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JEE Main 8 April 2019 Shift 2 Question Paper with Answers

8 April 2019 · April session · 74 questions

74 of the 90 questions from the JEE Main 8 April 2019 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

16 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
25
Chemistry
27
Mathematics
22

Physics — JEE Main 8 April 2019 Shift 2

Q1·PhysicsSingle correct
A solid sphere and solid cylinder of identical radii approach an incline with the same linear velocity (see figure). Both roll without slipping all throughout. The two climb maximum heights hsphh_{sph}hsph​ and hcylh_{cyl}hcyl​ on the incline. The radio hsphhcyl\frac{h_{sph}}{h_{cyl}}hcyl​hsph​​ is given by:
  1. (A)1
  2. (B)45\frac{4}{5}54​
  3. (C)25\frac{2}{\sqrt{5}}5​2​
  4. (D)1415\frac{14}{15}1514​

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
In the circuit shown, a four wire potentiometer is made of a 400 cm long wire, which extends between A and B. The resistance per unit length of the potentiometer wire is r = 0.01 Ω\OmegaΩ/cm. If an ideal voltmeter is connected as shown with jockey J at 50 cm from end A, the expected reading of the voltmeter will be:
  1. (A)0.75V
  2. (B)0.20V
  3. (C)0.25V
  4. (D)0.50V

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
A parallel plate capacitor has 1μ\muμF capacitance. One of its two plates is given +2μ\muμC charge and the other plate, +4μ\muμC charge. The potential difference developed across the capacitor is:
  1. (A)3V
  2. (B)1V
  3. (C)5V
  4. (D)2V

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
If Surface tension (S), Moment of Inertia (I) and Planck's constant (h), were to be taken as the fundamental units, the dimensional formula for linear momentum would be:
  1. (A)S1/2I1/2h0S^{1/2}I^{1/2}h^{0}S1/2I1/2h0
  2. (B)S1/2I3/2h−1S^{1/2}I^{3/2}h^{-1}S1/2I3/2h−1
  3. (C)S3/2I1/2h0S^{3/2}I^{1/2}h^{0}S3/2I1/2h0
  4. (D)S1/2I1/2h−1S^{1/2}I^{1/2}h^{-1}S1/2I1/2h−1

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
Two magnetic dipoles X and Y are placed at a separation d, with their axes perpendicular to each other. The dipole moment of Y is twice that of X. A particle of charge q is passing through their mid-point P, at angle θ=450\theta = 45^{0}θ=450 with the horizontal line as shown in the figure. What would be the magnitude of force on the particle at that instant? (d is much larger than the dimensions of the dipole)
  1. (A)(μ04π)M(d/2)3×qv\left(\frac{\mu_0}{4\pi}\right)\frac{M}{(d/2)^3} \times qv(4πμ0​​)(d/2)3M​×qv
  2. (B)0
  3. (C)(μ04π)2M(d/2)3×qv\left(\frac{\mu_0}{4\pi}\right)\frac{2M}{(d/2)^3} \times qv(4πμ0​​)(d/2)32M​×qv
  4. (D)2(μ04π)M(d/2)3×qv\sqrt{2}\left(\frac{\mu_0}{4\pi}\right)\frac{M}{(d/2)^3} \times qv2​(4πμ0​​)(d/2)3M​×qv

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
A damped harmonic oscillator has a frequency of 5 oscillations per second. The amplitude drops to half its value for every 10 oscillations. The time it will take to drop to 11000\frac{1}{1000}10001​ of the original amplitude is close to:
  1. (A)10s
  2. (B)100s
  3. (C)50s
  4. (D)20s

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
A convex lens (of focal length 20 cm) and a concave mirror, having their principal axes along the same lines, are kept 80 cm apart from each other. The concave mirror is to the right of the convex lens. When an object is kept at a distance of 30 cm to the left o the convex lens, its image remains at the same position even if the concave mirror is removed. The maximum distance of the object for which this concave mirror, by itself would produce a virtual image would be:
  1. (A)20 cm
  2. (B)10 cm
  3. (C)30 cm
  4. (D)20 cm

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
A cell of internal resistance r drives current through an external resistance R. The power delivered by the cell to the external resistance will be maximum when:
  1. (A)R = 0.001 r
  2. (B)R = 1000 r
  3. (C)R = 2r
  4. (D)R = r

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
In a simple pendulum experiment for determination of acceleration due to gravity (g), time taken for 20 oscillations is measured by using a watch of 1 second least count. The mean value of time taken comes out to be 30s.. The length of pendulum is measured by using a meter scale of least count 1 mm and the value obtained is 55.0 cm. The percentage error in the determination of g is close to:
  1. (A)0.7 %
  2. (B)3.5%
  3. (C)6.8%
  4. (D)0.2%

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth is closest to: [Boltzmans Constant kB=1.38×10−23k_B = 1.38 \times 10^{-23}kB​=1.38×10−23 J/K Avogadro number NA=6.02×1026N_A = 6.02 \times 10^{26}NA​=6.02×1026 /kg Radius of Earth: 6.4×1066.4 \times 10^{6}6.4×106 m Gravitation acceleration on Earth = 10 ms−2^{-2}−2]
  1. (A)800k
  2. (B)10410^{4}104 K
  3. (C)3×1053\times 10^{5}3×105
  4. (D)650 K

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
A particle starts from origin O from rest and moves with a uniform acceleration along the positive x −-− axis. Identify all figures that correctly represent the motion qualitatively. (a = acceleration, v = velocity, x = displacement, t = time)
  1. (A)a, b, c
  2. (B)a
  3. (C)b, c
  4. (D)a, b, d

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
The election field in a region is given by E⃗=(Ax+B)i^\vec{E} = (Ax + B)\hat{i}E=(Ax+B)i^ where E is in NC−1^{-1}−1 and x in meters. The values of constants are A = 20 SI unit and B = 10 SI unit. If the potential at x =1 is V1_11​ and that at x = −-−5 is V2_22​ then V1_11​ - V2_22​ is:
  1. (A)320 V
  2. (B)−-−48 V
  3. (C)−-−520 V
  4. (D)180 V

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
Young's moduli of two wires A and B are in the ratio 7 : 4. Wire A is 2 m long and has radius R. Wire A is 2 m long and has radius R. Wire B is 1.5 m long and has radius 2 mm. If the two wires stretch by the same length for a given load, then the value of R is close to:
  1. (A)1.3 mm
  2. (B)1.5 mm
  3. (C)1.7 mm
  4. (D)1.9 mm

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
A body of mass m1_11​ moving with an unknown velocity of v1i^v_1\hat{i}v1​i^ undergoes a collinear collision with a body of mass m2_22​ moving with a velocity v2i^v_2\hat{i}v2​i^. After collision m1_11​ and m2_22​ move with velocities of v3i^v_3\hat{i}v3​i^ and v4i^v_4\hat{i}v4​i^ respectively. If m2_22​ = 0.5 m1_11​ and v3_33​ = 0.5 v1_11​ then v1_11​ is:
  1. (A)v4−v22v_4 - \frac{v_2}{2}v4​−2v2​​
  2. (B)v4−v24v_4 - \frac{v_2}{4}v4​−4v2​​
  3. (C)v4−v2v_4 - v_2v4​−v2​
  4. (D)v4+v2v_4 + v_2v4​+v2​

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
The ratio of mass densities of nuclei of 40Ca^{40}C_a40Ca​ and 16O^{16}O16O is close to:
  1. (A)0.1
  2. (B)5
  3. (C)2
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, RC=1kΩR_C = 1k\OmegaRC​=1kΩ and VCC=10VV_{CC} = 10VVCC​=10V. What is the minimum base current for VCEV_{CE}VCE​ to reach saturation?
  1. (A)7μA7\mu A7μA
  2. (B)40μA40\mu A40μA
  3. (C)10μA10\mu A10μA
  4. (D)100μA100\mu A100μA

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
A positive point charge is released from rest at a distance r0r_0r0​ from a positive line charge with uniform density. The speed (v) of the point charge, as a function of instantaneous distance r from line charge, is proportional to
  1. (A)v∝e+r/r0v \propto e^{+r/r_0}v∝e+r/r0​
  2. (B)v∝ln⁡(rr0)v \propto \ln\left(\dfrac{r}{r_0}\right)v∝ln(r0​r​)
  3. (C)v∝ln⁡(rr0)v \propto \sqrt{\ln\left(\dfrac{r}{r_0}\right)}v∝ln(r0​r​)​
  4. (D)v∝(rr0)v \propto \left(\dfrac{r}{r_0}\right)v∝(r0​r​)

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
Let ∣A⃗1∣=3,∣A⃗2∣=5|\vec{A}_1| = 3, |\vec{A}_2| = 5∣A1​∣=3,∣A2​∣=5, and ∣A⃗1+A⃗2∣=5|\vec{A}_1 + \vec{A}_2| = 5∣A1​+A2​∣=5. The value of (2A⃗1+3A⃗2)⋅(3A⃗1−2A⃗2)(2\vec{A}_1 + 3\vec{A}_2)\cdot(3\vec{A}_1 - 2\vec{A}_2)(2A1​+3A2​)⋅(3A1​−2A2​) is:
  1. (A)−106.5-106.5−106.5
  2. (B)−112.5-112.5−112.5
  3. (C)−118.5-118.5−118.5
  4. (D)−99.5-99.5−99.5

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
In the figure shown, what is the current (in Ampere) drawn from the battery? You are given R1=15Ω,R2=10Ω,R3=20Ω,R4=5Ω,R5=25Ω,R6=30Ω,E=15VR_1 = 15\Omega, R_2 = 10\Omega, R_3 = 20\Omega, R_4 = 5\Omega, R_5 = 25\Omega, R_6 = 30\Omega, E = 15VR1​=15Ω,R2​=10Ω,R3​=20Ω,R4​=5Ω,R5​=25Ω,R6​=30Ω,E=15V
  1. (A)13/2413/2413/24
  2. (B)7/187/187/18
  3. (C)9/329/329/32
  4. (D)20/320/320/3

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70m, then the minimum height of the transmitting antenna should be: (Radius of the Earth =6.4×106= 6.4\times10^{6}=6.4×106 m)
  1. (A)32 m
  2. (B)40 m
  3. (C)51 m
  4. (D)20 m

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsSingle correct
A rocket has to be launched from each in such a way that it never returns. If E is the minimum energy delivered by the rocket launcher, what should be the minimum energy that the launcher should have if the same rocket is to be launched from the surface of the moon? Assume that the density of the earth and the moon are equal and that the earth's volume is 64 times the volume of the moon.
  1. (A)E32\dfrac{E}{32}32E​
  2. (B)E16\dfrac{E}{16}16E​
  3. (C)E64\dfrac{E}{64}64E​
  4. (D)E4\dfrac{E}{4}4E​

Correct answer: (B)

Step-by-step solution →
Q22·PhysicsSingle correct
A circuit connected to an ac source of emf e=e0sin⁡(1000t)e = e_0\sin(1000t)e=e0​sin(1000t) with t in seconds, gives a phase difference of π4\dfrac{\pi}{4}4π​ between the emf e and current i. Which of the following circuits will exhibit this?
  1. (A)RC circuit with R=1kΩR = 1k\OmegaR=1kΩ and C=1μFC = 1\mu FC=1μF
  2. (B)RL circuit with R=1kΩR = 1k\OmegaR=1kΩ and L=10mHL = 10mHL=10mH
  3. (C)RL circuit with R=1kΩR = 1k\OmegaR=1kΩ and L=1mHL = 1mHL=1mH
  4. (D)RC circuit with R=1kΩR = 1k\OmegaR=1kΩ and C=10μFC = 10\mu FC=10μF

Correct answer: (D)

Step-by-step solution →
Q23·PhysicsSingle correct
Calculate the limit of resolution of a telescope objective having a diameter of 200 cm, if it has to detect light of wavelength 500 nm coming from a star.
  1. (A)457.5×10−9457.5\times10^{-9}457.5×10−9 radian
  2. (B)610×10−9610\times10^{-9}610×10−9 radian
  3. (C)305×10−9305\times10^{-9}305×10−9 radian
  4. (D)152.5×10−9152.5\times10^{-9}152.5×10−9 radian

Correct answer: (C)

Step-by-step solution →
Q24·PhysicsSingle correct
Two very long, straight and insulated wires are kept at 90090^{0}900 angle from each other In xy-plane as shown in the figure. These wires carry currently of equal magnitude I, whose directions are shown in the figure. The met magnetic field at point P will be:
  1. (A)μ0I2πd(x^+y^)\dfrac{\mu_0 I}{2\pi d}(\hat{x}+\hat{y})2πdμ0​I​(x^+y^​)
  2. (B)+μ0Iπd(z^)\dfrac{+\mu_0 I}{\pi d}(\hat{z})πd+μ0​I​(z^)
  3. (C)Zero
  4. (D)−μ0I2πd(x^+y^)-\dfrac{\mu_0 I}{2\pi d}(\hat{x}+\hat{y})−2πdμ0​I​(x^+y^​)

Correct answer: (C)

Step-by-step solution →
Q25·PhysicsSingle correct
A uniform rectangular thin sheet ABCD of mass M has length a and breadth b, as shown in the figure. If the shaded portion HBGO is cut off, the coordinates of the centre of mass of the remaining portion will be:
  1. (A)(5a3,5b3)\left(\dfrac{5a}{3}, \dfrac{5b}{3}\right)(35a​,35b​)
  2. (B)(2a3,2b3)\left(\dfrac{2a}{3}, \dfrac{2b}{3}\right)(32a​,32b​)
  3. (C)(3a4,3b4)\left(\dfrac{3a}{4}, \dfrac{3b}{4}\right)(43a​,43b​)
  4. (D)(5a12,5b12)\left(\dfrac{5a}{12}, \dfrac{5b}{12}\right)(125a​,125b​)

Correct answer: (D)

Step-by-step solution →

Chemistry — JEE Main 8 April 2019 Shift 2

Q26·ChemistrySingle correct
The statement that is INCORRECT about the interstitial compound is:
  1. (A)they have metallic conductivity
  2. (B)they have high melting points
  3. (C)they are chemically reactive
  4. (D)they are very hard

Correct answer: (C)

Step-by-step solution →
Q27·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q28·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correct
The ion that has sp3d2sp^{3}d^{2}sp3d2 hybridization for the central atom is:
  1. (A)[IF6]−[IF_{6}]^{-}[IF6​]−
  2. (B)[ICl4]−[ICl_{4}]^{-}[ICl4​]−
  3. (C)[ICl2]−[ICl_{2}]^{-}[ICl2​]−
  4. (D)[BrF2]−[BrF_{2}]^{-}[BrF2​]−

Correct answer: (B)

Step-by-step solution →
Q30·ChemistrySingle correct
The major product obtained in the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q31·ChemistrySingle correct
For a reaction scheme. A→k1B→k2CA\xrightarrow{k_{1}}B\xrightarrow{k_{2}}CAk1​​Bk2​​C if the rate of formation of B is set to be zero then the concentration of B is given by
  1. (A)(k1k2)[A]\left(\dfrac{k_{1}}{k_{2}}\right)[A](k2​k1​​)[A]
  2. (B)(k1−k2)[A](k_{1}-k_{2})[A](k1​−k2​)[A]
  3. (C)k1k2[A]k_{1}k_{2}[A]k1​k2​[A]
  4. (D)(k1+k2)[A](k_{1}+k_{2})[A](k1​+k2​)[A]

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
For the following reactions, equilibrium constants are given: S(s)+O2(g)⇌SO2(g);K1=1052S(s)+O_{2}(g)\rightleftharpoons SO_{2}(g);K_{1}=10^{52}S(s)+O2​(g)⇌SO2​(g);K1​=1052 2S(s)+3O2(g)⇌2SO3(g);K2=101292S(s)+3O_{2}(g)\rightleftharpoons 2SO_{3}(g);K_{2}=10^{129}2S(s)+3O2​(g)⇌2SO3​(g);K2​=10129 The equilibrium constant for the reaction 2SO2(g)+O2(g)⇌2SO3(g)2SO_{2}(g)+O_{2}(g)\rightleftharpoons 2SO_{3}(g)2SO2​(g)+O2​(g)⇌2SO3​(g) is:
  1. (A)107710^{77}1077
  2. (B)102510^{25}1025
  3. (C)1018110^{181}10181
  4. (D)1015410^{154}10154

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
Calculate the standard cell potential (in V) of the cell in which following reaction takes place: Fe2+(aq)+Ag+(aq)→Fe3+(aq)+Ag(s)Fe^{2}+(aq)+Ag^{+}(aq)\rightarrow Fe^{3+}(aq)+Ag(s)Fe2+(aq)+Ag+(aq)→Fe3+(aq)+Ag(s) Given that: EAg′/Ag0=xVE^{0}_{Ag'/Ag}=xVEAg′/Ag0​=xV EFe2+/Fe0=yVE^{0}_{Fe^{2+}/Fe}=yVEFe2+/Fe0​=yV EFe3+/Fe0=zVE^{0}_{Fe^{3+}/Fe}=zVEFe3+/Fe0​=zV
  1. (A)x \u2212 z
  2. (B)x + y \u2212 z
  3. (C)x \u2212 y
  4. (D)x + 2y \u2212 3z

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
The covalent alkaline earth metal halide (X=Cl,Br,I)(X=Cl,Br,I)(X=Cl,Br,I) is:
  1. (A)BeX2BeX_{2}BeX2​
  2. (B)CaX2CaX_{2}CaX2​
  3. (C)SrX2SrX_{2}SrX2​
  4. (D)MgX2MgX_{2}MgX2​

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
The structure of Nylon \u2013 6 is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
The IUPAC symbols for the element with atomic number 119 would be:
  1. (A)uun
  2. (B)uue
  3. (C)unh
  4. (D)une

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
Which of the following compounds will show the maximum 'enol' content?
  1. (A)CH3COCH3CH_{3}COCH_{3}CH3​COCH3​
  2. (B)CH3COCH2CONH2CH_{3}COCH_{2}CONH_{2}CH3​COCH2​CONH2​
  3. (C)CH3COCH2COCH3CH_{3}COCH_{2}COCH_{3}CH3​COCH2​COCH3​
  4. (D)CH3COCH2COOC2H5CH_{3}COCH_{2}COOC_{2}H_{5}CH3​COCH2​COOC2​H5​

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
0.27 g of a long chain fatty acid was dissolved in 100 cm3cm^{3}cm3 of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. What is the height of the monolayer? [Density of fatty acid =0.9gcm−3=0.9\\ g\\ cm^{-3}=0.9gcm−3, π=3\pi=3π=3]
  1. (A)10−410^{-4}10−4 m
  2. (B)10−810^{-8}10−8 m
  3. (C)10−210^{-2}10−2 m
  4. (D)10−610^{-6}10−6 m

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
The percentage composition of carbon by mole in methane is:
  1. (A)80%
  2. (B)20%
  3. (C)75%
  4. (D)25%

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
The Mond process is used for the:
  1. (A)Extraction of Mo
  2. (B)Extraction of Zn
  3. (C)Purification of Zr and Ti
  4. (D)Purification of Ni

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correct
Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?
  1. (A)H2N−CH=CH2H_2N-CH=CH_2H2​N−CH=CH2​
  2. (B)F3C−CH=CH2F_3C-CH=CH_2F3​C−CH=CH2​
  3. (C)CH3O−CH=CH2CH_3O-CH=CH_2CH3​O−CH=CH2​
  4. (D)Cl−CH=CH2Cl-CH=CH_2Cl−CH=CH2​

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV=28 JK−1mol−1C_V=28\ JK^{-1}mol^{-1}CV​=28 JK−1mol−1, calculate ΔU\Delta UΔU and ΔpV\Delta pVΔpV for this process. (R = 8.0 J K−1^{-1}−1 mol−1^{-1}−1)
  1. (A)ΔU=2.8kJ;Δ(pV)=0.8kJ\Delta U=2.8kJ;\Delta(pV)=0.8kJΔU=2.8kJ;Δ(pV)=0.8kJ
  2. (B)ΔU=14kJ;Δ(pV)=4kJ\Delta U=14kJ;\Delta(pV)=4kJΔU=14kJ;Δ(pV)=4kJ
  3. (C)ΔU=14kJ;Δ(pV)=18kJ\Delta U=14kJ;\Delta(pV)=18kJΔU=14kJ;Δ(pV)=18kJ
  4. (D)ΔU=14kJ;Δ(pV)=0.8J\Delta U=14kJ;\Delta(pV)=0.8JΔU=14kJ;Δ(pV)=0.8J

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Fructose and glucose can be distinguished by:
  1. (A)Benedict's test
  2. (B)Fehling's test
  3. (C)Barfoed's test
  4. (D)Seliwanoff's test

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
The major product in the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
Polysubstitution is a major drawback in:
  1. (A)Friedel Craft's alkylation
  2. (B)Reimer Tiemann reaction
  3. (C)Acetylation of aniline
  4. (D)Friedel Craft's acylation

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
The strength of 11.2 volume solution of H2O2H_2O_2H2​O2​ is: [Given that molar mass of H = 1 g mol−1^{-1}−1 and O = 16 g mol−1^{-1}−1]
  1. (A)3.4%
  2. (B)1.7%
  3. (C)13.6%
  4. (D)34%

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
Among the following molecules / ions C22−,N22−,O22−,O2C_2^{2-},N_2^{2-},O_2^{2-},O_2C22−​,N22−​,O22−​,O2​ which one is diamagnetic and has the shortest bond length?
  1. (A)O22−O_2^{2-}O22−​
  2. (B)C22−C_2^{2-}C22−​
  3. (C)O2O_2O2​
  4. (D)N22−N_2^{2-}N22−​

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
The major product obtained in the following reactions is"
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
The maximum prescribed concentration of copper in drinking water is:
  1. (A)0.5 ppm
  2. (B)3 ppm
  3. (C)5 ppm
  4. (D)0.05 ppm

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
The correct statement about ICl5ICl_5ICl5​ and ICl4−ICl_4^-ICl4−​ is:
  1. (A)ICl5ICl_5ICl5​ is trigonal bipyramidal and ICl4−ICl_4^-ICl4−​ is tetrahedral
  2. (B)ICl5ICl_5ICl5​ is square pyramidal and ICl4−ICl_4^-ICl4−​ is square planar
  3. (C)ICl5ICl_5ICl5​ is square pyramidal and ICl4−ICl_4^-ICl4−​ is tetrahedral
  4. (D)Both are isostructural

Correct answer: (B)

Step-by-step solution →
Q51·ChemistrySingle correct
The compound that inhibits the growth of tumors is:
  1. (A)trans - [Pd(Cl)2(NH3)2][Pd(Cl)_2(NH_3)_2][Pd(Cl)2​(NH3​)2​]
  2. (B)trans - [Pt(Cl)2(NH3)2][Pt(Cl)_2(NH_3)_2][Pt(Cl)2​(NH3​)2​]
  3. (C)cis - [Pd(Cl)2(NH3)2][Pd(Cl)_2(NH_3)_2][Pd(Cl)2​(NH3​)2​]
  4. (D)cis - [Pt(Cl)2(NH3)2][Pt(Cl)_2(NH_3)_2][Pt(Cl)2​(NH3​)2​]

Correct answer: (D)

Step-by-step solution →
Q52·ChemistrySingle correct
Consider the bcc unit cells of the solid 1 and 2 with the position of atoms as shown below. The radius of atom B is twice that of atom A. The unit cell edge length is 50% more in solid 2 than in 1. What is the approximate packing efficiency in solid 2?
  1. (A)90%
  2. (B)75%
  3. (C)65%
  4. (D)45%

Correct answer: (A)

Step-by-step solution →

Mathematics — JEE Main 8 April 2019 Shift 2

Q53·MathematicsSingle correct
Let f(x)=∫0xg(t) dtf(x)=\int_{0}^{x} g(t)\,dtf(x)=∫0x​g(t)dt, were g is a non zero even function. If f(x+5)=g(x)f(x+5)=g(x)f(x+5)=g(x), then ∫0xf(t) dt\int_{0}^{x} f(t)\,dt∫0x​f(t)dt equals
  1. (A)∫x+55g(t) dt\int_{x+5}^{5} g(t)\,dt∫x+55​g(t)dt
  2. (B)2∫5x−5g(t) dt2\int_{5}^{x-5} g(t)\,dt2∫5x−5​g(t)dt
  3. (C)∫5x+5g(t) dt\int_{5}^{x+5} g(t)\,dt∫5x+5​g(t)dt
  4. (D)5∫x+55g(t) dt5\int_{x+5}^{5} g(t)\,dt5∫x+55​g(t)dt

Correct answer: (A)

Step-by-step solution →
Q54·MathematicsSingle correct
Suppose that the points (h,k)(h,k)(h,k), (1,2)(1,2)(1,2) and (−3,4)(-3,4)(−3,4) lie on the line L1L_{1}L1​. If a line L2L_{2}L2​ passing through the points (h,k)(h,k)(h,k) and (4,3)(4,3)(4,3) is perpendicular to L1L_{1}L1​, then kh\frac{k}{h}hk​ equals:
  1. (A)−17-\frac{1}{7}−71​
  2. (B)13\frac{1}{3}31​
  3. (C)3
  4. (D)0

Correct answer: (B)

Step-by-step solution →
Q55·MathematicsSingle correct
Let f(x)=axf(x)=a^{x}f(x)=ax (a>0)(a>0)(a>0) be written as f(x)=f1(x)+f2(x)f(x)=f_{1}(x)+f_{2}(x)f(x)=f1​(x)+f2​(x), where f1(x)f_{1}(x)f1​(x) is an even function and f2(x)f_{2}(x)f2​(x) is an odd function. Then f1(x+y)+f1(x−y)f_{1}(x+y)+f_{1}(x-y)f1​(x+y)+f1​(x−y) equals
  1. (A)2f1(x)f2(y)2f_{1}(x)f_{2}(y)2f1​(x)f2​(y)
  2. (B)2f1(x)f1(y)2f_{1}(x)f_{1}(y)2f1​(x)f1​(y)
  3. (C)2f1(x+y)f2(x−y)2f_{1}(x+y)f_{2}(x-y)2f1​(x+y)f2​(x−y)
  4. (D)2f1(x+y)f1(x−y)2f_{1}(x+y)f_{1}(x-y)2f1​(x+y)f1​(x−y)

Correct answer: (B)

Step-by-step solution →
Q56·MathematicsSingle correct
If z=32+i2(i+−1)z=\frac{\sqrt{3}}{2}+\frac{i}{2}\left(i+\sqrt{-1}\right)z=23​​+2i​(i+−1​), then (1+iz+z5+iz8)9\left(1+iz+z^{5}+iz^{8}\right)^{9}(1+iz+z5+iz8)9 is equal to:
  1. (A)-1
  2. (B)1
  3. (C)(−1+2i)9(-1+2i)^{9}(−1+2i)9
  4. (D)0

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correct
Given that the slope of the tangent to a curve y=y(x)y=y(x)y=y(x) at any point (x,y)(x,y)(x,y) is 2yx2\frac{2y}{x^{2}}x22y​. If the curve passes through the centre of the circle x2+y2−2x−2y=0x^{2}+y^{2}-2x-2y=0x2+y2−2x−2y=0, then its equation is:
  1. (A)xlog⁡e∣y∣=x−1x\log_{e}|y|=x-1xloge​∣y∣=x−1
  2. (B)xlog⁡e∣y∣=−2(x−1)x\log_{e}|y|=-2(x-1)xloge​∣y∣=−2(x−1)
  3. (C)x2log⁡e∣y∣=−2(x−1)x^{2}\log_{e}|y|=-2(x-1)x2loge​∣y∣=−2(x−1)
  4. (D)xlog⁡e∣y∣=2(x−1)x\log_{e}|y|=2(x-1)xloge​∣y∣=2(x−1)

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsSingle correct
If f(1)=1,f′(1)=3f(1)=1, f'(1)=3f(1)=1,f′(1)=3, then the derivative of f(f(f(x)))+(f(x))2f(f(f(x)))+(f(x))^{2}f(f(f(x)))+(f(x))2 at x=1x=1x=1 is:
  1. (A)33
  2. (B)15
  3. (C)9
  4. (D)12

Correct answer: (A)

Step-by-step solution →
Q59·MathematicsSingle correct
The number of four \u2013 digit numbers strictly greater than 4321 that can be formed using the digits 0, 1, 2, 3, 4, 5 (repetition of digits is allowed) is:
  1. (A)360
  2. (B)288
  3. (C)310
  4. (D)306

Correct answer: (C)

Step-by-step solution →
Q60·MathematicsSingle correct
If a point R(4,y,z)R(4,y,z)R(4,y,z) lies on the line segment joining the points P(2,−3,4)P(2,-3,4)P(2,−3,4) and Q(8,0,10)Q(8,0,10)Q(8,0,10), then the distance of R from the origin is:
  1. (A)53\sqrt{53}53​
  2. (B)6
  3. (C)2142\sqrt{14}214​
  4. (D)2212\sqrt{21}221​

Correct answer: (C)

Step-by-step solution →
Q61·MathematicsSingle correct
If the system of linear equations x−2y+kz=1x-2y+kz=1x−2y+kz=1, 2x+y+z=22x+y+z=22x+y+z=2, 3x−y−kz=33x-y-kz=33x−y−kz=3 has a solution (x,y,z)≠0(x,y,z)\ne 0(x,y,z)=0, then (x,y)(x,y)(x,y) lies on the straight line whose equation is:
  1. (A)3x−4y−1=03x-4y-1=03x−4y−1=0
  2. (B)4x−3y−4=04x-3y-4=04x−3y−4=0
  3. (C)4x−3y−1=04x-3y-1=04x−3y−1=0
  4. (D)3x−4y−4=03x-4y-4=03x−4y−4=0

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
A student score the following marks in five tests : 45, 54, 41, 57, 43. His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is:
  1. (A)103\frac{10}{3}310​
  2. (B)1003\frac{100}{3}3100​
  3. (C)1003\frac{100}{\sqrt{3}}3​100​
  4. (D)103\frac{10}{\sqrt{3}}3​10​

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
The vector equation of the plane through the line of intersection of the planes x+y+z=1x+y+z=1x+y+z=1 and 2x+3y+4z=52x+3y+4z=52x+3y+4z=5 which is perpendicular to the plane x−y+z=0x-y+z=0x−y+z=0 is:
  1. (A)r⃗×(i^−k^)+2=0\vec{r}\times(\hat{i}-\hat{k})+2=0r×(i^−k^)+2=0
  2. (B)r⃗.(i^−k^)−2=0\vec{r}.(\hat{i}-\hat{k})-2=0r.(i^−k^)−2=0
  3. (C)r⃗.(i^−k^)+2=0\vec{r}.(\hat{i}-\hat{k})+2=0r.(i^−k^)+2=0
  4. (D)x⃗×(i^−k^)+2=0\vec{x}\times(\hat{i}-\hat{k})+2=0x×(i^−k^)+2=0

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
If the lengths of the sides of a triangle are in A.P. and the greatest angle is double the smallest, then a ratio of lengths of the sides of this triangle:
  1. (A)4:5:6
  2. (B)5:6:7
  3. (C)3:4:5
  4. (D)5:9:13

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
In an ellipse, with centre at the origin, if the difference of the lengths of major axis and minor axis is 10 and one of the foci is at (0,53)(0, 5\sqrt{3})(0,53​), then the length of its latus rectum is:
  1. (A)6
  2. (B)5
  3. (C)8
  4. (D)10

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
The minimum number of times one has to toss a fair coin so that the probability; of observing at least one head is at least 90% is:
  1. (A)2
  2. (B)3
  3. (C)4
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
If the eccentricity of the standard hyperbola passing, through the point (4, 6) is 2, then the equation of the tangent to the hyperbola at (4, 6) is:
  1. (A)2x−3y+10=02x-3y+10=02x−3y+10=0
  2. (B)x−2y+8=0x-2y+8=0x−2y+8=0
  3. (C)2x−y−2=02x-y-2=02x−y−2=0
  4. (D)3x−2y=03x-2y=03x−2y=0

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
The number of integral values of m for which the equation (1+m2)x2−2(1+3m)x+(1+8m)=0\left(1+m^{2}\right)x^{2}-2(1+3m)x+(1+8m)=0(1+m2)x2−2(1+3m)x+(1+8m)=0 has no real root is:
  1. (A)infinitely many
  2. (B)2
  3. (C)3
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
Then sum ∑k=120k12k\sum_{k=1}^{20}k\frac{1}{2^{k}}∑k=120​k2k1​ is equal to:
  1. (A)2−112192-\frac{11}{2^{19}}2−21911​
  2. (B)1−112201-\frac{11}{2^{20}}1−22011​
  3. (C)2−212202-\frac{21}{2^{20}}2−22021​
  4. (D)2−32172-\frac{3}{2^{17}}2−2173​

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
Let a⃗=3i^+2j^+xk^\vec{a}=3\hat{i}+2\hat{j}+x\hat{k}a=3i^+2j^​+xk^ and b⃗=i^−−j^+k^\vec{b}=\hat{i}--\hat{j}+\hat{k}b=i^−−j^​+k^, for some real x. Then ∣a⃗×b⃗∣=r|\vec{a}\times\vec{b}|=r∣a×b∣=r is possible if:
  1. (A)r≥532r\geq5\sqrt{\frac{3}{2}}r≥523​​
  2. (B)332<r<5323\sqrt{\frac{3}{2}}<r<5\sqrt{\frac{3}{2}}323​​<r<523​​
  3. (C)32<r≤332\sqrt{\frac{3}{2}}<r\leq3\sqrt{\frac{3}{2}}23​​<r≤323​​
  4. (D)0<r≤320<r\leq\sqrt{\frac{3}{2}}0<r≤23​​

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Then tangent and the normal lines at the point (3,1)(\sqrt{3},1)(3​,1) to the circle x2+y2=4x^{2}+y^{2}=4x2+y2=4 and the x-axis form a triangle. The area of this triangle (in square units) is:
  1. (A)13\frac{1}{\sqrt{3}}3​1​
  2. (B)43\frac{4}{\sqrt{3}}3​4​
  3. (C)13\frac{1}{3}31​
  4. (D)23\frac{2}{\sqrt{3}}3​2​

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
The tangent to the parabola y2=4xy^{2}=4xy2=4x at the point where it intersects the circle x2+y2=5x^{2}+y^{2}=5x2+y2=5 in the first quadrant, passes through the point:
  1. (A)(−13,43)\left(-\frac{1}{3},\frac{4}{3}\right)(−31​,34​)
  2. (B)(34,74)\left(\frac{3}{4},\frac{7}{4}\right)(43​,47​)
  3. (C)(−14,12)\left(-\frac{1}{4},\frac{1}{2}\right)(−41​,21​)
  4. (D)(14,34)\left(\frac{1}{4},\frac{3}{4}\right)(41​,43​)

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
The height of a right circular cylinder of maximum volume inscribed in a sphere of radius 3 is:
  1. (A)3\sqrt{3}3​
  2. (B)6\sqrt{6}6​
  3. (C)232\sqrt{3}23​
  4. (D)233\frac{2}{3}\sqrt{3}32​3​

Correct answer: (C)

Step-by-step solution →
Q74·MathematicsSingle correct
Let f:R→Rf:R\rightarrow Rf:R→R be a differentiable function satisfying f′′(3)+f′(2)=0f''(3)+f'(2)=0f′′(3)+f′(2)=0. Then lim⁡x→∞(1+f(3+x)−f(3)1+f(2−x)−f(2))1x\lim_{x\rightarrow\infty}\left(\frac{1+f(3+x)-f(3)}{1+f(2-x)-f(2)}\right)^{\frac{1}{x}}limx→∞​(1+f(2−x)−f(2)1+f(3+x)−f(3)​)x1​ is equal to:
  1. (A)e2e^{2}e2
  2. (B)1
  3. (C)e
  4. (D)e−1e^{-1}e−1

Correct answer: (B)

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Kinetic Theory of Gases 135/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Polymers 64/186
  • Solid State 63/186
  • Magnetism and Matter 50/186
  • Communication Systems 11/186
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