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Diazonium Salts and Reactions — JEE Previous Year Questions

Every Diazonium Salts and Reactions question asked in JEE Main and JEE Advanced across the last 186 papers — 58 questions, each with its correct answer. Free to read, no account needed.

Questions

58

Papers it appeared in

53/186

Appearance rate

28%

All 58 Diazonium Salts and Reactions questions

Most recent papers first.

Q1·ChemistryMultiple correctJEE Advanced 2026
In the following reaction sequence, P, Q, S and T are the major products. The correct statement(s) about P, Q, S and T is(are)
  1. (A)Q on treatment with ethanol generates an aromatic aldehyde.
  2. (B)S gives positive phthalein dye test.
  3. (C)P is a dinitro compound.
  4. (D)T is a coloured compound.

Correct answer: (B), (D)

Step-by-step solution →
Q2·ChemistryNumericalJEE Main 2026
Consider the following sequence of reactions. The percentage of nitrogen in the yellow product (X) formed is _______%. (Nearest Integer) (Given Molar mass in g mol⁻¹ H:1, C:12, N:14)

Correct answer: 21

Step-by-step solution →
Q3·ChemistrySingle correctJEE Main 2026
Product CCC of the following reaction sequence will be
  1. (A)1-Bromo-4-nitrobenzene
  2. (B)1, 3, 5-Tribromo-2-nitrobenzene
  3. (C)4-Bromo-1-nitrobenzene
  4. (D)1, 3, 5-Tribromobenzene

Correct answer: (B)

Step-by-step solution →
Q4·ChemistrySingle correctJEE Main 2026
Identify compounds A and E in the following reaction sequence.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q5·ChemistrySingle correctJEE Main 2026
The correct stability order of the following diazonium salts is
  1. (A)A > B > C > D
  2. (B)C > D > B > A
  3. (C)A > C > D > B
  4. (D)C > A > D > B

Correct answer: (C)

Step-by-step solution →
Q6·ChemistrySingle correctJEE Main 2026
'A' is a neutral organic compound (M. F : C8_88​H9_99​ON ). On treatment with aqueous Br2_22​/HO(−)^{(-)}(−), 'A' forms a compound 'B' which is soluble in dilute acid. 'B' on treatment with aqueous NaNO2_22​/HCl(0–5°C) produces a compound 'C' which on treatment with CuCN/NaCN produces 'D' Hydrolysis of 'D' produces 'E' which is also obtainable from the hydrolysis of 'A'. 'E' on treatment with acidified KMnO4_44​ produces 'F'. 'F' contains two different types of hydrogen atoms. The structure of 'A' is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q7·ChemistrySingle correctJEE Main 2026
(1) Br2/FeBr3/Δ\text{Br}_{2}/\text{FeBr}_{3}/\DeltaBr2​/FeBr3​/Δ (2) Sn/HCl/Δ\text{Sn}/\text{HCl}/\DeltaSn/HCl/Δ (3) pH neutralisation (4) Br2/H2O\text{Br}_{2}/\text{H}_{2}\text{O}Br2​/H2​O (5) NaNO2/HBr\text{NaNO}_{2}/\text{HBr}NaNO2​/HBr, 0-5∘^{\circ}∘C (6) CuBr/NaBr\text{CuBr}/\text{NaBr}CuBr/NaBr →\rightarrow→ Major Product (P) Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be:
  1. (A)1
  2. (B)6
  3. (C)5
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q8·ChemistrySingle correctJEE Main 2025
Identify [A], [B] and [C], respectively in the following reaction sequence (shown in the figure): [A]→NaNO2, HCl, 273-278K[benzenediazonium chloride]→KI[B]→2Na, Dry ether[C][A]\xrightarrow{NaNO_2,\,HCl,\,273\text{-}278K}[\text{benzenediazonium chloride}]\xrightarrow{KI}[B]\xrightarrow{2Na,\,\text{Dry ether}}[C][A]NaNO2​,HCl,273-278K​[benzenediazonium chloride]KI​[B]2Na,Dry ether​[C]. Choose the correct option (the structure sets are shown in the figure):
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q9·ChemistrySingle correctJEE Main 2025
When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is: (Given molar mass in g mol−1^{-1}−1 — H:1, C:12, N:14, O:16, S:32)
  1. (A)343
  2. (B)330
  3. (C)33
  4. (D)66

Correct answer: (C)

Step-by-step solution →
Q10·ChemistrySingle correctJEE Main 2025
Which one of the following reaction sequences (shown in the figure) will give an azo dye?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q11·ChemistryIntegerJEE Main 2025
Consider the following sequence of reactions to produce major product (A). The starting compound (shown in the figure) is treated successively with: i) Br₂, Fe; ii) Sn, HCl; iii) NaNO₂, HCl, 273 K; iv) H₃PO₂, H₂O. Molar mass of product (A) is _______ g mol−1^{-1}−1. (Given molar mass in g mol−1^{-1}−1 of C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31)

Correct answer: 171

Step-by-step solution →
Q12·ChemistryIntegerJEE Main 2025
Consider the following sequence of reactions starting from 4-ethoxyaniline: →(i) NaNO2, HCl, 0-5∘C; (ii) HCl (dil)[A]→(i) phenol, NaOH; (ii) HCl (dil)[B] (C14H14N2O2)→(i) NaOH; (ii) H3CCH2Br[C] (C16H18N2O2)\xrightarrow{\text{(i) }NaNO_2,\,HCl,\,0\text{-}5^\circ C;\ \text{(ii) }HCl\,(dil)}[A]\xrightarrow{\text{(i) phenol, }NaOH;\ \text{(ii) }HCl\,(dil)}[B]\ (C_{14}H_{14}N_2O_2)\xrightarrow{\text{(i) }NaOH;\ \text{(ii) }H_3CCH_2Br}[C]\ (C_{16}H_{18}N_2O_2)(i) NaNO2​,HCl,0-5∘C; (ii) HCl(dil)​[A](i) phenol, NaOH; (ii) HCl(dil)​[B] (C14​H14​N2​O2​)(i) NaOH; (ii) H3​CCH2​Br​[C] (C16​H18​N2​O2​). Total number of sp3^33 hybridised carbon atoms in the major product C formed is __________.

Correct answer: 4

Step-by-step solution →
Q13·ChemistrySingle correctJEE Main 2025
Nitrobenzene is subjected to the reaction sequence (i) Br₂, AcOH; (ii) Sn, HCl; (iii) NaNO₂, HCl, 273 K; (iv) C₂H₅OH, giving products A and B. Identify A and B. (See figure for the option structures.)
  1. (A)3-bromophenol and 3-bromophenetole
  2. (B)3-bromophenetole and CH₃COOH
  3. (C)bromobenzene and CH₃CHO
  4. (D)3-bromophenol and CH₃CHO

Correct answer: (C)

Step-by-step solution →
Q14·ChemistryIntegerJEE Main 2025
Consider the following sequence of reactions on nitrobenzene: (i) Sn + HCl; (ii) NaNO₂, HCl, 0 °C; (iii) Cu₂Cl₂; (iv) Na, ether. The molar mass of the product A formed is ______ g mol⁻¹.

Correct answer: 154

Step-by-step solution →
Q15·ChemistryNumericalJEE Main 2024
If 279 g279\,g279g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ___ g. (nearest integer) (consider complete conversion)

Correct answer: 591

Step-by-step solution →
Q16·ChemistryNumericalJEE Main 2024
9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _______ g (nearest integer).

Correct answer: 20

Step-by-step solution →
Q17·ChemistrySingle correctJEE Main 2024
Identify the major product (A) in the reaction sequence shown in the figure.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q18·ChemistrySingle correctJEE Main 2024
The azo-dye (Y) formed in the following reactions is (shown in the figure).
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q19·ChemistryNumericalJEE Advanced 2023
PARAGRAPH II A trinitro compound, 1,3,5-tris-(4-nitrophenyl)benzene, on complete reaction with an excess of Sn/HCl gives a major product, which on treatment with an excess of NaNO2\mathrm{NaNO_2}NaNO2​/HCl at 0∘0^\circ0∘C provides P\mathbf{P}P as the product. P\mathbf{P}P, upon treatment with excess of H2O\mathrm{H_2O}H2​O at room temperature, gives the product Q\mathbf{Q}Q. Bromination of Q\mathbf{Q}Q in aqueous medium furnishes the product R\mathbf{R}R. The compound P\mathbf{P}P upon treatment with an excess of phenol under basic conditions gives the product S\mathbf{S}S. The molar mass difference between compounds Q\mathbf{Q}Q and R\mathbf{R}R is 474 g mol−1^{-1}−1 and between compounds P\mathbf{P}P and S\mathbf{S}S is 172.5 g mol−1^{-1}−1. The number of heteroatoms present in one molecule of R\mathbf{R}R is ______ . [Use: Molar mass (in g mol-1): H = 1, C = 12, N = 14, O = 16, Br = 80, Cl = 35.5 Atoms other than C and H are considered as heteroatoms]

Correct answer: 9

Step-by-step solution →
Q20·ChemistryNumericalJEE Advanced 2023
PARAGRAPH II A trinitro compound, 1,3,5-tris-(4-nitrophenyl)benzene, on complete reaction with an excess of Sn/HCl gives a major product, which on treatment with an excess of NaNO2\mathrm{NaNO_2}NaNO2​/HCl at 0∘0^\circ0∘C provides P\mathbf{P}P as the product. P\mathbf{P}P, upon treatment with excess of H2O\mathrm{H_2O}H2​O at room temperature, gives the product Q\mathbf{Q}Q. Bromination of Q\mathbf{Q}Q in aqueous medium furnishes the product R\mathbf{R}R. The compound P\mathbf{P}P upon treatment with an excess of phenol under basic conditions gives the product S\mathbf{S}S. The molar mass difference between compounds Q\mathbf{Q}Q and R\mathbf{R}R is 474 g mol−1^{-1}−1 and between compounds P\mathbf{P}P and S\mathbf{S}S is 172.5 g mol−1^{-1}−1. The total number of carbon atoms and heteroatoms present in one molecule of S\mathbf{S}S is ______ . [Use: Molar mass (in g mol−1^{-1}−1): H = 1, C = 12, N = 14, O = 16, Br = 80, Cl = 35.5 Atoms other than C and H are considered as heteroatoms]

Correct answer: 51

Step-by-step solution →
Q21·ChemistrySingle correctJEE Main 2023
Consider the following sequence of reactions: aniline (C6H5NH2C_6H_5NH_2C6​H5​NH2​) with NaNO2NaNO_2NaNO2​ at 0−5 ∘C0-5\,^{\circ}C0−5∘C gives 'A', then 'A' with N,N-Dimethylaniline gives 'B'. The product 'B' is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q22·ChemistrySingle correctJEE Main 2023
In the above conversion the correct sequence of reagents to be added is (the conversion shown is 4-nitrotoluene to 2-bromo-4-chlorobenzoic acid).
  1. (A)(i) Fe/H+Fe/H^+Fe/H+, (ii) HONO, (iii) CuCl, (iv) KMnO4KMnO_4KMnO4​, (v) Br2Br_2Br2​
  2. (B)(i) KMnO4KMnO_4KMnO4​, (ii) Br2/FeBr_2/FeBr2​/Fe, (iii) Fe/H+Fe/H^+Fe/H+, (iv) Cl2Cl_2Cl2​
  3. (C)(i) Br2/FeBr_2/FeBr2​/Fe, (ii) Fe/H+Fe/H^+Fe/H+, (iii) HONO, (iv) CuCl, (v) KMnO4KMnO_4KMnO4​
  4. (D)Br2/FeBr_2/FeBr2​/Fe, (ii) Fe/H+Fe/H^+Fe/H+, (iii) KMnO4KMnO_4KMnO4​, (iv) Cl2Cl_2Cl2​

Correct answer: (C)

Step-by-step solution →
Q23·ChemistrySingle correctJEE Main 2023
Compound A from the following reaction sequence is:
  1. (A)Benzoic Acid
  2. (B)Phenol
  3. (C)Salicylic Acid
  4. (D)Aniline

Correct answer: (D)

Step-by-step solution →
Q24·ChemistrySingle correctJEE Main 2023
In the following reaction sequence, compound 'B' is (choose the correct structure from the options shown in the figure):
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q25·ChemistrySingle correctJEE Main 2023
o-Phenylenediamine reacts with HNO2HNO_2HNO2​ to give the major product 'X'. 'X' is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q26·ChemistrySingle correctJEE Main 2023
The product (P) formed from the following multistep reaction is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q27·ChemistrySingle correctJEE Main 2023
Benzenediazonium chloride is reacted with reagents in List-I to form products in List-II. Match List-I (Reagent) with List-II (Product). Choose the correct answer:
  1. (A)A-IV, B-III, C-II, D-I
  2. (B)A-I, B-III, C-IV, D-II
  3. (C)A-III, B-I, C-II, D-IV
  4. (D)A-III, B-I, C-IV, D-II

Correct answer: (D)

Step-by-step solution →
Q28·ChemistrySingle correctJEE Main 2023
For the conversion of compound (X) = 4-nitrotoluene to product (Y) = 3,5-dibromotoluene, the sequence of reagents to be used will be:
  1. (A)(i) Br2(aq)Br_2(aq)Br2​(aq) (ii) LiAlH4LiAlH_4LiAlH4​ (iii) H3O+H_3O^+H3​O+
  2. (B)(i) Br2Br_2Br2​, Fe (ii) Fe, H+H^+H+ (iii) LiAlH4LiAlH_4LiAlH4​
  3. (C)(i) Fe, H+H^+H+ (ii) Br2(aq)Br_2(aq)Br2​(aq) (iii) HNO2HNO_2HNO2​ (iv) H3PO2H_3PO_2H3​PO2​
  4. (D)(i) Fe, H+H^+H+ (ii) Br2(aq)Br_2(aq)Br2​(aq) (iii) HNO2HNO_2HNO2​ (iv) CuBr

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correctJEE Main 2023
Identify the products (intermediate A and final product E) in the reaction sequence carried out on 4-nitrotoluene: Br2Br_2Br2​; then Sn/HClSn/HClSn/HCl; then NaNO2/HClNaNO_2/HClNaNO2​/HCl at 273-278 K; then H3PO2/H2OH_3PO_2/H_2OH3​PO2​/H2​O; then KMnO4/KOHKMnO_4/KOHKMnO4​/KOH, H+H^+H+. (Option structures shown in the figure.)
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q30·ChemistrySingle correctJEE Main 2023
Choose the correct colour of the product for the following reaction.
  1. (A)White
  2. (B)Red
  3. (C)Blue
  4. (D)Yellow

Correct answer: (B)

Step-by-step solution →
Q31·ChemistryMultiple correctJEE Advanced 2022
Considering the following reaction sequence, the correct option(s) is(are)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (B), (C)

Step-by-step solution →
Q32·ChemistrySingle correctJEE Main 2022
Which among the following represent reagent 'A'?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correctJEE Main 2022
The correct stability order of the following diazonium salt is
  1. (A)(A) > (B) > (C) > (D)
  2. (B)(A) > (C) > (D) > (B)
  3. (C)(C) > (A) > (D) > (B)
  4. (D)(C) > (D) > (B) > (A)

Correct answer: (B)

Step-by-step solution →
Q34·ChemistrySingle correctJEE Main 2022
Hydrolysis of which compound will give carbolic acid ?
  1. (A)Cumene
  2. (B)Benzenediazonium chloride
  3. (C)Benzal chloride
  4. (D)Ethylene glycol ketal

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correctJEE Main 2022
The correct sequential order of the reagents for the given reaction is :
  1. (A)HNO2HNO_{2}HNO2​, Fe/H+Fe/H^{+}Fe/H+, HNO2HNO_{2}HNO2​, KI, H2O/H+H_{2}O/H^{+}H2​O/H+
  2. (B)HNO2HNO_{2}HNO2​, KI, Fe/H+Fe/H^{+}Fe/H+, HNO2HNO_{2}HNO2​, H2OH_{2}OH2​O/warm
  3. (C)HNO2HNO_{2}HNO2​, KI, HNO2HNO_{2}HNO2​, Fe/H+Fe/H^{+}Fe/H+, H2O/H+H_{2}O/H^{+}H2​O/H+
  4. (D)HNO2HNO_{2}HNO2​, Fe/H+Fe/H^{+}Fe/H+, KI, HNO2HNO_{2}HNO2​, H2OH_{2}OH2​O/warm

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correctJEE Main 2022
The final product 'C' is the following series series of reactions
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correctJEE Main 2021
Which one of the following gives the most stable Diazonium salt ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correctJEE Main 2021
The correct sequence of correct reagent for the following transformation is:
  1. (A)(i) Cl2_22​,FeCl3_33​ (ii) NaNO2_22​,HCl,0° C (iii) Fe,HCl (iv) H2_22​O/H+^++
  2. (B)(i) Cl2_22​,FeCl3_33​ (ii) Fe,HCl (iii) NaNO2_22​,HCl,0° C (iv) H2_22​O/H+^++
  3. (C)(i) Fe,HCl (ii) Cl2_22​,HCl (iii) NaNO2_22​,HCl,0° C (iv) H2_22​O/H+^++
  4. (D)(i) Fe,HCl (ii) NaNO2_22​,HCl,0° C (iii) H2_22​O/H+^++ (iv) Cl2_22​,FeCl3_33​

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correctJEE Main 2021
Consider the above reaction, the product "P" is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correctJEE Main 2021
In the chemical reactions given above A and B respectively are:
  1. (A)CH3CH2OHCH_{3}CH_{2}OHCH3​CH2​OH and H3PO2H_{3}PO_{2}H3​PO2​
  2. (B)CH3CH2ClCH_{3}CH_{2}ClCH3​CH2​Cl and H3PO2H_{3}PO_{2}H3​PO2​
  3. (C)H3PO2H_{3}PO_{2}H3​PO2​ and CH3CH2OHCH_{3}CH_{2}OHCH3​CH2​OH
  4. (D)H3PO2H_{3}PO_{2}H3​PO2​ and CH3CH2ClCH_{3}CH_{2}ClCH3​CH2​Cl

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correctJEE Main 2021
Consider the above reaction, compound B is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correctJEE Main 2021
Considering the above reaction, X and Y respectively are :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correctJEE Main 2021
In the above reaction, the structural formula of (A), "X" and "Y" respectively are :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correctJEE Main 2021
In the above chemical reaction, intermediate "X" and reagent/condition "A" are :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correctJEE Main 2021
'A' and 'B' in the following reactions are :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correctJEE Main 2021
The diazonium salt of which of the following compounds will form a coloured dye on reaction with β\betaβ-Naphthol in NaOH ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correctJEE Main 2021
What is the correct sequence of reagents used for converting nitrobenzene into m-dibromobenzene ?
  1. (A)→Sn/HCl\xrightarrow{Sn/HCl}Sn/HCl​ / →Br2\xrightarrow{Br_{2}}Br2​​ / →NaNO2\xrightarrow{NaNO_{2}}NaNO2​​ / →NaBr\xrightarrow{NaBr}NaBr​
  2. (B)→Sn/HCl\xrightarrow{Sn/HCl}Sn/HCl​ / →KBr\xrightarrow{KBr}KBr​ / →Br2\xrightarrow{Br_{2}}Br2​​ / →H+\xrightarrow{H^{+}}H+​
  3. (C)→NaNO2\xrightarrow{NaNO_{2}}NaNO2​​ / →HCl\xrightarrow{HCl}HCl​ / →KBr\xrightarrow{KBr}KBr​ / →H+\xrightarrow{H^{+}}H+​
  4. (D)→Br2/Fe\xrightarrow{Br_{2}/Fe}Br2​/Fe​ / →Sn/HCl\xrightarrow{Sn/HCl}Sn/HCl​ / →NaNO2/HCl\xrightarrow{NaNO_{2}/HCl}NaNO2​/HCl​ / →CuBr/HBr\xrightarrow{CuBr/HBr}CuBr/HBr​

Correct answer: (D)

Step-by-step solution →
Q48·ChemistryNumericalJEE Advanced 2020
Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is 75%. What is the amount in grams of Q obtained from 9.3 mL of P? (Use density of P = 1.00 g mL−1mL^{-1}mL−1, Molar mass of C = 12.0, H = 1.0, O = 16.0 and N = 14.0 g mol−1mol^{-1}mol−1)

Correct answer: 18.60

Step-by-step solution →
Q49·ChemistrySingle correctJEE Main 2020
The major product Z obtained in the following reaction scheme is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correctJEE Main 2020
Consider the following reaction: →OH−\xrightarrow{OH^{-}}OH−​ 'X' The product 'X' is used
  1. (A)in protein estimation as an alternative to ninhydrin
  2. (B)as food grade colourant
  3. (C)in laboratory test for phenols
  4. (D)in acid-base titration as an indicator

Correct answer: (D)

Step-by-step solution →
Q51·ChemistryNumericalJEE Advanced 2019
Schemes 1 and 2 describe the conversion of P to Q and R to S, respectively. Scheme 3 describes the synthesis of T from Q and S. The total number of Br atoms in a molecule of T is

Correct answer: 4.00

Step-by-step solution →
Q52·ChemistrySingle correctJEE Main 2019
Benzene diazonium chloride on reaction with aniline in the presence of dilute hydrochloric acid gives :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q53·ChemistrySingle correctJEE Main 2019
Aniline dissolved in dilute HCl is reacted with sodium nitrite at 0∘C0^{\circ}C0∘C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

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Q54·ChemistrySingle correctJEE Main 2019
Coupling of benzene diazonium chloride with 1 – naphthol in alkaline medium will give:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q55·ChemistrySingle correctJEE Advanced 2017
The major product of the following reaction is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q56·ChemistryMultiple correctJEE Advanced 2016
The product(s) of the following reaction sequence is (are)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q57·ChemistryMultiple correctJEE Advanced 2015
In the following reactions, the major product W\mathbf{W}W is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q58·ChemistrySingle correctJEE Advanced 2014
For the identification of β\betaβ-naphthol using dye test, it is necessary to use
  1. (A)dichloromethane solution of β\betaβ-naphthol.
  2. (B)acidic solution of β\betaβ-naphthol.
  3. (C)neutral solution of β\betaβ-naphthol.
  4. (D)alkaline solution of β\betaβ-naphthol.

Correct answer: (D)

Step-by-step solution →

Diazonium Salts and Reactions — frequently asked

How many questions from Diazonium Salts and Reactions appear in JEE?

Diazonium Salts and Reactions has appeared in 53 of the last 186 JEE Main and JEE Advanced papers — about 28% of them — contributing 58 questions in total across those papers.

Is Diazonium Salts and Reactions an important chapter for JEE?

Judged by how often it is actually tested, it appears in roughly 28% of papers. Chapters above about 50% are effectively guaranteed to show up every session, so they repay thorough preparation; lower-frequency chapters are better treated as targeted revision.

Where do these Diazonium Salts and Reactions questions come from?

Every question is from an official JEE Main or JEE Advanced paper, transcribed from the original paper and tagged to this chapter. Answers follow the official answer key.

Other Chemistry chapters

  • Coordination Compounds 318
  • p-Block Elements 276
  • Redox Reactions and Electrochemistry 265
  • Chemical Bonding and Molecular Structure 207
  • d- and f-Block Elements 202
  • Aldehydes and Ketones 199
  • Equilibrium 199
  • Solutions 198

All 36 Chemistry chapters →

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