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JEE Main 5 September 2020 Shift 2 Question Paper with Answers

5 September 2020 · September session · 63 questions

63 of the 75 questions from the JEE Main 5 September 2020 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

12 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
21
Chemistry
19
Mathematics
23

Physics — JEE Main 5 September 2020 Shift 2

Q1·PhysicsSingle correct
Two coherent sources of sound, S1S_1S1​ and S2S_2S2​ produce source waves of the same wavelength, λ=1\lambda = 1λ=1 m, in phase. S1S_1S1​ and S2S_2S2​ are placed 1.5 m apart (see fig). A listener located at L, directly in front of S2S_2S2​ finds that the intensity is at a minimum when he is 2 m away from S2S_2S2​. The listener moves away from S1S_1S1​, keeping his distance from S2S_2S2​ fixed. The adjacent maximum of intensity is observed when the listener is at a distance d from S1S_1S1​. Then, d is:
  1. (A)12 m
  2. (B)3 m
  3. (C)5 m
  4. (D)2 m

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
Two different wires having lengths L1L_1L1​ and L2L_2L2​, and respective temperature coefficient of linear 4expansion α1\alpha_1α1​ and α2\alpha_2α2​, are joined end-to-end. Then the effective temperature coefficient of linear expansion is:
  1. (A)α1+α22\dfrac{\alpha_1+\alpha_2}{2}2α1​+α2​​
  2. (B)2α1α22\sqrt{\alpha_1\alpha_2}2α1​α2​​
  3. (C)α1L1+a2L2L1+L2\dfrac{\alpha_1 L_1 + a_2 L_2}{L_1+L_2}L1​+L2​α1​L1​+a2​L2​​
  4. (D)4α1α2α1+α2L1L2(L2+L1)24\dfrac{\alpha_1\alpha_2}{\alpha_1+\alpha_2}\dfrac{L_1 L_2}{(L_2+L_1)^{2}}4α1​+α2​α1​α2​​(L2​+L1​)2L1​L2​​

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
In the circuit shown, charge on the 5 μ\muμF capacitor is:
  1. (A)16.36 μ\muμC
  2. (B)5.45 μ\muμC
  3. (C)10.90 μ\muμC
  4. (D)18.00 μ\muμC

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
In adiabatic process, the density of a diatomic gas becomes 32 times its initial value. The final pressure of the gas is found to be n times the initial pressure. The value of n is:
  1. (A)128
  2. (B)132\dfrac{1}{32}321​
  3. (C)32
  4. (D)326

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
An iron rod of volume 10−310^{-3}10−3 m3^33 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be:
  1. (A)0.5×1020.5 \times 10^{2}0.5×102 Am2^22
  2. (B)50×10250 \times 10^{2}50×102 Am2^22
  3. (C)500×102500 \times 10^{2}500×102 Am2^22
  4. (D)5×1025 \times 10^{2}5×102 Am2^22

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
The correct match between the entries in column I and column II are:
RadiationWavelength
a.Microwavei.100 m
b.Gamma raysii.10−1510^{-15}10−15 m
c.A.M. radio wavesiii.10−1010^{-10}10−10 m
d.X-raysiv.10−310^{-3}10−3 m
  1. (A)(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
  2. (B)(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
  3. (C)(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
  4. (D)(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
A radioactive nucleus decays by two difference processes. The half life for the first process is 10 s and that for the second is 100 s. The effective half life of the nucleus is closes to:
  1. (A)6 sec.
  2. (B)9 sec.
  3. (C)12 sec.
  4. (D)55 sec.

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
Ten charges are placed on the circumference of a circle of radius R with constant angular separation between successive charges. Alternate charges 1, 3, 5, 7, 9 have charge (+ q) each, while 2, 4, 6, 8, 10 have charge (− q) each. The potential V and the electric field E at the centre of the circle are respectively: (Take V = 0 at infinity)
  1. (A)V=10q4πϵ0RV = \dfrac{10q}{4\pi \epsilon_0 R}V=4πϵ0​R10q​; E=10q4πϵ0R2E = \dfrac{10q}{4\pi \epsilon_0 R^{2}}E=4πϵ0​R210q​
  2. (B)V=0V = 0V=0; E=10q4πϵ0R2E = \dfrac{10q}{4\pi \epsilon_0 R^{2}}E=4πϵ0​R210q​
  3. (C)V=0V = 0V=0 ; E=0E = 0E=0
  4. (D)V=10q4πϵ0RV = \dfrac{10q}{4\pi \epsilon_0 R}V=4πϵ0​R10q​; E=0E = 0E=0

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A driver in a car, approaching a vertical wall notices that the frequency of his car horn, has changed from 440 Hz to 480 Hz, when it gets reflected from the wall. If the speed of sound in air is 345 m/s, then the speed of the car is:
  1. (A)24 km/hr
  2. (B)36 km/hr
  3. (C)18 km/hr
  4. (D)54 km/hr

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
A parallel plate capacitor has plate of length '\ell', width 'w' and separation of plates is 'd'. It is connected to a battery of emf V. A dielectric slap of the same thickness 'd' and of dielectric constant k = 4 is being, inserted between the plates of the capacitor. At what length of the slab inside plates, will be energy stored in the capacitor be two times the initial energy stored?
  1. (A)2ℓ/32\ell/32ℓ/3
  2. (B)ℓ/2\ell/2ℓ/2
  3. (C)ℓ/4\ell/4ℓ/4
  4. (D)ℓ/3\ell/3ℓ/3

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
A spaceship in space sweeps stationary interplanetary dust. As a result, its mass increases at a rate dM(t)dt=bv2(t)\dfrac{dM(t)}{dt} = bv^{2}(t)dtdM(t)​=bv2(t), where v(t) its instantaneous velocity. The instantaneous acceleration of the satellite is:
  1. (A)−2bv3M(t)-\dfrac{2bv^{3}}{M(t)}−M(t)2bv3​
  2. (B)−bv3M(t)-\dfrac{bv^{3}}{M(t)}−M(t)bv3​
  3. (C)−bv(t)-bv(t)−bv(t)
  4. (D)−bv32M(t)-\dfrac{bv^{3}}{2M(t)}−2M(t)bv3​

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
The acceleration due to gravity on the earth's surface at the poles is g an and angular velocity of the earth about the axis passing through the pole is ω\omegaω. An object is weight at the equator and at a height h above the poles by using a spring balance. If the weights are found to be same, then h is : (h<<R, where R is the radius of the earth)
  1. (A)R2ω22g\dfrac{R^{2}\omega^{2}}{2g}2gR2ω2​
  2. (B)R2ω2g\dfrac{R^{2}\omega^{2}}{g}gR2ω2​
  3. (C)R2ω28g\dfrac{R^{2}\omega^{2}}{8g}8gR2ω2​
  4. (D)R2ω24g\dfrac{R^{2}\omega^{2}}{4g}4gR2ω2​

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
In an experiment to verify Stokes law, a small spherical ball of radius r and density ρ\rhoρ falls under gravity through a distance h in air before entering a tank of water. If the terminal velocity of the ball inside water is same as its velocity just before entering the water surface, then the value of h is proportional to: (ignore viscosity of air)
  1. (A)r3r^{3}r3
  2. (B)r4r^{4}r4
  3. (C)r2r^{2}r2
  4. (D)rrr

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
A ring is hung on a nail. It can oscillate, without slipping or sliding (i) in its plane with a time period T1_11​ and, T(ii) back and forth in a direction perpendicular to its plane, with a period T2_22​. The ratio T1T2\dfrac{T_1}{T_2}T2​T1​​ will be:
  1. (A)23\dfrac{2}{\sqrt{3}}3​2​
  2. (B)33\dfrac{3}{\sqrt{3}}3​3​
  3. (C)23\dfrac{\sqrt{2}}{3}32​​
  4. (D)23\dfrac{2}{3}32​

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correct
The velocity (v) and time (t) graph of a body in a straight line motion is shown in the figure. The point S is at 4.333 seconds. The total distance covered by the body in 6 s is:
  1. (A)11 m
  2. (B)373\dfrac{37}{3}337​ m
  3. (C)12 m
  4. (D)494\dfrac{49}{4}449​ m

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
A galvanometer is used in laboratory for detecting the null point in electrical experiments. If, on passing a current of 6 mA it produces a deflection of 2°, its figure of merit is close to:
  1. (A)666° A/div.
  2. (B)6×10−36 \times 10^{-3}6×10−3 A/div.
  3. (C)333° A/div.
  4. (D)3×10−33 \times 10^{-3}3×10−3 A/div.

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is:
  1. (A)+ 1 V
  2. (B)– 1 V
  3. (C)+ 2 V
  4. (D)– 2 V

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsNumerical
A thin rod of mass 0.9 kg and length 1 m is suspended, at rest, from one end so that it can freely oscillate in the vertical plane. A particle of move 0.1 kg moving in a straight line with velocity 80 m/s hits the rod at its bottom most point and sticks to it (see figure). The angular speed (in rad/s) of the rod immediately after the collision will be __________.

Correct answer: 20.00

Step-by-step solution →
Q19·PhysicsNumerical
The surface of a metal is illuminated alternately with photons of energies E1_11​ = 4 eV and E2_22​ = 2.5 eV respectively. The ratio of maximum speeds of the photoelectrons emitted in the two cases is 2. The work function of the metal in (eV) is __________.

Correct answer: 2.00

Step-by-step solution →
Q20·PhysicsNumerical
A prism of angle A = 1° has a refractive index μ=1.5\mu = 1.5μ=1.5. A good estimate for the minimum angle of deviation (in degrees) is close to N/10. Value of N is __________.

Correct answer: 5.00

Step-by-step solution →
Q21·PhysicsNumerical
A body of mass 2 kg, is driven by an engine delivering, a constant power 1 J/s. the body starts from rest and moves in a straight line. After 9 seconds, the body has moved a distance (in m) __________.

Correct answer: 18.00

Step-by-step solution →

Chemistry — JEE Main 5 September 2020 Shift 2

Q22·ChemistrySingle correct
An element crystallises in a face-centred cubic (fcc) unit cell with cell edge a. The distance between the centres of two nearest octahedral voids in the crystal lattice is:
  1. (A)a2\dfrac{a}{2}2a​
  2. (B)2a\sqrt{2}a2​a
  3. (C)a
  4. (D)a2\dfrac{a}{\sqrt{2}}2​a​

Correct answer: (D)

Step-by-step solution →
Q23·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q24·ChemistrySingle correct
Adsorption of a gas follows Freundlich adsorption isotherm. If x is the mass of the gas adsorbed on mass m of the adsorbent, the correct plot of xm\dfrac{x}{m}mx​ versus p is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q25·ChemistrySingle correct
The variation of molar conductivity with concentration of an electrolyte (X) in aqueous solution is shown in the given figure.
  1. (A)KNO3KNO_3KNO3​
  2. (B)CH3COOHCH_3COOHCH3​COOH
  3. (C)HClHClHCl
  4. (D)NaClNaClNaCl

Correct answer: (B)

Step-by-step solution →
Q26·ChemistrySingle correct
The compound that has the largest H – M – H bond angle (M = N, O, S, C), is
  1. (A)H2OH_2OH2​O
  2. (B)CH4CH_4CH4​
  3. (C)H2SH_2SH2​S
  4. (D)NH3NH_3NH3​

Correct answer: (B)

Step-by-step solution →
Q27·ChemistrySingle correct
Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ mol−1^{-1}−1 and 4 kJ mol−1^{-1}−1, respectively. The hydration enthalpy of NaCl is:
  1. (A)784 kJ mol−1^{-1}−1
  2. (B)-784 kJ mol−1^{-1}−1
  3. (C)780 kJ mol−1^{-1}−1
  4. (D)-780 kJ mol−1^{-1}−1

Correct answer: (B)

Step-by-step solution →
Q28·ChemistrySingle correct
The rate constant (k) of a reaction is measured at different temperatures (T), and the data are plotted in the given figure. The activation energy of the reaction in kJ mol−1^{-1}−1 is: (R is gas constant)
  1. (A)2R
  2. (B)2/R
  3. (C)R
  4. (D)1/R

Correct answer: (A)

Step-by-step solution →
Q29·ChemistrySingle correct
The major product formed in the following reaction is: CH3CH=CHCH(CH3)2→HBrCH_3CH=CHCH(CH_3)_2 \xrightarrow{HBr}CH3​CH=CHCH(CH3​)2​HBr​
  1. (A)CH3CH2CH(Br)CH(CH3)2CH_3CH_2CH(Br)CH(CH_3)_2CH3​CH2​CH(Br)CH(CH3​)2​
  2. (B)CH3CH2CH2C(Br)(CH3)2CH_3CH_2CH_2C(Br)(CH_3)_2CH3​CH2​CH2​C(Br)(CH3​)2​
  3. (C)Br(CH2)3CH(CH3)2Br(CH_2)_3CH(CH_3)_2Br(CH2​)3​CH(CH3​)2​
  4. (D)CH3CH(Br)CH2CH(CH3)2CH_3CH(Br)CH_2CH(CH_3)_2CH3​CH(Br)CH2​CH(CH3​)2​

Correct answer: (B)

Step-by-step solution →
Q30·ChemistrySingle correct
Among the following compounds, geometrical isomerism is exhibited by:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q31·ChemistrySingle correct
Boron and silicon of very high purity can be obtained through:
  1. (A)zone refining
  2. (B)electrolytic refining
  3. (C)liquation
  4. (D)vapour phase refining

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
The following molecule acts as an:
  1. (A)Antiseptic
  2. (B)Anti-depressant
  3. (C)Anti-histamine
  4. (D)Anti-bacterial

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
Which one of the following polymers is not obtained by condensation polymerisation?
  1. (A)Buna – N
  2. (B)Nylon 6
  3. (C)Nylon 6, 6
  4. (D)Bakelite

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
Hydrogen peroxide, in the pure state, is:
  1. (A)non-planar and blue in color
  2. (B)planar and blue in color
  3. (C)linear and blue in color
  4. (D)linear and almost colorless

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
The one that is NOT suitable for the removal of permanent hardness of water is:
  1. (A)Calgon's method
  2. (B)Clark's method
  3. (C)Treatment with sodium carbonate
  4. (D)Ion-exchange method

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
Consider the complex ions, trans −[Co(en)2Cl2]+-\left[Co(en)_2Cl_2\right]^+−[Co(en)2​Cl2​]+ (A) and cis −[Co(en)2Cl2]+-\left[Co(en)_2Cl_2\right]^+−[Co(en)2​Cl2​]+ (B). The correct statement regarding them is:
  1. (A)both (A) and (B) cannot be optically active.
  2. (B)(A) cannot be optically active, but (B) can be optically active.
  3. (C)both (A) and (B) can be optically active.
  4. (D)(A) can be optically active, but (B) cannot be optically active.

Correct answer: (B)

Step-by-step solution →
Q37·ChemistryNumerical
The number of chiral carbons present in sucrose is __________.

Correct answer: 9.00

Step-by-step solution →
Q38·ChemistryNumerical
Considering that Δ0>P\Delta_0 > PΔ0​>P, the magnetic moment (in BM) of [Ru(H2O)6]2+\left[Ru(H_2O)_6\right]^{2+}[Ru(H2​O)6​]2+ would be __________.

Correct answer: 0.00

Step-by-step solution →
Q39·ChemistryNumerical
The volume, in mL, of 0.02 M K2_22​Cr2_22​O7_77​ solution required to react with 0.288 g of ferrous oxalate in acidic medium is __________. (Molar mass of Fe = 56 mol−1^{-1}−1)

Correct answer: 50.00

Step-by-step solution →
Q40·ChemistryNumerical
For a reaction X + Y = 2Z, 1.0 mol of X, 1.5 mol of Y and 0.5 mol of Z were taken in a 1 L vessel and allowed to react. At equilibrium, the concentration of Z was 1.0 mol L−1^{-1}−1. The equilibrium constant of the reaction is __________ x15\dfrac{x}{15}15x​. The value of x is __________.

Correct answer: 16.00

Step-by-step solution →

Mathematics — JEE Main 5 September 2020 Shift 2

Q41·MathematicsSingle correct
The value of (−1+i31−i)30\left(\dfrac{-1+i\sqrt{3}}{1-i}\right)^{30}(1−i−1+i3​​)30 is:
  1. (A)215i2^{15}i215i
  2. (B)−215-2^{15}−215
  3. (C)656^565
  4. (D)−215i-2^{15}i−215i

Correct answer: (D)

Step-by-step solution →
Q42·MathematicsSingle correct
If the system of linear equations x+y+3z=0x+y+3z=0x+y+3z=0 x+3y+k2z=0x+3y+k^2z=0x+3y+k2z=0 3x+y+3z=03x+y+3z=03x+y+3z=0 has a non-zero solution (x,y,z)(x,y,z)(x,y,z) for some k∈Rk\in Rk∈R, then x+(yz)x+\left(\dfrac{y}{z}\right)x+(zy​) is equal to:
  1. (A)333
  2. (B)999
  3. (C)−3-3−3
  4. (D)−9-9−9

Correct answer: (C)

Step-by-step solution →
Q43·MathematicsSingle correct
lim⁡x→0x(e(1+x2+x4−1)/x−1)1+x2+x4−1\displaystyle\lim_{x\to 0}\dfrac{x\left(e^{\left(\sqrt{1+x^2+x^4}-1\right)/x}-1\right)}{\sqrt{1+x^2+x^4}-1}x→0lim​1+x2+x4​−1x(e(1+x2+x4​−1)/x−1)​
  1. (A)does not exist
  2. (B)is equal to 111
  3. (C)is equal to e\sqrt{e}e​
  4. (D)is equal to 000

Correct answer: (B)

Step-by-step solution →
Q44·MathematicsSingle correct
If for some α∈R\alpha\in Rα∈R, the lines L1:x+12=y−2−1=z−11L_1:\dfrac{x+1}{2}=\dfrac{y-2}{-1}=\dfrac{z-1}{1}L1​:2x+1​=−1y−2​=1z−1​ and L2:x+2α=y+15−α=z+11L_2:\dfrac{x+2}{\alpha}=\dfrac{y+1}{5-\alpha}=\dfrac{z+1}{1}L2​:αx+2​=5−αy+1​=1z+1​ are coplanar, then the line L2L_2L2​ passes through the point:
  1. (A)(2,−10,−2)(2,-10,-2)(2,−10,−2)
  2. (B)(10,−2,−2)(10,-2,-2)(10,−2,−2)
  3. (C)(10,2,2)(10,2,2)(10,2,2)
  4. (D)(−2,10,2)(-2,10,2)(−2,10,2)

Correct answer: (A)

Step-by-step solution →
Q45·MathematicsSingle correct
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation cos⁡xdydx+2ysin⁡x=sin⁡2x,x∈(0,π2)\cos x\dfrac{dy}{dx}+2y\sin x=\sin 2x, x\in\left(0,\dfrac{\pi}{2}\right)cosxdxdy​+2ysinx=sin2x,x∈(0,2π​). If y(π/3)=0y(\pi/3)=0y(π/3)=0, then y(π/4)y(\pi/4)y(π/4) is equal to:
  1. (A)2+22+\sqrt{2}2+2​
  2. (B)12−1\dfrac{1}{\sqrt{2}}-12​1​−1
  3. (C)2−22-\sqrt{2}2−2​
  4. (D)2−2\sqrt{2}-22​−2

Correct answer: (D)

Step-by-step solution →
Q46·MathematicsSingle correct
If L=sin⁡2(π16)−sin⁡2(π8)L=\sin^2\left(\dfrac{\pi}{16}\right)-\sin^2\left(\dfrac{\pi}{8}\right)L=sin2(16π​)−sin2(8π​) and M=cos⁡2(π16)−sin⁡2(π8)M=\cos^2\left(\dfrac{\pi}{16}\right)-\sin^2\left(\dfrac{\pi}{8}\right)M=cos2(16π​)−sin2(8π​), then:
  1. (A)M=142+14cos⁡π8M=\dfrac{1}{4\sqrt{2}}+\dfrac{1}{4}\cos\dfrac{\pi}{8}M=42​1​+41​cos8π​
  2. (B)L=−122+12cos⁡π8L=-\dfrac{1}{2\sqrt{2}}+\dfrac{1}{2}\cos\dfrac{\pi}{8}L=−22​1​+21​cos8π​
  3. (C)M=122+12cos⁡π8M=\dfrac{1}{2\sqrt{2}}+\dfrac{1}{2}\cos\dfrac{\pi}{8}M=22​1​+21​cos8π​
  4. (D)L=142−14cos⁡π8L=\dfrac{1}{4\sqrt{2}}-\dfrac{1}{4}\cos\dfrac{\pi}{8}L=42​1​−41​cos8π​

Correct answer: (C)

Step-by-step solution →
Q47·MathematicsSingle correct
Which of the following point lies on the tangent to the curve x4ey+2y+1=3x^4e^y+2\sqrt{y+1}=3x4ey+2y+1​=3 at the point (1,0)(1,0)(1,0)?
  1. (A)(2,2)(2,2)(2,2)
  2. (B)(−2,6)(-2,6)(−2,6)
  3. (C)(−2,4)(-2,4)(−2,4)
  4. (D)(2,6)(2,6)(2,6)

Correct answer: (B)

Step-by-step solution →
Q48·MathematicsSingle correct
The derivation of tan⁡−1(1+x2−1x)\tan^{-1}\left(\dfrac{\sqrt{1+x^2}-1}{x}\right)tan−1(x1+x2​−1​) with respect to tan⁡−1(2x1−x21−2x2)\tan^{-1}\left(\dfrac{2x\sqrt{1-x^2}}{1-2x^2}\right)tan−1(1−2x22x1−x2​​) at x=12x=\dfrac{1}{2}x=21​ is:
  1. (A)233\dfrac{2\sqrt{3}}{3}323​​
  2. (B)310\dfrac{\sqrt{3}}{10}103​​
  3. (C)312\dfrac{\sqrt{3}}{12}123​​
  4. (D)235\dfrac{2\sqrt{3}}{5}523​​

Correct answer: (B)

Step-by-step solution →
Q49·MathematicsSingle correct
If the sum of the second, third and fourth terms of a positive term G.P. is 3 and the sum of its sixth, seventh and eights terms is 243, then the sum of the first 50 terms of this G.P. is:
  1. (A)126(350−1)\dfrac{1}{26}\left(3^{50}-1\right)261​(350−1)
  2. (B)113(350−1)\dfrac{1}{13}\left(3^{50}-1\right)131​(350−1)
  3. (C)213(350−1)\dfrac{2}{13}\left(3^{50}-1\right)132​(350−1)
  4. (D)126(349−1)\dfrac{1}{26}\left(3^{49}-1\right)261​(349−1)

Correct answer: (A)

Step-by-step solution →
Q50·MathematicsSingle correct
If ∫cos⁡θ5+7sin⁡θ−2cos⁡2θ dθ=Alog⁡e∣B(θ)∣+C\displaystyle\int\dfrac{\cos\theta}{5+7\sin\theta-2\cos^2\theta}\,d\theta=A\log_e\left|B(\theta)\right|+C∫5+7sinθ−2cos2θcosθ​dθ=Aloge​∣B(θ)∣+C, where C is a constant of integration, then B(θ)A\dfrac{B(\theta)}{A}AB(θ)​ can be:
  1. (A)5(sin⁡θ+3)2sin⁡θ+1\dfrac{5(\sin\theta+3)}{2\sin\theta+1}2sinθ+15(sinθ+3)​
  2. (B)5(2sin⁡θ+1)sin⁡θ+3\dfrac{5(2\sin\theta+1)}{\sin\theta+3}sinθ+35(2sinθ+1)​
  3. (C)2sin⁡θ+15(sin⁡θ+3)\dfrac{2\sin\theta+1}{5(\sin\theta+3)}5(sinθ+3)2sinθ+1​
  4. (D)2sin⁡θ+1sin⁡θ+3\dfrac{2\sin\theta+1}{\sin\theta+3}sinθ+32sinθ+1​

Correct answer: (B)

Step-by-step solution →
Q51·MathematicsSingle correct
If α\alphaα and β\betaβ are the roots of the equation, 7x2−3x−2=07x^2-3x-2=07x2−3x−2=0, then the value of α1−α2+β1−β2\dfrac{\alpha}{1-\alpha^2}+\dfrac{\beta}{1-\beta^2}1−α2α​+1−β2β​ is equal to:
  1. (A)2732\dfrac{27}{32}3227​
  2. (B)2716\dfrac{27}{16}1627​
  3. (C)38\dfrac{3}{8}83​
  4. (D)124\dfrac{1}{24}241​

Correct answer: (B)

Step-by-step solution →
Q52·MathematicsSingle correct
If the length of the chord of the circle, x2+y2=r2 (r>0)x^2+y^2=r^2\ (r>0)x2+y2=r2 (r>0) along the line y−2x=3y-2x=3y−2x=3 is r, the r2r^2r2 is equal to:
  1. (A)121212
  2. (B)125\dfrac{12}{5}512​
  3. (C)95\dfrac{9}{5}59​
  4. (D)245\dfrac{24}{5}524​

Correct answer: (B)

Step-by-step solution →
Q53·MathematicsSingle correct
The statement (P→(q→p))→(p→(p∨q))(P \to (q \to p)) \to (p \to (p \vee q))(P→(q→p))→(p→(p∨q)) is:
  1. (A)a tautology
  2. (B)equivalent to (p∧q)∨(∼q)(p \wedge q) \vee (\sim q)(p∧q)∨(∼q)
  3. (C)equivalent to (p∨q)∧(∼p)(p \vee q) \wedge (\sim p)(p∨q)∧(∼p)
  4. (D)a contradiction

Correct answer: (A)

Step-by-step solution →
Q54·MathematicsSingle correct
There are 3 sections in a question paper and each section contains 5 questions. A candidate has to answer a total of 5 questions, choosing at least one question from each section. Then the number of ways, in which the candidate can choose the questions, is:
  1. (A)2255
  2. (B)3000
  3. (C)2250
  4. (D)1500

Correct answer: (C)

Step-by-step solution →
Q55·MathematicsSingle correct
If a + x = b + y = c + z + 1, where a, b, c, x, y, x are non-zero distinct real numbers then ∣xa+yx+ayb+yy+bzc+yz+c∣\begin{vmatrix} x & a+y & x+a \\ y & b+y & y+b \\ z & c+y & z+c \end{vmatrix}​xyz​a+yb+yc+y​x+ay+bz+c​​ is equal to:
  1. (A)y(a - b)
  2. (B)y(b - a)
  3. (C)0
  4. (D)y(a - c)

Correct answer: (A)

Step-by-step solution →
Q56·MathematicsSingle correct
If the sum of the first 20 terms of the series log⁡(71/2)x+log⁡(71/3)x+log⁡(71/4)x+...\log_{(7^{1/2})} x + \log_{(7^{1/3})} x + \log_{(7^{1/4})} x + ...log(71/2)​x+log(71/3)​x+log(71/4)​x+... is 460, then x is equal to:
  1. (A)727^272
  2. (B)746/217^{46/21}746/21
  3. (C)71/27^{1/2}71/2
  4. (D)e2e^2e2

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correct
If the line y = mx + c is a common tangent to the hyperbola x2100−y264=1\dfrac{x^2}{100} - \dfrac{y^2}{64} = 1100x2​−64y2​=1 and the circle x2+y2=36x^2 + y^2 = 36x2+y2=36, then which one of the following is true?
  1. (A)4c2=3694c^2 = 3694c2=369
  2. (B)c2=369c^2 = 369c2=369
  3. (C)5m=45m = 45m=4
  4. (D)8m+5=08m + 5 = 08m+5=0

Correct answer: (A)

Step-by-step solution →
Q58·MathematicsSingle correct
If the mean and standard deviation of the data 3, 5, 7, a, b are 5 and 2 respectively, then a and b are the roots of the equation:
  1. (A)x2−10x+19=0x^2 - 10x + 19 = 0x2−10x+19=0
  2. (B)x2−20x+18=0x^2 - 20x + 18 = 0x2−20x+18=0
  3. (C)x2−10x+18=0x^2 - 10x + 18 = 0x2−10x+18=0
  4. (D)2x2−20x+19=02x^2 - 20x + 19 = 02x2−20x+19=0

Correct answer: (A)

Step-by-step solution →
Q59·MathematicsNumerical
Let A=(a,b,c)A = (a, b, c)A=(a,b,c) and B=(1,2,3,4)B = (1, 2, 3, 4)B=(1,2,3,4). Then the number of elements in the set C={f:A→B∣2∈f(A) and f is not one-one}C = \{f : A \to B \mid 2 \in f(A) \text{ and } f \text{ is not one-one}\}C={f:A→B∣2∈f(A) and f is not one-one} is __________.

Correct answer: 19.00

Step-by-step solution →
Q60·MathematicsNumerical
The coefficient of x4x^4x4 in the expansion of (1+x+x2+x3)6(1 + x + x^2 + x^3)^6(1+x+x2+x3)6 in powers of x, is __________.

Correct answer: 120.00

Step-by-step solution →
Q61·MathematicsNumerical
If the lines x + y = a and x - y = b touch the curve y=x2−3x+2y = x^2 - 3x + 2y=x2−3x+2 at the points where the curve intersects the x-axis, then ab\dfrac{a}{b}ba​ is equal to __________.

Correct answer: 0.50

Step-by-step solution →
Q62·MathematicsNumerical
Let the vectors a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c}a,b,c be such that ∣a⃗∣=2,∣b⃗∣=4|\vec{a}| = 2, |\vec{b}| = 4∣a∣=2,∣b∣=4 and ∣c⃗∣=4|\vec{c}| = 4∣c∣=4. if the projection of b⃗\vec{b}b on a⃗\vec{a}a is equal to the projection of c⃗\vec{c}c on a⃗\vec{a}a and b⃗\vec{b}b is perpendicular to c⃗\vec{c}c, then the value of ∣a⃗+b⃗−c⃗∣|\vec{a} + \vec{b} - \vec{c}|∣a+b−c∣ is __________.

Correct answer: 6.00

Step-by-step solution →
Q63·MathematicsNumerical
In a bombing attack, there is 50% chance that a bomb will hit the target. At least two independent hits are required to destroy the target completely. Then the minimum number of bombs, that must be dropped to ensure that there is at least 99% chance of completely destroying the target, is __________.

Correct answer: 11.00

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Hydrogen 81/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • Solid State 63/186
  • Chemistry in Everyday Life 60/186
  • Isomerism 51/186
  • Magnetism and Matter 50/186
  • Mathematical Reasoning 26/186
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