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JEE Advanced 2013 Paper 1 Question Paper with Answers

60 questions · Physics, Chemistry & Mathematics

The complete JEE Advanced 2013 Paper 1 paper — every question with its correct answer, tagged to the chapter it tests. Free to read, no account needed.

Physics
20
Chemistry
20
Mathematics
20

Physics — JEE Advanced 2013 Paper 1

Q1·PhysicsSingle correct
One end of a horizontal thick copper wire of length 2L2L2L and radius 2R2R2R is welded to an end of another horizontal thin copper wire of length LLL and radius RRR. When the arrangement is stretched by applying forces at two ends, the ratio of the elongation in the thin wire to that in the thick wire is
  1. (A)0.25
  2. (B)0.50
  3. (C)2.00
  4. (D)4.00

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
The work done on a particle of mass mmm by a force K[x(x2+y2)3/2i^+y(x2+y2)3/2j^]K\left[\frac{x}{(x^{2}+y^{2})^{3/2}}\hat{i}+\frac{y}{(x^{2}+y^{2})^{3/2}}\hat{j}\right]K[(x2+y2)3/2x​i^+(x2+y2)3/2y​j^​] (K being a constant of appropriate dimensions), when the particle is taken from the point (a,0)(a, 0)(a,0) to the point (0,a)(0, a)(0,a) along a circular path of radius aaa about the origin in the x-y plane is
  1. (A)2Kπa\frac{2K\pi}{a}a2Kπ​
  2. (B)Kπa\frac{K\pi}{a}aKπ​
  3. (C)Kπ2a\frac{K\pi}{2a}2aKπ​
  4. (D)0

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
Two rectangular blocks, having identical dimensions, can be arranged either in configuration I or in configuration II as shown in the figure. One of the blocks has thermal conductivity κ\kappaκ and the other 2κ2\kappa2κ. The temperature difference between the ends along the x-axis is the same in both the configurations. It takes 9 s to transport a certain amount of heat from the hot end to the cold end in the configuration I. The time to transport the same amount of heat in the configuration II is
  1. (A)2.0 s
  2. (B)3.0 s
  3. (C)4.5 s
  4. (D)6.0 s

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
A ray of light travelling in the direction 12(i^+3j^)\frac{1}{2}(\hat{i}+\sqrt{3}\hat{j})21​(i^+3​j^​) is incident on a plane mirror. After reflection, it travels along the direction 12(i^−3j^)\frac{1}{2}(\hat{i}-\sqrt{3}\hat{j})21​(i^−3​j^​). The angle of incidence is
  1. (A)30°
  2. (B)45°
  3. (C)60°
  4. (D)75°

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10 cm and 5.15 cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm. The 24th^{th}th division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is
  1. (A)5.112 cm
  2. (B)5.124 cm
  3. (C)5.136 cm
  4. (D)5.148 cm

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
Two non-reactive monoatomic ideal gases have their atomic masses in the ratio 2 : 3. The ratio of their partial pressures, when enclosed in a vessel kept at a constant temperature, is 4 : 3. The ratio of their densities is
  1. (A)1 : 4
  2. (B)1 : 2
  3. (C)6 : 9
  4. (D)8 : 9

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
In the Young’s double slit experiment using a monochromatic light of wavelength λ\lambdaλ, the path difference (in terms of an integer n) corresponding to any point having half the peak intensity is
  1. (A)(2n+1)λ2\frac{(2n+1)\lambda}{2}2(2n+1)λ​
  2. (B)(2n+1)λ4\frac{(2n+1)\lambda}{4}4(2n+1)λ​
  3. (C)(2n+1)λ8\frac{(2n+1)\lambda}{8}8(2n+1)λ​
  4. (D)(2n+1)λ16\frac{(2n+1)\lambda}{16}16(2n+1)λ​

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
The image of an object, formed by a plano-convex lens at a distance of 8 m behind the lens, is real and is one-third the size of the object. The wavelength of light inside the lens is 23\frac{2}{3}32​ times the wavelength in free space. The radius of the curved surface of the lens is
  1. (A)1 m
  2. (B)2 m
  3. (C)3 m
  4. (D)4 m

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A particle of mass m is projected from the ground with an initial speed u0u_{0}u0​ at an angle α\alphaα with the horizontal. At the highest point of its trajectory, it makes a completely inelastic collision with another identical particle, which was thrown vertically upward from the ground with the same initial speed u0u_{0}u0​. The angle that the composite system makes with the horizontal immediately after the collision is
  1. (A)π4\frac{\pi}{4}4π​
  2. (B)π4+α\frac{\pi}{4}+\alpha4π​+α
  3. (C)π4−α\frac{\pi}{4}-\alpha4π​−α
  4. (D)π2\frac{\pi}{2}2π​

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is 3×1083\times 10^{8}3×108 m/s. The final momentum of the object is
  1. (A)0.3×10−170.3\times 10^{-17}0.3×10−17 kg ms−1^{-1}−1
  2. (B)1.0×10−171.0\times 10^{-17}1.0×10−17 kg ms−1^{-1}−1
  3. (C)3.0×10−173.0\times 10^{-17}3.0×10−17 kg ms−1^{-1}−1
  4. (D)9.0×10−179.0\times 10^{-17}9.0×10−17 kg ms−1^{-1}−1

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsMultiple correct
In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance C. The switch S1S_{1}S1​ is pressed first to fully charge the capacitor C1C_{1}C1​ and then released. The switch S2S_{2}S2​ is then pressed to charge the capacitor C2C_{2}C2​. After some time, S2S_{2}S2​ is released and then S3S_{3}S3​ is pressed. After some time,
  1. (A)the charge on the upper plate of C1C_{1}C1​ is 2CV02CV_{0}2CV0​.
  2. (B)the charge on the upper plate of C1C_{1}C1​ is CV0CV_{0}CV0​.
  3. (C)the charge on the upper plate of C1C_{1}C1​ is 0.
  4. (D)the charge on the upper plate of C2C_{2}C2​ is −CV0-CV_{0}−CV0​.

Correct answer: (B), (D)

Step-by-step solution →
Q12·PhysicsMultiple correct
A particle of mass M and positive charge Q, moving with a constant velocity u1=4i^u_{1}=4\hat{i}u1​=4i^ ms−1^{-1}−1, enters a region of uniform static magnetic field normal to the x-y plane. The region of the magnetic field extends from x = 0 to x = L for all values of y. After passing through this region, the particle emerges on the other side after 10 milliseconds with a velocity u2=2(3i^+j^)u_{2}=2(\sqrt{3}\hat{i}+\hat{j})u2​=2(3​i^+j^​) m/s. The correct statement(s) is (are)
  1. (A)The direction of the magnetic field is −z-z−z direction.
  2. (B)The direction of the magnetic field is +z+z+z direction.
  3. (C)The magnitude of the magnetic field is 50πM3Q\frac{50\pi M}{3Q}3Q50πM​ units.
  4. (D)The magnitude of the magnetic field is 100πM3Q\frac{100\pi M}{3Q}3Q100πM​ units.

Correct answer: (A), (C)

Step-by-step solution →
Q13·PhysicsMultiple correct
A horizontal stretched string fixed at two ends, is vibrating in its fifth harmonic according to the equation y(x,t)=0.01sin⁡[(62.8 m−1)x]cos⁡[(628 s−1)t]y(x, t) = 0.01 \sin[(62.8 \text{ m}^{-1})x]\cos[(628 \text{ s}^{-1})t]y(x,t)=0.01sin[(62.8 m−1)x]cos[(628 s−1)t] m. Assuming π=3.14\pi = 3.14π=3.14, the correct statement(s) is (are)
  1. (A)The number of nodes is 5.
  2. (B)the length of the string is 0.25 m.
  3. (C)The maximum displacement of the midpoint of the string, from its equilibrium position is 0.01 m.
  4. (D)The fundamental frequency is 100 Hz.

Correct answer: (B), (C)

Step-by-step solution →
Q14·PhysicsMultiple correct
A solid sphere of radius R and density ρ\rhoρ is attached to one end of a mass-less spring of force constant k. The other end of the spring is connected to another solid sphere of radius R and density 3ρ3\rho3ρ. The complete arrangement is placed in a liquid of density 2ρ2\rho2ρ and is allowed to reach equilibrium. The correct statement(s) is (are)
  1. (A)the net elongation of the spring is 4πR3ρg3k\frac{4\pi R^{3}\rho g}{3k}3k4πR3ρg​
  2. (B)the net elongation of the spring is 8πR3ρg3k\frac{8\pi R^{3}\rho g}{3k}3k8πR3ρg​
  3. (C)the light sphere is partially submerged.
  4. (D)the light sphere is completely submerged.

Correct answer: (A), (D)

Step-by-step solution →
Q15·PhysicsMultiple correct
Two non-conducting solid spheres of radii R and 2R, having uniform volume charge densities ρ1\rho_{1}ρ1​ and ρ2\rho_{2}ρ2​ respectively, touch each other. The net electric field at a distance 2R from the centre of the smaller sphere, along the line joining the centre of the spheres is zero. The ratio ρ1/ρ2\rho_{1}/\rho_{2}ρ1​/ρ2​ can be
  1. (A)−4-4−4
  2. (B)−3225-\frac{32}{25}−2532​
  3. (C)3225\frac{32}{25}2532​
  4. (D)444

Correct answer: (B), (D)

Step-by-step solution →
Q16·PhysicsInteger
A bob of mass m, suspended by a string of length l1l_{1}l1​ is given a minimum velocity required to complete a full circle in the vertical plane. At the highest point, it collides elastically with another bob of mass m suspended by a string of length l2l_{2}l2​, which is initially at rest. Both the strings are mass-less and inextensible. If the second bob, after collision acquires the minimum speed required to complete a full circle in the vertical plane, the ratio l1/l2l_{1}/l_{2}l1​/l2​ is

Correct answer: 5

Step-by-step solution →
Q17·PhysicsInteger
A particle of mass 0.2 kg is moving in one dimension under a force that delivers a constant power 0.5 W to the particle. If the initial speed (in m/s) of the particle is zero, the speed (in m/s) after 5 s is

Correct answer: 5

Step-by-step solution →
Q18·PhysicsInteger
The work functions of Silver and Sodium are 4.6 and 2.3 eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for Silver to that of Sodium is

Correct answer: 1

Step-by-step solution →
Q19·PhysicsInteger
A freshly prepared sample of a radioisotope of half-life 1386 s has activity 10310^{3}103 disintegrations per second. Given that ln⁡2=0.693\ln 2 = 0.693ln2=0.693, the fraction of the initial number of nuclei (expressed in nearest integer percentage) that will decay in the first 80 s after preparation of the sample is

Correct answer: 4

Step-by-step solution →
Q20·PhysicsInteger
A uniform circular disc of mass 50 kg and radius 0.4 m is rotating with an angular velocity of 10 rad s−1^{-1}−1 about its own axis, which is vertical. Two uniform circular rings, each of mass 6.25 kg and radius 0.2 m, are gently placed symmetrically on the disc in such a manner that they are touching each other along the axis of the disc and are horizontal. Assume that the friction is large enough such that the rings are at rest relative to the disc and the system rotates about the original axis. The new angular velocity (in rad s−1^{-1}−1) of the system is

Correct answer: 8

Step-by-step solution →

Chemistry — JEE Advanced 2013 Paper 1

Q21·ChemistrySingle correct
In the reaction, P + Q → R + S the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is
  1. (A)2
  2. (B)3
  3. (C)0
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q22·ChemistrySingle correct
Consider the following complex ions, P, Q and R: P = [FeF6]3−[FeF_6]^{3-}[FeF6​]3−, Q = [V(H2O)6]2+[V(H_2O)_6]^{2+}[V(H2​O)6​]2+ and R = [Fe(H2O)6]2+[Fe(H_2O)_6]^{2+}[Fe(H2​O)6​]2+. The correct order of the complex ions, according to their spin–only magnetic moment values (in B.M.) is
  1. (A)R < Q < P
  2. (B)Q < R < P
  3. (C)R < P < Q
  4. (D)Q < P < R

Correct answer: (B)

Step-by-step solution →
Q23·ChemistrySingle correct
The arrangement of X−^{-}− ions around A+^{+}+ ion in solid AX is given in the figure (not drawn to scale). If the radius of X−^{-}− is 250 pm, the radius of A+^{+}+ is
  1. (A)104 pm
  2. (B)125 pm
  3. (C)183 pm
  4. (D)57 pm

Correct answer: (A)

Step-by-step solution →
Q24·ChemistrySingle correct
Concentrated nitric acid, upon long standing, turns yellow–brown due to the formation of
  1. (A)NONONO
  2. (B)NO2NO_2NO2​
  3. (C)N2ON_2ON2​O
  4. (D)N2O4N_2O_4N2​O4​

Correct answer: (B)

Step-by-step solution →
Q25·ChemistrySingle correct
The compound that does NOT liberate CO2CO_2CO2​, on treatment with aqueous sodium bicarbonate solution, is
  1. (A)Benzoic acid
  2. (B)Benzenesulphonic acid
  3. (C)Salicylic acid
  4. (D)Carbolic acid (Phenol)

Correct answer: (D)

Step-by-step solution →
Q26·ChemistrySingle correct
Sulfide ores are common for the metals
  1. (A)Ag, Cu and Pb
  2. (B)Ag, Cu and Sn
  3. (C)Ag, Mg and Pb
  4. (D)Al, Cu and Pb

Correct answer: (A)

Step-by-step solution →
Q27·ChemistrySingle correct
Methylene blue, from its aqueous solution, is adsorbed on activated charcoal at 25∘^{\circ}∘C. For this process, the correct statement is
  1. (A)The adsorption requires activation at 25∘^{\circ}∘C.
  2. (B)The adsorption is accompanied by a decrease in enthalpy.
  3. (C)The adsorption increases with increase of temperature.
  4. (D)The adsorption is irreversible.

Correct answer: (B)

Step-by-step solution →
Q28·ChemistrySingle correct
KI in acetone, undergoes SN2S_N2SN​2 reaction with each of P, Q, R and S. The rates of the reaction vary as shown in the figure.
  1. (A)P > Q > R > S
  2. (B)S > P > R > Q
  3. (C)P > R > Q > S
  4. (D)R > P > S > Q

Correct answer: (B)

Step-by-step solution →
Q29·ChemistrySingle correct
The standard enthalpies of formation of CO2CO_2CO2​(g), H2OH_2OH2​O(l) and glucose(s) at 25∘^{\circ}∘C are –400 kJ/mol, –300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25∘^{\circ}∘C is
  1. (A)+2900 kJ
  2. (B)–2900 kJ
  3. (C)–16.11 kJ
  4. (D)+16.11 kJ

Correct answer: (C)

Step-by-step solution →
Q30·ChemistrySingle correct
Upon treatment with ammoniacal H2SH_2SH2​S, the metal ion that precipitates as a sulfide is
  1. (A)Fe(III)
  2. (B)Al(III)
  3. (C)Mg(II)
  4. (D)Zn(II)

Correct answer: (D)

Step-by-step solution →
Q31·ChemistryMultiple correct
The initial rate of hydrolysis of methyl acetate (1 M) by a weak acid (HA, 1M) is 1/100th^{th}th of that of a strong acid (HX, 1M), at 25∘^{\circ}∘C. The KaK_aKa​ of HA is
  1. (A)1×10−41 \times 10^{-4}1×10−4
  2. (B)1×10−51 \times 10^{-5}1×10−5
  3. (C)1×10−61 \times 10^{-6}1×10−6
  4. (D)1×10−31 \times 10^{-3}1×10−3

Correct answer: (A)

Step-by-step solution →
Q32·ChemistryMultiple correct
The hyperconjugative stabilities of tert-butyl cation and 2-butene, respectively, are due to
  1. (A)σ→p (empty) and σ→π* electron delocalisations.
  2. (B)σ→σ* and σ→π electron delocalisations.
  3. (C)σ→p (filled) and σ→π electron delocalisations.
  4. (D)p(filled)→σ* and σ→π* electron delocalisations.

Correct answer: (A)

Step-by-step solution →
Q33·ChemistryMultiple correct
The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is(are)
  1. (A)[Cr(NH3)5Cl]Cl2[Cr(NH_3)_5Cl]Cl_2[Cr(NH3​)5​Cl]Cl2​ and [Cr(NH3)4Cl2]Cl[Cr(NH_3)_4Cl_2]Cl[Cr(NH3​)4​Cl2​]Cl
  2. (B)[Co(NH3)4Cl2]+[Co(NH_3)_4Cl_2]^{+}[Co(NH3​)4​Cl2​]+ and [Pt(NH3)2(H2O)Cl]+[Pt(NH_3)_2(H_2O)Cl]^{+}[Pt(NH3​)2​(H2​O)Cl]+
  3. (C)[CoBr2Cl2]2−[CoBr_2Cl_2]^{2-}[CoBr2​Cl2​]2− and [PtBr2Cl2]2−[PtBr_2Cl_2]^{2-}[PtBr2​Cl2​]2−
  4. (D)[Pt(NH3)3(NO3)]Cl[Pt(NH_3)_3(NO_3)]Cl[Pt(NH3​)3​(NO3​)]Cl and [Pt(NH3)3Cl]Br[Pt(NH_3)_3Cl]Br[Pt(NH3​)3​Cl]Br

Correct answer: (B), (D)

Step-by-step solution →
Q34·ChemistryMultiple correct
Among P, Q, R and S, the aromatic compound(s) is/are
  1. (A)P
  2. (B)Q
  3. (C)R
  4. (D)S

Correct answer: (A), (B), (C), (D)

Step-by-step solution →
Q35·ChemistryMultiple correct
Benzene and naphthalene form an ideal solution at room temperature. For this process, the true statement(s) is(are)
  1. (A)ΔG\Delta GΔG is positive
  2. (B)ΔSsystem\Delta S_{system}ΔSsystem​ is positive
  3. (C)ΔSsurroundings=0\Delta S_{surroundings} = 0ΔSsurroundings​=0
  4. (D)ΔH=0\Delta H = 0ΔH=0

Correct answer: (B), (C), (D)

Step-by-step solution →
Q36·ChemistryInteger
The atomic masses of He and Ne are 4 and 20 a.m.u., respectively. The value of the de Broglie wavelength of He gas at – 73∘^{\circ}∘C is "M" times that of the de Broglie wavelength of Ne at 727∘^{\circ}∘C. M is

Correct answer: 5

Step-by-step solution →
Q37·ChemistryInteger
EDTA4−^{4-}4− is ethylenediaminetetraacetate ion. The total number of N – Co – O bond angles in [Co(EDTA)]1−[Co(EDTA)]^{1-}[Co(EDTA)]1− complex ion is

Correct answer: 8

Step-by-step solution →
Q38·ChemistryInteger
The total number of carboxylic acid groups in the product P is

Correct answer: 2

Step-by-step solution →
Q39·ChemistryInteger
A tetrapeptide has – COOH group on alanine. This produces glycine (Gly), valine (Val), phenyl alanine (Phe) and alanine (Ala), on complete hydrolysis. For this tetrapeptide, the number of possible sequences (primary structures) with – NH2_22​ group attached to a chiral center is

Correct answer: 4

Step-by-step solution →
Q40·ChemistryInteger
The total number of lone-pairs of electrons in melamine is

Correct answer: 6

Step-by-step solution →

Mathematics — JEE Advanced 2013 Paper 1

Q41·MathematicsSingle correct
Perpendiculars are drawn from points on the line x+22=y+1−1=z3\frac{x+2}{2}=\frac{y+1}{-1}=\frac{z}{3}2x+2​=−1y+1​=3z​ to the plane x+y+z=3x+y+z=3x+y+z=3. The feet of perpendiculars lie on the line
  1. (A)x5=y−18=z−2−13\frac{x}{5}=\frac{y-1}{8}=\frac{z-2}{-13}5x​=8y−1​=−13z−2​
  2. (B)x2=y−13=z−2−5\frac{x}{2}=\frac{y-1}{3}=\frac{z-2}{-5}2x​=3y−1​=−5z−2​
  3. (C)x4=y−13=z−2−7\frac{x}{4}=\frac{y-1}{3}=\frac{z-2}{-7}4x​=3y−1​=−7z−2​
  4. (D)x2=y−1−7=z−25\frac{x}{2}=\frac{y-1}{-7}=\frac{z-2}{5}2x​=−7y−1​=5z−2​

Correct answer: (D)

Step-by-step solution →
Q42·MathematicsSingle correct
For a>b>c>0a>b>c>0a>b>c>0, the distance between (1,1)(1,1)(1,1) and the point of intersection of the lines ax+by+c=0ax+by+c=0ax+by+c=0 and bx+ay+c=0bx+ay+c=0bx+ay+c=0 is less than 222\sqrt{2}22​, then
  1. (A)a+b−c>0a+b-c>0a+b−c>0
  2. (B)a−b+c<0a-b+c<0a−b+c<0
  3. (C)a−b+c>0a-b+c>0a−b+c>0
  4. (D)a+b−c<0a+b-c<0a+b−c<0

Correct answer: (A)

Step-by-step solution →
Q43·MathematicsSingle correct
The area enclosed by the curves y=sin⁡x+cos⁡xy=\sin x+\cos xy=sinx+cosx and y=∣cos⁡x−sin⁡x∣y=|\cos x-\sin x|y=∣cosx−sinx∣ over the interval [0,π2][0,\frac{\pi}{2}][0,2π​] is
  1. (A)4(2−1)4(\sqrt{2}-1)4(2​−1)
  2. (B)22(2−1)2\sqrt{2}(\sqrt{2}-1)22​(2​−1)
  3. (C)2(2+1)2(\sqrt{2}+1)2(2​+1)
  4. (D)22(2+1)2\sqrt{2}(\sqrt{2}+1)22​(2​+1)

Correct answer: (B)

Step-by-step solution →
Q44·MathematicsSingle correct
Four persons independently solve a certain problem correctly with probabilities 12,34,14,18\frac{1}{2},\frac{3}{4},\frac{1}{4},\frac{1}{8}21​,43​,41​,81​. Then the probability that the problem is solved correctly by at least one of them is
  1. (A)235256\frac{235}{256}256235​
  2. (B)21256\frac{21}{256}25621​
  3. (C)3256\frac{3}{256}2563​
  4. (D)253256\frac{253}{256}256253​

Correct answer: (A)

Step-by-step solution →
Q45·MathematicsSingle correct
Let complex numbers α\alphaα and 1αˉ\frac{1}{\bar{\alpha}}αˉ1​ lie on circles (x−x0)2+(y−y0)2=r2(x-x_0)^2+(y-y_0)^2=r^2(x−x0​)2+(y−y0​)2=r2 and (x−x0)2+(y−y0)2=4r2(x-x_0)^2+(y-y_0)^2=4r^2(x−x0​)2+(y−y0​)2=4r2, respectively. If z0=x0+iy0z_0=x_0+iy_0z0​=x0​+iy0​ satisfies the equation 2∣z0∣2=r2+22|z_0|^2=r^2+22∣z0​∣2=r2+2, then ∣α∣=|\alpha|=∣α∣=
  1. (A)12\frac{1}{\sqrt{2}}2​1​
  2. (B)12\frac{1}{2}21​
  3. (C)17\frac{1}{\sqrt{7}}7​1​
  4. (D)13\frac{1}{3}31​

Correct answer: (C)

Step-by-step solution →
Q46·MathematicsSingle correct
The number of points in (−∞,∞)(-\infty,\infty)(−∞,∞), for which x2−xsin⁡x−cos⁡x=0x^2-x\sin x-\cos x=0x2−xsinx−cosx=0, is
  1. (A)666
  2. (B)444
  3. (C)222
  4. (D)000

Correct answer: (C)

Step-by-step solution →
Q47·MathematicsSingle correct
Let f:[12,1]→Rf:[\frac{1}{2},1]\to Rf:[21​,1]→R (the set of all real numbers) be a positive, non-constant and differentiable function such that f′(x)<2f(x)f'(x)<2f(x)f′(x)<2f(x) and f(12)=1f(\frac{1}{2})=1f(21​)=1. Then the value of ∫1/21f(x) dx\int_{1/2}^{1}f(x)\,dx∫1/21​f(x)dx lies in the interval
  1. (A)(2e−1,2e)(2e-1,2e)(2e−1,2e)
  2. (B)(e−1,2e−1)(e-1,2e-1)(e−1,2e−1)
  3. (C)(e−12,e−1)(\frac{e-1}{2},e-1)(2e−1​,e−1)
  4. (D)(0,e−12)(0,\frac{e-1}{2})(0,2e−1​)

Correct answer: (D)

Step-by-step solution →
Q48·MathematicsSingle correct
Let PR→=3i^+j^−2k^\overrightarrow{PR}=3\hat{i}+\hat{j}-2\hat{k}PR=3i^+j^​−2k^ and SQ→=i^−3j^−4k^\overrightarrow{SQ}=\hat{i}-3\hat{j}-4\hat{k}SQ​=i^−3j^​−4k^ determine diagonals of a parallelogram PQRS and PT→=i^+2j^+3k^\overrightarrow{PT}=\hat{i}+2\hat{j}+3\hat{k}PT=i^+2j^​+3k^ be another vector. Then the volume of the parallelepiped determined by the vectors PT→,PQ→\overrightarrow{PT},\overrightarrow{PQ}PT,PQ​ and PS→\overrightarrow{PS}PS is
  1. (A)555
  2. (B)202020
  3. (C)101010
  4. (D)303030

Correct answer: (C)

Step-by-step solution →
Q49·MathematicsSingle correct
The value of cot⁡(∑n=123cot⁡−1(1+∑k=1n2k))\cot\left(\sum_{n=1}^{23}\cot^{-1}\left(1+\sum_{k=1}^{n}2k\right)\right)cot(∑n=123​cot−1(1+∑k=1n​2k)) is
  1. (A)2325\frac{23}{25}2523​
  2. (B)2523\frac{25}{23}2325​
  3. (C)2324\frac{23}{24}2423​
  4. (D)2423\frac{24}{23}2324​

Correct answer: (B)

Step-by-step solution →
Q50·MathematicsSingle correct
A curve passes through the point (1,π6)(1,\frac{\pi}{6})(1,6π​). Let the slope of the curve at each point (x,y)(x,y)(x,y) be yx+sec⁡(yx)\frac{y}{x}+\sec\left(\frac{y}{x}\right)xy​+sec(xy​), x>0x>0x>0. Then the equation of the curve is
  1. (A)sin⁡(yx)=log⁡x+12\sin\left(\frac{y}{x}\right)=\log x+\frac{1}{2}sin(xy​)=logx+21​
  2. (B)cosec⁡(yx)=log⁡x+2\operatorname{cosec}\left(\frac{y}{x}\right)=\log x+2cosec(xy​)=logx+2
  3. (C)sec⁡(2yx)=log⁡x+2\sec\left(\frac{2y}{x}\right)=\log x+2sec(x2y​)=logx+2
  4. (D)cos⁡(2yx)=log⁡x+12\cos\left(\frac{2y}{x}\right)=\log x+\frac{1}{2}cos(x2y​)=logx+21​

Correct answer: (A)

Step-by-step solution →
Q51·MathematicsMultiple correct
A line lll passing through the origin is perpendicular to the lines l1:(3+t)i^+(−1+2t)j^+(4+2t)k^l_1:(3+t)\hat{i}+(-1+2t)\hat{j}+(4+2t)\hat{k}l1​:(3+t)i^+(−1+2t)j^​+(4+2t)k^, −∞<t<∞-\infty<t<\infty−∞<t<∞, l2:(3+2s)i^+(3+2s)j^+(2+s)k^l_2:(3+2s)\hat{i}+(3+2s)\hat{j}+(2+s)\hat{k}l2​:(3+2s)i^+(3+2s)j^​+(2+s)k^, −∞<s<∞-\infty<s<\infty−∞<s<∞. Then, the coordinate(s) of the point(s) on l2l_2l2​ at a distance of 17\sqrt{17}17​ from the point of intersection of lll and l1l_1l1​ is (are)
  1. (A)(73,73,53)(\frac{7}{3},\frac{7}{3},\frac{5}{3})(37​,37​,35​)
  2. (B)(−1,−1,0)(-1,-1,0)(−1,−1,0)
  3. (C)(1,1,1)(1,1,1)(1,1,1)
  4. (D)(79,79,89)(\frac{7}{9},\frac{7}{9},\frac{8}{9})(97​,97​,98​)

Correct answer: (B), (D)

Step-by-step solution →
Q52·MathematicsMultiple correct
Let f(x)=xsin⁡πxf(x)=x\sin\pi xf(x)=xsinπx, x>0x>0x>0. Then for all natural numbers nnn, f′(x)f'(x)f′(x) vanishes at
  1. (A)a unique point in the interval (n,n+12)(n,n+\frac{1}{2})(n,n+21​)
  2. (B)a unique point in the interval (n+12,n+1)(n+\frac{1}{2},n+1)(n+21​,n+1)
  3. (C)a unique point in the interval (n,n+1)(n,n+1)(n,n+1)
  4. (D)two points in the interval (n,n+1)(n,n+1)(n,n+1)

Correct answer: (B), (C)

Step-by-step solution →
Q53·MathematicsMultiple correct
Let Sn=∑k=14n(−1)k(k+1)2k2S_n=\sum_{k=1}^{4n}(-1)^{\frac{k(k+1)}{2}}k^2Sn​=∑k=14n​(−1)2k(k+1)​k2. Then SnS_nSn​ can take value(s)
  1. (A)105610561056
  2. (B)108810881088
  3. (C)112011201120
  4. (D)133213321332

Correct answer: (A), (D)

Step-by-step solution →
Q54·MathematicsMultiple correct
For 3×33\times 33×3 matrices M and N, which of the following statement(s) is (are) NOT correct ?
  1. (A)NTMNN^TMNNTMN is symmetric or skew symmetric, according as M is symmetric or skew symmetric
  2. (B)MN−NMMN-NMMN−NM is skew symmetric for all symmetric matrices M and N
  3. (C)MNMNMN is symmetric for all symmetric matrices M and N
  4. (D)(adj M)(adj N)=adj(MN)(\text{adj }M)(\text{adj }N)=\text{adj}(MN)(adj M)(adj N)=adj(MN) for all invertible matrices M and N

Correct answer: (C), (D)

Step-by-step solution →
Q55·MathematicsMultiple correct
A rectangular sheet of fixed perimeter with sides having their lengths in the ratio 8:158:158:15 is converted into an open rectangular box by folding after removing squares of equal area from all four corners. If the total area of removed squares is 100, the resulting box has maximum volume. Then the lengths of the sides of the rectangular sheet are
  1. (A)242424
  2. (B)323232
  3. (C)454545
  4. (D)606060

Correct answer: (A), (C)

Step-by-step solution →
Q56·MathematicsInteger
Consider the set of eight vectors V={ai^+bj^+ck^;a,b,c∈{−1,1}}V=\{a\hat{i}+b\hat{j}+c\hat{k}; a,b,c\in\{-1,1\}\}V={ai^+bj^​+ck^;a,b,c∈{−1,1}}. Three non-coplanar vectors can be chosen from V in 2p2^p2p ways. Then p is ________

Correct answer: 5

Step-by-step solution →
Q57·MathematicsInteger
Of the three independent events E1E_1E1​, E2E_2E2​, and E3E_3E3​, the probability that only E1E_1E1​ occurs is α\alphaα, only E2E_2E2​ occurs is β\betaβ and only E3E_3E3​ occurs is γ\gammaγ. Let the probability ppp that none of events E1E_1E1​, E2E_2E2​ or E3E_3E3​ occurs satisfy the equations (α−2β)p=αβ(\alpha-2\beta)p=\alpha\beta(α−2β)p=αβ and (β−3γ)p=2βγ(\beta-3\gamma)p=2\beta\gamma(β−3γ)p=2βγ. All the given probabilities are assumed to lie in the interval (0,1)(0,1)(0,1). Then Probability of occurrence of E1Probability of occurrence of E3=\dfrac{\text{Probability of occurrence of }E_1}{\text{Probability of occurrence of }E_3}=Probability of occurrence of E3​Probability of occurrence of E1​​= ___________

Correct answer: 6

Step-by-step solution →
Q58·MathematicsInteger
The coefficients of three consecutive terms of (1+x)n+5(1+x)^{n+5}(1+x)n+5 are in the ratio 5:10:145:10:145:10:14. Then n = _______

Correct answer: 6

Step-by-step solution →
Q59·MathematicsInteger
A pack contains n cards numbered from 1 to n. Two consecutive numbered cards are removed from the pack and the sum of the numbers on the remaining cards is 1224. If the smaller of the numbers on the removed cards is k, then k−20=k-20=k−20= ________

Correct answer: 5

Step-by-step solution →
Q60·MathematicsInteger
A vertical line passing through the point (h,0)(h,0)(h,0) intersects the ellipse x24+y23=1\frac{x^2}{4}+\frac{y^2}{3}=14x2​+3y2​=1 at the points P and Q. Let the tangents to the ellipse at P and Q meet at the point R. If Δ(h)\Delta(h)Δ(h) = area of the triangle PQR, Δ1=max⁡1/2≤h≤1Δ(h)\Delta_1=\max_{1/2\leq h\leq 1}\Delta(h)Δ1​=max1/2≤h≤1​Δ(h) and Δ2=min⁡1/2≤h≤1Δ(h)\Delta_2=\min_{1/2\leq h\leq 1}\Delta(h)Δ2​=min1/2≤h≤1​Δ(h), then 85Δ1−8Δ2=\frac{8}{\sqrt{5}}\Delta_1-8\Delta_2=5​8​Δ1​−8Δ2​= ________

Correct answer: 9

Step-by-step solution →

Chapters tested in this paper

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Geometrical Optics 172/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Dual Nature of Matter and Radiation 155/186
  • Work, Energy and Power 132/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Electronic Effects and Stability 74/186
  • Carboxylic Acids and Derivatives 54/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Aromaticity 22/186
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