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JEE Main 25 June 2022 Shift 2 Question Paper with Answers

25 June 2022 · June session · 89 questions

89 of the 90 questions from the JEE Main 25 June 2022 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
29
Mathematics
30

Physics — JEE Main 25 June 2022 Shift 2

Q1·PhysicsSingle correct
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A :Two identical balls A and B thrown with same velocity 'u' at two different angles with horizontal attained the same range R. If A and B reached the maximum height h1h_1h1​ and h2h_2h2​ respectively, then R=4h1h2R = 4\sqrt{h_1 h_2}R=4h1​h2​​ Reason R: Product of said heights. h1h2=(u2sin⁡2θ2g)⋅(u2cos⁡2θ2g)h_1 h_2 = \left(\frac{u^2 \sin^2 \theta}{2g}\right) \cdot \left(\frac{u^2 \cos^2 \theta}{2g}\right)h1​h2​=(2gu2sin2θ​)⋅(2gu2cos2θ​) Choose the CORRECT answer :
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
Two buses P and Q start from a point at the same time and move in a straight line and their positions are represented by XP(t)=αt+βt2X_P(t) = \alpha t + \beta t^2XP​(t)=αt+βt2 and XQ(t)=ft−t2X_Q(t) = ft - t^2XQ​(t)=ft−t2. At what time, both the buses have same velocity ?
  1. (A)α−f1+β\frac{\alpha - f}{1 + \beta}1+βα−f​
  2. (B)α+f2(β−1)\frac{\alpha + f}{2(\beta - 1)}2(β−1)α+f​
  3. (C)α+f2(1+β)\frac{\alpha + f}{2(1 + \beta)}2(1+β)α+f​
  4. (D)f−α2(1+β)\frac{f - \alpha}{2(1 + \beta)}2(1+β)f−α​

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
A disc with a flat small bottom beaker placed on it at a distance R from its center is revolving about an axis passing through the center and perpendicular to its plane with an angular velocity ω. The coefficient of static friction between the bottom of the beaker and the surface of the disc is μ. The beaker will revolve with the disc if :
  1. (A)R≤μg2ω2R \le \frac{\mu g}{2\omega^2}R≤2ω2μg​
  2. (B)R≤μgω2R \le \frac{\mu g}{\omega^2}R≤ω2μg​
  3. (C)R≥μg2ω2R \ge \frac{\mu g}{2\omega^2}R≥2ω2μg​
  4. (D)R≥μgω2R \ge \frac{\mu g}{\omega^2}R≥ω2μg​

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A solid metallic cube having total surface area 24 m2m^2m2 is uniformly heated. If its temperature is increased by 10°C, calculate the increase in volume of the cube (Given:α=5.0×10−4 ∘C−1)\left(\text{Given} : \alpha = 5.0 \times 10^{-4}\ {}^\circ C^{-1}\right)(Given:α=5.0×10−4 ∘C−1)
  1. (A)2.4×1062.4 \times 10^62.4×106 cm3^33
  2. (B)1.2×1051.2 \times 10^51.2×105 cm3^33
  3. (C)6.0×1046.0 \times 10^46.0×104 cm3^33
  4. (D)4.8×1054.8 \times 10^54.8×105 cm3^33

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper: 0.39 J g−1 ∘C−10.39\,\mathrm{J}\,\mathrm{g}^{-1}\,{}^\circ\mathrm{C}^{-1}0.39Jg−1∘C−1 and latent heat of fusion of water : 335 J g−1\mathrm{g}^{-1}g−1]
  1. (A)1.5 kg
  2. (B)5.8 kg
  3. (C)2.9 kg
  4. (D)3.8 kg

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
The ratio of specific heats (CPCV)\left(\frac{C_P}{C_V}\right)(CV​CP​​) in terms of degree of freedom (f) is given by:
  1. (A)(1+f3)\left(1 + \frac{f}{3}\right)(1+3f​)
  2. (B)(1+2f)\left(1 + \frac{2}{f}\right)(1+f2​)
  3. (C)(1+f2)\left(1 + \frac{f}{2}\right)(1+2f​)
  4. (D)(1+1f)\left(1 + \frac{1}{f}\right)(1+f1​)

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
For a particle in uniform circular motion, the acceleration a⃗\vec{a}a at any point P(R,θ) on the circular path of radius R is (when θ is measured from the positive x –axis and v is uniform speed) :
  1. (A)−v2Rsin⁡θ i^+v2Rcos⁡θ j^-\frac{v^2}{R}\sin\theta\,\hat{i} + \frac{v^2}{R}\cos\theta\,\hat{j}−Rv2​sinθi^+Rv2​cosθj^​
  2. (B)−v2Rcos⁡θ i^+v2Rsin⁡θ j^-\frac{v^2}{R}\cos\theta\,\hat{i} + \frac{v^2}{R}\sin\theta\,\hat{j}−Rv2​cosθi^+Rv2​sinθj^​
  3. (C)−v2Rcos⁡θ i^−v2Rsin⁡θ j^-\frac{v^2}{R}\cos\theta\,\hat{i} - \frac{v^2}{R}\sin\theta\,\hat{j}−Rv2​cosθi^−Rv2​sinθj^​
  4. (D)−v2Ri^+v2Rj^-\frac{v^2}{R}\hat{i} + \frac{v^2}{R}\hat{j}−Rv2​i^+Rv2​j^​

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
Two metallic plates form a parallel plate capacitor. The distance between the plates is 'd'. A metal sheet of thickness d2\frac{d}{2}2d​ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor ?
  1. (A)2:1
  2. (B)1:2
  3. (C)1:4
  4. (D)4:1

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
Two cells of same emf but different internal resistances r1r_1r1​ and r2r_2r2​ are connected in series with a resistance R. The value of resistance R, for which the potential difference across second cell is zero, is
  1. (A)r2−r1r_2 - r_1r2​−r1​
  2. (B)r1−r2r_1 - r_2r1​−r2​
  3. (C)r1r_1r1​
  4. (D)r2r_2r2​

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
Given below are two statements: Statement – I : Susceptibilities of paramagnetic and ferromagnetic substances increase with decrease in temperature. Statement – II: Diamagnetism is a result of orbital motions of electrons developing magnetic moments opposite to the applied magnetic field. Choose the CORRECT answer from the options given below : -
  1. (A)Both statement – I and statement -II are true.
  2. (B)Both statement – I and Statement – II are false.
  3. (C)Statement – I is true but statement – II is false.
  4. (D)Statement-I is false but Statement-II is true.

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal to
  1. (A)B
  2. (B)2 B
  3. (C)4 B
  4. (D)B2\frac{B}{2}2B​

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
A sinusoidal voltage V(t) = 210 sin 3000t volt is applied to a series LCR circuit in which L = 10 mH, C = 25 μF and R = 100Ω. The phase difference (Φ) between the applied voltage and resultant current will be :
  1. (A)tan⁡−1(0.17)\tan^{-1}(0.17)tan−1(0.17)
  2. (B)tan⁡−1(9.46)\tan^{-1}(9.46)tan−1(9.46)
  3. (C)tan⁡−1(0.30)\tan^{-1}(0.30)tan−1(0.30)
  4. (D)tan⁡−1(13.33)\tan^{-1}(13.33)tan−1(13.33)

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
The electromagnetic waves travel in a medium at a speed of 2.0×1082.0 \times 10^82.0×108 m/s.The relative permeability of the medium is 1.0. The relative permittivity of the medium will be:
  1. (A)2.25
  2. (B)4.25
  3. (C)6.25
  4. (D)8.25

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
The interference pattern is obtained with two coherent light sources of intensity ratio 4 :1. And the ratio Imax+IminImax−Imin\frac{I_{max} + I_{min}}{I_{max} - I_{min}}Imax​−Imin​Imax​+Imin​​ is 5x\frac{5}{x}x5​. Then, the value of x will be equal to :
  1. (A)3
  2. (B)4
  3. (C)2
  4. (D)1

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
A light whose electric field vectors are completely removed by using a good Polaroid, allowed to incident on the surface of the prism at Brewster's angle. Choose the most suitable option for the phenomenon related to the prism.
  1. (A)Reflected and refracted rays will be perpendicular to each other
  2. (B)Wave will propagate along the surface of prism
  3. (C)No refraction, and there will be total reflection of light.
  4. (D)No reflection and there will be total transmission of light.

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
A proton, a neutron, an electron and an α-particle have same energy. If λp,λn,λe\lambda_p, \lambda_n, \lambda_eλp​,λn​,λe​ and λα\lambda_\alphaλα​ are the de Broglie's wavelengths of proton, neutron, electron and α particle respectively, then choose the correct relation from the following :
  1. (A)λp=λn>λe>λα\lambda_p = \lambda_n > \lambda_e > \lambda_\alphaλp​=λn​>λe​>λα​
  2. (B)λα<λn<λp<λe\lambda_\alpha < \lambda_n < \lambda_p < \lambda_eλα​<λn​<λp​<λe​
  3. (C)λe<λp=λn>λα\lambda_e < \lambda_p = \lambda_n > \lambda_\alphaλe​<λp​=λn​>λα​
  4. (D)λe=λp=λn=λα\lambda_e = \lambda_p = \lambda_n = \lambda_\alphaλe​=λp​=λn​=λα​

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
Which of the following figure represents the variation of ln⁡(RR0)\ln\left(\frac{R}{R_0}\right)ln(R0​R​) with ln A(If R = radius of a nucleus and A = its mass number)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
Identify the logic operation performed by the given circuit :
  1. (A)AND gate
  2. (B)OR gate
  3. (C)NOR gate
  4. (D)NAND gate

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
Match List I with List II. Choose the correct answer from the following options :
List - IList - II
A.FacsimileI.Static Document Image
B.Guided media ChannelII.Local Broadcast Radio
C.Frequency ModulationIII.Rectangular wave
D.Digital SignalIV.Optical Fiber
  1. (A)A –IV, B-III, C-II, D-I
  2. (B)A-I, B-IV, C-II, D-III
  3. (C)A –IV, B-II, C-III, D-I
  4. (D)A-I, B-II, C-III, D-IV

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be :
  1. (A)KS(S+G)\frac{KS}{\left(S+G\right)}(S+G)KS​
  2. (B)(G+S)nKS\frac{\left(G+S\right)}{nKS}nKS(G+S)​
  3. (C)nKS(G+S)\frac{nKS}{\left(G+S\right)}(G+S)nKS​
  4. (D)nK(G+S)S\frac{nK\left(G+S\right)}{S}SnK(G+S)​

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
For z=a2x3y12z = a^2 x^3 y^{\frac{1}{2}}z=a2x3y21​, where 'a' is a constant. If percentage error in measurement of 'x' and 'y' are 4% and 12%, respectively, then the percentage error for 'z' will be %.

Correct answer: 18

Step-by-step solution →
Q22·PhysicsNumerical
A curved in a level road has a radius 75m. The maximum speed of a car turning this curved road can be 30 m/s without skidding. If radius of curved road is changed to 48 m and the coefficient of friction between the tyres and the road remains same, then maximum allowed speed would be__ m/s.

Correct answer: 24

Step-by-step solution →
Q23·PhysicsNumerical
A block of mass 200 g is kept stationary on a smooth inclined plane by applying a minimum horizontal force F=xNF = \sqrt{x} NF=x​N as shown in figure. The value of x = _________.

Correct answer: 12

Step-by-step solution →
Q24·PhysicsNumerical
Moment of Inertia (M.I.) of four bodies having same mass 'M' and radius '2R' are as follows: I1I_1I1​= M.I. of solid sphere about its diameter I2I_2I2​ = M.I. of solid cylinder about its axis I3I_3I3​ = M.I. of solid circular disc about its diameter I4I_4I4​ = M.I. of thin circular ring about its diameter If 2(I2+I3)+I4=x.I12(I_2 + I_3) + I_4 = x. I_12(I2​+I3​)+I4​=x.I1​ then the value of x will be ____

Correct answer: 5

Step-by-step solution →
Q25·PhysicsNumerical
Two satellites S1S_1S1​ and S2S_2S2​ are revolving in circular orbits around a planet with radius R1R_1R1​ = 3200 km and R2R_2R2​ = 800 km respectively. The ratio of speed of satellite S1S_1S1​ to the speed of satellite S2S_2S2​ in their respective orbits would be 1x\frac{1}{x}x1​ where x =

Correct answer: 2

Step-by-step solution →
Q26·PhysicsNumerical
When a gas filled in a closed vessel is heated by raising the temperature by 1°C, its pressure increase by 0.4%. The initial temperature of the gas is_______ K.

Correct answer: 250

Step-by-step solution →
Q27·PhysicsNumerical
27 identical drops are charged at 22V each. They combine to form a bigger drop. The potential of the bigger drop will be _____ V.

Correct answer: 198

Step-by-step solution →
Q28·PhysicsNumerical
The length of a given cylindrical wire is increased to double of its original length. The percentage increase in the resistance of the wire will be _____%.

Correct answer: 300

Step-by-step solution →
Q29·PhysicsNumerical
In a series LCR circuit, the inductance, capacitance and resistance are L = 100mH, C = 100μF and R = 10Ω respectively. They are connected to an AC source of voltage 220V and frequency of 50 Hz. The approximate value of current in the circuit will be____ A.

Correct answer: 22

Step-by-step solution →
Q30·PhysicsNumerical
In an experiment of CE configuration of n-p-n transistor, the transfer characteristics are observed as given in figure. If the input resistance is 200Ω and output resistance is 60 Ω the voltage gain in this experiment will be ______

Correct answer: 15

Step-by-step solution →

Chemistry — JEE Main 25 June 2022 Shift 2

Q31·ChemistrySingle correct
The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is 1.3 ×\times× 1015^{15}15 s−1^{-1}−1 and h = 6.6 ×\times× 10−34^{-34}−34 J s.]
  1. (A)3.21 ×\times× 10−14^{-14}−14 J
  2. (B)6.24 ×\times× 10−16^{-16}−16 J
  3. (C)8.58 ×\times× 10−19^{-19}−19 J
  4. (D)9.76 ×\times× 10−20^{-20}−20 J

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
At 25∘^{\circ}∘C and 1 atm pressure, the enthalpy of combustion of benzene (1) and acetylene (g) are -3268 kJ mol−1^{-1}−1 and -1300 kJ mol−1^{-1}−1, respectively. The change in enthalpy for the reaction 3 C2_22​H2_22​(g) →\rightarrow→ C6_66​H6_66​(l), is
  1. (A)+ 324 kJ mol−1^{-1}−1
  2. (B)+632 kJ mol−1^{-1}−1
  3. (C)- 632 kJ mol−1^{-1}−1
  4. (D)- 732 kJ mol−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 g of water, it depresses the freezing point by 0.2∘^{\circ}∘C. The percentage association of solute A in water, is [Given : Molar mass of A = 93 g mol−1^{-1}−1. Molal depression constant of water is 1.86 K kg mol−1^{-1}−1]
  1. (A)50 %
  2. (B)60 %
  3. (C)70 %
  4. (D)80 %

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
The Ksp_{sp}sp​ for bismuth sulphide (Bi2_22​S3_33​) is 1.08 ×\times× 10−73^{-73}−73. The solubility of Bi2_22​S3_33​ in mol L−1^{-1}−1 at 298 K is
  1. (A)1.0 ×\times× 10−15^{-15}−15
  2. (B)2.7 ×\times× 10−12^{-12}−12
  3. (C)3.2 ×\times× 10−10^{-10}−10
  4. (D)4.2 ×\times× 10−8^{-8}−8

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
Match List I with List II. Choose the correct answer from the options given below:
List IList II
A.ZymaseI.Stomach
B.DiastaseII.Yeast
C.UreaseIII.Malt
D.PepsinIV.Soyabean
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-II, B-III, C-IV, D-I
  3. (C)A-III, B-II, C-IV, D-I
  4. (D)A-III, B-II, C-I, D-IV

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
The correct order of electron gain enthalpies of Cl, F, Te and Po is
  1. (A)F < Cl < Te < Po
  2. (B)Po < Te < F < Cl
  3. (C)Te < Po < Cl < F
  4. (D)Cl < F < Te < Po

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
Given below are two statements. Statement I: During electrolytic refining, blister copper deposits precious metals Statement II: In the process of obtaining pure copper by electrolysis method, copper blister is used to make the anode. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Both Statement I and Statement II are true.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Statement I is false but Statement II is true.

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correct
Given below are two statements one is labelled as Assertion A and the other is labelled as Reason R: Assertion A : The amphoteric nature of water is explained by using Lewis acid/base concept. Reason R : Water acts as an acid with NH3_33​ and as a base with H2_22​S. In the light of the above statements choose the correct answer from the options given below :
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false.
  4. (D)A is false but R is true.

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
The correct order of reduction potentials of the following pairs is A. Cl2_22​/Cl−^-− B. I2_22​/I−^-− C. Ag+^++/Ag D. Na+^++/Na E. Li+^++/Li Choose the correct answer from the options given below.
  1. (A)A > C > B > D > E
  2. (B)A > B > C > D > E
  3. (C)A > C > B > E > D
  4. (D)A > B > C > E > D

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
The number of bridged oxygen atoms present in compound B formed from the following reactions is Pb(NO3_33​)2_22​ →673 K\xrightarrow{673\ K}673 K​ A + PbO + O2_22​ A →Dimerise\xrightarrow{Dimerise}Dimerise​ B
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (A)

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Q41·ChemistrySingle correct
The metal ion (in gaseous state) with lowest spin-only magnetic moment value is
  1. (A)V2+^{2+}2+
  2. (B)Ni2+^{2+}2+
  3. (C)Cr2+^{2+}2+
  4. (D)Fe2+^{2+}2+

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: Polluted water may have a value of BOD of the order of 17 ppm. Reason R: BOD is a measure of oxygen required to oxidise both the biodegradable and non-biodegradable organic material in water. In the light of the above statements, choose the most appropriate answer from the options given below.
  1. (A)Both A and R are correct and R is the correct explanation of A.
  2. (B)Both A and R are correct but R is NOT the correct explanation of A.
  3. (C)A is correct but R is not correct.
  4. (D)A is not correct but R is correct.

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: A mixture contains benzoic acid and napthalene. The pure benzoic acid can be separated out by the use of benzene. Reason R: Benzoic acid is soluble in hot water. In the light of the above statements, choose the most appropriate answer from the options given below.
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false.
  4. (D)A is false but R is true.

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
During halogen test, sodium fusion extract is boiled with concentrated HNO3_33​ to
  1. (A)remove unreacted sodium
  2. (B)decompose cyanide or sulphide of sodium
  3. (C)extract halogen from organic compound
  4. (D)maintain the pH of extract

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
Amongst the following, the major product of the given chemical reaction is Br2_22​/CH3_33​OH →\rightarrow→ Major Product
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
In the given reaction 2 A →(iii) H2O/H+(i) 2 Mg, THF; (ii) Methyl benzoate\xrightarrow[\text{(iii) H}_2\text{O/H}^+]{\text{(i) 2 Mg, THF; (ii) Methyl benzoate}}(i) 2 Mg, THF; (ii) Methyl benzoate(iii) H2​O/H+​ 'A' can be
  1. (A)benzyl bromide
  2. (B)bromobenzene
  3. (C)cyclohexyl bromide
  4. (D)methyl bromide

Correct answer: (B)

Step-by-step solution →
Q47·ChemistrySingle correct
Which of the following conditions or reaction sequence will NOT give acetophenone as the major product ?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q48·ChemistrySingle correct
The major product formed in the following reaction, is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
Which of the following ketone will NOT give enamine on treatment with secondary amines? [where t-Bu is −-−C(CH3_33​)3_33​]
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q50·ChemistrySingle correct
An antiseptic dettol is a mixture of two compounds 'A' and 'B' where A has 6π\piπ electrons and B has 2π\piπ electrons. What is 'B'?
  1. (A)Bithionol
  2. (B)Terpineol
  3. (C)Chloroxylenol
  4. (D)Chloramphenicol

Correct answer: (B)

Step-by-step solution →
Q51·ChemistryNumerical
A protein 'A' contains 0.30% of glycine (molecular weight 75). The minimum molar mass of the protein 'A' is________ ×\times× 103^33 g mol−1^{-1}−1 [nearest integer]

Correct answer: 25

Step-by-step solution →
Q52·ChemistryNumerical
A rigid nitrogen tank stored inside a laboratory has a pressure of 30 atm at 06:00 am when the temperature is 27 ∘^\circ∘C. At 03:00 pm, when the temperature is 45∘^\circ∘C, the pressure in the tank will be ____________atm. [nearest integer]

Correct answer: 32

Step-by-step solution →
Q53·ChemistryNumerical
Amongst BeF2_22​, BF3_33​, H2_22​O, NH3_33​, CCl4_44​ and HCl, the number of molecules with non-zero net dipole moment is __________.

Correct answer: 3

Step-by-step solution →
Q54·ChemistryNumerical
At 345 K, the half life for the decomposition of a sample of a gaseous compound initially at 55.5 kPa was 340 s. When the pressure was 27.8 kPa, the half life was fund to be 170 s. The order of the reaction is_________. [integer answer]

Correct answer: 0

Step-by-step solution →
Q55·ChemistryNumerical
A solution of Fe2_22​(SO4_44​)3_33​ is electrolyzed for 'x' min with a current of 1.5 A to deposit 0.3482 g of Fe. The value of x is______. [nearest integer] Given : 1 F = 96500 C mol−1^{-1}−1 Atomic mass of Fe = 56 g mol−1^{-1}−1

Correct answer: 20

Step-by-step solution →
Q56·ChemistryNumerical
Consider the following reactions : PCl3_33​ + H2_22​O ⟶\longrightarrow⟶ A + HCl A + H2_22​O ⟶\longrightarrow⟶ B + HCl number of ionisable protons present in the product B_________.

Correct answer: 2

Step-by-step solution →
Q57·ChemistryNumerical
Amongst FeCl3_33​.3H2_22​O, K3_33​[Fe(CN)6_66​] and [Co(NH3_33​)6_66​]Cl3_33​, the spin-only magnetic moment value of the inner-orbital complex that absorbs light at shortest wavelength is________ B.M. [nearest integer]

Correct answer: 2

Step-by-step solution →
Q58·ChemistryNumerical
How many of the given compounds will give a positive Biuret test ______ ? Glycine, Glycylalanine, Tripeptide, Biuret

Correct answer: 2

Step-by-step solution →
Q59·ChemistryNumerical
The neutralization occurs when 10 mL of 0.1 M acid 'A' is allowed to react with 30 mL of 0.05 M base M(OH)2_22​. The basicity of the acid 'A' is______. [M is a metal]

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 25 June 2022 Shift 2

Q60·MathematicsSingle correct
Let A={x∈R:∣x+1∣<2}A = \{x \in R : |x+1| < 2\}A={x∈R:∣x+1∣<2} and B={x∈R:∣x−1∣≥2}B = \{x \in R : |x-1| \ge 2\}B={x∈R:∣x−1∣≥2}. Then which one of the following statements is NOT true ?
  1. (A)A−B=(−1,1)A - B = (-1,1)A−B=(−1,1)
  2. (B)B−A=R−(−3,1)B - A = R - (-3,1)B−A=R−(−3,1)
  3. (C)A∩B=(−3,−1]A \cap B = (-3,-1]A∩B=(−3,−1]
  4. (D)A∪B=R−[1,3)A \cup B = R - [1,3)A∪B=R−[1,3)

Correct answer: (B)

Step-by-step solution →
Q61·MathematicsSingle correct
Let a,b∈Ra, b \in Ra,b∈R be such that the equation ax2−2bx+15=0ax^2 - 2bx + 15 = 0ax2−2bx+15=0 has a repeated root α\alphaα. If α\alphaα and β\betaβ are the roots of the equation x2−2bx+21=0x^2 - 2bx + 21 = 0x2−2bx+21=0, then α2+β2\alpha^2 + \beta^2α2+β2 is equal to:
  1. (A)37
  2. (B)58
  3. (C)68
  4. (D)92

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
Let z1z_1z1​ and z2z_2z2​ be two complex numbers such that z‾1=iz‾2\overline{z}_1 = i\overline{z}_2z1​=iz2​ and arg⁡(z1z‾2)=π\arg\left(\frac{z_1}{\overline{z}_2}\right) = \piarg(z2​z1​​)=π. Then
  1. (A)arg⁡z2=π4\arg z_2 = \frac{\pi}{4}argz2​=4π​
  2. (B)arg⁡z2=−3π4\arg z_2 = -\frac{3\pi}{4}argz2​=−43π​
  3. (C)arg⁡z1=π4\arg z_1 = \frac{\pi}{4}argz1​=4π​
  4. (D)arg⁡z1=−3π4\arg z_1 = -\frac{3\pi}{4}argz1​=−43π​

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
The system of equations −kx+3y−14z=25-kx + 3y - 14z = 25−kx+3y−14z=25 −15x+4y−kz=3-15x + 4y - kz = 3−15x+4y−kz=3 −4x+y+3z=4-4x + y + 3z = 4−4x+y+3z=4 is consistent for all k in the set
  1. (A)RRR
  2. (B)R−{−11,13}R - \{-11,13\}R−{−11,13}
  3. (C)R−{13}R - \{13\}R−{13}
  4. (D)R−{−11,11}R - \{-11,11\}R−{−11,11}

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
lim⁡x→π2(tan⁡2x((2sin⁡2x+3sin⁡x+4)12−(sin⁡2x+6sin⁡x+2)12))\lim_{x \to \frac{\pi}{2}}\left( \tan^2 x \left( \left(2\sin^2 x + 3\sin x + 4\right)^{\frac{1}{2}} - \left(\sin^2 x + 6\sin x + 2\right)^{\frac{1}{2}} \right) \right)limx→2π​​(tan2x((2sin2x+3sinx+4)21​−(sin2x+6sinx+2)21​)) is equal to
  1. (A)112\frac{1}{12}121​
  2. (B)−118-\frac{1}{18}−181​
  3. (C)−112-\frac{1}{12}−121​
  4. (D)−16-\frac{1}{6}−61​

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
The area of the region enclosed between the parabolas y2=2x−1y^2 = 2x - 1y2=2x−1 and y2=4x−3y^2 = 4x - 3y2=4x−3 is
  1. (A)13\frac{1}{3}31​
  2. (B)16\frac{1}{6}61​
  3. (C)23\frac{2}{3}32​
  4. (D)34\frac{3}{4}43​

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
The coefficient of x101x^{101}x101 in the expression (5+x)500+x(5+x)499+x2(5+x)498+.....x500(5+x)^{500} + x(5+x)^{499} + x^2(5+x)^{498} + .....x^{500}(5+x)500+x(5+x)499+x2(5+x)498+.....x500, x>0x > 0x>0, is
  1. (A)501C101(5)399^{501}C_{101}(5)^{399}501C101​(5)399
  2. (B)501C101(5)400^{501}C_{101}(5)^{400}501C101​(5)400
  3. (C)501C100(5)400^{501}C_{100}(5)^{400}501C100​(5)400
  4. (D)500C101(5)399^{500}C_{101}(5)^{399}500C101​(5)399

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
The sum 1+2⋅3+3⋅32+.....+10⋅391 + 2 \cdot 3 + 3 \cdot 3^2 + ..... + 10 \cdot 3^91+2⋅3+3⋅32+.....+10⋅39 is equal to
  1. (A)2⋅312+104\frac{2 \cdot 3^{12} + 10}{4}42⋅312+10​
  2. (B)19⋅310+14\frac{19 \cdot 3^{10} + 1}{4}419⋅310+1​
  3. (C)5⋅310−25 \cdot 3^{10} - 25⋅310−2
  4. (D)9⋅310+12\frac{9 \cdot 3^{10} + 1}{2}29⋅310+1​

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let P be the plane passing through the intersection of the planes r⃗⋅(i^+3j^−k^)=5\vec{r} \cdot \left(\hat{i} + 3\hat{j} - \hat{k}\right) = 5r⋅(i^+3j^​−k^)=5 and r⃗⋅(2i^−j^+k^)=3\vec{r} \cdot \left(2\hat{i} - \hat{j} + \hat{k}\right) = 3r⋅(2i^−j^​+k^)=3, and the point (2,1,−2)(2,1,-2)(2,1,−2). Let the position vectors of the points X and Y be i^−2j^+4k^\hat{i} - 2\hat{j} + 4\hat{k}i^−2j^​+4k^ and 5i^−j^+2k^5\hat{i} - \hat{j} + 2\hat{k}5i^−j^​+2k^ respectively. Then the points
  1. (A)X and X + Y are on the same side of P
  2. (B)Y and Y −-− X are on the opposite sides of P
  3. (C)X and Y are on the opposite sides of P
  4. (D)X + Y and X −-− Y are on the same side of P

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
A circle touches both the y-axis and the line x+y=0x + y = 0x+y=0. Then the locus of its center is
  1. (A)y=2xy = \sqrt{2}xy=2​x
  2. (B)x=2yx = \sqrt{2}yx=2​y
  3. (C)y2−x2=2xyy^2 - x^2 = 2xyy2−x2=2xy
  4. (D)x2−y2=2xyx^2 - y^2 = 2xyx2−y2=2xy

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
Water is being filled at the rate of 1 cm3/sec⁡1\,\mathrm{cm}^3/\sec1cm3/sec in a right circular conical vessel (vertex downwards) of height 35 cm and diameter 14 cm. When the height of the water level is 10 cm, the rate (in cm2/sec⁡\mathrm{cm}^2/\seccm2/sec) at which the wet conical surface area of the vessel increases is
  1. (A)5
  2. (B)215\frac{\sqrt{21}}{5}521​​
  3. (C)265\frac{\sqrt{26}}{5}526​​
  4. (D)2610\frac{\sqrt{26}}{10}1026​​

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correct
If bn=∫0π2cos⁡2nxsin⁡xdxb_n = \int_{0}^{\frac{\pi}{2}} \frac{\cos^2 nx}{\sin x} dxbn​=∫02π​​sinxcos2nx​dx, n∈Nn \in Nn∈N, then
  1. (A)b3−b2b_3 - b_2b3​−b2​, b4−b3b_4 - b_3b4​−b3​, b5−b4b_5 - b_4b5​−b4​ are in an A.P. with common difference −2-2−2
  2. (B)1b3−b2,1b4−b3,1b5−b4\frac{1}{b_3 - b_2}, \frac{1}{b_4 - b_3}, \frac{1}{b_5 - b_4}b3​−b2​1​,b4​−b3​1​,b5​−b4​1​ are in an A.P. with common difference 2
  3. (C)b3−b2b_3 - b_2b3​−b2​, b4−b3b_4 - b_3b4​−b3​, b5−b4b_5 - b_4b5​−b4​ are in a G.P.
  4. (D)1b3−b2,1b4−b3,1b5−b4\frac{1}{b_3 - b_2}, \frac{1}{b_4 - b_3}, \frac{1}{b_5 - b_4}b3​−b2​1​,b4​−b3​1​,b5​−b4​1​ are in an A.P. with common difference −2-2−2

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
If y=y(x)y = y(x)y=y(x) is the solution of the differential equation 2x2dydx−2xy+3y2=02x^2 \frac{dy}{dx} - 2xy + 3y^2 = 02x2dxdy​−2xy+3y2=0 such that y(e)=e3y(e) = \frac{e}{3}y(e)=3e​, then y(1)y(1)y(1) is equal to
  1. (A)13\frac{1}{3}31​
  2. (B)23\frac{2}{3}32​
  3. (C)32\frac{3}{2}23​
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
If the angle made by the tangent at the point (x0,y0)(x_0, y_0)(x0​,y0​) on the curve x=12(t+sin⁡tcos⁡t)x = 12(t + \sin t \cos t)x=12(t+sintcost), y=12(1+sin⁡t)2,0<t<π2y = 12(1 + \sin t)^2, 0 < t < \frac{\pi}{2}y=12(1+sint)2,0<t<2π​, with the positive x-axis is π3\frac{\pi}{3}3π​, then y0y_0y0​ is equal to
  1. (A)6(3+22)6\left(3 + 2\sqrt{2}\right)6(3+22​)
  2. (B)3(7+43)3\left(7 + 4\sqrt{3}\right)3(7+43​)
  3. (C)27
  4. (D)48

Correct answer: (C)

Step-by-step solution →
Q74·MathematicsSingle correct
The value of 2sin⁡(12∘)−sin⁡(72∘)2\sin(12^\circ) - \sin(72^\circ)2sin(12∘)−sin(72∘) is :
  1. (A)5(1−3)4\frac{\sqrt{5}\left(1 - \sqrt{3}\right)}{4}45​(1−3​)​
  2. (B)1−58\frac{1 - \sqrt{5}}{8}81−5​​
  3. (C)3(1−5)2\frac{\sqrt{3}\left(1 - \sqrt{5}\right)}{2}23​(1−5​)​
  4. (D)3(1−5)4\frac{\sqrt{3}\left(1 - \sqrt{5}\right)}{4}43​(1−5​)​

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsSingle correct
A biased die is marked with numbers 2,4, 8, 16, 32, 32 on its faces and the probability of getting a face with mark n is 1n\frac{1}{n}n1​. If the die is thrown thrice, then the probability, that the sum of the numbers obtained is 48, is
  1. (A)7211\frac{7}{2^{11}}2117​
  2. (B)7212\frac{7}{2^{12}}2127​
  3. (C)3210\frac{3}{2^{10}}2103​
  4. (D)13212\frac{13}{2^{12}}21213​

Correct answer: (D)

Step-by-step solution →
Q76·MathematicsSingle correct
The negation of the Boolean expression ((∼q)∧p)⇒((∼p)∨q)((\sim q) \wedge p) \Rightarrow ((\sim p) \vee q)((∼q)∧p)⇒((∼p)∨q) is logically equivalent to
  1. (A)p⇒qp \Rightarrow qp⇒q
  2. (B)q⇒pq \Rightarrow pq⇒p
  3. (C)∼(p⇒q)\sim\left(p \Rightarrow q\right)∼(p⇒q)
  4. (D)∼(q⇒p)\sim\left(q \Rightarrow p\right)∼(q⇒p)

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
If the line y=4+kxy = 4 + kxy=4+kx, k>0k > 0k>0, is the tangent to the parabola y=x−x2y = x - x^{2}y=x−x2 at the point P and V is the vertex of the parabola, then the slope of the line through P and V is :
  1. (A)32\frac{3}{2}23​
  2. (B)269\frac{26}{9}926​
  3. (C)52\frac{5}{2}25​
  4. (D)236\frac{23}{6}623​

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
The value of tan⁡−1(cos⁡(15π4)−1sin⁡(π4))\tan^{-1}\left(\frac{\cos\left(\frac{15\pi}{4}\right) - 1}{\sin\left(\frac{\pi}{4}\right)}\right)tan−1(sin(4π​)cos(415π​)−1​) is equal to
  1. (A)−π4-\frac{\pi}{4}−4π​
  2. (B)−π8-\frac{\pi}{8}−8π​
  3. (C)−5π12-\frac{5\pi}{12}−125π​
  4. (D)−4π9-\frac{4\pi}{9}−94π​

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
The line y=x+1y = x + 1y=x+1 meets the ellipse x24+y22=1\frac{x^{2}}{4} + \frac{y^{2}}{2} = 14x2​+2y2​=1 at two points P and Q. If r is the radius of the circle with PQ as diameter then (3r)2(3r)^{2}(3r)2 is equal to
  1. (A)20
  2. (B)12
  3. (C)11
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsNumerical
Let A=(2−21−1)A = \begin{pmatrix} 2 & -2 \\ 1 & -1 \end{pmatrix}A=(21​−2−1​) and B=(−12−12)B = \begin{pmatrix} -1 & 2 \\ -1 & 2 \end{pmatrix}B=(−1−1​22​). Then the number of elements in the set {(n,m):n,m∈{1,2,.....,10}\{(n, m) : n, m \in \{1, 2, ....., 10\}{(n,m):n,m∈{1,2,.....,10} and nAn+mBm=I}nA^{n} + mB^{m} = I\}nAn+mBm=I} is ______

Correct answer: 1

Step-by-step solution →
Q81·MathematicsNumerical
Let f(x)=[2x2+1]f(x) = [2x^{2} + 1]f(x)=[2x2+1] and g(x)={2x−3,x<02x+3,x≥0g(x) = \begin{cases} 2x - 3, & x < 0 \\ 2x + 3, & x \geq 0 \end{cases}g(x)={2x−3,2x+3,​x<0x≥0​, where [t] is the greatest integer ≤t\leq t≤t. Then, in the open interval (−1,1)(-1, 1)(−1,1), the number of points where fog is discontinuous is equal to ______

Correct answer: 62

Step-by-step solution →
Q82·MathematicsNumerical
The value of b > 3 for which 12∫3b1(x2−1)(x2−4)dx=log⁡e(4940)12\int_{3}^{b}\frac{1}{\left(x^{2} - 1\right)\left(x^{2} - 4\right)}dx = \log_{e}\left(\frac{49}{40}\right)12∫3b​(x2−1)(x2−4)1​dx=loge​(4049​), is equal to

Correct answer: 6

Step-by-step solution →
Q83·MathematicsNumerical
If the sum of the coefficients of all the positive even powers of x in the binomial expansion of (2x3+3x)10\left(2x^{3} + \frac{3}{x}\right)^{10}(2x3+x3​)10 is 510−β⋅395^{10} - \beta \cdot 3^{9}510−β⋅39, then β\betaβ is equal to ______

Correct answer: 83

Step-by-step solution →
Q84·MathematicsNumerical
If the mean deviation about the mean of the numbers 1, 2, 3, ....., n, where n is odd, is 5(n+1)n\frac{5(n + 1)}{n}n5(n+1)​, then n is equal to ______

Correct answer: 21

Step-by-step solution →
Q85·MathematicsNumerical
Let b⃗=i^+j^+λk^,λ∈R\vec{b} = \hat{i} + \hat{j} + \lambda\hat{k}, \lambda \in Rb=i^+j^​+λk^,λ∈R. If a⃗\vec{a}a is a vector such that a⃗×b⃗=13i^−j^−4k^\vec{a} \times \vec{b} = 13\hat{i} - \hat{j} - 4\hat{k}a×b=13i^−j^​−4k^ and a⃗⋅b⃗+21=0\vec{a} \cdot \vec{b} + 21 = 0a⋅b+21=0, then (b⃗−a⃗)⋅(k^−j^)+(b⃗+a⃗)⋅(i^−k^)\left(\vec{b} - \vec{a}\right) \cdot \left(\hat{k} - \hat{j}\right) + \left(\vec{b} + \vec{a}\right) \cdot \left(\hat{i} - \hat{k}\right)(b−a)⋅(k^−j^​)+(b+a)⋅(i^−k^) is equal to

Correct answer: 14

Step-by-step solution →
Q86·MathematicsNumerical
The total number of three-digit numbers, with one digit repeated exactly two times, is

Correct answer: 243

Step-by-step solution →
Q87·MathematicsNumerical
Let f(x)=∣(x−1)(x2−2x−3)∣+x−3f(x) = \left|(x - 1)(x^{2} - 2x - 3)\right| + x - 3f(x)=​(x−1)(x2−2x−3)​+x−3, x∈Rx \in Rx∈R. If m and M are respectively the number of points of local minimum and local maximum of f in the interval (0, 4), then m + M is equal to ______

Correct answer: 3

Step-by-step solution →
Q88·MathematicsNumerical
Let the eccentricity of the hyperbola x2a2−y2b2=1\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1a2x2​−b2y2​=1 be 54\frac{5}{4}45​. If the equation of the normal at the point (85,125)\left(\frac{8}{\sqrt{5}}, \frac{12}{5}\right)(5​8​,512​) on the hyperbola is 85x+βy=λ8\sqrt{5}x + \beta y = \lambda85​x+βy=λ, then λ−β\lambda - \betaλ−β is equal to

Correct answer: 85

Step-by-step solution →
Q89·MathematicsNumerical
Let l1l_{1}l1​ be the line in xy-plane with x and y intercepts 18\frac{1}{8}81​ and 142\frac{1}{4\sqrt{2}}42​1​ respectively, and l2l_{2}l2​ be the line in zx-plane with x and z intercepts −18-\frac{1}{8}−81​ and −163-\frac{1}{6\sqrt{3}}−63​1​ respectively. If d is the shortest distance between the line l1l_{1}l1​ and l2l_{2}l2​, then d−2d^{-2}d−2 is equal to

Correct answer: 51

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Chemistry in Everyday Life 60/186
  • Magnetism and Matter 50/186
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