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JEE Main 30 January 2023 Shift 2 Question Paper with Answers

30 January 2023 · January session · 90 questions

The complete JEE Main 30 January 2023 Shift 2 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
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Chemistry
30
Mathematics
30

Physics — JEE Main 30 January 2023 Shift 2

Q1·PhysicsSingle correct
A current carrying rectangular loop PQRS is made of uniform wire with PR=QS=5PR=QS=5PR=QS=5 cm and PQ=RS=100PQ=RS=100PQ=RS=100 cm. If the current reading changes from III to 2I2I2I, the ratio of the magnetic force per unit length on the wire PQ due to wire RS in the two cases respectively (fPQI:fPQ2If_{PQ}^{I}:f_{PQ}^{2I}fPQI​:fPQ2I​) is:
  1. (A)1:21:21:2
  2. (B)1:31:31:3
  3. (C)1:41:41:4
  4. (D)1:51:51:5

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
The output Y for the inputs A and B of the circuit shown in the figure is given by the truth table (choose the correct truth table from the options shown in the figure):
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Efficiency of a reversible heat engine will be highest at −273 ∘-273\,^{\circ}−273∘C temperature of the cold reservoir. Reason R: The efficiency of Carnot's engine depends not only on temperature of the cold reservoir but it depends on the temperature of the hot reservoir too and is given as η=(1−T2T1)\eta=\left(1-\dfrac{T_2}{T_1}\right)η=(1−T1​T2​​). In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
A point charge QQQ is placed at the centre of a conducting spherical shell of inner radius aaa and outer radius bbb. The electric field due to charge QQQ in the three regions I (r<ar<ar<a), II (a<r<ba<r<ba<r<b) and III (r>br>br>b) is given by:
  1. (A)EI=0, EII=0, EIII=0E_I=0,\ E_{II}=0,\ E_{III}=0EI​=0, EII​=0, EIII​=0
  2. (B)EI=0, EII=0, EIII≠0E_I=0,\ E_{II}=0,\ E_{III}\neq0EI​=0, EII​=0, EIII​=0
  3. (C)EI≠0, EII=0, EIII≠0E_I\neq0,\ E_{II}=0,\ E_{III}\neq0EI​=0, EII​=0, EIII​=0
  4. (D)EI≠0, EII=0, EIII=0E_I\neq0,\ E_{II}=0,\ E_{III}=0EI​=0, EII​=0, EIII​=0

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correct
The equivalent resistance between A and B for the network shown in the figure is:
  1. (A)13 Ω\dfrac{1}{3}\,\Omega31​Ω
  2. (B)12 Ω\dfrac{1}{2}\,\Omega21​Ω
  3. (C)32 Ω\dfrac{3}{2}\,\Omega23​Ω
  4. (D)23 Ω\dfrac{2}{3}\,\Omega32​Ω

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
A vehicle travels 4 km with a speed of 3 km/h and another 4 km with a speed of 5 km/h, then its average speed is:
  1. (A)3.503.503.50 km/h
  2. (B)4.254.254.25 km/h
  3. (C)4.004.004.00 km/h
  4. (D)3.753.753.75 km/h

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
In a series AC circuit with inductive reactance XL=200 ΩX_L=200\,\OmegaXL​=200Ω, capacitive reactance XC=100 ΩX_C=100\,\OmegaXC​=100Ω and resistance R=100 ΩR=100\,\OmegaR=100Ω connected to a source of Vrms=2002V_{rms}=200\sqrt{2}Vrms​=2002​ V, the rms value of current (IrmsI_{rms}Irms​) through the resistor R is:
  1. (A)222\sqrt{2}22​ A
  2. (B)222 A
  3. (C)202020 A
  4. (D)12\dfrac{1}{2}21​ A

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
A point source of 100 W emits light with 5% efficiency. At a distance of 5 m from the source, the intensity produced by the electric field component is:
  1. (A)12π Wm2\dfrac{1}{2\pi}\ \dfrac{W}{m^2}2π1​ m2W​
  2. (B)120π Wm2\dfrac{1}{20\pi}\ \dfrac{W}{m^2}20π1​ m2W​
  3. (C)110π Wm2\dfrac{1}{10\pi}\ \dfrac{W}{m^2}10π1​ m2W​
  4. (D)140π Wm2\dfrac{1}{40\pi}\ \dfrac{W}{m^2}40π1​ m2W​

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
A block of 3\sqrt{3}3​ kg is attached to a string whose other end is attached to the wall. An unknown horizontal force F is applied so that the string makes an angle of 30∘30^{\circ}30∘ with the wall. The tension T is: (Given g=10g=10g=10 ms−2^{-2}−2)
  1. (A)202020 N
  2. (B)101010 N
  3. (C)151515 N
  4. (D)252525 N

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
Match List-I (communication-system terms) with List-II (their descriptions). Choose the correct answer from the options given below:
List-IList-II
A.AttenuationI.Combination of a receiver and transmitter
B.TransducerII.Process of retrieval of information from the carrier wave at receiver
C.DemodulationIII.Converts one form of energy into another
D.RepeaterIV.Loss of strength of a signal while propagating through a medium
  1. (A)A-IV, B-III, C-I, D-II
  2. (B)A-I, B-II, C-III, D-IV
  3. (C)A-IV, B-III, C-II, D-I
  4. (D)A-II, B-III, C-IV, D-I

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
An electron accelerated through a potential difference V1V_1V1​ has a de-Broglie wavelength of λ\lambdaλ. When the potential is changed to V2V_2V2​, its de-Broglie wavelength increases by 50%. The value of V1V2\dfrac{V_1}{V_2}V2​V1​​ is equal to:
  1. (A)333
  2. (B)32\dfrac{3}{2}23​
  3. (C)444
  4. (D)94\dfrac{9}{4}49​

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
A flask contains hydrogen and oxygen in the ratio of 2:1 by mass at temperature 27 ∘27\,^{\circ}27∘C. The ratio of average kinetic energy per molecule of hydrogen and oxygen respectively is:
  1. (A)2:12:12:1
  2. (B)1:11:11:1
  3. (C)1:41:41:4
  4. (D)4:14:14:1

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
A current of 2 A is flowing in an equilateral triangle of side 434\sqrt{3}43​ cm. The magnetic field at the centroid O of the triangle is (neglect the effect of earth's magnetic field):
  1. (A)1.43×10−51.4\sqrt{3}\times10^{-5}1.43​×10−5 T
  2. (B)43×10−44\sqrt{3}\times10^{-4}43​×10−4 T
  3. (C)33×10−53\sqrt{3}\times10^{-5}33​×10−5 T
  4. (D)3×10−4\sqrt{3}\times10^{-4}3​×10−4 T

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
An object is allowed to fall from a height RRR above the earth, where RRR is the radius of the earth. Its velocity when it strikes the earth's surface, ignoring air resistance, will be:
  1. (A)2gR\sqrt{2gR}2gR​
  2. (B)gR2\sqrt{\dfrac{gR}{2}}2gR​​
  3. (C)2gR2\sqrt{gR}2gR​
  4. (D)gR\sqrt{gR}gR​

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
Match List-I (physical quantities) with List-II (their dimensional formulae). Choose the correct answer from the options given below:
List-IList-II
A.TorqueI.kg m−1 s−2kg\,m^{-1}\,s^{-2}kgm−1s−2
B.Energy densityII.kg m s−1kg\,m\,s^{-1}kgms−1
C.Pressure gradientIII.kg m−2 s−2kg\,m^{-2}\,s^{-2}kgm−2s−2
D.ImpulseIV.kg m2 s−2kg\,m^{2}\,s^{-2}kgm2s−2
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-IV, B-III, C-I, D-II
  3. (C)A-IV, B-I, C-II, D-III
  4. (D)A-I, B-IV, C-III, D-II

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The nuclear density of nuclides 510B^{10}_{5}B510​B, 36Li^{6}_{3}Li36​Li, 2656Fe^{56}_{26}Fe2656​Fe, 1020Ne^{20}_{10}Ne1020​Ne and 83209Bi^{209}_{83}Bi83209​Bi can be arranged as ρBiN>ρFeN>ρNeN>ρBN>ρLiN\rho^{N}_{Bi}>\rho^{N}_{Fe}>\rho^{N}_{Ne}>\rho^{N}_{B}>\rho^{N}_{Li}ρBiN​>ρFeN​>ρNeN​>ρBN​>ρLiN​. Reason R: The radius R of a nucleus is related to its mass number A as R=R0A1/3R=R_0 A^{1/3}R=R0​A1/3, where R0R_0R0​ is a constant. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is false but R is true
  2. (B)A is true but R is false
  3. (C)Both A and R are true but R is NOT the correct explanation of A
  4. (D)Both A and R are true and R is the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
A force is applied to a steel wire 'A', rigidly clamped at one end. As a result the elongation in the wire is 0.2 mm. If the same force is applied to another steel wire 'B' of double the length and a diameter 2.4 times that of wire 'A', the elongation in wire 'B' will be (wires having uniform circular cross sections):
  1. (A)6.06×10−26.06\times10^{-2}6.06×10−2 mm
  2. (B)2.77×10−22.77\times10^{-2}2.77×10−2 mm
  3. (C)3.0×10−23.0\times10^{-2}3.0×10−2 mm
  4. (D)6.9×10−26.9\times10^{-2}6.9×10−2 mm

Correct answer: (D)

Step-by-step solution →
Q18·PhysicsSingle correct
A thin prism P1P_1P1​ with an angle 6∘6^{\circ}6∘ and made of glass of refractive index 1.54 is combined with another prism P2P_2P2​ made from glass of refractive index 1.72 to produce dispersion without average deviation. The angle of prism P2P_2P2​ is:
  1. (A)1.3∘1.3^{\circ}1.3∘
  2. (B)6∘6^{\circ}6∘
  3. (C)4.5∘4.5^{\circ}4.5∘
  4. (D)7.8∘7.8^{\circ}7.8∘

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
A machine gun of mass 10 kg fires 20 g bullets at the rate of 180 bullets per minute with a speed of 100 m s−1^{-1}−1 each. The recoil velocity of the gun is:
  1. (A)1.51.51.5 m/s
  2. (B)0.60.60.6 m/s
  3. (C)2.52.52.5 m/s
  4. (D)0.020.020.02 m/s

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
For a simple harmonic motion in a mass-spring system on a frictionless surface, the angular frequency is ω1\omega_1ω1​ when the mass of the block is 1 kg and ω2\omega_2ω2​ when the mass is 2 kg. The ratio ω2ω1\dfrac{\omega_2}{\omega_1}ω1​ω2​​ is:
  1. (A)12\dfrac{1}{\sqrt{2}}2​1​
  2. (B)2\sqrt{2}2​
  3. (C)222
  4. (D)12\dfrac{1}{2}21​

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
A uniform disc of mass 0.5 kg and radius rrr is projected with velocity 18 m/s at t=0t=0t=0 s on a rough horizontal surface. It starts with a purely sliding motion at t=0t=0t=0 s and after 2 s it acquires a purely rolling motion. The total kinetic energy of the disc after 2 s will be _______ J. (Given coefficient of friction is 0.3 and g=10g=10g=10 m/s2^22)

Correct answer: 54

Step-by-step solution →
Q22·PhysicsNumerical
For the bridge network shown in the figure, if the potential difference between B and D is zero, the value of xxx is 1n Ω\dfrac{1}{n}\,\Omegan1​Ω. The value of nnn is _______.

Correct answer: 2

Step-by-step solution →
Q23·PhysicsNumerical
A stone tied to a 180 cm long string at its end is making 28 revolutions in a horizontal circle in every minute. The magnitude of acceleration of the stone is 1936x\dfrac{1936}{x}x1936​ ms−2^{-2}−2. The value of xxx is _______. (Take π=227\pi=\dfrac{22}{7}π=722​)

Correct answer: 125

Step-by-step solution →
Q24·PhysicsNumerical
A radioactive nucleus decays by two different processes. The half life of the first process is 5 minutes and that of the second process is 30 s. The effective half-life of the nucleus is calculated to be α11\dfrac{\alpha}{11}11α​ s. The value of α\alphaα is _______.

Correct answer: 300

Step-by-step solution →
Q25·PhysicsNumerical
A faulty thermometer reads 5 ∘5\,^{\circ}5∘C in melting ice and 95 ∘95\,^{\circ}95∘C in steam. The correct temperature on the absolute scale will be _______ K when the faulty thermometer reads 41 ∘41\,^{\circ}41∘C.

Correct answer: 313

Step-by-step solution →
Q26·PhysicsNumerical
In an ac generator, a rectangular coil of 100 turns each having area 14×10−214\times10^{-2}14×10−2 m2^22 is rotated at 360 rev/min about an axis perpendicular to a uniform magnetic field of magnitude 3.0 T. The maximum value of the emf produced will be _______ V. (Take π=227\pi=\dfrac{22}{7}π=722​)

Correct answer: 1584

Step-by-step solution →
Q27·PhysicsNumerical
A body of mass 2 kg is initially at rest. It starts moving unidirectionally under the influence of a source of constant power P. Its displacement in 4 s is 13α22Pm\dfrac{1}{3}\alpha^{2}\sqrt{\dfrac{2P}{m}}31​α2m2P​​. The value of α\alphaα will be _______.

Correct answer: 4

Step-by-step solution →
Q28·PhysicsNumerical
A cuboid with one corner at the origin and edges of length 1 m, 2 m and 3 m along the x, y and z axes respectively lies in a region with electric field E⃗=2x2i^−4yj^+6k^\vec{E}=2x^{2}\hat{i}-4y\hat{j}+6\hat{k}E=2x2i^−4yj^​+6k^ N/C. The magnitude of charge within the cuboid is nε0n\varepsilon_0nε0​ C. The value of nnn is _______.

Correct answer: 12

Step-by-step solution →
Q29·PhysicsNumerical
In a Young's double slit experiment, the intensities at two points, for the path differences λ4\dfrac{\lambda}{4}4λ​ and λ3\dfrac{\lambda}{3}3λ​ (λ\lambdaλ being the wavelength of light used) are I1I_1I1​ and I2I_2I2​ respectively. If I0I_0I0​ denotes the intensity produced by each one of the individual slits, then I1+I2I0=\dfrac{I_1+I_2}{I_0}=I0​I1​+I2​​= _______.

Correct answer: 3

Step-by-step solution →
Q30·PhysicsNumerical
The velocity of a particle executing SHM varies with displacement (xxx) as 4v2=50−x24v^{2}=50-x^{2}4v2=50−x2. The time period of oscillation is x7\dfrac{x}{7}7x​ s. The value of xxx is _______. (Take π=227\pi=\dfrac{22}{7}π=722​)

Correct answer: 88

Step-by-step solution →

Chemistry — JEE Main 30 January 2023 Shift 2

Q31·ChemistrySingle correct
The Cl−-−Co−-−Cl bond angle value(s) in a fac-[Co(NH3)3Cl3][Co(NH_3)_3Cl_3][Co(NH3​)3​Cl3​] complex is/are:
  1. (A)90∘90^{\circ}90∘
  2. (B)90∘ & 120∘90^{\circ}\ \&\ 120^{\circ}90∘ & 120∘
  3. (C)180∘180^{\circ}180∘
  4. (D)90∘ & 180∘90^{\circ}\ \&\ 180^{\circ}90∘ & 180∘

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
The correct order of pKa values for the following compounds (a, b, c, d shown in the figure) is:
  1. (A)c>a>d>bc>a>d>bc>a>d>b
  2. (B)b>a>d>cb>a>d>cb>a>d>c
  3. (C)b>d>a>cb>d>a>cb>d>a>c
  4. (D)a>b>c>da>b>c>da>b>c>d

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
Given below are two statements: Statement I: During electrolytic refining, the pure metal is made to act as anode and its impure metallic form is used as cathode. Statement II: During the Hall-Heroult electrolysis process, purified Al2O3Al_2O_3Al2​O3​ is mixed with Na3AlF6Na_3AlF_6Na3​AlF6​ to lower the melting point of the mixture. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but Statement II is incorrect
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Both Statement I and Statement II are correct
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Match List-I (Mixture) with List-II (Separation Technique). Choose the correct answer from the options given below:
List-I (Mixture)List-II (Separation Technique)
A.CHCl3+C6H5NH2CHCl_3 + C_6H_5NH_2CHCl3​+C6​H5​NH2​I.Steam distillation
B.C6H14+C5H12C_6H_{14} + C_5H_{12}C6​H14​+C5​H12​II.Differential extraction
C.C6H5NH2+H2OC_6H_5NH_2 + H_2OC6​H5​NH2​+H2​OIII.Distillation
D.Organic compound in H2OH_2OH2​OIV.Fractional distillation
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-III, B-IV, C-I, D-II
  3. (C)A-III, B-I, C-IV, D-II
  4. (D)A-II, B-I, C-III, D-IV

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
1 L, 0.02 M solution of [Co(NH3)5SO4]Br[Co(NH_3)_5SO_4]Br[Co(NH3​)5​SO4​]Br is mixed with 1 L, 0.02 M solution of [Co(NH3)5Br]SO4[Co(NH_3)_5Br]SO_4[Co(NH3​)5​Br]SO4​. The resulting solution is divided into two equal parts (X). One part is treated with excess of AgNO3AgNO_3AgNO3​ solution to give Y, and the other with excess of BaCl2BaCl_2BaCl2​ solution to give Z. The number of moles of Y and Z respectively are:
  1. (A)0.02, 0.01
  2. (B)0.01, 0.01
  3. (C)0.01, 0.02
  4. (D)0.02, 0.02

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
The decreasing order towards SN1S_N1SN​1 reaction for the following compounds (a, b, c, d shown in the figure) is:
  1. (A)a>c>d>ba>c>d>ba>c>d>b
  2. (B)b>d>c>ab>d>c>ab>d>c>a
  3. (C)a>b>c>da>b>c>da>b>c>d
  4. (D)d>b>c>ad>b>c>ad>b>c>a

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
Which of the following reactions is correct?
  1. (A)4LiNO3→Δ2Li2O+2N2O4+O24LiNO_3 \xrightarrow{\Delta} 2Li_2O + 2N_2O_4 + O_24LiNO3​Δ​2Li2​O+2N2​O4​+O2​
  2. (B)2LiNO3→Δ2NaNO2+O22LiNO_3 \xrightarrow{\Delta} 2NaNO_2 + O_22LiNO3​Δ​2NaNO2​+O2​
  3. (C)2LiNO3→2Li+2NO2+O22LiNO_3 \rightarrow 2Li + 2NO_2 + O_22LiNO3​→2Li+2NO2​+O2​
  4. (D)4LiNO3→Δ2Li2O+4NO2+O24LiNO_3 \xrightarrow{\Delta} 2Li_2O + 4NO_2 + O_24LiNO3​Δ​2Li2​O+4NO2​+O2​

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
Boric acid is solid, whereas BF3BF_3BF3​ is gas at room temperature because of:
  1. (A)Strong van der Waal's interaction in Boric acid
  2. (B)Strong covalent bond in BF3BF_3BF3​
  3. (C)Strong ionic bond in Boric acid
  4. (D)Strong hydrogen bond in Boric acid

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Antihistamines do not affect the secretion of acid in stomach. Reason R: Antiallergic and antacid drugs work on different receptors. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is false but R is true
  2. (B)Both A and R are true but R is not the correct explanation of A
  3. (C)Both A and R are true and R is the correct explanation of A
  4. (D)A is true but R is false

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
The formula for Nessler's reagent is:
  1. (A)HgI2HgI_2HgI2​
  2. (B)K2HgI4K_2HgI_4K2​HgI4​
  3. (C)KHgI3KHgI_3KHgI3​
  4. (D)KHg2I2KHg_2I_2KHg2​I2​

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: 2'-hydroxyacetophenone (a 2-hydroxy aryl methyl ketone) can be easily reduced using Zn-Hg/HCl to 2-ethylphenol. Reason R: Zn-Hg/HCl is used to reduce a carbonyl group to a −CH2−-CH_2-−CH2​− group. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is true but R is false
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)A is false but R is true
  4. (D)Both A and R are true but R is not the correct explanation of A

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
The maximum number of electrons that can be accommodated in the shell with n=4n=4n=4 is:
  1. (A)16
  2. (B)32
  3. (C)72
  4. (D)50

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
The wave function (Ψ\PsiΨ) of 2s is given by Ψ2s=122π(1a0)1/2(2−ra0)e−r/2a0\Psi_{2s}=\dfrac{1}{2\sqrt{2\pi}}\left(\dfrac{1}{a_0}\right)^{1/2}\left(2-\dfrac{r}{a_0}\right)e^{-r/2a_0}Ψ2s​=22π​1​(a0​1​)1/2(2−a0​r​)e−r/2a0​. At r=r0r=r_0r=r0​, a radial node is formed. Thus r0r_0r0​ in terms of a0a_0a0​ is:
  1. (A)r0=4a0r_0=4a_0r0​=4a0​
  2. (B)r0=a02r_0=\dfrac{a_0}{2}r0​=2a0​​
  3. (C)r0=a0r_0=a_0r0​=a0​
  4. (D)r0=2a0r_0=2a_0r0​=2a0​

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
For the conversion of compound (X) = 4-nitrotoluene to product (Y) = 3,5-dibromotoluene, the sequence of reagents to be used will be:
  1. (A)(i) Br2(aq)Br_2(aq)Br2​(aq) (ii) LiAlH4LiAlH_4LiAlH4​ (iii) H3O+H_3O^+H3​O+
  2. (B)(i) Br2Br_2Br2​, Fe (ii) Fe, H+H^+H+ (iii) LiAlH4LiAlH_4LiAlH4​
  3. (C)(i) Fe, H+H^+H+ (ii) Br2(aq)Br_2(aq)Br2​(aq) (iii) HNO2HNO_2HNO2​ (iv) H3PO2H_3PO_2H3​PO2​
  4. (D)(i) Fe, H+H^+H+ (ii) Br2(aq)Br_2(aq)Br2​(aq) (iii) HNO2HNO_2HNO2​ (iv) CuBr

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
Match List-I (Complexes) with List-II (Hybridisation). Choose the correct answer from the options given below:
List-I (Complexes)List-II (Hybridisation)
A.[Ni(CO)4][Ni(CO)_4][Ni(CO)4​]I.sp3sp^3sp3
B.[Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}[Cu(NH3​)4​]2+II.dsp2dsp^2dsp2
C.[Fe(NH3)6]2+[Fe(NH_3)_6]^{2+}[Fe(NH3​)6​]2+III.sp3d2sp^3d^2sp3d2
D.[Fe(H2O)6]2+[Fe(H_2O)_6]^{2+}[Fe(H2​O)6​]2+IV.d2sp3d^2sp^3d2sp3
  1. (A)A-I, B-II, C-IV, D-III
  2. (B)A-II, B-I, C-III, D-IV
  3. (C)A-II, B-I, C-IV, D-III
  4. (D)A-I, B-II, C-III, D-IV

Correct answer: (A)

Step-by-step solution →
Q46·Chemistry·Electronic Effects and StabilitySingle correct
The most stable carbocation for the following (structures a, b, c, d shown in the figure) is:
  1. (A)a
  2. (B)c
  3. (C)d
  4. (D)b

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
Chlorides of which metal are soluble in organic solvents:
  1. (A)K
  2. (B)Be
  3. (C)Mg
  4. (D)Ca

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
KMnO4KMnO_4KMnO4​ oxidises I−I^-I− in acidic and neutral/faintly alkaline solution, respectively, to:
  1. (A)IO3− & IO3−IO_3^-\ \&\ IO_3^-IO3−​ & IO3−​
  2. (B)I2 & IO3−I_2\ \&\ IO_3^-I2​ & IO3−​
  3. (C)I2 & I2I_2\ \&\ I_2I2​ & I2​
  4. (D)IO3− & I2IO_3^-\ \&\ I_2IO3−​ & I2​

Correct answer: (B)

Step-by-step solution →
Q49·ChemistrySingle correct
The bond dissociation energy of the "E-H" bond of the "H2EH_2EH2​E" hydrides of group 16 elements (A. O, B. S, C. Se, D. Te) follows the order. Choose the correct one from the options given below:
  1. (A)B>A>C>DB>A>C>DB>A>C>D
  2. (B)A>B>D>CA>B>D>CA>B>D>C
  3. (C)A>B>C>DA>B>C>DA>B>C>D
  4. (D)D>C>B>AD>C>B>AD>C>B>A

Correct answer: (C)

Step-by-step solution →
Q50·ChemistrySingle correct
The water quality of a pond was analysed and its BOD was found to be 4. The pond has:
  1. (A)Highly polluted water
  2. (B)Slightly polluted water
  3. (C)Water has high amount of fluoride compounds
  4. (D)Very clean water

Correct answer: (D)

Step-by-step solution →
Q51·Chemistry·Alcohols and EthersNumerical
The number of compounds from the following (shown in the figure) which will not dissolve in cold NaHCO3NaHCO_3NaHCO3​ and NaOHNaOHNaOH solutions but will dissolve in hot NaOHNaOHNaOH solution is _______.

Correct answer: 3

Step-by-step solution →
Q52·ChemistryNumerical
1 mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27 ∘27\,^{\circ}27∘C. The work done is 3 kJ mol−1^{-1}−1. The final temperature of the gas is _______ K (nearest integer). (Given CV=20C_V=20CV​=20 J mol−1^{-1}−1 K−1^{-1}−1)

Correct answer: 150

Step-by-step solution →
Q53·ChemistryNumerical
A short peptide on complete hydrolysis produces 3 moles of glycine (G), two moles of leucine (L) and two moles of valine (V) per mole of peptide. The number of peptide linkages in it are _______.

Correct answer: 6

Step-by-step solution →
Q54·ChemistryNumerical
A lead storage battery contains a 38% by weight solution of H2SO4H_2SO_4H2​SO4​. The van't Hoff factor is 2.67 at this concentration. The temperature in Kelvin at which the solution in the battery will freeze is _______ (nearest integer). (Given Kf=1.8K_f=1.8Kf​=1.8 K kg mol−1^{-1}−1)

Correct answer: 243

Step-by-step solution →
Q55·ChemistryNumerical
The strength of a 50 volume solution of hydrogen peroxide is _______ g/L (nearest integer). (Given: molar mass of H2O2H_2O_2H2​O2​ is 34 g mol−1^{-1}−1; molar volume of gas at STP = 22.7 L)

Correct answer: 150

Step-by-step solution →
Q56·ChemistryNumerical
The electrode potential of the following cell at 298 K, X ∣ X2+(0.001 M) ∥ Y2+(0.01 M) ∣ YX\,|\,X^{2+}(0.001\,M)\,\|\,Y^{2+}(0.01\,M)\,|\,YX∣X2+(0.001M)∥Y2+(0.01M)∣Y, is _______ ×10−2\times10^{-2}×10−2 V (nearest integer). (Given: EX2+∣X0=−2.36E^{0}_{X^{2+}|X}=-2.36EX2+∣X0​=−2.36 V; EY2+∣Y0=+0.36E^{0}_{Y^{2+}|Y}=+0.36EY2+∣Y0​=+0.36 V; 2.303RTF=0.06\dfrac{2.303RT}{F}=0.06F2.303RT​=0.06 V)

Correct answer: 275

Step-by-step solution →
Q57·ChemistryNumerical
An organic compound undergoes first order decomposition. If the time taken for the 60% decomposition is 540 s, then the time required for 90% decomposition will be _______ s (nearest integer). (Given: ln⁡10=2.3\ln 10=2.3ln10=2.3; log⁡2=0.3\log 2=0.3log2=0.3)

Correct answer: 1350

Step-by-step solution →
Q58·ChemistryNumerical
Consider the equilibrium 2SO2(g)+O2(g)⇌2SO3(g)2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)2SO2​(g)+O2​(g)⇌2SO3​(g), ΔH=−190\Delta H=-190ΔH=−190 kJ. The number of factors from the following which will increase the yield of SO3SO_3SO3​ at equilibrium is _______: A. Increasing temperature, B. Increasing pressure, C. Adding more SO2SO_2SO2​, D. Adding more O2O_2O2​, E. Addition of catalyst.

Correct answer: 3

Step-by-step solution →
Q59·ChemistryNumerical
Iron oxide FeO crystallises in a cubic lattice with a unit cell edge length of 5.0 Å. If the density of FeO in the crystal is 4.0 g cm−3^{-3}−3, then the number of FeO units present per unit cell is _______ (nearest integer). (Given: molar mass of Fe and O is 56 and 16 g mol−1^{-1}−1 respectively; NA=6.0×1023N_A=6.0\times10^{23}NA​=6.0×1023 mol−1^{-1}−1)

Correct answer: 4

Step-by-step solution →
Q60·ChemistryNumerical
The graph of log⁡xm\log\dfrac{x}{m}logmx​ vs log⁡p\log plogp for an adsorption process is a straight line inclined at an angle of 45∘45^{\circ}45∘ with intercept equal to 0.6020. The mass of gas adsorbed per unit mass of adsorbent at a pressure of 0.4 atm is _______ ×10−1\times10^{-1}×10−1 (nearest integer). (Given: log⁡2=0.3010\log 2=0.3010log2=0.3010)

Correct answer: 16

Step-by-step solution →

Mathematics — JEE Main 30 January 2023 Shift 2

Q61·MathematicsSingle correct
A vector v⃗\vec{v}v in the first octant is inclined to the x-axis at 60∘60^{\circ}60∘, to the y-axis at 45∘45^{\circ}45∘ and to the z-axis at an acute angle. If a plane passing through the points (2,−1,1)(\sqrt{2}, -1, 1)(2​,−1,1) and (a,b,c)(a, b, c)(a,b,c) is normal to v⃗\vec{v}v, then:
  1. (A)2a+b+c=1\sqrt{2}a + b + c = 12​a+b+c=1
  2. (B)a+2b+c=1a + \sqrt{2}b + c = 1a+2​b+c=1
  3. (C)a+b+2c=1a + b + \sqrt{2}c = 1a+b+2​c=1
  4. (D)2a−b+c=1\sqrt{2}a - b + c = 12​a−b+c=1

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
Let a,b,c>1a, b, c > 1a,b,c>1; a3,b3a^3, b^3a3,b3 and c3c^3c3 be in A.P., and log⁡ab,log⁡ca\log_a b, \log_c aloga​b,logc​a and log⁡bc\log_b clogb​c be in G.P. If the sum of the first 20 terms of an A.P., whose first term is a+4b+c3\dfrac{a + 4b + c}{3}3a+4b+c​ and the common difference is a−8b+c10\dfrac{a - 8b + c}{10}10a−8b+c​, is −444-444−444, then abcabcabc is equal to:
  1. (A)1258\dfrac{125}{8}8125​
  2. (B)216216216
  3. (C)343343343
  4. (D)3438\dfrac{343}{8}8343​

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
Let a1=1,a2,a3,a4,…a_1=1, a_2, a_3, a_4, \ldotsa1​=1,a2​,a3​,a4​,… be consecutive natural numbers. Then tan⁡−1(11+a1a2)+tan⁡−1(11+a2a3)+⋯+tan⁡−1(11+a2021a2022)\tan^{-1}\left(\dfrac{1}{1 + a_1 a_2}\right) + \tan^{-1}\left(\dfrac{1}{1 + a_2 a_3}\right) + \cdots + \tan^{-1}\left(\dfrac{1}{1 + a_{2021} a_{2022}}\right)tan−1(1+a1​a2​1​)+tan−1(1+a2​a3​1​)+⋯+tan−1(1+a2021​a2022​1​) is equal to:
  1. (A)cot⁡−1(2022)−π4\cot^{-1}(2022) - \dfrac{\pi}{4}cot−1(2022)−4π​
  2. (B)π4−cot⁡−1(2022)\dfrac{\pi}{4} - \cot^{-1}(2022)4π​−cot−1(2022)
  3. (C)tan⁡−1(2022)−π4\tan^{-1}(2022) - \dfrac{\pi}{4}tan−1(2022)−4π​
  4. (D)π4−tan⁡−1(2022)\dfrac{\pi}{4} - \tan^{-1}(2022)4π​−tan−1(2022)

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
Let λ∈R\lambda \in \mathbb{R}λ∈R, a⃗=λi^+2j^−3k^\vec{a}=\lambda \hat{i} + 2\hat{j} - 3\hat{k}a=λi^+2j^​−3k^, b⃗=i^−λj^+2k^\vec{b}=\hat{i} - \lambda\hat{j} + 2\hat{k}b=i^−λj^​+2k^. If ((a⃗+b⃗)×(a⃗×b⃗))×(a⃗−b⃗)=8i^−40j^−24k^\left((\vec{a} + \vec{b}) \times (\vec{a} \times \vec{b})\right) \times (\vec{a} - \vec{b})=8\hat{i} - 40\hat{j} - 24\hat{k}((a+b)×(a×b))×(a−b)=8i^−40j^​−24k^, then ∣λ(a⃗+b⃗)×(a⃗−b⃗)∣2\left|\lambda(\vec{a} + \vec{b}) \times (\vec{a} - \vec{b})\right|^2​λ(a+b)×(a−b)​2 is equal to:
  1. (A)132132132
  2. (B)136136136
  3. (C)140140140
  4. (D)144144144

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let qqq be the maximum integral value of ppp in [0,10][0, 10][0,10] for which the roots of the equation x2−px+54p=0x^2 - px + \dfrac{5}{4}p=0x2−px+45​p=0 are rational. Then the area of the region {(x,y):0≤y≤(x−q)2, 0≤x≤q}\{(x, y): 0 \le y \le (x - q)^2,\ 0 \le x \le q\}{(x,y):0≤y≤(x−q)2, 0≤x≤q} is:
  1. (A)243243243
  2. (B)164164164
  3. (C)1253\dfrac{125}{3}3125​
  4. (D)252525

Correct answer: (A)

Step-by-step solution →
Q66·Mathematics·Limits and ContinuitySingle correct
Let f,gf, gf,g and hhh be the real valued functions defined on R\mathbb{R}R as f(x)={x∣x∣,x≠01,x=0f(x)=\begin{cases} \dfrac{x}{|x|}, & x \ne 0 \\ 1, & x=0 \end{cases}f(x)=⎩⎨⎧​∣x∣x​,1,​x=0x=0​, g(x)={sin⁡(x+1)(x+1),x≠−11,x=−1g(x)=\begin{cases} \dfrac{\sin(x + 1)}{(x + 1)}, & x \ne -1 \\ 1, & x=-1 \end{cases}g(x)=⎩⎨⎧​(x+1)sin(x+1)​,1,​x=−1x=−1​ and h(x)=2[x]−f(x)h(x)=2[x] - f(x)h(x)=2[x]−f(x), where [x][x][x] is the greatest integer ≤x\le x≤x. Then the value of lim⁡x→1g(h(x−1))\displaystyle\lim_{x \to 1} g(h(x - 1))x→1lim​g(h(x−1)) is:
  1. (A)−1-1−1
  2. (B)000
  3. (C)sin⁡(1)\sin(1)sin(1)
  4. (D)111

Correct answer: (D)

Step-by-step solution →
Q67·MathematicsSingle correct
Let SSS be the set of all values of a1a_1a1​ for which the mean deviation about the mean of 100 consecutive positive integers a1,a2,a3,…,a100a_1, a_2, a_3, \ldots, a_{100}a1​,a2​,a3​,…,a100​ is 252525. Then SSS is:
  1. (A)N\mathbb{N}N
  2. (B)ϕ\phiϕ
  3. (C){99}\{99\}{99}
  4. (D){9}\{9\}{9}

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
For α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R, suppose the system of linear equations x−y+z=1x - y + z=1x−y+z=1, 2x+2y+αz=82x + 2y + \alpha z=82x+2y+αz=8, 3x−y+4z=β3x - y + 4z=\beta3x−y+4z=β has infinitely many solutions. Then α\alphaα and β\betaβ are the roots of:
  1. (A)x2+14x+24=0x^2 + 14x + 24=0x2+14x+24=0
  2. (B)x2+18x+56=0x^2 + 18x + 56=0x2+18x+56=0
  3. (C)x2−18x+56=0x^2 - 18x + 56=0x2−18x+56=0
  4. (D)x2−10x+16=0x^2 - 10x + 16=0x2−10x+16=0

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
Let a⃗\vec{a}a and b⃗\vec{b}b be two vectors. Let ∣a⃗∣=1|\vec{a}|=1∣a∣=1, ∣b⃗∣=4|\vec{b}|=4∣b∣=4 and a⃗⋅b⃗=2\vec{a} \cdot \vec{b}=2a⋅b=2. If c⃗=(2a⃗×b⃗)−3b⃗\vec{c}=(2\vec{a} \times \vec{b}) - 3\vec{b}c=(2a×b)−3b, then the value of b⃗⋅c⃗\vec{b} \cdot \vec{c}b⋅c is:
  1. (A)−24-24−24
  2. (B)−84-84−84
  3. (C)−48-48−48
  4. (D)−60-60−60

Correct answer: (C)

Step-by-step solution →
Q70·MathematicsSingle correct
If the functions f(x)=x33+2bx+ax22f(x)=\dfrac{x^3}{3} + 2bx + \dfrac{ax^2}{2}f(x)=3x3​+2bx+2ax2​ and g(x)=x33+ax+bx2g(x)=\dfrac{x^3}{3} + ax + bx^2g(x)=3x3​+ax+bx2, a≠2ba \ne 2ba=2b, have a common extreme point, then a+2b+7a + 2b + 7a+2b+7 is equal to:
  1. (A)32\dfrac{3}{2}23​
  2. (B)333
  3. (C)444
  4. (D)666

Correct answer: (D)

Step-by-step solution →
Q71·MathematicsSingle correct
If PPP is a 3×33 \times 33×3 real matrix such that PT=aP+(a−1)IP^T=aP + (a - 1)IPT=aP+(a−1)I, where a>1a > 1a>1, then:
  1. (A)∣Adj P∣=12|\mathrm{Adj}\,P|=\dfrac{1}{2}∣AdjP∣=21​
  2. (B)∣Adj P∣=1|\mathrm{Adj}\,P|=1∣AdjP∣=1
  3. (C)PPP is a singular matrix
  4. (D)∣Adj P∣>1|\mathrm{Adj}\,P| > 1∣AdjP∣>1

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
The number of ways of selecting two numbers aaa and bbb, a∈{2,4,6,…,100}a \in \{2, 4, 6, \ldots, 100\}a∈{2,4,6,…,100} and b∈{1,3,5,…,99}b \in \{1, 3, 5, \ldots, 99\}b∈{1,3,5,…,99}, such that 222 is the remainder when a+ba + ba+b is divided by 232323, is:
  1. (A)268268268
  2. (B)108108108
  3. (C)545454
  4. (D)186186186

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
lim⁡n→∞3n{4+(2+1n)2+(2+2n)2+⋯+(3−1n)2}\displaystyle\lim_{n \to \infty} \dfrac{3}{n}\left\{4 + \left(2 + \dfrac{1}{n}\right)^2 + \left(2 + \dfrac{2}{n}\right)^2 + \cdots + \left(3 - \dfrac{1}{n}\right)^2\right\}n→∞lim​n3​{4+(2+n1​)2+(2+n2​)2+⋯+(3−n1​)2} is equal to:
  1. (A)121212
  2. (B)193\dfrac{19}{3}319​
  3. (C)000
  4. (D)191919

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
Let AAA be a point on the x-axis. Common tangents are drawn from AAA to the curves x2+y2=8x^2 + y^2=8x2+y2=8 and y2=16xy^2=16xy2=16x. If one of these tangents touches the two curves at QQQ and RRR, then (QR)2(QR)^2(QR)2 is equal to:
  1. (A)818181
  2. (B)727272
  3. (C)767676
  4. (D)646464

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
If a plane passes through the points (−1,k,0),(2,k,−1),(1,1,2)(-1, k, 0), (2, k, -1), (1, 1, 2)(−1,k,0),(2,k,−1),(1,1,2) and is parallel to the line x−11=2y+12=z+1−1\dfrac{x - 1}{1}=\dfrac{2y + 1}{2}=\dfrac{z + 1}{-1}1x−1​=22y+1​=−1z+1​, then the value of k2+1(k−1)(k−2)\dfrac{k^2 + 1}{(k - 1)(k - 2)}(k−1)(k−2)k2+1​ is:
  1. (A)175\dfrac{17}{5}517​
  2. (B)136\dfrac{13}{6}613​
  3. (C)613\dfrac{6}{13}136​
  4. (D)517\dfrac{5}{17}175​

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
The range of the function f(x)=3−x+2+xf(x)=\sqrt{3 - x} + \sqrt{2 + x}f(x)=3−x​+2+x​ is:
  1. (A)[22,11][2\sqrt{2}, \sqrt{11}][22​,11​]
  2. (B)[5,13][\sqrt{5}, \sqrt{13}][5​,13​]
  3. (C)[2,7][\sqrt{2}, \sqrt{7}][2​,7​]
  4. (D)[5,10][\sqrt{5}, \sqrt{10}][5​,10​]

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
The solution of the differential equation dydx=−(x2+3y23x2+y2)\dfrac{dy}{dx}=-\left(\dfrac{x^2 + 3y^2}{3x^2 + y^2}\right)dxdy​=−(3x2+y2x2+3y2​), y(1)=0y(1)=0y(1)=0, is:
  1. (A)log⁡e∣x+y∣−xy(x+y)2=0\log_e|x + y| - \dfrac{xy}{(x + y)^2}=0loge​∣x+y∣−(x+y)2xy​=0
  2. (B)log⁡e∣x+y∣+2xy(x+y)2=0\log_e|x + y| + \dfrac{2xy}{(x + y)^2}=0loge​∣x+y∣+(x+y)22xy​=0
  3. (C)log⁡e∣x+y∣−2xy(x+y)2=0\log_e|x + y| - \dfrac{2xy}{(x + y)^2}=0loge​∣x+y∣−(x+y)22xy​=0
  4. (D)log⁡e∣x+y∣+xy(x+y)2=0\log_e|x + y| + \dfrac{xy}{(x + y)^2}=0loge​∣x+y∣+(x+y)2xy​=0

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
The parabolas ax2+2bx+cy=0ax^2 + 2bx + cy=0ax2+2bx+cy=0 and dx2+2ex+fy=0dx^2 + 2ex + fy=0dx2+2ex+fy=0 intersect on the line y=1y=1y=1. If a,b,c,d,e,fa, b, c, d, e, fa,b,c,d,e,f are positive real numbers and a,b,ca, b, ca,b,c are in G.P., then:
  1. (A)d,e,fd, e, fd,e,f are in G.P.
  2. (B)da,eb,fc\dfrac{d}{a}, \dfrac{e}{b}, \dfrac{f}{c}ad​,be​,cf​ are in A.P.
  3. (C)d,e,fd, e, fd,e,f are in A.P.
  4. (D)da,eb,fc\dfrac{d}{a}, \dfrac{e}{b}, \dfrac{f}{c}ad​,be​,cf​ are in G.P.

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
Consider the following statements: P: I have fever; Q: I will not take medicine; R: I will take rest. The statement "If I have fever, then I will take medicine and I will take rest" is equivalent to:
  1. (A)((∼P)∨∼Q)∧((∼P)∨R)((\sim P) \vee \sim Q) \wedge ((\sim P) \vee R)((∼P)∨∼Q)∧((∼P)∨R)
  2. (B)(P∨Q)∧((∼P)∨R)(P \vee Q) \wedge ((\sim P) \vee R)(P∨Q)∧((∼P)∨R)
  3. (C)((∼P)∨∼Q)∧((∼P)∨∼R)((\sim P) \vee \sim Q) \wedge ((\sim P) \vee \sim R)((∼P)∨∼Q)∧((∼P)∨∼R)
  4. (D)(P∨∼Q)∧(P∨∼R)(P \vee \sim Q) \wedge (P \vee \sim R)(P∨∼Q)∧(P∨∼R)

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsSingle correct
x=(83+13)13x=(8\sqrt{3} + 13)^{13}x=(83​+13)13 and y=(72+9)9y=(7\sqrt{2} + 9)^{9}y=(72​+9)9. If [t][t][t] denotes the greatest integer ≤t\le t≤t, then:
  1. (A)[x][x][x] is odd but [y][y][y] is even
  2. (B)[x]+[y][x] + [y][x]+[y] is even
  3. (C)[x][x][x] and [y][y][y] are both odd
  4. (D)[x][x][x] is even but [y][y][y] is odd

Correct answer: (B)

Step-by-step solution →
Q81·MathematicsNumerical
Let a line LLL pass through the point P(2,3,1)P(2, 3, 1)P(2,3,1) and be parallel to the line x+3y−2z−2=0=x−y+2zx + 3y - 2z - 2=0=x - y + 2zx+3y−2z−2=0=x−y+2z. If the distance of LLL from the point (5,3,8)(5, 3, 8)(5,3,8) is α\alphaα, then 3α23\alpha^23α2 is equal to _______.

Correct answer: 158

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Q82·MathematicsNumerical
A bag contains six balls of different colours. Two balls are drawn in succession with replacement. The probability that both the balls are of the same colour is ppp. Next four balls are drawn in succession with replacement and the probability that exactly three balls are of the same colour is qqq. If p:q=m:np:q=m:np:q=m:n, where mmm and nnn are coprime, then m+nm + nm+n is equal to _______.

Correct answer: 14

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Q83·MathematicsNumerical
Let P(a1,b1)P(a_1, b_1)P(a1​,b1​) and Q(a2,b2)Q(a_2, b_2)Q(a2​,b2​) be two distinct points on a circle with center C(2,3)C(\sqrt{2}, \sqrt{3})C(2​,3​). Let OOO be the origin and OCOCOC be perpendicular to both CPCPCP and CQCQCQ. If the area of the triangle OCPOCPOCP is 352\dfrac{\sqrt{35}}{2}235​​, then a12+a22+b12+b22a_1^2 + a_2^2 + b_1^2 + b_2^2a12​+a22​+b12​+b22​ is equal to _______.

Correct answer: 24

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Q84·MathematicsNumerical
Let AAA be the area of the region {(x,y):y≥x2, y≥(1−x)2, y≤2x(1−x)}\{(x, y): y \ge x^2,\ y \ge (1 - x)^2,\ y \le 2x(1 - x)\}{(x,y):y≥x2, y≥(1−x)2, y≤2x(1−x)}. Then 540 A540\,A540A is equal to _______.

Correct answer: 25

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Q85·MathematicsNumerical
The 8th8^{th}8th common term of the series S1=3+7+11+15+19+⋯S_1=3 + 7 + 11 + 15 + 19 + \cdotsS1​=3+7+11+15+19+⋯ and S2=1+6+11+16+21+⋯S_2=1 + 6 + 11 + 16 + 21 + \cdotsS2​=1+6+11+16+21+⋯ is _______.

Correct answer: 151

Step-by-step solution →
Q86·MathematicsNumerical
Let A={1,2,3,5,8,9}A=\{1, 2, 3, 5, 8, 9\}A={1,2,3,5,8,9}. Then the number of possible functions f:A→Af: A \to Af:A→A such that f(m⋅n)=f(m)⋅f(n)f(m \cdot n)=f(m) \cdot f(n)f(m⋅n)=f(m)⋅f(n) for every m,n∈Am, n \in Am,n∈A with m⋅n∈Am \cdot n \in Am⋅n∈A is equal to _______.

Correct answer: 432

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Q87·MathematicsNumerical
If ∫sec⁡2x−1 dx=αlog⁡e∣cos⁡2x+β+cos⁡2x(1+cos⁡1βx)∣+constant\displaystyle\int \sqrt{\sec 2x - 1}\,dx=\alpha \log_e\left|\cos 2x + \beta + \sqrt{\cos 2x\left(1 + \cos\dfrac{1}{\beta}x\right)}\right| + \text{constant}∫sec2x−1​dx=αloge​​cos2x+β+cos2x(1+cosβ1​x)​​+constant, then β−α\beta - \alphaβ−α is equal to _______.

Correct answer: 1

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Q88·MathematicsNumerical
If the value of the real number a>0a > 0a>0 for which x2−5ax+1=0x^2 - 5ax + 1=0x2−5ax+1=0 and x2−ax−5=0x^2 - ax - 5=0x2−ax−5=0 have a common real root is 32β\dfrac{3}{\sqrt{2\beta}}2β​3​, then β\betaβ is equal to _______.

Correct answer: 13

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Q89·MathematicsNumerical
The 50th50^{th}50th root of a number xxx is 121212 and the 50th50^{th}50th root of another number yyy is 181818. Then the remainder obtained on dividing (x+y)(x + y)(x+y) by 252525 is _______.

Correct answer: 23

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Q90·MathematicsNumerical
The number of seven-digit odd numbers that can be formed using all the seven digits 1,2,2,2,3,3,51, 2, 2, 2, 3, 3, 51,2,2,2,3,3,5 is _______.

Correct answer: 240

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Parabola 101/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Indefinite Integration 66/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Chemistry in Everyday Life 60/186
  • Diazonium Salts and Reactions 53/186
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