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JEE Main 4 April 2024 Shift 1 Question Paper with Answers

4 April 2024 · April session · 89 questions

89 of the 90 questions from the JEE Main 4 April 2024 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
30
Mathematics
29

Physics — JEE Main 4 April 2024 Shift 1

Q1·PhysicsSingle correct
An electron is projected with uniform velocity along the axis inside a current carrying long solenoid. Then:
  1. (A)the electron will be accelerated along the axis.
  2. (B)the electron will continue to move with uniform velocity along the axis of the solenoid.
  3. (C)the electron will be deflected to move along the circular path about axis.
  4. (D)the electron will experience a force at 45∘45^\circ45∘ to the axis and execute a helical path.

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
The electric field in an electromagnetic wave is given by E⃗=i^ 40cos⁡ω(t−zc) NC−1\vec E=\hat i\,40\cos\omega\left(t-\dfrac zc\right)\,NC^{-1}E=i^40cosω(t−cz​)NC−1. The magnetic field induction of this wave is (in SI unit):
  1. (A)B⃗=i^40ccos⁡ω(t−zc)\vec B=\hat i\dfrac{40}{c}\cos\omega\left(t-\dfrac zc\right)B=i^c40​cosω(t−cz​)
  2. (B)B⃗=j^ 40ccos⁡ω(t−zc)\vec B=\hat j\,40c\cos\omega\left(t-\dfrac zc\right)B=j^​40ccosω(t−cz​)
  3. (C)B⃗=k^40ccos⁡ω(t−zc)\vec B=\hat k\dfrac{40}{c}\cos\omega\left(t-\dfrac zc\right)B=k^c40​cosω(t−cz​)
  4. (D)B⃗=j^40ccos⁡ω(t−zc)\vec B=\hat j\dfrac{40}{c}\cos\omega\left(t-\dfrac zc\right)B=j^​c40​cosω(t−cz​)

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
Which of the following nuclear fragments corresponding to nuclear fission between neutron (01n)({}^1_0n)(01​n) and uranium isotope (92235U)({}^{235}_{92}U)(92235​U) is correct:
  1. (A)56144Ba+3689Kr+401n{}^{144}_{56}Ba+{}^{89}_{36}Kr+4{}^1_0n56144​Ba+3689​Kr+401​n
  2. (B)54140Xe+3894Sr+301n{}^{140}_{54}Xe+{}^{94}_{38}Sr+3{}^1_0n54140​Xe+3894​Sr+301​n
  3. (C)51153Sb+4199Nb+301n{}^{153}_{51}Sb+{}^{99}_{41}Nb+3{}^1_0n51153​Sb+4199​Nb+301​n
  4. (D)56144Ba+3689Kr+301n{}^{144}_{56}Ba+{}^{89}_{36}Kr+3{}^1_0n56144​Ba+3689​Kr+301​n

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
In an experiment to measure the focal length (f)(f)(f) of a convex lens, the least count of the measuring scales for the position of object (u)(u)(u) and for the position of image (v)(v)(v) are Δu\Delta uΔu and Δv\Delta vΔv, respectively. The error in the measurement of the focal length of the convex lens is:
  1. (A)f2(Δuu+Δvv)f^2\left(\dfrac{\Delta u}{u}+\dfrac{\Delta v}{v}\right)f2(uΔu​+vΔv​)
  2. (B)f2(Δuu2+Δvv2)f^2\left(\dfrac{\Delta u}{u^2}+\dfrac{\Delta v}{v^2}\right)f2(u2Δu​+v2Δv​)
  3. (C)2f(Δuu+Δvv)2f\left(\dfrac{\Delta u}{u}+\dfrac{\Delta v}{v}\right)2f(uΔu​+vΔv​)
  4. (D)f(Δuu+Δvv)f\left(\dfrac{\Delta u}{u}+\dfrac{\Delta v}{v}\right)f(uΔu​+vΔv​)

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
Given below are two statements: Statement I: When speed of liquid is zero everywhere, pressure difference at any two points depends on equation P1−P2=ρg(h2−h1)P_1-P_2=\rho g(h_2-h_1)P1​−P2​=ρg(h2​−h1​). Statement II: In venturi tube shown 2gh=v12−v222gh=v_1^2-v_2^22gh=v12​−v22​. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Statement I is incorrect but Statement II is correct.
  3. (C)Both Statement I and Statement II are incorrect.
  4. (D)Statement I is correct but Statement II is incorrect.

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
The resistances of the platinum wire of a platinum resistance thermometer at the ice point and steam point are 8 Ω8\,\Omega8Ω and 10 Ω10\,\Omega10Ω respectively. After inserting in a hot bath of temperature 400∘C400^\circ C400∘C, the resistance of platinum wire is:
  1. (A)2 Ω2\,\Omega2Ω
  2. (B)16 Ω16\,\Omega16Ω
  3. (C)8 Ω8\,\Omega8Ω
  4. (D)10 Ω10\,\Omega10Ω

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
A metal wire of uniform mass density having length LLL and mass MMM is bent to form a semicircular arc and a particle of mass mmm is placed at the centre of the arc. The gravitational force on the particle by the wire is:
  1. (A)GMmπ2L2\dfrac{GMm\pi}{2L^2}2L2GMmπ​
  2. (B)000
  3. (C)GMmπL2\dfrac{GMm\pi}{L^2}L2GMmπ​
  4. (D)2GMmπL2\dfrac{2GMm\pi}{L^2}L22GMmπ​

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
On celsius scale the temperature of body increases by 40∘C40^\circ C40∘C. The increase in temperature on Fahrenheit scale is:
  1. (A)70∘F70^\circ F70∘F
  2. (B)68∘F68^\circ F68∘F
  3. (C)72∘F72^\circ F72∘F
  4. (D)75∘F75^\circ F75∘F

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
An effective power of a combination of 555 identical convex lenses which are kept in contact along the principal axis is 25 D25\,D25D. Focal length of each of the convex lens is:
  1. (A)20 cm20\,cm20cm
  2. (B)50 cm50\,cm50cm
  3. (C)500 cm500\,cm500cm
  4. (D)25 cm25\,cm25cm

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
Which figure shows the correct variation of applied potential difference (V)(V)(V) with photoelectric current (I)(I)(I) at two different intensities of light (I1<I2)(I_1<I_2)(I1​<I2​) of same wavelengths:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
A wooden block, initially at rest on the ground, is pushed by a force which increases linearly with time ttt. Which of the following curve best describes acceleration of the block with time ttt:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
If a rubber ball falls from a height hhh and rebounds upto the height of h/2h/2h/2. The percentage loss of total energy of the initial system as well as velocity of ball before it strikes the ground, respectively, are:
  1. (A)50%, gh250\%,\ \sqrt{\dfrac{gh}{2}}50%, 2gh​​
  2. (B)50%, gh50\%,\ \sqrt{gh}50%, gh​
  3. (C)40%, 2gh40\%,\ \sqrt{2gh}40%, 2gh​
  4. (D)50%, 2gh50\%,\ \sqrt{2gh}50%, 2gh​

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
The equation of stationary wave is y=2asin⁡(2πntλ)cos⁡(2πxλ)y=2a\sin\left(\dfrac{2\pi nt}{\lambda}\right)\cos\left(\dfrac{2\pi x}{\lambda}\right)y=2asin(λ2πnt​)cos(λ2πx​). Which of the following is NOT correct:
  1. (A)The dimensions of ntntnt is [L][L][L].
  2. (B)The dimensions of nnn is [LT−1][LT^{-1}][LT−1].
  3. (C)The dimensions of n/λn/\lambdan/λ is [T][T][T].
  4. (D)The dimensions of xxx is [L][L][L].

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
A body travels 102.5 m102.5\,m102.5m in nthn^{th}nth second and 115.0 m115.0\,m115.0m in (n+2)th(n+2)^{th}(n+2)th second. The acceleration is:
  1. (A)9 m/s29\,m/s^29m/s2
  2. (B)6.25 m/s26.25\,m/s^26.25m/s2
  3. (C)12.5 m/s212.5\,m/s^212.5m/s2
  4. (D)5 m/s25\,m/s^25m/s2

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
To measure the internal resistance of a battery, potentiometer is used. For R=10 ΩR=10\,\OmegaR=10Ω, the balance point is observed at ℓ=500 cm\ell=500\,cmℓ=500cm and for R=1 ΩR=1\,\OmegaR=1Ω the balance point is observed at ℓ=400 cm\ell=400\,cmℓ=400cm. The internal resistance of the battery is approximately:
  1. (A)0.2 Ω0.2\,\Omega0.2Ω
  2. (B)0.4 Ω0.4\,\Omega0.4Ω
  3. (C)0.1 Ω0.1\,\Omega0.1Ω
  4. (D)0.3 Ω0.3\,\Omega0.3Ω

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
An infinitely long positively charged straight thread has a linear charge density λ Cm−1\lambda\,Cm^{-1}λCm−1. An electron revolves along a circular path having axis along the length of the wire. The graph that correctly represents the variation of the kinetic energy of electron as a function of radius of circular path from the wire is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
The value of net resistance of the network as shown in the given figure is:
  1. (A)52 Ω\dfrac52\,\Omega25​Ω
  2. (B)154 Ω\dfrac{15}{4}\,\Omega415​Ω
  3. (C)6 Ω6\,\Omega6Ω
  4. (D)3011 Ω\dfrac{30}{11}\,\Omega1130​Ω

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
P-T diagram of an ideal gas having three different densities ρ1,ρ2,ρ3\rho_1,\rho_2,\rho_3ρ1​,ρ2​,ρ3​ (in three different cases) is shown in the figure. Which of the following is correct:
  1. (A)ρ2<ρ1\rho_2<\rho_1ρ2​<ρ1​
  2. (B)ρ1>ρ2\rho_1>\rho_2ρ1​>ρ2​
  3. (C)ρ1<ρ2\rho_1<\rho_2ρ1​<ρ2​
  4. (D)ρ1=ρ2=ρ3\rho_1=\rho_2=\rho_3ρ1​=ρ2​=ρ3​

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
The co-ordinates of a particle moving in x-y plane are given by x=2+4tx=2+4tx=2+4t, y=3t+8t2y=3t+8t^2y=3t+8t2. The motion of the particle is:
  1. (A)non-uniformly accelerated.
  2. (B)uniformly accelerated having motion along a straight line.
  3. (C)uniform motion along a straight line.
  4. (D)uniformly accelerated having motion along a parabolic path.

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsSingle correct
In an a.c. circuit, the instantaneous current is zero, when the instantaneous voltage is maximum. In this case, the source may be connected to: A. pure inductor. B. pure capacitor. C. pure resistor. D. combination of an inductor and capacitor. Choose the correct answer from the options given below:
  1. (A)A, B and C only
  2. (B)B, C and D only
  3. (C)A and B only
  4. (D)A, B and D only

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
An infinite plane sheet of charge having uniform surface charge density +σs C/m2+\sigma_s\,C/m^2+σs​C/m2 is placed on x-y plane. Another infinitely long line charge having uniform linear charge density +λs C/m+\lambda_s\,C/m+λs​C/m is placed at z=4 mz=4\,mz=4m plane and parallel to y-axis. If the magnitude when ∣σs∣=2∣λs∣|\sigma_s|=2|\lambda_s|∣σs​∣=2∣λs​∣ then at point (0,0,2)(0,0,2)(0,0,2), the ratio of magnitudes of electric field values due to sheet charge to that of line charge is πn:1\pi\sqrt n:1πn​:1. The value of nnn is ___

Correct answer: 16

Step-by-step solution →
Q22·PhysicsNumerical
A hydrogen atom changes its state from n=3n=3n=3 to n=2n=2n=2. Due to recoil, the percentage change in the wave length of emitted light is approximately 1×10−n1\times10^{-n}1×10−n. The value of nnn is ___. (Given Rhc=13.6 eVRhc=13.6\,eVRhc=13.6eV, hc=1242 eV nmhc=1242\,eV\,nmhc=1242eVnm, h=6.6×10−34 J sh=6.6\times10^{-34}\,J\,sh=6.6×10−34Js, mass of hydrogen atom =1.6×10−27 kg=1.6\times10^{-27}\,kg=1.6×10−27kg)

Correct answer: 7

Step-by-step solution →
Q23·PhysicsNumerical
The magnetic field existing in a region is given by B⃗=0.2(1+2x)k^\vec B=0.2(1+2x)\hat kB=0.2(1+2x)k^ T. A square loop of edge 50 cm50\,cm50cm carrying 0.5 A0.5\,A0.5A current is placed in x-y plane with its edges parallel to the x-y axes, as shown in figure. The magnitude of the net magnetic force experienced by the loop is ___ mN.

Correct answer: 50

Step-by-step solution →
Q24·PhysicsNumerical
A alternating current at any instant is given by i=[6+56sin⁡(100πt+π3)] Ai=\left[6+\sqrt{56}\sin\left(100\pi t+\dfrac\pi3\right)\right]\,Ai=[6+56​sin(100πt+3π​)]A. The rms value of the current is ___ A.

Correct answer: 8

Step-by-step solution →
Q25·PhysicsNumerical
Twelve wires each having resistance 2 Ω2\,\Omega2Ω are joined to form a cube. A battery of 6 V6\,V6V emf is joined across point aaa and ccc. The voltage difference between eee and fff is ___ V.

Correct answer: 1

Step-by-step solution →
Q26·PhysicsNumerical
A soap bubble is blown to a diameter of 7 cm7\,cm7cm. 369603696036960 erg of work is done in blowing it further. If surface tension of soap solution is 40 dyne/cm40\,dyne/cm40dyne/cm then the new radius is ___ cm. Take (π=227)\left(\pi=\dfrac{22}{7}\right)(π=722​)

Correct answer: 7

Step-by-step solution →
Q27·PhysicsNumerical
Two wavelengths λ1\lambda_1λ1​ and λ2\lambda_2λ2​ are used in Young's double slit experiment. λ1=450 nm\lambda_1=450\,nmλ1​=450nm and λ2=650 nm\lambda_2=650\,nmλ2​=650nm. The minimum order of fringe produced by λ2\lambda_2λ2​ which overlaps with the fringe produced by λ1\lambda_1λ1​ is nnn. The value of nnn is ___

Correct answer: 9

Step-by-step solution →
Q28·PhysicsNumerical
An elastic spring under tension of 3 N3\,N3N has a length aaa. Its length is bbb under tension 2 N2\,N2N. For its length (3a−2b)(3a-2b)(3a−2b), the value of tension will be ___ N.

Correct answer: 5

Step-by-step solution →
Q29·PhysicsNumerical
Two forces F⃗1\vec F_1F1​ and F⃗2\vec F_2F2​ are acting on a body. One force has magnitude thrice that of the other force and the resultant of the two forces is equal to the force of larger magnitude. The angle between F⃗1\vec F_1F1​ and F⃗2\vec F_2F2​ is cos⁡−1(1n)\cos^{-1}\left(\dfrac1n\right)cos−1(n1​). The value of ∣n∣|n|∣n∣ is ___

Correct answer: 6

Step-by-step solution →
Q30·PhysicsNumerical
A solid sphere and a hollow cylinder roll up without slipping on same inclined plane with same initial speed vvv. The sphere and the cylinder reaches upto maximum heights h1h_1h1​ and h2h_2h2​, respectively, above the initial level. The ratio h1:h2h_1:h_2h1​:h2​ is n10\dfrac{n}{10}10n​. The value of nnn is ___

Correct answer: 7

Step-by-step solution →

Chemistry — JEE Main 4 April 2024 Shift 1

Q31·ChemistrySingle correct
What pressure (bar) of H2H_2H2​ would be required to make emf of hydrogen electrode zero in pure water at 25∘C25^\circ C25∘C?
  1. (A)10−1410^{-14}10−14
  2. (B)10−710^{-7}10−7
  3. (C)111
  4. (D)0.50.50.5

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
The correct sequence of ligands in the order of decreasing field strength is:
  1. (A)CO>H2O>F−>S2−CO>H_2O>F^->S^{2-}CO>H2​O>F−>S2−
  2. (B)−OH>F−>NH3>CN−^-OH>F^->NH_3>CN^-−OH>F−>NH3​>CN−
  3. (C)NCS−>EDTA4−>CN−>CONCS^->EDTA^{4-}>CN^->CONCS−>EDTA4−>CN−>CO
  4. (D)S2−>−OH>EDTA4−>COS^{2-}>{}^-OH>EDTA^{4-}>COS2−>−OH>EDTA4−>CO

Correct answer: (A)

Step-by-step solution →
Q33·Chemistry·Electronic Effects and StabilitySingle correct
Match List-I (electronic-effect mechanism steps) with List-II (the electronic effect). Choose the correct answer from the options given below:
List-I (Mechanism step)List-II (Effect)
A.see figureI.−E-E−E effect
B.see figureII.−R-R−R effect
C.see figureIII.+E+E+E effect
D.see figureIV.+R+R+R effect
  1. (A)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  2. (B)(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  3. (C)(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
  4. (D)(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

Correct answer: (A)

Step-by-step solution →
Q34·Chemistry·Electronic Effects and StabilitySingle correct
What will be the decreasing order of basic strength of the following conjugate bases? −OH^-OH−OH, RO−RO^-RO−, CH3COO−CH_3COO^-CH3​COO−, Cl−Cl^-Cl−
  1. (A)Cl > OH > R O > CH3COO
  2. (B)RO >–OH > CH3CO O > Cl
  3. (C)–OH > RO > CH3 COO > Cl
  4. (D)Cl > RO > –OH > CH3CO O

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
In the precipitation of the iron group (III) in qualitative analysis, ammonium chloride is added before adding ammonium hydroxide to:
  1. (A)prevent interference by phosphate ions
  2. (B)decrease concentration of −OH^-OH−OH ions
  3. (C)increase concentration of Cl−Cl^-Cl− ions
  4. (D)increase concentration of NH4+NH_4^+NH4+​ ions

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
In the following sequence of reactions, A (p-BrC6H4CH2CH2Br)→alc. NaOHB→HBr/EtherCA\ (p\text{-}BrC_6H_4CH_2CH_2Br)\xrightarrow{\text{alc. NaOH}}B\xrightarrow{\text{HBr/Ether}}CA (p-BrC6​H4​CH2​CH2​Br)alc. NaOH​BHBr/Ether​C, identify (B)(B)(B) and (C)(C)(C) (shown in the figure) and how are (A)(A)(A) and (C)(C)(C) related?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
One of the commonly used electrode is calomel electrode. Under which of the following categories calomel electrode comes?
  1. (A)Metal – Insoluble Salt – Anion electrodes
  2. (B)Oxidation – Reduction electrodes
  3. (C)Gas – Ion electrodes
  4. (D)Metal ion – Metal electrodes

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correct
Number of complexes from the following with even number of unpaired "d" electrons is ___. [V(H2O)6]2+[V(H_2O)_6]^{2+}[V(H2​O)6​]2+, [Cr(H2O)6]2+[Cr(H_2O)_6]^{2+}[Cr(H2​O)6​]2+, [Fe(H2O)6]3+[Fe(H_2O)_6]^{3+}[Fe(H2​O)6​]3+, [Ni(H2O)6]2+[Ni(H_2O)_6]^{2+}[Ni(H2​O)6​]2+, [Cu(H2O)6]2+[Cu(H_2O)_6]^{2+}[Cu(H2​O)6​]2+. [Given atomic numbers: V=23=23=23, Cr=24=24=24, Fe=26=26=26, Ni=28=28=28, Cu=29=29=29]
  1. (A)222
  2. (B)444
  3. (C)555
  4. (D)111

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
Which one of the following molecules has maximum dipole moment?
  1. (A)NF3NF_3NF3​
  2. (B)CH4CH_4CH4​
  3. (C)NH3NH_3NH3​
  4. (D)PF3PF_3PF3​

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
Number of molecules/ions from the following in which the central atom is involved in sp3sp^3sp3 hybridization is ___. NO3−NO_3^-NO3−​, BCl3BCl_3BCl3​, ClO2−ClO_2^-ClO2−​, ClO3−ClO_3^-ClO3−​
  1. (A)222
  2. (B)444
  3. (C)333
  4. (D)111

Correct answer: (A)

Step-by-step solution →
Q41·Chemistry·Electronic Effects and StabilitySingle correct
Which among the following is incorrect statement?
  1. (A)Electromeric effect dominates over inductive effect
  2. (B)The electromeric effect is a temporary effect
  3. (C)The organic compound shows electromeric effect in the presence of the reagent only
  4. (D)Hydrogen ion (H+)(H^+)(H+) shows negative electromeric effect

Correct answer: (D)

Step-by-step solution →
Q42·Chemistry·Aldehydes and KetonesSingle correct
Given below are two statements: Statement I: Acidity of α\alphaα-hydrogens of aldehydes and ketones is responsible for Aldol reaction. Statement II: Reaction between benzaldehyde and ethanal will NOT give Cross-Aldol product. In the light of above statements, choose the most appropriate answer from the options given below.
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is incorrect but Statement II is correct.
  4. (D)Statement I is correct but Statement II is incorrect.

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
Which of the following nitrogen containing compound does not give Lassaigne's test?
  1. (A)Phenyl hydrazine
  2. (B)Glycine
  3. (C)Urea
  4. (D)Hydrazine

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
Which of the following is the correct structure of L-Glucose?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q45·ChemistrySingle correct
The element which shows only one oxidation state other than its elemental form is:
  1. (A)Cobalt
  2. (B)Scandium
  3. (C)Titanium
  4. (D)Nickel

Correct answer: (B)

Step-by-step solution →
Q46·Chemistry·Aldehydes and KetonesSingle correct
Identify the product in the following reaction (Clemmensen reduction, Zn-Hg/HCl):
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q47·ChemistrySingle correct
Number of elements from the following that CANNOT form compounds with valencies which match with their respective group valencies is ___. B, C, N, S, O, F, P, Al, Si
  1. (A)777
  2. (B)555
  3. (C)666
  4. (D)333

Correct answer: (D)

Step-by-step solution →
Q48·ChemistrySingle correct
The Molarity (M) of an aqueous solution containing 5.85 g5.85\,g5.85g of NaCl in 500 mL500\,mL500mL water is: (Given: Molar Mass Na: 232323 and Cl: 35.5 g mol−135.5\,g\,mol^{-1}35.5gmol−1)
  1. (A)202020
  2. (B)0.20.20.2
  3. (C)222
  4. (D)444

Correct answer: (B)

Step-by-step solution →
Q49·ChemistrySingle correct
Identify the correct set of reagents or reaction conditions "X" and "Y" in the following transformation: CH3−CH2−CH2−Br→XCH_3-CH_2-CH_2-Br\xrightarrow{X}CH3​−CH2​−CH2​−BrX​ Product →YCH3−CH∣Br−CH3\xrightarrow{Y}CH_3-\underset{\underset{Br}{|}}{CH}-CH_3Y​CH3​−Br∣​CH​−CH3​
  1. (A)X = conc. alc. NaOH, 80∘C80^\circ C80∘C; Y = Br2/CHCl3Br_2/CHCl_3Br2​/CHCl3​
  2. (B)X = dil. aq. NaOH, 20∘C20^\circ C20∘C; Y = HBr/acetic acid
  3. (C)X = conc. alc. NaOH, 20∘C20^\circ C20∘C; Y = HBr/acetic acid
  4. (D)X = dil. aq. NaOH, 20∘C20^\circ C20∘C; Y = Br2/CHCl3Br_2/CHCl_3Br2​/CHCl3​

Correct answer: (C)

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Q50·ChemistrySingle correct
The correct order of first ionization enthalpy values of the following elements is: (A) O (B) N (C) Be (D) F (E) B. Choose the correct answer from the options given below:
  1. (A)B < D < C < E < A
  2. (B)E < C < A < B < D
  3. (C)C < E < A < B < D
  4. (D)A < B < D < C < E

Correct answer: (B)

Step-by-step solution →
Q51·ChemistryNumerical
The enthalpy of formation of ethane (C2H6)(C_2H_6)(C2​H6​) from ethylene by addition of hydrogen where the bond-energies of C−HC-HC−H, C−CC-CC−C, C=CC=CC=C and H−HH-HH−H are 414 kJ414\,kJ414kJ, 347 kJ347\,kJ347kJ, 615 kJ615\,kJ615kJ and 435 kJ435\,kJ435kJ respectively is −-− ___ kJkJkJ.

Correct answer: 125

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Q52·ChemistryNumerical
The number of correct reaction(s) among the following is ___

Correct answer: 1

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Q53·ChemistryNumerical
XXX g of ethylamine is subjected to reaction with NaNO2/HClNaNO_2/HClNaNO2​/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L2.24\,L2.24L volume at STP. XXX is ___ ×10−1\times10^{-1}×10−1 g.

Correct answer: 45

Step-by-step solution →
Q54·ChemistryNumerical
The de-Broglie's wavelength of an electron in the 4th4^{th}4th orbit is ___ πa0\pi a_0πa0​. (a0a_0a0​ = Bohr's radius)

Correct answer: 8

Step-by-step solution →
Q55·ChemistryNumerical
Only 2 mL2\,mL2mL of KMnO4KMnO_4KMnO4​ solution of unknown molarity is required to reach the end point of a titration of 20 mL20\,mL20mL of oxalic acid (2 M)(2\,M)(2M) in acidic medium. The molarity of KMnO4KMnO_4KMnO4​ solution should be ___ M.

Correct answer: 8

Step-by-step solution →
Q56·ChemistryNumerical
Consider the following reaction MnO2+KOH+O2→A+H2OMnO_2+KOH+O_2\to A+H_2OMnO2​+KOH+O2​→A+H2​O. Product "A" in neutral or acidic medium disproportionate to give products "B" and "C" along with water. The sum of spin-only magnetic moment values of B and C is ___ BM. (nearest integer) (Given atomic number of Mn is 252525)

Correct answer: 4

Step-by-step solution →
Q57·ChemistryNumerical
Consider the transformation A+B→Step 1C→Step 2PA+B\xrightarrow{\text{Step 1}}C\xrightarrow{\text{Step 2}}PA+BStep 1​CStep 2​P (first order elementary reaction in each step). The rate constants and activation energies are: Step 1: k1k_1k1​, Ea=300 kJ mol−1E_a=300\,kJ\,mol^{-1}Ea​=300kJmol−1; Step 2: k2k_2k2​, Ea=200 kJ mol−1E_a=200\,kJ\,mol^{-1}Ea​=200kJmol−1; Step 3: k3k_3k3​, Ea=Ea3E_a=E_{a_3}Ea​=Ea3​​. If the overall rate constant k=k1k2k3k=\dfrac{k_1 k_2}{k_3}k=k3​k1​k2​​ and the overall activation energy EaE_aEa​ is 400 kJ mol−1400\,kJ\,mol^{-1}400kJmol−1, then the value of Ea3E_{a_3}Ea3​​ is ___ kJ mol−1kJ\,mol^{-1}kJmol−1 (nearest integer)

Correct answer: 100

Step-by-step solution →
Q58·ChemistryNumerical
2.5 g2.5\,g2.5g of a non-volatile, non-electrolyte is dissolved in 100 g100\,g100g of water at 25∘C25^\circ C25∘C. The solution showed a boiling point elevation by 2∘C2^\circ C2∘C. Assuming the solute concentration is negligible with respect to the solvent concentration, the vapour pressure of the resulting aqueous solution is ___ mm of Hg (nearest integer). [Given: Molal boiling point elevation constant of water (Kb)=0.52 K kg mol−1(K_b)=0.52\,K\,kg\,mol^{-1}(Kb​)=0.52Kkgmol−1, 111 atm pressure =760 mm=760\,mm=760mm of Hg, molar mass of water =18 g mol−1=18\,g\,mol^{-1}=18gmol−1]

Correct answer: 707

Step-by-step solution →
Q59·Chemistry·IsomerismNumerical
The number of different chain isomers for C7H16C_7H_{16}C7​H16​ is ___

Correct answer: 9

Step-by-step solution →
Q60·ChemistryNumerical
Number of molecules/species from the following having one unpaired electron is ___. O2O_2O2​, O2−O_2^-O2−​, NONONO, CN−CN^-CN−, O22−O_2^{2-}O22−​

Correct answer: 2

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Mathematics — JEE Main 4 April 2024 Shift 1

Q61·Mathematics·Limits and ContinuitySingle correct
Let f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R be a function given by f(x)={1−cos⁡2xx2, x<0α, x=0β1−cos⁡xx, x>0f(x)=\begin{cases}\dfrac{1-\cos 2x}{x^2} & ,\ x<0\\ \alpha & ,\ x=0\\ \dfrac{\beta\sqrt{1-\cos x}}{x} & ,\ x>0\end{cases}f(x)=⎩⎨⎧​x21−cos2x​αxβ1−cosx​​​, x<0, x=0, x>0​ where α,β∈R\alpha,\beta\in\mathbb{R}α,β∈R. If fff is continuous at x=0x=0x=0, then α2+β2\alpha^2+\beta^2α2+β2 is equal to:
  1. (A)484848
  2. (B)121212
  3. (C)333
  4. (D)666

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
Three urns AAA, BBB and CCC contain 777 red, 555 black; 555 red, 777 black and 666 red, 666 black balls, respectively. One of the urn is selected at random and a ball is drawn from it. If the ball drawn is black, then the probability that it is drawn from urn AAA is:
  1. (A)417\dfrac{4}{17}174​
  2. (B)518\dfrac{5}{18}185​
  3. (C)718\dfrac{7}{18}187​
  4. (D)516\dfrac{5}{16}165​

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
The vertices of a triangle are A(−1,3)A(-1,3)A(−1,3), B(−2,2)B(-2,2)B(−2,2) and C(3,−1)C(3,-1)C(3,−1). A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is:
  1. (A)x−y−(2+2)=0x-y-(2+\sqrt2)=0x−y−(2+2​)=0
  2. (B)−x+y−(2−2)=0-x+y-(2-\sqrt2)=0−x+y−(2−2​)=0
  3. (C)x+y−(2−2)=0x+y-(2-\sqrt2)=0x+y−(2−2​)=0
  4. (D)x+y+(2−2)=0x+y+(2-\sqrt2)=0x+y+(2−2​)=0

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
If the solution y=y(x)y=y(x)y=y(x) of the differential equation (x4+2x3+3x2+2x+2) dy=(2x2+2x+3) dx(x^4+2x^3+3x^2+2x+2)\,dy=(2x^2+2x+3)\,dx(x4+2x3+3x2+2x+2)dy=(2x2+2x+3)dx satisfies y(−1)=−π4y(-1)=-\dfrac\pi4y(−1)=−4π​, then y(0)y(0)y(0) is equal to:
  1. (A)−π12-\dfrac{\pi}{12}−12π​
  2. (B)000
  3. (C)π4\dfrac\pi44π​
  4. (D)π2\dfrac\pi22π​

Correct answer: (C)

Step-by-step solution →
Q65·Mathematics·Application of DerivativesSingle correct
Let the sum of the maximum and the minimum values of the function f(x)=2x2−3x+82x2+3x+8f(x)=\dfrac{2x^2-3x+8}{2x^2+3x+8}f(x)=2x2+3x+82x2−3x+8​ be mn\dfrac{m}{n}nm​, where gcd⁡(m,n)=1\gcd(m,n)=1gcd(m,n)=1. Then m+nm+nm+n is equal to:
  1. (A)182182182
  2. (B)217217217
  3. (C)195195195
  4. (D)201201201

Correct answer: (D)

Step-by-step solution →
Q66·MathematicsSingle correct
One of the points of intersection of the curves y=1+3x−2x2y=1+3x-2x^2y=1+3x−2x2 and y=1xy=\dfrac1xy=x1​ is (12,2)\left(\dfrac12,2\right)(21​,2). Let the area of the region bounded by these curves be 124(ℓ5+m)−nlog⁡e(1+5)\dfrac{1}{24}(\ell\sqrt5+m)-n\log_e(1+\sqrt5)241​(ℓ5​+m)−nloge​(1+5​), where ℓ,m,n∈N\ell,m,n\in\mathbb{N}ℓ,m,n∈N. Then ℓ+m+n\ell+m+nℓ+m+n is equal to:
  1. (A)323232
  2. (B)303030
  3. (C)292929
  4. (D)313131

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
Let the system of linear equations x+(2sin⁡α)y+(2cos⁡α)z=0x+(\sqrt2\sin\alpha)y+(\sqrt2\cos\alpha)z=0x+(2​sinα)y+(2​cosα)z=0, x+(cos⁡α)y+(sin⁡α)z=0x+(\cos\alpha)y+(\sin\alpha)z=0x+(cosα)y+(sinα)z=0, x+(sin⁡α)y−(cos⁡α)z=0x+(\sin\alpha)y-(\cos\alpha)z=0x+(sinα)y−(cosα)z=0 has a non-trivial solution, then α∈(0,π2)\alpha\in\left(0,\dfrac\pi2\right)α∈(0,2π​) is equal to:
  1. (A)3π4\dfrac{3\pi}{4}43π​
  2. (B)7π24\dfrac{7\pi}{24}247π​
  3. (C)5π24\dfrac{5\pi}{24}245π​
  4. (D)11π24\dfrac{11\pi}{24}2411π​

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
There are 555 points P1,P2,P3,P4,P5P_1,P_2,P_3,P_4,P_5P1​,P2​,P3​,P4​,P5​ on the side ABABAB, excluding AAA and BBB, of a triangle ABCABCABC. Similarly there are 666 points P6,P7,…,P11P_6,P_7,\ldots,P_{11}P6​,P7​,…,P11​ on the side BCBCBC and 777 points P12,P13,…,P18P_{12},P_{13},\ldots,P_{18}P12​,P13​,…,P18​ on the side CACACA of the triangle. The number of triangles, that can be formed using the points P1,P2,…,P18P_1,P_2,\ldots,P_{18}P1​,P2​,…,P18​ as vertices, is:
  1. (A)776776776
  2. (B)751751751
  3. (C)796796796
  4. (D)771771771

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
Let f(x)={−2, −2≤x≤0x−2, 0<x≤2f(x)=\begin{cases}-2 & ,\ -2\le x\le0\\ x-2 & ,\ 0<x\le2\end{cases}f(x)={−2x−2​, −2≤x≤0, 0<x≤2​ and h(x)=f(∣x∣)+∣f(x)∣h(x)=f(|x|)+|f(x)|h(x)=f(∣x∣)+∣f(x)∣. Then ∫−22h(x) dx\displaystyle\int_{-2}^{2}h(x)\,dx∫−22​h(x)dx is equal to:
  1. (A)222
  2. (B)444
  3. (C)111
  4. (D)666

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
The sum of all rational terms in the expansion of (21/5+51/3)15\left(2^{1/5}+5^{1/3}\right)^{15}(21/5+51/3)15 is equal to:
  1. (A)313331333133
  2. (B)633633633
  3. (C)931931931
  4. (D)613161316131

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Let a unit vector which makes an angle of 60∘60^\circ60∘ with 2i^+2j^−k^2\hat i+2\hat j-\hat k2i^+2j^​−k^ and an angle of 45∘45^\circ45∘ with i^−k^\hat i-\hat ki^−k^ be C⃗\vec CC. Then C⃗+(−12i^+132j^−23k^)\vec C+\left(-\dfrac12\hat i+\dfrac{1}{3\sqrt2}\hat j-\dfrac{\sqrt2}{3}\hat k\right)C+(−21​i^+32​1​j^​−32​​k^) is:
  1. (A)−23i^+23j^+(12+223)k^-\dfrac{\sqrt2}{3}\hat i+\dfrac{\sqrt2}{3}\hat j+\left(\dfrac12+\dfrac{2\sqrt2}{3}\right)\hat k−32​​i^+32​​j^​+(21​+322​​)k^
  2. (B)23i^+132j^−12k^\dfrac{\sqrt2}{3}\hat i+\dfrac{1}{3\sqrt2}\hat j-\dfrac12\hat k32​​i^+32​1​j^​−21​k^
  3. (C)(13+12)i^+(13−132)j^+(13+23)k^\left(\dfrac{1}{\sqrt3}+\dfrac12\right)\hat i+\left(\dfrac{1}{\sqrt3}-\dfrac{1}{3\sqrt2}\right)\hat j+\left(\dfrac{1}{\sqrt3}+\dfrac{\sqrt2}{3}\right)\hat k(3​1​+21​)i^+(3​1​−32​1​)j^​+(3​1​+32​​)k^
  4. (D)23i^−12k^\dfrac{\sqrt2}{3}\hat i-\dfrac12\hat k32​​i^−21​k^

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
Let the first three terms 222, ppp and qqq, with q≠2q\ne2q=2, of a G.P. be respectively the 7th7^{th}7th, 8th8^{th}8th and 13th13^{th}13th terms of an A.P. If the 5th5^{th}5th term of the G.P. is the nthn^{th}nth term of the A.P., then nnn is equal to:
  1. (A)151151151
  2. (B)169169169
  3. (C)177177177
  4. (D)163163163

Correct answer: (D)

Step-by-step solution →
Q73·MathematicsSingle correct
Let a,b∈Ra,b\in\mathbb{R}a,b∈R. Let the mean and the variance of 666 observations −3,4,7,−6,a,b-3,4,7,-6,a,b−3,4,7,−6,a,b be 222 and 232323, respectively. The mean deviation about the mean of these 666 observations is:
  1. (A)133\dfrac{13}{3}313​
  2. (B)163\dfrac{16}{3}316​
  3. (C)113\dfrac{11}{3}311​
  4. (D)143\dfrac{14}{3}314​

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
If 222 and 666 are the roots of the equation ax2+bx+1=0ax^2+bx+1=0ax2+bx+1=0, then the quadratic equation, whose roots are 12a+b\dfrac{1}{2a+b}2a+b1​ and 16a+b\dfrac{1}{6a+b}6a+b1​, is:
  1. (A)2x2+11x+12=02x^2+11x+12=02x2+11x+12=0
  2. (B)4x2+14x+12=04x^2+14x+12=04x2+14x+12=0
  3. (C)x2+10x+16=0x^2+10x+16=0x2+10x+16=0
  4. (D)x2+8x+12=0x^2+8x+12=0x2+8x+12=0

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsSingle correct
Let α\alphaα and β\betaβ be the sum and the product of all the non-zero solutions of the equation (zˉ)2+∣z∣=0(\bar z)^2+|z|=0(zˉ)2+∣z∣=0, z∈Cz\in\mathbb{C}z∈C. Then 4(α2+β2)4(\alpha^2+\beta^2)4(α2+β2) is equal to:
  1. (A)666
  2. (B)444
  3. (C)888
  4. (D)222

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let the point, on the line passing through the points P(1,−2,3)P(1,-2,3)P(1,−2,3) and Q(5,−4,7)Q(5,-4,7)Q(5,−4,7), farther from the origin and at a distance of 999 units from the point PPP, be (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ). Then α2+β2+γ2\alpha^2+\beta^2+\gamma^2α2+β2+γ2 is equal to:
  1. (A)155155155
  2. (B)150150150
  3. (C)160160160
  4. (D)165165165

Correct answer: (A)

Step-by-step solution →
Q77·MathematicsSingle correct
A square is inscribed in the circle x2+y2−10x−6y+30=0x^2+y^2-10x-6y+30=0x2+y2−10x−6y+30=0. One side of this square is parallel to y=x+3y=x+3y=x+3. If (xi,yi)(x_i,y_i)(xi​,yi​) are the vertices of the square, then ∑(xi2+yi2)\sum(x_i^2+y_i^2)∑(xi2​+yi2​) is equal to:
  1. (A)148148148
  2. (B)156156156
  3. (C)160160160
  4. (D)152152152

Correct answer: (D)

Step-by-step solution →
Q78·MathematicsSingle correct
If the domain of the function sin⁡−1(3x−222x−19)+log⁡e(3x2−8x+5x2−3x−10)\sin^{-1}\left(\dfrac{3x-22}{2x-19}\right)+\log_e\left(\dfrac{3x^2-8x+5}{x^2-3x-10}\right)sin−1(2x−193x−22​)+loge​(x2−3x−103x2−8x+5​) is (α,β](\alpha,\beta](α,β], then 3α+10β3\alpha+10\beta3α+10β is equal to:
  1. (A)979797
  2. (B)100100100
  3. (C)959595
  4. (D)989898

Correct answer: (A)

Step-by-step solution →
Q79·Mathematics·DifferentiabilitySingle correct
Let f(x)=x5+2ex/4f(x)=x^5+2e^{x/4}f(x)=x5+2ex/4 for all x∈Rx\in\mathbb{R}x∈R. Consider a function g(x)g(x)g(x) such that (g∘f)(x)=x(g\circ f)(x)=x(g∘f)(x)=x for all x∈Rx\in\mathbb{R}x∈R. Then the value of 8g′(2)8g'(2)8g′(2) is:
  1. (A)161616
  2. (B)444
  3. (C)888
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsSingle correct
Let α∈(0,∞)\alpha\in(0,\infty)α∈(0,∞) and A=[12α101012]A=\begin{bmatrix}1 & 2 & \alpha\\ 1 & 0 & 1\\ 0 & 1 & 2\end{bmatrix}A=​110​201​α12​​. If det⁡(adj(2A−AT)⋅adj(A−2AT))=28\det\big(\mathrm{adj}(2A-A^T)\cdot\mathrm{adj}(A-2A^T)\big)=2^8det(adj(2A−AT)⋅adj(A−2AT))=28, then ∣A∣2|A|^2∣A∣2 is equal to:
  1. (A)111
  2. (B)494949
  3. (C)161616
  4. (D)444

Correct answer: (C)

Step-by-step solution →
Q81·Mathematics·Limits and ContinuityNumerical
If lim⁡x→1(5x+1)1/3−(x+5)1/3(2x+3)1/2−(x+4)1/2=m5n(2n)2/3\displaystyle\lim_{x\to1}\dfrac{(5x+1)^{1/3}-(x+5)^{1/3}}{(2x+3)^{1/2}-(x+4)^{1/2}}=\dfrac{m\sqrt5}{n(2n)^{2/3}}x→1lim​(2x+3)1/2−(x+4)1/2(5x+1)1/3−(x+5)1/3​=n(2n)2/3m5​​, where gcd⁡(m,n)=1\gcd(m,n)=1gcd(m,n)=1, then 8m+12n8m+12n8m+12n is equal to ___

Correct answer: 100

Step-by-step solution →
Q82·MathematicsNumerical
In a survey of 220220220 students of a higher secondary school, it was found that at least 125125125 and at most 130130130 studied Mathematics; at least 858585 and at most 959595 studied Physics; at least 757575 and at most 909090 studied Chemistry; 303030 studied both Physics and Chemistry; 505050 studied both Chemistry and Mathematics; 404040 studied both Mathematics and Physics and 101010 studied none of these three subjects. Let mmm and nnn respectively be the least and the most number of students who studied all the three subjects. Then m+nm+nm+n is equal to ___

Correct answer: 45

Step-by-step solution →
Q83·MathematicsNumerical
Let the solution y=y(x)y=y(x)y=y(x) of the differential equation dydx−y=1+4sin⁡x\dfrac{dy}{dx}-y=1+4\sin xdxdy​−y=1+4sinx satisfy y(π)=1y(\pi)=1y(π)=1. Then y(π2)+10y\left(\dfrac\pi2\right)+10y(2π​)+10 is equal to ___

Correct answer: 7

Step-by-step solution →
Q84·MathematicsNumerical
If the shortest distance between the lines x+22=y+33=z−54\dfrac{x+2}{2}=\dfrac{y+3}{3}=\dfrac{z-5}{4}2x+2​=3y+3​=4z−5​ and x−31=y−2−3=z+42\dfrac{x-3}{1}=\dfrac{y-2}{-3}=\dfrac{z+4}{2}1x−3​=−3y−2​=2z+4​ is 3835k\dfrac{38}{3\sqrt5}k35​38​k and ∫0k[x2] dx=α−α\displaystyle\int_0^k[x^2]\,dx=\alpha-\sqrt\alpha∫0k​[x2]dx=α−α​, where [x][x][x] denotes the greatest integer function, then 6α36\alpha^36α3 is equal to ___

Correct answer: 48

Step-by-step solution →
Q85·MathematicsNumerical
Let a=1+2C23!+3C24!+4C25!+…a=1+\dfrac{{}^2C_2}{3!}+\dfrac{{}^3C_2}{4!}+\dfrac{{}^4C_2}{5!}+\ldotsa=1+3!2C2​​+4!3C2​​+5!4C2​​+… and b=1+1C0+1C1+2C21!+2C0+3C1+4C22!+3C0+4C1+5C23!+…b=1+\dfrac{{}^1C_0+{}^1C_1+{}^2C_2}{1!}+\dfrac{{}^2C_0+{}^3C_1+{}^4C_2}{2!}+\dfrac{{}^3C_0+{}^4C_1+{}^5C_2}{3!}+\ldotsb=1+1!1C0​+1C1​+2C2​​+2!2C0​+3C1​+4C2​​+3!3C0​+4C1​+5C2​​+…. Then 2ba2\dfrac{2b}{a^2}a22b​ is equal to ___

Correct answer: 8

Step-by-step solution →
Q86·MathematicsNumerical
Let AAA be a 3×33\times33×3 matrix of non-negative real elements such that A[111]=3[111]A\begin{bmatrix}1\\1\\1\end{bmatrix}=3\begin{bmatrix}1\\1\\1\end{bmatrix}A​111​​=3​111​​. Then the maximum value of det⁡(A)\det(A)det(A) is ___

Correct answer: 27

Step-by-step solution →
Q87·MathematicsNumerical
Let the length of the focal chord PQPQPQ of the parabola y2=12xy^2=12xy2=12x be 151515 units. If the distance of PQPQPQ from the origin is ppp, then 10p210p^210p2 is equal to ___

Correct answer: 72

Step-by-step solution →
Q88·MathematicsNumerical
Let ABCABCABC be a triangle of area 15215\sqrt2152​ and the vectors AB⃗=i^+2j^−7k^\vec{AB}=\hat i+2\hat j-7\hat kAB=i^+2j^​−7k^, BC⃗=ai^+bj^+ck^\vec{BC}=a\hat i+b\hat j+c\hat kBC=ai^+bj^​+ck^ and AC⃗=6i^+dj^−2k^\vec{AC}=6\hat i+d\hat j-2\hat kAC=6i^+dj^​−2k^, d>0d>0d>0. Then the square of the length of the largest side of the triangle ABCABCABC is ___

Correct answer: 54

Step-by-step solution →
Q89·MathematicsNumerical
If ∫0π/4sin⁡2x1+sin⁡xcos⁡x dx=1alog⁡e(a3)+πb3\displaystyle\int_0^{\pi/4}\dfrac{\sin^2 x}{1+\sin x\cos x}\,dx=\dfrac1a\log_e\left(\dfrac a3\right)+\dfrac{\pi}{b\sqrt3}∫0π/4​1+sinxcosxsin2x​dx=a1​loge​(3a​)+b3​π​, where a,b∈Na,b\in\mathbb{N}a,b∈N, then a+ba+ba+b is equal to ___

Correct answer: 8

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Aldehydes and Ketones 135/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Differentiability 91/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
  • Principles of Qualitative Analysis 58/186
  • Isomerism 51/186
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