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JEE Advanced 2019 Paper 2 Question Paper with Answers

54 questions · Physics, Chemistry & Mathematics

The complete JEE Advanced 2019 Paper 2 paper — every question with its correct answer, tagged to the chapter it tests. Free to read, no account needed.

Physics
18
Chemistry
18
Mathematics
18

Physics — JEE Advanced 2019 Paper 2

Q1·PhysicsMultiple correct
In a Young's double slit experiment, the slit separation d is 0.3 mm and the screen distance D is 1 m. A parallel beam of light of wavelength 600 nm is incident on the slits at angle α\alphaα as shown in figure. On the screen, the point O is equidistant from the slits and distance PO is 11.0 mm. Which of the following statements(s) is/are correct ?
  1. (A)For α=0.36π\alpha = \frac{0.36}{\pi}α=π0.36​ degree, there will be destructive interference at point O.
  2. (B)Fringe spacing depends on α\alphaα.
  3. (C)For α=0.36π\alpha = \frac{0.36}{\pi}α=π0.36​ degree, there will be destructive interference at point P.
  4. (D)For α=0\alpha = 0α=0, there will be constructive interference at point P.

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsMultiple correct
A block of mass 2M is attached to a massless spring with spring-constant k. This block is connected to two other blocks of masses M and 2M using two massless pulleys and strings. The accelerations of the blocks are a1a_1a1​, a2a_2a2​ and a3a_3a3​ as shown in the figure. the system is released from rest with the spring in its unstretched state. The maximum extension of the spring is x0x_0x0​. Which of the following option(s) is/are correct? [g is the acceleration due to gravity. neglect friction]
  1. (A)a2−a1=a1−a3a_2 - a_1 = a_1 - a_3a2​−a1​=a1​−a3​
  2. (B)At an extension of x04\frac{x_0}{4}4x0​​ of the spring, the magnitude of acceleration of the block connected to the spring is 3g10\frac{3g}{10}103g​
  3. (C)x0=4Mgkx_0 = \frac{4Mg}{k}x0​=k4Mg​
  4. (D)When spring achieves an extension of x02\frac{x_0}{2}2x0​​ for the first time, the speed of the block connected to the spring is 3gM5k3g\sqrt{\frac{M}{5k}}3g5kM​​.

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsMultiple correct
A thin and uniform rod of mass M and length L is held vertical on a floor with large friction. The rod is released from rest so that it falls by rotating about its contact-point with the floor without slipping. Which of the following statement(s) is/are correct, when the rod makes an angle 60∘60^\circ60∘ with vertical ? [g is the acceleration due to gravity]
  1. (A)The radial acceleration of the rod's center of mass will be 3g4\frac{3g}{4}43g​
  2. (B)The angular speed of the rod will be 3g2L\sqrt{\frac{3g}{2L}}2L3g​​
  3. (C)The angular acceleration of the rod will be 2gL\frac{2g}{L}L2g​
  4. (D)The normal reaction force from the floor on the rod will be Mg16\frac{Mg}{16}16Mg​

Correct answer: (A), (B), (D)

Step-by-step solution →
Q4·PhysicsMultiple correct
A small particle of mass m moving inside a heavy, hollow and straight tube along the tube axis undergoes elastic collision at two ends. The tube has no friction and it is closed at one end by a flat surface while the other end is fitted with a heavy movable flat piston as shown in figure. When the distance of the piston from closed end is L=L0L = L_0L=L0​ the particle speed is v=v0v = v_0v=v0​. The piston is moved inward at a very low speed V such that V<<dLLv0V << \frac{dL}{L}v_0V<<LdL​v0​, where dL is the infinitesimal displacement of the piston. which of the following statement(s) is/are correct ?
  1. (A)The particle's kinetic energy increases by a factor of 4 when the piston is moved inward from L0L_0L0​ to 12L0\frac{1}{2}L_021​L0​.
  2. (B)After each collision with the piston, the particle speed increases by 2V.
  3. (C)If the piston moves inward by dL, the particle speed increases by 2vdLL2v\frac{dL}{L}2vLdL​
  4. (D)The rate at which the particle strikes the piston is v/L

Correct answer: (A), (B)

Step-by-step solution →
Q5·PhysicsMultiple correct
Three glass cylinders of equal height H = 30 cm and same refractive index n = 1.5 are placed on a horizontal surface as shown in figure. Cylinder I has a flat top, cylinder II has a convex top and cylinder III has a concave top. The radii of curvature of the two curved tops are same (R = 3m). If H1H_1H1​, H2H_2H2​ and H3H_3H3​ are the apparent depths of a point X on the bottom of the three cylinders, respectively, the correct statement(s) is/are:
  1. (A)H2>H1H_2 > H_1H2​>H1​
  2. (B)H2>H3H_2 > H_3H2​>H3​
  3. (C)H3>H1H_3 > H_1H3​>H1​
  4. (D)0.80.80.8 cm <(H2−H1)<0.9< (H_2 - H_1) < 0.9<(H2​−H1​)<0.9 cm

Correct answer: (A), (B)

Step-by-step solution →
Q6·PhysicsMultiple correct
An electric dipole with dipole moment p02(i^+j^)\frac{p_0}{\sqrt{2}}\left(\hat{i}+\hat{j}\right)2​p0​​(i^+j^​) is held fixed at the origin O in the presence of an uniform electric field of magnitude E0E_0E0​. If the potential is constant on a circle of radius R centered at the origin as shown in figure, then the correct statement(s) is/are : (ϵ0\epsilon_0ϵ0​ is permittivity of free space. R >> dipole size)
  1. (A)Total electric field at point A is E⃗A=2E0(i^+j^)\vec{E}_A = \sqrt{2}E_0\left(\hat{i}+\hat{j}\right)EA​=2​E0​(i^+j^​)
  2. (B)Total electric field at point B is E⃗B=0\vec{E}_B = 0EB​=0
  3. (C)R=(p04πϵ0E0)1/3R = \left(\frac{p_0}{4\pi\epsilon_0 E_0}\right)^{1/3}R=(4πϵ0​E0​p0​​)1/3
  4. (D)The magnitude of total electric field on any two points of the circle will be same.

Correct answer: (B), (C)

Step-by-step solution →
Q7·PhysicsMultiple correct
A free hydrogen atom after absorbing a photon of wavelength λa\lambda_aλa​ gets excited from the state n = 1 to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon of wavelength λe\lambda_eλe​. Let the change in momentum of atom due to the absorption and the emission are Δpa\Delta p_aΔpa​ and Δpe\Delta p_eΔpe​. respectively. If λaλe=15\frac{\lambda_a}{\lambda_e} = \frac{1}{5}λe​λa​​=51​, which of the option(s) is /are correct ? [Use hc = 1242 eV nm; 1 nm = 10−910^{-9}10−9m, h and c are Planck's constant and speed of light, respectively]
  1. (A)ΔpaΔpe=12\frac{\Delta p_a}{\Delta p_e} = \frac{1}{2}Δpe​Δpa​​=21​
  2. (B)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 14\frac{1}{4}41​
  3. (C)λe=418\lambda_e = 418λe​=418 nm
  4. (D)m = 2

Correct answer: (B), (D)

Step-by-step solution →
Q8·PhysicsMultiple correct
A mixture of ideal gas contains 5 moles of monatomic gas and 1 mole of rigid diatomic gas is initially at pressure P0P_0P0​, volume V0V_0V0​, and temperature T0T_0T0​. If the gas mixture is adiabatically compressed to a volume V04\frac{V_0}{4}4V0​​, then the correct statement(s) is /are, (Given 21.2=2.32^{1.2} = 2.321.2=2.3; 23.2=9.22^{3.2} = 9.223.2=9.2; R is gas constant)
  1. (A)Adiabatic constant of the gas mixture is 1.6
  2. (B)The final pressure of the gas mixture after compression is in between 9P09P_09P0​ and 10P010P_010P0​
  3. (C)The work ∣W∣|W|∣W∣ done during the process is 13RT013RT_013RT0​
  4. (D)The average kinetic energy of the gas mixture after compression is in between 18RT018RT_018RT0​ and 19RT019RT_019RT0​.

Correct answer: (A), (B), (C)

Step-by-step solution →
Q9·PhysicsNumerical
Suppose a 88226Ra^{226}_{88}\mathrm{Ra}88226​Ra nucleus at rest and in ground state undergoes α\alphaα-decay to a 86222Rn^{222}_{86}\mathrm{Rn}86222​Rn nucleus in its excited state. The kinetic energy of the emitted α\alphaα particle is found to be 4.44 MeV. 86222Rn^{222}_{86}\mathrm{Rn}86222​Rn nucleus then goes to its ground state by γ\gammaγ-decay. The energy of the emitted γ\gammaγ photon is ______keV. [Given: atomic mass of 88226Ra^{226}_{88}\mathrm{Ra}88226​Ra = 226.005 u, atomic mass of 86222Rn^{222}_{86}\mathrm{Rn}86222​Rn = 222.000 u, atomic mass of α\alphaα particle = 4.000 u, 1 u = 931 MeV/c2c^2c2, c is speed of the light]

Correct answer: 135.00

Step-by-step solution →
Q10·PhysicsNumerical
A ball is thrown from ground at an angle θ\thetaθ with horizontal and with an initial speed u0u_0u0​. For the resulting projectile motion, the magnitude of average velocity of the ball up to the point when it hits the ground for the first time is V1V_1V1​. After hitting the ground, the ball rebounds at the same angle θ\thetaθ but with a reduced speed of u0/αu_0/\alphau0​/α. Its motion continues for a long time as shown in figure. If the magnitude of average velocity of the ball for entire duration of motion is 0.8V10.8 V_10.8V1​, the value of α\alphaα is_________.

Correct answer: 4.00

Step-by-step solution →
Q11·PhysicsNumerical
A 10 cm long perfectly conducting wire PQ is moving with a velocity 1 cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1 Ω\OmegaΩ as shown in the figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x×10−3x \times 10^{-3}x×10−3 A, where the value of x is ________. [Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed. Given: e−1=0.37e^{-1} = 0.37e−1=0.37, where e is base of the natural logarithm]

Correct answer: 0.63

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Q12·PhysicsNumerical
A perfectly reflecting mirror of mass M mounted on a spring constitutes a spring-mass system of angular frequency Ω\OmegaΩ such that 4πMΩh=1024 m−2\frac{4\pi M\Omega}{h} = 10^{24}\ \mathrm{m}^{-2}h4πMΩ​=1024 m−2 with h as Planck's constant. N photons of wavelength λ=8π×10−6\lambda = 8\pi \times 10^{-6}λ=8π×10−6 m strike the mirror simultaneously at normal incidence such that the mirror gets displaced by 1 μ\muμm. If the value of N is x×1012x \times 10^{12}x×1012, then the value of x is __________. [Consider the spring as massless]

Correct answer: 1.00

Step-by-step solution →
Q13·PhysicsNumerical
A monochromatic light is incident from air on a refracting surface of prism of angle 75∘75^\circ75∘ and refractive index n0=3n_0 = \sqrt{3}n0​=3​. The other refracting surface of the prism is coated by a thin film of material of refractive index n as shown in figure. The light suffers total internal reflection at the coated prism surface for an incidence angle of θ≤60∘\theta \le 60^\circθ≤60∘. The value of n2n^2n2 is ________.

Correct answer: 1.50

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Q14·PhysicsNumerical
An optical bench has 1.5 m long scale having four equal divisions in each cm. While measuring the focal length of a convex lens, the lens is kept at 75 cm mark of the scale and the object pin is kept at 45 cm mark. The image of the object pin on the other side of the lens overlaps with image pin that is kept at 135 cm mark. In this experiment, the percentage error in the measurement of the focal length of the lens is________.

Correct answer: 1.39

Step-by-step solution →
Q15·PhysicsSingle correct
Answer the following by appropriately matching the list based on the information given in the paragraph. A musical instrument is made using four different metal strings, 1, 2, 3 and 4 with mass per unit length μ\muμ, 2μ2\mu2μ, 3μ3\mu3μ and 4μ4\mu4μ respectively. The instrument is played by vibrating the strings by varying the free length in between the range L0L_0L0​ and 2L02L_02L0​. It is found that in string-1 (μ\muμ) at free length L0L_0L0​ and tension T0T_0T0​ the fundamental mode frequency is f0f_0f0​. List-I gives the above four strings while list-II lists the magnitude of some quantity. If the tension in each string is T0T_0T0​, the correct match for the highest fundamental frequency in f0f_0f0​ units will be,
List-IList-II
I.String-1 (μ\muμ)P.111
II.String-2 (2μ2\mu2μ)Q.12\frac{1}{2}21​
III.String-3 (3μ3\mu3μ)R.12\frac{1}{\sqrt{2}}2​1​
IV.String-4 (4μ4\mu4μ)S.13\frac{1}{\sqrt{3}}3​1​
T.316\frac{3}{16}163​
U.116\frac{1}{16}161​
  1. (A)I →\to→ P, II →\to→ R, III →\to→ S, IV →\to→ Q
  2. (B)I →\to→ Q, II →\to→ S, III →\to→ R, IV →\to→ P
  3. (C)I →\to→ P, II →\to→ Q, III →\to→ T, IV →\to→ S
  4. (D)I →\to→ Q, II →\to→ P, III →\to→ R, IV →\to→ T

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
Answer the following by appropriately matching the list based on the information given in the paragraph. A musical instrument is made using four different metal strings, 1, 2, 3 and 4 with mass per unit length μ\muμ, 2μ2\mu2μ, 3μ3\mu3μ and 4μ4\mu4μ respectively. The instrument is played by vibrating the strings by varying the free length in between the range L0L_0L0​ and 2L02L_02L0​. It is found that in string-1 (μ\muμ) at free length L0L_0L0​ and tension T0T_0T0​ the fundamental mode frequency is f0f_0f0​. List-I gives the above four strings while list-II lists the magnitude of some quantity. The length of the string 1, 2, 3 and 4 are kept fixed at L0L_0L0​, 3L02\frac{3L_0}{2}23L0​​, 5L04\frac{5L_0}{4}45L0​​ and 7L04\frac{7L_0}{4}47L0​​, respectively. Strings 1, 2, 3 and 4 are vibrated at their 1st1^{st}1st, 3rd3^{rd}3rd, 5th5^{th}5th and 14th14^{th}14th harmonics, respectively such that all the strings have same frequency. The correct match for the tension in the four strings in the units of T0T_0T0​ will be,
List-IList-II
I.String-1 (μ\muμ)P.111
II.String-2 (2μ2\mu2μ)Q.12\frac{1}{2}21​
III.String-3 (3μ3\mu3μ)R.12\frac{1}{\sqrt{2}}2​1​
IV.String-4 (4μ4\mu4μ)S.13\frac{1}{\sqrt{3}}3​1​
T.316\frac{3}{16}163​
U.116\frac{1}{16}161​
  1. (A)I →\to→ P, II →\to→ Q, III →\to→ T, IV →\to→ U
  2. (B)I →\to→ P, II →\to→ Q, III →\to→ R, IV →\to→ T
  3. (C)I →\to→ P, II →\to→ R, III →\to→ T, IV →\to→ U
  4. (D)I →\to→ T, II →\to→ Q, III →\to→ R, IV →\to→ U

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
Answer the following by appropriately matching the list based on the information given in the paragraph. In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔXT\Delta XTΔX, where T is temperature of the system and ΔX\Delta XΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=32Rln⁡(TTA)+Rln⁡(VVA)X = \frac{3}{2}R\ln\left(\frac{T}{T_A}\right) + R\ln\left(\frac{V}{V_A}\right)X=23​Rln(TA​T​)+Rln(VA​V​). Here, R is gas constant, V is volume of gas. TAT_ATA​ and VAV_AVA​ are constants. The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities. If the process carried out on one mole of monatomic ideal gas is as shown in figure in the PV-diagram with P0V0=13RT0P_0V_0 = \frac{1}{3}RT_0P0​V0​=31​RT0​, the correct match is,
List-IList-II
I.Work done by the system in process 1→2→31 \to 2 \to 31→2→3P.13RT0ln⁡2\frac{1}{3}RT_0\ln 231​RT0​ln2
II.Change in internal energy in process 1→2→31 \to 2 \to 31→2→3Q.13RT0\frac{1}{3}RT_031​RT0​
III.Heat absorbed by the system in process 1→2→31 \to 2 \to 31→2→3R.RT0RT_0RT0​
IV.Heat absorbed by the system in process 1→21 \to 21→2S.43RT0\frac{4}{3}RT_034​RT0​
T.13RT0(3+ln⁡2)\frac{1}{3}RT_0(3+\ln 2)31​RT0​(3+ln2)
U.56RT0\frac{5}{6}RT_065​RT0​
  1. (A)I →\to→ Q, II →\to→ R, III →\to→ S, IV →\to→ U
  2. (B)I →\to→ Q, II →\to→ S, III →\to→ R, IV →\to→ U
  3. (C)I →\to→ Q, II →\to→ R, III →\to→ P, IV →\to→ U
  4. (D)I →\to→ S, II →\to→ R, III →\to→ Q, IV →\to→ T

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
Answer the following by appropriately matching the list based on the information given in the paragraph. In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔXT\Delta XTΔX, where T is temperature of the system and ΔX\Delta XΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=32Rln⁡(TTA)+Rln⁡(VVA)X = \frac{3}{2}R\ln\left(\frac{T}{T_A}\right) + R\ln\left(\frac{V}{V_A}\right)X=23​Rln(TA​T​)+Rln(VA​V​). Here, R is gas constant, V is volume of gas. TAT_ATA​ and VAV_AVA​ are constants. The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities. If the process on one mole of monatomic ideal gas is as shown in the TV-diagram with P0V0=13RT0P_0V_0 = \frac{1}{3}RT_0P0​V0​=31​RT0​, the correct match is,
List-IList-II
I.Work done by the system in process 1→2→31 \to 2 \to 31→2→3P.13RT0ln⁡2\frac{1}{3}RT_0\ln 231​RT0​ln2
II.Change in internal energy in process 1→2→31 \to 2 \to 31→2→3Q.13RT0\frac{1}{3}RT_031​RT0​
III.Heat absorbed by the system in process 1→2→31 \to 2 \to 31→2→3R.RT0RT_0RT0​
IV.Heat absorbed by the system in process 1→21 \to 21→2S.43RT0\frac{4}{3}RT_034​RT0​
T.13RT0(3+ln⁡2)\frac{1}{3}RT_0(3+\ln 2)31​RT0​(3+ln2)
U.56RT0\frac{5}{6}RT_065​RT0​
  1. (A)I →\to→ P, II →\to→ T, III →\to→ Q, IV →\to→ T
  2. (B)I →\to→ S, II →\to→ T, III →\to→ Q, IV →\to→ U
  3. (C)I →\to→ P, II →\to→ R, III →\to→ T, IV →\to→ S
  4. (D)I →\to→ P, II →\to→ R, III →\to→ T, IV →\to→ P

Correct answer: (D)

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Chemistry — JEE Advanced 2019 Paper 2

Q19·ChemistryMultiple correct
Choose the correct option(s) that give(s) an aromatic compound as the major product
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B), (D)

Step-by-step solution →
Q20·ChemistryMultiple correct
Consider the following reactions (unbalanced) Zn + hot conc. H2_{2}2​SO4_{4}4​ ⟶\longrightarrow⟶ G + R + X Zn + conc.NaOH ⟶\longrightarrow⟶ T + Q G + H2_{2}2​S + NH4_{4}4​OH ⟶\longrightarrow⟶ Z(a precipitate) + X + Y Choose the correct option(s)
  1. (A)The oxidation state of Zn in T is +1
  2. (B)R is a V-shaped molecule
  3. (C)Z is dirty white in colour
  4. (D)Bond order of Q is 1 in its ground state

Correct answer: (B), (C), (D)

Step-by-step solution →
Q21·ChemistryMultiple correct
Which of the following reactions produce(s) propane as a major product?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (B)

Step-by-step solution →
Q22·ChemistryMultiple correct
Choose the correct option(s) from the following:
  1. (A)Cellulose has only α\alphaα-D-glucose units that are joined by glycosidic linkages
  2. (B)Teflon is prepared by heating tetrafluoroethene in presence of a persulphate catalyst at high pressure
  3. (C)Natural rubber is polyisoprene containing \textit{trans} alkene units
  4. (D)Nylon-6 has amide linkages

Correct answer: (B), (D)

Step-by-step solution →
Q23·ChemistryMultiple correct
The ground state energy of hydrogen atom is −-− 13.6 eV. Consider an electronic state ψ\psiψ of He+^{+}+ whose energy, azumuthal quantum number and magnetic quantum number are -3.4 eV, 2 and 0, respectively. Which of the following statement(s) is(are) true for the state ψ\psiψ ?
  1. (A)It is a 4d state
  2. (B)It has 2 angular nodes
  3. (C)It has 3 radial nodes
  4. (D)The nuclear charge experienced by the electron in this state is less than 2e, where e is the magnitude of the electronic charge

Correct answer: (A), (B)

Step-by-step solution →
Q24·ChemistryMultiple correct
The cyanide process of gold extraction involves leaching out gold from its ore with CN−^{-}− in the presence of Q in water to form R. Subsequently, R is treated with T to obtain Au and Z. Choose the correct option(s)
  1. (A)Z is [Zn(CN)4]2−\left[\mathrm{Zn(CN)}_{4}\right]^{2-}[Zn(CN)4​]2−
  2. (B)T is Zn
  3. (C)R is [Au(CN)4]−\left[\mathrm{Au(CN)}_{4}\right]^{-}[Au(CN)4​]−
  4. (D)Q is O2_{2}2​

Correct answer: (A), (B), (D)

Step-by-step solution →
Q25·ChemistryMultiple correct
With reference to \textit{aqua regia}, choose the correct option(s)
  1. (A)The yellow colour of \textit{aqua regia} is due to the presence of NOCl and Cl2_{2}2​
  2. (B)\textit{Aqua regia} is prepared by mixing conc. HCl and conc. HNO3_{3}3​ in 3 : 1 (\textit{v/v}) ratio
  3. (C)Reaction of gold with \textit{aqua regia} produces an anion having Au in +3 oxidation state
  4. (D)Reaction of gold with \textit{aqua regia} produces NO2_{2}2​ in the absence of air

Correct answer: (A), (C)

Step-by-step solution →
Q26·ChemistryMultiple correct
Choose the correct option(s) for the following reaction sequence Consider Q, R and S as major products
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (D)

Step-by-step solution →
Q27·ChemistryNumerical
Total number of isomers, considering both structural and stereoisomers, of cyclic ethers with the molecular formula C4_{4}4​H8_{8}8​O is________

Correct answer: 10.00

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Q28·ChemistryNumerical
The mole fraction of urea in an aqueous urea solution containing 900 g of water is 0.05. If the density of the solution is 1.2 g cm−3^{-3}−3, the molarity of urea solution is_______ (Given data: Molar masses of urea and water are 60 g mol−1^{-1}−1 and 18 g mol−1^{-1}−1, respectively)

Correct answer: 2.98

Step-by-step solution →
Q29·ChemistryNumerical
Total number of \textit{cis} N-Mn-Cl bond angles (that is, Mn −-− N and Mn −-− Cl bonds in \textit{cis} positions) present in a molecule of \textit{cis}-[Mn(en)2_{2}2​Cl2_{2}2​] complex is______(en = NH2_{2}2​CH2_{2}2​CH2_{2}2​NH2_{2}2​)

Correct answer: 6.00

Step-by-step solution →
Q30·ChemistryNumerical
The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3_{3}3​ to a compound with the highest oxidation state of sulphur is______ (Given data : Molar mass of water = 18 g mol−1^{-1}−1)

Correct answer: 288.00

Step-by-step solution →
Q31·ChemistryNumerical
The decomposition reaction 2N2O5(g)→Δ2N2O4(g)+O2(g)2\mathrm{N}_{2}\mathrm{O}_{5}\left(g\right) \xrightarrow{\Delta} 2\mathrm{N}_{2}\mathrm{O}_{4}\left(g\right) + \mathrm{O}_{2}\left(g\right)2N2​O5​(g)Δ​2N2​O4​(g)+O2​(g) is started in a closed cylinder under isothermal isochoric condition at an initial pressure of 1 atm. After Y ×\times× 103^{3}3 s, the pressure inside the cylinder is found to be 1.45 atm. If the rate constant of the reaction is 5 ×\times× 10−4^{-4}−4 s−1^{-1}−1, assuming ideal gas behaviour, the value of \textbf{Y} is________

Correct answer: 2.30

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Q32·ChemistryNumerical
Total number of hydroxyl groups present in a molecule of the major product \textbf{P} is__________

Correct answer: 6.00

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Q33·ChemistrySingle correct
Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following, List-I contains some quantities for the nth^{th}th orbit of the atom and List-II contains options showing how they depend on n. Which of the following options has the correct combination considering List-I and List-II?
LIST-ILIST-II
I.Radius of the nth^{th}th orbitP.∝n−2\propto n^{-2}∝n−2
II.Angular momentum of the electron in the nth^{th}th orbitQ.∝n−1\propto n^{-1}∝n−1
III.Kinetic energy of the electron in the nth^{th}th orbitR.∝n0\propto n^{0}∝n0
IV.Potential energy of the electron in the nth^{th}th orbitS.∝n1\propto n^{1}∝n1
T.∝n2\propto n^{2}∝n2
U.∝n1/2\propto n^{1/2}∝n1/2
  1. (A)(III), (P)
  2. (B)(IV), (U)
  3. (C)(III), (S)
  4. (D)(IV), (Q)

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following, List-I contains some quantities for the nth^{th}th orbit of the atom and List-II contains options showing how they depend on n. Which of the following options has the correct combination considering List-I and List-II?
LIST-ILIST-II
I.Radius of the nth^{th}th orbitP.∝n−2\propto n^{-2}∝n−2
II.Angular momentum of the electron in the nth^{th}th orbitQ.∝n−1\propto n^{-1}∝n−1
III.Kinetic energy of the electron in the nth^{th}th orbitR.∝n0\propto n^{0}∝n0
IV.Potential energy of the electron in the nth^{th}th orbitS.∝n1\propto n^{1}∝n1
T.∝n2\propto n^{2}∝n2
U.∝n1/2\propto n^{1/2}∝n1/2
  1. (A)(I), (T)
  2. (B)(II), (R)
  3. (C)(I), (P)
  4. (D)(II), (Q)

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
Answer the following by appropriately matching the lists based on the information given in the paragraph List-I includes starting materials and reagents of selected chemical reactions. List-II gives structures of compounds that may be formed as intermediate products and/or final products from the reactions of List-I. Which of the following options has the correct combination considering List-I and List-II?
LIST-ILIST-II
I.see figureP.see figure
II.see figureQ.see figure
III.see figureR.see figure
IV.see figureS.see figure
T.see figure
U.see figure
  1. (A)(II), (P), (S), (T)
  2. (B)(II), (P), (S), (U)
  3. (C)(I), (S), (Q), (R)
  4. (D)(I), (Q), (T), (U)

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
Answer the following by appropriately matching the lists based on the information given in the paragraph List-I includes starting materials and reagents of selected chemical reactions. List-II gives structures of compounds that may be formed as intermediate products and/or final products from the reactions of List-I. Which of the following options has the correct combination considering List-I and List-II?
LIST-ILIST-II
I.see figureP.see figure
II.see figureQ.see figure
III.see figureR.see figure
IV.see figureS.see figure
T.see figure
U.see figure
  1. (A)(IV), (Q), (U)
  2. (B)(IV), (Q), (R)
  3. (C)(III), (S), (R)
  4. (D)(III), (T), (U)

Correct answer: (B)

Step-by-step solution →

Mathematics — JEE Advanced 2019 Paper 2

Q37·MathematicsMultiple correct
Three lines L1:r⃗=λi^, λ∈RL_1 : \vec{r} = \lambda\hat{i},\ \lambda \in \mathbb{R}L1​:r=λi^, λ∈R L2:r⃗=k^+μj^, μ∈RL_2 : \vec{r} = \hat{k} + \mu\hat{j},\ \mu \in \mathbb{R}L2​:r=k^+μj^​, μ∈R and L3:r⃗=i^+j^+νk^, ν∈RL_3 : \vec{r} = \hat{i} + \hat{j} + \nu\hat{k},\ \nu \in \mathbb{R}L3​:r=i^+j^​+νk^, ν∈R are given. For which point(s) Q on L2L_2L2​ can we find a point P on L1L_1L1​ and a point R on L3L_3L3​ so that P, Q and R are collinear?
  1. (A)k^−12j^\hat{k} - \dfrac{1}{2}\hat{j}k^−21​j^​
  2. (B)k^+12j^\hat{k} + \dfrac{1}{2}\hat{j}k^+21​j^​
  3. (C)k^\hat{k}k^
  4. (D)k^+j^\hat{k} + \hat{j}k^+j^​

Correct answer: (A), (B)

Step-by-step solution →
Q38·MathematicsMultiple correct
Let x∈Rx \in \mathbb{R}x∈R and let P=[111022003]P = \begin{bmatrix} 1 & 1 & 1 \\ 0 & 2 & 2 \\ 0 & 0 & 3 \end{bmatrix}P=​100​120​123​​, Q=[2xx040xx6]Q = \begin{bmatrix} 2 & x & x \\ 0 & 4 & 0 \\ x & x & 6 \end{bmatrix}Q=​20x​x4x​x06​​ and R=PQP−1R = PQP^{-1}R=PQP−1 Then which of the following options is/are correct?
  1. (A)For x=0x = 0x=0, if R[1ab]=6[1ab]R\begin{bmatrix} 1 \\ a \\ b \end{bmatrix} = 6\begin{bmatrix} 1 \\ a \\ b \end{bmatrix}R​1ab​​=6​1ab​​, then a+b=5a + b = 5a+b=5
  2. (B)For x=1x = 1x=1, there exists a unit vector αi^+βj^+γk^\alpha\hat{i} + \beta\hat{j} + \gamma\hat{k}αi^+βj^​+γk^ for which R[αβγ]=[000]R\begin{bmatrix} \alpha \\ \beta \\ \gamma \end{bmatrix} = \begin{bmatrix} 0 \\ 0 \\ 0 \end{bmatrix}R​αβγ​​=​000​​
  3. (C)det⁡R=det⁡[2xx040xx5]+8\det R = \det\begin{bmatrix} 2 & x & x \\ 0 & 4 & 0 \\ x & x & 5 \end{bmatrix} + 8detR=det​20x​x4x​x05​​+8, for all x∈Rx \in \mathbb{R}x∈R
  4. (D)There exists a real number xxx such that PQ=QPPQ = QPPQ=QP

Correct answer: (A), (C)

Step-by-step solution →
Q39·MathematicsMultiple correct
For non–negative integers n, let f(n)=∑k=0nsin⁡(k+1n+2π)sin⁡(k+2n+2π)∑k=0nsin⁡2(k+1n+2π)f(n) = \dfrac{\displaystyle\sum_{k=0}^{n} \sin\left(\dfrac{k+1}{n+2}\pi\right)\sin\left(\dfrac{k+2}{n+2}\pi\right)}{\displaystyle\sum_{k=0}^{n} \sin^{2}\left(\dfrac{k+1}{n+2}\pi\right)}f(n)=k=0∑n​sin2(n+2k+1​π)k=0∑n​sin(n+2k+1​π)sin(n+2k+2​π)​ Assuming cos⁡−1x\cos^{-1}xcos−1x takes values in [0,π][0, \pi][0,π], which of the following options is/are correct?
  1. (A)f(4)=32f(4) = \dfrac{\sqrt{3}}{2}f(4)=23​​
  2. (B)If α=tan⁡(cos⁡−1f(6))\alpha = \tan(\cos^{-1}f(6))α=tan(cos−1f(6)), then α2+2α−1=0\alpha^{2} + 2\alpha - 1 = 0α2+2α−1=0
  3. (C)sin⁡(7 cos⁡−1f(5))=0\sin(7\,\cos^{-1}f(5)) = 0sin(7cos−1f(5))=0
  4. (D)lim⁡n→∞f(n)=12\lim\limits_{n \to \infty} f(n) = \dfrac{1}{2}n→∞lim​f(n)=21​

Correct answer: (A), (B), (C)

Step-by-step solution →
Q40·MathematicsMultiple correct
For a∈Ra \in \mathbb{R}a∈R ∣a∣>1|a| > 1∣a∣>1, let lim⁡n→∞(1+23+....+n3n7/3(1(an+1)2+1(an+2)2+...+1(an+n)2))=54\lim\limits_{n \to \infty}\left( \dfrac{1 + \sqrt[3]{2} + .... + \sqrt[3]{n}}{n^{7/3}\left( \dfrac{1}{(an+1)^{2}} + \dfrac{1}{(an+2)^{2}} + ... + \dfrac{1}{(an+n)^{2}} \right)} \right) = 54n→∞lim​​n7/3((an+1)21​+(an+2)21​+...+(an+n)21​)1+32​+....+3n​​​=54 Then the possible value(s) of a is/are
  1. (A)8
  2. (B)−6-6−6
  3. (C)7
  4. (D)−9-9−9

Correct answer: (A), (D)

Step-by-step solution →
Q41·MathematicsMultiple correct
Let f(x)=sin⁡πxx2f(x) = \dfrac{\sin \pi x}{x^{2}}f(x)=x2sinπx​, x>0x > 0x>0 Let x1<x2<x3<...<xn<....x_1 < x_2 < x_3 < ... < x_n < ....x1​<x2​<x3​<...<xn​<.... be all the points of local maximum of f and y1<y2<y3<....<yn<....y_1 < y_2 < y_3 < .... < y_n < ....y1​<y2​<y3​<....<yn​<.... be all the points of local minimum of f. Then which of the following options is/are correct?
  1. (A)x1<y1x_1 < y_1x1​<y1​
  2. (B)∣xn−yn∣>1|x_n - y_n| > 1∣xn​−yn​∣>1 for every n
  3. (C)xn∈(2n, 2n+12)x_n \in \left(2n,\ 2n + \dfrac{1}{2}\right)xn​∈(2n, 2n+21​) for every n
  4. (D)xn+1−xn>2x_{n+1} - x_n > 2xn+1​−xn​>2 for every n

Correct answer: (B), (C), (D)

Step-by-step solution →
Q42·MathematicsMultiple correct
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be given by f(x)=(x−1)(x−2)(x−5)f(x) = (x - 1)(x - 2)(x - 5)f(x)=(x−1)(x−2)(x−5). Define F(x)=∫0xf(t) dtF(x) = \displaystyle\int_{0}^{x} f(t)\, dtF(x)=∫0x​f(t)dt, x>0x > 0x>0 Then which of the following options is/are correct?
  1. (A)F(x)≠0F(x) \neq 0F(x)=0 for all x∈(0,5)x \in (0, 5)x∈(0,5)
  2. (B)F has a local minimum at x=1x = 1x=1
  3. (C)F has a local maximum at x=2x = 2x=2
  4. (D)F has two local maxima and one local minimum in (0,∞)(0, \infty)(0,∞)

Correct answer: (A), (B), (C)

Step-by-step solution →
Q43·MathematicsMultiple correct
Let P1=I=[100010001]P_1 = I = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}P1​=I=​100​010​001​​, P2=[100001010]P_2 = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0 \end{bmatrix}P2​=​100​001​010​​ P3=[010100001]P_3 = \begin{bmatrix} 0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1 \end{bmatrix}P3​=​010​100​001​​ P4=[010001100]P_4 = \begin{bmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0 \end{bmatrix}P4​=​001​100​010​​, P5=[001100010]P_5 = \begin{bmatrix} 0 & 0 & 1 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \end{bmatrix}P5​=​010​001​100​​, P6=[001010100]P_6 = \begin{bmatrix} 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \end{bmatrix}P6​=​001​010​100​​ and X=∑k=16Pk[213102321]PkTX = \displaystyle\sum_{k=1}^{6} P_k \begin{bmatrix} 2 & 1 & 3 \\ 1 & 0 & 2 \\ 3 & 2 & 1 \end{bmatrix} P_k^{T}X=k=1∑6​Pk​​213​102​321​​PkT​ where PkTP_k^{T}PkT​ denotes the transpose of the matrix PkP_kPk​. Then which of the following options is/are correct?
  1. (A)X−30IX - 30IX−30I is an invertible matrix
  2. (B)X is a symmetric matrix
  3. (C)The sum of diagonal entries of X is 18
  4. (D)If X[111]=α[111]X\begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \alpha\begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix}X​111​​=α​111​​, then α=30\alpha = 30α=30

Correct answer: (B), (C), (D)

Step-by-step solution →
Q44·MathematicsMultiple correct
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be a function. We say that f has PROPERTY 1 if lim⁡h→0f(h)−f(0)∣h∣\lim\limits_{h \to 0} \dfrac{f(h) - f(0)}{\sqrt{|h|}}h→0lim​∣h∣​f(h)−f(0)​ exists and is finite, and PROPERTY 2 if lim⁡h→0f(h)−f(0)h2\lim\limits_{h \to 0} \dfrac{f(h) - f(0)}{h^{2}}h→0lim​h2f(h)−f(0)​ exists and if finite. Then which of the following options is/are correct?
  1. (A)f(x)=x∣x∣f(x) = x|x|f(x)=x∣x∣ has PROPERTY 2
  2. (B)f(x)=sin⁡xf(x) = \sin xf(x)=sinx has PROPERTY 2
  3. (C)f(x)=∣x∣f(x) = |x|f(x)=∣x∣ has PROPERTY 1
  4. (D)f(x)=x2/3f(x) = x^{2/3}f(x)=x2/3 has PROPERTY 1

Correct answer: (C), (D)

Step-by-step solution →
Q45·MathematicsNumerical
The value of the integral ∫0π/23cos⁡θ(cos⁡θ+sin⁡θ)5 dθ\displaystyle\int_{0}^{\pi/2} \dfrac{3\sqrt{\cos\theta}}{\left(\sqrt{\cos\theta} + \sqrt{\sin\theta}\right)^{5}}\, d\theta∫0π/2​(cosθ​+sinθ​)53cosθ​​dθ equals ____

Correct answer: 0.50

Step-by-step solution →
Q46·MathematicsNumerical
Let a⃗=2i^+j^−k^\vec{a} = 2\hat{i} + \hat{j} - \hat{k}a=2i^+j^​−k^ and b⃗=i^+2j^+k^\vec{b} = \hat{i} + 2\hat{j} + \hat{k}b=i^+2j^​+k^ be two vectors. Consider a vector c⃗=αa⃗+βb⃗\vec{c} = \alpha\vec{a} + \beta\vec{b}c=αa+βb, α, β∈R\alpha,\ \beta \in \mathbb{R}α, β∈R. If the projection of c⃗\vec{c}c on the vector (a⃗+b⃗)\left(\vec{a} + \vec{b}\right)(a+b) is 323\sqrt{2}32​, then the minimum value of (c⃗−(a⃗×b⃗))⋅c⃗\left(\vec{c} - \left(\vec{a} \times \vec{b}\right)\right)\cdot\vec{c}(c−(a×b))⋅c equals ____

Correct answer: 18.00

Step-by-step solution →
Q47·MathematicsNumerical
Five persons A, B, C, D and E are seated in a circular arrangement. If each of them is given a hat of one of the three colours red, blue and green, then the number of ways of distributing the hats such that the persons seated in adjacent seats get different coloured hats is ______

Correct answer: 30.00

Step-by-step solution →
Q48·MathematicsNumerical
Suppose det⁡[∑k=0nk∑k=0nnCkk2∑k=0nnCkk∑k=0nnCk3k]=0\det \begin{bmatrix} \displaystyle\sum_{k=0}^{n} k & \displaystyle\sum_{k=0}^{n} {}^{n}C_k k^{2} \\ \displaystyle\sum_{k=0}^{n} {}^{n}C_k k & \displaystyle\sum_{k=0}^{n} {}^{n}C_k 3^{k} \end{bmatrix} = 0det​k=0∑n​kk=0∑n​nCk​k​k=0∑n​nCk​k2k=0∑n​nCk​3k​​=0 holds for some positive integer n. Then ∑k=0nnCkk+1\displaystyle\sum_{k=0}^{n} \dfrac{{}^{n}C_k}{k+1}k=0∑n​k+1nCk​​ equals. ____

Correct answer: 6.20

Step-by-step solution →
Q49·MathematicsNumerical
Let ∣x∣|x|∣x∣ denote the number of elements in a set X. Let S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}S={1,2,3,4,5,6} be a sample space, where each element is equally likely to occur. If A and B are independent events associated with S, then the number of ordered pairs (A, B) such that 1≤∣B∣<∣A∣1 \le |B| < |A|1≤∣B∣<∣A∣, equals ______

Correct answer: 422.00

Step-by-step solution →
Q50·MathematicsNumerical
The value of sec⁡−1(14∑k=010sec⁡(7π12+kπ2)sec⁡(7π12+(k+1)π2))\sec^{-1}\left( \dfrac{1}{4}\displaystyle\sum_{k=0}^{10} \sec\left(\dfrac{7\pi}{12} + \dfrac{k\pi}{2}\right)\sec\left(\dfrac{7\pi}{12} + \dfrac{(k+1)\pi}{2}\right) \right)sec−1(41​k=0∑10​sec(127π​+2kπ​)sec(127π​+2(k+1)π​)) in the interval [−π4, 3π4]\left[-\dfrac{\pi}{4},\ \dfrac{3\pi}{4}\right][−4π​, 43π​] equals ____

Correct answer: 0.00

Step-by-step solution →
Q51·MathematicsSingle correct
Answer the following by appropriately matching the lists based on the information given in the paragraph Let f(x)=sin⁡(πcos⁡x)f(x) = \sin(\pi \cos x)f(x)=sin(πcosx) and g(x)=cos⁡(2πsin⁡x)g(x) = \cos(2\pi \sin x)g(x)=cos(2πsinx) be two functions defined for x>0x > 0x>0. Define the following sets whose elements are written in the increasing order: X={x:f(x)=0}X = \{x : f(x) = 0\}X={x:f(x)=0}, Y={x:f′(x)=0}Y = \{x : f'(x) = 0\}Y={x:f′(x)=0}, Z={x:g(x)=0}Z = \{x : g(x) = 0\}Z={x:g(x)=0}, W={x:g′(x)=0}W = \{x : g'(x) = 0\}W={x:g′(x)=0} List – I contains the set X, Y, Z and W. List – II contains some information regarding these sets. Which of the following is the only CORRECT combination?
List – IList – II
I.XP.⊇{π2, 3π2, 4π, 7π}\supseteq\left\{\dfrac{\pi}{2},\ \dfrac{3\pi}{2},\ 4\pi,\ 7\pi\right\}⊇{2π​, 23π​, 4π, 7π}
II.YQ.an arithmetic progression
III.ZR.NOT an arithmetic progression
IV.WS.⊇{π6, 7π6, 13π6}\supseteq\left\{\dfrac{\pi}{6},\ \dfrac{7\pi}{6},\ \dfrac{13\pi}{6}\right\}⊇{6π​, 67π​, 613π​}
T.⊇{π3, 2π3, π}\supseteq\left\{\dfrac{\pi}{3},\ \dfrac{2\pi}{3},\ \pi\right\}⊇{3π​, 32π​, π}
U.⊇{π6, 3π4}\supseteq\left\{\dfrac{\pi}{6},\ \dfrac{3\pi}{4}\right\}⊇{6π​, 43π​}
  1. (A)(II), (R), (S)
  2. (B)(I), (Q), (U)
  3. (C)(II), (Q), (T)
  4. (D)(I), (P), (R)

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correct
Answer the following by appropriately matching the lists based on the information given in the paragraph Let f(x)=sin⁡(πcos⁡x)f(x) = \sin(\pi \cos x)f(x)=sin(πcosx) and g(x)=cos⁡(2πsin⁡x)g(x) = \cos(2\pi \sin x)g(x)=cos(2πsinx) be two functions defined for x>0x > 0x>0. Define the following sets whose elements are written in the increasing order: X={x:f(x)=0}X = \{x : f(x) = 0\}X={x:f(x)=0}, Y={x:f′(x)=0}Y = \{x : f'(x) = 0\}Y={x:f′(x)=0}, Z={x:g(x)=0}Z = \{x : g(x) = 0\}Z={x:g(x)=0}, W={x:g′(x)=0}W = \{x : g'(x) = 0\}W={x:g′(x)=0} List – I contains the set X, Y, Z and W. List – II contains some information regarding these sets. Which of the following is the only CORRECT combination?
List – IList – II
I.XP.⊇{π2, 3π2, 4π, 7π}\supseteq\left\{\dfrac{\pi}{2},\ \dfrac{3\pi}{2},\ 4\pi,\ 7\pi\right\}⊇{2π​, 23π​, 4π, 7π}
II.YQ.an arithmetic progression
III.ZR.NOT an arithmetic progression
IV.WS.⊇{π6, 7π6, 13π6}\supseteq\left\{\dfrac{\pi}{6},\ \dfrac{7\pi}{6},\ \dfrac{13\pi}{6}\right\}⊇{6π​, 67π​, 613π​}
T.⊇{π3, 2π3, π}\supseteq\left\{\dfrac{\pi}{3},\ \dfrac{2\pi}{3},\ \pi\right\}⊇{3π​, 32π​, π}
U.⊇{π6, 3π4}\supseteq\left\{\dfrac{\pi}{6},\ \dfrac{3\pi}{4}\right\}⊇{6π​, 43π​}
  1. (A)(IV), (P), (R), (S)
  2. (B)(III), (P), (Q), (U)
  3. (C)(IV), (Q), (T)
  4. (D)(III), (R), (U)

Correct answer: (A)

Step-by-step solution →
Q53·MathematicsSingle correct
Answer the following by appropriately matching the lists based on the information given in the paragraph Let the circles C1:x2+y2=9C_1 : x^{2} + y^{2} = 9C1​:x2+y2=9 and C2:(x−3)2+(y−4)2=16C_2 : (x - 3)^{2} + (y - 4)^{2} = 16C2​:(x−3)2+(y−4)2=16, intersect at the points X and Y. Suppose that another circle C3:(x−h)2+(y−k)2=r2C_3 : (x - h)^{2} + (y - k)^{2} = r^{2}C3​:(x−h)2+(y−k)2=r2 satisfies and following conditions: (i) centre of C3C_3C3​ is collinear with the centres of C1C_1C1​ and C2C_2C2​ (ii) C1C_1C1​ and C2C_2C2​ both lie inside C3C_3C3​, and (iii) C3C_3C3​ touches C1C_1C1​ at M and C2C_2C2​ at N. Let the line through X and Y intersect C3C_3C3​ at Z and W, and let a common tangent of C1C_1C1​ and C3C_3C3​ be a tangent to the parabola x2=8αyx^{2} = 8\alpha yx2=8αy. There are some expressions given in the List–I whose values are given in List–II below: Which of the following is the only CORRECT combination?
List – IList – II
I.2h+k2h + k2h+kP.6
II.Length of ZWLength of XY\dfrac{\text{Length of ZW}}{\text{Length of XY}}Length of XYLength of ZW​Q.6\sqrt{6}6​
III.Area of triangle MZNArea of triaangle ZMW\dfrac{\text{Area of triangle MZN}}{\text{Area of triaangle ZMW}}Area of triaangle ZMWArea of triangle MZN​R.54\dfrac{5}{4}45​
IV.α\alphaαS.215\dfrac{21}{5}521​
T.262\sqrt{6}26​
U.103\dfrac{10}{3}310​
  1. (A)(II), (T)
  2. (B)(II), (Q)
  3. (C)(I), (U)
  4. (D)(I), (S)

Correct answer: (B)

Step-by-step solution →
Q54·MathematicsSingle correct
Answer the following by appropriately matching the lists based on the information given in the paragraph Let the circles C1:x2+y2=9C_1 : x^{2} + y^{2} = 9C1​:x2+y2=9 and C2:(x−3)2+(y−4)2=16C_2 : (x - 3)^{2} + (y - 4)^{2} = 16C2​:(x−3)2+(y−4)2=16, intersect at the points X and Y. Suppose that another circle C3:(x−h)2+(y−k)2=r2C_3 : (x - h)^{2} + (y - k)^{2} = r^{2}C3​:(x−h)2+(y−k)2=r2 satisfies and following conditions: (i) centre of C3C_3C3​ is collinear with the centres of C1C_1C1​ and C2C_2C2​ (ii) C1C_1C1​ and C2C_2C2​ both lie inside C3C_3C3​, and (iii) C3C_3C3​ touches C1C_1C1​ at M and C2C_2C2​ at N. Let the line through X and Y intersect C3C_3C3​ at Z and W, and let a common tangent of C1C_1C1​ and C3C_3C3​ be a tangent to the parabola x2=8αyx^{2} = 8\alpha yx2=8αy. There are some expressions given in the List–I whose values are given in List–II below: Which of the following is the only INCORRECT combination?
List – IList – II
I.2h+k2h + k2h+kP.6
II.Length of ZWLength of XY\dfrac{\text{Length of ZW}}{\text{Length of XY}}Length of XYLength of ZW​Q.6\sqrt{6}6​
III.Area of triangle MZNArea of triaangle ZMW\dfrac{\text{Area of triangle MZN}}{\text{Area of triaangle ZMW}}Area of triaangle ZMWArea of triangle MZN​R.54\dfrac{5}{4}45​
IV.α\alphaαS.215\dfrac{21}{5}521​
T.262\sqrt{6}26​
U.103\dfrac{10}{3}310​
  1. (A)(IV), (S)
  2. (B)(III), (R)
  3. (C)(IV), (U)
  4. (D)(I), (P)

Correct answer: (A)

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Chapters tested in this paper

  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Application of Derivatives 139/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Hydrocarbons 126/186
  • Trigonometric Functions 144/186
  • Chemical Kinetics 169/186
  • Atomic Structure 161/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Nuclei 116/186
  • Waves 109/186
  • Atoms 112/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • Inverse Trigonometric Functions 93/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Polymers 64/186
  • Carboxylic Acids and Derivatives 54/186
  • Isomerism 51/186
  • Aromaticity 22/186
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