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JEE Advanced 2015 Paper 1 Question Paper with Answers

59 questions · Physics, Chemistry & Mathematics

59 of the 60 questions from the JEE Advanced 2015 Paper 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back while we re-check the transcription or the answer key.

Physics
20
Chemistry
20
Mathematics
19

Physics — JEE Advanced 2015 Paper 1

Q1·PhysicsInteger
Consider a concave mirror and a convex lens (refractive index = 1.5) of focal length 10 cm each, separated by a distance of 50 cm in air (refractive index = 1) as shown in the figure. An object is placed at a distance of 15 cm from the mirror. Its erect image formed by this combination has magnification M1M_{1}M1​. When the set-up is kept in a medium of refractive index 7/67/67/6, the magnification becomes M2M_{2}M2​. The magnitude ∣M2M1∣\left|\dfrac{M_{2}}{M_{1}}\right|​M1​M2​​​ is

Correct answer: 7

Step-by-step solution →
Q2·PhysicsInteger
An infinitely long uniform line charge distribution of charge per unit length λ\lambdaλ lies parallel to the y-axis in the y-z plane at z=32az = \dfrac{\sqrt{3}}{2}az=23​​a (see figure). If the magnitude of the flux of the electric field through the rectangular surface ABCD lying in the x-y plane with its center at the origin is λLnε0\dfrac{\lambda L}{n\varepsilon_{0}}nε0​λL​ (ε0\varepsilon_{0}ε0​ = permittivity of free space), then the value of nnn is

Correct answer: 6

Step-by-step solution →
Q3·PhysicsInteger
Consider a hydrogen atom with its electron in the nthn^{\text{th}}nth orbital. An electromagnetic radiation of wavelength 90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of nnn is (hc = 1242 eV nm)

Correct answer: 2

Step-by-step solution →
Q4·PhysicsInteger
A bullet is fired vertically upwards with velocity vvv from the surface of a spherical planet. When it reaches its maximum height, its acceleration due to the planet's gravity is 1/4th1/4^{\text{th}}1/4th of its value at the surface of the planet. If the escape velocity from the planet is vesc=vNv_{\text{esc}} = v\sqrt{N}vesc​=vN​, then the value of NNN is (ignore energy loss due to atmosphere)

Correct answer: 2

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Q5·PhysicsInteger
Two identical uniform discs roll without slipping on two different surfaces AB and CD (see figure) starting at A and C with linear speeds v1v_{1}v1​ and v2v_{2}v2​, respectively, and always remain in contact with the surfaces. If they reach B and D with the same linear speed and v1=3v_{1} = 3v1​=3 m/s, then v2v_{2}v2​ in m/s is (g=10g = 10g=10 m/s2^{2}2)

Correct answer: 7

Step-by-step solution →
Q6·PhysicsInteger
Two spherical stars A and B emit blackbody radiation. The radius of A is 400 times that of B and A emits 10410^{4}104 times the power emitted from B. The ratio (λA/λB)\left(\lambda_{A}/\lambda_{B}\right)(λA​/λB​) of their wavelengths λA\lambda_{A}λA​ and λB\lambda_{B}λB​ at which the peaks occur in their respective radiation curves is

Correct answer: 2

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Q7·PhysicsInteger
A nuclear power plant supplying electrical power to a village uses a radioactive material of half life T years as the fuel. The amount of fuel at the beginning is such that the total power requirement of the village is 12.5 % of the electrical power available form the plant at that time. If the plant is able to meet the total power needs of the village for a maximum period of nTnTnT years, then the value of nnn is

Correct answer: 3

Step-by-step solution →
Q8·PhysicsInteger
A Young's double slit interference arrangement with slits S1S_{1}S1​ and S2S_{2}S2​ is immersed in water (refractive index = 4/3) as shown in the figure. The positions of maxima on the surface of water are given by x2=p2m2λ2−d2x^{2} = p^{2}m^{2}\lambda^{2} - d^{2}x2=p2m2λ2−d2, where λ\lambdaλ is the wavelength of light in air (refractive index = 1), 2d2d2d is the separation between the slits and mmm is an integer. The value of ppp is

Correct answer: 3

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Q9·PhysicsMultiple correct
For photo-electric effect with incident photon wavelength λ\lambdaλ, the stopping potential is V0V_{0}V0​. Identify the correct variation(s) of V0V_{0}V0​ with λ\lambdaλ and 1/λ1/\lambda1/λ.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A), (C)

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Q10·PhysicsMultiple correct
Consider a Vernier callipers in which each 1 cm on the main scale is divided into 8 equal divisions and a screw gauge with 100 divisions on its circular scale. In the Vernier callipers, 5 divisions of the Vernier scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the circular scale moves it by two divisions on the linear scale. Then:
  1. (A)If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.
  2. (B)If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.
  3. (C)If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.
  4. (D)If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.

Correct answer: (B), (C)

Step-by-step solution →
Q11·PhysicsMultiple correct
Planck's constant h, speed of light c and gravitational constant G are used to form a unit of length L and a unit of mass M. Then the correct option(s) is(are)
  1. (A)M∝cM \propto \sqrt{c}M∝c​
  2. (B)M∝GM \propto \sqrt{G}M∝G​
  3. (C)L∝hL \propto \sqrt{h}L∝h​
  4. (D)L∝GL \propto \sqrt{G}L∝G​

Correct answer: (A), (C), (D)

Step-by-step solution →
Q12·PhysicsMultiple correct
Two independent harmonic oscillators of equal mass are oscillating about the origin with angular frequencies ω1\omega_{1}ω1​ and ω2\omega_{2}ω2​ and have total energies E1E_{1}E1​ and E2E_{2}E2​, respectively. The variations of their momenta ppp with positions xxx are shown in the figures. If ab=n2\dfrac{a}{b} = n^{2}ba​=n2 and aR=n\dfrac{a}{R} = nRa​=n, then the correct equation(s) is(are)
  1. (A)E1ω1=E2ω2E_{1}\omega_{1} = E_{2}\omega_{2}E1​ω1​=E2​ω2​
  2. (B)ω2ω1=n2\dfrac{\omega_{2}}{\omega_{1}} = n^{2}ω1​ω2​​=n2
  3. (C)ω1ω2=n2\omega_{1}\omega_{2} = n^{2}ω1​ω2​=n2
  4. (D)E1ω1=E2ω2\dfrac{E_{1}}{\omega_{1}} = \dfrac{E_{2}}{\omega_{2}}ω1​E1​​=ω2​E2​​

Correct answer: (B), (D)

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Q13·PhysicsMultiple correct
A ring of mass M and radius R is rotating with angular speed ω\omegaω about a fixed vertical axis passing through its centre O with two point masses each of mass M8\dfrac{M}{8}8M​ at rest at O. These masses can move radially outwards along two massless rods fixed on the ring as shown in the figure. At some instant the angular speed of the system is 89ω\dfrac{8}{9}\omega98​ω and one of the masses is at a distance of 35R\dfrac{3}{5}R53​R from O. At this instant the distance of the other mass from O is
  1. (A)23R\dfrac{2}{3}R32​R
  2. (B)13R\dfrac{1}{3}R31​R
  3. (C)35R\dfrac{3}{5}R53​R
  4. (D)45R\dfrac{4}{5}R54​R

Correct answer: (D)

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Q14·PhysicsMultiple correct
The figures below depict two situations in which two infinitely long static line charges of constant positive line charge density λ\lambdaλ are kept parallel to each other. In their resulting electric field, point charges qqq and −q-q−q are kept in equilibrium between them. The point charges are confined to move in the x direction only. If they are given a small displacement about their equilibrium positions, then the correct statement(s) is(are)
  1. (A)Both charges execute simple harmonic motion.
  2. (B)Both charges will continue moving in the direction of their displacement.
  3. (C)Charge +q+q+q executes simple harmonic motion while charge −q-q−q continues moving in the direction of its displacement.
  4. (D)Charge −q-q−q executes simple harmonic motion while charge +q+q+q continues moving in the direction of its displacement.

Correct answer: (C)

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Q15·PhysicsMultiple correct
Two identical glass rods S1S_{1}S1​ and S2S_{2}S2​ (refractive index = 1.5) have one convex end of radius of curvature 10 cm. They are placed with the curved surfaces at a distance ddd as shown in the figure, with their axes (shown by the dashed line) aligned. When a point source of light P is placed inside rod S1S_{1}S1​ on its axis at a distance of 50 cm from the curved face, the light rays emanating from it are found to be parallel to the axis inside S2S_{2}S2​. The distance ddd is
  1. (A)60 cm
  2. (B)70 cm
  3. (C)80 cm
  4. (D)90 cm

Correct answer: (B)

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Q16·PhysicsMultiple correct
A conductor (shown in the figure) carrying constant current I is kept in the x-y plane in a uniform magnetic field B⃗\vec{B}B. If F is the magnitude of the total magnetic force acting on the conductor, then the correct statement(s) is(are)
  1. (A)If B⃗\vec{B}B is along z^\hat{z}z^, F∝(L+R)F \propto (L + R)F∝(L+R)
  2. (B)If B⃗\vec{B}B is along x^\hat{x}x^, F=0F = 0F=0
  3. (C)If B⃗\vec{B}B is along y^\hat{y}y^​, F∝(L+R)F \propto (L + R)F∝(L+R)
  4. (D)If B⃗\vec{B}B is along z^\hat{z}z^, F=0F = 0F=0

Correct answer: (A), (B), (C)

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Q17·PhysicsMultiple correct
A container of fixed volume has a mixture of one mole of hydrogen and one mole of helium in equilibrium at temperature T. Assuming the gases are ideal, the correct statement(s) is(are)
  1. (A)The average energy per mole of the gas mixture is 2RT.
  2. (B)The ratio of speed of sound in the gas mixture to that in helium gas is 6/5\sqrt{6/5}6/5​.
  3. (C)The ratio of the rms speed of helium atoms to that of hydrogen molecules is 1/21/21/2.
  4. (D)The ratio of the rms speed of helium atoms to that of hydrogen molecules is 1/21/\sqrt{2}1/2​.

Correct answer: (A), (B), (D)

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Q18·PhysicsMultiple correct
In an aluminium (Al) bar of square cross section, a square hole is drilled and is filled with iron (Fe) as shown in the figure. The electrical resistivities of Al and Fe are 2.7×10−8 Ω2.7 \times 10^{-8}\ \Omega2.7×10−8 Ω m and 1.0×10−7 Ω1.0 \times 10^{-7}\ \Omega1.0×10−7 Ω m, respectively. The electrical resistance between the two faces P and Q of the composite bar is
  1. (A)247564 μΩ\dfrac{2475}{64}\ \mu\Omega642475​ μΩ
  2. (B)187564 μΩ\dfrac{1875}{64}\ \mu\Omega641875​ μΩ
  3. (C)187549 μΩ\dfrac{1875}{49}\ \mu\Omega491875​ μΩ
  4. (D)2475132 μΩ\dfrac{2475}{132}\ \mu\Omega1322475​ μΩ

Correct answer: (B)

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Q19·PhysicsMatrix match
Match the nuclear processes given in column I with the appropriate option(s) in column II
Column IColumn II
A.Nuclear fusionP.Absorption of thermal neutrons by 92235U^{235}_{92}\mathrm{U}92235​U
B.Fission in a nuclear reactorQ.2760Co^{60}_{27}\mathrm{Co}2760​Co nucleus
C.β\betaβ-decayR.Energy production in stars via hydrogen conversion to helium
D.γ\gammaγ-ray emissionS.Heavy water
T.Neutrino emission

Correct answer: A-(R,T); B-(P,S); C-(P,Q,R,T); D-(P,Q,R,T)

Step-by-step solution →
Q20·PhysicsMatrix match
A particle of unit mass is moving along the x-axis under the influence of a force and its total energy is conserved. Four possible forms of the potential energy of the particle are given in column I (aaa and U0U_{0}U0​ are constants). Match the potential energies in column I to the corresponding statement(s) in column II.
Column IColumn II
A.U1(x)=U02[1−(xa)2]2U_{1}(x) = \dfrac{U_{0}}{2}\left[1 - \left(\dfrac{x}{a}\right)^{2}\right]^{2}U1​(x)=2U0​​[1−(ax​)2]2P.The force acting on the particle is zero at x=ax = ax=a.
B.U2(x)=U02(xa)2U_{2}(x) = \dfrac{U_{0}}{2}\left(\dfrac{x}{a}\right)^{2}U2​(x)=2U0​​(ax​)2Q.The force acting on the particle is zero at x=0x = 0x=0.
C.U3(x)=U02(xa)2exp⁡[−(xa)2]U_{3}(x) = \dfrac{U_{0}}{2}\left(\dfrac{x}{a}\right)^{2}\exp\left[-\left(\dfrac{x}{a}\right)^{2}\right]U3​(x)=2U0​​(ax​)2exp[−(ax​)2]R.The force acting on the particle is zero at x=−ax = -ax=−a.
D.U4(x)=U02[xa−13(xa)3]U_{4}(x) = \dfrac{U_{0}}{2}\left[\dfrac{x}{a} - \dfrac{1}{3}\left(\dfrac{x}{a}\right)^{3}\right]U4​(x)=2U0​​[ax​−31​(ax​)3]S.The particle experiences an attractive force towards x=0x = 0x=0 in the region ∣x∣<a|x| < a∣x∣<a.
T.The particle with total energy U04\dfrac{U_{0}}{4}4U0​​ can oscillate about the point x=−ax = -ax=−a.

Correct answer: A-(P,Q,R,T); B-(Q,S); C-(P,Q,R,S); D-(P,R,T)

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Chemistry — JEE Advanced 2015 Paper 1

Q21·ChemistryInteger
If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex (which behaves as a strong electrolyte) is −0.0558 0-0.0558\,^{0}−0.05580C, the number of chloride(s) in the coordination sphere of the complex is [KfK_{f}Kf​ of water = 1.86 K kg mol−1^{-1}−1]

Correct answer: 1

Step-by-step solution →
Q22·ChemistryInteger
The total number of stereoisomers that can exist for M\mathbf{M}M is

Correct answer: 2

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Q23·ChemistryInteger
The number of resonance structures for N\mathbf{N}N is

Correct answer: 9

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Q24·ChemistryInteger
The total number of lone pairs of electrons in N2O3\mathrm{N_{2}O_{3}}N2​O3​ is

Correct answer: 8

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Q25·ChemistryInteger
For the octahedral complexes of Fe3+\mathrm{Fe^{3+}}Fe3+ in SCN−\mathrm{SCN^{-}}SCN− (thiocyanato-S) and in CN−\mathrm{CN^{-}}CN− ligand environments, the difference between the spin-only magnetic moments in Bohr magnetons (When approximated to the nearest integer) is [Atomic number of Fe = 26]

Correct answer: 4

Step-by-step solution →
Q26·ChemistryInteger
Among the triatomic molecules/ions, BeCl2\mathrm{BeCl_{2}}BeCl2​, N3−\mathrm{N_{3}^{-}}N3−​, N2O\mathrm{N_{2}O}N2​O, NO2+\mathrm{NO_{2}^{+}}NO2+​, O3\mathrm{O_{3}}O3​, SCl2\mathrm{SCl_{2}}SCl2​, ICl2−\mathrm{ICl_{2}^{-}}ICl2−​, I3−\mathrm{I_{3}^{-}}I3−​ and XeF2\mathrm{XeF_{2}}XeF2​, the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the ddd-orbital(s) is [Atomic number: S = 16, Cl = 17, I = 53 and Xe = 54]

Correct answer: 4

Step-by-step solution →
Q27·ChemistryInteger
Not considering the electronic spin, the degeneracy of the second excited state (n=3n = 3n=3) of H atom is 9, while the degeneracy of the second excited state of H−\mathrm{H^{-}}H− is

Correct answer: 3

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Q28·ChemistryInteger
All the energy released from the reaction X→Y\mathbf{X} \to \mathbf{Y}X→Y, ΔrG0=−193\Delta_{r}G^{0} = -193Δr​G0=−193 kJ mol−1^{-1}−1 is used for oxidizing M+\mathbf{M^{+}}M+ as M+→M3++2e−\mathbf{M^{+}} \to \mathbf{M^{3+}} + 2e^{-}M+→M3++2e−, E0=−0.25E^{0} = -0.25E0=−0.25 V. Under standard conditions, the number of moles of M+\mathbf{M^{+}}M+ oxidized when one\mathbf{one}one mole of X\mathbf{X}X is converted to Y\mathbf{Y}Y is [F = 96500 C mol−1^{-1}−1]

Correct answer: 4

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Q29·ChemistryMultiple correct
If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m\mathbf{m}m fraction of octahedral holes occupied by aluminium ions and n\mathbf{n}n fraction of tetrahedral holes occupied by magnesium ions, m and n, respectively, are
  1. (A)12, 18\dfrac{1}{2},\ \dfrac{1}{8}21​, 81​
  2. (B)1, 141,\ \dfrac{1}{4}1, 41​
  3. (C)12, 12\dfrac{1}{2},\ \dfrac{1}{2}21​, 21​
  4. (D)14, 18\dfrac{1}{4},\ \dfrac{1}{8}41​, 81​

Correct answer: (A)

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Q30·ChemistryMultiple correct
Compound(s) that on hydrogenation produce(s) optically inactive compound(s) is (are)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B), (D)

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Q31·ChemistryMultiple correct
The major product of the following reaction is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

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Q32·ChemistryMultiple correct
In the following reaction, the major product is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

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Q33·ChemistryMultiple correct
The structure of D-(+)-glucose is The structure of L-(−)-glucose is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

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Q34·ChemistryMultiple correct
The major product of the reaction is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

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Q35·ChemistryMultiple correct
The correct statement(s) about Cr2+\mathrm{Cr^{2+}}Cr2+ and Mn3+\mathrm{Mn^{3+}}Mn3+ is(are) [Atomic numbers of Cr = 24 and Mn = 25]
  1. (A)Cr2+\mathrm{Cr^{2+}}Cr2+ is a reducing agent
  2. (B)Mn3+\mathrm{Mn^{3+}}Mn3+ is an oxidizing agent
  3. (C)Both Cr2+\mathrm{Cr^{2+}}Cr2+ and Mn3+\mathrm{Mn^{3+}}Mn3+ exhibit d4d^{4}d4 electronic configuration
  4. (D)When Cr2+\mathrm{Cr^{2+}}Cr2+ is used as a reducing agent, the chromium ion attains d5d^{5}d5 electronic configuration

Correct answer: (A), (B), (C)

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Q36·ChemistryMultiple correct
Copper is purified by electrolytic refining of blister copper. The correct statement(s) about this process is(are)
  1. (A)Impure Cu strip is used as cathode
  2. (B)Acidified aqueous CuSO4\mathrm{CuSO_{4}}CuSO4​ is used as electrolyte
  3. (C)Pure Cu deposits at cathode
  4. (D)Impurities settle as anode – mud

Correct answer: (B), (C), (D)

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Q37·ChemistryMultiple correct
Fe3+\mathrm{Fe^{3+}}Fe3+ is reduced to Fe2+\mathrm{Fe^{2+}}Fe2+ by using
  1. (A)H2O2\mathrm{H_{2}O_{2}}H2​O2​ in presence of NaOH
  2. (B)Na2O2\mathrm{Na_{2}O_{2}}Na2​O2​ in water
  3. (C)H2O2\mathrm{H_{2}O_{2}}H2​O2​ in presence of H2SO4\mathrm{H_{2}SO_{4}}H2​SO4​
  4. (D)Na2O2\mathrm{Na_{2}O_{2}}Na2​O2​ in presence of H2SO4\mathrm{H_{2}SO_{4}}H2​SO4​

Correct answer: (A), (B)

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Q38·ChemistryMultiple correct
The % yield of ammonia as a function of time in the reaction N2(g)+3H2(g)⇌2NH3(g)\mathrm{N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g)}N2​(g)+3H2​(g)⇌2NH3​(g), ΔH<0\Delta H < 0ΔH<0 at (P, T1T_{1}T1​) is given below: If this reaction is conducted at (P, T2T_{2}T2​), with T2>T1T_{2} > T_{1}T2​>T1​, the % yield of ammonia as a function of time is represented by
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

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Q39·ChemistryMatrix match
Match the anionic species given in Column I that are present in the ore(s) given in Column II
Column IColumn II
A.CarbonateP.Siderite
B.SulphideQ.Malachite
C.HydroxideR.Bauxite
D.OxideS.Calamine
T.Argentite

Correct answer: A-(P,Q,S); B-(T); C-(Q,R); D-(R)

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Q40·ChemistryMatrix match
Match the thermodynamic processes given under Column I with the expression given under Column II:
Column IColumn II
A.Freezing of water at 273 K and 1 atmP.q=0q = 0q=0
B.Expansion of 1 mol of an ideal gas into a vacuum under isolated conditionsQ.w=0w = 0w=0
C.Mixing of equal volumes of two ideal gases at constant temperature and pressure in an isolated containerR.ΔSsys<0\Delta S_{\text{sys}} < 0ΔSsys​<0
D.Reversible heating of H2(g)\mathrm{H_{2}(g)}H2​(g) at 1 atm from 300 K to 600 K, followed by reversible cooling to 300 K at 1 atmS.ΔU=0\Delta U = 0ΔU=0
T.ΔG=0\Delta G = 0ΔG=0

Correct answer: A-(R,T); B-(P,Q,S); C-(P,Q,S); D-(P,Q,S,T)

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Mathematics — JEE Advanced 2015 Paper 1

Q41·MathematicsInteger
Let F(x)=∫xx2+π62cos⁡2t dtF(x) = \displaystyle\int_{x}^{x^{2}+\frac{\pi}{6}} 2\cos^{2} t\, dtF(x)=∫xx2+6π​​2cos2tdt for all x∈Rx \in \mathbb{R}x∈R and f:[0,12]→[0,∞)f : \left[0, \dfrac{1}{2}\right] \to [0, \infty)f:[0,21​]→[0,∞) be a continuous function. For a∈[0,12]a \in \left[0, \dfrac{1}{2}\right]a∈[0,21​], if F′(a)+2F'(a) + 2F′(a)+2 is the area of the region bounded by x=0x = 0x=0, y=0y = 0y=0, y=f(x)y = f(x)y=f(x) and x=ax = ax=a, then f(0)f(0)f(0) is

Correct answer: 3

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Q42·MathematicsInteger
The number of distinct solutions of the equation 54cos⁡22x+cos⁡4x+sin⁡4x+cos⁡6x+sin⁡6x=2\dfrac{5}{4}\cos^{2}2x + \cos^{4}x + \sin^{4}x + \cos^{6}x + \sin^{6}x = 245​cos22x+cos4x+sin4x+cos6x+sin6x=2 in the interval [0,2π][0, 2\pi][0,2π] is

Correct answer: 8

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Q43·MathematicsInteger
Let the curve C be the mirror image of the parabola y2=4xy^{2} = 4xy2=4x with respect to the line x+y+4=0x + y + 4 = 0x+y+4=0. If A and B are the points of intersection of C with the line y=−5y = -5y=−5, then the distance between A and B is

Correct answer: 4

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Q44·MathematicsInteger
The minimum number of times a fair coin needs to be tossed, so that the probability of getting at least two heads is at least 0.96 is

Correct answer: 8

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Q45·MathematicsInteger
Let nnn be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let mmm be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue. Then the value of mn\dfrac{m}{n}nm​ is

Correct answer: 5

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Q46·MathematicsInteger
If the normals of the parabola y2=4xy^{2} = 4xy2=4x drawn at the end points of its latus rectum are tangents to the circle (x−3)2+(y+2)2=r2(x - 3)^{2} + (y + 2)^{2} = r^{2}(x−3)2+(y+2)2=r2, then the value of r2r^{2}r2 is

Correct answer: 2

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Q47·MathematicsInteger
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be a function defined by f(x)={[x],x≤20,x>2f(x) = \begin{cases} [x], & x \le 2 \\ 0, & x > 2 \end{cases}f(x)={[x],0,​x≤2x>2​, where [x][x][x] is the greatest integer less than or equal to xxx. If I=∫−12xf(x2)2+f(x+1) dxI = \displaystyle\int_{-1}^{2} \dfrac{x f(x^{2})}{2 + f(x+1)}\, dxI=∫−12​2+f(x+1)xf(x2)​dx, then the value of (4I−1)(4I - 1)(4I−1) is

Correct answer: 0

Step-by-step solution →
Q48·MathematicsInteger
A cylindrical container is to be made from certain solid material with the following constraints: It has a fixed inner volume of V mm3^{3}3, has a 2 mm thick solid wall and is open at the top. The bottom of the container is a solid circular disc of thickness 2 mm and is of radius equal to the outer radius of the container. If the volume of the material used to make the container is minimum when the inner radius of the container is 10 mm, then the value of V250π\dfrac{V}{250\pi}250πV​ is

Correct answer: 4

Step-by-step solution →
Q49·MathematicsMultiple correct
Let ΔPQR\Delta PQRΔPQR be a triangle. Let a⃗=QR→\vec{a} = \overrightarrow{QR}a=QR​, b⃗=RP→\vec{b} = \overrightarrow{RP}b=RP and c⃗=PQ→\vec{c} = \overrightarrow{PQ}c=PQ​. If ∣a⃗∣=12|\vec{a}| = 12∣a∣=12, ∣b⃗∣=43|\vec{b}| = 4\sqrt{3}∣b∣=43​ and b⃗⋅c⃗=24\vec{b} \cdot \vec{c} = 24b⋅c=24, then which of the following is (are) true ?
  1. (A)∣c⃗∣22−∣a⃗∣=12\dfrac{|\vec{c}|^{2}}{2} - |\vec{a}| = 122∣c∣2​−∣a∣=12
  2. (B)∣c⃗∣22+∣a⃗∣=30\dfrac{|\vec{c}|^{2}}{2} + |\vec{a}| = 302∣c∣2​+∣a∣=30
  3. (C)∣a⃗×b⃗+c⃗×a⃗∣=483|\vec{a} \times \vec{b} + \vec{c} \times \vec{a}| = 48\sqrt{3}∣a×b+c×a∣=483​
  4. (D)a⃗⋅b⃗=−72\vec{a} \cdot \vec{b} = -72a⋅b=−72

Correct answer: (A), (C), (D)

Step-by-step solution →
Q50·MathematicsMultiple correct
Which of the following values of α\alphaα satisfy the equation ∣(1+α)2(1+2α)2(1+3α)2(2+α)2(2+2α)2(2+3α)2(3+α)2(3+2α)2(3+3α)2∣=−648α\begin{vmatrix} (1+\alpha)^{2} & (1+2\alpha)^{2} & (1+3\alpha)^{2} \\ (2+\alpha)^{2} & (2+2\alpha)^{2} & (2+3\alpha)^{2} \\ (3+\alpha)^{2} & (3+2\alpha)^{2} & (3+3\alpha)^{2} \end{vmatrix} = -648\alpha​(1+α)2(2+α)2(3+α)2​(1+2α)2(2+2α)2(3+2α)2​(1+3α)2(2+3α)2(3+3α)2​​=−648α ?
  1. (A)−4-4−4
  2. (B)999
  3. (C)−9-9−9
  4. (D)444

Correct answer: (B), (C)

Step-by-step solution →
Q51·MathematicsMultiple correct
In R3\mathbb{R}^{3}R3, consider the planes P1:y=0P_{1} : y = 0P1​:y=0 and P2:x+z=1P_{2} : x + z = 1P2​:x+z=1. Let P3P_{3}P3​ be a plane, different from P1P_{1}P1​ and P2P_{2}P2​, which passes through the intersection of P1P_{1}P1​ and P2P_{2}P2​. If the distance of the point (0,1,0)(0, 1, 0)(0,1,0) from P3P_{3}P3​ is 1 and the distance of a point (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) from P3P_{3}P3​ is 2, then which of the following relations is (are) true ?
  1. (A)2α+β+2γ+2=02\alpha + \beta + 2\gamma + 2 = 02α+β+2γ+2=0
  2. (B)2α−β+2γ+4=02\alpha - \beta + 2\gamma + 4 = 02α−β+2γ+4=0
  3. (C)2α+β−2γ−10=02\alpha + \beta - 2\gamma - 10 = 02α+β−2γ−10=0
  4. (D)2α−β+2γ−8=02\alpha - \beta + 2\gamma - 8 = 02α−β+2γ−8=0

Correct answer: (B), (D)

Step-by-step solution →
Q52·MathematicsMultiple correct
In R3\mathbb{R}^{3}R3, let LLL be a straight line passing through the origin. Suppose that all the points on L are at a constant distance from the two planes P1:x+2y−z+1=0P_{1} : x + 2y - z + 1 = 0P1​:x+2y−z+1=0 and P2:2x−y+z−1=0P_{2} : 2x - y + z - 1 = 0P2​:2x−y+z−1=0. Let MMM be the locus of the feet of the perpendiculars drawn from the points on LLL to the plane P1P_{1}P1​. Which of the following points lie(s) on MMM ?
  1. (A)(0,−56,−23)\left(0, -\dfrac{5}{6}, -\dfrac{2}{3}\right)(0,−65​,−32​)
  2. (B)(−16,−13,16)\left(-\dfrac{1}{6}, -\dfrac{1}{3}, \dfrac{1}{6}\right)(−61​,−31​,61​)
  3. (C)(−56,0,16)\left(-\dfrac{5}{6}, 0, \dfrac{1}{6}\right)(−65​,0,61​)
  4. (D)(−13,0,23)\left(-\dfrac{1}{3}, 0, \dfrac{2}{3}\right)(−31​,0,32​)

Correct answer: (A), (B)

Step-by-step solution →
Q53·MathematicsMultiple correct
Let PPP and QQQ be distinct points on the parabola y2=2xy^{2} = 2xy2=2x such that a circle with PQPQPQ as diameter passes through the vertex O of the parabola. If PPP lies in the first quadrant and the area of the triangle ΔOPQ\Delta OPQΔOPQ is 323\sqrt{2}32​, then which of the following is (are) the coordinates of PPP ?
  1. (A)(4,22)\left(4, 2\sqrt{2}\right)(4,22​)
  2. (B)(9,32)\left(9, 3\sqrt{2}\right)(9,32​)
  3. (C)(14,12)\left(\dfrac{1}{4}, \dfrac{1}{\sqrt{2}}\right)(41​,2​1​)
  4. (D)(1,2)\left(1, \sqrt{2}\right)(1,2​)

Correct answer: (A), (D)

Step-by-step solution →
Q54·MathematicsMultiple correct
Let y(x)y(x)y(x) be a solution of the differential equation (1+ex)y′+yex=1(1 + e^{x})y' + ye^{x} = 1(1+ex)y′+yex=1. If y(0)=2y(0) = 2y(0)=2, then which of the following statements is (are) true ?
  1. (A)y(−4)=0y(-4) = 0y(−4)=0
  2. (B)y(−2)=0y(-2) = 0y(−2)=0
  3. (C)y(x)y(x)y(x) has a critical point in the interval (−1,0)(-1, 0)(−1,0)
  4. (D)y(x)y(x)y(x) has no critical point in the interval (−1,0)(-1, 0)(−1,0)

Correct answer: (A), (C)

Step-by-step solution →
Q55·MathematicsMultiple correct
Consider the family of all circles whose centers lie on the straight line y=xy = xy=x. If this family of circles is represented by the differential equation Py′′+Qy′+1=0Py'' + Qy' + 1 = 0Py′′+Qy′+1=0, where PPP, QQQ are functions of xxx, yyy and y′y'y′ (here y′=dydxy' = \dfrac{dy}{dx}y′=dxdy​, y′′=d2ydx2y'' = \dfrac{d^{2}y}{dx^{2}}y′′=dx2d2y​), then which of the following statements is (are) true ?
  1. (A)P=y+xP = y + xP=y+x
  2. (B)P=y−xP = y - xP=y−x
  3. (C)P+Q=1−x+y+y′+(y′)2P + Q = 1 - x + y + y' + (y')^{2}P+Q=1−x+y+y′+(y′)2
  4. (D)P−Q=x+y−y′−(y′)2P - Q = x + y - y' - (y')^{2}P−Q=x+y−y′−(y′)2

Correct answer: (B), (C)

Step-by-step solution →
Q56·MathematicsMultiple correct
Let g:R→Rg : \mathbb{R} \to \mathbb{R}g:R→R be a differential function with g(0)=0g(0) = 0g(0)=0, g′(0)=0g'(0) = 0g′(0)=0 and g′(1)≠0g'(1) \ne 0g′(1)=0. Let f(x)={x∣x∣g(x),x≠00,x=0f(x) = \begin{cases} \dfrac{x}{|x|}g(x), & x \ne 0 \\ 0, & x = 0 \end{cases}f(x)=⎩⎨⎧​∣x∣x​g(x),0,​x=0x=0​ and h(x)=e∣x∣h(x) = e^{|x|}h(x)=e∣x∣ for all x∈Rx \in \mathbb{R}x∈R. Let (f∘h)(x)(f \circ h)(x)(f∘h)(x) denote f(h(x))f(h(x))f(h(x)) and (h∘f)(x)(h \circ f)(x)(h∘f)(x) denote h(f(x))h(f(x))h(f(x)). Then which of the following is (are) true?
  1. (A)fff is differentiable at x=0x = 0x=0
  2. (B)hhh is differentiable at x=0x = 0x=0
  3. (C)f∘hf \circ hf∘h is differentiable at x=0x = 0x=0
  4. (D)h∘fh \circ fh∘f is differentiable at x=0x = 0x=0

Correct answer: (A), (D)

Step-by-step solution →
Q57·MathematicsMultiple correct
Let f(x)=sin⁡(π6sin⁡(π2sin⁡x))f(x) = \sin\left(\dfrac{\pi}{6}\sin\left(\dfrac{\pi}{2}\sin x\right)\right)f(x)=sin(6π​sin(2π​sinx)) for all x∈Rx \in \mathbb{R}x∈R and g(x)=π2sin⁡xg(x) = \dfrac{\pi}{2}\sin xg(x)=2π​sinx for all x∈Rx \in \mathbb{R}x∈R. Let (f∘g)(x)(f \circ g)(x)(f∘g)(x) denote f(g(x))f(g(x))f(g(x)) and (g∘f)(x)(g \circ f)(x)(g∘f)(x) denote g(f(x))g(f(x))g(f(x)). Then which of the following is (are) true ?
  1. (A)Range of fff is [−12,12]\left[-\dfrac{1}{2}, \dfrac{1}{2}\right][−21​,21​]
  2. (B)Range of f∘gf \circ gf∘g is [−12,12]\left[-\dfrac{1}{2}, \dfrac{1}{2}\right][−21​,21​]
  3. (C)lim⁡x→0f(x)g(x)=π6\displaystyle\lim_{x \to 0} \dfrac{f(x)}{g(x)} = \dfrac{\pi}{6}x→0lim​g(x)f(x)​=6π​
  4. (D)There is an x∈Rx \in \mathbb{R}x∈R such that (g∘f)(x)=1(g \circ f)(x) = 1(g∘f)(x)=1

Correct answer: (A), (B), (C)

Step-by-step solution →
Q58·MathematicsMatrix match
Match the entries in Column I with the entries in Column II.
Column – IColumn – II
A.In R2\mathbb{R}^{2}R2, if the magnitude of the projection vector of the vector αi^+βj^\alpha\hat{i} + \beta\hat{j}αi^+βj^​ on 3i^+j^\sqrt{3}\hat{i} + \hat{j}3​i^+j^​ is 3\sqrt{3}3​ and if α=2+3β\alpha = 2 + \sqrt{3}\betaα=2+3​β, then possible value(s) of ∣α∣|\alpha|∣α∣ is (are)P.1
B.Let aaa and bbb be real numbers such that the function f(x)={−3ax2−2,x<1bx+a2,x≥1f(x) = \begin{cases} -3ax^{2} - 2, & x < 1 \\ bx + a^{2}, & x \ge 1 \end{cases}f(x)={−3ax2−2,bx+a2,​x<1x≥1​ is differentiable for all x∈Rx \in \mathbb{R}x∈R. Then possible value(s) of aaa is (are)Q.2
C.Let ω≠1\omega \ne 1ω=1 be a complex cube root of unity. If (3−3ω+2ω2)4n+3+(2+3ω−3ω2)4n+3+(−3+2ω+3ω2)4n+3=0(3 - 3\omega + 2\omega^{2})^{4n+3} + (2 + 3\omega - 3\omega^{2})^{4n+3} + (-3 + 2\omega + 3\omega^{2})^{4n+3} = 0(3−3ω+2ω2)4n+3+(2+3ω−3ω2)4n+3+(−3+2ω+3ω2)4n+3=0, then possible value(s) of nnn is (are)R.3
D.Let the harmonic mean of two positive real numbers aaa and bbb be 4. If qqq is a positive real number such that aaa, 5, qqq, bbb is an arithmetic progression, then the value(s) of ∣q−a∣|q - a|∣q−a∣ is (are)S.4
T.5

Correct answer: A-(P,Q); B-(P,Q); C-(P,Q,S,T); D-(Q,T)

Step-by-step solution →
Q59·MathematicsMatrix match
Match the entries in Column I with the entries in Column II.
Column – IColumn – II
A.In a triangle ΔXYZ\Delta XYZΔXYZ, let aaa, bbb and ccc be the lengths of the sides opposite to the angles XXX, YYY and ZZZ, respectively. If 2(a2−b2)=c22(a^{2} - b^{2}) = c^{2}2(a2−b2)=c2 and λ=sin⁡(X−Y)sin⁡Z\lambda = \dfrac{\sin(X - Y)}{\sin Z}λ=sinZsin(X−Y)​, then possible values of nnn for which cos⁡(nπλ)=0\cos(n\pi\lambda) = 0cos(nπλ)=0 is (are)P.1
B.In a triangle ΔXYZ\Delta XYZΔXYZ, let aaa, bbb and ccc be the lengths of the sides opposite to the angles XXX, YYY and ZZZ, respectively. If 1+cos⁡2X−2cos⁡2Y=2sin⁡Xsin⁡Y1 + \cos 2X - 2\cos 2Y = 2\sin X \sin Y1+cos2X−2cos2Y=2sinXsinY, then possible value(s) of ab\dfrac{a}{b}ba​ is (are)Q.2
C.In R2\mathbb{R}^{2}R2, let 3i^+j^\sqrt{3}\hat{i} + \hat{j}3​i^+j^​, i^+3j^\hat{i} + \sqrt{3}\hat{j}i^+3​j^​ and βi^+(1−β)j^\beta\hat{i} + (1-\beta)\hat{j}βi^+(1−β)j^​ be the position vectors of XXX, YYY and ZZZ with respect of the origin O, respectively. If the distance of ZZZ from the bisector of the acute angle of OX→\overrightarrow{OX}OX with OY→\overrightarrow{OY}OY is 32\dfrac{3}{\sqrt{2}}2​3​, then possible value(s) of ∣β∣|\beta|∣β∣ is (are)R.3
D.Suppose that F(α)F(\alpha)F(α) denotes the area of the region bounded by x=0x = 0x=0, x=2x = 2x=2, y2=4xy^{2} = 4xy2=4x and y=∣αx−1∣+∣αx−2∣+αxy = |\alpha x - 1| + |\alpha x - 2| + \alpha xy=∣αx−1∣+∣αx−2∣+αx, where α∈{0,1}\alpha \in \{0, 1\}α∈{0,1}. Then the value(s) of F(α)+832F(\alpha) + \dfrac{8}{3}\sqrt{2}F(α)+38​2​, when α=0\alpha = 0α=0 and α=1\alpha = 1α=1, is (are)S.5
T.6

Correct answer: A-(P,R,S); B-(P); C-(P,Q); D-(S,T)

Step-by-step solution →

Chapters tested in this paper

  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Work, Energy and Power 132/186
  • Wave Optics 130/186
  • Kinetic Theory of Gases 135/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Atoms 112/186
  • Parabola 101/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
  • Solid State 63/186
  • Isomerism 51/186
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