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JEE Main 12 January 2019 Shift 1 Question Paper with Answers

12 January 2019 · January session · 84 questions

84 of the 90 questions from the JEE Main 12 January 2019 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

6 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
26
Mathematics
29

Physics — JEE Main 12 January 2019 Shift 1

Q1·PhysicsSingle correct
A travelling harmonic wave is represented by the equation y(x,t)=10−3sin⁡(50t+2x)y(x, t) = 10^{-3}\sin(50t + 2x)y(x,t)=10−3sin(50t+2x), where x and y are in meter and t is in seconds. Which of the following is a correct statement about the wave?
  1. (A)The wave is propagating along the negative x-axis with speed 25 ms−1^{-1}−1.
  2. (B)The wave is propagating along the positive x-axis with speed 100 ms−1^{-1}−1.
  3. (C)The wave is propagating along the positive x-axis with speed 25 ms−1^{-1}−1.
  4. (D)The wave is propagating along the negative x-axis with speed 100 ms−1^{-1}−1.

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
An ideal battery of 4 V and resistance R are connected in series in the primary circuit of a potentiometer of length 1 m and resistance 5 Ω\OmegaΩ. The value of R, to give a difference of 5 mV across 10 cm of potentiometer wire, is:
  1. (A)490 Ω\OmegaΩ
  2. (B)480 Ω\OmegaΩ
  3. (C)395 Ω\OmegaΩ
  4. (D)495 Ω\OmegaΩ

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
In a meter bridge, the wire of length 1 m has a non-uniform cross-section such that, the variation dRdℓ\frac{dR}{d\ell}dℓdR​ of its resistance R with length ℓ\ellℓ is dRdℓ∝1ℓ\frac{dR}{d\ell} \propto \frac{1}{\sqrt{\ell}}dℓdR​∝ℓ​1​. Two equal resistances are connected as shown in the figure. The galvanometer has zero deflection when the jockey is at point P. What is the length AP?
  1. (A)0.2 m
  2. (B)0.3 m
  3. (C)0.25 m
  4. (D)0.35 m

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
A passenger train of length 60 m travels at a speed of 80 km/hr. Another freight train of length 120 m travels at a speed of 30 km/hr. The ratio of times taken by the passenger train to completely cross the freight train when: (i) they are moving in the same direction, and (ii) in the opposite directions is:
  1. (A)115\frac{11}{5}511​
  2. (B)52\frac{5}{2}25​
  3. (C)32\frac{3}{2}23​
  4. (D)2511\frac{25}{11}1125​

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
Two electric bulbs, rated at (25 W, 220 V) and (100 W, 220 V), are connected in series across a 220 V voltage source. If the 25 W and 100 W bulbs draw powers P1_{1}1​ and P2_{2}2​ respectively, then:
  1. (A)P1_{1}1​ = 16 W, P2_{2}2​ = 4 W
  2. (B)P1_{1}1​ = 16 W, P2_{2}2​ = 9 W
  3. (C)P1_{1}1​ = 9 W, P2_{2}2​ = 16 W
  4. (D)P1_{1}1​ = 4 W, P2_{2}2​ = 16 W

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
A straight rod of length L extends from x = a to x = L + a. The gravitational force it exerts on a point mass 'm' at x = 0, if the mass per unit length of the rod is A + Bx2^{2}2, is given by:
  1. (A)Gm[A(1a+L−1a)−BL]Gm\left[A\left(\frac{1}{a+L} - \frac{1}{a}\right) - BL\right]Gm[A(a+L1​−a1​)−BL]
  2. (B)Gm[A(1a−1a+L)−BL]Gm\left[A\left(\frac{1}{a} - \frac{1}{a+L}\right) - BL\right]Gm[A(a1​−a+L1​)−BL]
  3. (C)Gm[A(1a+L−1a)+BL]Gm\left[A\left(\frac{1}{a+L} - \frac{1}{a}\right) + BL\right]Gm[A(a+L1​−a1​)+BL]
  4. (D)Gm[A(1a−1a+L)+BL]Gm\left[A\left(\frac{1}{a} - \frac{1}{a+L}\right) + BL\right]Gm[A(a1​−a+L1​)+BL]

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
What is the position and nature of image formed by lens combination shown in figure? (f1_{1}1​, f2_{2}2​ are focal lengths)
  1. (A)70 cm from point B at left; virtual
  2. (B)40 cm from point B at right; real
  3. (C)203\frac{20}{3}320​ cm from point B at right; real
  4. (D)70 cm from point B at right ; real

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
A point source of light, S is placed at a distance L in front of the centre of plane mirror of width d which is hanging vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror, at a distance 2 L as shown below. The distance over which the man can see the image of the light source in the mirror:
  1. (A)d
  2. (B)2d
  3. (C)3d
  4. (D)d2\frac{d}{2}2d​

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A light wave is incident normally on a glass slab of refractive index 1.5. If 4% of light gets reflected and the amplitude of the electric field of the incident light is 30 V/m, then the amplitude of the electric field for the wave propagating in the glass medium will be:
  1. (A)30 V/m
  2. (B)10 V/m
  3. (C)24 V/m
  4. (D)6 V/m

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
For the given cyclic process CAB as shown for a gas, the work done is:
  1. (A)30 J
  2. (B)10 J
  3. (C)1 J
  4. (D)5 J

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
Determine the electric dipole moment of the system of three charges, placed on the vertices of an equilateral triangle, as shown in the figure:
  1. (A)3 qℓj^−i^2\sqrt{3}\, q\ell \frac{\hat{j} - \hat{i}}{\sqrt{2}}3​qℓ2​j^​−i^​
  2. (B)(qℓ)i^+j^2(q\ell)\frac{\hat{i} + \hat{j}}{\sqrt{2}}(qℓ)2​i^+j^​​
  3. (C)2qℓj^2q\ell \hat{j}2qℓj^​
  4. (D)−3 qℓj^-\sqrt{3}\, q\ell \hat{j}−3​qℓj^​

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
The position vector of the centre of mass r⃗\vec{r}r cm of an asymmetric uniform bar of negligible area of cross-section as shown in figure is:
  1. (A)r⃗\vec{r}r cm =138Lx^+58Ly^= \frac{13}{8}L\hat{x} + \frac{5}{8}L\hat{y}=813​Lx^+85​Ly^​
  2. (B)r⃗\vec{r}r cm =58Lx^+138Ly^= \frac{5}{8}L\hat{x} + \frac{13}{8}L\hat{y}=85​Lx^+813​Ly^​
  3. (C)r⃗\vec{r}r cm =38Lx^+118Ly^= \frac{3}{8}L\hat{x} + \frac{11}{8}L\hat{y}=83​Lx^+811​Ly^​
  4. (D)r⃗\vec{r}r cm =118Lx^+38Ly^= \frac{11}{8}L\hat{x} + \frac{3}{8}L\hat{y}=811​Lx^+83​Ly^​

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
A person standing on an open ground hears the sound of a jet aeroplane, coming from north at an angle 60° with ground level. But he finds the aeroplane right vertically above his position. If υ\upsilonυ is the speed of sound, speed of the plane is:
  1. (A)32υ\frac{\sqrt{3}}{2}\upsilon23​​υ
  2. (B)2υ3\frac{2\upsilon}{\sqrt{3}}3​2υ​
  3. (C)υ\upsilonυ
  4. (D)υ2\frac{\upsilon}{2}2υ​

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
Two light identical springs of spring constant k are attached horizontally at the two ends of a uniform horizontal rod AB of length l and mass m. the rod is pivoted at its centre 'O' and can rotate freely in horizontal plane. The other ends of the two springs are fixed to rigid supports as shown in figure. The rod is gently pushed through a small angle and released. The frequency of resulting oscillation is:
  1. (A)12π3km\frac{1}{2\pi}\sqrt{\frac{3k}{m}}2π1​m3k​​
  2. (B)12π2km\frac{1}{2\pi}\sqrt{\frac{2k}{m}}2π1​m2k​​
  3. (C)12π6km\frac{1}{2\pi}\sqrt{\frac{6k}{m}}2π1​m6k​​
  4. (D)12πkm\frac{1}{2\pi}\sqrt{\frac{k}{m}}2π1​mk​​

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
A simple pendulum, made of a string of length l and a bob of mass m, is released from a small angle θ0\theta_0θ0​. It strikes a block of mass M, kept on a horizontal surface at its lowest point of oscillations, elastically. It bounces back and goes up to an angle θ1\theta_1θ1​. Then M is given by:
  1. (A)m2(θ0+θ1θ0−θ1)\dfrac{m}{2}\left(\dfrac{\theta_0+\theta_1}{\theta_0-\theta_1}\right)2m​(θ0​−θ1​θ0​+θ1​​)
  2. (B)m(θ0−θ1θ0+θ1)m\left(\dfrac{\theta_0-\theta_1}{\theta_0+\theta_1}\right)m(θ0​+θ1​θ0​−θ1​​)
  3. (C)m(θ0+θ1θ0−θ1)m\left(\dfrac{\theta_0+\theta_1}{\theta_0-\theta_1}\right)m(θ0​−θ1​θ0​+θ1​​)
  4. (D)m2(θ0−θ1θ0+θ1)\dfrac{m}{2}\left(\dfrac{\theta_0-\theta_1}{\theta_0+\theta_1}\right)2m​(θ0​+θ1​θ0​−θ1​​)

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
A 100 V carrier wave is made to vary between 160 V and 40 V by a modulating signal. What is the modulation index?
  1. (A)0.3
  2. (B)0.5
  3. (C)0.6
  4. (D)0.4

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A cylinder of radius R is surrounded by a cylindrical shell of inner radius R and outer radius 2R. The thermal conductivity of the material of the inner cylinder is K1K_1K1​ and that of the outer cylinder is K2K_2K2​. Assuming no loss of heat, the effective thermal conductivity of the system for heat flowing along the length of the cylinder is:
  1. (A)K1+K22\dfrac{K_1+K_2}{2}2K1​+K2​​
  2. (B)K1+K2K_1+K_2K1​+K2​
  3. (C)2K1+3K25\dfrac{2K_1+3K_2}{5}52K1​+3K2​​
  4. (D)K1+3K24\dfrac{K_1+3K_2}{4}4K1​+3K2​​

Correct answer: (D)

Step-by-step solution →
Q18·PhysicsSingle correct
The least count of the main scale of a screw gauge is 1 mm. The minimum number of divisions on its circular scale required to measure 5 μ\muμm diameter of a wire is:
  1. (A)50
  2. (B)200
  3. (C)100
  4. (D)500

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
The output of the given logic circuit is:
  1. (A)ABˉ+AˉBA\bar{B}+\bar{A}BABˉ+AˉB
  2. (B)AB+AB‾AB+\overline{AB}AB+AB
  3. (C)ABˉA\bar{B}ABˉ
  4. (D)AˉB\bar{A}BAˉB

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
As shown in the figure, two infinitely long, identical wires are bent by 90° and placed in such a way that the segments LP and QM are along the x-axis, while segments PS and QN are parallel to the y-axis. If OP = OQ = 4 cm, and the magnitude of the magnetic field at O is 10−410^{-4}10−4 T, and the two wires carry equal current (see figure), the magnitude of the current in each wire and the direction of the magnetic field at O will be (μ0=4π×10−7\mu_0=4\pi\times10^{-7}μ0​=4π×10−7 NA−2^{-2}−2):
  1. (A)20 A, perpendicular out of the page
  2. (B)40 A, perpendicular out of the page
  3. (C)20 A, perpendicular into the page
  4. (D)40 A, perpendicular into the page

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsSingle correct
A particle of mass m moves in a circular orbit in a central potential field U(r)=12kr2U(r)=\dfrac{1}{2}kr^2U(r)=21​kr2. If Bohr's quantization conditions are applied, radii of possible orbits and energy levels vary with quantum number n as:
  1. (A)rn∝nr_n \propto \sqrt{n}rn​∝n​, En∝nE_n \propto nEn​∝n
  2. (B)rn∝nr_n \propto \sqrt{n}rn​∝n​, En∝1nE_n \propto \dfrac{1}{n}En​∝n1​
  3. (C)rn∝nr_n \propto nrn​∝n, En∝nE_n \propto nEn​∝n
  4. (D)rn∝n2r_n \propto n^2rn​∝n2, En∝1n2E_n \propto \dfrac{1}{n^2}En​∝n21​

Correct answer: (A)

Step-by-step solution →
Q22·PhysicsSingle correct
A proton and an α\alphaα-particle (with their masses in the ratio of 1:4 and charges in the ratio of 1:2 are accelerated from rest through a potential difference V. If a uniform magnetic field (B) is set up perpendicular to their velocities, the ratio of the radii rp:rαr_p : r_\alpharp​:rα​ of the circular paths described by them will be:
  1. (A)1:21:\sqrt{2}1:2​
  2. (B)1:21:21:2
  3. (C)1:31:31:3
  4. (D)1:31:\sqrt{3}1:3​

Correct answer: (A)

Step-by-step solution →
Q23·PhysicsSingle correct
Let the moment of inertia of a hollow cylinder of length 30 cm (inner radius 10 cm and outer radius 20 cm), about its axis be I. The radius of a thin cylinder of the same mass such that its moment of inertia about its axis is also I, is:
  1. (A)12 cm
  2. (B)16 cm
  3. (C)14 cm
  4. (D)18 cm

Correct answer: (B)

Step-by-step solution →
Q24·PhysicsSingle correct
In the figure shown, a circuit contains two identical resistors with resistance R = 5 Ω\OmegaΩ and an inductance with L = 2 mH. An ideal battery of 15 V is connected in the circuit. What will be the current through the battery long after the switch is closed?
  1. (A)5.5 A
  2. (B)7.5 A
  3. (C)3 A
  4. (D)6 A

Correct answer: (D)

Step-by-step solution →
Q25·PhysicsSingle correct
In the figure shown, after the switch 'S' is turned from position 'A' to position 'B', the energy dissipated in the circuit in terms of capacitance 'C' and total charge 'Q' is:
  1. (A)18Q2C\dfrac{1}{8}\dfrac{Q^2}{C}81​CQ2​
  2. (B)38Q2C\dfrac{3}{8}\dfrac{Q^2}{C}83​CQ2​
  3. (C)58Q2C\dfrac{5}{8}\dfrac{Q^2}{C}85​CQ2​
  4. (D)34Q2C\dfrac{3}{4}\dfrac{Q^2}{C}43​CQ2​

Correct answer: (B)

Step-by-step solution →
Q26·PhysicsSingle correct
A satellite of mass M is in a circular orbit of radius R about the centre of the earth. A meteorite of the same mass, falling towards the earth collides with the satellite completely inelastically. The speeds of the satellite and the meteorite are the same, just before the collision. The subsequent motion of the combined body will be:
  1. (A)such that it escapes to infinity
  2. (B)in an elliptical orbit
  3. (C)in the same circular orbit of radius R
  4. (D)in a circular orbit of a different radius

Correct answer: (B)

Step-by-step solution →
Q27·PhysicsSingle correct
The galvanometer deflection, when key K1K_1K1​ is closed but K2K_2K2​ is open, equals θ0\theta_0θ0​ (see figure). On closing K2K_2K2​ also and adjusting R2R_2R2​ to 5 Ω\OmegaΩ, the deflection in galvanometer becomes θ05\dfrac{\theta_0}{5}5θ0​​. The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery]:
  1. (A)5 Ω\OmegaΩ
  2. (B)22 Ω\OmegaΩ
  3. (C)25 Ω\OmegaΩ
  4. (D)12 Ω\OmegaΩ

Correct answer: (B)

Step-by-step solution →
Q28·PhysicsSingle correct
A particle A of mass 'm' and charge 'q' is accelerated by a potential difference of 50 V. Another particle B of mass '4 m' and charge 'q' is accelerated by a potential difference of 2500 V. The ratio of de-Broglie wavelength λAλB\dfrac{\lambda_A}{\lambda_B}λB​λA​​ is close to:
  1. (A)10.00
  2. (B)0.07
  3. (C)14.14
  4. (D)4.47

Correct answer: (C)

Step-by-step solution →
Q29·PhysicsSingle correct
There is a uniform spherically symmetric surface charge density at a distance R0R_0R0​ from the origin. The charge distribution is initially at rest and starts expanding because of mutual repulsion. The figure that represents best the speed V(R(t)) of the distribution as a function of its instantaneous radius R(t) is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →

Chemistry — JEE Main 12 January 2019 Shift 1

Q30·ChemistrySingle correct
In the Hall-heroult process, aluminium is formed at the cathode. The cathode is made out of
  1. (A)Pure Aluminium
  2. (B)Carbon
  3. (C)Copper
  4. (D)Platinum

Correct answer: (B)

Step-by-step solution →
Q31·ChemistrySingle correct
The correct order for acid strength of compounds: CH≡CHCH \equiv CHCH≡CH, CH3−C≡CHCH_3-C\equiv CHCH3​−C≡CH, CH2=CH2CH_2=CH_2CH2​=CH2​ is as follows:
  1. (A)CH≡CH>CH2=CH2>CH3−C≡CHCH \equiv CH > CH_2=CH_2 > CH_3-C\equiv CHCH≡CH>CH2​=CH2​>CH3​−C≡CH
  2. (B)CH3−C≡CH>CH≡CH>CH2=CH2CH_3-C\equiv CH > CH\equiv CH > CH_2=CH_2CH3​−C≡CH>CH≡CH>CH2​=CH2​
  3. (C)CH3−C≡CH>CH2=CH2>HC≡CHCH_3-C\equiv CH > CH_2=CH_2 > HC\equiv CHCH3​−C≡CH>CH2​=CH2​>HC≡CH
  4. (D)HC≡CH>CH3−C≡CH>CH2=CH2HC\equiv CH > CH_3-C\equiv CH > CH_2=CH_2HC≡CH>CH3​−C≡CH>CH2​=CH2​

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
In a chemical reaction A+2B⇌K2C+DA + 2B \underset{}{\overset{K}{\rightleftharpoons}} 2C + DA+2B⇌K​​2C+D, the initial concentration of B was 1.5 times of A but the equilibrium concentrations of A and B were found to be equal. The equilibrium, constant(K) for the aforesaid chemical reaction is
  1. (A)4
  2. (B)16
  3. (C)1/4
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
Mn2(CO)10Mn_2(CO)_{10}Mn2​(CO)10​ is an organometalic compound due to the presence of
  1. (A)Mn - C bond
  2. (B)Mn - Mn bond
  3. (C)Mn - O bond
  4. (D)C - O bond

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
A metal on combustion in excess air forms X, X upon hydrolysis with water yields H2O2H_2O_2H2​O2​ and O2O_2O2​ along with another product. The metal is:
  1. (A)Na
  2. (B)Rb
  3. (C)Mg
  4. (D)Li

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
The molecules that has minimum/no role in the formation of photochemical smog is:
  1. (A)N2N_2N2​
  2. (B)CH2=OCH_2=OCH2​=O
  3. (C)O3O_3O3​
  4. (D)NO

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
The pair of metal ions that can give a spin-only magnetic moment of 3.9 BM for the complex [M(H2O)6]Cl2[M(H_2O)_6]Cl_2[M(H2​O)6​]Cl2​ is
  1. (A)V2+V^{2+}V2+ and Co2+Co^{2+}Co2+
  2. (B)V2+V^{2+}V2+ and Fe2+Fe^{2+}Fe2+
  3. (C)Co2+Co^{2+}Co2+ and Fe2+Fe^{2+}Fe2+
  4. (D)Cr2+Cr^{2+}Cr2+ and Mn2+Mn^{2+}Mn2+

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correct
For a disatomic ideal gas in a closed system, which of the following plots does not correctly describe the relation between various thermodynamic quantities?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
Among the following compounds most basic amino acid is
  1. (A)Asparagine
  2. (B)Lysine
  3. (C)Serine
  4. (D)Histidine

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
The increasing order of reactivity of the following compounds towards reaction with alkyl halide directly is:
  1. (A)(b) < (a) < (c) < (d)
  2. (B)(a) < (b) < (c) < (d)
  3. (C)(b) < (a) < (d) < (c)
  4. (D)(a) < (c) < (d) < (b)

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Which of the following has lowest freezing point?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
The volume of gas A has is twice than that of gas B. The compressibility factor of gas A is thrice that that of gas B at same temperature. The pressure of gases for equal per moles are
  1. (A)3PA=2PB3P_A = 2P_B3PA​=2PB​
  2. (B)2PA=3PB2P_A = 3P_B2PA​=3PB​
  3. (C)PA=3PBP_A = 3P_BPA​=3PB​
  4. (D)PA=2PBP_A = 2P_BPA​=2PB​

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
The hardness of water sample (in terms of equivalents of CaCO3CaCO_3CaCO3​) containing 10−310^{-3}10−3 M CaSO4CaSO_4CaSO4​ is (molar mass of CaSO4CaSO_4CaSO4​ = 136 g mol−1^{-1}−1)
  1. (A)10 ppm
  2. (B)50 ppm
  3. (C)90 ppm
  4. (D)100 ppm

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
CH3−CH2−C(OH)(Ph)−CH3CH_3-CH_2-C(OH)(Ph)-CH_3CH3​−CH2​−C(OH)(Ph)−CH3​ can not be prepared by :
  1. (A)CH3CH2COCH3CH_3CH_2COCH_3CH3​CH2​COCH3​ + PhMgX
  2. (B)PhCOCH2CH3PhCOCH_2CH_3PhCOCH2​CH3​ + CH3MgXCH_3MgXCH3​MgX
  3. (C)PhCOCH3PhCOCH_3PhCOCH3​ + CH3CH2MgXCH_3CH_2MgXCH3​CH2​MgX
  4. (D)HCHO + PhCH(CH3)CH2MgXPhCH(CH_3)CH_2MgXPhCH(CH3​)CH2​MgX

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
Freezing point of a 4% aqueous solution of X is equal to freezing point of 12% aqueous solution of Y. If molecular weight of X is A then molecular weight of Y is
  1. (A)3A
  2. (B)2A
  3. (C)A
  4. (D)4A

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
The metal d-orbital that can directly facing the ligands in K3[Co(CN)6]K_3[Co(CN)_6]K3​[Co(CN)6​] are
  1. (A)dxyd_{xy}dxy​ and dx2−y2d_{x^2-y^2}dx2−y2​
  2. (B)dx2−y2d_{x^2-y^2}dx2−y2​ and dz2d_{z^2}dz2​
  3. (C)dxz,dyzd_{xz}, d_{yz}dxz​,dyz​ and dz2d_{z^2}dz2​
  4. (D)dxy,dxzd_{xy}, d_{xz}dxy​,dxz​ and dyzd_{yz}dyz​

Correct answer: (B)

Step-by-step solution →
Q47·ChemistrySingle correct
Decomposition of X exhibits a rate constant for 0.05 μg\mu gμg/year. How many years are required for the decomposition of 5 μg\mu gμg of X into 2.5 μg\mu gμg?
  1. (A)50
  2. (B)25
  3. (C)20
  4. (D)40

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
The standard electrode potential E⊖E^{\ominus}E⊖ and its temperature coefficient (dE⊖dT)\left(\dfrac{dE^{\ominus}}{dT}\right)(dTdE⊖​) for a cell are 2 V and −5×10−4-5\times10^{-4}−5×10−4 VK−1K^{-1}K−1 at 300 K respectively. The cell reaction is : Zn(s)+Cu2+(aq)⇌Zn2+(aq)+Cu(s)Zn(s)+Cu^{2+}(aq)\rightleftharpoons Zn^{2+}(aq)+Cu(s)Zn(s)+Cu2+(aq)⇌Zn2+(aq)+Cu(s) Standard reaction enthalpy (ΔrH⊖\Delta_rH^{\ominus}Δr​H⊖)........
  1. (A)-412.8
  2. (B)-384.0
  3. (C)1920
  4. (D)206.4 kJ

Correct answer: (A)

Step-by-step solution →
Q49·ChemistrySingle correct
The element with Z = 120 (not yet discovered) will be an/a
  1. (A)Inner transition metal
  2. (B)Alkaline earth metal
  3. (C)Alkali metal
  4. (D)Transition metal

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
In the following reaction Aldehyde + Alcohol →HCl\xrightarrow{HCl}HCl​ Acetal The best combination is
AldehydeAlcohol
HCHOtBuOH^tBuOHtBuOH
CH3CHOCH_3CHOCH3​CHOMeOH
  1. (A)CH3CHOCH_3CHOCH3​CHO and tBuOH^tBuOHtBuOH
  2. (B)HCHO and MeOH
  3. (C)CH3CHOCH_3CHOCH3​CHO and MeOH
  4. (D)HCHO and tBuOH^tBuOHtBuOH

Correct answer: (B)

Step-by-step solution →
Q51·ChemistrySingle correct
Two solids dissociate as follows A(s)⇌B(g)+C(g);Kp1=x atm2A(s)\rightleftharpoons B(g)+C(g); K_{p_1}=x\ atm^2A(s)⇌B(g)+C(g);Kp1​​=x atm2 D(s)⇌C(g)+E(g);Kp2=y atm2D(s)\rightleftharpoons C(g)+E(g); K_{p_2}=y\ atm^2D(s)⇌C(g)+E(g);Kp2​​=y atm2 The total pressure when both the solids dissociate simultaneously is
  1. (A)x+y\sqrt{x+y}x+y​ atm
  2. (B)2(x+y)2(\sqrt{x+y})2(x+y​) atm
  3. (C)(x+y)(x+y)(x+y) atm
  4. (D)x2+y2x^2+y^2x2+y2 atm

Correct answer: (B)

Step-by-step solution →
Q52·ChemistrySingle correct
In the following reactions, products A and B are: →dil NaOH\xrightarrow{dil\ NaOH}dil NaOH​ [A] [A] →ΔH3O+\xrightarrow[\Delta]{H_3O^+}H3​O+Δ​ [B]
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q53·ChemistrySingle correct
What is the work function of the metal if the light of wavelength 4000 Å generates photoelectrons of velocity 6×1056\times10^56×105 ms−1^{-1}−1 from it? (Mass of electron = 9×10−319\times10^{-31}9×10−31 kg Velocity of light = 3×1083\times10^83×108 ms−1^{-1}−1 Planck's constant = 6.626×10−346.626\times10^{-34}6.626×10−34 Js Charge of electron = 1.6×10−191.6\times10^{-19}1.6×10−19 JeV−1^{-1}−1)
  1. (A)0.9 eV
  2. (B)3.1 eV
  3. (C)2.1 eV
  4. (D)4.0 eV

Correct answer: (C)

Step-by-step solution →
Q54·ChemistrySingle correct
Poly - \u03b2-hydroxybutyrate-co-\u03b2-hydroxyvalerate(PHBV) is a copolymer of ________
  1. (A)3-hydroxybutanoic acid and 4-hydroxypentanoic acid
  2. (B)2-hydroxybutanoic acid and 3-hydroxypentanoic acid
  3. (C)3-hydroxybutanoic acid and 2-hydroxypentanoic acid
  4. (D)3-hydroxy butanoic acid and 3-hydroxypentanoic acid

Correct answer: (D)

Step-by-step solution →
Q55·ChemistrySingle correct
Water sample with BOD vales of 4 ppm and 18 ppm respectively are
  1. (A)Clean and clean
  2. (B)Highly polluted and clean
  3. (C)Clean and highly polluted
  4. (D)Highly polluted and highly polluted.

Correct answer: (C)

Step-by-step solution →

Mathematics — JEE Main 12 January 2019 Shift 1

Q56·MathematicsSingle correct
An ordered pair (α,β)(\alpha, \beta)(α,β) for which the system of linear equations (1+α)x+βy+z=2(1 + \alpha)x + \beta y + z = 2(1+α)x+βy+z=2 αx+(1+β)y+z=3\alpha x + (1 + \beta)y + z = 3αx+(1+β)y+z=3 αx+βy+2z=2\alpha x + \beta y + 2z = 2αx+βy+2z=2 has a unique solution, is:
  1. (A)(2,4)(2, 4)(2,4)
  2. (B)(−3,1)(-3, 1)(−3,1)
  3. (C)(−4,2)(-4, 2)(−4,2)
  4. (D)(1,−3)(1, -3)(1,−3)

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correct
The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is:
  1. (A)36
  2. (B)32
  3. (C)24
  4. (D)28

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsSingle correct
The Boolean expression ((p∧q)∨(p∨∼q))∧(∼p∧∼q)((p \wedge q) \vee (p \vee \sim q)) \wedge (\sim p \wedge \sim q)((p∧q)∨(p∨∼q))∧(∼p∧∼q) is equivalent to:
  1. (A)p∧qp \wedge qp∧q
  2. (B)p∧(∼q)p \wedge (\sim q)p∧(∼q)
  3. (C)(∼p)∧(∼q)(\sim p) \wedge (\sim q)(∼p)∧(∼q)
  4. (D)p∨(∼q)p \vee (\sim q)p∨(∼q)

Correct answer: (C)

Step-by-step solution →
Q59·MathematicsSingle correct
Consider three boxes, each containing 10 balls labelled 1, 2, ....., 10. Suppose one ball is randomly drawn from each of the boxes. Denote by nin_ini​, the label of the ball drawn from the ithi^{th}ith box, (i=1,2,3)(i = 1, 2, 3)(i=1,2,3). Then, the number of ways in which the balls can be chosen such that n1<n2<n3n_1 < n_2 < n_3n1​<n2​<n3​ is:
  1. (A)120
  2. (B)82
  3. (C)240
  4. (D)164

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
A tetrahedron has vertices P(1, 2, 1), Q(2, 1, 3), R(-1, 1, 2) and O(0, 0, 0). The angle between the faces OPQ and PQR is:
  1. (A)cos⁡−1(1731)\cos^{-1}\left(\dfrac{17}{31}\right)cos−1(3117​)
  2. (B)cos⁡−1(1935)\cos^{-1}\left(\dfrac{19}{35}\right)cos−1(3519​)
  3. (C)cos⁡−1(935)\cos^{-1}\left(\dfrac{9}{35}\right)cos−1(359​)
  4. (D)cos⁡−1(731)\cos^{-1}\left(\dfrac{7}{31}\right)cos−1(317​)

Correct answer: (B)

Step-by-step solution →
Q61·MathematicsSingle correct
The maximum area (in sq. units) of a rectangle having its base on the x-axis and its other two vertices on the parabola, y=12−x2y = 12 - x^{2}y=12−x2 such that the rectangle lies inside the parabola, is:
  1. (A)36
  2. (B)20220\sqrt{2}202​
  3. (C)32
  4. (D)18318\sqrt{3}183​

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
If the straight line, 2x−3y+17=02x - 3y + 17 = 02x−3y+17=0 is perpendicular to the line passing through the points (7, 17) and (15,β)(15, \beta)(15,β), then β\betaβ equals:
  1. (A)353\dfrac{35}{3}335​
  2. (B)-5
  3. (C)−353-\dfrac{35}{3}−335​
  4. (D)5

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
The sum of the distinct real values of μ\muμ, for which the vectors, μi^+j^+k^\mu\hat{i} + \hat{j} + \hat{k}μi^+j^​+k^, i^+μj^+k^\hat{i} + \mu\hat{j} + \hat{k}i^+μj^​+k^, i^+j^+μk^\hat{i} + \hat{j} + \mu\hat{k}i^+j^​+μk^ are co-planar, is:
  1. (A)-1
  2. (B)0
  3. (C)1
  4. (D)2

Correct answer: (A)

Step-by-step solution →
Q64·MathematicsSingle correct
Let P(4, -4) and Q(9, 6) be two points on the parabola, y2=4xy^{2} = 4xy2=4x and let X be any point on the arc POQ of this parabola, where O is the vertex of this parabola, such that the area of △PXQ\triangle PXQ△PXQ is maximum. Then this maximum Area (in sq. units) is:
  1. (A)752\dfrac{75}{2}275​
  2. (B)1254\dfrac{125}{4}4125​
  3. (C)6254\dfrac{625}{4}4625​
  4. (D)1252\dfrac{125}{2}2125​

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let P=[100310931]P = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix}P=​139​013​001​​ and Q=[qij]Q = [q_{ij}]Q=[qij​] be two 3×33 \times 33×3 matrices such that Q−P5=I3Q - P^{5} = I_{3}Q−P5=I3​. Then q21+q31q32\dfrac{q_{21} + q_{31}}{q_{32}}q32​q21​+q31​​ is equal to:
  1. (A)10
  2. (B)135
  3. (C)15
  4. (D)9

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation, xdydx+y=xlog⁡ex,(x>1)x\dfrac{dy}{dx} + y = x\log_{e} x, (x > 1)xdxdy​+y=xloge​x,(x>1). If 2y(2)=log⁡e4−12y(2) = \log_{e} 4 - 12y(2)=loge​4−1, then y(e)y(e)y(e) is equal to:
  1. (A)−e2-\dfrac{e}{2}−2e​
  2. (B)−e22-\dfrac{e^{2}}{2}−2e2​
  3. (C)e4\dfrac{e}{4}4e​
  4. (D)e24\dfrac{e^{2}}{4}4e2​

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
The area (in sq. units) of the region bounded by the parabola, y=x2+2y = x^{2} + 2y=x2+2 and the lines, y=x+1y = x + 1y=x+1, x=0x = 0x=0 and x=3x = 3x=3, is:
  1. (A)154\dfrac{15}{4}415​
  2. (B)212\dfrac{21}{2}221​
  3. (C)174\dfrac{17}{4}417​
  4. (D)152\dfrac{15}{2}215​

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
In a random experiment, a fair die is rolled until two fours are obtained in succession. The probability that the experiment will end in the fifth throw of the die is equal to:
  1. (A)20065\dfrac{200}{6^{5}}65200​
  2. (B)15065\dfrac{150}{6^{5}}65150​
  3. (C)22565\dfrac{225}{6^{5}}65225​
  4. (D)17565\dfrac{175}{6^{5}}65175​

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correct
Let C1C_1C1​ and C2C_2C2​ be the centres of the circles x2+y2−2x−2y−2=0x^{2} + y^{2} - 2x - 2y - 2 = 0x2+y2−2x−2y−2=0 and x2+y2−6x−6y+14=0x^{2} + y^{2} - 6x - 6y + 14 = 0x2+y2−6x−6y+14=0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1QC2PC_1QC_2PC1​QC2​ is:
  1. (A)8
  2. (B)6
  3. (C)9
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
The maximum value of 3cos⁡θ+5sin⁡(θ−π6)3\cos\theta + 5\sin\left(\theta - \dfrac{\pi}{6}\right)3cosθ+5sin(θ−6π​) for any real value of θ\thetaθ is:
  1. (A)19\sqrt{19}19​
  2. (B)792\dfrac{\sqrt{79}}{2}279​​
  3. (C)34\sqrt{34}34​
  4. (D)31\sqrt{31}31​

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Considering only the principal values of inverse functions, the set A={x≥0:tan⁡−1(2x)+tan⁡−1(3x)=π4}A=\left\{x\geq 0: \tan^{-1}(2x)+\tan^{-1}(3x)=\frac{\pi}{4}\right\}A={x≥0:tan−1(2x)+tan−1(3x)=4π​}
  1. (A)contains two elements
  2. (B)contains more than two elements
  3. (C)is a singleton
  4. (D)is an empty set

Correct answer: (C)

Step-by-step solution →
Q72·MathematicsSingle correct
If λ\lambdaλ be the ratio of the roots of the quadratic equation in x, 3m2x2+m(m−4)x+2=03m^{2}x^{2}+m(m-4)x+2=03m2x2+m(m−4)x+2=0, then the least value of m for which λ+1λ=1\lambda+\frac{1}{\lambda}=1λ+λ1​=1, is:
  1. (A)2−32-\sqrt{3}2−3​
  2. (B)4−324-3\sqrt{2}4−32​
  3. (C)−2+2-2+\sqrt{2}−2+2​
  4. (D)4−234-2\sqrt{3}4−23​

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
If a variable line, 3x+4y−λ=03x+4y-\lambda=03x+4y−λ=0 is such that the two circles x2+y2−2x−2y+1=0x^{2}+y^{2}-2x-2y+1=0x2+y2−2x−2y+1=0 and x2+y2−18x−2y+78=0x^{2}+y^{2}-18x-2y+78=0x2+y2−18x−2y+78=0 are on its opposite sides, then the set of all values of λ\lambdaλ is the interval:
  1. (A)(2,17)(2, 17)(2,17)
  2. (B)[13,23][13, 23][13,23]
  3. (C)[12,21][12, 21][12,21]
  4. (D)(23,31)(23, 31)(23,31)

Correct answer: (C)

Step-by-step solution →
Q74·MathematicsSingle correct
For x > 1, if (2x)2y=4e2x−2y(2x)^{2y}=4e^{2x-2y}(2x)2y=4e2x−2y, then (1+log⁡e2x)2dydx(1+\log_{e}2x)^{2}\frac{dy}{dx}(1+loge​2x)2dxdy​ is equal to:
  1. (A)xlog⁡e2x−log⁡e2x\frac{x\log_{e}2x-\log_{e}2}{x}xxloge​2x−loge​2​
  2. (B)log⁡e2x\log_{e}2xloge​2x
  3. (C)xlog⁡e2x+log⁡e2x\frac{x\log_{e}2x+\log_{e}2}{x}xxloge​2x+loge​2​
  4. (D)xlog⁡e2xx\log_{e}2xxloge​2x

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
The integral ∫cos⁡(log⁡ex)dx\int \cos(\log_{e}x)dx∫cos(loge​x)dx is equal to: (where C is a constant of integration)
  1. (A)x2[sin⁡(log⁡ex)−cos⁡(log⁡ex)]+C\frac{x}{2}\left[\sin(\log_{e}x)-\cos(\log_{e}x)\right]+C2x​[sin(loge​x)−cos(loge​x)]+C
  2. (B)x[cos⁡(log⁡ex)+sin⁡(log⁡ex)]+Cx\left[\cos(\log_{e}x)+\sin(\log_{e}x)\right]+Cx[cos(loge​x)+sin(loge​x)]+C
  3. (C)x2[cos⁡(log⁡ex)+sin⁡(log⁡ex)]+C\frac{x}{2}\left[\cos(\log_{e}x)+\sin(\log_{e}x)\right]+C2x​[cos(loge​x)+sin(loge​x)]+C
  4. (D)x[cos⁡(log⁡ex)−sin⁡(log⁡ex)]+Cx\left[\cos(\log_{e}x)-\sin(\log_{e}x)\right]+Cx[cos(loge​x)−sin(loge​x)]+C

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsSingle correct
Let Sk=1+2+3+.....+kkS_{k}=\frac{1+2+3+.....+k}{k}Sk​=k1+2+3+.....+k​. If S12+S22+.....+S102=512AS_{1}^{2}+S_{2}^{2}+.....+S_{10}^{2}=\frac{5}{12}AS12​+S22​+.....+S102​=125​A, then A equal to:
  1. (A)283
  2. (B)301
  3. (C)303
  4. (D)156

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
The perpendicular distance from the origin to the plane containing the two lines, x+23=y−25=z+57\frac{x+2}{3}=\frac{y-2}{5}=\frac{z+5}{7}3x+2​=5y−2​=7z+5​ and x−11=y−44=z+47\frac{x-1}{1}=\frac{y-4}{4}=\frac{z+4}{7}1x−1​=4y−4​=7z+4​, is:
  1. (A)11611\sqrt{6}116​
  2. (B)11/611/\sqrt{6}11/6​
  3. (C)11
  4. (D)6116\sqrt{11}611​

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is:
  1. (A)30
  2. (B)51
  3. (C)50
  4. (D)31

Correct answer: (D)

Step-by-step solution →
Q79·MathematicsSingle correct
Let S be the set of all points in (−π,π)(-\pi, \pi)(−π,π) at which the function, f(x)=min⁡{sin⁡x,cos⁡x}f(x)=\min\{\sin x, \cos x\}f(x)=min{sinx,cosx} is non-differentiable. Then S is a subset of which of the following?
  1. (A){−π4,0,π4}\left\{-\frac{\pi}{4},0,\frac{\pi}{4}\right\}{−4π​,0,4π​}
  2. (B){−3π4,−π4,3π4,π4}\left\{-\frac{3\pi}{4},-\frac{\pi}{4},\frac{3\pi}{4},\frac{\pi}{4}\right\}{−43π​,−4π​,43π​,4π​}
  3. (C){−π2,−π4,π4,π2}\left\{-\frac{\pi}{2},-\frac{\pi}{4},\frac{\pi}{4},\frac{\pi}{2}\right\}{−2π​,−4π​,4π​,2π​}
  4. (D){−3π4,−π2,π2,3π4}\left\{-\frac{3\pi}{4},-\frac{\pi}{2},\frac{\pi}{2},\frac{3\pi}{4}\right\}{−43π​,−2π​,2π​,43π​}

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsSingle correct
Let f and g be continuous functions on [0,a][0, a][0,a] such that f(x)=f(a−x)f(x)=f(a-x)f(x)=f(a−x) and g(x)+g(a−x)=4g(x)+g(a-x)=4g(x)+g(a−x)=4, then ∫0af(x)g(x)dx\int_{0}^{a}f(x)g(x)dx∫0a​f(x)g(x)dx is equal to:
  1. (A)4∫0af(x)dx4\int_{0}^{a}f(x)dx4∫0a​f(x)dx
  2. (B)∫0af(x)dx\int_{0}^{a}f(x)dx∫0a​f(x)dx
  3. (C)2∫0af(x)dx2\int_{0}^{a}f(x)dx2∫0a​f(x)dx
  4. (D)−3∫0af(x)dx-3\int_{0}^{a}f(x)dx−3∫0a​f(x)dx

Correct answer: (C)

Step-by-step solution →
Q81·MathematicsSingle correct
lim⁡x→π/4cot⁡3x−tan⁡xcos⁡(x+π/4)\lim_{x\to \pi/4}\frac{\cot^{3}x-\tan x}{\cos\left(x+\pi/4\right)}limx→π/4​cos(x+π/4)cot3x−tanx​ is:
  1. (A)4
  2. (B)424\sqrt{2}42​
  3. (C)828\sqrt{2}82​
  4. (D)8

Correct answer: (D)

Step-by-step solution →
Q82·MathematicsSingle correct
If z−αz+α(α∈R)\frac{z-\alpha}{z+\alpha}(\alpha \in R)z+αz−α​(α∈R) is a purely imaginary number and ∣z∣=2|z|=2∣z∣=2, then a value of α\alphaα is:
  1. (A)2
  2. (B)1
  3. (C)12\frac{1}{2}21​
  4. (D)2\sqrt{2}2​

Correct answer: (A)

Step-by-step solution →
Q83·MathematicsSingle correct
Let S={1,2,3,.....,100}S=\{1, 2, 3, ....., 100\}S={1,2,3,.....,100}. The number of non-empty subsets A of S such that the product of elements in A is even is:
  1. (A)2100−12^{100}-12100−1
  2. (B)250(250−1)2^{50}(2^{50}-1)250(250−1)
  3. (C)250−12^{50}-1250−1
  4. (D)250+12^{50}+1250+1

Correct answer: (B)

Step-by-step solution →
Q84·MathematicsSingle correct
If the vertices of a hyperbola be at (−2,0)(-2, 0)(−2,0) and (2,0)(2, 0)(2,0) and one of its foci be at (−3,0)(-3, 0)(−3,0), then which one of the following points does not lie on this hyperbola?
  1. (A)(−6,210)\left(-6,2\sqrt{10}\right)(−6,210​)
  2. (B)(26,5)\left(2\sqrt{6},5\right)(26​,5)
  3. (C)(4,15)\left(4,\sqrt{15}\right)(4,15​)
  4. (D)(6,52)\left(6,5\sqrt{2}\right)(6,52​)

Correct answer: (D)

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Alcohols and Ethers 106/186
  • Oscillations 117/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Hyperbola 77/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • States of Matter: Gases and Liquids 52/186
  • Mathematical Reasoning 26/186
  • Communication Systems 11/186
← 11 Jan Shift 2 2019All papers12 Jan Shift 2 2019 →

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