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JEE Main 9 April 2019 Shift 1 Question Paper with Answers

9 April 2019 · April session · 78 questions

78 of the 90 questions from the JEE Main 9 April 2019 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

12 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
24
Chemistry
26
Mathematics
28

Physics — JEE Main 9 April 2019 Shift 1

Q1·PhysicsSingle correct
The total number of turns and cross-section area in solenoid is fixed. However, its length L is varied by adjusting the separation between windings. The inductance of solenoid will be proportional to:
  1. (A)1/L
  2. (B)L
  3. (C)1/L2^22
  4. (D)L2^22

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
A system of three charges are placed as shown in the figure: If D >> d, the potential energy of the system is best given by:
  1. (A)14πεo[−q2d−qQdD2]\frac{1}{4\pi\varepsilon_o}\left[-\frac{q^2}{d}-\frac{qQd}{D^2}\right]4πεo​1​[−dq2​−D2qQd​]
  2. (B)14πεo[−q2d−qQd2D2]\frac{1}{4\pi\varepsilon_o}\left[-\frac{q^2}{d}-\frac{qQd}{2D^2}\right]4πεo​1​[−dq2​−2D2qQd​]
  3. (C)14πεo[−q2d+2qQdD2]\frac{1}{4\pi\varepsilon_o}\left[-\frac{q^2}{d}+\frac{2qQd}{D^2}\right]4πεo​1​[−dq2​+D22qQd​]
  4. (D)14πεo[+q2d−qQdD2]\frac{1}{4\pi\varepsilon_o}\left[+\frac{q^2}{d}-\frac{qQd}{D^2}\right]4πεo​1​[+dq2​−D2qQd​]

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
A moving coil galvanometer has resistance 50 Ω and it indicates full deflection at 4mA current. A voltmeter is made using this galvanometer and a 5 kΩ resistance. The maximum voltage, that can be measured using this voltamenter, will be close to:
  1. (A)15 V
  2. (B)20 V
  3. (C)10 V
  4. (D)40 V

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius '2r' is:
  1. (A)4 M
  2. (B)M2\frac{M}{2}2M​
  3. (C)M
  4. (D)2 M

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
An NPN transistor is used in common emitter configuration as an amplifier with 1 kΩ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15 μA change in the base current of the amplifier. The input resistance and voltage gain are:
  1. (A)0.67 kΩ, 300
  2. (B)0.67 kΩ, 200
  3. (C)0.33 kΩ, 1.5
  4. (D)0.33 kΩ, 300

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
The electric field of light wave is given as E⃗=10−3cos⁡(2πx5×10−7−2π×6×1014t)x^NC\vec{E}=10^{-3}\cos\left(\frac{2\pi x}{5\times10^{-7}}-2\pi\times6\times10^{14}t\right)\hat{x}\frac{N}{C}E=10−3cos(5×10−72πx​−2π×6×1014t)x^CN​. This light falls on a metal plate of work function 2eV. The stopping potential of the photoelectrons is:
  1. (A)0.48 V
  2. (B)2.48 V
  3. (C)0.72 V
  4. (D)2.0 V

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
Following figure shows two processes A and B for a gas. If ΔQA\Delta Q_AΔQA​ and ΔQB\Delta Q_BΔQB​ are the amount of heat absorbed by the system in two cases, and ΔUA\Delta U_AΔUA​ and ΔUB\Delta U_BΔUB​ are changes in internal energies, respectively, then:
  1. (A)ΔQA=ΔQB;ΔUA=ΔUB\Delta Q_A=\Delta Q_B; \Delta U_A=\Delta U_BΔQA​=ΔQB​;ΔUA​=ΔUB​
  2. (B)ΔQA>ΔQB;ΔUA=ΔUB\Delta Q_A>\Delta Q_B; \Delta U_A=\Delta U_BΔQA​>ΔQB​;ΔUA​=ΔUB​
  3. (C)ΔQA<ΔQB;ΔUA<ΔUB\Delta Q_A<\Delta Q_B; \Delta U_A<\Delta U_BΔQA​<ΔQB​;ΔUA​<ΔUB​
  4. (D)ΔQA>ΔQB;ΔUA>ΔUB\Delta Q_A>\Delta Q_B; \Delta U_A>\Delta U_BΔQA​>ΔQB​;ΔUA​>ΔUB​

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
A uniform cable of mass 'M' and length 'L' is placed on a horizontal surface such that its (1n)th\left(\frac{1}{n}\right)^{th}(n1​)th part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be:
  1. (A)nMgL
  2. (B)MgL2n2\frac{MgL}{2n^2}2n2MgL​
  3. (C)2MgLn2\frac{2MgL}{n^2}n22MgL​
  4. (D)MgLn2\frac{MgL}{n^2}n2MgL​

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
A signal A cosω\omegaωt is transmitted using ν0\nu_0ν0​ sinω0\omega_0ω0​t as carrier wave. The correct amplitude modulated (AM) signal is:
  1. (A)ν0sin⁡[ω0(1+0.01Asin⁡ωt)t]\nu_0\sin\left[\omega_0(1+0.01A\sin\omega t)t\right]ν0​sin[ω0​(1+0.01Asinωt)t]
  2. (B)ν0sin⁡ω0t+A2sin⁡(ω0−ω)t+A2sin⁡(ω0+ω)t\nu_0\sin\omega_0t+\frac{A}{2}\sin(\omega_0-\omega)t+\frac{A}{2}\sin(\omega_0+\omega)tν0​sinω0​t+2A​sin(ω0​−ω)t+2A​sin(ω0​+ω)t
  3. (C)ν0sin⁡ω0t+Acos⁡ωt\nu_0\sin\omega_0t+A\cos\omega tν0​sinω0​t+Acosωt
  4. (D)(ν0+A)cos⁡ωtsin⁡ω0t(\nu_0+A)\cos\omega t\sin\omega_0t(ν0​+A)cosωtsinω0​t

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
A concave mirror for face viewing has focal length of 0.4 m. The distance at which you hold the mirror from your face in order to see your image upright with a magnification of 5 is:
  1. (A)0.16 m
  2. (B)1.60 m
  3. (C)0.24 m
  4. (D)0.32 m

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
Determine the charge on the capacitor in the following circuit:
  1. (A)200 μC
  2. (B)60 μC
  3. (C)10 μC
  4. (D)2 μC

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ\thetaθ, where θ\thetaθ is the angle by which it has rotated, is given as kθ2k\theta^2kθ2. If its moment of inertia is I then the angular acceleration of the disc is:
  1. (A)kIθ\dfrac{k}{I}\thetaIk​θ
  2. (B)k2Iθ\dfrac{k}{2I}\theta2Ik​θ
  3. (C)k4Iθ\dfrac{k}{4I}\theta4Ik​θ
  4. (D)2kIθ\dfrac{2k}{I}\thetaI2k​θ

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is 116\dfrac{1}{16}161​th of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is:
  1. (A)2T1102T\sqrt{\dfrac{1}{10}}2T101​​
  2. (B)2T1142T\sqrt{\dfrac{1}{14}}2T141​​
  3. (C)4T1154T\sqrt{\dfrac{1}{15}}4T151​​
  4. (D)4T1144T\sqrt{\dfrac{1}{14}}4T141​​

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at 127°C. At 2 atm pressure and at 227°C, the rms speed of the molecules will be:
  1. (A)80 m/s
  2. (B)80580\sqrt{5}805​ m / s
  3. (C)100 m/s
  4. (D)1005100\sqrt{5}1005​ m / s

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
The magnetic field of a plane electromagnetic wave is given by: B⃗=B0i^[cos⁡(kz−ωt)]+B1j^cos⁡(kz−ωt)\vec{B} = B_0\hat{i}[\cos(kz-\omega t)] + B_1\hat{j}\cos(kz-\omega t)B=B0​i^[cos(kz−ωt)]+B1​j^​cos(kz−ωt) where B0=3×10−5B_0 = 3\times 10^{-5}B0​=3×10−5T and B1=2×10−6B_1 = 2\times 10^{-6}B1​=2×10−6T. The rms value of the force experienced by a stationary charge Q=10−4=CQ = 10^{-4}=CQ=10−4=C at z=0z = 0z=0 is closet to:
  1. (A)0.9 N
  2. (B)0.6 N
  3. (C)0.1 N
  4. (D)3×10−23\times 10^{-2}3×10−2N

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
The stream of a river is flowing with a speed of 2 km/h. A swimmer can swim at a speed of 4 km/h. What should be the direction of the swimmer with respect to the flow of the river to cross the river straight?
  1. (A)60°
  2. (B)90°
  3. (C)120°
  4. (D)150°

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A rigid square loop of side 'a' and carrying current I2I_2I2​ is laying on a horizontal surface near a long current I1I_1I1​ wire in the same plane as shown in figure. The net force on the loop due to the wire will be:
  1. (A)Repulsive and equal to μ0I1I22π\dfrac{\mu_0 I_1 I_2}{2\pi}2πμ0​I1​I2​​
  2. (B)Attractive and equal to μ0I1I23π\dfrac{\mu_0 I_1 I_2}{3\pi}3πμ0​I1​I2​​
  3. (C)Zero
  4. (D)Repulsive and equal to μ0I1I24π\dfrac{\mu_0 I_1 I_2}{4\pi}4πμ0​I1​I2​​

Correct answer: (D)

Step-by-step solution →
Q18·PhysicsSingle correct
A solid sphere of mass 'M' and radius 'a' is surrounded by a uniform concentric spherical shell of thickness 2a and mass 2M. The gravitational field at distance '3a' from the centre will be:
  1. (A)2GM3a2\dfrac{2GM}{3a^2}3a22GM​
  2. (B)2GM9a2\dfrac{2GM}{9a^2}9a22GM​
  3. (C)GM9a2\dfrac{GM}{9a^2}9a2GM​
  4. (D)GM3a2\dfrac{GM}{3a^2}3a2GM​

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
A string is clamed at both the ends and it is vibrating in its 4th harmonic. The equation of the stationary wave is Y=0.3sin⁡(0.157x)cos⁡(200πt)Y = 0.3\sin(0.157x)\cos(200\pi t)Y=0.3sin(0.157x)cos(200πt). The length of the string is: (all quantities are in SI units)
  1. (A)80 m
  2. (B)60 m
  3. (C)40 m
  4. (D)20 m

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correct
A ball is thrown vertically up (taken as +z-axis) from the ground. The correct momentum-height (p-h) diagram is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsSingle correct
A capacitor with capacitance 5 μF is charged to 5 μC. If the plates are pulled apart to reduce the capacitance to 2 μF, how much work is done?
  1. (A)3.75×10−63.75\times10^{-6}3.75×10−6 J
  2. (B)2.55×10−62.55\times10^{-6}2.55×10−6 J
  3. (C)6.25×10−66.25\times10^{-6}6.25×10−6 J
  4. (D)2.16×10−62.16\times10^{-6}2.16×10−6 J

Correct answer: (A)

Step-by-step solution →
Q22·PhysicsSingle correct
A body of mass 2 kg makes an elastic collision with a second body at rest and continues to move in the original direction but with one fourth of its original speed. What is the mass of the second body?
  1. (A)1.5 kg
  2. (B)1.2 kg
  3. (C)1.8 kg
  4. (D)1.0 kg

Correct answer: (B)

Step-by-step solution →
Q23·PhysicsSingle correct
The pressure wave, P = 0.01sin[1000t−3x]0.01sin[1000t-3x]0.01sin[1000t−3x]NM−2^{-2}−2, corresponds to the sound produced by a vibrating blade on a day when atmospheric temperature is 0°C. On some other day when temperature is T, the speed of sound produced by the same blade and at the same frequency is found to be 336 ms−1^{-1}−1. Approximate value of T is:
  1. (A)12°C
  2. (B)11°C
  3. (C)15°C
  4. (D)4°C

Correct answer: (D)

Step-by-step solution →
Q24·PhysicsSingle correct
A wire of resistance R is bent to form a square ABCD as shown in the figure. The effective resistance between E and C is: (E is mid-point of arm CD)
  1. (A)116\dfrac{1}{16}161​R
  2. (B)764\dfrac{7}{64}647​R
  3. (C)34\dfrac{3}{4}43​R
  4. (D)R

Correct answer: (B)

Step-by-step solution →

Chemistry — JEE Main 9 April 2019 Shift 1

Q25·ChemistrySingle correct
Magnesium powder burns in air to give:
  1. (A)MgOMgOMgO and Mg(NO3)2Mg(NO_3)_2Mg(NO3​)2​
  2. (B)MgOMgOMgO and Mg3N2Mg_3N_2Mg3​N2​
  3. (C)MgOMgOMgO only
  4. (D)Mg(NO3)2Mg(NO_3)_2Mg(NO3​)2​ and Mg3N2Mg_3N_2Mg3​N2​

Correct answer: (B)

Step-by-step solution →
Q26·ChemistrySingle correct
The number of water molecule(s) not coordinated to copper ion directly in CuSO4⋅5H2OCuSO_4 \cdot 5H_2OCuSO4​⋅5H2​O, is:
  1. (A)1
  2. (B)3
  3. (C)2
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q27·ChemistrySingle correct
The one that will show optical activity is: (en = ethane-1, 2-diamine)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correct
Consider the van der Waals constants, a and b, for the following gases. Which gas is expected to have the highest critical temperature?
GasArNeKrXe
a/(atm dm6^66mol−2^{-2}−2)1.30.25.14.1
b/(10−2^{-2}−2dm3^33mol−1^{-1}−1)3.21.71.05.0
  1. (A)Ar
  2. (B)Xe
  3. (C)Kr
  4. (D)Ne

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correct
Among the following, the molecule expected to be stabilized by anion formation is:
  1. (A)F2F_2F2​
  2. (B)C2C_2C2​
  3. (C)O2O_2O2​
  4. (D)NO

Correct answer: (B)

Step-by-step solution →
Q30·ChemistrySingle correct
Among the following the set of parameters that represents path functions, is: (a) q + w (b) q (c) w (d) H – TS
  1. (A)(b) and (c)
  2. (B)(b), (c) and (d)
  3. (C)(a), (b) and (c)
  4. (D)(a) and (d)

Correct answer: (A)

Step-by-step solution →
Q31·ChemistrySingle correct
The degenerate orbitals of [Cr(H2O)6]3+[Cr(H_2O)_6]^{3+}[Cr(H2​O)6​]3+ are:
  1. (A)dxzd_{xz}dxz​ and dyzd_{yz}dyz​
  2. (B)dx2−y2d_{x^2-y^2}dx2−y2​ and dxyd_{xy}dxy​
  3. (C)dyzd_{yz}dyz​ and dz2d_{z^2}dz2​
  4. (D)dz2d_{z^2}dz2​ and dxzd_{xz}dxz​

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
The aerosol is a kind of colloid in which:
  1. (A)solid is dispersed in gas
  2. (B)gas is dispersed in solid
  3. (C)liquid is dispersed in water
  4. (D)gas is dispersed in liquid

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
The given plots represent the variation of the concentration of a reactant R with time for two different reactions (i) and (ii). The respective orders of the reactions are:
  1. (A)1, 1
  2. (B)0, 2
  3. (C)0, 1
  4. (D)1, 0

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
The organic compound that gives following qualitative analysis is:
TestInference
(a) Dil. HClInsoluble
(b) NaOH solutionSoluble
(c) Br2_22​/waterDecolourization
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
Aniline dissolved in dilute HCl is reacted with sodium nitrite at 0∘C0^{\circ}C0∘C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
Excessive release of CO2CO_2CO2​ into the atmosphere results in:
  1. (A)formation of smog
  2. (B)depletion of ozone
  3. (C)global warming
  4. (D)polar vortex

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
The ore that contains the metal in the form of fluoride is:
  1. (A)saphalerite
  2. (B)malachite
  3. (C)magnetite
  4. (D)cryolite

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
The correct IUPAC name of the following compound is
  1. (A)5-chloro-4-methyl-1-nitrobenzene
  2. (B)2-methyl-5-nitro-1-chlorobenzene
  3. (C)3-chloro-4-methyl-1-nitrobenzene
  4. (D)2-chloro-1-methyl-4-nitrobenzene

Correct answer: (D)

Step-by-step solution →
Q40·ChemistrySingle correct
The major product of the following reaction is : CH3CH=CHCO2CH3→LiAlH4CH_3CH=CHCO_2CH_3 \xrightarrow{LiAlH_4}CH3​CH=CHCO2​CH3​LiAlH4​​
  1. (A)CH3CH2CH2CHOCH_3CH_2CH_2CHOCH3​CH2​CH2​CHO
  2. (B)CH3CH=CHCH2OHCH_3CH=CHCH_2OHCH3​CH=CHCH2​OH
  3. (C)CH3CH2CH2CO2CH3CH_3CH_2CH_2CO_2CH_3CH3​CH2​CH2​CO2​CH3​
  4. (D)CH3CH2CH2CH2OHCH_3CH_2CH_2CH_2OHCH3​CH2​CH2​CH2​OH

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
The element having greatest difference between its first and second ionization energies, is
  1. (A)Ca
  2. (B)K
  3. (C)Ba
  4. (D)Sc

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
For a reaction, N2(g)+3H2(g)→2NH3(g)N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)N2​(g)+3H2​(g)→2NH3​(g); identify dihydrogen (H2H_2H2​) as a limiting reagent in the following reaction mixtures.
  1. (A)14g of N2N_2N2​ + 4g of H2H_2H2​
  2. (B)28g of N2N_2N2​ + 6g of H2H_2H2​
  3. (C)56g of N2N_2N2​ + 10g of H2H_2H2​
  4. (D)35g of N2N_2N2​ + 8g of H2H_2H2​

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
The major product of the following reaction is : CH3C≡CH→(2) DI(i) DCl(1 equiv.)CH_3C \equiv CH \xrightarrow[(2)\ DI]{(i)\ DCl(1\ equiv.)}CH3​C≡CH(i) DCl(1 equiv.)(2) DI​
  1. (A)CH3CD(I)CHD(Cl)CH_3CD(I)CHD(Cl)CH3​CD(I)CHD(Cl)
  2. (B)CH3C(I)(Cl)CHD2CH_3C(I)(Cl)CHD_2CH3​C(I)(Cl)CHD2​
  3. (C)CH3CD2CH(Cl)(I)CH_3CD_2CH(Cl)(I)CH3​CD2​CH(Cl)(I)
  4. (D)CH3CD(Cl)CHD(I)CH_3CD(Cl)CHD(I)CH3​CD(Cl)CHD(I)

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
The osmotic pressure of a dilute solution of an ionic compound XY in water is four times that of a solution of 0.01 M BaCl2BaCl_2BaCl2​ in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of XY (in mol L−1L^{-1}L−1) in solution is
  1. (A)4×10−44 \times 10^{-4}4×10−4
  2. (B)6×10−26 \times 10^{-2}6×10−2
  3. (C)16×10−416 \times 10^{-4}16×10−4
  4. (D)4×10−24 \times 10^{-2}4×10−2

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
The increasing order of reactivity of thefollowing compounds towards aromatic electrophilic substitution reaction is
  1. (A)D < B < A < C
  2. (B)A < B < C < D
  3. (C)D < A < C < B
  4. (D)B < C < A < D

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
C60C_{60}C60​, an allotrope of carbon contains:
  1. (A)20 hexagons and 12 pentagons.
  2. (B)12 hexagons and 20 pentagons.
  3. (C)18 hexagons and 14 pentagons.
  4. (D)16 hexagons and 16 pentagons

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
The correct order of the oxidation states of nitrogen in NO, N2ON_2ON2​O, NO2NO_2NO2​ and N2O3N_2O_3N2​O3​ is:
  1. (A)N2O<N2O3<NO<NO2N_2O < N_2O_3 < NO < NO_2N2​O<N2​O3​<NO<NO2​
  2. (B)NO2<NO<N2O3<N2ONO_2 < NO < N_2O_3 < N_2ONO2​<NO<N2​O3​<N2​O
  3. (C)NO2<N2O3<NO<N2ONO_2 < N_2O_3 < NO < N_2ONO2​<N2​O3​<NO<N2​O
  4. (D)N2O<NO<N2O3<NO2N_2O < NO < N_2O_3 < NO_2N2​O<NO<N2​O3​<NO2​

Correct answer: (D)

Step-by-step solution →
Q48·ChemistrySingle correct
The standard Gibbs energy for the given cell reaction in kJ mol−1mol^{-1}mol−1 at 298 K is: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s),E∘=2VZn(s) + Cu^{2+}(aq) \rightarrow Zn^{2+}(aq) + Cu(s), E^\circ = 2 VZn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s),E∘=2V at 298K [Faraday's constant F = 96500 C mol−1mol^{-1}mol−1]
  1. (A)-192
  2. (B)384
  3. (C)-384
  4. (D)192

Correct answer: (C)

Step-by-step solution →
Q49·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
Match the catalysis(Column – I) with products (Column-II)
Column-I (Catalyst)Column-II (Product)
a.V2O5V_2O_5V2​O5​i.Polyethylene
b.TiCl4/Al(Me)3TiCl_4/Al(Me)_3TiCl4​/Al(Me)3​ii.Ethanal
c.PdCl2PdCl_2PdCl2​iii.H2SO4H_2SO_4H2​SO4​
d.Iron oxideiv.NH3NH_3NH3​
  1. (A)(a)-(iii); (b)-(iv); (c)-(i); (d)-(ii)
  2. (B)(a)-(iv); (b)-(iii); (c)-(ii); (d)-(i)
  3. (C)(a)-(ii); (b)-(iii); (c)-(i); (d)-(iv)
  4. (D)(a)-(iii); (b)-(i); (c)-(ii); (d)-(iv)

Correct answer: (D)

Step-by-step solution →

Mathematics — JEE Main 9 April 2019 Shift 1

Q51·MathematicsSingle correct
If the function f:R−{1,−1}→Af: R-\{1, -1\} \to Af:R−{1,−1}→A defined by f(x)=x21−x2f(x) = \dfrac{x^{2}}{1-x^{2}}f(x)=1−x2x2​, is surjective, then A is equal to:
  1. (A)R−[−1,0)R - [-1, 0)R−[−1,0)
  2. (B)R−(−1,0)R - (-1, 0)R−(−1,0)
  3. (C)R−{−1}R - \{-1\}R−{−1}
  4. (D)[0,∞][0, \infty][0,∞]

Correct answer: (A)

Step-by-step solution →
Q52·MathematicsSingle correct
Let α⃗=3i^+j^\vec{\alpha}=3\hat{i}+\hat{j}α=3i^+j^​ and β⃗=2i^−j^+3k^\vec{\beta}=2\hat{i}-\hat{j}+3\hat{k}β​=2i^−j^​+3k^. If β⃗=β1⃗−β2⃗\vec{\beta}=\vec{\beta_{1}}-\vec{\beta_{2}}β​=β1​​−β2​​, where β1⃗\vec{\beta_{1}}β1​​ is parallel to α⃗\vec{\alpha}α and β2⃗\vec{\beta_{2}}β2​​ is perpendicular to α⃗\vec{\alpha}α, then β1⃗×β2⃗\vec{\beta_{1}}\times\vec{\beta_{2}}β1​​×β2​​ is equal to:
  1. (A)12(−3i^+9j^+5k^)\dfrac{1}{2}(-3\hat{i}+9\hat{j}+5\hat{k})21​(−3i^+9j^​+5k^)
  2. (B)12(3i^−9j^+5k^)\dfrac{1}{2}(3\hat{i}-9\hat{j}+5\hat{k})21​(3i^−9j^​+5k^)
  3. (C)−3i^+9j^+5k^-3\hat{i}+9\hat{j}+5\hat{k}−3i^+9j^​+5k^
  4. (D)3i^−9j^−5k^3\hat{i}-9\hat{j}-5\hat{k}3i^−9j^​−5k^

Correct answer: (A)

Step-by-step solution →
Q53·MathematicsSingle correct
The integral ∫sec⁡2/3x cosec4/3x dx\displaystyle\int \sec^{2/3}x\,\text{cosec}^{4/3}x\,dx∫sec2/3xcosec4/3xdx is equal to: (Here C is a constant of integration)
  1. (A)3tan⁡−1/3x+C3\tan^{-1/3}x+C3tan−1/3x+C
  2. (B)−34tan⁡−4/3x+C-\dfrac{3}{4}\tan^{-4/3}x+C−43​tan−4/3x+C
  3. (C)−3cot⁡−1/3x+C-3\cot^{-1/3}x+C−3cot−1/3x+C
  4. (D)−3tan⁡−1/3x+C-3\tan^{-1/3}x+C−3tan−1/3x+C

Correct answer: (D)

Step-by-step solution →
Q54·MathematicsSingle correct
A plane passing through the points (0,−1,0)(0,-1,0)(0,−1,0) and (0,0,1)(0,0,1)(0,0,1) and making an angle π4\dfrac{\pi}{4}4π​ with plane y−z+5=0y-z+5=0y−z+5=0, also passes through the point:
  1. (A)(2,1,4)(\sqrt{2},1,4)(2​,1,4)
  2. (B)(−2,−1,−4)(-\sqrt{2},-1,-4)(−2​,−1,−4)
  3. (C)(−2,1,−4)(-\sqrt{2},1,-4)(−2​,1,−4)
  4. (D)(2,−1,4)(\sqrt{2},-1,4)(2​,−1,4)

Correct answer: (A)

Step-by-step solution →
Q55·MathematicsSingle correct
If the tangent to the curve, y=x3+ax−by=x^{3}+ax-by=x3+ax−b at the point (1,−5)(1,-5)(1,−5) is perpendicular to the line, −x+y+4=0-x+y+4=0−x+y+4=0, then which one of the following, points lies on the curve?
  1. (A)(2,−2)(2,-2)(2,−2)
  2. (B)(−2,2)(-2,2)(−2,2)
  3. (C)(−2,1)(-2,1)(−2,1)
  4. (D)(2,−1)(2,-1)(2,−1)

Correct answer: (A)

Step-by-step solution →
Q56·MathematicsSingle correct
If the standard deviation of the numbers −1,0,1,k-1,0,1,k−1,0,1,k is 5\sqrt{5}5​ where k>0k>0k>0, then k is equal to:
  1. (A)4534\sqrt{\dfrac{5}{3}}435​​
  2. (B)6\sqrt{6}6​
  3. (C)262\sqrt{6}26​
  4. (D)21032\sqrt{\dfrac{10}{3}}2310​​

Correct answer: (C)

Step-by-step solution →
Q57·MathematicsSingle correct
Let f(x)=15−∣x−10∣;x∈Rf(x)=15-|x-10|; x\in Rf(x)=15−∣x−10∣;x∈R. then the set of all values of x, at which the function, g(x)=f(f(x))g(x)=f(f(x))g(x)=f(f(x)) is not differentiable, is:
  1. (A){5,10,15}\{5,10,15\}{5,10,15}
  2. (B){10}\{10\}{10}
  3. (C){5,10,15,20}\{5,10,15,20\}{5,10,15,20}
  4. (D){10,15}\{10,15\}{10,15}

Correct answer: (A)

Step-by-step solution →
Q58·MathematicsSingle correct
If the fourth term in the Binomial expansion of (2x+xlog⁡8x)6(x>0)\left(\dfrac{2}{x}+x^{\log_{8}x}\right)^{6}(x>0)(x2​+xlog8​x)6(x>0) is 20×8720\times 8^{7}20×87, then a value of x is:
  1. (A)838^{3}83
  2. (B)8−28^{-2}8−2
  3. (C)888
  4. (D)828^{2}82

Correct answer: (D)

Step-by-step solution →
Q59·MathematicsSingle correct
If f(x) is a non-zero polynomial of degree four, having local extreme points at x=−1,0,1x=-1,0,1x=−1,0,1; then the set S={x∈R;f(x)=f(0)}S=\{x\in R; f(x)=f(0)\}S={x∈R;f(x)=f(0)} contains exactly:
  1. (A)four irrational numbers
  2. (B)four rational numbers
  3. (C)two irrational and one rational number
  4. (D)two irrational and two rational numbers

Correct answer: (C)

Step-by-step solution →
Q60·MathematicsSingle correct
For any two statements p and q, the negation of the expression p∨(∼p∧q)p\vee(\sim p\wedge q)p∨(∼p∧q) is:
  1. (A)p↔qp\leftrightarrow qp↔q
  2. (B)∼p∨∼q\sim p\vee \sim q∼p∨∼q
  3. (C)∼p∧∼q\sim p\wedge \sim q∼p∧∼q
  4. (D)p∧qp\wedge qp∧q

Correct answer: (C)

Step-by-step solution →
Q61·MathematicsSingle correct
A committee of 11 members is to be formed from 8 males and 5 females. If m is the number of ways the committee is formed with at least 6 males and n is the number of ways the committee is formed with at least 3 females, then:
  1. (A)n=m−8n=m-8n=m−8
  2. (B)m+n=68m+n=68m+n=68
  3. (C)m=n=78m=n=78m=n=78
  4. (D)m=n=68m=n=68m=n=68

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
If the line, x−12=y+13=z−24\dfrac{x-1}{2}=\dfrac{y+1}{3}=\dfrac{z-2}{4}2x−1​=3y+1​=4z−2​ meets the plane, x+2y+3z=15x+2y+3z=15x+2y+3z=15 at a point P, then the distance of P from the origin is:
  1. (A)52\dfrac{\sqrt{5}}{2}25​​
  2. (B)252\sqrt{5}25​
  3. (C)92\dfrac{9}{2}29​
  4. (D)72\dfrac{7}{2}27​

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
The value of cos⁡210∘−cos⁡10∘cos⁡50∘+cos⁡250∘\cos^{2}10^{\circ}-\cos 10^{\circ}\cos 50^{\circ}+\cos^{2}50^{\circ}cos210∘−cos10∘cos50∘+cos250∘ is:
  1. (A)32(1+cos⁡20∘)\dfrac{3}{2}(1+\cos 20^{\circ})23​(1+cos20∘)
  2. (B)34\dfrac{3}{4}43​
  3. (C)32\dfrac{3}{2}23​
  4. (D)34+cos⁡20∘\dfrac{3}{4}+\cos 20^{\circ}43​+cos20∘

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
If [1101][1201][1301]…………[1n−101]=[17801]\begin{bmatrix}1&1\\0&1\end{bmatrix}\begin{bmatrix}1&2\\0&1\end{bmatrix}\begin{bmatrix}1&3\\0&1\end{bmatrix}\ldots\ldots\ldots\ldots\begin{bmatrix}1&n-1\\0&1\end{bmatrix}=\begin{bmatrix}1&78\\0&1\end{bmatrix}[10​11​][10​21​][10​31​]…………[10​n−11​]=[10​781​], then the inverse of [1n01]\begin{bmatrix}1&n\\0&1\end{bmatrix}[10​n1​] is:
  1. (A)[1−1201]\begin{bmatrix}1&-12\\0&1\end{bmatrix}[10​−121​]
  2. (B)[10131]\begin{bmatrix}1&0\\13&1\end{bmatrix}[113​01​]
  3. (C)[10121]\begin{bmatrix}1&0\\12&1\end{bmatrix}[112​01​]
  4. (D)[1−1301]\begin{bmatrix}1&-13\\0&1\end{bmatrix}[10​−131​]

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correct
All the points in the set S={α+iα−i:α∈R}S = \left\{\dfrac{\alpha+i}{\alpha-i} : \alpha \in R\right\}S={α−iα+i​:α∈R} (i=−1)(i=\sqrt{-1})(i=−1​) lie on a:
  1. (A)straight line whose slope is 1
  2. (B)circle whose radius is 2\sqrt{2}2​
  3. (C)straight line whose slope is −1-1−1
  4. (D)circle whose radius is 1

Correct answer: (D)

Step-by-step solution →
Q66·MathematicsSingle correct
Let the sum of the first n terms of a non-constant A.P., a1,a2,a3,......a_1, a_2, a_3, ......a1​,a2​,a3​,...... be 50n+n(n−7)2A50n + \dfrac{n(n-7)}{2}A50n+2n(n−7)​A, where A is a constant. If d is the common difference of this A.P., then the ordered pair (d,a50)(d, a_{50})(d,a50​) is equal to:
  1. (A)(A,50+46A)(A, 50+46A)(A,50+46A)
  2. (B)(A,50+45A)(A, 50+45A)(A,50+45A)
  3. (C)(50,50+45A)(50, 50+45A)(50,50+45A)
  4. (D)(50,50+46A)(50, 50+46A)(50,50+46A)

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
The value of ∫0π/2sin⁡3xsin⁡x+cos⁡xdx\displaystyle\int_{0}^{\pi/2} \dfrac{\sin^{3}x}{\sin x+\cos x}dx∫0π/2​sinx+cosxsin3x​dx is:
  1. (A)π−24\dfrac{\pi-2}{4}4π−2​
  2. (B)π−12\dfrac{\pi-1}{2}2π−1​
  3. (C)π−14\dfrac{\pi-1}{4}4π−1​
  4. (D)π−28\dfrac{\pi-2}{8}8π−2​

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
If the line y=mx+73y=mx+7\sqrt{3}y=mx+73​ is normal to the hyperbola x224−y218=1\dfrac{x^{2}}{24}-\dfrac{y^{2}}{18}=124x2​−18y2​=1, then a value of m is:
  1. (A)25\dfrac{2}{\sqrt{5}}5​2​
  2. (B)52\dfrac{\sqrt{5}}{2}25​​
  3. (C)152\dfrac{\sqrt{15}}{2}215​​
  4. (D)35\dfrac{3}{\sqrt{5}}5​3​

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
The solution of the differential equation xdydx+2y=x2 (x≠0)x\dfrac{dy}{dx}+2y=x^{2}\ (x\neq 0)xdxdy​+2y=x2 (x=0) with y(1)=1y(1)=1y(1)=1, is:
  1. (A)y=x35+15x2y=\dfrac{x^{3}}{5}+\dfrac{1}{5x^{2}}y=5x3​+5x21​
  2. (B)y=x24+34x2y=\dfrac{x^{2}}{4}+\dfrac{3}{4x^{2}}y=4x2​+4x23​
  3. (C)y=45x3+15x2y=\dfrac{4}{5}x^{3}+\dfrac{1}{5x^{2}}y=54​x3+5x21​
  4. (D)y=34x2+14x2y=\dfrac{3}{4}x^{2}+\dfrac{1}{4x^{2}}y=43​x2+4x21​

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
If one end of a focal chord of the parabola, y2=16xy^{2}=16xy2=16x is at (1,4)(1, 4)(1,4), then the length of this focal chord is:
  1. (A)25
  2. (B)24
  3. (C)22
  4. (D)20

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Let S be the set of all values of x for which the tangent to the curve y=f(x)=x3−x2−2xy=f(x)=x^{3}-x^{2}-2xy=f(x)=x3−x2−2x at (x,y)(x, y)(x,y) is parallel to the line segment joining the points (1,f(1))(1, f(1))(1,f(1)) and (−1,f(−1))(-1, f(-1))(−1,f(−1)), then S is equal to:
  1. (A){13,−1}\left\{\dfrac{1}{3},-1\right\}{31​,−1}
  2. (B){−13,−1}\left\{-\dfrac{1}{3},-1\right\}{−31​,−1}
  3. (C){13,1}\left\{\dfrac{1}{3},1\right\}{31​,1}
  4. (D){−13,1}\left\{-\dfrac{1}{3},1\right\}{−31​,1}

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
Let ∑k=110f(a+k)=16(210−1)\displaystyle\sum_{k=1}^{10} f(a+k)=16(2^{10}-1)k=1∑10​f(a+k)=16(210−1), where the function f satisfies f(x+y)=f(x)f(y)f(x+y)=f(x)f(y)f(x+y)=f(x)f(y) for all natural numbers x, y and f(1)=2f(1)=2f(1)=2. Then the natural number 'a' is:
  1. (A)4
  2. (B)16
  3. (C)2
  4. (D)3

Correct answer: (D)

Step-by-step solution →
Q73·MathematicsSingle correct
Let S={θ∈[−2π,2π]:2cos⁡2θ+3sin⁡θ=0}S=\{\theta\in[-2\pi, 2\pi] : 2\cos^{2}\theta+3\sin\theta=0\}S={θ∈[−2π,2π]:2cos2θ+3sinθ=0}. Then the sum of the elements of S is:
  1. (A)13π6\dfrac{13\pi}{6}613π​
  2. (B)2π2\pi2π
  3. (C)π\piπ
  4. (D)5π3\dfrac{5\pi}{3}35π​

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
If a tangent to the circle x2+y2=1x^{2}+y^{2}=1x2+y2=1 intersects the coordinate axes at distinct points P and Q, then the locus of the mid-point of PQ is:
  1. (A)x2+y2−16x2y2=0x^{2}+y^{2}-16x^{2}y^{2}=0x2+y2−16x2y2=0
  2. (B)x2+y2−2x2y2=0x^{2}+y^{2}-2x^{2}y^{2}=0x2+y2−2x2y2=0
  3. (C)x2+y2−4x2y2=0x^{2}+y^{2}-4x^{2}y^{2}=0x2+y2−4x2y2=0
  4. (D)x2+y2−2xy=0x^{2}+y^{2}-2xy=0x2+y2−2xy=0

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
Four persons can hit a target correctly with probabilities 12,13,14\dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{4}21​,31​,41​ and 18\dfrac{1}{8}81​ respectively. If all hit at the target independently, then the probability that the target would be hit, is:
  1. (A)2532\dfrac{25}{32}3225​
  2. (B)25192\dfrac{25}{192}19225​
  3. (C)732\dfrac{7}{32}327​
  4. (D)1192\dfrac{1}{192}1921​

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
The area (in sq. units) of the region A={(x,y):x2≤y≤x+2}A=\{(x, y) : x^{2}\leq y\leq x+2\}A={(x,y):x2≤y≤x+2} is:
  1. (A)316\dfrac{31}{6}631​
  2. (B)136\dfrac{13}{6}613​
  3. (C)92\dfrac{9}{2}29​
  4. (D)103\dfrac{10}{3}310​

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
Let α\alphaα and β\betaβ be the roots of the equation x2+x+1=0x^{2}+x+1=0x2+x+1=0. Then for y≠0y\neq 0y=0 in R, ∣y+1αβαy+β1β1y+α∣\begin{vmatrix}y+1 & \alpha & \beta\\ \alpha & y+\beta & 1\\ \beta & 1 & y+\alpha\end{vmatrix}​y+1αβ​αy+β1​β1y+α​​ is equal to:
  1. (A)y(y2−3)y(y^{2}-3)y(y2−3)
  2. (B)y3−1y^{3}-1y3−1
  3. (C)y3y^{3}y3
  4. (D)y(y2−1)y(y^{2}-1)y(y2−1)

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
If the function f defined on (π6,π3)\left(\dfrac{\pi}{6}, \dfrac{\pi}{3}\right)(6π​,3π​) by f(x)={2cos⁡x−1cot⁡x−1,x≠π4k,x=π4f(x)=\begin{cases}\dfrac{\sqrt{2}\cos x-1}{\cot x-1}, & x\neq \dfrac{\pi}{4}\\ k, & x=\dfrac{\pi}{4}\end{cases}f(x)=⎩⎨⎧​cotx−12​cosx−1​,k,​x=4π​x=4π​​ is continuous, then k is equal to:
  1. (A)1
  2. (B)2
  3. (C)12\dfrac{1}{2}21​
  4. (D)12\dfrac{1}{\sqrt{2}}2​1​

Correct answer: (C)

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Oscillations 117/186
  • Organic Compounds Containing Halogens 109/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Carboxylic Acids and Derivatives 54/186
  • Diazonium Salts and Reactions 53/186
  • States of Matter: Gases and Liquids 52/186
  • IUPAC Nomenclature 37/186
  • Mathematical Reasoning 26/186
  • Communication Systems 11/186
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