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JEE Main 28 June 2022 Shift 1 Question Paper with Answers

28 June 2022 · June session · 85 questions

85 of the 90 questions from the JEE Main 28 June 2022 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

5 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
26
Chemistry
29
Mathematics
30

Physics — JEE Main 28 June 2022 Shift 1

Q1·PhysicsSingle correct
Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Product of Pressure (P) and time (t) has the same dimension as that of coefficient of viscosity. Reason R: Coefficient of viscosity =ForceVelocity gradient= \frac{\text{Force}}{\text{Velocity gradient}}=Velocity gradientForce​ Question: Choose the correct answer from the options given below :
  1. (A)Both A and R true, and R is correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false.
  4. (D)A is false but R is true.

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration (a) is varying with time t as a=k2rt2a = k^{2}rt^{2}a=k2rt2. where k is a constant. The power delivered to the particle by the force acting on it is given as
  1. (A)zero
  2. (B)mk2r2t2mk^{2}r^{2}t^{2}mk2r2t2
  3. (C)mk2r2tmk^{2}r^{2}tmk2r2t
  4. (D)mk2rtmk^{2}rtmk2rt

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
Motion of a particle in x-y plane is described by a set of following equations x=4sin⁡(π2−ωt)x = 4\sin\left(\frac{\pi}{2} - \omega t\right)x=4sin(2π​−ωt) m and y=4sin⁡(ωt)y = 4\sin\left(\omega t\right)y=4sin(ωt) m. The path of particle will be –
  1. (A)circular
  2. (B)helical
  3. (C)parabolic
  4. (D)elliptical

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
Given below are two statement : Statement – I : What μ amount of an ideal gas undergoes adiabatic change from state (P1,V1,T1)\left(P_{1}, V_{1}, T_{1}\right)(P1​,V1​,T1​) to state (P2,V2,T2)\left(P_{2}, V_{2}, T_{2}\right)(P2​,V2​,T2​), the work done is W=1R(T2−T1)1−γW = \frac{1R\left(T_{2} - T_{1}\right)}{1 - \gamma}W=1−γ1R(T2​−T1​)​, where γ=CPCV\gamma = \frac{C_{P}}{C_{V}}γ=CV​CP​​ and R = universal gas constant, Statement — II: In the above case. when work is done on the gas. the temperature of the gas would rise. Choose the correct answer from the options given below:
  1. (A)Both statement—I and statement-II are true.
  2. (B)Both statement—I and statement-II are false.
  3. (C)Statement-I is true but statement-II is false.
  4. (D)Statement-I is false but statement-II is true.

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
Given below are two statements : Statement-I : A point charge is brought in an electric field. The value of electric field at a point near to the charge may increase if the charge is positive. Statement-II : An electric dipole is placed in a non-uniform electric field. The net electric force on the dipole will not be zero. Choose the correct answer from the options given below :
  1. (A)Both statement-I and statement-II are true.
  2. (B)Both statement-I and statement-I are false.
  3. (C)Statement-I is true but statement-II is false.
  4. (D)Statement-I is false but statement-II is true.

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
The three charges q/2, q and q/2 are placed at the corners A, B and C of a square of side 'a' as shown in figure. The magnitude of electric field (E) at the comer D of the square, is :
  1. (A)q4πϵ0a2(12+12)\frac{q}{4\pi\epsilon_{0}a^{2}}\left(\frac{1}{\sqrt{2}} + \frac{1}{2}\right)4πϵ0​a2q​(2​1​+21​)
  2. (B)q4πϵ0a2(1+12)\frac{q}{4\pi\epsilon_{0}a^{2}}\left(1 + \frac{1}{\sqrt{2}}\right)4πϵ0​a2q​(1+2​1​)
  3. (C)q4πϵ0a2(1−12)\frac{q}{4\pi\epsilon_{0}a^{2}}\left(1 - \frac{1}{\sqrt{2}}\right)4πϵ0​a2q​(1−2​1​)
  4. (D)q4πϵ0a2(12−12)\frac{q}{4\pi\epsilon_{0}a^{2}}\left(\frac{1}{\sqrt{2}} - \frac{1}{2}\right)4πϵ0​a2q​(2​1​−21​)

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
An infinitely long hollow conducting cylinder with radius R carries a uniform current along its surface. Choose the correct representation of magnetic field (B) as a function of radial distance (r) from the axis of cylinder.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
A radar sends an electromagnetic signal of electric field (E0)(E_{0})(E0​) = 2.25 V/m and magnetic field (B0)(B_{0})(B0​) = 1.5×10−81.5 \times 10^{-8}1.5×10−8 T which strikes a target on line of sight at a distance of 3 km in a medium. After that, a pail of signal (echo) reflects back towards the radar vit1i same velocity and by same path. If the signal was transmitted at time t0t_{0}t0​ from radar. then after how much time echo will reach to the radar?
  1. (A)2.0×10−52.0\times10^{-5}2.0×10−5 s
  2. (B)4.0×10−54.0\times10^{-5}4.0×10−5 s
  3. (C)1.0×10−51.0\times10^{-5}1.0×10−5 s
  4. (D)8.0×10−58.0\times10^{-5}8.0×10−5 s

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
The refracting angle of a prism is A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be -
  1. (A)180 – 2A
  2. (B)90 – A
  3. (C)180 + 2A
  4. (D)180 – 3A

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
The aperture of the objective is 24.4 cm. The resolving power of this telescope. If a light of wavelength 2440 Å is used to see the object will be
  1. (A)8.1×1068.1\times10^{6}8.1×106
  2. (B)10.0×10710.0\times10^{7}10.0×107
  3. (C)8.2×1058.2\times10^{5}8.2×105
  4. (D)1.0×10−81.0\times10^{-8}1.0×10−8

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
The de Brogue wavelengths for an electron and a photon are λe\lambda_{e}λe​ and λp\lambda_{p}λp​ respectively. For the same kinetic energy of electron and photon. which of the following presents the correct relation between the de Brogue wavelengths of two ?
  1. (A)λp∝λe2\lambda_{p} \propto \lambda_{e}^{2}λp​∝λe2​
  2. (B)λp∝λe\lambda_{p} \propto \lambda_{e}λp​∝λe​
  3. (C)λp∝λe\lambda_{p} \propto \sqrt{\lambda_{e}}λp​∝λe​​
  4. (D)λp∝1λe\lambda_{p} \propto \sqrt{\frac{1}{\lambda_{e}}}λp​∝λe​1​​

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
The Q-value of a nuclear reaction and kinetic energy of the projectile particle, KpK_{p}Kp​ are related as :
  1. (A)Q=KpQ = K_{p}Q=Kp​
  2. (B)(Kp+Q)<O(K_{p} + Q) < O(Kp​+Q)<O
  3. (C)Q<KpQ < K_{p}Q<Kp​
  4. (D)(Kp+Q)>0(K_{p} + Q) > 0(Kp​+Q)>0

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
In the following circuit, the correct relation between output (Y) and inputs A and B will be :
  1. (A)Y=ABY = ABY=AB
  2. (B)Y=A+BY = A + BY=A+B
  3. (C)Y=AB‾Y = \overline{AB}Y=AB
  4. (D)Y=A+B‾Y = \overline{A + B}Y=A+B​

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
For using a multimeter to identify diode from electrical components. choose the correct statement out of the following about the diode :
  1. (A)It is two terminal device which conducts current in both directions.
  2. (B)It is two terminal device which conducts current in one direction only
  3. (C)It does not conduct current gives an initial deflection which decays to zero.
  4. (D)It is three terminal device which conducts current in ne direction only between central terminal and either of the remaining two terminals

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : n-p-n transistor permits more current than a p-n-p transistor. Reason R : Electrons have greater mobility as a charge carrier. Choose the correct answer from the options given below :
  1. (A)Both A and R true. and R is correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false.
  4. (D)A is false but R is true.

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
Match List-I with List-II List-I (A) Television signal (B) Radio signal (C) High Quality Music (D) Human speech List-II (I) 03 KHz (II) 20 KHz (III) 02 MHz (IV) 06 MHz Choose the correct answer from the options given below :
  1. (A)A-I, B-II, C-III, D-IV
  2. (B)A-IV, B-III, C-I, D-II
  3. (C)A-IV, B-III, C-II, D-I
  4. (D)A-I, B-II, C-IV, D-III

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
The velocity of sound in a gas. in which two wavelengths 4.084.084.08 m and 4.164.164.16 m produce 40 beats in 12s, will be :
  1. (A)2.82.8 ms−1^{-1}−1
  2. (B)175.5175.5175.5 ms−1^{-1}−1
  3. (C)353.6353.6353.6 ms−1^{-1}−1
  4. (D)707.2707.2707.2 ms−1^{-1}−1

Correct answer: (D)

Step-by-step solution →
Q18·PhysicsNumerical
A pendulum is suspended by a string of length 250 cm. The mass of the bob of the pendulum is 200 g. The bob is pulled aside until the string is at 60° with vertical as shown in the figure. After releasing the bob. the maximum velocity attained by the bob will be ______________ ms−1^{-1}−1. (if g = 10 m/s2^{2}2)

Correct answer: 5

Step-by-step solution →
Q19·PhysicsNumerical
A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given resistor of 1 5 Ω. The galvanometer (G) shows null deflection when tapping key is at 43 cm mark from end A. If the end correction for end A is 2 cm. then the determined value of R will be ________ Ω.

Correct answer: 19

Step-by-step solution →
Q20·PhysicsNumerical
Current measured by the ammeter (A) in the reported circuit when no current flows through 10 Ω resistance. will be __________ A.

Correct answer: 10

Step-by-step solution →
Q21·PhysicsNumerical
The position vector of 1 kg object is r⃗=(3i^−j^)\vec{r} = \left(3\hat{i} - \hat{j}\right)r=(3i^−j^​) m and its velocity v⃗=(3j^+k)\vec{v} = \left(3\hat{j} + k\right)v=(3j^​+k) ms−1^{-1}−1. The magnitude of its angular momentum is x\sqrt{x}x​ Nm where x is ______ .

Correct answer: 91

Step-by-step solution →
Q22·PhysicsNumerical
A man of 60 kg is running on the road and suddenly jumps into a stationary trolly car of mass 120 kg. Then. the trolly car starts moving with velocity 2 ms−1^{-1}−1. The velocity of the running man was ______________ ms−1^{-1}−1. when he jumps into the car.

Correct answer: 6

Step-by-step solution →
Q23·PhysicsNumerical
A hanging mass M is connected to a four times bigger mass by using a string-pulley arrangement. as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2 Mg force. In this situation. tension in the string is x5\frac{x}{5}5x​ Mg for x = _________. Neglect mass of the string and friction of the block (bigger mass) with ice slab. (Given g = acceleration due to gravity)

Correct answer: 6

Step-by-step solution →
Q24·PhysicsNumerical
The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be J. (Given R = 8.31 J/mol.K)

Correct answer: 7479

Step-by-step solution →
Q25·PhysicsNumerical
A sing1y ionized magnesium atom (A24) ion is accelerated to kinetic energy 5 keV and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be ____________ cm.

Correct answer: 10

Step-by-step solution →
Q26·PhysicsNumerical
A telegraph line of length loo km has a capacity of 0.010.010.01 μF/km and it carries an alternating current at 0.50.50.5 kilo cycle per second. If minimum impedance is required, then the value of the inductance that needs to be introduced in series is _________ mH. (if π=10)\left(\text{if } \pi = \sqrt{10}\right)(if π=10​)

Correct answer: 100

Step-by-step solution →

Chemistry — JEE Main 28 June 2022 Shift 1

Q27·ChemistrySingle correct
The incorrect statement about the imperfections in solids is :
  1. (A)Schottky defect decreases the density of the substance.
  2. (B)Interstitial defect increases the density of the substance.
  3. (C)Frenkel defect does not alter the density of the substance.
  4. (D)Vacancy defect increases the density of the substance.

Correct answer: (D)

Step-by-step solution →
Q28·ChemistrySingle correct
The Zeta potential is related to which property of colloids”
  1. (A)Colour
  2. (B)Tyndall effect
  3. (C)Charge on the surface of colloidal particles
  4. (D)Brownian movement

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correct
Element "E" belongs to the period 4 and group 16 of the periodic table. The valence shell electron configuration of the element, which is just above ‘E’ in the group is
  1. (A)3s2.3p43s^2. 3p^43s2.3p4
  2. (B)3d10.4s2,4p43d^{10}. 4s^2, 4p^43d10.4s2,4p4
  3. (C)4d10.5s2,5p44d^{10}. 5s^2, 5p^44d10.5s2,5p4
  4. (D)2s22s^22s2, p4

Correct answer: (A)

Step-by-step solution →
Q30·ChemistrySingle correct
Given are two statements one is labelled as Assertion A and other is labelled as Reason R. Assertion A :Magnesium can reduce Al2O3Al_2O_3Al2​O3​ at a temperature below 1350°C, while above 1350°C aluminium can reduce MgO. Reason R : The melting and boiling points of magnesium are lower than those of aluminium. In light of the above statements. choose most appropriate answer from the options given below:
  1. (A)Both A and R are correct. and R is correct explanation of A.
  2. (B)Both A and R are correct. but R is NOT the correct explanation of A.
  3. (C)A is correct R is not correct.
  4. (D)A is not correct. R is correct.

Correct answer: (B)

Step-by-step solution →
Q31·ChemistrySingle correct
Dihydrogen reacts with CuO to give
  1. (A)CuH2CuH_2CuH2​
  2. (B)Cu
  3. (C)Cu2OCu_2OCu2​O
  4. (D)Cu(OH)2Cu(OH)_2Cu(OH)2​

Correct answer: (B)

Step-by-step solution →
Q32·ChemistrySingle correct
Nitrogen gas is obtained by thermal decomposition of
  1. (A)Ba(NO3)2Ba(NO_3)_2Ba(NO3​)2​
  2. (B)Ba(N3)2Ba(N_3)_2Ba(N3​)2​
  3. (C)NaNO2NaNO_2NaNO2​
  4. (D)NaNO3NaNO_3NaNO3​

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
Given below are two statements : Statement -I :The pentavalent oxide of group- 15 element. E2O5E_2O_5E2​O5​. is less acidic than trivalent oxide. E2O3E_2O_3E2​O3​. of the same element. Statement -II :The acidic character of trivalent oxide of group 15 elements. E2O3E_2O_3E2​O3​. decreases down the group. In light of the above statements. choose most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are true.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I true. but statement II is false.
  4. (D)Statement I is false but statement II is true.

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Which one of the lanthanoids given below is the most stable in divalent form?
  1. (A)Ce (Atomic Number 58)
  2. (B)Sm (Atomic Number 62)
  3. (C)Eu (Atomic Number 63)
  4. (D)Yb (Atomic Number 70)

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are two statements : Statement I : [Ni(CN)4]2−[Ni(CN)4]^{2-}[Ni(CN)4]2− is square planar and diamagnetic complex. with dsp2dsp^2dsp2 hybridization for Ni but [Ni(CO)4][Ni(CO)_4][Ni(CO)4​] is tetrahedral. paramagnetic and with sp3sp^3sp3-hybridication for Ni. Statement II: [NiCl4]2−[NiCl_4]^{2-}[NiCl4​]2− and [Ni(CO)4][Ni(CO)_4][Ni(CO)4​] both have same d-electron configuration have same geometry and are paramagnetic. In light the above statements. choose the correct answer form the options given below:
  1. (A)Both Statement I and Statement II are true.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I is correct but statement II is false.
  4. (D)Statement I is incorrect but statement II is true.

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
Which amongst the following is not a pesticide ?
  1. (A)DDT
  2. (B)Organophosphates
  3. (C)Dieldrin
  4. (D)Sodium arsenite

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
Which one of the following techniques is not used to spot components of a mixture separated on thin layer chromatographic plate?
  1. (A)I2I_2I2​ (Solid)
  2. (B)U.V. Light
  3. (C)Visualisation agent as a component of mobile phase
  4. (D)Spraying of an appropriate reagent

Correct answer: (C)

Step-by-step solution →
Q38·Chemistry·AromaticitySingle correct
Which of the following structures are aromatic in nature?
  1. (A)A,B,C and D
  2. (B)Only A and B
  3. (C)Only A and C
  4. (D)Only B, C and D

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
The major product (P) in the reaction [Ph is – C6H5C_6H_5C6​H5​] is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
The correct structure of product ‘A’ formed in the following reaction. PhCHO+Ph⋅CHO→in D2ONaODA+Ph−CO∥−O−\text{PhCHO} + \text{Ph}\cdot\text{CHO} \xrightarrow[\text{in D}_2\text{O}]{\text{NaOD}} \text{A} + \text{Ph} - \overset{\substack{\text{O}\\\|}}{\text{C}} - \text{O}^-PhCHO+Ph⋅CHONaODin D2​O​A+Ph−CO∥​−O− (Ph is−C6H5)\left(\text{Ph is} - \text{C}_6\text{H}_5\right)(Ph is−C6​H5​)
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Which one of the following compounds is inactive towards SN1S_N1SN​1 reaction?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
A primary aliphatic amine on reaction with nitrous acid in cold (273 K) and there after raising temperature of reaction mixture to room temperature (298 K). Gives a/an
  1. (A)nitrile
  2. (B)alcohol
  3. (C)diazonium salt
  4. (D)secondary amine

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Which one of the following is NOT a copolymer ?
  1. (A)Buna-S
  2. (B)Neoprene
  3. (C)PHBV
  4. (D)Butadiene-styrene

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
Stability of α - Helix structure of proteins depends upon
  1. (A)dipolar interaction
  2. (B)H-bonding interaction
  3. (C)van der Waals forces
  4. (D)π -stacking interaction

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
The formula of the purple colour formed in Laissaigne's test for sulphur using sodium nitroprusside is
  1. (A)NaFe[Fe(CN)6]NaFe[Fe(CN)_6]NaFe[Fe(CN)6​]
  2. (B)Na[Cr(NH3)2(NCS)4]Na[Cr(NH_3)_2(NCS)_4]Na[Cr(NH3​)2​(NCS)4​]
  3. (C)Na2[Fe(CN)5(NO)]Na_2[Fe(CN)_5(NO)]Na2​[Fe(CN)5​(NO)]
  4. (D)Na4[Fe(CN)5(NOS)]Na_4[Fe(CN)_5(NOS)]Na4​[Fe(CN)5​(NOS)]

Correct answer: (D)

Step-by-step solution →
Q46·ChemistryNumerical
A 2.0 g sample containing MnO2MnO_2MnO2​ is treated with HCl liberating Cl2Cl_2Cl2​. The Cl2Cl_2Cl2​ gas is passed into a solution of KI and 60.0 mL of 0.1 M Na2S2O3Na_2S_2O_3Na2​S2​O3​ is required to titrate the liberated iodine. The percentage of MnO2MnO_2MnO2​ in the sample is __________. (Nearest integer) [Atomic masses (in u) Mn = 55; Cl = 35.5; O = 16, I = 127, Na = 23, K = 39, S = 32]

Correct answer: 13

Step-by-step solution →
Q47·ChemistryNumerical
If the work function of a metal is 6.63×10−196.63 \times 10^{-19}6.63×10−19 J, the maximum wavelength of the photon required to remove a photoelectron from the metal is _______ nm. (Nearest integer) [Given : h = 6.63×10−346.63 \times 10^{-34}6.63×10−34 J s, and c = 3×1083 \times 10^{8}3×108 m s−1s^{-1}s−1]

Correct answer: 300

Step-by-step solution →
Q48·ChemistryNumerical
The hybridization of P exhibited in PF5PF_5PF5​ is spxdysp^{x}d^{y}spxdy. The value of y is __________.

Correct answer: 1

Step-by-step solution →
Q49·ChemistryNumerical
4.0 L of an ideal gas is allowed to expand isothermally into vacuum until the total volume is 20 L. The amount of heat absorbed in this expansion is __________ L atm.

Correct answer: 0

Step-by-step solution →
Q50·ChemistryNumerical
The vapour pressures of two volatile liquids A and B at 25°C are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0.3 mole fraction of A, then the mole fraction of liquid B in the vapour phase is x17\frac{x}{17}17x​. The value of x is ________.

Correct answer: 14

Step-by-step solution →
Q51·ChemistryNumerical
The solubility product of a sparingly soluble salt A2X3A_2X_3A2​X3​ is 1.1×10−231.1 \times 10^{-23}1.1×10−23. If specific conductance of the solution is 3×10−53 \times 10^{-5}3×10−5 S m−1m^{-1}m−1, the limiting molar conductivity of the solution is x ×10−3\times 10^{-3}×10−3 S m2m^{2}m2 mol−1mol^{-1}mol−1. The value of x is __________.

Correct answer: 3

Step-by-step solution →
Q52·ChemistryNumerical
The quantity of electricity in Faraday needed to reduce 1 mol of Cr2O72−Cr_2O_7^{2-}Cr2​O72−​ to Cr3+Cr^{3+}Cr3+ is __________.

Correct answer: 6

Step-by-step solution →
Q53·ChemistryNumerical
For a first order reaction A→BA \rightarrow BA→B, the rate constant, k=5.5×10−14s−1k = 5.5 \times 10^{-14} s^{-1}k=5.5×10−14s−1. The time required for 67% completion of reaction is x ×10−1\times 10^{-1}×10−1 times the half life of reaction. The value of x is ________ (Nearest integer) (Given : log 3 = 0.4771)

Correct answer: 16

Step-by-step solution →
Q54·ChemistryNumerical
Number of complexes which will exhibit synergic bonding amongst, [Cr(CO)6][Cr(CO)_6][Cr(CO)6​], [Mn(CO)5][Mn(CO)_5][Mn(CO)5​] and [Mn2(CO)10][Mn_2(CO)_{10}][Mn2​(CO)10​] is ________.

Correct answer: 3

Step-by-step solution →
Q55·ChemistryNumerical
In the estimation of bromine, 0.5 g of an organic compound gave 0.40 g of silver bromide. The percentage of bromine in the given compound is __________% (nearest integer) (Relative atomic masses of Ag and Br are 108u and 80u, respectively).

Correct answer: 34

Step-by-step solution →

Mathematics — JEE Main 28 June 2022 Shift 1

Q56·MathematicsSingle correct
If ∑k=131(31Ck)(31Ck−1)−∑k=130(30Ck)(30Ck−1)=α (60!)(30!)(31!),\sum_{k=1}^{31}\left({}^{31}\mathrm{C}_{k}\right)\left({}^{31}\mathrm{C}_{k-1}\right)-\sum_{k=1}^{30}\left({}^{30}\mathrm{C}_{k}\right)\left({}^{30}\mathrm{C}_{k-1}\right)=\frac{\alpha\,(60!)}{(30!)(31!)},∑k=131​(31Ck​)(31Ck−1​)−∑k=130​(30Ck​)(30Ck−1​)=(30!)(31!)α(60!)​, Where α∈R,\alpha \in \mathrm{R},α∈R, then the value of 16α16\alpha16α is equal to
  1. (A)1411
  2. (B)1320
  3. (C)1615
  4. (D)1855

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correct
Let a function f:N→N\mathrm{f}:\mathbb{N} \to \mathbb{N}f:N→N be defined by f(n)={2n,n=2,4,6,8,.....n−1,n=3,7,11,15,.....n+12,n=1,5,9,13,.....\mathrm{f(n)}=\begin{cases} 2\mathrm{n}, & \mathrm{n}=2,4,6,8,..... \\ \mathrm{n}-1, & \mathrm{n}=3,7,11,15,..... \\ \dfrac{\mathrm{n}+1}{2}, & \mathrm{n}=1,5,9,13,..... \end{cases}f(n)=⎩⎨⎧​2n,n−1,2n+1​,​n=2,4,6,8,.....n=3,7,11,15,.....n=1,5,9,13,.....​ then, f is
  1. (A)one-one but not onto
  2. (B)onto but not one-one
  3. (C)neither one-one nor onto
  4. (D)one-one and onto

Correct answer: (D)

Step-by-step solution →
Q58·Mathematics·Matrices and DeterminantsSingle correct
If the system of linear equations 2x+3y−z=−22x + 3y - z = -22x+3y−z=−2 x+y+z=4x + y + z = 4x+y+z=4 x−y+∣λ∣z=4λ−4x - y + |\lambda| z = 4\lambda - 4x−y+∣λ∣z=4λ−4 where λ∈R,\lambda \in \mathbb{R},λ∈R, has no solution, then
  1. (A)λ=7\lambda = 7λ=7
  2. (B)λ=−7\lambda = -7λ=−7
  3. (C)λ=8\lambda = 8λ=8
  4. (D)λ2=1\lambda^{2} = 1λ2=1

Correct answer: (B)

Step-by-step solution →
Q59·Mathematics·Matrices and DeterminantsSingle correct
Let A be a matrix of order 3 × 3 and det (A) = 2. Then det (det (A) adj (5 adj (A3\mathrm{A}^{3}A3))) is equal to ____.
  1. (A)512×106512 \times 10^{6}512×106
  2. (B)256×106256 \times 10^{6}256×106
  3. (C)1024×1061024 \times 10^{6}1024×106
  4. (D)256×1011256 \times 10^{11}256×1011

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
The total number of 5-digit numbers, formed by using the digits 1, 2, 3, 5, 6, 7 without repetition, which are multiple of 6, is
  1. (A)36
  2. (B)48
  3. (C)60
  4. (D)72

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
Let A1,\mathrm{A}_{1},A1​, A2,\mathrm{A}_{2},A2​, A3,\mathrm{A}_{3},A3​, …… be an increasing geometric progression of positive real numbers. If A1A3A5A7=11296\mathrm{A}_{1}\mathrm{A}_{3}\mathrm{A}_{5}\mathrm{A}_{7}=\frac{1}{1296}A1​A3​A5​A7​=12961​ and A2+A4=736,\mathrm{A}_{2}+\mathrm{A}_{4}=\frac{7}{36},A2​+A4​=367​, then, the value of A6+A8+A10\mathrm{A}_{6}+\mathrm{A}_{8}+\mathrm{A}_{10}A6​+A8​+A10​ is equal to
  1. (A)33
  2. (B)37
  3. (C)43
  4. (D)47

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
Let [t] denote the greatest integer less than or equal to t. Then, the value of the integral ∫01[−8x2+6x−1] dx\int_{0}^{1}[-8x^{2}+6x-1]\,dx∫01​[−8x2+6x−1]dx is equal to
  1. (A)−1-1−1
  2. (B)−54-\frac{5}{4}−45​
  3. (C)17−138\frac{\sqrt{17}-13}{8}817​−13​
  4. (D)17−168\frac{\sqrt{17}-16}{8}817​−16​

Correct answer: (C)

Step-by-step solution →
Q63·Mathematics·Limits and ContinuitySingle correct
Let f:R→R\mathrm{f}:\mathbb{R} \to \mathbb{R}f:R→R be defined as f(x)={[ex],x<0aex+[x−1],0≤x<1b+[sin⁡(πx)],1≤x<2[e−x]−c,x≥2\mathrm{f(x)}=\begin{cases} [e^{x}], & x<0 \\ ae^{x}+[x-1], & 0 \le x < 1 \\ b+[\sin(\pi x)], & 1 \le x < 2 \\ [e^{-x}]-c, & x \ge 2 \end{cases}f(x)=⎩⎨⎧​[ex],aex+[x−1],b+[sin(πx)],[e−x]−c,​x<00≤x<11≤x<2x≥2​ where a,b,c∈Ra, b, c \in \mathbb{R}a,b,c∈R and [t] denotes greatest integer less than or equal to t. Then, which of the following statements is true ?
  1. (A)There exists a,b,c∈Ra, b, c \in \mathbb{R}a,b,c∈R such that f is continuous of R\mathbb{R}R.
  2. (B)If f is discontinuous at exactly one point, then a+b+c=1a + b + c = 1a+b+c=1.
  3. (C)If f is discontinuous at exactly one point, then a+b+c≠1a + b + c \ne 1a+b+c=1.
  4. (D)f is discontinuous at atleast two points, for any values of a, b and c.

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
The area of the region S={(x,y):y2≤8x,y≥2x,x≥1}\mathrm{S}=\{(x,y):y^{2} \le 8x, y \ge \sqrt{2}x, x \ge 1\}S={(x,y):y2≤8x,y≥2​x,x≥1} is
  1. (A)1326\frac{13\sqrt{2}}{6}6132​​
  2. (B)1126\frac{11\sqrt{2}}{6}6112​​
  3. (C)526\frac{5\sqrt{2}}{6}652​​
  4. (D)1926\frac{19\sqrt{2}}{6}6192​​

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let the solution curve y=y(x)y = y(x)y=y(x) of the differential equation, [xx2−y2+eyx]xdydx=x+[xx2−y2+eyx]y\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right]x\frac{dy}{dx}=x+\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right]y[x2−y2​x​+exy​]xdxdy​=x+[x2−y2​x​+exy​]y pass through the points (1, 0) and (2α,α),α>0.(2\alpha, \alpha), \alpha > 0.(2α,α),α>0. Then α\alphaα is equal to
  1. (A)12exp⁡(π6+e−1)\frac{1}{2}\exp\left(\frac{\pi}{6}+\sqrt{e}-1\right)21​exp(6π​+e​−1)
  2. (B)12exp⁡(π3+e−1)\frac{1}{2}\exp\left(\frac{\pi}{3}+\sqrt{e}-1\right)21​exp(3π​+e​−1)
  3. (C)exp⁡(π6+e+1)\exp\left(\frac{\pi}{6}+\sqrt{e}+1\right)exp(6π​+e​+1)
  4. (D)2exp⁡(π3+e−1)2\exp\left(\frac{\pi}{3}+\sqrt{e}-1\right)2exp(3π​+e​−1)

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation x(1−x2)dydx+(3x2y−y−4x3)=0,x>1,x\left(1-x^{2}\right)\frac{dy}{dx}+\left(3x^{2}y-y-4x^{3}\right)=0, x>1,x(1−x2)dxdy​+(3x2y−y−4x3)=0,x>1, with y(2)=−2.y(2) = -2.y(2)=−2. Then y(3)y(3)y(3) is equal to
  1. (A)−18-18−18
  2. (B)−12-12−12
  3. (C)−6-6−6
  4. (D)−3-3−3

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
The number of real solutions of x7+5x3+3x+1=0x^{7}+5x^{3}+3x+1=0x7+5x3+3x+1=0 is equal to ________.
  1. (A)0
  2. (B)1
  3. (C)3
  4. (D)5

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let the eccentricity of the hyperbola H:x2a2−y2b2=1\mathrm{H}:\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1H:a2x2​−b2y2​=1 be 52\sqrt{\frac{5}{2}}25​​ and length of its latus rectum be 62,6\sqrt{2},62​, If y=2x+cy = 2x + cy=2x+c is a tangent to the hyperbola H, then the value of c2c^{2}c2 is equal to
  1. (A)18
  2. (B)20
  3. (C)24
  4. (D)32

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
If the tangents drawn at the point O(0, 0) and P(1+5,2)\mathrm{P}\left(1+\sqrt{5},2\right)P(1+5​,2) on the circle x2+y2−2x−4y=0x^{2}+y^{2}-2x-4y=0x2+y2−2x−4y=0 intersect at the point Q, then the area of the triangle OPQ is equal to
  1. (A)3+52\frac{3+\sqrt{5}}{2}23+5​​
  2. (B)4+252\frac{4+2\sqrt{5}}{2}24+25​​
  3. (C)5+352\frac{5+3\sqrt{5}}{2}25+35​​
  4. (D)7+352\frac{7+3\sqrt{5}}{2}27+35​​

Correct answer: (C)

Step-by-step solution →
Q70·MathematicsSingle correct
If two distinct point Q, R lie on the line of intersection of the planes −x+2y−z=0-x + 2y - z = 0−x+2y−z=0 and 3x−5y+2z=03x - 5y + 2z = 03x−5y+2z=0 and PQ=PR=18\mathrm{PQ}=\mathrm{PR}=\sqrt{18}PQ=PR=18​ where the point P is (1, −2, 3), then the area of the triangle PQR is equal to
  1. (A)2338\frac{2}{3}\sqrt{38}32​38​
  2. (B)4338\frac{4}{3}\sqrt{38}34​38​
  3. (C)8338\frac{8}{3}\sqrt{38}38​38​
  4. (D)1523\sqrt{\frac{152}{3}}3152​​

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
The acute angle between the planes P1P_1P1​ and P2P_2P2​, when P1P_1P1​ and P2P_2P2​ are the planes passing through the intersection of the planes 5x + 8y + 13z − 29 = 0 and 8x − 7y + z − 20 = 0 and the points (2, 1, 3) and (0, 1, 2), respectively, is
  1. (A)π3\frac{\pi}{3}3π​
  2. (B)π4\frac{\pi}{4}4π​
  3. (C)π6\frac{\pi}{6}6π​
  4. (D)π12\frac{\pi}{12}12π​

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
Let the plane P:r⃗⋅a⃗=dP : \vec{r} \cdot \vec{a} = dP:r⋅a=d contain the line of intersection of two planes r⃗⋅(i^+3j^−k^)=6\vec{r} \cdot \left(\hat{i} + 3\hat{j} - \hat{k}\right) = 6r⋅(i^+3j^​−k^)=6 and r⃗⋅(−6i^+5j^−k^)=7\vec{r} \cdot \left(-6\hat{i} + 5\hat{j} - \hat{k}\right) = 7r⋅(−6i^+5j^​−k^)=7. If the plane P passes through the point (2, 3, 12)\left(2,\, 3,\, \frac{1}{2}\right)(2,3,21​), then the value of ∣13a⃗∣2d2\frac{|13\vec{a}|^2}{d^2}d2∣13a∣2​ is equal to
  1. (A)90
  2. (B)93
  3. (C)95
  4. (D)97

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
The probability, that in a randomly selected 3-digit number at least two digits are odd, is
  1. (A)1936\frac{19}{36}3619​
  2. (B)1536\frac{15}{36}3615​
  3. (C)1336\frac{13}{36}3613​
  4. (D)2336\frac{23}{36}3623​

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
Let AB and PQ be two vertical poles, 160 m apart from each other. Let C be the middle point of B and Q, which are feet of these two poles. Let π8\frac{\pi}{8}8π​ and θ be the angles of elevation from C to P and A, respectively. If the height of pole PQ is twice the height of pole AB, then tan⁡2θ\tan^2 \thetatan2θ is equal to
  1. (A)3−222\frac{3-2\sqrt{2}}{2}23−22​​
  2. (B)3+22\frac{3+\sqrt{2}}{2}23+2​​
  3. (C)3−224\frac{3-2\sqrt{2}}{4}43−22​​
  4. (D)3−24\frac{3-\sqrt{2}}{4}43−2​​

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
Let p, q, r be three logical statements. Consider the compound statements S1:((∼p)∨q)∨((∼p)∨r)S_1 : ((\sim p) \vee q) \vee ((\sim p) \vee r)S1​:((∼p)∨q)∨((∼p)∨r) and S2:p→(q∨r)S_2 : p \rightarrow (q \vee r)S2​:p→(q∨r) Then, which of the following is NOT true ?
  1. (A)If S2S_2S2​ is True, then S1S_1S1​ is True
  2. (B)If S2S_2S2​ is False, then S1S_1S1​ is False
  3. (C)If S2S_2S2​ is False, then S1S_1S1​ is True
  4. (D)If S1S_1S1​ is False, then S2S_2S2​ is False

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsNumerical
Let R1R_1R1​ and R2R_2R2​ be relations on the set {1, 2, …, 50} such that R1={(p, pn):p is a prime and n≥0 is an integer}R_1 = \{(p,\, p^n) : p \text{ is a prime and } n \geq 0 \text{ is an integer}\}R1​={(p,pn):p is a prime and n≥0 is an integer} and R2={(p, pn):p is a prime and n=0 or 1}R_2 = \{(p,\, p^n) : p \text{ is a prime and } n = 0 \text{ or } 1\}R2​={(p,pn):p is a prime and n=0 or 1}. Then, the number of elements in R1−R2R_1 - R_2R1​−R2​ is ______.

Correct answer: 8

Step-by-step solution →
Q77·MathematicsNumerical
The number of real solutions of the equation e4x+4e3x−58e2x+4ex+1=0e^{4x} + 4e^{3x} - 58e^{2x} + 4e^{x} + 1 = 0e4x+4e3x−58e2x+4ex+1=0 is ______.

Correct answer: 2

Step-by-step solution →
Q78·MathematicsNumerical
The mean and standard deviation of 15 observations are found to be 8 and 3 respectively. On rechecking it was found that, in the observations, 20 was misread as 5. Then, the correct variance is equal to ______.

Correct answer: 17

Step-by-step solution →
Q79·MathematicsNumerical
If a⃗=2i^+j^+3k^,\vec{a} = 2\hat{i} + \hat{j} + 3\hat{k},a=2i^+j^​+3k^, b⃗=3i^+3j^+k^\vec{b} = 3\hat{i} + 3\hat{j} + \hat{k}b=3i^+3j^​+k^ and c⃗=c1i^+c2j^+c3k^\vec{c} = c_1\hat{i} + c_2\hat{j} + c_3\hat{k}c=c1​i^+c2​j^​+c3​k^ are coplanar vectors and a⃗⋅c⃗=5,\vec{a} \cdot \vec{c} = 5,a⋅c=5, b⃗⊥c⃗,\vec{b} \perp \vec{c},b⊥c, then 122 (c1+c2+c3)122\,(c_1 + c_2 + c_3)122(c1​+c2​+c3​) is equal to ______.

Correct answer: 150

Step-by-step solution →
Q80·MathematicsNumerical
A ray of light passing through the point P(2, 3) reflects on the x-axis at point A and the reflected ray passes through the point Q(5, 4). Let R be the point that divides the line segment AQ internally into the ratio 2 : 1. Let the co-ordinates of the foot of the perpendicular M from R on the bisector of the angle PAQ be (α, β). Then, the value of 7α+3β7\alpha + 3\beta7α+3β is equal to ______.

Correct answer: 31

Step-by-step solution →
Q81·MathematicsNumerical
Let ℓ\ellℓ be a line which is normal to the curve y=2x2+x+2y = 2x^2 + x + 2y=2x2+x+2 at a point P on the curve. If the point Q(6, 4) lies on the line ℓ\ellℓ and O is origin, then the area of the triangle OPQ is equal to ______.

Correct answer: 13

Step-by-step solution →
Q82·MathematicsNumerical
Let A={1, a1, a2……a18, 77}A = \{1,\, a_1,\, a_2 \ldots\ldots a_{18},\, 77\}A={1,a1​,a2​……a18​,77} be a set of integers with 1<a1<a2<…..<a18<771 < a_1 < a_2 < \ldots.. < a_{18} < 771<a1​<a2​<…..<a18​<77. Let the set A+A={x+y:x,y∈A}A + A = \{x + y : x, y \in A\}A+A={x+y:x,y∈A} contain exactly 39 elements. Then, the value of a1+a2+…..+a18a_1 + a_2 + \ldots.. + a_{18}a1​+a2​+…..+a18​ is equal to ______.

Correct answer: 702

Step-by-step solution →
Q83·MathematicsNumerical
The number of positive integers k such that the constant term in the binomial expansion of (2x3+3xk)12\left(2x^3 + \frac{3}{x^k}\right)^{12}(2x3+xk3​)12, x≠0x \neq 0x=0 is 28⋅ℓ,2^8 \cdot \ell,28⋅ℓ, where ℓ\ellℓ is an odd integer, is ______.

Correct answer: 2

Step-by-step solution →
Q84·MathematicsNumerical
The number of elements in the set {z=a+ib∈C:a,b∈Z and 1<∣z−3+2i∣<4}\{z = a + ib \in \mathbb{C} : a, b \in \mathbb{Z} \text{ and } 1 < |z - 3 + 2i| < 4\}{z=a+ib∈C:a,b∈Z and 1<∣z−3+2i∣<4} is ______.

Correct answer: 40

Step-by-step solution →
Q85·MathematicsNumerical
Let the lines y+2x=11+77y + 2x = \sqrt{11} + 7\sqrt{7}y+2x=11​+77​ and 2y+x=211+672y + x = 2\sqrt{11} + 6\sqrt{7}2y+x=211​+67​ be normal to a circle C:(x−h)2+(y−k)2=r2.C : (x - h)^2 + (y - k)^2 = r^2.C:(x−h)2+(y−k)2=r2. If the line 11y−3x=5773+11\sqrt{11}y - 3x = \frac{5\sqrt{77}}{3} + 1111​y−3x=3577​​+11 is tangent to the circle C, then the value of (5h−8k)2+5r2(5h - 8k)^2 + 5r^2(5h−8k)2+5r2 is equal to ______.

Correct answer: 816

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Polymers 64/186
  • Solid State 63/186
  • Aromaticity 22/186
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