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JEE Main 10 April 2023 Shift 1 Question Paper with Answers

10 April 2023 · April session · 90 questions

The complete JEE Main 10 April 2023 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 10 April 2023 Shift 1

Q1·PhysicsSingle correct
A physical quantity P is given as P=a2b3cdP=\dfrac{a^2 b^3}{c\sqrt d}P=cd​a2b3​. The percentage error in the measurement of a, b, c and d are 1%,2%,3%1\%, 2\%, 3\%1%,2%,3% and 4%4\%4% respectively. The percentage error in the measurement of quantity P will be
  1. (A)13%
  2. (B)14%
  3. (C)15%
  4. (D)16%

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
Assuming the earth to be a sphere of uniform mass density, the weight of a body at a depth R2\dfrac{R}{2}2R​ from the surface of earth, if its weight on the surface of earth is 200 N, will be: (Given R = Radius of earth)
  1. (A)400 N
  2. (B)500 N
  3. (C)300 N
  4. (D)100 N

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
A zener diode of power rating 1.6 W is to be used as voltage regulator. If the zener diode has a breakdown of 8V and it has to regulate voltage fluctuating between 3V and 10 V, the value of resistance R for safe operation of diode will be:
  1. (A)13.3 Ω13.3\,\Omega13.3Ω
  2. (B)12 Ω12\,\Omega12Ω
  3. (C)10 Ω10\,\Omega10Ω
  4. (D)11 Ω11\,\Omega11Ω

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
The range of the projectile projected at an angle of 15°15°15° with horizontal is 50 m. If the projectile is projected with same velocity at an angle of 45°45°45° with horizontal, then the range will be
  1. (A)50 m
  2. (B)50250\sqrt2502​ m
  3. (C)100 m
  4. (D)1002100\sqrt21002​ m

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correct
A carrier wave of amplitude 15V is modulated by a sinusoidal base band signal of amplitude 3V. The ratio of maximum amplitude to minimum amplitude in an amplitude modulated wave is:
  1. (A)2
  2. (B)32\dfrac3223​
  3. (C)5
  4. (D)12\dfrac1221​

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
The angular momentum for the electron in Bohr's orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be:
  1. (A)L2\dfrac{L}{2}2L​
  2. (B)zero
  3. (C)L
  4. (D)2L

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correct
A particle of mass m moving with velocity v collides with a stationary particle of mass 2m. After collision, they stick together and continue to move together with velocity
  1. (A)v
  2. (B)v2\dfrac{v}{2}2v​
  3. (C)v3\dfrac{v}{3}3v​
  4. (D)v4\dfrac{v}{4}4v​

Correct answer: (C)

Step-by-step solution →
Q8·Physics·Magnetic Field of CurrentSingle correct
Given below are two statements: Statement I: If the number of turns in the coil of a moving coil galvanometer is doubled then the current sensitivity becomes double. Statement II: Increasing current sensitivity of a moving coil galvanometer by only increasing the number of turns in the coil will also increase its voltage sensitivity in the same ratio. In the light of the above statement, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is true but Statement II is false

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
Match List I (degrees of freedom) with List II (type of gas). Choose the correct answer from the options given below:
List IList II
A.3 Translational degrees of freedomI.Monoatomic gases
B.3 Translational, 2 rotational degrees of freedomII.Polyatomic gases
C.3 Translational, 2 rotational and 1 vibrational degrees of freedomIII.Rigid diatomic gases
D.3 Translational, 3 rotational and more than one vibrational degrees of freedomIV.Nonrigid diatomic gases
  1. (A)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  2. (B)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  3. (C)(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
  4. (D)(A)-(I), (B)-(IV), (C)-(III), (D)-(II)

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
The equivalent resistance of the circuit shown below between points a and b is:
  1. (A)24 Ω24\,\Omega24Ω
  2. (B)3.2 Ω3.2\,\Omega3.2Ω
  3. (C)20 Ω20\,\Omega20Ω
  4. (D)16 Ω16\,\Omega16Ω

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
Consider two containers A and B containing monoatomic gases at the same Pressure (P), Volume (V) and Temperature (T). The gas in A is compressed isothermally to 18\dfrac1881​ of its original volume while the gas in B is compressed adiabatically to 18\dfrac1881​ of its original volume. The ratio of final pressure of gas in B to that of gas in A is:
  1. (A)8
  2. (B)18\dfrac1881​
  3. (C)14\dfrac1441​
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q12·Physics·Alternating CurrentsSingle correct
Given below are two statements: Statement I: Maximum power is dissipated in a circuit containing an inductor, a capacitor and a resistor connected in series with an AC source, when resonance occurs. Statement II: Maximum power is dissipated in a circuit containing pure resistor due to zero phase difference between current and voltage. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are true
  4. (D)Both Statement I and Statement II are false

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
Two satellites of masses m and 3m revolve around the earth in circular orbits of radii r and 3r respectively. The ratio of orbital speeds of the satellites respectively is:
  1. (A)1 : 1
  2. (B)2 : 3
  3. (C)3:1\sqrt3:13​:1
  4. (D)9 : 1

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
Given below are two statements: Statement I: Pressure in a reservoir of water is same at all points at the same level of water. Statement II: The pressure applied to enclosed water is transmitted in all directions equally. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are false

Correct answer: (B)

Step-by-step solution →
Q15·Physics·Capacitors and DielectricsSingle correct
The equivalent capacitance of the combination shown is:
  1. (A)C2\dfrac{C}{2}2C​
  2. (B)4C
  3. (C)3C
  4. (D)53C\dfrac53 C35​C

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
The energy of an electromagnetic wave contained in a small volume oscillates with
  1. (A)zero frequency
  2. (B)half the frequency of the wave
  3. (C)double the frequency of the wave
  4. (D)the frequency of the wave

Correct answer: (C)

Step-by-step solution →
Q17·Physics·Geometrical OpticsSingle correct
An object is placed at a distance of 12 cm in front of a plane mirror. The virtual and erect image is formed by the mirror. Now the mirror is moved by 4 cm towards the stationary object. The distance by which the position of image would be shifted, will be:
  1. (A)4 cm towards mirror
  2. (B)8 cm towards mirror
  3. (C)8 cm away from mirror
  4. (D)4 cm away from mirror

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
The de Broglie wavelength of a molecule in a gas at room temperature (300 K) is λ1\lambda_1λ1​. If the temperature of the gas is increased to 600 K, then the de Broglie wavelength of the same gas molecule becomes
  1. (A)12λ1\dfrac{1}{\sqrt2}\lambda_12​1​λ1​
  2. (B)2λ12\lambda_12λ1​
  3. (C)12λ1\dfrac12\lambda_121​λ1​
  4. (D)2λ1\sqrt2\lambda_12​λ1​

Correct answer: (A)

Step-by-step solution →
Q19·Physics·OscillationsSingle correct
A particle executes S.H.M. of amplitude A along x-axis. At t=0t=0t=0, the position of the particle is x=A2x=\dfrac{A}{2}x=2A​ and it moves along positive x-axis. The displacement of particle in time t i.e. x=Asin⁡(ωt+δ)x=A\sin(\omega t+\delta)x=Asin(ωt+δ), then the value of δ\deltaδ will be:
  1. (A)π6\dfrac{\pi}{6}6π​
  2. (B)π3\dfrac{\pi}{3}3π​
  3. (C)π4\dfrac{\pi}{4}4π​
  4. (D)π2\dfrac{\pi}{2}2π​

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correct
The position-time graphs for two students A and B returning from the school to their homes are shown in figure. [Conclusions: (A) A lives closer to the school; (B) B lives closer to the school; (C) A takes lesser time to reach home; (D) A travels faster than B; (E) B travels faster than A.] Choose the correct answer from the options given below:
  1. (A)(A) and (E) only
  2. (B)(B) and (E) only
  3. (C)(A), (C) and (E) only
  4. (D)(A), (D) and (E) only

Correct answer: (A)

Step-by-step solution →
Q21·Physics·Wave OpticsNumerical
Unpolarised light of intensity 32 Wm−232\,W m^{-2}32Wm−2 passes through the combination of three polaroids such that the pass axis of the last polaroid is perpendicular to that of the pass axis of first polaroid. If intensity of emerging light is 3 Wm−23\,W m^{-2}3Wm−2, then the angle between pass axis of first two polaroids is _________ °.

Correct answer: 30

Step-by-step solution →
Q22·PhysicsNumerical
A closed circular tube of average radius 15 cm, whose inner walls are rough, is kept in vertical plane. A block of mass 1 kg just fits inside the tube. The speed of block is 22 m/s when it is introduced at the top of tube. After completing five oscillations, the block stops at the bottom region of tube. The work done by the tube on the block is _________ J. [Given g=10g=10g=10 m/s2^22]

Correct answer: 245

Step-by-step solution →
Q23·PhysicsNumerical
If the earth suddenly shrinks to 164\dfrac{1}{64}641​th of its original volume with its mass remaining the same, the period of rotation of earth becomes 24x\dfrac{24}{x}x24​ h. The value of x is _________.

Correct answer: 16

Step-by-step solution →
Q24·Physics·Magnetism and MatterNumerical
The current required to be passed through a solenoid of 15 cm length and 60 turns in order to demagnetise a bar magnet of magnetic intensity 2.4×1032.4\times10^32.4×103 Am−1^{-1}−1 is _________ A.

Correct answer: 6

Step-by-step solution →
Q25·Physics·Electromagnetic InductionNumerical
A 1m long metal rod XY completes the circuit as shown in figure. The plane of the circuit is perpendicular to the magnetic field of flux density 0.15 T. If the resistance of the circuit is 5 Ω5\,\Omega5Ω, the force needed to move the rod in direction, as indicated, with a constant speed of 4 m/s will be _________ ×10−3\times10^{-3}×10−3 N.

Correct answer: 18

Step-by-step solution →
Q26·Physics·WavesNumerical
A transverse harmonic wave on a string is given by y(x,t)=5sin⁡(6t+0.003x)y(x,t)=5\sin(6t+0.003x)y(x,t)=5sin(6t+0.003x) where x and y are in cm and t in sec. The wave velocity is _________ ms−1^{-1}−1.

Correct answer: 20

Step-by-step solution →
Q27·PhysicsNumerical
The decay constant for a radioactive nuclide is 1.5×10−51.5\times10^{-5}1.5×10−5 s−1^{-1}−1. Atomic weight of the substance is 60 g mole−1^{-1}−1, (NA=6×1023)(N_A=6\times10^{23})(NA​=6×1023). The activity of 1.0 µg of the substance is _________ ×1010\times10^{10}×1010 Bq.

Correct answer: 15

Step-by-step solution →
Q28·Physics·Electric PotentialNumerical
Three concentric spherical metallic shells X, Y and Z of radius a, b and c respectively [a<b<c][a<b<c][a<b<c] have surface charge densities σ,−σ\sigma, -\sigmaσ,−σ and σ\sigmaσ respectively. The shells X and Z are at same potential. If the radii of X and Y are 2 cm and 3 cm respectively, the radius of shell Z is _________ cm.

Correct answer: 5

Step-by-step solution →
Q29·PhysicsNumerical
10 resistors each of resistance 10 Ω10\,\Omega10Ω can be connected in such a way as to get maximum and minimum equivalent resistance. The ratio of maximum and minimum equivalent resistance will be _________.

Correct answer: 100

Step-by-step solution →
Q30·PhysicsNumerical
Two wires each of radius 0.2 cm and negligible mass, one made of steel and other made of brass are loaded as shown in the figure. The elongation of the steel wire is _________ ×10−6\times10^{-6}×10−6 m. [Young's modulus for steel =2×1011=2\times10^{11}=2×1011 Nm−2^{-2}−2 and g=10g=10g=10 ms−2^{-2}−2]

Correct answer: 20

Step-by-step solution →

Chemistry — JEE Main 10 April 2023 Shift 1

Q31·ChemistrySingle correct
Using column chromatography, mixture of two compounds 'A' and 'B' was separated. 'A' eluted first, this indicates 'B' has
  1. (A)lower Rf_ff​, weaker adsorption
  2. (B)high Rf_ff​, stronger adsorption
  3. (C)high Rf_ff​, weaker adsorption
  4. (D)low Rf_ff​, stronger adsorption

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Prolonged heating is avoided during the preparation of ferrous ammonium sulphate to
  1. (A)prevent oxidation
  2. (B)prevent reduction
  3. (C)prevent hydrolysis
  4. (D)prevent breaking

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
Lime reacts exothermally with water to give 'A' which has low solubility in water. Aqueous solution of 'A' is often used for the test of CO2_22​, a test in which insoluble B is formed. If B is further reacted with CO2_22​ then soluble compound is formed. 'A' is
  1. (A)Quick lime
  2. (B)Slaked lime
  3. (C)Lime water
  4. (D)White lime

Correct answer: (B)

Step-by-step solution →
Q34·ChemistrySingle correct
The pair from the following pairs having both compounds with net non-zero dipole moment is
  1. (A)Benzene, anisidine
  2. (B)1,4-Dichlorobenzene, 1,3-Dichlorobenzene
  3. (C)CH2_22​Cl2_22​, CHCl3_33​
  4. (D)cis-butene, trans-butene

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Match List-I (Industry) with List-II (Waste Generated). Choose the correct answer from the options given below:
List I (Industry)List II (Waste Generated)
A.Steel plantsI.Gypsum
B.Thermal power plantsII.Fly ash
C.Fertilizer industriesIII.Slag
D.Paper millsIV.Bio-degradable Wastes
  1. (A)(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  2. (B)(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  3. (C)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  4. (D)(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

Correct answer: (A)

Step-by-step solution →
Q36·Chemistry·AminesSingle correct
Isomeric amines with molecular formula C8_88​H11_{11}11​N give the following tests. Isomer (P): can be prepared by Gabriel phthalimide synthesis. Isomer (Q): reacts with Hinsberg's reagent to give solid insoluble in NaOH. Isomer (R): reacts with HONO followed by β\betaβ-naphthol in NaOH to give red dye. Isomers (P), (Q) and (R) respectively are
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
Given below are two statements. Statement I: Aqueous solution of K2_22​Cr2_22​O7_77​ is preferred as a primary standard in volumetric analysis as compared to Na2_22​Cr2_22​O7_77​ aqueous solution. Statement II: K2_22​Cr2_22​O7_77​ has a higher solubility in water than Na2_22​Cr2_22​O7_77​. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
The one that does not stabilize 2° and 3° structures of proteins is
  1. (A)H-bonding
  2. (B)–S-S-linkage
  3. (C)–O-O-linkage
  4. (D)van der Waals forces

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
Given below are two reactions involved in the commercial production of dihydrogen (H2_22​), carried out at temperatures T1T_1T1​ and T2T_2T2​ respectively: C(s)+H2O(g)→T1CO(g)+H2(g)C(s)+H_2O(g)\xrightarrow{T_1}CO(g)+H_2(g)C(s)+H2​O(g)T1​​CO(g)+H2​(g) and CO(g)+H2O(g)→T2CO2(g)+H2(g)CO(g)+H_2O(g)\xrightarrow{T_2}CO_2(g)+H_2(g)CO(g)+H2​O(g)T2​​CO2​(g)+H2​(g). The temperatures T1T_1T1​ and T2T_2T2​ are correctly related as
  1. (A)T1>T2T_1>T_2T1​>T2​
  2. (B)T1=T2T_1=T_2T1​=T2​
  3. (C)T1=100T_1=100T1​=100 K, T2=1270T_2=1270T2​=1270 K
  4. (D)T1<T2T_1<T_2T1​<T2​

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
Which of the following statements are correct? (A) The M3+^{3+}3+/M2+^{2+}2+ reduction potential for iron is greater than manganese. (B) The higher oxidation states of first row d-block elements get stabilized by oxide ion. (C) Aqueous solution of Cr2+^{2+}2+ can liberate hydrogen from dilute acid. (D) Magnetic moment of V2+^{2+}2+ is observed between 4.4-5.2 BM. Choose the correct answer from the options given below:
  1. (A)(B), (C) only
  2. (B)(C), (D) only
  3. (C)(A), (B), (D) only
  4. (D)(A), (B) only

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Which of the following is used as a stabilizer during the concentration of sulphide ores?
  1. (A)Pine oils
  2. (B)Xanthates
  3. (C)Fatty acids
  4. (D)Cresols

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
The octahedral diamagnetic low spin complex among the following is
  1. (A)[NiCl4_44​]2−^{2-}2−
  2. (B)[CoCl4_44​]−^-−
  3. (C)[CoF6_66​]3−^{3-}3−
  4. (D)[Co(NH3_33​)6_66​]3+^{3+}3+

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
Given (A) 2CO(g)+O2(g)→2CO2(g)2CO(g)+O_2(g)\rightarrow2CO_2(g)2CO(g)+O2​(g)→2CO2​(g), ΔH10=−x\Delta H_1^0=-xΔH10​=−x kJ mol−1^{-1}−1 and (B) C(graphite)+O2(g)→CO2(g)C(graphite)+O_2(g)\rightarrow CO_2(g)C(graphite)+O2​(g)→CO2​(g), ΔH20=−y\Delta H_2^0=-yΔH20​=−y kJ mol−1^{-1}−1. The ΔH0\Delta H^0ΔH0 for the reaction C(graphite)+12O2(g)→CO(g)C(graphite)+\dfrac12 O_2(g)\rightarrow CO(g)C(graphite)+21​O2​(g)→CO(g) is
  1. (A)x−2y2\dfrac{x-2y}{2}2x−2y​
  2. (B)x+2y2\dfrac{x+2y}{2}2x+2y​
  3. (C)2x−y2\dfrac{2x-y}{2}22x−y​
  4. (D)2y−x2y-x2y−x

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
The compound which does not exist is
  1. (A)NaO2_22​
  2. (B)(NH4_44​)2_22​BeF4_44​
  3. (C)BeH2_22​
  4. (D)PbI4_44​

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
Match List I (Polymer) with List II (Type/Class). Choose the correct answer from the options given below:
List I (Polymer)List II (Type/Class)
A.Nylon-2-Nylon-6I.Thermosetting Polymer
B.Buna-NII.Biodegradable Polymer
C.Urea-formaldehyde resinIII.Synthetic rubber
D.DacronIV.Polyester
  1. (A)(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  2. (B)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  3. (C)(A)-(II), (B)-(IV), (C)-(IV), (D)-(III)
  4. (D)(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
The number of molecules and moles in 2.8375 litres of O2_22​ at STP are respectively
  1. (A)1.752 ×\times× 1022^{22}22 and 0.250 mol
  2. (B)1.505 ×\times× 1023^{23}23 and 0.250 mol
  3. (C)7.527 ×\times× 1022^{22}22 and 0.125 mol
  4. (D)7.527 ×\times× 1023^{23}23 and 0.125 mol

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
The enthalpy change for the adsorption process and micelle formation respectively are
  1. (A)ΔHads<0\Delta H_{ads}<0ΔHads​<0 and ΔHmic>0\Delta H_{mic}>0ΔHmic​>0
  2. (B)ΔHads>0\Delta H_{ads}>0ΔHads​>0 and ΔHmic<0\Delta H_{mic}<0ΔHmic​<0
  3. (C)ΔHads<0\Delta H_{ads}<0ΔHads​<0 and ΔHmic<0\Delta H_{mic}<0ΔHmic​<0
  4. (D)ΔHads>0\Delta H_{ads}>0ΔHads​>0 and ΔHmic>0\Delta H_{mic}>0ΔHmic​>0

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
The major product 'P' formed in the given reaction is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q49·Chemistry·Alcohols and EthersSingle correct
Suitable reaction condition for preparation of Methyl phenyl ether is
  1. (A)Ph – Br, MeO−^-− Na+^++
  2. (B)PhO−^-− Na+^++, MeOH
  3. (C)PhO−^-− Na+^++, MeBr
  4. (D)Benzene, MeBr

Correct answer: (C)

Step-by-step solution →
Q50·ChemistrySingle correct
Identify the correct order of reactivity for the following pairs towards the respective mechanism: (A) SN_NN​2 (B) SN_NN​1 (C) Electrophilic substitution (D) Nucleophilic substitution. Choose the correct answer from the options given below:
  1. (A)(A), (B) and (D) only
  2. (B)(A), (B), (C) and (D)
  3. (C)(A), (C) and (D) only
  4. (D)(B), (C) and (D) only

Correct answer: (B)

Step-by-step solution →
Q51·ChemistryNumerical
The number of incorrect statement/s involving equilibria in physical process from the following is _________. (A) Equilibrium is possible only in a closed system at a given temperature. (B) Both the opposing processes occur at the same rate. (C) When equilibrium is attained at a given temperature, the value of all its parameters becomes equal. (D) For dissolution of solids in liquids, the solubility is constant at a given temperature.

Correct answer: 3

Step-by-step solution →
Q52·ChemistryNumerical
The number of bent-shaped molecule/s from the following is _________: N3−N_3^-N3−​, NO2+NO_2^+NO2+​, I3−I_3^-I3−​, SO2SO_2SO2​

Correct answer: 3

Step-by-step solution →
Q53·ChemistryNumerical
A molecule undergoes two independent first order reactions whose respective half lives are 12 min and 3 min. If both the reactions are occurring then the time taken for the 50% consumption of the reactant is _________ min. (Nearest integer)

Correct answer: 2

Step-by-step solution →
Q54·ChemistryNumerical
The number of incorrect statement/s about the black body from the following is _________. (A) Emit or absorb energy in the form of electromagnetic radiation. (B) Frequency distribution of the emitted radiation depends on temperature. (C) At a given temperature, intensity vs frequency curve passes through a maximum value. (D) The maximum of the intensity vs frequency curve is at a higher frequency at higher temperature compared to that at lower temperature.

Correct answer: 0

Step-by-step solution →
Q55·ChemistryNumerical
In the following reactions, the total number of oxygen atoms in X and Y is _________. Na2O+H2O→2XNa_2O+H_2O\rightarrow2XNa2​O+H2​O→2X; Cl2O7+H2O→2YCl_2O_7+H_2O\rightarrow2YCl2​O7​+H2​O→2Y

Correct answer: 5

Step-by-step solution →
Q56·ChemistryNumerical
FeO42−→−2.2VFe3+→−0.70VFe2+→−0.45VFe0FeO_4^{2-}\xrightarrow{-2.2V}Fe^{3+}\xrightarrow{-0.70V}Fe^{2+}\xrightarrow{-0.45V}Fe^{0}FeO42−​−2.2V​Fe3+−0.70V​Fe2+−0.45V​Fe0. EFeO42−/Fe2+0E^0_{FeO_4^{2-}/Fe^{2+}}EFeO42−​/Fe2+0​ is x×10−1x\times10^{-1}x×10−1 V. The value of x is _________.

Correct answer: 1825

Step-by-step solution →
Q57·ChemistryNumerical
The degree of dissociation of aqueous solution of weak monobasic acid is determined to be 0.3, then the observed freezing point will be _________ % higher than the expected/theoretical freezing point. (Nearest integer)

Correct answer: 30

Step-by-step solution →
Q58·ChemistryNumerical
In potassium ferrocyanide, there are _________ pairs of electrons in the t2g_{2g}2g​ set of orbitals.

Correct answer: 3

Step-by-step solution →
Q59·ChemistryNumerical
At constant temperature a gas is at a pressure of 940.3 mm Hg. The pressure at which its volume decreases by 40% is _________ mm Hg. (Nearest Integer)

Correct answer: 1567

Step-by-step solution →
Q60·ChemistryNumerical
The sum of lone pairs present on the central atom of the interhalogen IF5_55​ and IF7_77​ is _________.

Correct answer: 1

Step-by-step solution →

Mathematics — JEE Main 10 April 2023 Shift 1

Q61·MathematicsSingle correct
Let O be the origin and the position vector of the point P be −i^−2j^+3k^-\hat i-2\hat j+3\hat k−i^−2j^​+3k^. If the position vectors of the points A, B and C are −2i^+j^−3k^-2\hat i+\hat j-3\hat k−2i^+j^​−3k^, 2i^+4j^−2k^2\hat i+4\hat j-2\hat k2i^+4j^​−2k^ and −4i^+2j^−k^-4\hat i+2\hat j-\hat k−4i^+2j^​−k^ respectively, then the projection of the vector OP→\overrightarrow{OP}OP on a vector perpendicular to the vectors AB→\overrightarrow{AB}AB and AC→\overrightarrow{AC}AC is
  1. (A)333
  2. (B)83\dfrac8338​
  3. (C)103\dfrac{10}{3}310​
  4. (D)73\dfrac7337​

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let the ellipse E: x2+9y2=9x^2+9y^2=9x2+9y2=9 intersect the positive x- and y-axes at the points A and B respectively. Let the major axis of E be a diameter of the circle C. Let the line passing through A and B meet the circle C at the point P. If the area of the triangle with vertices A, P and the origin O is mn\dfrac{m}{n}nm​, where m and n are coprime, then m−nm-nm−n is equal to
  1. (A)181818
  2. (B)161616
  3. (C)171717
  4. (D)151515

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
If f(x)=(tan⁡1°)x+log⁡e(123)xlog⁡e(1234)−(tan⁡1°), x>0f(x)=\dfrac{(\tan 1°)x+\log_e(123)}{x\log_e(1234)-(\tan 1°)},\ x>0f(x)=xloge​(1234)−(tan1°)(tan1°)x+loge​(123)​, x>0, then the least value of f(f(x))+f(f(4x))f(f(x))+f\left(f\left(\dfrac4x\right)\right)f(f(x))+f(f(x4​)) is
  1. (A)888
  2. (B)444
  3. (C)222
  4. (D)000

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
A square piece of tin of side 30 cm is to be made into a box without top by cutting a square from each corner and folding up the flaps to form a box. If the volume of the box is maximum, then its surface area (in cm2^22) is equal to
  1. (A)675675675
  2. (B)102510251025
  3. (C)800800800
  4. (D)900900900

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let fff be a differentiable function such that x2f(x)−x=4∫0xt f(t) dtx^2 f(x)-x=4\int_0^x t\,f(t)\,dtx2f(x)−x=4∫0x​tf(t)dt, f(1)=23f(1)=\dfrac23f(1)=32​. Then 18 f(3)18\,f(3)18f(3) is equal to
  1. (A)160160160
  2. (B)210210210
  3. (C)180180180
  4. (D)150150150

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
A line segment AB of length λ\lambdaλ moves such that the points A and B remain on the periphery of a circle of radius λ\lambdaλ. Then the locus of the point, that divides the line segment AB in the ratio 2:32:32:3, is a circle of radius
  1. (A)35λ\dfrac35\lambda53​λ
  2. (B)197λ\dfrac{\sqrt{19}}{7}\lambda719​​λ
  3. (C)23λ\dfrac23\lambda32​λ
  4. (D)195λ\dfrac{\sqrt{19}}{5}\lambda519​​λ

Correct answer: (D)

Step-by-step solution →
Q67·MathematicsSingle correct
Let the complex number z=x+iyz=x+iyz=x+iy be such that 2z−3i2z+i\dfrac{2z-3i}{2z+i}2z+i2z−3i​ is purely imaginary. If x+y2=0x+y^2=0x+y2=0, then y4+y2−yy^4+y^2-yy4+y2−y is equal to:
  1. (A)32\dfrac3223​
  2. (B)43\dfrac4334​
  3. (C)23\dfrac2332​
  4. (D)34\dfrac3443​

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
96cos⁡π33cos⁡2π33cos⁡4π33cos⁡8π33cos⁡16π3396\cos\dfrac{\pi}{33}\cos\dfrac{2\pi}{33}\cos\dfrac{4\pi}{33}\cos\dfrac{8\pi}{33}\cos\dfrac{16\pi}{33}96cos33π​cos332π​cos334π​cos338π​cos3316π​ is equal to
  1. (A)333
  2. (B)222
  3. (C)444
  4. (D)111

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
If A is a 3×33\times33×3 matrix and ∣A∣=2|A|=2∣A∣=2, then ∣3 adj(∣3A∣A2)∣\left|3\,adj\left(\left|3A\right|A^2\right)\right|​3adj(∣3A∣A2)​ is equal to
  1. (A)311⋅6103^{11}\cdot6^{10}311⋅610
  2. (B)312⋅6103^{12}\cdot6^{10}312⋅610
  3. (C)310⋅6113^{10}\cdot6^{11}310⋅611
  4. (D)312⋅6113^{12}\cdot6^{11}312⋅611

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
The slope of tangent at any point (x,y)(x,y)(x,y) on a curve y=y(x)y=y(x)y=y(x) is x2+y22xy\dfrac{x^2+y^2}{2xy}2xyx2+y2​, x>0x>0x>0. If y(2)=0y(2)=0y(2)=0, then a value of y(8)y(8)y(8) is
  1. (A)−23-2\sqrt3−23​
  2. (B)434\sqrt343​
  3. (C)232\sqrt323​
  4. (D)−42-4\sqrt2−42​

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
For the system of linear equations 2x−y+3z=52x-y+3z=52x−y+3z=5, 3x+2y−z=73x+2y-z=73x+2y−z=7, 4x+5y+αz=β4x+5y+\alpha z=\beta4x+5y+αz=β, which of the following is NOT correct?
  1. (A)The system has infinitely many solutions for α=−5\alpha=-5α=−5 and β=9\beta=9β=9
  2. (B)The system has a unique solution for α≠−5\alpha\neq-5α=−5 and β=8\beta=8β=8
  3. (C)The system has infinitely many solutions for α=−6\alpha=-6α=−6 and β=9\beta=9β=9
  4. (D)The system is inconsistent for α=−5\alpha=-5α=−5 and β=8\beta=8β=8

Correct answer: (C)

Step-by-step solution →
Q72·MathematicsSingle correct
Let N denotes the sum of the numbers obtained when two dice are rolled. If the probability that 2N<N!2^N<N!2N<N! is mn\dfrac{m}{n}nm​, where m and n are coprime, then 4m−3n4m-3n4m−3n is equal to
  1. (A)888
  2. (B)161616
  3. (C)101010
  4. (D)121212

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
Let P be the point of intersection of the line x+33=y+21=1−z2\dfrac{x+3}{3}=\dfrac{y+2}{1}=\dfrac{1-z}{2}3x+3​=1y+2​=21−z​ and the plane x+y+z=2x+y+z=2x+y+z=2. If the distance of the point P from the plane 3x−4y+12z=323x-4y+12z=323x−4y+12z=32 is q, then q and 2q are the roots of the equation
  1. (A)x2−18x−72=0x^2-18x-72=0x2−18x−72=0
  2. (B)x2+18x+72=0x^2+18x+72=0x2+18x+72=0
  3. (C)x2−18x+72=0x^2-18x+72=0x2−18x+72=0
  4. (D)x2+18x−72=0x^2+18x-72=0x2+18x−72=0

Correct answer: (C)

Step-by-step solution →
Q74·MathematicsSingle correct
The negation of the statement (p∨q)∧(q∨(∼r))(p\lor q)\land(q\lor(\sim r))(p∨q)∧(q∨(∼r)) is
  1. (A)((∼p)∨r)∧(∼q)((\sim p)\lor r)\land(\sim q)((∼p)∨r)∧(∼q)
  2. (B)((∼p)∨(∼q))∧(∼r)((\sim p)\lor(\sim q))\land(\sim r)((∼p)∨(∼q))∧(∼r)
  3. (C)((∼p)∨(∼q))∨(∼r)((\sim p)\lor(\sim q))\lor(\sim r)((∼p)∨(∼q))∨(∼r)
  4. (D)(p∨r)∧(∼q)(p\lor r)\land(\sim q)(p∨r)∧(∼q)

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
If the coefficient of x7x^7x7 in (ax−1bx2)13\left(ax-\dfrac{1}{bx^2}\right)^{13}(ax−bx21​)13 and the coefficient of x−5x^{-5}x−5 in (ax+1bx2)13\left(ax+\dfrac{1}{bx^2}\right)^{13}(ax+bx21​)13 are equal, then a4b4a^4 b^4a4b4 is equal to:
  1. (A)444444
  2. (B)222222
  3. (C)111111
  4. (D)333333

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let two vertices of triangle ABC be (2,4,6)(2,4,6)(2,4,6) and (0,−2,−5)(0,-2,-5)(0,−2,−5), and its centroid be (2,1,−1)(2,1,-1)(2,1,−1). If the image of third vertex in the plane x+2y+4z=11x+2y+4z=11x+2y+4z=11 is (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ), then αβ+βγ+γα\alpha\beta+\beta\gamma+\gamma\alphaαβ+βγ+γα is equal to
  1. (A)727272
  2. (B)747474
  3. (C)767676
  4. (D)707070

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsSingle correct
The shortest distance between the lines x+21=y−2=z−52\dfrac{x+2}{1}=\dfrac{y}{-2}=\dfrac{z-5}{2}1x+2​=−2y​=2z−5​ and x−41=y−12=z+30\dfrac{x-4}{1}=\dfrac{y-1}{2}=\dfrac{z+3}{0}1x−4​=2y−1​=0z+3​ is
  1. (A)666
  2. (B)999
  3. (C)777
  4. (D)888

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
If I(x)=∫esin⁡2x(cos⁡xsin⁡2x−sin⁡x) dxI(x)=\int e^{\sin^2 x}(\cos x\sin 2x-\sin x)\,dxI(x)=∫esin2x(cosxsin2x−sinx)dx and I(0)=1I(0)=1I(0)=1, then I(π3)I\left(\dfrac{\pi}{3}\right)I(3π​) is equal to
  1. (A)−12e34-\dfrac12 e^{\frac34}−21​e43​
  2. (B)e34e^{\frac34}e43​
  3. (C)12e34\dfrac12 e^{\frac34}21​e43​
  4. (D)−e34-e^{\frac34}−e43​

Correct answer: (C)

Step-by-step solution →
Q79·MathematicsSingle correct
Let the first term aaa and the common ratio rrr of a geometric progression be positive integers. If the sum of squares of its first three terms is 33033, then the sum of these three terms is equal to
  1. (A)231231231
  2. (B)210210210
  3. (C)220220220
  4. (D)241241241

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsSingle correct
An arc PQ of a circle subtends a right angle at its centre O. The mid point of the arc PQ is R. If OP→=u⃗\overrightarrow{OP}=\vec uOP=u, OR→=v⃗\overrightarrow{OR}=\vec vOR=v and OQ→=αu⃗+βv⃗\overrightarrow{OQ}=\alpha\vec u+\beta\vec vOQ​=αu+βv, then α,β2\alpha,\beta^2α,β2 are the roots of the equation
  1. (A)x2−x−2=0x^2-x-2=0x2−x−2=0
  2. (B)3x2+2x−1=03x^2+2x-1=03x2+2x−1=0
  3. (C)x2+x−2=0x^2+x-2=0x2+x−2=0
  4. (D)3x2−2x−1=03x^2-2x-1=03x2−2x−1=0

Correct answer: (A)

Step-by-step solution →
Q81·MathematicsNumerical
The coefficient of x7x^7x7 in (1−x+2x3)10\left(1-x+2x^3\right)^{10}(1−x+2x3)10 is _________.

Correct answer: 960

Step-by-step solution →
Q82·Mathematics·Limits and ContinuityNumerical
Let f:(−2,2)→Rf:(-2,2)\to\mathbb{R}f:(−2,2)→R be defined by f(x)={x[x],−2<x<0(x−1)[x],0≤x<2f(x)=\begin{cases}x[x] & ,-2<x<0\\(x-1)[x] & ,0\le x<2\end{cases}f(x)={x[x](x−1)[x]​,−2<x<0,0≤x<2​ where [x][x][x] denotes the greatest integer function. If m and n respectively are the number of points in (−2,2)(-2,2)(−2,2) at which y=∣f(x)∣y=|f(x)|y=∣f(x)∣ is not continuous and not differentiable, then m+nm+nm+n is equal to _________.

Correct answer: 4

Step-by-step solution →
Q83·MathematicsNumerical
The sum of all those terms, of the arithmetic progression 3,8,13,…,3733,8,13,\ldots,3733,8,13,…,373, which are not divisible by 3, is equal to _________.

Correct answer: 9525

Step-by-step solution →
Q84·MathematicsNumerical
Let a common tangent to the curves y2=4xy^2=4xy2=4x and (x−4)2+y2=16(x-4)^2+y^2=16(x−4)2+y2=16 touch the curves at the points P and Q. Then (PQ)2(PQ)^2(PQ)2 is equal to _________.

Correct answer: 32

Step-by-step solution →
Q85·MathematicsNumerical
The number of permutations, of the digits 1,2,3,…,71,2,3,\ldots,71,2,3,…,7 without repetition, which neither contain the string 153 nor the string 2467, is _________.

Correct answer: 4898

Step-by-step solution →
Q86·MathematicsNumerical
Let a, b, c be three distinct positive real numbers such that (2a)log⁡ea=(bc)log⁡eb(2a)^{\log_e a}=(bc)^{\log_e b}(2a)loge​a=(bc)loge​b and blog⁡e2=alog⁡ecb^{\log_e 2}=a^{\log_e c}bloge​2=aloge​c. Then 6a+5bc6a+5bc6a+5bc is equal to _________.

Correct answer: 8

Step-by-step solution →
Q87·MathematicsNumerical
Let y=p(x)y=p(x)y=p(x) be the parabola passing through the points (−1,0),(0,1)(-1,0),(0,1)(−1,0),(0,1) and (1,0)(1,0)(1,0). If the area of the region {(x,y):(x+1)2+(y−1)2≤1, y≤p(x)}\{(x,y):(x+1)^2+(y-1)^2\le1,\ y\le p(x)\}{(x,y):(x+1)2+(y−1)2≤1, y≤p(x)} is A, then 12(π−4A)12(\pi-4A)12(π−4A) is equal to _________.

Correct answer: 16

Step-by-step solution →
Q88·MathematicsNumerical
If the mean of the frequency distribution — Class: 0-10, 10-20, 20-30, 30-40, 40-50; Frequency: 2, 3, x, 5, 4 — is 28, then its variance is _________.

Correct answer: 151

Step-by-step solution →
Q89·MathematicsNumerical
Some couples participated in a mixed doubles badminton tournament. If the number of matches played, so that no couple played in a match, is 840, then the total number of persons who participated in the tournament is _________.

Correct answer: 16

Step-by-step solution →
Q90·MathematicsNumerical
The number of elements in the set {n∈Z:∣n2−10n+19∣<6}\{n\in\mathbb{Z}:|n^2-10n+19|<6\}{n∈Z:∣n2−10n+19∣<6} is _________.

Correct answer: 6

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • States of Matter: Gases and Liquids 52/186
  • Magnetism and Matter 50/186
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