Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Advanced PYQs
  3. /2019
  4. /Paper 1

JEE Advanced 2019 Paper 1 Question Paper with Answers

54 questions · Physics, Chemistry & Mathematics

The complete JEE Advanced 2019 Paper 1 paper — every question with its correct answer, tagged to the chapter it tests. Free to read, no account needed.

Physics
18
Chemistry
18
Mathematics
18

Physics — JEE Advanced 2019 Paper 1

Q1·PhysicsSingle correct
Consider a spherical gaseous cloud of mass density ρ(r) in free space where r is the radial distance from its center. The gaseous cloud is made of particles of equal mass m moving in circular orbits about the common center with the same kinetic energy K. The force acting on the particles is their mutual gravitational force. If ρ(r) is constant in time, the particle number density n(r) = ρ(r)/m is [ G is universal gravitational constant]
  1. (A)3Kπr2m2G\frac{3K}{\pi r^2 m^2 G}πr2m2G3K​
  2. (B)K2πr2m2G\frac{K}{2\pi r^2 m^2 G}2πr2m2GK​
  3. (C)K6πr2m2G\frac{K}{6\pi r^2 m^2 G}6πr2m2GK​
  4. (D)Kπr2m2G\frac{K}{\pi r^2 m^2 G}πr2m2GK​

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
A thin spherical insulating shell of radius R carries a uniformly distributed charge such that the potential at its surface is V0V_0V0​. A hole with a small area α4πR2(α<<1)\alpha 4\pi R^2 (\alpha << 1)α4πR2(α<<1) is made on the shell without affecting the rest of the shell. Which one of the following statements is correct?
  1. (A)The magnitude of electric field at a point, located on a line passing through the hole and shell's center, on a distance 2R from the center of the spherical shell will be reduced by αV02R\frac{\alpha V_0}{2R}2RαV0​​
  2. (B)The magnitude of electric field at the center of the shell is reduced by αV02R\frac{\alpha V_0}{2R}2RαV0​​
  3. (C)The ratio of the potential at the center of the shell to that of the point at 12\frac{1}{2}21​R from center towards the hole will be 1−α1−2α\frac{1-\alpha}{1-2\alpha}1−2α1−α​
  4. (D)The potential at the center of the shell is reduced by 2αV02\alpha V_02αV0​

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
A current carrying wire heats a metal rod. The wire provides a constant power (P) to the rod. The metal rod is enclosed in an insulated container. It is observed that the temperature (T) in the metal rod changes with time (t) as T(t)=T0(1+βt1/4)T (t) = T_0 (1 + \beta t^{1/4})T(t)=T0​(1+βt1/4) where β is a constant with appropriate dimension while T0T_0T0​ is a constant with dimension of temperature. The heat capacity of the metal is
  1. (A)4P(T(t)−T0)4β4T05\frac{4P(T(t)-T_0)^4}{\beta^4 T_0^5}β4T05​4P(T(t)−T0​)4​
  2. (B)4P(T(t)−T0)β4T02\frac{4P(T(t)-T_0)}{\beta^4 T_0^2}β4T02​4P(T(t)−T0​)​
  3. (C)4P(T(t)−T0)2β4T02\frac{4P(T(t)-T_0)^2}{\beta^4 T_0^2}β4T02​4P(T(t)−T0​)2​
  4. (D)4P(T(t)−T0)3β4T04\frac{4P(T(t)-T_0)^3}{\beta^4 T_0^4}β4T04​4P(T(t)−T0​)3​

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
In a radioactive sample 1940^{40}_{19}1940​K nuclei either decay into stable 2040^{40}_{20}2040​Ca nuclei with decay constant 4.5 × 10−1010^{-10}10−10 per year or into stable 1840^{40}_{18}1840​Ar nuclei with decay constant 0.5×10−100.5 \times 10^{-10}0.5×10−10 per year. Given that in this sample all the stable 2040^{40}_{20}2040​Ca and 1840^{40}_{18}1840​Ar nuclei are produced by the 1940^{40}_{19}1940​K nuclei only. In time t × 10910^9109 years, if the ratio of the sum of stable 2040^{40}_{20}2040​Ca and 1840^{40}_{18}1840​Ar nuclei to the radioactive 1940^{40}_{19}1940​K nuclei is 99, the value of t will be [Given : ln10 = 2.3]
  1. (A)1.15
  2. (B)4.6
  3. (C)9.2
  4. (D)2.3

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsMultiple correct
A conducting wire of parabolic shape, initially y=x2y = x^2y=x2, is moving with velocity V⃗=V0i^\vec{V} = V_0\hat{i}V=V0​i^ in a non uniform magnetic field B⃗=B0(1+(yL)β)k^\vec{B} = B_0\left(1+\left(\frac{y}{L}\right)^{\beta}\right)\hat{k}B=B0​(1+(Ly​)β)k^, as shown in figure. If V0V_0V0​, B0B_0B0​, L and β are positive constants and Δφ is the potential difference developed between the ends of the wire, then the correct statement(s) is/are:
  1. (A)∣Δϕ∣|\Delta\phi|∣Δϕ∣ is proportional to the length of the wire projected on the y-axis.
  2. (B)∣Δϕ∣|\Delta\phi|∣Δϕ∣ remains the same if the parabolic wire is replaced by a straight wire, y = x initially, of length 2\sqrt{2}2​ L
  3. (C)∣Δϕ∣=12B0V0L|\Delta\phi| = \frac{1}{2}B_0V_0L∣Δϕ∣=21​B0​V0​L for β = 0
  4. (D)∣Δϕ∣=43B0V0L|\Delta\phi| = \frac{4}{3}B_0V_0L∣Δϕ∣=34​B0​V0​L for β = 2

Correct answer: (A), (B), (D)

Step-by-step solution →
Q6·PhysicsMultiple correct
A thin convex lens is made of two materials with refractive indices n1n_1n1​ and n2n_2n2​, as shown in figure. The radius of curvature of the left and right spherical surfaces are equal. f is the focal length of the lens when n1=n2=nn_1 = n_2 = nn1​=n2​=n. The focal length is f + Δf when n1n_1n1​ = n and n2n_2n2​ = n + Δn. Assuming Δn << (n – 1) and 1 < n < 2. The correct statement(s) is/are.
  1. (A)∣Δff∣<∣Δnn∣\left|\frac{\Delta f}{f}\right| < \left|\frac{\Delta n}{n}\right|​fΔf​​<​nΔn​​
  2. (B)If Δnn<0\frac{\Delta n}{n} < 0nΔn​<0 then Δff>0\frac{\Delta f}{f} > 0fΔf​>0
  3. (C)For n = 1.5, Δn = 10−310^{-3}10−3 and f = 20 cm, the value of |Δf| will be 0.02 cm (round off to 2nd2^{nd}2nd decimal place).
  4. (D)The relation between Δff\frac{\Delta f}{f}fΔf​ and Δnn\frac{\Delta n}{n}nΔn​ remains unchanged if both the convex surfaces are replaced by concave surfaces of the same radius of curvature.

Correct answer: (B), (C), (D)

Step-by-step solution →
Q7·PhysicsMultiple correct
A cylindrical capillary tube of 0.2 mm radius is made by joining two capillaries T1T_1T1​ and T2T_2T2​ of different materials having water contact angles of 000^000 and 60060^0600, respectively. The capillary tube is dipped vertically in water in two different configurations, case I and II as shown in figure. Which of the following option(s) is (are) correct? [Surface tension of a water = 0.075 N/m, density of water = 1000 kg/m3m^3m3, take g = 10 m/s2s^2s2]
  1. (A)For case I, if the joint is kept at 8 cm above the water surface, the height of water column in the tube will be 7.5 cm. (Neglect the weight of the water in the meniscus)
  2. (B)For case I, if the capillary joint is 5 cm above the water surface, the height of water column raised in the tube will be more than 8.75 cm. (Neglect the weight of the water in the meniscus)
  3. (C)For case II, if the capillary joint is 5 cm above the water surface, the height of water column raised in the tube will be 3.75 cm. (Neglect the weight of the water in the meniscus)
  4. (D)The correction in the height of water column raised in the tube, due to weight of water contained in the meniscus, will be different for both cases.

Correct answer: (A), (C), (D)

Step-by-step solution →
Q8·PhysicsMultiple correct
A charged shell of radius R carries a total charge Q. Given φ as the flux of electric field through a closed cylindrical surface of height h, radius r and with its center same as that of the shell. Here, center of the cylinder is a point on the axis of the cylinder which is equidistant from its top and bottom surfaces. Which of the following option(s) is/are correct? [ε0\varepsilon_0ε0​ is permittivity of free space]
  1. (A)If h < 8R/5 and r = 3R/5 then φ = 0
  2. (B)If h > 2R and r > R then φ = Q/ε0\varepsilon_0ε0​
  3. (C)If h > 2R and r = 4R/5 then φ = Q/5ε05\varepsilon_05ε0​
  4. (D)If h > 2R and r = 3R/5 then φ = Q/5ε05\varepsilon_05ε0​

Correct answer: (A), (B), (D)

Step-by-step solution →
Q9·PhysicsMultiple correct
Let us consider a system of units in which mass and angular momentum are dimensionless. If length has dimension of L, which of the following statement(s) is/are correct?
  1. (A)The dimension of energy is L−2L^{-2}L−2
  2. (B)The dimension of force is L−3L^{-3}L−3
  3. (C)The dimension of power is L−5L^{-5}L−5
  4. (D)The dimension of linear momentum is L−1L^{-1}L−1

Correct answer: (A), (B), (D)

Step-by-step solution →
Q10·PhysicsMultiple correct
In the circuit shown, initially there is no charge on capacitors and keys S1S_1S1​ and S2S_2S2​ are open. The values of the capacitors are C1C_1C1​ = 10 μF, C2C_2C2​ = 30 μF and C3C_3C3​ = C4C_4C4​ = 80 μF. Which of the statement(s) is/are correct?
  1. (A)The key S1S_1S1​ is kept closed for long time such that capacitors are fully charged. Now key S2S_2S2​ is closed, at this time, the instantaneous current across 30Ω resistor (between points P and Q) will be 0.2 A (round off to 1st1^{st}1st decimal place).
  2. (B)If key S1S_1S1​ is kept closed for long time such that capacitors are fully charged, the voltage across the capacitor C1C_1C1​ will be 4V.
  3. (C)At time t = 0, the key S1S_1S1​ is closed, the instantaneous current in the closed circuit will be 25 mA
  4. (D)If key S1S_1S1​ is kept closed for long time such that capacitors are fully charged, the voltage difference between points P and Q will be 10 V.

Correct answer: (B), (C)

Step-by-step solution →
Q11·PhysicsMultiple correct
One mole of a monatomic ideal gas goes through a thermodynamic cycle, as shown in the volume versus temperature (V – T) diagram. The correct statement(s) is/are: [R is the gas constant]
  1. (A)Work done in this thermodynamic cycle (1 → 2 → 3 → 4 → 1) is ∣W∣=12RT0|W| = \frac{1}{2}RT_0∣W∣=21​RT0​
  2. (B)The ratio of heat transfer during processes 1 → 2 and 2 → 3 is ∣Q1→2Q2→3∣=53\left|\frac{Q_{1\to 2}}{Q_{2\to 3}}\right| = \frac{5}{3}​Q2→3​Q1→2​​​=35​
  3. (C)The above thermodynamic cycle exhibits only isochoric and adiabatic processes.
  4. (D)The ratio of heat transfer during processes 1 → 2 and 3 → 4 is ∣Q1→2Q3→4∣=12\left|\frac{Q_{1\to 2}}{Q_{3\to 4}}\right| = \frac{1}{2}​Q3→4​Q1→2​​​=21​

Correct answer: (A), (B)

Step-by-step solution →
Q12·PhysicsMultiple correct
Two identical moving coil galvanometers have 10 Ω resistance and full scale deflection at 2 μA current. One of them is converted into a voltmeter of 100 mV full scale reading and the other into an Ammeter of 1mA full scale current using appropriate resistors. These are then used to measure the voltage and current in the Ohm's law experiment with R = 1000 Ω resistor by using an ideal cell. Which of the following statement(s) is/are correct?
  1. (A)The measured value of R will be 978 Ω < R < 982 Ω
  2. (B)The resistance of the Voltmeter will be 100 kΩ
  3. (C)If the ideal cell is replaced by a cell having internal resistance of 5Ω then the measured value of R will be more than 1000 Ω
  4. (D)The resistance of the Ammeter will be 0.02Ω (round off to 2nd2^{nd}2nd decimal place)

Correct answer: (A), (D)

Step-by-step solution →
Q13·PhysicsNumerical
A block of weight 100 N is suspended by copper and steel wires of same cross sectional area 0.5 cm2cm^2cm2 and, length 3\sqrt{3}3​ m and 1 m, respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30° and 60°, respectively. If elongation in copper wire is (ΔℓC)\left(\Delta\ell_C\right)(ΔℓC​) and elongation in steel wire is (ΔℓS)\left(\Delta\ell_S\right)(ΔℓS​), then the ratio ΔℓCΔℓS\frac{\Delta\ell_C}{\Delta\ell_S}ΔℓS​ΔℓC​​ is ______ [Young's modulus for copper and steel are 1 × 101110^{11}1011 N/m2m^2m2 and 2 × 101110^{11}1011 N/m2m^2m2, respectively.]

Correct answer: 2.00

Step-by-step solution →
Q14·PhysicsNumerical
A particle is moved along a path AB-BC-CD-DE-EF-FA, as shown in figure, in presence of a force F⃗=(αyi^+2αxj^)N\vec{F} = \left(\alpha y\hat{i} + 2\alpha x\hat{j}\right) NF=(αyi^+2αxj^​)N, where x and y are in meter and α = – 1 Nm−1Nm^{-1}Nm−1. The work done on the particle by this force F⃗\vec{F}F will be ________ Joule.

Correct answer: 0.75

Step-by-step solution →
Q15·PhysicsNumerical
A train S1, moving with a uniform velocity of 108 km/h, approaches another train S2 standing on a platform. An observer O moves with a uniform velocity of 36 km/h towards S2, as shown in figure. Both the trains are blowing whistles of same frequency 120 Hz. When O is 600 m away from S2 and distance between S1 and S2 is 800 m, the number of beats heard by O is ______. [Speed of the sound = 330 m/s]

Correct answer: 8.12 or 8.13

Step-by-step solution →
Q16·PhysicsNumerical
A liquid at 30°C is poured very slowly into a Calorimeter that is at temperature of 110°C. The boiling temperature of the liquid is 80°C. It is found that the first 5 gm of the liquid completely evaporates. After pouring another 80 gm of the liquid the equilibrium temperature is found to be 50°C. The ratio of the Latent heat of the liquid to its specific heat will be ______ °C. [Neglect the heat exchange with surrounding]

Correct answer: 270.00

Step-by-step solution →
Q17·PhysicsNumerical
A planar structure of length L and width W is made of two different optical media of refractive indices n1n_1n1​ = 1.5 and n2n_2n2​ = 1.44 as shown in figure. If L >> W, a ray entering from end AB will emerge from end CD only if the total internal reflection condition is met inside the structure. For L = 9.6 m, if the incident angle θ is varied, the maximum time taken by a ray to exit the plane CD is t × 10−910^{-9}10−9 s, where t is ______. [Speed of light c = 3 × 10810^8108 m/s]

Correct answer: 50.00

Step-by-step solution →
Q18·PhysicsNumerical
A parallel plate capacitor of capacitance C has spacing d between two plates having area A. The region between the plates is filled with N dielectric layers, parallel to its plates, each with thickness δ=dN\delta = \frac{d}{N}δ=Nd​. The dielectric constant of the mthm^{th}mth layer is Km=K(1+mN)K_m = K\left(1+\frac{m}{N}\right)Km​=K(1+Nm​). For a very large N(>103)N\left(>10^3\right)N(>103), the capacitance C is α(Kε0Adln⁡2)\alpha\left(\frac{K\varepsilon_0 A}{d \ln 2}\right)α(dln2Kε0​A​). The value of α will be ______. [ε0\varepsilon_0ε0​ is the permittivity of free space]

Correct answer: 1.00

Step-by-step solution →

Chemistry — JEE Advanced 2019 Paper 1

Q19·ChemistrySingle correct
The green colour produced in the borax bead test of a chromium(III) salt is due to
  1. (A)CrB
  2. (B)Cr2_{2}2​O3_{3}3​
  3. (C)Cr2_{2}2​(B4_{4}4​O7_{7}7​)3_{3}3​
  4. (D)Cr(BO2_{2}2​)3_{3}3​

Correct answer: (D)

Step-by-step solution →
Q20·ChemistrySingle correct
Molar conductivity (Λm\Lambda_{m}Λm​) of aqueous solution of sodium stearate, which behaves as a strong electrolyte, is recorded at varying concentrations (c) of sodium stearate. Which one of the following plots provides the correct representation of micelle formation in the solution? (critical micelle concentration (CMC) is marked with an arrow in the figures
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q21·ChemistrySingle correct
Calamine, malachite, magnetite and cryolite, respectively, are
  1. (A)ZnSO4_{4}4​, Cu(OH)2_{2}2​, Fe3_{3}3​O4_{4}4​, Na3_{3}3​AlF6_{6}6​
  2. (B)ZnCO3_{3}3​, CuCO3_{3}3​.Cu(OH)2_{2}2​, Fe3_{3}3​O4_{4}4​, Na3_{3}3​AlF6_{6}6​
  3. (C)ZnSO4_{4}4​, CuCO3_{3}3​, Fe2_{2}2​O3_{3}3​, AlF3_{3}3​
  4. (D)ZnCO3_{3}3​, CuCO3_{3}3​, Fe2_{2}2​O3_{3}3​, Na3_{3}3​AlF6_{6}6​

Correct answer: (B)

Step-by-step solution →
Q22·ChemistrySingle correct
The correct order of acid strength of the following carboxylic acids is
  1. (A)I > III > II > IV
  2. (B)III > II > I > IV
  3. (C)I > II > III > IV
  4. (D)II > I > IV > III

Correct answer: (C)

Step-by-step solution →
Q23·ChemistryMultiple correct
Which of the following statements(s) is (are) true ?
  1. (A)Oxidation of glucose with bromine water gives glutamic acid
  2. (B)The two six-membered cyclic hemiacetal forms of D-(+)-glucose are called anomers
  3. (C)Monosaccharides cannot be hydrolysed to give polyhydroxy aldehydes and ketones
  4. (D)Hydrolysis of sucrose gives dextrorotatory glucose and laevorotatory fructose

Correct answer: (B), (C), (D)

Step-by-step solution →
Q24·ChemistryMultiple correct
Choose the correct option(s) for the following set of reactions
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C), (D)

Step-by-step solution →
Q25·ChemistryMultiple correct
Each of the following options contains a set of four molecules, Identify the option(s) where all four molecules possess permanent dipole moment at room temperature.
  1. (A)SO2_{2}2​, C6_{6}6​H5_{5}5​Cl, H2_{2}2​Se, BrF5_{5}5​
  2. (B)BeCl2_{2}2​, CO2_{2}2​, BCl3_{3}3​, CHCl3_{3}3​
  3. (C)BF3_{3}3​, O3_{3}3​, SF6_{6}6​, XeF6_{6}6​
  4. (D)NO2_{2}2​, NH3_{3}3​, POCl3_{3}3​, CH3_{3}3​Cl

Correct answer: (A), (D)

Step-by-step solution →
Q26·ChemistryMultiple correct
Choose the reaction(s) from the following options, for which the standard enthalpy of reaction is equal to the standard enthalpy of formation.
  1. (A)2C(g) + 3H2_{2}2​(g) ⟶\longrightarrow⟶ C2_{2}2​H6_{6}6​(g)
  2. (B)32\frac{3}{2}23​O2_{2}2​(g) ⟶\longrightarrow⟶ O3_{3}3​(g)
  3. (C)2H2_{2}2​(g) + O2_{2}2​(g) ⟶\longrightarrow⟶ 2H2_{2}2​O(ℓ\ellℓ)
  4. (D)18\frac{1}{8}81​S8_{8}8​(s) + O2_{2}2​(g) ⟶\longrightarrow⟶ SO2_{2}2​(g)

Correct answer: (B), (D)

Step-by-step solution →
Q27·ChemistryMultiple correct
Fusion of MnO2_{2}2​ with KOH in presence of O2_{2}2​ produces a salt W. Alkaline solution of W upon electrolytic oxidation yields another salt X. The manganese containing ions present in W and X, respectively, are Y and Z. Correct statement(s) is(are)
  1. (A)In aqueous acidic solution, Y undergoes disproportionation reaction to give Z and MnO2_{2}2​
  2. (B)In both Y and Z, π\piπ-bonding occurs between p-orbitals of oxygen and d-orbitals of manganese
  3. (C)Y is diamagnetic in nature while Z is paramagnetic
  4. (D)Both Y and Z are coloured and have tetrahedral shape

Correct answer: (A), (B), (D)

Step-by-step solution →
Q28·ChemistryMultiple correct
Which of the following statement(s) is(are) correct regarding the root mean square speed (Urms_{rms}rms​) and average translational kinetic energy (εav\varepsilon_{av}εav​) of a molecule in a gas at equilibrium ?
  1. (A)εav\varepsilon_{av}εav​ at a given temperature does not depend on its molecular mass
  2. (B)Urms_{rms}rms​ is doubled when its temperature is increased four times
  3. (C)εav\varepsilon_{av}εav​ is doubled when its temperature is increased four times
  4. (D)Urms_{rms}rms​ is inversely proportional to the square root of its molecular mass

Correct answer: (A), (B), (D)

Step-by-step solution →
Q29·ChemistryMultiple correct
A tin chloride Q undergoes the following reactions (not balanced) Q + Cl−^{-}− ⟶\longrightarrow⟶ X Q + Me3_{3}3​N ⟶\longrightarrow⟶ Y Q + CuCl2_{2}2​ ⟶\longrightarrow⟶ Z + CuCl X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the correct option(s)
  1. (A)The central atom in Z has one lone pair of electrons
  2. (B)The central atom in X is sp3^{3}3 hybridized
  3. (C)There is a coordinate bond in Y
  4. (D)The oxidation state of the central atom in Z is +2

Correct answer: (B), (C)

Step-by-step solution →
Q30·ChemistryMultiple correct
In the decay sequence, 92238^{238}_{92}92238​U →−x1\xrightarrow{-x_{1}}−x1​​ 90234^{234}_{90}90234​Th →−x2\xrightarrow{-x_{2}}−x2​​ 91234^{234}_{91}91234​Pa →−x3\xrightarrow{-x_{3}}−x3​​ 234^{234}234Z →−x4\xrightarrow{-x_{4}}−x4​​ 90230^{230}_{90}90230​Th x1_{1}1​, x2_{2}2​, x3_{3}3​ and x4_{4}4​ are particles /radiation emitted by the respective isotopes. The correct option(s) is(are)
  1. (A)x3_{3}3​ is γ\gammaγ-ray
  2. (B)Z is an isotope of uranium
  3. (C)x2_{2}2​ is β−\beta^{-}β−
  4. (D)x1_{1}1​ will deflect towards negatively charged plate

Correct answer: (B), (C), (D)

Step-by-step solution →
Q31·ChemistryNumerical
Among B2_{2}2​H6_{6}6​, B3_{3}3​N3_{3}3​H6_{6}6​, N2_{2}2​O, N2_{2}2​O4_{4}4​, H2_{2}2​S2_{2}2​O3_{3}3​ and H2_{2}2​S2_{2}2​O8_{8}8​, the total number of molecules containing covalent bond between two atoms of the same kind is

Correct answer: 4.00

Step-by-step solution →
Q32·ChemistryNumerical
On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapour pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is (Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol−1^{-1}−1 and 5.12 K kg mol−1^{-1}−1, respectively)

Correct answer: 1.02 or 1.03

Step-by-step solution →
Q33·ChemistryNumerical
For the following reaction, the equilibrium constant Kc_{c}c​ at 298 K is 1.6 ×\times× 1017^{17}17 Fe2+^{2+}2+(aq) + S2−^{2-}2−(aq) ⇌\rightleftharpoons⇌ FeS(s) When equal volumes of 0.06 M Fe2+^{2+}2+(aq) and 0.2 M S2−^{2-}2−(aq) solutions are mixed, the equilibrium concentration of Fe2+^{2+}2+(aq) is found to be Y ×\times× 10−17^{-17}−17 M. The value of Y is ……… .

Correct answer: 8.92 or 8.93

Step-by-step solution →
Q34·ChemistryNumerical
Experiment No. | [A] (mol dm−3^{-3}−3) | [B] (mol dm−3^{-3}−3) | [C] (mol dm−3^{-3}−3) | Rate of reaction (mol dm−3^{-3}−3s−1^{-1}−1) 1 | 0.2 | 0.1 | 0.1 | 6.0 ×\times× 10−5^{-5}−5 2 | 0.2 | 0.2 | 0.1 | 6.0 ×\times× 10−5^{-5}−5 3 | 0.2 | 0.1 | 0.2 | 1.2 ×\times× 10−4^{-4}−4 4 | 0.3 | 0.1 | 0.1 | 9.0 ×\times× 10−5^{-5}−5 The rate of the reaction for [A] = 0.15 mol dm−3^{-3}−3, [B] = 0.25 mol dm−3^{-3}−3 and [C] = 0.15 mol dm−3^{-3}−3 is found to be Y ×\times× 10−5^{-5}−5 mol dm−3^{-3}−3s−1^{-1}−1. The value of Y is ……… .

Correct answer: 6.75

Step-by-step solution →
Q35·ChemistryNumerical
Schemes 1 and 2 describe the conversion of P to Q and R to S, respectively. Scheme 3 describes the synthesis of T from Q and S. The total number of Br atoms in a molecule of T is

Correct answer: 4.00

Step-by-step solution →
Q36·ChemistryNumerical
At 143 K, the reaction of XeF4_{4}4​ with O2_{2}2​F2_{2}2​ produces xenon compound Y. The total number of lone Pair(s) of electrons present on the whole molecule of Y is ……… .

Correct answer: 19.00

Step-by-step solution →

Mathematics — JEE Advanced 2019 Paper 1

Q37·MathematicsSingle correct
Let M=[sin⁡4θ−1−sin⁡2θ1+cos⁡2θcos⁡4θ]=αI+βM−1M = \begin{bmatrix} \sin^4\theta & -1-\sin^2\theta \\ 1+\cos^2\theta & \cos^4\theta \end{bmatrix} = \alpha I + \beta M^{-1}M=[sin4θ1+cos2θ​−1−sin2θcos4θ​]=αI+βM−1, where α=α(θ)\alpha = \alpha(\theta)α=α(θ) and β=β(θ)\beta = \beta(\theta)β=β(θ) are real numbers, and I is the 2×22 \times 22×2 identity matrix. If α∗\alpha^*α∗ is the minimum of the set {α(θ):θ∈[0,2π)}\{\alpha(\theta) : \theta \in [0, 2\pi)\}{α(θ):θ∈[0,2π)} and β∗\beta^*β∗ is the minimum of the set {β(θ):θ∈[0,2π)}\{\beta(\theta) : \theta \in [0, 2\pi)\}{β(θ):θ∈[0,2π)}, then the value of α∗+β∗\alpha^* + \beta^*α∗+β∗ is
  1. (A)−3716-\frac{37}{16}−1637​
  2. (B)−3116-\frac{31}{16}−1631​
  3. (C)−1716-\frac{17}{16}−1617​
  4. (D)−2916-\frac{29}{16}−1629​

Correct answer: (D)

Step-by-step solution →
Q38·MathematicsSingle correct
The area of the region {(x,y):xy≤8,1≤y≤x2}\{(x, y) : xy \le 8, 1 \le y \le x^2\}{(x,y):xy≤8,1≤y≤x2} is
  1. (A)16log⁡e2−616\log_e 2 - 616loge​2−6
  2. (B)8log⁡e2−1438\log_e 2 - \frac{14}{3}8loge​2−314​
  3. (C)16log⁡e2−14316\log_e 2 - \frac{14}{3}16loge​2−314​
  4. (D)8log⁡e2−738\log_e 2 - \frac{7}{3}8loge​2−37​

Correct answer: (C)

Step-by-step solution →
Q39·MathematicsSingle correct
Let S be the set of all complex numbers z satisfying ∣z−2+i∣≥5|z - 2 + i| \ge \sqrt{5}∣z−2+i∣≥5​. If the complex number z0z_0z0​ is such that 1∣z0−1∣\frac{1}{|z_0 - 1|}∣z0​−1∣1​ is the maximum of the set {1∣z−1∣:z∈S}\left\{ \frac{1}{|z - 1|} : z \in S \right\}{∣z−1∣1​:z∈S}, then the principal argument of 4−z0−z0‾z0−z0‾+2i\frac{4 - z_0 - \overline{z_0}}{z_0 - \overline{z_0} + 2i}z0​−z0​​+2i4−z0​−z0​​​ is
  1. (A)3π4\frac{3\pi}{4}43π​
  2. (B)π4\frac{\pi}{4}4π​
  3. (C)−π2-\frac{\pi}{2}−2π​
  4. (D)π2\frac{\pi}{2}2π​

Correct answer: (C)

Step-by-step solution →
Q40·MathematicsSingle correct
A line y=mx+1y = mx + 1y=mx+1 intersects the circle (x−3)2+(y+2)2=25(x - 3)^2 + (y + 2)^2 = 25(x−3)2+(y+2)2=25 at the points P and Q. If the midpoint of the line segment PQ has x-coordinate −35-\frac{3}{5}−53​, then which one of the following options is correct?
  1. (A)4≤m<64 \le m < 64≤m<6
  2. (B)−3≤m<−1-3 \le m < -1−3≤m<−1
  3. (C)2≤m<42 \le m < 42≤m<4
  4. (D)6≤m<86 \le m < 86≤m<8

Correct answer: (C)

Step-by-step solution →
Q41·MathematicsMultiple correct
Let α\alphaα and β\betaβ be the roots of x2−x−1=0x^2 - x - 1 = 0x2−x−1=0, with α>β\alpha > \betaα>β. For all positive integers n, define an=αn−βnα−βa_n = \frac{\alpha^n - \beta^n}{\alpha - \beta}an​=α−βαn−βn​, n≥1n \ge 1n≥1, b1=1b_1 = 1b1​=1 and bn=an−1+an+1b_n = a_{n-1} + a_{n+1}bn​=an−1​+an+1​, n≥2n \ge 2n≥2. Then which of the following options is/are correct?
  1. (A)∑n=1∞bn10n=889\sum_{n=1}^{\infty} \frac{b_n}{10^n} = \frac{8}{89}∑n=1∞​10nbn​​=898​
  2. (B)bn=αn+βnb_n = \alpha^n + \beta^nbn​=αn+βn for all n≥1n \ge 1n≥1
  3. (C)a1+a2+a3+.....+an=an+2−1a_1 + a_2 + a_3 + ..... + a_n = a_{n+2} - 1a1​+a2​+a3​+.....+an​=an+2​−1 for all n≥1n \ge 1n≥1
  4. (D)∑n=1∞an10n=1089\sum_{n=1}^{\infty} \frac{a_n}{10^n} = \frac{10}{89}∑n=1∞​10nan​​=8910​

Correct answer: (B), (C), (D)

Step-by-step solution →
Q42·MathematicsMultiple correct
In a non-right-angled triangle ΔPQR\Delta PQRΔPQR, let p, q, r denote the lengths of the sides opposite to the angles at P, Q, R respectively. The median from R meets the side PQ at S, the perpendicular from P meets the side QR at E, and RS and PE intersect at O. If p=3p = \sqrt{3}p=3​, q=1q = 1q=1, and the radius of the circumcircle of the ΔPQR\Delta PQRΔPQR equals 1, then which of the following options is/are correct?
  1. (A)length of OE=16OE = \frac{1}{6}OE=61​
  2. (B)Radius of incircle of ΔPQR=32(2−3)\Delta PQR = \frac{\sqrt{3}}{2}\left(2 - \sqrt{3}\right)ΔPQR=23​​(2−3​)
  3. (C)Length of RS=72RS = \frac{\sqrt{7}}{2}RS=27​​
  4. (D)Are of ΔSOE=312\Delta SOE = \frac{\sqrt{3}}{12}ΔSOE=123​​

Correct answer: (A), (B), (C)

Step-by-step solution →
Q43·MathematicsMultiple correct
Let Γ\GammaΓ denote a curve y=y(x)y = y(x)y=y(x) which is in the first quadrant and let the point (1, 0) lie on it. Let the tangent to Γ\GammaΓ at a point P intersect the y-axis at YPY_PYP​. If PYPPY_PPYP​ has length 1 for each point P on Γ\GammaΓ, then which of the following option is/are correct?
  1. (A)y=log⁡e(1+1−x2x)−1−x2y = \log_e\left(\frac{1 + \sqrt{1 - x^2}}{x}\right) - \sqrt{1 - x^2}y=loge​(x1+1−x2​​)−1−x2​
  2. (B)xy′+1−x2=0xy' + \sqrt{1 - x^2} = 0xy′+1−x2​=0
  3. (C)y=−log⁡e(1+1−x2x)+1−x2y = -\log_e\left(\frac{1 + \sqrt{1 - x^2}}{x}\right) + \sqrt{1 - x^2}y=−loge​(x1+1−x2​​)+1−x2​
  4. (D)xy′−1−x2=0xy' - \sqrt{1 - x^2} = 0xy′−1−x2​=0

Correct answer: (A), (B)

Step-by-step solution →
Q44·MathematicsMultiple correct
Let M=[01a1233b1]M = \begin{bmatrix} 0 & 1 & a \\ 1 & 2 & 3 \\ 3 & b & 1 \end{bmatrix}M=​013​12b​a31​​ and adj M=[−11−18−62−53−1]M = \begin{bmatrix} -1 & 1 & -1 \\ 8 & -6 & 2 \\ -5 & 3 & -1 \end{bmatrix}M=​−18−5​1−63​−12−1​​ where a and b area real numbers. Which of the following options is/are correct?
  1. (A)(adj M)−1+adj M−1=−M(\mathrm{adj}\ M)^{-1} + \mathrm{adj}\ M^{-1} = -M(adj M)−1+adj M−1=−M
  2. (B)If M[αβγ]=[123]M \begin{bmatrix} \alpha \\ \beta \\ \gamma \end{bmatrix} = \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix}M​αβγ​​=​123​​, then α−β+γ=3\alpha - \beta + \gamma = 3α−β+γ=3
  3. (C)det⁡(adj M2)=81\det(\mathrm{adj}\ M^2) = 81det(adj M2)=81
  4. (D)a+b=3a + b = 3a+b=3

Correct answer: (A), (B), (D)

Step-by-step solution →
Q45·MathematicsMultiple correct
Define the collections {E1,E2,E3,.......}\{E_1, E_2, E_3, .......\}{E1​,E2​,E3​,.......} of ellipses and {R1,R2,R3,...}\{R_1, R_2, R_3, ...\}{R1​,R2​,R3​,...} of rectangles as follows: E1:x29+y24=1E_1 : \frac{x^2}{9} + \frac{y^2}{4} = 1E1​:9x2​+4y2​=1; R1R_1R1​ : rectangle of largest area, with sides parallel to the axes, inscribed in E1E_1E1​; EnE_nEn​ : ellipse x2an2+y2bn2=1\frac{x^2}{a_n^2} + \frac{y^2}{b_n^2} = 1an2​x2​+bn2​y2​=1 of largest area inscribed in Rn−1R_{n-1}Rn−1​, n>1n > 1n>1; RnR_nRn​ : rectangle of largest area, with sides parallel to the axes, inscribed in EnE_nEn​, n>1n > 1n>1. Then which of the following options is/are correct?
  1. (A)∑n=1N(area of Rn)<24\sum_{n=1}^{N} \left(\text{area of } R_n\right) < 24∑n=1N​(area of Rn​)<24, for each positive integer N
  2. (B)The distance of a focus from the centre in E9E_9E9​ is 532\frac{\sqrt{5}}{32}325​​
  3. (C)The eccentricities of E18E_{18}E18​ and E19E_{19}E19​ are NOT equal
  4. (D)The length of latus rectum of E9E_9E9​ is 16\frac{1}{6}61​

Correct answer: (A), (D)

Step-by-step solution →
Q46·MathematicsMultiple correct
Let f:R→Rf : R \to Rf:R→R by given by f(x)={x5+5x4+10x3+10x2+3x+1,x<0;x2−x+1,0≤x<1;23x3−4x2+7x−83,1≤x<3;(x−2)log⁡e(x−2)−x+103,x≥3.f(x) = \begin{cases} x^5 + 5x^4 + 10x^3 + 10x^2 + 3x + 1, & x < 0; \\ x^2 - x + 1, & 0 \le x < 1; \\ \frac{2}{3}x^3 - 4x^2 + 7x - \frac{8}{3}, & 1 \le x < 3; \\ (x - 2)\log_e (x - 2) - x + \frac{10}{3}, & x \ge 3. \end{cases}f(x)=⎩⎨⎧​x5+5x4+10x3+10x2+3x+1,x2−x+1,32​x3−4x2+7x−38​,(x−2)loge​(x−2)−x+310​,​x<0;0≤x<1;1≤x<3;x≥3.​ Then which of the following options is/are correct?
  1. (A)f′f'f′ has a local maximum at x=1x = 1x=1
  2. (B)f′f'f′ is NOT differentiable at x=1x = 1x=1
  3. (C)f is onto
  4. (D)f is increasing on (−∞,0)(-\infty, 0)(−∞,0)

Correct answer: (A), (B), (C)

Step-by-step solution →
Q47·MathematicsMultiple correct
Let L1L_1L1​ and L2L_2L2​ denote the lines r⃗=i^+λ(−i^+2j^+2k^),λ∈R\vec{r} = \hat{i} + \lambda\left(-\hat{i} + 2\hat{j} + 2\hat{k}\right), \lambda \in Rr=i^+λ(−i^+2j^​+2k^),λ∈R and r⃗=μ(2i^−j^+2k^),μ∈R\vec{r} = \mu\left(2\hat{i} - \hat{j} + 2\hat{k}\right), \mu \in Rr=μ(2i^−j^​+2k^),μ∈R respectively. If L3L_3L3​ is a line which is perpendicular to both L1L_1L1​ and L2L_2L2​ and cuts both of them, then which of the following options describe (s) L3L_3L3​?
  1. (A)r⃗=29(4i^+j^+k^)+t(2i^+2j^−k^),t∈R\vec{r} = \frac{2}{9}\left(4\hat{i} + \hat{j} + \hat{k}\right) + t\left(2\hat{i} + 2\hat{j} - \hat{k}\right), t \in Rr=92​(4i^+j^​+k^)+t(2i^+2j^​−k^),t∈R
  2. (B)r⃗=13(2i^+k^)+t(2i^+2j^−k^),t∈R\vec{r} = \frac{1}{3}\left(2\hat{i} + \hat{k}\right) + t\left(2\hat{i} + 2\hat{j} - \hat{k}\right), t \in Rr=31​(2i^+k^)+t(2i^+2j^​−k^),t∈R
  3. (C)r⃗=29(2i^−j^+2k^)+t(2i^+2j^−k^),t∈R\vec{r} = \frac{2}{9}\left(2\hat{i} - \hat{j} + 2\hat{k}\right) + t\left(2\hat{i} + 2\hat{j} - \hat{k}\right), t \in Rr=92​(2i^−j^​+2k^)+t(2i^+2j^​−k^),t∈R
  4. (D)r⃗=t(2i^+2j^−k^),t∈R\vec{r} = t\left(2\hat{i} + 2\hat{j} - \hat{k}\right), t \in Rr=t(2i^+2j^​−k^),t∈R

Correct answer: (A), (B), (C)

Step-by-step solution →
Q48·MathematicsMultiple correct
There are three bags B1B_1B1​, B2B_2B2​ and B3B_3B3​. The bag B1B_1B1​ contains 5 red and 5 green balls, B2B_2B2​ contains 3 red and 5 green balls and B3B_3B3​ contains 5 red and 3 green balls. Bags B1B_1B1​, B2B_2B2​ and B3B_3B3​ have probabilities 310\frac{3}{10}103​, 310\frac{3}{10}103​ and 410\frac{4}{10}104​ respectively of being chosen. A bag is selected at random and a ball is chosen at random from the bag. Then which of the following options is/are correct?
  1. (A)Probability that the chosen ball is green equals 3980\frac{39}{80}8039​
  2. (B)Probability that the chosen ball is green, given that the selected bag is B3B_3B3​, equals 38\frac{3}{8}83​
  3. (C)Probability that the selected bag is B3B_3B3​ and the chosen ball is green equals 310\frac{3}{10}103​
  4. (D)Probability that the selected bag is B3B_3B3​, given that the chosen ball is green, equals 513\frac{5}{13}135​

Correct answer: (A), (B)

Step-by-step solution →
Q49·MathematicsNumerical
Let ω≠1\omega \ne 1ω=1 be a cube root of unity. Then the minimum of the set {∣a+bω+cω2∣2:a,b,c\{|a + b\omega + c\omega^2|^2 : a, b, c{∣a+bω+cω2∣2:a,b,c distinct non-zero integers}\}} equals ____

Correct answer: 3.00

Step-by-step solution →
Q50·MathematicsNumerical
If I=2π∫−π/4π/4dx(1+esin⁡x)(2−cos⁡2x)I = \frac{2}{\pi} \int_{-\pi/4}^{\pi/4} \frac{dx}{\left(1 + e^{\sin x}\right)\left(2 - \cos 2x\right)}I=π2​∫−π/4π/4​(1+esinx)(2−cos2x)dx​ then 27I227 I^227I2 equals ____

Correct answer: 4.00

Step-by-step solution →
Q51·MathematicsNumerical
Let S be the sample space of all 3×33 \times 33×3 matrices with entries from the set {0,1}\{0, 1\}{0,1}. Let the events E1E_1E1​ and E2E_2E2​ be given by E1={A∈S:det⁡A=0}E_1 = \{A \in S : \det A = 0\}E1​={A∈S:detA=0} and E2={A∈S:E_2 = \{A \in S :E2​={A∈S: sum of entries of A is 7}7\}7} If a matrix is chosen at random from S, then the conditional probability P(E1/E2)P(E_1/E_2)P(E1​/E2​) equals ____

Correct answer: 0.50

Step-by-step solution →
Q52·MathematicsNumerical
Let the point B be the reflection of the point A(2, 3) with respect to line 8x−6y−23=08x - 6y - 23 = 08x−6y−23=0. Let ΓA\Gamma_AΓA​ and ΓB\Gamma_BΓB​ be circles of radii 2 and 1 with centres A and B respectively. Let T be a common tangent to the circles ΓA\Gamma_AΓA​ and ΓB\Gamma_BΓB​ such that both the circles are on the same side of T. If C is the point of intersection of T and the line passing through A and B, then the length of the line segment AC is ____

Correct answer: 10.00

Step-by-step solution →
Q53·MathematicsNumerical
Let AP(a; d) denote the set of all the terms of an infinite arithmetic progression with first term a and common difference d>0d > 0d>0. If AP(1;3)∩AP(2;5)∩AP(3;7)=AP(a;d)AP(1; 3) \cap AP(2; 5) \cap AP(3; 7) = AP(a; d)AP(1;3)∩AP(2;5)∩AP(3;7)=AP(a;d) then a+da + da+d equals ____

Correct answer: 157.00

Step-by-step solution →
Q54·MathematicsNumerical
Three lines are given by r⃗=λi^,λ∈R\vec{r} = \lambda\hat{i}, \lambda \in Rr=λi^,λ∈R, r⃗=μ(i^+j^),μ∈R\vec{r} = \mu\left(\hat{i} + \hat{j}\right), \mu \in Rr=μ(i^+j^​),μ∈R and r⃗=v(i^+j^+k^),v∈R\vec{r} = v\left(\hat{i} + \hat{j} + \hat{k}\right), v \in Rr=v(i^+j^​+k^),v∈R. Let the lines cut the plane x+y+z=1x + y + z = 1x+y+z=1 at the points A, B and C respectively. If the area of the triangle ABC is Δ\DeltaΔ then the value of (6Δ)2(6\Delta)^2(6Δ)2 equals

Correct answer: 0.75

Step-by-step solution →

Chapters tested in this paper

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Geometrical Optics 172/186
  • Differential Equations 167/186
  • Probability 176/186
  • Chemical Bonding and Molecular Structure 151/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Circles 142/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Nuclei 116/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • Surface Chemistry 98/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Principles of Qualitative Analysis 58/186
  • Diazonium Salts and Reactions 53/186
  • States of Matter: Gases and Liquids 52/186
  • Reaction Mechanism 29/186
← 2019 Paper 2All papers2020 Paper 2 →

Attempt JEE Advanced 2019 Paper 1 under exam timing.

Advanced questions are multi-step, so a wrong answer rarely tells you which step broke. Jarvis works out where your reasoning failed and puts that exact gap back in front of you before the next paper.

Attempt this paper freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS