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JEE Main 29 July 2022 Shift 2 Question Paper with Answers

29 July 2022 · July session · 89 questions

89 of the 90 questions from the JEE Main 29 July 2022 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
29
Mathematics
30

Physics — JEE Main 29 July 2022 Shift 2

Q1·PhysicsSingle correct
Two identical metallic spheres A and B when placed at certain distance in air repel each other with a force of F. Another identical uncharged sphere C is first placed in contact with A and then in contact with B and finally placed at midpoint between spheres A and B. The force experienced by sphere C will be :
  1. (A)3F/2
  2. (B)3F/4
  3. (C)F
  4. (D)2F

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
Match List I with List II. List I A. Torque B. Stress C. Latent Heat D. Power List II I. Nms−1^{-1}−1 II. J kg−1^{-1}−1 III. Nm IV. Nm−2^{-2}−2 Choose the correct answer from the options given below:
  1. (A)A-III, B-II, C-I, D-IV
  2. (B)A-III, B-IV, C-II, D-I
  3. (C)A-IV, B-I, C-III, D-II
  4. (D)A-II, B-III, C-I, D-IV

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
Two identical thin metal plates has charge q1q_1q1​ and q2q_2q2​ respectively such that q1>q2q_1 > q_2q1​>q2​. The plates were brought close to each other to form a parallel plate capacitor of capacitance C. The potential difference between them is :
  1. (A)(q1+q2)C\frac{(q_1 + q_2)}{C}C(q1​+q2​)​
  2. (B)(q1−q2)C\frac{(q_1 - q_2)}{C}C(q1​−q2​)​
  3. (C)(q1−q2)2C\frac{(q_1 - q_2)}{2C}2C(q1​−q2​)​
  4. (D)2(q1−q2)C\frac{2(q_1 - q_2)}{C}C2(q1​−q2​)​

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Alloys such as constantan and manganin are used in making standard resistance coils. Reason R: Constantan and manganin have very small value of temperature coefficient of resistance. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false.
  4. (D)A is false but R is true.

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
A 1 m long wire is broken into two unequal parts X and Y The X part of the wire is streched into another wire W. Length of W is twice the length of X and the resistance of W is twice that of Y. Find the ratio of length of X and Y.
  1. (A)1 : 4
  2. (B)1 : 2
  3. (C)4 :1
  4. (D)2 : 1

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
A wire X of length 50 cm carrying a current of 2 A is placed parallel to a long wire Y of length 5 m. The wire Y carries a current of 3 A. The distance between two wires is 5 cm and currents flow in the same direction. The force acting on the wire Y is :
  1. (A)1.2×10−51.2 \times 10^{-5}1.2×10−5 N directed towards wire X.
  2. (B)1.2×10−41.2 \times 10^{-4}1.2×10−4 N directed away from wire X.
  3. (C)1.2×10−41.2 \times 10^{-4}1.2×10−4 N directed towards wire X.
  4. (D)2.4×10−52.4 \times 10^{-5}2.4×10−5 N directed towards wire X.

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is
  1. (A)g/2n
  2. (B)g/n
  3. (C)2gn
  4. (D)g/2n2g/2n^{2}g/2n2

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
A circuit element X when connected to an a.c. supply of peak voltage 100 V gives a peak current of 5 A which is in phase with the voltage. A second element Y when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by π2\frac{\pi}{2}2π​. If X and Y are connected in series to the same supply, what will be the rms value of the current in ampere ?
  1. (A)102\frac{10}{\sqrt{2}}2​10​
  2. (B)52\frac{5}{\sqrt{2}}2​5​
  3. (C)525\sqrt{2}52​
  4. (D)52\frac{5}{2}25​

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
An unpolarised light beam of intensity 2I02I_02I0​ is passed through a polaroid P and then through another polaroid Q which is oriented in such a way that its passing axis makes an angle of 30° relative to that of P. The intensity of the emergent light is
  1. (A)I04\frac{I_0}{4}4I0​​
  2. (B)I02\frac{I_0}{2}2I0​​
  3. (C)3I04\frac{3I_0}{4}43I0​​
  4. (D)3I02\frac{3I_0}{2}23I0​​

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
An α particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particals will be :
  1. (A)2:1\sqrt{2} : 12​:1
  2. (B)22:12\sqrt{2} : 122​:1
  3. (C)42:14\sqrt{2} : 142​:1
  4. (D)8 : 1

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
Read the following statements: (A) Volume of the nucleus is directly proportional to the mass number. (B) Volume of the nucleus is independent of mass number. (C) Density of the nucleus is directly proportional to the mass number. (D) Density of the nucleus is directly proportional to the cube root of the mass number. (E) Density of the nucleus is independent of the mass number. Choose the correct option from the following options.
  1. (A)(A) and (D) only.
  2. (B)(A) and (E) only.
  3. (C)(B) and (E) only.
  4. (D)(A) and (C) only

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
An object of mass 1 kg is taken to a height from the surface of earth which is equal to three times the radius of earth. The gain in potential energy of the object will be [If, g=10ms−2^{-2}−2 and radius of earth = 6400 km]
  1. (A)48 MJ
  2. (B)24 MJ
  3. (C)36 MJ
  4. (D)12 MJ

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
A ball is released from a height h. If t1t_1t1​ and t2t_2t2​ be the time required to complete first half and second half of the distance respectively. Then, choose the correct relation between t1t_1t1​ and t2t_2t2​.
  1. (A)t1=(2)t2t_1 = \left(\sqrt{2}\right)t_2t1​=(2​)t2​
  2. (B)t1=(2−1)t2t_1 = \left(\sqrt{2} - 1\right)t_2t1​=(2​−1)t2​
  3. (C)t2=(2+1)t1t_2 = \left(\sqrt{2} + 1\right)t_1t2​=(2​+1)t1​
  4. (D)t2=(2−1)t1t_2 = \left(\sqrt{2} - 1\right)t_1t2​=(2​−1)t1​

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
Two bodies of masses m1=5m_1 = 5m1​=5 kg and m2=3m_2 = 3m2​=3 kg are connected by a light string going over a smooth light pulley on a smooth inclined plane as shown in the figure. The system is at rest. The force exerted by the inclined plane on the body of mass m1m_1m1​ will be :[Take g=10g = 10g=10 ms−2^{-2}−2]
  1. (A)30 N
  2. (B)40 N
  3. (C)50 N
  4. (D)60 N

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
If momentum of a body is increased by 20%, then its kinetic energy increases by :
  1. (A)36%
  2. (B)40%
  3. (C)44%
  4. (D)48%

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
The torque of a force 5i^+3j^−7k^5\hat{i} + 3\hat{j} - 7\hat{k}5i^+3j^​−7k^ about the origin is τ. If the force acts on a particle whose position vector is 2i^+2j^+k^2\hat{i} + 2\hat{j} + \hat{k}2i^+2j^​+k^, then the value of τ will be :
  1. (A)11i^+19j^−4k^11\hat{i} + 19\hat{j} - 4\hat{k}11i^+19j^​−4k^
  2. (B)−11i^+9j^−16k^-11\hat{i} + 9\hat{j} - 16\hat{k}−11i^+9j^​−16k^
  3. (C)−17i^+19j^−4k^-17\hat{i} + 19\hat{j} - 4\hat{k}−17i^+19j^​−4k^
  4. (D)17i^+9j^+16k^17\hat{i} + 9\hat{j} + 16\hat{k}17i^+9j^​+16k^

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A thermodynamic system is taken from an original state D to an intermediate state E by the linear process shown in the figure. Its volume is then reduced to the original volume from E to F by an isobaric process. The total work done by the gas from D to E to F will be
  1. (A)−450 J
  2. (B)450 J
  3. (C)900 J
  4. (D)1350 J

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
The vertical component of the earth's magnetic field is 6×10−56 \times 10^{-5}6×10−5 T at any place where the angle of dip is 37º. The earth's resultant magnetic field at that place will be (Given tan 37º =34= \frac{3}{4}=43​)
  1. (A)8×10−58 \times 10^{-5}8×10−5 T
  2. (B)6×10−56 \times 10^{-5}6×10−5 T
  3. (C)5×10−45 \times 10^{-4}5×10−4 T
  4. (D)1×10−41 \times 10^{-4}1×10−4 T

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
The root mean square speed of smoke particles of mass 5×10−175 \times 10^{-17}5×10−17 kg in their Brownian motion in air at NTP is approximately. [Given k =1.38×10−23= 1.38 \times 10^{-23}=1.38×10−23 JK−1^{-1}−1]
  1. (A)60 mm s−1^{-1}−1
  2. (B)12 mm s−1^{-1}−1
  3. (C)15 mm s−1^{-1}−1
  4. (D)36 mm s−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
Light enters from air into a given medium at an angle of 45° with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of 15° from its original direction. The refractive index of the medium is :
  1. (A)1.732
  2. (B)1.333
  3. (C)1.414
  4. (D)2.732

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsNumerical
A tube of length 50 cm is filled completely with an incompressible liquid of mass 250 g and closed at both ends. The tube is then rotated in horizontal plane about one of its ends with a uniform angular velocity xFx\sqrt{F}xF​ rad s−1^{-1}−1. If F be the force exerted by the liquid at the other end then the value of x will be ______.

Correct answer: 4

Step-by-step solution →
Q22·PhysicsNumerical
Nearly 10% of the power of a 110 W light bulb is converted to visible radiation. The change in average intensities of visible radiation, at a distance of 1 m from the bulb to a distance of 5 m is a×10−2a \times 10^{-2}a×10−2 W/m2^22. The value of 'a' will be

Correct answer: 84

Step-by-step solution →
Q23·PhysicsNumerical
A metal wire of length 0.5 m and cross-sectional area 10−410^{-4}10−4 m2^22 has breaking stress 5×1085 \times 10^{8}5×108 Nm−2^{-2}−2. A block of 10 kg is attached at one end of the string and is rotating in a horizontal circle. The maximum linear velocity of block will be____ ms−1^{-1}−1.

Correct answer: 50

Step-by-step solution →
Q24·PhysicsNumerical
The velocity of a small ball of mass 0.3g and density 8g/cc when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is 1.3 g/cc, then the value of viscous force acting on the ball will be x×10−4x \times 10^{-4}x×10−4 N, the value of x is____. [use g =10= 10=10m/s2^22]

Correct answer: 25

Step-by-step solution →
Q25·PhysicsNumerical
A modulating signal 2sin⁡(6.28×106)t2\sin(6.28 \times 10^{6})t2sin(6.28×106)t is added to the carrier signal 4sin⁡(12.56×109)t4\sin(12.56 \times 10^{9})t4sin(12.56×109)t for amplitude modulation. The combined signal is passed through a non-linear square law device. The output is then passed through a band pass filter. The bandwidth of the output signal of band pass filter will be___MHz.

Correct answer: 2

Step-by-step solution →
Q26·PhysicsNumerical
The speed of a transverse wave passing through a string of length 50 cm and mass 10 g is 60 ms−1^{-1}−1. The area of cross-section of the wire is 2.0 mm2^22 and its Young's modulus is 1.2×10111.2 \times 10^{11}1.2×1011 Nm−2^{-2}−2. The extension of the wire over its natural length due to its tension will be x×10−5x \times 10^{-5}x×10−5 m. The value of x is_______.

Correct answer: 15

Step-by-step solution →
Q27·PhysicsNumerical
The metallic bob of simple pendulum has the relative density 5. The time period of this pendulum is 10 s. If the metallic bob is immersed in water, then the new time period becomes 5x5\sqrt{x}5x​ s. The value of x will be ________.

Correct answer: 5

Step-by-step solution →
Q28·PhysicsNumerical
A 8 V Zener diode along with a series resistance R is connected across a 20 V supply (as shown in the figure). If the maximum Zener current is 25 mA, then the minimum value of R will be ______Ω.

Correct answer: 480

Step-by-step solution →
Q29·PhysicsNumerical
Two radioactive materials A and B have decay constants 25λ and 16λ respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of B to that of A will be "e" after a time 1aλ\frac{1}{a\lambda}aλ1​. The value of a is________.

Correct answer: 9

Step-by-step solution →
Q30·PhysicsNumerical
A capacitor of capacitance 500 μF is charged completely using a dc supply of 100 V. It is now connected to an inductor of inductance 50 mH to form an LC circuit. The maximum current in LC circuit will be _______ A.

Correct answer: 10

Step-by-step solution →

Chemistry — JEE Main 29 July 2022 Shift 2

Q31·ChemistrySingle correct
Consider the reaction 4HNO3_{3}3​(l) + 3KCl(s) → Cl2_{2}2​(g) + NOCl(g) + 2H2_{2}2​O(g) + 3KNO3_{3}3​(s) The amount of HNO3_{3}3​ required to produce 110.0 g of KNO3_{3}3​ is : (Given : Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.)
  1. (A)32.2 g
  2. (B)69.4 g
  3. (C)91.5 g
  4. (D)162.5 g

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
Given below are the quantum numbers for 4 electrons. A. n = 3, lll = 2, ml_{l}l​ = 1, ms_{s}s​ = +1/2 B. n = 4, lll = 1, ml_{l}l​ = 0, ms_{s}s​ = +1/2 C. n = 4, lll = 2, ml_{l}l​ = −2, ms_{s}s​ = −1/2 D. n = 3, lll = 1, ml_{l}l​ = −1, ms_{s}s​ = +1/2 The correct order of increasing energy is :
  1. (A)D < B < A < C
  2. (B)D < A < B < C
  3. (C)B < D < A < C
  4. (D)B < D < C < A

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
C(s) + O2_{2}2​(g) → CO2_{2}2​(g) + 400 kJ C(s) + 12\frac{1}{2}21​O2_{2}2​(g) → CO(g) + 100 kJ When coal of purity 60% is allowed to burn in presence of insufficient oxygen, 60% of carbon is converted into 'CO' and the remaining is converted into 'CO2_{2}2​'. The heat generated when 0.6 kg of coal is burnt is ______.
  1. (A)1600 kJ
  2. (B)3200 kJ
  3. (C)4400 kJ
  4. (D)6600 kJ

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
200 mL of 0.01 M HCl is mixed with 400 mL of 0.01M H2_{2}2​SO4_{4}4​. The pH of the mixture is ____.
  1. (A)1.14
  2. (B)1.78
  3. (C)2.34
  4. (D)3.02

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are the critical temperatures of some of the gases : Gas — Critical temperature (K) He — 5.2 CH4_{4}4​ — 190 CO2_{2}2​ — 304.2 NH3_{3}3​ — 405.5 The gas showing least adsorption on a definite amount of charcoal is :
  1. (A)He
  2. (B)CH4_{4}4​
  3. (C)CO2_{2}2​
  4. (D)NH3_{3}3​

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
In liquation process used for tin (Sn), the metal :
  1. (A)is reacted with acid
  2. (B)is dissolved in water
  3. (C)is brought to molten form which is made to flow on a slope
  4. (D)is fused with NaOH.

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
Given below are two statements. Statement I : Stannane is an example of a molecular hydride. Statement II : Stannane is a planar molecule. In the light of the above statement, choose the most appropriate answer from the options given below :
  1. (A)Both Statement I and Statement II are true.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Statement I is false but Statement II is true.

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Portland cement contains 'X' to enhance the setting time. What is 'X'?
  1. (A)CaSO4_{4}4​. 12\frac{1}{2}21​ H2_{2}2​O
  2. (B)CaSO4_{4}4​.2H2_{2}2​O
  3. (C)CaSO4_{4}4​
  4. (D)CaCO3_{3}3​

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
When borax is heated with CoO on a platinum loop, blue coloured bead formed is largely due to :
  1. (A)B2_{2}2​O3_{3}3​
  2. (B)Co(BO2_{2}2​)2_{2}2​
  3. (C)CoB4_{4}4​O7_{7}7​
  4. (D)Co[B4_{4}4​O5_{5}5​(OH)4_{4}4​]

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Which of the following 3d-metal ion will give the lowest enthalpy of hydration (Δhyd_{hyd}hyd​H) when dissolved in water ?
  1. (A)Cr2+^{2+}2+
  2. (B)Mn2+^{2+}2+
  3. (C)Fe2+^{2+}2+
  4. (D)Co2+^{2+}2+

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Dinitrogen is a robust compound, but reacts at high altitude to form oxides. The oxide of nitrogen that can damage plant leaves and retard photosynthesis is :
  1. (A)NO
  2. (B)NO3−_{3}^{-}3−​
  3. (C)NO2_{2}2​
  4. (D)NO2−_{2}^{-}2−​

Correct answer: (C)

Step-by-step solution →
Q42·Chemistry·IUPAC NomenclatureSingle correct
Correct structure of γ-methylcyclohexane carbaldehyde is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q43·ChemistrySingle correct
Compound 'A' undergoes following sequence of reactions to give compound 'B'. The correct structure and chirality of compound 'B' is: [where Et is –C2_{2}2​H5_{5}5​]
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q44·Chemistry·Electronic Effects and StabilitySingle correct
Given below are two statements. Statement I and Statement II are shown in the figure. In the light of the above statement, choose the most appropriate answer from the options given below.
  1. (A)Both Statement I and Statement II are correct
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
When enthanol is heated with conc. H2_{2}2​SO4_{4}4​, a gas is produced. The compound formed, when this gas is treated with cold dilute aqueous solution of Baeyer's reagent, is :
  1. (A)Formaldehyde
  2. (B)Formic acid
  3. (C)Glycol
  4. (D)Ethanoic acid

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
The Hinsberg reagent is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
Which of the following is NOT a natural polymer?
  1. (A)Protein
  2. (B)Starch
  3. (C)Rubber
  4. (D)Rayon

Correct answer: (D)

Step-by-step solution →
Q48·ChemistrySingle correct
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Amylose is insoluble in water. Reason R : Amylose is a long linear molecule with more than 200 glucose units. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Both A and R are correct and R is the correct explanation of A.
  2. (B)Both A and R are correct and R is NOT the correct explanation of A.
  3. (C)A is correct but R is not correct.
  4. (D)A is not correct but R is correct.

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
A compound 'X' is a weak acid and it exhibits colour change at pH close to the equivalence point during neutralization of NaOH with CH3_{3}3​COOH. Compound 'X' exists in ionized form in basic medium. The compound 'X' is :
  1. (A)methyl orange
  2. (B)methyl red
  3. (C)phenolphthalein
  4. (D)erichrome Black T

Correct answer: (C)

Step-by-step solution →
Q50·ChemistryNumerical
'x' g of molecular oxygen (O2_{2}2​) is mixed with 200 g of neon (Ne). The total pressure of the non-reactive mixture of O2_{2}2​ and Ne in the cylinder is 25 bar. The partial pressure of Ne is 20 bar at the same temperature and volume. The value of 'x' is_____. [Given: Molar mass of O2_{2}2​ = 32 g mol−1^{-1}−1. Molar mass of Ne = 20 g mol−1^{-1}−1]

Correct answer: 80

Step-by-step solution →
Q51·ChemistryNumerical
Consider, PF5_{5}5​, BrF5_{5}5​, PCl3_{3}3​, SF6_{6}6​, [ICl4_{4}4​]−^{-}−, ClF3_{3}3​ and IF5_{5}5​. Amongst the above molecule(s)/ion(s), the number of molecule(s)/ion(s) having sp3^{3}3d2^{2}2 hybridisation is____.

Correct answer: 4

Step-by-step solution →
Q52·ChemistryNumerical
1.80 g of solute A was dissolved in 62.5 cm3^{3}3 of ethanol and freezing point of the solution was found to be 155.1 K. The molar mass of solute A is __g mol−1^{-1}−1. [Given: Freezing point of ethanol is 156.0 K. Density of ethanol is 0.80 g cm−3^{-3}−3. Freezing point depression constant of ethanol is 2.00 K kg mol−1^{-1}−1]

Correct answer: 80

Step-by-step solution →
Q53·ChemistryNumerical
For a cell, Cu(s) |Cu2+^{2+}2+(0.001M| |Ag+^{+}+(0.01M)| Ag(s) the cell potential is found to be 0.43 V at 298 K. The magnitude of standard electrode potential for Cu2+^{2+}2+/Cu is ___×10−2\times 10^{-2}×10−2 V. [Given : EAg+/Ag⊖E^{\ominus}_{Ag^{+}/Ag}EAg+/Ag⊖​ = 0.80V and 2.303RTF\frac{2.303RT}{F}F2.303RT​ = 0.06V]

Correct answer: 34

Step-by-step solution →
Q54·ChemistryNumerical
Assuming 1μ\muμg of trace radioactive element X with a half life of 30 years is absorbed by a growing tree. The amount of X remaining in the tree after 100 years is___×10−1μ\times 10^{-1}\mu×10−1μg. [Given : ln 10 = 2.303; log2 = 0.30]

Correct answer: 1

Step-by-step solution →
Q55·ChemistryNumerical
Sum of oxidation state (magnitude) and coordination number of cobalt in Na[Co(bpy)Cl4_{4}4​] is__. (Given bpy = )

Correct answer: 9

Step-by-step solution →
Q56·ChemistryNumerical
Consider the following sulphure based oxoacids. H2_{2}2​SO3_{3}3​, H2_{2}2​SO4_{4}4​, H2_{2}2​S2_{2}2​O8_{8}8​ and H2_{2}2​S2_{2}2​O7_{7}7​. Amongst these oxoacids, the number of those with peroxo(O-O) bond is______.

Correct answer: 1

Step-by-step solution →
Q57·ChemistryNumerical
A 1.84 mg sample of polyhydric alcoholic compound 'X' of molar mass 92.0 g/mol gave 1.344 mL of H2_{2}2​ gas at STP. The number of alcoholic hydrogens present in compound 'X' is____.

Correct answer: 6

Step-by-step solution →
Q58·ChemistryNumerical
The number of stereoisomers formed in a reaction of (±\pm±) Ph(C=O) C(OH)(CN)Ph with HCN is_____.

Correct answer: 3

Step-by-step solution →
Q59·ChemistryNumerical
The number of chlorine atoms in bithionol is____.

Correct answer: 4

Step-by-step solution →

Mathematics — JEE Main 29 July 2022 Shift 2

Q60·MathematicsSingle correct
If z≠0z \neq 0z=0 be a complex number such that ∣z−1z∣=2\left| z - \frac{1}{z} \right| = 2​z−z1​​=2, then the maximum value of ∣z∣|z|∣z∣ is:
  1. (A)2\sqrt{2}2​
  2. (B)111
  3. (C)2−1\sqrt{2} - 12​−1
  4. (D)2+1\sqrt{2} + 12​+1

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
Which of the following matrices can NOT be obtained from the matrix [−121−1]\begin{bmatrix} -1 & 2 \\ 1 & -1 \end{bmatrix}[−11​2−1​] by a single elementary row operation?
  1. (A)[011−1]\begin{bmatrix} 0 & 1 \\ 1 & -1 \end{bmatrix}[01​1−1​]
  2. (B)[1−1−12]\begin{bmatrix} 1 & -1 \\ -1 & 2 \end{bmatrix}[1−1​−12​]
  3. (C)[−12−27]\begin{bmatrix} -1 & 2 \\ -2 & 7 \end{bmatrix}[−1−2​27​]
  4. (D)[−12−13]\begin{bmatrix} -1 & 2 \\ -1 & 3 \end{bmatrix}[−1−1​23​]

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
If the system of equations x+y+z=6x + y + z = 6x+y+z=6 2x+5y+αz=β2x + 5y + \alpha z = \beta2x+5y+αz=β x+2y+3z=14x + 2y + 3z = 14x+2y+3z=14 has infinitely many solutions, then α+β\alpha + \betaα+β is equal to :
  1. (A)888
  2. (B)363636
  3. (C)444444
  4. (D)484848

Correct answer: (C)

Step-by-step solution →
Q63·Mathematics·Limits and ContinuitySingle correct
Let the function f(x)={log⁡e(1+5x)−log⁡e(1+αx)x;if x≠010;if x=0f(x) = \begin{cases} \dfrac{\log_e (1 + 5x) - \log_e (1 + \alpha x)}{x} & ; \text{if } x \neq 0 \\ 10 & ; \text{if } x = 0 \end{cases}f(x)=⎩⎨⎧​xloge​(1+5x)−loge​(1+αx)​10​;if x=0;if x=0​ be continuous at x=0x = 0x=0. The α\alphaα is equal to :
  1. (A)101010
  2. (B)−10-10−10
  3. (C)555
  4. (D)−5-5−5

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
If [t][t][t] denotes the greatest integer ≤t\leq t≤t, then the value of ∫01[2x−∣3x2−5x+2∣+1]dx\int_{0}^{1} \left[ 2x - |3x^2 - 5x + 2| + 1 \right] dx∫01​[2x−∣3x2−5x+2∣+1]dx is:
  1. (A)37+13−46\frac{\sqrt{37} + \sqrt{13} - 4}{6}637​+13​−4​
  2. (B)37−13−46\frac{\sqrt{37} - \sqrt{13} - 4}{6}637​−13​−4​
  3. (C)−37−13+46\frac{-\sqrt{37} - \sqrt{13} + 4}{6}6−37​−13​+4​
  4. (D)−37+13+46\frac{-\sqrt{37} + \sqrt{13} + 4}{6}6−37​+13​+4​

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
Let {an}n=0∞\{a_n\}_{n=0}^{\infty}{an​}n=0∞​ be a sequence such that a0=a1=0a_0 = a_1 = 0a0​=a1​=0 and an+2=3an+1−2an+1a_{n+2} = 3a_{n+1} - 2a_n + 1an+2​=3an+1​−2an​+1, ∀ n≥0\forall\ n \geq 0∀ n≥0. Then a25 a23−2 a25 a22−2 a23 a24+4 a22 a24a_{25}\, a_{23} - 2\, a_{25}\, a_{22} - 2\, a_{23}\, a_{24} + 4\, a_{22}\, a_{24}a25​a23​−2a25​a22​−2a23​a24​+4a22​a24​ is equal to:
  1. (A)483483483
  2. (B)528528528
  3. (C)575575575
  4. (D)624624624

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
∑r=120(r2+1)(r!)\sum_{r=1}^{20} \left( r^2 + 1 \right)\left( r! \right)∑r=120​(r2+1)(r!) is equal to:
  1. (A)22!−21!22! - 21!22!−21!
  2. (B)22!−2 (21!)22! - 2\,(21!)22!−2(21!)
  3. (C)21!−2 (20!)21! - 2\,(20!)21!−2(20!)
  4. (D)21!−20!21! - 20!21!−20!

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
For I(x)=∫sec⁡2x−2022sin⁡2022xdxI(x) = \int \frac{\sec^2 x - 2022}{\sin^{2022} x} dxI(x)=∫sin2022xsec2x−2022​dx, if I(π4)=21011I\left( \frac{\pi}{4} \right) = 2^{1011}I(4π​)=21011, then
  1. (A)31010I(π3)−I(π6)=03^{1010} I\left( \frac{\pi}{3} \right) - I\left( \frac{\pi}{6} \right) = 031010I(3π​)−I(6π​)=0
  2. (B)31010I(π6)−I(π3)=03^{1010} I\left( \frac{\pi}{6} \right) - I\left( \frac{\pi}{3} \right) = 031010I(6π​)−I(3π​)=0
  3. (C)31011I(π3)−I(π6)=03^{1011} I\left( \frac{\pi}{3} \right) - I\left( \frac{\pi}{6} \right) = 031011I(3π​)−I(6π​)=0
  4. (D)31011I(π6)−I(π3)=03^{1011} I\left( \frac{\pi}{6} \right) - I\left( \frac{\pi}{3} \right) = 031011I(6π​)−I(3π​)=0

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
If the solution curve of the differential equation dydx=x+y−2x−y\frac{dy}{dx} = \frac{x + y - 2}{x - y}dxdy​=x−yx+y−2​ passes through the point (2,1)(2, 1)(2,1) and (k+1,2)(k + 1, 2)(k+1,2), k>0k > 0k>0, then
  1. (A)2tan⁡−1(1k)=log⁡e(k2+1)2\tan^{-1}\left( \frac{1}{k} \right) = \log_e \left( k^2 + 1 \right)2tan−1(k1​)=loge​(k2+1)
  2. (B)tan⁡−1(1k)=log⁡e(k2+1)\tan^{-1}\left( \frac{1}{k} \right) = \log_e \left( k^2 + 1 \right)tan−1(k1​)=loge​(k2+1)
  3. (C)2tan⁡−1(1k+1)=log⁡e(k2+2k+2)2\tan^{-1}\left( \frac{1}{k + 1} \right) = \log_e \left( k^2 + 2k + 2 \right)2tan−1(k+11​)=loge​(k2+2k+2)
  4. (D)2tan⁡−1(1k)=log⁡e(k2+1k2)2\tan^{-1}\left( \frac{1}{k} \right) = \log_e \left( \frac{k^2 + 1}{k^2} \right)2tan−1(k1​)=loge​(k2k2+1​)

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution curve of the differential equation dydx+(2x2+11x+13x3+6x2+11x+6)y=(x+3)x+1\frac{dy}{dx} + \left( \frac{2x^2 + 11x + 13}{x^3 + 6x^2 + 11x + 6} \right) y = \frac{(x + 3)}{x + 1}dxdy​+(x3+6x2+11x+62x2+11x+13​)y=x+1(x+3)​, x>−1x > -1x>−1, which passes through the point (0,1)(0, 1)(0,1). Then y(1)y(1)y(1) is equal to:
  1. (A)12\frac{1}{2}21​
  2. (B)32\frac{3}{2}23​
  3. (C)52\frac{5}{2}25​
  4. (D)72\frac{7}{2}27​

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
Let m1m_1m1​, m2m_2m2​ be the slopes of two adjacent sides of a square of side aaa such that a2+11a+3(m22+m22)=220a^2 + 11a + 3\left( m_2^2 + m_2^2 \right) = 220a2+11a+3(m22​+m22​)=220. If one vertex of the square is (10(cos⁡α−sin⁡α), 10(sin⁡α+cos⁡α))(10(\cos\alpha - \sin\alpha),\ 10(\sin\alpha + \cos\alpha))(10(cosα−sinα), 10(sinα+cosα)), where α∈(0,π2)\alpha \in \left( 0, \frac{\pi}{2} \right)α∈(0,2π​) and the equation of one diagonal is (cos⁡α−sin⁡α)x+(sin⁡α+cos⁡α)y=10(\cos\alpha - \sin\alpha)x + (\sin\alpha + \cos\alpha)y = 10(cosα−sinα)x+(sinα+cosα)y=10, then 72(sin⁡4α+cos⁡4α)+a2−3a+1372(\sin^4\alpha + \cos^4\alpha) + a^2 - 3a + 1372(sin4α+cos4α)+a2−3a+13 is equal to:
  1. (A)119119119
  2. (B)128128128
  3. (C)145145145
  4. (D)155155155

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
The number of elements in the set S={x∈R:2cos⁡(x2+x6)=4x+4−x}S = \left\{ x \in \mathbb{R} : 2\cos\left( \frac{x^2 + x}{6} \right) = 4^x + 4^{-x} \right\}S={x∈R:2cos(6x2+x​)=4x+4−x} is:
  1. (A)111
  2. (B)333
  3. (C)000
  4. (D)infinite

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
Let A(α,−2)A(\alpha, -2)A(α,−2), B(α,6)B(\alpha, 6)B(α,6) and C(α4,−2)C\left( \frac{\alpha}{4}, -2 \right)C(4α​,−2) be vertices of a △ABC\triangle ABC△ABC. If (5,α4)\left( 5, \frac{\alpha}{4} \right)(5,4α​) is the circumcentre of △ABC\triangle ABC△ABC, then which of the following is NOT correct about △ABC\triangle ABC△ABC:
  1. (A)ares is 24
  2. (B)perimeter is 25
  3. (C)circumradius is 5
  4. (D)inradius is 2

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
Let Q be the foot of perpendicular drawn from the point P(1,2,3)P(1, 2, 3)P(1,2,3) to the plane x+2y+z=14x + 2y + z = 14x+2y+z=14. If R is a point on the plane such that ∠PRQ=60∘\angle PRQ = 60^\circ∠PRQ=60∘, then the area of △PQR\triangle PQR△PQR is equal to:
  1. (A)32\frac{\sqrt{3}}{2}23​​
  2. (B)3\sqrt{3}3​
  3. (C)232\sqrt{3}23​
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
If (2,3,9)(2, 3, 9)(2,3,9), (5,2,1)(5, 2, 1)(5,2,1), (1,λ,8)(1, \lambda, 8)(1,λ,8) and (λ,2,3)(\lambda, 2, 3)(λ,2,3) are coplanar, then the product of all possible values of λ\lambdaλ is:
  1. (A)212\frac{21}{2}221​
  2. (B)598\frac{59}{8}859​
  3. (C)578\frac{57}{8}857​
  4. (D)958\frac{95}{8}895​

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsSingle correct
Bag I contains 3 red, 4 black and 3 white balls and Bag II contains 2 red, 5 black and 2 white balls. One ball is transferred from Bag I to Bag II and then a ball is draw from Bag II. The ball so drawn is found to be black in colour. Then the probability, that the transferred ball is red, is:
  1. (A)49\frac{4}{9}94​
  2. (B)518\frac{5}{18}185​
  3. (C)16\frac{1}{6}61​
  4. (D)310\frac{3}{10}103​

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let S={z=x+iy:∣z−1+i∣≥∣z∣,∣z∣<2,∣z+i∣=∣z−1∣}S = \{ z = x + iy : |z - 1 + i| \ge |z|, |z| < 2, |z + i| = |z - 1| \}S={z=x+iy:∣z−1+i∣≥∣z∣,∣z∣<2,∣z+i∣=∣z−1∣}. Then the set of all values of x, for which w=2x+iy∈Sw = 2x + iy \in Sw=2x+iy∈S for some y∈Ry \in \mathbb{R}y∈R, is
  1. (A)(−2,122]\left(-\sqrt{2}, \frac{1}{2\sqrt{2}}\right](−2​,22​1​]
  2. (B)(−12,14]\left(-\frac{1}{\sqrt{2}}, \frac{1}{4}\right](−2​1​,41​]
  3. (C)(−2,12]\left(-\sqrt{2}, \frac{1}{2}\right](−2​,21​]
  4. (D)(−12,122]\left(-\frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}\right](−2​1​,22​1​]

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsSingle correct
Let a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c}a,b,c be three coplanar concurrent vectors such that angles between any two of them is same. If the product of their magnitudes is 14 and (a⃗×b⃗)⋅(b⃗×c⃗)+(b⃗×c⃗)⋅(c⃗×a⃗)+(c⃗×a⃗)⋅(a⃗×b⃗)=168\left(\vec{a} \times \vec{b}\right) \cdot \left(\vec{b} \times \vec{c}\right) + \left(\vec{b} \times \vec{c}\right) \cdot \left(\vec{c} \times \vec{a}\right) + \left(\vec{c} \times \vec{a}\right) \cdot \left(\vec{a} \times \vec{b}\right) = 168(a×b)⋅(b×c)+(b×c)⋅(c×a)+(c×a)⋅(a×b)=168 then ∣a⃗∣+∣b⃗∣+∣c⃗∣|\vec{a}| + |\vec{b}| + |\vec{c}|∣a∣+∣b∣+∣c∣ is equal to:
  1. (A)10
  2. (B)14
  3. (C)16
  4. (D)18

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
The domain of the function f(x)=sin⁡−1(x2−3x+2x2+2x+7)f(x) = \sin^{-1}\left(\frac{x^2 - 3x + 2}{x^2 + 2x + 7}\right)f(x)=sin−1(x2+2x+7x2−3x+2​) is :
  1. (A)[1,∞)[1, \infty)[1,∞)
  2. (B)(−1,2](-1, 2](−1,2]
  3. (C)[−1,∞)[-1, \infty)[−1,∞)
  4. (D)(−∞,2](-\infty, 2](−∞,2]

Correct answer: (C)

Step-by-step solution →
Q79·MathematicsSingle correct
The statement (p⇒q)∨(p⇒r)\left(p \Rightarrow q\right) \vee \left(p \Rightarrow r\right)(p⇒q)∨(p⇒r) is NOT equivalent to:
  1. (A)(p∧(∼r))⇒q\left(p \wedge (\sim r)\right) \Rightarrow q(p∧(∼r))⇒q
  2. (B)(∼q)⇒((∼r)∨p)(\sim q) \Rightarrow \left((\sim r) \vee p\right)(∼q)⇒((∼r)∨p)
  3. (C)p⇒(q∨r)p \Rightarrow (q \vee r)p⇒(q∨r)
  4. (D)(p∧(∼q))⇒r\left(p \wedge (\sim q)\right) \Rightarrow r(p∧(∼q))⇒r

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsNumerical
The sum and product of the mean and variance of a binomial distribution are 82.5 and 1350 respectively. They the number of trials in the binomial distribution is:

Correct answer: 96

Step-by-step solution →
Q81·MathematicsNumerical
Let α,β\alpha, \betaα,β (α>β)(\alpha > \beta)(α>β) be the roots of the quadratic equation x2−x−4=0x^2 - x - 4 = 0x2−x−4=0. If Pn=αn−βnP_n = \alpha^n - \beta^nPn​=αn−βn, n∈Nn \in \mathbb{N}n∈N, then P15P16−P14P16−P152+P14P15P13P14\frac{P_{15}P_{16} - P_{14}P_{16} - P_{15}^2 + P_{14}P_{15}}{P_{13}P_{14}}P13​P14​P15​P16​−P14​P16​−P152​+P14​P15​​ is equal to ______.

Correct answer: 16

Step-by-step solution →
Q82·MathematicsNumerical
Let x=[111]x = \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix}x=​111​​ and A=[−12301600−1]A = \begin{bmatrix} -1 & 2 & 3 \\ 0 & 1 & 6 \\ 0 & 0 & -1 \end{bmatrix}A=​−100​210​36−1​​. For k∈Nk \in \mathbb{N}k∈N, if X′AkX=33X' A^k X = 33X′AkX=33, then k is equal to:

Correct answer: 10

Step-by-step solution →
Q83·MathematicsNumerical
The number of natural numbers lying between 1012 and 23421 that can be formed using the digits 2, 3, 4, 5, 6 (repetition of digits is not allowed) and divisible by 55 is____,

Correct answer: 6

Step-by-step solution →
Q84·MathematicsNumerical
If ∑k=110K2(10CK)2=22000L\sum_{k=1}^{10} K^2 \left({}^{10}C_K\right)^2 = 22000L∑k=110​K2(10CK​)2=22000L, then L is equal to ___.

Correct answer: 221

Step-by-step solution →
Q85·Mathematics·DifferentiabilityNumerical
If [t] denotes the greatest integer ≤t\le t≤t, then number of points, at which the function f(x)=4∣2x+3∣+9[x+12]−12[x+20]f(x) = 4|2x + 3| + 9\left[x + \frac{1}{2}\right] - 12[x + 20]f(x)=4∣2x+3∣+9[x+21​]−12[x+20] is not differentiable in the open interval (−20,20)(-20, 20)(−20,20), is___.

Correct answer: 79

Step-by-step solution →
Q86·MathematicsNumerical
If the tangent to the curve y=x3−x2+xy = x^3 - x^2 + xy=x3−x2+x at the point (a,b)(a, b)(a,b) is also tangent to the curve y=5x2+2x−25y = 5x^2 + 2x - 25y=5x2+2x−25 at the point (2,−1)(2, -1)(2,−1), then ∣2a+9b∣|2a + 9b|∣2a+9b∣ is equal to ______.

Correct answer: 195

Step-by-step solution →
Q87·MathematicsNumerical
Let AB be a chord of length 12 of the circle (x−2)2+(y+1)2=1694(x - 2)^2 + (y + 1)^2 = \frac{169}{4}(x−2)2+(y+1)2=4169​. If tangents drawn to the circle at points A and B intersect at the point P, then five times the distance of point P from chord AB is equal to ___.

Correct answer: 72

Step-by-step solution →
Q88·MathematicsNumerical
Let a⃗\vec{a}a and b⃗\vec{b}b be two vectors such that ∣a⃗+b⃗∣2=∣a⃗∣2+2∣b⃗∣2|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + 2|\vec{b}|^2∣a+b∣2=∣a∣2+2∣b∣2, a⃗⋅b⃗=3\vec{a} \cdot \vec{b} = 3a⋅b=3 and ∣a⃗×b⃗∣2=75|\vec{a} \times \vec{b}|^2 = 75∣a×b∣2=75. Then ∣a⃗∣2|\vec{a}|^2∣a∣2 is equal to____.

Correct answer: 14

Step-by-step solution →
Q89·MathematicsNumerical
Let S={(x,y)∈N×N:9(x−3)2+16(y−4)2≤144}S = \left\{ (x, y) \in \mathbb{N} \times \mathbb{N} : 9(x - 3)^2 + 16(y - 4)^2 \le 144 \right\}S={(x,y)∈N×N:9(x−3)2+16(y−4)2≤144} and T={(x,y)∈R×R:(x−7)2+(y−4)2≤36}T = \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : (x - 7)^2 + (y - 4)^2 \le 36 \right\}T={(x,y)∈R×R:(x−7)2+(y−4)2≤36}. The n(S∩T)n(S \cap T)n(S∩T) is equal to______.

Correct answer: 27

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • Chemistry in Everyday Life 60/186
  • States of Matter: Gases and Liquids 52/186
  • Magnetism and Matter 50/186
  • IUPAC Nomenclature 37/186
← 29 Jul Shift 1 2022All papers24 Jan Shift 1 2023 →

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