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JEE Main 7 April 2025 Shift 2 Question Paper with Answers

7 April 2025 · April session · 75 questions

The complete JEE Main 7 April 2025 Shift 2 paper — all 75 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
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Chemistry
25
Mathematics
25

Physics — JEE Main 7 April 2025 Shift 2

Q1·Physics·Electric Field and Coulomb's LawSingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The outer body of an aircraft is made of metal which protects persons sitting inside from lightning-strikes. Reason (R): The electric field inside the cavity enclosed by a conductor is zero. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  2. (B)(A) is correct but (R) is not correct
  3. (C)Both (A) and (R) are correct but (R) is not correct explanation of (A)
  4. (D)(A) is not correct but (R) is correct

Correct answer: (A)

Step-by-step solution →
Q2·Physics·Atoms and NucleiSingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The density of the copper (2964Cu)\left({}^{64}_{29}\mathrm{Cu}\right)(2964​Cu) nucleus is greater than that of the carbon (612C)\left({}^{12}_{6}\mathrm{C}\right)(612​C) nucleus. Reason (R): The nucleus of mass number A has a radius proportional to A1/3A^{1/3}A1/3. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)(A) is correct but (R) is not correct
  2. (B)(A) is not correct but (R) is correct
  3. (C)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  4. (D)Both (A) and (R) are correct but (R) is not the correct explanation of (A)

Correct answer: (B)

Step-by-step solution →
Q3·Physics·Electromagnetic WavesSingle correct
The unit of 2Iϵ0 c\sqrt{\dfrac{2I}{\epsilon_0\,c}}ϵ0​c2I​​ is: (III = intensity of an electromagnetic wave, ccc = speed of light)
  1. (A)Vm
  2. (B)NC
  3. (C)Nm
  4. (D)NC−1NC^{-1}NC−1

Correct answer: (D)

Step-by-step solution →
Q4·Physics·Electromagnetic WavesSingle correct
The dimension of μ0ϵ0\sqrt{\dfrac{\mu_0}{\epsilon_0}}ϵ0​μ0​​​ is equal to that of: (μ0\mu_0μ0​ = vacuum permeability and ϵ0\epsilon_0ϵ0​ = vacuum permittivity)
  1. (A)Voltage
  2. (B)Capacitance
  3. (C)Inductance
  4. (D)Resistance

Correct answer: (D)

Step-by-step solution →
Q5·Physics·Dual Nature of Matter and RadiationSingle correct
A photo-emissive substance is illuminated with a radiation of wavelength λi\lambda_iλi​ so that it releases electrons with de-Broglie wavelength λe\lambda_eλe​. The longest wavelength of radiation that can emit photoelectron is λ0\lambda_0λ0​. Expression for de-Broglie wavelength is given by: (mmm = mass of the electron, hhh = Planck's constant and ccc = speed of light)
  1. (A)λe=h2mc(1λi−1λ0)\lambda_e=\sqrt{\dfrac{h}{2mc\left(\frac{1}{\lambda_i}-\frac{1}{\lambda_0}\right)}}λe​=2mc(λi​1​−λ0​1​)h​​
  2. (B)λe=hλ02mc\lambda_e=\sqrt{\dfrac{h\lambda_0}{2mc}}λe​=2mchλ0​​​
  3. (C)λe=h2mc(1λi−1λ0)\lambda_e=\dfrac{h}{\sqrt{2mc\left(\frac{1}{\lambda_i}-\frac{1}{\lambda_0}\right)}}λe​=2mc(λi​1​−λ0​1​)​h​
  4. (D)λe=hλi2mc\lambda_e=\sqrt{\dfrac{h\lambda_i}{2mc}}λe​=2mchλi​​​

Correct answer: (A)

Step-by-step solution →
Q6·Physics·GravitationSingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The radius vector from the Sun to a planet sweeps out equal areas in equal intervals of time and areal velocity of planet is constant. Reason (R): For a central force field the angular momentum is constant. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  2. (B)Both (A) and (R) are correct but (R) is not the correct explanation of (A)
  3. (C)(A) is correct but (R) is not correct
  4. (D)(A) is not correct but (R) is correct

Correct answer: (A)

Step-by-step solution →
Q7·Physics·Kinetic Theory of GasesSingle correct
The helium and argon are put in the flask at the same room temperature (300 K). The ratio of average kinetic energies (per molecule) of helium and argon is: (Given: Molar mass of helium = 4 g/mol, Molar mass of argon = 40 g/mol)
  1. (A)1 : 10
  2. (B)10 : 1
  3. (C)1:101:\sqrt{10}1:10​
  4. (D)1 : 1

Correct answer: (D)

Step-by-step solution →
Q8·Physics·Properties of Solids and LiquidsSingle correct
A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70 dyn/cm and glass-water contact angle ≃0∘\simeq 0^\circ≃0∘) with 30∘30^\circ30∘ inclined with vertical. The length of water risen in the capillary is __________ cm. (Take g=9.8g=9.8g=9.8 m/s2^22)
  1. (A)825\dfrac{82}{5}582​
  2. (B)572\dfrac{57}{2}257​
  3. (C)715\dfrac{71}{5}571​
  4. (D)685\dfrac{68}{5}568​

Correct answer: (A)

Step-by-step solution →
Q9·Physics·Geometrical OpticsSingle correct
A mirror is used to produce an image with magnification of 14\dfrac{1}{4}41​. If the distance between object and its image is 40 cm, then the focal length of the mirror is __________.
  1. (A)10 cm
  2. (B)12.7 cm
  3. (C)10.7 cm
  4. (D)15 cm

Correct answer: (C)

Step-by-step solution →
Q10·Physics·Electric Field and Coulomb's LawSingle correct
A dipole with two electric charges of 2 μC magnitude each, with separation distance 0.5 μm, is placed between the plates of a capacitor such that its axis is parallel to an electric field established between the plates with a potential difference of 5 V applied. Separation between the plates is 0.5 mm. If the dipole is rotated by 30∘30^\circ30∘ from the axis, it tends to realign in the direction due to a torque. The value of torque is:
  1. (A)5×10−95\times10^{-9}5×10−9 Nm
  2. (B)5×10−35\times10^{-3}5×10−3 Nm
  3. (C)2.5×10−122.5\times10^{-12}2.5×10−12 Nm
  4. (D)2.5×10−92.5\times10^{-9}2.5×10−9 Nm

Correct answer: (A)

Step-by-step solution →
Q11·Physics·Electronic DevicesSingle correct
Consider the following logic circuit. The output is Y=0Y=0Y=0 when:
  1. (A)A = 1 and B = 1
  2. (B)A = 0 and B = 1
  3. (C)A = 1 and B = 0
  4. (D)A = 0 and B = 0

Correct answer: (A)

Step-by-step solution →
Q12·Physics·Units and MeasurementsSingle correct
Match the LIST-I (Mechanical quantity) with LIST-II (Dimensional formula). Choose the correct answer from the options given below:
LIST-I (Mechanical quantity)LIST-II (Dimensional formula)
A.Mass densityI.[ML2T−3][ML^2T^{-3}][ML2T−3]
B.ImpulseII.[MLT−1][MLT^{-1}][MLT−1]
C.PowerIII.[ML2T0][ML^2T^0][ML2T0]
D.Moment of inertiaIV.[ML−3T0][ML^{-3}T^0][ML−3T0]
  1. (A)(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  2. (B)(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
  3. (C)(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  4. (D)(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Correct answer: (C)

Step-by-step solution →
Q13·Physics·OscillationsSingle correct
The equation of a wave travelling on a string is y=sin⁡[20πx+10πt]y=\sin[20\pi x+10\pi t]y=sin[20πx+10πt], where xxx and ttt are distance and time in SI units. The minimum distance between two points having the same oscillating speed is:
  1. (A)5.0 cm
  2. (B)20 cm
  3. (C)10 cm
  4. (D)2.5 cm

Correct answer: (A)

Step-by-step solution →
Q14·Physics·Geometrical OpticsSingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): Refractive index of glass is higher than that of air. Reason (R): Optical density of a medium is directly proportionate to its mass density which results in a proportionate refractive index. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)(A) is not correct but (R) is correct
  2. (B)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  3. (C)(A) is correct but (R) is not correct
  4. (D)Both (A) and (R) are correct but (R) is not the correct explanation of (A)

Correct answer: (C)

Step-by-step solution →
Q15·Physics·Magnetism and MatterSingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): Magnetic monopoles do not exist. Reason (R): Magnetic field lines are continuous and form closed loops. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both (A) and (R) are correct but (R) is not the correct explanation of (A)
  2. (B)(A) is correct but (R) is not correct
  3. (C)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  4. (D)(A) is not correct but (R) is correct

Correct answer: (C)

Step-by-step solution →
Q16·Physics·Work, Energy and PowerSingle correct
Which one of the following forces cannot be expressed in terms of potential energy?
  1. (A)Coulomb's force
  2. (B)Gravitational force
  3. (C)Frictional force
  4. (D)Restoring force

Correct answer: (C)

Step-by-step solution →
Q17·Physics·ThermodynamicsSingle correct
Match the LIST-I (Thermodynamic process) with LIST-II (Characteristic). Choose the correct answer from the options given below:
LIST-I (Thermodynamic process)LIST-II (Characteristic)
A.IsothermalI.ΔW\Delta WΔW (work done) =0=0=0
B.AdiabaticII.ΔQ\Delta QΔQ (supplied heat) =0=0=0
C.IsobaricIII.ΔU\Delta UΔU (change in internal energy) ≠0\ne 0=0
D.IsochoricIV.ΔU=0\Delta U=0ΔU=0
  1. (A)(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  2. (B)(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  3. (C)(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  4. (D)(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct answer: (C)

Step-by-step solution →
Q18·Physics·KinematicsSingle correct
A helicopter flying horizontally with a speed of 360 km/h at an altitude of 2 km, drops an object at an instant. The object hits the ground at a point O, 20 s after it is dropped. Displacement of 'O' from the position of helicopter where the object was released is: (use acceleration due to gravity g=10g=10g=10 m/s2^22 and neglect air resistance)
  1. (A)252\sqrt{5}25​ km
  2. (B)4 km
  3. (C)7.2 km
  4. (D)222\sqrt{2}22​ km

Correct answer: (D)

Step-by-step solution →
Q19·Physics·Laws of MotionSingle correct
An object with mass 500 g moves along x-axis with speed v=4xv=4\sqrt{x}v=4x​ m/s. The force acting on the object is:
  1. (A)8 N
  2. (B)5 N
  3. (C)6 N
  4. (D)4 N

Correct answer: (D)

Step-by-step solution →
Q20·Physics·Geometrical OpticsSingle correct
A transparent block A having refractive index μ=1.25\mu=1.25μ=1.25 is surrounded by another medium of refractive index μ=1.0\mu=1.0μ=1.0 as shown in the figure. A light ray is incident on the flat face of the block with incident angle θ\thetaθ as shown in the figure. What is the maximum value of θ\thetaθ for which light suffers total internal reflection at the top surface of the block?
  1. (A)tan⁡−1(4/3)\tan^{-1}(4/3)tan−1(4/3)
  2. (B)tan⁡−1(3/4)\tan^{-1}(3/4)tan−1(3/4)
  3. (C)sin⁡−1(3/4)\sin^{-1}(3/4)sin−1(3/4)
  4. (D)cos⁡−1(3/4)\cos^{-1}(3/4)cos−1(3/4)

Correct answer: (C)

Step-by-step solution →
Q21·Physics·Capacitors and DielectricsInteger
A parallel plate capacitor has charge 5×10−85\times10^{-8}5×10−8 C. A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is 4×10−84\times10^{-8}4×10−8 C then the dielectric constant of the slab is __________.

Correct answer: 5

Step-by-step solution →
Q22·Physics·Alternating CurrentsInteger
An inductor of reactance 100 Ω\OmegaΩ, a capacitor of reactance 50 Ω\OmegaΩ, and a resistor of resistance 50 Ω\OmegaΩ are connected in series with an AC source of 10 V, 50 Hz. Average power dissipated by the circuit is __________ W.

Correct answer: 1

Step-by-step solution →
Q23·Physics·Properties of Solids and LiquidsInteger
Two cylindrical rods A and B made of different materials, are joined in a straight line. The ratio of lengths, radii and thermal conductivities of these rods are: LALB=12\dfrac{L_A}{L_B}=\dfrac{1}{2}LB​LA​​=21​, rArB=2\dfrac{r_A}{r_B}=2rB​rA​​=2 and KAKB=12\dfrac{K_A}{K_B}=\dfrac{1}{2}KB​KA​​=21​. The free ends of rods A and B are maintained at 400 K, 200 K, respectively. The temperature of the rods' interface is __________ K, when equilibrium is established.

Correct answer: 360

Step-by-step solution →
Q24·Physics·Electric Field and Coulomb's LawInteger
The electric field in a region is given by E⃗=(2i^+4j^+6k^)×103\vec{E}=\left(2\hat{i}+4\hat{j}+6\hat{k}\right)\times10^{3}E=(2i^+4j^​+6k^)×103 N/C. The flux of the field through a rectangular surface parallel to the x-z plane is 6.06.06.0 Nm2^22C−1^{-1}−1. The area of the surface is __________ cm2^22.

Correct answer: 15

Step-by-step solution →
Q25·Physics·Rotational MotionInteger
Let M and R be the mass and radius of a disc. A small disc of radius R3\dfrac{R}{3}3R​ is removed from the bigger disc as shown in the figure. The moment of inertia of the remaining part of the bigger disc about an axis AB passing through the centre O and perpendicular to the plane of the disc is 4xMR2\dfrac{4}{x}MR^2x4​MR2. The value of x is __________.

Correct answer: 9

Step-by-step solution →

Chemistry — JEE Main 7 April 2025 Shift 2

Q26·Chemistry·BiomoleculesSingle correct
Given below are two statements: Statement (I): On hydrolysis, oligo peptides give rise to fewer number of α-amino acids while proteins give rise to a large number of β-amino acids. Statement (II): Natural proteins are denatured by acids which convert the water soluble form of fibrous proteins to their water insoluble form. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both statement I and statement II are correct
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Both statement I and statement II are incorrect
  4. (D)Statement I is correct but Statement II is incorrect

Correct answer: (C)

Step-by-step solution →
Q27·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
Mixture of 1 g each of chlorobenzene, aniline and benzoic acid is dissolved in 50 mL ethyl acetate and placed in a separating funnel. 5 M NaOH (30 mL) was added in the same funnel. The funnel was shaken vigorously and then kept aside. The ethyl acetate layer in the funnel contains:
  1. (A)benzoic acid
  2. (B)benzoic acid and aniline
  3. (C)benzoic acid and chlorobenzene
  4. (D)chlorobenzene and aniline

Correct answer: (D)

Step-by-step solution →
Q28·Chemistry·Chemical ThermodynamicsSingle correct
The hydration energies of K+K^+K+ and Cl−Cl^-Cl− are −x-x−x and −y-y−y kJ/mol respectively. If lattice energy of KCl is −z-z−z kJ/mol, then the heat of solution of KCl is:
  1. (A)+x−y−z+x-y-z+x−y−z
  2. (B)x+y+zx+y+zx+y+z
  3. (C)z−(x+y)z-(x+y)z−(x+y)
  4. (D)−z−(x+y)-z-(x+y)−z−(x+y)

Correct answer: (C)

Step-by-step solution →
Q29·Chemistry·Chemical KineticsSingle correct
A(g)→B(g)+C(g)A(g)\rightarrow B(g)+C(g)A(g)→B(g)+C(g) is a first order reaction. The reaction was started with reactant A only. The total pressure of the system is PtP_tPt​ at time ttt and P∞P_\inftyP∞​ at the end of the reaction (t=∞t=\inftyt=∞). Which of the following expression is correct for the rate constant kkk?
  1. (A)k=1tln⁡2(P∞−Pt)Ptk=\dfrac{1}{t}\ln\dfrac{2(P_\infty-P_t)}{P_t}k=t1​lnPt​2(P∞​−Pt​)​
  2. (B)k=1tln⁡P∞Ptk=\dfrac{1}{t}\ln\dfrac{P_\infty}{P_t}k=t1​lnPt​P∞​​
  3. (C)k=1tln⁡P∞2(P∞−Pt)k=\dfrac{1}{t}\ln\dfrac{P_\infty}{2(P_\infty-P_t)}k=t1​ln2(P∞​−Pt​)P∞​​
  4. (D)k=1tln⁡P∞(P∞−Pt)k=\dfrac{1}{t}\ln\dfrac{P_\infty}{(P_\infty-P_t)}k=t1​ln(P∞​−Pt​)P∞​​

Correct answer: (C)

Step-by-step solution →
Q30·Chemistry·Aldehydes and KetonesSingle correct
"P" is an optically active compound with molecular formula C6H12OC_6H_{12}OC6​H12​O. When "P" is treated with 2,4-dinitrophenylhydrazine, it gives a positive test. However, in presence of Tollens reagent, "P" gives a negative test. Predict the structure of "P".
  1. (A)CH3−CO−CH2−CH2−CH2−CH3CH_3{-}CO{-}CH_2{-}CH_2{-}CH_2{-}CH_3CH3​−CO−CH2​−CH2​−CH2​−CH3​
  2. (B)CH3−CO−CH(CH2CH3)−CH3CH_3{-}CO{-}CH(CH_2CH_3){-}CH_3CH3​−CO−CH(CH2​CH3​)−CH3​
  3. (C)H−CO−CH2−CH(CH2CH3)−CH3H{-}CO{-}CH_2{-}CH(CH_2CH_3){-}CH_3H−CO−CH2​−CH(CH2​CH3​)−CH3​
  4. (D)CH3−CO−CH2−CH(CH3)−CH3CH_3{-}CO{-}CH_2{-}CH(CH_3){-}CH_3CH3​−CO−CH2​−CH(CH3​)−CH3​

Correct answer: (B)

Step-by-step solution →
Q31·Chemistry·Classification of Elements and Periodicity in PropertiesSingle correct
Choose the incorrect trend in the atomic radii (r) of the elements:
  1. (A)rBr<rKr_{Br}<r_KrBr​<rK​
  2. (B)rMg<rAlr_{Mg}<r_{Al}rMg​<rAl​
  3. (C)rRb<rCsr_{Rb}<r_{Cs}rRb​<rCs​
  4. (D)rAt<rCsr_{At}<r_{Cs}rAt​<rCs​

Correct answer: (B)

Step-by-step solution →
Q32·Chemistry·Organic Compounds Containing HalogensSingle correct
Match the LIST-I (Conversion) with LIST-II (Reagents and conditions used). Choose the correct answer from the options given below:
LIST-I (Conversion)LIST-II (Reagents and conditions used)
A.see figureI.Warm, H2OH_2OH2​O
B.see figureII.(a) NaOH, 368 K; (b) H3O+H_3O^+H3​O+
C.see figureIII.(a) NaOH, 443 K; (b) H3O+H_3O^+H3​O+
D.see figureIV.(a) NaOH, 623 K, 300 atm; (b) H3O+H_3O^+H3​O+
  1. (A)(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
  2. (B)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  3. (C)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  4. (D)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Correct answer: (C)

Step-by-step solution →
Q33·Chemistry·Chemical ThermodynamicsSingle correct
The correct statement amongst the following is:
  1. (A)The term 'standard state' implies that the temperature is 0∘0^\circ0∘C
  2. (B)The standard state of pure gas is the pure gas at a pressure of 1 bar and temperature 273 K
  3. (C)ΔfH298⊖\Delta_f H^{\ominus}_{298}Δf​H298⊖​ is zero for O(g)
  4. (D)ΔfH500⊖\Delta_f H^{\ominus}_{500}Δf​H500⊖​ is zero for O2O_2O2​(g)

Correct answer: (D)

Step-by-step solution →
Q34·Chemistry·SolutionsSingle correct
Liquid A and B form an ideal solution. The vapour pressure of pure liquids A and B are 350 and 750 mm Hg respectively at the same temperature. If xAx_AxA​ and xBx_BxB​ are the mole fraction of A and B in solution while yAy_AyA​ and yBy_ByB​ are the mole fraction of A and B in vapour phase then:
  1. (A)xAxB<yAyB\dfrac{x_A}{x_B}<\dfrac{y_A}{y_B}xB​xA​​<yB​yA​​
  2. (B)xAxB=yAyB\dfrac{x_A}{x_B}=\dfrac{y_A}{y_B}xB​xA​​=yB​yA​​
  3. (C)xAxB>yAyB\dfrac{x_A}{x_B}>\dfrac{y_A}{y_B}xB​xA​​>yB​yA​​
  4. (D)(xA−yA)<(xB−yB)(x_A-y_A)<(x_B-y_B)(xA​−yA​)<(xB​−yB​)

Correct answer: (C)

Step-by-step solution →
Q35·Chemistry·Coordination CompoundsSingle correct
'X' is the number of acidic oxides among VO2VO_2VO2​, V2O3V_2O_3V2​O3​, CrO3CrO_3CrO3​, V2O5V_2O_5V2​O5​ and Mn2O7Mn_2O_7Mn2​O7​. The primary valency of cobalt in [Co(H2NCH2CH2NH2)3]2(SO4)3[Co(H_2NCH_2CH_2NH_2)_3]_2(SO_4)_3[Co(H2​NCH2​CH2​NH2​)3​]2​(SO4​)3​ is Y. The value of X + Y is:
  1. (A)5
  2. (B)4
  3. (C)2
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q36·Chemistry·AminesSingle correct
The descending order of basicity of the following amines is:
  1. (A)B > E > D > A > C
  2. (B)E > D > B > A > C
  3. (C)E > D > A > B > C
  4. (D)E > A > D > C > B

Correct answer: (B)

Step-by-step solution →
Q37·Chemistry·Coordination CompoundsSingle correct
Match the LIST-I (Complex) with LIST-II (Primary and secondary valency). Choose the correct answer from the options given below:
LIST-I (Complex)LIST-II (Primary and secondary valency)
A.[Co(en)2Cl2]Cl[Co(en)_2Cl_2]Cl[Co(en)2​Cl2​]ClI.3, 6
B.[Pt(NH3)2Cl(NO2)][Pt(NH_3)_2Cl(NO_2)][Pt(NH3​)2​Cl(NO2​)]II.3, 4
C.Hg[Co(SCN)4]Hg[Co(SCN)_4]Hg[Co(SCN)4​]III.2, 6
D.[Mg(EDTA)]2−[Mg(EDTA)]^{2-}[Mg(EDTA)]2−IV.2, 4
  1. (A)(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  2. (B)(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
  3. (C)(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  4. (D)(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Correct answer: (B)

Step-by-step solution →
Q38·Chemistry·SolutionsSingle correct
Match the LIST-I (Binary solution) with LIST-II (Property). Choose the correct answer from the options given below:
LIST-I (Binary solution)LIST-II (Property)
A.Solution of chloroform and acetoneI.Minimum boiling azeotrope
B.Solution of ethanol and waterII.Dimerizes
C.Solution of benzene and tolueneIII.Maximum boiling azeotrope
D.Solution of acetic acid in benzeneIV.ΔVmix=0\Delta V_{mix}=0ΔVmix​=0
  1. (A)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. (B)(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  3. (C)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. (D)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Correct answer: (A)

Step-by-step solution →
Q39·Chemistry·Chemical Bonding and Molecular StructureSingle correct
In SO2SO_2SO2​, NO2−NO_2^-NO2−​ and N3−N_3^-N3−​ the hybridizations at the central atom are respectively:
  1. (A)sp2sp^2sp2, sp2sp^2sp2 and spspsp
  2. (B)sp2sp^2sp2, spspsp and spspsp
  3. (C)sp2sp^2sp2, sp2sp^2sp2 and sp2sp^2sp2
  4. (D)spspsp, sp2sp^2sp2 and spspsp

Correct answer: (A)

Step-by-step solution →
Q40·Chemistry·Coordination CompoundsSingle correct
The number of unpaired electrons responsible for the paramagnetic nature of the following complex species are respectively: [Fe(CN)6]3−[Fe(CN)_6]^{3-}[Fe(CN)6​]3−, [FeF6]3−[FeF_6]^{3-}[FeF6​]3−, [CoF6]3−[CoF_6]^{3-}[CoF6​]3−, [Mn(CN)6]3−[Mn(CN)_6]^{3-}[Mn(CN)6​]3−
  1. (A)1, 5, 4, 2
  2. (B)1, 5, 5, 2
  3. (C)1, 1, 4, 2
  4. (D)1, 4, 4, 2

Correct answer: (A)

Step-by-step solution →
Q41·Chemistry·HydrocarbonsSingle correct
The number of optically active products obtained from the complete ozonolysis of the given compound is:
  1. (A)2
  2. (B)0
  3. (C)1
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q42·Chemistry·Electronic Effects and StabilitySingle correct
Given below are two statements: Statement (I): cis-1,2-dichloroethene is more polar than cis-1,2-dibromoethene. Statement (II): Boiling point of trans-1,2-dibromoethene is lower than cis-1,2-dibromoethene but it is more polar than cis-1,2-dibromoethene. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but statement II is incorrect
  2. (B)Statement I is incorrect but statement II is correct
  3. (C)Both statement I and statement II are incorrect
  4. (D)Both statement I and statement II are correct

Correct answer: (A)

Step-by-step solution →
Q43·Chemistry·Atomic StructureSingle correct
The extra stability of half-filled subshell is due to: (A) Symmetrical distribution of electrons (B) Smaller coulombic repulsion energy (C) The presence of electrons with the same spin in non-degenerate orbitals (D) Larger exchange energy (E) Relatively smaller shielding of electrons by one another Identify the correct statements:
  1. (A)(B), (D) and (E) only
  2. (B)(A), (B), (D) and (E) only
  3. (C)(B), (C) and (D) only
  4. (D)(A), (B) and (D) only

Correct answer: (B)

Step-by-step solution →
Q44·Chemistry·p-Block ElementsSingle correct
The correct statements from the following are: (A) Tl3+Tl^{3+}Tl3+ is a powerful oxidising agent (B) Al3+Al^{3+}Al3+ does not get reduced easily (C) Both Al3+Al^{3+}Al3+ and Tl3+Tl^{3+}Tl3+ are very stable in solution (D) Tl+Tl^+Tl+ is more stable than Tl3+Tl^{3+}Tl3+ (E) Al3+Al^{3+}Al3+ and Tl+Tl^+Tl+ are highly stable Choose the correct answer from the options given below:
  1. (A)(A), (B), (C), (D) and (E)
  2. (B)(A), (B), (D) and (E) only
  3. (C)(B), (D) and (E) only
  4. (D)(A), (C) and (D) only

Correct answer: (B)

Step-by-step solution →
Q45·Chemistry·Redox Reactions and ElectrochemistrySingle correct
1 M aqueous solution of each of Cu(NO3)2Cu(NO_3)_2Cu(NO3​)2​, AgNO3AgNO_3AgNO3​, Hg2(NO3)2Hg_2(NO_3)_2Hg2​(NO3​)2​ and Mg(NO3)2Mg(NO_3)_2Mg(NO3​)2​ are electrolysed using inert electrodes. Given: EAg+/Ag⊖=0.80E^{\ominus}_{Ag^+/Ag}=0.80EAg+/Ag⊖​=0.80 V, EHg22+/Hg⊖=0.79E^{\ominus}_{Hg_2^{2+}/Hg}=0.79EHg22+​/Hg⊖​=0.79 V, ECu2+/Cu⊖=0.24E^{\ominus}_{Cu^{2+}/Cu}=0.24ECu2+/Cu⊖​=0.24 V and EMg2+/Mg⊖=−2.37E^{\ominus}_{Mg^{2+}/Mg}=-2.37EMg2+/Mg⊖​=−2.37 V. Statement (I): With increasing voltage, the sequence of deposition of metals on the cathode will be Ag, Hg and Cu. Statement (II): Magnesium will not be deposited at cathode instead oxygen gas will be evolved at the cathode. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both statement I and statement II are incorrect
  2. (B)Statement I is correct but statement II is incorrect
  3. (C)Both statement I and statement II are correct
  4. (D)Statement I is incorrect but statement II is correct

Correct answer: (B)

Step-by-step solution →
Q46·Chemistry·EquilibriumInteger
One litre buffer solution was prepared by adding 0.10 mol each of NH3NH_3NH3​ and NH4ClNH_4ClNH4​Cl in deionised water. The change in pH on addition of 0.05 mol of HCl to the above solution is __________ ×10−2\times 10^{-2}×10−2. (Nearest integer) (Given: pKbpK_bpKb​ of NH3=4.745NH_3=4.745NH3​=4.745 and log⁡103=0.477\log_{10}3=0.477log10​3=0.477)

Correct answer: 48

Step-by-step solution →
Q47·Chemistry·Purification and Characterisation of Organic CompoundsInteger
In Dumas' method, 292 mg of an organic compound released 50 mL of nitrogen gas (N2N_2N2​) at 300 K temperature and 715 mm Hg pressure. The percentage composition of 'N' in the organic compound is __________ %. (Nearest integer) (Aqueous tension at 300 K = 15 mm Hg)

Correct answer: 18

Step-by-step solution →
Q48·Chemistry·Some Basic Concepts in ChemistryInteger
Butane reacts with oxygen to produce carbon dioxide and water following the equation given below: C4H10(g)+132O2(g)→4CO2(g)+5H2O(l)C_4H_{10}(g)+\dfrac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)C4​H10​(g)+213​O2​(g)→4CO2​(g)+5H2​O(l) If 174.0 kg of butane is mixed with 320.0 kg of O2O_2O2​, the volume of water formed in litres is __________. (Nearest integer) [Given: (a) Molar mass of C, H, O are 12, 1, 16 g mol−1^{-1}−1 respectively, (b) Density of water = 1 g mL−1^{-1}−1]

Correct answer: 138

Step-by-step solution →
Q49·Chemistry·Coordination CompoundsInteger
The number of paramagnetic metal complex species among [Co(NH3)6]3+[Co(NH_3)_6]^{3+}[Co(NH3​)6​]3+, [Co(C2O4)3]3−[Co(C_2O_4)_3]^{3-}[Co(C2​O4​)3​]3−, [MnCl6]3−[MnCl_6]^{3-}[MnCl6​]3−, [Mn(CN)6]3−[Mn(CN)_6]^{3-}[Mn(CN)6​]3−, [CoF6]3−[CoF_6]^{3-}[CoF6​]3−, [Fe(CN)6]3−[Fe(CN)_6]^{3-}[Fe(CN)6​]3− and [FeF6]3−[FeF_6]^{3-}[FeF6​]3− with same number of unpaired electrons is __________.

Correct answer: 2

Step-by-step solution →
Q50·Chemistry·Reaction MechanismInteger
Identify the structure of the final product (D) in the following sequence of reactions: Ph−CO−CH3→PCl5, ΔA→3 eq. NaNH2/NH3B→AcidifyC→1. B2H6; 2. H2O2/OH−DPh{-}CO{-}CH_3 \xrightarrow{PCl_5,\ \Delta} A \xrightarrow{3\ eq.\ NaNH_2/NH_3} B \xrightarrow{Acidify} C \xrightarrow{1.\ B_2H_6;\ 2.\ H_2O_2/OH^-} DPh−CO−CH3​PCl5​, Δ​A3 eq. NaNH2​/NH3​​BAcidify​C1. B2​H6​; 2. H2​O2​/OH−​D Total number of sp2sp^2sp2 hybridised carbon atoms in product D is __________.

Correct answer: 7

Step-by-step solution →

Mathematics — JEE Main 7 April 2025 Shift 2

Q51·Mathematics·CirclesSingle correct
If the orthocentre of the triangle formed by the lines y=x+1y=x+1y=x+1, y=4x−8y=4x-8y=4x−8 and y=mx+cy=mx+cy=mx+c is at (3,−1)(3,-1)(3,−1), then m−cm-cm−c is:
  1. (A)0
  2. (B)−2-2−2
  3. (C)4
  4. (D)2

Correct answer: (A)

Step-by-step solution →
Q52·Mathematics·Vector AlgebraSingle correct
Let a⃗\vec{a}a and b⃗\vec{b}b be the vectors of the same magnitude such that ∣a⃗+b⃗∣+∣a⃗−b⃗∣∣a⃗+b⃗∣−∣a⃗−b⃗∣=2+1\dfrac{|\vec{a}+\vec{b}|+|\vec{a}-\vec{b}|}{|\vec{a}+\vec{b}|-|\vec{a}-\vec{b}|}=\sqrt{2}+1∣a+b∣−∣a−b∣∣a+b∣+∣a−b∣​=2​+1. Then ∣a⃗+b⃗∣2∣a⃗∣2\dfrac{|\vec{a}+\vec{b}|^2}{|\vec{a}|^2}∣a∣2∣a+b∣2​ is:
  1. (A)2+422+4\sqrt{2}2+42​
  2. (B)1+21+\sqrt{2}1+2​
  3. (C)2+22+\sqrt{2}2+2​
  4. (D)4+224+2\sqrt{2}4+22​

Correct answer: (C)

Step-by-step solution →
Q53·Mathematics·Sets, Relations and FunctionsSingle correct
Let A={(α,β)∈R×R:∣α−1∣≤4 and ∣β−5∣≤6}A=\{(\alpha,\beta)\in\mathbb{R}\times\mathbb{R}:|\alpha-1|\le 4 \text{ and } |\beta-5|\le 6\}A={(α,β)∈R×R:∣α−1∣≤4 and ∣β−5∣≤6} and B={(α,β)∈R×R:16(α−2)2+9(β−6)2≤144}B=\{(\alpha,\beta)\in\mathbb{R}\times\mathbb{R}:16(\alpha-2)^2+9(\beta-6)^2\le 144\}B={(α,β)∈R×R:16(α−2)2+9(β−6)2≤144}. Then
  1. (A)B⊂AB\subset AB⊂A
  2. (B)A∪B={(x,y):−4≤x≤4, −1≤y≤11}A\cup B=\{(x,y):-4\le x\le 4,\ -1\le y\le 11\}A∪B={(x,y):−4≤x≤4, −1≤y≤11}
  3. (C)neither A⊂BA\subset BA⊂B nor B⊂AB\subset AB⊂A
  4. (D)A⊂BA\subset BA⊂B

Correct answer: (A)

Step-by-step solution →
Q54·Mathematics·Sets, Relations and FunctionsSingle correct
If the range of the function f(x)=5−xx2−3x+2f(x)=\dfrac{5-x}{x^2-3x+2}f(x)=x2−3x+25−x​, x≠1,2x\ne 1,2x=1,2, is (−∞,α]∪[β,∞)(-\infty,\alpha]\cup[\beta,\infty)(−∞,α]∪[β,∞), then α2+β2\alpha^2+\beta^2α2+β2 is equal to:
  1. (A)190
  2. (B)192
  3. (C)188
  4. (D)194

Correct answer: (D)

Step-by-step solution →
Q55·Mathematics·Statistics and ProbabilitySingle correct
A bag contains 19 unbiased coins and one coin with head on both sides. One coin drawn at random is tossed and head turns up. If the probability that the drawn coin was unbiased, is mn\dfrac{m}{n}nm​, gcd⁡(m,n)=1\gcd(m,n)=1gcd(m,n)=1, then n2−m2n^2-m^2n2−m2 is equal to:
  1. (A)80
  2. (B)60
  3. (C)72
  4. (D)64

Correct answer: (A)

Step-by-step solution →
Q56·Mathematics·Statistics and ProbabilitySingle correct
Let a random variable XXX take values 0,1,2,30,1,2,30,1,2,3 with P(X=0)=P(X=1)=pP(X=0)=P(X=1)=pP(X=0)=P(X=1)=p, P(X=2)=P(X=3)P(X=2)=P(X=3)P(X=2)=P(X=3) and E(X2)=2E(X)E(X^2)=2E(X)E(X2)=2E(X). Then the value of 8p−18p-18p−1 is:
  1. (A)0
  2. (B)2
  3. (C)1
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q57·Mathematics·Area Under CurvesSingle correct
If the area of the region {(x,y):1+x2≤y≤min⁡{x+7, 11−3x}}\{(x,y):1+x^2\le y\le \min\{x+7,\ 11-3x\}\}{(x,y):1+x2≤y≤min{x+7, 11−3x}} is AAA, then 3A3A3A is equal to:
  1. (A)50
  2. (B)49
  3. (C)46
  4. (D)47

Correct answer: (A)

Step-by-step solution →
Q58·Mathematics·Limits and ContinuitySingle correct
Let f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R be a polynomial function of degree four having extreme values at x=4x=4x=4 and x=5x=5x=5. If lim⁡x→0f(x)x2=5\lim\limits_{x\to 0}\dfrac{f(x)}{x^2}=5x→0lim​x2f(x)​=5, then f(2)f(2)f(2) is equal to:
  1. (A)12
  2. (B)10
  3. (C)8
  4. (D)14

Correct answer: (B)

Step-by-step solution →
Q59·Mathematics·Trigonometric FunctionsSingle correct
The number of solutions of the equation cos⁡2θ cos⁡θ2+cos⁡5θ2=2cos⁡35θ2\cos 2\theta\,\cos\dfrac{\theta}{2}+\cos\dfrac{5\theta}{2}=2\cos^3\dfrac{5\theta}{2}cos2θcos2θ​+cos25θ​=2cos325θ​ in [−π2,π2]\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right][−2π​,2π​] is:
  1. (A)7
  2. (B)5
  3. (C)6
  4. (D)9

Correct answer: (A)

Step-by-step solution →
Q60·Mathematics·Sequence and SeriesSingle correct
Let ana_nan​ be the nthn^{th}nth term of an A.P. If Sn=a1+a2+a3+⋯+an=700S_n=a_1+a_2+a_3+\dots+a_n=700Sn​=a1​+a2​+a3​+⋯+an​=700, a6=7a_6=7a6​=7 and S7=7S_7=7S7​=7, then ana_nan​ is equal to:
  1. (A)56
  2. (B)65
  3. (C)64
  4. (D)70

Correct answer: (C)

Step-by-step solution →
Q61·Mathematics·Complex NumbersSingle correct
Let the locus of z∈Cz\in\mathbb{C}z∈C, such that Re(z−12z+i)+Re(zˉ−12zˉ−i)=2\mathrm{Re}\left(\dfrac{z-1}{2z+i}\right)+\mathrm{Re}\left(\dfrac{\bar{z}-1}{2\bar{z}-i}\right)=2Re(2z+iz−1​)+Re(2zˉ−izˉ−1​)=2, is a circle of radius rrr and center (a,b)(a,b)(a,b), then 15abr2\dfrac{15ab}{r^2}r215ab​ is equal to:
  1. (A)24
  2. (B)12
  3. (C)18
  4. (D)16

Correct answer: (C)

Step-by-step solution →
Q62·Mathematics·EllipseSingle correct
Let the length of a latus rectum of an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1a2x2​+b2y2​=1 be 10. If its eccentricity is the minimum value of the function f(t)=t2+t+1112f(t)=t^2+t+\dfrac{11}{12}f(t)=t2+t+1211​, t∈Rt\in\mathbb{R}t∈R, then a2+b2a^2+b^2a2+b2 is equal to:
  1. (A)125
  2. (B)126
  3. (C)120
  4. (D)115

Correct answer: (B)

Step-by-step solution →
Q63·Mathematics·Differential EquationsSingle correct
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x2+1)y′−2xy=(x4+2x2+1)cos⁡x(x^2+1)y'-2xy=(x^4+2x^2+1)\cos x(x2+1)y′−2xy=(x4+2x2+1)cosx, y(0)=1y(0)=1y(0)=1. Then ∫−33y(x) dx\displaystyle\int_{-3}^{3} y(x)\,dx∫−33​y(x)dx is:
  1. (A)24
  2. (B)36
  3. (C)30
  4. (D)18

Correct answer: (A)

Step-by-step solution →
Q64·Mathematics·Three Dimensional GeometrySingle correct
If the equation of the line passing through the point (0,−12,0)\left(0,-\dfrac{1}{2},0\right)(0,−21​,0) and perpendicular to the lines r⃗=λ(i^+aj^+bk^)\vec{r}=\lambda(\hat{i}+a\hat{j}+b\hat{k})r=λ(i^+aj^​+bk^) and r⃗=(i^−j^−6k^)+μ(−bi^+aj^+5k^)\vec{r}=(\hat{i}-\hat{j}-6\hat{k})+\mu(-b\hat{i}+a\hat{j}+5\hat{k})r=(i^−j^​−6k^)+μ(−bi^+aj^​+5k^) is x−1−2=y+4d=z−c−4\dfrac{x-1}{-2}=\dfrac{y+4}{d}=\dfrac{z-c}{-4}−2x−1​=dy+4​=−4z−c​, then a+b+c+da+b+c+da+b+c+d is equal to:
  1. (A)10
  2. (B)14
  3. (C)13
  4. (D)12

Correct answer: (B)

Step-by-step solution →
Q65·Mathematics·Permutations and CombinationsSingle correct
Let ppp be the number of all triangles that can be formed by joining the vertices of a regular polygon PPP of nnn sides and qqq be the number of all quadrilaterals that can be formed by joining the vertices of PPP. If p+q=126p+q=126p+q=126, then the eccentricity of the ellipse x216+y2n=1\dfrac{x^2}{16}+\dfrac{y^2}{n}=116x2​+ny2​=1 is:
  1. (A)34\dfrac{3}{4}43​
  2. (B)12\dfrac{1}{2}21​
  3. (C)74\dfrac{\sqrt{7}}{4}47​​
  4. (D)12\dfrac{1}{\sqrt{2}}2​1​

Correct answer: (D)

Step-by-step solution →
Q66·Mathematics·Three Dimensional GeometrySingle correct
Consider the lines L1:x−1=y−2=zL_1:x-1=y-2=zL1​:x−1=y−2=z and L2:x−2=y=z−1L_2:x-2=y=z-1L2​:x−2=y=z−1. Let the feet of the perpendiculars from the point P(5,1,−3)P(5,1,-3)P(5,1,−3) on the lines L1L_1L1​ and L2L_2L2​ be QQQ and RRR respectively. If the area of the triangle PQRPQRPQR is AAA, then 4A24A^24A2 is equal to:
  1. (A)139
  2. (B)147
  3. (C)151
  4. (D)143

Correct answer: (B)

Step-by-step solution →
Q67·Mathematics·Quadratic EquationsSingle correct
The number of real roots of the equation x∣x−2∣+3∣x−3∣+1=0x|x-2|+3|x-3|+1=0x∣x−2∣+3∣x−3∣+1=0 is:
  1. (A)4
  2. (B)2
  3. (C)1
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q68·Mathematics·EllipseSingle correct
Let e1e_1e1​ and e2e_2e2​ be the eccentricities of the ellipse x2b2+y225=1\dfrac{x^2}{b^2}+\dfrac{y^2}{25}=1b2x2​+25y2​=1 and the hyperbola x216−y2b2=1\dfrac{x^2}{16}-\dfrac{y^2}{b^2}=116x2​−b2y2​=1, respectively. If b<5b<5b<5 and e1e2=1e_1e_2=1e1​e2​=1, then the eccentricity of the ellipse having its axes along the coordinate axes and passing through all four foci (two of the ellipse and two of the hyperbola) is:
  1. (A)45\dfrac{4}{5}54​
  2. (B)35\dfrac{3}{5}53​
  3. (C)74\dfrac{\sqrt{7}}{4}47​​
  4. (D)32\dfrac{\sqrt{3}}{2}23​​

Correct answer: (B)

Step-by-step solution →
Q69·Mathematics·Matrices and DeterminantsSingle correct
Let the system of equations x+5y−z=1x+5y-z=1x+5y−z=1, 4x+3y−3z=74x+3y-3z=74x+3y−3z=7, 24x+y+λz=μ24x+y+\lambda z=\mu24x+y+λz=μ; λ,μ∈R\lambda,\mu\in\mathbb{R}λ,μ∈R, have infinitely many solutions. Then the number of the solutions of this system, if x,y,zx,y,zx,y,z are integers and satisfy 7≤x+y+z≤777\le x+y+z\le 777≤x+y+z≤77, is
  1. (A)3
  2. (B)6
  3. (C)5
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q70·Mathematics·Sequence and SeriesSingle correct
If the sum of the second, fourth and sixth terms of a G.P. of positive terms is 21 and the sum of its eighth, tenth and twelfth terms is 15309, then the sum of its first nine terms is:
  1. (A)760
  2. (B)755
  3. (C)750
  4. (D)757

Correct answer: (D)

Step-by-step solution →
Q71·Mathematics·Limits and ContinuityInteger
If the function f(x)=tan⁡(tan⁡x)−sin⁡(sin⁡x)tan⁡x−sin⁡xf(x)=\dfrac{\tan(\tan x)-\sin(\sin x)}{\tan x-\sin x}f(x)=tanx−sinxtan(tanx)−sin(sinx)​ is continuous at x=0x=0x=0, then f(0)f(0)f(0) is equal to __________.

Correct answer: 2

Step-by-step solution →
Q72·Mathematics·Indefinite IntegrationInteger
If ∫(1x+1x3)(3x−24+x−26)1/23dx=−α3(α+1)(3xβ+xγ)α+1α+C\displaystyle\int\left(\dfrac{1}{x}+\dfrac{1}{x^3}\right)\left(3x^{-24}+x^{-26}\right)^{1/23}dx=-\dfrac{\alpha}{3(\alpha+1)}\left(3x^{\beta}+x^{\gamma}\right)^{\frac{\alpha+1}{\alpha}}+C∫(x1​+x31​)(3x−24+x−26)1/23dx=−3(α+1)α​(3xβ+xγ)αα+1​+C, x>0x>0x>0, (α,β,γ∈Z)(\alpha,\beta,\gamma\in\mathbb{Z})(α,β,γ∈Z), where CCC is the constant of integration, then α+β+γ\alpha+\beta+\gammaα+β+γ is equal to __________.

Correct answer: 19

Step-by-step solution →
Q73·Mathematics·Limits and ContinuityInteger
For t>−1t>-1t>−1, let αt\alpha_tαt​ and βt\beta_tβt​ be the roots of the equation ((t+2)1/7−1)x2+((t+2)1/6−1)x+((t+2)1/21−1)=0\left((t+2)^{1/7}-1\right)x^2+\left((t+2)^{1/6}-1\right)x+\left((t+2)^{1/21}-1\right)=0((t+2)1/7−1)x2+((t+2)1/6−1)x+((t+2)1/21−1)=0. If lim⁡t→−1+αt=a\lim\limits_{t\to -1^+}\alpha_t=at→−1+lim​αt​=a and lim⁡t→−1+βt=b\lim\limits_{t\to -1^+}\beta_t=bt→−1+lim​βt​=b, then 72(a+b)272(a+b)^272(a+b)2 is equal to __________.

Correct answer: 98

Step-by-step solution →
Q74·Mathematics·HyperbolaInteger
Let the lengths of the transverse and conjugate axes of a hyperbola in standard form be 2a2a2a and 2b2b2b, respectively, and one focus and the corresponding directrix of this hyperbola be (−5,0)(-5,0)(−5,0) and 5x+9=05x+9=05x+9=0, respectively. If the product of the focal distances of a point (α,25)\left(\alpha,2\sqrt{5}\right)(α,25​) on the hyperbola is ppp, then 4p4p4p is equal to __________.

Correct answer: 189

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Q75·Mathematics·Binomial Theorem and Its Simple ApplicationsInteger
The sum of the series 2×1×20C4−3×2×20C5+4×3×20C6−5×4×20C7+⋯+18×17×20C202\times 1\times{}^{20}C_4-3\times 2\times{}^{20}C_5+4\times 3\times{}^{20}C_6-5\times 4\times{}^{20}C_7+\dots+18\times 17\times{}^{20}C_{20}2×1×20C4​−3×2×20C5​+4×3×20C6​−5×4×20C7​+⋯+18×17×20C20​, is equal to __________.

Correct answer: 34

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Chapters tested in this paper

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  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Ellipse 103/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Indefinite Integration 66/186
  • Magnetism and Matter 50/186
  • Reaction Mechanism 29/186
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