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JEE Advanced 2018 Paper 1 Question Paper with Answers

54 questions · Physics, Chemistry & Mathematics

The complete JEE Advanced 2018 Paper 1 paper — every question with its correct answer, tagged to the chapter it tests. Free to read, no account needed.

Physics
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Chemistry
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Mathematics
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Physics — JEE Advanced 2018 Paper 1

Q1·PhysicsMultiple correct
The potential energy of a particle of mass mmm at a distance rrr from a fixed point OOO is given by V(r)=kr2/2V(r) = kr^{2}/2V(r)=kr2/2, where kkk is a positive constant of appropriate dimensions. This particle is moving in a circular orbit of radius RRR about the point OOO. If vvv is the speed of the particle and LLL is the magnitude of its angular momentum about OOO, which of the following statements is (are) true?
  1. (A)v=k2m Rv = \sqrt{\frac{k}{2m}}\,Rv=2mk​​R
  2. (B)v=km Rv = \sqrt{\frac{k}{m}}\,Rv=mk​​R
  3. (C)L=mk R2L = \sqrt{mk}\,R^{2}L=mk​R2
  4. (D)L=mk2 R2L = \sqrt{\frac{mk}{2}}\,R^{2}L=2mk​​R2

Correct answer: (B), (C)

Step-by-step solution →
Q2·PhysicsMultiple correct
Consider a body of mass 1.0 kg1.0\ kg1.0 kg at rest at the origin at time t=0t = 0t=0. A force F⃗=(αt i^+β j^)\vec{F} = \left(\alpha t\,\hat{i} + \beta\,\hat{j}\right)F=(αti^+βj^​) is applied on the body, where α=1.0 Ns−1\alpha = 1.0\,Ns^{-1}α=1.0Ns−1 and β=1.0 N\beta = 1.0\,Nβ=1.0N. The torque acting on the body about the origin at time t=1.0 st = 1.0\ st=1.0 s is τ⃗\vec{\tau}τ. Which of the following statements is (are) true?
  1. (A)∣τ⃗∣=13 Nm\left|\vec{\tau}\right| = \frac{1}{3}\,Nm∣τ∣=31​Nm
  2. (B)The torque τ⃗\vec{\tau}τ is in the direction of the unit vector + k^+\ \hat{k}+ k^
  3. (C)The velocity of the body at t=1st = 1st=1s is v⃗=12(i^+2j^)ms−1\vec{v} = \frac{1}{2}\left(\hat{i} + 2\hat{j}\right)ms^{-1}v=21​(i^+2j^​)ms−1
  4. (D)The magnitude of displacement of the body at t=1 st = 1\ st=1 s is 16 m\frac{1}{6}\,m61​m

Correct answer: (A), (C)

Step-by-step solution →
Q3·PhysicsMultiple correct
A uniform capillary tube of inner radius rrr is dipped vertically into a beaker filled with water. The water rises to a height hhh in the capillary tube above the water surface in the beaker. The surface tension of water is σ\sigmaσ. The angle of contact between water and the wall of the capillary tube is θ\thetaθ. Ignore the mass of water in the meniscus. Which of the following statements is (are) true?
  1. (A)For a given material of the capillary tube, h decreases with increase in rrr
  2. (B)For a given material of the capillary tube, h is independent of σ\sigmaσ
  3. (C)If this experiment is performed in a lift going up with a constant acceleration, then hhh decreases
  4. (D)hhh is proportional to contact angle θ\thetaθ

Correct answer: (A), (C)

Step-by-step solution →
Q4·PhysicsMultiple correct
In the figure below, the switches S1S_{1}S1​ and S2S_{2}S2​ are closed simultaneously at t=0t = 0t=0 and a current starts to flow in the circuit. Both the batteries have the same magnitude of the electromotive force (emf) and the polarities are as indicated in the figure. Ignore mutual inductance between the inductors. The current III in the middle wire reaches its maximum magnitude ImaxI_{max}Imax​ at time t=τt = \taut=τ. Which of the following statements is (are) true?
  1. (A)Imax=V2RI_{max} = \frac{V}{2R}Imax​=2RV​
  2. (B)Imax=V4RI_{max} = \frac{V}{4R}Imax​=4RV​
  3. (C)τ=LRln⁡2\tau = \frac{L}{R}\ln 2τ=RL​ln2
  4. (D)τ=2LRln⁡2\tau = \frac{2L}{R}\ln 2τ=R2L​ln2

Correct answer: (B), (D)

Step-by-step solution →
Q5·PhysicsMultiple correct
Two infinitely long straight wires lie in the xyxyxy-plane along the lines x=±Rx = \pm Rx=±R. The wire located at x=+Rx = +Rx=+R carries a constant current I1I_{1}I1​ and the wire located at x=−Rx = -Rx=−R carries a constant current I2I_{2}I2​. A circular loop of radius RRR is suspended with its centre at (0,0,3R)(0, 0, \sqrt{3}R)(0,0,3​R) and in a plane parallel to the xyxyxy-plane. This loop carries a constant current III in the clockwise direction as seen from above the loop. The current in the wire is taken to be positive if it is in the +j^+\hat{j}+j^​ direction. Which of the following statements regarding the magnetic field B⃗\vec{B}B is (are) true?
  1. (A)If I1=I2I_{1} = I_{2}I1​=I2​, then B⃗\vec{B}B cannot be equal to zero at the origin (0,0,0)(0, 0, 0)(0,0,0)
  2. (B)If I1>0I_{1} > 0I1​>0, and I2<0I_{2} < 0I2​<0, then B⃗\vec{B}B can be equal to zero at the origin (0,0,0)(0, 0, 0)(0,0,0)
  3. (C)If I1<0I_{1} < 0I1​<0, and I2>0I_{2} > 0I2​>0, then B⃗\vec{B}B can be equal to zero at the origin (0,0,0)(0, 0, 0)(0,0,0)
  4. (D)If I1=I2I_{1} = I_{2}I1​=I2​, then the zzz-component of the magnetic field at the centre of the loop is (−μ0I2R)\left(-\frac{\mu_{0}I}{2R}\right)(−2Rμ0​I​)

Correct answer: (A), (B), (D)

Step-by-step solution →
Q6·PhysicsMultiple correct
One mole of a monatomic ideal gas undergoes a cyclic process as shown in the figure (where VVV is the volume and TTT is the temperature). Which of the statements below is (are) true?
  1. (A)Process I is an isochoric process
  2. (B)In process II, gas absorbs heat
  3. (C)In process IV, gas releases heat
  4. (D)Processes I and III are not isobaric

Correct answer: (B), (C), (D)

Step-by-step solution →
Q7·PhysicsNumerical
Two vectors A⃗\vec{A}A and B⃗\vec{B}B are defined as A⃗=ai^\vec{A} = a\hat{i}A=ai^ and B⃗=a(cos⁡ωt i^+sin⁡ωt j^)\vec{B} = a\left(\cos\omega t\,\hat{i} + \sin\omega t\,\hat{j}\right)B=a(cosωti^+sinωtj^​), where aaa is a constant and ω=π/6 rad s−1\omega = \pi/6\ rad\ s^{-1}ω=π/6 rad s−1. If ∣A⃗+B⃗∣=3∣A⃗−B⃗∣\left|\vec{A} + \vec{B}\right| = \sqrt{3}\left|\vec{A} - \vec{B}\right|​A+B​=3​​A−B​ at time t=τt = \taut=τ for the first time, the value of τ\tauτ, in seconds, is ______.

Correct answer: 2.00

Step-by-step solution →
Q8·PhysicsNumerical
Two men are walking along a horizontal straight line in the same direction. The man in front walks at a speed 1.0 ms−11.0\ ms^{-1}1.0 ms−1 and the man behind walks at a speed 2.0 ms−12.0\ ms^{-1}2.0 ms−1. A third man is standing at a height 12 m12\ m12 m above the same horizontal line such that all three men are in a vertical plane. The two walking men are blowing identical whistles which emit a sound of frequency 1430 Hz1430\ Hz1430 Hz. The speed of sound in air is 330 ms−1330\ ms^{-1}330 ms−1. At the instant, when the moving men are 10 m10\ m10 m apart, the stationary man is equidistant from them. The frequency of beats in HzHzHz, heard by the stationary man at this instant, is __________.

Correct answer: 5.00

Step-by-step solution →
Q9·PhysicsNumerical
A ring and a disc are initially at rest, side by side, at the top of an inclined plane which makes an angle 60∘60^{\circ}60∘ with the horizontal. They start to roll without slipping at the same instant of time along the shortest path. If the time difference between their reaching the ground is (2−3)/10 s(2 - \sqrt{3})/\sqrt{10}\ s(2−3​)/10​ s, then the height of the top of the inclined plane, in metres, is __________. Take g=10 ms−2g = 10\ ms^{-2}g=10 ms−2.

Correct answer: 0.75

Step-by-step solution →
Q10·PhysicsNumerical
A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 N m−12.0\ N\,m^{-1}2.0 Nm−1 and the mass of the block is 2.0 kg2.0\ kg2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition. Another block of mass 1.0 kg1.0\ kg1.0 kg moving with a speed of 2.0 m s−12.0\ m\ s^{-1}2.0 m s−1 collides elastically with the first block. The collision is such that the 2.0 kg2.0\ kg2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time is __________.

Correct answer: 2.09

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Q11·PhysicsNumerical
Three identical capacitors C1C_{1}C1​, C2C_{2}C2​ and C3C_{3}C3​ have a capacitance of 1.0 μF1.0\ \mu F1.0 μF each and they are uncharged initially. They are connected in a circuit as shown in the figure and C1C_{1}C1​ is then filled completely with a dielectric material of relative permittivity ∈r\in_{r}∈r​. The cell electromotive force (emf) V0=8VV_{0} = 8VV0​=8V. First the switch S1S_{1}S1​ is closed while the switch S2S_{2}S2​ is kept open. When the capacitor C3C_{3}C3​ is fully charged, S1S_{1}S1​ is opened and S2S_{2}S2​ is closed simultaneously. When all the capacitors reach equilibrium, the charge on C3C_{3}C3​ is found to be 5μC5\mu C5μC. The value of ∈r=\in_{r} = ∈r​=__________.

Correct answer: 1.50

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Q12·PhysicsNumerical
In the xyxyxy-plane, the region y>0y > 0y>0 has a uniform magnetic field B1k^B_{1}\hat{k}B1​k^ and the region y<0y < 0y<0 has another uniform magnetic field B2k^B_{2}\hat{k}B2​k^. A positively charged particle is projected from the origin along the positive yyy-axis with speed v0=π m s−1v_{0} = \pi\ m\ s^{-1}v0​=π m s−1 at t=0t = 0t=0, as shown in the figure. Neglect gravity in this problem. Let t=Tt = Tt=T be the time when the particle crosses the xxx-axis from below for the first time. If B2=4B1B_{2} = 4B_{1}B2​=4B1​, the average speed of the particle, in ms−1ms^{-1}ms−1, along the xxx-axis in the time interval TTT is __________.

Correct answer: 2.00

Step-by-step solution →
Q13·PhysicsNumerical
Sunlight of intensity 1.3 kWm−21.3\ \mathrm{kWm}^{-2}1.3 kWm−2 is incident normally on a thin convex lens of focal length 20 cm20\ cm20 cm. Ignore the energy loss of light due to the lens and assume that the lens aperture size is much smaller than its focal length. The average intensity of light, in kW m−2kW\ m^{-2}kW m−2, at a distance 22 cm22\ cm22 cm from the lens on the other side is __________.

Correct answer: 130.00

Step-by-step solution →
Q14·PhysicsNumerical
Two conducting cylinders of equal length but different radii are connected in series between two heat baths kept at temperatures T1=300 KT_{1} = 300\ KT1​=300 K and T2=100 KT_{2} = 100\ KT2​=100 K, as shown in the figure. The radius of the bigger cylinder is twice that of the smaller one and the thermal conductivities of the materials of the smaller and the larger cylinders are K1K_{1}K1​ and K2K_{2}K2​ respectively. If the temperature at the junction of the two cylinders in the steady state is 200 K200\ K200 K, then K1/K2=K_{1}/K_{2} = K1​/K2​=__________.

Correct answer: 4.00

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Q15·PhysicsSingle correct
PARAGRAPH "X" In electromagnetic theory, the electric and magnetic phenomena are related to each other. Therefore, the dimensions of electric and magnetic quantities must also be related to each other. In the questions below, [E][E][E] and [B][B][B] stand for dimensions of electric and magnetic fields respectively, while [∈0][\in_{0}][∈0​] and [μ0][\mu_{0}][μ0​] stand for dimensions of the permittivity and permeability of free space respectively. [L][L][L] and [T][T][T] are dimensions of length and time respectively. All the quantities are given in SI units. (There are two questions based on PARAGRAPH "X", the question given below is one of them) The relation between [E][E][E] and [B][B][B] is
  1. (A)[E]=[B] [L] [T][E] = [B]\,[L]\,[T][E]=[B][L][T]
  2. (B)[E]=[B] [L]−1 [T][E] = [B]\,[L]^{-1}\,[T][E]=[B][L]−1[T]
  3. (C)[E]=[B] [L] [T]−1[E] = [B]\,[L]\,[T]^{-1}[E]=[B][L][T]−1
  4. (D)[E]=[B] [L]−1 [T]−1[E] = [B]\,[L]^{-1}\,[T]^{-1}[E]=[B][L]−1[T]−1

Correct answer: (C)

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Q16·PhysicsSingle correct
PARAGRAPH "X" In electromagnetic theory, the electric and magnetic phenomena are related to each other. Therefore, the dimensions of electric and magnetic quantities must also be related to each other. In the questions below, [E][E][E] and [B][B][B] stand for dimensions of electric and magnetic fields respectively, while [∈0][\in_{0}][∈0​] and [μ0][\mu_{0}][μ0​] stand for dimensions of the permittivity and permeability of free space respectively. [L][L][L] and [T][T][T] are dimensions of length and time respectively. All the quantities are given in SI units. (There are two questions based on PARAGRAPH "X", the question given below is one of them) The relation between [∈0][\in_{0}][∈0​] and [μ0][\mu_{0}][μ0​] is
  1. (A)[μ0]=[∈0] [L]2 [T]−2[\mu_{0}] = [\in_{0}]\,[L]^{2}\,[T]^{-2}[μ0​]=[∈0​][L]2[T]−2
  2. (B)[μ0]=[∈0] [L]−2 [T]2[\mu_{0}] = [\in_{0}]\,[L]^{-2}\,[T]^{2}[μ0​]=[∈0​][L]−2[T]2
  3. (C)[μ0]=[∈0]−1 [L]2 [T]−2[\mu_{0}] = [\in_{0}]^{-1}\,[L]^{2}\,[T]^{-2}[μ0​]=[∈0​]−1[L]2[T]−2
  4. (D)[μ0]=[∈0]−1 [L]−2 [T]2[\mu_{0}] = [\in_{0}]^{-1}\,[L]^{-2}\,[T]^{2}[μ0​]=[∈0​]−1[L]−2[T]2

Correct answer: (D)

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Q17·PhysicsSingle correct
PARAGRAPH "A" If the measurement errors in all the independent quantities are known, then it is possible to determine the error in any dependent quantity. This is done by the use of series expansion and truncating the expansion at the first power of the error. For example, consider the relation z=x/yz = x/yz=x/y. If the errors in x,yx, yx,y and zzz are Δx\Delta xΔx, Δy\Delta yΔy and Δz\Delta zΔz, respectively, then z±Δz=x±Δxy±Δy=xy(1±Δxx)(1±Δyy)−1.z \pm \Delta z = \frac{x \pm \Delta x}{y \pm \Delta y} = \frac{x}{y}\left(1 \pm \frac{\Delta x}{x}\right)\left(1 \pm \frac{\Delta y}{y}\right)^{-1}.z±Δz=y±Δyx±Δx​=yx​(1±xΔx​)(1±yΔy​)−1. The series expansion for (1±Δyy)−1\left(1 \pm \frac{\Delta y}{y}\right)^{-1}(1±yΔy​)−1, to first power in Δy/y\Delta y/yΔy/y, is 1∓(Δy/y)1 \mp (\Delta y/y)1∓(Δy/y). The relative errors in independent variables are always added. So the error in zzz will be Δz=z(Δxx+Δyy).\Delta z = z\left(\frac{\Delta x}{x} + \frac{\Delta y}{y}\right).Δz=z(xΔx​+yΔy​). The above derivation makes the assumption that Δx/x≪1\Delta x/x \ll 1Δx/x≪1, Δy/y≪1\Delta y/y \ll 1Δy/y≪1. Therefore, the higher powers of these quantities are neglected. (There are two questions based on PARAGRAPH "A", the question given below is one of them) Consider the ratio r=(1−a)(1+a)r = \frac{(1 - a)}{(1 + a)}r=(1+a)(1−a)​ to be determined by measuring a dimensionless quantity aaa. If the error in the measurement of aaa is Δa\Delta aΔa (Δa/a≪1)(\Delta a/a \ll 1)(Δa/a≪1), then what is the error Δr\Delta rΔr in determining rrr ?
  1. (A)Δa(1+a)2\frac{\Delta a}{(1 + a)^{2}}(1+a)2Δa​
  2. (B)2Δa(1+a)2\frac{2\Delta a}{(1 + a)^{2}}(1+a)22Δa​
  3. (C)2Δa(1−a2)\frac{2\Delta a}{(1 - a^{2})}(1−a2)2Δa​
  4. (D)2aΔa(1−a2)\frac{2a\Delta a}{(1 - a^{2})}(1−a2)2aΔa​

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
PARAGRAPH "A" If the measurement errors in all the independent quantities are known, then it is possible to determine the error in any dependent quantity. This is done by the use of series expansion and truncating the expansion at the first power of the error. For example, consider the relation z=x/yz = x/yz=x/y. If the errors in x,yx, yx,y and zzz are Δx\Delta xΔx, Δy\Delta yΔy and Δz\Delta zΔz, respectively, then z±Δz=x±Δxy±Δy=xy(1±Δxx)(1±Δyy)−1.z \pm \Delta z = \frac{x \pm \Delta x}{y \pm \Delta y} = \frac{x}{y}\left(1 \pm \frac{\Delta x}{x}\right)\left(1 \pm \frac{\Delta y}{y}\right)^{-1}.z±Δz=y±Δyx±Δx​=yx​(1±xΔx​)(1±yΔy​)−1. The series expansion for (1±Δyy)−1\left(1 \pm \frac{\Delta y}{y}\right)^{-1}(1±yΔy​)−1, to first power in Δy/y\Delta y/yΔy/y, is 1∓(Δy/y)1 \mp (\Delta y/y)1∓(Δy/y). The relative errors in independent variables are always added. So the error in zzz will be Δz=z(Δxx+Δyy).\Delta z = z\left(\frac{\Delta x}{x} + \frac{\Delta y}{y}\right).Δz=z(xΔx​+yΔy​). The above derivation makes the assumption that Δx/x≪1\Delta x/x \ll 1Δx/x≪1, Δy/y≪1\Delta y/y \ll 1Δy/y≪1. Therefore, the higher powers of these quantities are neglected. (There are two questions based on PARAGRAPH "A", the question given below is one of them) In an experiment the initial number of radioactive nuclei is 3000. It is found that 1000±401000 \pm 401000±40 nuclei decayed in the first 1.0s1.0s1.0s. For ∣x∣≪1|x| \ll 1∣x∣≪1, ln⁡(1+x)=x\ln(1 + x) = xln(1+x)=x up to first power in xxx. The error Δλ\Delta\lambdaΔλ, in the determination of the decay constant λ\lambdaλ, in s−1s^{-1}s−1, is
  1. (A)0.04
  2. (B)0.03
  3. (C)0.02
  4. (D)0.01

Correct answer: (C)

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Chemistry — JEE Advanced 2018 Paper 1

Q19·ChemistryMultiple correct
The compound(s) which generate(s) N2N_{2}N2​ gas upon thermal decomposition below 300°C is (are)
  1. (A)NH4NO3NH_{4}NO_{3}NH4​NO3​
  2. (B)(NH4)2Cr2O7(NH_{4})_{2}Cr_{2}O_{7}(NH4​)2​Cr2​O7​
  3. (C)Ba(N3)2Ba(N_{3})_{2}Ba(N3​)2​
  4. (D)Mg3N2Mg_{3}N_{2}Mg3​N2​

Correct answer: (B), (C)

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Q20·ChemistryMultiple correct
The correct statement(s) regarding the binary transition metal carbonyl compounds is (are) (Atomic numbers: Fe = 26, Ni = 28)
  1. (A)Total number of valence shell electrons at metal centre in Fe(CO)5Fe(CO)_{5}Fe(CO)5​ or Ni(CO)4Ni(CO)_{4}Ni(CO)4​ is 16
  2. (B)These are predominantly low spin in nature
  3. (C)Metal–carbon bond strengthens when the oxidation state of the metal is lowered
  4. (D)The carbonyl C−O bond weakens when the oxidation state of the metal is increased

Correct answer: (B), (C)

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Q21·ChemistryMultiple correct
Based on the compounds of group 15 elements, the correct statement(s) is (are)
  1. (A)Bi2O5Bi_{2}O_{5}Bi2​O5​ is more basic than N2O5N_{2}O_{5}N2​O5​
  2. (B)NF3NF_{3}NF3​ is more covalent than BiF3BiF_{3}BiF3​
  3. (C)PH3PH_{3}PH3​ boils at lower temperature than NH3NH_{3}NH3​
  4. (D)The N−N single bond is stronger than the P−P single bond

Correct answer: (A), (B), (C)

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Q22·ChemistryMultiple correct
In the following reaction sequence, the correct structure(s) of X is (are)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q23·ChemistryMultiple correct
The reaction(s) leading to the formation of 1,3,5-trimethylbenzene is(are)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (B), (D)

Step-by-step solution →
Q24·ChemistryMultiple correct
A reversible cyclic process for an ideal gas is shown below. Here, PPP, VVV, and TTT are pressure, volume and temperature, respectively. The thermodynamic parameters qqq, www, HHH and UUU are heat, work, enthalpy and internal energy, respectively. The correct option(s) is (are)
  1. (A)qAC=ΔUBCq_{AC} = \Delta U_{BC}qAC​=ΔUBC​ and wAB=P2(V2−V1)w_{AB} = P_{2}(V_{2}-V_{1})wAB​=P2​(V2​−V1​)
  2. (B)wBC=P2(V2−V1)w_{BC} = P_{2}(V_{2}-V_{1})wBC​=P2​(V2​−V1​) and qBC=ΔHACq_{BC} = \Delta H_{AC}qBC​=ΔHAC​
  3. (C)ΔHCA<ΔUCA\Delta H_{CA} < \Delta U_{CA}ΔHCA​<ΔUCA​ and qAC=ΔUBCq_{AC} = \Delta U_{BC}qAC​=ΔUBC​
  4. (D)qBC=ΔHACq_{BC} = \Delta H_{AC}qBC​=ΔHAC​ and ΔHCA>ΔUCA\Delta H_{CA} > \Delta U_{CA}ΔHCA​>ΔUCA​

Correct answer: (B), (C)

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Q25·ChemistryNumerical
Among the species given below, the total number of diamagnetic species is ___. H atom, NO2NO_{2}NO2​ monomer, O2−O_{2}^{-}O2−​ (superoxide), dimeric sulphur in vapour phase, Mn3O4Mn_{3}O_{4}Mn3​O4​, (NH4)2[FeCl4](NH_{4})_{2}[FeCl_{4}](NH4​)2​[FeCl4​], (NH4)2[NiCl4](NH_{4})_{2}[NiCl_{4}](NH4​)2​[NiCl4​], K2MnO4K_{2}MnO_{4}K2​MnO4​, K2CrO4K_{2}CrO_{4}K2​CrO4​

Correct answer: 1

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Q26·ChemistryNumerical
The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by NiCl2.6H2ONiCl_{2}.6H_{2}ONiCl2​.6H2​O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2ONiCl_{2}.6H_{2}ONiCl2​.6H2​O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ___. (Atomic weights in g mol−1mol^{-1}mol−1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)

Correct answer: 2992

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Q27·ChemistryNumerical
Consider an ionic solid MX with NaCl structure. Construct a new structure (Z) whose unit cell is constructed from the unit cell of MX following the sequential instructions given below. Neglect the charge balance. (i) Remove all the anions (X) except the central one (ii) Replace all the face centered cations (M) by anions (X) (iii) Remove all the corner cations (M) (iv) Replace the central anion (X) with cation (M) The value of (number of anionsnumber of cations)\left(\dfrac{\text{number of anions}}{\text{number of cations}}\right)(number of cationsnumber of anions​) in Z is ___.

Correct answer: 3

Step-by-step solution →
Q28·ChemistryNumerical
For the electrochemical cell, Mg(s)∣Mg2+(aq,1 M)∥Cu2+(aq,1 M)∣Cu(s)Mg(s) \mid Mg^{2+} (aq, 1\ M) \parallel Cu^{2+} (aq, 1\ M) \mid Cu(s)Mg(s)∣Mg2+(aq,1 M)∥Cu2+(aq,1 M)∣Cu(s) the standard emf of the cell is 2.70 V at 300 K. When the concentration of Mg2+Mg^{2+}Mg2+ is changed to xxx M, the cell potential changes to 2.67 V at 300 K. The value of xxx is ___. (given, FR=11500\dfrac{F}{R} = 11500RF​=11500 K V−1V^{-1}V−1, where FFF is the Faraday constant and RRR is the gas constant, ln⁡(10)=2.30\ln(10) = 2.30ln(10)=2.30)

Correct answer: 10

Step-by-step solution →
Q29·ChemistryNumerical
A closed tank has two compartments A and B, both filled with oxygen (assumed to be ideal gas). The partition separating the two compartments is fixed and is a perfect heat insulator (Figure 1). If the old partition is replaced by a new partition which can slide and conduct heat but does NOT allow the gas to leak across (Figure 2), the volume (in m3m^{3}m3) of the compartment A after the system attains equilibrium is ___.

Correct answer: 2.22

Step-by-step solution →
Q30·ChemistryNumerical
Liquids A and B form ideal solution over the entire range of composition. At temperature T, equimolar binary solution of liquids A and B has vapour pressure 45 Torr. At the same temperature, a new solution of A and B having mole fractions xAx_{A}xA​ and xBx_{B}xB​, respectively, has vapour pressure of 22.5 Torr. The value of xA/xBx_{A}/x_{B}xA​/xB​ in the new solution is ___. (given that the vapour pressure of pure liquid A is 20 Torr at temperature T)

Correct answer: 19

Step-by-step solution →
Q31·ChemistryNumerical
The solubility of a salt of weak acid (AB) at pH 3 is Y×10−3Y \times 10^{-3}Y×10−3 mol L−1L^{-1}L−1. The value of Y is ___. (Given that the value of solubility product of AB (KspK_{sp}Ksp​) =2×10−10= 2 \times 10^{-10}=2×10−10 and the value of ionization constant of HB (KaK_{a}Ka​) =1×10−8= 1 \times 10^{-8}=1×10−8)

Correct answer: 4.47

Step-by-step solution →
Q32·ChemistryNumerical
The plot given below shows P—T curves (where PPP is the pressure and TTT is the temperature) for two solvents X and Y and isomolal solutions of NaCl in these solvents. NaCl completely dissociates in both the solvents. On addition of equal number of moles of a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is ___.

Correct answer: 0.05

Step-by-step solution →
Q33·ChemistrySingle correct
PARAGRAPH "X" Treatment of benzene with CO/HCl in the presence of anhydrous AlCl3AlCl_{3}AlCl3​/CuCl followed by reaction with Ac2OAc_{2}OAc2​O/NaOAc gives compound X as the major product. Compound X upon reaction with Br2Br_{2}Br2​/Na2CO3Na_{2}CO_{3}Na2​CO3​, followed by heating at 473 K with moist KOH furnishes Y as the major product. Reaction of X with H2H_{2}H2​/Pd-C, followed by H3PO4H_{3}PO_{4}H3​PO4​ treatment gives Z as the major product. (There are two questions based on PARAGRAPH "X", the question given below is one of them) The compound Y is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
PARAGRAPH "X" Treatment of benzene with CO/HCl in the presence of anhydrous AlCl3AlCl_{3}AlCl3​/CuCl followed by reaction with Ac2OAc_{2}OAc2​O/NaOAc gives compound X as the major product. Compound X upon reaction with Br2Br_{2}Br2​/Na2CO3Na_{2}CO_{3}Na2​CO3​, followed by heating at 473 K with moist KOH furnishes Y as the major product. Reaction of X with H2H_{2}H2​/Pd-C, followed by H3PO4H_{3}PO_{4}H3​PO4​ treatment gives Z as the major product. (There are two questions based on PARAGRAPH "X", the question given below is one of them) The compound Z is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
PARAGRAPH "A" An organic acid P (C11H12O2C_{11}H_{12}O_{2}C11​H12​O2​) can easily be oxidized to a dibasic acid which reacts with ethylene glycol to produce a polymer dacron. Upon ozonolysis, P gives an aliphatic ketone as one of the products. P undergoes the following reaction sequences to furnish R via Q. The compound P also undergoes another set of reactions to produce S. S ←\xleftarrow{}​ [1) H2H_{2}H2​/Pd−C, 2) NH3NH_{3}NH3​/Δ\DeltaΔ, 3) Br2Br_{2}Br2​/NaOH, 4) CHCl3CHCl_{3}CHCl3​, KOH, Δ\DeltaΔ, 5) H2H_{2}H2​/Pd−C] P →\xrightarrow{}​ [1) H2H_{2}H2​/Pd−C, 2) SOCl2SOCl_{2}SOCl2​, 3) MeMgBr, CdCl2CdCl_{2}CdCl2​, 4) NaBH4NaBH_{4}NaBH4​] Q →\xrightarrow{}​ [1) HCl, 2) Mg/Et2OEt_{2}OEt2​O, 3) CO2CO_{2}CO2​ (dry ice), 4) H3O+H_{3}O^{+}H3​O+] R (There are two questions based on PARAGRAH 'A', the question given below is one of them) The compound R is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
PARAGRAPH "A" An organic acid P (C11H12O2C_{11}H_{12}O_{2}C11​H12​O2​) can easily be oxidized to a dibasic acid which reacts with ethylene glycol to produce a polymer dacron. Upon ozonolysis, P gives an aliphatic ketone as one of the products. P undergoes the following reaction sequences to furnish R via Q. The compound P also undergoes another set of reactions to produce S. S ←\xleftarrow{}​ [1) H2H_{2}H2​/Pd−C, 2) NH3NH_{3}NH3​/Δ\DeltaΔ, 3) Br2Br_{2}Br2​/NaOH, 4) CHCl3CHCl_{3}CHCl3​, KOH, Δ\DeltaΔ, 5) H2H_{2}H2​/Pd−C] P →\xrightarrow{}​ [1) H2H_{2}H2​/Pd−C, 2) SOCl2SOCl_{2}SOCl2​, 3) MeMgBr, CdCl2CdCl_{2}CdCl2​, 4) NaBH4NaBH_{4}NaBH4​] Q →\xrightarrow{}​ [1) HCl, 2) Mg/Et2OEt_{2}OEt2​O, 3) CO2CO_{2}CO2​ (dry ice), 4) H3O+H_{3}O^{+}H3​O+] R (There are two questions based on PARAGRAPH "A", the question given below is one of them) The compound S is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →

Mathematics — JEE Advanced 2018 Paper 1

Q37·MathematicsMultiple correct
For a non-zero complex number z, let arg(z) denote the principal argument with −π<arg⁡(z)≤π-\pi < \arg(z) \le \pi−π<arg(z)≤π. Then, which of the following statement(s) is (are) FALSE ?
  1. (A)arg⁡(−1−i)=π4\arg(-1-i) = \frac{\pi}{4}arg(−1−i)=4π​, where i=−1i = \sqrt{-1}i=−1​
  2. (B)The function f:R→(−π,π]f : R \to (-\pi, \pi]f:R→(−π,π], defined by f(t)=arg⁡(−1+it)f(t) = \arg(-1+it)f(t)=arg(−1+it) for all t∈Rt \in Rt∈R, is continuous at all points of R, where i=−1i = \sqrt{-1}i=−1​
  3. (C)For any two non-zero complex numbers z1z_{1}z1​ and z2z_{2}z2​, arg⁡(z1z2)−arg⁡(z1)+arg⁡(z2)\arg\left(\frac{z_{1}}{z_{2}}\right) - \arg(z_{1}) + \arg(z_{2})arg(z2​z1​​)−arg(z1​)+arg(z2​) is an integer multiple of 2π2\pi2π
  4. (D)For any three given distinct complex numbers z1z_{1}z1​, z2z_{2}z2​ and z3z_{3}z3​, the locus of the point z satisfying the condition arg⁡((z−z1)(z2−z3)(z−z3)(z2−z1))=π\arg\left(\frac{(z-z_{1})(z_{2}-z_{3})}{(z-z_{3})(z_{2}-z_{1})}\right) = \piarg((z−z3​)(z2​−z1​)(z−z1​)(z2​−z3​)​)=π, lies on a straight line

Correct answer: (A), (B), (D)

Step-by-step solution →
Q38·MathematicsMultiple correct
In a triangle PQR, let ∠PQR=30∘\angle PQR = 30^{\circ}∠PQR=30∘ and the sides PQ and QR have lengths 10310\sqrt{3}103​ and 10, respectively. Then, which of the following statement(s) is (are) TRUE ?
  1. (A)∠QPR=45∘\angle QPR = 45^{\circ}∠QPR=45∘
  2. (B)The area of the triangle PQR is 25325\sqrt{3}253​ and ∠QRP=120∘\angle QRP = 120^{\circ}∠QRP=120∘
  3. (C)The radius of the incircle of the triangle PQR is 103−1510\sqrt{3} - 15103​−15
  4. (D)The area of the circumcircle of the triangle PQR is 100π100\pi100π

Correct answer: (B), (C), (D)

Step-by-step solution →
Q39·MathematicsMultiple correct
Let P1:2x+y−z=3P_{1} : 2x + y - z = 3P1​:2x+y−z=3 and P2:x+2y+z=2P_{2} : x + 2y + z = 2P2​:x+2y+z=2 be two planes. Then, which of the following statement(s) is (are) TRUE ?
  1. (A)The line of intersection of P1P_{1}P1​ and P2P_{2}P2​ has direction ratios 1, 2, −1-1−1
  2. (B)The line 3x−49=1−3y9=z3\frac{3x-4}{9} = \frac{1-3y}{9} = \frac{z}{3}93x−4​=91−3y​=3z​ is perpendicular to the line of intersection of P1P_{1}P1​ and P2P_{2}P2​
  3. (C)The acute angle between P1P_{1}P1​ and P2P_{2}P2​ is 60∘60^{\circ}60∘
  4. (D)If P3P_{3}P3​ is the plane passing through the point (4,2,−2)(4, 2, -2)(4,2,−2) and perpendicular to the line of intersection of P1P_{1}P1​ and P2P_{2}P2​, then the distance of the point (2,1,1)(2, 1, 1)(2,1,1) from the plane P3P_{3}P3​ is 23\frac{2}{\sqrt{3}}3​2​

Correct answer: (C), (D)

Step-by-step solution →
Q40·MathematicsMultiple correct
For every twice differentiable function f:R→[−2,2]f : R \to [-2, 2]f:R→[−2,2] with (f(0))2+(f′(0))2=85(f(0))^{2} + (f'(0))^{2} = 85(f(0))2+(f′(0))2=85, which of the following statement(s) is (are) TRUE ?
  1. (A)There exist r, s ∈\in∈ R, where r<sr < sr<s, such that f is one-one on the open interval (r, s)
  2. (B)There exists x0∈(−4,0)x_{0} \in (-4, 0)x0​∈(−4,0) such that ∣f′(x0)∣≤1|f'(x_{0})| \le 1∣f′(x0​)∣≤1
  3. (C)lim⁡x→∞f(x)=1\lim_{x \to \infty} f(x) = 1limx→∞​f(x)=1
  4. (D)There exist α∈(−4,4)\alpha \in (-4, 4)α∈(−4,4) such that f(α)+f′′(α)=0f(\alpha) + f''(\alpha) = 0f(α)+f′′(α)=0 and f′(α)≠0f'(\alpha) \ne 0f′(α)=0

Correct answer: (A), (B), (D)

Step-by-step solution →
Q41·MathematicsMultiple correct
Let f:R→Rf : R \to Rf:R→R and g:R→Rg : R \to Rg:R→R be two non-constant differentiable functions. If f′(x)=(e(f(x)−g(x)))g′(x)f'(x) = \left(e^{(f(x)-g(x))}\right) g'(x)f′(x)=(e(f(x)−g(x)))g′(x) for all x∈Rx \in Rx∈R, and f(1)=g(2)=1f(1) = g(2) = 1f(1)=g(2)=1, then which of the following statement(s) is (are) TRUE ?
  1. (A)f(2)<1−log⁡e2f(2) < 1 - \log_{e} 2f(2)<1−loge​2
  2. (B)f(2)>1−log⁡e2f(2) > 1 - \log_{e} 2f(2)>1−loge​2
  3. (C)g(1)>1−log⁡e2g(1) > 1 - \log_{e} 2g(1)>1−loge​2
  4. (D)g(1)<1−log⁡e2g(1) < 1 - \log_{e} 2g(1)<1−loge​2

Correct answer: (B), (C)

Step-by-step solution →
Q42·MathematicsMultiple correct
Let f:[0,∞)→Rf : [0, \infty) \to Rf:[0,∞)→R be a continuous function such that f(x)=1−2x+∫0xex−tf(t)dtf(x) = 1 - 2x + \int_{0}^{x} e^{x-t} f(t) dtf(x)=1−2x+∫0x​ex−tf(t)dt for all x∈[0,∞)x \in [0, \infty)x∈[0,∞). Then, which of the following statement(s) is (are) TRUE ?
  1. (A)The curve y=f(x)y = f(x)y=f(x) passes through the point (1,2)(1, 2)(1,2)
  2. (B)The curve y=f(x)y = f(x)y=f(x) passes through the point (2,−1)(2, -1)(2,−1)
  3. (C)The area of the region {(x,y)∈[0,1]×R:f(x)≤y≤1−x2}\{(x, y) \in [0, 1] \times R : f(x) \le y \le \sqrt{1-x^{2}}\}{(x,y)∈[0,1]×R:f(x)≤y≤1−x2​} is π−24\frac{\pi-2}{4}4π−2​
  4. (D)The area of the region {(x,y)∈[0,1]×R:f(x)≤y≤1−x2}\{(x, y) \in [0, 1] \times R : f(x) \le y \le \sqrt{1-x^{2}}\}{(x,y)∈[0,1]×R:f(x)≤y≤1−x2​} is π−14\frac{\pi-1}{4}4π−1​

Correct answer: (B), (C)

Step-by-step solution →
Q43·MathematicsNumerical
The value of ((log⁡29)2)1log⁡2(log⁡29)×(7)1log⁡47\left(\left(\log_{2} 9\right)^{2}\right)^{\frac{1}{\log_{2}\left(\log_{2} 9\right)}} \times \left(\sqrt{7}\right)^{\frac{1}{\log_{4} 7}}((log2​9)2)log2​(log2​9)1​×(7​)log4​71​ is ______ .

Correct answer: 8

Step-by-step solution →
Q44·MathematicsNumerical
The number of 5 digit numbers which are divisible by 4, with digits from the set {1,2,3,4,5}\{1, 2, 3, 4, 5\}{1,2,3,4,5} and the repetition of digits is allowed, is ______ .

Correct answer: 625

Step-by-step solution →
Q45·MathematicsNumerical
Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ….. , and Y be the set consisting of the first 2018 terms of arithmetic progression 9, 16, 23, ….. . Then, the number of elements in the set X∪YX \cup YX∪Y is ______ .

Correct answer: 3748

Step-by-step solution →
Q46·MathematicsNumerical
The number of real solutions of the equation sin⁡−1(∑i=1∞xi+1−x∑i=1∞(x2)i)=π2−cos⁡−1(∑i=1∞(−x2)i−∑i=1∞(−x)i)\sin^{-1}\left(\sum_{i=1}^{\infty} x^{i+1} - x \sum_{i=1}^{\infty}\left(\frac{x}{2}\right)^{i}\right) = \frac{\pi}{2} - \cos^{-1}\left(\sum_{i=1}^{\infty}\left(-\frac{x}{2}\right)^{i} - \sum_{i=1}^{\infty}(-x)^{i}\right)sin−1(∑i=1∞​xi+1−x∑i=1∞​(2x​)i)=2π​−cos−1(∑i=1∞​(−2x​)i−∑i=1∞​(−x)i) lying in the interval (−12,12)\left(-\frac{1}{2}, \frac{1}{2}\right)(−21​,21​) is ______ . (Here, the inverse trigonometric functions sin⁡−1x\sin^{-1}xsin−1x and cos⁡−1x\cos^{-1}xcos−1x assume values in [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right][−2π​,2π​] and [0,π][0, \pi][0,π], respectively.)

Correct answer: 2

Step-by-step solution →
Q47·MathematicsNumerical
For each positive integer n, let yn=1n((n+1)(n+2)....(n+n))1/ny_{n} = \frac{1}{n}\left((n+1)(n+2)....(n+n)\right)^{1/n}yn​=n1​((n+1)(n+2)....(n+n))1/n. For x∈Rx \in Rx∈R, let [x] be the greatest integer less than or equal to x. If lim⁡n→∞yn=L\lim_{n \to \infty} y_{n} = Llimn→∞​yn​=L, then the value of [L] is ______ .

Correct answer: 1

Step-by-step solution →
Q48·MathematicsNumerical
Let a⃗\vec{a}a and b⃗\vec{b}b be two unit vectors such that a⃗⋅b⃗=0\vec{a} \cdot \vec{b} = 0a⋅b=0. For some x, y ∈\in∈ R, let c⃗=xa⃗+yb⃗+(a⃗×b⃗)\vec{c} = x\vec{a} + y\vec{b} + \left(\vec{a} \times \vec{b}\right)c=xa+yb+(a×b). If ∣c⃗∣=2|\vec{c}| = 2∣c∣=2 and the vector c⃗\vec{c}c is inclined at the same angle α\alphaα to both a⃗\vec{a}a and b⃗\vec{b}b, then the value of 8cos⁡2α8\cos^{2}\alpha8cos2α is ______ .

Correct answer: 3

Step-by-step solution →
Q49·MathematicsNumerical
Let a, b, c be three non-zero real numbers such that the equation 3acos⁡x+2bsin⁡x=c\sqrt{3}a \cos x + 2b \sin x = c3​acosx+2bsinx=c, x∈[−π2,π2]x \in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]x∈[−2π​,2π​], has two distinct real roots α\alphaα and β\betaβ with α+β=π3\alpha + \beta = \frac{\pi}{3}α+β=3π​. Then, the value of ba\frac{b}{a}ab​ is ______ .

Correct answer: 0.5

Step-by-step solution →
Q50·MathematicsNumerical
A farmer F1F_{1}F1​ has a land in the shape of a triangle with vertices at P(0,0)P(0, 0)P(0,0), Q(1,1)Q(1, 1)Q(1,1) and R(2,0)R(2, 0)R(2,0). From this land, a neighbouring farmer F2F_{2}F2​ takes away the region which lies between the side PQ and a curve of the form y=xny = x^{n}y=xn (n>1)(n > 1)(n>1). If the area of the region taken away by the farmer F2F_{2}F2​ is exactly 30% of the area of Δ\DeltaΔPQR, then the value of n is ______ .

Correct answer: 4

Step-by-step solution →
Q51·MathematicsSingle correct
PARAGRAPH "X" Let S be the circle in the x-y plane defined by the equation x2+y2=4x^{2} + y^{2} = 4x2+y2=4. (There are two questions based on PARAGRAPH "X", the question given below is one of them) Let E1E2E_{1}E_{2}E1​E2​ and F1F2F_{1}F_{2}F1​F2​ be the chords of S passing through the point P0(1,1)P_{0}(1, 1)P0​(1,1) and parallel to the x-axis and the y-axis, respectively. Let G1G2G_{1}G_{2}G1​G2​ be the chord of S passing through P0P_{0}P0​ and having slope −1-1−1. Let the tangents to S at E1E_{1}E1​ and E2E_{2}E2​ meet at E3E_{3}E3​, the tangents to S at F1F_{1}F1​ and F2F_{2}F2​ meet at F3F_{3}F3​, and the tangents to S at G1G_{1}G1​ and G2G_{2}G2​ meet at G3G_{3}G3​. Then, the points E3E_{3}E3​, F3F_{3}F3​, and G3G_{3}G3​ lie on the curve
  1. (A)x+y=4x + y = 4x+y=4
  2. (B)(x−4)2+(y−4)2=16(x-4)^{2} + (y-4)^{2} = 16(x−4)2+(y−4)2=16
  3. (C)(x−4)(y−4)=4(x-4)(y-4) = 4(x−4)(y−4)=4
  4. (D)xy=4xy = 4xy=4

Correct answer: (A)

Step-by-step solution →
Q52·MathematicsSingle correct
PARAGRAPH "X" Let S be the circle in the x-y plane defined by the equation x2+y2=4x^{2} + y^{2} = 4x2+y2=4. (There are two questions based on PARAGRAPH "X", the question given below is one of them) Let P be a point on the circle S with both coordinates being positive. Let the tangent to S at P intersect the coordinate axes at the points M and N. Then, the mid-point of the line segment MN must lie on the curve
  1. (A)(x+y)2=3xy(x+y)^{2} = 3xy(x+y)2=3xy
  2. (B)x2/3+y2/3=24/3x^{2/3} + y^{2/3} = 2^{4/3}x2/3+y2/3=24/3
  3. (C)x2+y2=2xyx^{2} + y^{2} = 2xyx2+y2=2xy
  4. (D)x2+y2=x2y2x^{2} + y^{2} = x^{2}y^{2}x2+y2=x2y2

Correct answer: (D)

Step-by-step solution →
Q53·MathematicsSingle correct
PARAGRAPH "A" There are five students S1S_{1}S1​, S2S_{2}S2​, S3S_{3}S3​, S4S_{4}S4​ and S5S_{5}S5​ in a music class and for them there are five seats R1R_{1}R1​, R2R_{2}R2​, R3R_{3}R3​, R4R_{4}R4​ and R5R_{5}R5​ arranged in a row, where initially the seat RiR_{i}Ri​ is allotted to the student SiS_{i}Si​, i=1,2,3,4,5i = 1, 2, 3, 4, 5i=1,2,3,4,5. But, on the examination day, the five students are randomly allotted the five seats. (There are two questions based on PARAGRAPH "A", the question given below is one of them) The probability that, on the examination day, the student S1S_{1}S1​ gets the previously allotted seat R1R_{1}R1​, and NONE of the remaining students gets the seat previously allotted to him/her is
  1. (A)340\frac{3}{40}403​
  2. (B)18\frac{1}{8}81​
  3. (C)740\frac{7}{40}407​
  4. (D)15\frac{1}{5}51​

Correct answer: (A)

Step-by-step solution →
Q54·MathematicsSingle correct
PARAGRAPH "A" There are five students S1S_{1}S1​, S2S_{2}S2​, S3S_{3}S3​, S4S_{4}S4​ and S5S_{5}S5​ in a music class and for them there are five seats R1R_{1}R1​, R2R_{2}R2​, R3R_{3}R3​, R4R_{4}R4​ and R5R_{5}R5​ arranged in a row, where initially the seat RiR_{i}Ri​ is allotted to the student SiS_{i}Si​, i=1,2,3,4,5i = 1, 2, 3, 4, 5i=1,2,3,4,5. But, on the examination day, the five students are randomly allotted the five seats. (There are two questions based on PARAGRAPH "A", the question given below is one of them) For i=1,2,3,4i = 1, 2, 3, 4i=1,2,3,4, let TiT_{i}Ti​ denote the event that the students SiS_{i}Si​ and Si+1S_{i+1}Si+1​ do NOT sit adjacent to each other on the day of the examination. Then, the probability of the event T1∩T2∩T3∩T4T_{1} \cap T_{2} \cap T_{3} \cap T_{4}T1​∩T2​∩T3​∩T4​ is
  1. (A)115\frac{1}{15}151​
  2. (B)110\frac{1}{10}101​
  3. (C)760\frac{7}{60}607​
  4. (D)15\frac{1}{5}51​

Correct answer: (C)

Step-by-step solution →

Chapters tested in this paper

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Circles 142/186
  • Amines 133/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Oscillations 117/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Inverse Trigonometric Functions 93/186
  • Carboxylic Acids and Derivatives 54/186
  • Solid State 63/186
  • States of Matter: Gases and Liquids 52/186
  • Reaction Mechanism 29/186
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