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JEE Main 8 April 2023 Shift 1 Question Paper with Answers

8 April 2023 · April session · 89 questions

89 of the 90 questions from the JEE Main 8 April 2023 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
29
Mathematics
30

Physics — JEE Main 8 April 2023 Shift 1

Q1·Physics·Magnetic Field of CurrentSingle correct
A charge particle moving in magnetic field BBB, has the components of velocity along BBB as well as perpendicular to BBB. The path of the charge particle will be
  1. (A)helical path with the axis perpendicular to the direction of magnetic field BBB
  2. (B)straight along the direction of magnetic field BBB
  3. (C)helical path with the axis along magnetic field BBB
  4. (D)circular path

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
Two projectiles A and B are thrown with initial velocities of 404040 m/s and 606060 m/s at angles 30∘30^{\circ}30∘ and 60∘60^{\circ}60∘ with the horizontal respectively. The ratio of their ranges respectively is (g=10(g = 10(g=10 m/s2)^{2})2)
  1. (A)3:2\sqrt{3} : 23​:2
  2. (B)2:32 : \sqrt{3}2:3​
  3. (C)1:11 : 11:1
  4. (D)4:94 : 94:9

Correct answer: (D)

Step-by-step solution →
Q3·Physics·Magnetic Field of CurrentSingle correct
Certain galvanometers have a fixed core made of non magnetic metallic material. The function of this metallic material is
  1. (A)to oscillate the coil in magnetic field for longer period of time
  2. (B)to bring the coil to rest quickly
  3. (C)to produce large deflecting torque on the coil
  4. (D)to make the magnetic field radial

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A TV transmitting antenna is 989898 m high and the receiving antenna is at the ground level. If the radius of the earth is 640064006400 km, the surface area covered by the transmitting antenna is approximately:
  1. (A)124012401240 km2^{2}2
  2. (B)394239423942 km2^{2}2
  3. (C)486848684868 km2^{2}2
  4. (D)154915491549 km2^{2}2

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
In a reflecting telescope, a secondary mirror is used to:
  1. (A)reduce the problem of mechanical support
  2. (B)remove spherical aberration
  3. (C)make chromatic aberration zero
  4. (D)move the eyepiece outside the telescopic tube

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
Given below are two statements: Statement I: If heat is added to a system, its temperature must increase. Statement II: If positive work is done by a system in a thermodynamic process, its volume must increase. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
The weight of a body on the earth is 400400400 N. Then weight of the body when taken to a depth half of the radius of the earth will be:
  1. (A)Zero
  2. (B)300300300 N
  3. (C)100100100 N
  4. (D)200200200 N

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
An aluminium rod with Young's modulus Y=7.0×1010Y = 7.0 \times 10^{10}Y=7.0×1010 N/m2^{2}2 undergoes elastic strain of 0.04%0.04\%0.04%. The energy per unit volume stored in the rod in SI unit is:
  1. (A)560056005600
  2. (B)840084008400
  3. (C)280028002800
  4. (D)112001120011200

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
At any instant the velocity of a particle of mass 500500500 g is (2t i^+3t2 j^)(2t\,\hat{i} + 3t^{2}\,\hat{j})(2ti^+3t2j^​) ms−1^{-1}−1. If the force acting on the particle at t=1t = 1t=1 s is (i^+xj^)(\hat{i} + x\hat{j})(i^+xj^​) N. Then the value of xxx will be:
  1. (A)333
  2. (B)444
  3. (C)666
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
For the logic circuit shown, the output waveform at Y is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
For a nucleus ZAX^{A}_{Z}XZA​X having mass number A and atomic number Z: A. The surface energy per nucleon (bs)=a1A2/3(b_{s}) = a_{1}A^{2/3}(bs​)=a1​A2/3. B. The Coulomb contribution to the binding energy bc=−a2Z(Z−1)A4/3b_{c} = -a_{2}\dfrac{Z(Z-1)}{A^{4/3}}bc​=−a2​A4/3Z(Z−1)​. C. The volume energy bv=a3Ab_{v} = a_{3}Abv​=a3​A. D. Decrease in the binding energy is proportional to surface area. E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons, (a1,a2(a_{1}, a_{2}(a1​,a2​ and a3a_{3}a3​ are constants). Choose the most appropriate answer from the options given below:
  1. (A)C, D only
  2. (B)B, C, E only
  3. (C)A, B, C, D only
  4. (D)B, C only

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Given below are two statements: Statement I: If E be the total energy of a satellite moving around the earth, then its potential energy will be E2\dfrac{E}{2}2E​. Statement II: The kinetic energy of a satellite revolving in an orbit is equal to the half the magnitude of total energy E. In the light of the above statements, choose the most appropriate answer from the options given below
  1. (A)Both Statement I and Statement II are correct
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Statement I is incorrect but Statement II is correct
  4. (D)Statement I is correct but Statement II is incorrect

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
Dimension of 1μ0 ϵ0\dfrac{1}{\mu_{0}\,\epsilon_{0}}μ0​ϵ0​1​ should be equal to
  1. (A)T2/L2T^{2}/L^{2}T2/L2
  2. (B)L/TL/TL/T
  3. (C)L2/T2L^{2}/T^{2}L2/T2
  4. (D)T/LT/LT/L

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
In this figure the resistance of the coil of galvanometer G is 2 Ω2\,\Omega2Ω. The emf of the cell is 444 V. The ratio of potential difference across C1C_{1}C1​ and C2C_{2}C2​ is:
  1. (A)111
  2. (B)45\dfrac{4}{5}54​
  3. (C)34\dfrac{3}{4}43​
  4. (D)54\dfrac{5}{4}45​

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Graphical variation of electric field due to a uniformly charged insulating solid sphere of radius R, with distance r from the centre O is represented by:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
Two forces having magnitude AAA and A2\frac{A}{2}2A​ are perpendicular to each other. The magnitude of their resultant is
  1. (A)5A4\frac{\sqrt{5}A}{4}45​A​
  2. (B)5A2\frac{5A}{2}25A​
  3. (C)5A22\frac{\sqrt{5}A^{2}}{2}25​A2​
  4. (D)5A2\frac{\sqrt{5}A}{2}25​A​

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
The engine of a train moving with speed 10 ms−110\,\text{ms}^{-1}10ms−1 towards a platform sounds a whistle at frequency 400 Hz400\,\text{Hz}400Hz. The frequency heard by a passenger inside the train is (neglect air speed. Speed of sound in air 330 ms−1330\,\text{ms}^{-1}330ms−1)
  1. (A)200 Hz200\,\text{Hz}200Hz
  2. (B)400 Hz400\,\text{Hz}400Hz
  3. (C)412 Hz412\,\text{Hz}412Hz
  4. (D)388 Hz388\,\text{Hz}388Hz

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
An air bubble of volume 1 cm31\,\text{cm}^{3}1cm3 rises from the bottom of a lake 40 m40\,\text{m}40m deep to the surface at a temperature of 12∘C12^\circ\text{C}12∘C. The atmospheric pressure is 1×105 Pa1\times10^{5}\,\text{Pa}1×105Pa, the density of water is 1000 kg/m31000\,\text{kg/m}^{3}1000kg/m3 and g=10 m/s2g=10\,\text{m/s}^{2}g=10m/s2. There is no difference of the temperature of water at the depth of 40 m40\,\text{m}40m and on the surface. The volume of air bubble when it reaches the surface will be
  1. (A)5 cm35\,\text{cm}^{3}5cm3
  2. (B)2 cm32\,\text{cm}^{3}2cm3
  3. (C)4 cm34\,\text{cm}^{3}4cm3
  4. (D)3 cm33\,\text{cm}^{3}3cm3

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
A cylindrical wire of mass (0.4±0.01) g(0.4\pm0.01)\,\text{g}(0.4±0.01)g has length (8±0.04) cm(8\pm0.04)\,\text{cm}(8±0.04)cm and radius (6±0.03) mm(6\pm0.03)\,\text{mm}(6±0.03)mm. The maximum error in its density will be
  1. (A)1%1\%1%
  2. (B)3.5%3.5\%3.5%
  3. (C)4%4\%4%
  4. (D)5%5\%5%

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
Proton (P) and electron (e) will have same de-Broglie wavelength when the ratio of their momentum is (assume, mp=1849 mem_{p}=1849\,m_{e}mp​=1849me​)
  1. (A)1:431:431:43
  2. (B)43:143:143:1
  3. (C)1:18491:18491:1849
  4. (D)1:11:11:1

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
An electric dipole of dipole moment is 6.0×10−6 Cm6.0\times10^{-6}\,\text{Cm}6.0×10−6Cm placed in a uniform electric field of 1.5×103 NC−11.5\times10^{3}\,\text{NC}^{-1}1.5×103NC−1 in such a way that dipole moment is along electric field. The work done in rotating dipole by 180∘180^\circ180∘ in this field will be ______ mJ\text{mJ}mJ

Correct answer: 18

Step-by-step solution →
Q22·PhysicsNumerical
Two vertical parallel mirrors A and B are separated by 10 cm10\,\text{cm}10cm. A point object O is placed at a distance of 2 cm2\,\text{cm}2cm from mirror A. The distance of the second nearest image behind mirror A from the mirror A is ______ cm\text{cm}cm

Correct answer: 18

Step-by-step solution →
Q23·PhysicsNumerical
The momentum of a body is increased by 50%50\%50%. The percentage increase in the kinetic energy of the body is ______ %\%%

Correct answer: 125

Step-by-step solution →
Q24·PhysicsNumerical
The moment of inertia of semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1xMR2\frac{1}{x}MR^{2}x1​MR2, where RRR is the radius and MMM is the mass of semicircular ring. The value of xxx will be

Correct answer: 1

Step-by-step solution →
Q25·PhysicsNumerical
An organ pipe 40 cm40\,\text{cm}40cm long is open at both ends. The speed of sound in air is 360 ms−1360\,\text{ms}^{-1}360ms−1. The frequency of the second harmonic is ______ Hz\text{Hz}Hz

Correct answer: 900

Step-by-step solution →
Q26·PhysicsNumerical
An air bubble of diameter 6 mm6\,\text{mm}6mm rises steadily through a solution of density 1750 kg/m31750\,\text{kg/m}^{3}1750kg/m3 at the rate of 0.35 cm/s0.35\,\text{cm/s}0.35cm/s. The co-efficient of viscosity of the solution (neglect density of air) is ______ Pas\text{Pas}Pas (given, g=10 ms−2g=10\,\text{ms}^{-2}g=10ms−2)

Correct answer: 10

Step-by-step solution →
Q27·PhysicsNumerical
An oscillating LC circuit consists of a 75 mH75\,\text{mH}75mH inductor and a 1.2 μF1.2\,\mu\text{F}1.2μF capacitor. If the maximum charge to the capacitor is 2.7 μC2.7\,\mu\text{C}2.7μC. The maximum current in the circuit will be ______ mA\text{mA}mA.

Correct answer: 9

Step-by-step solution →
Q28·Physics·Magnetism and MatterNumerical
The magnetic intensity at the centre of a long current carrying solenoid is found to be 1.6×103 Am−11.6\times10^{3}\,\text{Am}^{-1}1.6×103Am−1. If the number of turns is 8 per cm, then the current flowing through the solenoid is ______ A\text{A}A.

Correct answer: 2

Step-by-step solution →
Q29·PhysicsNumerical
A current of 2 A2\,\text{A}2A flows through a wire of cross-sectional area 25.0 mm225.0\,\text{mm}^{2}25.0mm2. The number of free electrons in a cubic meter are 2.0×10282.0\times10^{28}2.0×1028. The drift velocity of the electrons is ______ ×10−6 ms−1\times10^{-6}\,\text{ms}^{-1}×10−6ms−1 (given, charge on electron =1.6×10−19 C=1.6\times10^{-19}\,\text{C}=1.6×10−19C)

Correct answer: 25

Step-by-step solution →
Q30·PhysicsNumerical
A nucleus with mass number 242 and binding energy per nucleon as 7.6 MeV7.6\,\text{MeV}7.6MeV breaks into fragment each with mass number 121. If each fragment nucleus has binding energy per nucleon as 8.1 MeV8.1\,\text{MeV}8.1MeV, the total gain in binding energy is ______ MeV\text{MeV}MeV

Correct answer: 121

Step-by-step solution →

Chemistry — JEE Main 8 April 2023 Shift 1

Q31·ChemistrySingle correct
2IO3−+xI−+12H+→6I2+6H2O2IO_3^- + xI^- + 12H^+ \rightarrow 6I_2 + 6H_2O2IO3−​+xI−+12H+→6I2​+6H2​O What is the value of x?
  1. (A)12
  2. (B)2
  3. (C)6
  4. (D)10

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Which of the following metals can be extracted through alkali leaching technique?
  1. (A)Cu
  2. (B)Sn
  3. (C)Pb
  4. (D)Au

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
Match List I with List II. Choose the correct answer from the options given below:
List IList II
A.SaccharinI.High potency sweetener
B.AspartameII.First artificial sweetening agent
C.AlitameIII.Stable at cooking temperature
D.SucraloseIV.Unstable at cooking temperature
  1. (A)A-II, B-III, C-IV, D-I
  2. (B)A-II, B-IV, C-III, D-I
  3. (C)A-IV, B-III, C-I, D-II
  4. (D)A-II, B-IV, C-I, D-III

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Which of the following represent the Freundlich adsorption isotherms? Choose the correct answer from the options given below:
  1. (A)B, C, D only
  2. (B)A, B, D only
  3. (C)A, B only
  4. (D)A, C, D only

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
Sulphur (S) containing amino acids from the following are: (a) isoleucine (b) cysteine (c) lysine (d) methionine (e) glutamic acid
  1. (A)a, d
  2. (B)b, d
  3. (C)b, c, e
  4. (D)a, b, c

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
The water gas on reacting with cobalt as a catalyst forms
  1. (A)Ethanol
  2. (B)Methanoic acid
  3. (C)Methanal
  4. (D)Methanol

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
The major product formed in the following reaction is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Which of the following complex is octahedral, diamagnetic and the most stable?
  1. (A)Na3[CoCl6]Na_3[CoCl_6]Na3​[CoCl6​]
  2. (B)[Ni(NH3)6]Cl2[Ni(NH_3)_6]Cl_2[Ni(NH3​)6​]Cl2​
  3. (C)K3[Co(CN)6]K_3[Co(CN)_6]K3​[Co(CN)6​]
  4. (D)[Co(H2O)6]Cl2[Co(H_2O)_6]Cl_2[Co(H2​O)6​]Cl2​

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
The reaction 12H2(g)+AgCl(s)⇌H+(aq)+Cl−(aq)+Ag(s)\frac{1}{2}H_2(g) + AgCl(s) \rightleftharpoons H^+(aq) + Cl^-(aq) + Ag(s)21​H2​(g)+AgCl(s)⇌H+(aq)+Cl−(aq)+Ag(s) occurs in which of the given galvanic cell.
  1. (A)Pt∣H2(g)∣KCl(soln)∣AgCl(s)∣AgPt | H_2(g) | KCl(sol^n) | AgCl(s) | AgPt∣H2​(g)∣KCl(soln)∣AgCl(s)∣Ag
  2. (B)Pt∣H2(g)∣HCl(soln)∣AgCl(s)∣AgPt | H_2(g) | HCl(sol^n) | AgCl(s) | AgPt∣H2​(g)∣HCl(soln)∣AgCl(s)∣Ag
  3. (C)Ag∣AgCl(s)∣KCl(soln)∣AgCl(s)∣AgAg | AgCl(s) | KCl(sol^n) | AgCl(s) | AgAg∣AgCl(s)∣KCl(soln)∣AgCl(s)∣Ag
  4. (D)Pt∣H2(g)∣HCl(soln)∣AgNO3(soln)∣AgPt | H_2(g) | HCl(sol^n) | AgNO_3(sol^n) | AgPt∣H2​(g)∣HCl(soln)∣AgNO3​(soln)∣Ag

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Match List-I (Reagents used) with List-II (Compound with functional group detected). Choose the correct answer from the options given below:
List-I (Reagents used)List-II (Compound with functional group detected)
A.Alkaline solution of copper sulphate and sodium citrateI.see figure
B.Neutral FeCl3FeCl_3FeCl3​ solutionII.see figure
C.Alkaline chloroform solutionIII.see figure
D.Potassium iodide and sodium hypochloriteIV.see figure
  1. (A)A-II, B-IV, C-III, D-I
  2. (B)A-IV, B-I, C-II, D-III
  3. (C)A-III, B-IV, C-I, D-II
  4. (D)A-III, B-IV, C-II, D-I

Correct answer: (D)

Step-by-step solution →
Q41·Chemistry·Alcohols and EthersSingle correct
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Butan-1-ol has higher boiling point than ethoxyethane. Reason R: Extensive hydrogen bonding leads to stronger association of molecules. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)A is true but R is false
  3. (C)Both A and R are true but R is NOT the correct explanation of A
  4. (D)A is false but R is true

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
In chromyl chloride, the number of d-electrons present on chromium is same as in (Given at. no. of Ti : 22, V : 23, Cr : 24, Mn : 25, Fe : 26)
  1. (A)Ti (III)
  2. (B)Fe (III)
  3. (C)V (IV)
  4. (D)Mn (VII)

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
What is the purpose of adding gypsum to cement?
  1. (A)To facilitate the hydration of cement
  2. (B)To speed up the process of setting
  3. (C)To slow down the process of setting
  4. (D)To give a hard mass

Correct answer: (C)

Step-by-step solution →
Q44·ChemistrySingle correct
The correct order of spin only magnetic moments for the following complex ions is
  1. (A)[Fe(CN)6]3−<[CoF6]3−<[MnBr4]2−<[Mn(CN)6]3−[Fe(CN)_6]^{3-} < [CoF_6]^{3-} < [MnBr_4]^{2-} < [Mn(CN)_6]^{3-}[Fe(CN)6​]3−<[CoF6​]3−<[MnBr4​]2−<[Mn(CN)6​]3−
  2. (B)[Fe(CN)6]3−<[Mn(CN)6]3−<[CoF6]3−<[MnBr4]2−[Fe(CN)_6]^{3-} < [Mn(CN)_6]^{3-} < [CoF_6]^{3-} < [MnBr_4]^{2-}[Fe(CN)6​]3−<[Mn(CN)6​]3−<[CoF6​]3−<[MnBr4​]2−
  3. (C)[MnBr4]2−<[CoF6]3−<[Fe(CN)6]3−<[Mn(CN)6]3−[MnBr_4]^{2-} < [CoF_6]^{3-} < [Fe(CN)_6]^{3-} < [Mn(CN)_6]^{3-}[MnBr4​]2−<[CoF6​]3−<[Fe(CN)6​]3−<[Mn(CN)6​]3−
  4. (D)[CoF6]3−<[MnBr4]2−<[Fe(CN)6]3−<[Mn(CN)6]3−[CoF_6]^{3-} < [MnBr_4]^{2-} < [Fe(CN)_6]^{3-} < [Mn(CN)_6]^{3-}[CoF6​]3−<[MnBr4​]2−<[Fe(CN)6​]3−<[Mn(CN)6​]3−

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
Which halogen is known to cause the reaction given below: 2Cu2++4X−→Cu2X2(s)+X22Cu^{2+} + 4X^- \rightarrow Cu_2X_2(s) + X_22Cu2++4X−→Cu2​X2​(s)+X2​
  1. (A)Only Iodine
  2. (B)Only Bromine
  3. (C)All halogens
  4. (D)Only Chlorine

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
Match List-I (Species) with List-II (Maximum allowed concentration in ppm in drinking water). Choose the correct answer:
List-I (Species)List-II (Maximum allowed concentration in ppm in drinking water)
A.F−F^-F−I.< 50 ppm
B.SO42−SO_4^{2-}SO42−​II.< 5 ppm
C.NO3−NO_3^-NO3−​IV.< 500 ppm
D.ZnIII.< 2 ppm
  1. (A)A-II, B-I, C-III, D-IV
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-I, B-II, C-III, D-IV
  4. (D)A-III, B-II, C-I, D-IV

Correct answer: (D)

Step-by-step solution →
Q47·ChemistrySingle correct
The correct order of electronegativity for given elements is:
  1. (A)C > P > At > Br
  2. (B)Br > P > At > C
  3. (C)P > Br > C > At
  4. (D)Br > C > At > P

Correct answer: (D)

Step-by-step solution →
Q48·ChemistrySingle correct
Benzenediazonium chloride is reacted with reagents in List-I to form products in List-II. Match List-I (Reagent) with List-II (Product). Choose the correct answer:
  1. (A)A-IV, B-III, C-II, D-I
  2. (B)A-I, B-III, C-IV, D-II
  3. (C)A-III, B-I, C-II, D-IV
  4. (D)A-III, B-I, C-IV, D-II

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
Given below are two statements: Statement I: Lithium and Magnesium do not form superoxide. Statement II: The ionic radius of Li+Li^+Li+ is larger than ionic radius of Mg2+Mg^{2+}Mg2+. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Both Statement I and Statement II are correct
  4. (D)Both Statement I and Statement II are incorrect

Correct answer: (C)

Step-by-step solution →
Q50·ChemistryNumerical
Molar mass of the hydrocarbon (X) which on ozonolysis consumes one mole of O3O_3O3​ per mole of (X) and gives one mole each of ethanal and propanone is _______ g mol−1mol^{-1}mol−1 (Molar mass of C : 12 g mol−1mol^{-1}mol−1, H : 1 g mol−1mol^{-1}mol−1)

Correct answer: 70

Step-by-step solution →
Q51·ChemistryNumerical
The number of following factors which affect the percent covalent character of the ionic bond is ____ (a) Polarising power of cation (b) Extent of distortion of anion (c) Polarisability of the anion (d) Polarising power of anion

Correct answer: 3

Step-by-step solution →
Q52·ChemistryNumerical
When a 60 W electric heater is immersed in a gas for 100s in a constant volume container with adiabatic walls, the temperature of the gas rises by 5 ∘C5\,^\circ C5∘C. The heat capacity of the given gas is ____ J K−1K^{-1}K−1 (Nearest integer)

Correct answer: 1200

Step-by-step solution →
Q53·ChemistryNumerical
The number of given statement/s which is/are correct is ____ (A) The stronger the temperature dependence of the rate constant, the higher is the activation energy. (B) If a reaction has zero activation energy, its rate is independent of temperature. (C) The stronger the temperature dependence of the rate constant, the smaller is the activation energy. (D) If there is no correlation between the temperature and the rate constant then it means that the reaction has negative activation energy.

Correct answer: 2

Step-by-step solution →
Q54·ChemistryNumerical
The vapour pressure vs. temperature curve for a solution solvent system is shown below. The boiling point of the solvent is ____ ∘C^\circ C∘C

Correct answer: 82

Step-by-step solution →
Q55·ChemistryNumerical
XeF4XeF_4XeF4​ reacts with SbF5SbF_5SbF5​ to form [XeFm]n+[SbFy]z−[XeF_m]^{n+}[SbF_y]^{z-}[XeFm​]n+[SbFy​]z−. m+n+y+z=m + n + y + z =m+n+y+z= ____

Correct answer: 11

Step-by-step solution →
Q56·ChemistryNumerical
0.5 g of an organic compound (X) with 60% carbon will produce ____ ×10−1\times 10^{-1}×10−1 g of CO2CO_2CO2​ on complete combustion.

Correct answer: 11

Step-by-step solution →
Q57·ChemistryNumerical
The titration curve of weak acid vs. strong base with phenolphthalein as indicator) is shown below. The Kphenolphthalein=4×10−10K_{phenolphthalein} = 4 \times 10^{-10}Kphenolphthalein​=4×10−10. Given: log⁡2=0.3\log 2 = 0.3log2=0.3. The number of following statements which is/are correct about phenolphthalein is ____ A. It can be used as an indicator for the titration of weak acid with weak base. B. It begins to change colour at pH=8.4pH = 8.4pH=8.4 C. It is a weak organic base D. It is colourless in acidic medium

Correct answer: 2

Step-by-step solution →
Q58·ChemistryNumerical
Three bulbs are filled with CH4CH_4CH4​, CO2CO_2CO2​ and Ne as shown in the picture. The bulbs are connected through pipes of zero volume. When the stopcocks are opened and the temperature is kept constant throughout, the pressure of the system is found to be ____ atm. (Nearest integer)

Correct answer: 3

Step-by-step solution →
Q59·ChemistryNumerical
The number of following statement/s which is/are incorrect is ____ (A) Line emission spectra are used to study the electronic structure (B) The emission spectra of atoms in the gas phase show a continuous spread of wavelength from red to violet (C) An absorption spectrum is like the photographic negative of an emission spectrum (D) The element helium was discovered in the sun by spectroscopic method

Correct answer: 1

Step-by-step solution →

Mathematics — JEE Main 8 April 2023 Shift 1

Q60·MathematicsSingle correct
Let I(x)=∫(x+1)x(1+xex)2 dx, x>0I(x)=\int \frac{(x+1)}{x(1+xe^{x})^{2}}\,dx,\ x>0I(x)=∫x(1+xex)2(x+1)​dx, x>0. If lim⁡x→∞I(x)=0\lim_{x\to\infty} I(x)=0limx→∞​I(x)=0, then I(1)I(1)I(1) is equal to
  1. (A)e+1e+2−log⁡e(e+1)\frac{e+1}{e+2}-\log_{e}(e+1)e+2e+1​−loge​(e+1)
  2. (B)e+1e+2+log⁡e(e+1)\frac{e+1}{e+2}+\log_{e}(e+1)e+2e+1​+loge​(e+1)
  3. (C)e+2e+1+log⁡e(e+1)\frac{e+2}{e+1}+\log_{e}(e+1)e+1e+2​+loge​(e+1)
  4. (D)e+2e+1−log⁡e(e+1)\frac{e+2}{e+1}-\log_{e}(e+1)e+1e+2​−loge​(e+1)

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
If the equation of the plane containing the line x+2y+3z−4=0=2x+y−z+5x+2y+3z-4=0=2x+y-z+5x+2y+3z−4=0=2x+y−z+5 and perpendicular to the plane r⃗=(i^−j^)+λ(i^+j^+k^)+μ(i^−2j^+3k^)\vec{r}=(\hat{i}-\hat{j})+\lambda(\hat{i}+\hat{j}+\hat{k})+\mu(\hat{i}-2\hat{j}+3\hat{k})r=(i^−j^​)+λ(i^+j^​+k^)+μ(i^−2j^​+3k^) is ax+by+cz=4ax+by+cz=4ax+by+cz=4, then (a−b+c)(a-b+c)(a−b+c) is equal to
  1. (A)20
  2. (B)24
  3. (C)22
  4. (D)18

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
Let RRR be the focus of the parabola y2=20xy^{2}=20xy2=20x and the line y=mx+cy=mx+cy=mx+c intersect the parabola at two points PPP and QQQ. Let the point G(10,10)G(10,10)G(10,10) be the centroid of the triangle PQRPQRPQR. If c−m=6c-m=6c−m=6, then (PQ)2(PQ)^{2}(PQ)2 is
  1. (A)325
  2. (B)317
  3. (C)296
  4. (D)346

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
Let C(α,β)C(\alpha,\beta)C(α,β) be the circumcenter of the triangle formed by the lines 4x+3y=694x+3y=694x+3y=69, 4y−3x=174y-3x=174y−3x=17 and x+7y=61x+7y=61x+7y=61. Then (α−β)2+α+β(\alpha-\beta)^{2}+\alpha+\beta(α−β)2+α+β is equal to
  1. (A)18
  2. (B)17
  3. (C)16
  4. (D)15

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Let P=[3212−1232]P=\begin{bmatrix}\frac{\sqrt{3}}{2} & \frac{1}{2}\\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{bmatrix}P=[23​​−21​​21​23​​​], A=[1101]A=\begin{bmatrix}1 & 1\\ 0 & 1\end{bmatrix}A=[10​11​] and Q=PAPTQ=PAP^{T}Q=PAPT. If PTQ2007P=[abcd]P^{T}Q^{2007}P=\begin{bmatrix}a & b\\ c & d\end{bmatrix}PTQ2007P=[ac​bd​], then 2a+b−3c−4d2a+b-3c-4d2a+b−3c−4d equal to
  1. (A)2007
  2. (B)2005
  3. (C)2006
  4. (D)2004

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let α,β,γ\alpha,\beta,\gammaα,β,γ be the three roots of the equation x3+bx+c=0x^{3}+bx+c=0x3+bx+c=0. If βγ=1=−α\beta\gamma=1=-\alphaβγ=1=−α, then b3+2c3−3α3−6β3−8γ3b^{3}+2c^{3}-3\alpha^{3}-6\beta^{3}-8\gamma^{3}b3+2c3−3α3−6β3−8γ3 is equal to
  1. (A)21
  2. (B)1698\frac{169}{8}8169​
  3. (C)19
  4. (D)1558\frac{155}{8}8155​

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
The number of ways, in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together, is
  1. (A)126(5!)2126(5!)^{2}126(5!)2
  2. (B)7(360)27(360)^{2}7(360)2
  3. (C)720
  4. (D)7(720)27(720)^{2}7(720)2

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
In a bolt factory, machines A, B and C manufacture respectively 20%, 30% and 50% of the total bolts. Of their output 3, 4 and 2 percent are respectively defective bolts. A bolt is drawn at random from the product. If the bolt drawn is found the defective, then the probability that it is manufactured by the machine C is
  1. (A)27\frac{2}{7}72​
  2. (B)928\frac{9}{28}289​
  3. (C)514\frac{5}{14}145​
  4. (D)37\frac{3}{7}73​

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
The number of arrangements of the letter of the word "INDEPENDENCE" in which all the vowels always occur together is
  1. (A)16800
  2. (B)14800
  3. (C)18000
  4. (D)33600

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
Let f(x)=sin⁡x+cos⁡x−2sin⁡x−cos⁡x, x∈[0,π]−{π4}f(x)=\frac{\sin x+\cos x-\sqrt{2}}{\sin x-\cos x},\ x\in[0,\pi]-\left\{\frac{\pi}{4}\right\}f(x)=sinx−cosxsinx+cosx−2​​, x∈[0,π]−{4π​}. Then f(7π12)f′′(7π12)f\left(\frac{7\pi}{12}\right)f''\left(\frac{7\pi}{12}\right)f(127π​)f′′(127π​) is equal to
  1. (A)−23\frac{-2}{3}3−2​
  2. (B)29\frac{2}{9}92​
  3. (C)−133-\frac{1}{3\sqrt{3}}−33​1​
  4. (D)−233\frac{-2}{3\sqrt{3}}33​−2​

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
If the points with vectors αi^+10j^+13k^\alpha\hat{i}+10\hat{j}+13\hat{k}αi^+10j^​+13k^, 6i^+11j^+11k^6\hat{i}+11\hat{j}+11\hat{k}6i^+11j^​+11k^, 92i^+βj^−8k^\frac{9}{2}\hat{i}+\beta\hat{j}-8\hat{k}29​i^+βj^​−8k^ are collinear, then (19α−6β)2(19\alpha-6\beta)^{2}(19α−6β)2 is equal to
  1. (A)36
  2. (B)16
  3. (C)25
  4. (D)49

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
If the coefficients of the three consecutive terms in the expansion of (1+x)n(1+x)^{n}(1+x)n are in the ratio 1:5:201:5:201:5:20, then the coefficient of the fourth term is
  1. (A)3654
  2. (B)1827
  3. (C)5481
  4. (D)2436

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
Let Sk=1+2+⋯+KKS_{k}=\frac{1+2+\dots+K}{K}Sk​=K1+2+⋯+K​ and ∑j=1nSj2=nA(Bn2+Cn+D)\sum_{j=1}^{n} S_{j}^{2}=\frac{n}{A}(Bn^{2}+Cn+D)∑j=1n​Sj2​=An​(Bn2+Cn+D), where A,B,C,D∈NA,B,C,D\in NA,B,C,D∈N and AAA has least value. Then
  1. (A)A+BA+BA+B is divisible by DDD
  2. (B)A+B=5(D−C)A+B=5(D-C)A+B=5(D−C)
  3. (C)A+C+DA+C+DA+C+D is not divisible by BBB
  4. (D)A+B+C+DA+B+C+DA+B+C+D is divisible by 5

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
Let A=[21012−10−12]A=\begin{bmatrix}2 & 1 & 0\\ 1 & 2 & -1\\ 0 & -1 & 2\end{bmatrix}A=​210​12−1​0−12​​. If ∣ adj(adj(adj 2A)) ∣=(16)n|\,\mathrm{adj}(\mathrm{adj}(\mathrm{adj}\,2A))\,|=(16)^{n}∣adj(adj(adj2A))∣=(16)n, then nnn is equal to
  1. (A)10
  2. (B)9
  3. (C)12
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
Negation of p⇒q⇒q⇒pp\Rightarrow q\Rightarrow q\Rightarrow pp⇒q⇒q⇒p is
  1. (A)(∼p)∨q(\sim p)\vee q(∼p)∨q
  2. (B)(∼q)∧p(\sim q)\wedge p(∼q)∧p
  3. (C)q∧(∼p)q\wedge(\sim p)q∧(∼p)
  4. (D)p∨(∼q)p\vee(\sim q)p∨(∼q)

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
The shortest distance between the lines x−44=y+25=z+33\frac{x-4}{4}=\frac{y+2}{5}=\frac{z+3}{3}4x−4​=5y+2​=3z+3​ and x−13=y−34=z−42\frac{x-1}{3}=\frac{y-3}{4}=\frac{z-4}{2}3x−1​=4y−3​=2z−4​ is
  1. (A)363\sqrt{6}36​
  2. (B)636\sqrt{3}63​
  3. (C)626\sqrt{2}62​
  4. (D)262\sqrt{6}26​

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
The area of the region {(x,y):x2≤y≤8−x2, y≤7}\{(x,y):x^{2}\le y\le 8-x^{2},\, y\le 7\}{(x,y):x2≤y≤8−x2,y≤7} is
  1. (A)21
  2. (B)18
  3. (C)24
  4. (D)20

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
Let the number of elements in sets AAA and BBB be five and two respectively. Then the number of subsets of A×BA\times BA×B each having at least 3 and at most 6 element is :
  1. (A)792
  2. (B)752
  3. (C)782
  4. (D)772

Correct answer: (A)

Step-by-step solution →
Q78·Mathematics·Limits and ContinuitySingle correct
lim⁡x→0((1−cos⁡2(3x)cos⁡3(4x))(sin⁡3(4x)(log⁡e(2x+1))5))\lim_{x\to 0}\left(\left(\frac{1-\cos^{2}(3x)}{\cos^{3}(4x)}\right)\left(\frac{\sin^{3}(4x)}{(\log_{e}(2x+1))^{5}}\right)\right)limx→0​((cos3(4x)1−cos2(3x)​)((loge​(2x+1))5sin3(4x)​)) is equal to
  1. (A)9
  2. (B)18
  3. (C)15
  4. (D)24

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
If for z=α+iβz=\alpha+i\betaz=α+iβ, ∣z+2∣=z+4(1+i)|z+2|=z+4(1+i)∣z+2∣=z+4(1+i), then α+β\alpha+\betaα+β and αβ\alpha\betaαβ are the roots of the equation
  1. (A)x2+7x+12=0x^{2}+7x+12=0x2+7x+12=0
  2. (B)x2+3x−4=0x^{2}+3x-4=0x2+3x−4=0
  3. (C)x2+2x−3=0x^{2}+2x-3=0x2+2x−3=0
  4. (D)x2+x−12=0x^{2}+x-12=0x2+x−12=0

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsNumerical
Let [t][t][t] denotes the greatest integer ≤t\le t≤t. Then 2π∫π/65π/6(8[cosec⁡x]−5[cot⁡x])dx\frac{2}{\pi}\int_{\pi/6}^{5\pi/6}\left(8[\operatorname{cosec} x]-5[\cot x]\right)dxπ2​∫π/65π/6​(8[cosecx]−5[cotx])dx is equal to

Correct answer: 14

Step-by-step solution →
Q81·MathematicsNumerical
Let [t][t][t] denotes the greatest integer ≤t\le t≤t. If the constant term in the expansion of (3x2−12x5)7\left(3x^{2}-\frac{1}{2x^{5}}\right)^{7}(3x2−2x51​)7 is α\alphaα, then [α][\alpha][α] is equal to

Correct answer: 1275

Step-by-step solution →
Q82·MathematicsNumerical
Let a⃗=6i^+9j^+12k^\vec{a}=6\hat{i}+9\hat{j}+12\hat{k}a=6i^+9j^​+12k^, b⃗=αi^+11j^−2k^\vec{b}=\alpha\hat{i}+11\hat{j}-2\hat{k}b=αi^+11j^​−2k^ and c⃗\vec{c}c be vectors such that a⃗×c⃗=a⃗×b⃗\vec{a}\times\vec{c}=\vec{a}\times\vec{b}a×c=a×b. If a⃗⋅c⃗=−12\vec{a}\cdot\vec{c}=-12a⋅c=−12, c⃗⋅(i^−2j^+k^)=5\vec{c}\cdot(\hat{i}-2\hat{j}+\hat{k})=5c⋅(i^−2j^​+k^)=5, then c⃗⋅(i^+j^+k^)\vec{c}\cdot(\hat{i}+\hat{j}+\hat{k})c⋅(i^+j^​+k^) is equal to

Correct answer: 11

Step-by-step solution →
Q83·MathematicsNumerical
The largest natural number nnn such that 3n3^{n}3n divides 66!66!66! is

Correct answer: 31

Step-by-step solution →
Q84·MathematicsNumerical
If ana_{n}an​ is the greatest term in the sequence an=n3n4+147a_{n}=\frac{n^{3}}{n^{4}+147}an​=n4+147n3​, n=1,2,3,…n=1,2,3,\ldotsn=1,2,3,…, then α\alphaα is equal to

Correct answer: 5

Step-by-step solution →
Q85·MathematicsNumerical
Let A={0,3,4,6,7,8,9,10}A=\{0,3,4,6,7,8,9,10\}A={0,3,4,6,7,8,9,10} and RRR be the relation defined on AAA such that R={(x,y)∈A×A:x−y is odd positive integer or x−y=2}R=\{(x,y)\in A\times A: x-y \text{ is odd positive integer or } x-y=2\}R={(x,y)∈A×A:x−y is odd positive integer or x−y=2}. The minimum number of elements that must be added to the relation RRR, so that it is a symmetric relation, is equal to

Correct answer: 19

Step-by-step solution →
Q86·MathematicsNumerical
Consider a circle C1:x2+y2−4x−2y=α−5C_{1}:x^{2}+y^{2}-4x-2y=\alpha-5C1​:x2+y2−4x−2y=α−5. Let its mirror image in the line y=2x+1y=2x+1y=2x+1 be another circle C2:5x2+5y2−10fx−10gy+36=0C_{2}:5x^{2}+5y^{2}-10fx-10gy+36=0C2​:5x2+5y2−10fx−10gy+36=0. Let rrr be the radius of C2C_{2}C2​. Then α+r\alpha+rα+r is equal to

Correct answer: 2

Step-by-step solution →
Q87·MathematicsNumerical
If the solution curve of the differential equation (y−2log⁡ex)dx+(xlog⁡ex2)dy=0(y-2\log_{e}x)dx+(x\log_{e}x^{2})dy=0(y−2loge​x)dx+(xloge​x2)dy=0, x>1x>1x>1 passes through the points (e,43)\left(e,\frac{4}{3}\right)(e,34​) and (e4,α)(e^{4},\alpha)(e4,α), then α\alphaα is equal to

Correct answer: 3

Step-by-step solution →
Q88·MathematicsNumerical
Let λ1,λ2\lambda_{1},\lambda_{2}λ1​,λ2​ be the values of λ\lambdaλ for which the points (52,1,λ)\left(\frac{5}{2},1,\lambda\right)(25​,1,λ) and (−2,0,1)(-2,0,1)(−2,0,1) are at equal distance from the plane 2x+3y−6z+7=02x+3y-6z+7=02x+3y−6z+7=0. If λ1>λ2\lambda_{1}>\lambda_{2}λ1​>λ2​, then the distance of the point (λ1−λ2,λ2,λ1)(\lambda_{1}-\lambda_{2},\lambda_{2},\lambda_{1})(λ1​−λ2​,λ2​,λ1​) from the line x−51=y−12=z+72\frac{x-5}{1}=\frac{y-1}{2}=\frac{z+7}{2}1x−5​=2y−1​=2z+7​ is

Correct answer: 9

Step-by-step solution →
Q89·MathematicsNumerical
Let the mean and variance of 8 numbers xxx, yyy, 10, 12, 6, 12, 4, 8, be 9 and 9.25 respectively. If x>yx>yx>y, then 3x−2y3x-2y3x−2y is equal to

Correct answer: 25

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Area Under Curves 139/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Parabola 101/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Indefinite Integration 66/186
  • Carboxylic Acids and Derivatives 54/186
  • Chemistry in Everyday Life 60/186
  • Diazonium Salts and Reactions 53/186
  • States of Matter: Gases and Liquids 52/186
  • Magnetism and Matter 50/186
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