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JEE Main 29 January 2023 Shift 1 Question Paper with Answers

29 January 2023 · January session · 90 questions

The complete JEE Main 29 January 2023 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 29 January 2023 Shift 1

Q1·PhysicsSingle correct
Find the mutual inductance in the arrangement, when a small circular loop of wire of radius RRR is placed inside a large square loop of wire of side LLL (L≫RL \gg RL≫R). The loops are coplanar and their centers coincide:
  1. (A)M=2 μ0R2LM=\dfrac{\sqrt{2}\,\mu_0 R^2}{L}M=L2​μ0​R2​
  2. (B)M=22 μ0RL2M=\dfrac{2\sqrt{2}\,\mu_0 R}{L^2}M=L222​μ0​R​
  3. (C)M=2 μ0RL2M=\dfrac{\sqrt{2}\,\mu_0 R}{L^2}M=L22​μ0​R​
  4. (D)M=22 μ0R2LM=\dfrac{2\sqrt{2}\,\mu_0 R^2}{L}M=L22​μ0​R2​

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
The threshold wavelength for photoelectric emission from a material is 5500 Å. Photoelectrons will be emitted, when this material is illuminated with monochromatic radiation from a: (A) 75 W infra-red lamp (B) 10 W infra-red lamp (C) 75 W ultra-violet lamp (D) 10 W ultra-violet lamp. Choose the correct answer from the options given below:
  1. (A)B and C only
  2. (B)A and D only
  3. (C)C only
  4. (D)C and D only

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
Match List I with List II and choose the correct answer from the options given below:
List I (Physical Quantity)List II (Dimensional Formula)
A.Pressure gradientI.[M0L2T−2][M^0 L^2 T^{-2}][M0L2T−2]
B.Energy densityII.[M1L−1T−2][M^1 L^{-1} T^{-2}][M1L−1T−2]
C.Electric FieldIII.[M1L−2T−2][M^1 L^{-2} T^{-2}][M1L−2T−2]
D.Latent heatIV.[M1L1T−3A−1][M^1 L^1 T^{-3} A^{-1}][M1L1T−3A−1]
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-II, B-III, C-IV, D-I
  3. (C)A-III, B-II, C-IV, D-I
  4. (D)A-III, B-II, C-I, D-IV

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
In a cuboid of dimension 2L×2L×L2L \times 2L \times L2L×2L×L, a charge qqq is placed at the center of the surface 'SSS' having area 4L24L^24L2. The flux through the opposite surface to 'SSS' is given by:
  1. (A)q12ε0\dfrac{q}{12\varepsilon_0}12ε0​q​
  2. (B)q6ε0\dfrac{q}{6\varepsilon_0}6ε0​q​
  3. (C)q3ε0\dfrac{q}{3\varepsilon_0}3ε0​q​
  4. (D)q2ε0\dfrac{q}{2\varepsilon_0}2ε0​q​

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
A person observes two moving trains, 'A' reaching the station and 'B' leaving the station with equal speed of 30 m/s. If both trains emit sounds with frequency 300 Hz (speed of sound = 330 m/s), the approximate difference of frequencies heard by the person will be:
  1. (A)55 Hz
  2. (B)80 Hz
  3. (C)33 Hz
  4. (D)10 Hz

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
A block of mass mmm slides down the plane inclined at angle 30∘30^\circ30∘ with an acceleration g4\dfrac{g}{4}4g​. The value of coefficient of kinetic friction will be:
  1. (A)123\dfrac{1}{2\sqrt{3}}23​1​
  2. (B)32\dfrac{\sqrt{3}}{2}23​​
  3. (C)23+12\dfrac{2\sqrt{3}+1}{2}223​+1​
  4. (D)23−12\dfrac{2\sqrt{3}-1}{2}223​−1​

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
A bicycle tyre is filled with air having pressure of 270 kPa at 27 °C. The approximate pressure of the air in the tyre when the temperature increases to 36 °C is:
  1. (A)270 kPa
  2. (B)262 kPa
  3. (C)360 kPa
  4. (D)278 kPa

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
A single current carrying loop of wire carrying current III flowing in anticlockwise direction seen from +z+z+z direction and lying in the xyxyxy plane is shown in figure. The plot of j^\hat{j}j^​ component of magnetic field (ByB_yBy​) at a distance 'aaa' (less than radius of the coil) and on the yzyzyz plane vs zzz coordinate looks like:
  1. (A)(graph 1)
  2. (B)(graph 2)
  3. (C)(graph 3)
  4. (D)(graph 4)

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
Surface tension of a soap bubble is 2.0×10−22.0 \times 10^{-2}2.0×10−2 N m−1^{-1}−1. Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be: (Take π=227\pi = \dfrac{22}{7}π=722​)
  1. (A)9.24×10−49.24 \times 10^{-4}9.24×10−4 J
  2. (B)5.76×10−45.76 \times 10^{-4}5.76×10−4 J
  3. (C)0.72×10−40.72 \times 10^{-4}0.72×10−4 J
  4. (D)18.48×10−418.48 \times 10^{-4}18.48×10−4 J

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: If dQdQdQ and dWdWdW represent the heat supplied to the system and the work done on the system respectively, then according to the first law of thermodynamics dQ=dU−dWdQ = dU - dWdQ=dU−dW. Reason R: First law of thermodynamics is based on law of conservation of energy. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)A is not correct but R is correct
  3. (C)A is correct but R is not correct
  4. (D)Both A and R are correct but R is not the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
If a radioactive element having half-life of 30 min is undergoing beta decay, the fraction of radioactive element remains undecayed after 90 min will be:
  1. (A)18\dfrac{1}{8}81​
  2. (B)12\dfrac{1}{2}21​
  3. (C)14\dfrac{1}{4}41​
  4. (D)116\dfrac{1}{16}161​

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Two particles of equal mass 'mmm' move in a circle of radius 'rrr' under the action of their mutual gravitational attraction. The speed of each particle will be:
  1. (A)4Gmr\sqrt{\dfrac{4Gm}{r}}r4Gm​​
  2. (B)Gm4r\sqrt{\dfrac{Gm}{4r}}4rGm​​
  3. (C)Gmr\sqrt{\dfrac{Gm}{r}}rGm​​
  4. (D)Gm2r\sqrt{\dfrac{Gm}{2r}}2rGm​​

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
If the height of transmitting and receiving antennas are 80 m each, the maximum line of sight distance will be: (Given: Earth's radius = 6.4×1066.4 \times 10^66.4×106 m)
  1. (A)28 km
  2. (B)36 km
  3. (C)32 km
  4. (D)64 km

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
A car is moving on a horizontal curved road with radius 50 m. The approximate maximum speed of the car will be, if friction between tyres and road is 0.34. [take g=10g = 10g=10 ms−2^{-2}−2]
  1. (A)17 ms−1^{-1}−1
  2. (B)13 ms−1^{-1}−1
  3. (C)22.4 ms−1^{-1}−1
  4. (D)3.4 ms−1^{-1}−1

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Ratio of thermal energy released in two resistors RRR and 3R3R3R connected in parallel in an electric circuit is:
  1. (A)1 : 27
  2. (B)1 : 1
  3. (C)1 : 3
  4. (D)3 : 1

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
A stone is projected at angle 30∘30^\circ30∘ to the horizontal. The ratio of kinetic energy of the stone at point of projection to its kinetic energy at the highest point of flight will be:
  1. (A)1 : 2
  2. (B)1 : 4
  3. (C)4 : 1
  4. (D)4 : 3

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
Which of the following are true? A. Speed of light in vacuum is dependent on the direction of propagation. B. Speed of light in a medium is independent of the wavelength of light. C. The speed of light is independent of the motion of the source. D. The speed of light in a medium is independent of intensity. Choose the correct answer from the options given below:
  1. (A)C and D only
  2. (B)B and C only
  3. (C)A and C only
  4. (D)B and D only

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
In a Young's double slit experiment, two slits are illuminated with a light of wavelength 800 nm. The line joining A1PA_1PA1​P is perpendicular to A1A2A_1A_2A1​A2​ as shown in the figure. If the first minimum is detected at PPP, the value of slits separation 'aaa' will be: (The distance of screen from slits D=5D = 5D=5 cm)
  1. (A)0.5 mm
  2. (B)0.1 mm
  3. (C)0.4 mm
  4. (D)0.2 mm

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
Which one of the following statements is not correct in the case of light emitting diodes? A. It is a heavily doped p-n junction. B. It emits light only when it is forward biased. C. It emits light only when it is reverse biased. D. The energy of the light emitted is equal to or slightly less than the energy gap of the semiconductor used. Choose the correct answer from the options given below:
  1. (A)A
  2. (B)C and D
  3. (C)C
  4. (D)B

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
The magnitude of magnetic induction at mid point OOO due to the current arrangement as shown in the figure will be:
  1. (A)μ0Iπa\dfrac{\mu_0 I}{\pi a}πaμ0​I​
  2. (B)μ0I2πa\dfrac{\mu_0 I}{2\pi a}2πaμ0​I​
  3. (C)000
  4. (D)μ0I4πa\dfrac{\mu_0 I}{4\pi a}4πaμ0​I​

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
As shown in the figure, three identical polaroids P1P_1P1​, P2P_2P2​ and P3P_3P3​ are placed one after another. The pass axis of P2P_2P2​ and P3P_3P3​ are inclined at angle of 60∘60^\circ60∘ and 90∘90^\circ90∘ with respect to the axis of P1P_1P1​. The source SSS has an intensity of 256 Wm2256\ \dfrac{W}{m^2}256 m2W​. The intensity of light at point OOO is ________ Wm2\dfrac{W}{m^2}m2W​.

Correct answer: 24

Step-by-step solution →
Q22·PhysicsNumerical
A 0.4 kg mass takes 8 s to reach the ground when dropped from a certain height 'PPP' above the surface of earth. The loss of potential energy in the last second of fall is ________ J. (Take g=10g = 10g=10 m/s2^22)

Correct answer: 300

Step-by-step solution →
Q23·PhysicsNumerical
Two simple harmonic waves having equal amplitudes of 8 cm and equal frequency of 10 Hz are moving along the same direction. The resultant amplitude is also 8 cm. The phase difference between the individual waves is ________ degree.

Correct answer: 120

Step-by-step solution →
Q24·PhysicsNumerical
A tennis ball is dropped on to the floor from a height of 9.8 m. It rebounds to a height 5.0 m. The ball comes in contact with the floor for 0.2 s. The average acceleration during contact is ________ ms−2^{-2}−2. (Given g=10g = 10g=10 ms−2^{-2}−2)

Correct answer: 120

Step-by-step solution →
Q25·PhysicsNumerical
A certain elastic conducting material is stretched into a circular loop. It is placed with its plane perpendicular to a uniform magnetic field B=0.8B = 0.8B=0.8 T. When released the radius of the loop starts shrinking at a constant rate of 2 cm s−1^{-1}−1. The induced emf in the loop at an instant when the radius of the loop is 10 cm will be ________ mV.

Correct answer: 10

Step-by-step solution →
Q26·PhysicsNumerical
A solid sphere of mass 2 kg is making pure rolling on a horizontal surface with kinetic energy 2240 J. The velocity of centre of mass of the sphere will be ________ ms−1^{-1}−1.

Correct answer: 40

Step-by-step solution →
Q27·PhysicsNumerical
A body cools from 60∘60^\circ60∘C to 40∘40^\circ40∘C in 6 minutes. If the temperature of surroundings is 10∘10^\circ10∘C, then after the next 6 minutes its temperature will be ________ ∘^\circ∘C.

Correct answer: 28

Step-by-step solution →
Q28·PhysicsNumerical
In a metre bridge experiment the balance point is obtained when the gaps are closed by 2 Ω2\,\Omega2Ω and 3 Ω3\,\Omega3Ω. A shunt of XXX is added to the 3 Ω3\,\Omega3Ω resistor to shift the balancing point by 22.5 cm. The value of XXX is ________ Ω\OmegaΩ.

Correct answer: 2

Step-by-step solution →
Q29·PhysicsNumerical
A point charge q1=4q0q_1 = 4q_0q1​=4q0​ is placed at the origin. Another point charge q2=−q0q_2 = -q_0q2​=−q0​ is placed at x=12x = 12x=12 cm. The charge of a proton is q0q_0q0​. The proton is placed on the x-axis so that the electrostatic force on the proton is zero. In this situation, the position of the proton from the origin is ________ cm.

Correct answer: 24

Step-by-step solution →
Q30·PhysicsNumerical
A radioactive element 92242X_{92}^{242}X92242​X emits two α\alphaα-particles, one electron and two positrons. The product nucleus is represented by P234Y_{P}^{234}YP234​Y. The value of PPP is ________ .

Correct answer: 87

Step-by-step solution →

Chemistry — JEE Main 29 January 2023 Shift 1

Q31·ChemistrySingle correct
"A" obtained by Ostwald's method involving air oxidation of NH3_33​, upon further air oxidation produces "B". "B" on hydration forms an oxoacid of Nitrogen along with evolution of "A". The oxoacid also produces "A" and gives positive brown ring test. Identify A and B, respectively.
  1. (A)N2_22​O3_33​, NO2_22​
  2. (B)NO2_22​, N2_22​O4_44​
  3. (C)NO2_22​, N2_22​O5_55​
  4. (D)NO, NO2_22​

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Correct statement about smog is:
  1. (A)Classical smog also has high concentration of oxidizing agents
  2. (B)Both NO2_22​ and SO2_22​ are present in classical smog
  3. (C)NO2_22​ is present in classical smog
  4. (D)Photochemical smog has high concentration of oxidizing agents

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
The standard electrode potential (M3+/M2+M^{3+}/M^{2+}M3+/M2+) for V, Cr, Mn and Co are −0.26-0.26−0.26 V, −0.41-0.41−0.41 V, +1.57+1.57+1.57 V and +1.97+1.97+1.97 V, respectively. The metal ions which can liberate H2_22​ from a dilute acid are:
  1. (A)Mn2+^{2+}2+ and Co2+^{2+}2+
  2. (B)Cr2+^{2+}2+ and Co2+^{2+}2+
  3. (C)V2+^{2+}2+ and Cr2+^{2+}2+
  4. (D)V2+^{2+}2+ and Mn2+^{2+}2+

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
The shortest wavelength of hydrogen atom in Lyman series is λ\lambdaλ. The longest wavelength in Balmer series of He+^++ is:
  1. (A)36λ5\dfrac{36\lambda}{5}536λ​
  2. (B)9λ5\dfrac{9\lambda}{5}59λ​
  3. (C)59λ\dfrac{5}{9\lambda}9λ5​
  4. (D)5λ9\dfrac{5\lambda}{9}95λ​

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
The bond dissociation energy is highest for:
  1. (A)F2_22​
  2. (B)Br2_22​
  3. (C)I2_22​
  4. (D)Cl2_22​

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
The increasing order of pKa for the following phenols is: (A) 2,4-Dinitrophenol (B) 4-Nitrophenol (C) 2,4,5-Trimethylphenol (D) Phenol (E) 3-Chlorophenol. Choose the correct answer from the option given below:
  1. (A)(A), (B), (E), (D), (C)
  2. (B)(C), (D), (E), (B), (A)
  3. (C)(A), (E), (B), (D), (C)
  4. (D)(C), (E), (D), (B), (A)

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
For 1 mol of gas, the plot of pVpVpV vs ppp is shown in the figure. ppp is the pressure and VVV is the volume of the gas. What is the value of compressibility factor at point A?
  1. (A)1+aRTV1 + \dfrac{a}{RTV}1+RTVa​
  2. (B)1−aRTV1 - \dfrac{a}{RTV}1−RTVa​
  3. (C)1+bV1 + \dfrac{b}{V}1+Vb​
  4. (D)1−bV1 - \dfrac{b}{V}1−Vb​

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
Match List I (Antimicrobials) with List II (Names). Choose the correct answer from the options given below:
List I (Antimicrobials)List II (Names)
A.Narrow Spectrum AntibioticI.Furacin
B.AntisepticII.Sulphur dioxide
C.DisinfectantsIII.Penicillin G
D.Broad spectrum antibioticIV.Chloramphenicol
  1. (A)(A)-II, (B)-I, (C)-IV, (D)-III
  2. (B)(A)-I, (B)-II, (C)-IV, (D)-III
  3. (C)(A)-II, (B)-I, (C)-IV, (D)-II
  4. (D)(A)-III, (B)-I, (C)-II, (D)-IV

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
During the borax bead test with CuSO4_44​, a blue green colour of the bead was observed in oxidising flame due to the formation of:
  1. (A)CuO
  2. (B)Cu(BO2_22​)2_22​
  3. (C)Cu3_33​B2_22​
  4. (D)Cu

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Which of the following salt solution would coagulate the colloid solution formed when FeCl3_33​ is added to NaOH solution, at the fastest rate?
  1. (A)10 mL of 0.1 mol dm−3^{-3}−3 Na2_22​SO4_44​
  2. (B)10 mL of 0.2 mol dm−3^{-3}−3 AlCl3_33​
  3. (C)10 mL of 0.1 mol dm−3^{-3}−3 Ca3_33​(PO4_44​)2_22​
  4. (D)10 mL of 0.15 mol dm−3^{-3}−3 CaCl2_22​

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Number of cyclic tripeptides formed with 2 amino acids A and B is:
  1. (A)5
  2. (B)2
  3. (C)4
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
The correct order of hydration enthalpies is: (A) K+^++ (B) Rb+^++ (C) Mg2+^{2+}2+ (D) Cs+^++ (E) Ca2+^{2+}2+. Choose the correct answer from the options given below:
  1. (A)E > C > A > B > D
  2. (B)C > A > E > B > D
  3. (C)C > E > A > D > B
  4. (D)C > E > A > B > D

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
Chiral complex from the following is: (Here en = ethylene diamine)
  1. (A)cis-[PtCl2_22​(en)2_22​]2+^{2+}2+
  2. (B)trans-[PtCl2_22​(en)2_22​]2+^{2+}2+
  3. (C)cis-[PtCl2_22​(NH3_33​)2_22​]
  4. (D)trans-[Co(NH3_33​)4_44​Cl2_22​]+^++

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
Identify the correct order for the given property for following compounds. (A) Boiling Point: (B) Density: (C) Boiling Point: (D) Density: (E) Boiling Point: Choose the correct answer from the option given below:
  1. (A)(B), (C) and (D) only
  2. (B)(A), (C) and (D) only
  3. (C)(A), (B) and (E) only
  4. (D)(A), (C) and (E) only

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
The magnetic behavior of Li2_22​O, Na2_22​O2_22​ and KO2_22​, respectively, are:
  1. (A)Paramagnetic, paramagnetic and diamagnetic
  2. (B)diamagnetic, paramagnetic and diamagnetic
  3. (C)paramagnetic, diamagnetic and paramagnetic
  4. (D)diamagnetic, diamagnetic and paramagnetic

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
The reaction representing the Mond process for metal refining is:
  1. (A)ZnO + C →Δ\xrightarrow{\Delta}Δ​ Zn + CO
  2. (B)Zr + 2I2_22​ →Δ\xrightarrow{\Delta}Δ​ ZrI4_44​
  3. (C)2K[Au(CN)2_22​] + Zn →Δ\xrightarrow{\Delta}Δ​ K2_22​[Zn(CN)4_44​] + 2Au
  4. (D)Ni + 4CO →Δ\xrightarrow{\Delta}Δ​ Ni(CO)4_44​

Correct answer: (D)

Step-by-step solution →
Q47·ChemistrySingle correct
Which of the given compounds can enhance the efficiency of hydrogen storage tank?
  1. (A)Di-isobutylaluminium hydride
  2. (B)NaNi5_55​
  3. (C)Li/P4_44​
  4. (D)SiH4_44​

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
Match List I (Reaction) with List II (Reagents). Choose the correct answer from the options given below:
List I (Reaction)List II (Reagents)
A.Hoffmann DegradationI.Conc. KOH, Δ\DeltaΔ
B.Clemmensen reductionII.CHCl3_33​, NaOH/H3_33​O+^++
C.Cannizzaro reactionIII.Br2_22​, NaOH
D.Reimer-Tiemann ReactionIV.Zn-Hg/HCl
  1. (A)(A)-III, (B)-IV, (C)-I, (D)-II
  2. (B)(A)-II, (B)-I, (C)-III, (D)-IV
  3. (C)(A)-III, (B)-IV, (C)-II, (D)-I
  4. (D)(A)-II, (B)-IV, (C)-I, (D)-III

Correct answer: (A)

Step-by-step solution →
Q49·ChemistrySingle correct
The major product ‘P’ for the following sequence of reactions is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q50·ChemistrySingle correct
Compound that will give positive Lassaigne’s test for both nitrogen and halogen is:
  1. (A)NH2_22​OH.HCl
  2. (B)CH3_33​NH2_22​.HCl
  3. (C)NH4_44​Cl
  4. (D)N2_22​H4_44​.HCl

Correct answer: (B)

Step-by-step solution →
Q51·ChemistryNumerical
Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is x×10−1x \times 10^{-1}x×10−1. The value of xxx is ________ (Nearest integer). Assume complete dissociation.

Correct answer: 5

Step-by-step solution →
Q52·ChemistryNumerical
Water decomposes at 2300 K: H2_22​O(g) →\rightarrow→ H2_22​(g) + 12\dfrac{1}{2}21​O2_22​(g). The percent of water decomposing at 2300 K and 1 bar is ________ (Nearest integer). Equilibrium constant for the reaction is 2×10−32 \times 10^{-3}2×10−3 at 2300 K.

Correct answer: 2

Step-by-step solution →
Q53·ChemistryNumerical
The sum of bridging carbonyls in W(CO)6_66​ and Mn2_22​(CO)10_{10}10​ is ________ .

Correct answer: 0

Step-by-step solution →
Q54·ChemistryNumerical
Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15 °C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at −0.8-0.8−0.8 °C. The solubility product of PbCl2_22​ formed is ________ ×10−6\times 10^{-6}×10−6 at 298 K. (Nearest integer) (Given: Kb_bb​ = 0.5 K kg mol−1^{-1}−1 and Kf_ff​ = 1.8 K kg mol−1^{-1}−1. Assume molality to be equal to molarity in all cases.)

Correct answer: 13

Step-by-step solution →
Q55·ChemistryNumerical
17 mg of a hydrocarbon (M.F. C10_{10}10​H16_{16}16​) takes up 8.40 mL of the H2_22​ gas measured at 0 °C and 760 mm of Hg. Ozonolysis of the same hydrocarbon yields the products shown. The number of double bond/s present in the hydrocarbon is ________ .

Correct answer: 3

Step-by-step solution →
Q56·ChemistryNumerical
Consider the following reaction approaching equilibrium at 27 °C and 1 atm pressure: A + B ⇌kf=103kr=102\underset{k_r = 10^2}{\overset{k_f = 10^3}{\rightleftharpoons}}kr​=102⇌kf​=103​​ C + D. The standard Gibb's energy change (ΔrGθ\Delta_r G^\thetaΔr​Gθ) at 27 °C is (−)(-)(−) ________ kJ mol−1^{-1}−1 (Nearest integer). (Given: R = 8.3 J K−1^{-1}−1 mol−1^{-1}−1 and ln 10 = 2.3)

Correct answer: 6

Step-by-step solution →
Q57·ChemistryNumerical
The number of molecules or ions from the following, which do not have odd number of electrons are ________ . (A) NO2_22​ (B) ICl4−_4^-4−​ (C) BrF3_33​ (D) ClO2_22​ (E) NO2+_2^+2+​ (F) NO

Correct answer: 3

Step-by-step solution →
Q58·ChemistryNumerical
Following chromatogram was developed by adsorption of compound 'A' on a 6 cm TLC glass plate. Retardation factor of the compound 'A' is ________ ×10−1\times 10^{-1}×10−1.

Correct answer: 6

Step-by-step solution →
Q59·ChemistryNumerical
For certain chemical reaction X →\rightarrow→ Y, the rate of formation of product is plotted against the time as shown in the figure. The number of correct statement/s from the following is ________ . (A) Over all order of this reaction is one (B) Order of this reaction can't be determined (C) In region I and III, the reaction is of first and zero order respectively (D) In region-II, the reaction is of first order (E) In region-II, the order of reaction is in the range of 0.1 to 0.9.

Correct answer: 2

Step-by-step solution →
Q60·ChemistryNumerical
Following figure shows dependence of molar conductance of two electrolytes on concentration. Λm∘\Lambda_m^\circΛm∘​ is the limiting molar conductivity. The number of incorrect statement(s) from the following is ________ . (A) Λm∘\Lambda_m^\circΛm∘​ for electrolyte A is obtained by extrapolation (B) For electrolyte B, Λm\Lambda_mΛm​ vs c\sqrt{c}c​ graph is a straight line with intercept equal to Λm∘\Lambda_m^\circΛm∘​ (C) At infinite dilution, the value of degree of dissociation approaches zero for electrolyte B. (D) Λm∘\Lambda_m^\circΛm∘​ for any electrolyte A or B can be calculated using λ∘\lambda^\circλ∘ for individual ions.

Correct answer: 2

Step-by-step solution →

Mathematics — JEE Main 29 January 2023 Shift 1

Q61·MathematicsSingle correct
Let α\alphaα and β\betaβ be real numbers. Consider a 3×33 \times 33×3 matrix AAA such that A2=3A+αIA^2 = 3A + \alpha IA2=3A+αI. If A4=21A+βIA^4 = 21A + \beta IA4=21A+βI, then
  1. (A)β=−8\beta = -8β=−8
  2. (B)β=8\beta = 8β=8
  3. (C)α=4\alpha = 4α=4
  4. (D)α=1\alpha = 1α=1

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let x=2x = 2x=2 be a root of the equation x2+px+q=0x^2 + px + q = 0x2+px+q=0 and f(x)={1−cos⁡(x2−4px+q2+8q+16)(x−2p)4,x≠2p0,x=2pf(x) = \begin{cases} \dfrac{1 - \cos(x^2 - 4px + q^2 + 8q + 16)}{(x - 2p)^4}, & x \neq 2p \\ 0, & x = 2p \end{cases}f(x)=⎩⎨⎧​(x−2p)41−cos(x2−4px+q2+8q+16)​,0,​x=2px=2p​. Then lim⁡x→2p+[f(x)]\lim_{x \to 2p^+} [f(x)]limx→2p+​[f(x)], where [⋅][\cdot][⋅] denotes greatest integer function, is
  1. (A)0
  2. (B)−1-1−1
  3. (C)2
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
Let BBB and CCC be the two points on the line y+x=0y + x = 0y+x=0 such that BBB and CCC are symmetric with respect to the origin. Suppose AAA is a point on y−2x=2y - 2x = 2y−2x=2 such that △ABC\triangle ABC△ABC is an equilateral triangle. Then, the area of the △ABC\triangle ABC△ABC is
  1. (A)103\dfrac{10}{\sqrt{3}}3​10​
  2. (B)333\sqrt{3}33​
  3. (C)232\sqrt{3}23​
  4. (D)83\dfrac{8}{\sqrt{3}}3​8​

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
Consider the following system of equations αx+2y+z=1\alpha x + 2y + z = 1αx+2y+z=1, 2αx+3y+z=12\alpha x + 3y + z = 12αx+3y+z=1, 3x+αy+2z=β3x + \alpha y + 2z = \beta3x+αy+2z=β for some β∈R\beta \in \mathbb{R}β∈R. Then which of the following is NOT correct.
  1. (A)It has a solution if α=−1\alpha = -1α=−1 and β≠2\beta \neq 2β=2
  2. (B)It has a solution for all α≠−1\alpha \neq -1α=−1 and β=2\beta = 2β=2
  3. (C)It has no solution for α=3\alpha = 3α=3 and for all β≠2\beta \neq 2β=2
  4. (D)It has no solution for α=−1\alpha = -1α=−1 and for all β∈R\beta \in \mathbb{R}β∈R

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correct
Let y=f(x)y = f(x)y=f(x) be the solution of the differential equation y(x+1)dx−x2dy=0y(x + 1)dx - x^2 dy = 0y(x+1)dx−x2dy=0, y(1)=ey(1) = ey(1)=e. Then lim⁡x→0+f(x)\lim_{x \to 0^+} f(x)limx→0+​f(x) is equal to
  1. (A)1e2\dfrac{1}{e^2}e21​
  2. (B)e2e^2e2
  3. (C)0
  4. (D)1e\dfrac{1}{e}e1​

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
The domain of f(x)=log⁡(x+1)(x−2)e2log⁡ex−(2x+3)f(x) = \dfrac{\log_{(x+1)}(x - 2)}{e^{2\log_e x} - (2x + 3)}f(x)=e2loge​x−(2x+3)log(x+1)​(x−2)​, x∈Rx \in \mathbb{R}x∈R is
  1. (A)R−{3}\mathbb{R} - \{3\}R−{3}
  2. (B)(−1,∞)−{3}(-1, \infty) - \{3\}(−1,∞)−{3}
  3. (C)(2,∞)−{3}(2, \infty) - \{3\}(2,∞)−{3}
  4. (D)R−{−1,3}\mathbb{R} - \{-1, 3\}R−{−1,3}

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
Fifteen football players of a club-team are given 15 T-shirts with their names written on the backside. If the players pick up the T-shirts randomly, then the probability that at least 3 players pick the correct T-shirt is
  1. (A)524\dfrac{5}{24}245​
  2. (B)16\dfrac{1}{6}61​
  3. (C)536\dfrac{5}{36}365​
  4. (D)215\dfrac{2}{15}152​

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let [x][x][x] denote the greatest integer ≤x\leq x≤x. Consider the function f(x)=max⁡{x2,1+[x]}f(x) = \max\{x^2, 1 + [x]\}f(x)=max{x2,1+[x]}. Then the value of the integral ∫02f(x) dx\int_0^2 f(x)\,dx∫02​f(x)dx is
  1. (A)5+423\dfrac{5 + 4\sqrt{2}}{3}35+42​​
  2. (B)4+523\dfrac{4 + 5\sqrt{2}}{3}34+52​​
  3. (C)1+523\dfrac{1 + 5\sqrt{2}}{3}31+52​​
  4. (D)8+423\dfrac{8 + 4\sqrt{2}}{3}38+42​​

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
For two non-zero complex numbers z1z_1z1​ and z2z_2z2​, if Re(z1z2ˉ)=0\text{Re}(z_1 \bar{z_2}) = 0Re(z1​z2​ˉ​)=0 and Re(z1+z2)=0\text{Re}(z_1 + z_2) = 0Re(z1​+z2​)=0, then which of the following are possible? A. Im(z1)>0\text{Im}(z_1) > 0Im(z1​)>0 and Im(z2)>0\text{Im}(z_2) > 0Im(z2​)>0 B. Im(z1)<0\text{Im}(z_1) < 0Im(z1​)<0 and Im(z2)>0\text{Im}(z_2) > 0Im(z2​)>0 C. Im(z1)>0\text{Im}(z_1) > 0Im(z1​)>0 and Im(z2)<0\text{Im}(z_2) < 0Im(z2​)<0 D. Im(z1)<0\text{Im}(z_1) < 0Im(z1​)<0 and Im(z2)<0\text{Im}(z_2) < 0Im(z2​)<0. Choose the correct answer from the options given below:
  1. (A)B and D
  2. (B)A and B
  3. (C)B and C
  4. (D)A and C

Correct answer: (C)

Step-by-step solution →
Q70·MathematicsSingle correct
If the vectors a⃗=λi^+μj^+4k^\vec{a} = \lambda\hat{i} + \mu\hat{j} + 4\hat{k}a=λi^+μj^​+4k^, b⃗=2i^+4j^−2k^\vec{b} = 2\hat{i} + 4\hat{j} - 2\hat{k}b=2i^+4j^​−2k^ and c⃗=2i^+3j^+k^\vec{c} = 2\hat{i} + 3\hat{j} + \hat{k}c=2i^+3j^​+k^ are coplanar and the projection of a⃗\vec{a}a on the vector b⃗\vec{b}b is 54\sqrt{54}54​ units, then the sum of all possible values of λ+μ\lambda + \muλ+μ is equal to
  1. (A)0
  2. (B)24
  3. (C)6
  4. (D)18

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
Let f(θ)=3(sin⁡4(3π2−θ)+sin⁡4(3π+θ))−2(1−sin⁡22θ)f(\theta) = 3\left(\sin^4\left(\dfrac{3\pi}{2} - \theta\right) + \sin^4(3\pi + \theta)\right) - 2(1 - \sin^2 2\theta)f(θ)=3(sin4(23π​−θ)+sin4(3π+θ))−2(1−sin22θ) and S={θ∈[0,π]:f′(θ)=−32}S = \left\{\theta \in [0, \pi] : f'(\theta) = -\dfrac{\sqrt{3}}{2}\right\}S={θ∈[0,π]:f′(θ)=−23​​}. If β∈S\beta \in Sβ∈S, then f(β)f(\beta)f(β) is equal to
  1. (A)54\dfrac{5}{4}45​
  2. (B)32\dfrac{3}{2}23​
  3. (C)98\dfrac{9}{8}89​
  4. (D)118\dfrac{11}{8}811​

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
If ppp, qqq and rrr three propositions, then which of the following combination of truth values of ppp, qqq and rrr makes the logical expression {(p∨q)∧((∼p)∨r)}→((∼q)∨r)\{(p \vee q) \wedge ((\sim p) \vee r)\} \to ((\sim q) \vee r){(p∨q)∧((∼p)∨r)}→((∼q)∨r) false?
  1. (A)p = T, q = T, r = F
  2. (B)p = T, q = F, r = T
  3. (C)p = F, q = T, r = F
  4. (D)p = T, q = F, r = F

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
Let Δ\DeltaΔ be the area of the region {(x,y)∈R2:x2+y2≤21,y2≤4x,x≥1}\{(x, y) \in \mathbb{R}^2 : x^2 + y^2 \leq 21, y^2 \leq 4x, x \geq 1\}{(x,y)∈R2:x2+y2≤21,y2≤4x,x≥1}. Then 12(Δ−21sin⁡−127)\dfrac{1}{2}\left(\Delta - 21\sin^{-1}\dfrac{2}{\sqrt{7}}\right)21​(Δ−21sin−17​2​) is equal to
  1. (A)23−232\sqrt{3} - \dfrac{2}{3}23​−32​
  2. (B)3−43\sqrt{3} - \dfrac{4}{3}3​−34​
  3. (C)3−23\sqrt{3} - \dfrac{2}{3}3​−32​
  4. (D)23−132\sqrt{3} - \dfrac{1}{3}23​−31​

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
A light ray emits from the origin making an angle 30∘30^\circ30∘ with the positive x-axis. After getting reflected by the line x+y=1x + y = 1x+y=1, if this ray intersects x-axis at QQQ, then the abscissa of QQQ is
  1. (A)32(3+1)\dfrac{\sqrt{3}}{2(\sqrt{3}+1)}2(3​+1)3​​
  2. (B)23+3\dfrac{2}{3+\sqrt{3}}3+3​2​
  3. (C)23−1\dfrac{2}{\sqrt{3}-1}3​−12​
  4. (D)23−3\dfrac{2}{3-\sqrt{3}}3−3​2​

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
Let A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2}A = \{(x, y) \in \mathbb{R}^2 : y \geq 0, 2x \leq y \leq \sqrt{4 - (x - 1)^2}\}A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2​} and B={(x,y)∈R×R:0≤y≤min⁡{2x,4−(x−1)2}}B = \{(x, y) \in \mathbb{R} \times \mathbb{R} : 0 \leq y \leq \min\{2x, \sqrt{4 - (x - 1)^2}\}\}B={(x,y)∈R×R:0≤y≤min{2x,4−(x−1)2​}}. Then the ratio of the area of AAA to the area of BBB is
  1. (A)π+1π−1\dfrac{\pi + 1}{\pi - 1}π−1π+1​
  2. (B)ππ−1\dfrac{\pi}{\pi - 1}π−1π​
  3. (C)π−1π+1\dfrac{\pi - 1}{\pi + 1}π+1π−1​
  4. (D)ππ+1\dfrac{\pi}{\pi + 1}π+1π​

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsSingle correct
Let λ≠0\lambda \neq 0λ=0 be a real number. Let α,β\alpha, \betaα,β be the roots of the equation 14x2−31x+3λ=014x^2 - 31x + 3\lambda = 014x2−31x+3λ=0 and α,γ\alpha, \gammaα,γ be the roots of the equation 35x2−53x+4λ=035x^2 - 53x + 4\lambda = 035x2−53x+4λ=0. Then 3αβ\dfrac{3\alpha}{\beta}β3α​ and 4αγ\dfrac{4\alpha}{\gamma}γ4α​ are the roots of the equation
  1. (A)49x2−245x+250=049x^2 - 245x + 250 = 049x2−245x+250=0
  2. (B)7x2+245x−250=07x^2 + 245x - 250 = 07x2+245x−250=0
  3. (C)7x2−245x+250=07x^2 - 245x + 250 = 07x2−245x+250=0
  4. (D)49x2+245x+250=049x^2 + 245x + 250 = 049x2+245x+250=0

Correct answer: (A)

Step-by-step solution →
Q77·MathematicsSingle correct
Let the tangents at the points A(4,−11)A(4, -11)A(4,−11) and B(8,−5)B(8, -5)B(8,−5) on the circle x2+y2−3x+10y−15=0x^2 + y^2 - 3x + 10y - 15 = 0x2+y2−3x+10y−15=0, intersect at the point CCC. Then the radius of the circle, whose centre is CCC and the line joining AAA and BBB is its tangent, is equal to
  1. (A)2132\sqrt{13}213​
  2. (B)13\sqrt{13}13​
  3. (C)334\dfrac{3\sqrt{3}}{4}433​​
  4. (D)2133\dfrac{2\sqrt{13}}{3}3213​​

Correct answer: (D)

Step-by-step solution →
Q78·MathematicsSingle correct
Let f(x)=x+aπ2−4sin⁡x+bπ2−4cos⁡xf(x) = x + \dfrac{a}{\pi^2 - 4}\sin x + \dfrac{b}{\pi^2 - 4}\cos xf(x)=x+π2−4a​sinx+π2−4b​cosx, x∈Rx \in \mathbb{R}x∈R be a function which satisfies f(x)=x+∫0π/2sin⁡(x+y)f(y) dyf(x) = x + \int_0^{\pi/2} \sin(x + y) f(y)\,dyf(x)=x+∫0π/2​sin(x+y)f(y)dy. Then (a+b)(a + b)(a+b) is equal to
  1. (A)−2π(π−2)-2\pi(\pi - 2)−2π(π−2)
  2. (B)−2π(π+2)-2\pi(\pi + 2)−2π(π+2)
  3. (C)−π(π−2)-\pi(\pi - 2)−π(π−2)
  4. (D)−π(π+2)-\pi(\pi + 2)−π(π+2)

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
Let f:R→Rf: \mathbb{R} \to \mathbb{R}f:R→R be a function such that f(x)=x2+2x+1x2+1f(x) = \dfrac{x^2 + 2x + 1}{x^2 + 1}f(x)=x2+1x2+2x+1​. Then
  1. (A)f(x)f(x)f(x) is one-one in [1,∞)[1, \infty)[1,∞) but not in (−∞,∞)(-\infty, \infty)(−∞,∞)
  2. (B)f(x)f(x)f(x) is one-one in (−∞,∞)(-\infty, \infty)(−∞,∞)
  3. (C)f(x)f(x)f(x) is many-one in (−∞,−1)(-\infty, -1)(−∞,−1)
  4. (D)f(x)f(x)f(x) is many-one in (1,∞)(1, \infty)(1,∞)

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsSingle correct
Three rotten apples are mixed accidently with seven good apples and four apples are drawn one by one without replacement. Let the random variable XXX denote the number of rotten apples. If μ\muμ and σ2\sigma^2σ2 represent mean and variance of XXX, respectively, then 10(μ2+σ2)10(\mu^2 + \sigma^2)10(μ2+σ2) is equal to
  1. (A)250
  2. (B)25
  3. (C)30
  4. (D)20

Correct answer: (D)

Step-by-step solution →
Q81·MathematicsNumerical
Let the co-ordinates of one vertex of △ABC\triangle ABC△ABC be A(0,2,α)A(0, 2, \alpha)A(0,2,α) and the other two vertices lie on the line x+α5=y−12=z+43\dfrac{x + \alpha}{5} = \dfrac{y - 1}{2} = \dfrac{z + 4}{3}5x+α​=2y−1​=3z+4​. For α∈Z\alpha \in \mathbb{Z}α∈Z, if the area of △ABC\triangle ABC△ABC is 21 sq. units and the line segment BCBCBC has length 2212\sqrt{21}221​ units, then α2\alpha^2α2 is equal to ________ .

Correct answer: 9

Step-by-step solution →
Q82·MathematicsNumerical
Let f:R→Rf: \mathbb{R} \to \mathbb{R}f:R→R be a differentiable function that satisfies the relation f(x+y)=f(x)+f(y)−1f(x + y) = f(x) + f(y) - 1f(x+y)=f(x)+f(y)−1, ∀x,y∈R\forall x, y \in \mathbb{R}∀x,y∈R. If f′(0)=2f'(0) = 2f′(0)=2, then ∣f(−2)∣|f(-2)|∣f(−2)∣ is equal to ________ .

Correct answer: 3

Step-by-step solution →
Q83·MathematicsNumerical
Suppose fff is a function satisfying f(x+y)=f(x)+f(y)f(x + y) = f(x) + f(y)f(x+y)=f(x)+f(y) for all x,y∈Nx, y \in \mathbb{N}x,y∈N and f(1)=15f(1) = \dfrac{1}{5}f(1)=51​. If ∑n=1mf(n)n(n+1)(n+2)=112\sum_{n=1}^{m} \dfrac{f(n)}{n(n + 1)(n + 2)} = \dfrac{1}{12}∑n=1m​n(n+1)(n+2)f(n)​=121​, then mmm is equal to ________ .

Correct answer: 10

Step-by-step solution →
Q84·MathematicsNumerical
Let the coefficients of three consecutive terms in the binomial expansion of (1+2x)n(1 + 2x)^n(1+2x)n be in the ratio 2:5:82 : 5 : 82:5:8. Then the coefficient of the term, which is in the middle of these three terms, is ________ .

Correct answer: 1120

Step-by-step solution →
Q85·MathematicsNumerical
Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1​,a2​,a3​,… be a GP of increasing positive numbers. If the product of fourth and sixth terms is 9 and the sum of fifth and seventh terms is 24, then a1a9+a2a4a9+a5+a7a_1 a_9 + a_2 a_4 a_9 + a_5 + a_7a1​a9​+a2​a4​a9​+a5​+a7​ is equal to ________ .

Correct answer: 60

Step-by-step solution →
Q86·MathematicsNumerical
Let the equation of the plane PPP containing the line x+10=8−y2=zx + 10 = \dfrac{8 - y}{2} = zx+10=28−y​=z be ax+by+3z=2(a+b)ax + by + 3z = 2(a + b)ax+by+3z=2(a+b) and the distance of the plane PPP from the point (1,27,7)(1, 27, 7)(1,27,7) be ccc. Then a2+b2+c2a^2 + b^2 + c^2a2+b2+c2 is equal to ________ .

Correct answer: 355

Step-by-step solution →
Q87·MathematicsNumerical
If the co-efficient of x9x^9x9 in (αx3+1βx)11\left(\alpha x^3 + \dfrac{1}{\beta x}\right)^{11}(αx3+βx1​)11 and the co-efficient of x−9x^{-9}x−9 in (αx−1βx3)11\left(\alpha x - \dfrac{1}{\beta x^3}\right)^{11}(αx−βx31​)11 are equal, then (αβ)2(\alpha\beta)^2(αβ)2 is equal to ________ .

Correct answer: 1

Step-by-step solution →
Q88·MathematicsNumerical
Let a⃗\vec{a}a, b⃗\vec{b}b and c⃗\vec{c}c be three non-zero non-coplanar vectors. Let the position vectors of four points AAA, BBB, CCC and DDD be a⃗−b⃗+c⃗\vec{a} - \vec{b} + \vec{c}a−b+c, λa⃗−3b⃗+4c⃗\lambda\vec{a} - 3\vec{b} + 4\vec{c}λa−3b+4c, −a⃗+2b⃗−3c⃗-\vec{a} + 2\vec{b} - 3\vec{c}−a+2b−3c and 2a⃗−4b⃗+6c⃗2\vec{a} - 4\vec{b} + 6\vec{c}2a−4b+6c respectively. If AB⃗\vec{AB}AB, AC⃗\vec{AC}AC and AD⃗\vec{AD}AD are coplanar, then λ\lambdaλ is equal to ________ .

Correct answer: 2

Step-by-step solution →
Q89·MathematicsNumerical
Five digit numbers are formed using the digits 1, 2, 3, 5, 7 with repetitions and are written in descending order with serial numbers. For example, the number 77777 has serial number 1. Then the serial number of 35337 is ________ .

Correct answer: 1436

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Q90·MathematicsNumerical
If all the six digit numbers x1x2x3x4x5x6x_1 x_2 x_3 x_4 x_5 x_6x1​x2​x3​x4​x5​x6​ with 0<x1<x2<x3<x4<x5<x60 < x_1 < x_2 < x_3 < x_4 < x_5 < x_60<x1​<x2​<x3​<x4​<x5​<x6​ are arranged in the increasing order, then the sum of the digits in the 72th number is ________ .

Correct answer: 32

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Chapters tested in this paper

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  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Principles of Qualitative Analysis 58/186
  • Chemistry in Everyday Life 60/186
  • States of Matter: Gases and Liquids 52/186
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