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JEE Main 17 March 2021 Shift 1 Question Paper with Answers

17 March 2021 · March session · 85 questions

85 of the 90 questions from the JEE Main 17 March 2021 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

5 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
28
Mathematics
27

Physics — JEE Main 17 March 2021 Shift 1

Q1·PhysicsSingle correct
A triangular plate is shown. A force F⃗=4i^−3j^\vec{F} = 4\hat{i} - 3\hat{j}F=4i^−3j^​ is applied at point P. The torque at point P with respect to point 'O' and 'Q' are :
  1. (A)−15−203-15 - 20\sqrt{3}−15−203​ , 15−20315 - 20\sqrt{3}15−203​
  2. (B)15+20315 + 20\sqrt{3}15+203​ , 15−20315 - 20\sqrt{3}15−203​
  3. (C)15−20315 - 20\sqrt{3}15−203​ , 15+20315 + 20\sqrt{3}15+203​
  4. (D)−15+203-15 + 20\sqrt{3}−15+203​ , 15+20315 + 20\sqrt{3}15+203​

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
When two soap bubbles of radii a and b (b > a) coalesce, the radius of curvature of common surface is :
  1. (A)abb−a\frac{ab}{b-a}b−aab​
  2. (B)a+bab\frac{a+b}{ab}aba+b​
  3. (C)b−aab\frac{b-a}{ab}abb−a​
  4. (D)aba+b\frac{ab}{a+b}a+bab​

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
A polyatomic ideal gas has 24 vibrational modes. What is the value of γ\gammaγ ?
  1. (A)1.03
  2. (B)1.30
  3. (C)1.37
  4. (D)10.3

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
If an electron is moving in the nthn^{th}nth orbit of the hydrogen atom, then its velocity (vn)(v_n)(vn​) for the nthn^{th}nth orbit is given as :
  1. (A)vn∝nv_n \propto nvn​∝n
  2. (B)vn∝1nv_n \propto \frac{1}{n}vn​∝n1​
  3. (C)vn∝n2v_n \propto n^2vn​∝n2
  4. (D)vn∝1n2v_n \propto \frac{1}{n^2}vn​∝n21​

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is : (c being the velocity of light)
  1. (A)1c(2mE)1/2\frac{1}{c}\left(\frac{2m}{E}\right)^{1/2}c1​(E2m​)1/2
  2. (B)1c(E2m)1/2\frac{1}{c}\left(\frac{E}{2m}\right)^{1/2}c1​(2mE​)1/2
  3. (C)(E2m)1/2\left(\frac{E}{2m}\right)^{1/2}(2mE​)1/2
  4. (D)c (2mE)1/2c\,(2mE)^{1/2}c(2mE)1/2

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
Two identical metal wires of thermal conductivities K1K_1K1​ and K2K_2K2​ respectively are connected in series. The effective thermal conductivity of the combination is :
  1. (A)2K1K2K1+K2\frac{2K_1 K_2}{K_1 + K_2}K1​+K2​2K1​K2​​
  2. (B)K1+K22K1K2\frac{K_1 + K_2}{2K_1 K_2}2K1​K2​K1​+K2​​
  3. (C)K1+K2K1K2\frac{K_1 + K_2}{K_1 K_2}K1​K2​K1​+K2​​
  4. (D)K1K2K1+K2\frac{K_1 K_2}{K_1 + K_2}K1​+K2​K1​K2​​

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
The vernier scale used for measurement has a positive zero error of 0.2 mm. If while taking a measurement it was noted that '0' on the vernier scale lies between 8.5 cm and 8.6 cm, vernier coincidence is 6, then the correct value of measurement is_____ cm. (least count = 0.01 cm)
  1. (A)8.36 cm
  2. (B)8.54 cm
  3. (C)8.58 cm
  4. (D)8.56 cm

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
An AC current is given by I=I1sin⁡ωt+I2cos⁡ωtI = I_1 \sin\omega t + I_2 \cos\omega tI=I1​sinωt+I2​cosωt. A hot wire ammeter will give a reading :
  1. (A)I12−I222\sqrt{\frac{I_1^2 - I_2^2}{2}}2I12​−I22​​​
  2. (B)I12+I222\sqrt{\frac{I_1^2 + I_2^2}{2}}2I12​+I22​​​
  3. (C)I1+I22\frac{I_1 + I_2}{\sqrt{2}}2​I1​+I2​​
  4. (D)I1+I222\frac{I_1 + I_2}{2\sqrt{2}}22​I1​+I2​​

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
A modern grand-prix racing car of mass m is travelling on a flat track in a circular arc of radius R with a speed v. If the coefficient of static friction between the tyres and the track is μs\mu_sμs​, then the magnitude of negative lift FLF_LFL​ acting downwards on the car is : (Assume forces on the four tyres are identical and g = acceleration due to gravity)
  1. (A)m(v2μsR+g)m\left(\frac{v^2}{\mu_s R} + g\right)m(μs​Rv2​+g)
  2. (B)m(v2μsR−g)m\left(\frac{v^2}{\mu_s R} - g\right)m(μs​Rv2​−g)
  3. (C)m(g−v2μsR)m\left(g - \frac{v^2}{\mu_s R}\right)m(g−μs​Rv2​)
  4. (D)−m(g+v2μsR)-m\left(g + \frac{v^2}{\mu_s R}\right)−m(g+μs​Rv2​)

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
A car accelerates from rest at a constant rate α\alphaα for some time after which it decelerates at a constant rate β\betaβ to come to rest. If the total time elapsed is t seconds, the total distance travelled is :
  1. (A)4αβ(α+β)t2\frac{4\alpha\beta}{(\alpha+\beta)}t^2(α+β)4αβ​t2
  2. (B)2αβ(α+β)t2\frac{2\alpha\beta}{(\alpha+\beta)}t^2(α+β)2αβ​t2
  3. (C)αβ2(α+β)t2\frac{\alpha\beta}{2(\alpha+\beta)}t^22(α+β)αβ​t2
  4. (D)αβ4(α+β)t2\frac{\alpha\beta}{4(\alpha+\beta)}t^24(α+β)αβ​t2

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
A solenoid of 1000 turns per metre has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5A. The magnetic flux density produced by the solenoid is : (permeability of free space = 4π×10−74\pi \times 10^{-7}4π×10−7 H/m)
  1. (A)π\piπT
  2. (B)2×10−3 π2 \times 10^{-3}\ \pi2×10−3 πT
  3. (C)π5\frac{\pi}{5}5π​ T
  4. (D)10−4π10^{-4}\pi10−4πT

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
A mass M hangs on a massless rod of length lll which rotates at a constant angular frequency. The mass M moves with steady speed in a circular path of constant radius. Assume that the system is in steady circular motion with constant angular velocity ω\omegaω. The angular momentum of M about point A is LAL_ALA​ which lies in the positive z direction and the angular momentum of M about B is LBL_BLB​. The correct statement for this system is :
  1. (A)LAL_ALA​ and LBL_BLB​ are both constant in magnitude and direction
  2. (B)LBL_BLB​ is constant in direction with varying magnitude
  3. (C)LBL_BLB​ is constant, both in magnitude and direction
  4. (D)LAL_ALA​ is constant, both in magnitude and direction

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal ?
  1. (A)x=0x = 0x=0
  2. (B)x=±Ax = \pm Ax=±A
  3. (C)x=±A2x = \pm \frac{A}{\sqrt{2}}x=±2​A​
  4. (D)x=A2x = \frac{A}{2}x=2A​

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
A Carnot's engine working between 400 K and 800 K has a work output of 1200 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is :
  1. (A)3200 J
  2. (B)1800 J
  3. (C)1600 J
  4. (D)2400 J

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
The thickness at the centre of a plano convex lens is 3 mm and the diameter is 6 cm. If the speed of light in the material of the lens is 2×1082 \times 10^82×108 ms−1ms^{-1}ms−1. The focal length of the lens is _____.
  1. (A)0.30 cm
  2. (B)15 cm
  3. (C)1.5 cm
  4. (D)30 cm

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
The output of the given combination gates represents :
  1. (A)XOR Gate
  2. (B)NAND Gate
  3. (C)AND Gate
  4. (D)NOR Gate

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
A boy is rolling a 0.5 kg ball on the frictionless floor with the speed of 20 ms−1ms^{-1}ms−1. The ball gets deflected by an obstacle on the way. After deflection it moves with 5% of its initial kinetic energy. What is the speed of the ball now ?
  1. (A)19.0 ms−1ms^{-1}ms−1
  2. (B)4.47 ms−1ms^{-1}ms−1
  3. (C)14.41 ms−1ms^{-1}ms−1
  4. (D)1.00 ms−1ms^{-1}ms−1

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
Which level of the single ionized carbon has the same energy as the ground state energy of hydrogen atom?
  1. (A)1
  2. (B)6
  3. (C)4
  4. (D)8

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
Two ideal polyatomic gases at temperatures T1T_1T1​ and T2T_2T2​ are mixed so that there is no loss of energy. If F1F_1F1​ and F2F_2F2​, m1m_1m1​ and m2m_2m2​, n1n_1n1​ and n2n_2n2​ be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is :
  1. (A)n1T1+n2T2n1+n2\frac{n_1 T_1 + n_2 T_2}{n_1 + n_2}n1​+n2​n1​T1​+n2​T2​​
  2. (B)n1F1T1+n2F2T2n1F1+n2F2\frac{n_1 F_1 T_1 + n_2 F_2 T_2}{n_1 F_1 + n_2 F_2}n1​F1​+n2​F2​n1​F1​T1​+n2​F2​T2​​
  3. (C)n1F1T1+n2F2T2F1+F2\frac{n_1 F_1 T_1 + n_2 F_2 T_2}{F_1 + F_2}F1​+F2​n1​F1​T1​+n2​F2​T2​​
  4. (D)n1F1T1+n2F2T2n1+n2\frac{n_1 F_1 T_1 + n_2 F_2 T_2}{n_1 + n_2}n1​+n2​n1​F1​T1​+n2​F2​T2​​

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
A current of 10A exists in a wire of crosssectional area of 5 mm2mm^2mm2 with a drift velocity of 2×10−32 \times 10^{-3}2×10−3 ms−1ms^{-1}ms−1. The number of free electrons in each cubic meter of the wire is ___.
  1. (A)2×1062 \times 10^62×106
  2. (B)625×1025625 \times 10^{25}625×1025
  3. (C)2×10252 \times 10^{25}2×1025
  4. (D)1×10231 \times 10^{23}1×1023

Correct answer: (B)

Step-by-step solution →
Q21·PhysicsNumerical
For VHF signal broadcasting, ____ km2^22 of maximum service area will be covered by an antenna tower of height 30m, if the receiving antenna is placed at ground. Let radius of the earth be 6400 km. (Round off to the Nearest Integer) (Take π\piπ as 3.14)

Correct answer: 1206

Step-by-step solution →
Q22·PhysicsNumerical
The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is _______. (Assuming the acceleration to be uniform).

Correct answer: 728

Step-by-step solution →
Q23·PhysicsNumerical
The equivalent resistance of series combination of two resistors is 's'. When they are connected in parallel, the equivalent resistance is 'p'. If s = np, then the minimum value for n is ___. (Round off to the Nearest Integer)

Correct answer: 4

Step-by-step solution →
Q24·PhysicsNumerical
Four identical rectangular plates with length, lll = 2 cm and breadth, b = 32\frac{3}{2}23​ cm are arranged as shown in figure. The equivalent capacitance between A and C is x ε0d\frac{\mathrm{x}\,\varepsilon_0}{\mathrm{d}}dxε0​​. The value of x is ___. (Round off to the Nearest Integer)

Correct answer: 2

Step-by-step solution →
Q25·PhysicsNumerical
The radius in kilometer to which the present radius of earth (R = 6400 km) to be compressed so that the escape velocity is increased 10 time is ________.

Correct answer: 64

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Q26·PhysicsNumerical
Consider two identical springs each of spring constant k and negligible mass compared to the mass M as shown. Fig.1 shows one of them and Fig.2 shows their series combination. The ratios of time period of oscillation of the two SHM is TbTa=x\frac{\mathrm{T}_b}{\mathrm{T}_a} = \sqrt{\mathrm{x}}Ta​Tb​​=x​, where value of x is _______. (Round off to the Nearest Integer)

Correct answer: 2

Step-by-step solution →
Q27·PhysicsNumerical
The following bodies, (1) a ring (2) a disc (3) a solid cylinder (4) a solid sphere, of same mass 'm' and radius 'R' are allowed to roll down without slipping simultaneously from the top of the inclined plane. The body which will reach first at the bottom of the inclined plane is ______. [Mark the body as per their respective numbering given in the question]

Correct answer: 4

Step-by-step solution →
Q28·PhysicsNumerical
A parallel plate capacitor whose capacitance C is 14 pF is charged by a battery to a potential difference V = 12V between its plates. The charging battery is now disconnected and a porcelin plate with k = 7 is inserted between the plates, then the plate would oscillate back and forth between the plates with a constant mechanical energy of ______ pJ. (Assume no friction)

Correct answer: 864

Step-by-step solution →
Q29·PhysicsNumerical
Two blocks (m = 0.5 kg and M = 4.5 kg) are arranged on a horizontal frictionless table as shown in figure. The coefficient of static friction between the two blocks is 37\frac{3}{7}73​. Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is ______ N. (Round off to the Nearest Integer) [Take g as 9.8 ms−2^{-2}−2]

Correct answer: 21

Step-by-step solution →
Q30·PhysicsNumerical
If 2.5×10−62.5 \times 10^{-6}2.5×10−6 N average force is exerted by a light wave on a non-reflecting surface of 30 cm2^22 area during 40 minutes of time span, the energy flux of light just before it falls on the surface is ____ W/cm2^22. (Round off to the Nearest Integer) (Assume complete absorption and normal incidence conditions are there)

Correct answer: 25

Step-by-step solution →

Chemistry — JEE Main 17 March 2021 Shift 1

Q31·ChemistrySingle correct
With respect to drug-enzyme interaction, identify the wrong statement:
  1. (A)Non-Competitive inhibitor binds to the allosteric site
  2. (B)Allosteric inhibitor changes the enzyme's active site
  3. (C)Allosteric inhibitor competes with the enzyme's active site
  4. (D)Competitive inhibitor binds to the enzyme's active site

Correct answer: (C)

Step-by-step solution →
Q32·Chemistry·AromaticitySingle correct
Which of the following is an aromatic compound?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
The product "A" in the above reaction is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q34·ChemistrySingle correct
A central atom in a molecule has two lone pairs of electrons and forms three single bonds. The shape of this molecule is:
  1. (A)see-saw
  2. (B)planar triangular
  3. (C)T-shaped
  4. (D)trigonal pyramidal

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are two statements: Statement I : Potassium permanganate on heating at 573 K forms potassium manganate. Statement II : Both potassium permanganate and potassium manganate are tetrahedral and paramagnetic in nature. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is true but statement II is false
  2. (B)Both statement I and statement II are true
  3. (C)Statement I is false but statement II is true
  4. (D)Both statement I and statement II are false

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Which of the following is correct structure of tyrosine?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
The above reaction requires which of the following reaction conditions?
  1. (A)573 K, Cu, 300 atm
  2. (B)623 K, Cu, 300 atm
  3. (C)573 K, 300 atm
  4. (D)623 K, 300 atm

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
The absolute value of the electron gain enthalpy of halogens satisfies:
  1. (A)I>Br>Cl>F\mathrm{I > Br > Cl > F}I>Br>Cl>F
  2. (B)Cl>Br>F>I\mathrm{Cl > Br > F > I}Cl>Br>F>I
  3. (C)Cl>F>Br>I\mathrm{Cl > F > Br > I}Cl>F>Br>I
  4. (D)F>Cl>Br>I\mathrm{F > Cl > Br > I}F>Cl>Br>I

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
Which of the following compound CANNOT act as a Lewis base?
  1. (A)NF3\mathrm{NF_3}NF3​
  2. (B)PCl5\mathrm{PCl_5}PCl5​
  3. (C)SF4\mathrm{SF_4}SF4​
  4. (D)ClF3\mathrm{ClF_3}ClF3​

Correct answer: (B)

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Q40·ChemistrySingle correct
Reducing smog is a mixture of:
  1. (A)Smoke, fog and O3\mathrm{O_3}O3​
  2. (B)Smoke, fog and SO2\mathrm{SO_2}SO2​
  3. (C)Smoke, fog and CH2=CH−CHO\mathrm{CH_2{=}CH-CHO}CH2​=CH−CHO
  4. (D)Smoke, fog and N2O3\mathrm{N_2O_3}N2​O3​

Correct answer: (B)

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Q41·ChemistrySingle correct
Hoffmann bromomide degradation of benzamide gives product A, which upon heating with CHCl3\mathrm{CHCl_3}CHCl3​ and NaOH gives product B. The structures of A and B are :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

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Q42·ChemistrySingle correct
Mesityl oxide is a common name of :
  1. (A)2,4-Dimethyl pentan-3-one
  2. (B)3-Methyl cyclohexane carbaldehyde
  3. (C)2-Methyl cyclohexanone
  4. (D)4-Methyl pent-3-en-2-one

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
Which of the following reaction is an example of ammonolysis?
  1. (A)C6H5COCl+C6H5NH2⟶C6H5CONHC6H5\mathrm{C_6H_5COCl + C_6H_5NH_2 \longrightarrow C_6H_5CONHC_6H_5}C6​H5​COCl+C6​H5​NH2​⟶C6​H5​CONHC6​H5​
  2. (B)C6H5CH2CN→[H]C6H5CH2CH2NH2\mathrm{C_6H_5CH_2CN \xrightarrow{[H]} C_6H_5CH_2CH_2NH_2}C6​H5​CH2​CN[H]​C6​H5​CH2​CH2​NH2​
  3. (C)C6H5NH2→HClC6H5N+H3Cl−\mathrm{C_6H_5NH_2 \xrightarrow{HCl} C_6H_5\overset{+}{N}H_3Cl^-}C6​H5​NH2​HCl​C6​H5​N+H3​Cl−
  4. (D)C6H5CH2Cl+NH3⟶C6H5CH2NH2\mathrm{C_6H_5CH_2Cl + NH_3 \longrightarrow C_6H_5CH_2NH_2}C6​H5​CH2​Cl+NH3​⟶C6​H5​CH2​NH2​

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
A colloidal system consisting of a gas dispersed in a solid is called a/an :
  1. (A)solid sol
  2. (B)gel
  3. (C)aerosol
  4. (D)foam

Correct answer: (A)

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Q45·ChemistrySingle correct
The INCORRECT statement(s) about heavy water is (are) (A) used as a moderator in nuclear reactor (B) obtained as a by-product in fertilizer industry. (C) used for the study of reaction mechanism (D) has a higher dielectric constant than water Choose the correct answer from the options given below :
  1. (A)(B) only
  2. (B)(C) only
  3. (C)(D) only
  4. (D)(B) and (D) only

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
The correct order of conductivity of ions in water is :
  1. (A)Na+>K+>Rb+>Cs+\mathrm{Na^+ > K^+ > Rb^+ > Cs^+}Na+>K+>Rb+>Cs+
  2. (B)Cs+>Rb+>K+>Na+\mathrm{Cs^+ > Rb^+ > K^+ > Na^+}Cs+>Rb+>K+>Na+
  3. (C)K+>Na+>Cs+>Rb+\mathrm{K^+ > Na^+ > Cs^+ > Rb^+}K+>Na+>Cs+>Rb+
  4. (D)Rb+>Na+>K+>Li+\mathrm{Rb^+ > Na^+ > K^+ > Li^+}Rb+>Na+>K+>Li+

Correct answer: (B)

Step-by-step solution →
Q47·ChemistrySingle correct
What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25, in it's aqueous solution?
  1. (A)5.92
  2. (B)5.0
  3. (C)zero
  4. (D)5.26

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
Given below are two statements : Statement-I : Retardation factor (Rf\mathrm{R_f}Rf​) can be measured in meter/centimeter. Statement-II : Rf\mathrm{R_f}Rf​ value of a compound remains constant in all solvents. Choose the most appropriate answer from the options given below:
  1. (A)Statement-I is true but statement-II is false
  2. (B)Both statement-I and statement-II are true
  3. (C)Both statement-I and statement-II are false
  4. (D)Statement-I is false but statement-II is true

Correct answer: (C)

Step-by-step solution →
Q49·ChemistryNumerical
The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction 1 mol of 'A' with excess of AgNO3\mathrm{AgNO_3}AgNO3​ in aqueous medium gives ________ mol(s) of Ag. (Round off to the Nearest Integer).

Correct answer: 4

Step-by-step solution →
Q50·ChemistryNumerical
0.01 moles of a weak acid HA(Ka=2.0×10−6)\mathrm{HA}(\mathrm{K_a} = 2.0 \times 10^{-6})HA(Ka​=2.0×10−6) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is ________ ×10−5\times 10^{-5}×10−5 (Round off to the Nearest Integer). [Neglect volume change on adding HA. Assume degree of dissociation <<1]

Correct answer: 2

Step-by-step solution →
Q51·ChemistryNumerical
A certain orbital has n = 4 and mL=−3\mathrm{m_L} = -3mL​=−3. The number of radial nodes in this orbital is ________. (Round off to the Nearest Integer).

Correct answer: 0

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Q52·ChemistryNumerical
In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is ________ %. (Round off to the Nearest Integer). (Given atomic mass : C : 12.0 u, H : 1.0u, O : 16.0 u, N : 14.0 u)

Correct answer: 80

Step-by-step solution →
Q53·ChemistryNumerical
The mole fraction of a solute in a 100 molal aqueous solution ________ ×10−2\times 10^{-2}×10−2. (Round off to the Nearest Integer). [Given : Atomic masses : H : 1.0 u, O : 16.0 u]

Correct answer: 64

Step-by-step solution →
Q54·ChemistryNumerical
For a certain first order reaction 32% of the reactant is left after 570 s. The rate constant of this reaction is ________ ×10−3 s−1\times 10^{-3}\ \mathrm{s^{-1}}×10−3 s−1. (Round off to the Nearest Integer). [Given : log⁡102=0.301\log_{10} 2 = 0.301log10​2=0.301, ln⁡10=2.303\ln 10 = 2.303ln10=2.303]

Correct answer: 2

Step-by-step solution →
Q55·ChemistryNumerical
The standard enthalpies of formation of Al2O3\mathrm{Al_2O_3}Al2​O3​ and CaO are −1675-1675−1675 kJ mol−1\mathrm{mol^{-1}}mol−1 and −635-635−635 kJ mol−1\mathrm{mol^{-1}}mol−1 respectively. For the reaction 3CaO+2Al→3Ca+Al2O3\mathrm{3CaO + 2Al \rightarrow 3Ca + Al_2O_3}3CaO+2Al→3Ca+Al2​O3​ the standard reaction enthalpy ΔrH0=\Delta_\mathrm{r} H^0 =Δr​H0= ________ kJ. (Round off to the Nearest Integer).

Correct answer: 230

Step-by-step solution →
Q56·ChemistryNumerical
15 mL of aqueous solution of Fe2+\mathrm{Fe^{2+}}Fe2+ in acidic medium completely reacted with 20 mL of 0.03 M aqueous Cr2O72−\mathrm{Cr_2O_7^{2-}}Cr2​O72−​. The molarity of the Fe2+\mathrm{Fe^{2+}}Fe2+ solution is ________ ×10−2\times 10^{-2}×10−2 M (Round off to the Nearest Integer).

Correct answer: 24

Step-by-step solution →
Q57·ChemistryNumerical
The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is ________ ×10−5\times 10^{-5}×10−5 mol dm−3\mathrm{dm^{-3}}dm−3. (Round off to the Nearest Integer). [Given : Henry's law constant =KH=8.0×104= \mathrm{K_H} = 8.0 \times 10^{4}=KH​=8.0×104 kPa for O2\mathrm{O_2}O2​. Density of water with dissolved oxygen =1.0= 1.0=1.0 kg dm−3\mathrm{dm^{-3}}dm−3]

Correct answer: 1389

Step-by-step solution →
Q58·ChemistryNumerical
The pressure exerted by a non-reactive gaseous mixture of 6.4 g of methane and 8.8 g of carbon dioxide in a 10 L vessel at 27∘27^\circ27∘C is ________ kPa. (Round off to the Nearest Integer). [Assume gases are ideal, R = 8.314 J mol−1 K−1\mathrm{mol^{-1}\ K^{-1}}mol−1 K−1 Atomic masses : C : 12.0 u, H : 1.0 u, O : 16.0 u]

Correct answer: 150

Step-by-step solution →

Mathematics — JEE Main 17 March 2021 Shift 1

Q59·MathematicsSingle correct
Let a⃗=2i^−3j^+4k^\vec{a} = 2\hat{i} - 3\hat{j} + 4\hat{k}a=2i^−3j^​+4k^ and b⃗=7i^+j^−6k^\vec{b} = 7\hat{i} + \hat{j} - 6\hat{k}b=7i^+j^​−6k^. If r⃗×a⃗=r⃗×b⃗,r⃗⋅(i^+2j^+k^)=−3\vec{r} \times \vec{a} = \vec{r} \times \vec{b}, \vec{r} \cdot \left(\hat{i} + 2\hat{j} + \hat{k}\right) = -3r×a=r×b,r⋅(i^+2j^​+k^)=−3, then r⃗⋅(2i^−3j^+k^)\vec{r} \cdot \left(2\hat{i} - 3\hat{j} + \hat{k}\right)r⋅(2i^−3j^​+k^) is equal to :
  1. (A)12
  2. (B)8
  3. (C)13
  4. (D)10

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
The system of equations kx+y+z=1kx + y + z = 1kx+y+z=1, x+ky+z=kx + ky + z = kx+ky+z=k and x+y+zk=k2x + y + zk = k^2x+y+zk=k2 has no solution if k is equal to :
  1. (A)0
  2. (B)1
  3. (C)−1-1−1
  4. (D)−2-2−2

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
If cot⁡−1(α)=cot⁡−12+cot⁡−18+cot⁡−118+cot⁡−132+.....\cot^{-1}(\alpha) = \cot^{-1} 2 + \cot^{-1} 8 + \cot^{-1} 18 + \cot^{-1} 32 + .....cot−1(α)=cot−12+cot−18+cot−118+cot−132+..... upto 100 terms, then α\alphaα is :
  1. (A)1.01
  2. (B)1.00
  3. (C)1.02
  4. (D)1.03

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
The equation of the plane which contains the y-axis and passes through the point (1,2,3)(1, 2, 3)(1,2,3) is :
  1. (A)x+3z=10x + 3z = 10x+3z=10
  2. (B)x+3z=0x + 3z = 0x+3z=0
  3. (C)3x+z=63x + z = 63x+z=6
  4. (D)3x−z=03x - z = 03x−z=0

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
If A=(0sin⁡αsin⁡α0)A = \begin{pmatrix} 0 & \sin\alpha \\ \sin\alpha & 0 \end{pmatrix}A=(0sinα​sinα0​) and det⁡(A2−12I)=0\det\left(A^2 - \frac{1}{2}I\right) = 0det(A2−21​I)=0, then a possible value of α\alphaα is
  1. (A)π2\frac{\pi}{2}2π​
  2. (B)π3\frac{\pi}{3}3π​
  3. (C)π4\frac{\pi}{4}4π​
  4. (D)π6\frac{\pi}{6}6π​

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
If the Boolean expression (p⇒q)⇔(q∗(∼p))(p \Rightarrow q) \Leftrightarrow (q * (\sim p))(p⇒q)⇔(q∗(∼p)) is a tautology, then the Boolean expression p∗(∼q)p * (\sim q)p∗(∼q) is equivalent to :
  1. (A)q⇒pq \Rightarrow pq⇒p
  2. (B)∼q⇒p\sim q \Rightarrow p∼q⇒p
  3. (C)p⇒∼qp \Rightarrow \sim qp⇒∼q
  4. (D)p⇒qp \Rightarrow qp⇒q

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is :
  1. (A)49\frac{4}{9}94​
  2. (B)1736\frac{17}{36}3617​
  3. (C)512\frac{5}{12}125​
  4. (D)12\frac{1}{2}21​

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
If the fourth term in the expansion of (x+xlog⁡2x)7\left(x + x^{\log_2 x}\right)^7(x+xlog2​x)7 is 4480, then the value of x where x∈Nx \in Nx∈N is equal to :
  1. (A)2
  2. (B)4
  3. (C)3
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
In a school, there are three types of games to be played. Some of the students play two types of games, but none play all the three games. Which Venn diagrams can justify the above statement?
  1. (A)P and Q
  2. (B)P and R
  3. (C)None of these
  4. (D)Q and R

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
The sum of possible values of x for tan⁡−1(x+1)+cot⁡−1(1x−1)=tan⁡−1(831)\tan^{-1}(x + 1) + \cot^{-1}\left(\frac{1}{x - 1}\right) = \tan^{-1}\left(\frac{8}{31}\right)tan−1(x+1)+cot−1(x−11​)=tan−1(318​) is :
  1. (A)−324-\frac{32}{4}−432​
  2. (B)−314-\frac{31}{4}−431​
  3. (C)−304-\frac{30}{4}−430​
  4. (D)−334-\frac{33}{4}−433​

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
The area of the triangle with vertices A(z)A(z)A(z), B(iz)B(iz)B(iz) and C(z+iz)C(z + iz)C(z+iz) is :
  1. (A)1
  2. (B)12∣z∣2\frac{1}{2}|z|^221​∣z∣2
  3. (C)12\frac{1}{2}21​
  4. (D)12∣z+iz∣2\frac{1}{2}|z + iz|^221​∣z+iz∣2

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
The line 2x−y+1=02x - y + 1 = 02x−y+1=0 is a tangent to the circle at the point (2,5)(2, 5)(2,5) and the centre of the circle lies on x−2y=4x - 2y = 4x−2y=4. Then, the radius of the circle is:
  1. (A)353\sqrt{5}35​
  2. (B)535\sqrt{3}53​
  3. (C)545\sqrt{4}54​
  4. (D)454\sqrt{5}45​

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Team 'A' consists of 7 boys and n girls and Team 'B' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to :
  1. (A)5
  2. (B)2
  3. (C)4
  4. (D)6

Correct answer: (C)

Step-by-step solution →
Q72·MathematicsSingle correct
The value of 4+15+14+15+14+.......∞4 + \cfrac{1}{5 + \cfrac{1}{4 + \cfrac{1}{5 + \cfrac{1}{4 + .......\infty}}}}4+5+4+5+4+.......∞1​1​1​1​ is :
  1. (A)2+25302 + \frac{2}{5}\sqrt{30}2+52​30​
  2. (B)2+45302 + \frac{4}{\sqrt{5}}\sqrt{30}2+5​4​30​
  3. (C)4+45304 + \frac{4}{\sqrt{5}}\sqrt{30}4+5​4​30​
  4. (D)5+25305 + \frac{2}{5}\sqrt{30}5+52​30​

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
Choose the incorrect statement about the two circles whose equations are given below : x2+y2−10x−10y+41=0x^2 + y^2 - 10x - 10y + 41 = 0x2+y2−10x−10y+41=0 and x2+y2−16x−10y+80=0x^2 + y^2 - 16x - 10y + 80 = 0x2+y2−16x−10y+80=0
  1. (A)Distance between two centres is the average of radii of both the circles.
  2. (B)Both circles' centres lie inside region of one another.
  3. (C)Both circles pass through the centre of each other.
  4. (D)Circles have two intersection points.

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
Which of the following is true for y(x)y(x)y(x) that satisfies the differential equation dydx=xy−1+x−y\frac{dy}{dx} = xy - 1 + x - ydxdy​=xy−1+x−y ; y(0)=0y(0) = 0y(0)=0 :
  1. (A)y(1)=e−12−1y(1) = e^{-\frac{1}{2}} - 1y(1)=e−21​−1
  2. (B)y(1)=e12−e−12y(1) = e^{\frac{1}{2}} - e^{-\frac{1}{2}}y(1)=e21​−e−21​
  3. (C)y(1)=1y(1) = 1y(1)=1
  4. (D)y(1)=e12−1y(1) = e^{\frac{1}{2}} - 1y(1)=e21​−1

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
The value of lim⁡x→0+cos⁡−1(x−[x]2)⋅sin⁡−1(x−[x]2)x−x3\lim_{x \to 0^{+}} \frac{\cos^{-1}\left(x - [x]^2\right) \cdot \sin^{-1}\left(x - [x]^2\right)}{x - x^3}limx→0+​x−x3cos−1(x−[x]2)⋅sin−1(x−[x]2)​, where [x][x][x] denotes the greatest integer ≤x\leq x≤x is :
  1. (A)π\piπ
  2. (B)0
  3. (C)π4\frac{\pi}{4}4π​
  4. (D)π2\frac{\pi}{2}2π​

Correct answer: (D)

Step-by-step solution →
Q76·MathematicsNumerical
The maximum value of z in the following equation z=6xy+y2z = 6xy + y^2z=6xy+y2, where 3x+4y≤1003x + 4y \leq 1003x+4y≤100 and 4x+3y≤754x + 3y \leq 754x+3y≤75 for x≥0x \geq 0x≥0 and y≥0y \geq 0y≥0 is _______ .

Correct answer: 904

Step-by-step solution →
Q77·MathematicsNumerical
If the function f(x)=cos⁡(sin⁡x)−cos⁡xx4f(x) = \frac{\cos(\sin x) - \cos x}{x^4}f(x)=x4cos(sinx)−cosx​ is continuous at each point in its domain and f(0)=1kf(0) = \frac{1}{k}f(0)=k1​, then k is _________ .

Correct answer: 6

Step-by-step solution →
Q78·Mathematics·DifferentiabilityNumerical
If f(x)=sin⁡(cos⁡−1(1−22x1+22x))f(x) = \sin\left(\cos^{-1}\left(\frac{1 - 2^{2x}}{1 + 2^{2x}}\right)\right)f(x)=sin(cos−1(1+22x1−22x​)) and its first derivative with respect to x is −balog⁡e2-\frac{b}{a}\log_e 2−ab​loge​2 when x=1x = 1x=1, where a and b are integers, then the minimum value of ∣a2−b2∣|a^2 - b^2|∣a2−b2∣ is _______ .

Correct answer: 481

Step-by-step solution →
Q79·MathematicsNumerical
Let there be three independent events E1E_1E1​, E2E_2E2​ and E3E_3E3​. The probability that only E1E_1E1​ occurs is α\alphaα, only E2E_2E2​ occurs is β\betaβ and only E3E_3E3​ occurs is γ\gammaγ. Let 'p' denote the probability of none of events occurs that satisfies the equations (α−2β)p=αβ(\alpha - 2\beta)p = \alpha\beta(α−2β)p=αβ and (β−3γ)p=2βγ(\beta - 3\gamma)p = 2\beta\gamma(β−3γ)p=2βγ. All the given probabilities are assumed to lie in the interval (0, 1). Then, Probability of occurrence of E1Probability of occurrence of E3\frac{\text{Probability of occurrence of } E_1}{\text{Probability of occurrence of } E_3}Probability of occurrence of E3​Probability of occurrence of E1​​ is equal to _____.

Correct answer: 6

Step-by-step solution →
Q80·MathematicsNumerical
If a⃗=αi^+βj^+3k^\vec{a} = \alpha\hat{i} + \beta\hat{j} + 3\hat{k}a=αi^+βj^​+3k^, b⃗=−βi^−αj^−k^\vec{b} = -\beta\hat{i} - \alpha\hat{j} - \hat{k}b=−βi^−αj^​−k^ and c⃗=i^−2j^−k^\vec{c} = \hat{i} - 2\hat{j} - \hat{k}c=i^−2j^​−k^ such that a⃗⋅b⃗=1\vec{a} \cdot \vec{b} = 1a⋅b=1 and b⃗⋅c⃗=−3\vec{b} \cdot \vec{c} = -3b⋅c=−3, then 13((a⃗×b⃗)⋅c⃗)\frac{1}{3}\left(\left(\vec{a} \times \vec{b}\right) \cdot \vec{c}\right)31​((a×b)⋅c) is equal to _______.

Correct answer: 2

Step-by-step solution →
Q81·MathematicsNumerical
If A=[230−1]A = \begin{bmatrix} 2 & 3 \\ 0 & -1 \end{bmatrix}A=[20​3−1​], then the value of det⁡(A4)+det⁡(A10−(Adj(2A))10)\det(A^4) + \det\left(A^{10} - (\text{Adj}(2A))^{10}\right)det(A4)+det(A10−(Adj(2A))10) is _________ .

Correct answer: 16

Step-by-step solution →
Q82·MathematicsNumerical
If [⋅][\cdot][⋅] represents the greatest integer function, then the value of ∣∫0π2[[x2]−cos⁡x]dx∣\left| \int_{0}^{\sqrt{\frac{\pi}{2}}} \left[ \left[x^2\right] - \cos x \right] dx \right|​∫02π​​​[[x2]−cosx]dx​ is _________ .

Correct answer: 1

Step-by-step solution →
Q83·MathematicsNumerical
The minimum distance between any two points P1P_1P1​ and P2P_2P2​ while considering point P1P_1P1​ on one circle and point P2P_2P2​ on the other circle for the given circles' equations x2+y2−10x−10y+41=0x^2 + y^2 - 10x - 10y + 41 = 0x2+y2−10x−10y+41=0 x2+y2−24x−10y+160=0x^2 + y^2 - 24x - 10y + 160 = 0x2+y2−24x−10y+160=0 is ______ .

Correct answer: 1

Step-by-step solution →
Q84·MathematicsNumerical
If the equation of the plane passing through the line of intersection of the planes 2x−7y+4z−3=02x - 7y + 4z - 3 = 02x−7y+4z−3=0, 3x−5y+4z+11=03x - 5y + 4z + 11 = 03x−5y+4z+11=0 and the point (−2,1,3)(-2, 1, 3)(−2,1,3) is ax+by+cz−7=0ax + by + cz - 7 = 0ax+by+cz−7=0, then the value of 2a+b+c−72a + b + c - 72a+b+c−7 is ______ .

Correct answer: 4

Step-by-step solution →
Q85·MathematicsNumerical
If (2021)3762(2021)^{3762}(2021)3762 is divided by 17, then the remainder is _______ .

Correct answer: 4

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Experimental Skills 68/186
  • Chemistry in Everyday Life 60/186
  • States of Matter: Gases and Liquids 52/186
  • Aromaticity 22/186
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