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JEE Main 20 July 2021 Shift 2 Question Paper with Answers

20 July 2021 · July session · 87 questions

87 of the 90 questions from the JEE Main 20 July 2021 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

3 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
29
Mathematics
28

Physics — JEE Main 20 July 2021 Shift 2

Q1·PhysicsSingle correct
For a series LCR circuit with R=100 ΩR = 100\,\OmegaR=100Ω, L=0.5 mHL = 0.5\,mHL=0.5mH and C=0.1 pFC = 0.1\,pFC=0.1pF connected across 220V−50Hz220V - 50Hz220V−50Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is :
  1. (A)≈90∘\approx 90^\circ≈90∘, predominantly inductive circuit
  2. (B)0∘0^\circ0∘, resonance circuit
  3. (C)≈90∘\approx 90^\circ≈90∘, predominantly capacitive circuit
  4. (D)0∘0^\circ0∘, resistive circuit

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
If the kinetic energy of a moving body becomes four times its initial kinetic energy, then the percentage change in its momentum will be :
  1. (A)100%
  2. (B)200%
  3. (C)400%
  4. (D)300%

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
If time (t)(t)(t), velocity (υ)(\upsilon)(υ), and angular momentum (ℓ)(\ell)(ℓ) are taken as the fundamental units. Then the dimension of mass (m)(m)(m) in terms of t,υ,t, \upsilon,t,υ, and ℓ\ellℓ is :
  1. (A)[t−2 υ−1 ℓ1]\left[ t^{-2}\,\upsilon^{-1}\,\ell^{1} \right][t−2υ−1ℓ1]
  2. (B)[t−1 υ1 ℓ−2]\left[ t^{-1}\,\upsilon^{1}\,\ell^{-2} \right][t−1υ1ℓ−2]
  3. (C)[t−1 υ−2 ℓ1]\left[ t^{-1}\,\upsilon^{-2}\,\ell^{1} \right][t−1υ−2ℓ1]
  4. (D)[t1 υ2 ℓ−1]\left[ t^{1}\,\upsilon^{2}\,\ell^{-1} \right][t1υ2ℓ−1]

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
An electron having de-Broglie wavelength λ\lambdaλ is indent on a target in a X-ray tube. Cut-off wavelength of emitted X-ray is:
  1. (A)0
  2. (B)2mc λ2h\dfrac{2mc\,\lambda^{2}}{h}h2mcλ2​
  3. (C)hcmc\dfrac{hc}{mc}mchc​
  4. (D)2m2c2λ2h2\dfrac{2m^{2}c^{2}\lambda^{2}}{h^{2}}h22m2c2λ2​

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
Two small drops of mercury each of radius R coalesce to from a single large drop. The ratio of total surface energy before and after the change is :
  1. (A)213:12^{\frac{1}{3}} : 1231​:1
  2. (B)1:2131 : 2^{\frac{1}{3}}1:231​
  3. (C)2:12 : 12:1
  4. (D)1:21 : 21:2

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
Two vectors P⃗\vec{P}P and Q⃗\vec{Q}Q​ have equal magnitudes. If the magnitude of P⃗+Q⃗\vec{P} + \vec{Q}P+Q​ is n times the magnitude of P⃗−Q⃗\vec{P} - \vec{Q}P−Q​, then angle between P⃗\vec{P}P and Q⃗\vec{Q}Q​ is :
  1. (A)sin⁡−1(n2−1n2+1)\sin^{-1}\left( \dfrac{n^{2}-1}{n^{2}+1} \right)sin−1(n2+1n2−1​)
  2. (B)cos⁡−1(n2−1n2+1)\cos^{-1}\left( \dfrac{n^{2}-1}{n^{2}+1} \right)cos−1(n2+1n2−1​)
  3. (C)sin⁡−1(n−1n+1)\sin^{-1}\left( \dfrac{n-1}{n+1} \right)sin−1(n+1n−1​)
  4. (D)cos⁡−1(n−1n+1)\cos^{-1}\left( \dfrac{n-1}{n+1} \right)cos−1(n+1n−1​)

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
A boy reaches the airport and finds that the escalator is not working. He walks up the stationary escalator in time t1t_1t1​. If he remains stationary on a moving escalator then the escalator takes him up in time t2t_2t2​. The time taken by him to walk up on the moving escalator will be :
  1. (A)t1t2t2+t1\dfrac{t_1 t_2}{t_2 + t_1}t2​+t1​t1​t2​​
  2. (B)t2−t1t_2 - t_1t2​−t1​
  3. (C)t1+t22\dfrac{t_1 + t_2}{2}2t1​+t2​​
  4. (D)t1t2t2−t1\dfrac{t_1 t_2}{t_2 - t_1}t2​−t1​t1​t2​​

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
The correct relation between the degrees of freedom f and the ratio of specific heat γ\gammaγ is :
  1. (A)f=2γ+1f = \dfrac{2}{\gamma + 1}f=γ+12​
  2. (B)f=2γ−1f = \dfrac{2}{\gamma - 1}f=γ−12​
  3. (C)f=1γ+1f = \dfrac{1}{\gamma + 1}f=γ+11​
  4. (D)f=γ+12f = \dfrac{\gamma + 1}{2}f=2γ+1​

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
For a certain radioactive process the graph between ℓn(R)\ell n(R)ℓn(R) and t(sec) is obtained as shown in the figure. Then the value of half life for the unknown radioactive material is approximately :
  1. (A)2.62 sec
  2. (B)9.15 sec
  3. (C)4.62 sec
  4. (D)6.93 sec

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
A body rolls down an inclined plane without slipping. The kinetic energy of rotation is 50% of its translational kinetic energy. The body is :
  1. (A)Hollow cylinder
  2. (B)Ring
  3. (C)Solid sphere
  4. (D)Solid cylinder

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
In an electromagnetic wave the electric field vector and magnetic field vector are given as E⃗=E0i^\vec{E} = E_0 \hat{i}E=E0​i^ and B⃗=B0k^\vec{B} = B_0 \hat{k}B=B0​k^ respectively. The direction of propagation of electromagnetic wave is along.
  1. (A)(−k^)\left( -\hat{k} \right)(−k^)
  2. (B)(k^)\left( \hat{k} \right)(k^)
  3. (C)(−j^)\left( -\hat{j} \right)(−j^​)
  4. (D)j^\hat{j}j^​

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correct
The length of a metal wire is ℓ1\ell_1ℓ1​, when the tension in it is T1T_1T1​ and is ℓ2\ell_2ℓ2​ when the tension is T2T_2T2​. The natural length of the wire is :
  1. (A)ℓ1ℓ2\sqrt{\ell_1 \ell_2}ℓ1​ℓ2​​
  2. (B)ℓ1+ℓ22\dfrac{\ell_1 + \ell_2}{2}2ℓ1​+ℓ2​​
  3. (C)ℓ1T2−ℓ2T1T2−T1\dfrac{\ell_1 T_2 - \ell_2 T_1}{T_2 - T_1}T2​−T1​ℓ1​T2​−ℓ2​T1​​
  4. (D)ℓ1T2+ℓ2T1T2+T1\dfrac{\ell_1 T_2 + \ell_2 T_1}{T_2 + T_1}T2​+T1​ℓ1​T2​+ℓ2​T1​​

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
A body at rest is moved along a horizontal straight line by a machine delivering a constant power. The distance moved by the body in time 't' is proportional to :
  1. (A)t34t^{\frac{3}{4}}t43​
  2. (B)t32t^{\frac{3}{2}}t23​
  3. (C)t12t^{\frac{1}{2}}t21​
  4. (D)t14t^{\frac{1}{4}}t41​

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
Which of the following graphs represent the behaviour of an ideal gas? Symbols have their usual meaning.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
With what speed should a galaxy move outward with respect to earth so that the sodium −D-D−D line at wavelength 5890 A∘5890\,\overset{\circ}{A}5890A∘ is observed at 5896 A∘5896\,\overset{\circ}{A}5896A∘ ?
  1. (A)322 km / sec
  2. (B)296 km / sec
  3. (C)306 km / sec
  4. (D)336 km / sec

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
A particle is making simple harmonic motion along the X-axis. If at a distances x1x_1x1​ and x2x_2x2​ from the mean position the velocities of the particle are υ1\upsilon_1υ1​ and υ2\upsilon_2υ2​ respectively. The time period of its oscillation is given as :
  1. (A)T=2πx22−x12υ12−υ22T = 2\pi \sqrt{ \dfrac{x_2^{2} - x_1^{2}}{\upsilon_1^{2} - \upsilon_2^{2}} }T=2πυ12​−υ22​x22​−x12​​​
  2. (B)T=2πx22+x12υ12−υ22T = 2\pi \sqrt{ \dfrac{x_2^{2} + x_1^{2}}{\upsilon_1^{2} - \upsilon_2^{2}} }T=2πυ12​−υ22​x22​+x12​​​
  3. (C)T=2πx22−x12υ12+υ22T = 2\pi \sqrt{ \dfrac{x_2^{2} - x_1^{2}}{\upsilon_1^{2} + \upsilon_2^{2}} }T=2πυ12​+υ22​x22​−x12​​​
  4. (D)T=2πx22+x12υ12+υ22T = 2\pi \sqrt{ \dfrac{x_2^{2} + x_1^{2}}{\upsilon_1^{2} + \upsilon_2^{2}} }T=2πυ12​+υ22​x22​+x12​​​

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
A satellite is launched into a circular orbit of radius R around earth, while a second satellite is launched into a circular orbit of radius 1.02R. The percentage difference in the time periods of the two satellites is :
  1. (A)0.7
  2. (B)3.0
  3. (C)2.0
  4. (D)1.5

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
Consider a binary star system of star A and star B with masses mAm_AmA​ and mBm_BmB​ revolving in a circular orbit of radii rAr_ArA​ and rBr_BrB​, respectively. If TAT_ATA​ and TBT_BTB​ are the time period of star A and star B, respectively, then :
  1. (A)TA=TBT_A = T_BTA​=TB​
  2. (B)TA>TB(if mA>mB)T_A > T_B \left( \text{if } m_A > m_B \right)TA​>TB​(if mA​>mB​)
  3. (C)TATB=(rArB)32\dfrac{T_A}{T_B} = \left( \dfrac{r_A}{r_B} \right)^{\frac{3}{2}}TB​TA​​=(rB​rA​​)23​
  4. (D)TA>TB(if rA>rB)T_A > T_B \left( \text{if } r_A > r_B \right)TA​>TB​(if rA​>rB​)

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
At an angle of 30∘30^{\circ}30∘ to the magnetic meridian, the apparent dip is 45∘45^{\circ}45∘. Find the true dip:
  1. (A)tan⁡−132\tan^{-1}\frac{\sqrt{3}}{2}tan−123​​
  2. (B)tan⁡−13\tan^{-1}\sqrt{3}tan−13​
  3. (C)tan⁡−113\tan^{-1}\frac{1}{\sqrt{3}}tan−13​1​
  4. (D)tan⁡−123\tan^{-1}\frac{2}{\sqrt{3}}tan−13​2​

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correct
The magnetic susceptibility of a material of a rod is 499. Permeability in vacuum is 4π×10−7 H/m4\pi \times 10^{-7}\ \mathrm{H/m}4π×10−7 H/m. Absolute permeability of the material of the rod is:
  1. (A)3π×10−4 H/m3\pi \times 10^{-4}\ \mathrm{H/m}3π×10−4 H/m
  2. (B)π×10−4 H/m\pi \times 10^{-4}\ \mathrm{H/m}π×10−4 H/m
  3. (C)2π×10−4 H/m2\pi \times 10^{-4}\ \mathrm{H/m}2π×10−4 H/m
  4. (D)4π×10−4 H/m4\pi \times 10^{-4}\ \mathrm{H/m}4π×10−4 H/m

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsNumerical
A radioactive substance decays to (116)th\left(\frac{1}{16}\right)^{th}(161​)th of this initial activity in 80 days. The half life of the radioactive substance expressed in days is ____________.

Correct answer: 20

Step-by-step solution →
Q22·PhysicsNumerical
A certain metallic surface is illuminated by monochromatic radiation of wavelength λ\lambdaλ. The stopping potential for photoelectric current for this radiation is 3V03V_{0}3V0​. If the same surface is illuminated with a radiation of wavelength 2λ2\lambda2λ, the stopping potential is V0V_{0}V0​. The threshold wavelength of this surface for photoelectric effect is _________ λ\lambdaλ.

Correct answer: 4

Step-by-step solution →
Q23·PhysicsNumerical
Two bodies, a ring and a solid cylinder of same material are rolling down without slipping an inclined plane. The radii of the bodies are same. The ratio of velocity centre of mass at the bottom of the inclined plane of the ring to that of the cylinder is x2\frac{\sqrt{x}}{2}2x​​. Then, the value of x is ___________.

Correct answer: 3

Step-by-step solution →
Q24·PhysicsNumerical
A series LCR circuit of R=5Ω,L=20 mH\mathrm{R} = 5\Omega, \mathrm{L} = 20\,\mathrm{mH}R=5Ω,L=20mH and C=0.5 μF\mathrm{C} = 0.5\,\mu\mathrm{F}C=0.5μF is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is _________ ×102\times 10^{2}×102 W.

Correct answer: 125

Step-by-step solution →
Q25·PhysicsNumerical
A body rotating with an angular speed of 600 rpm is uniformly accelerated to 1800 rpm in 10 sec. The number of rotations made in the process is ____________.

Correct answer: 200

Step-by-step solution →
Q26·PhysicsNumerical
For the forward biased diode characteristics shown in the figure, the dynamic resistance at ID=3 mA\mathrm{I}_{\mathrm{D}} = 3\,\mathrm{mA}ID​=3mA will be ___________ Ω\OmegaΩ.

Correct answer: 25

Step-by-step solution →
Q27·PhysicsNumerical
One mole of an ideal gas at 27∘C27^{\circ}\mathrm{C}27∘C is taken from A to B as shown in the given PV indicator diagram. The work done by the system will be ________ ×10−1\times 10^{-1}×10−1 J. [Given : R=8.3 J/mole K\mathrm{R} = 8.3\,\mathrm{J/mole\ K}R=8.3J/mole K, ℓn 2=0.6931\ell\mathrm{n}\,2 = 0.6931ℓn2=0.6931 ] (Round off to the nearest integer)

Correct answer: 17258

Step-by-step solution →
Q28·PhysicsNumerical
In the given figure switches S1\mathrm{S}_{1}S1​ and S2\mathrm{S}_{2}S2​ are in open condition. The resistance across ab when the switches S1\mathrm{S}_{1}S1​ and S2\mathrm{S}_{2}S2​ are closed is ________ Ω\OmegaΩ.

Correct answer: 10

Step-by-step solution →
Q29·PhysicsNumerical
A body of mass 'm' is launched up on a rough inclined plane making an angle of 30∘30^{\circ}30∘ with the horizontal. The coefficient of friction between the body and plane is x5\frac{\sqrt{x}}{5}5x​​ if the time of ascent is half of the time of descent. The value of x is ___________.

Correct answer: 3

Step-by-step solution →
Q30·PhysicsNumerical
A zener diode having zener voltage 8 V and power dissipation rating of 0.5 W is connected across a potential divider arranged with maximum potential drop across zener diode is as shown in the diagram. The value of protective resistance Rp\mathrm{R}_{\mathrm{p}}Rp​ is __________ Ω\OmegaΩ.

Correct answer: 192

Step-by-step solution →

Chemistry — JEE Main 20 July 2021 Shift 2

Q31·ChemistrySingle correct
Major product P of above reaction, is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Outermost electronic configuration of a group 13 element, E, is 4s2,4p1\mathrm{4s^2, 4p^1}4s2,4p1. The electronic configuration of an element of p-block period-five placed diagonally to element, E is:
  1. (A)[Kr]4d10 5s2 5p2\mathrm{[Kr]4d^{10}\,5s^2\,5p^2}[Kr]4d105s25p2
  2. (B)[Kr]3d10 4s2 4p2\mathrm{[Kr]3d^{10}\,4s^2\,4p^2}[Kr]3d104s24p2
  3. (C)[Xe]5d10 6s2 6p2\mathrm{[Xe]5d^{10}\,6s^2\,6p^2}[Xe]5d106s26p2
  4. (D)[Ar]3d10 4s2 4p2\mathrm{[Ar]3d^{10}\,4s^2\,4p^2}[Ar]3d104s24p2

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
In the above reactions, product A and product B respectively are:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q34·ChemistrySingle correct
Bakelite is a cross- linked polymer of formaldehyde and :
  1. (A)PHBV
  2. (B)Buna – S
  3. (C)Novolac
  4. (D)Dacron

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Consider two chemical reactions (A) and (B) that take place during metallurgical process: (a) ZnCO3(s)→ΔZnO(s)+CO2(g)\mathrm{ZnCO_{3(s)} \xrightarrow{\Delta} ZnO_{(s)} + CO_{2(g)}}ZnCO3(s)​Δ​ZnO(s)​+CO2(g)​ (b) 2ZnS(s)+3O2(g)→Δ2ZnO(s)+2SO2(g)\mathrm{2ZnS_{(s)} + 3O_{2(g)} \xrightarrow{\Delta} 2ZnO_{(s)} + 2SO_{2(g)}}2ZnS(s)​+3O2(g)​Δ​2ZnO(s)​+2SO2(g)​ The correct option of names given to them respectively is :
  1. (A)(a) is calcination and (b) is roasting
  2. (B)Both (a) and (b) are producing same product so both are calcination
  3. (C)Both (a) and (b) are producing same product so both are roasting
  4. (D)(a) is roasting and (b) is calcination

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
The correct order of their reactivity towards hydrolysis at room temperature is:
  1. (A)(d) > (b) > (a) > (c)
  2. (B)(d) > (a) > (b) > (c)
  3. (C)(a) > (c) > (b) > (d)
  4. (D)(a) > (b) > (c) > (d)

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
Spin only magnetic moment of an octahedral complex of Fe2+\mathrm{Fe^{2+}}Fe2+ in the presence of a strong field ligand in BM is :
  1. (A)2.82
  2. (B)3.46
  3. (C)0
  4. (D)4.89

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Which one of the following statements is not true about enzymes ?
  1. (A)The action of enzymes is temperature and pH specific.
  2. (B)Enzymes are non-specific for a reaction and substrate.
  3. (C)Enzymes work as catalysts by lowering the activation energy of a biochemical reaction.
  4. (D)Almost all enzymes are proteins.

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
Consider the above reaction, compound B is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q40·ChemistrySingle correct
Which one of the following gases is reported to retard photosynthesis ?
  1. (A)CO2\mathrm{CO_2}CO2​
  2. (B)CFCs
  3. (C)CO\mathrm{CO}CO
  4. (D)NO2\mathrm{NO_2}NO2​

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correct
Benzene on nitration gives nitrobenzene in presence of HNO3\mathrm{HNO_3}HNO3​ and H2SO4\mathrm{H_2SO_4}H2​SO4​ mixture, where:
  1. (A)both H2SO4\mathrm{H_2SO_4}H2​SO4​ and HNO3\mathrm{HNO_3}HNO3​ act as a bases
  2. (B)both H2SO4\mathrm{H_2SO_4}H2​SO4​ and HNO3\mathrm{HNO_3}HNO3​ act as an acids
  3. (C)HNO3\mathrm{HNO_3}HNO3​ acts as a base and H2SO4\mathrm{H_2SO_4}H2​SO4​ acts as an acid
  4. (D)HNO3\mathrm{HNO_3}HNO3​ acts as an acid and H2SO4\mathrm{H_2SO_4}H2​SO4​ acts as a base

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
Which one of the following species doesn't have a magnetic moment of 1.73 BM, (spin only value)?
  1. (A)CuI\mathrm{CuI}CuI
  2. (B)[Cu(NH3)4]Cl2\mathrm{[Cu(NH_3)_4]Cl_2}[Cu(NH3​)4​]Cl2​
  3. (C)O2−\mathrm{O_2^-}O2−​
  4. (D)O2+\mathrm{O_2^+}O2+​

Correct answer: (A)

Step-by-step solution →
Q43·Chemistry·IsomerismSingle correct
Which one of the following pairs of isomers is an example of metamerism?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q44·ChemistrySingle correct
The hybridisations of the atomic orbitals of nitrogen in NO2−\mathrm{NO_2^-}NO2−​, NO2+\mathrm{NO_2^+}NO2+​ and NH4+\mathrm{NH_4^+}NH4+​ respectively are :
  1. (A)sp3\mathrm{sp^3}sp3, sp\mathrm{sp}sp and sp2\mathrm{sp^2}sp2
  2. (B)sp\mathrm{sp}sp, sp2\mathrm{sp^2}sp2 and sp3\mathrm{sp^3}sp3
  3. (C)sp2\mathrm{sp^2}sp2, sp\mathrm{sp}sp and sp3\mathrm{sp^3}sp3
  4. (D)sp3\mathrm{sp^3}sp3, sp2\mathrm{sp^2}sp2 and sp\mathrm{sp}sp

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
Metallic sodium does not react normally with :
  1. (A)gaseous ammonia
  2. (B)tert – butyl alcohol
  3. (C)But – 2 – yne
  4. (D)Ethyne

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
In Carius method, halogen containing organic compound is heated with fuming nitric acid in the presence of :
  1. (A)AgNO3\mathrm{AgNO_3}AgNO3​
  2. (B)HNO3\mathrm{HNO_3}HNO3​
  3. (C)BaSO4\mathrm{BaSO_4}BaSO4​
  4. (D)CuSO4\mathrm{CuSO_4}CuSO4​

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
The single largest industrial application of dihydrogen is :
  1. (A)Rocket fuel in space research
  2. (B)In the synthesis of nitric acid
  3. (C)In the synthesis of ammonia
  4. (D)Manufacture of metal hydrides

Correct answer: (C)

Step-by-step solution →
Q48·ChemistrySingle correct
The major product (P) in the following reaction is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
A solution is 0.1 M in Cl−\mathrm{Cl}^-Cl− and 0.001 M in CrO42−\mathrm{CrO_4^{2-}}CrO42−​. Solid AgNO3\mathrm{AgNO_3}AgNO3​ is gradually added to it. Assuming that the addition does not change in volume and Ksp(AgCl)=1.7×10−10 M2\mathrm{K_{sp}}\left(\mathrm{AgCl}\right) = 1.7 \times 10^{-10}\ \mathrm{M^2}Ksp​(AgCl)=1.7×10−10 M2 and Ksp(Ag2CrO4)=1.9×10−12 M3\mathrm{K_{sp}}\left(\mathrm{Ag_2CrO_4}\right) = 1.9 \times 10^{-12}\ \mathrm{M^3}Ksp​(Ag2​CrO4​)=1.9×10−12 M3. Select correct statement from the following :
  1. (A)Ag2CrO4\mathrm{Ag_2CrO_4}Ag2​CrO4​ precipitates first because the amount of Ag+\mathrm{Ag}^+Ag+ needed is low.
  2. (B)Ag2CrO4\mathrm{Ag_2CrO_4}Ag2​CrO4​ precipitates first as its Ksp\mathrm{K_{sp}}Ksp​ is low.
  3. (C)AgCl\mathrm{AgCl}AgCl will precipitate first as the amount of Ag+\mathrm{Ag}^+Ag+ needed to precipitate is low.
  4. (D)AgCl\mathrm{AgCl}AgCl precipitates first because its Ksp\mathrm{K_{sp}}Ksp​ is high.

Correct answer: (C)

Step-by-step solution →
Q50·ChemistryNumerical
4g equimolar mixture of NaOH\mathrm{NaOH}NaOH and Na2CO3\mathrm{Na_2CO_3}Na2​CO3​ contains xxx g of NaOH\mathrm{NaOH}NaOH and yyy g of Na2CO3\mathrm{Na_2CO_3}Na2​CO3​. The value of x is __________ g. (Nearest Integer)

Correct answer: 1

Step-by-step solution →
Q51·ChemistryNumerical
When 0.15 g of an organic compound was analyzed using carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest Integer) (Atomic mass: Ag = 108, Br = 80)

Correct answer: 68

Step-by-step solution →
Q52·ChemistryNumerical
For a given chemical reaction A→B\mathrm{A} \rightarrow \mathrm{B}A→B at 300 K the free energy change is − 49.4-\,49.4−49.4 kJ mol−1\mathrm{mol^{-1}}mol−1 and the enthalpy of reaction is 51.4 kJ mol−1\mathrm{mol^{-1}}mol−1. The entropy change of the reaction is ________ J K−1 mol−1\mathrm{J\ K^{-1}\ mol^{-1}}J K−1 mol−1.

Correct answer: 336

Step-by-step solution →
Q53·ChemistryNumerical
The wavelength of electrons accelerated from rest through a potential difference of 40 kV is x×10−12x \times 10^{-12}x×10−12 m. The value of xxx is ________. (Nearest Integer) Given : Mass of electron =9.1×10−31 kg= 9.1 \times 10^{-31}\ \mathrm{kg}=9.1×10−31 kg Charge on an electron =1.6×10−19 C= 1.6 \times 10^{-19}\ \mathrm{C}=1.6×10−19 C Planck's constant =6.63×10−34 Js= 6.63 \times 10^{-34}\ \mathrm{Js}=6.63×10−34 Js

Correct answer: 6

Step-by-step solution →
Q54·ChemistryNumerical
100 ml of 0.0018% (w/v) solution of Cl−\mathrm{Cl}^-Cl− ion was the minimum concentration of Cl−\mathrm{Cl}^-Cl− required to precipitate a negative sol in one h. The coagulating value of Cl−\mathrm{Cl}^-Cl− ion is ________. (Nearest integer)

Correct answer: 1

Step-by-step solution →
Q55·ChemistryNumerical
An aqueous solution of NiCl2\mathrm{NiCl_2}NiCl2​ was heated with excess sodium cyanide in presence of strong oxidizing agent to form [Ni(CN)6]2−\left[\mathrm{Ni(CN)_6}\right]^{2-}[Ni(CN)6​]2−. The total change in number of unpaired electrons on metal centre is ________.

Correct answer: 2

Step-by-step solution →
Q56·ChemistryNumerical
Diamond has a three dimensional structure of C atoms formed by covalent bonds. The structure of diamond has face centred cubic lattice where 50% of the tetrahedral voids are also occupied by carbon atoms. The number of carbon atoms present per unit cell of diamond is __________.

Correct answer: 8

Step-by-step solution →
Q57·ChemistryNumerical
The vapour pressures of A and B at 25∘C25^\circ \mathrm{C}25∘C are 90 mm Hg and 15 mm Hg respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x×10−1x \times 10^{-1}x×10−1. The value xxx is ________. (Nearest Integer)

Correct answer: 1

Step-by-step solution →
Q58·ChemistryNumerical
PCl5(g)→PCl3(g)+Cl2(g)\mathrm{PCl_5}\left(\mathrm{g}\right) \rightarrow \mathrm{PCl_3}\left(\mathrm{g}\right) + \mathrm{Cl_2}\left(\mathrm{g}\right)PCl5​(g)→PCl3​(g)+Cl2​(g) In the above first order reaction, the concentration of PCl5\mathrm{PCl_5}PCl5​ reduces from initial concentration 50 mol L−150\ \mathrm{mol\ L^{-1}}50 mol L−1 to 10 mol L−110\ \mathrm{mol\ L^{-1}}10 mol L−1 in 120 minutes at 300 K. The rate constant for the reaction at 300 K is x×10−2 min−1x \times 10^{-2}\ \mathrm{min^{-1}}x×10−2 min−1. the value of xxx is ________. [Given log⁡5=0.6989\log 5 = 0.6989log5=0.6989]

Correct answer: 1

Step-by-step solution →
Q59·Chemistry·Redox Reactions and ElectrochemistryNumerical
Potassium chlorate is prepared by electrolysis of KCl\mathrm{KCl}KCl in basic solution as shown by following equation. 6 OH−+Cl−→ClO3−+3 H2O+6 e−6\,\mathrm{OH}^- + \mathrm{Cl}^- \rightarrow \mathrm{ClO_3^-} + 3\,\mathrm{H_2O} + 6\,\mathrm{e}^-6OH−+Cl−→ClO3−​+3H2​O+6e− A current of xA has to be passed for 10 h to produce 10.0 g of potassium chlorate. The value of xxx is ________. (Nearest Integer) (Molar mass of KClO3=122.6 g mol−1, F=96500 C\mathrm{KClO_3} = 122.6\ \mathrm{g\ mol^{-1}},\ \mathrm{F} = 96500\ \mathrm{C}KClO3​=122.6 g mol−1, F=96500 C)

Correct answer: 1

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Mathematics — JEE Main 20 July 2021 Shift 2

Q60·MathematicsSingle correct
Consider the line L given by the equation x−32=y−11=z−21\frac{x-3}{2}=\frac{y-1}{1}=\frac{z-2}{1}2x−3​=1y−1​=1z−2​. Let Q be the mirror image of the point (2,3,−1)(2,3,-1)(2,3,−1) with respect to L. Let a plane P be such that it passes through Q, and the line L is perpendicular to P. Then which of the following points is one the plane P ?
  1. (A)(1,2,2)(1,2,2)(1,2,2)
  2. (B)(−1,1,2)(-1,1,2)(−1,1,2)
  3. (C)(1,1,1)(1,1,1)(1,1,1)
  4. (D)(1,1,2)(1,1,2)(1,1,2)

Correct answer: (A)

Step-by-step solution →
Q61·MathematicsSingle correct
If the real part of the complex number (1−cos⁡θ+2isin⁡θ)−1\left(1-\cos\theta+2i\sin\theta\right)^{-1}(1−cosθ+2isinθ)−1 is 15\frac{1}{5}51​ for θ∈(0,π)\theta\in(0,\pi)θ∈(0,π), then the value of the integral ∫0θsin⁡x dx\int_{0}^{\theta}\sin x\,dx∫0θ​sinxdx is equal to :
  1. (A)−1-1−1
  2. (B)000
  3. (C)222
  4. (D)111

Correct answer: (D)

Step-by-step solution →
Q62·Mathematics·Matrices and DeterminantsSingle correct
The value of k∈Rk\in Rk∈R, for which the following system of linear equations 3x−y+4z=3,3x-y+4z=3,3x−y+4z=3, x+2y−3z=−2,x+2y-3z=-2,x+2y−3z=−2, 6x+5y+kz=−3,6x+5y+kz=-3,6x+5y+kz=−3, has infinitely many solutions, is :
  1. (A)333
  2. (B)−3-3−3
  3. (C)−5-5−5
  4. (D)555

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
For the natural numbers m,nm,nm,n, if (1−y)m(1+y)n=1+a1y+a2y2+....+am+nym+n(1-y)^{m}(1+y)^{n}=1+a_{1}y+a_{2}y^{2}+....+a_{m+n}y^{m+n}(1−y)m(1+y)n=1+a1​y+a2​y2+....+am+n​ym+n and a1=a2=10,a_{1}=a_{2}=10,a1​=a2​=10, then the value of (m+n)(m+n)(m+n) is equal to :
  1. (A)646464
  2. (B)888888
  3. (C)808080
  4. (D)100100100

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
The value of tan⁡(2tan⁡−1(35)+sin⁡−1(513))\tan\left(2\tan^{-1}\left(\frac{3}{5}\right)+\sin^{-1}\left(\frac{5}{13}\right)\right)tan(2tan−1(53​)+sin−1(135​)) is equal to :
  1. (A)15163\frac{151}{63}63151​
  2. (B)−29176\frac{-291}{76}76−291​
  3. (C)22021\frac{220}{21}21220​
  4. (D)−18169\frac{-181}{69}69−181​

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
If f:R→Rf:R\to Rf:R→R is given by f(x)=x+1,f(x)=x+1,f(x)=x+1, then the value of lim⁡n→∞1n[f(0)+f(5n)+f(10n)+....+f(5(n−1)n)]\lim_{n\to\infty}\frac{1}{n}\left[f(0)+f\left(\frac{5}{n}\right)+f\left(\frac{10}{n}\right)+....+f\left(\frac{5(n-1)}{n}\right)\right]limn→∞​n1​[f(0)+f(n5​)+f(n10​)+....+f(n5(n−1)​)], is :
  1. (A)32\frac{3}{2}23​
  2. (B)12\frac{1}{2}21​
  3. (C)72\frac{7}{2}27​
  4. (D)52\frac{5}{2}25​

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
Let P be a variable point on the parabola y=4x2+1y=4x^{2}+1y=4x2+1. Then, the locus of the mid-point of the point P and the foot of the perpendicular drawn from the point P to the line y=xy=xy=x is :
  1. (A)2(x−3y)2+(3x−y)+2=02(x-3y)^{2}+(3x-y)+2=02(x−3y)2+(3x−y)+2=0
  2. (B)(3x−y)2+(x−3y)+2=0(3x-y)^{2}+(x-3y)+2=0(3x−y)2+(x−3y)+2=0
  3. (C)2(3x−y)2+(x−3y)+2=02(3x-y)^{2}+(x-3y)+2=02(3x−y)2+(x−3y)+2=0
  4. (D)(3x−y)2+2(x−3y)+2=0(3x-y)^{2}+2(x-3y)+2=0(3x−y)2+2(x−3y)+2=0

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
The sum of all the local minimum values of the twice differentiable function f:R→Rf:R\to Rf:R→R defined by f(x)=x3−3x2−3f′′(2)2x+f′′(1)f(x)=x^{3}-3x^{2}-\frac{3f''(2)}{2}x+f''(1)f(x)=x3−3x2−23f′′(2)​x+f′′(1) is :
  1. (A)−22-22−22
  2. (B)555
  3. (C)000
  4. (D)−27-27−27

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
Let r1r_{1}r1​ and r2r_{2}r2​ be the radii of the largest and smallest circles, respectively, which pass through the point (−4,1)(-4,1)(−4,1) and having their centres on the circumference of the circle x2+y2+2x+4y−4=0x^{2}+y^{2}+2x+4y-4=0x2+y2+2x+4y−4=0. If r1r2=a+b2,\frac{r_{1}}{r_{2}}=a+b\sqrt{2},r2​r1​​=a+b2​, then a+ba+ba+b is equal to :
  1. (A)555
  2. (B)111111
  3. (C)777
  4. (D)333

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
If the mean and variance of six observations 7, 10, 11, 15, a, b7,\ 10,\ 11,\ 15,\ a,\ b7, 10, 11, 15, a, b are 101010 and 203\frac{20}{3}320​, respectively, then the value of ∣a−b∣|a-b|∣a−b∣ is equal to
  1. (A)999
  2. (B)777
  3. (C)111111
  4. (D)111

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
Let y=y(x)y=y(x)y=y(x) satisfies the equation dydx−∣A∣=0,\frac{dy}{dx}-|A|=0,dxdy​−∣A∣=0, for all x>0,x>0,x>0, where A=[ysin⁡x10−11201x]A=\begin{bmatrix} y & \sin x & 1 \\ 0 & -1 & 1 \\ 2 & 0 & \frac{1}{x} \end{bmatrix}A=​y02​sinx−10​11x1​​​. If y(π)=π+2,y(\pi)=\pi+2,y(π)=π+2, then the value of y(π2)y\left(\frac{\pi}{2}\right)y(2π​) is :
  1. (A)π2+4π\frac{\pi}{2}+\frac{4}{\pi}2π​+π4​
  2. (B)3π2−1π\frac{3\pi}{2}-\frac{1}{\pi}23π​−π1​
  3. (C)π2−4π\frac{\pi}{2}-\frac{4}{\pi}2π​−π4​
  4. (D)π2−1π\frac{\pi}{2}-\frac{1}{\pi}2π​−π1​

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Let f:R−{α6}→Rf:R-\left\{\frac{\alpha}{6}\right\}\to Rf:R−{6α​}→R be defined by f(x)=5x+36x−αf(x)=\frac{5x+3}{6x-\alpha}f(x)=6x−α5x+3​. Then the value of α\alphaα for which (fof)(x)=x,(fof)(x)=x,(fof)(x)=x, for all x∈R−{α6}x\in R-\left\{\frac{\alpha}{6}\right\}x∈R−{6α​}, is :
  1. (A)666
  2. (B)888
  3. (C)No such α\alphaα exists
  4. (D)555

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
The lines x=ay−1=z−2x=ay-1=z-2x=ay−1=z−2 and x=3y−2=bz−2, (ab≠0)x=3y-2=bz-2,\ (ab\neq 0)x=3y−2=bz−2, (ab=0) are coplanar, if :
  1. (A)a=2, b=2a=2,\ b=2a=2, b=2
  2. (B)b=1, a∈R−{0}b=1,\ a\in R-\{0\}b=1, a∈R−{0}
  3. (C)a=2, b=3a=2,\ b=3a=2, b=3
  4. (D)a=1, b∈R−{0}a=1,\ b\in R-\{0\}a=1, b∈R−{0}

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
In a triangle ABC, if ∣BC→∣=3,∣CA→∣=5\left|\overrightarrow{BC}\right|=3,\left|\overrightarrow{CA}\right|=5​BC​=3,​CA​=5 and ∣BA→∣=7,\left|\overrightarrow{BA}\right|=7,​BA​=7, then the projection of the vector BA→\overrightarrow{BA}BA on BC→\overrightarrow{BC}BC is equal to :
  1. (A)192\frac{19}{2}219​
  2. (B)132\frac{13}{2}213​
  3. (C)152\frac{15}{2}215​
  4. (D)112\frac{11}{2}211​

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
Let g(t)=∫−π/2π/2cos⁡(π4t+f(x))dx,g(t)=\int_{-\pi/2}^{\pi/2}\cos\left(\frac{\pi}{4}t+f(x)\right)dx,g(t)=∫−π/2π/2​cos(4π​t+f(x))dx, where f(x)=log⁡e(x+x2+1), x∈Rf(x)=\log_{e}\left(x+\sqrt{x^{2}+1}\right),\ x\in Rf(x)=loge​(x+x2+1​), x∈R. Then which one of the following is correct?
  1. (A)g(1)=g(0)g(1)=g(0)g(1)=g(0)
  2. (B)g(1)=2g(0)g(1)=\sqrt{2}g(0)g(1)=2​g(0)
  3. (C)g(1)+g(0)=0g(1)+g(0)=0g(1)+g(0)=0
  4. (D)2g(1)=g(0)\sqrt{2}g(1)=g(0)2​g(1)=g(0)

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsSingle correct
Consider the following three statements : (A) if 3 + 3 = 7 then 4 + 3 = 8. (B) If 5 + 3 = 8 then earth is flat. (C) If both (A) and (B) are true then 5 + 6 = 17. Then, which of the following statements is correct?
  1. (A)(A) and (C) are true while (B) is false
  2. (B)(A) and (B) are false while (C) is true
  3. (C)(A) is true while (B) and (C) are false
  4. (D)(A) is false, but (B) and (C) are true

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
If sum of the first 21 terms of the series log⁡91/2x+log⁡91/3x+log⁡91/4x+....,\log_{9^{1/2}}x+\log_{9^{1/3}}x+\log_{9^{1/4}}x+....,log91/2​x+log91/3​x+log91/4​x+...., where x>0x>0x>0 is 504, then x is equal to :
  1. (A)777
  2. (B)999
  3. (C)243243243
  4. (D)818181

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
If [x] denotes the greatest integer less than or equal to x, then the value of the integral ∫−π/2π/2[[x]−sin⁡x]dx\int_{-\pi/2}^{\pi/2}\left[[x]-\sin x\right]dx∫−π/2π/2​[[x]−sinx]dx is equal to :
  1. (A)−π-\pi−π
  2. (B)000
  3. (C)111
  4. (D)π\piπ

Correct answer: (A)

Step-by-step solution →
Q78·MathematicsSingle correct
Let in a right angled triangle, the smallest angle be θ\thetaθ. If a triangle formed by taking the reciprocal of its sides is also a right angled triangle, then sin⁡θ\sin\thetasinθ is equal to :
  1. (A)2−12\frac{\sqrt{2}-1}{2}22​−1​
  2. (B)5+14\frac{\sqrt{5}+1}{4}45​+1​
  3. (C)5−12\frac{\sqrt{5}-1}{2}25​−1​
  4. (D)5−14\frac{\sqrt{5}-1}{4}45​−1​

Correct answer: (C)

Step-by-step solution →
Q79·MathematicsSingle correct
Let A, B and C be three events such that the probability that exactly one of A and B occurs is (1−k)(1-k)(1−k), the probability that exactly one of B and C occurs is (1−2k)(1-2k)(1−2k), the probability that exactly one of C and A occurs is (1−k)(1-k)(1−k) and the probability of all A, B and C occur simultaneously is k2k^{2}k2, where 0<k<10<k<10<k<1. Then the probability that at least one of A, B and C occur is :
  1. (A)greater than 12\frac{1}{2}21​
  2. (B)greater than 14\frac{1}{4}41​ but less than 12\frac{1}{2}21​
  3. (C)exactly equal to 12\frac{1}{2}21​
  4. (D)greater than 18\frac{1}{8}81​ but less than 14\frac{1}{4}41​

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsNumerical
Let {an}n=1∞\{a_{n}\}_{n=1}^{\infty}{an​}n=1∞​ be a sequence such that a1=1,a2=1a_{1}=1, a_{2}=1a1​=1,a2​=1 and an+2=2an+1+ana_{n+2}=2a_{n+1}+a_{n}an+2​=2an+1​+an​ for all n≥1n\ge 1n≥1. Then the value of 47∑n=1∞an23n47\sum_{n=1}^{\infty}\frac{a_{n}}{2^{3n}}47∑n=1∞​23nan​​ is equal to……..

Correct answer: 7

Step-by-step solution →
Q81·MathematicsNumerical
Consider a triangle having vertices A(−2,3)A(-2,3)A(−2,3), B(1,9)B(1,9)B(1,9) and C(3,8)C(3,8)C(3,8). If a line L passing through the circum-center of triangle ABC, bisects line BC, and intersects y-axis at point (0,α2)\left(0,\frac{\alpha}{2}\right)(0,2α​), then the value of real number α\alphaα is…………

Correct answer: 9

Step-by-step solution →
Q82·MathematicsNumerical
If the point on the curve y2=6xy^{2}=6xy2=6x, nearest to the point (3,32)\left(3,\frac{3}{2}\right)(3,23​) is (α,β)(\alpha,\beta)(α,β), then 2(α+β)2(\alpha+\beta)2(α+β) is equal to………

Correct answer: 9

Step-by-step solution →
Q83·Mathematics·Matrices and DeterminantsNumerical
Let A={aij}A=\{a_{ij}\}A={aij​} be a 3 x 3 matrix, where aij={(−1)j−iif i<j,2if i=j,(−1)i+jif i>j,a_{ij}=\begin{cases}(-1)^{j-i} & \text{if } i<j, \\ 2 & \text{if } i=j, \\ (-1)^{i+j} & \text{if } i>j,\end{cases}aij​=⎩⎨⎧​(−1)j−i2(−1)i+j​if i<j,if i=j,if i>j,​ then det⁡(3 Adj(2A−1))\det\left(3\,\text{Adj}\left(2A^{-1}\right)\right)det(3Adj(2A−1)) is equal to…….

Correct answer: 108

Step-by-step solution →
Q84·MathematicsNumerical
For p>0p>0p>0, a vector v⃗2=2i^+(p+1)j^\vec{v}_{2}=2\hat{i}+(p+1)\hat{j}v2​=2i^+(p+1)j^​ is obtained by rotating the vector v⃗1=3 pi^+j^\vec{v}_{1}=\sqrt{3}\,p\hat{i}+\hat{j}v1​=3​pi^+j^​ by an angle θ\thetaθ about origin in counter clockwise direction. If tan⁡θ=(α3−2)(43+3)\tan\theta=\frac{\left(\alpha\sqrt{3}-2\right)}{\left(4\sqrt{3}+3\right)}tanθ=(43​+3)(α3​−2)​, then the value of α\alphaα is equal to……….

Correct answer: 6

Step-by-step solution →
Q85·MathematicsNumerical
Let a curve y=y(x)y=y(x)y=y(x) be given by the solution of the differential equation cos⁡(12cos⁡−1(e−x))dx=e2x−1 dy\cos\left(\frac{1}{2}\cos^{-1}\left(e^{-x}\right)\right)dx=\sqrt{e^{2x}-1}\,dycos(21​cos−1(e−x))dx=e2x−1​dy If it intersects y-axis at y=−1y=-1y=−1, and the intersection point of the curve with x-axis is (α,0)(\alpha,0)(α,0), then eαe^{\alpha}eα is equal to……..

Correct answer: 2

Step-by-step solution →
Q86·MathematicsNumerical
The number of solutions of the equation log⁡(x+1)(2x2+7x+5)+log⁡(2x+5)(x+1)2−4=0\log_{(x+1)}\left(2x^{2}+7x+5\right)+\log_{(2x+5)}(x+1)^{2}-4=0log(x+1)​(2x2+7x+5)+log(2x+5)​(x+1)2−4=0, x>0x>0x>0, is………

Correct answer: 1

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Q87·MathematicsNumerical
Let a function g:[0,4]→Rg:[0,4]\to Rg:[0,4]→R be defined as g(x)={max⁡0≤t≤x{t3−6t2+9t−3},0≤x≤34−x,3<x≤4g(x)=\begin{cases}\max\limits_{0\le t\le x}\{t^{3}-6t^{2}+9t-3\}, & 0\le x\le 3 \\ 4-x, & 3<x\le 4\end{cases}g(x)={0≤t≤xmax​{t3−6t2+9t−3},4−x,​0≤x≤33<x≤4​, then the number of points in the interval (0,4)(0,4)(0,4) where g(x)g(x)g(x) is NOT differentiable, is…….

Correct answer: 1

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