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JEE Main 4 September 2020 Shift 1 Question Paper with Answers

4 September 2020 · September session · 73 questions

73 of the 75 questions from the JEE Main 4 September 2020 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

2 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
23
Chemistry
25
Mathematics
25

Physics — JEE Main 4 September 2020 Shift 1

Q1·PhysicsSingle correct
On the x-axis and at a distance x from the origin, the gravitational field due to a mass distribution is given by Ax(x2+a2)3/2\frac{Ax}{\left(x^{2}+a^{2}\right)^{3/2}}(x2+a2)3/2Ax​ in the x-direction. The magnitude of gravitational potential on the x-axis at a distance x, taking its value to be zero at infinity is:
  1. (A)A(x2+a2)1/2A\left(x^{2}+a^{2}\right)^{1/2}A(x2+a2)1/2
  2. (B)A(x2+a2)3/2\frac{A}{\left(x^{2}+a^{2}\right)^{3/2}}(x2+a2)3/2A​
  3. (C)A(x2+a2)3/2A\left(x^{2}+a^{2}\right)^{3/2}A(x2+a2)3/2
  4. (D)A(x2+a2)1/2\frac{A}{\left(x^{2}+a^{2}\right)^{1/2}}(x2+a2)1/2A​

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
Given figure shows few data points in a photo electric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is: (Plancks constant h=6.62×10−34h = 6.62 \times 10^{-34}h=6.62×10−34 J.s)
  1. (A)1.93 eV
  2. (B)2.10 eV
  3. (C)2.59 eV
  4. (D)2.27 eV

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
A Tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height h2\frac{h}{2}2h​. The velocity versus height of the ball during its motion may be represented graphically by: (graphs are drawn schematically and on not to scale)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
Dimensional formula for thermal conductivity is (here K denotes the temperature):
  1. (A)MLT−3K−1MLT^{-3}K^{-1}MLT−3K−1
  2. (B)MLT−2K−2MLT^{-2}K^{-2}MLT−2K−2
  3. (C)MLT−2KMLT^{-2}KMLT−2K
  4. (D)MLT−3KMLT^{-3}KMLT−3K

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
Particle A of mass mA=m2m_{A} = \frac{m}{2}mA​=2m​ moving along the x-axis with velocity v0v_{0}v0​ collides elastically with another particle B at rest having mass mB=m3m_{B} = \frac{m}{3}mB​=3m​. If both particles move along the x-axis after the collision, the change Δλ\Delta\lambdaΔλ in de-Broglie wavelength of particle A, in terms of its de-Broglie wavelength (λ0)(\lambda_{0})(λ0​) before collision is:
  1. (A)Δλ=32λ0\Delta\lambda = \frac{3}{2}\lambda_{0}Δλ=23​λ0​
  2. (B)Δλ=52λ0\Delta\lambda = \frac{5}{2}\lambda_{0}Δλ=25​λ0​
  3. (C)Δλ=2λ0\Delta\lambda = 2\lambda_{0}Δλ=2λ0​
  4. (D)Δλ=4λ0\Delta\lambda = 4\lambda_{0}Δλ=4λ0​

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
A wire A, bent in the shape of an arc of a circle, carrying a current of 2 A and having radius 2 cm and another wire B, also bent in the shape of arc of a circle, carrying a current of 3 A and having radius of 4 cm, are placed as shown in the figure. The ratio of the magnetic fields due to the wires A and B at the common centre O is:
  1. (A)6 : 5
  2. (B)2 : 5
  3. (C)6 : 4
  4. (D)4 : 6

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
The specific heat of water = 4200 J kg−1^{-1}−1K−1^{-1}−1 and the latent heat of ice = 3.4×1053.4 \times 10^{5}3.4×105 J kg−1^{-1}−1. 100 grams of ice at 0°C is placed in 200 g of water at 25°C. The amount of ice that will melt as the temperature of water reaches 0°C is close to (in grams):
  1. (A)64.6
  2. (B)61.7
  3. (C)69.3
  4. (D)63.8

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
Take the breakdown voltage of the zener diode used in the given circuit as 6V. For the input voltage shown in figure below, the time variation of the output voltage is: (Graphs drawn are schematic and not to scale)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
A beam of plane polarized light of large cross-sectional area and uniform intensity of 3.3 Wm−2^{-2}−2 falls normally on a polarizer (cross sectional area 3×10−43 \times 10^{-4}3×10−4 m2^{2}2) which rotates about its axis with an angular speed of 31.4 rad/s. The energy of light passing through the polariser per revolution, is close to:
  1. (A)1.0×10−51.0 \times 10^{-5}1.0×10−5 J
  2. (B)1.5×10−41.5 \times 10^{-4}1.5×10−4 J
  3. (C)5.0×10−45.0 \times 10^{-4}5.0×10−4 J
  4. (D)1.0×10−41.0 \times 10^{-4}1.0×10−4 J

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
A small bar magnet placed with its axis at 30° with an external field of 0.06 T experiences a torque of 0.018 Nm. The minimum work required to rotate it from its stable to unstable equilibrium position is:
  1. (A)11.7×10−311.7 \times 10^{-3}11.7×10−3 J
  2. (B)9.2×10−39.2 \times 10^{-3}9.2×10−3 J
  3. (C)7.2×10−27.2 \times 10^{-2}7.2×10−2 J
  4. (D)6.4×10−26.4 \times 10^{-2}6.4×10−2 J

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
A two point charges 4q and −q are fixed on the x-axis at x=−d2x = -\frac{d}{2}x=−2d​ and x=d2x = \frac{d}{2}x=2d​, respectively. If a third point charge 'q' is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will:
  1. (A)decrease by 4q23πϵ0d\frac{4q^{2}}{3\pi \epsilon_{0} d}3πϵ0​d4q2​
  2. (B)increase by 2q23πϵ0d\frac{2q^{2}}{3\pi \epsilon_{0} d}3πϵ0​d2q2​
  3. (C)increase by 3q24πϵ0d\frac{3q^{2}}{4\pi \epsilon_{0} d}4πϵ0​d3q2​
  4. (D)decrease by q24πϵ0d\frac{q^{2}}{4\pi \epsilon_{0} d}4πϵ0​dq2​

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Choose the correct option relating wavelengths of different parts of electromagnetic wave spectrum:
  1. (A)λx-rays<λmicro waves<λradio waves<λvisible\lambda_{\text{x-rays}} < \lambda_{\text{micro waves}} < \lambda_{\text{radio waves}} < \lambda_{\text{visible}}λx-rays​<λmicro waves​<λradio waves​<λvisible​
  2. (B)λvisible<λmicro waves<λradio waves<λx-rays\lambda_{\text{visible}} < \lambda_{\text{micro waves}} < \lambda_{\text{radio waves}} < \lambda_{\text{x-rays}}λvisible​<λmicro waves​<λradio waves​<λx-rays​
  3. (C)λvisible>λx-rays>λradio waves>λmicro waves\lambda_{\text{visible}} > \lambda_{\text{x-rays}} > \lambda_{\text{radio waves}} > \lambda_{\text{micro waves}}λvisible​>λx-rays​>λradio waves​>λmicro waves​
  4. (D)λradio waves>λmicro waves>λvisible>λx-rays\lambda_{\text{radio waves}} > \lambda_{\text{micro waves}} > \lambda_{\text{visible}} > \lambda_{\text{x-rays}}λradio waves​>λmicro waves​>λvisible​>λx-rays​

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
Match the CP/CVC_{P}/C_{V}CP​/CV​ ratio for ideal gases with different type of molecules: Match the correct option?
Molecule Type$C_{P}/C_{V}$
A.MonatomicI.75\frac{7}{5}57​
B.Diatomic rigid moleculesII.97\frac{9}{7}79​
C.Diatomic non-rigid moleculesIII.43\frac{4}{3}34​
D.Triatomic rigid moleculesIV.53\frac{5}{3}35​
  1. (A)A → III; B → IV; C → II; D → I
  2. (B)A → IV; B → I; C → II; D → III
  3. (C)A → II; B → III; C → I; D → IV
  4. (D)A → IV; B → II; C → I; D → III

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
A small bar magnet is moved through a coil at constant speed from one end to the other. Which of the following series of observations will be seen on the galvanometer G attached across the coil? Three positions shown describe: (a) the magnet's entry (b) magnet is completely inside and (c) magnet's exit
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correct
For a transverse wave traveling along a straight line, the distance between two peaks (crests) is 5 m, while the distance between one crest and one trough is 1.5 m. The possible wavelengths (in m) of the waves are:
  1. (A)1, 3, 5, …..
  2. (B)11,13,15,....\frac{1}{1}, \frac{1}{3}, \frac{1}{5}, ....11​,31​,51​,....
  3. (C)12,14,16,....\frac{1}{2}, \frac{1}{4}, \frac{1}{6}, ....21​,41​,61​,....
  4. (D)1, 2, 3, ……

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
A air bubble of radius 1 cm in water has an upward acceleration 9.8 cm s−2^{-2}−2. The density of water is 1 gm cm−3^{-3}−3 and water offers negligible drag force on the bubble. The mass of the bubble is: (g = 980 cm/s2^{2}2).
  1. (A)4.51 gm
  2. (B)1.52 gm
  3. (C)3.15 gm
  4. (D)4.15 gm

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
Starting from the origin at time t=0, with initial velocity 5j^5\hat{j}5j^​ ms−1^{-1}−1, a particle moves in the x – y plane with a constant acceleration of (10i^+4j^)\left(10\hat{i} + 4\hat{j}\right)(10i^+4j^​) ms−2^{-2}−2. At time t, its coordinates are (20 m, y0y_0y0​ m). The values of t and y0y_0y0​ are, respectively:
  1. (A)2 s and 24 m
  2. (B)4 s and 52 m
  3. (C)5 s and 25 m
  4. (D)2 s and 18 m

Correct answer: (D)

Step-by-step solution →
Q18·PhysicsSingle correct
Two charged thin infinite plane sheets of uniform surface charge density σ+\sigma_+σ+​ and σ−\sigma_-σ−​, where ∣σ+∣>∣σ−∣|\sigma_+| > |\sigma_-|∣σ+​∣>∣σ−​∣, intersect at right angle. Which of the following best represents the electric field lines for this system.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
Blocks of masses m, 2m and 8m are arranged in a line on a frictionless floor. Another block of mass m, moving with speed v along the same line (see figure) collides with mass m in perfectly inelastic manner. All the subsequent collisions are also perfectly inelastic. By the time the last block of mass 8m starts moving the total energy loss is p% of the original energy. Value of 'p' is close to:
  1. (A)77
  2. (B)37
  3. (C)87
  4. (D)94

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsSingle correct
A battery of 3.0 V is connected to a resistor dissipating 0.5 W of power. If the terminal voltage of the battery is 2.5 V, the power dissipated within the internal resistance is:
  1. (A)0.50 W
  2. (B)0.10 W
  3. (C)0.125 W
  4. (D)0.072 W

Correct answer: (B)

Step-by-step solution →
Q21·PhysicsNumerical
In a compound microscope, the magnified virtual image is formed at a distance of 25 cm from the eye-piece. The focal length of its objective lens is 1 cm. If the magnification is 100 and the tube length of the microscope is 20 cm, then the focal length of the eye-piece lens (in cm) is _________.

Correct answer: 6.25

Step-by-step solution →
Q22·PhysicsNumerical
ABC is a plane lamina of the shape of an equilateral triangle. D, E are mid points of AB, AC and G is the centroid of the lamina. Moment of inertia of the lamina about an axis passing through G and perpendicular to the plane ABC is I0I_0I0​. If part ADE is removed, the moment of inertia of the remaining part about the same axis is NI016\frac{NI_0}{16}16NI0​​ where N is an integer. Value of N is _________.

Correct answer: 11

Step-by-step solution →
Q23·PhysicsNumerical
A circular disc of mass M and radius R is rotating about its axis with angular speed ω1\omega_1ω1​. If another stationary disc having radius R2\frac{R}{2}2R​ and same mass M is dropped co-axially on to the rotating disc. Gradually both discs attain constant angular speed ω2\omega_2ω2​. The energy lost in the process is p% of the initial energy. Value of p is ________.

Correct answer: 20

Step-by-step solution →

Chemistry — JEE Main 4 September 2020 Shift 1

Q24·ChemistrySingle correct
Among statements (a) – (d), the correct ones are: (a) Lime stone is decomposed to CaO during the extraction of iron from its oxides. (b) In the extraction of silver, silver is extracted as an anionic complex. (c) Nickel is purified by Mond's process. (d) Zr and Ti are purified by Van Arkel method.
  1. (A)(a), (b), (c) and (d)
  2. (B)(c) and (d) only
  3. (C)(a), (c) and (d) only
  4. (D)(b), (c) and (d) only

Correct answer: (A)

Step-by-step solution →
Q25·ChemistrySingle correct
The decreasing order of reactivity of the following organic molecules towards AgNO3\mathrm{AgNO_3}AgNO3​ solution is:
  1. (A)(A) > (B) > (D) > (C)
  2. (B)(C) > (D) > (A) > (B)
  3. (C)(A) > (B) > (C) > (D)
  4. (D)(B) > (A) > (C) > (D)

Correct answer: (D)

Step-by-step solution →
Q26·ChemistrySingle correct
The region in the electromagnetic spectrum where the Balmer series lines appear is:
  1. (A)Ultraviolet
  2. (B)Visible
  3. (C)Infrared
  4. (D)Microwave

Correct answer: (B)

Step-by-step solution →
Q27·ChemistrySingle correct
The pair in which both the species have the same magnetic moment (spin only) is:
  1. (A)[Co(OH)4]2−\left[\mathrm{Co(OH)_4}\right]^{2-}[Co(OH)4​]2− and [Fe(NH3)6]2+\left[\mathrm{Fe(NH_3)_6}\right]^{2+}[Fe(NH3​)6​]2+
  2. (B)[Mn(H2O)6]2+\left[\mathrm{Mn(H_2O)_6}\right]^{2+}[Mn(H2​O)6​]2+ and [Cr(H2O)]2+\left[\mathrm{Cr(H_2O)}\right]^{2+}[Cr(H2​O)]2+
  3. (C)[Cr(H2O)6]2+\left[\mathrm{Cr(H_2O)_6}\right]^{2+}[Cr(H2​O)6​]2+ and [Fe(H2O)6]2+\left[\mathrm{Fe(H_2O)_6}\right]^{2+}[Fe(H2​O)6​]2+
  4. (D)[Cr(H2O)6]2+\left[\mathrm{Cr(H_2O)_6}\right]^{2+}[Cr(H2​O)6​]2+ and [CoCl4]2−\left[\mathrm{CoCl_4}\right]^{2-}[CoCl4​]2−

Correct answer: (C)

Step-by-step solution →
Q28·ChemistrySingle correct
On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is:
  1. (A)+4
  2. (B)+3
  3. (C)+2
  4. (D)+5

Correct answer: (B)

Step-by-step solution →
Q29·ChemistrySingle correct
[P] on treatment with Br2/FeBr3\mathrm{Br_2/FeBr_3}Br2​/FeBr3​ in CCl4\mathrm{CCl_4}CCl4​ produced a single isomer C8H7O2Br\mathrm{C_8H_7O_2Br}C8​H7​O2​Br while heating [P] with sodalime gave toluene. The compound [P] is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q30·ChemistrySingle correct
The ionic radii of O2−\mathrm{O^{2-}}O2−, F−\mathrm{F^-}F−, Na+\mathrm{Na^+}Na+ and Mg2+\mathrm{Mg^{2+}}Mg2+ are in the order:
  1. (A)O2−>F−>Mg2+>Na+\mathrm{O^{2-}} > \mathrm{F^-} > \mathrm{Mg^{2+}} > \mathrm{Na^+}O2−>F−>Mg2+>Na+
  2. (B)Mg2+>Na+>F−>O2−\mathrm{Mg^{2+}} > \mathrm{Na^+} > \mathrm{F^-} > \mathrm{O^{2-}}Mg2+>Na+>F−>O2−
  3. (C)F−>O2−>Na+>Mg2+\mathrm{F^-} > \mathrm{O^{2-}} > \mathrm{Na^+} > \mathrm{Mg^{2+}}F−>O2−>Na+>Mg2+
  4. (D)O2−>F−>Na+>Mg2+\mathrm{O^{2-}} > \mathrm{F^-} > \mathrm{Na^+} > \mathrm{Mg^{2+}}O2−>F−>Na+>Mg2+

Correct answer: (D)

Step-by-step solution →
Q31·ChemistrySingle correct
The intermolecular potential energy for the molecules A, B, C and D given below suggest that:
  1. (A)A – A has the largest bond enthalpy
  2. (B)A – D has the shortest bond length
  3. (C)D is more electronegative than other atoms
  4. (D)A – B has the stiffest bond.

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
An organic compound (A) (molecular formula C6H12O2\mathrm{C_6H_{12}O_2}C6​H12​O2​) was hydrolysed with dil. H2SO4\mathrm{H_2SO_4}H2​SO4​ to give a carboxylic acid (B) and an alcohol (C). 'C' gives white turbidity immediately when treated with anhydrous ZnCl2\mathrm{ZnCl_2}ZnCl2​ and conc. HCl. The organic compound (A) is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
For the equilibrium A ⇌\rightleftharpoons⇌ B, the variation of the rate of the forward (a) and reverse (B) reaction with time is given by:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
The number of isomers possible for [Pt(en)(NO2)2]\left[\mathrm{Pt(en)(NO_2)_2}\right][Pt(en)(NO2​)2​] is:
  1. (A)4
  2. (B)3
  3. (C)1
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
The IUPAC name of the following compound is:
  1. (A)4–Bromo–5–methylcyclopentanoic acid
  2. (B)4–Bromo–2–methylcyclopentane carboxylic acid
  3. (C)3–Bromo–5– methylcyclopentane carboxylic acid
  4. (D)5–Bromo–3–methylcyclopentanoic acid

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
What are the functional groups present in the structure of maltose?
  1. (A)One acetal and one hemiacetal
  2. (B)One ketal and one hemiketal
  3. (C)One acetal and one ketal
  4. (D)Two acetals

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
Identify the incorrect statement from the options below for the above cell:
  1. (A)If Eext<1.1E_{ext} < 1.1Eext​<1.1 V, Zn dissolves at anode and Cu deposits at cathode
  2. (B)If Eext=1.1E_{ext} = 1.1Eext​=1.1 V, no flow of e−^-− or current occurs
  3. (C)If Eext>1.1E_{ext} > 1.1Eext​>1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode
  4. (D)If Eext>1.1E_{ext} > 1.1Eext​>1.1 V, e−^-− flows from Cu to Zn

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Which of the following will react with CHCl3_33​ + alc. KOH?
  1. (A)Adenine and proline
  2. (B)Adenine and lysine
  3. (C)Adenine and thymine
  4. (D)Thymine and proline

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
Match the following:
Column IColumn II
(i).Foam(a).smoke
(ii).Gel(b).cell fluid
(iii).Aerosol(c).jellies
(iv).Emulsion(d).rubber
(e).froth
(f).milk
  1. (A)(i)-(d), (ii)-(b), (iii)-(a), (iv)-(e)
  2. (B)(i)-(d), (ii)-(b), (iii)-(e), (iv)-(f)
  3. (C)(i)-(b), (ii)-(c), (iii)-(e), (iv)-(d)
  4. (D)(i)-(e), (ii)-(c), (iii)-(a), (iv)-(f)

Correct answer: (D)

Step-by-step solution →
Q40·ChemistrySingle correct
For one mole of an ideal gas, which of these statements must be true? (a) U and H each depends only on temperature (b) Compressibility factor z is not equal to 1 (c) CP,m−CV,m=RC_{P,m} - C_{V,m} = RCP,m​−CV,m​=R (d) dU=CVdTdU = C_V dTdU=CV​dT for any process
  1. (A)(a), (c) and (d)
  2. (B)(b), (c) and (d)
  3. (C)(a) and (c)
  4. (D)(c) and (d)

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
On combustion of Li, Na and K in excess of air, the major oxides formed, respectively, are:
  1. (A)Li2_22​O, Na2_22​O2_22​ and K2_22​O
  2. (B)Li2_22​O, Na2_22​O2_22​ and KO2_22​
  3. (C)Li2_22​O, Na2_22​O and K2_22​O2_22​
  4. (D)Li2_22​O, Na2_22​O2_22​ and K2_22​O2_22​

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
When neopentyl alcohol is heated with an acid, it slowly converted into an 85:15 mixture of alkenes A and B, respectively. What are these alkenes?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
The elements with atomic numbers 101 and 104 belong to, respectively:
  1. (A)Actinoids and Group 6
  2. (B)Actinoids and Group 4
  3. (C)Group 11 and Group 4
  4. (D)Group 6 and Actinoids

Correct answer: (B)

Step-by-step solution →
Q44·ChemistryNumerical
At 300K, the vapour pressure of a solution containing 1 mole of n-hexane and 3 moles of n-heptane is 550 mm of Hg. At the same temperature, if one more mole of n-heptane is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. What is the vapour pressure in mm Hg of n-heptane in its pure state ________?

Correct answer: 600

Step-by-step solution →
Q45·ChemistryNumerical
If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes) __________. (Take: log 2 = 0.30; log 2.5 = 0.40)

Correct answer: 60

Step-by-step solution →
Q46·ChemistryNumerical
The mass of ammonia in grams produced when 2.8 kg of dinitrogen quantitatively reacts with 1 kg of dihydrogen is ___________.

Correct answer: 3400

Step-by-step solution →
Q47·ChemistryNumerical
The number of chiral centres present in [B] is ___________.

Correct answer: 4

Step-by-step solution →
Q48·ChemistryNumerical
At 20.0 mL solution containing 0.2 g impure H2_22​O2_22​ reacts completely with 0.316 g of KMnO4_44​ in acid solution. The purity of H2_22​O2_22​ (in %) is _______________. (mol. wt. of H2_22​O2_22​ = 34; mol. wt. of KMnO4_44​ = 158)

Correct answer: 85

Step-by-step solution →

Mathematics — JEE Main 4 September 2020 Shift 1

Q49·MathematicsSingle correct
Let α\alphaα and β\betaβ be roots of x2−3x+p=0x^{2} - 3x + p = 0x2−3x+p=0 and γ\gammaγ and δ\deltaδ be the roots of x2−6x+q=0x^{2} - 6x + q = 0x2−6x+q=0. If α\alphaα, β\betaβ, γ\gammaγ, δ\deltaδ, form a geometric progression. Then ratio (2q+p):(2q−p)(2q + p) : (2q - p)(2q+p):(2q−p) is:
  1. (A)33:3133 : 3133:31
  2. (B)5:35 : 35:3
  3. (C)3:13 : 13:1
  4. (D)9:79 : 79:7

Correct answer: (D)

Step-by-step solution →
Q50·MathematicsSingle correct
Let f(x)=∣x−2∣f(x) = |x - 2|f(x)=∣x−2∣ and g(x)=f(f(x))g(x) = f(f(x))g(x)=f(f(x)), x∈[0,4]x \in [0, 4]x∈[0,4]. Then ∫03(g(x)−f(x)) dx\int\limits_{0}^{3} \left( g(x) - f(x) \right)\, dx0∫3​(g(x)−f(x))dx is equal to:
  1. (A)12\frac{1}{2}21​
  2. (B)32\frac{3}{2}23​
  3. (C)111
  4. (D)000

Correct answer: (C)

Step-by-step solution →
Q51·MathematicsSingle correct
Let fff be a twice differentiable function on (1,6)(1, 6)(1,6). If f(2)=8f(2) = 8f(2)=8, f′(2)=5f'(2) = 5f′(2)=5, f′(x)≥1f'(x) \geq 1f′(x)≥1 and f′′(x)≥4f''(x) \geq 4f′′(x)≥4, for all x∈(1,6)x \in (1, 6)x∈(1,6), then:
  1. (A)f(5)+f′(5)≤26f(5) + f'(5) \leq 26f(5)+f′(5)≤26
  2. (B)f(5)≤10f(5) \leq 10f(5)≤10
  3. (C)f(5)+f′(5)≥28f(5) + f'(5) \geq 28f(5)+f′(5)≥28
  4. (D)f′(5)+f′′(5)≤20f'(5) + f''(5) \leq 20f′(5)+f′′(5)≤20

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correct
Let x2a2+y2b2=1 (a>b)\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1\,(a > b)a2x2​+b2y2​=1(a>b) be given ellipse, length of whose latus rectum is 10. If its eccentricity is the maximum value of the function, ϕ(t)=512+t−t2\phi(t) = \frac{5}{12} + t - t^{2}ϕ(t)=125​+t−t2, then a2+b2a^{2} + b^{2}a2+b2 is equal to:
  1. (A)126126126
  2. (B)135135135
  3. (C)116116116
  4. (D)145145145

Correct answer: (A)

Step-by-step solution →
Q53·MathematicsSingle correct
The mean and variance of 8 observations are 10 and 13.5, respectively. If 6 of these observations are 5, 7, 10, 12, 14, 15, then the absolute difference of the remaining two observations is:
  1. (A)333
  2. (B)555
  3. (C)777
  4. (D)999

Correct answer: (C)

Step-by-step solution →
Q54·MathematicsSingle correct
Let x0x_{0}x0​ be the point of local maxima of f(x)=a⃗⋅(b⃗×c⃗)f(x) = \vec{a} \cdot \left( \vec{b} \times \vec{c} \right)f(x)=a⋅(b×c) where a⃗=xi^−2j^+3k^\vec{a} = x\hat{i} - 2\hat{j} + 3\hat{k}a=xi^−2j^​+3k^, b⃗=−2i^+xj^−k^\vec{b} = -2\hat{i} + x\hat{j} - \hat{k}b=−2i^+xj^​−k^ and c⃗=7i^−2j^+xk^\vec{c} = 7\hat{i} - 2\hat{j} + x\hat{k}c=7i^−2j^​+xk^. Then the value of a⃗⋅b⃗+b⃗⋅c⃗+c⃗⋅a⃗\vec{a} \cdot \vec{b} + \vec{b} \cdot \vec{c} + \vec{c} \cdot \vec{a}a⋅b+b⋅c+c⋅a at x=x0x = x_{0}x=x0​ is
  1. (A)−4-4−4
  2. (B)−22-22−22
  3. (C)−30-30−30
  4. (D)141414

Correct answer: (B)

Step-by-step solution →
Q55·MathematicsSingle correct
If (a+2 bcos⁡x)(a−2 bcos⁡y)=a2−b2\left( a + \sqrt{2}\, b \cos x \right)\left( a - \sqrt{2}\, b \cos y \right) = a^{2} - b^{2}(a+2​bcosx)(a−2​bcosy)=a2−b2, where a>b>0a > b > 0a>b>0, then dxdy\frac{dx}{dy}dydx​ at (π4,π4)\left( \frac{\pi}{4}, \frac{\pi}{4} \right)(4π​,4π​) is:
  1. (A)a−2ba+2b\frac{a - 2b}{a + 2b}a+2ba−2b​
  2. (B)2a+b2a−2\frac{2a + b}{2a - 2}2a−22a+b​
  3. (C)a+ba−b\frac{a + b}{a - b}a−ba+b​
  4. (D)a−ba+b\frac{a - b}{a + b}a+ba−b​

Correct answer: (C)

Step-by-step solution →
Q56·MathematicsSingle correct
Two vertical poles AB = 15 m and CD = 10 m are standing apart on a horizontal ground with points A and C on the ground. If P is the point of intersection of BC and AD, then the height of P (in m) above the line AC is:
  1. (A)103\frac{10}{3}310​
  2. (B)666
  3. (C)555
  4. (D)203\frac{20}{3}320​

Correct answer: (B)

Step-by-step solution →
Q57·MathematicsSingle correct
If 1+(1−22⋅1)+(1−42⋅3)+(1−62⋅5)+……+(1−202⋅19)=α−220β1 + (1 - 2^{2} \cdot 1) + (1 - 4^{2} \cdot 3) + (1 - 6^{2} \cdot 5) + \ldots\ldots + (1 - 20^{2} \cdot 19) = \alpha - 220\beta1+(1−22⋅1)+(1−42⋅3)+(1−62⋅5)+……+(1−202⋅19)=α−220β, then an ordered pair (α,β)(\alpha, \beta)(α,β) is equal to:
  1. (A)(11,97)(11, 97)(11,97)
  2. (B)(10,97)(10, 97)(10,97)
  3. (C)(10,103)(10, 103)(10,103)
  4. (D)(11,103)(11, 103)(11,103)

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsSingle correct
Given the following two statements: (S1):(q∨p)→(p↔∼q)(S_{1}) : (q \vee p) \rightarrow (p \leftrightarrow \sim q)(S1​):(q∨p)→(p↔∼q) is a tautology. (S2):∼q∧(∼p↔q)(S_{2}) : \sim q \wedge (\sim p \leftrightarrow q)(S2​):∼q∧(∼p↔q) is a fallacy. Then:
  1. (A)both (S1)(S_{1})(S1​) and (S2)(S_{2})(S2​) are correct
  2. (B)only (S2)(S_{2})(S2​) is correct
  3. (C)both (S1)(S_{1})(S1​) and (S2)(S_{2})(S2​) are incorrect
  4. (D)only (S1)(S_{1})(S1​) is correct

Correct answer: (C)

Step-by-step solution →
Q59·MathematicsSingle correct
Let u=2z+iz−kiu = \frac{2z + i}{z - ki}u=z−ki2z+i​, z=x+iyz = x + iyz=x+iy and k>0k > 0k>0. If the curve represented by Re(u)+Im(u)=1\mathrm{Re}(u) + \mathrm{Im}(u) = 1Re(u)+Im(u)=1 intersects the y-axis at the points P and Q where PQ = 5, then the value of k is:
  1. (A)222
  2. (B)12\frac{1}{2}21​
  3. (C)32\frac{3}{2}23​
  4. (D)444

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
A triangle ABC lying in the first quadrant has two vertices as A(1, 2) and B(3, 1). If ∠BAC=90°\angle BAC = 90°∠BAC=90°, and ar(ΔABC)=55\mathrm{ar}\left( \Delta ABC \right) = 5\sqrt{5}ar(ΔABC)=55​ sq. units, then the abscissa of the vertex C is:
  1. (A)1+251 + 2\sqrt{5}1+25​
  2. (B)1+51 + \sqrt{5}1+5​
  3. (C)25−12\sqrt{5} - 125​−1
  4. (D)2+52 + \sqrt{5}2+5​

Correct answer: (A)

Step-by-step solution →
Q61·MathematicsSingle correct
Let P (3, 3) be a point on the hyperbola, x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1. If the normal to it at P intersects the x-axis at (9, 0) and e is its eccentricity, then the ordered pair (a2,e2)(a^{2}, e^{2})(a2,e2) is equal to:
  1. (A)(32, 2)\left( \frac{3}{2},\, 2 \right)(23​,2)
  2. (B)(92, 2)\left( \frac{9}{2},\, 2 \right)(29​,2)
  3. (C)(9, 3)(9,\, 3)(9,3)
  4. (D)(92, 3)\left( \frac{9}{2},\, 3 \right)(29​,3)

Correct answer: (D)

Step-by-step solution →
Q62·MathematicsSingle correct
The integral ∫(xxsin⁡x+cos⁡x)2dx\int \left( \frac{x}{x \sin x + \cos x} \right)^{2} dx∫(xsinx+cosxx​)2dx is equal to (where C is constant of integration):
  1. (A)tan⁡x+xsec⁡xxsin⁡x+cos⁡x+C\tan x + \frac{x \sec x}{x \sin x + \cos x} + Ctanx+xsinx+cosxxsecx​+C
  2. (B)tan⁡x−xsec⁡xxsin⁡x+cos⁡x+C\tan x - \frac{x \sec x}{x \sin x + \cos x} + Ctanx−xsinx+cosxxsecx​+C
  3. (C)sec⁡x+xtan⁡xxsin⁡x+cos⁡x+C\sec x + \frac{x \tan x}{x \sin x + \cos x} + Csecx+xsinx+cosxxtanx​+C
  4. (D)sec⁡x−xtan⁡xxsin⁡x+cos⁡x+C\sec x - \frac{x \tan x}{x \sin x + \cos x} + Csecx−xsinx+cosxxtanx​+C

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
If A=[cos⁡θisin⁡θisin⁡θcos⁡θ]A = \begin{bmatrix} \cos\theta & i\sin\theta \\ i\sin\theta & \cos\theta \end{bmatrix}A=[cosθisinθ​isinθcosθ​], (θ=π24)\left( \theta = \frac{\pi}{24} \right)(θ=24π​) and A5=[abcd]A^{5} = \begin{bmatrix} a & b \\ c & d \end{bmatrix}A5=[ac​bd​], where i=−1i = \sqrt{-1}i=−1​, then, which one of the following is not true?
  1. (A)a2−c2=1a^{2} - c^{2} = 1a2−c2=1
  2. (B)a2−b2=12a^{2} - b^{2} = \frac{1}{2}a2−b2=21​
  3. (C)0≤a2+b2≤10 \le a^{2} + b^{2} \le 10≤a2+b2≤1
  4. (D)a2−d2=0a^{2} - d^{2} = 0a2−d2=0

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
The value of ∑r=02050−rC6\sum_{r=0}^{20} {}^{50-r}C_{6}∑r=020​50−rC6​ is equal to:
  1. (A)50C6−30C6{}^{50}C_{6} - {}^{30}C_{6}50C6​−30C6​
  2. (B)51C7+30C7{}^{51}C_{7} + {}^{30}C_{7}51C7​+30C7​
  3. (C)51C7−30C7{}^{51}C_{7} - {}^{30}C_{7}51C7​−30C7​
  4. (D)50C7−30C7{}^{50}C_{7} - {}^{30}C_{7}50C7​−30C7​

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let [t] denote the greatest integer ≤t\le t≤t. Then the equation in x, [x]2+2[x+2]−7=0[x]^{2} + 2[x+2] - 7 = 0[x]2+2[x+2]−7=0 has:
  1. (A)infinitely many solutions
  2. (B)exactly two solutions
  3. (C)no integral solution
  4. (D)exactly four integral solutions

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let f(x)=∫x(1+x)2dxf(x) = \int \frac{\sqrt{x}}{(1+x)^{2}} dxf(x)=∫(1+x)2x​​dx (x≥0)(x \ge 0)(x≥0). Then f(3)−f(1)f(3) - f(1)f(3)−f(1) is equal to:
  1. (A)π12+12−34\frac{\pi}{12} + \frac{1}{2} - \frac{\sqrt{3}}{4}12π​+21​−43​​
  2. (B)−π12+12+34-\frac{\pi}{12} + \frac{1}{2} + \frac{\sqrt{3}}{4}−12π​+21​+43​​
  3. (C)π6+12−34\frac{\pi}{6} + \frac{1}{2} - \frac{\sqrt{3}}{4}6π​+21​−43​​
  4. (D)−π6+12+34-\frac{\pi}{6} + \frac{1}{2} + \frac{\sqrt{3}}{4}−6π​+21​+43​​

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
A survey shows that 63% of the people in a city read newspaper A whereas 76% read newspaper B. if x% of the people read both the newspapers, then a possible value of x can be:
  1. (A)29
  2. (B)55
  3. (C)37
  4. (D)65

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation, xy′−y=x2(xcos⁡x+sin⁡x)xy' - y = x^{2}(x \cos x + \sin x)xy′−y=x2(xcosx+sinx), x>0x > 0x>0. If y(π)=πy(\pi) = \piy(π)=π, then y′′(π2)+y(π2)y''\left(\frac{\pi}{2}\right) + y\left(\frac{\pi}{2}\right)y′′(2π​)+y(2π​) is equal to:
  1. (A)1+π2+π241 + \frac{\pi}{2} + \frac{\pi^{2}}{4}1+2π​+4π2​
  2. (B)2+π2+π242 + \frac{\pi}{2} + \frac{\pi^{2}}{4}2+2π​+4π2​
  3. (C)2+π22 + \frac{\pi}{2}2+2π​
  4. (D)1+π21 + \frac{\pi}{2}1+2π​

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsNumerical
Let (2x2+3x+4)10=∑r=020arxr(2x^{2} + 3x + 4)^{10} = \sum_{r=0}^{20} a_{r} x^{r}(2x2+3x+4)10=∑r=020​ar​xr. Then a7a13\frac{a_{7}}{a_{13}}a13​a7​​ is equal to __________.

Correct answer: 8

Step-by-step solution →
Q70·MathematicsNumerical
If the equation of a plane P, passing through the intersection of the planes, x+4y−z+7=0x + 4y - z + 7 = 0x+4y−z+7=0 and 3x+y+5z=83x + y + 5z = 83x+y+5z=8 is ax+by+6z=15ax + by + 6z = 15ax+by+6z=15 for some a,b∈Ra, b \in Ra,b∈R, then the distance of the point (3,2,−1)(3, 2, -1)(3,2,−1) from the plane P is __________.

Correct answer: 3

Step-by-step solution →
Q71·MathematicsNumerical
If the system of equations x−2y+3z=9x - 2y + 3z = 9x−2y+3z=9 2x+y+z=b2x + y + z = b2x+y+z=b x−7y+az=24x - 7y + az = 24x−7y+az=24, has infinitely many solutions, then a−ba - ba−b is equal to __________.

Correct answer: 5

Step-by-step solution →
Q72·MathematicsNumerical
Suppose a differentiable function f(x)f(x)f(x) satisfies the identity f(x+y)=f(x)+f(y)+xy2+x2yf(x+y) = f(x) + f(y) + xy^{2} + x^{2}yf(x+y)=f(x)+f(y)+xy2+x2y, for all real x and y. If lim⁡x→0f(x)x=1\lim_{x \to 0} \frac{f(x)}{x} = 1limx→0​xf(x)​=1 then f′(3)f'(3)f′(3) is equal to __________.

Correct answer: 10

Step-by-step solution →
Q73·MathematicsNumerical
The probability of a man hitting a target is 110\frac{1}{10}101​. The least number of shots required, so that the probability of his hitting the target at least once is greater than 14\frac{1}{4}41​, is __________.

Correct answer: 3

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Hyperbola 77/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Carboxylic Acids and Derivatives 54/186
  • Isomerism 51/186
  • Magnetism and Matter 50/186
  • IUPAC Nomenclature 37/186
  • Mathematical Reasoning 26/186
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