Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Main PYQs
  3. /2023
  4. /6 Apr Shift 2

JEE Main 6 April 2023 Shift 2 Question Paper with Answers

6 April 2023 · April session · 90 questions

The complete JEE Main 6 April 2023 Shift 2 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 6 April 2023 Shift 2

Q1·PhysicsSingle correct
A 2 metre long scale with least count of 0.2 cm is used to measure the locations of objects on an optical bench. While measuring the focal length of a convex lens, the object pin and the convex lens are placed at 80 cm mark and 1 m mark, respectively. The image of the object pin on the other side of lens coincides with image pin that is kept at 180 cm mark. The percentage error in the estimation of focal length is:
  1. (A)1.021.021.02
  2. (B)0.850.850.85
  3. (C)1.701.701.70
  4. (D)0.510.510.51

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
A capacitor of capacitance 150.0 μF\mu FμF is connected to an alternating source of emf given by E=36sin⁡(120πt)E = 36\sin(120\pi t)E=36sin(120πt) V. The maximum value of current in the circuit is approximately equal to:
  1. (A)2 A2\,A2A
  2. (B)12 A\frac{1}{\sqrt{2}}\,A2​1​A
  3. (C)2 A\sqrt{2}\,A2​A
  4. (D)22 A2\sqrt{2}\,A22​A

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: When you squeeze one end of a tube to get toothpaste out from the other end, Pascal's principle is observed. Reason R: A change in the pressure applied to an enclosed incompressible fluid is transmitted undiminished to every portion of the fluid and to the walls of its container. In the light of the above statements, choose the most appropriate answer from the options given below
  1. (A)A is not correct but R is correct
  2. (B)A is correct but R is not correct
  3. (C)Both A and R are correct and R is the correct explanation of A
  4. (D)Both A and R are correct but R is NOT the correct explanation of A

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The phase difference of two light waves change if they travel through different media having same thickness, but different indices of refraction. Reason R: The wavelengths of waves are different in different media. In the light of the above statements, choose the most appropriate answer from the options given below
  1. (A)Both A and R are correct but R is NOT the correct explanation of A
  2. (B)A is correct but R is not correct
  3. (C)Both A and R are correct and R is the correct explanation of A
  4. (D)A is not correct but R is correct

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correct
Figure shows a part of an electric circuit. The potentials at points aaa, bbb and ccc are 30 V, 12 V and 2 V respectively. The current through the 20 Ω\OmegaΩ resistor will be
  1. (A)0.4 A0.4\,A0.4A
  2. (B)0.2 A0.2\,A0.2A
  3. (C)0.6 A0.6\,A0.6A
  4. (D)1.0 A1.0\,A1.0A

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
As shown in the figure, a particle is moving with constant speed π\piπ m/s. Considering its motion from A to B, the magnitude of the average velocity is:
  1. (A)π\piπ m/s
  2. (B)3\sqrt{3}3​ m/s
  3. (C)232\sqrt{3}23​ m/s
  4. (D)1.531.5\sqrt{3}1.53​ m/s

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
The work functions of Aluminium and Gold are 4.1 eV and 5.1 eV respectively. The ratio of the slope of the stopping potential versus frequency plot for Gold to that of Aluminium is
  1. (A)1.241.241.24
  2. (B)222
  3. (C)111
  4. (D)1.51.51.5

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
The ratio of speed of sound in hydrogen gas to the speed of sound in oxygen gas at the same temperature is:
  1. (A)4:14 : 14:1
  2. (B)1:21 : 21:2
  3. (C)1:41 : 41:4
  4. (D)1:11 : 11:1

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
A child of mass 5 kg is going round a merry-go-round that makes 1 rotation in 3.14 s. The radius of the merry-go-round is 2 m. The centrifugal force on the child will be
  1. (A)80 N80\ N80 N
  2. (B)50 N50\ N50 N
  3. (C)100 N100\ N100 N
  4. (D)40 N40\ N40 N

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
A particle starts with an initial velocity of 10.0 ms−110.0\,\text{ms}^{-1}10.0ms−1 along x-direction and accelerates uniformly at the rate of 2.0 ms−22.0\,\text{ms}^{-2}2.0ms−2. The time taken by the particle to reach the velocity of 60.0 ms−160.0\,\text{ms}^{-1}60.0ms−1 is
  1. (A)6 s6\,s6s
  2. (B)3 s3\,s3s
  3. (C)30 s30\,s30s
  4. (D)25 s25\,s25s

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
Choose the incorrect statement from the following:
  1. (A)The speed of satellite in a given circular orbit remains constant.
  2. (B)For a planet revolving around the sun in an elliptical orbit, the total energy of the planet remains constant.
  3. (C)When a body falls towards earth, the displacement of earth towards the body is negligible.
  4. (D)The linear speed of a planet revolving around the sun remains constant.

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Diffusion current in a p-n junction is greater than the drift current in magnitude if the junction is forward biased. Reason R: Diffusion current in a p-n junction is from the n-side to the p-side if the junction is forward biased. In the light of the above statements, choose the most appropriate answer from the options given below
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)Both A and R are correct but R is NOT the correct explanation of A
  3. (C)A is correct but R is not correct
  4. (D)A is not correct but R is correct

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
A dipole comprises of two charged particles of identical magnitude qqq and opposite in nature. The mass 'mmm' of the positive charged particle is half of the mass of the negative charged particle. The two charges are separated by a distance 'lll'. If the dipole is placed in a uniform electric field 'E⃗\vec{E}E' in such a way that dipole axis makes a very small angle with the electric field 'E⃗\vec{E}E'. The angular frequency of the oscillations of the dipole when released is given by:
  1. (A)8qE3ml\sqrt{\dfrac{8qE}{3ml}}3ml8qE​​
  2. (B)4qEml\sqrt{\dfrac{4qE}{ml}}ml4qE​​
  3. (C)4qE3ml\sqrt{\dfrac{4qE}{3ml}}3ml4qE​​
  4. (D)8qEml\sqrt{\dfrac{8qE}{ml}}ml8qE​​

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
The energy density associated with electric field E⃗\vec{E}E and magnetic field B⃗\vec{B}B of an electromagnetic wave in free space is given by (ε0\varepsilon_0ε0​ - permittivity of free space, μ0\mu_0μ0​ - permeability of free space)
  1. (A)UE=E22 ε0, UB=B22μ0U_E=\dfrac{E^2}{2\,\varepsilon_0},\ U_B=\dfrac{B^2}{2\mu_0}UE​=2ε0​E2​, UB​=2μ0​B2​
  2. (B)UE=E22 ε0, UB=μ0B22U_E=\dfrac{E^2}{2\,\varepsilon_0},\ U_B=\dfrac{\mu_0 B^2}{2}UE​=2ε0​E2​, UB​=2μ0​B2​
  3. (C)UE=ε0E22, UB=μ0B22U_E=\dfrac{\varepsilon_0 E^2}{2},\ U_B=\dfrac{\mu_0 B^2}{2}UE​=2ε0​E2​, UB​=2μ0​B2​
  4. (D)UE=ε0E22, UB=B22μ0U_E=\dfrac{\varepsilon_0 E^2}{2},\ U_B=\dfrac{B^2}{2\mu_0}UE​=2ε0​E2​, UB​=2μ0​B2​

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
The temperature of an ideal gas is increased from 200 K to 800 K. If r.m.s. speed of gas at 200 K is v0v_0v0​, then r.m.s. speed of the gas at 800 K will be:
  1. (A)v0v_0v0​
  2. (B)4v04v_04v0​
  3. (C)v04\dfrac{v_0}{4}4v0​​
  4. (D)2v02v_02v0​

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
A student is provided with a variable voltage source VVV, a test resistor RT=10 ΩR_T=10\,\OmegaRT​=10Ω, two identical galvanometers G1G_1G1​ and G2G_2G2​ and two additional resistors, R1=10 MΩR_1 = 10\,M\OmegaR1​=10MΩ and R2=0.001 ΩR_2 = 0.001\,\OmegaR2​=0.001Ω. For conducting an experiment to verify Ohm's law, the most suitable circuit is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A body cools in 7 minutes from 60 °C to 40 °C. The temperature of the surrounding is 10 °C. The temperature of the body after the next 7 minutes will be:
  1. (A)32 °C32\,°C32°C
  2. (B)30 °C30\,°C30°C
  3. (C)28 °C28\,°C28°C
  4. (D)34 °C34\,°C34°C

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
A small particle of mass mmm moves in such a way that its potential energy U=12mω2r2U = \dfrac{1}{2}m\omega^2 r^2U=21​mω2r2 where ω\omegaω is constant and rrr is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of nthn^{th}nth orbit will be proportional to:
  1. (A)n\sqrt{n}n​
  2. (B)nnn
  3. (C)n2n^2n2
  4. (D)1n\dfrac{1}{n}n1​

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
For an amplitude modulated wave the minimum amplitude is 3 V, while the modulation index is 60%. The maximum amplitude of the modulated wave is:
  1. (A)15 V15\,V15V
  2. (B)12 V12\,V12V
  3. (C)10 V10\,V10V
  4. (D)5 V5\,V5V

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
The weight of a body on the surface of the earth is 100 N. The gravitational force on it when taken at a height, from the surface of earth, equal to one-fourth the radius of the earth is:
  1. (A)100 N100\ N100 N
  2. (B)64 N64\ N64 N
  3. (C)50 N50\ N50 N
  4. (D)25 N25\ N25 N

Correct answer: (B)

Step-by-step solution →
Q21·PhysicsNumerical
As shown in the figure, the voltmeter reads 2 V across a 5 Ω\OmegaΩ resistor. The resistance of the voltmeter is

Correct answer: 20

Step-by-step solution →
Q22·PhysicsNumerical
A metal block of mass mmm is suspended from a rigid support through a metal wire of diameter 14 mm. The tensile stress developed in the wire under equilibrium state is 7×1057\times10^57×105 Nm−2^{-2}−2. The value of mass mmm is ____ kg. (Take g=9.8g = 9.8g=9.8 ms−2^{-2}−2 and π=227\pi = \dfrac{22}{7}π=722​)

Correct answer: 11

Step-by-step solution →
Q23·PhysicsNumerical
As shown in the figure, two parallel plate capacitors having equal plate area of 200 cm2^22 are joined together. The equivalent capacitance of the combination is x ε0x\,\varepsilon_0xε0​ F. The value of xxx is

Correct answer: 5

Step-by-step solution →
Q24·PhysicsNumerical
A ring and a solid sphere rotating about an axis passing through their centers have same radii of gyration. The axis of rotation is perpendicular to plane of ring. The ratio of radius of ring to that of sphere is 2x\sqrt{\dfrac{2}{x}}x2​​. The value of xxx is

Correct answer: 5

Step-by-step solution →
Q25·PhysicsNumerical
A simple pendulum with length 100 cm and bob of mass 250 g is executing S.H.M. of amplitude 10 cm. The maximum tension in the string is found to be x40\dfrac{x}{40}40x​ N. The value of xxx is

Correct answer: 99

Step-by-step solution →
Q26·PhysicsNumerical
Two concentric circular coils with radii 1 cm and 1000 cm, and number of turns 10 and 200 respectively are placed coaxially with centers coinciding. The mutual inductance of this arrangement will be ____ ×10−8\times 10^{-8}×10−8 H. (Take π2=10\pi^2=10π2=10)

Correct answer: 4

Step-by-step solution →
Q27·PhysicsNumerical
A beam of light consisting of two wavelengths 7000 Å and 5500 Å is used to obtain interference pattern in Young's double slit experiment. The distance between the slits is 2.5 mm and the distance between the plane of slits and the screen is 150 cm. The least distance from the central fringe, where the bright fringes coincide, will be n×10−5n \times 10^{-5}n×10−5 m. The value of nnn is

Correct answer: 462

Step-by-step solution →
Q28·PhysicsNumerical
A body is dropped on ground from a height 'h1h_1h1​' and after hitting the ground, it rebounds to a height 'h2h_2h2​'. If the ratio of velocities of the body just before and after hitting ground is 4, then percentage loss in kinetic energy of the body is x4\dfrac{x}{4}4x​. The value of xxx is

Correct answer: 375

Step-by-step solution →
Q29·PhysicsNumerical
Experimentally it is found that 12.8 eV energy is required to separate a hydrogen atom into a proton and an electron. The orbital radius of the electron in a hydrogen atom is 9x×10−10\dfrac{9}{x}\times10^{-10}x9​×10−10 m. The value of xxx is (14πε0=9×109\dfrac{1}{4\pi\varepsilon_0}=9\times10^94πε0​1​=9×109 Nm2^22/C2^22 and electronic charge =1.6×10−19=1.6\times10^{-19}=1.6×10−19 C)

Correct answer: 16

Step-by-step solution →
Q30·PhysicsNumerical
A proton with a kinetic energy of 2.0 eV moves into a region of uniform magnetic field of magnitude π2×10−3\dfrac{\pi}{2}\times10^{-3}2π​×10−3 T. The angle between the direction of magnetic field and velocity of proton is 60°. The pitch of the helical path taken by the proton is ____ cm. (Take mass of proton =1.6×10−27=1.6\times10^{-27}=1.6×10−27 kg and charge on proton =1.6×10−19=1.6\times10^{-19}=1.6×10−19 C)

Correct answer: 40

Step-by-step solution →

Chemistry — JEE Main 6 April 2023 Shift 2

Q31·ChemistrySingle correct
Ion having highest hydration enthalpy among the given alkaline earth metal ions is:
  1. (A)Be2+Be^{2+}Be2+
  2. (B)Ba2+Ba^{2+}Ba2+
  3. (C)Sr2+Sr^{2+}Sr2+
  4. (D)Ca2+Ca^{2+}Ca2+

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
The IUPAC name of K3[Co(C2O4)3]K_3[Co(C_2O_4)_3]K3​[Co(C2​O4​)3​] is:
  1. (A)Potassium trioxalatocobaltate(III)
  2. (B)Potassium trisoxalato cobalt(III)
  3. (C)Potassium trisoxalato cobaltate(III)
  4. (D)Potassium trioxalatocobalt(III)

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
Match List I (Natural Amino acid) with List II (One Letter Code). Choose the correct answer from the options given below:
List I (Natural Amino acid)List II (One Letter Code)
A.ArginineI.D
B.Aspartic acidII.N
C.AsparagineIII.A
D.AlanineIV.R
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-I, B-III, C-IV, D-II
  3. (C)A-III, B-I, C-II, D-IV
  4. (D)A-IV, B-I, C-II, D-III

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Element not present in Nessler's reagent is:
  1. (A)Hg
  2. (B)I
  3. (C)K
  4. (D)N

Correct answer: (D)

Step-by-step solution →
Q35·ChemistrySingle correct
Structure of BeCl2BeCl_2BeCl2​ in solid state, vapour phase and at very high temperature respectively are:
  1. (A)Dimeric, Polymeric, Monomeric
  2. (B)Polymeric, Dimeric, Monomeric
  3. (C)Monomeric, Dimeric, Polymeric
  4. (D)Polymeric, Monomeric, Dimeric

Correct answer: (D)

Step-by-step solution →
Q36·Chemistry·Electronic Effects and StabilitySingle correct
The strongest acid from the following is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
Group-13 elements react with O2O_2O2​ in amorphous form to form oxides of type M2O3M_2O_3M2​O3​ (MMM = element). Which among the following is the most basic oxide?
  1. (A)Al2O3Al_2O_3Al2​O3​
  2. (B)Ga2O3Ga_2O_3Ga2​O3​
  3. (C)Tl2O3Tl_2O_3Tl2​O3​
  4. (D)B2O3B_2O_3B2​O3​

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Consider the following reaction that goes from A to B in three steps as shown below. Choose the correct option.
  1. (A)Number of intermediates: 3, Number of activated complexes: 2, Rate determining step: II
  2. (B)Number of intermediates: 2, Number of activated complexes: 3, Rate determining step: II
  3. (C)Number of intermediates: 2, Number of activated complexes: 3, Rate determining step: I
  4. (D)Number of intermediates: 2, Number of activated complexes: 3, Rate determining step: III

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: In the complex Ni(CO)4Ni(CO)_4Ni(CO)4​ and Fe(CO)5Fe(CO)_5Fe(CO)5​, the metals have zero oxidation state. Reason R: Low oxidation states are found when a complex has ligands capable of π\piπ-donor character in addition to the σ\sigmaσ-bonding. In the light of the above statements, choose the most appropriate answer from the option given below.
  1. (A)A is correct but R is not correct
  2. (B)A is not correct but R is correct
  3. (C)Both A and R are correct but R is NOT the correct explanation of A
  4. (D)Both A and R are correct and R is the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
During the reaction of permanganate with thiosulphate, the change in oxidation number of manganese occurs by value of 3. Identify which of the below medium will favour the reaction.
  1. (A)aqueous acidic
  2. (B)aqueous neutral
  3. (C)both aqueous acidic and neutral
  4. (D)both aqueous acidic and faintly alkaline

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Find out the major product from the following reaction
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
Formation of which complex, among the following, is not a confirmatory test of Pb2+Pb^{2+}Pb2+ ions
  1. (A)lead chromate
  2. (B)lead iodide
  3. (C)lead nitrate
  4. (D)lead sulphate

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
From the figure of column chromatography given below, identify incorrect statements. A. Compound 'c' is more polar than 'a' and 'b'. B. Compound 'a' spends least time on the column. C. Compound 'b' comes out of the column before 'c' and after 'a'. D. Compound 'a' spends more time in the column. Choose the correct answer from the options given below:
  1. (A)A, B and C only
  2. (B)B, C and D only
  3. (C)A, B and D only
  4. (D)B and D only

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
Given below are two statements: Statement-I: Morphine is a narcotic analgesic. It helps in relieving pain without producing sleep. Statement-II: Morphine and its derivatives are obtained from opium poppy. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are false
  3. (C)Both Statement I and Statement II are true
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
The volume of 0.02 M aqueous HBr required to neutralize 10.0 mL of 0.01 M aqueous Ba(OH)2Ba(OH)_2Ba(OH)2​ (Assume complete neutralization) is
  1. (A)2.5 mL
  2. (B)5.0 mL
  3. (C)10.0 mL
  4. (D)7.5 mL

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
The product, which is not obtained during the electrolysis of brine solution is
  1. (A)NaOH
  2. (B)Cl2Cl_2Cl2​
  3. (C)H2H_2H2​
  4. (D)HCl

Correct answer: (D)

Step-by-step solution →
Q47·ChemistrySingle correct
The group of chemicals used as pesticide is
  1. (A)Sodium chloride, DDT, PAN
  2. (B)Aldrin, Sodium chlorate, Sodium arsinite
  3. (C)DDT, Aldrin
  4. (D)Dieldrin, Sodium arsinite, Tetrachloroethene

Correct answer: (C)

Step-by-step solution →
Q48·Chemistry·Reaction MechanismSingle correct
In the following reaction, 'B' is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q49·ChemistrySingle correct
Which one of the following elements will remain as liquid inside pure boiling water?
  1. (A)Cs
  2. (B)Ga
  3. (C)Li
  4. (D)Br

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
If the radius of the first orbit of hydrogen atom is a0a_0a0​, then de Broglie's wavelength of electron in 3rd3^{rd}3rd orbit is
  1. (A)πa02\frac{\pi a_0}{2}2πa0​​
  2. (B)πa03\frac{\pi a_0}{3}3πa0​​
  3. (C)6πa06\pi a_06πa0​
  4. (D)3πa03\pi a_03πa0​

Correct answer: (C)

Step-by-step solution →
Q51·ChemistryNumerical
In an ice crystal, each water molecule is hydrogen bonded to ____ neighbouring molecules.

Correct answer: 4

Step-by-step solution →
Q52·ChemistryNumerical
The equilibrium composition for the reaction PCl3+Cl2⇌PCl5PCl_3 + Cl_2 \rightleftharpoons PCl_5PCl3​+Cl2​⇌PCl5​ at 298 K is given below. [PCl3]eq=0.2[PCl_3]_{eq} = 0.2[PCl3​]eq​=0.2 mol L−1L^{-1}L−1, [Cl2]eq=0.1[Cl_2]_{eq} = 0.1[Cl2​]eq​=0.1 mol L−1L^{-1}L−1, [PCl5]eq=0.40[PCl_5]_{eq} = 0.40[PCl5​]eq​=0.40 mol L−1L^{-1}L−1. If 0.2 mol of Cl2Cl_2Cl2​ is added at the same temperature, the equilibrium concentration of PCl5PCl_5PCl5​ is ____ ×10−2\times 10^{-2}×10−2 mol L−1L^{-1}L−1. (Given: KcK_cKc​ for the reaction at 298 K is 20)

Correct answer: 48

Step-by-step solution →
Q53·ChemistryNumerical
Consider the following pairs of solutions which will be isotonic at the same temperature. The number of pairs of solutions is/are ____. A. 1 M aq. NaCl and 2 M aq. Urea. B. 1 M aq. CaCl2CaCl_2CaCl2​ and 1.5 M aq. KCl. C. 1.5 M aq. AlCl3AlCl_3AlCl3​ and 2 M aq. Na2SO4Na_2SO_4Na2​SO4​. D. 2.5 M aq. KCl and 1 M aq. Al2(SO4)3Al_2(SO_4)_3Al2​(SO4​)3​.

Correct answer: 4

Step-by-step solution →
Q54·ChemistryNumerical
The standard reduction potentials at 298 K for the following half cells are given: NO3−+4H++3e−→NO(g)+2H2ONO_3^- + 4H^+ + 3e^- \rightarrow NO(g) + 2H_2ONO3−​+4H++3e−→NO(g)+2H2​O, E0=0.97E^0 = 0.97E0=0.97 V; V2+(aq)+2e−→VV^{2+}(aq) + 2e^- \rightarrow VV2+(aq)+2e−→V, E0=−1.19E^0 = -1.19E0=−1.19 V; Fe3+(aq)+3e−→FeFe^{3+}(aq) + 3e^- \rightarrow FeFe3+(aq)+3e−→Fe, E0=−0.04E^0 = -0.04E0=−0.04 V; Ag+(aq)+e−→Ag(s)Ag^+(aq) + e^- \rightarrow Ag(s)Ag+(aq)+e−→Ag(s), E0=0.80E^0 = 0.80E0=0.80 V; Au3+(aq)+3e−→Au(s)Au^{3+}(aq) + 3e^- \rightarrow Au(s)Au3+(aq)+3e−→Au(s), E0=1.40E^0 = 1.40E0=1.40 V. The number of metal(s) which will be oxidized by NO3−NO_3^-NO3−​ in aqueous solution is ____.

Correct answer: 3

Step-by-step solution →
Q55·ChemistryNumerical
The number of colloidal systems from the following, which will have 'liquid' as the dispersion medium, is ____. Gem stones, paints, smoke, cheese, milk, hair cream, insecticide sprays, froth, soap lather.

Correct answer: 5

Step-by-step solution →
Q56·ChemistryNumerical
The number of species having a square planar shape from the following is ____. XeF4XeF_4XeF4​, SF4SF_4SF4​, SiF4SiF_4SiF4​, BF4−BF_4^-BF4−​, BrF4−BrF_4^-BrF4−​, [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}[Cu(NH3​)4​]2+, [FeCl4]2−[FeCl_4]^{2-}[FeCl4​]2−, [PtCl4]2−[PtCl_4]^{2-}[PtCl4​]2−

Correct answer: 4

Step-by-step solution →
Q57·ChemistryNumerical
Consider the following data: Heat of combustion of H2(g)=−241.8H_2(g) = -241.8H2​(g)=−241.8 kJ mol−1^{-1}−1; Heat of combustion of C(s)=−393.5C(s) = -393.5C(s)=−393.5 kJ mol−1^{-1}−1; Heat of combustion of C2H5OH(l)=−1234.7C_2H_5OH(l) = -1234.7C2​H5​OH(l)=−1234.7 kJ mol−1^{-1}−1. The heat of formation of C2H5OH(l)C_2H_5OH(l)C2​H5​OH(l) is (−)(-)(−) ____ kJ mol−1^{-1}−1 (Nearest integer).

Correct answer: 278

Step-by-step solution →
Q58·ChemistryNumerical
Among the following, the number of compounds which will give positive iodoform reaction is ____. (a) 1-Phenylbutan-2-one (b) 2-Methylbutan-2-ol (c) 3-Methylbutan-2-ol (d) 1-Phenylethanol (e) 3,3-dimethylbutan-2-ol (f) 1-Phenylpropan-2-ol

Correct answer: 4

Step-by-step solution →
Q59·ChemistryNumerical
Number of isomeric aromatic amines with molecular formula C8H11NC_8H_{11}NC8​H11​N, which can be synthesized by Gabriel Phthalimide synthesis is ____.

Correct answer: 5

Step-by-step solution →
Q60·ChemistryNumerical
Number of crystal systems from the following where body centred unit cell can be found, is ____. Cubic, orthorhombic, tetragonal, hexagonal, rhombohedral, monoclinic, triclinic.

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 6 April 2023 Shift 2

Q61·MathematicsSingle correct
Three dice are rolled. If the probability of getting different numbers on the three dice is pq\frac{p}{q}qp​, where ppp and qqq are co-prime, then q−pq-pq−p is equal to
  1. (A)4
  2. (B)3
  3. (C)1
  4. (D)2

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Among the statements: (S1):20232022−19992022(S1):2023^{2022}-1999^{2022}(S1):20232022−19992022 is divisible by 8. (S2):13(13)n−11n−13(S2):13(13)^n-11n-13(S2):13(13)n−11n−13 is divisible by 144 for infinitely many n∈Nn\in \mathbb{N}n∈N.
  1. (A)both (S1) and (S2) are incorrect
  2. (B)only (S2) is correct
  3. (C)both (S1) and (S2) are correct
  4. (D)only (S1) is correct

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
lim⁡n→∞{(212−213)(212−215)⋯(212−212n+1)}\lim_{n\to\infty}\left\{\left(2^{\frac{1}{2}}-2^{\frac{1}{3}}\right)\left(2^{\frac{1}{2}}-2^{\frac{1}{5}}\right)\cdots\left(2^{\frac{1}{2}}-2^{\frac{1}{2n+1}}\right)\right\}limn→∞​{(221​−231​)(221​−251​)⋯(221​−22n+11​)} is equal to
  1. (A)12\frac{1}{\sqrt{2}}2​1​
  2. (B)1
  3. (C)2\sqrt{2}2​
  4. (D)0

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
Let a≠ba\neq ba=b be two non-zero real numbers. Then the number of elements in the set X={z∈C:Re⁡(az2+bz)=a and Re⁡(bz2+az)=b}X=\{z\in \mathbb{C}:\operatorname{Re}(az^2+bz)=a \text{ and } \operatorname{Re}(bz^2+az)=b\}X={z∈C:Re(az2+bz)=a and Re(bz2+az)=b} is equal to
  1. (A)1
  2. (B)3
  3. (C)0
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let the sets AAA and BBB denote the domain and range respectively of the function f(x)=1⌈x⌉−xf(x)=\frac{1}{\sqrt{\lceil x\rceil-x}}f(x)=⌈x⌉−x​1​, where ⌈x⌉\lceil x\rceil⌈x⌉ denotes the smallest integer greater than or equal to xxx. Then among the statements (S1): A∩B=(1,∞)−NA\cap B=(1,\infty)-\mathbb{N}A∩B=(1,∞)−N and (S2): A∪B=(1,∞)A\cup B=(1,\infty)A∪B=(1,∞)
  1. (A)only (S1) is true
  2. (B)both (S1) and (S2) are true
  3. (C)neither (S1) nor (S2) is true
  4. (D)only (S2) is true

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
If the solution curve f(x,y)=0f(x, y) = 0f(x,y)=0 of the differential equation (1+log⁡ex)dxdy−xlog⁡ex=ey(1+\log_e x)\frac{dx}{dy}-x\log_e x=e^y(1+loge​x)dydx​−xloge​x=ey, x>0x>0x>0, passes through the points (1,0)(1,0)(1,0) and (α,2)(\alpha,2)(α,2) then αα\alpha^\alphaαα is equal to
  1. (A)e2e2e^{2e^{\sqrt{2}}}e2e2​
  2. (B)e2e2e^{\sqrt{2}e^2}e2​e2
  3. (C)ee2e^{e^2}ee2
  4. (D)e2e2e^{2e^2}e2e2

Correct answer: (D)

Step-by-step solution →
Q67·MathematicsSingle correct
The sum of all values of α\alphaα, for which the points whose position vectors i^−2j^+3k^\hat{i}-2\hat{j}+3\hat{k}i^−2j^​+3k^, 2i^−3j^+4k^2\hat{i}-3\hat{j}+4\hat{k}2i^−3j^​+4k^, (α+1)i^+2k^(\alpha+1)\hat{i}+2\hat{k}(α+1)i^+2k^ and 9i^+(α−8)j^+6k^9\hat{i}+(\alpha-8)\hat{j}+6\hat{k}9i^+(α−8)j^​+6k^ are coplanar, is equal to
  1. (A)6
  2. (B)4
  3. (C)−2-2−2
  4. (D)2

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
For the system of equations x+y+z=6x+y+z=6x+y+z=6, x+2y+αz=10x+2y+\alpha z=10x+2y+αz=10, x+3y+5z=βx+3y+5z=\betax+3y+5z=β, which one of the following is NOT true?
  1. (A)System has a unique solution for α=3,β≠14\alpha=3,\beta\neq 14α=3,β=14.
  2. (B)System has no solution for α=3,β=24\alpha=3,\beta=24α=3,β=24.
  3. (C)System has a unique solution for α=−3,β=14\alpha=-3,\beta=14α=−3,β=14.
  4. (D)System has infinitely many solutions for α=3,β=14\alpha=3,\beta=14α=3,β=14.

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
The area bounded by the curves y=∣x−1∣+∣x−2∣y=|x-1|+|x-2|y=∣x−1∣+∣x−2∣ and y=3y=3y=3 is equal to
  1. (A)3
  2. (B)4
  3. (C)5
  4. (D)6

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
Let PPP be a square matrix such that P2=I−PP^2=I-PP2=I−P. For α,β,γ,δ∈N\alpha,\beta,\gamma,\delta\in \mathbb{N}α,β,γ,δ∈N, if Pα+Pβ=γI−29PP^\alpha+P^\beta=\gamma I-29PPα+Pβ=γI−29P and Pα−Pβ=δI−13PP^\alpha-P^\beta=\delta I-13PPα−Pβ=δI−13P, then α+β+γ−δ\alpha+\beta+\gamma-\deltaα+β+γ−δ is equal to
  1. (A)18
  2. (B)40
  3. (C)24
  4. (D)22

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correct
All the letters of the word PUBLIC are written in all possible orders and these words are written as in a dictionary with serial numbers. Then the serial number of the word PUBLIC is
  1. (A)580
  2. (B)582
  3. (C)578
  4. (D)576

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
Let the line LLL pass through the point (0,1,2)(0,1,2)(0,1,2), intersect the line x−12=y−23=z−34\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}2x−1​=3y−2​=4z−3​ and be parallel to the plane 2x+y−3z=42x+y-3z=42x+y−3z=4. Then the distance of the point P(1,−9,2)P(1,-9,2)P(1,−9,2) from the line LLL is
  1. (A)9
  2. (B)54\sqrt{54}54​
  3. (C)69\sqrt{69}69​
  4. (D)74\sqrt{74}74​

Correct answer: (D)

Step-by-step solution →
Q73·MathematicsSingle correct
A plane PPP contains the line of intersection of the plane r⃗⋅(i^+j^+k^)=6\vec{r}\cdot(\hat{i}+\hat{j}+\hat{k})=6r⋅(i^+j^​+k^)=6 and r⃗⋅(2i^+3j^+4k^)=−5\vec{r}\cdot(2\hat{i}+3\hat{j}+4\hat{k})=-5r⋅(2i^+3j^​+4k^)=−5. If PPP passes through the point (0,2,−2)(0,2,-2)(0,2,−2), then the square of distance of the point (12,12,18)(12,12,18)(12,12,18) from the plane PPP is
  1. (A)620
  2. (B)156
  3. (C)310
  4. (D)144

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
Let f(x)f(x)f(x) be a function satisfying f(x)+f(π−x)=π2f(x)+f(\pi-x)=\pi^2f(x)+f(π−x)=π2, ∀x∈R\forall x\in \mathbb{R}∀x∈R. Then ∫0πf(x)sin⁡x dx\int_0^\pi f(x)\sin x\,dx∫0π​f(x)sinxdx is equal to
  1. (A)π24\frac{\pi^2}{4}4π2​
  2. (B)π22\frac{\pi^2}{2}2π2​
  3. (C)2π22\pi^22π2
  4. (D)π2\pi^2π2

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsSingle correct
If the coefficients of x7x^7x7 in (ax2+12bx)11\left(ax^2+\frac{1}{2bx}\right)^{11}(ax2+2bx1​)11 and x−7x^{-7}x−7 in (ax−13bx2)11\left(ax-\frac{1}{3bx^2}\right)^{11}(ax−3bx21​)11 are equal, then
  1. (A)64ab=24364ab=24364ab=243
  2. (B)729ab=32729ab=32729ab=32
  3. (C)243ab=64243ab=64243ab=64
  4. (D)32ab=72932ab=72932ab=729

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Among the statements: (S1): (p⇒q)∨(∼p∧q)(p\Rightarrow q)\lor(\sim p\land q)(p⇒q)∨(∼p∧q) is a tautology (S2): (q⇒p)⇒(∼p∧q)(q\Rightarrow p)\Rightarrow(\sim p\land q)(q⇒p)⇒(∼p∧q) is a contradiction
  1. (A)neither (S1) nor (S2) is True
  2. (B)only (S1) is True
  3. (C)only (S2) is True
  4. (D)both (S1) and (S2) are True

Correct answer: (A)

Step-by-step solution →
Q77·MathematicsSingle correct
If the tangents at the points PPP and QQQ on the circle x2+y2−2x+y=5x^2+y^2-2x+y=5x2+y2−2x+y=5 meet at the point R(94,−24)R\left(\frac{9}{4},-\frac{2}{4}\right)R(49​,−42​), then the area of the triangle PQRPQRPQR is
  1. (A)134\frac{13}{4}413​
  2. (B)138\frac{13}{8}813​
  3. (C)54\frac{5}{4}45​
  4. (D)58\frac{5}{8}85​

Correct answer: (D)

Step-by-step solution →
Q78·MathematicsSingle correct
Let the vectors a⃗,b⃗,c⃗\vec{a},\vec{b},\vec{c}a,b,c represent three coterminous edges of a parallelepiped of volume VVV. Then the volume of the parallelepiped, whose coterminous edges are represented by a⃗, b⃗+c⃗\vec{a},\ \vec{b}+\vec{c}a, b+c and a⃗+2b⃗+3c⃗\vec{a}+2\vec{b}+3\vec{c}a+2b+3c is equal to
  1. (A)3V
  2. (B)6V
  3. (C)2V
  4. (D)V

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
If gcd⁡(m,n)=1\gcd(m,n)=1gcd(m,n)=1 and 12−22+32−42+⋯+(2021)2−(2022)2+(2023)2=1012 m2n1^2-2^2+3^2-4^2+\cdots+(2021)^2-(2022)^2+(2023)^2=1012\,m^2n12−22+32−42+⋯+(2021)2−(2022)2+(2023)2=1012m2n then m2−n2m^2-n^2m2−n2 is equal to
  1. (A)240
  2. (B)220
  3. (C)210
  4. (D)180

Correct answer: (D)

Step-by-step solution →
Q80·MathematicsSingle correct
In a group of 100 persons 75 speak English and 40 speak Hindi. Each person speaks at least one of the two languages. If the number of persons, who speak only English is aaa and the number of persons who speak only Hindi is bbb, then the eccentricity of the ellipse 25(x2b2+y2a2)=125\left(\frac{x^2}{b^2}+\frac{y^2}{a^2}\right)=125(b2x2​+a2y2​)=1 is equal to
  1. (A)31512\frac{3\sqrt{15}}{12}12315​​
  2. (B)11712\frac{\sqrt{117}}{12}12117​​
  3. (C)11912\frac{\sqrt{119}}{12}12119​​
  4. (D)12912\frac{\sqrt{129}}{12}12129​​

Correct answer: (C)

Step-by-step solution →
Q81·MathematicsNumerical
Let f(x)=x(1+xn)1nf(x)=\frac{x}{\left(1+x^n\right)^{\frac{1}{n}}}f(x)=(1+xn)n1​x​, x∈R−{−1}x\in \mathbb{R}-\{-1\}x∈R−{−1}, n∈Nn\in \mathbb{N}n∈N, n>2n>2n>2. If fn(x)=(f∘f∘⋯∘f⏟n times)(x)f^n(x)=(\underbrace{f\circ f\circ \cdots \circ f}_{n\text{ times}})(x)fn(x)=(n timesf∘f∘⋯∘f​​)(x), then lim⁡n→∞∫xn−2(fn(x))dx\lim_{n\to\infty}\int x^{n-2}\left(f^n(x)\right)dxlimn→∞​∫xn−2(fn(x))dx is equal to

Correct answer: 0

Step-by-step solution →
Q82·MathematicsNumerical
The value of tan⁡9∘−tan⁡27∘−tan⁡63∘+tan⁡81∘\tan 9^\circ-\tan 27^\circ-\tan 63^\circ+\tan 81^\circtan9∘−tan27∘−tan63∘+tan81∘ is

Correct answer: 4

Step-by-step solution →
Q83·MathematicsNumerical
If the lines x−12=2−y−3=z−3α\frac{x-1}{2}=\frac{2-y}{-3}=\frac{z-3}{\alpha}2x−1​=−32−y​=αz−3​ and x−45=y−12=zβ\frac{x-4}{5}=\frac{y-1}{2}=\frac{z}{\beta}5x−4​=2y−1​=βz​ intersect, then the magnitude of the minimum value of 8αβ8\alpha\beta8αβ is

Correct answer: 18

Step-by-step solution →
Q84·MathematicsNumerical
If (20)19+2(21)(20)18+3(21)2(20)17+⋯+20(21)19=k(20)18(20)^{19}+2(21)(20)^{18}+3(21)^2(20)^{17}+\cdots+20(21)^{19}=k(20)^{18}(20)19+2(21)(20)18+3(21)2(20)17+⋯+20(21)19=k(20)18 then kkk is equal to

Correct answer: 400

Step-by-step solution →
Q85·MathematicsNumerical
The number of 4-letter words, with or without meaning, each consisting of 2 vowels and 2 consonants, which can be formed from the letters of the word UNIVERSE without repetition is

Correct answer: 432

Step-by-step solution →
Q86·MathematicsNumerical
The number of points, where the curve y=x5−20x3+50x+2y=x^5-20x^3+50x+2y=x5−20x3+50x+2 crosses the x-axis, is

Correct answer: 5

Step-by-step solution →
Q87·MathematicsNumerical
For α,β,z∈C\alpha,\beta,z\in \mathbb{C}α,β,z∈C and λ>1\lambda>1λ>1, if λ−1\sqrt{\lambda-1}λ−1​ is the radius of the circle ∣z−α∣2+∣z−β∣2=2λ|z-\alpha|^2+|z-\beta|^2=2\lambda∣z−α∣2+∣z−β∣2=2λ, then ∣α−β∣|\alpha-\beta|∣α−β∣ is equal to

Correct answer: 2

Step-by-step solution →
Q88·MathematicsNumerical
Let a curve y=f(x)y=f(x)y=f(x), x∈(0,∞)x\in(0,\infty)x∈(0,∞) pass through the points P(1,32)P\left(1,\frac{3}{2}\right)P(1,23​) and Q(a,12)Q\left(a,\frac{1}{2}\right)Q(a,21​). If the tangent at any point R(b,f(b))R(b,f(b))R(b,f(b)) to the given curve cuts the y-axis at the point S(0,c)S(0,c)S(0,c) such that bc=3bc=3bc=3, then (PQ)2(PQ)^2(PQ)2 is equal to

Correct answer: 5

Step-by-step solution →
Q89·MathematicsNumerical
Let the eccentricity of an ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1a2x2​+b2y2​=1 be reciprocal to that of the hyperbola 2x2−2y2=12x^2-2y^2=12x2−2y2=1. If the ellipse intersects the hyperbola at right angles, then square of length of the latus-rectum of the ellipse is

Correct answer: 2

Step-by-step solution →
Q90·MathematicsNumerical
If the mean and variance of the frequency distribution xi=2,4,6,8,10,12,14,16x_i = 2,4,6,8,10,12,14,16xi​=2,4,6,8,10,12,14,16 with frequencies fi=4,4,α,15,8,β,4,5f_i = 4,4,\alpha,15,8,\beta,4,5fi​=4,4,α,15,8,β,4,5 are 9 and 15.08 respectively, then the value of α2+β2−αβ\alpha^2+\beta^2-\alpha\betaα2+β2−αβ is

Correct answer: 25

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Statistics 118/186
  • Ellipse 103/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Chemistry in Everyday Life 60/186
  • Reaction Mechanism 29/186
← 6 Apr Shift 1 2023All papers8 Apr Shift 1 2023 →

Attempt this paper under exam timing.

Take the 6 April 2023 Shift 2 paper as a timed mock and Jarvis marks it, then tells you which errors were conceptual gaps, which were silly mistakes, and which pattern you have now repeated. Step-by-step solutions for every question included.

Attempt this paper freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS