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JEE Main 1 February 2024 Shift 2 Question Paper with Answers

1 February 2024 · January session · 90 questions

The complete JEE Main 1 February 2024 Shift 2 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 1 February 2024 Shift 2

Q1·Physics·Current ElectricitySingle correct
In an ammeter, 5% of the main current passes through the galvanometer. If resistance of the galvanometer is GGG, the resistance of ammeter will be:
  1. (A)G200\dfrac{G}{200}200G​
  2. (B)G199\dfrac{G}{199}199G​
  3. (C)199 G199\,G199G
  4. (D)200 G200\,G200G

Correct answer: (A)

Step-by-step solution →
Q2·Physics·Experimental SkillsSingle correct
To measure the temperature coefficient of resistivity α\alphaα of a semiconductor, an electrical arrangement shown in the figure is prepared. The arm BC is made up of the semiconductor. The experiment is being conducted at 25∘25^{\circ}25∘C and resistance of the semiconductor arm is 3 mΩ\OmegaΩ. Arm BC is cooled at a constant rate of 2∘2^{\circ}2∘C/s. If the galvanometer G shows no deflection after 10 s, then α\alphaα is:
  1. (A)−2×10−2 ∘-2\times 10^{-2}\,^{\circ}−2×10−2∘C−1^{-1}−1
  2. (B)−1.5×10−2 ∘-1.5\times 10^{-2}\,^{\circ}−1.5×10−2∘C−1^{-1}−1
  3. (C)−1×10−2 ∘-1\times 10^{-2}\,^{\circ}−1×10−2∘C−1^{-1}−1
  4. (D)−2.5×10−2 ∘-2.5\times 10^{-2}\,^{\circ}−2.5×10−2∘C−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q3·Physics·Atoms and NucleiSingle correct
From the statements given below: (A) The angular momentum of an electron in nthn^{\text{th}}nth orbit is an integral multiple of hhh. (B) Nuclear forces do not obey inverse square law. (C) Nuclear forces are spin dependent. (D) Nuclear forces are central and charge independent. (E) Stability of nucleus is inversely proportional to the value of packing fraction. Choose the correct answer from the options given below:
  1. (A)(A), (B), (C), (D) only
  2. (B)(A), (C), (D), (E) only
  3. (C)(A), (B), (C), (E) only
  4. (D)(B), (C), (D), (E) only

Correct answer: (C)

Step-by-step solution →
Q4·Physics·ThermodynamicsSingle correct
A diatomic gas (γ=1.4)(\gamma=1.4)(γ=1.4) does 200 J of work when it is expanded isobarically. The heat given to the gas in the process is:
  1. (A)850 J
  2. (B)800 J
  3. (C)600 J
  4. (D)700 J

Correct answer: (D)

Step-by-step solution →
Q5·Physics·Rotational MotionSingle correct
A disc of radius R and mass M is rolling horizontally without slipping with speed vvv. It then moves up an inclined smooth surface as shown in figure. The maximum height that the disc can go up the incline is:
  1. (A)v2g\dfrac{v^2}{g}gv2​
  2. (B)34v2g\dfrac{3}{4}\dfrac{v^2}{g}43​gv2​
  3. (C)12v2g\dfrac{1}{2}\dfrac{v^2}{g}21​gv2​
  4. (D)23v2g\dfrac{2}{3}\dfrac{v^2}{g}32​gv2​

Correct answer: (C)

Step-by-step solution →
Q6·Physics·Dual Nature of Matter and RadiationSingle correct
Conductivity of a photodiode starts changing only if the wavelength of incident light is less than 660 nm. The band gap of photodiode is found to be (X/8)(X/8)(X/8) eV. The value of X is: (Given, h=6.6×10−34h=6.6\times 10^{-34}h=6.6×10−34 Js, e=1.6×10−19e=1.6\times 10^{-19}e=1.6×10−19 C)
  1. (A)15
  2. (B)11
  3. (C)13
  4. (D)21

Correct answer: (A)

Step-by-step solution →
Q7·Physics·Properties of Solids and LiquidsSingle correct
A big drop is formed by coalescing 1000 small droplets of water. The surface energy will become:
  1. (A)100 times
  2. (B)10 times
  3. (C)1100\dfrac{1}{100}1001​ th
  4. (D)110\dfrac{1}{10}101​ th

Correct answer: (D)

Step-by-step solution →
Q8·Physics·Electromagnetic WavesSingle correct
If frequency of electromagnetic wave is 60 MHz and it travels in air along z direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave (in m) is:
  1. (A)2.5
  2. (B)10
  3. (C)5
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q9·Physics·Laws of MotionSingle correct
A cricket player catches a ball of mass 120 g moving with 25 m/s speed. If the catching process is completed in 0.1 s then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):
  1. (A)24
  2. (B)12
  3. (C)25
  4. (D)30

Correct answer: (D)

Step-by-step solution →
Q10·Physics·Dual Nature of Matter and RadiationSingle correct
Monochromatic light of frequency 6×10146\times 10^{14}6×1014 Hz is produced by a laser. The power emitted is 2×10−32\times 10^{-3}2×10−3 W. How many photons per second on an average, are emitted by the source? (Given h=6.63×10−34h=6.63\times 10^{-34}h=6.63×10−34 Js)
  1. (A)9×10189\times 10^{18}9×1018
  2. (B)6×10156\times 10^{15}6×1015
  3. (C)5×10155\times 10^{15}5×1015
  4. (D)7×10167\times 10^{16}7×1016

Correct answer: (C)

Step-by-step solution →
Q11·Physics·Wave OpticsSingle correct
A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit, will be:
  1. (A)30∘30^{\circ}30∘
  2. (B)15∘15^{\circ}15∘
  3. (C)60∘60^{\circ}60∘
  4. (D)45∘45^{\circ}45∘

Correct answer: (C)

Step-by-step solution →
Q12·Physics·Electric Field and Coulomb's LawSingle correct
C1C_1C1​ and C2C_2C2​ are two hollow concentric cubes enclosing charges 2Q2Q2Q and 3Q3Q3Q respectively as shown in figure. The ratio of electric flux passing through C1C_1C1​ and C2C_2C2​ is:
  1. (A)2:5
  2. (B)5:2
  3. (C)2:3
  4. (D)3:2

Correct answer: (A)

Step-by-step solution →
Q13·Physics·Kinetic Theory of GasesSingle correct
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km/s, the root mean square velocity of oxygen at the same condition in km/s is:
  1. (A)2.0
  2. (B)0.5
  3. (C)1.5
  4. (D)1.0

Correct answer: (B)

Step-by-step solution →
Q14·Physics·KinematicsSingle correct
Train A is moving along two parallel rail tracks towards north with speed 72 km/h and train B is moving towards south with speed 108 km/h. Velocity of train B with respect to A and velocity of ground with respect to B are (in ms−1^{-1}−1):
  1. (A)−30-30−30 and 505050
  2. (B)−50-50−50 and −30-30−30
  3. (C)−50-50−50 and 303030
  4. (D)505050 and −30-30−30

Correct answer: (C)

Step-by-step solution →
Q15·Physics·Current ElectricitySingle correct
A galvanometer (G) of 2Ω\OmegaΩ resistance is connected in the given circuit. The ratio of charge stored in C1C_1C1​ and C2C_2C2​ is:
  1. (A)23\dfrac{2}{3}32​
  2. (B)32\dfrac{3}{2}23​
  3. (C)1
  4. (D)12\dfrac{1}{2}21​

Correct answer: (D)

Step-by-step solution →
Q16·Physics·Current ElectricitySingle correct
In a metre-bridge when a resistance in the left gap is 2Ω\OmegaΩ and unknown resistance in the right gap, the balance length is found to be 40 cm. On shunting the unknown resistance with 2Ω\OmegaΩ, the balance length changes by:
  1. (A)22.5 cm
  2. (B)20 cm
  3. (C)62.5 cm
  4. (D)65 cm

Correct answer: (A)

Step-by-step solution →
Q17·Physics·Units and MeasurementsSingle correct
Match List-I (Number) with List-II (Significant figures). Choose the correct answer from the options given below:
List-I (Number)List-II (Significant figure)
A.1001I.3
B.010.1II.4
C.100.100III.5
D.0.0010010IV.6
  1. (A)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  2. (B)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  3. (C)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  4. (D)(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Correct answer: (C)

Step-by-step solution →
Q18·Physics·Alternating CurrentsSingle correct
A transformer has an efficiency of 80%80\%80% and works at 10 V and 4 kW. If the secondary voltage is 240 V, then the current in the secondary coil is:
  1. (A)1.59 A
  2. (B)13.33 A
  3. (C)1.33 A
  4. (D)15.1 A

Correct answer: (B)

Step-by-step solution →
Q19·Physics·GravitationSingle correct
A light planet is revolving around a massive star in a circular orbit of radius R with a period of revolution T. If the force of attraction between planet and star is proportional to R−3/2R^{-3/2}R−3/2 then choose the correct option:
  1. (A)T2∝R5/2T^2\propto R^{5/2}T2∝R5/2
  2. (B)T2∝R7/2T^2\propto R^{7/2}T2∝R7/2
  3. (C)T2∝R3/2T^2\propto R^{3/2}T2∝R3/2
  4. (D)T2∝R3T^2\propto R^3T2∝R3

Correct answer: (A)

Step-by-step solution →
Q20·Physics·Laws of MotionSingle correct
A body of mass 4 kg experiences two forces F⃗1=5i^+8j^+7k^\vec F_1=5\hat i+8\hat j+7\hat kF1​=5i^+8j^​+7k^ and F⃗2=3i^−4j^−3k^\vec F_2=3\hat i-4\hat j-3\hat kF2​=3i^−4j^​−3k^. The acceleration acting on the body is:
  1. (A)−2i^−j^−k^-2\hat i-\hat j-\hat k−2i^−j^​−k^
  2. (B)4i^+2j^+2k^4\hat i+2\hat j+2\hat k4i^+2j^​+2k^
  3. (C)2i^+j^+k^2\hat i+\hat j+\hat k2i^+j^​+k^
  4. (D)2i^+3j^+3k^2\hat i+3\hat j+3\hat k2i^+3j^​+3k^

Correct answer: (C)

Step-by-step solution →
Q21·Physics·OscillationsNumerical
A mass m is suspended from a spring of negligible mass and the system oscillates with a frequency f1f_1f1​. The frequency of oscillations if a mass 9m is suspended from the same spring is f2f_2f2​. The value of f1f2\dfrac{f_1}{f_2}f2​f1​​ is __________.

Correct answer: 3

Step-by-step solution →
Q22·Physics·KinematicsNumerical
A particle initially at rest starts moving from reference point x=0x=0x=0 along x-axis, with velocity vvv that varies as v=4xv=4\sqrt xv=4x​ m/s. The acceleration of the particle is __________ ms−2^{-2}−2.

Correct answer: 8

Step-by-step solution →
Q23·Physics·Magnetic Field of CurrentNumerical
A moving coil galvanometer has 100 turns and each turn has an area 2.0 cm2^22. The magnetic field produced by the magnet is 0.01 T and the deflection in the coil is 0.05 radian when a current of 10 mA is passed through it. The torsional constant of the suspension wire is x×10−5x\times 10^{-5}x×10−5 N-m/rad. The value of x is __________.

Correct answer: 4

Step-by-step solution →
Q24·Physics·Properties of Solids and LiquidsNumerical
One end of a metal wire is fixed to a ceiling and a load of 2 kg hangs from the other end. A similar wire is attached to the bottom of the load and another load of 1 kg hangs from this lower wire. Then the ratio of longitudinal strain of upper wire to that of the lower wire will be __________. [Area of cross section of wire = 0.005 cm2^22, Y=2×1011Y=2\times 10^{11}Y=2×1011 Nm−2^{-2}−2 and g=10g=10g=10 ms−2^{-2}−2]

Correct answer: 3

Step-by-step solution →
Q25·Physics·Atoms and NucleiNumerical
A particular hydrogen-like ion emits the radiation of frequency 3×10153\times 10^{15}3×1015 Hz when it makes transition from n=2n=2n=2 to n=1n=1n=1. The frequency of radiation emitted in transition from n=3n=3n=3 to n=1n=1n=1 is X9×1015\dfrac{X}{9}\times 10^{15}9X​×1015 Hz, when X=X=X= __________.

Correct answer: 32

Step-by-step solution →
Q26·Physics·Current ElectricityNumerical
In an electrical circuit drawn below the amount of charge stored in the capacitor is __________ μ\muμC.

Correct answer: 60

Step-by-step solution →
Q27·Physics·Electromagnetic InductionNumerical
A coil of 200 turns and area 0.20 m2^22 is rotated at half a revolution per second and is placed in uniform magnetic field of 0.01 T perpendicular to axis of rotation of the coil. The maximum voltage generated in the coil is 2πβ\dfrac{2\pi}{\beta}β2π​ volt. The value of β\betaβ is __________.

Correct answer: 5

Step-by-step solution →
Q28·Physics·Wave OpticsNumerical
In Young's double slit experiment, monochromatic light of wavelength 5000 \AA{} is used. The slits are 1.0 mm apart and screen is placed at 1.0 m away from slits. The distance from the centre of the screen where intensity becomes half of the maximum intensity for the first time is __________ ×10−6\times 10^{-6}×10−6 m.

Correct answer: 125

Step-by-step solution →
Q29·Physics·Rotational MotionNumerical
A uniform rod AB of mass 2 kg and Length 30 cm at rest on a smooth horizontal surface. An impulse of force 0.2 Ns is applied to end B. The time taken by the rod to turn through at right angles will be πx\dfrac{\pi}{x}xπ​ s, where x=x=x= __________.

Correct answer: 4

Step-by-step solution →
Q30·Physics·Electric Field and Coulomb's LawNumerical
Suppose a uniformly charged wall provides a uniform electric field of 2×1042\times 10^42×104 N/C normally. A charged particle of mass 2 g being suspended through a silk thread of length 20 cm and remain stayed at a distance of 10 cm from the wall. Then the charge on the particle will be 1x μ\dfrac{1}{\sqrt x}\,\mux​1​μC where x=x=x= __________. [use g=10g=10g=10 m/s2^22]

Correct answer: 3

Step-by-step solution →

Chemistry — JEE Main 1 February 2024 Shift 2

Q31·Chemistry·d- and f-Block ElementsSingle correct
The transition metal having highest 3rd3^{\text{rd}}3rd ionisation enthalpy is:
  1. (A)Cr
  2. (B)Mn
  3. (C)V
  4. (D)Fe

Correct answer: (B)

Step-by-step solution →
Q32·Chemistry·Chemical Bonding and Molecular StructureSingle correct
Given below are two statements: Statement (I): A π\piπ bonding MO has lower electron density above and below the inter-nuclear axis. Statement (II): The π∗\pi^*π∗ antibonding MO has a node between the nuclei. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is false but Statement II is true
  4. (D)Statement I is true but Statement II is false

Correct answer: (C)

Step-by-step solution →
Q33·Chemistry·d- and f-Block ElementsSingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): In aqueous solutions Cr2+\text{Cr}^{2+}Cr2+ is reducing and Mn3+\text{Mn}^{3+}Mn3+ is oxidising in nature. Reason (R): Extra stability to half filled electronic configuration is observed than incompletely filled electronic configuration. In the light of the above statement, choose the most appropriate answer from the options given below:
  1. (A)Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. (B)Both (A) and (R) are true but (R) is not the correct explanation of (A)
  3. (C)(A) is false but (R) is true
  4. (D)(A) is true but (R) is false

Correct answer: (A)

Step-by-step solution →
Q34·Chemistry·Alcohols and EthersSingle correct
Match List-I (Reactants of phenol) with List-II (Product). Choose the correct answer from the options given below:
List-I (Reactants)List-II (Products)
A.Phenol, Zn/Δ\text{Zn}/\DeltaZn/ΔI.Salicylaldehyde
B.Phenol, CHCl3\text{CHCl}_3CHCl3​, NaOH, HClII.Salicylic acid
C.Phenol, CO2\text{CO}_2CO2​, NaOH, HClIII.Benzene
D.Phenol, conc. HNO3\text{HNO}_3HNO3​IV.Picric acid
  1. (A)(A)-(IV), (B), (II), (C)-(I), (D)-(III)
  2. (B)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  3. (C)(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  4. (D)(A)-(I), (B)-(IV), (C)-(I), (D)-(II)

Correct answer: (C)

Step-by-step solution →
Q35·Chemistry·Classification of Elements and Periodicity in PropertiesSingle correct
Given below are two statements: Statement (I): Both metal and non-metal exist in p and d-block elements. Statement (II): Non-metals have higher ionisation enthalpy and higher electronegativity than the metals. In the light of the above statements, choose the most appropriate answer from the option given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is false but Statement II is true
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are true

Correct answer: (B)

Step-by-step solution →
Q36·Chemistry·p-Block ElementsSingle correct
The strongest reducing agent among the following is:
  1. (A)NH3\text{NH}_3NH3​
  2. (B)SbH3\text{SbH}_3SbH3​
  3. (C)BiH3\text{BiH}_3BiH3​
  4. (D)PH3\text{PH}_3PH3​

Correct answer: (C)

Step-by-step solution →
Q37·Chemistry·d- and f-Block ElementsSingle correct
Which of the following compounds show colour due to d–d transition?
  1. (A)CuSO4⋅5H2O\text{CuSO}_4\cdot 5\text{H}_2\text{O}CuSO4​⋅5H2​O
  2. (B)K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7K2​Cr2​O7​
  3. (C)K2CrO4\text{K}_2\text{CrO}_4K2​CrO4​
  4. (D)KMnO4\text{KMnO}_4KMnO4​

Correct answer: (A)

Step-by-step solution →
Q38·Chemistry·Electronic Effects and StabilitySingle correct
The set of meta directing functional groups from the following sets is:
  1. (A)−CN-\text{CN}−CN, −NH2-\text{NH}_2−NH2​, −NHR-\text{NHR}−NHR, −OCH3-\text{OCH}_3−OCH3​
  2. (B)−NO2-\text{NO}_2−NO2​, −NH2-\text{NH}_2−NH2​, −COOH-\text{COOH}−COOH, −COOR-\text{COOR}−COOR
  3. (C)−NO2-\text{NO}_2−NO2​, −CHO-\text{CHO}−CHO, −SO3H-\text{SO}_3\text{H}−SO3​H, −COR-\text{COR}−COR
  4. (D)−CN-\text{CN}−CN, −CHO-\text{CHO}−CHO, −NHCOCH3-\text{NHCOCH}_3−NHCOCH3​, −COOR-\text{COOR}−COOR

Correct answer: (C)

Step-by-step solution →
Q39·Chemistry·Chemical Bonding and Molecular StructureSingle correct
Select the compound from the following that will show intramolecular hydrogen bonding.
  1. (A)H2O\text{H}_2\text{O}H2​O
  2. (B)NH3\text{NH}_3NH3​
  3. (C)C2H5OH\text{C}_2\text{H}_5\text{OH}C2​H5​OH
  4. (D)o-nitrophenol

Correct answer: (D)

Step-by-step solution →
Q40·Chemistry·Some Basic Concepts in ChemistrySingle correct
Lassaigne's test is used for detection of:
  1. (A)Nitrogen and Sulphur only
  2. (B)Nitrogen, Sulphur and Phosphorous Only
  3. (C)Phosphorous and halogens only
  4. (D)Nitrogen, Sulphur, phosphorous and halogens

Correct answer: (D)

Step-by-step solution →
Q41·Chemistry·HydrocarbonsSingle correct
Which among the following has highest boiling point?
  1. (A)CH3CH2CH2CH3\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_3CH3​CH2​CH2​CH3​
  2. (B)CH3CH2CH2−OH\text{CH}_3\text{CH}_2\text{CH}_2-\text{OH}CH3​CH2​CH2​−OH
  3. (C)CH3CH2CH2CHO\text{CH}_3\text{CH}_2\text{CH}_2\text{CHO}CH3​CH2​CH2​CHO
  4. (D)H3C2−O−C2H5\text{H}_3\text{C}_2-\text{O}-\text{C}_2\text{H}_5H3​C2​−O−C2​H5​

Correct answer: (B)

Step-by-step solution →
Q42·Chemistry·HydrocarbonsSingle correct
In the given reactions identify A and B. H2+A→Pd/C\text{H}_2+\text{A}\xrightarrow{\text{Pd/C}}H2​+APd/C​ (cis-pent-2-ene structure); CH3−C≡C−CH3+H2→Na/Liquid NH3\text{CH}_3-\text{C}\equiv\text{C}-\text{CH}_3+\text{H}_2\xrightarrow{\text{Na/Liquid NH}_3}CH3​−C≡C−CH3​+H2​Na/Liquid NH3​​ "B".
  1. (A)A: 2-Pentyne, B: trans-2-butene
  2. (B)A: n-Pentane, B: trans-2-butene
  3. (C)A: 2-Pentyne, B: Cis-2-butene
  4. (D)A: n-Pentane, B: Cis-2-butene

Correct answer: (A)

Step-by-step solution →
Q43·Chemistry·Atomic StructureSingle correct
The number of radial node/s for 3p orbital is:
  1. (A)1
  2. (B)4
  3. (C)2
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q44·Chemistry·HydrocarbonsSingle correct
Match List-I (Haloalkane / freon) with List-II (Industrial use). Choose the correct answer from the options given below:
List-I (Compound)List-II (Use)
A.Carbon tetrachlorideI.Paint remover
B.Methylene chlorideII.Refrigerators and air conditioners
C.DDTIII.Fire extinguisher
D.FreonsIV.Non Biodegradable insecticide
  1. (A)(A)-(I), (B), (II), (C)-(III), (D)-(IV)
  2. (B)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  3. (C)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  4. (D)(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Correct answer: (B)

Step-by-step solution →
Q45·Chemistry·Electronic Effects and StabilitySingle correct
The functional group that shows negative resonance effect is:
  1. (A)−NH2-\text{NH}_2−NH2​
  2. (B)−OH-\text{OH}−OH
  3. (C)−COOH-\text{COOH}−COOH
  4. (D)−OR-\text{OR}−OR

Correct answer: (C)

Step-by-step solution →
Q46·Chemistry·Coordination CompoundsSingle correct
[Co(NH3)6]3+[\text{Co(NH}_3)_6]^{3+}[Co(NH3​)6​]3+ and [CoF6]3−[\text{CoF}_6]^{3-}[CoF6​]3− are respectively known as:
  1. (A)Spin free Complex, Spin paired Complex
  2. (B)Spin paired Complex, Spin free Complex
  3. (C)Outer orbital Complex, Inner orbital Complex
  4. (D)Inner orbital Complex, Spin paired Complex

Correct answer: (B)

Step-by-step solution →
Q47·Chemistry·p-Block ElementsSingle correct
Given below are two statements: Statement (I): SiO2\text{SiO}_2SiO2​ and GeO2\text{GeO}_2GeO2​ are acidic while SnO and PbO are amphoteric in nature. Statement (II): Allotropic forms of carbon are due to property of catenation and pπ\piπ–dπ\piπ bond formation. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q48·Chemistry·HydrocarbonsSingle correct
C2H5Br→alc. KOHA→Br2/CCl4B→KCN excessC→H3O+ExcessD\text{C}_2\text{H}_5\text{Br}\xrightarrow{\text{alc. KOH}}\text{A}\xrightarrow{\text{Br}_2/\text{CCl}_4}\text{B}\xrightarrow{\text{KCN excess}}\text{C}\xrightarrow{\text{H}_3\text{O}^+\text{Excess}}\text{D}C2​H5​Bralc. KOH​ABr2​/CCl4​​BKCN excess​CH3​O+Excess​D. Acid D formed in above reaction is:
  1. (A)Gluconic acid
  2. (B)Succinic acid
  3. (C)Oxalic acid
  4. (D)Malonic acid

Correct answer: (B)

Step-by-step solution →
Q49·Chemistry·EquilibriumSingle correct
Solubility of calcium phosphate (molecular mass, M) in water is WgW_gWg​ per 100 mL at 25∘25^{\circ}25∘ C. Its solubility product at 25∘25^{\circ}25∘C will be approximately:
  1. (A)107(WM)310^7\left(\dfrac{W}{M}\right)^3107(MW​)3
  2. (B)107(WM)510^7\left(\dfrac{W}{M}\right)^5107(MW​)5
  3. (C)103(WM)510^3\left(\dfrac{W}{M}\right)^5103(MW​)5
  4. (D)105(WM)510^5\left(\dfrac{W}{M}\right)^5105(MW​)5

Correct answer: (B)

Step-by-step solution →
Q50·Chemistry·Coordination CompoundsSingle correct
Given below are two statements: Statement (I): Dimethyl glyoxime forms a six-membered covalent chelate when treated with NiCl2\text{NiCl}_2NiCl2​ solution in presence of NH4OH\text{NH}_4\text{OH}NH4​OH. Statement (II): Prussian blue precipitate contains iron both in (+2) and (+3) oxidation states. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is true but Statement II is false

Correct answer: (A)

Step-by-step solution →
Q51·Chemistry·HydrocarbonsNumerical
Total number of isomeric compounds (including stereoisomers) formed by monochlorination of 2-methylbutane is __________.

Correct answer: 6

Step-by-step solution →
Q52·Chemistry·Chemical KineticsNumerical
The following data were obtained during the first order thermal decomposition of a gas A at constant volume: A(g)→2B(g)+C(g)\text{A}(g)\to 2\text{B}(g)+\text{C}(g)A(g)→2B(g)+C(g). S.No 1: t=0t=0t=0 s, Total pressure =0.1=0.1=0.1 atm. S.No 2: t=115t=115t=115 s, Total pressure =0.28=0.28=0.28 atm. The rate constant of the reaction is __________ ×10−2\times 10^{-2}×10−2 s−1^{-1}−1 (nearest integer).

Correct answer: 2

Step-by-step solution →
Q53·Chemistry·BiomoleculesNumerical
The number of tripeptides formed by three different amino acids using each amino acid once is __________.

Correct answer: 6

Step-by-step solution →
Q54·Chemistry·AminesNumerical
Number of compounds which give reaction with Hinsberg's reagent is __________.

Correct answer: 5

Step-by-step solution →
Q55·Chemistry·SolutionsNumerical
Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at −24∘-24^{\circ}−24∘C is __________ kg (Molar mass in g mol−1^{-1}−1 for ethylene glycol 62, KfK_fKf​ of water =1.86=1.86=1.86 K kg mol−1^{-1}−1).

Correct answer: 15

Step-by-step solution →
Q56·Chemistry·Some Basic Concepts in ChemistryNumerical
Following Kjeldahl's method, 1g of organic compound released ammonia, that neutralised 10 mL of 2M H2SO4\text{H}_2\text{SO}_4H2​SO4​. The percentage of nitrogen in the compound is __________ %.

Correct answer: 56

Step-by-step solution →
Q57·Chemistry·Redox Reactions and ElectrochemistryNumerical
The amount of electricity in Coulomb required for the oxidation of 1 mol of H2O\text{H}_2\text{O}H2​O to O2\text{O}_2O2​ is __________ ×105\times 10^5×105 C.

Correct answer: 2

Step-by-step solution →
Q58·Chemistry·Chemical ThermodynamicsNumerical
For a certain reaction at 300 K, K=10K=10K=10, then ΔG∘\Delta G^{\circ}ΔG∘ for the same reaction is −-− __________ ×10−1\times 10^{-1}×10−1 kJ mol−1^{-1}−1. (Given R=8.314R=8.314R=8.314 JK−1^{-1}−1 mol−1^{-1}−1)

Correct answer: 57

Step-by-step solution →
Q59·Chemistry·Redox Reactions and ElectrochemistryNumerical
Consider the following redox reaction: MnO4−+H++H2C2O4⇌Mn2++H2O+CO2\text{MnO}_4^-+\text{H}^++\text{H}_2\text{C}_2\text{O}_4\rightleftharpoons\text{Mn}^{2+}+\text{H}_2\text{O}+\text{CO}_2MnO4−​+H++H2​C2​O4​⇌Mn2++H2​O+CO2​. The standard reduction potentials are given as below (Ered∘E^{\circ}_{\text{red}}Ered∘​): EMnO4−/Mn2+∘=+1.51E^{\circ}_{\text{MnO}_4^-/\text{Mn}^{2+}}=+1.51EMnO4−​/Mn2+∘​=+1.51 V, ECO2/H2C2O4∘=−0.49E^{\circ}_{\text{CO}_2/\text{H}_2\text{C}_2\text{O}_4}=-0.49ECO2​/H2​C2​O4​∘​=−0.49 V. If the equilibrium constant of the above reaction is given as Keq=10xK_{\text{eq}}=10^xKeq​=10x, then the value of x=x=x= __________ (nearest integer).

Correct answer: 338

Step-by-step solution →
Q60·Chemistry·Some Basic Concepts in ChemistryNumerical
10 mL of gaseous hydrocarbon on combustion gives 40 mL of CO2(g)\text{CO}_2(g)CO2​(g) and 50 mL of water vapour. Total number of carbon and hydrogen atoms in the hydrocarbon is __________.

Correct answer: 14

Step-by-step solution →

Mathematics — JEE Main 1 February 2024 Shift 2

Q61·Mathematics·Limits and ContinuitySingle correct
Let f(x)=∣ 2x2+5∣x∣−3 ∣f(x)=\big|\,2x^2+5|x|-3\,\big|f(x)=​2x2+5∣x∣−3​, x∈Rx\in\mathbb Rx∈R. If mmm and nnn denote the number of points where fff is not continuous and not differentiable respectively, then m+nm+nm+n is equal to:
  1. (A)5
  2. (B)2
  3. (C)0
  4. (D)3

Correct answer: (D)

Step-by-step solution →
Q62·Mathematics·Quadratic EquationsSingle correct
Let α\alphaα and β\betaβ be the roots of the equation px2+qx−r=0px^2+qx-r=0px2+qx−r=0, where p≠0p\neq 0p=0. If ppp, qqq and rrr be the consecutive terms of a non-constant GP and 1α+1β=34\dfrac{1}{\alpha}+\dfrac{1}{\beta}=\dfrac{3}{4}α1​+β1​=43​, then the value of (α−β)2(\alpha-\beta)^2(α−β)2 is:
  1. (A)809\dfrac{80}{9}980​
  2. (B)9
  3. (C)203\dfrac{20}{3}320​
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q63·Mathematics·Trigonometric FunctionsSingle correct
The number of solutions of the equation 4sin⁡2x−4cos⁡3x+9−4cos⁡x=04\sin^2 x-4\cos^3 x+9-4\cos x=04sin2x−4cos3x+9−4cosx=0, x∈[−2π, 2π]x\in[-2\pi,\,2\pi]x∈[−2π,2π] is:
  1. (A)1
  2. (B)3
  3. (C)2
  4. (D)0

Correct answer: (D)

Step-by-step solution →
Q64·Mathematics·Definite IntegrationSingle correct
The value of ∫01(2x3−3x2−x+1)1/3 dx\displaystyle\int_0^1 (2x^3-3x^2-x+1)^{1/3}\,dx∫01​(2x3−3x2−x+1)1/3dx is equal to:
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)−1-1−1

Correct answer: (A)

Step-by-step solution →
Q65·Mathematics·EllipseSingle correct
Let P be a point on the ellipse x29+y24=1\dfrac{x^2}{9}+\dfrac{y^2}{4}=19x2​+4y2​=1. Let the line passing through P and parallel to y-axis meet the circle x2+y2=9x^2+y^2=9x2+y2=9 at point Q such that P and Q are on the same side of the x-axis. Then, the eccentricity of the locus of the point R on PQ such that PR:RQ=4:3PR:RQ=4:3PR:RQ=4:3 as P moves on the ellipse, is:
  1. (A)1119\dfrac{11}{19}1911​
  2. (B)1321\dfrac{13}{21}2113​
  3. (C)13923\dfrac{\sqrt{139}}{23}23139​​
  4. (D)137\dfrac{\sqrt{13}}{7}713​​

Correct answer: (D)

Step-by-step solution →
Q66·Mathematics·Binomial Theorem and Its Simple ApplicationsSingle correct
Let mmm and nnn be the coefficients of seventh and thirteenth terms respectively in the expansion of (13x1/3+12x2/3)18\left(\dfrac{1}{3}x^{1/3}+\dfrac{1}{2x^{2/3}}\right)^{18}(31​x1/3+2x2/31​)18. Then (nm)1/3\left(\dfrac{n}{m}\right)^{1/3}(mn​)1/3 is:
  1. (A)49\dfrac{4}{9}94​
  2. (B)19\dfrac{1}{9}91​
  3. (C)14\dfrac{1}{4}41​
  4. (D)94\dfrac{9}{4}49​

Correct answer: (D)

Step-by-step solution →
Q67·Mathematics·Differential EquationsSingle correct
Let α\alphaα be a non-zero real number. Suppose f:R→Rf:\mathbb R\to\mathbb Rf:R→R is a differentiable function such that f(0)=2f(0)=2f(0)=2 and lim⁡x→−∞f(x)=1\displaystyle\lim_{x\to-\infty}f(x)=1x→−∞lim​f(x)=1. If f′(x)=αf(x)+3f'(x)=\alpha f(x)+3f′(x)=αf(x)+3, for all x∈Rx\in\mathbb Rx∈R, then f(−log⁡e2)f(-\log_e 2)f(−loge​2) is equal to:
  1. (A)3
  2. (B)5
  3. (C)9
  4. (D)7

Correct answer: (C)

Step-by-step solution →
Q68·Mathematics·Three Dimensional GeometrySingle correct
Let P and Q be the points on the line x+38=y−42=z+12\dfrac{x+3}{8}=\dfrac{y-4}{2}=\dfrac{z+1}{2}8x+3​=2y−4​=2z+1​ which are at a distance of 6 units from the point R(1, 2, 3). If the centroid of the triangle PQR is (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ), then α2+β2+γ2\alpha^2+\beta^2+\gamma^2α2+β2+γ2 is:
  1. (A)26
  2. (B)36
  3. (C)18
  4. (D)24

Correct answer: (C)

Step-by-step solution →
Q69·Mathematics·Vector AlgebraSingle correct
Consider a △ABC\triangle ABC△ABC where A(1,2,3)A(1,2,3)A(1,2,3), B(−2,8,0)B(-2,8,0)B(−2,8,0) and C(3,6,7)C(3,6,7)C(3,6,7). If the angle bisector of ∠BAC\angle BAC∠BAC meets the line BC at D, then the length of the projection of the vector AD⃗\vec{AD}AD on the vector AC⃗\vec{AC}AC is:
  1. (A)37238\dfrac{37}{2\sqrt{38}}238​37​
  2. (B)382\dfrac{\sqrt{38}}{2}238​​
  3. (C)39238\dfrac{39}{2\sqrt{38}}238​39​
  4. (D)19\sqrt{19}19​

Correct answer: (A)

Step-by-step solution →
Q70·Mathematics·Sequence and SeriesSingle correct
Let SnS_nSn​ denote the sum of the first nnn terms of an arithmetic progression. If S10=390S_{10}=390S10​=390 and the ratio of the tenth and the fifth terms is 15:715:715:7, then S15−S5S_{15}-S_5S15​−S5​ is equal to:
  1. (A)800
  2. (B)890
  3. (C)790
  4. (D)690

Correct answer: (C)

Step-by-step solution →
Q71·Mathematics·Definite IntegrationSingle correct
If ∫0π/3cos⁡4x dx=aπ+b3\displaystyle\int_0^{\pi/3}\cos^4 x\,dx=a\pi+b\sqrt 3∫0π/3​cos4xdx=aπ+b3​, where aaa and bbb are rational numbers, then 9a+8b9a+8b9a+8b is equal to:
  1. (A)2
  2. (B)1
  3. (C)3
  4. (D)32\dfrac{3}{2}23​

Correct answer: (A)

Step-by-step solution →
Q72·Mathematics·Complex NumbersSingle correct
If zzz is a complex number such that ∣z∣≥1|z|\ge 1∣z∣≥1, then the minimum value of ∣z+12(3+4i)∣\left|z+\dfrac{1}{2}(3+4i)\right|​z+21​(3+4i)​ is:
  1. (A)52\dfrac{5}{2}25​
  2. (B)2
  3. (C)3
  4. (D)32\dfrac{3}{2}23​

Correct answer: (D)

Step-by-step solution →
Q73·Mathematics·Sets, Relations and FunctionsSingle correct
If the domain of the function f(x)=x2−25(4−x2)+log⁡10(x2+2x−15)f(x)=\dfrac{\sqrt{x^2-25}}{(4-x^2)}+\log_{10}(x^2+2x-15)f(x)=(4−x2)x2−25​​+log10​(x2+2x−15) is (−∞,α)∪[β,∞)(-\infty,\alpha)\cup[\beta,\infty)(−∞,α)∪[β,∞), then α2+β3\alpha^2+\beta^3α2+β3 is equal to:
  1. (A)140
  2. (B)175
  3. (C)150
  4. (D)125

Correct answer: (C)

Step-by-step solution →
Q74·Mathematics·Sets, Relations and FunctionsSingle correct
Consider the relations R1R_1R1​ and R2R_2R2​ defined as aR1b⇔a2+b2=1aR_1 b\Leftrightarrow a^2+b^2=1aR1​b⇔a2+b2=1 for all a,b∈Ra,b\in\mathbb Ra,b∈R and (a,b)R2(c,d)⇔a+d=b+c(a,b)R_2(c,d)\Leftrightarrow a+d=b+c(a,b)R2​(c,d)⇔a+d=b+c for all (a,b),(c,d)∈N×N(a,b),(c,d)\in\mathbb N\times\mathbb N(a,b),(c,d)∈N×N. Then
  1. (A)Only R1R_1R1​ is an equivalence relation
  2. (B)Only R2R_2R2​ is an equivalence relation
  3. (C)R1R_1R1​ and R2R_2R2​ both are equivalence relations
  4. (D)Neither R1R_1R1​ nor R2R_2R2​ is an equivalence relation

Correct answer: (B)

Step-by-step solution →
Q75·Mathematics·Three Dimensional GeometrySingle correct
If the mirror image of the point P(3,4,9)P(3,4,9)P(3,4,9) in the line x−13=y+12=z−21\dfrac{x-1}{3}=\dfrac{y+1}{2}=\dfrac{z-2}{1}3x−1​=2y+1​=1z−2​ is (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ), then 14(α+β+γ)14(\alpha+\beta+\gamma)14(α+β+γ) is:
  1. (A)102
  2. (B)138
  3. (C)108
  4. (D)132

Correct answer: (C)

Step-by-step solution →
Q76·Mathematics·Limits and ContinuitySingle correct
Let f(x)={x−1,x is even,2x,x is odd,  x∈Nf(x)=\begin{cases} x-1,& x\text{ is even},\\ 2x,& x\text{ is odd},\end{cases}\;x\in\mathbb Nf(x)={x−1,2x,​x is even,x is odd,​x∈N. If for some a∈Na\in\mathbb Na∈N, f(f(f(a)))=21f(f(f(a)))=21f(f(f(a)))=21, then lim⁡x→a−{∣x∣3a−[xa]}\displaystyle\lim_{x\to a^-}\left\{\dfrac{|x|^3}{a}-\left[\dfrac{x}{a}\right]\right\}x→a−lim​{a∣x∣3​−[ax​]}, where [t][t][t] denotes the greatest integer less than or equal to ttt, is equal to:
  1. (A)121
  2. (B)144
  3. (C)169
  4. (D)225

Correct answer: (B)

Step-by-step solution →
Q77·Mathematics·Matrices and DeterminantsSingle correct
Let the system of equations x+2y+3z=5x+2y+3z=5x+2y+3z=5, 2x+3y+z=92x+3y+z=92x+3y+z=9, 4x+3y+λz=μ4x+3y+\lambda z=\mu4x+3y+λz=μ have infinite number of solutions. Then λ+2μ\lambda+2\muλ+2μ is equal to:
  1. (A)28
  2. (B)17
  3. (C)22
  4. (D)15

Correct answer: (B)

Step-by-step solution →
Q78·Mathematics·Statistics and ProbabilitySingle correct
Consider 10 observations x1,x2,…,x10x_1,x_2,\ldots,x_{10}x1​,x2​,…,x10​ such that ∑i=110(xi−α)=2\displaystyle\sum_{i=1}^{10}(x_i-\alpha)=2i=1∑10​(xi​−α)=2 and ∑i=110(xi−β)2=40\displaystyle\sum_{i=1}^{10}(x_i-\beta)^2=40i=1∑10​(xi​−β)2=40, where α,β\alpha,\betaα,β are positive integers. Let the mean and the variance of the observations be 65\dfrac{6}{5}56​ and 8425\dfrac{84}{25}2584​ respectively. The βα\dfrac{\beta}{\alpha}αβ​ is equal to:
  1. (A)2
  2. (B)32\dfrac{3}{2}23​
  3. (C)52\dfrac{5}{2}25​
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q79·Mathematics·Statistics and ProbabilitySingle correct
Let Ajay will not appear in JEE exam with probability p=27p=\dfrac{2}{7}p=72​, while both Ajay and Vijay will appear in the exam with probability q=15q=\dfrac{1}{5}q=51​. Then the probability, that Ajay will appear in the exam and Vijay will not appear is:
  1. (A)935\dfrac{9}{35}359​
  2. (B)1835\dfrac{18}{35}3518​
  3. (C)2435\dfrac{24}{35}3524​
  4. (D)335\dfrac{3}{35}353​

Correct answer: (B)

Step-by-step solution →
Q80·Mathematics·CirclesSingle correct
Let the locus of the mid points of the chords of circle x2+(y−1)2=1x^2+(y-1)^2=1x2+(y−1)2=1 drawn from the origin intersect the line x+y=1x+y=1x+y=1 at P and Q. Then, the length of PQ is:
  1. (A)12\dfrac{1}{\sqrt 2}2​1​
  2. (B)2\sqrt 22​
  3. (C)12\dfrac{1}{2}21​
  4. (D)1

Correct answer: (A)

Step-by-step solution →
Q81·Mathematics·Sequence and SeriesNumerical
If three successive terms of a G.P. with common ratio rrr (r>1)(r>1)(r>1) are the lengths of the sides of a triangle and [r][r][r] denotes the greatest integer less than or equal to rrr, then 3[r]+[−r]3[r]+[-r]3[r]+[−r] is equal to __________.

Correct answer: 1

Step-by-step solution →
Q82·Mathematics·Matrices and DeterminantsNumerical
Let A=I2−2MMTA=I_2-2MM^TA=I2​−2MMT, where MMM is real matrix of order 2×12\times 12×1 such that the relation MTM=I1M^T M=I_1MTM=I1​ holds. If λ\lambdaλ is a real number such that the relation AX=λXAX=\lambda XAX=λX holds for some non-zero real matrix XXX of order 2×12\times 12×1, then the sum of squares of all possible values of λ\lambdaλ is equal to __________.

Correct answer: 2

Step-by-step solution →
Q83·Mathematics·Definite IntegrationNumerical
Let f:(0,∞)→Rf:(0,\infty)\to\mathbb Rf:(0,∞)→R and F(x)=∫0xtf(t) dtF(x)=\displaystyle\int_0^x t f(t)\,dtF(x)=∫0x​tf(t)dt. If F(x2)=x4+x5F(x^2)=x^4+x^5F(x2)=x4+x5, then ∑r=112f(r2)\displaystyle\sum_{r=1}^{12} f(r^2)r=1∑12​f(r2) is equal to __________.

Correct answer: 219

Step-by-step solution →
Q84·Mathematics·Limits and ContinuityNumerical
If y=(x+1)(x2−x)xx+x+x+115(3cos⁡2x−5)cos⁡3xy=\dfrac{(\sqrt x+1)(x^2-\sqrt x)}{x\sqrt x+x+\sqrt x}+\dfrac{1}{15}(3\cos^2 x-5)\cos^3 xy=xx​+x+x​(x​+1)(x2−x​)​+151​(3cos2x−5)cos3x, then 96 y′ ⁣(π6)96\,y'\!\left(\dfrac{\pi}{6}\right)96y′(6π​) is equal to __________.

Correct answer: 105

Step-by-step solution →
Q85·Mathematics·Vector AlgebraNumerical
Let a⃗=i^+j^+k^\vec a=\hat i+\hat j+\hat ka=i^+j^​+k^, b⃗=−i^−8j^+2k^\vec b=-\hat i-8\hat j+2\hat kb=−i^−8j^​+2k^ and c⃗=4i^+c2j^+c3k^\vec c=4\hat i+c_2\hat j+c_3\hat kc=4i^+c2​j^​+c3​k^ be three vectors such that b⃗×a⃗=c⃗×a⃗\vec b\times\vec a=\vec c\times\vec ab×a=c×a. If the angle between the vector c⃗\vec cc and the vector 3i^+4j^+k^3\hat i+4\hat j+\hat k3i^+4j^​+k^ is θ\thetaθ, then the greatest integer less than or equal to tan⁡2θ\tan^2\thetatan2θ is __________.

Correct answer: 38

Step-by-step solution →
Q86·Mathematics·Straight LinesNumerical
The lines L1,L2,…,L20L_1,L_2,\ldots,L_{20}L1​,L2​,…,L20​ are distinct. For n=1,2,3,…,10n=1,2,3,\ldots,10n=1,2,3,…,10 all the lines L2n−1L_{2n-1}L2n−1​ are parallel to each other and all the lines L2nL_{2n}L2n​ pass through a given point P. The maximum number of points of intersection of pairs of lines from the set {L1,L2,…,L20}\{L_1,L_2,\ldots,L_{20}\}{L1​,L2​,…,L20​} is equal to __________.

Correct answer: 101

Step-by-step solution →
Q87·Mathematics·Area Under CurvesNumerical
Three points O(0,0)O(0,0)O(0,0), P(a,a2)P(a,a^2)P(a,a2), Q(−b,b2)Q(-b,b^2)Q(−b,b2), a>0,b>0a>0,b>0a>0,b>0, are on the parabola y=x2y=x^2y=x2. Let S1S_1S1​ be the area of the region bounded by the line PQ and the parabola, and S2S_2S2​ be the area of the triangle OPQ. If the minimum value of S1S2\dfrac{S_1}{S_2}S2​S1​​ is mn\dfrac{m}{n}nm​, gcd⁡(m,n)=1\gcd(m,n)=1gcd(m,n)=1, then m+nm+nm+n is equal to __________.

Correct answer: 7

Step-by-step solution →
Q88·Mathematics·Area Under CurvesNumerical
The sum of squares of all possible values of kkk, for which area of the region bounded by the parabolas 2y2=kx2y^2=kx2y2=kx and ky2=2(y−x)ky^2=2(y-x)ky2=2(y−x) is maximum, is equal to __________.

Correct answer: 8

Step-by-step solution →
Q89·Mathematics·Differential EquationsNumerical
If dxdy=1+x−y2y\dfrac{dx}{dy}=\dfrac{1+x-y^2}{y}dydx​=y1+x−y2​, x(1)=1x(1)=1x(1)=1, then 5x(2)5x(2)5x(2) is equal to __________.

Correct answer: 5

Step-by-step solution →
Q90·Mathematics·Trigonometric FunctionsNumerical
Let ABC be an isosceles triangle in which A is at (−1,0)(-1,0)(−1,0), ∠A=2π3\angle A=\dfrac{2\pi}{3}∠A=32π​, AB=ACAB=ACAB=AC and B is on the positive x-axis. If BC=43BC=4\sqrt 3BC=43​ and the line BC intersects the line y=x+3y=x+3y=x+3 at (α,β)(\alpha,\beta)(α,β), then β4α2\dfrac{\beta^4}{\alpha^2}α2β4​ is __________.

Correct answer: 36

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Straight Lines 114/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
← 1 Feb Shift 1 2024All papers4 Apr Shift 1 2024 →

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