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JEE Main 23 January 2026 Shift 1 Question Paper with Answers

23 January 2026 · January session · 73 questions

73 of the 75 questions from the JEE Main 23 January 2026 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

2 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
24
Chemistry
24
Mathematics
25

Physics — JEE Main 23 January 2026 Shift 1

Q1·PhysicsSingle correct
A thin prism with angle 5° of refractive index 1.72 is combined with another prism of refractive index 1.9 to produce dispersion without deviation. The angle of second prism is _______.
  1. (A)4.5°
  2. (B)6°
  3. (C)4°
  4. (D)5°

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
A small both A of mass m is attached to a massless rigid rod of length 1m pivoted at point P and kept at an angle of 60° with vertical as shown in figure. At distance of 1m below point P, an identical bob B is kept at rest on a smooth horizontal surface that extends to a circular track of radius R as shown in figure. If bob B just manages to complete the circular path of radius R upto a point Q after being hit elastically by bob A, then radius R is _______m.
  1. (A)35\frac{3}{5}53​
  2. (B)15\frac{1}{5}51​
  3. (C)2+35\frac{2+\sqrt{3}}{5}52+3​​
  4. (D)2−35\frac{2-\sqrt{3}}{5}52−3​​

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
Match List-I (Relation) with List-II (Law). Choose the correct answer from the options given below :
List-I (Relation)List-II (Law)
A.∮E⃗⋅dl⃗=−ddt∮B⃗⋅da⃗\oint \vec{E} \cdot \vec{dl} = -\frac{d}{dt}\oint \vec{B} \cdot \vec{da}∮E⋅dl=−dtd​∮B⋅daI.Ampere's circuital law.
B.∮B⃗⋅dl⃗=μ0(1+∈0dϕEdt)\oint \vec{B} \cdot \vec{dl} = \mu_0\left(1 + \in_0 \frac{d\phi_E}{dt}\right)∮B⋅dl=μ0​(1+∈0​dtdϕE​​)II.Faraday's laws of electromagnetic induction.
C.∮E⃗⋅da⃗=1∈0∫ρdv\oint \vec{E} \cdot \vec{da} = \frac{1}{\in_0}\int \rho dv∮E⋅da=∈0​1​∫ρdvIII.Ampere-Maxwell law
D.∮B⃗⋅dl⃗=μ0I\oint \vec{B} \cdot \vec{dl} = \mu_0 I∮B⋅dl=μ0​IIV.Gauss's law of electrostatics
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-II, B-III, C-IV, D-I
  3. (C)A-I, B-IV, C-III, D-II
  4. (D)A-IV, B-I, C-II, D-III

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
Four persons measure the length of a rod as 20.00 cm, 19.75 cm, 17.01 cm and 18.25 cm. The relative error in the measurement of average length of the rod is :
  1. (A)0.24
  2. (B)0.18
  3. (C)0.06
  4. (D)0.08

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correct
The de Broglie wavelength of an oxygen molecule at 27°C is x×10−12x \times 10^{-12}x×10−12 m. The value of x is (take Planck's constant =6.63×10−34= 6.63 \times 10^{-34}=6.63×10−34 J.s, Boltzmann constant =1.38×10−23= 1.38 \times 10^{-23}=1.38×10−23 J/K, mass of oxygen. Molecule =5.31×10−26= 5.31 \times 10^{-26}=5.31×10−26 kg).
  1. (A)26
  2. (B)24
  3. (C)30
  4. (D)20

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
A simple pendulum of string length 30 cm performs 20 oscillations in 10s. The length of the string required for the pendulum to perform 40 oscillations in the same time duration is ______cm. [Assume that the mass of the pendulum remains same.]
  1. (A)120
  2. (B)0.75
  3. (C)7.5
  4. (D)15

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correct
Two blocks with masses 100g and 200g are attached to the ends of springs A and B as shown in figure. The energy stored in A is E. The energy stored in B, when spring constants kAk_AkA​, kBk_BkB​ of A and B, respectively satisfy the relation 4kA=3kB4k_A = 3k_B4kA​=3kB​, is :
  1. (A)4E
  2. (B)2E
  3. (C)3E
  4. (D)43E\frac{4}{3}E34​E

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
The moment of inertia of a square loop made of four uniform solid cylinders, each having radius R and length L (R < L) about an axis passing through the mid points of opposite sides, is (Take the mass of the entire loop as M) :
  1. (A)38MR2+712ML2\frac{3}{8}MR^2 + \frac{7}{12}ML^283​MR2+127​ML2
  2. (B)34MR2+16ML2\frac{3}{4}MR^2 + \frac{1}{6}ML^243​MR2+61​ML2
  3. (C)34MR2+712ML2\frac{3}{4}MR^2 + \frac{7}{12}ML^243​MR2+127​ML2
  4. (D)38MR2+16ML2\frac{3}{8}MR^2 + \frac{1}{6}ML^283​MR2+61​ML2

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
A wire of uniform resistance λΩ/m is bent into a circle of radius r and another piece of wire with length 2r is connected between points A and B (AOB) as shown in figure. The equivalent resistance between points A and B is ______Ω.
  1. (A)3πλr8\frac{3\pi\lambda r}{8}83πλr​
  2. (B)(π+1) 2rλ(\pi + 1)\,2r\lambda(π+1)2rλ
  3. (C)6πλr3π+16\frac{6\pi\lambda r}{3\pi + 16}3π+166πλr​
  4. (D)2πλr2\pi\lambda r2πλr

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
The strain-stress plot for materials A,B,C and D is shown in the figure. Which material has the largest Young's modulus ?
  1. (A)C
  2. (B)D
  3. (C)A
  4. (D)B

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
Consider light travelling from a medium A to medium B separated by a plane interface. If the light undergoes total internal reflection during its travel from medium A to B and the speed of light in media A and B are 2.4×1082.4 \times 10^82.4×108 m/s and 2.7×1082.7 \times 10^82.7×108 m/s respectively, then the value of critical angle is :
  1. (A)cot⁡−1(313)\cot^{-1}\left(\frac{3}{\sqrt{13}}\right)cot−1(13​3​)
  2. (B)sin⁡−1(98)\sin^{-1}\left(\frac{9}{8}\right)sin−1(89​)
  3. (C)tan⁡−1(817)\tan^{-1}\left(\frac{8}{\sqrt{17}}\right)tan−1(17​8​)
  4. (D)cos⁡−1(89)\cos^{-1}\left(\frac{8}{9}\right)cos−1(98​)

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correct
In hydrogen atom spectrum, (R → Rydberg's constant) A. the maximum wavelength of the radiation of Lyman series is 43R\frac{4}{3R}3R4​ B. the Balmer series lies in the visible region of the spectrum C. the minimum wavelength of the radiation of Paschen series is 9R\frac{9}{R}R9​ D. the minimum wavelength of Lyman series is 54R\frac{5}{4R}4R5​ Choose the correct answer from the options given below :
  1. (A)B, D Only
  2. (B)A, B and C Only
  3. (C)A, B and D Only
  4. (D)A, B Only

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
An object is projected with kinetic energy K from a point A at an angle 60° with the horizontal. The ratio of the difference in kinetic energies points B and C to that at point A (see figure), in the absence of air friction is :
  1. (A)1:21 : 21:2
  2. (B)2:32 : 32:3
  3. (C)1:41 : 41:4
  4. (D)3:43 : 43:4

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
Two point charges 2q and q are placed at vertex A and centre of face CDEF of the cube as shown in figure. The electric flux passing through the cube is :
  1. (A)3qε0\frac{3q}{\varepsilon_0}ε0​3q​
  2. (B)qε0\frac{q}{\varepsilon_0}ε0​q​
  3. (C)3q2ε0\frac{3q}{2\varepsilon_0}2ε0​3q​
  4. (D)3q4ε0\frac{3q}{4\varepsilon_0}4ε0​3q​

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
A 20 m long uniform copper wire held horizontally is allowed to fall under the gravity (g = 10 m/s2^22) through a uniform horizontal magnetic field of 0.5 Gauss perpendicular to the length of the wire. The induced EMF across the wire it travells a vertical distance of 200 m is ______ mV.
  1. (A)0.2100.2\sqrt{10}0.210​
  2. (B)201020\sqrt{10}2010​
  3. (C)2102\sqrt{10}210​
  4. (D)20010200\sqrt{10}20010​

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
Two small balls with masses m and 2m are attached to both ends of a rigid rod of length d and negligible mass. If angular momentum of this system is L about an axis (A) passing through its centre of mass and perpendicular to the rod then angular velocity of the system about A is :
  1. (A)32Lmd2\frac{3}{2}\frac{L}{md^2}23​md2L​
  2. (B)2Lmd2\frac{2L}{md^2}md22L​
  3. (C)43Lmd2\frac{4}{3}\frac{L}{md^2}34​md2L​
  4. (D)2L5md2\frac{2L}{5md^2}5md22L​

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
In a perfectly inelastic collision, two spheres made of the same material with masses 15 kg and 25 kg, moving in opposite directions with speeds of 10 m/s and 30 m/s, respectively, strike each other and stick together. The rise in temperature (in °C), if all the heat produced during the collision is retained by these spheres, is : (specific heat of sphere material 31 cal/kg. °C and 1 cal = 4.2 J)
  1. (A)1.751.751.75
  2. (B)1.441.441.44
  3. (C)1.151.151.15
  4. (D)1.951.951.95

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument thickness of a sheet is measured. If pitch scale reading is 1 mm and the circular scale reading is 51 then the correct thickness of the sheet is ______ mm. [Assume least count is 0.01 mm]
  1. (A)1.501.501.50
  2. (B)1.481.481.48
  3. (C)1.541.541.54
  4. (D)1.511.511.51

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Consider a ferromagnetic material : Assertion (A) : The individual atoms in a ferromagnetic material possess a magnetic dipole moment and interact with one another in such a way that they spontaneously align themselves forming domains. Reason (R) : At high enough temperature, the domain structure of ferromagnetic material disintegrates. Thus, magnetization will disappear at high enough temperature known as Curie temperature. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)(A) is true but (R) is false
  2. (B)Both (A) and (R) are true but (R) is not the correct explanation of (A)
  3. (C)Both (A) and (R) are true and (R) is the correct explanation of (A)
  4. (D)(A) is false but (R) is true

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsNumerical
A simple pendulum made of mass 10 g and a metallic wire of length 10 cm is suspended vertically in a uniform magnetic field of 2 T. The magnetic field direction is perpendicular to the plane of oscillations of the pendulum. If the pendulum is released from an angle of 60° with vertical, then maximum induced EMF between the point of suspension and point of oscillation is ______ mV. (Take g = 10 m/s2^22)

Correct answer: 100

Step-by-step solution →
Q21·PhysicsNumerical
The equation of the electric field of an electromagnetic wave propagating through free space is given by : E=377 sin⁡(6.27×103t−2.09×10−5x)E = \sqrt{377}\ \sin(6.27 \times 10^{3}t - 2.09 \times 10^{-5}x)E=377​ sin(6.27×103t−2.09×10−5x) N/C he average power of the electromagnetic wave is (1α)\left(\frac{1}{\alpha}\right)(α1​) W/m2^22. The value of α\alphaα is ______ (Take μ0ε0=377 in SI units)\left(\text{Take } \sqrt{\frac{\mu_0}{\varepsilon_0}} = 377 \text{ in SI units}\right)(Take ε0​μ0​​​=377 in SI units)

Correct answer: 2

Step-by-step solution →
Q22·PhysicsNumerical
Using a variable-frequency a.c. voltage source, the maximum current measured in the given LCR circuit is 50 mA for V=5sin(100t). The values of L and R are shown in the figure. The capacitance of the capacitor (C) used is ______ μF.

Correct answer: 50

Step-by-step solution →
Q23·PhysicsNumerical
In two separate Young's double-slit experimental set-ups, two monochromatic light sources of different wavelengths are used to get fringes of equal width. The ratios of the slit separations and that of the wavelengths of light used are 2 : 1 and 1 : 2 respectively. The corresponding ratio of the distances between the slits and the respective screens (D1/D2D_1 / D_2D1​/D2​) is ______.

Correct answer: 4

Step-by-step solution →
Q24·PhysicsNumerical
The space between the plates of a parallel-plate capacitor of capacitance C (without any dielectric) is now filled with three dielectric slabs of dielectric constants K1=2K_1 = 2K1​=2, K2=3K_2 = 3K2​=3, and K3=5K_3 = 5K3​=5 (as shown in the figure). If new capacitance is n3C\frac{n}{3}C3n​C then the value of n is ______.

Correct answer: 8

Step-by-step solution →

Chemistry — JEE Main 23 January 2026 Shift 1

Q25·ChemistrySingle correct
Which of the following statements regarding the energy of the stationary state is true in the following one-electron system ?
  1. (A)−1.09×10−18-1.09 \times 10^{-18}−1.09×10−18 J for second orbit of H atom.
  2. (B)+2.18×10−18+2.18 \times 10^{-18}+2.18×10−18 J for second orbit of He+^++ ion
  3. (C)+8.72×10−18+8.72 \times 10^{-18}+8.72×10−18 J for first orbit of He+^++ ion
  4. (D)−2.18×10−18-2.18 \times 10^{-18}−2.18×10−18 J for third orbit of Li2+^{2+}2+ ion

Correct answer: (D)

Step-by-step solution →
Q26·ChemistrySingle correct
Which one of the following graphs accurately represents the plot of partial pressure of CS2_22​ vs its mole fraction in a mixture of acetone and CS2_22​ at constant temperature ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q27·ChemistrySingle correct
The correct trend in the first ionization enthalpies of the elements in the 3rd^{rd}rd period of periodic table is:
  1. (A)Al < Si < S < P < Cl
  2. (B)Al < S < P < Si < Cl
  3. (C)Si < S < Al < P < Cl
  4. (D)S < Si < Al < P < Cl

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correct
The correct sequence of reagents for the above conversion of X to Y is :
  1. (A)(i) NaOH (aq) (ii) Jones reagent (iii) H3_33​O+^++
  2. (B)B2_22​H6_66​/H2_22​O2_22​ (ii) NaOEt (iii) Jones reagent
  3. (C)(i) Jones reagent (ii) NaOEt (iii) Hot KMnO4_44​/KOH
  4. (D)(i) NaOEt (ii) B2_22​H6_66​/H2_22​O2_22​ (iii) Jones reagent

Correct answer: (D)

Step-by-step solution →
Q29·ChemistrySingle correct
'x' is the product which is obtained from propanenitrile and stannous chloride in the presence of hydrochloric acid followed by hydrolysis. 'y' is the product which is obtained from the but-2-ene by the ozonolysis followed by hydrolysis. From the following, which product is not obtained when one mole of 'x' and one mole of 'y' react with each other in the presence of alkali followed by heating ?
  1. (A)2-Methylbut-2-enal
  2. (B)Pent-2-enal
  3. (C)2-Methylpent-2-enal
  4. (D)3-Methylbut-2-enal

Correct answer: (D)

Step-by-step solution →
Q30·ChemistrySingle correct
Consider the following sequence of reactions. 4-Nitrotoluene Assuming that the reaction proceeds to completion, then 137 mg of 4-nitrotoluene will produce ______mg of B. (Given molar mass in g mol−1^{-1}−1 H : 1, C : 12, N :14, O :16, Br : 80)
  1. (A)301
  2. (B)146
  3. (C)228
  4. (D)208

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
A cup of water at 5∘^\circ∘C (system) is placed in a microwave oven and the oven is turned on for one minute during which, the water begins to boil. Which of the following option is true ?
  1. (A)q = +ve, w = 0, Δ\DeltaΔU = -ve
  2. (B)q = +ve, w = -ve, Δ\DeltaΔU = +ve
  3. (C)q = -ve, w = -ve, Δ\DeltaΔU = -ve
  4. (D)q = +ve, w = -ve, Δ\DeltaΔU = -ve

Correct answer: (B)

Step-by-step solution →
Q32·ChemistrySingle correct
Given below are two statements : Statement I : [CoBr4_44​]2−^{2-}2− ion will absorb light of lower energy than [CoCl4_44​]2−^{2-}2− ion. Statement II : In [CoI4_44​]2−^{2-}2− ion, the energy separation between the two set of d-orbitals is more than [CoCl4_44​]2−^{2-}2− ion. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is true but Statement II is false
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are true

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
But-2-yne and hydrogen (one mole each) are separately treated with (i) Pd/C and (ii) Na/liq. NH3_33​ to give the products X and Y respectively. Identify the incorrect statements. A. X and Y are stereoisomers. B. Dipole moment of X is zero C. Boiling point of X is higher than Y. D. X and Y react with O3_33​/Zn + H2_22​O to give different products. Choose the correct answer from the options given below :
  1. (A)B and C only
  2. (B)B and D only
  3. (C)A and B only
  4. (D)A and C only

Correct answer: (B)

Step-by-step solution →
Q34·ChemistrySingle correct
Given, (A) n = 5, ml_ll​ = −1-1−1 (B) n = 3, l = 2, ml_ll​ = −1-1−1, ms_ss​ = +12+\frac{1}{2}+21​ The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) respectively are :
  1. (A)26 and 1
  2. (B)4 and 1
  3. (C)2 and 4
  4. (D)8 and 1

Correct answer: (D)

Step-by-step solution →
Q35·ChemistrySingle correct
Consider the following compounds Arrange these compounds in the increasing order of reactivity with nitrating mixture.
  1. (A)c < a < b
  2. (B)b < c < a
  3. (C)c < b < a
  4. (D)b < a < c

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
The statements that are incorrect about the nickel (II) complex of dimethylglyoxime are : A. It is red in colour B. It has a high solubility in water at pH = 9 C. The Ni ion has two unpaired d-electrons D. The N - Ni - N bond angle is almost close to 90∘^\circ∘ E. The complex contains four five-membered metallacycles (metal containing rings) Choose the correct answer from the options given below :
  1. (A)C and E only
  2. (B)A, D and B only
  3. (C)B, C and E only
  4. (D)C and D only

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are :
  1. (A)B and D
  2. (B)A and D
  3. (C)A and B
  4. (D)B and C

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
Identify the molecule(X) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among HNO3_33​, H2_22​SO4_44​, NF3_33​ and O3_33​. Choose the correct bond angle made by the central atom of the molecule (X).
  1. (A)120°
  2. (B)107°
  3. (C)102°
  4. (D)116°

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
Match List-I (Functional group (detection)) with List-II (Change observed during detection). Choose the correct answer from the options given below :
List-I (Functional group (detection))List-II (Change observed during detection)
A.Unsaturation (Baeyer's test)I.Red colour Appears
B.Alcoholic group (Ceric ammonium nitrate test)II.Silver mirror appears
C.Aldehyde group (Tollen's reagent)III.Violet colour appears
D.Phenolic group (FeCl3_33​ test)IV.Discharge of pink colour
  1. (A)A-III, B-IV, C-II, D-I
  2. (B)A-III, B-IV, C-I, D-II
  3. (C)A-IV, B-I, C-II, D-III
  4. (D)A-IV, B-III, C-II, D-I

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
Given below are two statements : Statement-I : Sublimation is used for the separation and purification of compounds with low melting point. Statement-II : The boiling point of a liquid increases as the external pressure is reduced. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Statement-I is false but Statement-II is true.
  2. (B)Statement-I is true but Statement-II is false.
  3. (C)Both Statement-I and Statement-II are true.
  4. (D)Both Statement-I and Statement-II are false.

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correct
Compound 'P' undergoes the following sequence of reactions : 'P' is :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
The correct statements from the following are : (A) Ionic radii of trivalent cations of group 13 elements decreases down the group. (B) Electronegativity of group 13 elements decreases down the group. (C) Among the group 13 elements, Boron has highest first ionisation enthalpy. (D) The trichloride and triiodide of group 13 elements are covalent in nature. Choose the correct answer from the otpions given below :
  1. (A)A and C only
  2. (B)A and D only
  3. (C)C and D only
  4. (D)B and D only

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
Consider the general reaction given below at 400 K xA(g) ⇌ yB(g) The values of Kp_pp​ and Kc_cc​ are studied under the same condition of temperature but variation in x and y. (i) Kp_pp​ = 85.87 and Kc_cc​ = 2.586 appropriate units (ii) Kp_pp​ = 0.862 and Kc_cc​ = 28.62 appropriate units The value of x and y in (i) and (ii) respectively are:
  1. (A)(i) 3, 1 ; (ii) 3, 1
  2. (B)(i) 4, 1 ; (ii) 4, 1
  3. (C)(i) 1, 3 ; (ii) 2, 1
  4. (D)(i) 1, 2 ; (ii) 2, 1

Correct answer: (D)

Step-by-step solution →
Q44·ChemistryNumerical
For the thermal decomposition of reaction AB(g), the following is constructed. The half life of the reaction is 'x' min. x = ______ min. (Nearest integer)

Correct answer: 10

Step-by-step solution →
Q45·ChemistryNumerical
For the following gas phase equilibrium reaction at constant temperature, NH3_33​(g) ⇌ 12\frac{1}{2}21​ N2_22​(g) + 32\frac{3}{2}23​ H2_22​(g) If the total pressure is 3\sqrt{3}3​ atm and the pressure equilibrium constant (Kp_pp​) is 9 atm, then the degree of dissociation is given as (x×10−2)−1/2(x \times 10^{-2})^{-1/2}(x×10−2)−1/2. The value of x is ______ (Nearest integer)

Correct answer: 125

Step-by-step solution →
Q46·ChemistryNumerical
x mg of pure HCl was used to make an aqueous solution. 25.0 mL of 0.1M Ba(OH)2_22​ solution is used when the HCl solution was titrated against it. The numerical value of x is ______ ×10−1\times 10^{-1}×10−1. (Nearest integer) Given : Molar mass of HCl and Ba(OH)2_22​ are 36.5 and 171.0 g mol−1^{-1}−1 respectively.

Correct answer: 1825

Step-by-step solution →
Q47·ChemistryNumerical
Consider all the structural isomers with molecular formula C5_55​H11_{11}11​Br are separately treated with KOH (aq) to give respective substitution products, without any rearrangement. The number of products which can exhibit optical isomerism from these is ________.

Correct answer: 3

Step-by-step solution →
Q48·ChemistryNumerical
The crystal field splitting energy of [Co(oxalate)3_33​]3−^{3-}3− complex is 'n' times that of the [Cr(oxalate)3_33​]3−^{3-}3− complex. Here 'n' is ______. [Assume Δ0\Delta_0Δ0​ >> P]

Correct answer: 2

Step-by-step solution →

Mathematics — JEE Main 23 January 2026 Shift 1

Q49·MathematicsSingle correct
Let the domain of the function f(x)=log⁡3log⁡5log⁡7(9x−x2−13)f(x) = \log_3\log_5\log_7 (9x - x^2 - 13)f(x)=log3​log5​log7​(9x−x2−13) be the interval (m, n). Let the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1a2x2​−b2y2​=1 have eccentricity n3\frac{n}{3}3n​ and the length of the latus rectum 8m3\frac{8m}{3}38m​. Then b2−a2b^2 - a^2b2−a2 is equal to :
  1. (A)5
  2. (B)11
  3. (C)9
  4. (D)7

Correct answer: (D)

Step-by-step solution →
Q50·MathematicsSingle correct
Let f(x)=∫(2−x2).ex(1+x)(1−x)3/2dxf(x) = \int \frac{(2-x^2).e^x}{\left(\sqrt{1+x}\right)(1-x)^{3/2}} dxf(x)=∫(1+x​)(1−x)3/2(2−x2).ex​dx . If f(0)−0f(0) - 0f(0)−0, then f(12)f\left(\frac{1}{2}\right)f(21​) is equal to :
  1. (A)3e−1\sqrt{3e} - 13e​−1
  2. (B)2e+1\sqrt{2e} + 12e​+1
  3. (C)2e−1\sqrt{2e} - 12e​−1
  4. (D)3e+1\sqrt{3e} + 13e​+1

Correct answer: (A)

Step-by-step solution →
Q51·MathematicsSingle correct
Let a⃗=−i^+j^+2k^\vec{a} = -\hat{i} + \hat{j} + 2\hat{k}a=−i^+j^​+2k^, b⃗=i^−j^−3k^\vec{b} = \hat{i} - \hat{j} - 3\hat{k}b=i^−j^​−3k^, c⃗=a⃗×b⃗\vec{c} = \vec{a} \times \vec{b}c=a×b and d⃗=c⃗×a⃗\vec{d} = \vec{c} \times \vec{a}d=c×a. Then (a⃗−b⃗)⋅d⃗\left(\vec{a} - \vec{b}\right) \cdot \vec{d}(a−b)⋅d is equal to :
  1. (A)4
  2. (B)-4
  3. (C)-2
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correct
A rectangle is formed by the lines x = 0, y = 0, x = 3 and y = 4. Let the line L be perpendicular to 3x + y + 6 = 0 and divide the area of the rectangle into two equal parts. Then the distance of the point (12,−5)\left(\frac{1}{2}, -5\right)(21​,−5) from the line L is equal to :
  1. (A)252\sqrt{5}25​
  2. (B)3103\sqrt{10}310​
  3. (C)10\sqrt{10}10​
  4. (D)2102\sqrt{10}210​

Correct answer: (D)

Step-by-step solution →
Q53·MathematicsSingle correct
Let the line y - x = 1 intersect the ellipse x22+y21=1\frac{x^2}{2} + \frac{y^2}{1} = 12x2​+1y2​=1 at the points A and B. Then the angle made by the line segment AB at the center of the ellipse is :
  1. (A)π−tan⁡−1(14)\pi - \tan^{-1}\left(\frac{1}{4}\right)π−tan−1(41​)
  2. (B)π2+tan⁡−1(14)\frac{\pi}{2} + \tan^{-1}\left(\frac{1}{4}\right)2π​+tan−1(41​)
  3. (C)π2+2tan⁡−1(14)\frac{\pi}{2} + 2\tan^{-1}\left(\frac{1}{4}\right)2π​+2tan−1(41​)
  4. (D)π2−tan⁡−1(14)\frac{\pi}{2} - \tan^{-1}\left(\frac{1}{4}\right)2π​−tan−1(41​)

Correct answer: (B)

Step-by-step solution →
Q54·MathematicsSingle correct
Let A={-2, -1, 0,1, 2, 3, 4}. Let R be a relation on A defined by xRy if and only if 2x+y≤22x + y \le 22x+y≤2. Let lll be the number of elements in R. Let m and n be the minimum number of elements required to be added in R to make it reflexive and symmetric relations respectively. Then lll + m + n is equal to :
  1. (A)32
  2. (B)34
  3. (C)33
  4. (D)35

Correct answer: (C)

Step-by-step solution →
Q55·MathematicsSingle correct
Let y = y(x) be the solution of the differential equation x4dy+(4x3y+2sin⁡x)dx=0x^4 dy + (4x^3 y + 2\sin x)dx = 0x4dy+(4x3y+2sinx)dx=0, x>0x > 0x>0, y(π2)=0y\left(\frac{\pi}{2}\right) = 0y(2π​)=0. Then π4y(π3)\pi^4 y\left(\frac{\pi}{3}\right)π4y(3π​) is equal to :
  1. (A)81
  2. (B)92
  3. (C)64
  4. (D)72

Correct answer: (A)

Step-by-step solution →
Q56·MathematicsSingle correct
If α\alphaα and β\betaβ (α<β\alpha < \betaα<β) are the roots of the equation (−2+3)(∣x−3∣)+(x−6x)+(9−23)=0\left(-2 + \sqrt{3}\right)\left(\left|\sqrt{x} - 3\right|\right) + \left(x - 6\sqrt{x}\right) + \left(9 - 2\sqrt{3}\right) = 0(−2+3​)(∣x​−3∣)+(x−6x​)+(9−23​)=0, x≥0x \ge 0x≥0, then βα+αβ\sqrt{\frac{\beta}{\alpha}} + \sqrt{\alpha\beta}αβ​​+αβ​ is equal to :
  1. (A)8
  2. (B)9
  3. (C)10
  4. (D)11

Correct answer: (C)

Step-by-step solution →
Q57·Mathematics·Limits and ContinuitySingle correct
Let f(x)={ax2+2ax+34x2+4x−3,x≠−32,12b,x=−32,12f(x) = \begin{cases} \frac{ax^2 + 2ax + 3}{4x^2 + 4x - 3}, & x \ne -\frac{3}{2}, \frac{1}{2} \\ b, & x = -\frac{3}{2}, \frac{1}{2} \end{cases}f(x)={4x2+4x−3ax2+2ax+3​,b,​x=−23​,21​x=−23​,21​​ be continuous at x=−32x = -\frac{3}{2}x=−23​. If fof(x)=75fof(x) = \frac{7}{5}fof(x)=57​, then x is equal to :
  1. (A)2
  2. (B)1
  3. (C)0
  4. (D)1.4

Correct answer: (B)

Step-by-step solution →
Q58·MathematicsSingle correct
The value of the integral ∫π245π24dx1+tan⁡2x3\int_{\frac{\pi}{24}}^{\frac{5\pi}{24}} \frac{dx}{1 + \sqrt[3]{\tan 2x}}∫24π​245π​​1+3tan2x​dx​ is :
  1. (A)π12\frac{\pi}{12}12π​
  2. (B)π18\frac{\pi}{18}18π​
  3. (C)π6\frac{\pi}{6}6π​
  4. (D)π3\frac{\pi}{3}3π​

Correct answer: (A)

Step-by-step solution →
Q59·MathematicsSingle correct
Among the statements : I : If ∣1cos⁡αcos⁡βcos⁡α1cos⁡γcos⁡βcos⁡γ1∣=∣0cos⁡αcos⁡βcos⁡α0cos⁡γcos⁡βcos⁡γ0∣\begin{vmatrix} 1 & \cos\alpha & \cos\beta \\ \cos\alpha & 1 & \cos\gamma \\ \cos\beta & \cos\gamma & 1 \end{vmatrix} = \begin{vmatrix} 0 & \cos\alpha & \cos\beta \\ \cos\alpha & 0 & \cos\gamma \\ \cos\beta & \cos\gamma & 0 \end{vmatrix}​1cosαcosβ​cosα1cosγ​cosβcosγ1​​=​0cosαcosβ​cosα0cosγ​cosβcosγ0​​, then cos⁡2α+cos⁡2β+cos⁡2γ=32\cos^2\alpha + \cos^2\beta + \cos^2\gamma = \frac{3}{2}cos2α+cos2β+cos2γ=23​, and II : If ∣x2+xx+1x−22x2+3x−13x3x−3x2+2x+32x−12x−1∣=px+q\begin{vmatrix} x^2 + x & x + 1 & x - 2 \\ 2x^2 + 3x - 1 & 3x & 3x - 3 \\ x^2 + 2x + 3 & 2x - 1 & 2x - 1 \end{vmatrix} = px + q​x2+x2x2+3x−1x2+2x+3​x+13x2x−1​x−23x−32x−1​​=px+q, then p2=196q2p^2 = 196q^2p2=196q2,
  1. (A)both are false
  2. (B)only II is true
  3. (C)both are true
  4. (D)only I is true

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
The value of 100C5051+100C5152+…+100C100101\frac{^{100}C_{50}}{51} + \frac{^{100}C_{51}}{52} + \ldots + \frac{^{100}C_{100}}{101}51100C50​​+52100C51​​+…+101100C100​​ is :
  1. (A)2101100\frac{2^{101}}{100}1002101​
  2. (B)2100100\frac{2^{100}}{100}1002100​
  3. (C)2101101\frac{2^{101}}{101}1012101​
  4. (D)2100101\frac{2^{100}}{101}1012100​

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
Let the mean and variance of 8 numbers -10, -7, -1, x, y, 9, 2, 16 be 72\frac{7}{2}27​ and 2934\frac{293}{4}4293​, respectively. Then the mean of 4 numbers x, y, x + y + 1, |x - y| is:
  1. (A)11
  2. (B)9
  3. (C)10
  4. (D)12

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
The sum of all possible values of n∈Nn \in Nn∈N, so that the coefficients of xxx, x2x^{2}x2 and x3x^{3}x3 in the expansion of (1+x2)2(1+x)n(1 + x^{2})^{2} (1 + x)^{n}(1+x2)2(1+x)n, are in arithmetic progression is :
  1. (A)3
  2. (B)7
  3. (C)12
  4. (D)9

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
The vertices B and C of a triangle ABC lie on the line x1=1−y−2=z−23\frac{x}{1} = \frac{1-y}{-2} = \frac{z-2}{3}1x​=−21−y​=3z−2​. The coordinates of A and B are (1, 6, 3) and (4, 9, α\alphaα) respectively and C is at a distance of 10 units from B. The area (in sq. units) of ΔABC\Delta ABCΔABC is:
  1. (A)5135\sqrt{13}513​
  2. (B)151315\sqrt{13}1513​
  3. (C)201320\sqrt{13}2013​
  4. (D)101310\sqrt{13}1013​

Correct answer: (A)

Step-by-step solution →
Q64·MathematicsSingle correct
Number of solutions of 3 cos⁡2θ+8cos⁡θ+33=0\sqrt{3}\ \cos 2\theta + 8 \cos\theta + 3\sqrt{3} = 03​ cos2θ+8cosθ+33​=0, θ∈[−3π,2π]\theta \in [-3\pi, 2\pi]θ∈[−3π,2π] is:
  1. (A)0
  2. (B)5
  3. (C)3
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let S={z:3≤∣2z−3(1+i)∣≤7}S = \{z : 3 \le | 2z - 3(1 + i)| \le 7\}S={z:3≤∣2z−3(1+i)∣≤7} be a set of complex numbers. Then Minz∈S ∣(z+12(5+3i))∣\underset{z \in S}{\mathrm{Min}}\ \left|\left(z + \frac{1}{2}(5 + 3i)\right)\right|z∈SMin​ ​(z+21​(5+3i))​ is equal to :
  1. (A)12\frac{1}{2}21​
  2. (B)32\frac{3}{2}23​
  3. (C)2
  4. (D)52\frac{5}{2}25​

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
Let α\alphaα and β\betaβ respectively be the maximum and the minimum values of the function f(θ)=4(sin⁡4(7π2−θ)+sin⁡4(11π+θ))−2(sin⁡6(3π2−θ)+sin⁡6(9π−θ))f(\theta) = 4\left(\sin^{4}\left(\frac{7\pi}{2} - \theta\right) + \sin^{4}(11\pi + \theta)\right) - 2\left(\sin^{6}\left(\frac{3\pi}{2} - \theta\right) + \sin^{6}(9\pi - \theta)\right)f(θ)=4(sin4(27π​−θ)+sin4(11π+θ))−2(sin6(23π​−θ)+sin6(9π−θ)), θ∈R\theta \in \mathbf{R}θ∈R. Then α+2β\alpha + 2\betaα+2β is equal to :
  1. (A)4
  2. (B)5
  3. (C)3
  4. (D)6

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
A building construction work can be completed by two masons A and B together in 22.5 days. Mason A alone can complete the construction work in 24 days less than mason B alone. Then mason A alone will complete the construction work in:
  1. (A)24 days
  2. (B)42 days
  3. (C)30 days
  4. (D)36 days

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
Let the direction cosines of two lines satisfy the equations : 4ℓ+m−n=04\ell + m - n = 04ℓ+m−n=0 and 2mn+10nℓ+3ℓm=02mn + 10n\ell + 3\ell m = 02mn+10nℓ+3ℓm=0. Then the cosine of the acute angle between these lines is :
  1. (A)1038\frac{10}{\sqrt{38}}38​10​
  2. (B)20338\frac{20}{3\sqrt{38}}338​20​
  3. (C)10738\frac{10}{7\sqrt{38}}738​10​
  4. (D)10338\frac{10}{3\sqrt{38}}338​10​

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsNumerical
Let ∣A∣=6|A| = 6∣A∣=6, where A is a 3×33 \times 33×3 matrix. If ∣adj(3adj(A2⋅adj(2A)))∣=2m⋅3n|\mathrm{adj}(3\mathrm{adj}(A^{2} \cdot \mathrm{adj}(2A)))| = 2^{m} \cdot 3^{n}∣adj(3adj(A2⋅adj(2A)))∣=2m⋅3n, m,n∈Nm, n \in \mathbf{N}m,n∈N, then m+nm + nm+n is equal to __________.

Correct answer: 62

Step-by-step solution →
Q70·MathematicsNumerical
Let the area of the region bounded by the curve y=max⁡ {sin⁡x,cos⁡x}y = \max\ \{\sin x, \cos x\}y=max {sinx,cosx}, lines x=0x = 0x=0, x=3π2x = \frac{3\pi}{2}x=23π​, and the x-axis be A. Then, A+A2A + A^{2}A+A2 is equal to

Correct answer: 12

Step-by-step solution →
Q71·MathematicsNumerical
Let f be a twice differentiable non-negative function such that (f(x))2=25+∫0x((f(t))2+(f′(t))2)dt(f(x))^{2} = 25 + \int\limits_{0}^{x}\left((f(t))^{2} + (f'(t))^{2}\right) dt(f(x))2=25+0∫x​((f(t))2+(f′(t))2)dt. Then the mean of f(log⁡e(1))f(\log_{e}(1))f(loge​(1)), f(log⁡e(2))f(\log_{e}(2))f(loge​(2)), ....., f(log⁡e(625))f(\log_{e}(625))f(loge​(625)) is equal to _________ .

Correct answer: 1565

Step-by-step solution →
Q72·MathematicsNumerical
From the first 100 natural numbers, two numbers first a and then b are selected randomly without replacement. If the probability that a−b≥10a - b \ge 10a−b≥10 is mn\frac{m}{n}nm​, gcd (m, n) = 1, then m+nm + nm+n is equal to _______.

Correct answer: 311

Step-by-step solution →
Q73·MathematicsNumerical
The number of 4-letter words, with or without meaning, which can be formed using the letters PQRPQRSTUVP, is _______ .

Correct answer: 1422

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Indefinite Integration 66/186
  • Magnetism and Matter 50/186
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