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JEE Advanced 2018 Paper 2 Question Paper with Answers

53 questions · Physics, Chemistry & Mathematics

53 of the 54 questions from the JEE Advanced 2018 Paper 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back while we re-check the transcription or the answer key.

Physics
18
Chemistry
18
Mathematics
17

Physics — JEE Advanced 2018 Paper 2

Q1·PhysicsMultiple correct
A particle of mass m is initially at rest at the origin. It is subjected to a force and starts moving along the x-axis. Its kinetic energy K changes with time as dK/dt=γtdK/dt = \gamma tdK/dt=γt, where γ\gammaγ is a positive constant of appropriate dimensions. Which of the following statements is (are) true?
  1. (A)The force applied on the particle is constant
  2. (B)The speed of the particle is proportional to time
  3. (C)The distance of the particle from the origin increases linearly with time
  4. (D)The force is conservative

Correct answer: (A), (B), (D)

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Q2·PhysicsMultiple correct
Consider a thin square plate floating on a viscous liquid in a large tank. The height hhh of the liquid in the tank is much less than the width of the tank. The floating plate is pulled horizontally with a constant velocity u0u_{0}u0​. Which of the following statements is (are) true?
  1. (A)The resistive force of liquid on the plate is inversely proportional to hhh
  2. (B)The resistive force of liquid on the plate is independent of the area of the plate
  3. (C)The tangential (shear) stress on the floor of the tank increases with u0u_{0}u0​
  4. (D)The tangential (shear) stress on the plate varies linearly with the viscosity η\etaη of the liquid

Correct answer: (A), (C), (D)

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Q3·PhysicsMultiple correct
An infinitely long thin non-conducting wire is parallel to the z-axis and carries a uniform line charge density λ\lambdaλ. It pierces a thin non-conducting spherical shell of radius RRR in such a way that the arc PQPQPQ subtends an angle 120∘120^{\circ}120∘ at the centre OOO of the spherical shell, as shown in the figure. The permittivity of free space is ε0\varepsilon_{0}ε0​. Which of the following statements is (are) true?
  1. (A)The electric flux through the shell is 3Rλ/ε0\sqrt{3}R\lambda/\varepsilon_{0}3​Rλ/ε0​
  2. (B)The z-component of the electric field is zero at all the points on the surface of the shell
  3. (C)The electric flux through the shell is 2Rλ/ε0\sqrt{2}R\lambda/\varepsilon_{0}2​Rλ/ε0​
  4. (D)The electric field is normal to the surface of the shell at all points

Correct answer: (A), (B)

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Q4·PhysicsMultiple correct
A wire is bent in the shape of a right angled triangle and is placed in front of a concave mirror of focal length fff, as shown in the figure. Which of the figures shown in the four options qualitatively represent(s) the shape of the image of the bent wire? (These figures are not to scale.)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

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Q5·PhysicsMultiple correct
In a radioactive decay chain, 90232^{232}_{90}90232​Th nucleus decays to 82212^{212}_{82}82212​Pb nucleus. Let NαN_{\alpha}Nα​ and NβN_{\beta}Nβ​ be the number of α\alphaα and β−\beta^{-}β− particles, respectively, emitted in this decay process. Which of the following statements is (are) true?
  1. (A)Nα=5N_{\alpha} = 5Nα​=5
  2. (B)Nα=6N_{\alpha} = 6Nα​=6
  3. (C)Nβ=2N_{\beta} = 2Nβ​=2
  4. (D)Nβ=4N_{\beta} = 4Nβ​=4

Correct answer: (A), (C)

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Q6·PhysicsMultiple correct
In an experiment to measure the speed of sound by a resonating air column, a tuning fork of frequency 500 Hz is used. The length of the air column is varied by changing the level of water in the resonance tube. Two successive resonances are heard at air columns of length 50.7 cm and 83.9 cm. Which of the following statements is (are) true?
  1. (A)The speed of sound determined from this experiment is 332 ms−1^{-1}−1
  2. (B)The end correction in this experiment is 0.9 cm
  3. (C)The wavelength of the sound wave is 66.4 cm
  4. (D)The resonance at 50.7 cm corresponds to the fundamental harmonic

Correct answer: (A), (C)

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Q7·PhysicsNumerical
A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m=0.4m = 0.4m=0.4 kg is at rest on this surface. An impulse of 1.0 Ns is applied to the block at time t = 0 so that it starts moving along the x-axis with a velocity v(t)=v0e−t/τv(t) = v_{0}e^{-t/\tau}v(t)=v0​e−t/τ, where v0v_{0}v0​ is a constant and τ\tauτ = 4 s. The displacement of the block, in meters, at t = τ\tauτ is __________. Take e−1e^{-1}e−1 = 0.37.

Correct answer: 6.30

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Q8·PhysicsNumerical
A ball is projected from the ground at an angle of 45∘45^{\circ}45∘ with the horizontal surface. It reaches a maximum height of 120 mmm and returns to the ground. Upon hitting the ground for the first time, it loses half of its kinetic energy. Immediately after the bounce, the velocity of the ball makes an angle of 30∘30^{\circ}30∘ with the horizontal surface. The maximum height it reaches after the bounce, in metres, is ____________.

Correct answer: 30.00

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Q9·PhysicsNumerical
A particle, of mass 10−310^{-3}10−3 kg and charge 1.0 C, is initially at rest. At time t = 0, the particle comes under the influence of an electric field E⃗(t)=E0sin⁡ωt i^\vec{E}(t) = E_{0}\sin\omega t\,\hat{i}E(t)=E0​sinωti^, where E0=1.0E_{0} = 1.0E0​=1.0 NC−1^{-1}−1 and ω=103\omega = 10^{3}ω=103 rad s−1^{-1}−1. Consider the effect of only the electrical force on the particle. Then the maximum speed, in m s−1^{-1}−1, attained by the particle at subsequent times is ____________.

Correct answer: 2.00

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Q10·PhysicsNumerical
A moving coil galvanometer has 50 turns and each turn has an area 2×10−42 \times 10^{-4}2×10−4 m2^{2}2. The magnetic field produced by the magnet inside the galvanometer is 0.02 T. The torsional constant of the suspension wire is 10−410^{-4}10−4 N m rad−1^{-1}−1. When a current flows through the galvanometer, a full scale deflection occurs if the coil rotates by 0.2 rad. The resistance of the coil of the galvanometer is 50 Ω\OmegaΩ. This galvanometer is to be converted into an ammeter capable of measuring current in the range 0−1.00 - 1.00−1.0 A. For this purpose, a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance, in ohms, is ___________.

Correct answer: 5.56

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Q11·PhysicsNumerical
A steel wire of diameter 0.5 mm and Young's modulus 2×10112 \times 10^{11}2×1011 Nm−2^{-2}−2 carries a load of mass M. The length of the wire with the load is 1.0 m. A vernier scale with 10 divisions is attached to the end of this wire. Next to the steel wire is a reference wire to which a main scale, of least count 1.0 mm, is attached. The 10 divisions of the vernier scale correspond to 9 divisions of the main scale. Initially, the zero of vernier scale coincides with the zero of main scale. If the load on the steel wire is increased by 1.2 kg, the vernier scale division which coincides with a main scale division is ___________. Take g = 10 ms−2^{-2}−2 and is π\piπ = 3.2.

Correct answer: 3.00

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Q12·PhysicsNumerical
One mole of a monatomic ideal gas undergoes an adiabatic expansion in which its volume becomes eight times its initial value. If the initial temperature of the gas is 100 K and the universal gas constant R = 8.0 J mol−1^{-1}−1K−1^{-1}−1, the decrease in its internal energy, in Joule, is___________.

Correct answer: 900.00

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Q13·PhysicsNumerical
In a photoelectric experiment a parallel beam of monochromatic light with power of 200 W is incident on a perfectly absorbing cathode of work function 6.25 eV. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is 100%. A potential difference of 500 V is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a force F=n×10−4F = n \times 10^{-4}F=n×10−4 N due to the impact of the electrons. The value of n is ___________. Mass of the electron me=9×10−31m_{e} = 9 \times 10^{-31}me​=9×10−31 kg and 1.0 eV =1.6×10−19= 1.6 \times 10^{-19}=1.6×10−19 J.

Correct answer: 24.00

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Q14·PhysicsNumerical
Consider a hydrogen-like ionized atom with atomic number Z with a single electron. In the emission spectrum of this atom, the photon emitted in the n = 2 to n = 1 transition has energy 74.8 eV higher than the photon emitted in the n = 3 to n = 2 transition. The ionization energy of the hydrogen atom is 13.6 eV. The value of Z is ___________.

Correct answer: 3.00

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Q15·PhysicsSingle correct
The electric field E is measured at a point P(0, 0, d) generated due to various charge distributions and the dependence of E on d is found to be different for different charge distributions. List-I contains different relations between EEE and d. List-II describes different electric charge distributions, along with their locations. Match the functions in List-I with the related charge distributions in List-II.
LIST-ILIST-II
P.E is independent of d1.A point charge Q at the origin
Q.E∝1dE \propto \dfrac{1}{d}E∝d1​2.A small dipole with point charges Q at (0,0,ℓ)(0, 0, \ell)(0,0,ℓ) and −Q-Q−Q at (0,0,−ℓ)(0, 0, -\ell)(0,0,−ℓ). Take 2ℓ≪d2\ell \ll d2ℓ≪d
R.E∝1d2E \propto \dfrac{1}{d^{2}}E∝d21​3.An infinite line charge coincident with the x-axis, with uniform linear charge density λ\lambdaλ
S.E∝1d3E \propto \dfrac{1}{d^{3}}E∝d31​4.Two infinite wires carrying uniform linear charge density parallel to the x- axis. The one along (y=0,z=ℓ)(y = 0, z = \ell)(y=0,z=ℓ) has a charge density +λ+\lambda+λ and the one along (y=0,z=−ℓ)(y = 0, z = -\ell)(y=0,z=−ℓ) has a charge density −λ-\lambda−λ. Take 2ℓ<<d2\ell << d2ℓ<<d
5.Infinite plane charge coincident with the xy-plane with uniform surface charge density
  1. (A)P →\rightarrow→ 5; Q →\rightarrow→ 3, 4; R →\rightarrow→ 1; S →\rightarrow→ 2
  2. (B)P →\rightarrow→ 5; Q →\rightarrow→ 3; R →\rightarrow→ 1, 4; S →\rightarrow→ 2
  3. (C)P →\rightarrow→ 5; Q →\rightarrow→ 3; R →\rightarrow→ 1, 2; S →\rightarrow→ 4
  4. (D)P →\rightarrow→ 4; Q →\rightarrow→ 2, 3; R →\rightarrow→ 1; S →\rightarrow→ 5

Correct answer: (B)

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Q16·PhysicsSingle correct
A planet of mass M, has two natural satellites with masses m1m_{1}m1​ and m2m_{2}m2​. The radii of their circular orbits are R1R_{1}R1​ and R2R_{2}R2​ respectively. Ignore the gravitational force between the satellites. Define v1v_{1}v1​, L1L_{1}L1​, K1K_{1}K1​ and T1T_{1}T1​ to be, respectively, the orbital speed, angular momentum, kinetic energy and time period of revolution of satellite 1; and v2v_{2}v2​, L2L_{2}L2​, K2K_{2}K2​ and T2T_{2}T2​ to be the corresponding quantities of satellite 2. Given m1/m2=2m_{1}/m_{2} = 2m1​/m2​=2 and R1/R2=1/4R_{1}/R_{2} = 1/4R1​/R2​=1/4, match the ratios in List-I to the numbers in List-II.
LIST-ILIST-II
P.v1v2\dfrac{v_{1}}{v_{2}}v2​v1​​1.18\dfrac{1}{8}81​
Q.L1L2\dfrac{L_{1}}{L_{2}}L2​L1​​2.1
R.K1K2\dfrac{K_{1}}{K_{2}}K2​K1​​3.2
S.T1T2\dfrac{T_{1}}{T_{2}}T2​T1​​4.8
  1. (A)P →\rightarrow→ 4; Q →\rightarrow→ 2; R →\rightarrow→ 1; S →\rightarrow→ 3
  2. (B)P →\rightarrow→ 3; Q →\rightarrow→ 2; R →\rightarrow→ 4; S →\rightarrow→ 1
  3. (C)P →\rightarrow→ 2; Q →\rightarrow→ 3; R →\rightarrow→ 1; S →\rightarrow→ 4
  4. (D)P →\rightarrow→ 2; Q →\rightarrow→ 3; R →\rightarrow→ 4; S →\rightarrow→ 1

Correct answer: (B)

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Q17·PhysicsSingle correct
One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV-diagram below. Among these four processes, one is isobaric, one is isochoric, one is isothermal and one is adiabatic. Match the processes mentioned in List-1 with the corresponding statements in List-II.
LIST-ILIST-II
P.In process I1.Work done by the gas is zero
Q.In process II2.Temperature of the gas remains unchanged
R.In process III3.No heat is exchanged between the gas and its surroundings
S.In process IV4.Work done by the gas is 6P0V06P_{0}V_{0}6P0​V0​
  1. (A)P →\rightarrow→ 4; Q →\rightarrow→ 3; R →\rightarrow→ 1; S →\rightarrow→ 2
  2. (B)P →\rightarrow→ 1; Q →\rightarrow→ 3; R →\rightarrow→ 2; S →\rightarrow→ 4
  3. (C)P →\rightarrow→ 3; Q →\rightarrow→ 4; R →\rightarrow→ 1; S →\rightarrow→ 2
  4. (D)P →\rightarrow→ 3; Q →\rightarrow→ 4; R →\rightarrow→ 2; S →\rightarrow→ 1

Correct answer: (C)

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Q18·PhysicsSingle correct
In the List-I below, four different paths of a particle are given as functions of time. In these functions, α\alphaα and β\betaβ are positive constants of appropriate dimensions and α≠β\alpha \neq \betaα=β. In each case, the force acting on the particle is either zero or conservative. In List-II, five physical quantities of the particle are mentioned: p⃗\vec{p}p​ is the linear momentum, L⃗\vec{L}L is the angular momentum about the origin, K is the kinetic energy, U is the potential energy and E is the total energy. Match each path in List-I with those quantities in List-II, which are conserved for that path.
LIST-ILIST-II
P.r⃗(t)=αt i^+βt j^\vec{r}(t) = \alpha t\,\hat{i} + \beta t\,\hat{j}r(t)=αti^+βtj^​1.p⃗\vec{p}p​
Q.r⃗(t)=αcos⁡ωt i^+βsin⁡ωt j^\vec{r}(t) = \alpha \cos \omega t\,\hat{i} + \beta \sin \omega t\,\hat{j}r(t)=αcosωti^+βsinωtj^​2.L⃗\vec{L}L
R.r⃗(t)=α(cos⁡ωt i^+sin⁡ωt j^)\vec{r}(t) = \alpha(\cos \omega t\,\hat{i} + \sin \omega t\,\hat{j})r(t)=α(cosωti^+sinωtj^​)3.K
S.r⃗(t)=αt i^+β2t2 j^\vec{r}(t) = \alpha t\,\hat{i} + \dfrac{\beta}{2}t^{2}\,\hat{j}r(t)=αti^+2β​t2j^​4.U
5.E
  1. (A)P →\rightarrow→ 1, 2, 3, 4, 5; Q →\rightarrow→ 2, 5; R →\rightarrow→ 2, 3, 4, 5; S →\rightarrow→ 5
  2. (B)P →\rightarrow→ 1, 2, 3, 4, 5; Q →\rightarrow→ 3, 5; R →\rightarrow→ 2, 3, 4, 5; S →\rightarrow→ 2, 5
  3. (C)P →\rightarrow→ 2, 3, 4; Q →\rightarrow→ 5; R →\rightarrow→ 1, 2, 4; S →\rightarrow→ 2, 5
  4. (D)P →\rightarrow→ 1, 2, 3, 5; Q →\rightarrow→ 2, 5; R →\rightarrow→ 2, 3, 4, 5; S →\rightarrow→ 2, 5

Correct answer: (A)

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Chemistry — JEE Advanced 2018 Paper 2

Q19·ChemistryMultiple correct
The correct option(s) regarding the complex [Co(en)(NH3)3(H2O)]3+\left[Co(en)(NH_{3})_{3}(H_{2}O)\right]^{3+}[Co(en)(NH3​)3​(H2​O)]3+ (en = H2NCH2CH2NH2H_{2}NCH_{2}CH_{2}NH_{2}H2​NCH2​CH2​NH2​) is (are)
  1. (A)It has two geometrical isomers
  2. (B)It will have three geometrical isomers if bidentate 'en' is replaced by two cyanide ligands
  3. (C)It is paramagnetic
  4. (D)It absorbs light at longer wavelength as compared to [Co(en)(NH3)4]3+[Co(en)(NH_{3})_{4}]^{3+}[Co(en)(NH3​)4​]3+

Correct answer: (A), (B), (D)

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Q20·ChemistryMultiple correct
The correct option(s) to distinguish nitrate salts of Mn2+Mn^{2+}Mn2+ and Cu2+Cu^{2+}Cu2+ taken separately is (are)
  1. (A)Mn2+Mn^{2+}Mn2+ shows the characteristic green colour in the flame test
  2. (B)Only Cu2+Cu^{2+}Cu2+ shows the formation of precipitate by passing H2SH_{2}SH2​S in acidic medium
  3. (C)Only Mn2+Mn^{2+}Mn2+ shows the formation of precipitate by passing H2SH_{2}SH2​S in faintly basic medium
  4. (D)Cu2+/CuCu^{2+}/CuCu2+/Cu has higher reduction potential than Mn2+/MnMn^{2+}/MnMn2+/Mn (measured under similar conditions)

Correct answer: (B), (D)

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Q21·ChemistryMultiple correct
Aniline reacts with mixed acid (conc. HNO3HNO_{3}HNO3​ and conc. H2SO4H_{2}SO_{4}H2​SO4​) at 288 K to give P (51%), Q (47%) and R(2%). The major product(s) of the following reaction sequence is (are) R →(1) Ac2O, pyridine; (2) Br2, CH3CO2H; (3) H3O+; (4) NaNO2, HCl/273–278 K; (5) EtOH, Δ\xrightarrow{\text{(1) Ac}_{2}\text{O, pyridine; (2) Br}_{2}\text{, CH}_{3}\text{CO}_{2}\text{H; (3) H}_{3}\text{O}^{+}\text{; (4) NaNO}_{2}\text{, HCl/273--278 K; (5) EtOH, }\Delta}(1) Ac2​O, pyridine; (2) Br2​, CH3​CO2​H; (3) H3​O+; (4) NaNO2​, HCl/273–278 K; (5) EtOH, Δ​ S →(1) Sn/HCl; (2) Br2/H2O (excess); (3) NaNO2, HCl/273–278 K; (4) H3PO2\xrightarrow{\text{(1) Sn/HCl; (2) Br}_{2}\text{/H}_{2}\text{O (excess); (3) NaNO}_{2}\text{, HCl/273--278 K; (4) H}_{3}\text{PO}_{2}}(1) Sn/HCl; (2) Br2​/H2​O (excess); (3) NaNO2​, HCl/273–278 K; (4) H3​PO2​​ major product(s)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

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Q22·ChemistryMultiple correct
The Fischer presentation of D-glucose is given below The correct structures(s) of β\betaβ-L-glucopyranose is(are)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

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Q23·ChemistryMultiple correct
For a first order reaction A(g)→2B(g)+C(g)A(g) \rightarrow 2B(g) + C(g)A(g)→2B(g)+C(g) at constant volume and 300 K, the total pressure at the beginning (t = 0) and at time t are P0P_{0}P0​ and PtP_{t}Pt​, respectively. Initially, only A is present with concentration [A]0[A]_{0}[A]0​, and t1/3t_{1/3}t1/3​ is the time required for the partial pressure of A to reach 1/3rd1/3^{rd}1/3rd of its initial value. The correct option(s) is (are) (Assume that all these gases behave as ideal gases)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (D)

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Q24·ChemistryMultiple correct
For a reaction, A⇌PA \rightleftharpoons PA⇌P, the plots of [A] and [P] with time at temperatures T1T_{1}T1​ and T2T_{2}T2​ are given below. If T2>T1T_{2} > T_{1}T2​>T1​, the correct statement(s) is (are) (Assume ΔH⊖\Delta H^{\ominus}ΔH⊖ and ΔS⊖\Delta S^{\ominus}ΔS⊖ are independent of temperature and ratio of ln⁡K\ln KlnK at T1T_{1}T1​ to ln⁡K\ln KlnK at T2T_{2}T2​ is greater than T2/T1T_{2}/T_{1}T2​/T1​. Here HHH, SSS, GGG and KKK are enthalpy, entropy, Gibbs energy and equilibrium constant, respectively.)
  1. (A)ΔH⊖<0,ΔS⊖<0\Delta H^{\ominus} < 0, \Delta S^{\ominus} < 0ΔH⊖<0,ΔS⊖<0
  2. (B)ΔG⊖<0,ΔH⊖>0\Delta G^{\ominus} < 0, \Delta H^{\ominus} > 0ΔG⊖<0,ΔH⊖>0
  3. (C)ΔG⊖<0,ΔS⊖<0\Delta G^{\ominus} < 0, \Delta S^{\ominus} < 0ΔG⊖<0,ΔS⊖<0
  4. (D)ΔG⊖<0,ΔS⊖>0\Delta G^{\ominus} < 0, \Delta S^{\ominus} > 0ΔG⊖<0,ΔS⊖>0

Correct answer: (A), (C)

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Q25·ChemistryNumerical
The total number of compounds having at least one bridging oxo group among the molecules given below is ____. N2O3N_{2}O_{3}N2​O3​, N2O5N_{2}O_{5}N2​O5​, P4O6P_{4}O_{6}P4​O6​, P4O7P_{4}O_{7}P4​O7​, H4P2O5H_{4}P_{2}O_{5}H4​P2​O5​, H5P3O10H_{5}P_{3}O_{10}H5​P3​O10​, H2S2O3H_{2}S_{2}O_{3}H2​S2​O3​, H2S2O5H_{2}S_{2}O_{5}H2​S2​O5​

Correct answer: 6

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Q26·ChemistryNumerical
Galena (an ore) is partially oxidized by passing air through it at high temperature. After some time, the passage of air is stopped, but the heating is continued in a closed furnace such that the contents undergo self-reduction. The weight (in kg) of Pb produced per kg of O2O_{2}O2​ consumed is ____. (Atomic weights in g mol−1mol^{-1}mol−1: O = 16, S = 32, Pb = 207)

Correct answer: 6.47

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Q27·ChemistryNumerical
To measure the quantity of MnCl2MnCl_{2}MnCl2​ dissolved in an aqueous solution, it was completely converted to KMnO4KMnO_{4}KMnO4​ using the reaction, MnCl2+K2S2O8+H2O→KMnO4+H2SO4+HClMnCl_{2} + K_{2}S_{2}O_{8} + H_{2}O \rightarrow KMnO_{4} + H_{2}SO_{4} + HClMnCl2​+K2​S2​O8​+H2​O→KMnO4​+H2​SO4​+HCl (equation not balanced). Few drops of concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) was added in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2MnCl_{2}MnCl2​ (in mg) present in the initial solution is ____. (Atomic weights in g mol−1mol^{-1}mol−1: Mn = 55, Cl = 35.5)

Correct answer: 126

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Q28·ChemistryNumerical
For the given compound X, the total number of optically active stereoisomers is ____ This type of bond indicates that the configuration at the specific carbon and geometry of the double bond is fixed This type of bond indicates that the configuration at the specific carbon and the geometry of the double bond is NOT fixed

Correct answer: 7

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Q29·ChemistryNumerical
In the following reaction sequence, the amount of D (in g) formed from 10 moles of acetophenone is ____. (Atomic weights in g mol−1mol^{-1}mol−1: H = 1, C = 12, N = 14, O = 16, Br = 80. The yield (%) corresponding to the product in each step is given in the parenthesis)

Correct answer: 495

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Q30·ChemistryNumerical
The surface of copper gets tarnished by the formation of copper oxide. N2N_{2}N2​ gas was passed to prevent the oxide formation during heating of copper at 1250 K. However, the N2N_{2}N2​ gas contains 1 mole % of water vapour as impurity. The water vapour oxidises copper as per the reaction given below: 2Cu(s)+H2O(g)→Cu2O(s)+H2(g)2Cu(s) + H_{2}O(g) \rightarrow Cu_{2}O(s) + H_{2}(g)2Cu(s)+H2​O(g)→Cu2​O(s)+H2​(g) pH2p_{H_{2}}pH2​​ is the minimum partial pressure of H2H_{2}H2​ (in bar) needed to prevent the oxidation at 1250 K. The value of ln⁡(pH2)\ln\left(p_{H_{2}}\right)ln(pH2​​) is ____. (Given: total pressure = 1 bar, RRR (universal gas constant) = 8 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1, ln⁡(10)\ln(10)ln(10) = 2.3. Cu(s) and Cu2O(s)Cu_{2}O(s)Cu2​O(s) are mutually immiscible. At 1250 K: 2Cu(s)+12O2(g)→Cu2O(s)2Cu(s) + \frac{1}{2} O_{2}(g) \rightarrow Cu_{2}O(s)2Cu(s)+21​O2​(g)→Cu2​O(s); ΔG⊖=−78,000\Delta G^{\ominus} = -78,000ΔG⊖=−78,000 J mol−1mol^{-1}mol−1 H2(g)+12O2(g)→H2O(g)H_{2}(g) + \frac{1}{2} O_{2}(g) \rightarrow H_{2}O(g)H2​(g)+21​O2​(g)→H2​O(g); ΔG⊖=−1,78,000\Delta G^{\ominus} = -1,78,000ΔG⊖=−1,78,000 J mol−1mol^{-1}mol−1; GGG is the Gibbs energy)

Correct answer: -14.6

Step-by-step solution →
Q31·ChemistryNumerical
Consider the following reversible reaction, A(g)+B(g)⇌AB(g)A(g) + B(g) \rightleftharpoons AB(g)A(g)+B(g)⇌AB(g) The activation energy of the backward reaction exceeds that of the forward reaction by 2RT (in J mol−1mol^{-1}mol−1). If the pre-exponential factor of the forward reaction is 4 times that of the reverse reaction, the absolute value of ΔG⊖\Delta G^{\ominus}ΔG⊖ (in J mol−1mol^{-1}mol−1) for the reaction at 300 K is ____. (Given; ln⁡(2)=0.7\ln(2) = 0.7ln(2)=0.7, RT = 2500 J mol−1mol^{-1}mol−1 at 300 K and GGG is the Gibbs energy)

Correct answer: 8500

Step-by-step solution →
Q32·ChemistryNumerical
Consider an electrochemical cell: A(s)∣An+(aq,2M)∣∣B2n+(aq,1M)∣B(s)A(s) | A^{n+} (aq, 2 M) || B^{2n+} (aq, 1 M) | B(s)A(s)∣An+(aq,2M)∣∣B2n+(aq,1M)∣B(s). The value of ΔH⊖\Delta H^{\ominus}ΔH⊖ for the cell reaction is twice that of ΔG⊖\Delta G^{\ominus}ΔG⊖ at 300 K. If the emf of the cell is zero, the ΔS⊖\Delta S^{\ominus}ΔS⊖ (in J K−1K^{-1}K−1 mol−1mol^{-1}mol−1) of the cell reaction per mole of B formed at 300 K is ____. (Given: ln⁡(2)=0.7\ln(2) = 0.7ln(2)=0.7, R (universal gas constant) = 8.3 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1. HHH, SSS and GGG are enthalpy, entropy and Gibbs energy, respectively.)

Correct answer: -11.62

Step-by-step solution →
Q33·ChemistrySingle correct
Match each set of hybrid orbitals from LIST-I with complex(es) given in LIST-II. The correct option is
LIST-ILIST-II
P.dsp2dsp^{2}dsp21.[FeF6]4−[FeF_{6}]^{4-}[FeF6​]4−
Q.sp3sp^{3}sp32.[Ti(H2O)3Cl3][Ti(H_{2}O)_{3}Cl_{3}][Ti(H2​O)3​Cl3​]
R.sp3d2sp^{3}d^{2}sp3d23.[Cr(NH3)6]3+[Cr(NH_{3})_{6}]^{3+}[Cr(NH3​)6​]3+
S.d2sp3d^{2}sp^{3}d2sp34.[FeCl4]2−[FeCl_{4}]^{2-}[FeCl4​]2−
5.Ni(CO)4Ni(CO)_{4}Ni(CO)4​
6.[Ni(CN)4]2−[Ni(CN)_{4}]^{2-}[Ni(CN)4​]2−
  1. (A)P →\rightarrow→ 5; Q →\rightarrow→ 4,6; R →\rightarrow→ 2,3; S →\rightarrow→ 1
  2. (B)P →\rightarrow→ 5,6; Q →\rightarrow→ 4; R →\rightarrow→ 3; S →\rightarrow→ 1,2
  3. (C)P →\rightarrow→ 6; Q →\rightarrow→ 4,5; R →\rightarrow→ 1; S →\rightarrow→ 2,3
  4. (D)P →\rightarrow→ 4,6; Q →\rightarrow→ 5,6; R →\rightarrow→ 1,2; S →\rightarrow→ 3

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
The desired product X can be prepared by reacting the major product of the reactions in LIST-I with one or more appropriate reagents in LIST-II. (Given, order of migratory aptitude: aryl > alkyl > hydrogen) The correct option is
LIST-ILIST-II
P.see figure1.I2I_{2}I2​, NaOH
Q.see figure2.[Ag(NH3)2]OH[Ag(NH_{3})_{2}]OH[Ag(NH3​)2​]OH
R.see figure3.Fehling solution
S.see figure4.HCHO, NaOH
5.NaOBr
  1. (A)P →\rightarrow→ 1; Q →\rightarrow→ 2,3; R →\rightarrow→ 1,4; S →\rightarrow→ 2,4
  2. (B)P →\rightarrow→ 1,5; Q →\rightarrow→ 3,4; R →\rightarrow→ 4,5; S →\rightarrow→ 3
  3. (C)P →\rightarrow→ 1,5; Q →\rightarrow→ 3,4; R →\rightarrow→ 5; S →\rightarrow→ 2,4
  4. (D)P →\rightarrow→ 1,5; Q →\rightarrow→ 2,3; R →\rightarrow→ 1,5; S →\rightarrow→ 2,3

Correct answer: (D)

Step-by-step solution →
Q35·ChemistrySingle correct
LIST-I contains reactions and LIST-II contains major products. Match each reaction in LIST-I with one or more products in LIST-II and choose the correct option.
LIST-ILIST-II
P.see figure1.see figure
Q.see figure2.see figure
R.see figure3.see figure
S.see figure4.see figure
5.see figure
  1. (A)P →\rightarrow→ 1,5; Q →\rightarrow→ 2; R →\rightarrow→ 3; S →\rightarrow→ 4
  2. (B)P →\rightarrow→ 1,4; Q →\rightarrow→ 2; R →\rightarrow→ 4; S →\rightarrow→ 3
  3. (C)P →\rightarrow→ 1,4; Q →\rightarrow→ 1,2; R →\rightarrow→ 3,4; S →\rightarrow→ 4
  4. (D)P →\rightarrow→ 4,5; Q →\rightarrow→ 4; R →\rightarrow→ 4; S →\rightarrow→ 3,4

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
Dilution processes of different aqueous solutions, with water, are given in LIST-I. The effects of dilution of the solutions on [H+][H^{+}][H+] are given in LIST-II. (Note: Degree of dissociation (α\alphaα) of weak acid and weak base is << 1; degree of hydrolysis of salt <<1; [H+][H^{+}][H+] represents the concentration of H+H^{+}H+ ions) Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is
LIST-ILIST-II
P.(10 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 60 mL1.the value of [H+][H^{+}][H+] does not change on dilution
Q.(20 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 80 mL2.the value of [H+][H^{+}][H+] changes to half of its initial value on dilution
R.(20 mL of 0.1 M HCl + 20 mL of 0.1 M ammonia solution) diluted to 80 mL3.the value of [H+][H^{+}][H+] changes to two times of its initial value on dilution
S.10 mL saturated solution of Ni(OH)2Ni(OH)_{2}Ni(OH)2​ in equilibrium with excess solid Ni(OH)2Ni(OH)_{2}Ni(OH)2​ is diluted to 20 mL (solid Ni(OH)2Ni(OH)_{2}Ni(OH)2​ is still present after dilution).4.the value of [H+][H^{+}][H+] changes to 12\frac{1}{\sqrt{2}}2​1​ times of its initial value on dilution
5.the value of [H+][H^{+}][H+] changes to 2\sqrt{2}2​ times of its initial value on dilution
  1. (A)P →\rightarrow→ 4; Q →\rightarrow→ 2; R →\rightarrow→ 3; S →\rightarrow→ 1
  2. (B)P →\rightarrow→ 4; Q →\rightarrow→ 3; R →\rightarrow→ 2; S →\rightarrow→ 3
  3. (C)P →\rightarrow→ 1; Q →\rightarrow→ 4; R →\rightarrow→ 5; S →\rightarrow→ 3
  4. (D)P →\rightarrow→ 1; Q →\rightarrow→ 5; R →\rightarrow→ 4; S →\rightarrow→ 1

Correct answer: (D)

Step-by-step solution →

Mathematics — JEE Advanced 2018 Paper 2

Q37·MathematicsMultiple correct
Let T be the line passing through the points P(−2-2−2, 7) and Q(2, −5-5−5). Let F1F_{1}F1​ be the set of all pairs of circles (S1S_{1}S1​, S2S_{2}S2​) such that T is tangent to S1S_{1}S1​ at P and tangent to S2S_{2}S2​ at Q, and also such that S1S_{1}S1​ and S2S_{2}S2​ touch each other at a point, say, M. Let E1E_{1}E1​ be the set representing the locus of M as the pair (S1S_{1}S1​, S2S_{2}S2​) varies in F1F_{1}F1​. Let the set of all straight line segments joining a pair of distinct points of E1E_{1}E1​ and passing through the point R(1, 1) be F2F_{2}F2​. Let E2E_{2}E2​ be the set of the mid-points of the line segments in the set F2F_{2}F2​. Then, which of the following statement(s) is (are) TRUE ?
  1. (A)The point (−2,7)(-2, 7)(−2,7) lies in E1E_{1}E1​
  2. (B)The point (45,75)\left(\frac{4}{5}, \frac{7}{5}\right)(54​,57​) does NOT lie in E2E_{2}E2​
  3. (C)The point (12,1)\left(\frac{1}{2}, 1\right)(21​,1) lies in E2E_{2}E2​
  4. (D)The point (0,32)\left(0, \frac{3}{2}\right)(0,23​) does NOT lie in E1E_{1}E1​

Correct answer: (B), (D)

Step-by-step solution →
Q38·MathematicsMultiple correct
Let S be the set of all column matrices [b1b2b3]\begin{bmatrix} b_{1} \\ b_{2} \\ b_{3} \end{bmatrix}​b1​b2​b3​​​ such that b1b_{1}b1​, b2b_{2}b2​, b3∈Rb_{3} \in Rb3​∈R and the system of equations (in real variables) −x+2y+5z=b1-x + 2y + 5z = b_{1}−x+2y+5z=b1​ 2x−4y+3z=b22x - 4y + 3z = b_{2}2x−4y+3z=b2​ x−2y+2z=b3x - 2y + 2z = b_{3}x−2y+2z=b3​ has at least one solution. Then, which of the following system(s) (in real variables) has (have) at least one solution for each [b1b2b3]∈S\begin{bmatrix} b_{1} \\ b_{2} \\ b_{3} \end{bmatrix} \in S​b1​b2​b3​​​∈S ?
  1. (A)x+2y+3z=b1x + 2y + 3z = b_{1}x+2y+3z=b1​, 4y+5z=b24y + 5z = b_{2}4y+5z=b2​ and x+2y+6z=b3x + 2y + 6z = b_{3}x+2y+6z=b3​
  2. (B)x+y+3z=b1x + y + 3z = b_{1}x+y+3z=b1​, 5x+2y+6z=b25x + 2y + 6z = b_{2}5x+2y+6z=b2​ and −2x−y−3z=b3-2x - y - 3z = b_{3}−2x−y−3z=b3​
  3. (C)−x+2y−5z=b1-x + 2y - 5z = b_{1}−x+2y−5z=b1​, 2x−4y+10z=b22x - 4y + 10z = b_{2}2x−4y+10z=b2​ and x−2y+5z=b3x - 2y + 5z = b_{3}x−2y+5z=b3​
  4. (D)x+2y+5z=b1x + 2y + 5z = b_{1}x+2y+5z=b1​, 2x+3z=b22x + 3z = b_{2}2x+3z=b2​ and x+4y−5z=b3x + 4y - 5z = b_{3}x+4y−5z=b3​

Correct answer: (A), (D)

Step-by-step solution →
Q39·MathematicsMultiple correct
Consider two straight lines, each of which is tangent to both the circle x2+y2=12x^{2} + y^{2} = \frac{1}{2}x2+y2=21​ and the parabola y2=4xy^{2} = 4xy2=4x. Let these lines intersect at the point Q. Consider the ellipse whose center is at the origin O(0, 0) and whose semi-major axis is OQ. If the length of the minor axis of this ellipse is 2\sqrt{2}2​, then which of the following statement(s) is (are) TRUE ?
  1. (A)For the ellipse, the eccentricity is 12\frac{1}{\sqrt{2}}2​1​ and the length of the latus rectum is 1
  2. (B)For the ellipse, the eccentricity is 12\frac{1}{2}21​ and the length of the latus rectum is 12\frac{1}{2}21​
  3. (C)The area of the region bounded by the ellipse between the lines x=12x = \frac{1}{\sqrt{2}}x=2​1​ and x=1x = 1x=1 is 142(π−2)\frac{1}{4\sqrt{2}}(\pi - 2)42​1​(π−2)
  4. (D)The area of the region bounded by the ellipse between the lines x=12x = \frac{1}{\sqrt{2}}x=2​1​ and x=1x = 1x=1 is 116(π−2)\frac{1}{16}(\pi - 2)161​(π−2)

Correct answer: (A), (C)

Step-by-step solution →
Q40·MathematicsMultiple correct
Let sss, ttt, rrr be non-zero complex numbers and L be the set of solutions z=x+iyz = x + iyz=x+iy (xxx, y∈Ry \in Ry∈R, i=−1i = \sqrt{-1}i=−1​) of the equation sz+tzˉ+r=0sz + t\bar{z} + r = 0sz+tzˉ+r=0, where zˉ=x−iy\bar{z} = x - iyzˉ=x−iy. Then, which of the following statement(s) is (are) TRUE ?
  1. (A)If L has exactly one element, then ∣s∣≠∣t∣|s| \neq |t|∣s∣=∣t∣
  2. (B)If ∣s∣=∣t∣|s| = |t|∣s∣=∣t∣, then L has infinitely many elements
  3. (C)The number of elements in L∩{z:∣z−1+i∣=5}L \cap \{z : |z - 1 + i| = 5\}L∩{z:∣z−1+i∣=5} is at most 2
  4. (D)If L has more than one element, then L has infinitely many elements

Correct answer: (A), (C), (D)

Step-by-step solution →
Q41·MathematicsMultiple correct
Let f:(0,π)→Rf : (0, \pi) \to Rf:(0,π)→R be a twice differentiable function such that lim⁡t→xf(x)sin⁡t−f(t)sin⁡xt−x=sin⁡2x\lim_{t \to x} \frac{f(x)\sin t - f(t)\sin x}{t - x} = \sin^{2} xlimt→x​t−xf(x)sint−f(t)sinx​=sin2x for all x∈(0,π)x \in (0, \pi)x∈(0,π) If f(π6)=−π12f\left(\frac{\pi}{6}\right) = -\frac{\pi}{12}f(6π​)=−12π​, then which of the following statement(s) is (are) TRUE ?
  1. (A)f(π4)=π42f\left(\frac{\pi}{4}\right) = \frac{\pi}{4\sqrt{2}}f(4π​)=42​π​
  2. (B)f(x)<x46−x2f(x) < \frac{x^{4}}{6} - x^{2}f(x)<6x4​−x2 for all x∈(0,π)x \in (0, \pi)x∈(0,π)
  3. (C)There exists α∈(0,π)\alpha \in (0, \pi)α∈(0,π) such that f′(α)=0f'(\alpha) = 0f′(α)=0
  4. (D)f′′(π2)+f(π2)=0f''\left(\frac{\pi}{2}\right) + f\left(\frac{\pi}{2}\right) = 0f′′(2π​)+f(2π​)=0

Correct answer: (B), (C), (D)

Step-by-step solution →
Q42·MathematicsNumerical
The value of the integral ∫01/21+3((x+1)2(1−x)6)1/4 dx\int_{0}^{1/2} \frac{1+\sqrt{3}}{\left((x+1)^{2}(1-x)^{6}\right)^{1/4}}\, dx∫01/2​((x+1)2(1−x)6)1/41+3​​dx is ______ .

Correct answer: 2

Step-by-step solution →
Q43·MathematicsNumerical
Let P be a matrix of order 3×33 \times 33×3 such that all the entries in P are from the set {−1,0,1}\{-1, 0, 1\}{−1,0,1}. Then, the maximum possible value of the determinant of P is ______ .

Correct answer: 4

Step-by-step solution →
Q44·MathematicsNumerical
Let X be a set with exactly 5 elements and Y be a set with exactly 7 elements. If α\alphaα is the number of one-one functions from X to Y and β\betaβ is the number of onto functions from Y to X, then the value of 15!(β−α)\frac{1}{5!}(\beta - \alpha)5!1​(β−α) is ______ .

Correct answer: 119

Step-by-step solution →
Q45·MathematicsNumerical
Let f:R→Rf : R \to Rf:R→R be a differentiable function with f(0)=0f(0) = 0f(0)=0. If y=f(x)y = f(x)y=f(x) satisfies the differential equation dydx=(2+5y)(5y−2)\frac{dy}{dx} = (2+5y)(5y-2)dxdy​=(2+5y)(5y−2), then the value of lim⁡x→−∞f(x)\lim_{x \to -\infty} f(x)limx→−∞​f(x) is ______ .

Correct answer: 0.4

Step-by-step solution →
Q46·MathematicsNumerical
Let f:R→Rf : R \to Rf:R→R be a differentiable function with f(0)=1f(0) = 1f(0)=1 and satisfying the equation f(x+y)=f(x)f′(y)+f′(x)f(y)f(x + y) = f(x)f'(y) + f'(x)f(y)f(x+y)=f(x)f′(y)+f′(x)f(y) for all xxx, y∈Ry \in Ry∈R. Then, the value of log⁡e(f(4))\log_{e}(f(4))loge​(f(4)) is ______ .

Correct answer: 2

Step-by-step solution →
Q47·MathematicsNumerical
Let P be a point in the first octant, whose image Q in the plane x+y=3x + y = 3x+y=3 (that is, the line segment PQ is perpendicular to the plane x+y=3x + y = 3x+y=3 and the mid-point of PQ lies in the plane x+y=3x + y = 3x+y=3) lies on the z-axis. Let the distance of P from the x-axis be 5. If R is the image of P in the xy-plane, then the length of PR is ______ .

Correct answer: 8

Step-by-step solution →
Q48·MathematicsNumerical
Consider the cube in the first octant with sides OP, OQ and OR of length 1, along the x-axis, y-axis and z-axis, respectively, where O(0, 0, 0) is the origin. Let S(12,12,12)S\left(\frac{1}{2}, \frac{1}{2}, \frac{1}{2}\right)S(21​,21​,21​) be the centre of the cube and T be the vertex of the cube opposite to the origin O such that S lies on the diagonal OT. If p⃗=SP→\vec{p} = \overrightarrow{SP}p​=SP, q⃗=SQ→\vec{q} = \overrightarrow{SQ}q​=SQ​, r⃗=SR→\vec{r} = \overrightarrow{SR}r=SR and t⃗=ST→\vec{t} = \overrightarrow{ST}t=ST, then the value of ∣(p⃗×q⃗)×(r⃗×t⃗)∣\left|(\vec{p} \times \vec{q}) \times (\vec{r} \times \vec{t})\right|​(p​×q​)×(r×t)​ is ______ .

Correct answer: 0.5

Step-by-step solution →
Q49·MathematicsNumerical
Let X=(10C1)2+2(10C2)2+3(10C3)2+....+10(10C10)2X = ({}^{10}C_{1})^{2} + 2({}^{10}C_{2})^{2} + 3({}^{10}C_{3})^{2} + .... + 10({}^{10}C_{10})^{2}X=(10C1​)2+2(10C2​)2+3(10C3​)2+....+10(10C10​)2, where 10Cr{}^{10}C_{r}10Cr​, r∈{1,2,.....,10}r \in \{1, 2, ....., 10\}r∈{1,2,.....,10} denote binomial coefficients. Then the value of 11430X\frac{1}{1430}X14301​X is ______ .

Correct answer: 646

Step-by-step solution →
Q50·MathematicsSingle correct
Let E1={x∈R:x≠1 and xx−1>0}E_{1} = \left\{x \in R : x \neq 1 \text{ and } \frac{x}{x-1} > 0\right\}E1​={x∈R:x=1 and x−1x​>0} and E2={x∈E1:sin⁡−1(log⁡e(xx−1)) is a real number}E_{2} = \left\{x \in E_{1} : \sin^{-1}\left(\log_{e}\left(\frac{x}{x-1}\right)\right) \text{ is a real number}\right\}E2​={x∈E1​:sin−1(loge​(x−1x​)) is a real number} (Here, the inverse trigonometric function sin⁡−1x assumes values in [−π2,π2].)\left(\text{Here, the inverse trigonometric function } \sin^{-1}x \text{ assumes values in } \left[-\frac{\pi}{2}, \frac{\pi}{2}\right].\right)(Here, the inverse trigonometric function sin−1x assumes values in [−2π​,2π​].) Let f:E1→Rf : E_{1} \to Rf:E1​→R be the function defined by f(x)=log⁡e(xx−1)f(x) = \log_{e}\left(\frac{x}{x-1}\right)f(x)=loge​(x−1x​) and g:E2→Rg : E_{2} \to Rg:E2​→R be the function defined by g(x)=sin⁡−1(log⁡e(xx−1))g(x) = \sin^{-1}\left(\log_{e}\left(\frac{x}{x-1}\right)\right)g(x)=sin−1(loge​(x−1x​)). The correct option is :
LIST-ILIST-II
P.The range of fff is1.(−∞,11−e]∪[ee−1,∞)\left(-\infty, \frac{1}{1-e}\right] \cup \left[\frac{e}{e-1}, \infty\right)(−∞,1−e1​]∪[e−1e​,∞)
Q.The range of ggg contains2.(0,1)(0, 1)(0,1)
R.The domain of fff contains3.[−12,12]\left[-\frac{1}{2}, \frac{1}{2}\right][−21​,21​]
S.The domain of ggg is4.(−∞,0)∪(0,∞)(-\infty, 0) \cup (0, \infty)(−∞,0)∪(0,∞)
5.(−∞,ee−1]\left(-\infty, \frac{e}{e-1}\right](−∞,e−1e​]
6.(−∞,0)∪(12,ee−1](-\infty, 0) \cup \left(\frac{1}{2}, \frac{e}{e-1}\right](−∞,0)∪(21​,e−1e​]
  1. (A)P →\to→ 4; Q →\to→ 2; R →\to→ 1; S →\to→ 1
  2. (B)P →\to→ 3; Q →\to→ 3; R →\to→ 6; S →\to→ 5
  3. (C)P →\to→ 4; Q →\to→ 2; R →\to→ 1; S →\to→ 6
  4. (D)P →\to→ 4; Q →\to→ 3; R →\to→ 6; S →\to→ 5

Correct answer: (A)

Step-by-step solution →
Q51·MathematicsSingle correct
In a high school, a committee has to be formed from a group of 6 boys M1M_{1}M1​, M2M_{2}M2​, M3M_{3}M3​, M4M_{4}M4​, M5M_{5}M5​, M6M_{6}M6​ and 5 girls G1G_{1}G1​, G2G_{2}G2​, G3G_{3}G3​, G4G_{4}G4​, G5G_{5}G5​. (i) Let α1\alpha_{1}α1​ be the total number of ways in which the committee can be formed such that the committee has 5 members, having exactly 3 boys and 2 girls. (ii) Let α2\alpha_{2}α2​ be the total number of ways in which the committee can be formed such that the committee has at least 2 members, and having an equal number of boys and girls. (iii) Let α3\alpha_{3}α3​ be the total number of ways in which the committee can be formed such that the committee has 5 members, at least 2 of them being girls. (iv) Let α4\alpha_{4}α4​ be the total number of ways in which the committee can be formed such that the committee has 4 members, having atleast 2 girls and such that both M1M_{1}M1​ and G1G_{1}G1​ are NOT in the committee together. The correct option is :
LIST-ILIST-II
P.The value of α1\alpha_{1}α1​ is1.136
Q.The value of α2\alpha_{2}α2​ is2.189
R.The value of α3\alpha_{3}α3​ is3.192
S.The value of α4\alpha_{4}α4​ is4.200
5.381
6.461
  1. (A)P →\to→ 4; Q →\to→ 6; R →\to→ 2; S →\to→ 1
  2. (B)P →\to→ 1; Q →\to→ 4; R →\to→ 2; S →\to→ 3
  3. (C)P →\to→ 4; Q →\to→ 6; R →\to→ 5; S →\to→ 2
  4. (D)P →\to→ 4; Q →\to→ 2; R →\to→ 3; S →\to→ 1

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correct
Let H : x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1, where a>b>0a > b > 0a>b>0, be a hyperbola in the xy-plane whose conjugate axis LM subtends an angle of 60∘60^{\circ}60∘ at one of its vertices N. Let the area of the triangle LMN be 434\sqrt{3}43​. The correct option is :
LIST-ILIST-II
P.The length of the conjugate axis of H is1.8
Q.The eccentricity of H is2.43\frac{4}{\sqrt{3}}3​4​
R.The distance between the foci of H is3.23\frac{2}{\sqrt{3}}3​2​
S.The length of the latus rectum of H is4.4
  1. (A)P →\to→ 4; Q →\to→ 2; R →\to→ 1; S →\to→ 3
  2. (B)P →\to→ 4; Q →\to→ 3; R →\to→ 1; S →\to→ 2
  3. (C)P →\to→ 4; Q →\to→ 1; R →\to→ 3; S →\to→ 2
  4. (D)P →\to→ 3; Q →\to→ 4; R →\to→ 2; S →\to→ 1

Correct answer: (B)

Step-by-step solution →
Q53·MathematicsSingle correct
Let f1:R→Rf_{1} : R \to Rf1​:R→R, f2:(−π2,π2)→Rf_{2} : \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \to Rf2​:(−2π​,2π​)→R, f3:(−1,eπ/2−2)→Rf_{3} : (-1, e^{\pi/2} - 2) \to Rf3​:(−1,eπ/2−2)→R and f4:R→Rf_{4} : R \to Rf4​:R→R be functions defined by (i) f1(x)=sin⁡(1−e−x2)f_{1}(x) = \sin\left(\sqrt{1 - e^{-x^{2}}}\right)f1​(x)=sin(1−e−x2​), (ii) f2(x)={∣sin⁡x∣tan⁡−1xif x≠01if x=0f_{2}(x) = \begin{cases} \frac{|\sin x|}{\tan^{-1} x} & \text{if } x \neq 0 \\\\ 1 & \text{if } x = 0 \end{cases}f2​(x)=⎩⎨⎧​tan−1x∣sinx∣​1​if x=0if x=0​, where the inverse trigonometric function tan⁡−1x\tan^{-1}xtan−1x assumes values in (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)(−2π​,2π​), (iii) f3(x)=[sin⁡(log⁡e(x+2))]f_{3}(x) = [\sin(\log_{e}(x + 2))]f3​(x)=[sin(loge​(x+2))], where, for t∈Rt \in Rt∈R, [t][t][t] denotes the greatest integer less than or equal to ttt, (iv) f4(x)={x2sin⁡(1x)if x≠00if x=0f_{4}(x) = \begin{cases} x^{2}\sin\left(\frac{1}{x}\right) & \text{if } x \neq 0 \\\\ 0 & \text{if } x = 0 \end{cases}f4​(x)=⎩⎨⎧​x2sin(x1​)0​if x=0if x=0​. The correct option is :
LIST-ILIST-II
P.The function f1f_{1}f1​ is1.NOT continuous at x=0x = 0x=0
Q.The function f2f_{2}f2​ is2.continuous at x=0x = 0x=0 and NOT differentiable at x=0x = 0x=0
R.The function f3f_{3}f3​ is3.differentiable at x=0x = 0x=0 and its derivative is NOT continuous at x=0x = 0x=0
S.The function f4f_{4}f4​ is4.differentiable at x=0x = 0x=0 and its derivative is continuous at x=0x = 0x=0
  1. (A)P →\to→ 2; Q →\to→ 3; R →\to→ 1; S →\to→ 4
  2. (B)P →\to→ 4; Q →\to→ 1; R →\to→ 2; S →\to→ 3
  3. (C)P →\to→ 4; Q →\to→ 2; R →\to→ 1; S →\to→ 3
  4. (D)P →\to→ 2; Q →\to→ 1; R →\to→ 4; S →\to→ 3

Correct answer: (D)

Step-by-step solution →

Chapters tested in this paper

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Permutations and Combinations 162/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Chemical Thermodynamics 165/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Work, Energy and Power 132/186
  • Nuclei 116/186
  • Waves 109/186
  • Atoms 112/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • Hyperbola 77/186
  • Principles of Qualitative Analysis 58/186
  • Isomerism 51/186
  • Reaction Mechanism 29/186
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