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JEE Main 21 January 2026 Shift 2 Question Paper with Answers

21 January 2026 · January session · 74 questions

74 of the 75 questions from the JEE Main 21 January 2026 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
25
Chemistry
24
Mathematics
25

Physics — JEE Main 21 January 2026 Shift 2

Q1·Physics·Electric PotentialSingle correct
Consider two identical metallic spheres of radius RRR each having charge QQQ and mass mmm. Their centers have an initial separation of 4R4R4R. Both the spheres are given an initial speed of uuu towards each other. The minimum value of u, so that they can just touch each other is : (Take k=14π∈0k = \frac{1}{4\pi \in_0}k=4π∈0​1​ and assume kQ2>Gm2kQ^2 > Gm^2kQ2>Gm2 where G is the Gravitational constant)
  1. (A)kQ24mR(1−Gm2kQ2)\sqrt{\frac{kQ^2}{4mR}\left(1 - \frac{Gm^2}{kQ^2}\right)}4mRkQ2​(1−kQ2Gm2​)​
  2. (B)kQ24mR(1+Gm2kQ2)\sqrt{\frac{kQ^2}{4mR}\left(1 + \frac{Gm^2}{kQ^2}\right)}4mRkQ2​(1+kQ2Gm2​)​
  3. (C)kQ22mR(1−Gm2kQ2)\sqrt{\frac{kQ^2}{2mR}\left(1 - \frac{Gm^2}{kQ^2}\right)}2mRkQ2​(1−kQ2Gm2​)​
  4. (D)kQ22mR(1−Gm22kQ2)\sqrt{\frac{kQ^2}{2mR}\left(1 - \frac{Gm^2}{2kQ^2}\right)}2mRkQ2​(1−2kQ2Gm2​)​

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
The charge stored by the capacitor C in the given circuit in the steady state is ………. μ\muμC.
  1. (A)12.5
  2. (B)10
  3. (C)7.5
  4. (D)5

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
The total length of potentiometer wire AB is 50 cm in the arrangement as shown in figure. If P is the point where the galvanometer shows zero reading then the length AP is ………. cm.
  1. (A)15
  2. (B)30
  3. (C)25
  4. (D)20

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A capacitor C is first charged fully with potential difference of V0V_0V0​ and disconnected from the battery. The charged capacitor is connected across an inductor having inductance L. In t s 25% of the initial energy in the capacitor is transferred to the inductor. The value of t is________s.
  1. (A)πLC3\frac{\pi\sqrt{LC}}{3}3πLC​​
  2. (B)πLC6\frac{\pi\sqrt{LC}}{6}6πLC​​
  3. (C)πLC2\frac{\pi\sqrt{LC}}{2}2πLC​​
  4. (D)πLC2\pi\sqrt{\frac{LC}{2}}π2LC​​

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
The r.m.s speed of oxygen molecules at 47∘47^\circ47∘C is equal to that of the hydrogen molecules kept at______∘^\circ∘C. (Mass of oxygen molecule/mass of hydrogen molecule=32/2)
  1. (A)−235
  2. (B)−100
  3. (C)−253
  4. (D)−20

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
Two cars A and B each of mass 10310^3103 kg are moving on parallel tracks separated by a distance of 10 m, in same direction with speeds 72 km/h and 36 km/h. The magnitude of angular momentum of car A with respect to car B is ___ J.s.
  1. (A)3.6×1053.6 \times 10^53.6×105
  2. (B)10510^5105
  3. (C)3×1053 \times 10^53×105
  4. (D)2×1052 \times 10^52×105

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
The pulley shown in figure is made using a thin rim and two rods of length equal to diameter of the rim. The rim and each rod have a mass of M. Two blocks of mass of M and m are attached to two ends of a light string passing over the pulley, which is hinged to rotate freely in vertical plane about its centre. The magnitudes of the acceleration experienced by the blocks is____ (assume no slipping of string on pulley.)
  1. (A)(M−m)g[(136)M+m]\frac{(M-m)g}{\left[\left(\frac{13}{6}\right)M + m\right]}[(613​)M+m](M−m)g​
  2. (B)(M−m)gM+m\frac{(M-m)g}{M+m}M+m(M−m)g​
  3. (C)(M−m)g[(83)M+m]\frac{(M-m)g}{\left[\left(\frac{8}{3}\right)M + m\right]}[(38​)M+m](M−m)g​
  4. (D)(M−m)g2M+m\frac{(M-m)g}{2M+m}2M+m(M−m)g​

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad/s. The frequency of this simple harmonic oscillator is_____Hz. [take π=227]\left[\text{take } \pi = \frac{22}{7}\right][take π=722​]
  1. (A)14
  2. (B)88
  3. (C)28
  4. (D)176

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
Given below are two statements: Statement I : In a Young's double slit experiment, the angular separation of fringes will increase as the screen is moved away from the plane of the slits Statement II : In a Young's double slit experiment, the angular separation of fringes will increase when monochromatic source is replaced by another monochromatic source of higher wavelength In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is false but Statement II is true
  4. (D)Statement I is true but Statement II is false

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
A battery with EMF E and internal resistance r is connected across a resistance R. The power consumption in R will be maximum when :
  1. (A)R=2rR = 2rR=2r
  2. (B)R=r2R = \frac{r}{2}R=2r​
  3. (C)R=2rR = \sqrt{2}rR=2​r
  4. (D)R=rR = rR=r

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
Keeping the significant figures in view, the sum of the physical quantities 52.01m, 153.2 m and 0.123 m is :
  1. (A)205 m
  2. (B)205.333 m
  3. (C)205.33 m
  4. (D)205.3 m

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
A spherical body of radius r and density σ falls freely through a viscous liquid having density ρ and viscosity η and attains a terminal velocity v0v_0v0​. Estimated maximum error in the quantity η is : (Ignore errors associated with σ, ρ and g, gravitational acceleration)
  1. (A)2Δrr−Δv0v02\frac{\Delta r}{r} - \frac{\Delta v_0}{v_0}2rΔr​−v0​Δv0​​
  2. (B)2Δrr+Δv0v0\frac{2\Delta r}{r} + \frac{\Delta v_0}{v_0}r2Δr​+v0​Δv0​​
  3. (C)2[Δrr+Δv0v0]2\left[\frac{\Delta r}{r} + \frac{\Delta v_0}{v_0}\right]2[rΔr​+v0​Δv0​​]
  4. (D)2[Δrr−Δv0v0]2\left[\frac{\Delta r}{r} - \frac{\Delta v_0}{v_0}\right]2[rΔr​−v0​Δv0​​]

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
Surface tension of two liquids (having same densities), T1T_1T1​ and T2T_2T2​, are measured using capillary rise method utilizing two tubes with inner radii of r1r_1r1​ and r2r_2r2​ where r1>r2r_1 > r_2r1​>r2​. The measured liquid heights in these tubes are h1h_1h1​ and h2h_2h2​ respectively. [Ignore the weight of the liquid about the lowest point of miniscus]. The heights h1h_1h1​ and h2h_2h2​ and surface tensions T1T_1T1​ and T2T_2T2​ satisfy the relation :
  1. (A)h1<h2h_1 < h_2h1​<h2​ and T1=T2T_1 = T_2T1​=T2​
  2. (B)h1=h2h_1 = h_2h1​=h2​ and T1=T2T_1 = T_2T1​=T2​
  3. (C)h1>h2h_1 > h_2h1​>h2​ and T1=T2T_1 = T_2T1​=T2​
  4. (D)h1>h2h_1 > h_2h1​>h2​ and T1<T2T_1 < T_2T1​<T2​

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
A river of width 200 m is flowing from west to east with a speed of 18 km/h. A boat, moving with speed of 36 km/h in still water, is made to travel one-round trip (bank to bank of the river). Minimum time taken by the boat for this journey and also the displacement along the river bank are ______ and ______ respectively.
  1. (A)20 s and 100 m
  2. (B)40 s and 0 m
  3. (C)40 s and 200 m
  4. (D)40 s and 100 m

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
Two known resistance of R Ω\OmegaΩ and 2R Ω\OmegaΩ and and one unknown resistance X Ω\OmegaΩ are connected in a circuit as shown in the figure. If the equivalent resistance between points A and B in the circuit is X Ω\OmegaΩ, then the value of X is ________ Ω\OmegaΩ.
  1. (A)(3−1)R\left(\sqrt{3}-1\right)\text{R}(3​−1)R
  2. (B)R\text{R}R
  3. (C)2(3−1)R2\left(\sqrt{3}-1\right)\text{R}2(3​−1)R
  4. (D)(3+1)R\left(\sqrt{3}+1\right)\text{R}(3​+1)R

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
The energy of an electron in an orbit of the Bohr's atom is −0.04E0-0.04\text{E}_0−0.04E0​ eV where E0\text{E}_0E0​ is the ground state energy. If L is the angular momentum of the electron in this orbit and h is the Planck's constant, then 2πLh\dfrac{2\pi\text{L}}{\text{h}}h2πL​ is __________ :
  1. (A)2
  2. (B)4
  3. (C)5
  4. (D)6

Correct answer: (C)

Step-by-step solution →
Q17·Physics·Magnetic Field of CurrentSingle correct
An infinitely long straight wire carrying current I is bent in a planer shape as shown in the diagram. The radius of the circular part is r. The magnetic field at the centre O of the circular loop is :
  1. (A)μ02πIr(π+1)i^\dfrac{\mu_0}{2\pi}\dfrac{\text{I}}{\text{r}}\left(\pi+1\right)\hat{\text{i}}2πμ0​​rI​(π+1)i^
  2. (B)−μ02πIr(π−1)i^-\dfrac{\mu_0}{2\pi}\dfrac{\text{I}}{\text{r}}\left(\pi-1\right)\hat{\text{i}}−2πμ0​​rI​(π−1)i^
  3. (C)μ02πIr(π−1)i^\dfrac{\mu_0}{2\pi}\dfrac{\text{I}}{\text{r}}\left(\pi-1\right)\hat{\text{i}}2πμ0​​rI​(π−1)i^
  4. (D)−μ02πIr(π+1)i^-\dfrac{\mu_0}{2\pi}\dfrac{\text{I}}{\text{r}}\left(\pi+1\right)\hat{\text{i}}−2πμ0​​rI​(π+1)i^

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
A large drum having radius R is spinning around its axis with angular velocity ω\omegaω, as shown in figure. The minimum value of ω\omegaω so that a body of mass M remains stuck to the inner wall of the drum, taking the coefficient of friction between the drum surface and mass M is μ\muμ, is :
  1. (A)μgR\sqrt{\dfrac{\mu\text{g}}{\text{R}}}Rμg​​
  2. (B)2gμR\sqrt{\dfrac{2\text{g}}{\mu\text{R}}}μR2g​​
  3. (C)g2μR\sqrt{\dfrac{\text{g}}{2\mu\text{R}}}2μRg​​
  4. (D)gμR\sqrt{\dfrac{\text{g}}{\mu\text{R}}}μRg​​

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
A body of mass 2 kg is moving along x-direction such that its displacement as function of time is given by x(t)=αt2+βt+γ m\text{x(t)} = \alpha\text{t}^2 + \beta\text{t} + \gamma\,\text{m}x(t)=αt2+βt+γm, where α=1 m/s2\alpha = 1\ \text{m/s}^2α=1 m/s2, β=1\beta = 1β=1 m/s and γ=1\gamma = 1γ=1m. The work done on the body during the time interval t = 2 s to t = 3 s, is ________ J.
  1. (A)49
  2. (B)42
  3. (C)24
  4. (D)12

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
As shown in the diagram, when the incident ray is parallel to base of the prism, the emergent ray grazes along the second surface. If refractive index of the material of prism is 2\sqrt{2}2​, the angle θ\thetaθ of prism is.
  1. (A)60°
  2. (B)75°
  3. (C)90°
  4. (D)45°

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
An electromagnetic wave of frequency 100 MHz propagates through a medium of conductivity, σ=10\sigma = 10σ=10 mho/m. The ratio of maximum conducting current density to maximum displacement current density is __________. [Take 14π∈0=9×109 Nm2/C2]\left[\text{Take }\dfrac{1}{4\pi\in_0} = 9\times10^9\,\text{Nm}^2/\text{C}^2\right][Take 4π∈0​1​=9×109Nm2/C2]

Correct answer: 1800

Step-by-step solution →
Q22·PhysicsNumerical
The terminal velocity of a metallic ball of radius 6 mm in a viscous fluid is 20 cm/s. The terminal velocity of another ball of same material and having radius 3 mm in the same fluid will be ________ cm/s.

Correct answer: 5

Step-by-step solution →
Q23·PhysicsNumerical
A particle having electric charge 3×10−193\times10^{-19}3×10−19 C and mass 6×10−276\times10^{-27}6×10−27 kg is accelerated by applying an electric potential of 1.21 V. Wavelength of the matter wave associated with the particle is α×10−12\alpha\times10^{-12}α×10−12 m. The value of α\alphaα is __________. (Take Planck's constant =6.6×10−34= 6.6\times10^{-34}=6.6×10−34 J.s)

Correct answer: 10

Step-by-step solution →
Q24·PhysicsNumerical
In a Young's double slit experiment set up, the two slits are kept 0.4. mm apart and screen is placed at 1 m from slits. If a thin transparent sheet of thickness 20 μm is introduced in front of one of the slits then centre bring fringe shifts by 20 mm on the screen. The refractive index of transparent sheet is given by α10\dfrac{\alpha}{10}10α​, where α\alphaα is ________.

Correct answer: 14

Step-by-step solution →
Q25·PhysicsNumerical
A diatomic gas (γ=1.4\gamma = 1.4γ=1.4) does 100 J of work when it is expanded isobarically. Then the heat given to the gas __________ J.

Correct answer: 350

Step-by-step solution →

Chemistry — JEE Main 21 January 2026 Shift 2

Q26·ChemistrySingle correct
Consider the following spectral lines for atomic hydrogen: A. First line of Paschen series B. Second line of Balmer series C. Third line of Paschen series D. Fourth line of Bracket sereis The correct arrangement of the above lines in ascending order of energy is:
  1. (A)D<C<A<B\text{D} < \text{C} < \text{A} < \text{B}D<C<A<B
  2. (B)A<B<C<D\text{A} < \text{B} < \text{C} < \text{D}A<B<C<D
  3. (C)C<D<B<A\text{C} < \text{D} < \text{B} < \text{A}C<D<B<A
  4. (D)D<A<C<B\text{D} < \text{A} < \text{C} < \text{B}D<A<C<B

Correct answer: (D)

Step-by-step solution →
Q27·Chemistry·IsomerismSingle correct
Match List-I (Pair of Compounds) with List-II (Type of Isomers). Choose the correct answer from the options given below:
Pair of CompoundsType of Isomers
A.2-Methylpropene and but-1-eneI.Stereoisomers
B.Cis-but-2-ene and trans-but-2-eneII.Position isomers
C.2-Butanol and diethyl etherIII.Chain isomers
D.But-1-ene and but-2-eneIV.Functional group isomers
  1. (A)A-III, B-I, C-IV, D-II
  2. (B)A-III, B-I, C-II, D-IV
  3. (C)A-I, B-IV, C-III, D-II
  4. (D)A-II, B-I, C-IV, D-III

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correct
(1) Br2/FeBr3/Δ\text{Br}_{2}/\text{FeBr}_{3}/\DeltaBr2​/FeBr3​/Δ (2) Sn/HCl/Δ\text{Sn}/\text{HCl}/\DeltaSn/HCl/Δ (3) pH neutralisation (4) Br2/H2O\text{Br}_{2}/\text{H}_{2}\text{O}Br2​/H2​O (5) NaNO2/HBr\text{NaNO}_{2}/\text{HBr}NaNO2​/HBr, 0-5∘^{\circ}∘C (6) CuBr/NaBr\text{CuBr}/\text{NaBr}CuBr/NaBr →\rightarrow→ Major Product (P) Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be:
  1. (A)1
  2. (B)6
  3. (C)5
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correct
Aqueous HCl reacts with MnO2(s)\text{MnO}_{2}\text{(s)}MnO2​(s) to form MnCl2(aq)\text{MnCl}_{2}\text{(aq)}MnCl2​(aq), Cl2(g)\text{Cl}_{2}\text{(g)}Cl2​(g) and H2O(l)\text{H}_{2}\text{O}(l)H2​O(l). What is the weight (in g) of Cl2\text{Cl}_{2}Cl2​ liberated when 8.7 g of MnO2(s)\text{MnO}_{2}\text{(s)}MnO2​(s) is reacted with excess aqueous HCl solution ? (Given Molar mass in g mol−1\text{g mol}^{-1}g mol−1 Mn = 55, Cl = 35.5, O = 16, H = 1)
  1. (A)7.1
  2. (B)71
  3. (C)21.3
  4. (D)14.2

Correct answer: (A)

Step-by-step solution →
Q30·ChemistrySingle correct
By usual analysis, 1.00g of compound (X) gave 1.79g of magnesium pyrophosphate. The percentage of phosphorus in compound (X) is: (nearest integer) (Given, molar mass in g mol−1\text{g mol}^{-1}g mol−1: O = 16, Mg = 24, P = 31)
  1. (A)50
  2. (B)30
  3. (C)20
  4. (D)40

Correct answer: (A)

Step-by-step solution →
Q31·ChemistrySingle correct
Consider the following data: ΔfH⊖\Delta_{\text{f}}\text{H}^{\ominus}Δf​H⊖(methane, g) = −X kJ mol−1-\text{X kJ mol}^{-1}−X kJ mol−1 Enthalpy of sublimation of graphite = Y kJ mol−1\text{Y kJ mol}^{-1}Y kJ mol−1 Dissociation enthalpy of H2\text{H}_{2}H2​ = Z kJ mol−1\text{Z kJ mol}^{-1}Z kJ mol−1 The bond enthalpy of C −-− H bond is given by:
  1. (A)X+Y+2Z4\frac{\text{X} + \text{Y} + 2\text{Z}}{4}4X+Y+2Z​
  2. (B)X+Y+4Z2\frac{\text{X} + \text{Y} + 4\text{Z}}{2}2X+Y+4Z​
  3. (C)X+Y+Z\text{X} + \text{Y} + \text{Z}X+Y+Z
  4. (D)−X+Y+Z4\frac{-\text{X} + \text{Y} + \text{Z}}{4}4−X+Y+Z​

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
Match List-I (Reagents) with List-II (Reaction Name (Involving aldehydes)). Choose the correct answer from the options given below:
ReagentsReaction Name (Involving aldehydes)
A.extH2 ext{H}_{2}extH2​, extPd−BaSO4 ext{Pd-BaSO}_{4}extPd−BaSO4​I.Etard Reaction
B.extSnCl2 ext{SnCl}_{2}extSnCl2​, HClII.Rosenmund Reduction
C.extCrO2extCl2 ext{CrO}_{2} ext{Cl}_{2}extCrO2​extCl2​, extCS2 ext{CS}_{2}extCS2​III.Gatterman - Koch Reaction
D.extCO,HCl ext{CO,HCl}extCO,HCl, Anhyd. extAlCl3 ext{AlCl}_{3}extAlCl3​IV.Stephen Reaction
  1. (A)A-II, B-III, C-IV, D-I
  2. (B)A-IV, B-III, C-I, D-II
  3. (C)A-IV, B-I, C-II, D-III
  4. (D)A-II, B-IV, C-I, D-III

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
Decomposition of A is a first order reaction at T(K) and is given by A(g)→B(g)+C(g)\text{A(g)} \rightarrow \text{B(g)} + \text{C(g)}A(g)→B(g)+C(g). In a closed 1 L vessel, 1 bar A(g) is allowed to decompose at T(K). After 100 minutes, the total pressure was 1.5 bar. What is the rate constant (in min−1\text{min}^{-1}min−1) of the reaction ? (log 2 = 0.3)
  1. (A)6.9×10−16.9 \times 10^{-1}6.9×10−1
  2. (B)6.9×10−36.9 \times 10^{-3}6.9×10−3
  3. (C)6.9×10−26.9 \times 10^{-2}6.9×10−2
  4. (D)6.9×10−46.9 \times 10^{-4}6.9×10−4

Correct answer: (B)

Step-by-step solution →
Q34·ChemistrySingle correct
The correct order of reactivity of the following benzyl halides towards reaction with KCN is:
  1. (A)a > b > c > d
  2. (B)b > a > d > c
  3. (C)b > a > c > d
  4. (D)a > b > d > d

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are two statements: Statement-I: The correct order in terms of atomic/ionic radii is Al>Mg>Mg2+>Al3+\text{Al} > \text{Mg} > \text{Mg}^{2+} > \text{Al}^{3+}Al>Mg>Mg2+>Al3+. Statement-II: The correct order in terms of the magnitude of electron gain enthalpy is Cl>Br>S>O\text{Cl} > \text{Br} > \text{S} > \text{O}Cl>Br>S>O. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is false but Statement II is true
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are true

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
The correct statements are: A. Activation energy for enzyme catalysed hydrolysis of sucrose is lower than that of acid catalysed hydrolysis. B. During denaturation, secondary and tertiary structures of a protein are destroyed but primary structure remains intact. C. Nucleotides are joined together by glycosidic linkage between C1\text{C}_{1}C1​ and C4\text{C}_{4}C4​ carbons of the pentose sugar D. Quaternary structure of proteins represents overall folding of the polypeptide chain. Choose the correct answer from the options given below:
  1. (A)A, C and D Only
  2. (B)A, B and D Only
  3. (C)A and B Only
  4. (D)B and C Only

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
The correct order of the rate of the reaction for the following reaction with respect to nucleophiles is: CH3Br+Nu⊖⟶CH3Nu+Br⊖\text{CH}_{3}\text{Br} + \text{Nu}^{\ominus} \longrightarrow \text{CH}_{3}\text{Nu} + \text{Br}^{\ominus}CH3​Br+Nu⊖⟶CH3​Nu+Br⊖
  1. (A)PhO−>−OH>CH3COO−>ClO4−\text{PhO}^{-} > {}^{-}\text{OH} > \text{CH}_{3}\text{COO}^{-} > \text{ClO}_{4}^{-}PhO−>−OH>CH3​COO−>ClO4−​
  2. (B)ClO4−>CH3COO−>−OH>PhO−\text{ClO}_{4}^{-} > \text{CH}_{3}\text{COO}^{-} > {}^{-}\text{OH} > \text{PhO}^{-}ClO4−​>CH3​COO−>−OH>PhO−
  3. (C)CH3COO−>PhO−>−OH>ClO4−\text{CH}_{3}\text{COO}^{-} > \text{PhO}^{-} > {}^{-}\text{OH} > \text{ClO}_{4}^{-}CH3​COO−>PhO−>−OH>ClO4−​
  4. (D)−OH>PhO−>CH3COO−>ClO4−{}^{-}\text{OH} > \text{PhO}^{-} > \text{CH}_{3}\text{COO}^{-} > \text{ClO}_{4}^{-}−OH>PhO−>CH3​COO−>ClO4−​

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
Given below are two statements: Statement I: Crystal Field Stabilization Energy (CFSE) of [Cr(H2O)6]2+\text{[Cr(H}_{2}\text{O)}_{6}\text{]}^{2+}[Cr(H2​O)6​]2+ is greater than that of [Mn(H2O)6]2+\text{[Mn(H}_{2}\text{O)}_{6}\text{]}^{2+}[Mn(H2​O)6​]2+. Statement II: Potassium ferricyanide has a greater spin-only magnetic moment than sodium Ferrocyanide. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
The correct increasing order of C−H(A)\text{C}-\text{H}(\text{A})C−H(A), C−O(B)\text{C}-\text{O}(\text{B})C−O(B), C=O(C)\text{C}=\text{O}(\text{C})C=O(C) and C≡N(D)\text{C}\equiv \text{N}(\text{D})C≡N(D) bonds in terms of covalent bond length is:
  1. (A)A<B<C<D\text{A} < \text{B} < \text{C} < \text{D}A<B<C<D
  2. (B)A<D<C<B\text{A} < \text{D} < \text{C} < \text{B}A<D<C<B
  3. (C)D<C<B<A\text{D} < \text{C} < \text{B} < \text{A}D<C<B<A
  4. (D)D<C<A<B\text{D} < \text{C} < \text{A} < \text{B}D<C<A<B

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Given below are four compounds: (a) n-propyl choride (b) iso-propyl chloride (c) sec-butyl chloride (d) neo-pentyl chloride Percentage of carbon in the one which exhibits optical isomerism is:
  1. (A)52
  2. (B)56
  3. (C)46
  4. (D)40

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Given below are some of the statements about Mn and Mn2O7\text{Mn}_{2}\text{O}_{7}Mn2​O7​. Identify the correct statements A. Mn forms the oxide Mn2O7\text{Mn}_{2}\text{O}_{7}Mn2​O7​ in which Mn is in its highest oxidation state. B. Oxygen stabilizes the Mn in higher oxidation states by forming multiple bonds with Mn C. Mn2O7\text{Mn}_{2}\text{O}_{7}Mn2​O7​ is an ionic oxide. D. The structure of Mn2O7\text{Mn}_{2}\text{O}_{7}Mn2​O7​ consists of one bridged oxygen. Choose the correct answer from the options given below:
  1. (A)A, B, C and D
  2. (B)A, B and D Only
  3. (C)A, C and D Only
  4. (D)A, B and C Only

Correct answer: (B)

Step-by-step solution →
Q42·Chemistry·Electronic Effects and StabilitySingle correct
Given below are two statements : Statement −-− I : Compound (X), shown below , dissolves in NaHCO3\text{NaHCO}_{3}NaHCO3​ solution and has two chiral carbon atoms Statement −-− II : Compound (Y), shown below, has two carbons with sp3\text{sp}^{3}sp3 hybridization, one carbon with sp2\text{sp}^{2}sp2 and one carbon with sp hybridization In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Statement I is true but Statement II is false
  2. (B)Statement I is false but Statement II is true
  3. (C)Both Statement I and Statement II are true
  4. (D)Both Statement I and Statement II are false

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
Given below are two statements : Statement I : The correct order in terms of bond dissociation enthalpy is Cl2>Br2>F2>I2\text{Cl}_{2} > \text{Br}_{2} > \text{F}_{2} > \text{I}_{2}Cl2​>Br2​>F2​>I2​ Statement II : The correct trend in the covalent character of the metal halides is [SnCl4>SnCl2][\text{SnCl}_{4} > \text{SnCl}_{2}][SnCl4​>SnCl2​], [PbCl4>PbCl2][\text{PbCl}_{4} > \text{PbCl}_{2}][PbCl4​>PbCl2​] and [UF4>UF6][\text{UF}_{4} > \text{UF}_{6}][UF4​>UF6​] In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are false

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
On heating a mixture of common salt and K2Cr2O7\text{K}_{2}\text{Cr}_{2}\text{O}_{7}K2​Cr2​O7​ in equal amount along with concentrated H2SO4\text{H}_{2}\text{SO}_{4}H2​SO4​ in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are :
  1. (A)CrO2Cl2\text{CrO}_{2}\text{Cl}_{2}CrO2​Cl2​ and +5+5+5
  2. (B)CrO2Cl2\text{CrO}_{2}\text{Cl}_{2}CrO2​Cl2​ and +6+6+6
  3. (C)Cr2O2Cl2\text{Cr}_{2}\text{O}_{2}\text{Cl}_{2}Cr2​O2​Cl2​ and +6+6+6
  4. (D)Cr2O2Cl2\text{Cr}_{2}\text{O}_{2}\text{Cl}_{2}Cr2​O2​Cl2​ and +3+3+3

Correct answer: (B)

Step-by-step solution →
Q45·ChemistryNumerical
The first and second ionization constants of H2X\text{H}_{2}\text{X}H2​X are 2.5×10−82.5 \times 10^{-8}2.5×10−8 and 1.0×10−131.0 \times 10^{-13}1.0×10−13 respectively. The concentration of X2−\text{X}^{2-}X2− in 0.1 M H2X\text{H}_{2}\text{X}H2​X solution is _______ ×10−15\times 10^{-15}×10−15 M. (Nearest Integer)

Correct answer: 100

Step-by-step solution →
Q46·ChemistryNumerical
The osmotic pressure of a living cell in 12 atm at 300 K. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is ________ g L−1\text{g L}^{-1}g L−1. (Nearest integer) Given : R=0.08\text{R} = 0.08R=0.08 L atm K−1\text{K}^{-1}K−1 mol−1\text{mol}^{-1}mol−1 Assume complete dissociation of NaCl (Given : Molar mass of Na and Cl are 23 and 35.5 g mol−1\text{g mol}^{-1}g mol−1 respectively.)

Correct answer: 15

Step-by-step solution →
Q47·ChemistryNumerical
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass =300= 300=300 g mol−1\text{g mol}^{-1}g mol−1) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is _________ ×10−2\times 10^{-2}×10−2. (Nearest integer) [Given : Kb\text{K}_{\text{b}}Kb​ of the solvent =5.0= 5.0=5.0 K kg mol−1\text{mol}^{-1}mol−1] Assume the solution to be dilute and no association or dissociation of X takes place in solution.

Correct answer: 3

Step-by-step solution →
Q48·ChemistryNumerical
Identify the metal ions among Co2+\text{Co}^{2+}Co2+, Ni2+\text{Ni}^{2+}Ni2+, Fe2+\text{Fe}^{2+}Fe2+, V3+\text{V}^{3+}V3+ and Ti2+\text{Ti}^{2+}Ti2+ having a spin-only magnetic moment value more than 3.0 BM. The sum of unpaired electrons present in the high spin octahedral complexes formed by those metal ions is ________.

Correct answer: 7

Step-by-step solution →
Q49·ChemistryNumerical
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K MX(s)⇌M+(aq)+X−(aq)\text{MX(s)} \rightleftharpoons \text{M}^{+}\text{(aq)} + \text{X}^{-}\text{(aq)}MX(s)⇌M+(aq)+X−(aq) ; Ksp=10−10\text{K}_{\text{sp}} = 10^{-10}Ksp​=10−10 If the standard reduction potential for M+(aq)→+e−M(s)\text{M}^{+}\text{(aq)} \xrightarrow{+e^{-}} \text{M(s)}M+(aq)+e−​M(s) is (EM+/M⊖)=0.79V\left(\text{E}^{\ominus}_{\text{M}^{+}/\text{M}}\right) = 0.79\text{V}(EM+/M⊖​)=0.79V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode EX−/MX(s)/M⊖\text{E}^{\ominus}_{\text{X}^{-}/\text{MX(s)}/\text{M}}EX−/MX(s)/M⊖​ is _________ mV. (nearest integer) [Given: 2.303RTF=0.059V\frac{2.303\text{RT}}{\text{F}} = 0.059\text{V}F2.303RT​=0.059V]

Correct answer: 200

Step-by-step solution →

Mathematics — JEE Main 21 January 2026 Shift 2

Q50·MathematicsSingle correct
The positive integer n, for which the solutions of the equation x(x+2)+(x+2)(x+4)+…+(x+2n−2)(x+2n)=8n3x(x+2) + (x + 2)(x + 4) + \ldots + (x + 2n - 2)(x+2n) = \frac{8n}{3}x(x+2)+(x+2)(x+4)+…+(x+2n−2)(x+2n)=38n​ are two consecutive even integers, is :-
  1. (A)3
  2. (B)6
  3. (C)12
  4. (D)9

Correct answer: (A)

Step-by-step solution →
Q51·MathematicsSingle correct
Let f:R→Rf : \mathbf{R} \to \mathbf{R}f:R→R be a twice differentiable function such that f′′(x)>0f''(x) > 0f′′(x)>0 for all x∈R\mathbf{R}R and f′(a−1)=0f'(a - 1) = 0f′(a−1)=0, where a is real number. Let g(x)=f(tan⁡2x−2tan⁡x+a)g(x) = f(\tan^2 x - 2\tan x + a)g(x)=f(tan2x−2tanx+a), 0<x<π20 < x < \frac{\pi}{2}0<x<2π​. Consider the following two statements : (I) g is increasing in (0,π4)\left(0, \frac{\pi}{4}\right)(0,4π​) (II) g is decreasing in (π4,π2)\left(\frac{\pi}{4}, \frac{\pi}{2}\right)(4π​,2π​) Then,
  1. (A)Neither (I) nor (II) is True
  2. (B)Only (II) is True
  3. (C)Only (I) is True
  4. (D)Both (I) and (II) are True

Correct answer: (A)

Step-by-step solution →
Q52·Mathematics·DifferentiabilitySingle correct
Let f(x)=x3+x2f′(1)+2xf′′(2)+f′′′(3)f(x) = x^3 + x^2 f'(1) + 2x f''(2) + f'''(3)f(x)=x3+x2f′(1)+2xf′′(2)+f′′′(3), x ∈ R. Then the value of f′(5)f'(5)f′(5) is :
  1. (A)625\frac{62}{5}562​
  2. (B)6575\frac{657}{5}5657​
  3. (C)25\frac{2}{5}52​
  4. (D)1175\frac{117}{5}5117​

Correct answer: (D)

Step-by-step solution →
Q53·MathematicsSingle correct
In the line αx+4y=7\alpha x + 4y = \sqrt{7}αx+4y=7​, where α ∈ R, touches the ellipse 3x2+4y2=13x^2 + 4y^2 = 13x2+4y2=1 at the point P in the first quadrant, then one of the focal distances of P is :
  1. (A)13−1211\frac{1}{\sqrt{3}} - \frac{1}{2\sqrt{11}}3​1​−211​1​
  2. (B)13+125\frac{1}{\sqrt{3}} + \frac{1}{2\sqrt{5}}3​1​+25​1​
  3. (C)13−125\frac{1}{\sqrt{3}} - \frac{1}{2\sqrt{5}}3​1​−25​1​
  4. (D)13+127\frac{1}{\sqrt{3}} + \frac{1}{2\sqrt{7}}3​1​+27​1​

Correct answer: (D)

Step-by-step solution →
Q54·MathematicsSingle correct
Let y2=12xy^2 = 12xy2=12x be the parabola with its vertex at O. Let P be a point on the parabola and A be a point on the x-axis such that ∠OPA = 90°. Then the locus of the centroid of such triangles OPA is :
  1. (A)y2−6x+4=0y^2 - 6x + 4 = 0y2−6x+4=0
  2. (B)y2−9x+6=0y^2 - 9x + 6 = 0y2−9x+6=0
  3. (C)y2−2x+8=0y^2 - 2x + 8 = 0y2−2x+8=0
  4. (D)y2−4x+8=0y^2 - 4x + 8 = 0y2−4x+8=0

Correct answer: (C)

Step-by-step solution →
Q55·MathematicsSingle correct
Let one end of a focal chord of the parabola y2=16xy^2 = 16xy2=16x be (16, 16). If P(α, β) divides this focal chord internally in the ratio 5 : 2, then the minimum value of α + β is equal to :
  1. (A)22
  2. (B)7
  3. (C)5
  4. (D)16

Correct answer: (B)

Step-by-step solution →
Q56·MathematicsSingle correct
Let the line L pass through the point (−3, 5, 2) and make equal angles with the positive coordinate axes. If the distance of L from the point (−2, r, 1) is 143\sqrt{\frac{14}{3}}314​​, then the sum of all possible values of r is :
  1. (A)12
  2. (B)16
  3. (C)6
  4. (D)10

Correct answer: (D)

Step-by-step solution →
Q57·MathematicsSingle correct
Let the line L1L_1L1​ be parallel to the vector −3i^+2j^+4k^-3\hat{i} + 2\hat{j} + 4\hat{k}−3i^+2j^​+4k^ and pass through the point (2, 6, 7) and the line L2L_2L2​ be parallel to the vector 2i^+j^+3k^2\hat{i} + \hat{j} + 3\hat{k}2i^+j^​+3k^ and pass through the point (4, 3, 5). If the line L3L_3L3​ is parallel to the vector −3i^+5j^+16k^-3\hat{i} + 5\hat{j} + 16\hat{k}−3i^+5j^​+16k^ and intersects the lines L1L_1L1​ and L2L_2L2​ at the points C and D, respectively, then ∣CD→∣2\left|\overrightarrow{CD}\right|^2​CD​2 is equal to :
  1. (A)171
  2. (B)290
  3. (C)312
  4. (D)89

Correct answer: (B)

Step-by-step solution →
Q58·MathematicsSingle correct
Let α and β be the roots of equation x2+2ax+(3a+10)=0x^2 + 2ax + (3a + 10) = 0x2+2ax+(3a+10)=0 such that α < 1 < β. Then the set of all possible values of a is :
  1. (A)(−∞,−115)∪(5,∞)\left(-\infty, \frac{-11}{5}\right) \cup (5, \infty)(−∞,5−11​)∪(5,∞)
  2. (B)(−∞,−2)∪(5,∞)(-\infty, -2) \cup (5, \infty)(−∞,−2)∪(5,∞)
  3. (C)(−∞,−3)(-\infty, -3)(−∞,−3)
  4. (D)(−∞,−115)\left(-\infty, \frac{-11}{5}\right)(−∞,5−11​)

Correct answer: (D)

Step-by-step solution →
Q59·MathematicsSingle correct
A random variable X takes values 0, 1, 2, 3 with probabilities 2a+130,8a−130,4a+130\frac{2a+1}{30}, \frac{8a-1}{30}, \frac{4a+1}{30}302a+1​,308a−1​,304a+1​, b respectively, where a, b ∈R\mathbf{R}R. Let μ and σ respectively be the mean and standard deviation of X such that σ2+μ2=2\sigma^2 + \mu^2 = 2σ2+μ2=2. Then ab\frac{a}{b}ba​ is equal to :
  1. (A)30
  2. (B)3
  3. (C)60
  4. (D)12

Correct answer: (C)

Step-by-step solution →
Q60·MathematicsSingle correct
If the area of the region {(x,y):1−2x≤y≤4−x2,x≥0,y≥0}\{(x, y) : 1 - 2x \le y \le 4 - x^2, x \ge 0, y \ge 0\}{(x,y):1−2x≤y≤4−x2,x≥0,y≥0} is αβ\frac{\alpha}{\beta}βα​, α, β, ∈ N, gcd (α, β) = 1, then the value of (α + β) is :
  1. (A)73
  2. (B)85
  3. (C)91
  4. (D)67

Correct answer: (A)

Step-by-step solution →
Q61·MathematicsSingle correct
Let a1,a22,a322,…,a1029a_1, \frac{a_2}{2}, \frac{a_3}{2^2}, \ldots, \frac{a_{10}}{2^9}a1​,2a2​​,22a3​​,…,29a10​​ be a G.P. of common ratio 12\frac{1}{\sqrt{2}}2​1​. If a1+a2+…+a10=62a_1 + a_2 + \ldots + a_{10} = 62a1​+a2​+…+a10​=62, then a1a_1a1​ is equal to :
  1. (A)2(2−1)2\left(\sqrt{2} - 1\right)2(2​−1)
  2. (B)2−22 - \sqrt{2}2−2​
  3. (C)2−1\sqrt{2} - 12​−1
  4. (D)2(2−2)2(2 - \sqrt{2})2(2−2​)

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let A={x:∣x2−10∣≤6}A = \{x : |x^2 - 10| \le 6\}A={x:∣x2−10∣≤6} and B={x:∣x−2∣>1}B = \{x : |x - 2| > 1\}B={x:∣x−2∣>1}. Then
  1. (A)A∪B=(−∞,1]∪(2,∞)A \cup B = (-\infty, 1] \cup (2, \infty)A∪B=(−∞,1]∪(2,∞)
  2. (B)A−B=[2,3)A - B = [2, 3)A−B=[2,3)
  3. (C)A∩B=[−4,−2]∪[3,4]A \cap B = [-4, -2] \cup [3, 4]A∩B=[−4,−2]∪[3,4]
  4. (D)B−A=(−∞,−4)∪(−2,1)∪(4,∞)B - A = (-\infty, -4) \cup (-2, 1) \cup (4, \infty)B−A=(−∞,−4)∪(−2,1)∪(4,∞)

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
For the matrices A=[3−41−1]A = \begin{bmatrix} 3 & -4 \\ 1 & -1 \end{bmatrix}A=[31​−4−1​] and B=[−2949−1318]B = \begin{bmatrix} -29 & 49 \\ -13 & 18 \end{bmatrix}B=[−29−13​4918​], if (A15+B)[xy]=[00](A^{15} + B)\begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} 0 \\ 0 \end{bmatrix}(A15+B)[xy​]=[00​], then among the following which one is true?
  1. (A)x=5x = 5x=5, y=7y = 7y=7
  2. (B)x=18x = 18x=18, y=11y = 11y=11
  3. (C)x=11x = 11x=11, y=2y = 2y=2
  4. (D)x=16x = 16x=16, y=3y = 3y=3

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
For a triangle ABC, let p⃗=BC→\vec{p} = \overrightarrow{BC}p​=BC, q⃗=CA→\vec{q} = \overrightarrow{CA}q​=CA and r⃗=BA→\vec{r} = \overrightarrow{BA}r=BA. If ∣p⃗∣=23|\vec{p}| = 2\sqrt{3}∣p​∣=23​, ∣q⃗∣=2|\vec{q}| = 2∣q​∣=2 and cos⁡θ=13\cos\theta = \frac{1}{\sqrt{3}}cosθ=3​1​, where θ\thetaθ is the angle between P⃗\vec{P}P and q⃗\vec{q}q​, then ∣p⃗×(q⃗−3r⃗)∣2+3∣r⃗∣2\left|\vec{p} \times \left(\vec{q} - 3\vec{r}\right)\right|^{2} + 3\left|\vec{r}\right|^{2}∣p​×(q​−3r)∣2+3∣r∣2 is equal to:
  1. (A)340
  2. (B)220
  3. (C)410
  4. (D)200

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation sec⁡xdydx−2y=2+3sin⁡x\sec x \frac{dy}{dx} - 2y = 2 + 3\sin xsecxdxdy​−2y=2+3sinx, x∈(−π2,π2)x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)x∈(−2π​,2π​), y(0)=−74y(0) = -\frac{7}{4}y(0)=−47​. Then y(π6)y\left(\frac{\pi}{6}\right)y(6π​) is equal to:
  1. (A)−52-\frac{5}{2}−25​
  2. (B)−54-\frac{5}{4}−45​
  3. (C)−33−7-3\sqrt{3} - 7−33​−7
  4. (D)−32−7-3\sqrt{2} - 7−32​−7

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let A={2,3,5,7,9}A = \{2, 3, 5, 7, 9\}A={2,3,5,7,9}. Let R be the relation on A defined by xxx R yyy if and only if 2x≤3y2x \le 3y2x≤3y. Let ℓ\ellℓ be the number of elements in R, and m be the minimum number of elements required to be added in R to make it a symmetric relation. Then ℓ+m\ell + mℓ+m is equal to:
  1. (A)23
  2. (B)25
  3. (C)21
  4. (D)27

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
If the system of equations 3x+y+4z=33x + y + 4z = 33x+y+4z=3 2x+αy−z=−32x + \alpha y - z = -32x+αy−z=−3 X+2y+z=4X + 2y + z = 4X+2y+z=4 has no solution, then the value of α\alphaα is equal to:
  1. (A)19
  2. (B)4
  3. (C)13
  4. (D)23

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
Let z be the complex number satisfying ∣z−5∣≤3|z - 5| \le 3∣z−5∣≤3 and having maximum positive principal argument. Then 34∣5z−125iz+16∣234\left|\frac{5z - 12}{5iz + 16}\right|^{2}34​5iz+165z−12​​2 is equal to:
  1. (A)16
  2. (B)12
  3. (C)26
  4. (D)20

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correct
The largest n∈Nn \in Nn∈N, for which 7n7^{n}7n divides 101!101!101!, is :
  1. (A)16
  2. (B)18
  3. (C)15
  4. (D)19

Correct answer: (A)

Step-by-step solution →
Q70·Mathematics·Limits and ContinuityNumerical
Let [⋅][\cdot][⋅] denote the greatest integer function and f(x)=lim⁡n→∞1n3∑k=1n[k23x]f(x) = \lim_{n \to \infty} \frac{1}{n^{3}} \sum_{k=1}^{n} \left[\frac{k^{2}}{3^{x}}\right]f(x)=limn→∞​n31​∑k=1n​[3xk2​]. Then 12∑j=1∞f(j)12\sum_{j=1}^{\infty} f(j)12∑j=1∞​f(j) is equal to _______.

Correct answer: 2

Step-by-step solution →
Q71·MathematicsNumerical
If ∫014cot⁡−1(1−2x+4x2)dx=atan⁡−1(2)−blog⁡e(5)\int_{0}^{1} 4\cot^{-1}(1 - 2x + 4x^{2})dx = a\tan^{-1}(2) - b\log_{e}(5)∫01​4cot−1(1−2x+4x2)dx=atan−1(2)−bloge​(5), where a,b∈Na, b \in Na,b∈N, then (2a+b)(2a + b)(2a+b) is equal to _______.

Correct answer: 9

Step-by-step solution →
Q72·MathematicsNumerical
Let the maximum value of (sin⁡−1x)2+(cos⁡−1x)2(\sin^{-1}x)^{2} + (\cos^{-1}x)^{2}(sin−1x)2+(cos−1x)2 for x∈[−32,12]x \in \left[-\frac{\sqrt{3}}{2}, \frac{1}{\sqrt{2}}\right]x∈[−23​​,2​1​] be mnπ2\frac{m}{n}\pi^{2}nm​π2, where gcd (m,n)=1(m, n) = 1(m,n)=1. Then m+nm + nm+n is equal to _______.

Correct answer: 65

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Q73·MathematicsNumerical
If (115C0+115C1)(115C1+115C2)⋯(115C12+115C13)=α1314C0 14C1⋯14C12\left(\frac{1}{{}^{15}C_{0}} + \frac{1}{{}^{15}C_{1}}\right)\left(\frac{1}{{}^{15}C_{1}} + \frac{1}{{}^{15}C_{2}}\right)\cdots\left(\frac{1}{{}^{15}C_{12}} + \frac{1}{{}^{15}C_{13}}\right) = \frac{\alpha^{13}}{{}^{14}C_{0}\,{}^{14}C_{1}\cdots{}^{14}C_{12}}(15C0​1​+15C1​1​)(15C1​1​+15C2​1​)⋯(15C12​1​+15C13​1​)=14C0​14C1​⋯14C12​α13​, then 30α30\alpha30α is equal to _______.

Correct answer: 32

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Q74·MathematicsNumerical
If P is a point on the circle x2+y2=4x^{2} + y^{2} = 4x2+y2=4, Q is a point on the straight line 5x+y+2=05x + y + 2 = 05x+y+2=0 and x−y+1=0x - y + 1 = 0x−y+1=0 is the perpendicular bisector of PQ, then 13 times the sum of abscissa of all such point P is _______.

Correct answer: 2

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Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Atomic Structure 161/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Ellipse 103/186
  • Differentiability 91/186
  • Inverse Trigonometric Functions 93/186
  • Electronic Effects and Stability 74/186
  • Electric Potential 63/186
  • Diazonium Salts and Reactions 53/186
  • Isomerism 51/186
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