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JEE Main 27 July 2022 Shift 1 Question Paper with Answers

27 July 2022 · July session · 89 questions

89 of the 90 questions from the JEE Main 27 July 2022 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
30
Mathematics
30

Physics — JEE Main 27 July 2022 Shift 1

Q1·PhysicsSingle correct
A torque meter is calibrated to reference standards of mass, length and time each with 5% accuracy. After calibration, the measured torque with this torque meter will have net accuracy of :
  1. (A)15%
  2. (B)25%
  3. (C)75%
  4. (D)5%

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
A bullet is shot vertically downwards with an initial velocity of 100 m/s from a certain height. Within 10 s, the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision. The velocity-time curve for total time t = 20 s will be : (Take g = 10 m/s2^{2}2)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Sand is being dropped from a stationary dropper at a rate of 0.5 kgs−1^{-1}−1 on a conveyor belt moving with a velocity of 5 ms−1^{-1}−1. The power needed to keep belt moving with the same velocity will be :
  1. (A)1.25 W
  2. (B)2.5 W
  3. (C)6.25 W
  4. (D)12.5 W

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
A bag is gently dropped on a conveyor belt moving at a speed of 2 m/s. The coefficient of friction between the conveyor belt and bag is 0.4 Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion is : [Take g = 10 m/s−2^{-2}−2]
  1. (A)2 m
  2. (B)0.5 m
  3. (C)3.2 m
  4. (D)0.8 ms

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
Two cylindrical vessels of equal cross-sectional area 16 cm2^{2}2 contain water upto heights 100 cm and 150 cm respectively. The vessels are interconnected so that the water levels in them become equal. The work done by the force of gravity during the process, is [Take density of water = 103^{3}3 kg/m3^{3}3 and g = 10 ms−2^{-2}−2]
  1. (A)0.25 J
  2. (B)1 J
  3. (C)8 J
  4. (D)12 J

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
Two satellites A and B having masses in the ratio 4:3 are revolving in circular orbits of radii 3r and 4 r respectively around the earth. The ratio of total mechanical energy of A to B is :
  1. (A)9 : 16
  2. (B)16 : 9
  3. (C)1 : 1
  4. (D)4 : 3

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
If K1_{1}1​ and K2_{2}2​ are the thermal conductivities L1_{1}1​ and L2_{2}2​ are the lengths and A1_{1}1​ and A2_{2}2​ are the cross sectional areas of steel and copper rods respectively such that K2K1=9,A1A2=2,L1L2=2\frac{K_{2}}{K_{1}} = 9, \frac{A_{1}}{A_{2}} = 2, \frac{L_{1}}{L_{2}} = 2K1​K2​​=9,A2​A1​​=2,L2​L1​​=2 . Then, for the arrangement as shown in the figure. The value of temperature T of the steel – copper junction in the steady state will be :
  1. (A)18ºC
  2. (B)14 ºC
  3. (C)45 ºC
  4. (D)150 ºC

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
Read the following statements : A. When small temperature difference between a liquid and its surrounding is doubled the rate of loss of heat of the liquid becomes twice. B. Two bodies P and Q having equal surface areas are maintained at temperature 10ºC and 20 ºC. The thermal radiation emitted in a given time by P and Q are in the ratio 1 : 1.15 C. A carnot Engine working between 100 K and 400 K has an efficiency of 75% D. When small temperature difference between a liquid and its surrounding is quadrupled, the rate of loss of heat of the liquid becomes twice. Choose the correct answer from the options given below :
  1. (A)A, B, C only
  2. (B)A, B only
  3. (C)A, C only
  4. (D)B, C, D only

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
Same gas is filled in two vessels of the same volume at the same temperature. If the ratio of the number of molecules is 1:4, then A. The r.m.s. velocity of gas molecules in two vessels will be the same. B. The ratio of pressure in these vessels will be 1 : 4 C. The ratio of pressure will be 1 : 1 D. The r.m.s. velocity of gas molecules in two vessels will be in the ratio of 1 : 4
  1. (A)A and C only
  2. (B)B and D only
  3. (C)A and B only
  4. (D)C and D only

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
Two identical positive charges Q each are fixed at a distance of ‘2a’ apart from each other. Another point charge q0_{0}0​ with mass ‘m’ is placed at midpoint between two fixed charges. For a small displacement along the line joining the fixed charges, the charge q0_{0}0​ executes SHM. The time period of oscillation of charge q0_{0}0​ will be :
  1. (A)4π3ε0ma3q0Q\sqrt{\dfrac{4\pi^{3}\varepsilon_{0}ma^{3}}{q_{0}Q}}q0​Q4π3ε0​ma3​​
  2. (B)q0Q4π3ε0ma3\sqrt{\dfrac{q_{0}Q}{4\pi^{3}\varepsilon_{0}ma^{3}}}4π3ε0​ma3q0​Q​​
  3. (C)2π2ε0ma3q0Q\sqrt{\dfrac{2\pi^{2}\varepsilon_{0}ma^{3}}{q_{0}Q}}q0​Q2π2ε0​ma3​​
  4. (D)8π3ε0ma3q0Q\sqrt{\dfrac{8\pi^{3}\varepsilon_{0}ma^{3}}{q_{0}Q}}q0​Q8π3ε0​ma3​​

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
Two sources of equal emfs are connected in series. This combination is connected to an external resistance R. The internal resistances of the two sources are r1_{1}1​ and r2_{2}2​ (r1_{1}1​ > r2_{2}2​). If the potential difference across the source of internal resistance r1_{1}1​ is zero then the value of R will be
  1. (A)r1−r2r_{1} - r_{2}r1​−r2​
  2. (B)r1r2r1+r2\dfrac{r_{1}r_{2}}{r_{1}+r_{2}}r1​+r2​r1​r2​​
  3. (C)r1+r22\dfrac{r_{1}+r_{2}}{2}2r1​+r2​​
  4. (D)r2−r1r_{2} - r_{1}r2​−r1​

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Two bar magnets oscillate in a horizontal plane in earth’s magnetic field with time periods of 3 s and 4 s respectively. If their moments of inertia are in the ratio of 3 : 2 then the ratio of their magnetic moments will e :
  1. (A)2 : 1
  2. (B)8 : 3
  3. (C)1 : 3
  4. (D)27 : 16

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
A magnet hung at 45º with magnetic meridian makes an angle of 60º with the horizontal. The actual value of the angle of dip is
  1. (A)tan⁡−1(32)\tan^{-1}\left(\sqrt{\dfrac{3}{2}}\right)tan−1(23​​)
  2. (B)tan⁡−1(6)\tan^{-1}\left(\sqrt{6}\right)tan−1(6​)
  3. (C)tan⁡−1(23)\tan^{-1}\left(\sqrt{\dfrac{2}{3}}\right)tan−1(32​​)
  4. (D)tan⁡−1(12)\tan^{-1}\left(\sqrt{\dfrac{1}{2}}\right)tan−1(21​​)

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
A direct current of 4 A and an alternating current of peak value 4 A flow through resistance of 3 Ω and 2 Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be :
  1. (A)3 : 2
  2. (B)3 : 1
  3. (C)3 : 4
  4. (D)4 : 3

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
A beam of light travelling along X-axis is described by the electric field Ey_{y}y​ = 900 sin ω\omegaω(t–x/c). The ratio of electric force to magnetic force on a charge q moving along Y-axis with a speed of 3 × 107^{7}7 ms−1^{-1}−1 will be : [Given speed of light = 3 × 108^{8}8 ms−1^{-1}−1]
  1. (A)1 : 1
  2. (B)1 : 10
  3. (C)10 : 1
  4. (D)1 : 2

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
An electron (mass m) with an initial velocity v⃗=v0i^ (v0>0)\vec{v} = v_0\hat{i}\,(v_0 > 0)v=v0​i^(v0​>0) is moving in an electric field E⃗=−E0i^ (E0>0)\vec{E} = -E_0\hat{i}\,(E_0 > 0)E=−E0​i^(E0​>0) where E0E_0E0​ is constant. If at t = 0 de Broglie wavelength is λ0=hmv0\lambda_0 = \frac{h}{mv_0}λ0​=mv0​h​, then its de Broglie wavelength after time t is given by
  1. (A)λ0\lambda_0λ0​
  2. (B)λ0(1+eE0tmv0)\lambda_0\left(1 + \frac{eE_0t}{mv_0}\right)λ0​(1+mv0​eE0​t​)
  3. (C)λ0t\lambda_0 tλ0​t
  4. (D)λ0(1+eE0tmv0)\dfrac{\lambda_0}{\left(1 + \frac{eE_0t}{mv_0}\right)}(1+mv0​eE0​t​)λ0​​

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
What is the half-life period of a radioactive material if its activity drops to 1/16th1/16^{\text{th}}1/16th of its initial value of 30 years ?
  1. (A)9.5 years
  2. (B)8.5 years
  3. (C)7.5 years
  4. (D)10.5 years

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
A logic gate circuit has two inputs A and B and output Y. The voltage waveforms of A, B and Y are shown below The logic gate circuit is
  1. (A)AND gate
  2. (B)OR gate
  3. (C)NOR gate
  4. (D)NAND gate

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
At a particular station, the TV transmission tower has a height of 100 m. To triple its coverage range, height of the tower should be increased to
  1. (A)200 m
  2. (B)300 m
  3. (C)600 m
  4. (D)900 m

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsNumerical
In meter bridge experiment for measuring unknown resistance 'S', the null point is obtained at a distance 30 cm from the left side as shown at point D. If R is 5.6 kΩ\mathrm{k}\OmegakΩ, then the value of unknown resistance 'S' will be ________ Ω\OmegaΩ.

Correct answer: 2400

Step-by-step solution →
Q21·PhysicsNumerical
The one division of main scale of vernier callipers reads 1 mm and 10 divisions of Vernier scale is equal to the 9 divisions on main scale. When the two jaws of the instrument touch each other the zero of the Vernier lies to the right of zero of the main scale and its fourth division coincides with a main scale division. When a spherical bob is tightly placed between the two jaws, the zero of the Vernier scale lies in between 4.1 cm and 4.2 cm and 6th6^{\text{th}}6th Vernier division coincides with a main scale division. The diameter of the bob will be______ 10−210^{-2}10−2 cm

Correct answer: 412

Step-by-step solution →
Q22·PhysicsNumerical
Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the two beams are π/2\pi/2π/2 and π/3\pi/3π/3 at points A and B respectively. The difference between the resultant intensities at the two points is xI. The value of x will be ______ .

Correct answer: 2

Step-by-step solution →
Q23·PhysicsNumerical
To light, a 50 W, 100 V lamp is connected, in series with a capacitor of capacitance 50πx μF\frac{50}{\pi\sqrt{x}}\,\mu\mathrm{F}πx​50​μF, with 200 V, 50Hz AC source. The value of x will be ____ .

Correct answer: 3

Step-by-step solution →
Q24·PhysicsNumerical
A 1 m long copper wire carries a current of 1 A. If the cross section of the wire is 2.0 mm2\mathrm{mm}^{2}mm2 and the resistivity of copper is 1.7×10−8 Ω m1.7 \times 10^{-8}\ \Omega\,\mathrm{m}1.7×10−8 Ωm. the force experienced by moving electron in the wire is ______ × 10−23\times\ 10^{-23}× 10−23 N. (charge on electron =1.6×10−19= 1.6 \times 10^{-19}=1.6×10−19 C)

Correct answer: 136

Step-by-step solution →
Q25·PhysicsNumerical
A long cylindrical volume contains a uniformly distributed charge of density ρ\rhoρ Cm−3\mathrm{Cm}^{-3}Cm−3. The electric field inside the cylindrical volume at a distance x=2ε0ρx = \frac{2\varepsilon_0}{\rho}x=ρ2ε0​​ m from its axis is ______ Vm−1\mathrm{Vm}^{-1}Vm−1

Correct answer: 1

Step-by-step solution →
Q26·PhysicsNumerical
A mass 0.9 kg, attached to a horizontal spring, executes SHM with an amplitude A1A_1A1​. When this mass passes through its mean position, then a smaller mass of 124 g is placed over it and both masses move together with amplitude A2A_2A2​. If the ratio A1A2\frac{A_1}{A_2}A2​A1​​ is αα−1\frac{\alpha}{\alpha-1}α−1α​, then the value of α\alphaα will be ____ .

Correct answer: 16

Step-by-step solution →
Q27·PhysicsNumerical
A square aluminium (shear modulus is 25×109 Nm−225 \times 10^{9}\ \mathrm{Nm}^{-2}25×109 Nm−2) slab of side 60 cm and thickness 15 cm is subjected to a shearing force (on its narrow face) of 18.0×10418.0 \times 10^{4}18.0×104 N. The lower edge is riveted to the floor. The displacement of the upper edge is ____ μ\muμ m.

Correct answer: 48

Step-by-step solution →
Q28·PhysicsNumerical
A pulley of radius 1.5 m is rotated about its axis by a force F=(12t−3t2)F = (12t - 3t^{2})F=(12t−3t2) N applied tangentially (while t is measured in seconds). If moment of inertia of the pulley about its axis of rotation is 4.5 kg m2\mathrm{m}^{2}m2, the number of rotations made by the pulley before its direction of motion is reversed, will be Kπ\frac{K}{\pi}πK​. The value of K is ____ .

Correct answer: 18

Step-by-step solution →
Q29·PhysicsNumerical
A ball of mass m is thrown vertically upward. Another ball of mass 2 m is thrown an angle θ\thetaθ with the vertical. Both the balls stay in air for the same period of time. The ratio of the heights attained by the two balls respectively is 1x\frac{1}{x}x1​. The value of x is ______ .

Correct answer: 1

Step-by-step solution →

Chemistry — JEE Main 27 July 2022 Shift 1

Q30·ChemistrySingle correct
250 g solution of D-glucose in water contains 10.8% of carbon by weight. The molality of the solution is nearest to (Given: Atomic Weights are H, 1u ; C, 12u ; O, 16u)
  1. (A)1.03
  2. (B)2.06
  3. (C)3.09
  4. (D)5.40

Correct answer: (B)

Step-by-step solution →
Q31·ChemistrySingle correct
Given below are two statements. Statement I : O2O_{2}O2​ , Cu2+Cu^{2+}Cu2+ and Fe3+Fe^{3+}Fe3+ are weakly attracted by magnetic field and are magnetized in the same direction as magnetic field. Statement II : NaCl and H2OH_{2}OH2​O are weakly magnetized in opposite direction to magnetic field. In the light of the above statements, choose the most appropriate answer form the options given below :
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Energy of 2s orbital of hydrogen atom is greater than that of 2s orbital of lithium. Reason R : Energies of the orbitals in the same subshell decrease with increase in the atomic number. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false.
  4. (D)A is false but R is true.

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Activated charcoal adsorbs SO2SO_{2}SO2​ more efficiently than CH4CH_{4}CH4​. Reason R : Gases with lower critical temperatures are readily adsorbed by activated charcoal. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Both A and R are correct and R is the correct explanation of A.
  2. (B)Both A and R are correct but R is NOT the correct explanation of A.
  3. (C)A is correct but R is not correct.
  4. (D)A is not correct but R is correct.

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
Boiling point of a 2% aqueous solution of a non-volatile solute A is equal to the boiling point of 8% aqueous solution of a non-volatile solute B. The relation between molecular weights of A and B is.
  1. (A)MA=4MBM_{A} = 4M_{B}MA​=4MB​
  2. (B)MB=4MAM_{B} = 4M_{A}MB​=4MA​
  3. (C)MA=8MBM_{A} = 8M_{B}MA​=8MB​
  4. (D)MB=8MAM_{B} = 8M_{A}MB​=8MA​

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
The incorrect statement is
  1. (A)The first ionization enthalpy of K is less than that of Na and Li
  2. (B)Xe does not have the lowest first ionization enthalpy in its group
  3. (C)The first ionization enthalpy of element with atomic number 37 is lower than that of the element with atomic number 38.
  4. (D)The first ionization enthalpy of Ga is higher than that of the d-block element with atomic number 30.

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
Which of the following methods are not used to refine any metal? (A) Liquation (B) Calcination (C) Electrolysis (D) Leaching (E) Distillation Choose the correct answer from the options given below:
  1. (A)B and D only
  2. (B)A, B, D and E only
  3. (C)B, D and E only
  4. (D)A, C and E only

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
Given below are two statements: Statement I : Hydrogen peroxide can act as an oxidizing agent in both acidic and basic conditions. Statement II: Density of hydrogen peroxide at 298 K is lower than that of D2OD_{2}OD2​O. In the light of the above statements. Choose the correct answer from the options.
  1. (A)Both statement I and Statement II are ture
  2. (B)Both statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Given below are two statements: Statement I : The chlorides of Be and Al have Cl-bridged structure. Both are soluble in organic solvents and act as Lewis bases. Statement II: Hydroxides of Be and Al dissolve in excess alkali to give beryllate and aluminate ions. In the light of the above statements. Choose the correct answer from the options given below.
  1. (A)Both statement I and Statement II are true
  2. (B)Both statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
Which oxoacid of phosphorous has the highest number of oxygen atoms present in its chemical formula?
  1. (A)Pyrophosphorous acid
  2. (B)Hypophosphoric acid
  3. (C)Phosphoric acid
  4. (D)Pyrophosphoric acid

Correct answer: (D)

Step-by-step solution →
Q40·ChemistrySingle correct
Given below are two statements: Statement I : Iron (III) catalyst, acidified K2Cr2O7K_{2}Cr_{2}O_{7}K2​Cr2​O7​ and neutral KMnO4KMnO_{4}KMnO4​ have the ability to oxidise I−I^{-}I− to I2I_{2}I2​ independently. Statement II: Manganate ion is paramagnetic in nature and involves pπ –pπ bonding. In the light of the above statements, choose the correct answer from the options.
  1. (A)Both statement I and Statement II are ture
  2. (B)Both statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
The total number of Mn = O bonds in Mn2O7Mn_{2}O_{7}Mn2​O7​ is ____
  1. (A)4
  2. (B)5
  3. (C)6
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
Match List I with List II Choose the correct answer from the options given below:
List I (Pollutant)List II (Disease /sickness)
A.Sulphate (>500 ppm)I.Methemoglobinemia
B.Nitrate (>50 ppm)II.Brown mottling of teeth
C.Lead (> 50 ppb)III.Laxative effect
D.Fluoride (>2 ppm)IV.Kidney damage
  1. (A)A-IV, B –I, C-II, D-III
  2. (B)A-III, B –I, C-IV, D-II
  3. (C)A-II, B –IV, C-I, D-III
  4. (D)A-II, B –IV, C-III, D-I

Correct answer: (B)

Step-by-step solution →
Q43·Chemistry·AromaticitySingle correct
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : [6] Annulene. [8] Annulene and cis –[10] Annulene, are respectively aromatic, not-aromatic and aromatic. Reason R : Planarity is one of the requirements of aromatic systems. In the light of the above statements, choose the most appropriate answer from the options given below.
  1. (A)Both A and R are correct and R is the correct explanation of A.
  2. (B)Both A and R are correct but R is NOT the correct explanation of A.
  3. (C)A is correct but R is not correct.
  4. (D)A is not correct but R is correct.

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
In the above reaction product B is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q45·ChemistrySingle correct
Match List I with List II Choose the correct answer from the options given below:
List I (Polymers)List II (Commenrcial names)
A.Phenol-formaldehyde resinI.Glyptal
B.Copolymer of 1,3-butadiene and styreneII.Novolac
C.Polyester of glycol and phthalic acidIII.Buna-S
D.Polyester of glycol and terephthalic acidIV.Dacron
  1. (A)A-II, B –III, C-IV, D-I
  2. (B)A-II, B –III, C-I, D-IV
  3. (C)A-II, B –I, C-III, D-IV
  4. (D)A-III, B –II, C-IV, D-I

Correct answer: (B)

Step-by-step solution →
Q46·ChemistrySingle correct
A sugar ‘X’ dehydrates very slowly under acidic condition to give furfural which on further reaction with resorcinol gives the coloured product after sometime. Sugar ‘X’ is
  1. (A)Aldopentose
  2. (B)Aldotetrose
  3. (C)Oxalic acid
  4. (D)Ketotetrose

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
Match List I with List II Choose the correct answer from the options given below:
List IList II
A.see figureI.Anti-depressant
B.see figureII.550 times sweeter than cane sugar
C.see figureIII.Narcotic analgesic
D.see figureIV.Antiseptic
  1. (A)A-IV, B –III, C-II, D-I
  2. (B)A-III, B –I, C-II, D-IV
  3. (C)A-III, B –IV, C-I, D-II
  4. (D)A-III, B –I, C-IV, D-II

Correct answer: (C)

Step-by-step solution →
Q48·ChemistrySingle correct
In Carius method of estimation of halogen. 0.45 g of an organic compound gave 0.36 g of AgBr. Find out the percentage of bromine in the compound. (Molar masses : AgBr = 188 g mol−1mol^{-1}mol−1: Br = 80 g mol−1mol^{-1}mol−1)
  1. (A)34.04%
  2. (B)40.04%
  3. (C)36.03%
  4. (D)38.04%

Correct answer: (A)

Step-by-step solution →
Q49·ChemistrySingle correct
Match List I with List II Choose the correct answer from the options given below:
List IList II
A.Benzenesulphonyl chlorideI.Test for primary amines
B.Hoffmann bromamide reactionII.Anti Saytzeff
C.Carbylamine reactionIII.Hinsberg reagent
D.Hoffmann orientationIV.Known reaction of Isocyanates.
  1. (A)A-IV, B –III, C-II, D-I
  2. (B)A-IV, B –II, C-I, D-III
  3. (C)A-III, B –IV, C-I, D-II
  4. (D)A-IV, B –III, C-I, D-II

Correct answer: (C)

Step-by-step solution →
Q50·ChemistryNumerical
20 mL of 0.02 M K2Cr2O7K_{2}Cr_{2}O_{7}K2​Cr2​O7​ solution is used for the titration of 10 mL of Fe2+Fe^{2+}Fe2+ solution in the acidic medium. The molarity of Fe2+Fe^{2+}Fe2+ solution is ______ ×10−2\times 10^{-2}×10−2 M. (Nearest Integer)

Correct answer: 24

Step-by-step solution →
Q51·ChemistryNumerical
2NO + 2H2H_{2}H2​ → N2N_{2}N2​ + 2H2H_{2}H2​O The above reaction has been studied at 800°C. The related data are given in the table below The order of the reaction with respect to NO is_____
Reaction serial numberInitial pressure of H2H_{2}H2​ / kPaInitial Pressure of NO/ kPaInitial rate (−dpdt)/(kPa/s)\left(\frac{-dp}{dt}\right)/\left(kPa/s\right)(dt−dp​)/(kPa/s)
165.640.00.135
265.620.10.033
338.665.60.214
419.265.60.106

Correct answer: 2

Step-by-step solution →
Q52·ChemistryNumerical
Amongst the following the number of oxide(s) which are paramagnetic in nature is Na2ONa_{2}ONa2​O, KO2KO_{2}KO2​, NO2NO_{2}NO2​, N2ON_{2}ON2​O, ClO2ClO_{2}ClO2​, NO, SO2SO_{2}SO2​, Cl2OCl_{2}OCl2​O

Correct answer: 4

Step-by-step solution →
Q53·ChemistryNumerical
The molar heat capacity for an ideal gas at constant pressure is 20.785 J K−1mol−1K^{-1}mol^{-1}K−1mol−1. The change in internal energy is 5000 J upon heating it from 300K to 500K. The number of moles of the gas at constant volume is ___ [Nearest integer] (Given: R = 8.314 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1)

Correct answer: 2

Step-by-step solution →
Q54·ChemistryNumerical
According to MO theory, number of species/ions from the following having identical bond order is______: CN−CN^{-}CN−, NO+NO^{+}NO+, O2O_{2}O2​, O2+O_{2}^{+}O2+​, O22+O_{2}^{2+}O22+​

Correct answer: 3

Step-by-step solution →
Q55·ChemistryNumerical
At 310 K, the solubility of CaF2CaF_{2}CaF2​ in water is 2.34×10−32.34 \times 10^{-3}2.34×10−3 g /100 mL. The solubility product of CaF2CaF_{2}CaF2​ is ___ ×10−8\times 10^{-8}×10−8 (mol/L)3(mol/L)^{3}(mol/L)3. (Given molar mass : CaF2CaF_{2}CaF2​ = 78 g mol−1mol^{-1}mol−1)

Correct answer: 0

Step-by-step solution →
Q56·ChemistryNumerical
The conductivity of a solution of complex with formula CoCl3(NH3)4CoCl_{3}(NH_{3})_{4}CoCl3​(NH3​)4​ corresponds to 1 : 1 electrolyte, then the primary valency of central metal ion is______

Correct answer: 3

Step-by-step solution →
Q57·ChemistryNumerical
In the titration of KMnO4KMnO_{4}KMnO4​ and oxalic acid in acidic medium, the change in oxidation number of carbon at the end point is______

Correct answer: 1

Step-by-step solution →
Q58·Chemistry·IsomerismNumerical
Optical activity of an enantiomeric mixture is +12.6° and the specific rotation of (+) isomer is +30°. The optical purity is____%

Correct answer: 42

Step-by-step solution →
Q59·ChemistryNumerical
In the following reaction The % yield for reaction I is 60% and that of reaction II is 50%. The overall yield of the complete reaction is ___% [nearest integer]

Correct answer: 30

Step-by-step solution →

Mathematics — JEE Main 27 July 2022 Shift 1

Q60·MathematicsSingle correct
Let R1R_1R1​ and R2R_2R2​ be two relations defined on R\mathbb{R}R by a R1 b⇔ab≥0a\,R_1\,b \Leftrightarrow ab \ge 0aR1​b⇔ab≥0 and a R2 b⇔a≥ba\,R_2\,b \Leftrightarrow a \ge baR2​b⇔a≥b, then
  1. (A)R1R_1R1​ is an equivalence relation but not R2R_2R2​
  2. (B)R2R_2R2​ is an equivalence relation but not R1R_1R1​
  3. (C)both R1R_1R1​ and R2R_2R2​ are equivalence relations
  4. (D)neither R1R_1R1​ nor R2R_2R2​ is an equivalence relation

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
Let f,g:N−{1}→Nf, g : \mathbb{N}-\{1\} \to \mathbb{N}f,g:N−{1}→N be functions defined by f(a)=αf(a) = \alphaf(a)=α, where α\alphaα is the maximum of the powers of those primes p such that pαp^{\alpha}pα divides aaa, and g(a)=a+1g(a) = a+1g(a)=a+1, for all a∈N−{1}a \in \mathbb{N}-\{1\}a∈N−{1}. Then, the function f+gf + gf+g is
  1. (A)one-one but not onto
  2. (B)onto but not one-one
  3. (C)both one-one and onto
  4. (D)neither one-one nor onto

Correct answer: (D)

Step-by-step solution →
Q62·MathematicsSingle correct
Let the minimum value v0v_0v0​ of v=∣z∣2+∣z−3∣2+∣z−6i∣2v = |z|^2 + |z-3|^2 + |z-6i|^2v=∣z∣2+∣z−3∣2+∣z−6i∣2, z∈Cz \in \mathbb{C}z∈C is attained at z=z0z = z_0z=z0​. Then ∣2z02−zˉ03+3∣2+v02\left| 2z_0^2 - \bar{z}_0^3 + 3 \right|^2 + v_0^2​2z02​−zˉ03​+3​2+v02​ is equal to
  1. (A)1000
  2. (B)1024
  3. (C)1105
  4. (D)1196

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
Let A=(12−2−5)A = \begin{pmatrix} 1 & 2 \\ -2 & -5 \end{pmatrix}A=(1−2​2−5​). Let α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R be such that αA2+βA=2I\alpha A^2 + \beta A = 2IαA2+βA=2I. Then α+β\alpha + \betaα+β is equal to -
  1. (A)-10
  2. (B)-6
  3. (C)6
  4. (D)10

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
The remainder when (2021)2022+(2022)2021(2021)^{2022} + (2022)^{2021}(2021)2022+(2022)2021 is divided by 7 is
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
Suppose a1,a2a_1, a_2a1​,a2​, ...., ana_nan​,... be an arithmetic progression of natural numbers. If the ratio of the sum of the first five terms of the sum of first nine terms of the progression is 5 : 17 and 110<a15<120110 < a_{15} < 120110<a15​<120, then the sum of the first ten terms of the progression is equal to -
  1. (A)290
  2. (B)380
  3. (C)460
  4. (D)510

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be a function defined as f(x)=asin⁡(π[x]2)+[2−x]f(x) = a\sin\left(\frac{\pi[x]}{2}\right) + [2-x]f(x)=asin(2π[x]​)+[2−x], a∈Ra \in \mathbb{R}a∈R, where [t] is the greatest integer less than or equal to ttt. If lim⁡x→−1f(x)\lim_{x \to -1} f(x)limx→−1​f(x) exists, then the value of ∫04f(x) dx\int_{0}^{4} f(x)\,dx∫04​f(x)dx is equal to :
  1. (A)-1
  2. (B)-2
  3. (C)1
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
I=∫π/4π/3(8sin⁡x−sin⁡2xx)dxI = \int_{\pi/4}^{\pi/3}\left(\frac{8\sin x - \sin 2x}{x}\right)dxI=∫π/4π/3​(x8sinx−sin2x​)dx. Then
  1. (A)π2<I<3π4\frac{\pi}{2} < I < \frac{3\pi}{4}2π​<I<43π​
  2. (B)π5<I<5π12\frac{\pi}{5} < I < \frac{5\pi}{12}5π​<I<125π​
  3. (C)5π12<I<23π\frac{5\pi}{12} < I < \frac{\sqrt{2}}{3}\pi125π​<I<32​​π
  4. (D)3π4<I<π\frac{3\pi}{4} < I < \pi43π​<I<π

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
The area of the smaller region enclosed by the curves y2=8x+4y^2 = 8x + 4y2=8x+4 and x2+y2+43x−4=0x^2 + y^2 + 4\sqrt{3}x - 4 = 0x2+y2+43​x−4=0 is equal to
  1. (A)13(2−123+8π)\frac{1}{3}\left(2 - 12\sqrt{3} + 8\pi\right)31​(2−123​+8π)
  2. (B)13(2−123+6π)\frac{1}{3}\left(2 - 12\sqrt{3} + 6\pi\right)31​(2−123​+6π)
  3. (C)13(4−123+8π)\frac{1}{3}\left(4 - 12\sqrt{3} + 8\pi\right)31​(4−123​+8π)
  4. (D)13(4−123+6π)\frac{1}{3}\left(4 - 12\sqrt{3} + 6\pi\right)31​(4−123​+6π)

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
Let y=y1(x)y = y_1(x)y=y1​(x) and y=y2(x)y = y_2(x)y=y2​(x) be two distinct solutions of the differential equation dydx=x+y\frac{dy}{dx} = x + ydxdy​=x+y, with y1(0)=0y_1(0) = 0y1​(0)=0 and y2(0)=1y_2(0) = 1y2​(0)=1 respectively. Then, the number of points of intersection of y=y1(x)y = y_1(x)y=y1​(x) and y=y2(x)y = y_2(x)y=y2​(x) is
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
Let P (a,b)(a, b)(a,b) be a point on the parabola y2=8xy^2 = 8xy2=8x such that the tangent at P passes through the centre of the circle x2+y2−10x−14y+65=0x^2 + y^2 - 10x - 14y + 65 = 0x2+y2−10x−14y+65=0. Let A be the product of all possible values of aaa and BBB be the product of all possible values of bbb. Then the value of A + B is equal to :
  1. (A)0
  2. (B)25
  3. (C)40
  4. (D)65

Correct answer: (D)

Step-by-step solution →
Q71·MathematicsSingle correct
Let a⃗=αi^+j^+βk^\vec{a} = \alpha\hat{i} + \hat{j} + \beta\hat{k}a=αi^+j^​+βk^ and b⃗=3i^−5j^+4k^\vec{b} = 3\hat{i} - 5\hat{j} + 4\hat{k}b=3i^−5j^​+4k^ be two vectors, such that a⃗×b⃗=−i^+9i^+12k\vec{a} \times \vec{b} = -\hat{i} + 9\hat{i} + 12ka×b=−i^+9i^+12k. Then the projection of b⃗−2a⃗\vec{b} - 2\vec{a}b−2a on b⃗+a⃗\vec{b} + \vec{a}b+a is equal to
  1. (A)2
  2. (B)395\frac{39}{5}539​
  3. (C)9
  4. (D)465\frac{46}{5}546​

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
Let a⃗=2i^−j^+5k^\vec{a} = 2\hat{i} - \hat{j} + 5\hat{k}a=2i^−j^​+5k^ and b⃗=αi^+βj^+2k^\vec{b} = \alpha\hat{i} + \beta\hat{j} + 2\hat{k}b=αi^+βj^​+2k^. If ((a⃗×b⃗)×i^).k^=232\left(\left(\vec{a} \times \vec{b}\right) \times \hat{i}\right).\hat{k} = \frac{23}{2}((a×b)×i^).k^=223​, then ∣b⃗×2j^∣\left| \vec{b} \times 2\hat{j} \right|​b×2j^​​ is equal to
  1. (A)4
  2. (B)5
  3. (C)21\sqrt{21}21​
  4. (D)17\sqrt{17}17​

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
Let S be the sample space of all five digit numbers. If ppp is the probability that a randomly selected number from S, is a multiple of 7 but not divisible by 5, then 9p9p9p is equal to
  1. (A)1.0146
  2. (B)1.2085
  3. (C)1.0285
  4. (D)1.1521

Correct answer: (C)

Step-by-step solution →
Q74·MathematicsSingle correct
Let a vertical tower AB of height 2h2h2h stands on a horizontal ground. Let from a point P on the ground a man can see upto height hhh of the tower with an angle of elevation 2α2\alpha2α. When from PPP, he moves a distance d in the direction of AP→\overrightarrow{AP}AP, he can see the top B of the tower with an angle of elevation α\alphaα. If d=7hd = \sqrt{7}hd=7​h, then tan⁡α\tan\alphatanα is equal to
  1. (A)5−2\sqrt{5} - 25​−2
  2. (B)3−1\sqrt{3} - 13​−1
  3. (C)7−2\sqrt{7} - 27​−2
  4. (D)7−3\sqrt{7} - \sqrt{3}7​−3​

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
(p∧r)⇔(p∧(∼q))\left(p\wedge r\right)\Leftrightarrow\left(p\wedge\left(\sim q\right)\right)(p∧r)⇔(p∧(∼q)) is equivalent to (∼p)\left(\sim p\right)(∼p) when r is
  1. (A)ppp
  2. (B)∼p\sim p∼p
  3. (C)qqq
  4. (D)∼q\sim q∼q

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsSingle correct
If the plane P passes through the intersection of two mutually perpendicular planes 2x + ky − 5z = 1 and 3kx − ky + z = 5, k < 3 and intercepts a unit length on positive x-axis, then the intercept made by the plane P on the y-axis is
  1. (A)111\frac{1}{11}111​
  2. (B)511\frac{5}{11}115​
  3. (C)6
  4. (D)7

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
Let A(1, 1), B(-4, 3) C(-2, -5) be vertices of a triangle ABC, P be a point on side BC, and Δ1\Delta_{1}Δ1​ and Δ2\Delta_{2}Δ2​ be the areas of triangle APB and ABC. Respectively. If Δ1:Δ2=4:7\Delta_{1}:\Delta_{2}=4:7Δ1​:Δ2​=4:7, then the area enclosed by the lines AP, AC and the x-axis is
  1. (A)14\frac{1}{4}41​
  2. (B)34\frac{3}{4}43​
  3. (C)12\frac{1}{2}21​
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
If the circle x2+y2−2gx+6y−19c=0x^{2}+y^{2}-2gx+6y-19c=0x2+y2−2gx+6y−19c=0, g,c∈Rg,c\in\mathbb{R}g,c∈R passes through the point (6, 1) and its centre lies on the line x − 2cy = 8, then the length of intercept made by the circle on x-axis is
  1. (A)11\sqrt{11}11​
  2. (B)4
  3. (C)3
  4. (D)2232\sqrt{23}223​

Correct answer: (D)

Step-by-step solution →
Q79·Mathematics·Limits and ContinuitySingle correct
Let a function f:R→Rf:\mathbb{R}\rightarrow\mathbb{R}f:R→R be defined as : f(x)={∫0x(5−∣t−3∣)dt,x>4x2+bx,x≤4f\left(x\right)=\begin{cases}\int_{0}^{x}\left(5-\left|t-3\right|\right)dt, & x>4\\ x^{2}+bx, & x\le 4\end{cases}f(x)={∫0x​(5−∣t−3∣)dt,x2+bx,​x>4x≤4​ where b∈Rb\in\mathbb{R}b∈R. If fff is continuous at x = 4, then which of the following statements is NOT true ?
  1. (A)fff is not differentiable at x = 4
  2. (B)f ′(3)+f ′(5)=354f\,'\left(3\right)+f\,'\left(5\right)=\frac{35}{4}f′(3)+f′(5)=435​
  3. (C)fff is increasing in (−∞,18)∪(8,∞)\left(-\infty,\frac{1}{8}\right)\cup\left(8,\infty\right)(−∞,81​)∪(8,∞)
  4. (D)fff has a local minima at x=18x=\frac{1}{8}x=81​

Correct answer: (C)

Step-by-step solution →
Q80·MathematicsNumerical
For k∈Rk\in\mathbb{R}k∈R, let the solutions of the equation cos⁡(sin⁡−1(xcot⁡(tan⁡−1(cos⁡(sin⁡−1x)))))=k,  0<∣x∣<12\cos\left(\sin^{-1}\left(x\cot\left(\tan^{-1}\left(\cos\left(\sin^{-1}x\right)\right)\right)\right)\right)=k,\;0<\left|x\right|<\frac{1}{\sqrt{2}}cos(sin−1(xcot(tan−1(cos(sin−1x)))))=k,0<∣x∣<2​1​ be α\alphaα and β\betaβ, where the inverse trigonometric functions take only principal values. If the solutions of the equation x2−bx−5=0x^{2}-bx-5=0x2−bx−5=0 are 1α2+1β2\frac{1}{\alpha^{2}}+\frac{1}{\beta^{2}}α21​+β21​ and αβ\frac{\alpha}{\beta}βα​, then bk2\frac{b}{k^{2}}k2b​ is equal to ______.

Correct answer: 12

Step-by-step solution →
Q81·MathematicsNumerical
The mean and variance of 10 observations were calculated as 15 and 15 respectively by a student who took by mistake 25 instead of 15 for one observation. Then, the correct standard deviation is __________.

Correct answer: 2

Step-by-step solution →
Q82·MathematicsNumerical
Let the line x−37=y−2−1=z−3−4\frac{x-3}{7}=\frac{y-2}{-1}=\frac{z-3}{-4}7x−3​=−1y−2​=−4z−3​ intersect the plane containing the lines x−41=y+1−2=z1\frac{x-4}{1}=\frac{y+1}{-2}=\frac{z}{1}1x−4​=−2y+1​=1z​ and 4ax−y+5z−7a=0=2x−5y−z−34ax-y+5z-7a=0=2x-5y-z-34ax−y+5z−7a=0=2x−5y−z−3, a∈Ra\in\mathbb{R}a∈R at the point P(α,β,γ)P\left(\alpha,\beta,\gamma\right)P(α,β,γ). Then the value of α+β+γ\alpha+\beta+\gammaα+β+γ equals ______.

Correct answer: 12

Step-by-step solution →
Q83·MathematicsNumerical
An ellipse E:x2a2+y2b2=1E:\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1E:a2x2​+b2y2​=1 passes through the vertices of the hyperbola H:x249−y264=−1H:\frac{x^{2}}{49}-\frac{y^{2}}{64}=-1H:49x2​−64y2​=−1. Let the major and minor axes of the ellipse E coincide with the transverse and conjugate axes of the hyperbola H. Let the product of the eccentricities of E and H be 12\frac{1}{2}21​. If lll is the length of the latus rectum of the ellipse E, then the value of 113l113l113l is equal to ______.

Correct answer: 1552

Step-by-step solution →
Q84·MathematicsNumerical
Let y = y(x) be the solution curve of the differential equation sin⁡(2x2)log⁡e(tan⁡x2)dy+(4xy−42xsin⁡(x2−π4))dx=0\sin\left(2x^{2}\right)\log_{e}\left(\tan x^{2}\right)dy+\left(4xy-4\sqrt{2}x\sin\left(x^{2}-\frac{\pi}{4}\right)\right)dx=0sin(2x2)loge​(tanx2)dy+(4xy−42​xsin(x2−4π​))dx=0, 0<x<π20<x<\sqrt{\frac{\pi}{2}}0<x<2π​​, which passes through the point (π6,1)\left(\sqrt{\frac{\pi}{6}},1\right)(6π​​,1). Then ∣y(π3)∣\left|y\left(\sqrt{\frac{\pi}{3}}\right)\right|​y(3π​​)​ is equal to ______.

Correct answer: 1

Step-by-step solution →
Q85·MathematicsNumerical
Let MMM and NNN be the number of points on the curve y5−9xy+2x=0y^{5}-9xy+2x=0y5−9xy+2x=0, where the tangents to the curve are parallel to x-axis and y-axis, respectively. Then the value of M + N equals ________.

Correct answer: 2

Step-by-step solution →
Q86·MathematicsNumerical
Let f(x)=2x2−x−1f\left(x\right)=2x^{2}-x-1f(x)=2x2−x−1 and S={n∈Z:∣f(n)∣≤800}S=\left\{n\in\mathbb{Z}:\left|f\left(n\right)\right|\le 800\right\}S={n∈Z:∣f(n)∣≤800}. Then, the value of ∑n∈Sf(n)\sum_{n\in S}f\left(n\right)∑n∈S​f(n) is equal to ________.

Correct answer: 10620

Step-by-step solution →
Q87·MathematicsNumerical
Let S be the set containing all 3×33\times 33×3 matrices with entries from {−1, 0, 1}\{-1,\,0,\,1\}{−1,0,1}. The total number of matrices A∈SA\in SA∈S such that the sum of all the diagonal elements of ATAA^{T}AATA is 6 is __________.

Correct answer: 5376

Step-by-step solution →
Q88·MathematicsNumerical
If the length of the latus rectum of the ellipse x2+4y2+2x+8y−λ=0x^{2}+4y^{2}+2x+8y-\lambda=0x2+4y2+2x+8y−λ=0 is 4, and lll is the length of its major axis, then λ+l\lambda+lλ+l is equal to ______.

Correct answer: 75

Step-by-step solution →
Q89·MathematicsNumerical
Let S={z∈C:z2+zˉ=0}S=\left\{z\in\mathbb{C}:z^{2}+\bar{z}=0\right\}S={z∈C:z2+zˉ=0}. Then ∑z∈S(Re(z)+Im(z))\sum_{z\in S}\left(\mathrm{Re}\left(z\right)+\mathrm{Im}\left(z\right)\right)∑z∈S​(Re(z)+Im(z)) is equal to ______.

Correct answer: 0

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Experimental Skills 68/186
  • Polymers 64/186
  • Chemistry in Everyday Life 60/186
  • Isomerism 51/186
  • Magnetism and Matter 50/186
  • Aromaticity 22/186
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