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JEE Main 27 July 2021 Shift 2 Question Paper with Answers

27 July 2021 · July session · 86 questions

86 of the 90 questions from the JEE Main 27 July 2021 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

4 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
28
Mathematics
29

Physics — JEE Main 27 July 2021 Shift 2

Q1·PhysicsSingle correct
The planet Mars has two moons, if one of them has a period 7 hours, 30 minutes and an orbital radius of 9.0 × 103^33 km. Find the mass of Mars. {Given 4π2G\frac{4\pi^2}{G}G4π2​ = 6 × 1011^{11}11 N−2^{-2}−2 kg2^22}
  1. (A)3.25 × 1021^{21}21 kg
  2. (B)6.00 × 1023^{23}23 kg
  3. (C)5.96 × 1019^{19}19 kg
  4. (D)7.02 × 1025^{25}25 kg

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
A raindrop with radius R = 0.2 mm falls from a cloud at a height h = 2000 m above the ground. Assume that the drop is spherical through its fall and the force of buoyancy may be neglected, then the terminal speed attained by the raindrop is : [Density of water fw_ww​ = 1000 kg m−3^{-3}−3 and Density of air fa_aa​ = 1.2 kg m−3^{-3}−3, g = 10 m / s2^22 Coefficient of viscosity of air = 1.8 × 10−5^{-5}−5 Nsm−2^{-2}−2]
  1. (A)4.94 ms−1^{-1}−1
  2. (B)14.4 ms−1^{-1}−1
  3. (C)43.56 ms−1^{-1}−1
  4. (D)250.6 ms−1^{-1}−1

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Figure A and B show long straight wires of circular cross − section (a and b with a < b), carrying current I which is uniformly distributed across the cross − section. The magnitude of magnetic field B varies with radius r and can be represented as :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
The resistance of a conductor at 15°C is 16 Ω and at 100°C is 20 Ω . What will be the temperature coefficient of resistance of the conductor ?
  1. (A)0.003°C−1^{-1}−1
  2. (B)0.042°C−1^{-1}−1
  3. (C)0.033°C−1^{-1}−1
  4. (D)0.010°C −1^{-1}−1

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
Two identical particles of mass 1 kg each go round a circle of radius R, under the action of their mutual gravitational attraction. The angular speed of each particle is :
  1. (A)12GR3\frac{1}{2}\sqrt{\frac{G}{R^3}}21​R3G​​
  2. (B)G2R3\sqrt{\frac{G}{2R^3}}2R3G​​
  3. (C)12R1G\frac{1}{2R}\sqrt{\frac{1}{G}}2R1​G1​​
  4. (D)2GR3\sqrt{\frac{2G}{R^3}}R32G​​

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
Consider the following statements : (A) Atoms of each element emit characteristics spectrum. (B) According to Bohr's Postulate, an electron in a hydrogen atom, revolves in a certain stationary orbit. (C) The density of nuclear matter depends on the size of the nucleus. (D) A free neutron is stable but a free proton decay is possible. (E) Radioactivity is an indication of the instability of nuclei. Choose the correct answer from the options given below :
  1. (A)B and D only
  2. (B)A, C and E only
  3. (C)A, B, C, D and E
  4. (D)A, B and E only

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
Match List I with List II. List I (a) Capacitance, C (b) Permittivity of free space, ε0\varepsilon_0ε0​ (c) Permeability of free space, μ0\mu_0μ0​ (d) Electric field, E List II (i) M1^11L1^11T−3^{-3}−3 A−1^{-1}−1 (ii) M−1^{-1}−1L−3^{-3}−3 T4^44 A2^22 (iii) M−1^{-1}−1L−2^{-2}−2 T4^44 A2^22 (iv) M1^11L1^11T−2^{-2}−2A−2^{-2}−2 Choose the correct answer from the options given below :
  1. (A)(a) → (iii), (b) → (ii), (c) → (iv), (d) → (i)
  2. (B)(a) → (iii), (b) → (iv), (c) → (ii), (d) → (i)
  3. (C)(a) → (iv), (b) → (ii), (c) → (iii), (d) → (i)
  4. (D)(a) → (iv), (b) → (iii), (c) → (ii), (d) → (i)

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
One mole of an ideal gas is taken through an adiabatic process where the temperature rises from 27°C to 37°C. If the ideal gas is composed of polyatomic molecule that has 4 vibrational modes, which of the following of the following is true ? [R = 8.314 J mol−1^{-1}−1 K−1^{-1}−1]
  1. (A)Work done by the gas is close to 582 J
  2. (B)Work done on the gas in close to 582 J
  3. (C)Work done on the gas is close to 332 J
  4. (D)Work done by the gas is close to 332 J

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
Two Carnot engines A and operate in series such that engine A absorbs heat at T1_11​ and rejects heat to a sink at temperature T. Engine B absorbs half of the heat rejected by Engine A and rejects heat to the sink at T3_33​ . When work done in both the cases is equal, the value of T is :
  1. (A)32T1+13T3\frac{3}{2}T_1+\frac{1}{3}T_323​T1​+31​T3​
  2. (B)23T1+32T3\frac{2}{3}T_1+\frac{3}{2}T_332​T1​+23​T3​
  3. (C)23T1+13T3\frac{2}{3}T_1+\frac{1}{3}T_332​T1​+31​T3​
  4. (D)13T1+23T3\frac{1}{3}T_1+\frac{2}{3}T_331​T1​+32​T3​

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
An electron and proton are separated by a large distance. The electron starts approaching the proton with energy 3 eV. The proton captures the electron and forms a hydrogen atom in second excited state. The resulting photon is incident on a photosensitive metal of threshold wavelength 4000 Å. What is the maximum kinetic energy of the emitted photoelectron ?
  1. (A)1.41 eV
  2. (B)7.61 eV .
  3. (C)3.3 eV
  4. (D)No photoelectron would be emitted

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
An object of mass 0.5 kg executing simple harmonic motion. Its amplitude is 5 cm and time period (T) is 0.2 s. What will be the potential energy of the object at an instant t = T4\frac{T}{4}4T​ s starting from mean position. Assume that the initial phase of the oscillation is zero.
  1. (A)6.2 × 10−3^{-3}−3 J
  2. (B)0.62 J
  3. (C)6.2 × 103^{3}3 J
  4. (D)1.2 × 103^{3}3 J

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
A 100 Ω resistance, a 0.1 μF capacitor and an inductor are connected in series across a 250 V supply at variable frequency. Calculate the value if inductance of inductor at which resonance will occur. Given that the resonant frequency is 60 Hz.
  1. (A)7.03 × 10−5^{-5}−5 H
  2. (B)70.3 H
  3. (C)70.3 mH
  4. (D)0.70 H

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
An automobile of mass 'm' accelerates starting from origin and initially at rest, while the engine supplies constant power P. The position is given as a function of time by :
  1. (A)(8P9m)12t32\left(\frac{8P}{9m}\right)^{\frac{1}{2}}t^{\frac{3}{2}}(9m8P​)21​t23​
  2. (B)(9P8m)12t32\left(\frac{9P}{8m}\right)^{\frac{1}{2}}t^{\frac{3}{2}}(8m9P​)21​t23​
  3. (C)(9m8P)12t32\left(\frac{9m}{8P}\right)^{\frac{1}{2}}t^{\frac{3}{2}}(8P9m​)21​t23​
  4. (D)(8P9m)12t23\left(\frac{8P}{9m}\right)^{\frac{1}{2}}t^{\frac{2}{3}}(9m8P​)21​t32​

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
Find the truth table for the function Y of A and B represented in the following figure.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
A simple pendulum of mass 'm', length 'ℓ\ellℓ' and charge '+q' suspended in the electric field produced by two conducting parallel plates as shown. The value of deflection of pendulum in equilibrium position will be :
  1. (A)tan⁡−1[qmg×C2(V2−V1)(C1+C2)(d−t)]\tan^{-1}\left[\frac{q}{mg} \times \frac{C_2(V_2 - V_1)}{(C_1 + C_2)(d - t)}\right]tan−1[mgq​×(C1​+C2​)(d−t)C2​(V2​−V1​)​]
  2. (B)tan⁡−1[qmg×C1(V1+V2)(C1+C2)(d−1)]\tan^{-1}\left[\frac{q}{mg} \times \frac{C_1(V_1 + V_2)}{(C_1 + C_2)(d - 1)}\right]tan−1[mgq​×(C1​+C2​)(d−1)C1​(V1​+V2​)​]
  3. (C)tan⁡−1[qmg×C1(V2−V1)(C1+C2)(d−t)]\tan^{-1}\left[\frac{q}{mg} \times \frac{C_1(V_2 - V_1)}{(C_1 + C_2)(d - t)}\right]tan−1[mgq​×(C1​+C2​)(d−t)C1​(V2​−V1​)​]
  4. (D)tan⁡−1[qmg×C2(V1+V2)(C1+C2)(d−t)]\tan^{-1}\left[\frac{q}{mg} \times \frac{C_2(V_1 + V_2)}{(C_1 + C_2)(d - t)}\right]tan−1[mgq​×(C1​+C2​)(d−t)C2​(V1​+V2​)​]

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
Given below is the plot of a potential energy function U(x) for a system, in which a particle is in one dimensional motion, while a conservation force F(x) acts on it. Suppose that EmechE_{mech}Emech​ = 8J, the incorrect statement for this system is : [ where K.E. = kinetic energy]
  1. (A)at x = x3_33​, K.E. = 4J.
  2. (B)at x > x4_44​, K.E. is constant throughout the region .
  3. (C)at x < x1_11​, K.E. is smallest and the particle is moving at the slowest speed.
  4. (D)at x = x2_22​, K.E. is greatest and the particle is moving at the fastest speed.

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
The expected graphical representation of the variation of angle of deviation 'δ' with angle of incidence 'i' in a prism is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
A physical 'y' is represented by the formula y = m2^22 r−4^{-4}−4 gx^xx ℓ−32\ell^{-\frac{3}{2}}ℓ−23​ if the percentage errors found in y, m, r, ℓ\ellℓ and g are 18, 1, 0.5, 4 and p respectively, then find the value of x and p.
  1. (A)5 and ± 2
  2. (B)163\frac{16}{3}316​ and ± 32\frac{3}{2}23​
  3. (C)8 and ± 2
  4. (D)4 and ± 3

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
A particle of mass M originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation F=F0[1−(t−TT)2]F = F_0\left[1 - \left(\frac{t - T}{T}\right)^2\right]F=F0​[1−(Tt−T​)2] Where F0_00​ and T are constants. The force acts only for the time interval 2T. The velocity υ of the particle after time 2T is :
  1. (A)F0_00​T / 3M
  2. (B)2F0_00​ T / M
  3. (C)4F0_00​ T / 3M
  4. (D)F0_00​T / 2M

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsNumerical
A swimmer wants to cross a river from point A to point B. Line AB makes an angle of 30° with the flow of river. Magnitude of velocity of the swimmer is same as that of the river. The angle θ with the line AB should be ________°, so that the swimmer reaches point B.

Correct answer: 30

Step-by-step solution →
Q21·PhysicsNumerical
For the circuit shown, the value of current at time t = 3.2 s will be ________ A. [Voltage distribution V(t) is shown by Fig.(1) and the circuit is shown in Fig.(2)]

Correct answer: 1

Step-by-step solution →
Q22·PhysicsNumerical
The difference in the number of waves when yellow light propagates through air and vacuum columns of the same thickness is one. The thickness of the air column is ________ mm. [Refractive index of air = 1.0003 , wavelength of yellow light in vacuum = 6000 Å ]

Correct answer: 2

Step-by-step solution →
Q23·PhysicsNumerical
In the given figure the magnetic flux through the loop increases according to the relation φβ_\betaβ​(t)10t2^22 + 20t, where φβ_\betaβ​ is in milliwebers and t is in seconds. The magnitude of current throughR = 2Ω resistor at t = 5s is ________ mA.

Correct answer: 60

Step-by-step solution →
Q24·PhysicsNumerical
The water is filled upto height of 12 m in a tank having vertical sidewalls. A hole is made in one of the walls at a depth 'h' below the water level. The value of 'h' for which the emerging stream of water strikes the ground at the maximum range is __________ m.

Correct answer: 6

Step-by-step solution →
Q25·PhysicsNumerical
The Kα_\alphaα​ - X ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atom with a K electron knocked out is 27.5 ke V, the energy of this atom when an L electron is knocked out will be ________ ke V. (Round off to the nearest integer) [ h = 4.14×10−15^{-15}−15 eVs,c = 3×108^88 ms−1^{-1}−1 ]

Correct answer: 10

Step-by-step solution →
Q26·PhysicsNumerical
The maximum amplitude wave is found to be 12 V while the minimum amplitude is found to be 3 V. The modulation index is 0.6x where x is __________.

Correct answer: 1

Step-by-step solution →
Q27·PhysicsNumerical
A small block slides down from the top of hemisphere of radius R = 3m as shown in the figure. The height ' h' at which the block will lose contact with the surface of the sphere is __________ m. (Assume there is no friction between the block and the hemisphere)

Correct answer: 2

Step-by-step solution →
Q28·PhysicsNumerical
In the given figure, two wheels P and Q are connected by a belt B. The radius of P is three times as that of Q. In case of same rotational kinetic energy, the ratio of rotational inertias (I1I2)\left(\frac{I_1}{I_2}\right)(I2​I1​​) will be x : 1. The value of x will be __________.

Correct answer: 9

Step-by-step solution →
Q29·PhysicsNumerical
A particle executes simple harmonic motion represented by displacement function as x(t) = A sin(ωt + φ) If the position and velocity of the particle at t = 0s are 2cm and 2ω cm s−1^{-1}−1 respectively, then its amplitude is x√2 cm where the value of x is __________.

Correct answer: 2

Step-by-step solution →

Chemistry — JEE Main 27 July 2021 Shift 2

Q30·ChemistrySingle correct
Select the correct statements. (A) Crystalline solids have long range order. (B) Crystalline solids are isotropic. (C) Amorphous solids are sometimes called pseudo solids (D) Amorphous solids soften over a range of temperatures. (E) Amorphous solids have a definite heat of fusion Choose the most appropriate answer from the options given below:
  1. (A)(B), (D) only
  2. (B)(A), (B), (E) only
  3. (C)(A), (C), (D) only
  4. (D)(C), (D) only

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
If the Thompson model of the atom was correct, then the result of Rutherford's gold foil experiment would have been:
  1. (A)All α − particles get bounced back by 180°.
  2. (B)α − particles are deflected over a wide range of angles.
  3. (C)All of α − particles pass through the gold foil without decrease in speed.
  4. (D)α − particles pass through the gold foil deflected by small angles and with reduced speed.

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: SO2_22​(g) is adsorbed to a larger extent than H2_22​(g) on activated charcoal. Reason R: SO2_22​(g) has a higher critical temperature than H2_22​(g) In the light of the above statements, choose the most appropriate answer from the option given below.
  1. (A)Both A and R are correct but R is not the correct explanation of A.
  2. (B)A is not correct but R is correct.
  3. (C)A is correct but R is not correct.
  4. (D)Both A and R are correct and R is the correct explanation of A.

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
Compound A gives D-Galactose and D-Glucose on hydrolysis. The compound A is:
  1. (A)Amylose
  2. (B)Sucrose
  3. (C)Maltose
  4. (D)Lactose

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements: Statement I : Hyper conjugation is permanent effect. Statement II : Hyper conjugation in ethyl cation (CH3_33​−C+^++H2_22​) involves the overlapping of Csp2^22−H1s_{1s}1s​ bond with empty 2p orbital of other carbon. Choose the correct option:
  1. (A)Statement I is incorrect but Statement II is true.
  2. (B)Statement I is correct but Statement II is false.
  3. (C)Both Statement I and Statement II are false.
  4. (D)Both Statement I and Statement II are true.

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
What is A in the following reaction?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Match List − I with List − II: List − I (a) Li (b) Na (c) K (d) Cs List − II (i) photoelectric cell (ii) absorbent of CO2_22​ (iii) coolant in fast breeder nuclear reactor (iv) treatment of cancer (v) bearings for motor engines Choose the correct answer from the options given below:
  1. (A)(a) − (v), (b) −(ii), (c) −(iv), (d) −(i)
  2. (B)(a) −(iv), (b) − (iii), (c) −(i), (d) − (ii)
  3. (C)(a) − (v), (b) − (i) , (c)- (ii), (d) − (iv)
  4. (D)(a) −(v), (b) − (iii) , (c) − (ii), (d) −(i)

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
The correct sequence of correct reagent for the following transformation is:
  1. (A)(i) Cl2_22​,FeCl3_33​ (ii) NaNO2_22​,HCl,0° C (iii) Fe,HCl (iv) H2_22​O/H+^++
  2. (B)(i) Cl2_22​,FeCl3_33​ (ii) Fe,HCl (iii) NaNO2_22​,HCl,0° C (iv) H2_22​O/H+^++
  3. (C)(i) Fe,HCl (ii) Cl2_22​,HCl (iii) NaNO2_22​,HCl,0° C (iv) H2_22​O/H+^++
  4. (D)(i) Fe,HCl (ii) NaNO2_22​,HCl,0° C (iii) H2_22​O/H+^++ (iv) Cl2_22​,FeCl3_33​

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
R−CN →(i) DIBAL−H  (ii) H2O\xrightarrow{(i)\,DIBAL-H\ \ (ii)\,H_2O}(i)DIBAL−H  (ii)H2​O​ R−Y Consider the above reaction and identify "Y"
  1. (A)−COOH
  2. (B)− CH2_22​NH2_22​
  3. (C)−CHO
  4. (D)− CONH3_33​

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
Given below are two statements : Statement I: Penicillin is a bacteriostatic type antibiotic. Statement II: The general structure of penicillin is: Choose the correct option:
  1. (A)Both statement I and statement II are true
  2. (B)Statement I is correct but statement II is false
  3. (C)Statement I is incorrect but statement II is true
  4. (D)Both statement I and statement II are false

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
Which one of the following set of elements can be detected using sodium fusion extract?
  1. (A)Halogens, Nitrogen, Oxygen, Sulfur
  2. (B)Sulfur, Nitrogen, Phosphorous Halogens
  3. (C)Phosphorous, Oxygen, Nitrogen, Halogens
  4. (D)Nitrogen, Phosphorous, Carbon, Sulfur

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
The addition of silica during the extraction of copper from its sulphide ore
  1. (A)reduces copper sulphide into metallic copper
  2. (B)reduces the melting point of the reaction mixture
  3. (C)converts copper sulphide into copper silicate
  4. (D)converts iron oxide into iron silicate

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
Consider the above reaction, the major product “P” formed is”
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
The number of neutrons and electrons respectively, present in the radioactive isotope of hydrogen is:
  1. (A)2 and 1
  2. (B)1 and 1
  3. (C)3 and 1
  4. (D)2 and 2

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
The CORRECT order of first ionisation enthalpy is:
  1. (A)Mg < Al < S < P
  2. (B)Al < Mg < S< P
  3. (C)Mg < S < Al < P
  4. (D)Mg < Al < P < S

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
Given below are two statements: Statement I : [Mn(CN)6]3−[Mn(CN)_6]^{3-}[Mn(CN)6​]3− , [Fe(CN)6]3−[Fe(CN)_6]^{3-}[Fe(CN)6​]3− and [Co(C2O4)3]3−[Co(C_2O_4)_3]^{3-}[Co(C2​O4​)3​]3− are d2^22sp3^33 hybridised Statement II : [MnCl6]3−[MnCl_6]^{3-}[MnCl6​]3− and [FeF6]3−[FeF_6]^{3-}[FeF6​]3− are paramagnetic and have 4 and 5 unpaired electrons, respectively. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is correct but Statement II is false
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is incorrect but Statement II is true
  4. (D)Both Statement I and Statement II are true

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
To an aqueous solution containing ions such as Al3+^{3+}3+,Zn2+^{2+}2+,Ca2+^{2+}2+,Fe3+^{3+}3+,Ni2+^{2+}2+,Ba2+^{2+}2+ and Cu2+^{2+}2+ was added conc. HCl, followed by H2_22​S . The total number of cations precipitated during this reaction is / are:
  1. (A)4
  2. (B)1
  3. (C)3
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q47·ChemistrySingle correct
Match List – I with List – II: List – I (compound) List – II (effect / affected species) (a) Carbon monoxide (i) Carcinogenic (b) Sulphur dioxide (ii) Metabolized by pyrus plants (c) Polychlorinated biphenyls (iii) Haemoglobin (d) Oxides of nitrogen (iv) Stiffness of flower buds Choose the correct answer from the options given below:
  1. (A)(a) –(iv), (b) –(i), (c) – (iii), (d) – (ii)
  2. (B)(a) – (i), (b) –(ii), (c) – (iii), (d) – (iv)
  3. (C)(a) – (iii), (b) – (iv), (c) – (ii), (d) – (i)
  4. (D)(a) – (iii), (b) – (iv), (c) – (i), (d) – (ii)

Correct answer: (D)

Step-by-step solution →
Q48·ChemistrySingle correct
Consider the above reaction, and choose the correct statement:
  1. (A)Both compounds A and B are formed equally
  2. (B)The reaction is not possible in acidic medium
  3. (C)Compound A will be the major product
  4. (D)Compound B will be the major product

Correct answer: (C)

Step-by-step solution →
Q49·ChemistrySingle correct
Number of Cl=O bonds in chlorous acid, chloric acid and perchloric acid respectively are:
  1. (A)4,1 and 0
  2. (B)1,1 and 3
  3. (C)1,2 and 3
  4. (D)3,1 and 1

Correct answer: (C)

Step-by-step solution →
Q50·ChemistryNumerical
In a solvent 50% of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is ______________ ×10−2^{-2}−2. (Round off to the Nearest Integer).

Correct answer: 125

Step-by-step solution →
Q51·ChemistryNumerical
2SO2_22​(g)+O2_22​(g) → 2SO3_33​(g) The above reaction is carried out in a vessel starting with partial pressure PSO2_{SO_2}SO2​​ = 250 m bar, PO2_{O_2}O2​​ = 750 m bar and PSO3_{SO_3}SO3​​ = 0 bar. When the reaction is complete, the total pressure in the reaction vessel is ____________ m bar. (Round off to the Nearest Integer).

Correct answer: 875

Step-by-step solution →
Q52·ChemistryNumerical
For the cell Cu(s) | Cu2+^{2+}2+ (aq)(0.1M) ‖ Ag+^++ (aq)(0.01M) | Ag(s) The cell potential E1_11​ = 0.3095V For the cell Cu(s) | Cu2+^{2+}2+ (aq)(0.01M) ‖ Ag+^++ (aq)(0.001M) | Ag(s) The cell potential = __________×10−2^{-2}−2 V. (Round off to the Nearest Integer). [Use : 2.303RTF\frac{2.303RT}{F}F2.303RT​ = 0.059 ]

Correct answer: 28

Step-by-step solution →
Q53·ChemistryNumerical
The dihedral angle in staggered from the Newman projection of 1,1,1,-Trichloro ethane is ______________ degree. (Round off to the Nearest Integer).

Correct answer: 60

Step-by-step solution →
Q54·ChemistryNumerical
The total number of electrons in all bonding molecular orbitals of O22−_2^{2-}22−​ is ____________. (Round off to the Nearest Integer).

Correct answer: 10

Step-by-step solution →
Q55·ChemistryNumerical
3 moles of metal complex with formula Co(en)2_22​Cl3_33​, gives 3moles of silver chloride on treatment with excess of silver nitrate. The secondary valency of Co in the complex is __________. (Round off to the Nearest Integer).

Correct answer: 6

Step-by-step solution →
Q56·ChemistryNumerical
When 400 mL of 0.2 M H2_22​SO4_44​ solution is mixed with 600 mL of of 0.1 M NaOH solution the increase in temperature of the final solution is ____________×10−2^{-2}−2 K. (Round off to the Nearest Integer). [Use: H+^++(aq) + OH−^-− (aq) → H2_22​O : Δr\Delta_rΔr​H = −57.1kJmol−1^{-1}−1 Specific heat of H2_22​O = 4.18JK−1^{-1}−1 g−1^{-1}−1 Density of H2_22​O = 1.0 gcm−3^{-3}−3 Assume no change in volume of solution on mixing]

Correct answer: 82

Step-by-step solution →
Q57·ChemistryNumerical
10.0 ml of 0.05 M KMnO4_44​ solution was consumed in a titration with 10.0 mL of given oxalic acid dehydrate solution. The strength of given oxalic acid solution is ___×10−2^{-2}−2 g/ L (Round off to the Nearest Integer).

Correct answer: 1575

Step-by-step solution →

Mathematics — JEE Main 27 July 2021 Shift 2

Q58·MathematicsSingle correct
Let a⃗,b⃗\vec{a}, \vec{b}a,b and c⃗\vec{c}c be three vectors such that a⃗=b⃗×(b⃗×c⃗)\vec{a} = \vec{b} \times \left( \vec{b} \times \vec{c} \right)a=b×(b×c). If magnitudes of the vectors a⃗,b⃗\vec{a}, \vec{b}a,b and c⃗\vec{c}c are √2, 1 and 2 respectively and the angle between b⃗\vec{b}b and c⃗\vec{c}c is θ(0<θ<π2)\theta\left( 0 < \theta < \frac{\pi}{2} \right)θ(0<θ<2π​), then the value of 1 + tan θ is equal to :
  1. (A)√3 + 1
  2. (B)3+13\frac{\sqrt{3} + 1}{\sqrt{3}}3​3​+1​
  3. (C)2
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q59·MathematicsSingle correct
Let N be the set of natural numbers and a relation R on N be defined by R = {(x,y)∈N×N:x3−3x2y−xy2+3y3=0}\left\{ (x, y) \in \mathbb{N} \times \mathbb{N} : x^3 - 3x^2 y - xy^2 + 3y^3 = 0 \right\}{(x,y)∈N×N:x3−3x2y−xy2+3y3=0}. Then the relation R is :
  1. (A)reflexive but neither symmetric nor transitive
  2. (B)an equivalence relation
  3. (C)symmetric but neither reflexive nor transitive
  4. (D)reflexive and symmetric, but not transitive

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
Let y = y(x) be the solution of the differential equation (x−x3)dy=(y+yx2−3x4)dx\left( x - x^3 \right) dy = \left( y + yx^2 - 3x^4 \right) dx(x−x3)dy=(y+yx2−3x4)dx, x > 2. If y(3) = 3 then y(4) is equal to
  1. (A)12
  2. (B)4
  3. (C)8
  4. (D)16

Correct answer: (A)

Step-by-step solution →
Q61·MathematicsSingle correct
Let f : [0, ∞) → [0, 3] be a function defined by f(x) = {max⁡{sin⁡t:0≤t≤x},0≤x≤π2+cos⁡x,x>π\begin{cases} \max\left\{ \sin t : 0 \le t \le x \right\}, & 0 \le x \le \pi \\ 2 + \cos x, & x > \pi \end{cases}{max{sint:0≤t≤x},2+cosx,​0≤x≤πx>π​ Then which of the following is true?
  1. (A)f is differentiable everywhere in (0,∞)\left( 0, \infty \right)(0,∞)
  2. (B)f is not continuous exactly at two points in (0,∞)\left( 0, \infty \right)(0,∞)
  3. (C)f is continuous everywhere but not differentiable exactly at two points in (0,∞)\left( 0, \infty \right)(0,∞)
  4. (D)f is continuous everywhere but not differentiable exactly at one point in (0,∞)\left( 0, \infty \right)(0,∞)

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
If tan⁡(π9)\tan\left( \frac{\pi}{9} \right)tan(9π​), x, tan⁡(7π18)\tan\left( \frac{7\pi}{18} \right)tan(187π​) are in arithmetic progression and tan⁡(π9)\tan\left( \frac{\pi}{9} \right)tan(9π​), y, tan⁡(5π18)\tan\left( \frac{5\pi}{18} \right)tan(185π​) are also in arithmetic progression, then ∣x−2y∣\left| x - 2y \right|∣x−2y∣ is equal to :
  1. (A)1
  2. (B)0
  3. (C)4
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
The area of the region bounded by y − x = 2 and x2^22 = y is equal to :
  1. (A)23\frac{2}{3}32​
  2. (B)92\frac{9}{2}29​
  3. (C)163\frac{16}{3}316​
  4. (D)43\frac{4}{3}34​

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Let f : ℝ → ℝ be defined as f(x + y) + f(x − y) = 2f(x) f(y), f(12)f\left( \frac{1}{2} \right)f(21​) = −1. Then, the value of ∑k=1201sin⁡(k)sin⁡(k+f(k))\sum_{k=1}^{20} \frac{1}{\sin\left( k \right) \sin\left( k + f\left( k \right) \right)}∑k=120​sin(k)sin(k+f(k))1​ is equal to :
  1. (A)cosec⁡2(21)cos⁡(20)cos⁡(2)\cosec^2\left( 21 \right) \cos\left( 20 \right) \cos\left( 2 \right)cosec2(21)cos(20)cos(2)
  2. (B)sec⁡2(1)sec⁡(21)cos⁡(20)\sec^2\left( 1 \right) \sec\left( 21 \right) \cos\left( 20 \right)sec2(1)sec(21)cos(20)
  3. (C)sec⁡2(21)sin⁡(20)sin⁡(2)\sec^2\left( 21 \right) \sin\left( 20 \right) \sin\left( 2 \right)sec2(21)sin(20)sin(2)
  4. (D)cosec⁡2(1)cosec⁡(21)sin⁡(20)\cosec^2\left( 1 \right) \cosec\left( 21 \right) \sin\left( 20 \right)cosec2(1)cosec(21)sin(20)

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correct
Let the mean and variance of the frequency distribution x: x1_11​ = 2, x2_22​ = 6, x3_33​ = 8, x4_44​ = 9 f: 4, 4, α, β be 6 and 6.8 respectively. If x3_33​ is changed from 8 to 7, then the mean for the new data will be :
  1. (A)4
  2. (B)5
  3. (C)173\frac{17}{3}317​
  4. (D)163\frac{16}{3}316​

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
The point P(a, b) undergoes the following three transformations successively : (a) reflection about the line y = x (b) translation through 2 units along the positive direction of x-axis. (c) rotation through angle π4\frac{\pi}{4}4π​ about the origin in the anti-clockwise direction. If the co-ordinates of the final position of the point P are (−12,72)\left( -\frac{1}{\sqrt{2}}, \frac{7}{\sqrt{2}} \right)(−2​1​,2​7​), then the value of 2a + b is equal to :
  1. (A)5
  2. (B)7
  3. (C)13
  4. (D)9

Correct answer: (D)

Step-by-step solution →
Q67·MathematicsSingle correct
Consider a circle C which touches the y-axis at (0, 6) and cuts off an intercept 6√5 on the x-axis. Then the radius of the circle C is equal to :
  1. (A)9
  2. (B)√82
  3. (C)8
  4. (D)√53

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
Let A and B be two 3 x 3 real matrices such that (A2−B2)(A^2 - B^2)(A2−B2) is invertible matrix. If A5=B5A^5 = B^5A5=B5 and A3B2=A2B3A^3B^2 = A^2B^3A3B2=A2B3, then the value of the determinant of the matrix A3+B3A^3 + B^3A3+B3 is equal to :
  1. (A)2
  2. (B)1
  3. (C)0
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
Let α=max⁡x∈R{82sin⁡3x.44cos⁡3x}\alpha = \max_{x \in R} \left\{ 8^{2\sin 3x} . 4^{4\cos 3x} \right\}α=maxx∈R​{82sin3x.44cos3x} and β=min⁡x∈R{82sin⁡3x.44cos⁡3x}\beta = \min_{x \in R} \left\{ 8^{2\sin 3x} . 4^{4\cos 3x} \right\}β=minx∈R​{82sin3x.44cos3x}. If 8x2+bx+c=08x^2 + bx + c = 08x2+bx+c=0 is a quadratic equation whose roots are α1/5\alpha^{1/5}α1/5 and β1/5\beta^{1/5}β1/5, then the value of c − b is equal to :
  1. (A)42
  2. (B)43
  3. (C)47
  4. (D)50

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
Let c be the set of all complex numbers. Let S1_11​ = {z∈C:∣z−2∣≤1}\left\{ z \in C : |z - 2| \le 1 \right\}{z∈C:∣z−2∣≤1} and S2_22​ = {z∈C:z(1+i)+zˉ(1−i)≥4}\left\{ z \in C : z(1+i) + \bar{z}(1-i) \ge 4 \right\}{z∈C:z(1+i)+zˉ(1−i)≥4}. Then, the maximum value of ∣z−52∣2\left| z - \frac{5}{2} \right|^2​z−25​​2 for z∈S1∩S2z \in S_1 \cap S_2z∈S1​∩S2​ is equal to :
  1. (A)5+224\frac{5 + 2\sqrt{2}}{4}45+22​​
  2. (B)5+222\frac{5 + 2\sqrt{2}}{2}25+22​​
  3. (C)3+224\frac{3 + 2\sqrt{2}}{4}43+22​​
  4. (D)3+222\frac{3 + 2\sqrt{2}}{2}23+22​​

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
A possible value of 'x', for which the ninth term in the expansion of {3log⁡325x−1+7+3(−18)log⁡3(5x−1+1)}10\left\{ 3^{\log_3 \sqrt{25^{x-1} + 7}} + 3^{\left( -\frac{1}{8} \right) \log_3 \left( 5^{x-1} + 1 \right)} \right\}^{10}{3log3​25x−1+7​+3(−81​)log3​(5x−1+1)}10 in the increasing powers of 3(−18)log⁡3(5x−1+1)3^{\left( -\frac{1}{8} \right) \log_3 \left( 5^{x-1} + 1 \right)}3(−81​)log3​(5x−1+1) is equal to 180, is :
  1. (A)1
  2. (B)2
  3. (C)0
  4. (D)−1

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
The value of lim⁡x→0(x1−sin⁡x8−1+sin⁡x8)\lim_{x \to 0} \left( \frac{x}{\sqrt[8]{1 - \sin x} - \sqrt[8]{1 + \sin x}} \right)limx→0​(81−sinx​−81+sinx​x​) is equal to :
  1. (A)4
  2. (B)0
  3. (C)−4
  4. (D)−1

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
For real numbers α and β ≠ 0, if the point of intersection of the straight lines x−α1=y−12=z−13\frac{x - \alpha}{1} = \frac{y - 1}{2} = \frac{z - 1}{3}1x−α​=2y−1​=3z−1​ and x−4β=y−63=z−73\frac{x - 4}{\beta} = \frac{y - 6}{3} = \frac{z - 7}{3}βx−4​=3y−6​=3z−7​, lies on the plane x + 2y − z = 8, then α − β is equal to :
  1. (A)3
  2. (B)9
  3. (C)7
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q74·MathematicsSingle correct
Two sides of a parallelogram are along the lines 4x + 5y = 0 and 7x + 2y = 0. If the equation of one of the diagonals of the parallelogram is 11x + 7y = 9, then other diagonal passes through the point :
  1. (A)(2,1)(2,1)(2,1)
  2. (B)(2,2)(2,2)(2,2)
  3. (C)(1,3)(1,3)(1,3)
  4. (D)(1,2)(1,2)(1,2)

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
Which of the following is the negation of the statement "for all M > 0, there exists x ∈ S such that x ≥ M"?
  1. (A)there exists M > 0, there exists x ∈ S such that x < M
  2. (B)there exists M > 0, such that x ≥ M for all x ∈ S
  3. (C)there exists M > 0, there exists x ∈ S such that x ≥ M
  4. (D)there exists M > 0, such that x < M for all x ∈ S

Correct answer: (D)

Step-by-step solution →
Q76·MathematicsSingle correct
A student appeared in an examination consisting of 8 true − false type questions. The student guesses the answers with equal probability. The smallest value of n, so that the probability of guessing at least 'n' correct answers is less than 12\frac{1}{2}21​, is :
  1. (A)5
  2. (B)6
  3. (C)3
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q77·MathematicsSingle correct
Let f : (a,b) → R be twice differentiable such that f(x)=∫axg(t)dtf(x) = \int_a^x g(t) dtf(x)=∫ax​g(t)dt for a differentiable function g(x). If f(x) = 0 has exactly five distinct roots in (a, b), then g(x)g′(x)=0g(x)g'(x) = 0g(x)g′(x)=0 has at least :
  1. (A)seven roots in (a, b)
  2. (B)twelve roots in (a, b)
  3. (C)five roots in (a, b)
  4. (D)three roots in (a, b)

Correct answer: (A)

Step-by-step solution →
Q78·MathematicsNumerical
The number of real roots of the equation e4xe^{4x}e4x − e3xe^{3x}e3x − 4e2x4e^{2x}4e2x − exe^{x}ex + 1 = 0 is equal to…………

Correct answer: 2

Step-by-step solution →
Q79·MathematicsNumerical
If the real part of the complex number z = 3+2icos⁡θ1−3icos⁡θ\frac{3+2i\cos\theta}{1-3i\cos\theta}1−3icosθ3+2icosθ​ , θ ∈ (0,π2)\left(0,\frac{\pi}{2}\right)(0,2π​) is zero, then the value of sin⁡23θ\sin^{2}3\thetasin23θ + cos⁡2θ\cos^{2}\thetacos2θ is equal to………

Correct answer: 1

Step-by-step solution →
Q80·MathematicsNumerical
Let n be a non-negative integer. Then the number of divisors of the form "4n + 1" of the number (10)10(10)^{10}(10)10 . (11)10(11)^{10}(11)10 . (13)13(13)^{13}(13)13 is equal to……….

Correct answer: 924

Step-by-step solution →
Q81·MathematicsNumerical
The distance of the point P(3,4,4) from the point of intersection of the line joining the points Q(3,−4,−5) and R(2, −3, 1) and the plane 2x + y + z = 7 , is equal to………….

Correct answer: 7

Step-by-step solution →
Q82·MathematicsNumerical
Let A = {n ∈ N|n2^22 ≤ n + 10,000}, B = {3k + 1|k ∈ N} and C = {2k|k ∈ N} , then the sum of all the elements of the set A ∩ (B − C) is equal to……

Correct answer: 832

Step-by-step solution →
Q83·MathematicsNumerical
If ∫0π(sin⁡3x)e−sin⁡2xdx\int_{0}^{\pi}\left(\sin^{3}x\right)e^{-\sin^{2}x}dx∫0π​(sin3x)e−sin2xdx = α − βe∫01t etdt\frac{\beta}{e}\int_{0}^{1}\sqrt{t}\ e^{t}dteβ​∫01​t​ etdt, then α + β is equal to……….

Correct answer: 5

Step-by-step solution →
Q84·MathematicsNumerical
Let E be an ellipse whose axes are parallel to the co-ordinates axes, having its center at (3,−4), one focus at (4,−4) and one vertex at (5,−4) . If mx − y = 4, m > 0 is a tangent to the ellipse E, then the value of 5m2^22 is equal to……………

Correct answer: 3

Step-by-step solution →
Q85·MathematicsNumerical
Let y = y(x)\left(x\right)(x) be the solution of the differential equation dy = eαx+ye^{\alpha x+y}eαx+ydx; α ∈ N . If y(log⁡e2)\left(\log_{e}2\right)(loge​2) = log⁡e2\log_{e}2loge​2 and y(0) = log⁡e(12)\log_{e}\left(\frac{1}{2}\right)loge​(21​), then the value of α is equal to………….

Correct answer: 2

Step-by-step solution →
Q86·MathematicsNumerical
Let a⃗\vec{a}a = î − αĵ + βk̂, b⃗\vec{b}b = 3î + βĵ − αk̂ and c⃗\vec{c}c = −αî − 2ĵ + k̂, where α and β are integers. If a⃗⋅b⃗\vec{a}\cdot\vec{b}a⋅b = −1 and b⃗⋅c⃗\vec{b}\cdot\vec{c}b⋅c = 10, then (a⃗×b⃗)⋅c⃗\left(\vec{a}\times\vec{b}\right)\cdot\vec{c}(a×b)⋅c is equal to…….

Correct answer: 9

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Chemistry in Everyday Life 60/186
  • Diazonium Salts and Reactions 53/186
  • States of Matter: Gases and Liquids 52/186
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