
The major product formed in the following reaction is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q26·ChemistrySingle correctJEE Main 2023
The descending order of acidity for the following carboxylic acids is: A. CH3COOHCH_3COOHCH3​COOH B. F3C–COOHF_3C\text{--}COOHF3​C–COOH C. ClCH2–COOHClCH_2\text{--}COOHClCH2​–COOH D. FCH2–COOHFCH_2\text{--}COOHFCH2​–COOH E. BrCH2–COOHBrCH_2\text{--}COOHBrCH2​–COOH. Choose the correct answer from the options given below:
  1. (A)D > B > A > E > C
  2. (B)E > D > B > A > C
  3. (C)B > C > D > E > A
  4. (D)B > D > C > E > A

Correct answer: (D)

Step-by-step solution →
Q27·ChemistrySingle correctJEE Main 2023
In the given reaction, reagents 'X' and 'Y' respectively are:
  1. (A)(CH3CO)2O/H+(CH_3CO)_2O/H^+(CH3​CO)2​O/H+ and (CH3CO)2O/H+(CH_3CO)_2O/H^+(CH3​CO)2​O/H+
  2. (B)CH3OH/H+, ΔCH_3OH/H^+,\ \DeltaCH3​OH/H+, Δ and (CH3CO)2O/H+(CH_3CO)_2O/H^+(CH3​CO)2​O/H+
  3. (C)CH3OH/H+, ΔCH_3OH/H^+,\ \DeltaCH3​OH/H+, Δ and CH3OH/H+, ΔCH_3OH/H^+,\ \DeltaCH3​OH/H+, Δ
  4. (D)(CH3CO)2O/H+(CH_3CO)_2O/H^+(CH3​CO)2​O/H+ and CH3OH/H+, ΔCH_3OH/H^+,\ \DeltaCH3​OH/H+, Δ

Correct answer: (D)

Step-by-step solution →
Q28·ChemistryMultiple correctJEE Advanced 2022
Considering the reaction sequence given below, the correct statement(s) is(are)
  1. (A)P\mathbf{P}P can be reduced to a primary alcohol using NaBH4\mathrm{NaBH_4}NaBH4​.
  2. (B)Treating P\mathbf{P}P with conc. NH4OH\mathrm{NH_4OH}NH4​OH solution followed by acidification gives Q\mathbf{Q}Q.
  3. (C)Treating Q\mathbf{Q}Q with a solution of NaNO2\mathrm{NaNO_2}NaNO2​ in aq. HCl liberates N2\mathrm{N_2}N2​.
  4. (D)P\mathbf{P}P is more acidic than CH3CH2COOH\mathrm{CH_3CH_2COOH}CH3​CH2​COOH.

Correct answer: (B), (C), (D)

Step-by-step solution →
Q29·ChemistryMultiple correctJEE Advanced 2022
Considering the following reaction sequence, the correct statement(s) is(are)
  1. (A)Compound P\mathbf{P}P and Q\mathbf{Q}Q are carboxylic acids.
  2. (B)Compound S\mathbf{S}S decolorizes bromine water.
  3. (C)Compounds P\mathbf{P}P and S\mathbf{S}S react with hydroxylamine to give the corresponding oximes.
  4. (D)Compound R\mathbf{R}R reacts with dialkylcadmium to give the corresponding tertiary alcohol.

Correct answer: (A), (C)

Step-by-step solution →
Q30·ChemistrySingle correctJEE Main 2022
Find out the major product for the above reaction.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q31·ChemistryNumericalJEE Main 2022
In the given reaction (Where Et is -C2H5C_{2}H_{5}C2​H5​) The number of chiral carbon/s in product A is

Correct answer: 2

Step-by-step solution →
Q32·ChemistrySingle correctJEE Main 2022
Given below are two statements : Statement I : The esterification of carboxylic acid with an alcohol is a nucleophilic acyl substitution. Statement II : Electron withdrawing groups in the carboxylic acid will increase the rate of esterification reaction. Choose the most appropriate option :
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correctJEE Main 2022
Two statements are given below : Statement I: The melting point of monocarboxylic acid with even number of carbon atoms is higher than that of with odd number of carbon atoms acid immediately below and above it in the series. Statement II : The solubility of monocarboxylic acids in water decreases with increase in molar mass. Choose the most appropriate option:
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correctJEE Main 2021
In the following sequence of reactions a compound A, (molecular formula C6_{6}6​H12_{12}12​O2_{2}2​) with a straight chain structure gives a C4_{4}4​ carboxylic acid. A is : A —[LiAlH4_{4}4​ / H3_{3}3​O+^{+}+]→ B —[Oxidation]→ C4_{4}4​ − carboxylic acid
  1. (A)CH3_{3}3​ – CH2_{2}2​ – COO – CH2_{2}2​ – CH2_{2}2​ – CH3_{3}3​
  2. (B)CH3_{3}3​–CH2_{2}2​–CH(OH)–CH2_{2}2​–O–CH=CH2_{2}2​
  3. (C)CH3_{3}3​ – CH2_{2}2​ – CH2_{2}2​ – COO – CH2_{2}2​ – CH3_{3}3​
  4. (D)CH3_{3}3​ – CH2_{2}2​ – CH2_{2}2​ – O – CH = CH – CH2_{2}2​ – OH

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correctJEE Main 2021
Given below are two statements : Statement I : Ethyl pent–4–yn–oate on reaction with CH3_{3}3​MgBr gives a 3°–alcohol. Statement II : In this reaction one mole of ethyl pent–4–yn–oate utilizes two moles of CH3_{3}3​MgBr. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Both Statement I and Statement II are false.
  2. (B)Statement I is false but Statement II is true.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Both Statement I and Statement II are true.

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correctJEE Main 2021
The major product formed in the following reaction is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correctJEE Main 2021
Maleic anhydride can be prepared by:
  1. (A)Heating cis-but-2-enedioic acid
  2. (B)Treating cis-but-2-enedioic acid with alcohol and acid
  3. (C)Heating trans- but-2- enedioic acid
  4. (D)Treating trans-but-2-enedioic acid with alcohol and acid

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correctJEE Main 2021
The correct order of their reactivity towards hydrolysis at room temperature is:
  1. (A)(d) > (b) > (a) > (c)
  2. (B)(d) > (a) > (b) > (c)
  3. (C)(a) > (c) > (b) > (d)
  4. (D)(a) > (b) > (c) > (d)

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correctJEE Main 2021
Considering the above chemical reaction, identify the product "X" :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correctJEE Main 2021
Consider the above chemical reaction and identify product "A"
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q41·ChemistryNumericalJEE Main 2021
Consider the above reaction. The percentage yield of amide product is ______. (Round off to the Nearest Integer). (Given : Atomic mass : C : 12.0 u, H : 1.0u, N : 14.0 u, O : 16.0 u, Cl : 35.5 u)

Correct answer: 77

Step-by-step solution →
Q42·ChemistrySingle correctJEE Main 2021
In the above reaction, the reagent "A" is :
  1. (A)NaBH4_{4}4​, H3_{3}3​O+^{+}+
  2. (B)LiAlH4_{4}4​
  3. (C)Alkaline KMnO4_{4}4​, H+^{+}+
  4. (D)HCl, Zn-Hg

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correctJEE Main 2021
The product "P" in the above reaction is :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correctJEE Main 2021
The correct order of acid character of the following compounds is : OHCOOHCOOHCOOH NO2CH3 IIIIIIIV
  1. (A)II>III>IV>I
  2. (B)III>II>I>IV
  3. (C)IV>III>II>I
  4. (D)I>II>III>IV

Correct answer: (A)

Step-by-step solution →
Q45·ChemistryNumericalJEE Main 2021
The number of compound/s given below which contain/s —COOH group is ______. (1) Sulphanilic acid (2) Picric acid (3) Aspirin (4) Ascorbic acid

Correct answer: 1

Step-by-step solution →
Q46·ChemistrySingle correctJEE Main 2020
An organic compound (A) (molecular formula C6H12O2\mathrm{C_6H_{12}O_2}C6​H12​O2​) was hydrolysed with dil. H2SO4\mathrm{H_2SO_4}H2​SO4​ to give a carboxylic acid (B) and an alcohol (C). 'C' gives white turbidity immediately when treated with anhydrous ZnCl2\mathrm{ZnCl_2}ZnCl2​ and conc. HCl. The organic compound (A) is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correctJEE Main 2020
[P] on treatment with Br2/FeBr3\mathrm{Br_2/FeBr_3}Br2​/FeBr3​ in CCl4\mathrm{CCl_4}CCl4​ produced a single isomer C8H7O2Br\mathrm{C_8H_7O_2Br}C8​H7​O2​Br while heating [P] with sodalime gave toluene. The compound [P] is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q48·ChemistrySingle correctJEE Main 2020
The most suitable reagent for the given conversion is :
  1. (A)LiAlH4_{4}4​
  2. (B)B2_{2}2​H6_{6}6​
  3. (C)H2_{2}2​/Pd
  4. (D)NaBH4_{4}4​

Correct answer: (B)

Step-by-step solution →
Q49·ChemistrySingle correctJEE Main 2020
What is the product of following reaction? Hex − 3 − ynal →(ii) PBr3 (iii) Mg/ether (iv) CO2/H3O+(i) NaBH4\xrightarrow[\text{(ii) PBr}_3\ \text{(iii) Mg/ether}\ \text{(iv) CO}_2\text{/H}_3\text{O}^+]{\text{(i) NaBH}_4}(i) NaBH4​(ii) PBr3​ (iii) Mg/ether (iv) CO2​/H3​O+​ ?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q50·ChemistryMultiple correctJEE Advanced 2019
Choose the correct option(s) for the following reaction sequence Consider Q, R and S as major products
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (D)

Step-by-step solution →
Q51·ChemistrySingle correctJEE Advanced 2019
Answer the following by appropriately matching the lists based on the information given in the paragraph List-I includes starting materials and reagents of selected chemical reactions. List-II gives structures of compounds that may be formed as intermediate products and/or final products from the reactions of List-I. Which of the following options has the correct combination considering List-I and List-II?
LIST-ILIST-II
I.see figureP.see figure
II.see figureQ.see figure
III.see figureR.see figure
IV.see figureS.see figure
T.see figure
U.see figure
  1. (A)(II), (P), (S), (T)
  2. (B)(II), (P), (S), (U)
  3. (C)(I), (S), (Q), (R)
  4. (D)(I), (Q), (T), (U)

Correct answer: (B)

Step-by-step solution →
Q52·ChemistrySingle correctJEE Main 2019
The major product of the following reaction is : (1) CrO3_33​ (2) SOCl2_22​/Δ\DeltaΔ (3) Δ\DeltaΔ
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q53·ChemistrySingle correctJEE Main 2019
The major product 'Y' in the following reaction is:-
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q54·ChemistrySingle correctJEE Main 2019
The major product of the following reaction is : CH3CH=CHCO2CH3→LiAlH4CH_3CH=CHCO_2CH_3 \xrightarrow{LiAlH_4}CH3​CH=CHCO2​CH3​LiAlH4​​
  1. (A)CH3CH2CH2CHOCH_3CH_2CH_2CHOCH3​CH2​CH2​CHO
  2. (B)CH3CH=CHCH2OHCH_3CH=CHCH_2OHCH3​CH=CHCH2​OH
  3. (C)CH3CH2CH2CO2CH3CH_3CH_2CH_2CO_2CH_3CH3​CH2​CH2​CO2​CH3​
  4. (D)CH3CH2CH2CH2OHCH_3CH_2CH_2CH_2OHCH3​CH2​CH2​CH2​OH

Correct answer: (B)

Step-by-step solution →
Q55·ChemistrySingle correctJEE Main 2019
The increasing order of the reactivity of the following with LiAlH4 is :
  1. (A)(b) < (a) < (c) < (d)
  2. (B)(b) < (a) < (d) < (c)
  3. (C)(a) < (b) < (d) < (c)
  4. (D)(a) < (b) < (c) < (d)

Correct answer: (C)

Step-by-step solution →
Q56·ChemistrySingle correctJEE Main 2019
The decreasing order of ease of alkaline hydrolysis for the following ester is
  1. (A)III > II > IV > I
  2. (B)III > II > I > IV
  3. (C)IV > II > III > I
  4. (D)II > III > I > IV

Correct answer: (B)

Step-by-step solution →
Q57·ChemistrySingle correctJEE Main 2019
Which diccarboxylic acid in presence of a dehydrating agent is least reactive to give anhydride?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q58·ChemistrySingle correctJEE Main 2019
The correct decreasing order for acidic strength is
  1. (A)NO2_{2}2​CH2_{2}2​COOH > FCH2_{2}2​COOH > CNCH2_{2}2​COOH > ClCH2_{2}2​COOH
  2. (B)FCH2_{2}2​COOH > NCCH2_{2}2​COOH > NO2_{2}2​CH2_{2}2​COOH > ClCH2_{2}2​COOH
  3. (C)CNCH2_{2}2​COOH > O2_{2}2​NCH2_{2}2​COOH > FCH2_{2}2​COOH > ClCH2_{2}2​COOH
  4. (D)NO2_{2}2​CH2_{2}2​COOH > NCCH2_{2}2​COOH > FCH2_{2}2​COOH > ClCH2_{2}2​COOH

Correct answer: (D)

Step-by-step solution →
Q59·ChemistrySingle correctJEE Main 2019
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q60·ChemistrySingle correctJEE Advanced 2018
PARAGRAPH "X" Treatment of benzene with CO/HCl in the presence of anhydrous AlCl3AlCl_{3}AlCl3​/CuCl followed by reaction with Ac2OAc_{2}OAc2​O/NaOAc gives compound X as the major product. Compound X upon reaction with Br2Br_{2}Br2​/Na2CO3Na_{2}CO_{3}Na2​CO3​, followed by heating at 473 K with moist KOH furnishes Y as the major product. Reaction of X with H2H_{2}H2​/Pd-C, followed by H3PO4H_{3}PO_{4}H3​PO4​ treatment gives Z as the major product. (There are two questions based on PARAGRAPH "X", the question given below is one of them) The compound Y is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q61·ChemistrySingle correctJEE Advanced 2018
PARAGRAPH "A" An organic acid P (C11H12O2C_{11}H_{12}O_{2}C11​H12​O2​) can easily be oxidized to a dibasic acid which reacts with ethylene glycol to produce a polymer dacron. Upon ozonolysis, P gives an aliphatic ketone as one of the products. P undergoes the following reaction sequences to furnish R via Q. The compound P also undergoes another set of reactions to produce S. S ←\xleftarrow{}​ [1) H2H_{2}H2​/Pd−C, 2) NH3NH_{3}NH3​/Δ\DeltaΔ, 3) Br2Br_{2}Br2​/NaOH, 4) CHCl3CHCl_{3}CHCl3​, KOH, Δ\DeltaΔ, 5) H2H_{2}H2​/Pd−C] P →\xrightarrow{}​ [1) H2H_{2}H2​/Pd−C, 2) SOCl2SOCl_{2}SOCl2​, 3) MeMgBr, CdCl2CdCl_{2}CdCl2​, 4) NaBH4NaBH_{4}NaBH4​] Q →\xrightarrow{}​ [1) HCl, 2) Mg/Et2OEt_{2}OEt2​O, 3) CO2CO_{2}CO2​ (dry ice), 4) H3O+H_{3}O^{+}H3​O+] R (There are two questions based on PARAGRAH 'A', the question given below is one of them) The compound R is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q62·ChemistrySingle correctJEE Advanced 2016
The correct order of acidity for the following compounds is
  1. (A)I > II > III > IV
  2. (B)III > I > II > IV
  3. (C)III > IV > II > I
  4. (D)I > III > IV > II

Correct answer: (A)

Step-by-step solution →
Q63·ChemistrySingle correctJEE Advanced 2013
P and Q are isomers of dicarboxylic acid C4H4O4\mathrm{C_4H_4O_4}C4​H4​O4​. Both decolorize Br2/H2O\mathrm{Br_2/H_2O}Br2​/H2​O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4\mathrm{KMnO_4}KMnO4​, P as well as Q could produce one or more than one from S, T and U. In the following reaction sequences V and W are, respectively
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q64·ChemistryIntegerJEE Advanced 2013
The total number of carboxylic acid groups in the product P is

Correct answer: 2

Step-by-step solution →

Carboxylic Acids and Derivatives — frequently asked

How many questions from Carboxylic Acids and Derivatives appear in JEE?

Carboxylic Acids and Derivatives has appeared in 54 of the last 186 JEE Main and JEE Advanced papers — about 29% of them — contributing 64 questions in total across those papers.

Is Carboxylic Acids and Derivatives an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 29% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Carboxylic Acids and Derivatives questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Chemistry chapters

  • Coordination Compounds 318
  • p-Block Elements 276
  • Redox Reactions and Electrochemistry 265
  • Chemical Bonding and Molecular Structure 207
  • d- and f-Block Elements 202
  • Aldehydes and Ketones 199
  • Equilibrium 199
  • Solutions 198

All 36 Chemistry chapters →

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