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JEE Main 5 September 2020 Shift 1 Question Paper with Answers

5 September 2020 · September session · 62 questions

62 of the 75 questions from the JEE Main 5 September 2020 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

13 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
21
Chemistry
18
Mathematics
23

Physics — JEE Main 5 September 2020 Shift 1

Q1·PhysicsSingle correct
A hollow spherical shell at outer radius R floats just submerged under the water surface. The inner radius of the shell is r. If the specific gravity of the shell material is 278\frac{27}{8}827​ w.r.t water, the value of r is.
  1. (A)23\frac{2}{3}32​R
  2. (B)49\frac{4}{9}94​R
  3. (C)13\frac{1}{3}31​R
  4. (D)89\frac{8}{9}98​R

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
A balloon is moving up in air vertically above a point A on the ground. When it is at a height h1h_1h1​, a girl standing at a distance d (point B) from A (see figure) sees it at the angle 45045^{0}450 with respect to the vertical. When the balloon climbs up a future height h2h_2h2​, it is seen at the angle 60060^{0}600 with respect to the vertical if the girl moves further by a distance 2.464 d (point C). Then the height h2h_2h2​ is (given tan 30030^{0}300 = 0.5774):
  1. (A)0.464 d
  2. (B)0.732 d
  3. (C)1.464 d
  4. (D)d

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
A physical quantity z depends on four observables a, c, c and d, as z = a2b23c d3\dfrac{a^{2}b^{\frac{2}{3}}}{\sqrt{c}\,d^{3}}c​d3a2b32​​. The percentages of error in the measurement of a, b, c and d are 2%, 1.5%, 4% and 2.5% respectively. The percentage of error in z is:
  1. (A)13.5%
  2. (B)16.5%
  3. (C)12.25%
  4. (D)14.5%

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
A wheel is rotating freely with an angular speed ω\omegaω on a shaft. The moment of inertia of the wheel is I and the moment of inertia of the shaft is negligible. Another wheel of moment of inertia 3I initially at rest is suddenly coupled to the same shaft. The resultant fractional loss in the kinetic energy of the system is:
  1. (A)34\frac{3}{4}43​
  2. (B)56\frac{5}{6}65​
  3. (C)14\frac{1}{4}41​
  4. (D)0

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
In a resonance tube experiment when the tube is filled with water up to a height of 17.0 cm from bottom, it resonates with a given tuning fork. When the water level is raised the next resonance with the same tuning fork occurs at a height of 24.5 cm. If the velocity of sound in air is 330 m/s, the tuning fork frequency is:
  1. (A)1100 Hz
  2. (B)2200 Hz
  3. (C)3300 Hz
  4. (D)550 Hz

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
An electron is constrained to move along the y − axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E⃗=30j^sin⁡(1.5×107t−5×10−2x)\vec{E} = 30\hat{j}\sin\left(1.5\times10^{7}t - 5\times10^{-2}x\right)E=30j^​sin(1.5×107t−5×10−2x) V/m. The maximum magnetic force experienced by the electron will be: (given c=3×108 ms−1c = 3\times10^{8}\,\mathrm{ms^{-1}}c=3×108ms−1 and electron charge =1.6×10−19= 1.6\times10^{-19}=1.6×10−19C)
  1. (A)3.2×10−183.2\times10^{-18}3.2×10−18N
  2. (B)1.5×10−191.5\times10^{-19}1.5×10−19N
  3. (C)2.4×10−182.4\times10^{-18}2.4×10−18N
  4. (D)4.8×10−194.8\times10^{-19}4.8×10−19N

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
A bullet of mass 5 g, traveling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullet while the other half is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal/(g-0C)0.030\,\text{cal}/(\text{g-}^{0}\text{C})0.030cal/(g-0C) (1cal=4.2×107 ergs)(1\text{cal}=4.2\times10^{7}\text{ ergs})(1cal=4.2×107 ergs) close to:
  1. (A)83.3083.3^{0}83.30C
  2. (B)38.4038.4^{0}38.40C
  3. (C)87.5087.5^{0}87.50C
  4. (D)119.20119.2^{0}119.20C

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
The value of the acceleration due to gravity is g1g_1g1​ at a height h=R2h=\dfrac{R}{2}h=2R​ (R= radius of the earth) from the surface of the earth. It is again equal to g1g_1g1​ at a depth d below the surface of the earth. The ratio (dR)\left(\dfrac{d}{R}\right)(Rd​) equals:
  1. (A)79\frac{7}{9}97​
  2. (B)13\frac{1}{3}31​
  3. (C)59\frac{5}{9}95​
  4. (D)49\frac{4}{9}94​

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
For a concave lens of focal length f, the relation between object and image distances u and is vvv, respectively, from its pole can best be represented by (u - vvv is the reference line):
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
A galvanometer of resistance G is converted into a voltmeter of range 0 – IV by connecting a resistance R1R_1R1​ in series with it. The additional resistance that should be connected in series with R1R_1R1​ to increase the range of the voltmeter to 0 – 2V will be:
  1. (A)R1R_1R1​ + G
  2. (B)R1R_1R1​
  3. (C)G
  4. (D)R1R_1R1​ − G

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
Number of molecules in a volume of 4 cm3^33 of a perfect monoatomic gas at some temperature T and at a pressure of 2 cm of mercury is close to? (Given, mean kinetic energy of a molecule (at T) is 4×10−144 \times 10^{-14}4×10−14 erg, g = 980 cm / s2^22, density of mercury = 13.6 g / cm3^33)
  1. (A)5.8×10185.8 \times 10^{18}5.8×1018
  2. (B)4.0×10164.0 \times 10^{16}4.0×1016
  3. (C)5.8×10165.8 \times 10^{16}5.8×1016
  4. (D)4.0×10184.0 \times 10^{18}4.0×1018

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
A square loop of side 2a, and carrying current I, is kept in XZ plane with its centre at origin. A long wire carrying the same current I is placed parallel to the z − axis and passing through the point (0, b, 0), (b >> a). The magnitude of the torque on the loop about z − axis is given by:
  1. (A)2μ0I2a3πb2\dfrac{2\mu_0 I^2 a^3}{\pi b^2}πb22μ0​I2a3​
  2. (B)μ0I2a22πb\dfrac{\mu_0 I^2 a^2}{2\pi b}2πbμ0​I2a2​
  3. (C)μ0I2a32πb2\dfrac{\mu_0 I^2 a^3}{2\pi b^2}2πb2μ0​I2a3​
  4. (D)2μ0I2a2πb\dfrac{2\mu_0 I^2 a^2}{\pi b}πb2μ0​I2a2​

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
Assume that the displacement (s) of air is proportional to the pressure difference (Λp)(\Lambda p)(Λp) created by a sound wave. Displacement (s) further depends on the speed of sound (v), density of air (ρ) and the frequency (f). If Λp∼10Pa\Lambda p \sim 10\text{Pa}Λp∼10Pa, υ∼300\upsilon \sim 300υ∼300 m/s, ρ∼π1 lg/m3\rho \sim \pi 1 \text{ lg} / \text{m}^3ρ∼π1 lg/m3 and f ∼ 1000 Hz, then s will be of the order of (take the multiplicative constant to be 1)
  1. (A)110\dfrac{1}{10}101​ mm
  2. (B)10 mm
  3. (C)3100\dfrac{3}{100}1003​ mm
  4. (D)1 mm

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to [g is the acceleration due to gravity]:
  1. (A)t=1.8hgt = 1.8\sqrt{\dfrac{h}{g}}t=1.8gh​​
  2. (B)t=2h3gt = \sqrt{\dfrac{2h}{3g}}t=3g2h​​
  3. (C)t=3.4(hg)t = 3.4\sqrt{\left(\dfrac{h}{g}\right)}t=3.4(gh​)​
  4. (D)t=23(hg)t = \dfrac{2}{3}\sqrt{\left(\dfrac{h}{g}\right)}t=32​(gh​)​

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
Activities of three radioactive substances A, B and C are represented by the curves A, B and C in the figure. Then their half lives T1/2(A):T1/2(B):T1/2(C)T_{1/2}(A) : T_{1/2}(B) : T_{1/2}(C)T1/2​(A):T1/2​(B):T1/2​(C) are in the radio:
  1. (A)3:2:1
  2. (B)2:1:3
  3. (C)4:3:1
  4. (D)2:1:1

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
An electrical power line, having a total resistance of 2Ω, delivers 1 kW at 220 V. The efficiency of the transmission line is approximately:
  1. (A)96%
  2. (B)72%
  3. (C)91%
  4. (D)85%

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
Two capacitors of capacitances C and 2C are charged to potential differences V and 2V, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is:
  1. (A)32CV2\dfrac{3}{2}CV^223​CV2
  2. (B)92CV2\dfrac{9}{2}CV^229​CV2
  3. (C)256CV2\dfrac{25}{6}CV^2625​CV2
  4. (D)zero

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsNumerical
A force F⃗=(i^+2j^+3k^)\vec{F} = (\hat{i} + 2\hat{j} + 3\hat{k})F=(i^+2j^​+3k^) N acts at a point (4i^+3j^−k^)(4\hat{i} + 3\hat{j} - \hat{k})(4i^+3j^​−k^) m. Then the magnitude of torque about the point (i^+2j^+k^)(\hat{i} + 2\hat{j} + \hat{k})(i^+2j^​+k^) m will be x\sqrt{x}x​ N-m. The value of x is ________.

Correct answer: 195.00

Step-by-step solution →
Q19·PhysicsNumerical
A particle of mass 200 MeV/c2^22 collides with a hydrogen atom at rest. Soon after the collision the particle comes to rest, and the atom recoils and goes to its first excited state. The initial kinetic energy of the particle (in eV) is N4\dfrac{N}{4}4N​. The value of N is: (Given the mass of the hydrogen atom to be 1 GeV / c2^22).

Correct answer: 51.00

Step-by-step solution →
Q20·PhysicsNumerical
Two concentric circular coils, C1_11​ and C2_22​ are placed in the XY plane. C1_11​ has 500 turns, and a radius of 1 cm. C2_22​ has 200 turns and radius of 20 cm. C2_22​ carries a time dependent current I(t)=(5t2−2t+3)I(t) = (5t^2 - 2t + 3)I(t)=(5t2−2t+3) A where t is in s. The emf induced in C1_11​ (in mV), at the instant t = 1 s is 4x\dfrac{4}{x}x4​. The value of x is ________.

Correct answer: 5.00

Step-by-step solution →
Q21·PhysicsNumerical
A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum is n40\dfrac{n}{40}40n​ cm. The value of n is ________.

Correct answer: 50.00

Step-by-step solution →

Chemistry — JEE Main 5 September 2020 Shift 1

Q22·ChemistrySingle correct
Which of the following is not an essential amino acid?
  1. (A)Valine
  2. (B)Tyrosine
  3. (C)Leucine
  4. (D)Lysine

Correct answer: (B)

Step-by-step solution →
Q23·ChemistrySingle correct
A flask contains a mixture of compounds A and B. Both compounds decompose by first – order kinetics. The half lives for A and B are 300 s and 180 s, respectively. If the concentrations of A and B are equal initially, the line required for the concentration of A to be four times that of B (in s) is : (Use ln⁡2=0.693\ln 2 = 0.693ln2=0.693)
  1. (A)120
  2. (B)300
  3. (C)900
  4. (D)180

Correct answer: (C)

Step-by-step solution →
Q24·ChemistrySingle correct
The equation that represents the water – gas shift reactions is:
  1. (A)CO(g)+H2O(g)→Catalyst673 KCO2(g)+H2(g)CO(g) + H_2O(g) \xrightarrow[\text{Catalyst}]{673\,K} CO_2(g) + H_2(g)CO(g)+H2​O(g)673KCatalyst​CO2​(g)+H2​(g)
  2. (B)C(s)+H2O(g)→1270 KCO(g)+H2(g)C(s) + H_2O(g) \xrightarrow{1270\,K} CO(g) + H_2(g)C(s)+H2​O(g)1270K​CO(g)+H2​(g)
  3. (C)2C(s)+O2(g)+4N2(g)→1273 K2CO(g)+4N2(g)2C(s) + O_2(g) + 4N_2(g) \xrightarrow{1273\,K} 2CO(g) + 4N_2(g)2C(s)+O2​(g)+4N2​(g)1273K​2CO(g)+4N2​(g)
  4. (D)CH4(g)+H2O(g)→Ni1270 KCO(g)+3H2(g)CH_4(g) + H_2O(g) \xrightarrow[\text{Ni}]{1270\,K} CO(g) + 3H_2(g)CH4​(g)+H2​O(g)1270KNi​CO(g)+3H2​(g)

Correct answer: (A)

Step-by-step solution →
Q25·ChemistrySingle correct
In the following reaction sequence the major products A and B are:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q26·ChemistrySingle correct
If a person is suffering from the deficiency of nor – adrenaline, what kind of drug can be suggested?
  1. (A)Antidepressant
  2. (B)Antihistamine
  3. (C)Analgesic
  4. (D)Anti – inflammatory

Correct answer: (A)

Step-by-step solution →
Q27·ChemistrySingle correct
The potential energy curve for the H2H_2H2​ molecule as a function of internuclear distance is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q28·ChemistrySingle correct
The most appropriate reagent for conversion of C2H5CNC_2H_5CNC2​H5​CN into CH3CH2CH2NH2CH_3CH_2CH_2NH_2CH3​CH2​CH2​NH2​ is:
  1. (A)CaH2CaH_2CaH2​
  2. (B)Na(CN)BH3Na(CN)BH_3Na(CN)BH3​
  3. (C)LiAlH4LiAlH_4LiAlH4​
  4. (D)NaBH4NaBH_4NaBH4​

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correct
Which of the following derivates of alcohol is unstable is an aqueous base?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q30·ChemistrySingle correct
The condition that indicates a polluted environment is:
  1. (A)0.03% of CO2CO_2CO2​ in the atmosphere
  2. (B)pH of rain water to be 5.6
  3. (C)eutrophication
  4. (D)BOD value of 5 ppm

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
The values of the crystal field stabilization energies for a high spin d6d^6d6 metal ion in octahedral and tetrahedral fields, respectively, are:
  1. (A)−0.4Δo-0.4\Delta_o−0.4Δo​ and −0.27Δt-0.27\Delta_t−0.27Δt​
  2. (B)−1.6Δo-1.6\Delta_o−1.6Δo​ and −0.4Δt-0.4\Delta_t−0.4Δt​
  3. (C)−0.4Δo-0.4\Delta_o−0.4Δo​ and −0.6Δt-0.6\Delta_t−0.6Δt​
  4. (D)−2.4Δo-2.4\Delta_o−2.4Δo​ and −0.6Δt-0.6\Delta_t−0.6Δt​

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
The difference between the radii of 3rd and 4th orbits of Li2+Li^{2+}Li2+ in ΔR1\Delta R_1ΔR1​.. The difference between the radii of 3rd and 4th orbits of He+He^+He+ is ΔR2\Delta R_2ΔR2​. Ratio ΔR1:ΔR2\Delta R_1 : \Delta R_2ΔR1​:ΔR2​ is:
  1. (A)8:3
  2. (B)2:3
  3. (C)3:8
  4. (D)3:2

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
The increasing order of the acidity of the α\alphaα-hydrogen of the following compounds is:
  1. (A)(C) < (A) < (B) < (D)
  2. (B)(B) < (C) < (A) < (D)
  3. (C)(D) < (C) < (A) < (B)
  4. (D)(A) < (C) < (D) < (B)

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
The correct electronic configuration and spin – only magnetic moment (BM) of Gd3+Gd^{3+}Gd3+ (Z = 64), respectively, are:
  1. (A)[Xe]4f74f^74f7 and 7.9
  2. (B)[Xe]4f74f^74f7 and 8.9
  3. (C)[Xe]5f75f^75f7 and 8.9
  4. (D)[Xe]5f75f^75f7 and 7.9

Correct answer: (A)

Step-by-step solution →
Q35·ChemistryNumerical
The total number of coordination sites in ethylenediaminetetraacetate (EDTA4−EDTA^{4-}EDTA4−) is ____.

Correct answer: 6

Step-by-step solution →
Q36·ChemistryNumerical
The minimum number of moles of O2O_2O2​ required for complete combustion of 1 mole of propane and 2 moles of butane is ___

Correct answer: 18

Step-by-step solution →
Q37·ChemistryNumerical
An oxidation – reduction in which 3 electrons are transferred has a ΔG0\Delta G^0ΔG0 of 17.37 kJ mol−1mol^{-1}mol−1 at 25025^0250 C. The value of Ecell0E^0_{cell}Ecell0​ (in V is _____ × 10−210^{-2}10−2) (1 F = 96,500 C mol−1mol^{-1}mol−1)

Correct answer: -6

Step-by-step solution →
Q38·ChemistryNumerical
The number of chiral carbon(s) present in peptide, Ile-Arg-Pro, is ___

Correct answer: 4

Step-by-step solution →
Q39·ChemistryNumerical
A soft drink was bottled with a partial pressure of CO2CO_2CO2​ of 3 bar over the liquid at room temperature. The partial pressure of CO2CO_2CO2​ over the solution approaches a value of 30 bar when 44 g of CO2CO_2CO2​ is dissolved in 1 kg of water at room temperature. The approximate pH of the soft drink is ___ x 10−110^{-1}10−1/ (First dissociation constant of H2CO3H_2CO_3H2​CO3​ = 4.0×10−74.0\times10^{-7}4.0×10−7;log 2 = 0.3; density of the soft drink = 1 g mL−1mL^{-1}mL−1)

Correct answer: 37

Step-by-step solution →

Mathematics — JEE Main 5 September 2020 Shift 1

Q40·MathematicsSingle correct
If the four complex numbers, z,zˉ,zˉ−2Re(zˉ)z, \bar{z}, \bar{z} - 2\text{Re}(\bar{z})z,zˉ,zˉ−2Re(zˉ) and z−2Re(z)z - 2\text{Re}(z)z−2Re(z) represent the vertices of a square of side 4 units in the Argand plane, then ∣z∣|z|∣z∣ is equal to:
  1. (A)222\sqrt{2}22​
  2. (B)2
  3. (C)424\sqrt{2}42​
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q41·MathematicsSingle correct
The negation of the Boolean expression x↔∼yx \leftrightarrow \sim yx↔∼y is equivalent to
  1. (A)(x∧∼y)∨(∼x∧y)(x \wedge \sim y) \vee (\sim x \wedge y)(x∧∼y)∨(∼x∧y)
  2. (B)(∼x∧y)∨(∼x∧∼y)(\sim x \wedge y) \vee (\sim x \wedge \sim y)(∼x∧y)∨(∼x∧∼y)
  3. (C)(x∧y)∧(∼x∨∼y)(x \wedge y) \wedge (\sim x \vee \sim y)(x∧y)∧(∼x∨∼y)
  4. (D)(x∧y)∨(∼x∧∼y)(x \wedge y) \vee (\sim x \wedge \sim y)(x∧y)∨(∼x∧∼y)

Correct answer: (D)

Step-by-step solution →
Q42·MathematicsSingle correct
If 210+29.31+28.32+...+2.39+310=S−2112^{10} + 2^{9}.3^{1} + 2^{8}.3^{2} + ... + 2.3^{9} + 3^{10} = S - 2^{11}210+29.31+28.32+...+2.39+310=S−211, then S is equal to
  1. (A)3112+210\dfrac{3^{11}}{2} + 2^{10}2311​+210
  2. (B)311−2123^{11} - 2^{12}311−212
  3. (C)2.3112.3^{11}2.311
  4. (D)3113^{11}311

Correct answer: (D)

Step-by-step solution →
Q43·MathematicsSingle correct
Let λ∈R\lambda \in Rλ∈R. The system of linear equations. 2x1−4x2+λx3=12x_1 - 4x_2 + \lambda x_3 = 12x1​−4x2​+λx3​=1 x1−6x2+x3=2x_1 - 6x_2 + x_3 = 2x1​−6x2​+x3​=2 λx1−10x2+4x3=3\lambda x_1 - 10x_2 + 4x_3 = 3λx1​−10x2​+4x3​=3 Is inconsistent for:
  1. (A)exactly one positive value of λ\lambdaλ
  2. (B)exactly one negative value of λ\lambdaλ
  3. (C)every value of λ\lambdaλ
  4. (D)exactly two values of λ\lambdaλ

Correct answer: (B)

Step-by-step solution →
Q44·MathematicsSingle correct
If ∫(e2x+2ex−e−x−1)e(ex+e−x)dx=g(x)e(ex+e−x)+c\int (e^{2x} + 2e^{x} - e^{-x} - 1)e^{(e^{x}+e^{-x})}dx = g(x)e^{(e^{x}+e^{-x})}+c∫(e2x+2ex−e−x−1)e(ex+e−x)dx=g(x)e(ex+e−x)+c where c is a constant of integration, then g(0) is equal to:
  1. (A)e
  2. (B)2
  3. (C)e2e^{2}e2
  4. (D)1

Correct answer: (B)

Step-by-step solution →
Q45·MathematicsSingle correct
If 32sin⁡2α−13^{2\sin 2\alpha - 1}32sin2α−1, 14 and 34−2sin⁡2α3^{4-2\sin 2\alpha}34−2sin2α are the first three terms of an AP for some α\alphaα, then the sixth term of this AP is:
  1. (A)65
  2. (B)78
  3. (C)66
  4. (D)81

Correct answer: (C)

Step-by-step solution →
Q46·MathematicsSingle correct
A survey shows that 73% of the persons working in an office like coffee, whereas 65% like tea. If x denotes the percentage of them, who like both coffee and tea, then x cannot be:
  1. (A)63
  2. (B)54
  3. (C)38
  4. (D)36

Correct answer: (D)

Step-by-step solution →
Q47·MathematicsSingle correct
If the common tangent to the parabolas y2=4xy^{2} = 4xy2=4x and x2=4yx^{2} = 4yx2=4y also touches the circle, x2+y2=c2x^{2} + y^{2} = c^{2}x2+y2=c2, then c is equal to
  1. (A)122\dfrac{1}{2\sqrt{2}}22​1​
  2. (B)12\dfrac{1}{\sqrt{2}}2​1​
  3. (C)12\dfrac{1}{2}21​
  4. (D)14\dfrac{1}{4}41​

Correct answer: (B)

Step-by-step solution →
Q48·MathematicsSingle correct
The product of the roots of the equation 9x2−18∣x∣+5=09x^{2} - 18|x| + 5 = 09x2−18∣x∣+5=0, is:
  1. (A)59\dfrac{5}{9}95​
  2. (B)259\dfrac{25}{9}925​
  3. (C)527\dfrac{5}{27}275​
  4. (D)2581\dfrac{25}{81}8125​

Correct answer: (D)

Step-by-step solution →
Q49·MathematicsSingle correct
The value of ∫−π/2π/211+esin⁡xdx\displaystyle\int_{-\pi/2}^{\pi/2} \dfrac{1}{1+e^{\sin x}}dx∫−π/2π/2​1+esinx1​dx is:
  1. (A)3π2\dfrac{3\pi}{2}23π​
  2. (B)π2\dfrac{\pi}{2}2π​
  3. (C)π\piπ
  4. (D)π4\dfrac{\pi}{4}4π​

Correct answer: (B)

Step-by-step solution →
Q50·MathematicsSingle correct
If S is the sum of the first 10 terms of the series tan⁡−1(13)+tan⁡−1(17)+tan⁡−1(113)+tan⁡−1(121)+....\tan^{-1}\left(\dfrac{1}{3}\right) + \tan^{-1}\left(\dfrac{1}{7}\right) + \tan^{-1}\left(\dfrac{1}{13}\right) + \tan^{-1}\left(\dfrac{1}{21}\right) + ....tan−1(31​)+tan−1(71​)+tan−1(131​)+tan−1(211​)+...., then tan(S) is equal to:
  1. (A)56\dfrac{5}{6}65​
  2. (B)1011\dfrac{10}{11}1110​
  3. (C)−65-\dfrac{6}{5}−56​
  4. (D)511\dfrac{5}{11}115​

Correct answer: (A)

Step-by-step solution →
Q51·MathematicsSingle correct
If (a, b, c) is the image of the point (1, 2, –3) in the line, x+12=y−3−2=z−1\dfrac{x+1}{2} = \dfrac{y-3}{-2} = \dfrac{z}{-1}2x+1​=−2y−3​=−1z​, then a + b+ c is equal to
  1. (A)3
  2. (B)1
  3. (C)2
  4. (D)-1

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correct
If y = y (x) is the solution of the differential equation 5+ex2+y.dydx+ex=0\dfrac{5+e^{x}}{2+y}.\dfrac{dy}{dx} + e^{x} = 02+y5+ex​.dxdy​+ex=0 satisfying y(0) = 1, then a value of y(log⁡e13)y(\log_{e} 13)y(loge​13) is:
  1. (A)0
  2. (B)1
  3. (C)-1
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q53·MathematicsSingle correct
If the co-ordinates of two points A and B are (7,0)(\sqrt{7},0)(7​,0) and (−7,0)(-\sqrt{7},0)(−7​,0) respectively and P is any point on the conic 9x2+16y2=1449x^{2}+16y^{2}=1449x2+16y2=144, then PA + PB is equal to:
  1. (A)8
  2. (B)16
  3. (C)9
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q54·MathematicsSingle correct
If the function f(x)={k1(x−π)2−1x≤πk2cos⁡xx>πf(x)=\begin{cases} k_{1}(x-\pi)^{2}-1 & x \le \pi \\ k_{2}\cos x & x > \pi \end{cases}f(x)={k1​(x−π)2−1k2​cosx​x≤πx>π​ is twice differentiable, then the ordered pair (k1,k2)(k_{1},k_{2})(k1​,k2​) is equal to:
  1. (A)(1,0)(1,0)(1,0)
  2. (B)(1,1)(1,1)(1,1)
  3. (C)(12,−1)\left(\dfrac{1}{2},-1\right)(21​,−1)
  4. (D)(12,1)\left(\dfrac{1}{2},1\right)(21​,1)

Correct answer: (D)

Step-by-step solution →
Q55·MathematicsSingle correct
The mean and variance of 7 observations are 8 and 16, respectively. If five observations are 2, 4, 10, 12, 14, then the absolute difference of the remaining two observations is:
  1. (A)2
  2. (B)4
  3. (C)1
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q56·MathematicsSingle correct
If the point P on the curve, 4x2+5y2=204x^{2}+5y^{2}=204x2+5y2=20 is farthest from the point Q(0, –4) then PQ2PQ^{2}PQ2 is equal to:
  1. (A)21
  2. (B)48
  3. (C)36
  4. (D)29

Correct answer: (C)

Step-by-step solution →
Q57·MathematicsSingle correct
If the volume of a parallelepiped, whose coterminus edges are given by the vectors a⃗=i^+j^+nk^,b⃗=2i^+4j^−nk^\vec{a}=\hat{i}+\hat{j}+n\hat{k}, \vec{b}=2\hat{i}+4\hat{j}-n\hat{k}a=i^+j^​+nk^,b=2i^+4j^​−nk^ and c⃗=i^+nj^+3k^\vec{c}=\hat{i}+n\hat{j}+3\hat{k}c=i^+nj^​+3k^ (n≥0)(n \ge 0)(n≥0), is 158 cu.units. then:
  1. (A)a⃗.c⃗=14\vec{a}.\vec{c}=14a.c=14
  2. (B)n=7
  3. (C)b⃗.c⃗=10\vec{b}.\vec{c}=10b.c=10
  4. (D)n=9

Correct answer: (C)

Step-by-step solution →
Q58·MathematicsNumerical
The natural number m, for which the coefficient of x in the binomial expansion of (xm+1x2)22\left(x^{m}+\dfrac{1}{x^{2}}\right)^{22}(xm+x21​)22 is 1540, is ____

Correct answer: 13.00

Step-by-step solution →
Q59·MathematicsNumerical
Let f(x)=x.[x2]f(x)=x.\left[\dfrac{x}{2}\right]f(x)=x.[2x​], for −10<x<10-10<x<10−10<x<10, where [t] denotes the greatest integer function. Then the number of points of discontinuity of f is equal to ___

Correct answer: 08.00

Step-by-step solution →
Q60·MathematicsNumerical
If the line, 2x−y+3=02x-y+3=02x−y+3=0 is at a distance 15\dfrac{1}{\sqrt{5}}5​1​ and 25\dfrac{2}{\sqrt{5}}5​2​ from the lines 4x−2y+α=04x-2y+\alpha=04x−2y+α=0 and 6x−3y+β=06x-3y+\beta=06x−3y+β=0, respectively, then the sum of all possible values of α\alphaα and β\betaβ is ____.

Correct answer: 30.00

Step-by-step solution →
Q61·MathematicsNumerical
Four fair dice are thrown independently 27 times. Then the expected number of times, at least two dice show up a three or a five, a ____.

Correct answer: 11.00

Step-by-step solution →
Q62·MathematicsNumerical
The number of words, with or without meaning, that can be formed by taking 4 letters at a time from the letters of the word ‘SYLLABUS’ such that two letters are distinct and two letters are alike, is ____.

Correct answer: 240.00

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Aldehydes and Ketones 135/186
  • Solutions 158/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Differentiability 91/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Indefinite Integration 66/186
  • Chemistry in Everyday Life 60/186
  • Mathematical Reasoning 26/186
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