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JEE Advanced 2021 Paper 1 Question Paper with Answers

57 questions · Physics, Chemistry & Mathematics

The complete JEE Advanced 2021 Paper 1 paper — every question with its correct answer, tagged to the chapter it tests. Free to read, no account needed.

Physics
19
Chemistry
19
Mathematics
19

Physics — JEE Advanced 2021 Paper 1

Q1·PhysicsSingle correct
The smallest division on the main scale of a Vernier calipers is 0.1 cm. Ten divisions of the Vernier scale correspond to nine divisions of the main scale. The figure below on the left shows the reading of this calipers with no gap between its two jaws. The figure on the right shows the reading with a solid sphere held between the jaws. The correct diameter of the sphere is
  1. (A)3.07 cm
  2. (B)3.11 cm
  3. (C)3.15 cm
  4. (D)3.17 cm

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
An ideal gas undergoes a four step cycle as shown in the P−VP - VP−V diagram below. During this cycle, heat is absorbed by the gas in
  1. (A)steps 1 and 2
  2. (B)steps 1 and 3
  3. (C)steps 1 and 4
  4. (D)steps 2 and 4

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
An extended object is placed at point O, 10 cm in front of a convex lens L1L_1L1​ and a concave lens L2L_2L2​ is placed 10 cm behind it, as shown in the figure. The radii of curvature of all the curved surfaces in both the lenses are 20 cm. The refractive index of both the lenses is 1.5. The total magnification of this lens system is
  1. (A)0.4
  2. (B)0.8
  3. (C)1.3
  4. (D)1.6

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A heavy nucleus Q of half-life 20 minutes undergoes alpha-decay with probability of 60% and beta-decay with probability of 40%. Initially, the number of Q nuclei is 1000. The number of alpha-decays of Q in the first one hour is
  1. (A)50
  2. (B)75
  3. (C)350
  4. (D)525

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsNumerical
A projectile is thrown from a point O on the ground at an angle 45∘45^\circ45∘ from the vertical and with a speed 525\sqrt{2}52​ m/s. The projectile at the highest point of its trajectory splits into two equal parts. One part falls vertically down to the ground, 0.5 s after the splitting. The other part, t seconds after the splitting, falls to the ground at a distance x meters from the point O. The acceleration due to gravity g=10 m/s2g = 10\,\mathrm{m/s^2}g=10m/s2. The value of t is ______ .

Correct answer: 0.50

Step-by-step solution →
Q6·PhysicsNumerical
A projectile is thrown from a point O on the ground at an angle 45∘45^\circ45∘ from the vertical and with a speed 525\sqrt{2}52​ m/s. The projectile at the highest point of its trajectory splits into two equal parts. One part falls vertically down to the ground, 0.5 s after the splitting. The other part, t seconds after the splitting, falls to the ground at a distance x meters from the point O. The acceleration due to gravity g=10 m/s2g = 10\,\mathrm{m/s^2}g=10m/s2. The value of x is ______ .

Correct answer: 7.50

Step-by-step solution →
Q7·PhysicsNumerical
In the circuit shown below, the switch S is connected to position P for a long time so that the charge on the capacitor becomes q1 μCq_1\,\mu\mathrm{C}q1​μC. Then S is switched to position Q. After a long time, the charge on the capacitor is q2 μCq_2\,\mu\mathrm{C}q2​μC. The magnitude of q1q_1q1​ is ______ .

Correct answer: 1.33

Step-by-step solution →
Q8·PhysicsNumerical
In the circuit shown below, the switch S is connected to position P for a long time so that the charge on the capacitor becomes q1 μCq_1\,\mu\mathrm{C}q1​μC. Then S is switched to position Q. After a long time, the charge on the capacitor is q2 μCq_2\,\mu\mathrm{C}q2​μC. The magnitude of q2q_2q2​ is ______ .

Correct answer: 0.67

Step-by-step solution →
Q9·PhysicsNumerical
Two point charges −Q-Q−Q and +Q/3+Q/\sqrt{3}+Q/3​ are placed in the xy-plane at the origin (0, 0) and a point (2, 0), respectively, as shown in the figure. This results in an equipotential circle of radius RRR and potential V = 0 in the xy-plane with its center at (b,0)(b, 0)(b,0). All lengths are measured in meters. The value of RRR is ______ meter.

Correct answer: 1.73

Step-by-step solution →
Q10·PhysicsNumerical
Two point charges −Q-Q−Q and +Q/3+Q/\sqrt{3}+Q/3​ are placed in the xy-plane at the origin (0, 0) and a point (2, 0), respectively, as shown in the figure. This results in an equipotential circle of radius RRR and potential V = 0 in the xy-plane with its center at (b,0)(b, 0)(b,0). All lengths are measured in meters. The value of bbb is ______ meter.

Correct answer: 3.00

Step-by-step solution →
Q11·PhysicsMultiple correct
A horizontal force FFF is applied at the center of mass of a cylindrical object of mass m and radius RRR, perpendicular to its axis as shown in the figure. The coefficient of friction between the object and the ground is μ\muμ. The center of mass of the object has an acceleration aaa. The acceleration due to gravity is ggg. Given that the object rolls without slipping, which of the following statement(s) is(are) correct?
  1. (A)For the same FFF, the value of aaa does not depend on whether the cylinder is solid or hollow
  2. (B)For a solid cylinder, the maximum possible value of aaa is 2μg2\mu g2μg
  3. (C)The magnitude of the frictional force on the object due to the ground is always μmg\mu mgμmg
  4. (D)For a thin-walled hollow cylinder, a=F2ma = \frac{F}{2m}a=2mF​

Correct answer: (B), (D)

Step-by-step solution →
Q12·PhysicsMultiple correct
A wide slab consisting of two media of refractive indices n1n_1n1​ and n2n_2n2​ is placed in air as shown in the figure. A ray of light is incident from medium n1n_1n1​ to n2n_2n2​ at an angle θ\thetaθ, where sin⁡θ\sin\thetasinθ is slightly larger than 1/n11/n_11/n1​. Take refractive index of air as 1. Which of the following statement(s) is(are) correct?
  1. (A)The light ray enters air if n2=n1n_2 = n_1n2​=n1​
  2. (B)The light ray is finally reflected back into the medium of refractive index n1n_1n1​ if n2<n1n_2 < n_1n2​<n1​
  3. (C)The light ray is finally reflected back into the medium of refractive index n1n_1n1​ if n2>n1n_2 > n_1n2​>n1​
  4. (D)The light ray is reflected back into the medium of refractive index n1n_1n1​ if n2=1n_2 = 1n2​=1

Correct answer: (B), (C), (D)

Step-by-step solution →
Q13·PhysicsMultiple correct
A particle of mass MMM = 0.2 kg is initially at rest in the xyxyxy-plane at a point (x = −l-l−l, y = −h-h−h), where lll = 10 m and hhh = 1m. The particle is accelerated at time t = 0 with a constant acceleration a = 10 m/s2^22 along the positive x-direction. Its angular momentum and torque with respect to the origin, in SI units, are represented by L⃗\vec{L}L and τ⃗\vec{\tau}τ, respectively. i^,j^\hat{i}, \hat{j}i^,j^​ and k^\hat{k}k^ are unit vectors along the positive x, y and z-directions, respectively. If k^=i^×j^\hat{k} = \hat{i} \times \hat{j}k^=i^×j^​ then which of the following statement(s) is(are) correct ?
  1. (A)The particle arrives at the point (x=lx = lx=l, y=−hy = -hy=−h) at time t = 2s.
  2. (B)τ⃗=2k^\vec{\tau} = 2\hat{k}τ=2k^ when the particle passes through the point (x=lx = lx=l, y=−hy = -hy=−h)
  3. (C)L⃗=4k^\vec{L} = 4\hat{k}L=4k^ when the particle passes through the point (x=lx = lx=l, y=−hy = -hy=−h)
  4. (D)τ⃗=k^\vec{\tau} = \hat{k}τ=k^ when the particle passes through the point (x=0x = 0x=0, y=−hy = -hy=−h)

Correct answer: (A), (B), (C)

Step-by-step solution →
Q14·PhysicsMultiple correct
Which of the following statement(s) is(are) correct about the spectrum of hydrogen atom ?
  1. (A)The ratio of the longest wavelength to the shortest wavelength in Balmer series is 9/5
  2. (B)There is an overlap between the wavelength ranges of Balmer and Paschen series.
  3. (C)The wavelengths of Lyman series are given by (1+1m2)λ0\left(1 + \frac{1}{m^2}\right)\lambda_0(1+m21​)λ0​ , where λ0\lambda_0λ0​ is the shortest wavelength of Lyman series and m is an integer
  4. (D)The wavelength ranges of Lyman and Balmer series do not overlap

Correct answer: (A), (D)

Step-by-step solution →
Q15·PhysicsMultiple correct
A long straight wire carries a current, III = 2 ampere. A semi-circular conducting rod is placed beside it on two conducting parallel rails of negligible resistance. Both the rails are parallel to the wire. The wire, the rod and the rails lie in the same horizontal plane, as shown in the figure. Two ends of the semi-circular rod are at distances 1cm and 4 cm from the wire. At time t = 0, the rod starts moving on the rails with a speed v = 3.0 m/s (see the figure). A resistor R = 1.4 Ω\OmegaΩ and a capacitor C0C_0C0​ = 5.0 μ\muμF are connected in series between the rails. At time t = 0, C0C_0C0​ is uncharged. Which of the following statement(s) is(are) correct ? [μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7}μ0​=4π×10−7 SI units. Take ln 2 = 0.7]
  1. (A)Maximum current through RRR is 1.2×10−61.2 \times 10^{-6}1.2×10−6 ampere
  2. (B)Maximum current through RRR is 3.8×10−63.8 \times 10^{-6}3.8×10−6 ampere
  3. (C)Maximum charge on capacitor C0C_0C0​ is 8.4×10−128.4 \times 10^{-12}8.4×10−12 coulomb
  4. (D)Maximum charge on capacitor C0C_0C0​ is 2.4×10−122.4 \times 10^{-12}2.4×10−12 coulomb

Correct answer: (A), (C)

Step-by-step solution →
Q16·PhysicsMultiple correct
A cylindrical tube, with its base as shown in the figure, is filled with water. It is moving down with a constant acceleration aaa along a fixed inclined plane with angle θ=45∘\theta = 45^\circθ=45∘. P1P_1P1​ and P2P_2P2​ are pressures at points 1 and 2, respectively, located at the base of the tube. Let β=(P1−P2)/(ρgd)\beta = (P_1 - P_2)/(\rho g d)β=(P1​−P2​)/(ρgd), where ρ\rhoρ is density of water, ddd is the inner diameter of the tube and g is the acceleration due to gravity. Which of the following statement(s) is(are) correct ?
  1. (A)β=0\beta = 0β=0 when a=g/2a = g/\sqrt{2}a=g/2​
  2. (B)β>0\beta > 0β>0 when a=g/2a = g/\sqrt{2}a=g/2​
  3. (C)β=2−12\beta = \frac{\sqrt{2}-1}{\sqrt{2}}β=2​2​−1​ when a=g/2a = g/2a=g/2
  4. (D)β=12\beta = \frac{1}{\sqrt{2}}β=2​1​ when a=g/2a = g/2a=g/2

Correct answer: (A), (C)

Step-by-step solution →
Q17·PhysicsInteger
An α\alphaα-particle (mass 4 amu) and a singly charged sulfur ion (mass 32 amu) are initially at rest. They are accelerated through a potential V and then allowed to pass into a region of uniform magnetic field which is normal to the velocities of the particles. Within this region, the α\alphaα-particle and the sulfur ion move in circular orbits of radii rαr_\alpharα​ and rsr_srs​, respectively. The ratio (rs/rα)(r_s/r_\alpha)(rs​/rα​) is____.

Correct answer: 4

Step-by-step solution →
Q18·PhysicsInteger
A thin rod of mass M and length aaa is free to rotate in horizontal plane about a fixed vertical axis passing through point O. A thin circular disc of mass M and of radius a/4a/4a/4 is pivoted on this rod with its center at a distance a/4a/4a/4 from the free end so that it can rotate freely about its vertical axis, as shown in the figure. Assume that both the rod and the disc have uniform density and they remain horizontal during the motion. An outside stationary observer finds the rod rotating with an angular velocity Ω\OmegaΩ and the disc rotating about its vertical axis with angular velocity 4Ω4\Omega4Ω. The total angular momentum of the system about the point O is (Ma2Ω48)n\left(\frac{Ma^2\Omega}{48}\right)n(48Ma2Ω​)n . The value of n is____.

Correct answer: 49

Step-by-step solution →
Q19·PhysicsInteger
A small object is placed at the center of a large evacuated hollow spherical container. Assume that the container is maintained at 0 K. At time t = 0, the temperature of the object is 200 K. The temperature of the object becomes 100 K at t = t1t_1t1​ and 50 K at t = t2t_2t2​. Assume the object and the container to be ideal black bodies. The heat capacity of the object does not depend on temperature. The ratio (t2/t1)(t_2/t_1)(t2​/t1​) is_____.

Correct answer: 9

Step-by-step solution →

Chemistry — JEE Advanced 2021 Paper 1

Q20·ChemistrySingle correct
The major product formed in the following reaction is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q21·ChemistrySingle correct
Among the following, the conformation that corresponds to the most stable conformation of meso–butane–2,3–diol is –
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q22·ChemistrySingle correct
For the given close packed structure of a salt made of cation X\mathbf{X}X and anion Y\mathbf{Y}Y shown below (ions of only one face are shown for clarity) , the packing fraction is approximately (packing fraction = Packing efficiency100\frac{\text{Packing efficiency}}{100}100Packing efficiency​)
  1. (A)0.74
  2. (B)0.63
  3. (C)0.52
  4. (D)0.48

Correct answer: (B)

Step-by-step solution →
Q23·ChemistrySingle correct
The calculated spin only magnetic moments of [Cr(NH3)6]3+[\mathrm{Cr(NH_3)_6}]^{3+}[Cr(NH3​)6​]3+ and [CuF6]3−[\mathrm{CuF_6}]^{3-}[CuF6​]3− in BM, respectively, are (Atomic numbers of Cr and Cu are 24 and 29, respectively)
  1. (A)3.87 and 2.84
  2. (B)4.90 and 1.73
  3. (C)3.87 and 1.73
  4. (D)4.90 and 2.84

Correct answer: (A)

Step-by-step solution →
Q24·ChemistryNumerical
For the following reaction scheme, percentage yields are given along the arrow : x\mathbf{x}x g and y\mathbf{y}y g are mass of R\mathbf{R}R and U\mathbf{U}U, respectively. (Use : Molar mass (in g mol−1^{-1}−1) of H, C and O as 1, 12 and 16, respectively) The value of x\mathbf{x}x is______.

Correct answer: 1.62

Step-by-step solution →
Q25·ChemistryNumerical
For the following reaction scheme, percentage yields are given along the arrow : x\mathbf{x}x g and y\mathbf{y}y g are mass of R\mathbf{R}R and U\mathbf{U}U, respectively. (Use : Molar mass (in g mol−1^{-1}−1) of H, C and O as 1, 12 and 16, respectively) The value of y\mathbf{y}y is______.

Correct answer: 3.20 OR 3.90 TO 3.91

Step-by-step solution →
Q26·ChemistryNumerical
For the reaction X(s)⇌Y(s)+Z(g)\mathbf{X}(s) \rightleftharpoons \mathbf{Y}(s) + \mathbf{Z}(g)X(s)⇌Y(s)+Z(g), the plot of ln⁡pzp⊖\ln\frac{p_z}{p^{\ominus}}lnp⊖pz​​ versus 104T\frac{10^4}{T}T104​ is given below (in solid line), where pzp_zpz​ is the pressure (in bar) of the gas Z\mathbf{Z}Z at temperature TTT and P⊖=1P^{\ominus} = 1P⊖=1 bar. (Given, d(ln⁡K)d(1T)=−ΔH⊖R\frac{d(\ln K)}{d\left(\frac{1}{T}\right)} = -\frac{\Delta H^{\ominus}}{R}d(T1​)d(lnK)​=−RΔH⊖​, where the equilibrium constant, K =pzp⊖= \frac{p_z}{p^{\ominus}}=p⊖pz​​ and the gas constant, R = 8.314 J K−1^{-1}−1 mol−1^{-1}−1) The value of standard enthalpy, ΔH⊖\Delta \mathrm{H}^{\ominus}ΔH⊖ (in kJ mol−1^{-1}−1) for the reaction is_____ .

Correct answer: 166.28

Step-by-step solution →
Q27·ChemistryNumerical
For the reaction X(s)⇌Y(s)+Z(g)\mathbf{X}(s) \rightleftharpoons \mathbf{Y}(s) + \mathbf{Z}(g)X(s)⇌Y(s)+Z(g), the plot of ln⁡pzp⊖\ln\frac{p_z}{p^{\ominus}}lnp⊖pz​​ versus 104T\frac{10^4}{T}T104​ is given below (in solid line), where pzp_zpz​ is the pressure (in bar) of the gas Z\mathbf{Z}Z at temperature TTT and P⊖=1P^{\ominus} = 1P⊖=1 bar. (Given, d(ln⁡K)d(1T)=−ΔH⊖R\frac{d(\ln K)}{d\left(\frac{1}{T}\right)} = -\frac{\Delta H^{\ominus}}{R}d(T1​)d(lnK)​=−RΔH⊖​, where the equilibrium constant, K =pzp⊖= \frac{p_z}{p^{\ominus}}=p⊖pz​​ and the gas constant, R = 8.314 J K−1^{-1}−1 mol−1^{-1}−1) The value of ΔS⊖\Delta \mathrm{S}^{\ominus}ΔS⊖ (in J K−1^{-1}−1 mol−1^{-1}−1) for the given reaction, at 1000 K is______ .

Correct answer: 141.33 or 141.34

Step-by-step solution →
Q28·ChemistryNumerical
The boiling point of water in a 0.1 molal silver nitrate solution (solution A\mathbf{A}A) is x\mathbf{x}x ∘^\circ∘C. To this solution A\mathbf{A}A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B\mathbf{B}B. The difference in the boiling points of water in the two solutions A\mathbf{A}A and B\mathbf{B}B is y×10−2\mathbf{y} \times 10^{-2}y×10−2 ∘^\circ∘C. (Assume : Densities of the solutions A\mathbf{A}A and B\mathbf{B}B are the same as that of water and the soluble salts dissociate completely.) Use: Molal elevation constant (Ebullioscopic Constant), Kb=0.5K_b = 0.5Kb​=0.5 K kg mol−1^{-1}−1; Boiling point of pure water as 100∘^\circ∘C.) The value of x\mathbf{x}x is _______.

Correct answer: 100.10

Step-by-step solution →
Q29·ChemistryNumerical
The boiling point of water in a 0.1 molal silver nitrate solution (solution A\mathbf{A}A) is x\mathbf{x}x ∘^\circ∘C. To this solution A\mathbf{A}A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B\mathbf{B}B. The difference in the boiling points of water in the two solutions A\mathbf{A}A and B\mathbf{B}B is y×10−2\mathbf{y} \times 10^{-2}y×10−2 ∘^\circ∘C. (Assume : Densities of the solutions A\mathbf{A}A and B\mathbf{B}B are the same as that of water and the soluble salts dissociate completely.) Use: Molal elevation constant (Ebullioscopic Constant), Kb=0.5K_b = 0.5Kb​=0.5 K kg mol−1^{-1}−1; Boiling point of pure water as 100∘^\circ∘C.) The value of ∣y∣|\mathbf{y}|∣y∣ is _____ .

Correct answer: 2.50

Step-by-step solution →
Q30·ChemistryMultiple correct
Given The compound(s), which on reaction with HNO3\mathrm{HNO_3}HNO3​ will give the product having degree of rotation, [α]D=−52.7∘[\alpha]_\mathrm{D} = -52.7^\circ[α]D​=−52.7∘ is (are)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C), (D)

Step-by-step solution →
Q31·ChemistryMultiple correct
The reaction of Q\mathbf{Q}Q with PhSNa yields an organic compound (major product) that gives positive Carius test on treatment with Na2O2\mathrm{Na_2O_2}Na2​O2​ followed by addition of BaCl2\mathrm{BaCl_2}BaCl2​. The correct option(s) for Q\mathbf{Q}Q is (are).
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (D)

Step-by-step solution →
Q32·ChemistryMultiple correct
The correct statement(s) related to colloids is(are)
  1. (A)The process of precipitating colloidal sol by an electrolyte is called peptization.
  2. (B)Colloidal solution freezes at higher temperature than the true solution at the same concentration.
  3. (C)Surfactants form micelle above critical micelle concentration (CMC). CMC depends on temperature
  4. (D)Micelles are macromolecular colloids.

Correct answer: (B), (C)

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Q33·ChemistryMultiple correct
An ideal gas undergoes a reversible isothermal expansion from state I\mathbf{I}I to state II\mathbf{II}II followed by a reversible adiabatic expansion from state II\mathbf{II}II to state III\mathbf{III}III. The correct plot(s) representing the changes from state I\mathbf{I}I to state III\mathbf{III}III is(are) (ppp : pressure, VVV : volume, TTT : temperature, HHH : enthalpy, SSS : entropy)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (B), (D)

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Q34·ChemistryMultiple correct
The correct statement(s) related to the metal extraction processes is(are)
  1. (A)A mixture of PbS and PbO undergoes self-reduction to produce Pb and SO2\mathrm{SO_2}SO2​.
  2. (B)In the extraction process of copper from copper pyrites, silica is added to produce copper silicate.
  3. (C)Partial oxidation of sulphide ore of copper by roasting, followed by self-reduction produces blister copper.
  4. (D)In cyanide process, zinc powder is utilized to precipitate gold from Na[Au(CN)2]\mathrm{Na[Au(CN)_2]}Na[Au(CN)2​]

Correct answer: (A), (C), (D)

Step-by-step solution →
Q35·ChemistryMultiple correct
A mixture of two salts is used to prepare a solution S\mathbf{S}S, which gives the following results : White precipitate(s) only ←Room temperatureDilute NaOH(aq.)\xleftarrow[\text{Room temperature}]{\text{Dilute NaOH(aq.)}}Dilute NaOH(aq.)Room temperature​ S\mathbf{S}S (aq. solution of the salts) →Room temperatureDilute HCl(aq.)\xrightarrow[\text{Room temperature}]{\text{Dilute HCl(aq.)}}Dilute HCl(aq.)Room temperature​ White precipitate(s) only The correct option(s) for the salt mixture is(are)
  1. (A)Pb(NO3)2\mathrm{Pb(NO_3)_2}Pb(NO3​)2​ and Zn(NO3)2\mathrm{Zn(NO_3)_2}Zn(NO3​)2​
  2. (B)Pb(NO3)2\mathrm{Pb(NO_3)_2}Pb(NO3​)2​ and Bi(NO3)3\mathrm{Bi(NO_3)_3}Bi(NO3​)3​
  3. (C)AgNO3\mathrm{AgNO_3}AgNO3​ and Bi(NO3)3\mathrm{Bi(NO_3)_3}Bi(NO3​)3​
  4. (D)Pb(NO3)2\mathrm{Pb(NO_3)_2}Pb(NO3​)2​ and Hg(NO3)2\mathrm{Hg(NO_3)_2}Hg(NO3​)2​

Correct answer: (A), (B)

Step-by-step solution →
Q36·ChemistryInteger
The maximum number of possible isomers (including stereoisomers) which may be formed on mono-bromination of 1-methylcyclohex-1-ene using Br2_22​ and UV light is ____

Correct answer: 9 OR 13 OR 12

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Q37·ChemistryInteger
In the reaction given below, the total number of atoms having sp2sp^2sp2 hybridization in the major product P\mathbf{P}P is ___

Correct answer: 8 OR 12

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Q38·ChemistryInteger
The total number of possible isomers for [Pt(NH3)4Cl2]Br2[\mathrm{Pt(NH_3)_4Cl_2}]\mathrm{Br_2}[Pt(NH3​)4​Cl2​]Br2​ is ______

Correct answer: 6

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Mathematics — JEE Advanced 2021 Paper 1

Q39·MathematicsSingle correct
Consider a triangle Δ\DeltaΔ whose two sides lie on the x-axis and the line x+y+1=0x + y + 1 = 0x+y+1=0. If the orthocenter of Δ\DeltaΔ is (1,1)(1, 1)(1,1), then the equation of the circle passing through the vertices of the triangle Δ\DeltaΔ is
  1. (A)x2+y2−3x+y=0x^2 + y^2 - 3x + y = 0x2+y2−3x+y=0
  2. (B)x2+y2+x+3y=0x^2 + y^2 + x + 3y = 0x2+y2+x+3y=0
  3. (C)x2+y2+2y−1=0x^2 + y^2 + 2y - 1 = 0x2+y2+2y−1=0
  4. (D)x2+y2+x+y=0x^2 + y^2 + x + y = 0x2+y2+x+y=0

Correct answer: (B)

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Q40·MathematicsSingle correct
The area of the region {(x,y):0≤x≤94, 0≤y≤1, x≥3y, x+y≥2}\left\{(x, y) : 0 \le x \le \frac{9}{4},\ 0 \le y \le 1,\ x \ge 3y,\ x + y \ge 2\right\}{(x,y):0≤x≤49​, 0≤y≤1, x≥3y, x+y≥2} is
  1. (A)1132\frac{11}{32}3211​
  2. (B)3596\frac{35}{96}9635​
  3. (C)3796\frac{37}{96}9637​
  4. (D)1332\frac{13}{32}3213​

Correct answer: (A)

Step-by-step solution →
Q41·MathematicsSingle correct
Consider three sets E1={1,2,3}E_1 = \{1, 2, 3\}E1​={1,2,3}, F1={1,3,4}F_1 = \{1, 3, 4\}F1​={1,3,4} and G1={2,3,4,5}G_1 = \{2, 3, 4, 5\}G1​={2,3,4,5}. Two elements are chosen at random, without replacement, from the set E1E_1E1​, and let S1S_1S1​ denote the set of these chosen elements. Let E2=E1−S1E_2 = E_1 - S_1E2​=E1​−S1​ and F2=F1∪S1F_2 = F_1 \cup S_1F2​=F1​∪S1​. Now two elements are chosen at random, without replacement, from the set F2F_2F2​ and let S2S_2S2​ denote the set of these chosen elements. Let G2=G1∪S2G_2 = G_1 \cup S_2G2​=G1​∪S2​. Finally, two elements are chosen at random, without replacement, from the set G2G_2G2​ and let S3S_3S3​ denote the set of these chosen elements. Let E3=E2∪S3E_3 = E_2 \cup S_3E3​=E2​∪S3​. Given that E1=E3E_1 = E_3E1​=E3​, let p be the conditional probability of the event S1={1,2}S_1 = \{1, 2\}S1​={1,2}. Then the value of p is
  1. (A)15\frac{1}{5}51​
  2. (B)35\frac{3}{5}53​
  3. (C)12\frac{1}{2}21​
  4. (D)25\frac{2}{5}52​

Correct answer: (A)

Step-by-step solution →
Q42·MathematicsSingle correct
Let θ1,θ2,...,θ10\theta_1, \theta_2, ..., \theta_{10}θ1​,θ2​,...,θ10​ be positive valued angles (in radian) such that θ1+θ2+...+θ10=2π\theta_1 + \theta_2 + ... + \theta_{10} = 2\piθ1​+θ2​+...+θ10​=2π. Define the complex numbers z1=eiθ1z_1 = e^{i\theta_1}z1​=eiθ1​, zk=zk−1eiθkz_k = z_{k-1}e^{i\theta_k}zk​=zk−1​eiθk​ for k=2,3,...,10k = 2, 3, ..., 10k=2,3,...,10, where i=−1i = \sqrt{-1}i=−1​. Consider the statements P and Q given below : P : ∣z2−z1∣+∣z3−z2∣+...+∣z10−z9∣+∣z1−z10∣≤2π\left|z_2 - z_1\right| + \left|z_3 - z_2\right| + ... + \left|z_{10} - z_9\right| + \left|z_1 - z_{10}\right| \le 2\pi∣z2​−z1​∣+∣z3​−z2​∣+...+∣z10​−z9​∣+∣z1​−z10​∣≤2π Q : ∣z22−z12∣+∣z32−z22∣+....+∣z102−z92∣+∣z12−z102∣≤4π\left|z_2^2 - z_1^2\right| + \left|z_3^2 - z_2^2\right| + .... + \left|z_{10}^2 - z_9^2\right| + \left|z_1^2 - z_{10}^2\right| \le 4\pi​z22​−z12​​+​z32​−z22​​+....+​z102​−z92​​+​z12​−z102​​≤4π Then,
  1. (A)P is TRUE and Q is FALSE
  2. (B)Q is TRUE and P is FALSE
  3. (C)both P and Q are TRUE
  4. (D)both P and Q are FALSE

Correct answer: (C)

Step-by-step solution →
Q43·MathematicsNumerical
Three numbers are chosen at random, one after another with replacement, from the set S={1,2,3,...,100}S = \{1, 2, 3, ..., 100\}S={1,2,3,...,100}. Let p1p_1p1​ be the probability that the maximum of chosen numbers is at least 81 and p2p_2p2​ be the probability that the minimum of chosen numbers is at most 40. The value of 6254p1\frac{625}{4}p_14625​p1​ is ________.

Correct answer: 76.25

Step-by-step solution →
Q44·MathematicsNumerical
Three numbers are chosen at random, one after another with replacement, from the set S={1,2,3,...,100}S = \{1, 2, 3, ..., 100\}S={1,2,3,...,100}. Let p1p_1p1​ be the probability that the maximum of chosen numbers is at least 81 and p2p_2p2​ be the probability that the minimum of chosen numbers is at most 40. The value of 1254p2\frac{125}{4}p_24125​p2​ is ________.

Correct answer: 24.50

Step-by-step solution →
Q45·MathematicsNumerical
Let α\alphaα, β\betaβ and γ\gammaγ be real numbers such that the system of linear equations x+2y+3z=αx + 2y + 3z = \alphax+2y+3z=α 4x+5y+6z=β4x + 5y + 6z = \beta4x+5y+6z=β 7x+8y+9z=γ−17x + 8y + 9z = \gamma - 17x+8y+9z=γ−1 is consistent. Let ∣M∣|M|∣M∣ represent the determinant of the matrix M=[α2γβ10−101]M = \begin{bmatrix} \alpha & 2 & \gamma \\ \beta & 1 & 0 \\ -1 & 0 & 1 \end{bmatrix}M=​αβ−1​210​γ01​​ Let P be the plane containing all those (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) for which the above system of linear equations is consistent, and D be the square of the distance of the point (0, 1, 0) from the plane P. The value of ∣M∣\left|M\right|∣M∣ is ________.

Correct answer: 1.00

Step-by-step solution →
Q46·MathematicsNumerical
Let α\alphaα, β\betaβ and γ\gammaγ be real numbers such that the system of linear equations x+2y+3z=αx + 2y + 3z = \alphax+2y+3z=α 4x+5y+6z=β4x + 5y + 6z = \beta4x+5y+6z=β 7x+8y+9z=γ−17x + 8y + 9z = \gamma - 17x+8y+9z=γ−1 is consistent. Let ∣M∣|M|∣M∣ represent the determinant of the matrix M=[α2γβ10−101]M = \begin{bmatrix} \alpha & 2 & \gamma \\ \beta & 1 & 0 \\ -1 & 0 & 1 \end{bmatrix}M=​αβ−1​210​γ01​​ Let P be the plane containing all those (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) for which the above system of linear equations is consistent, and D be the square of the distance of the point (0, 1, 0) from the plane P. The value of D is ________.

Correct answer: 1.50

Step-by-step solution →
Q47·MathematicsNumerical
Consider the lines L1L_1L1​ and L2L_2L2​ defined by L1:x2+y−1=0L_1 : x\sqrt{2} + y - 1 = 0L1​:x2​+y−1=0 and L2:x2−y+1=0L_2 : x\sqrt{2} - y + 1 = 0L2​:x2​−y+1=0 For a fixed constant λ\lambdaλ, let C be the locus of a point P such that the product of the distance of P from L1L_1L1​ and the distance of P from L2L_2L2​ is λ2\lambda^2λ2. The line y=2x+1y = 2x + 1y=2x+1 meets C at two points R and S, where the distance between R and S is 270\sqrt{270}270​. Let the perpendicular bisector of RS meet C at two distinct points R' and S'. Let D be the square of the distance between R' and S'. The value of λ2\lambda^2λ2 is ________.

Correct answer: 9.00

Step-by-step solution →
Q48·MathematicsNumerical
Consider the lines L1L_1L1​ and L2L_2L2​ defined by L1:x2+y−1=0L_1 : x\sqrt{2} + y - 1 = 0L1​:x2​+y−1=0 and L2:x2−y+1=0L_2 : x\sqrt{2} - y + 1 = 0L2​:x2​−y+1=0 For a fixed constant λ\lambdaλ, let C be the locus of a point P such that the product of the distance of P from L1L_1L1​ and the distance of P from L2L_2L2​ is λ2\lambda^2λ2. The line y=2x+1y = 2x + 1y=2x+1 meets C at two points R and S, where the distance between R and S is 270\sqrt{270}270​. Let the perpendicular bisector of RS meet C at two distinct points R' and S'. Let D be the square of the distance between R' and S'. The value of D is ________.

Correct answer: 77.14

Step-by-step solution →
Q49·MathematicsMultiple correct
For any 3×33 \times 33×3 matrix M, let ∣M∣\left|M\right|∣M∣ denote the determinant of M. Let E=[12323481318]E = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 3 & 4 \\ 8 & 13 & 18 \end{bmatrix}E=​128​2313​3418​​, P=[100001010]P = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0 \end{bmatrix}P=​100​001​010​​ and F=[13281813243]F = \begin{bmatrix} 1 & 3 & 2 \\ 8 & 18 & 13 \\ 2 & 4 & 3 \end{bmatrix}F=​182​3184​2133​​ If Q is a nonsingular matrix of order 3×33 \times 33×3, then which of the following statements is (are) TRUE ?
  1. (A)F=PEPF = PEPF=PEP and P2=[100010001]P^2 = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}P2=​100​010​001​​
  2. (B)∣EQ+PFQ−1∣=∣EQ∣+∣PFQ−1∣\left|EQ + PFQ^{-1}\right| = \left|EQ\right| + \left|PFQ^{-1}\right|​EQ+PFQ−1​=∣EQ∣+​PFQ−1​
  3. (C)∣(EF)3∣>∣EF∣2\left|(EF)^3\right| > \left|EF\right|^2​(EF)3​>∣EF∣2
  4. (D)Sum of the diagonal entries of P−1EP+FP^{-1}EP + FP−1EP+F is equal to the sum of diagonal entries of E+P−1FPE + P^{-1}FPE+P−1FP

Correct answer: (A), (B), (D)

Step-by-step solution →
Q50·MathematicsMultiple correct
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be defined by f(x)=x2−3x−6x2+2x+4f(x) = \frac{x^2 - 3x - 6}{x^2 + 2x + 4}f(x)=x2+2x+4x2−3x−6​. Then which of the following statements is (are) TRUE ?
  1. (A)fff is decreasing in the interval (−2,−1)(-2, -1)(−2,−1)
  2. (B)fff is increasing in the interval (1,2)(1, 2)(1,2)
  3. (C)fff is onto
  4. (D)Range of fff is [−32,2]\left[-\frac{3}{2}, 2\right][−23​,2]

Correct answer: (A), (B)

Step-by-step solution →
Q51·MathematicsMultiple correct
Let E,F and G be three events having probabilities P(E)=18,P(F)=16P(E) = \frac{1}{8}, P(F) = \frac{1}{6}P(E)=81​,P(F)=61​ and P(G)=14P(G) = \frac{1}{4}P(G)=41​, and let P(E∩F∩G)=110P(E \cap F \cap G) = \frac{1}{10}P(E∩F∩G)=101​. For any event H, if HCH^CHC denotes its complement, then which of the following statements is(are) TRUE ?
  1. (A)P(E∩F∩GC)≤140P\left(E \cap F \cap G^C\right) \le \frac{1}{40}P(E∩F∩GC)≤401​
  2. (B)P(EC∩F∩G)≤115P\left(E^C \cap F \cap G\right) \le \frac{1}{15}P(EC∩F∩G)≤151​
  3. (C)P(E∪F∪G)≤1324P\left(E \cup F \cup G\right) \le \frac{13}{24}P(E∪F∪G)≤2413​
  4. (D)P(EC∩FC∩GC)≤512P\left(E^C \cap F^C \cap G^C\right) \le \frac{5}{12}P(EC∩FC∩GC)≤125​

Correct answer: (A), (B), (C)

Step-by-step solution →
Q52·MathematicsMultiple correct
For any 3×33 \times 33×3 matrix M, let ∣M∣\left|M\right|∣M∣ denote the determinant of M. Let I be the 3×33 \times 33×3 identity matrix. Let E and F be two 3×33 \times 33×3 matrices such that (I−EF)(I - EF)(I−EF) is invertible. If G=(I−EF)−1G = (I - EF)^{-1}G=(I−EF)−1, then which of the following statements is (are) TRUE ?
  1. (A)∣FE∣=∣I−FE∣∣FGE∣\left|FE\right| = \left|I - FE\right|\left|FGE\right|∣FE∣=∣I−FE∣∣FGE∣
  2. (B)(I−FE)(I+FGE)=I(I - FE)(I + FGE) = I(I−FE)(I+FGE)=I
  3. (C)EFG=GEFEFG = GEFEFG=GEF
  4. (D)(I−FE)(I−FGE)=I\left(I - FE\right)\left(I - FGE\right) = I(I−FE)(I−FGE)=I

Correct answer: (A), (B), (C)

Step-by-step solution →
Q53·MathematicsMultiple correct
For any positive integer n, let Sn:(0,∞)→RS_n : (0, \infty) \to \mathbb{R}Sn​:(0,∞)→R be defined by Sn(x)=∑k=1ncot⁡−1(1+k(k+1)x2x)S_n(x) = \sum_{k=1}^{n} \cot^{-1}\left(\frac{1 + k(k+1)x^2}{x}\right)Sn​(x)=∑k=1n​cot−1(x1+k(k+1)x2​), where for any x∈Rx \in \mathbb{R}x∈R, cot⁡−1x∈(0,π)\cot^{-1}x \in (0, \pi)cot−1x∈(0,π) and tan⁡−1(x)∈(−π2,π2)\tan^{-1}(x) \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)tan−1(x)∈(−2π​,2π​). Then which of the following statements is (are) TRUE ?
  1. (A)S10(x)=π2−tan⁡−1(1+11x210x)S_{10}(x) = \frac{\pi}{2} - \tan^{-1}\left(\frac{1 + 11x^2}{10x}\right)S10​(x)=2π​−tan−1(10x1+11x2​), for all x>0x > 0x>0
  2. (B)lim⁡n→∞cot⁡(Sn(x))=x\lim_{n \to \infty} \cot\left(S_n(x)\right) = xlimn→∞​cot(Sn​(x))=x, for all x>0x > 0x>0
  3. (C)The equation S3(x)=π4S_3(x) = \frac{\pi}{4}S3​(x)=4π​ has a root in (0,∞)(0, \infty)(0,∞)
  4. (D)tan⁡(Sn(x))≤12\tan\left(S_n(x)\right) \le \frac{1}{2}tan(Sn​(x))≤21​, for all n≥1n \ge 1n≥1 and x>0x > 0x>0

Correct answer: (A), (B)

Step-by-step solution →
Q54·MathematicsMultiple correct
For any complex number w=c+idw = c + idw=c+id, let arg⁡(w)∈(−π,π]\arg(w) \in (-\pi, \pi]arg(w)∈(−π,π], where i=−1i = \sqrt{-1}i=−1​. Let α\alphaα and β\betaβ be real numbers such that for all complex numbers z=x+iyz = x + iyz=x+iy satisfying arg⁡(z+αz+β)=π4\arg\left(\frac{z + \alpha}{z + \beta}\right) = \frac{\pi}{4}arg(z+βz+α​)=4π​, the ordered pair (x,y)(x, y)(x,y) lies on the circle x2+y2+5x−3y+4=0x^2 + y^2 + 5x - 3y + 4 = 0x2+y2+5x−3y+4=0. Then which of the following statements is (are) TRUE ?
  1. (A)α=−1\alpha = -1α=−1
  2. (B)αβ=4\alpha\beta = 4αβ=4
  3. (C)αβ=−4\alpha\beta = -4αβ=−4
  4. (D)β=4\beta = 4β=4

Correct answer: (B), (D)

Step-by-step solution →
Q55·MathematicsInteger
For x∈Rx \in \mathbb{R}x∈R , then number of real roots of the equation 3x2−4∣x2−1∣+x−1=03x^2 - 4\left|x^2 - 1\right| + x - 1 = 03x2−4​x2−1​+x−1=0 is ____.

Correct answer: 4

Step-by-step solution →
Q56·MathematicsInteger
In a triangle ABC, let AB=23AB = \sqrt{23}AB=23​, BC=3BC = 3BC=3 and CA=4CA = 4CA=4. Then the value of cot⁡A+cot⁡Ccot⁡B\frac{\cot A + \cot C}{\cot B}cotBcotA+cotC​ is____.

Correct answer: 2

Step-by-step solution →
Q57·MathematicsInteger
Let u⃗,v⃗\vec{u}, \vec{v}u,v and w⃗\vec{w}w be vectors in three-dimensional space, where u⃗\vec{u}u and v⃗\vec{v}v are unit vectors which are not perpendicular to each other and u⃗⋅w⃗=1\vec{u}\cdot\vec{w} = 1u⋅w=1, v⃗⋅w⃗=1\vec{v}\cdot\vec{w} = 1v⋅w=1, w⃗⋅w⃗=4\vec{w}\cdot\vec{w} = 4w⋅w=4 If the volume of the parallelopiped, whose adjacent sides are represented by the vectors u⃗,v⃗\vec{u}, \vec{v}u,v and w⃗\vec{w}w , is 2\sqrt{2}2​ , then the value of ∣3u⃗+5v⃗∣\left|3\vec{u} + 5\vec{v}\right|∣3u+5v∣ is____.

Correct answer: 7

Step-by-step solution →

Chapters tested in this paper

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Current Electricity 160/186
  • Rotational Motion 172/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Probability 176/186
  • Magnetic Field of Current 147/186
  • Application of Derivatives 139/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Circles 142/186
  • Quadratic Equations 148/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Atoms 112/186
  • Isolation of Metals 106/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Isomerism 51/186
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