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JEE Main 16 March 2021 Shift 2 Question Paper with Answers

16 March 2021 · March session · 89 questions

89 of the 90 questions from the JEE Main 16 March 2021 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
30
Mathematics
30

Physics — JEE Main 16 March 2021 Shift 2

Q1·PhysicsSingle correct
The following logic gate is equivalent to :
  1. (A)NOR Gate
  2. (B)OR Gate
  3. (C)AND Gate
  4. (D)NAND Gate

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
A large block of wood of mass M = 5.99 kg is hanging from two long massless cords. A bullet of mass m = 10g is fired into the block and gets embedded in it. The (block + bullet) then swing upwards, their centre of mass rising a vertical distance h = 9.8 cm before the (block + bullet) pendulum comes momentarily to rest at the end of its arc. The speed of the bullet just before collision is : (Take g = 9.8 ms−2^{-2}−2)
  1. (A)841.4 m/s
  2. (B)811.4 m/s
  3. (C)831.4 m/s
  4. (D)821.4 m/s

Correct answer: (C)

Step-by-step solution →
Q3·Physics·Magnetic Field of CurrentSingle correct
A charge Q is moving dI→\overrightarrow{dI}dI distance in the magnetic field B⃗\vec{B}B. Find the value of work done by B⃗\vec{B}B.
  1. (A)1
  2. (B)Infinite
  3. (C)Zero
  4. (D)−1

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
What will be the nature of flow of water from a circular tap, when its flow rate increased from 0.18 L/min to 0.48 L/min ? The radius of the tap and viscosity of water are 0.5 cm and 10−3^{-3}−3 Pa s, respectively. (Density of water : 103^{3}3 kg/m3^{3}3)
  1. (A)Unsteady to steady flow
  2. (B)Remains steady flow
  3. (C)Remains turbulent flow
  4. (D)Steady flow to unsteady flow

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
Find out the surface charge density at the intersection of point x = 3 m plane and x-axis, in the region of uniform line charge of 8 nC/ m lying along the z-axis in free space.
  1. (A)0.424 nC m−2^{-2}−2
  2. (B)47.88 C/m
  3. (C)0.07 nC m−2^{-2}−2
  4. (D)4.0 nC m−2^{-2}−2

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100 V. What should nearly be the ratio of their wavelengths ? (mP_{P}P​ = 1.00727 u, me_{e}e​ = 0.00055u)
  1. (A)1860 : 1
  2. (B)(1860)2^{2}2 : 1
  3. (C)41.4 : 1
  4. (D)43 : 1

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
For the given circuit, comment on the type of transformer used :
  1. (A)Auxilliary transformer
  2. (B)Auto transformer
  3. (C)Step-up transformer
  4. (D)Step down transformer

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
The half-life of Au198^{198}198 is 2.7 days. The activity of 1.50 mg of Au198^{198}198 if its atomic weight is 198 g mol−1^{-1}−1 is, (NA_{A}A​ = 6 × 1023^{23}23/mol)
  1. (A)240 Ci
  2. (B)357 Ci
  3. (C)535 Ci
  4. (D)252 Ci

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
Calculate the value of mean free path (λ) for oxygen molecules at temperature 27°C and pressure 1.01 × 105^{5}5 Pa. Assume the molecular diameter 0.3 nm and the gas is ideal. (k = 1.38 × 10−23^{-23}−23 JK−1^{-1}−1)
  1. (A)58 nm
  2. (B)32 nm
  3. (C)86 nm
  4. (D)102 nm

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
The refractive index of a converging lens is 1.4. What will be the focal length of this lens if it is placed in a medium of same refractive index ? (Assume the radii of curvature of the faces of lens are R1_{1}1​ and R2_{2}2​ respectively)
  1. (A)1
  2. (B)Infinite
  3. (C)R1R2R1−R2\frac{R_{1}R_{2}}{R_{1}-R_{2}}R1​−R2​R1​R2​​
  4. (D)Zero

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
In order to determine the Young's Modulus of a wire of radius 0.2 cm (measured using a scale of least count = 0.001 cm) and length 1m (measured using a scale of least count = 1 mm), a weight of mass 1kg (measured using a scale of least count = 1g) was hanged to get the elongation of 0.5 cm (measured using a scale of least count 0.001 cm). What will be the fractional error in the value of Young's Modulus determined by this experiment ?
  1. (A)0.14%
  2. (B)0.9%
  3. (C)9%
  4. (D)1.4%

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
A bimetallic strip consists of metals A and B. It is mounted rigidly as shown. The metal A has higher coefficient of expansion compared to that of metal B. When the bimetallic strip is placed in a cold both, it will :
  1. (A)Bend towards the right
  2. (B)Not bend but shrink
  3. (C)Neither bend nor shrink
  4. (D)Bend towards the left

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
A resistor develops 500 J of thermal energy in 20s when a current of 1.5 A is passed through it. If the current is increased from 1.5 A to 3A, what will be the energy developed in 20 s.
  1. (A)1500 J
  2. (B)1000 J
  3. (C)500 J
  4. (D)2000 J

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
Statement I : A cyclist is moving on an unbanked road with a speed of 7 kmh−1^{-1}−1 and takes a sharp circular turn along a path of radius of 2m without reducing the speed. The static friction coefficient is 0.2. The cyclist will not slip and pass the curve (g = 9.8 m/s2^{2}2) Statement II : If the road is banked at an angle of 45°, cyclist can cross the curve of 2m radius with the speed of 18.5 kmh−1^{-1}−1 without slipping. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Statement I is incorrect and statement II is correct
  2. (B)Statement I is correct and statement II is incorrect
  3. (C)Both statement I and statement II are false
  4. (D)Both statement I and statement II are true

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
Two identical antennas mounted on identical towers are separated from each other by a distance of 45 km. What should nearly be the minimum height of receiving antenna to receive the signals in line of sight ? (Assume radius of earth is 6400 km)
  1. (A)19.77 m
  2. (B)39.55 m
  3. (C)79.1 m
  4. (D)158.2 m

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
The magnetic field in a region is given by B⃗=B0(xa)k^\vec{B} = B_{0}\left(\frac{x}{a}\right)\hat{k}B=B0​(ax​)k^. A square loop of side d is placed with its edges along the x and y axes. The loop is moved with a constant velocity v⃗=v0i^\vec{v} = v_{0}\hat{i}v=v0​i^. The emf induced in the loop is :
  1. (A)B0v02d2a\frac{B_{0}v_{0}^{2}d}{2a}2aB0​v02​d​
  2. (B)B0v0d2a\frac{B_{0}v_{0}d}{2a}2aB0​v0​d​
  3. (C)B0v0d2a\frac{B_{0}v_{0}d^{2}}{a}aB0​v0​d2​
  4. (D)B0v0d22a\frac{B_{0}v_{0}d^{2}}{2a}2aB0​v0​d2​

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass = 500g, Decay constant = 20 g/s then how much time is required for the amplitude of the system to drop to half of its initial value ? (ln 2 = 0.693)
  1. (A)34.65 s
  2. (B)17.32 s
  3. (C)0.034 s
  4. (D)15.01 s

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
Calculate the time interval between 33% decay and 67% decay if half-life of a substance is 20 minutes.
  1. (A)60 minutes
  2. (B)20 minutes
  3. (C)40 minutes
  4. (D)13 minutes

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
Red light differs from blue light as they have :
  1. (A)Different frequencies and different wavelengths
  2. (B)Different frequencies and same wavelengths
  3. (C)Same frequencies and same wavelengths
  4. (D)Same frequencies and different wavelengths

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsNumerical
The energy dissipated by a resistor is 10 mJ in 1s when an electric current of 2 mA flows through it. The resistance is _______ Ω. (Round off to the Nearest Integer)

Correct answer: 2500

Step-by-step solution →
Q21·PhysicsNumerical
In a parallel plate capacitor set up, the plate area of capacitor is 2 m2^{2}2 and the plates are separated by 1m. If the space between the plates are filled with a dielectric material of thickness 0.5 m and area 2m2^{2}2 (see fig.) the capacitance of the set-up will be _______ ε0_{0}0​. (Dielectric constant of the material = 3.2) (Round off to the Nearest Integer)

Correct answer: 3

Step-by-step solution →
Q22·PhysicsNumerical
A force F⃗=4i^+3j^+4k^\vec{F} = 4\hat{i} + 3\hat{j} + 4\hat{k}F=4i^+3j^​+4k^ is applied on an intersection point of x = 2 plane and x-axis. The magnitude of torque of this force about a point (2, 3, 4) is ________. (Round off to the Nearest Integer)

Correct answer: 20

Step-by-step solution →
Q23·PhysicsNumerical
If one wants to remove all the mass of the earth to infinity in order to break it up completely. The amount of energy that needs to be supplied will be x5GM2R\frac{x}{5}\frac{GM^{2}}{R}5x​RGM2​ where x is ____ (Round off to the Nearest Integer) (M is the mass of earth, R is the radius of earth, G is the gravitational constant)

Correct answer: 3

Step-by-step solution →
Q24·PhysicsNumerical
A deviation of 2° is produced in the yellow ray when prism of crown and flint glass are achromatically combined. Taking dispersive powers of crown and flint glass are 0.02 and 0.03 respectively and refractive index for yellow light for these glasses are 1.5 and 1.6 respectively. The refracting angles for crown glass prism will be ________° (in degree) (Round off to the Nearest Integer)

Correct answer: 12

Step-by-step solution →
Q25·PhysicsNumerical
A body of mass 2kg moves under a force of (2i^+3j^+5k^)(2\hat{i} + 3\hat{j} + 5\hat{k})(2i^+3j^​+5k^) N. It starts from rest and was at the origin initially. After 4s, its new coordinates are (8, b, 20). The value of b is __________. (Round off to the Nearest Integer)

Correct answer: 12

Step-by-step solution →
Q26·PhysicsNumerical
A swimmer can swim with velocity of 12 km/h in still water. Water flowing in a river has velocity 6 km/h. The direction with respect to the direction of flow of river water he should swim in order to reach the point on the other bank just opposite to his starting point is _________°. (Round off to the Nearest Integer) (find the angle in degree)

Correct answer: 120

Step-by-step solution →
Q27·PhysicsNumerical
A closed organ pipe of length L and an open organ pipe contain gases of densities ρ1_{1}1​ and ρ2_{2}2​ respectively. The compressibility of gases are equal in both the pipes. Both the pipes are vibrating in their first overtone with same frequency. The length of the open pipe is x3Lρ1ρ2\frac{x}{3}L\sqrt{\frac{\rho_{1}}{\rho_{2}}}3x​Lρ2​ρ1​​​ where x is ________. (Round off to the Nearest Integer)

Correct answer: 4

Step-by-step solution →
Q28·PhysicsNumerical
A solid disc of radius 'a' and mass 'm' rolls down without slipping on an inclined plane making an angle θ with the horizontal. The acceleration of the disc will be 2bgsin⁡θ\frac{2}{b}g\sin\thetab2​gsinθ where b is ______. (Round off to the Nearest Integer) (g = acceleration due to gravity) (θ = angle as shown in figure)

Correct answer: 3

Step-by-step solution →
Q29·PhysicsNumerical
For an ideal heat engine, the temperature of the source is 127°C. In order to have 60% efficiency the temperature of the sink should be _______°C. (Round off to the Nearest Integer)

Correct answer: -113

Step-by-step solution →

Chemistry — JEE Main 16 March 2021 Shift 2

Q30·ChemistrySingle correct
The green house gas/es is (are) : (A) Carbon dioxide (B) Oxygen (C) Water vapour (D) Methane Choose the most appropriate answer from the options given below :
  1. (A)(A) and (C) only
  2. (B)(A) only
  3. (C)(A), (C) and (D) only
  4. (D)(A) and (B) only

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
In the above reaction, the reagent "A" is :
  1. (A)NaBH4_{4}4​, H3_{3}3​O+^{+}+
  2. (B)LiAlH4_{4}4​
  3. (C)Alkaline KMnO4_{4}4​, H+^{+}+
  4. (D)HCl, Zn-Hg

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
Which of the following reduction reaction CANNOT be carried out with coke ?
  1. (A)Al2_{2}2​O3_{3}3​ → Al
  2. (B)ZnO → Zn
  3. (C)Fe2_{2}2​O3_{3}3​ → Fe
  4. (D)Cu2_{2}2​O → Cu

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
Identify the elements X and Y using the ionisation energy values given below : Ionization energy (kJ/mol) 1st^{st}st 2nd^{nd}nd X 495 4563 Y 731 1450
  1. (A)X = Na ; Y = Mg
  2. (B)X = Mg ; Y = F
  3. (C)X = Mg ; Y = Na
  4. (D)X = F ; Y = Mg

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
Identify the reagent(s) 'A' and condition(s) for the reaction :
  1. (A)A = HCl; Anhydrous AlCl3_{3}3​
  2. (B)A = HCl, ZnCl2_{2}2​
  3. (C)A = Cl2_{2}2​; UV light
  4. (D)A = Cl2_{2}2​; dark, Anhydrous AlCl3_{3}3​

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
The secondary structure of protein is stabilised by:
  1. (A)Peptide bond
  2. (B)glycosidic bond
  3. (C)Hydrogen bonding
  4. (D)van der Waals forces

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
Fex2_{2}2​ and Fey3_{3}3​ are known when x and y are :
  1. (A)x = F, Cl, Br, I and y = F, Cl, Br
  2. (B)x = F, Cl, Br and y = F, Cl, Br, I
  3. (C)x = Cl, Br, I and y = F, Cl, Br, I
  4. (D)x = F, Cl, Br, I and y = F, Cl, Br, I

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
Which of the following polymer is used in the manufacture of wood laminates ?
  1. (A)cis-poly isoprene
  2. (B)Melamine formaldehyde resin
  3. (C)Urea formaldehyde resin
  4. (D)Phenol and formaldehyde resin

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Statement I : Sodium hydride can be used as an oxidising agent. Statement II : The lone pair of electrons on nitrogen in pyridine makes it basic. Choose the CORRECT answer from the options given below :
  1. (A)Both statement I and statement II are false
  2. (B)Statement I is true but statement II is false
  3. (C)Statement I is false but statement II is true
  4. (D)Both statement I and statement II are true

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
The INCORRECT statement regarding the structure of C60_{60}60​ is :
  1. (A)The six-membered rings are fused to both six and five-membered rings.
  2. (B)Each carbon atom forms three sigma bonds.
  3. (C)The five-membered rings are fused only to six-membered rings.
  4. (D)It contains 12 six-membered rings and 24 five-membered rings.

Correct answer: (D)

Step-by-step solution →
Q40·ChemistrySingle correct
The correct statements about H2_{2}2​O2_{2}2​ are : (A) used in the treatment of effluents. (B) used as both oxidising and reducing agents. (C) the two hydroxyl groups lie in the same plane. (D) miscible with water. Choose the correct answer from the options given below :
  1. (A)(A), (B), (C) and (D)
  2. (B)(A), (B) and (D) only
  3. (C)(B), (C) and (D) only
  4. (D)(A), (C) and (D) only

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Ammonolysis of Alkyl halides followed by the treatment with NaOH solution can be used to prepare primary, secondary and tertiary amines. The purpose of NaOH in the reaction is :
  1. (A)to remove basic impurities
  2. (B)to activate NH3_{3}3​ used in the reaction
  3. (C)to remove acidic impurities
  4. (D)to increase the reactivity of alkyl halide

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
An unsaturated hydrocarbon X on ozonolysis gives A. Compound A when warmed with ammonical silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon X is :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
Which of the following is least basic ?
  1. (A)(CH3_{3}3​CO)N¨\ddot{\mathrm{N}}N¨HC2_{2}2​H5_{5}5​
  2. (B)(C2_{2}2​H5_{5}5​)3N¨_{3}\ddot{\mathrm{N}}3​N¨
  3. (C)(CH3_{3}3​CO)2N¨_{2}\ddot{\mathrm{N}}2​N¨H
  4. (D)(C2_{2}2​H5_{5}5​)2N¨_{2}\ddot{\mathrm{N}}2​N¨H

Correct answer: (C)

Step-by-step solution →
Q44·ChemistrySingle correct
The characteristics of elements X, Y and Z with atomic numbers, respectively, 33, 53 and 83 are :
  1. (A)X and Y are metalloids and Z is a metal.
  2. (B)X is a metalloid, Y is a non-metal and Z is a metal.
  3. (C)X, Y and Z are metals.
  4. (D)X and Z are non-metals and Y is a metalloid

Correct answer: (B)

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Q45·ChemistrySingle correct
Match List-I with List-II. The correct match is :
List-I (Test/Reagents/Observation(s))List-II (Species detected)
a.Lassaigne's Testi.Carbon
b.Cu(II) oxideii.Sulphur
c.Silver nitrateiii.N, S, P, and halogen
d.The sodium fusion extract gives black precipitate with acetic acid and lead acetateiv.Halogen Specifically
  1. (A)(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
  2. (B)(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
  3. (C)(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
  4. (D)(a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)

Correct answer: (C)

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Q46·ChemistrySingle correct
The INCORRECT statements below regarding colloidal solutions is :
  1. (A)A colloidal solution shows colligative properties.
  2. (B)An ordinary filter paper can stop the flow of colloidal particles.
  3. (C)The flocculating power of Al3+^{3+}3+ is more than that of Na+^{+}+.
  4. (D)A colloidal solution shows Brownian motion of colloidal particles.

Correct answer: (B)

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Q47·ChemistrySingle correct
Arrange the following metal complex/compounds in the increasing order of spin only magnetic moment. Presume all the three, high spin system. (Atomic numbers Ce = 58, Gd = 64 and Eu = 63.) (a) (NH4_{4}4​)2_{2}2​[Ce(NO3_{3}3​)6_{6}6​] (b) Gd(NO3_{3}3​)3_{3}3​ and (c) Eu(NO3_{3}3​)3_{3}3​ Answer is :
  1. (A)(b) < (a) < (c)
  2. (B)(c) < (a) < (b)
  3. (C)(a) < (b) < (c)
  4. (D)(a) < (c) < (b)

Correct answer: (D)

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Q48·ChemistrySingle correct
The exact volumes of 1 M NaOH solution required to neutralise 50 mL of 1 M H3_{3}3​PO3_{3}3​ solution and 100 mL of 2 M H3_{3}3​PO2_{2}2​ solution, respectively, are :
  1. (A)100 mL and 100 mL
  2. (B)100 mL and 50 mL
  3. (C)100 mL and 200 mL
  4. (D)50 mL and 50 mL

Correct answer: (C)

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Q49·ChemistrySingle correct
The structure of X is :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q50·ChemistryNumerical
Ga (atomic mass 70 u) crystallizes in a hexagonal close packed structure. The total number of voids in 0.581 g of Ga is _______ × 1021^{21}21. (Round off to the Nearest Integer).

Correct answer: 15

Step-by-step solution →
Q51·ChemistryNumerical
A 5.0 m mol dm−3^{-3}−3 aqueous solution of KCl has a conductance of 0.55 mS when measured in a cell constant 1.3 cm−1^{-1}−1. The molar conductivity of this solution is _______ mSm2^{2}2 mol−1^{-1}−1. (Round off to the Nearest Integer)

Correct answer: 14

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Q52·ChemistryNumerical
A and B decompose via first order kinetics with half-lives 54.0 min and 18.0 min respectively. Starting from an equimolar non reactive mixture of A and B, the time taken for the concentration of A to become 16 times that of B is ______ min. (Round off to the Nearest Integer).

Correct answer: 108

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Q53·ChemistryNumerical
In Duma's method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______. (Round off to the Nearest Integer). [Given : Aqueous tension at 287 K = 14 mm of Hg]

Correct answer: 19

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Q54·ChemistryNumerical
The number of orbitals with n = 5, m1_{1}1​ = + 2 is ______. (Round off to the Nearest Integer).

Correct answer: 3

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Q55·ChemistryNumerical
At 363 K, the vapour pressure of A is 21 kPa and that of B is 18 kPa. One mole of A and 2 moles of B are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is ________ kPa. (Round of to the Nearest Integer).

Correct answer: 19

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Q56·ChemistryNumerical
Sulphurous acid (H2_{2}2​SO3_{3}3​) has Ka1_{1}1​ = 1.7 × 10−2^{-2}−2 and Ka2_{2}2​ = 6.4 × 10−8^{-8}−8. The pH of 0.588 M H2_{2}2​SO3_{3}3​ is _________. (Round off to the Nearest Integer)

Correct answer: 1

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Q57·ChemistryNumerical
When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, ________ × 10−5^{-5}−5 moles of lead sulphate precipitate out. (Round off to the Nearest Integer).

Correct answer: 525

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Q58·ChemistryNumerical
At 25°C, 50 g of iron reacts with HCl to form FeCl2_{2}2​. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is _______ J. (Round off to the Nearest Integer) [Given : R = 8.314 J mol−1^{-1}−1 K−1^{-1}−1. Assume, hydrogen is an ideal gas] [Atomic mass off Fe is 55.85 u]

Correct answer: 2218

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Q59·ChemistryNumerical
[Ti(H2_{2}2​O)6_{6}6​]3+^{3+}3+ absorbs light of wavelength 498 nm during a d – d transition. The octahedral splitting energy for the above complex is _____ × 10−19^{-19}−19 J. (Round off to the Nearest Integer). h = 6.626 × 10−34^{-34}−34 Js; c = 3 × 108^{8}8 ms−1^{-1}−1.

Correct answer: 4

Step-by-step solution →

Mathematics — JEE Main 16 March 2021 Shift 2

Q60·MathematicsSingle correct
The maximum value of f(x)=∣sin⁡2x1+cos⁡2xcos⁡2x1+sin⁡2xcos⁡2xcos⁡2xsin⁡2xcos⁡2xsin⁡2x∣f(x)=\begin{vmatrix} \sin^{2}x & 1+\cos^{2}x & \cos 2x \\ 1+\sin^{2}x & \cos^{2}x & \cos 2x \\ \sin^{2}x & \cos^{2}x & \sin 2x \end{vmatrix}f(x)=​sin2x1+sin2xsin2x​1+cos2xcos2xcos2x​cos2xcos2xsin2x​​, x∈Rx \in Rx∈R is:
  1. (A)7\sqrt{7}7​
  2. (B)34\frac{3}{4}43​
  3. (C)5\sqrt{5}5​
  4. (D)555

Correct answer: (C)

Step-by-step solution →
Q61·MathematicsSingle correct
Let A denote the event that a 6-digit integer formed by 0, 1, 2, 3, 4, 5, 6 without repetitions, be divisible by 3. Then probability of event A is equal to :
  1. (A)956\frac{9}{56}569​
  2. (B)49\frac{4}{9}94​
  3. (C)37\frac{3}{7}73​
  4. (D)1127\frac{11}{27}2711​

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
Let α∈R\alpha \in Rα∈R be such that the function f(x)={cos⁡−1(1−{x}2)sin⁡−1(1−{x}){x}−{x}3,x≠0α,x=0f(x)=\begin{cases} \dfrac{\cos^{-1}(1-\{x\}^{2})\sin^{-1}(1-\{x\})}{\{x\}-\{x\}^{3}}, & x \neq 0 \\ \alpha, & x=0 \end{cases}f(x)=⎩⎨⎧​{x}−{x}3cos−1(1−{x}2)sin−1(1−{x})​,α,​x=0x=0​ is continuous at x=0x = 0x=0, where {x}=x−[x]\{x\} = x - [x]{x}=x−[x], [x][x][x] is the greatest integer less than or equal to x. Then :
  1. (A)α=π2\alpha = \frac{\pi}{\sqrt{2}}α=2​π​
  2. (B)α=0\alpha = 0α=0
  3. (C)no such α\alphaα exists
  4. (D)α=π4\alpha = \frac{\pi}{4}α=4π​

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
If (x, y, z) be an arbitrary point lying on a plane P which passes through the point (42, 0, 0), (0, 42, 0) and (0, 0, 42), then the value of expression 3+x−11(y−19)2(z−12)2+y−19(x−11)2(z−12)2+z−12(x−11)2(y−19)2−x+y+z14(x−11)(y−19)(z−12)3+\frac{x-11}{(y-19)^{2}(z-12)^{2}}+\frac{y-19}{(x-11)^{2}(z-12)^{2}}+\frac{z-12}{(x-11)^{2}(y-19)^{2}}-\frac{x+y+z}{14(x-11)(y-19)(z-12)}3+(y−19)2(z−12)2x−11​+(x−11)2(z−12)2y−19​+(x−11)2(y−19)2z−12​−14(x−11)(y−19)(z−12)x+y+z​
  1. (A)000
  2. (B)333
  3. (C)393939
  4. (D)−45-45−45

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Consider the integral I=∫010[x] e[x]ex−1dx,I=\int\limits_{0}^{10}\frac{[x]\,e^{[x]}}{e^{x-1}}dx,I=0∫10​ex−1[x]e[x]​dx, where [x] denotes the greatest integer less than or equal to x. Then the value of I is equal to:
  1. (A)9(e−1)9(e-1)9(e−1)
  2. (B)45(e+1)45(e+1)45(e+1)
  3. (C)45(e−1)45(e-1)45(e−1)
  4. (D)9(e+1)9(e+1)9(e+1)

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let C be the locus of the mirror image of a point on the parabola y2=4xy^{2}=4xy2=4x with respect to the line y=xy = xy=x. Then the equation of tangent to C at P(2,1) is :
  1. (A)x−y=1x-y=1x−y=1
  2. (B)2x+y=52x+y=52x+y=5
  3. (C)x+3y=5x+3y=5x+3y=5
  4. (D)x+2y=4x+2y=4x+2y=4

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
If y=y(x)y = y(x)y=y(x) is the solution of the differential equation dydx+(tan⁡x) y=sin⁡x, 0≤x≤π3\frac{dy}{dx}+(\tan x)\,y=\sin x,\ 0 \le x \le \frac{\pi}{3}dxdy​+(tanx)y=sinx, 0≤x≤3π​, with y(0)=0y(0) = 0y(0)=0, then y(π4)y\left(\frac{\pi}{4}\right)y(4π​) equal to :
  1. (A)14log⁡e2\frac{1}{4}\log_{e}241​loge​2
  2. (B)(122)log⁡e2\left(\frac{1}{2\sqrt{2}}\right)\log_{e}2(22​1​)loge​2
  3. (C)log⁡e2\log_{e}2loge​2
  4. (D)12log⁡e2\frac{1}{2}\log_{e}221​loge​2

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
Let A={2,3,4,5,....,30}A = \{2, 3, 4, 5, ...., 30\}A={2,3,4,5,....,30} and '≃\simeq≃' be an equivalence relation on A×AA \times AA×A, defined by (a,b)≃(c,d)(a, b) \simeq (c, d)(a,b)≃(c,d), if and only if ad=bcad = bcad=bc. Then the number of ordered pairs which satisfy this equivalence relation with ordered pair (4, 3) is equal to :
  1. (A)555
  2. (B)666
  3. (C)888
  4. (D)777

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
Let the lengths of intercepts on x-axis and y-axis made by the circle x2+y2+ax+2ay+c=0x^{2}+y^{2}+ax+2ay+c=0x2+y2+ax+2ay+c=0, (a<0)(a < 0)(a<0) be 222\sqrt{2}22​ and 252\sqrt{5}25​, respectively. Then the shortest distance from origin to a tangent to this circle which is perpendicular to the line x+2y=0x + 2y = 0x+2y=0, is euqal to :
  1. (A)11\sqrt{11}11​
  2. (B)7\sqrt{7}7​
  3. (C)6\sqrt{6}6​
  4. (D)10\sqrt{10}10​

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
The least value of ∣z∣|z|∣z∣ where z is complex number which satisfies the inequality exp⁡((∣z∣+3)(∣z∣−1)∣∣z∣+1∣log⁡e2)≥log⁡2∣57+9i∣,\exp\left(\frac{\left(|z|+3\right)\left(|z|-1\right)}{\left||z|+1\right|}\log_{e}2\right) \ge \log_{\sqrt{2}}\left|5\sqrt{7}+9i\right|,exp(∣∣z∣+1∣(∣z∣+3)(∣z∣−1)​loge​2)≥log2​​​57​+9i​, i=−1i=\sqrt{-1}i=−1​, is equal to :
  1. (A)333
  2. (B)5\sqrt{5}5​
  3. (C)222
  4. (D)888

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
Consider a rectangle ABCD having 5, 7, 6, 9 points in the interior of the line segments AB, CD, BC, DA respectively. Let α\alphaα be the number of triangles having these points from different sides as vertices and β\betaβ be the number of quadrilaterals having these points from different sides as vertices. Then (β−α)(\beta-\alpha)(β−α) is equal to :
  1. (A)795795795
  2. (B)117311731173
  3. (C)189018901890
  4. (D)717717717

Correct answer: (D)

Step-by-step solution →
Q71·MathematicsSingle correct
If the point of intersections of the ellipse x216+y2b2=1\frac{x^{2}}{16}+\frac{y^{2}}{b^{2}}=116x2​+b2y2​=1 and the circle x2+y2=4bx^{2}+y^{2}=4bx2+y2=4b, b>4b > 4b>4 lie on the curve y2=3x2y^{2}=3x^{2}y2=3x2, then b is equal to:
  1. (A)121212
  2. (B)555
  3. (C)666
  4. (D)101010

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
Given that the inverse trigonometric functions take principal values only. Then, the number of real values of x which satisfy sin⁡−1(3x5)+sin⁡−1(4x5)=sin⁡−1x\sin^{-1}\left(\frac{3x}{5}\right)+\sin^{-1}\left(\frac{4x}{5}\right)=\sin^{-1}xsin−1(53x​)+sin−1(54x​)=sin−1x is equal to:
  1. (A)222
  2. (B)111
  3. (C)333
  4. (D)000

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
Let A(-1, 1), B(3, 4) and C(2, 0) be given three points. A line y=mxy = mxy=mx, m>0m > 0m>0, intersects lines AC and BC at point P and Q respectively. Let A1A_{1}A1​ and A2A_{2}A2​ be the areas of ΔABC\Delta ABCΔABC and ΔPQC\Delta PQCΔPQC respectively, such that A1=3A2A_{1}=3A_{2}A1​=3A2​, then the value of m is equal to :
  1. (A)415\frac{4}{15}154​
  2. (B)111
  3. (C)222
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
Let f be a real valued function, defined on R−{−1,1}R - \{-1, 1\}R−{−1,1} and given by f(x)=3log⁡e∣x−1x+1∣−2x−1.f(x) = 3\log_{e}\left|\frac{x-1}{x+1}\right|-\frac{2}{x-1}.f(x)=3loge​​x+1x−1​​−x−12​. Then in which of the following intervals, function f(x) is increasing?
  1. (A)(−∞,−1)∪([12,∞)−{1})(-\infty,-1)\cup\left(\left[\frac{1}{2},\infty\right)-\{1\}\right)(−∞,−1)∪([21​,∞)−{1})
  2. (B)(−∞,∞)−{−1,1}(-\infty, \infty)-\{-1, 1\}(−∞,∞)−{−1,1}
  3. (C)(−1,12]\left(-1,\frac{1}{2}\right](−1,21​]
  4. (D)(−∞,12]−{−1}\left(-\infty,\frac{1}{2}\right]-\{-1\}(−∞,21​]−{−1}

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
Let f:S→Sf : S \rightarrow Sf:S→S where S=(0,∞)S = (0, \infty)S=(0,∞) be a twice differentiable function such that f(x+1)=xf(x)f(x + 1) = x f(x)f(x+1)=xf(x). If g:S→Rg : S \rightarrow Rg:S→R be defined as g(x)=log⁡ef(x)g(x)=\log_{e}f(x)g(x)=loge​f(x), then the value of ∣g′′(5)−g′′(1)∣\left|g''(5)-g''(1)\right|∣g′′(5)−g′′(1)∣ is equal to :
  1. (A)205144\frac{205}{144}144205​
  2. (B)197144\frac{197}{144}144197​
  3. (C)187144\frac{187}{144}144187​
  4. (D)111

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
Let P(x)=x2+bx+cP(x)=x^{2}+bx+cP(x)=x2+bx+c be a quadratic polynomial with real coefficients such that ∫01P(x)dx=1\int\limits_{0}^{1}P(x)dx=10∫1​P(x)dx=1 and P(x) leaves remainder 5 when it is divided by (x−2)(x - 2)(x−2). Then the value of 9(b+c)9(b + c)9(b+c) is equal to:
  1. (A)999
  2. (B)151515
  3. (C)777
  4. (D)111111

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
If the foot of the perpendicular from point (4, 3, 8) on the line L1:x−al=y−23=z−b4L_{1}:\frac{x-a}{l}=\frac{y-2}{3}=\frac{z-b}{4}L1​:lx−a​=3y−2​=4z−b​, l≠0l \neq 0l=0 is (3, 5, 7), then the shortest distance between the line L1L_{1}L1​ and line L2:x−23=y−44=z−55L_{2}:\frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5}L2​:3x−2​=4y−4​=5z−5​ is equal to :
  1. (A)12\frac{1}{2}21​
  2. (B)16\frac{1}{\sqrt{6}}6​1​
  3. (C)23\sqrt{\frac{2}{3}}32​​
  4. (D)13\frac{1}{\sqrt{3}}3​1​

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
Let C1C_{1}C1​ be the curve obtained by the solution of differential equation 2xydydx=y2−x22xy\frac{dy}{dx}=y^{2}-x^{2}2xydxdy​=y2−x2, x>0x > 0x>0. Let the curve C2C_{2}C2​ be the solution of 2xyx2−y2=dydx\frac{2xy}{x^{2}-y^{2}}=\frac{dy}{dx}x2−y22xy​=dxdy​. If both the curves pass through (1,1), then the area enclosed by the curves C1C_{1}C1​ and C2C_{2}C2​ is equal to :
  1. (A)π−1\pi-1π−1
  2. (B)π2−1\frac{\pi}{2}-12π​−1
  3. (C)π+1\pi+1π+1
  4. (D)π4+1\frac{\pi}{4}+14π​+1

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
Let a⃗=i^+2j^−3k^\vec{a}=\hat{i}+2\hat{j}-3\hat{k}a=i^+2j^​−3k^ and b⃗=2i^−3j^+5k^\vec{b}=2\hat{i}-3\hat{j}+5\hat{k}b=2i^−3j^​+5k^. If r⃗×a⃗=b⃗×r⃗\vec{r}\times\vec{a}=\vec{b}\times\vec{r}r×a=b×r, r⃗.(αi^+2j^+k^)=3\vec{r}.\left(\alpha\hat{i}+2\hat{j}+\hat{k}\right)=3r.(αi^+2j^​+k^)=3 and r⃗.(2i^+5j^−αk^)=−1\vec{r}.\left(2\hat{i}+5\hat{j}-\alpha\hat{k}\right)=-1r.(2i^+5j^​−αk^)=−1, α∈R\alpha \in Rα∈R, then the value of α+∣r⃗∣2\alpha+\left|\vec{r}\right|^{2}α+∣r∣2 is equal to :
  1. (A)999
  2. (B)151515
  3. (C)131313
  4. (D)111111

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsNumerical
If the distance of the point (1, -2, 3) from the plane x+2y−3z+10=0x + 2y - 3z + 10 = 0x+2y−3z+10=0 measured parallel to the line, x−13=2−ym=z+31\frac{x-1}{3}=\frac{2-y}{m}=\frac{z+3}{1}3x−1​=m2−y​=1z+3​ is 72\sqrt{\frac{7}{2}}27​​, then the value of ∣m∣|m|∣m∣ is equal to _______.

Correct answer: 2

Step-by-step solution →
Q81·MathematicsNumerical
Consider the statistics of two sets of observations as follows : Size Mean Variance Observation I 10 2 2 Observation II n 3 1 If the variance of the combined set of these two observations is 179\frac{17}{9}917​, then the value of n is equal to _________.

Correct answer: 5

Step-by-step solution →
Q82·MathematicsNumerical
Let A=[a1a2]A=\begin{bmatrix} a_{1} \\ a_{2} \end{bmatrix}A=[a1​a2​​] and B=[b1b2]B=\begin{bmatrix} b_{1} \\ b_{2} \end{bmatrix}B=[b1​b2​​] be two 2×12 \times 12×1 matrices with real entries such that A=XBA = XBA=XB, where X=13[1−11k]X=\frac{1}{\sqrt{3}}\begin{bmatrix} 1 & -1 \\ 1 & k \end{bmatrix}X=3​1​[11​−1k​], and k∈Rk \in Rk∈R. If a12+a22=23(b12+b22)a_{1}^{2}+a_{2}^{2}=\frac{2}{3}\left(b_{1}^{2}+b_{2}^{2}\right)a12​+a22​=32​(b12​+b22​) and (k2+1)b22≠−2b1b2(k^{2}+1)b_{2}^{2} \neq -2b_{1}b_{2}(k2+1)b22​=−2b1​b2​, then the value of k is ________.

Correct answer: 1

Step-by-step solution →
Q83·MathematicsNumerical
For real numbers α\alphaα, β\betaβ, γ\gammaγ and δ\deltaδ, if ∫(x2−1)+tan⁡−1(x2+1x)(x4+3x2+1)tan⁡−1(x2+1x)dx\int\frac{(x^{2}-1)+\tan^{-1}\left(\frac{x^{2}+1}{x}\right)}{(x^{4}+3x^{2}+1)\tan^{-1}\left(\frac{x^{2}+1}{x}\right)}dx∫(x4+3x2+1)tan−1(xx2+1​)(x2−1)+tan−1(xx2+1​)​dx =αlog⁡e(tan⁡−1(x2+1x))+βtan⁡−1(γ(x2−1)x)+δtan⁡−1(x2+1x)+C=\alpha\log_{e}\left(\tan^{-1}\left(\frac{x^{2}+1}{x}\right)\right)+\beta\tan^{-1}\left(\frac{\gamma(x^{2}-1)}{x}\right)+\delta\tan^{-1}\left(\frac{x^{2}+1}{x}\right)+C=αloge​(tan−1(xx2+1​))+βtan−1(xγ(x2−1)​)+δtan−1(xx2+1​)+C where C is an arbitrary constant, then the value of 10(α+βγ+δ)10(\alpha+\beta\gamma+\delta)10(α+βγ+δ) is equal to __________.

Correct answer: 6

Step-by-step solution →
Q84·MathematicsNumerical
Let f:R→Rf : R \rightarrow Rf:R→R and g:R→Rg : R \rightarrow Rg:R→R be defined as f(x)={x+a,x<0∣x−1∣,x≥0f(x)=\begin{cases} x+a, & x<0 \\ |x-1|, & x \ge 0 \end{cases}f(x)={x+a,∣x−1∣,​x<0x≥0​ and g(x)={x+1,x<0(x−1)2+b,x≥0g(x)=\begin{cases} x+1, & x<0 \\ (x-1)^{2}+b, & x \ge 0 \end{cases}g(x)={x+1,(x−1)2+b,​x<0x≥0​ where a, b are non-negative real numbers. If (gof)(x)(gof)(x)(gof)(x) is continuous for all x∈Rx \in Rx∈R, then a+ba + ba+b is equal to ___________.

Correct answer: 1

Step-by-step solution →
Q85·MathematicsNumerical
Let 116\frac{1}{16}161​, a and b be in G.P. and 1a,1b,6\frac{1}{a},\frac{1}{b},6a1​,b1​,6 be in A.P., where a, b > 0. Then 72(a+b)72(a + b)72(a+b) is equal to _________.

Correct answer: 14

Step-by-step solution →
Q86·MathematicsNumerical
In ΔABC\Delta ABCΔABC, the lengths of sides AC and AB are 12 cm and 5 cm, respectively. If the area of ΔABC\Delta ABCΔABC is 30 cm2^{2}2 and R and r are respectively the radii of circumcircle and incircle of ΔABC\Delta ABCΔABC, then the value of 2R+r2R + r2R+r (in cm) is equal to _______.

Correct answer: 15

Step-by-step solution →
Q87·MathematicsNumerical
Let n be a positive integer. Let A=∑k=0n(−1)k nCk[(12)k+(34)k+(78)k+(1516)k+(3132)k]A=\sum\limits_{k=0}^{n}(-1)^{k}\ {}^{n}C_{k}\left[\left(\frac{1}{2}\right)^{k}+\left(\frac{3}{4}\right)^{k}+\left(\frac{7}{8}\right)^{k}+\left(\frac{15}{16}\right)^{k}+\left(\frac{31}{32}\right)^{k}\right]A=k=0∑n​(−1)k nCk​[(21​)k+(43​)k+(87​)k+(1615​)k+(3231​)k] If 63A=1−123063A = 1-\frac{1}{2^{30}}63A=1−2301​, then n is equal to _______.

Correct answer: 6

Step-by-step solution →
Q88·MathematicsNumerical
Let c⃗\vec{c}c be a vector perpendicular to the vectors a⃗=i^+j^−k^\vec{a}=\hat{i}+\hat{j}-\hat{k}a=i^+j^​−k^ and b⃗=i^+2j^+k^\vec{b}=\hat{i}+2\hat{j}+\hat{k}b=i^+2j^​+k^. If c⃗.(i^+j^+3k^)=8\vec{c}.\left(\hat{i}+\hat{j}+3\hat{k}\right)=8c.(i^+j^​+3k^)=8 then the value of c⃗.(a⃗×b⃗)\vec{c}.\left(\vec{a}\times\vec{b}\right)c.(a×b) is equal to _________.

Correct answer: 28

Step-by-step solution →
Q89·MathematicsNumerical
Let Sn(x)=log⁡a1/2x+log⁡a1/3x+log⁡a1/6xS_{n}(x)=\log_{a^{1/2}}x+\log_{a^{1/3}}x+\log_{a^{1/6}}xSn​(x)=loga1/2​x+loga1/3​x+loga1/6​x +log⁡a1/11x+log⁡a1/18x+log⁡a1/27x+.....+\log_{a^{1/11}}x+\log_{a^{1/18}}x+\log_{a^{1/27}}x+.....+loga1/11​x+loga1/18​x+loga1/27​x+..... up to n-terms, where a > 1. If S24(x)=1093S_{24}(x) = 1093S24​(x)=1093 and S12(2x)=265S_{12}(2x) = 265S12​(2x)=265, then value of a is equal to _______.

Correct answer: 16

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • Carboxylic Acids and Derivatives 54/186
  • Solid State 63/186
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