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JEE Main 26 August 2021 Shift 1 Question Paper with Answers

26 August 2021 · August session · 85 questions

85 of the 90 questions from the JEE Main 26 August 2021 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

5 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
28
Chemistry
30
Mathematics
27

Physics — JEE Main 26 August 2021 Shift 1

Q1·PhysicsSingle correct
The fractional change in the magnetic field intensity at a distance 'r' from centre on the axis of current carrying coil of radius 'a' to the magnetic field intensity at the centre of the same coil is : (Take r < a)
  1. (A)32a2r2\frac{3}{2}\frac{a^2}{r^2}23​r2a2​
  2. (B)23a2r2\frac{2}{3}\frac{a^2}{r^2}32​r2a2​
  3. (C)23r2a2\frac{2}{3}\frac{r^2}{a^2}32​a2r2​
  4. (D)32r2a2\frac{3}{2}\frac{r^2}{a^2}23​a2r2​

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
Car B overtakes another car A at a relative speed of 40 ms−1ms^{-1}ms−1. How fast will the image of car B appear to move in the mirror of focal length 10 cm fitted in car A, when the car B is 1.9 m away from the car A?
  1. (A)4 ms−1ms^{-1}ms−1
  2. (B)0.2 ms−1ms^{-1}ms−1
  3. (C)40 ms−1ms^{-1}ms−1
  4. (D)0.1 ms−1ms^{-1}ms−1

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
Inside a uniform spherical shell : (a) the gravitational field is zero (b) the gravitational potential is zero (c) the gravitational field is same everywhere (d) the gravitation potential is same everywhere (e) all of the above Choose the most appropriate answer from the options given below :
  1. (A)(a), (c) and (d) only
  2. (B)(e) only
  3. (C)(a), (b) and (c) only
  4. (D)(b), (c) and (d) only

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
Two narrow bores of diameter 5.0 mm and 8.0 mm are joined together to form a U-shaped tube open at both ends. If this U-tube contains water, what is the difference in the level of two limbs of the tube. [Take surface tension of water T = 7.3 ×\times× 10−210^{-2}10−2 Nm−1Nm^{-1}Nm−1, angle of contact = 0, g = 10 ms−2ms^{-2}ms−2 and density of water = 1.0 ×\times× 10310^{3}103 kg m−3m^{-3}m−3]
  1. (A)3.62 mm
  2. (B)2.19 mm
  3. (C)5.34 mm
  4. (D)4.97 mm

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
An electric appliance supplies 6000 J/min heat to the system. If the system delivers a power of 90W. How long it would take to increase the internal energy by 2.5 ×\times× 10310^{3}103 J ?
  1. (A)2.5 ×\times× 10210^{2}102 s
  2. (B)4.1 ×\times× 10110^{1}101s
  3. (C)2.4 ×\times× 10310^{3}103 s
  4. (D)2.5 ×\times× 10110^{1}101s

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
An inductor coil stores 64 J of magnetic field energy and dissipates energy at the rate of 640 W when a current of 8A is passed through it. If this coil is joined across an ideal battery, find the time constant of the circuit in seconds :
  1. (A)0.4
  2. (B)0.8
  3. (C)0.125
  4. (D)0.2

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
A series LCR circuit driven by 300 V at a frequency of 50 Hz contains a resistance R = 3 kΩ\OmegaΩ, an inductor of inductive reactance XLX_LXL​ = 250 πΩ\pi\OmegaπΩ and an unknown capacitor. The value of capacitance to maximize the average power should be : (Take π2\pi^2π2 = 10)
  1. (A)4 μ\muμF
  2. (B)25 μ\muμF
  3. (C)400 μ\muμF
  4. (D)40 μ\muμF

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
Identify the logic operation carried out by the given circuit :-
  1. (A)OR
  2. (B)AND
  3. (C)NOR
  4. (D)NAND

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A particular hydrogen like ion emits radiation of frequency 2.92 ×\times× 101510^{15}1015 Hz when it makes transition from n = 3 to n = 1. The frequency in Hz of radiation emitted in transition from n = 2 to n = 1 will be :
  1. (A)0.44 ×\times× 101510^{15}1015
  2. (B)6.57 ×\times× 101510^{15}1015
  3. (C)4.38 ×\times× 101510^{15}1015
  4. (D)2.46 ×\times× 101510^{15}1015

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
In a photoelectric experiment ultraviolet light of wavelength 280 nm is used with lithium cathode having work function ϕ\phiϕ = 2.5 eV. If the wavelength of incident light is switched to 400 nm, find out the change in the stopping potential. (h = 6.63 ×\times× 10−3410^{-34}10−34 Js, c = 3 ×\times× 10810^{8}108 ms−1ms^{-1}ms−1)
  1. (A)1.3 V
  2. (B)1.1 V
  3. (C)1.9 V
  4. (D)0.6 V

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6Ω\OmegaΩ. Calculate the power dissipated in the whole circuit :
  1. (A)1.32 W
  2. (B)0.65 W
  3. (C)2.2 W
  4. (D)4.4 W

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correct
The rms speeds of the molecules of Hydrogen, Oxygen and Carbondioxide at the same temperature are VHV_HVH​, VOV_OVO​ and VCV_CVC​ respectively then :
  1. (A)VH>VO>VCV_H > V_O > V_CVH​>VO​>VC​
  2. (B)VC>VO>VHV_C > V_O > V_HVC​>VO​>VH​
  3. (C)VH=VO>VCV_H = V_O > V_CVH​=VO​>VC​
  4. (D)VH=VO=VCV_H = V_O = V_CVH​=VO​=VC​

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
In a Screw Gauge, fifth division of the circular scale coincides with the reference line when the ratchet is closed. There are 50 divisions on the circular scale, and the main scale moves by 0.5 mm on a complete rotation. For a particular observation the reading on the main scale is 5 mm and the 20th20^{th}20th division of the circular scale coincides with reference line. Calculate the true reading.
  1. (A)5.00 mm
  2. (B)5.25 mm
  3. (C)5.15 mm
  4. (D)5.20 mm

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
What equal length of an iron wire and a copper-nickel alloy wire, each of 2 mm diameter connected parallel to give an equivalent resistance of 3Ω\OmegaΩ? (Given resistivities of iron and copper-nickel alloy wire are 12 μΩ\mu\OmegaμΩ cm and 51 μΩ\mu\OmegaμΩ cm respectively)
  1. (A)82 m
  2. (B)97 m
  3. (C)110 m
  4. (D)90 m

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
The initial mass of a rocket is 1000 kg. Calculate at what rate the fuel should be burnt so that the rocket is given an acceleration of 20 ms−2ms^{-2}ms−2. The gases come out at a relative speed of 500 ms−1ms^{-1}ms−1 with respect to the rocket :[Use g = 10 m/s2m/s^{2}m/s2]
  1. (A)6.0 ×\times× 10210^{2}102 kg s−1s^{-1}s−1
  2. (B)500 kg s−1s^{-1}s−1
  3. (C)10 kg s−1s^{-1}s−1
  4. (D)60 kg s−1s^{-1}s−1

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
If E, L, M and G denote the quantities as energy, angular momentum, mass and constant of gravitation respectively, then the dimensions of P in the formula P = EL2M−5G−2EL^{2}M^{-5}G^{-2}EL2M−5G−2 are :-
  1. (A)[M0 L1 T0][M^{0}\,L^{1}\,T^{0}][M0L1T0]
  2. (B)[M−1 L−1 T2][M^{-1}\,L^{-1}\,T^{2}][M−1L−1T2]
  3. (C)[M1 L1 T−2][M^{1}\,L^{1}\,T^{-2}][M1L1T−2]
  4. (D)[M0 L0 T0][M^{0}\,L^{0}\,T^{0}][M0L0T0]

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
The material filled between the plates of a parallel plate capacitor has resistivity 200 Ω\OmegaΩm. The value of capacitance of the capacitor is 2 pF. If a potential difference of 40 V is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is : (given the value of relative permitivity of material is 50)
  1. (A)9.0 μ\muμA
  2. (B)9.0 mA
  3. (C)0.9 mA
  4. (D)0.9 μ\muμA

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
Statement-I : By doping silicon semiconductor with pentavalent material, the electrons density increases. Statement-II : The n-type semiconductor has net negative charge. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Statement-I is true but Statement-II is false.
  2. (B)Statement-I is false but Statement-II is true.
  3. (C)Both Statement-I and Statement-II are true.
  4. (D)Both Statement-I and Statement-II are false.

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsNumerical
A uniform chain of length 3 meter and mass 3 kg overhangs a smooth table with 2 meter laying on the table. If k is the kinetic energy of the chain in joule as it completely slips off the table, then the value of k is ........... . (Take g=10 m/s2g = 10\ \mathrm{m/s^2}g=10 m/s2)

Correct answer: 40

Step-by-step solution →
Q20·PhysicsNumerical
The electric field in a plane electromagnetic wave is given by E⃗=200cos⁡[(0.5×103m)x−(1.5×1011rads×t)]Vm j^\vec{E} = 200\cos\left[\left(\dfrac{0.5\times 10^{3}}{\mathrm{m}}\right)x - \left(1.5\times 10^{11}\dfrac{\mathrm{rad}}{\mathrm{s}}\times t\right)\right]\dfrac{\mathrm{V}}{\mathrm{m}}\ \hat{j}E=200cos[(m0.5×103​)x−(1.5×1011srad​×t)]mV​ j^​ If this wave falls normally on a perfectly reflecting surface having an area of 100 cm2100\ \mathrm{cm^2}100 cm2. If the radiation pressure exerted by the E.M. wave on the surface during a 10 minute exposure is x109Nm2\dfrac{x}{10^{9}}\dfrac{\mathrm{N}}{\mathrm{m^2}}109x​m2N​. Find the value of x.

Correct answer: 354

Step-by-step solution →
Q21·PhysicsNumerical
A source and a detector move away from each other in absence of wind with a speed of 20 m/s with respect to the ground. If the detector detects a frequency of 1800 Hz of the sound coming from the source, then the original frequency of source considering speed of sound in air 340 m/s will be ........ Hz.

Correct answer: 2025

Step-by-step solution →
Q22·PhysicsNumerical
Two spherical balls having equal masses with radius of 5 cm each are thrown upwards along the same vertical direction at an interval of 3s with the same initial velocity of 35 m/s, then these balls collide at a height of .......... m. (Take g=10 m/s2g = 10\ \mathrm{m/s^2}g=10 m/s2)

Correct answer: 50

Step-by-step solution →
Q23·PhysicsNumerical
A soap bubble of radius 3 cm is formed inside the another soap bubble of radius 6 cm. The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is ........ cm.

Correct answer: 2

Step-by-step solution →
Q24·PhysicsNumerical
An amplitude modulated wave is represented by Cm(t)=10(1+0.2cos⁡12560t)sin⁡(111×104t)C_m(t) = 10(1 + 0.2\cos 12560t)\sin(111\times 10^{4}t)Cm​(t)=10(1+0.2cos12560t)sin(111×104t) volts. The modulating frequency in kHz will be ....... .

Correct answer: 2

Step-by-step solution →
Q25·PhysicsNumerical
Two short magnetic dipoles m1m_1m1​ and m2m_2m2​ each having magnetic moment of 1 Am21\ \mathrm{Am^2}1 Am2 are placed at point O and P respectively. The distance between OP is 1 meter. The torque experienced by the magnetic dipole m2m_2m2​ due to the presence of m1m_1m1​ is ...... ×10−7\times 10^{-7}×10−7 Nm.

Correct answer: 1

Step-by-step solution →
Q26·PhysicsNumerical
Two travelling waves produces a standing wave represented by equation, y=1.0 mm cos⁡(1.57 cm−1) x sin⁡(78.5 s−1)t.y = 1.0\ \mathrm{mm}\ \cos(1.57\ \mathrm{cm^{-1}})\ x\ \sin(78.5\ \mathrm{s^{-1}})t.y=1.0 mm cos(1.57 cm−1) x sin(78.5 s−1)t. The node closest to the origin in the region x>0x > 0x>0 will be at x=x = x= ......... cm.

Correct answer: 1

Step-by-step solution →
Q27·PhysicsNumerical
White light is passed through a double slit and interference is observed on a screen 1.5 m away. The separation between the slits is 0.3 mm. The first violet and red fringes are formed 2.0 mm and 3.5 mm away from the central white fringes. The difference in wavelengths of red and voilet light is ......... nm.

Correct answer: 300

Step-by-step solution →
Q28·PhysicsNumerical
Consider a badminton racket with length scales as shown in the figure. If the mass of the linear and circular portions of the badminton racket are same (M) and the mass of the threads are negligible, the moment of inertia of the racket about an axis perpendicular to the handle and in the plane of the ring at, r2\dfrac{r}{2}2r​ distance from the end A of the handle will be ........ Mr2\mathrm{Mr^2}Mr2.

Correct answer: 52

Step-by-step solution →

Chemistry — JEE Main 26 August 2021 Shift 1

Q29·ChemistrySingle correct
Which one of the following complexes is violet in colour?
  1. (A)[Fe(CN)6]4−[\mathrm{Fe(CN)_6}]^{4-}[Fe(CN)6​]4−
  2. (B)[Fe(SCN)6]4−[\mathrm{Fe(SCN)_6}]^{4-}[Fe(SCN)6​]4−
  3. (C)Fe4[Fe(CN)6]3⋅H2O\mathrm{Fe_4[Fe(CN)_6]_3 \cdot H_2O}Fe4​[Fe(CN)6​]3​⋅H2​O
  4. (D)[Fe(CN)5NOS]4−[\mathrm{Fe(CN)_5NOS}]^{4-}[Fe(CN)5​NOS]4−

Correct answer: (D)

Step-by-step solution →
Q30·ChemistrySingle correct
Which one of the following is correct for the adsorption of a gas at a given temperature on a solid surface?
  1. (A)ΔH>0, ΔS>0\Delta H > 0,\ \Delta S > 0ΔH>0, ΔS>0
  2. (B)ΔH>0, ΔS<0\Delta H > 0,\ \Delta S < 0ΔH>0, ΔS<0
  3. (C)ΔH<0, ΔS<0\Delta H < 0,\ \Delta S < 0ΔH<0, ΔS<0
  4. (D)ΔH<0, ΔS>0\Delta H < 0,\ \Delta S > 0ΔH<0, ΔS>0

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
Which one of the following when dissolved in water gives coloured solution in nitrogen atmosphere?
  1. (A)CuCl2\mathrm{CuCl_2}CuCl2​
  2. (B)AgCl\mathrm{AgCl}AgCl
  3. (C)ZnCl2\mathrm{ZnCl_2}ZnCl2​
  4. (D)Cu2Cl2\mathrm{Cu_2Cl_2}Cu2​Cl2​

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
The major products formed in the following reaction sequence A\mathbf{A}A and B\mathbf{B}B are :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
The major product formed in the following reaction is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
The major product formed in the following reaction is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
The polymer formed on heating Novolac with formaldehyde is :
  1. (A)Bakelite
  2. (B)Polyester
  3. (C)Melamine
  4. (D)Nylon 6,6

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Given below are two statements : Statement I : The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH\mathrm{CH_3COOH}CH3​COOH (weak electrolyte). Statement II : Molar conductivity decreases with decrease in concentration of electrolyte. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Statement I is true but Statement II is false.
  2. (B)Statement I is false but Statement II is true.
  3. (C)Both Statement I and Statement II are true.
  4. (D)Both Statement I and Statement II are false.

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
The correct options for the products A\mathbf{A}A and B\mathbf{B}B of the following reactions are :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
The conversion of hydroxyapatite occurs due to presence of F−\mathrm{F^-}F− ions in water. The correct formula of hydroxyapatite is:
  1. (A)[3Ca3(PO4)2⋅Ca(OH)2][3\mathrm{Ca_3(PO_4)_2} \cdot \mathrm{Ca(OH)_2}][3Ca3​(PO4​)2​⋅Ca(OH)2​]
  2. (B)[3Ca(OH)2⋅CaF2][3\mathrm{Ca(OH)_2} \cdot \mathrm{CaF_2}][3Ca(OH)2​⋅CaF2​]
  3. (C)[Ca3(PO4)2⋅CaF2][\mathrm{Ca_3(PO_4)_2} \cdot \mathrm{CaF_2}][Ca3​(PO4​)2​⋅CaF2​]
  4. (D)[3Ca3(PO4)2⋅CaF2][3\mathrm{Ca_3(PO_4)_2} \cdot \mathrm{CaF_2}][3Ca3​(PO4​)2​⋅CaF2​]

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
Given below are two statements. Statement I: In the titration between strong acid and weak base methyl orange is suitable as an indicator. Statement II: For titration of acetic acid with NaOH phenolphthalein is not a suitable indicator. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are true
  4. (D)Both Statement I and Statement II are false

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Among the following compounds I-IV, which one forms a yellow precipitate on reacting sequentially with (i) NaOH (ii) dil. HNO3\mathrm{HNO_3}HNO3​ (iii) AgNO3\mathrm{AgNO_3}AgNO3​?
  1. (A)II
  2. (B)IV
  3. (C)I
  4. (D)III

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Which one of the following methods is most suitable for preparing deionized water?
  1. (A)Synthetic resin method
  2. (B)Clark's method
  3. (C)Calgon's method
  4. (D)Permutit method

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
Given below are two statements. Statement I: The choice of reducing agents for metals extraction can be made by using Ellingham diagram, a plot of ΔG\Delta GΔG vs temperature. Statement II: The value of ΔS\Delta SΔS increases from left to right in Ellingham diagram. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Statement I is false but Statement II is true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is true but Statement II is false

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
What are the products formed in sequence when excess of CO2\mathrm{CO_2}CO2​ is passed in slaked lime?
  1. (A)Ca(HCO3)2\mathrm{Ca(HCO_3)_2}Ca(HCO3​)2​, CaCO3\mathrm{CaCO_3}CaCO3​
  2. (B)CaCO3\mathrm{CaCO_3}CaCO3​, Ca(HCO3)2\mathrm{Ca(HCO_3)_2}Ca(HCO3​)2​
  3. (C)CaO\mathrm{CaO}CaO, Ca(HCO3)2\mathrm{Ca(HCO_3)_2}Ca(HCO3​)2​
  4. (D)CaO\mathrm{CaO}CaO, CaCO3\mathrm{CaCO_3}CaCO3​

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
Given below are two statements. Statement I: According to Bohr's model of an atom, qualitatively the magnitude of velocity of electron increases with decrease in positive charges on the nucleus as there is no strong hold on the electron by the nucleus. Statement II: According to Bohr's model of an atom, qualitatively the magnitude of velocity of electron increases with decrease in principal quantum number. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is false but Statement II is true
  4. (D)Statement I is true but Statement II is false

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
The correct sequential addition of reagents in the preparation of 3-nitrobenzoic acid from benzene is:
  1. (A)Br2/AlBr3\mathrm{Br_2/AlBr_3}Br2​/AlBr3​, HNO3/H2SO4\mathrm{HNO_3/H_2SO_4}HNO3​/H2​SO4​, Mg/ether, CO2\mathrm{CO_2}CO2​, H3O+\mathrm{H_3O^+}H3​O+
  2. (B)Br2/AlBr3\mathrm{Br_2/AlBr_3}Br2​/AlBr3​, NaCN, H3O+\mathrm{H_3O^+}H3​O+, HNO3/H2SO4\mathrm{HNO_3/H_2SO_4}HNO3​/H2​SO4​
  3. (C)Br2/AlBr3\mathrm{Br_2/AlBr_3}Br2​/AlBr3​, HNO3/H2SO4\mathrm{HNO_3/H_2SO_4}HNO3​/H2​SO4​, NaCN, H3O+\mathrm{H_3O^+}H3​O+
  4. (D)HNO3/H2SO4\mathrm{HNO_3/H_2SO_4}HNO3​/H2​SO4​, Br2/AlBr3\mathrm{Br_2/AlBr_3}Br2​/AlBr3​, Mg/ether, CO2\mathrm{CO_2}CO2​, H3O+\mathrm{H_3O^+}H3​O+

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
Given below are two statements. Statement I: Frenkel defects are vacancy as well as interstitial defects. Statement II: Frenkel defect leads to colour in ionic solids due to presence of F-centres. Choose the most appropriate answer for the statements from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are false

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
The incorrect statement is:
  1. (A)Cl2\mathrm{Cl_2}Cl2​ is more reactive than ClF.
  2. (B)F2\mathrm{F_2}F2​ is more reactive than ClF.
  3. (C)On hydrolysis ClF froms HOCl and HF.
  4. (D)F2\mathrm{F_2}F2​ is a stronger oxidizing agent than Cl2\mathrm{Cl_2}Cl2​ in aqueous solution

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
Excess of isobutane on reaction with Br2\mathrm{Br_2}Br2​ in presence of light at 125∘C125^\circ\mathrm{C}125∘C gives which one of the following, as the major product?
  1. (A)CH3−CBrCH3−CH2−Br\mathrm{CH_3-\underset{CH_3}{\overset{Br}{C}}-CH_2-Br}CH3​−CH3​CBr​−CH2​−Br
  2. (B)CH3−CHCH2Br−CH2Br\mathrm{CH_3-\underset{CH_2Br}{CH}-CH_2Br}CH3​−CH2​BrCH​−CH2​Br
  3. (C)CH3−CHCH3−CH2Br\mathrm{CH_3-\underset{CH_3}{CH}-CH_2Br}CH3​−CH3​CH​−CH2​Br
  4. (D)CH3−CCH3CH3−Br\mathrm{CH_3-\underset{CH_3}{\overset{CH_3}{C}}-Br}CH3​−CH3​CCH3​​−Br

Correct answer: (D)

Step-by-step solution →
Q49·ChemistryNumerical
AB3AB_3AB3​ is an interhalogen T-shaped molecule. The number of lone pairs of electrons on A is ________. (Integer answer)

Correct answer: 2

Step-by-step solution →
Q50·ChemistryNumerical
These are physical properties of an element (A) Sublimation enthalpy (B) Ionisation enthalpy (C) Hydration enthalpy (D) Electron gain enthalpy The total number of above properties that affect the reduction potential is _________ (Integer answer)

Correct answer: 3

Step-by-step solution →
Q51·ChemistryNumerical
Of the following four aqueous solutions, total number of those solutions whose freezing point is lower than that of 0.10 M C2H5OH0.10\ M\ C_2H_5OH0.10 M C2​H5​OH is ________ (Integer answer) (i) 0.10 M Ba3(PO4)20.10\ M\ Ba_3(PO_4)_20.10 M Ba3​(PO4​)2​ (ii) 0.10 M Na2SO40.10\ M\ Na_2SO_40.10 M Na2​SO4​ (iii) 0.10 M KCl0.10\ M\ KCl0.10 M KCl (iv) 0.10 M Li3PO40.10\ M\ Li_3PO_40.10 M Li3​PO4​

Correct answer: 4

Step-by-step solution →
Q52·ChemistryNumerical
The OH−OH^-OH− concentration in a mixture of 5.0 mL of 0.0504 M NH4Cl0.0504\ M\ NH_4Cl0.0504 M NH4​Cl and 2 mL of 0.0210 M NH30.0210\ M\ NH_30.0210 M NH3​ solution is x×10−6x \times 10^{-6}x×10−6 M. The value of x is ________. (Nearest integer) [Given Kw=1×10−14K_w = 1 \times 10^{-14}Kw​=1×10−14 and Kb=1.8×10−5K_b = 1.8 \times 10^{-5}Kb​=1.8×10−5]

Correct answer: 3

Step-by-step solution →
Q53·ChemistryNumerical
The number of 4f4f4f electrons in the ground state electronic configuration of Gd2+Gd^{2+}Gd2+ is _________. [Atomic number of Gd = 64]

Correct answer: 7

Step-by-step solution →
Q54·ChemistryNumerical
The ratio of number of water molecules in Mohr's salt and potash alum is _________ ×10−1\times 10^{-1}×10−1. (Integer answer)

Correct answer: 5

Step-by-step solution →
Q55·ChemistryNumerical
The following data was obtained for chemical reaction given below at 975 K. 2NO(g)+2H2(g)→N2(g)+2H2O(g)2NO_{(g)} + 2H_{2(g)} \rightarrow N_{2(g)} + 2H_2O_{(g)}2NO(g)​+2H2(g)​→N2(g)​+2H2​O(g)​ [NO][NO][NO] (mol L−1L^{-1}L−1), [H2][H_2][H2​] (mol L−1L^{-1}L−1), Rate (mol L−1s−1L^{-1}s^{-1}L−1s−1) (A) 8×10−58 \times 10^{-5}8×10−5, 8×10−58 \times 10^{-5}8×10−5, 7×10−97 \times 10^{-9}7×10−9 (B) 24×10−524 \times 10^{-5}24×10−5, 8×10−58 \times 10^{-5}8×10−5, 2.1×10−82.1 \times 10^{-8}2.1×10−8 (C) 24×10−524 \times 10^{-5}24×10−5, 32×10−532 \times 10^{-5}32×10−5, 8.4×10−88.4 \times 10^{-8}8.4×10−8 The order of the reaction with respect to NO is ________. [Integer answer]

Correct answer: 1

Step-by-step solution →
Q56·ChemistryNumerical
The Born-Haber cycle for KCl is evaluated with the following data : ΔfH⊖\Delta_f H^\ominusΔf​H⊖ for KCl=−436.7 kJ mol−1KCl = -436.7\ kJ\ mol^{-1}KCl=−436.7 kJ mol−1; ΔsubH⊖\Delta_{sub} H^\ominusΔsub​H⊖ for K=89.2 kJ mol−1K = 89.2\ kJ\ mol^{-1}K=89.2 kJ mol−1; ΔionizationH⊖\Delta_{ionization} H^\ominusΔionization​H⊖ for K=419.0 kJ mol−1K = 419.0\ kJ\ mol^{-1}K=419.0 kJ mol−1; Δelectron gainH⊖\Delta_{electron\ gain} H^\ominusΔelectron gain​H⊖ for Cl(g)=−348.6 kJ mol−1Cl_{(g)} = -348.6\ kJ\ mol^{-1}Cl(g)​=−348.6 kJ mol−1; ΔbondH⊖\Delta_{bond} H^\ominusΔbond​H⊖ for Cl2=243.0 kJ mol−1Cl_2 = 243.0\ kJ\ mol^{-1}Cl2​=243.0 kJ mol−1 The magnitude of lattice enthalpy of KCl in kJ mol−1kJ\ mol^{-1}kJ mol−1 is ________ (Nearest integer)

Correct answer: 718

Step-by-step solution →
Q57·ChemistryNumerical
The total number of negative charge in the tetrapeptide, Gly-Glu-Asp-Tyr, at pH 12.5 will be _________. (Integer answer)

Correct answer: 4

Step-by-step solution →
Q58·ChemistryNumerical
An aqueous KCl solution of density 1.20 g mL−11.20\ g\ mL^{-1}1.20 g mL−1 has a molality of 3.30 mol kg−13.30\ mol\ kg^{-1}3.30 mol kg−1. The molarity of the solution in mol L−1mol\ L^{-1}mol L−1 is ________ (Nearest integer) [Molar mass of KCl = 74.5]

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 26 August 2021 Shift 1

Q59·MathematicsSingle correct
The sum of solutions of the equation cos⁡x1+sin⁡x=∣tan⁡2x∣\frac{\cos x}{1+\sin x} = |\tan 2x|1+sinxcosx​=∣tan2x∣, x∈(−π2,π2)−{π4,−π4}x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) - \left\{\frac{\pi}{4}, -\frac{\pi}{4}\right\}x∈(−2π​,2π​)−{4π​,−4π​} is :
  1. (A)−11π30-\frac{11\pi}{30}−3011π​
  2. (B)π10\frac{\pi}{10}10π​
  3. (C)−7π30-\frac{7\pi}{30}−307π​
  4. (D)−π15-\frac{\pi}{15}−15π​

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
The mean and standard deviation of 20 observations were calculated as 10 and 2.5 respectively. It was found that by mistake one data value was taken as 25 instead of 35. If α\alphaα and β\sqrt{\beta}β​ are the mean and standard deviation respectively for correct data, then (α,β)(\alpha, \beta)(α,β) is :
  1. (A)(11,26)(11, 26)(11,26)
  2. (B)(10.5,25)(10.5, 25)(10.5,25)
  3. (C)(11,25)(11, 25)(11,25)
  4. (D)(10.5,26)(10.5, 26)(10.5,26)

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
On the ellipse x28+y24=1\frac{x^2}{8} + \frac{y^2}{4} = 18x2​+4y2​=1 let P be a point in the second quadrant such that the tangent at P to the ellipse is perpendicular to the line x+2y=0x + 2y = 0x+2y=0. Let S and S' be the foci of the ellipse and e be its eccentricity. If A is the area of the triangle SPS' then, the value of (5−e2)(5 - e^2)(5−e2). A is :
  1. (A)6
  2. (B)12
  3. (C)14
  4. (D)24

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be a solution curve of the differential equation (y+1)tan⁡2x dx+tan⁡x dy+y dx=0(y + 1)\tan^2 x\, dx + \tan x\, dy + y\, dx = 0(y+1)tan2xdx+tanxdy+ydx=0, x∈(0,π2)x \in \left(0, \frac{\pi}{2}\right)x∈(0,2π​). If lim⁡x→0+xy(x)=1\lim_{x \to 0+} xy(x) = 1limx→0+​xy(x)=1, then the value of y(π4)y\left(\frac{\pi}{4}\right)y(4π​) is :
  1. (A)−π4-\frac{\pi}{4}−4π​
  2. (B)π4−1\frac{\pi}{4} - 14π​−1
  3. (C)π4+1\frac{\pi}{4} + 14π​+1
  4. (D)π4\frac{\pi}{4}4π​

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
Let A and B be independent events such that P(A)=pP(A) = pP(A)=p, P(B)=2pP(B) = 2pP(B)=2p. The largest value of p, for which P (exactly one of A, B occurs) =59= \frac{5}{9}=95​, is :
  1. (A)13\frac{1}{3}31​
  2. (B)29\frac{2}{9}92​
  3. (C)49\frac{4}{9}94​
  4. (D)512\frac{5}{12}125​

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
Let θ∈(0,π2)\theta \in \left(0, \frac{\pi}{2}\right)θ∈(0,2π​). If the system of linear equations (1+cos⁡2θ)x+sin⁡2θ y+4sin⁡3θ z=0(1 + \cos^2\theta)x + \sin^2\theta\, y + 4\sin 3\theta\, z = 0(1+cos2θ)x+sin2θy+4sin3θz=0 cos⁡2θ x+(1+sin⁡2θ) y+4sin⁡3θ z=0\cos^2\theta\, x + (1 + \sin^2\theta)\, y + 4\sin 3\theta\, z = 0cos2θx+(1+sin2θ)y+4sin3θz=0 cos⁡2θ x+sin⁡2θ y+(1+4sin⁡3θ) z=0\cos^2\theta\, x + \sin^2\theta\, y + (1 + 4\sin 3\theta)\, z = 0cos2θx+sin2θy+(1+4sin3θ)z=0 has a non-trivial solution, then the value of θ\thetaθ is :
  1. (A)4π9\frac{4\pi}{9}94π​
  2. (B)7π18\frac{7\pi}{18}187π​
  3. (C)π18\frac{\pi}{18}18π​
  4. (D)5π18\frac{5\pi}{18}185π​

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let f(x)=cos⁡(2tan⁡−1sin⁡(cot⁡−11−xx))f(x) = \cos\left(2\tan^{-1}\sin\left(\cot^{-1}\sqrt{\frac{1-x}{x}}\right)\right)f(x)=cos(2tan−1sin(cot−1x1−x​​)), 0<x<10 < x < 10<x<1. Then :
  1. (A)(1−x)2f′(x)−2(f(x))2=0(1 - x)^2 f'(x) - 2(f(x))^2 = 0(1−x)2f′(x)−2(f(x))2=0
  2. (B)(1+x)2f′(x)+2(f(x))2=0(1 + x)^2 f'(x) + 2(f(x))^2 = 0(1+x)2f′(x)+2(f(x))2=0
  3. (C)(1−x)2f′(x)+2(f(x))2=0(1 - x)^2 f'(x) + 2(f(x))^2 = 0(1−x)2f′(x)+2(f(x))2=0
  4. (D)(1+x)2f′(x)−2(f(x))2=0(1 + x)^2 f'(x) - 2(f(x))^2 = 0(1+x)2f′(x)−2(f(x))2=0

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
If 20Cr^{20}C_r20Cr​ is the co-efficient of xrx^rxr in the expansion of (1+x)20(1 + x)^{20}(1+x)20, then the value of ∑r=020r2 20Cr\sum_{r=0}^{20} r^2\, ^{20}C_r∑r=020​r220Cr​ is equal to :
  1. (A)420×219420 \times 2^{19}420×219
  2. (B)380×219380 \times 2^{19}380×219
  3. (C)380×218380 \times 2^{18}380×218
  4. (D)420×218420 \times 2^{18}420×218

Correct answer: (D)

Step-by-step solution →
Q67·MathematicsSingle correct
Out of all the patients in a hospital 89% are found to be suffering from heart ailment and 98% are suffering from lungs infection. If K% of them are suffering from both ailments, then K can not belong to the set :
  1. (A){80,83,86,89}\{80, 83, 86, 89\}{80,83,86,89}
  2. (B){84,86,88,90}\{84, 86, 88, 90\}{84,86,88,90}
  3. (C){79,81,83,85}\{79, 81, 83, 85\}{79,81,83,85}
  4. (D){84,87,90,93}\{84, 87, 90, 93\}{84,87,90,93}

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
The equation arg⁡(z−1z+1)=π4\arg\left(\frac{z-1}{z+1}\right) = \frac{\pi}{4}arg(z+1z−1​)=4π​ represents a circle with:
  1. (A)centre at (0,−1)(0, -1)(0,−1) and radius 2\sqrt{2}2​
  2. (B)centre at (0,1)(0, 1)(0,1) and radius 2\sqrt{2}2​
  3. (C)centre at (0,0)(0,0)(0,0) and radius 2\sqrt{2}2​
  4. (D)centre at (0,1)(0,1)(0,1) and radius 222

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
Let a⃗=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}a=i^+j^​+k^ and b⃗=j^−k^\vec{b} = \hat{j} - \hat{k}b=j^​−k^. If c⃗\vec{c}c is a vector such that a⃗×c⃗=b⃗\vec{a} \times \vec{c} = \vec{b}a×c=b and a⃗⋅c⃗=3\vec{a} \cdot \vec{c} = 3a⋅c=3, then a⃗⋅(b⃗×c⃗)\vec{a} \cdot (\vec{b} \times \vec{c})a⋅(b×c) is equal to :
  1. (A)−2-2−2
  2. (B)−6-6−6
  3. (C)666
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
If a line along a chord of the circle 4x2+4y2+120x+675=04x^2 + 4y^2 + 120x + 675 = 04x2+4y2+120x+675=0, passes through the point (−30,0)(-30, 0)(−30,0) and is tangent to the parabola y2=30xy^2 = 30xy2=30x, then the length of this chord is :
  1. (A)555
  2. (B)777
  3. (C)535\sqrt{3}53​
  4. (D)353\sqrt{5}35​

Correct answer: (D)

Step-by-step solution →
Q71·MathematicsSingle correct
The value of ∫−1/21/2((x+1x−1)2+(x−1x+1)2−2)1/2dx\int_{-1/\sqrt{2}}^{1/\sqrt{2}} \left(\left(\frac{x+1}{x-1}\right)^2 + \left(\frac{x-1}{x+1}\right)^2 - 2\right)^{1/2} dx∫−1/2​1/2​​((x−1x+1​)2+(x+1x−1​)2−2)1/2dx is:
  1. (A)log⁡e4\log_e 4loge​4
  2. (B)log⁡e16\log_e 16loge​16
  3. (C)2log⁡e162\log_e 162loge​16
  4. (D)4log⁡e(3+22)4\log_e (3 + 2\sqrt{2})4loge​(3+22​)

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
A plane P contains the line x+2y+3z+1=0=x−y−z−6x + 2y + 3z + 1 = 0 = x - y - z - 6x+2y+3z+1=0=x−y−z−6, and is perpendicular to the plane −2x+y+z+8=0-2x + y + z + 8 = 0−2x+y+z+8=0. Then which of the following points lies on P ?
  1. (A)(−1,1,2)(-1, 1, 2)(−1,1,2)
  2. (B)(0,1,1)(0, 1, 1)(0,1,1)
  3. (C)(1,0,1)(1, 0, 1)(1,0,1)
  4. (D)(2,−1,1)(2, -1, 1)(2,−1,1)

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
If the sum of an infinite GP a, ar, ar2ar^2ar2, ar3ar^3ar3,... is 15 and the sum of the squares of its each term is 150, then the sum of ar2ar^2ar2, ar4ar^4ar4, ar6ar^6ar6, ... is :
  1. (A)52\frac{5}{2}25​
  2. (B)12\frac{1}{2}21​
  3. (C)252\frac{25}{2}225​
  4. (D)92\frac{9}{2}29​

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
The value of lim⁡n→∞1n∑r=02n−1n2n2+4r2\lim_{n \to \infty} \frac{1}{n} \sum_{r=0}^{2n-1} \frac{n^2}{n^2 + 4r^2}limn→∞​n1​∑r=02n−1​n2+4r2n2​ is:
  1. (A)12tan⁡−1(2)\frac{1}{2}\tan^{-1}(2)21​tan−1(2)
  2. (B)12tan⁡−1(4)\frac{1}{2}\tan^{-1}(4)21​tan−1(4)
  3. (C)tan⁡−1(4)\tan^{-1}(4)tan−1(4)
  4. (D)14tan⁡−1(4)\frac{1}{4}\tan^{-1}(4)41​tan−1(4)

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
If the truth value of the Boolean expression ((p∨q)∧(q→r)∧(∼r))→(p∧q)\left((p \vee q) \wedge (q \to r) \wedge (\sim r)\right) \to (p \wedge q)((p∨q)∧(q→r)∧(∼r))→(p∧q) is false, then the truth values of the statements p, q, r respectively can be:
  1. (A)T F T
  2. (B)F F T
  3. (C)T F F
  4. (D)F T F

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsNumerical
Let z=1−i32z = \frac{1-i\sqrt{3}}{2}z=21−i3​​, i=−1i = \sqrt{-1}i=−1​. Then the value of 21+(z+1z)3+(z2+1z2)3+(z3+1z3)3+...+(z21+1z21)321 + \left(z + \frac{1}{z}\right)^{3} + \left(z^{2} + \frac{1}{z^{2}}\right)^{3} + \left(z^{3} + \frac{1}{z^{3}}\right)^{3} + ... + \left(z^{21} + \frac{1}{z^{21}}\right)^{3}21+(z+z1​)3+(z2+z21​)3+(z3+z31​)3+...+(z21+z211​)3 is ________.

Correct answer: 13

Step-by-step solution →
Q77·MathematicsNumerical
The sum of all integral values of k (k≠0)(k \neq 0)(k=0) for which the equation 2x−1−1x−2=2k\frac{2}{x-1} - \frac{1}{x-2} = \frac{2}{k}x−12​−x−21​=k2​ in x has no real roots, is ________.

Correct answer: 66

Step-by-step solution →
Q78·MathematicsNumerical
Let the line L be the projection of the line x−12=y−31=z−42\frac{x-1}{2} = \frac{y-3}{1} = \frac{z-4}{2}2x−1​=1y−3​=2z−4​ in the plane x−2y−z=3x - 2y - z = 3x−2y−z=3. If d is the distance of the point (0,0,6)(0, 0, 6)(0,0,6) from L, then d2d^{2}d2 is equal to ________.

Correct answer: 26

Step-by-step solution →
Q79·MathematicsNumerical
If 1P1+2⋅2P2+3⋅3P3+...+15⋅15P15=qPr−s^{1}P_{1} + 2 \cdot {}^{2}P_{2} + 3 \cdot {}^{3}P_{3} + ... + 15 \cdot {}^{15}P_{15} = {}^{q}P_{r} - s1P1​+2⋅2P2​+3⋅3P3​+...+15⋅15P15​=qPr​−s, 0≤s≤10 \leq s \leq 10≤s≤1, then q+sCr−s^{q+s}C_{r-s}q+sCr−s​ is equal to ________.

Correct answer: 136

Step-by-step solution →
Q80·MathematicsNumerical
A wire of length 36 m is cut into two pieces, one of the pieces is bent to form a square and the other is bent to form a circle. If the sum of the areas of the two figures is minimum, and the circumference of the circle is k (meter), then (4π+1)k\left(\frac{4}{\pi} + 1\right)k(π4​+1)k is equal to ________.

Correct answer: 36

Step-by-step solution →
Q81·MathematicsNumerical
The area of the region S={(x,y):3x2≤4y≤6x+24}S = \{(x, y) : 3x^{2} \leq 4y \leq 6x + 24\}S={(x,y):3x2≤4y≤6x+24} is ________.

Correct answer: 27

Step-by-step solution →
Q82·MathematicsNumerical
The locus of a point, which moves such that the sum of squares of its distances from the points (0,0)(0, 0)(0,0), (1,0)(1, 0)(1,0), (0,1)(0, 1)(0,1) (1,1)(1, 1)(1,1) is 18 units, is a circle of diameter d. Then d2d^{2}d2 is equal to ________.

Correct answer: 16

Step-by-step solution →
Q83·MathematicsNumerical
If y=y(x)y = y(x)y=y(x) is an implicit function of x such that log⁡e(x+y)=4xy\log_{e}(x + y) = 4xyloge​(x+y)=4xy, then d2ydx2\frac{d^{2}y}{dx^{2}}dx2d2y​ at x=0x = 0x=0 is equal to ________.

Correct answer: 40

Step-by-step solution →
Q84·MathematicsNumerical
The number of three-digit even numbers, formed by the digits 0, 1, 3, 4, 6, 7 if the repetition of digits is not allowed, is ________.

Correct answer: 52

Step-by-step solution →
Q85·MathematicsNumerical
Let a, b ∈\in∈ R, b≠0b \neq 0b=0, Define a function f(x)={asin⁡π2(x−1),for x≤0tan⁡2x−sin⁡2xbx3,for x>0.f(x) = \begin{cases} a\sin\frac{\pi}{2}(x-1), & \text{for } x \leq 0 \\ \frac{\tan 2x - \sin 2x}{bx^{3}}, & \text{for } x > 0. \end{cases}f(x)={asin2π​(x−1),bx3tan2x−sin2x​,​for x≤0for x>0.​ If f is continuous at x=0x = 0x=0, then 10−ab10 - ab10−ab is equal to ________.

Correct answer: 14

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Hydrogen 81/186
  • Experimental Skills 68/186
  • Polymers 64/186
  • Carboxylic Acids and Derivatives 54/186
  • Solid State 63/186
  • Magnetism and Matter 50/186
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