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JEE Main 29 January 2025 Shift 2 Question Paper with Answers

29 January 2025 · January session · 73 questions

73 of the 75 questions from the JEE Main 29 January 2025 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

2 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
23
Chemistry
25
Mathematics
25

Physics — JEE Main 29 January 2025 Shift 2

Q1·Physics·Current ElectricitySingle correct
The difference of temperature in a material can convert heat energy into electrical energy. To harvest the heat energy, the material should have
  1. (A)high thermal conductivity and low electrical conductivity
  2. (B)high thermal conductivity and high electrical conductivity
  3. (C)low thermal conductivity and high electrical conductivity
  4. (D)low thermal conductivity and low electrical conductivity

Correct answer: (C)

Step-by-step solution →
Q2·Physics·ThermodynamicsSingle correct
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): With the increase in the pressure of an ideal gas, the volume falls off more rapidly in an isothermal process in comparison to the adiabatic process. Reason (R): In isothermal process, PV = constant, while in adiabatic process PVγPV^{\gamma}PVγ = constant. Here γ\gammaγ is the ratio of specific heats, P is the pressure and V is the volume of the ideal gas. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
  2. (B)(A) is true but (R) is false
  3. (C)Both (A) and (R) are true and (R) is the correct explanation of (A)
  4. (D)(A) is false but (R) is true

Correct answer: (C)

Step-by-step solution →
Q3·Physics·Electric Field and Coulomb's LawSingle correct
An electric dipole is placed at a distance of 2 cm from an infinite plane sheet having positive charge density σ0\sigma_0σ0​ (orientation as shown in the figure). Choose the correct option from the following.
  1. (A)Torque on dipole is zero and net force is directed away from the sheet.
  2. (B)Torque on dipole is zero and net force acts towards the sheet.
  3. (C)Potential energy of dipole is minimum and torque is zero.
  4. (D)Potential energy and torque both are maximum.

Correct answer: (C)

Step-by-step solution →
Q4·Physics·Dual Nature of Matter and RadiationSingle correct
In an experiment with photoelectric effect, the stopping potential,
  1. (A)increases with increase in the wavelength of the incident light
  2. (B)increases with increase in the intensity of the incident light
  3. (C)is (1e)\left(\dfrac{1}{e}\right)(e1​) times the maximum kinetic energy of the emitted photoelectrons
  4. (D)decreases with increase in the intensity of the incident light

Correct answer: (C)

Step-by-step solution →
Q5·Physics·Electric Field and Coulomb's LawSingle correct
A point charge causes an electric flux of −2×104-2\times 10^4−2×104 Nm²C⁻¹ to pass through a spherical Gaussian surface of 8.0 cm radius, centred on the charge. The value of the point charge is: (Given ε0=8.85×10−12\varepsilon_0=8.85\times 10^{-12}ε0​=8.85×10−12 C²N⁻¹m⁻²)
  1. (A)−17.7×10−8-17.7\times 10^{-8}−17.7×10−8 C
  2. (B)−15.7×10−8-15.7\times 10^{-8}−15.7×10−8 C
  3. (C)17.7×10−817.7\times 10^{-8}17.7×10−8 C
  4. (D)15.7×10−815.7\times 10^{-8}15.7×10−8 C

Correct answer: (A)

Step-by-step solution →
Q6·Physics·Geometrical OpticsSingle correct
Two identical symmetric double convex lenses of focal length f are cut into two equal parts L1,L2L_1, L_2L1​,L2​ by AB plane and L3,L4L_3, L_4L3​,L4​ by XY plane as shown in figure. The ratio of focal lengths of lenses L1L_1L1​ and L3L_3L3​ is
  1. (A)1 : 4
  2. (B)1 : 1
  3. (C)2 : 1
  4. (D)1 : 2

Correct answer: (D)

Step-by-step solution →
Q7·Physics·Electromagnetic WavesSingle correct
A plane electromagnetic wave propagates along the + x direction in free space. The components of the electric field, E⃗\vec{E}E and magnetic field, B⃗\vec{B}B vectors associated with the wave in Cartesian frame are:
  1. (A)Ey,BxE_y, B_xEy​,Bx​
  2. (B)Ey,BzE_y, B_zEy​,Bz​
  3. (C)Ex,ByE_x, B_yEx​,By​
  4. (D)Ez,ByE_z, B_yEz​,By​

Correct answer: (B)

Step-by-step solution →
Q8·Physics·Geometrical OpticsSingle correct
Two concave refracting surfaces of equal radii of curvature and refractive index 1.5 face each other in air as shown in figure. A point object O is placed midway, between P and B. The separation between the images of O, formed by each refracting surface is:
  1. (A)0.214R
  2. (B)0.114R
  3. (C)0.411R
  4. (D)0.124R

Correct answer: (B)

Step-by-step solution →
Q9·Physics·OscillationsSingle correct
Two bodies A and B of equal mass are suspended from two massless springs of spring constant k1k_1k1​ and k2k_2k2​, respectively. If the bodies oscillate vertically such that their amplitudes are equal, the ratio of the maximum velocity of A to the maximum velocity of B is
  1. (A)k1k2\sqrt{\dfrac{k_1}{k_2}}k2​k1​​​
  2. (B)k1k2\dfrac{k_1}{k_2}k2​k1​​
  3. (C)k2k1\dfrac{k_2}{k_1}k1​k2​​
  4. (D)k2k1\sqrt{\dfrac{k_2}{k_1}}k1​k2​​​

Correct answer: (A)

Step-by-step solution →
Q10·Physics·Work, Energy and PowerSingle correct
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): Three identical spheres of same mass undergo one dimensional motion as shown in figure with initial velocities vA=5v_A=5vA​=5 m/s, vB=2v_B=2vB​=2 m/s, vC=4v_C=4vC​=4 m/s (arranged A, B, C from left to right and all moving in the +x direction). If we wait sufficiently long for elastic collisions to happen, then vA=4v_A=4vA​=4 m/s, vB=2v_B=2vB​=2 m/s, vC=5v_C=5vC​=5 m/s will be the final velocities. Reason (R): In an elastic collision between identical masses, two objects exchange their velocities. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
  2. (B)(A) is true but (R) is false
  3. (C)Both (A) and (R) are true and (R) is the correct explanation of (A).
  4. (D)(A) is false but (R) is true

Correct answer: (D)

Step-by-step solution →
Q11·Physics·Laws of MotionSingle correct
A sand dropper drops sand of mass m(t) on a conveyer belt at a rate proportional to the square root of speed (v) of the belt, i.e. dmdt∝v\dfrac{dm}{dt}\propto\sqrt{v}dtdm​∝v​. If P is the power delivered to run the belt at constant speed then which of the following relationship is true?
  1. (A)P2∝v3P^2\propto v^3P2∝v3
  2. (B)P∝vP\propto\sqrt{v}P∝v​
  3. (C)P∝vP\propto vP∝v
  4. (D)P2∝v5P^2\propto v^5P2∝v5

Correct answer: (D)

Step-by-step solution →
Q12·Physics·Geometrical OpticsSingle correct
A convex lens made of glass (refractive index = 1.5) has focal length 24 cm in air. When it is totally immersed in water (refractive index = 1.33), its focal length changes to
  1. (A)72 cm
  2. (B)96 cm
  3. (C)24 cm
  4. (D)48 cm

Correct answer: (B)

Step-by-step solution →
Q13·Physics·Capacitors and DielectricsSingle correct
A capacitor, C1=6 μFC_1=6\ \mu FC1​=6 μF is charged to a potential difference of V0=5V_0=5V0​=5 V using a 5 V battery. The battery is removed and another capacitor, C2=12 μFC_2=12\ \mu FC2​=12 μF is inserted in place of the battery. When the switch ‘S’ is closed, the charge flows between the capacitors for some time until equilibrium condition is reached. What are the charges (q1q_1q1​ and q2q_2q2​) on the capacitors C1C_1C1​ and C2C_2C2​ when equilibrium condition is reached.
  1. (A)q1=15 μC,q2=30 μCq_1=15\ \mu C, q_2=30\ \mu Cq1​=15 μC,q2​=30 μC
  2. (B)q1=30 μC,q2=15 μCq_1=30\ \mu C, q_2=15\ \mu Cq1​=30 μC,q2​=15 μC
  3. (C)q1=10 μC,q2=20 μCq_1=10\ \mu C, q_2=20\ \mu Cq1​=10 μC,q2​=20 μC
  4. (D)q1=20 μC,q2=10 μCq_1=20\ \mu C, q_2=10\ \mu Cq1​=20 μC,q2​=10 μC

Correct answer: (C)

Step-by-step solution →
Q14·Physics·Rotational MotionSingle correct
Three equal masses m are kept at vertices (A, B, C) of an equilateral triangle of side a in free space. At t = 0, they are given an initial velocity V⃗A=V0 AC^\vec{V}_A=V_0\,\hat{AC}VA​=V0​AC^, V⃗B=V0 BA^\vec{V}_B=V_0\,\hat{BA}VB​=V0​BA^ and V⃗C=V0 CB^\vec{V}_C=V_0\,\hat{CB}VC​=V0​CB^. Here, AC^,CB^\hat{AC}, \hat{CB}AC^,CB^ and BA^\hat{BA}BA^ are unit vectors along the edges of the triangle. If the three masses interact gravitationally, then the magnitude of the net angular momentum of the system at the point of collision is:
  1. (A)12amV0\dfrac{1}{2}a m V_021​amV0​
  2. (B)3amV03 a m V_03amV0​
  3. (C)32amV0\dfrac{\sqrt{3}}{2}a m V_023​​amV0​
  4. (D)32amV0\dfrac{3}{2}a m V_023​amV0​

Correct answer: (C)

Step-by-step solution →
Q15·Physics·Units and MeasurementsSingle correct
Match List-I (Mechanical Quantity) with List-II (Dimensional Formula). Choose the correct answer from the options given below:
List-I (Mechanical Quantity)List-II (Dimensional Formula)
A.Young’s ModulusI.ML−1T−1ML^{-1}T^{-1}ML−1T−1
B.TorqueII.ML−1T−2ML^{-1}T^{-2}ML−1T−2
C.Coefficient of ViscosityIII.M−1L3T−2M^{-1}L^{3}T^{-2}M−1L3T−2
D.Gravitational ConstantIV.ML2T−2ML^{2}T^{-2}ML2T−2
  1. (A)(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  2. (B)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  3. (C)(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  4. (D)(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct answer: (D)

Step-by-step solution →
Q16·Physics·Electronic DevicesSingle correct
The truth table for the logic circuit given in the figure (inputs A, B; output Y) is:
  1. (A)A,B→Y: (0,0)→0, (0,1)→1, (1,0)→1, (1,1)→0
  2. (B)A,B→Y: (0,0)→0, (1,0)→0, (1,1)→1, (0,1)→1
  3. (C)A,B→Y: (0,0)→0, (1,0)→1, (0,1)→0, (1,1)→0
  4. (D)A,B→Y: (0,0)→0, (1,1)→1, (1,0)→1, (0,1)→1

Correct answer: (A)

Step-by-step solution →
Q17·Physics·ThermodynamicsSingle correct
A cup of coffee cools from 90°C to 80°C in t minutes when the room temperature is 20°C. The time taken by the similar cup of coffee to cool from 80°C to 60°C at the same room temperature is:
  1. (A)135t\dfrac{13}{5}t513​t
  2. (B)1013t\dfrac{10}{13}t1310​t
  3. (C)1310t\dfrac{13}{10}t1013​t
  4. (D)513t\dfrac{5}{13}t135​t

Correct answer: (A)

Step-by-step solution →
Q18·Physics·Atoms and NucleiSingle correct
The number of spectral lines emitted by atomic hydrogen that is in the 4th4^{\text{th}}4th energy level, is
  1. (A)6
  2. (B)0
  3. (C)3
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q19·Physics·Magnetic Field of CurrentInteger
The magnetic field inside a 200 turns solenoid of radius 10 cm is 2.9×10−42.9\times 10^{-4}2.9×10−4 Tesla. If the solenoid carries a current of 0.29 A, then the length of the solenoid is ______ π\piπ cm.

Correct answer: 8

Step-by-step solution →
Q20·Physics·Capacitors and DielectricsInteger
A parallel plate capacitor consisting of two circular plates of radius 10 cm is being charged by a constant current of 0.15 A. If the rate of change of potential difference between the plates is 7×1087\times 10^87×108 V/s then the integer value of the distance between the parallel plates is ______ μm. (Take ε0=9×10−12\varepsilon_0=9\times 10^{-12}ε0​=9×10−12 F/m, π=227\pi=\dfrac{22}{7}π=722​.)

Correct answer: 1320

Step-by-step solution →
Q21·Physics·Units and MeasurementsInteger
A physical quantity Q is related to four observables a, b, c, d as follows: Q=ab4cdQ=\dfrac{ab^4}{cd}Q=cdab4​, where a=(60±3)a=(60\pm 3)a=(60±3) Pa; b=(20±0.1)b=(20\pm 0.1)b=(20±0.1) m; c=(40±0.2)c=(40\pm 0.2)c=(40±0.2) Nsm⁻² and d=(50±0.1)d=(50\pm 0.1)d=(50±0.1) m, then the percentage error in Q is x1000\dfrac{x}{1000}1000x​, where x=x=x= ______.

Correct answer: 7700

Step-by-step solution →
Q22·Physics·GravitationInteger
Two planets, A and B are orbiting a common star in circular orbits of radii RAR_ARA​ and RBR_BRB​, respectively, with RB=2RAR_B=2R_ARB​=2RA​. The planet B is 424\sqrt{2}42​ times more massive than planet A. The ratio (LBLA)\left(\dfrac{L_B}{L_A}\right)(LA​LB​​) of angular momentum (LBL_BLB​) of planet B to that of planet A(LA)A(L_A)A(LA​) is closest to integer ______.

Correct answer: 8

Step-by-step solution →
Q23·Physics·KinematicsInteger
Two cars P and Q are moving on a road in the same direction. Acceleration of car P increases linearly with time whereas car Q moves with a constant acceleration. Both cars cross each other at time t = 0, for the first time. The maximum possible number of crossing(s) (including the crossing at t = 0) is ______.

Correct answer: 3

Step-by-step solution →

Chemistry — JEE Main 29 January 2025 Shift 2

Q24·Chemistry·Coordination CompoundsSingle correct
The calculated spin-only magnetic moments of K3[Fe(OH)6]K_3[Fe(OH)_6]K3​[Fe(OH)6​] and K4[Fe(OH)6]K_4[Fe(OH)_6]K4​[Fe(OH)6​] respectively are:
  1. (A)4.90 and 4.90 B.M.
  2. (B)5.92 and 4.90 B.M.
  3. (C)3.87 and 4.90 B.M.
  4. (D)4.90 and 5.92 B.M.

Correct answer: (B)

Step-by-step solution →
Q25·Chemistry·Atomic StructureSingle correct
For hydrogen like species, which of the following graphs provides the most appropriate representation of E vs Z plot for a constant a? [E: Energy of the stationary state, Z: atomic number, n = principal quantum number] (graphs shown in the figure)
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q26·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
Given below are two statements: Statement (I): In partition chromatography, stationary phase is thin film of liquid present in the inert support. Statement (II): In paper chromatography, paper acts as a stationary phase. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are true
  4. (D)Statement I is false but Statement II is true

Correct answer: (B)

Step-by-step solution →
Q27·Chemistry·BiomoleculesSingle correct
Identify the essential amino acids from below: (A) Valine (B) Proline (C) Lysine (D) Threonine (E) Tyrosine. Choose the correct answer from the options given below:
  1. (A)(A), (C) and (D) only
  2. (B)(A), (C) and (E) only
  3. (C)(B), (C) and (E) only
  4. (D)(C), (D) and (E) only

Correct answer: (A)

Step-by-step solution →
Q28·Chemistry·Organic Compounds Containing HalogensSingle correct
Which among the following halides (shown in the figure) will generate the most stable carbocation in a nucleophilic substitution reaction?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q29·Chemistry·EquilibriumSingle correct
Consider the equilibrium CO(g)+3H2(g)⇌CH4(g)+H2O(g)CO(g)+3H_2(g)\rightleftharpoons CH_4(g)+H_2O(g)CO(g)+3H2​(g)⇌CH4​(g)+H2​O(g). If the pressure applied over the system increases by two fold at constant temperature then (A) Concentration of reactants and products increases. (B) Equilibrium will shift in forward direction. (C) Equilibrium constant increases since concentration of products increases. (D) Equilibrium constant remains unchanged as concentration of reactants and products remain same. Choose the correct answer from the options given below:
  1. (A)(A) and (B) only
  2. (B)(A), (B) and (D) only
  3. (C)(B) and (C) only
  4. (D)(A), (B) and (C) only

Correct answer: (A)

Step-by-step solution →
Q30·Chemistry·SolutionsSingle correct
Given below are two statements: Statement (I): NaCl is added to the ice at 0°C, present in the ice cream box to prevent the melting of ice cream. Statement (II): On addition of NaCl to ice at 0°C, there is a depression in freezing point. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is true but Statement II is false

Correct answer: (B)

Step-by-step solution →
Q31·Chemistry·HydrocarbonsSingle correct
Given below are two statements: Statement (I): On nitration of m-xylene with HNO3HNO_3HNO3​, H2SO4H_2SO_4H2​SO4​ followed by oxidation, 4-nitrobenzene-1,3-dicarboxylic acid is obtained as the major product. Statement (II): −CH3-CH_3−CH3​ group is o/p-directing while −NO2-NO_2−NO2​ group is m-directing group. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is false but Statement II is true
  3. (C)Both Statement I and Statement II are true
  4. (D)Statement I is true but Statement II is false

Correct answer: (C)

Step-by-step solution →
Q32·Chemistry·Redox Reactions and ElectrochemistrySingle correct
0.1 M solution of KI reacts with excess of H2SO4H_2SO_4H2​SO4​ and KIO3KIO_3KIO3​ solution. According to the equation 5I−+IO3−+6H+→3I2+3H2O5I^-+IO_3^-+6H^+\rightarrow 3I_2+3H_2O5I−+IO3−​+6H+→3I2​+3H2​O. Identify the correct statements: (A) 200 mL of KI solution reacts with 0.004 mol of KIO3KIO_3KIO3​. (B) 200 mL of KI solution reacts with 0.006 mol of H2SO4H_2SO_4H2​SO4​. (C) 0.5 L of KI solution produced 0.005 mol of I2I_2I2​. (D) Equivalent weight of KIO3KIO_3KIO3​ is equal to Molecular weight5\dfrac{\text{Molecular weight}}{5}5Molecular weight​. Choose the correct answer from the options given below:
  1. (A)(A) and (D) only
  2. (B)(B) and (C) only
  3. (C)(A) and (B) only
  4. (D)(C) and (D) only

Correct answer: (A)

Step-by-step solution →
Q33·Chemistry·Redox Reactions and ElectrochemistrySingle correct
Match List-I (Applications) with List-II (Batteries/Cell). Choose the correct answer from the options given below:
List-I (Applications)List-II (Batteries/Cell)
A.TransistorsI.Anode – Zn/Hg ; Cathode – HgO + C
B.Hearing aidsII.Hydrogen fuel cell
C.InvertorsIII.Anode – Zn ; Cathode – Carbon
D.Apollo space shipIV.Anode – Pb ; Cathode – Pb | PbO₂
  1. (A)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. (B)(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  3. (C)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  4. (D)(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Correct answer: (A)

Step-by-step solution →
Q34·Chemistry·Redox Reactions and ElectrochemistrySingle correct
O2O_2O2​ gas will be evolved as a product of electrolysis of: (A) an aqueous solution of AgNO3AgNO_3AgNO3​ using silver electrodes. (B) an aqueous solution of AgNO3AgNO_3AgNO3​ using platinum electrodes. (C) a dilute solution of H2SO4H_2SO_4H2​SO4​ using platinum electrodes. (D) a high concentration solution of H2SO4H_2SO_4H2​SO4​ using platinum electrodes. Choose the correct answer from the options given below:
  1. (A)(B) and (C) only
  2. (B)(A) and (D) only
  3. (C)(B) and (D) only
  4. (D)(A) and (C) only

Correct answer: (A)

Step-by-step solution →
Q35·Chemistry·Coordination CompoundsSingle correct
Identify the homoleptic complexes with odd number of d electrons in the central metal. (A) [FeO4]2−[FeO_4]^{2-}[FeO4​]2− (B) [Fe(CN)6]3−[Fe(CN)_6]^{3-}[Fe(CN)6​]3− (C) [Fe(CN)5NO]2−[Fe(CN)_5NO]^{2-}[Fe(CN)5​NO]2− (D) [CoCl4]2−[CoCl_4]^{2-}[CoCl4​]2− (E) [Co(H2O)3F3][Co(H_2O)_3F_3][Co(H2​O)3​F3​]. Choose the correct answer from the options given below:
  1. (A)(B) and (D) only
  2. (B)(C) and (E) only
  3. (C)(A), (B) and (D) only
  4. (D)(A), (C) and (E) only

Correct answer: (A)

Step-by-step solution →
Q36·Chemistry·Some Basic Principles of Organic ChemistrySingle correct
Total number of sigma (σ\sigmaσ) ______ and pi (π\piπ) ______ bonds respectively present in the hex-1-en-4-yne are:
  1. (A)13 and 3
  2. (B)11 and 3
  3. (C)13 and 5
  4. (D)14 and 3

Correct answer: (A)

Step-by-step solution →
Q37·Chemistry·Chemical ThermodynamicsSingle correct
If C(diamond)→C(graphite)+XC(\text{diamond})\rightarrow C(\text{graphite})+XC(diamond)→C(graphite)+X kJ mol⁻¹; C(diamond)+O2(g)→CO2(g)+YC(\text{diamond})+O_2(g)\rightarrow CO_2(g)+YC(diamond)+O2​(g)→CO2​(g)+Y kJ mol⁻¹; C(graphite)+O2(g)→CO2(g)+ZC(\text{graphite})+O_2(g)\rightarrow CO_2(g)+ZC(graphite)+O2​(g)→CO2​(g)+Z kJ mol⁻¹. At constant temperature, then
  1. (A)X = Y + Z
  2. (B)X = Y − Z
  3. (C)X = Z − Y
  4. (D)X = Y = Z

Correct answer: (B)

Step-by-step solution →
Q38·Chemistry·Atomic StructureSingle correct
Given below are two statements: Statement (I): It is impossible to specify simultaneously with arbitrary precision, both the linear momentum and the position of a particle. Statement (II): If the uncertainty in the measurement of position and uncertainty in measurement of momentum are equal for an electron, then the uncertainty in the measurement of velocity is ≥12mhπ\ge\dfrac{1}{2m}\sqrt{\dfrac{h}{\pi}}≥2m1​πh​​. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I is false but Statement II is true.
  4. (D)Both Statement I and Statement II are true.

Correct answer: (D)

Step-by-step solution →
Q39·Chemistry·Diazonium Salts and ReactionsSingle correct
Which one of the following reaction sequences (shown in the figure) will give an azo dye?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q40·Chemistry·Chemical KineticsSingle correct
Drug X becomes ineffective after 50% decomposition. The original concentration of drug in a bottle was 16 mg/mL which becomes 4 mg/mL in 12 months. The expiry time of the drug in months is ______. Assume that the decomposition of the drug follows first order kinetics.
  1. (A)12
  2. (B)2
  3. (C)3
  4. (D)6

Correct answer: (D)

Step-by-step solution →
Q41·Chemistry·Classification of Elements and Periodicity in PropertiesSingle correct
The type of oxide formed by the element among Li, Na, Be, Mg, B and Al that has the least atomic radius is:
  1. (A)A2O3A_2O_3A2​O3​
  2. (B)AO2AO_2AO2​
  3. (C)AOAOAO
  4. (D)A2OA_2OA2​O

Correct answer: (A)

Step-by-step solution →
Q42·Chemistry·p-Block ElementsSingle correct
First ionisation enthalpy values of first four group 15 elements are given below. Choose the correct value for the element that is a main component of apatite family:
  1. (A)1012 kJ mol⁻¹
  2. (B)1402 kJ mol⁻¹
  3. (C)834 kJ mol⁻¹
  4. (D)947 kJ mol⁻¹

Correct answer: (A)

Step-by-step solution →
Q43·Chemistry·Alcohols and EthersSingle correct
Which one of the following (shown in the figure), with HBr will give a phenol?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q44·Chemistry·Coordination CompoundsInteger
Consider the following low-spin complexes K3[Co(NO2)6]K_3[Co(NO_2)_6]K3​[Co(NO2​)6​], K4[Fe(CN)6]K_4[Fe(CN)_6]K4​[Fe(CN)6​], K3[Fe(CN)6]K_3[Fe(CN)_6]K3​[Fe(CN)6​], Cu2[Fe(CN)6]Cu_2[Fe(CN)_6]Cu2​[Fe(CN)6​] and Zn2[Fe(CN)6]Zn_2[Fe(CN)_6]Zn2​[Fe(CN)6​]. The sum of the spin-only magnetic moment values of complexes having yellow colour is ______ B.M. (answer is nearest integer)

Correct answer: 0

Step-by-step solution →
Q45·Chemistry·HydrocarbonsInteger
Isomeric hydrocarbons → negative Baeyer’s test (Molecular formula C9H12C_9H_{12}C9​H12​). The total number of isomers from above with four different non-aliphatic substitution sites is ______.

Correct answer: 2

Step-by-step solution →
Q46·Chemistry·Aldehydes and KetonesInteger
In the Claisen-Schmidt reaction to prepare dibenzalacetone from 5.3 g benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction is ______ %.

Correct answer: 60

Step-by-step solution →
Q47·Chemistry·Purification and Characterisation of Organic CompoundsInteger
In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ______ ×10−1\times 10^{-1}×10−1 %. (Molar mass: O = 16, S = 32, Ba = 137 g mol⁻¹)

Correct answer: 275

Step-by-step solution →
Q48·Chemistry·Chemical Bonding and Molecular StructureInteger
Total number of non bonded electrons present in NO2−NO_2^-NO2−​ ion based on Lewis theory is ______.

Correct answer: 12

Step-by-step solution →

Mathematics — JEE Main 29 January 2025 Shift 2

Q49·Mathematics·Quadratic EquationsSingle correct
If the set of all a∈Ra\in Ra∈R, for which the equation 2x2+(a−5)x+15=3a2x^2+(a-5)x+15=3a2x2+(a−5)x+15=3a has no real root, is the interval (α,β)(\alpha,\beta)(α,β), and X={x∈Z:α<x<β}X=\{x\in Z:\alpha<x<\beta\}X={x∈Z:α<x<β}, then ∑x∈Xx2\displaystyle\sum_{x\in X}x^2x∈X∑​x2 is equal to
  1. (A)2109
  2. (B)2129
  3. (C)2139
  4. (D)2119

Correct answer: (C)

Step-by-step solution →
Q50·Mathematics·Trigonometric FunctionsSingle correct
If sin⁡x+sin⁡2x=1\sin x+\sin^2 x=1sinx+sin2x=1, x∈(0,π2)x\in\left(0,\dfrac{\pi}{2}\right)x∈(0,2π​), then (cos⁡12x+tan⁡12x)+3(cos⁡10x+tan⁡10x+cos⁡8x+tan⁡8x)+(cos⁡6x+tan⁡6x)(\cos^{12}x+\tan^{12}x)+3(\cos^{10}x+\tan^{10}x+\cos^{8}x+\tan^{8}x)+(\cos^{6}x+\tan^{6}x)(cos12x+tan12x)+3(cos10x+tan10x+cos8x+tan8x)+(cos6x+tan6x) is equal to
  1. (A)4
  2. (B)3
  3. (C)2
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q51·Mathematics·Area Under CurvesSingle correct
Let the area enclosed between the curves ∣y∣=1−x2|y|=1-x^2∣y∣=1−x2 and x2+y2=1x^2+y^2=1x2+y2=1 be α\alphaα. If 9α=βπ+γ9\alpha=\beta\pi+\gamma9α=βπ+γ; β,γ\beta,\gammaβ,γ are integers, then the value of ∣β−γ∣|\beta-\gamma|∣β−γ∣ equals
  1. (A)27
  2. (B)18
  3. (C)15
  4. (D)33

Correct answer: (D)

Step-by-step solution →
Q52·Mathematics·Sets, Relations and FunctionsSingle correct
If the domain of the function log⁡5(18x−x2−77)\log_5(18x-x^2-77)log5​(18x−x2−77) is (α,β)(\alpha,\beta)(α,β) and the domain of the function log⁡(x−1)(2x2+3x−2x2−3x−4)\log_{(x-1)}\left(\dfrac{2x^2+3x-2}{x^2-3x-4}\right)log(x−1)​(x2−3x−42x2+3x−2​) is (γ,δ)(\gamma,\delta)(γ,δ), then α2+β2+γ2\alpha^2+\beta^2+\gamma^2α2+β2+γ2 is equal to:
  1. (A)195
  2. (B)174
  3. (C)186
  4. (D)179

Correct answer: (C)

Step-by-step solution →
Q53·Mathematics·DifferentiabilitySingle correct
Let the function f(x)=(x2−1)∣x2−ax+2∣+cos⁡∣x∣f(x)=(x^2-1)|x^2-ax+2|+\cos|x|f(x)=(x2−1)∣x2−ax+2∣+cos∣x∣ be not differentiable at the two points x=α=2x=\alpha=2x=α=2 and x=βx=\betax=β. Then the distance of the point (α,β)(\alpha,\beta)(α,β) from the line 12x+5y+10=012x+5y+10=012x+5y+10=0 is equal to:
  1. (A)3
  2. (B)4
  3. (C)2
  4. (D)5

Correct answer: (A)

Step-by-step solution →
Q54·Mathematics·Three Dimensional GeometrySingle correct
Let a straight line L pass through the point P(2,−1,3)P(2,-1,3)P(2,−1,3) and be perpendicular to the lines x−12=y+11=z−3−2\dfrac{x-1}{2}=\dfrac{y+1}{1}=\dfrac{z-3}{-2}2x−1​=1y+1​=−2z−3​ and x−31=y−23=z+24\dfrac{x-3}{1}=\dfrac{y-2}{3}=\dfrac{z+2}{4}1x−3​=3y−2​=4z+2​. If the line L intersects the yz-plane at the point Q, then the distance between the points P and Q is:
  1. (A)2
  2. (B)10\sqrt{10}10​
  3. (C)3
  4. (D)232\sqrt{3}23​

Correct answer: (C)

Step-by-step solution →
Q55·Mathematics·Sets, Relations and FunctionsSingle correct
Let S=N∪{0}S=N\cup\{0\}S=N∪{0}. Define a relation R from S to R by: R={(x,y):log⁡ey=xlog⁡e(25), x∈S, y∈R}R=\left\{(x,y):\log_e y=x\log_e\left(\dfrac{2}{5}\right),\ x\in S,\ y\in R\right\}R={(x,y):loge​y=xloge​(52​), x∈S, y∈R}. Then, the sum of all the elements in the range of R is equal to
  1. (A)32\dfrac{3}{2}23​
  2. (B)53\dfrac{5}{3}35​
  3. (C)109\dfrac{10}{9}910​
  4. (D)52\dfrac{5}{2}25​

Correct answer: (B)

Step-by-step solution →
Q56·Mathematics·Straight LinesSingle correct
Let the line x+y=1x+y=1x+y=1 meet the axes of x and y at A and B, respectively. A right angled triangle AMN is inscribed in the triangle OAB, where O is the origin and the points M and N lie on the lines OB and AB, respectively. If the area of the triangle AMN is 49\dfrac{4}{9}94​ of the area of the triangle OAB and AN:NB=λ:1AN:NB=\lambda:1AN:NB=λ:1, then the sum of all possible value(s) of λ\lambdaλ is:
  1. (A)12\dfrac{1}{2}21​
  2. (B)136\dfrac{13}{6}613​
  3. (C)52\dfrac{5}{2}25​
  4. (D)2

Correct answer: (D)

Step-by-step solution →
Q57·Mathematics·EllipseSingle correct
If αx+βy=109\alpha x+\beta y=109αx+βy=109 is the equation of the chord of the ellipse x29+y24=1\dfrac{x^2}{9}+\dfrac{y^2}{4}=19x2​+4y2​=1, whose mid point is (52,12)\left(\dfrac{5}{2},\dfrac{1}{2}\right)(25​,21​), then α+β\alpha+\betaα+β is equal to
  1. (A)37
  2. (B)46
  3. (C)58
  4. (D)72

Correct answer: (C)

Step-by-step solution →
Q58·Mathematics·Permutations and CombinationsSingle correct
If all the words with or without meaning made using all the letters of the word “KANPUR” are arranged as in a dictionary, then the word at 440th440^{\text{th}}440th position in this arrangement, is:
  1. (A)PRNAKU
  2. (B)PRKANU
  3. (C)PRKAUN
  4. (D)PRNAUK

Correct answer: (C)

Step-by-step solution →
Q59·Mathematics·Matrices and DeterminantsSingle correct
Let α,β\alpha,\betaα,β (α≠β)(\alpha\ne\beta)(α=β) be the values of m, for which the equations x+y+z=1x+y+z=1x+y+z=1; x+2y+4z=mx+2y+4z=mx+2y+4z=m and x+4y+10z=m2x+4y+10z=m^2x+4y+10z=m2 have infinitely many solutions. Then the value of ∑n=110(nα+nβ)\displaystyle\sum_{n=1}^{10}\left(n^\alpha+n^\beta\right)n=1∑10​(nα+nβ) is equal to:
  1. (A)440
  2. (B)3080
  3. (C)3410
  4. (D)560

Correct answer: (A)

Step-by-step solution →
Q60·Mathematics·Matrices and DeterminantsSingle correct
Let A=[aij]A=[a_{ij}]A=[aij​] be a matrix of order 3×33\times 33×3, with aij=(2)i+ja_{ij}=(\sqrt{2})^{i+j}aij​=(2​)i+j. If the sum of all the elements in the third row of A2A^2A2 is α+β2\alpha+\beta\sqrt{2}α+β2​, α,β∈Z\alpha,\beta\in Zα,β∈Z, then α+β\alpha+\betaα+β is equal to
  1. (A)280
  2. (B)168
  3. (C)210
  4. (D)224

Correct answer: (D)

Step-by-step solution →
Q61·Mathematics·Three Dimensional GeometrySingle correct
Let P be the foot of the perpendicular from the point (1,2,2)(1, 2, 2)(1,2,2) on the line L:x−11=y+1−1=z−22L:\dfrac{x-1}{1}=\dfrac{y+1}{-1}=\dfrac{z-2}{2}L:1x−1​=−1y+1​=2z−2​. Let the line r⃗=(−i^−2k^)+λ(i^−j^+k^)\vec{r}=\left(-\hat{i}-2\hat{k}\right)+\lambda\left(\hat{i}-\hat{j}+\hat{k}\right)r=(−i^−2k^)+λ(i^−j^​+k^), λ∈R\lambda\in Rλ∈R, intersect the line L at Q. Then 2(PQ)22(PQ)^22(PQ)2 is equal to:
  1. (A)27
  2. (B)25
  3. (C)29
  4. (D)19

Correct answer: (A)

Step-by-step solution →
Q62·Mathematics·CirclesSingle correct
Let a circle C pass through the points (4,2)(4, 2)(4,2) and (0,2)(0, 2)(0,2), and its centre lie on 3x+2y+2=03x+2y+2=03x+2y+2=0. Then the length of the chord, of the circle C, whose mid-point is (1,2)(1, 2)(1,2), is:
  1. (A)3\sqrt{3}3​
  2. (B)232\sqrt{3}23​
  3. (C)424\sqrt{2}42​
  4. (D)222\sqrt{2}22​

Correct answer: (B)

Step-by-step solution →
Q63·Mathematics·Statistics and ProbabilitySingle correct
Let A=[aij]A=[a_{ij}]A=[aij​] be a 2×22\times 22×2 matrix such that aij∈{0,1}a_{ij}\in\{0, 1\}aij​∈{0,1} for all i and j. Let the random variable X denote the possible values of the determinant of the matrix A. Then the variance of X is:
  1. (A)14\dfrac{1}{4}41​
  2. (B)38\dfrac{3}{8}83​
  3. (C)58\dfrac{5}{8}85​
  4. (D)34\dfrac{3}{4}43​

Correct answer: (B)

Step-by-step solution →
Q64·Mathematics·Statistics and ProbabilitySingle correct
Bag 1 contains 4 white balls and 5 black balls, and Bag 2 contains n white balls and 3 black balls. One ball is drawn randomly from Bag 1 and transferred to Bag 2. A ball is then drawn randomly from Bag 2. If the probability, that the ball drawn from Bag 2, is white, is 2945\dfrac{29}{45}4529​, then n is equal to:
  1. (A)3
  2. (B)4
  3. (C)5
  4. (D)6

Correct answer: (D)

Step-by-step solution →
Q65·Mathematics·Binomial Theorem and Its Simple ApplicationsSingle correct
The remainder, when 71037^{103}7103 is divided by 23, is equal to:
  1. (A)14
  2. (B)9
  3. (C)17
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q66·Mathematics·Definite IntegrationSingle correct
Let f′(x)=∫0xt(t2−9t+20) dtf'(x)=\displaystyle\int_0^x t(t^2-9t+20)\,dtf′(x)=∫0x​t(t2−9t+20)dt, 1≤x≤51\le x\le 51≤x≤5. If the range of f is [α,β][\alpha,\beta][α,β], then 4(α+β)4(\alpha+\beta)4(α+β) equals:
  1. (A)157
  2. (B)253
  3. (C)125
  4. (D)154

Correct answer: (A)

Step-by-step solution →
Q67·Mathematics·Vector AlgebraSingle correct
Let a^\hat{a}a^ be a unit vector perpendicular to the vectors b⃗=i^−2j^+3k^\vec{b}=\hat{i}-2\hat{j}+3\hat{k}b=i^−2j^​+3k^ and c⃗=2i^+3j^−k^\vec{c}=2\hat{i}+3\hat{j}-\hat{k}c=2i^+3j^​−k^, and makes an angle of cos⁡−1(−13)\cos^{-1}\left(-\dfrac{1}{3}\right)cos−1(−31​) with the vector i^+j^+k^\hat{i}+\hat{j}+\hat{k}i^+j^​+k^. If a^\hat{a}a^ makes an angle of π3\dfrac{\pi}{3}3π​ with the vector i^+αj^+k^\hat{i}+\alpha\hat{j}+\hat{k}i^+αj^​+k^, then the value of α\alphaα is:
  1. (A)−3-\sqrt{3}−3​
  2. (B)6\sqrt{6}6​
  3. (C)−6-\sqrt{6}−6​
  4. (D)3\sqrt{3}3​

Correct answer: (C)

Step-by-step solution →
Q68·Mathematics·Differential EquationsSingle correct
If for the solution curve y=f(x)y=f(x)y=f(x) of the differential equation dydx+(tan⁡x)y=2+sec⁡x(1+2sec⁡x)2\dfrac{dy}{dx}+(\tan x)y=\dfrac{2+\sec x}{(1+2\sec x)^2}dxdy​+(tanx)y=(1+2secx)22+secx​, x∈(−π2,π2)x\in\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right)x∈(−2π​,2π​), f(π3)=310f\left(\dfrac{\pi}{3}\right)=\dfrac{\sqrt{3}}{10}f(3π​)=103​​, then f(π4)f\left(\dfrac{\pi}{4}\right)f(4π​) is equal to:
  1. (A)93+310(4+3)\dfrac{9\sqrt{3}+3}{10(4+\sqrt{3})}10(4+3​)93​+3​
  2. (B)3+110(4+3)\dfrac{\sqrt{3}+1}{10(4+\sqrt{3})}10(4+3​)3​+1​
  3. (C)5−322\dfrac{5-\sqrt{3}}{2\sqrt{2}}22​5−3​​
  4. (D)4−214\dfrac{4-\sqrt{2}}{14}144−2​​

Correct answer: (D)

Step-by-step solution →
Q69·Mathematics·Definite IntegrationInteger
If 24∫0π/4(sin⁡∣4x−π12∣+[2sin⁡x])dx=2π+α24\displaystyle\int_0^{\pi/4}\left(\sin\left|4x-\dfrac{\pi}{12}\right|+[2\sin x]\right)dx=2\pi+\alpha24∫0π/4​(sin​4x−12π​​+[2sinx])dx=2π+α, where [⋅][\cdot][⋅] denotes the greatest integer function, then α\alphaα is equal to ______.

Correct answer: 12

Step-by-step solution →
Q70·Mathematics·Limits and ContinuityInteger
If lim⁡t→0(∫01(3x+5)t dx)1t=α5e(85)23\displaystyle\lim_{t\to 0}\left(\int_0^1 (3x+5)^t\,dx\right)^{\frac{1}{t}}=\dfrac{\alpha}{5e}\left(\dfrac{8}{5}\right)^{\frac{2}{3}}t→0lim​(∫01​(3x+5)tdx)t1​=5eα​(58​)32​, then α\alphaα is equal to ______.

Correct answer: 64

Step-by-step solution →
Q71·Mathematics·Sequence and SeriesInteger
Let a1,a2,…,a2024a_1, a_2,\ldots,a_{2024}a1​,a2​,…,a2024​ be an Arithmetic Progression such that a1+(a5+a10+a15+⋯+a2020)+a2024=2233a_1+(a_5+a_{10}+a_{15}+\cdots+a_{2020})+a_{2024}=2233a1​+(a5​+a10​+a15​+⋯+a2020​)+a2024​=2233. Then a1+a2+a3+⋯+a2024a_1+a_2+a_3+\cdots+a_{2024}a1​+a2​+a3​+⋯+a2024​ is equal to ______.

Correct answer: 11132

Step-by-step solution →
Q72·Mathematics·Complex NumbersInteger
Let integers a,b∈[−3,3]a, b\in[-3, 3]a,b∈[−3,3] be such that a+b≠0a+b\ne 0a+b=0. Then the number of all possible ordered pairs (a,b)(a, b)(a,b), for which ∣z−az+b∣=1\left|\dfrac{z-a}{z+b}\right|=1​z+bz−a​​=1 and ∣z+1ωω2ωz+ω21ω21z+ω∣=1\begin{vmatrix}z+1 & \omega & \omega^2\\ \omega & z+\omega^2 & 1\\ \omega^2 & 1 & z+\omega\end{vmatrix}=1​z+1ωω2​ωz+ω21​ω21z+ω​​=1, z∈Cz\in Cz∈C, where ω\omegaω and ω2\omega^2ω2 are the roots of x2+x+1=0x^2+x+1=0x2+x+1=0, is equal to ______.

Correct answer: 10

Step-by-step solution →
Q73·Mathematics·ParabolaInteger
Let y2=12xy^2=12xy2=12x be the parabola and S be its focus. Let PQ be a focal chord of the parabola such that (SP)(SQ)=1474(SP)(SQ)=\dfrac{147}{4}(SP)(SQ)=4147​. Let C be the circle described taking PQ as a diameter. If the equation of a circle C is 64x2+64y2−αx−643 y=β64x^2+64y^2-\alpha x-64\sqrt{3}\,y=\beta64x2+64y2−αx−643​y=β, then β−α\beta-\alphaβ−α is equal to ______.

Correct answer: 1328

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Area Under Curves 139/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Ellipse 103/186
  • Differentiability 91/186
  • Diazonium Salts and Reactions 53/186
  • IUPAC Nomenclature 37/186
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