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JEE Advanced 2020 Paper 1 Question Paper with Answers

54 questions · Physics, Chemistry & Mathematics

The complete JEE Advanced 2020 Paper 1 paper — every question with its correct answer, tagged to the chapter it tests. Free to read, no account needed.

Physics
18
Chemistry
18
Mathematics
18

Physics — JEE Advanced 2020 Paper 1

Q1·PhysicsSingle correct
A football of radius R is kept on a hole of radius r (r<R)(r < R)(r<R) made on a plank kept horizontally. One end of the plank is now lifted so that it gets tilted making an angle θ\thetaθ from the horizontal as shown in the figure below. The maximum value of θ\thetaθ so that the football does not start rolling down the plank satisfies (figure is schematic and not drawn to scale) -
  1. (A)sin⁡θ=rR\sin\theta = \frac{r}{R}sinθ=Rr​
  2. (B)tan⁡θ=rR\tan\theta = \frac{r}{R}tanθ=Rr​
  3. (C)sin⁡θ=r2R\sin\theta = \frac{r}{2R}sinθ=2Rr​
  4. (D)cos⁡θ=r2R\cos\theta = \frac{r}{2R}cosθ=2Rr​

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
A light disc made of aluminium (a nonmagnetic material) is kept horizontally and is free to rotate about its axis as shown in the figure. A strong magnet is held vertically at a point above the disc away from its axis. On revolving the magnet about the axis of the disc, the disc will (figure is schematic and not drawn to scale)-
  1. (A)rotate in the direction opposite to the direction of magnet's motion
  2. (B)rotate in the same direction as the direction of magnet's motion
  3. (C)not rotate and its temperature will remain unchanged
  4. (D)not rotate but its temperature will slowly rise

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
A small roller of diameter 20 cm has an axle of diameter 10 cm (see figure below on the left). It is on a horizontal floor and a meter scale is positioned horizontally on its axle with one edge of the scale on top of the axle (see figure on the right). The scale is now pushed slowly on the axle so that it moves without slipping on the axle, and the roller starts rolling without slipping. After the roller has moved 50 cm, the position of the scale will look like (figures are schematic and not drawn to scale)-
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A circular coil of radius R and N turns has negligible resistance. As shown in the schematic figure, its two ends are connected to two wires and it is hanging by those wires with its plane being vertical. The wires are connected to a capacitor with charge Q through a switch. The coil is in a horizontal uniform magnetic field BoB_oBo​ parallel to the plane of the coil. When the switch is closed, the capacitor gets discharged through the coil in a very short time. By the time the capacitor is discharged fully, magnitude of the angular momentum gained by the coil will be (assume that the discharge time is so short that the coil has hardly rotated during this time)-
  1. (A)π2NQBoR2\frac{\pi}{2}NQB_oR^22π​NQBo​R2
  2. (B)πNQBoR2\pi NQB_oR^2πNQBo​R2
  3. (C)2πNQBoR22\pi NQB_oR^22πNQBo​R2
  4. (D)4πNQBoR24\pi NQB_oR^24πNQBo​R2

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
A parallel beam of light strikes a piece of transparent glass having cross section as shown in the figure below. Correct shape of the emergent wavefront will be (figures are schematic and not drawn to scale)-
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
An open-ended U-tube of uniform cross-sectional area contains water (density 10310^{3}103 kg m−3m^{-3}m−3). Initially the water level stands at 0.29 m from the bottom in each arm. Kerosene oil (a water-immiscible liquid) of density 800 kg m−3m^{-3}m−3 is added to the left arm until its length is 0.1 m, as shown in the schematic figure below. The ratio (h1h2)\left(\frac{h_1}{h_2}\right)(h2​h1​​) of the heights of the liquid in the two arms is-
  1. (A)1514\frac{15}{14}1415​
  2. (B)3533\frac{35}{33}3335​
  3. (C)76\frac{7}{6}67​
  4. (D)54\frac{5}{4}45​

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsMultiple correct
A particle of mass m moves in circular orbits with potential energy V(r)=FrV(r) = FrV(r)=Fr, where F is a positive constant and r is its distance from the origin. Its energies are calculated using the Bohr model. If the radius of the particle's orbit is denoted by R and its speed and energy are denoted by v and E, respectively, then for the nthn^{th}nth orbit (here h is the Planck's constant)-
  1. (A)R∝n1/3R \propto n^{1/3}R∝n1/3 and v∝n2/3v \propto n^{2/3}v∝n2/3
  2. (B)R∝n2/3R \propto n^{2/3}R∝n2/3 and v∝n1/3v \propto n^{1/3}v∝n1/3
  3. (C)E=32(n2h2F24π2m)1/3E = \frac{3}{2}\left(\frac{n^2h^2F^2}{4\pi^2m}\right)^{1/3}E=23​(4π2mn2h2F2​)1/3
  4. (D)E=2(n2h2F24π2m)1/3E = 2\left(\frac{n^2h^2F^2}{4\pi^2m}\right)^{1/3}E=2(4π2mn2h2F2​)1/3

Correct answer: (B), (C)

Step-by-step solution →
Q8·PhysicsMultiple correct
The filament of a light bulb has surface area 64 mm2mm^2mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer to be circular with radius 3 mm. Then (Take Stefan-Boltzmann constant = 5.67 × 10−810^{-8}10−8 Wm−2K−4Wm^{-2}K^{-4}Wm−2K−4, Wien's displacement constant = 2.90 × 10−310^{-3}10−3 m-K, Planck's constant = 6.63 × 10−3410^{-34}10−34 Js, speed of light in vacuum= 3.00 × 10810^{8}108 ms−1ms^{-1}ms−1)-
  1. (A)power radiated by the filament is in the range 642 W to 645 W
  2. (B)radiated power entering into one eye of the observer is in the range 3.15 × 10−810^{-8}10−8 W to 3.25 × 10−810^{-8}10−8 W
  3. (C)the wavelength corresponding to the maximum intensity of light is 1160 nm
  4. (D)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 101110^{11}1011 to 2.85 × 101110^{11}1011

Correct answer: (B), (C), (D)

Step-by-step solution →
Q9·PhysicsMultiple correct
Sometimes it is convenient to construct a system of units so that all quantities can be expressed in terms of only one physical quantity. In one such system, dimensions of different quantities are given in terms of a quantity X as follows: [position] = [Xα][X^{\alpha}][Xα]; [speed] = [Xβ][X^{\beta}][Xβ]; [acceleration] = [Xp][X^{p}][Xp]; [linear momentum] = [Xq][X^{q}][Xq]; [force] = [Xr][X^{r}][Xr]. Then -
  1. (A)α+p=2β\alpha + p = 2\betaα+p=2β
  2. (B)p+q−r=βp + q - r = \betap+q−r=β
  3. (C)p−q+r=αp - q + r = \alphap−q+r=α
  4. (D)p+q+r=βp + q + r = \betap+q+r=β

Correct answer: (A), (B)

Step-by-step solution →
Q10·PhysicsMultiple correct
A uniform electric field, E⃗=−4003y^\vec{E} = -400\sqrt{3}\hat{y}E=−4003​y^​ NC−1NC^{-1}NC−1 is applied in a region. A charged particle of mass m carrying positive charge q is projected in this region with an initial speed of 210×1062\sqrt{10} \times 10^{6}210​×106 ms−1ms^{-1}ms−1. This particle is aimed to hit a target T, which is 5 m away from its entry point into the field as shown schematically in the figure. Take qm=1010\frac{q}{m} = 10^{10}mq​=1010 Ckg−1Ckg^{-1}Ckg−1. Then-
  1. (A)the particle will hit T if projected at an angle 45º from the horizontal
  2. (B)the particle will hit T if projected either at an angle 30º or 60º from the horizontal
  3. (C)time taken by the particle to hit T could be 56\sqrt{\frac{5}{6}}65​​ μs as well as 52\sqrt{\frac{5}{2}}25​​ μs
  4. (D)time taken by the particle to hit T is 53\sqrt{\frac{5}{3}}35​​ μs

Correct answer: (B), (C)

Step-by-step solution →
Q11·PhysicsMultiple correct
Shown in the figure is a semicircular metallic strip that has thickness t and resistivity ρ. Its inner radius is R1R_1R1​ and outer radius is R2R_2R2​. If a voltage V0V_0V0​ is applied between its two ends, a current I flows in it. In addition, it is observed that a transverse voltage ΔV\Delta VΔV develops between its inner and outer surfaces due to purely kinetic effects of moving electrons (ignore any role of the magnetic field due to the current). Then (figure is schematic and not drawn to scale)-
  1. (A)I=V0tπρln⁡(R2R1)I = \frac{V_0t}{\pi\rho}\ln\left(\frac{R_2}{R_1}\right)I=πρV0​t​ln(R1​R2​​)
  2. (B)the outer surface is at a higher voltage than the inner surface
  3. (C)the outer surface is at a lower voltage than the inner surface
  4. (D)ΔV∝I2\Delta V \propto I^2ΔV∝I2

Correct answer: (A), (C), (D)

Step-by-step solution →
Q12·PhysicsMultiple correct
As shown schematically in the figure, two vessels contain water solutions (at temperature TTT) of potassium permanganate (KMnO4KMnO_4KMnO4​) of different concentrations n1n_1n1​ and n2n_2n2​ (n1>n2n_1 > n_2n1​>n2​) molecules per unit volume with Δn=(n1−n2)≪n1\Delta n = (n_1 - n_2) \ll n_1Δn=(n1​−n2​)≪n1​. When they are connected by a tube of small length ℓ\ellℓ and cross-sectional area S, KMnO4KMnO_4KMnO4​ starts to diffuse from the left to the right vessel through the tube. Consider the collection of molecules to behave as dilute ideal gases and the difference in their partial pressure in the two vessels causing the diffusion. The speed v of the molecules is limited by the viscous force −βv-\beta v−βv on each molecule, where β is a constant. Neglecting all terms of the order (Δn)2(\Delta n)^2(Δn)2, which of the following is/are correct? (kBk_BkB​ is the Boltzmann constant)-
  1. (A)the force causing the molecules to move across the tube is ΔnkBTS\Delta nk_BTSΔnkB​TS
  2. (B)force balance implies n1βvℓ=ΔnkBTn_1\beta v\ell = \Delta nk_BTn1​βvℓ=ΔnkB​T
  3. (C)total number of molecules going across the tube per sec is (Δnℓ)(kBTβ)S\left(\frac{\Delta n}{\ell}\right)\left(\frac{k_BT}{\beta}\right)S(ℓΔn​)(βkB​T​)S
  4. (D)rate of molecules getting transferred through the tube does not change with time

Correct answer: (A), (B), (C)

Step-by-step solution →
Q13·PhysicsNumerical
Put a uniform meter scale horizontally on your extended index fingers with the left one at 0.00 cm and the right one at 90.00 cm. When you attempt to move both the fingers slowly towards the center, initially only the left finger slips with respect to the scale and the right finger does not. After some distance, the left finger stops and the right one starts slipping. Then the right finger stops at a distance xRx_RxR​ from the center (50.00 cm) of the scale and the left one starts slipping again. This happens because of the difference in the frictional forces on the two fingers. If the coefficients of static and dynamic friction between the fingers and the scale are 0.40 and 0.32, respectively, the value of xRx_RxR​ (in cm) is ______.

Correct answer: 25.60

Step-by-step solution →
Q14·PhysicsNumerical
When water is filled carefully in a glass, one can fill it to a height h above the rim of the glass due to the surface tension of water. To calculate h just before water starts flowing, model the shape of the water above the rim as a disc of thickness h having semicircular edges, as shown schematically in the figure. When the pressure of water at the bottom of this disc exceeds what can be withstood due to the surface tension, the water surface breaks near the rim and water starts flowing from there. If the density of water, its surface tension and the acceleration due to gravity are 10310^{3}103 kg m−3m^{-3}m−3, 0.07 Nm−1Nm^{-1}Nm−1 and 10 ms−2ms^{-2}ms−2, respectively, the value of h (in mm) is _________.

Correct answer: 3.65 to 3.85

Step-by-step solution →
Q15·PhysicsNumerical
One end of a spring of negligible unstretched length and spring constant k is fixed at the origin (0,0). A point particle of mass m carrying a positive charge q is attached at its other end. The entire system is kept on a smooth horizontal surface. When a point dipole p⃗\vec{p}p​ pointing towards the charge q is fixed at the origin, the spring gets stretched to a length ℓ\ellℓ and attains a new equilibrium position (see figure below). If the point mass is now displaced slightly by Δℓ≪ℓ\Delta\ell \ll \ellΔℓ≪ℓ from its equilibrium position and released, it is found to oscillate at frequency 1δkm\frac{1}{\delta}\sqrt{\frac{k}{m}}δ1​mk​​. The value of δ is ______.

Correct answer: 0.50 OR 3.13 TO 3.15

Step-by-step solution →
Q16·PhysicsNumerical
Consider one mole of helium gas enclosed in a container at initial pressure P1P_1P1​ and volume V1V_1V1​. It expands isothermally to volume 4V14V_14V1​. After this, the gas expands adiabatically and its volume becomes 32V132V_132V1​. The work done by the gas during isothermal and adiabatic expansion processes are WisoW_{iso}Wiso​ and WadiaW_{adia}Wadia​, respectively. If the ratio WisoWadia=fln⁡2\frac{W_{iso}}{W_{adia}} = f\ln2Wadia​Wiso​​=fln2, then fff is _________.

Correct answer: 1.77 to 1.79

Step-by-step solution →
Q17·PhysicsNumerical
A stationary tuning fork is in resonance with an air column in a pipe. If the tuning fork is moved with a speed of 2 ms−1ms^{-1}ms−1 in front of the open end of the pipe and parallel to it, the length of the pipe should be changed for the resonance to occur with the moving tuning fork. If the speed of sound in air is 320 ms−1ms^{-1}ms−1, the smallest value of the percentage change required in the length of the pipe is ____________.

Correct answer: 0.62 to 0.64

Step-by-step solution →
Q18·PhysicsNumerical
A circular disc of radius RRR carries surface charge density σ(r)=σ0(1−rR)\sigma(r) = \sigma_0\left(1 - \frac{r}{R}\right)σ(r)=σ0​(1−Rr​), where σ0\sigma_0σ0​ is a constant and rrr is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is ϕ0\phi_0ϕ0​. Electric flux through another spherical surface of radius R4\frac{R}{4}4R​ and concentric with the disc is ϕ\phiϕ. Then the ratio ϕ0ϕ\frac{\phi_0}{\phi}ϕϕ0​​ is_________.

Correct answer: 6.40

Step-by-step solution →

Chemistry — JEE Advanced 2020 Paper 1

Q19·ChemistrySingle correct
If the distribution of molecular speeds of a gas is as per the figure shown below, then the ratio of the most probable, the average and the roots mean square speeds, respectively, is
  1. (A)1 : 1 : 1
  2. (B)1 : 1 : 1.224
  3. (C)1 : 1.128 : 1.224
  4. (D)1 : 1.128 : 1

Correct answer: (B)

Step-by-step solution →
Q20·ChemistrySingle correct
Which of the following liberates O2O_2O2​ upon hydrolysis?
  1. (A)Pb3O4Pb_3O_4Pb3​O4​
  2. (B)KO2KO_2KO2​
  3. (C)Na2O2Na_2O_2Na2​O2​
  4. (D)Li2O2Li_2O_2Li2​O2​

Correct answer: (B)

Step-by-step solution →
Q21·ChemistrySingle correct
A colorless aqueous solution contains nitrates of two metals, X and Y. When it was added to an aqueous solution of NaCl, a white precipitate was formed. This precipitate was found to be partly soluble in hot water to give a residue P and a solution Q. The residue P was soluble in aq. NH3NH_3NH3​ and also in excess sodium thiosulfate. The hot solution Q gave a yellow precipitate with KI. The metals X and Y, respectively, are
  1. (A)Ag and Pb
  2. (B)Ag and Cd
  3. (C)Cd and Pb
  4. (D)Cd and Zn

Correct answer: (A)

Step-by-step solution →
Q22·ChemistrySingle correct
Newman projections P, Q, R and S are shown below : Which one of the following options represents identical molecules ?
  1. (A)P and Q
  2. (B)Q and S
  3. (C)Q and R
  4. (D)R and S

Correct answer: (C)

Step-by-step solution →
Q23·ChemistrySingle correct
Which one of the following structures has the IUPAC name 3-ethynyl-2-hydroxy-4-methylhex-3-en-5-ynoic acid ?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q24·ChemistrySingle correct
The Fischer projection of D-erythrose is shown below. D-Erythrose and its isomers are listed as P, Q, R, and S in Column-I. Choose the correct relationship of P, Q, R, and S with D-erythrose from Column II.
Column-IColumn-II
P.see figure1.Diastereomer
Q.see figure2.Identical
R.see figure3.Enantiomer
S.see figure
  1. (A)P → 2, Q → 3, R → 2, S → 2
  2. (B)P → 3, Q → 1, R → 1, S → 2
  3. (C)P → 2, Q → 1, R → 1, S → 3
  4. (D)P → 2, Q → 3, R → 3, S → 1

Correct answer: (C)

Step-by-step solution →
Q25·ChemistryMultiple correct
In thermodynamics the P-V work done is given by w=−∫dV Pextw = -\int dV\, P_{ext}w=−∫dVPext​ . For a system undergoing a particular process, the work done is , w=−∫dV(RTV−b−aV2)w = -\int dV \left( \frac{RT}{V-b} - \frac{a}{V^2} \right)w=−∫dV(V−bRT​−V2a​). This equation is applicable to a
  1. (A)System that satisfies the van der Waals equation of state.
  2. (B)Process that is reversible and isothermal.
  3. (C)Process that is reversible and adiabatic.
  4. (D)Process that is irreversible and at constant pressure.

Correct answer: (A), (B), (C)

Step-by-step solution →
Q26·ChemistryMultiple correct
With respect to the compounds I-V, choose the correct statement(s).
  1. (A)The acidity of compound I is due to delocalization in the conjugate base.
  2. (B)The conjugate base of compound IV is aromatic.
  3. (C)Compound II becomes more acidic, when it has a −NO2-NO_2−NO2​ substituent.
  4. (D)The acidity of compounds follows the order I > IV > V > II > III.

Correct answer: (A), (B), (C)

Step-by-step solution →
Q27·ChemistryMultiple correct
In the reaction scheme shown below Q, R and S are the major products. The correct structure of
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B), (D)

Step-by-step solution →
Q28·ChemistryMultiple correct
Choose the correct statement(s) among the following :
  1. (A)[FeCl4]−[FeCl_4]^-[FeCl4​]− has tetrahedral geometry.
  2. (B)[Co(en)(NH3)2Cl2]+[Co(en)(NH_3)_2Cl_2]^+[Co(en)(NH3​)2​Cl2​]+ has 2 geometrical isomers.
  3. (C)[FeCl4]−[FeCl_4]^-[FeCl4​]− has higher spin-only magnetic moment than [Co(en)(NH3)2Cl2]+[Co(en)(NH_3)_2Cl_2]^+[Co(en)(NH3​)2​Cl2​]+.
  4. (D)The cobalt ion in [Co(en)(NH3)2Cl2]+[Co(en)(NH_3)_2Cl_2]^+[Co(en)(NH3​)2​Cl2​]+ has sp3d2sp^3d^2sp3d2 hybridization.

Correct answer: (A), (C)

Step-by-step solution →
Q29·ChemistryMultiple correct
With respect to hypochlorite, chlorate and perchlorate ions, choose the correct statement(s).
  1. (A)The hypochlorite ion is the strongest conjugate base.
  2. (B)The molecular shape of only chlorate ion is influenced by the lone pair of electrons of Cl.
  3. (C)The hypochlorite and chlorate ions disproportionate to give rise to identical set of ions.
  4. (D)The hypochlorite ion oxidizes the sulfite ion.

Correct answer: (A), (B), (D)

Step-by-step solution →
Q30·ChemistryMultiple correct
The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has smaller ionic radius. Choose the correct statement(s).
  1. (A)The empirical formula of the compound is MX.
  2. (B)The cation M and anion X have different coordination geometries.
  3. (C)The ratio of M-X bond length to the cubic unit cell edge length is 0.866.
  4. (D)The ratio of the ionic radii of cation M to anion X is 0.414.

Correct answer: (A), (C)

Step-by-step solution →
Q31·ChemistryNumerical
5.00 mL of 0.10 M oxalic acid solution taken in a conical flask is titrated against NaOH from a burette using phenolphthalein indicator. The volume of NaOH required for the appearance of permanent faint pink color is tabulated below for five experiments. What is the concentration, in molarity, of the NaOH solution ?
Exp. No.Vol. of NaOH (mL)
112.5
210.5
39.0
49.0
59.0

Correct answer: 0.11

Step-by-step solution →
Q32·ChemistryNumerical
Consider the reaction A ⇌ B at 1000 K. At time t', the temperature of the system was increased to 2000 K and the system was allowed to reach equilibrium. Throughout this experiment the partial pressure of A was maintained at 1 bar. Given below is the plot of the partial pressure of B with time. What is the ratio of the standard Gibbs energy of the reaction at 1000 K to that at 2000 K?

Correct answer: 0.25

Step-by-step solution →
Q33·ChemistryNumerical
Consider a 70% efficient hydrogen-oxygen fuel cell working under standard conditions at 1 bar and 298 K. Its cell reaction is H2(g)+12O2(g)→H2O(ℓ)H_2 (g) + \frac{1}{2} O_2(g) \rightarrow H_2O(\ell)H2​(g)+21​O2​(g)→H2​O(ℓ). The work derived from the cell on the consumption of 1.0×10−31.0 \times 10^{-3}1.0×10−3 mol of H2(g)H_2(g)H2​(g) is used to compress 1.00 mol of a monoatomic ideal gas in a thermally insulted container. What is the change in the temperature (in K) of the ideal gas ? The standard reduction potentials for the two half-cells are given below. O2(g)+4 H+(aq.)+4e−→2H2O (ℓ)O_2(g) + 4\,H^+ (aq.) + 4e^- \rightarrow 2H_2O\,(\ell)O2​(g)+4H+(aq.)+4e−→2H2​O(ℓ) , E∘=1.23E^\circ = 1.23E∘=1.23 V, 2H+(aq.)+2e−→H2(g)2H^+ (aq.) + 2e^- \rightarrow H_2(g)2H+(aq.)+2e−→H2​(g), E∘=0.00E^\circ = 0.00E∘=0.00 V. Use F=96500F = 96500F=96500 C mol−1mol^{-1}mol−1, R=8.314R = 8.314R=8.314 J mol−1K−1mol^{-1}K^{-1}mol−1K−1

Correct answer: 13.00 - 13.60

Step-by-step solution →
Q34·ChemistryNumerical
Aluminium reacts with sulfuric acid to form aluminium sulfate and hydrogen. What is the volume of hydrogen gas in liters (L) produced at 300 K and 1.0 atm pressure, when 5.4 g of aluminium and 50.0 mL of 5.0 M sulfuric acid are combined for the reaction ? (Use molar mass of aluminium as 27.0 g mol−1mol^{-1}mol−1 , R=0.082R = 0.082R=0.082 atm L mol−1 K−1mol^{-1}\,K^{-1}mol−1K−1)

Correct answer: 6.00 - 6.20

Step-by-step solution →
Q35·ChemistryNumerical
92238U^{238}_{92}U92238​U is known to undergo radioactive decay to form 82206Pb^{206}_{82}Pb82206​Pb by emitting alpha and beta particles. A rock initially contained 68×10−668 \times 10^{-6}68×10−6 g of 92238U^{238}_{92}U92238​U. If the number of alpha particles that it would emit during its radioactive decay of 92238U^{238}_{92}U92238​U to 82206Pb^{206}_{82}Pb82206​Pb in three half-lives is Z×1018Z \times 10^{18}Z×1018 , then what is the value of Z ?

Correct answer: 1.19 - 1.21

Step-by-step solution →
Q36·ChemistryNumerical
In the following reaction, compound Q is obtained from compound P via an ionic intermediate What is the degree of unsaturation of Q ?

Correct answer: 18.00

Step-by-step solution →

Mathematics — JEE Advanced 2020 Paper 1

Q37·MathematicsSingle correct
Suppose a, b denote the distinct real roots of the quadratic polynomial x2+20x−2020x^{2} + 20x - 2020x2+20x−2020 and suppose c,d denote the distinct complex roots of the quadratic polynomial x2−20x+2020x^{2} - 20x + 2020x2−20x+2020. Then the value of ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d)ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d) is
  1. (A)000
  2. (B)800080008000
  3. (C)808080808080
  4. (D)160001600016000

Correct answer: (D)

Step-by-step solution →
Q38·MathematicsSingle correct
If the function f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R is defined by f(x)=∣x∣(x−sin⁡x)f(x) = |x|(x - \sin x)f(x)=∣x∣(x−sinx), then which of the following statements is TRUE ?
  1. (A)fff is one-one, but NOT onto
  2. (B)fff is onto, but NOT one-one
  3. (C)fff is BOTH one-one and onto
  4. (D)fff is NEITHER one-one NOR onto

Correct answer: (C)

Step-by-step solution →
Q39·MathematicsSingle correct
Let the functions f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R and g:R→Rg : \mathbb{R} \to \mathbb{R}g:R→R be defined by f(x)=ex−1−e−∣x−1∣f(x) = e^{x-1} - e^{-|x-1|}f(x)=ex−1−e−∣x−1∣ and g(x)=12(ex−1+e1−x)g(x) = \frac{1}{2}\left(e^{x-1} + e^{1-x}\right)g(x)=21​(ex−1+e1−x). Then the area of the region in the first quadrant bounded by the curves y=f(x)y = f(x)y=f(x), y=g(x)y = g(x)y=g(x) and x=0x = 0x=0 is
  1. (A)(2−3)+12(e−e−1)\left(2 - \sqrt{3}\right) + \frac{1}{2}\left(e - e^{-1}\right)(2−3​)+21​(e−e−1)
  2. (B)(2+3)+12(e−e−1)\left(2 + \sqrt{3}\right) + \frac{1}{2}\left(e - e^{-1}\right)(2+3​)+21​(e−e−1)
  3. (C)(2−3)+12(e+e−1)\left(2 - \sqrt{3}\right) + \frac{1}{2}\left(e + e^{-1}\right)(2−3​)+21​(e+e−1)
  4. (D)(2+3)+12(e+e−1)\left(2 + \sqrt{3}\right) + \frac{1}{2}\left(e + e^{-1}\right)(2+3​)+21​(e+e−1)

Correct answer: (A)

Step-by-step solution →
Q40·MathematicsSingle correct
Let a, b and λ\lambdaλ be positive real numbers. Suppose P is an end point of the latus rectum of the parabola y2=4λxy^{2} = 4\lambda xy2=4λx, and suppose the ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1a2x2​+b2y2​=1 passes through the point P. If the tangents to the parabola and the ellipse at the point P are perpendicular to each other, then the eccentricity of the ellipse is
  1. (A)12\frac{1}{\sqrt{2}}2​1​
  2. (B)12\frac{1}{2}21​
  3. (C)13\frac{1}{3}31​
  4. (D)25\frac{2}{5}52​

Correct answer: (A)

Step-by-step solution →
Q41·MathematicsSingle correct
Let C1C_{1}C1​ and C2C_{2}C2​ be two biased coins such that the probabilities of getting head in a single toss are 23\frac{2}{3}32​ and 13\frac{1}{3}31​, respectively. Suppose α\alphaα is the number of heads that appear when C1C_{1}C1​ is tossed twice, independently, and suppose β\betaβ is the number of heads that appear when C2C_{2}C2​ is tossed twice, independently, Then probability that the roots of the quadratic polynomial x2−αx+βx^{2} - \alpha x + \betax2−αx+β are real and equal, is
  1. (A)4081\frac{40}{81}8140​
  2. (B)2081\frac{20}{81}8120​
  3. (C)12\frac{1}{2}21​
  4. (D)14\frac{1}{4}41​

Correct answer: (B)

Step-by-step solution →
Q42·MathematicsSingle correct
Consider all rectangles lying in the region {(x,y)∈R×R:0≤x≤π2 and 0≤y≤2sin⁡(2x)}\left\{(x, y) \in \mathbb{R} \times \mathbb{R} : 0 \leq x \leq \frac{\pi}{2} \text{ and } 0 \leq y \leq 2\sin(2x)\right\}{(x,y)∈R×R:0≤x≤2π​ and 0≤y≤2sin(2x)} and having one side on the x-axis. The area of the rectangle which has the maximum perimeter among all such rectangles, is
  1. (A)3π2\frac{3\pi}{2}23π​
  2. (B)π\piπ
  3. (C)π23\frac{\pi}{2\sqrt{3}}23​π​
  4. (D)π32\frac{\pi\sqrt{3}}{2}2π3​​

Correct answer: (C)

Step-by-step solution →
Q43·MathematicsMultiple correct
Let the function f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be defined by f(x)=x3−x2+(x−1)sin⁡xf(x) = x^{3} - x^{2} + (x - 1)\sin xf(x)=x3−x2+(x−1)sinx and let g:R→Rg : \mathbb{R} \to \mathbb{R}g:R→R be an arbitrary function. Let fg :R→R: \mathbb{R} \to \mathbb{R}:R→R be the product function defined by (fg)(x)=f(x) g(x)(f g)(x) = f(x)\, g(x)(fg)(x)=f(x)g(x). Then which of the following statements is/are TRUE ?
  1. (A)If g is continuous at x=1x = 1x=1, then fg is differentiable at x=1x = 1x=1
  2. (B)If fg is differentiable at x=1x = 1x=1, then g is continuous at x=1x = 1x=1
  3. (C)If g is differentiable at x=1x = 1x=1, then fg is differentiable at x=1x = 1x=1
  4. (D)If fg is differentiable at x=1x = 1x=1, then g is differentiable at x=1x = 1x=1

Correct answer: (A), (C)

Step-by-step solution →
Q44·MathematicsMultiple correct
Let M be a 3×33 \times 33×3 invertible matrix with real entries and let I denote the 3×33 \times 33×3 identity matrix. If M−1=adj⁡(adj⁡M)M^{-1} = \operatorname{adj}(\operatorname{adj} M)M−1=adj(adjM), then which of the following statement is/are ALWAYS TRUE ?
  1. (A)M=IM = IM=I
  2. (B)det⁡M=1\det M = 1detM=1
  3. (C)M2=IM^{2} = IM2=I
  4. (D)(adj⁡M)2=I(\operatorname{adj} M)^{2} = I(adjM)2=I

Correct answer: (B), (C), (D)

Step-by-step solution →
Q45·MathematicsMultiple correct
Let S be the set of all complex numbers z satisfying ∣z2+z+1∣=1|z^{2} + z + 1| = 1∣z2+z+1∣=1. Then which of the following statements is/are TRUE ?
  1. (A)∣z+12∣≤12\left|z + \frac{1}{2}\right| \leq \frac{1}{2}​z+21​​≤21​ for all z∈Sz \in Sz∈S
  2. (B)∣z∣≤2|z| \leq 2∣z∣≤2 for all z∈Sz \in Sz∈S
  3. (C)∣z+12∣≥12\left|z + \frac{1}{2}\right| \geq \frac{1}{2}​z+21​​≥21​ for all z∈Sz \in Sz∈S
  4. (D)The set S has exactly four elements

Correct answer: (B), (C)

Step-by-step solution →
Q46·MathematicsMultiple correct
Let x, y and z be positive real numbers. Suppose x, y and z are lengths of the sides of a triangle opposite to its angles X, Y and Z, respectively. If tan⁡X2+tan⁡Z2=2yx+y+z\tan\frac{X}{2} + \tan\frac{Z}{2} = \frac{2y}{x + y + z}tan2X​+tan2Z​=x+y+z2y​, then which of the following statements is/are TRUE?
  1. (A)2Y=X+Z2Y = X + Z2Y=X+Z
  2. (B)Y=X+ZY = X + ZY=X+Z
  3. (C)tan⁡X2=xy+z\tan\frac{X}{2} = \frac{x}{y + z}tan2X​=y+zx​
  4. (D)x2+z2−y2=xzx^{2} + z^{2} - y^{2} = xzx2+z2−y2=xz

Correct answer: (B), (C)

Step-by-step solution →
Q47·MathematicsMultiple correct
Let L1L_{1}L1​ and L2L_{2}L2​ be the following straight line. L1:x−11=y−1=z−13L_{1} : \frac{x - 1}{1} = \frac{y}{-1} = \frac{z - 1}{3}L1​:1x−1​=−1y​=3z−1​ and L2:x−1−3=y−1=z−11L_{2} : \frac{x - 1}{-3} = \frac{y}{-1} = \frac{z - 1}{1}L2​:−3x−1​=−1y​=1z−1​ Suppose the straight line L:x−αl=y−1m=z−γ−2L : \frac{x - \alpha}{l} = \frac{y - 1}{m} = \frac{z - \gamma}{-2}L:lx−α​=my−1​=−2z−γ​ lies in the plane containing L1L_{1}L1​ and L2L_{2}L2​, and passes through the point of intersection of L1L_{1}L1​ and L2L_{2}L2​. If the line L bisects the acute angle between the lines L1L_{1}L1​ and L2L_{2}L2​, then which of the following statements is/are TRUE?
  1. (A)α−γ=3\alpha - \gamma = 3α−γ=3
  2. (B)l+m=2l + m = 2l+m=2
  3. (C)α−γ=1\alpha - \gamma = 1α−γ=1
  4. (D)l+m=0l + m = 0l+m=0

Correct answer: (A), (B)

Step-by-step solution →
Q48·MathematicsMultiple correct
Which of the following inequalities is/are TRUE?
  1. (A)∫01xcos⁡x dx≥38\int_{0}^{1} x\cos x\, dx \geq \frac{3}{8}∫01​xcosxdx≥83​
  2. (B)∫01xsin⁡x dx≥310\int_{0}^{1} x\sin x\, dx \geq \frac{3}{10}∫01​xsinxdx≥103​
  3. (C)∫01x2cos⁡x dx≥12\int_{0}^{1} x^{2}\cos x\, dx \geq \frac{1}{2}∫01​x2cosxdx≥21​
  4. (D)∫01x2sin⁡x dx≥29\int_{0}^{1} x^{2}\sin x\, dx \geq \frac{2}{9}∫01​x2sinxdx≥92​

Correct answer: (A), (B), (D)

Step-by-step solution →
Q49·MathematicsNumerical
Let m be the minimum possible value of log⁡3(3y1+3y2+3y3)\log_{3}\left(3^{y_{1}} + 3^{y_{2}} + 3^{y_{3}}\right)log3​(3y1​+3y2​+3y3​), where y1,y2,y3y_{1}, y_{2}, y_{3}y1​,y2​,y3​ are real numbers for which y1+y2+y3=9y_{1} + y_{2} + y_{3} = 9y1​+y2​+y3​=9. Let M be the maximum possible value of (log⁡3x1+log⁡3x2+log⁡3x3)\left(\log_{3} x_{1} + \log_{3} x_{2} + \log_{3} x_{3}\right)(log3​x1​+log3​x2​+log3​x3​), where x1,x2,x3x_{1}, x_{2}, x_{3}x1​,x2​,x3​ are positive real numbers for which x1+x2+x3=9x_{1} + x_{2} + x_{3} = 9x1​+x2​+x3​=9. Then the value of log⁡2(m3)+log⁡3(M2)\log_{2}\left(m^{3}\right) + \log_{3}\left(M^{2}\right)log2​(m3)+log3​(M2) is ______.

Correct answer: 8.00

Step-by-step solution →
Q50·MathematicsNumerical
Let a1a_{1}a1​, a2a_{2}a2​, a3a_{3}a3​, ..... be a sequence of positive integers in arithmetic progression with common difference 2. Also, let b1b_{1}b1​, b2b_{2}b2​, b3b_{3}b3​, ..... be a sequence of positive integers in geometric progression with common ratio 2. If a1=b1=ca_{1} = b_{1} = ca1​=b1​=c, then the number of all possible values of c, for which the equality 2(a1+a2+…+an)=b1+b2+…+bn2\left(a_{1} + a_{2} + \ldots + a_{n}\right) = b_{1} + b_{2} + \ldots + b_{n}2(a1​+a2​+…+an​)=b1​+b2​+…+bn​ holds for some positive integer n, is ______

Correct answer: 1.00

Step-by-step solution →
Q51·MathematicsNumerical
Let f:[0,2]→Rf : [0, 2] \to \mathbb{R}f:[0,2]→R be the function defined by f(x)=(3−sin⁡(2πx))sin⁡(πx−π4)−sin⁡(3πx+π4)f(x) = (3 - \sin(2\pi x))\sin\left(\pi x - \frac{\pi}{4}\right) - \sin\left(3\pi x + \frac{\pi}{4}\right)f(x)=(3−sin(2πx))sin(πx−4π​)−sin(3πx+4π​) If α,β∈[0,2]\alpha, \beta \in [0, 2]α,β∈[0,2] are such that {x∈[0,2]:f(x)≥0}=[α,β]\{x \in [0, 2] : f(x) \geq 0\} = [\alpha, \beta]{x∈[0,2]:f(x)≥0}=[α,β], then the value of β−α\beta - \alphaβ−α is ______

Correct answer: 1.00

Step-by-step solution →
Q52·MathematicsNumerical
In a triangle PQR, let a⃗=QR→\vec{a} = \overrightarrow{QR}a=QR​, b⃗=RP→\vec{b} = \overrightarrow{RP}b=RP and c⃗=PQ→\vec{c} = \overrightarrow{PQ}c=PQ​. If ∣a⃗∣=3|\vec{a}| = 3∣a∣=3, ∣b⃗∣=4|\vec{b}| = 4∣b∣=4 and a⃗⋅(c⃗−b⃗)c⃗⋅(a⃗−b⃗)=∣a⃗∣∣a⃗∣+∣b⃗∣\frac{\vec{a}\cdot(\vec{c} - \vec{b})}{\vec{c}\cdot(\vec{a} - \vec{b})} = \frac{|\vec{a}|}{|\vec{a}| + |\vec{b}|}c⋅(a−b)a⋅(c−b)​=∣a∣+∣b∣∣a∣​, then the value of ∣a⃗×b⃗∣2\left|\vec{a} \times \vec{b}\right|^{2}​a×b​2 is ______

Correct answer: 108.00

Step-by-step solution →
Q53·MathematicsNumerical
For a polynomial g(x) with real coefficient, let mgm_{g}mg​ denote the number of distinct real roots of g(x). Suppose S is the set of polynomials with real coefficient defined by S={(x2−1)2(a0+a1x+a2x2+a3x3):a0,a1,a2,a3∈R}S = \left\{\left(x^{2} - 1\right)^{2}\left(a_{0} + a_{1}x + a_{2}x^{2} + a_{3}x^{3}\right) : a_{0}, a_{1}, a_{2}, a_{3} \in \mathbb{R}\right\}S={(x2−1)2(a0​+a1​x+a2​x2+a3​x3):a0​,a1​,a2​,a3​∈R}. For a polynomial f, let f′f'f′ and f′′f''f′′ denote its first and second order derivatives, respectively. Then the minimum possible value of (mf′+mf′′)\left(m_{f'} + m_{f''}\right)(mf′​+mf′′​), where f∈Sf \in Sf∈S, is ______

Correct answer: 5.00

Step-by-step solution →
Q54·MathematicsNumerical
Let e denote the base of the natural logarithm. The value of the real number a for which the right hand limit lim⁡x→0+(1−x)1x−e−1xa\lim_{x \to 0^{+}} \frac{(1 - x)^{\frac{1}{x}} - e^{-1}}{x^{a}}limx→0+​xa(1−x)x1​−e−1​ is equal to a nonzero real number, is ______.

Correct answer: 1.00

Step-by-step solution →

Chapters tested in this paper

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Vector Algebra 173/186
  • Probability 176/186
  • Magnetic Field of Current 147/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Chemical Kinetics 169/186
  • Electric Field and Coulomb's Law 133/186
  • Quadratic Equations 148/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Oscillations 117/186
  • Waves 109/186
  • Atoms 112/186
  • Ellipse 103/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Electronic Effects and Stability 74/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • States of Matter: Gases and Liquids 52/186
  • Isomerism 51/186
  • IUPAC Nomenclature 37/186
  • Reaction Mechanism 29/186
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