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JEE Main 4 April 2024 Shift 2 Question Paper with Answers

4 April 2024 · April session · 90 questions

The complete JEE Main 4 April 2024 Shift 2 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 4 April 2024 Shift 2

Q1·PhysicsSingle correct
The translational degrees of freedom (ftf_tft​) and rotational degrees of freedom (frf_rfr​) of CH4\text{CH}_4CH4​ molecule are
  1. (A)ft=2f_t=2ft​=2 and fr=2f_r=2fr​=2
  2. (B)ft=3f_t=3ft​=3 and fr=3f_r=3fr​=3
  3. (C)ft=3f_t=3ft​=3 and fr=2f_r=2fr​=2
  4. (D)ft=2f_t=2ft​=2 and fr=3f_r=3fr​=3

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
A cyclist starts from the point P of a circular ground of radius 2 km and travels along its circumference to the point S (shown in the figure). The displacement of a cyclist is
  1. (A)6 km
  2. (B)8\sqrt{8}8​ km
  3. (C)4 km
  4. (D)8 km

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
The magnetic moment of a bar magnet is 0.5 Am20.5\ \text{Am}^20.5 Am2. It is suspended in a uniform magnetic field of 8×10−28\times10^{-2}8×10−2 T. The work done in rotating it from its most stable to most unstable position is
  1. (A)2×10−22\times10^{-2}2×10−2 J
  2. (B)8×10−28\times10^{-2}8×10−2 J
  3. (C)4×10−24\times10^{-2}4×10−2 J
  4. (D)Zero

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
Which of the diode circuit shows correct biasing used for the measurement of dynamic resistance of p-n junction diode?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
Arrange the following in the ascending order of wavelength (λ)(\lambda)(λ): (A) Gamma rays (λ1)(\lambda_1)(λ1​), (B) X-ray (λ2)(\lambda_2)(λ2​), (C) Infrared waves (λ3)(\lambda_3)(λ3​), (D) Microwaves (λ4)(\lambda_4)(λ4​). Choose the most appropriate answer from the options given below:
  1. (A)λ4<λ3<λ1<λ2\lambda_4<\lambda_3<\lambda_1<\lambda_2λ4​<λ3​<λ1​<λ2​
  2. (B)λ4<λ3<λ2<λ1\lambda_4<\lambda_3<\lambda_2<\lambda_1λ4​<λ3​<λ2​<λ1​
  3. (C)λ1<λ2<λ3<λ4\lambda_1<\lambda_2<\lambda_3<\lambda_4λ1​<λ2​<λ3​<λ4​
  4. (D)λ2<λ1<λ4<λ3\lambda_2<\lambda_1<\lambda_4<\lambda_3λ2​<λ1​<λ4​<λ3​

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
Identify the logic gate given in the circuit (shown in the figure):
  1. (A)NAND - gate
  2. (B)OR - gate
  3. (C)AND gate
  4. (D)NOR gate

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is
  1. (A)9:19:19:1
  2. (B)16:116:116:1
  3. (C)1:11:11:1
  4. (D)4:14:14:1

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
Correct formula for height of a satellite from earth's surface is
  1. (A)(T2R2g4π)1/2−R\left(\tfrac{T^2R^2g}{4\pi}\right)^{1/2}-R(4πT2R2g​)1/2−R
  2. (B)(T2R2g4π2)1/3−R\left(\tfrac{T^2R^2g}{4\pi^2}\right)^{1/3}-R(4π2T2R2g​)1/3−R
  3. (C)(T2R24π2g)1/3−R\left(\tfrac{T^2R^2}{4\pi^2 g}\right)^{1/3}-R(4π2gT2R2​)1/3−R
  4. (D)(T2R24π2)−1/3+R\left(\tfrac{T^2R^2}{4\pi^2}\right)^{-1/3}+R(4π2T2R2​)−1/3+R

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
Match List-I (type of AC circuit) with List-II (the phasor diagram of current I and voltage V). Choose the correct answer from the options given below:
List-IList-II
A.Purely capacitive circuitI.see figure
B.Purely inductive circuitII.see figure
C.LCR series at resonanceIII.see figure
D.LCR series circuitIV.see figure
  1. (A)A-I, B-IV, C-III, D-II
  2. (B)A-IV, B-I, C-III, D-II
  3. (C)A-IV, B-I, C-II, D-III
  4. (D)A-I, B-IV, C-II, D-III

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
Given below are two statements: Statement I: The contact angle between a solid and a liquid is a property of the material of the solid and liquid as well. Statement II: The rise of a liquid in a capillary tube does not depend on the inner radius of the tube. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is false but Statement II is true
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are true

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
A body of mmm kg slides from rest along the curve of vertical circle from point A to B in friction less path (shown in the figure). The velocity of the body at B is (given, R=14R=14R=14 m, g=10 m/s2g=10\ \text{m/s}^2g=10 m/s2 and 2=1.4\sqrt{2}=1.42​=1.4)
  1. (A)19.8 m/s
  2. (B)21.9 m/s
  3. (C)16.7 m/s
  4. (D)10.6 m/s

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
An electric bulb rated 50 W−200 V50\ \text{W}-200\ \text{V}50 W−200 V is connected across a 100100100 V supply. The power dissipation of the bulb is
  1. (A)12.5 W
  2. (B)25 W
  3. (C)50 W
  4. (D)100 W

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
A 2 kg brick begins to slide over a surface which is inclined at an angle of 45∘45^{\circ}45∘ with respect to horizontal axis. The co-efficient of static friction between their surfaces is
  1. (A)1
  2. (B)13\tfrac{1}{\sqrt{3}}3​1​
  3. (C)0.5
  4. (D)12\tfrac{1}{\sqrt{2}}2​1​

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
In a simple harmonic motion, the total mechanical energy of given system is E. If mass of the oscillating particle P is doubled then the new energy of the system for same amplitude is
  1. (A)E2\tfrac{E}{\sqrt{2}}2​E​
  2. (B)E
  3. (C)E2E\sqrt{2}E2​
  4. (D)2E2E2E

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Number of photons increases with increase in frequency of light. Reason R: Maximum kinetic energy of emitted electrons increases with the frequency of incident radiation. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both A and R are correct and R is NOT the correct explanation of A.
  2. (B)A is correct but R is not correct.
  3. (C)Both A and R are correct and R is the correct explanation of A.
  4. (D)A is not correct but R is correct.

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
According to Bohr's theory, the moment of momentum of an electron revolving in 4th4^{\text{th}}4th orbit of hydrogen atom is
  1. (A)8hπ\tfrac{8h}{\pi}π8h​
  2. (B)hπ\tfrac{h}{\pi}πh​
  3. (C)2hπ\tfrac{2h}{\pi}π2h​
  4. (D)h2π\tfrac{h}{2\pi}2πh​

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A sample of gas at temperature T is adiabatically expanded to double its volume. Adiabatic constant for the gas is γ=32\gamma=\tfrac{3}{2}γ=23​. The work done by the gas in the process is (μ=1\mu=1μ=1 mole)
  1. (A)RT[2−2]RT\left[\sqrt{2}-2\right]RT[2​−2]
  2. (B)RT[1−22]RT\left[1-2\sqrt{2}\right]RT[1−22​]
  3. (C)RT[22−1]RT\left[2\sqrt{2}-1\right]RT[22​−1]
  4. (D)RT[2−2]RT\left[2-\sqrt{2}\right]RT[2−2​]

Correct answer: (D)

Step-by-step solution →
Q18·PhysicsSingle correct
A charge qqq is placed at the center of one of the surface of a cube. The flux linked with the cube is
  1. (A)q4ε0\tfrac{q}{4\varepsilon_0}4ε0​q​
  2. (B)q2ε0\tfrac{q}{2\varepsilon_0}2ε0​q​
  3. (C)q8ε0\tfrac{q}{8\varepsilon_0}8ε0​q​
  4. (D)Zero

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
Applying the principle of homogeneity of dimensions, determine which one is correct, where T is time period, G is gravitational constant, M is mass, r is radius of orbit.
  1. (A)T2=4π2rGM2T^2=\tfrac{4\pi^2 r}{GM^2}T2=GM24π2r​
  2. (B)T2=4π2r3T^2=4\pi^2 r^3T2=4π2r3
  3. (C)T2=4π2r3GMT^2=\tfrac{4\pi^2 r^3}{GM}T2=GM4π2r3​
  4. (D)T2=4π2r2GMT^2=\tfrac{4\pi^2 r^2}{GM}T2=GM4π2r2​

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
A 90 kg body placed at 2R2R2R distance from surface of earth experiences gravitational pull of (R = Radius of earth, g=10 ms−2g=10\ \text{ms}^{-2}g=10 ms−2)
  1. (A)300 N
  2. (B)225 N
  3. (C)450 N
  4. (D)100 N

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
The displacement of a particle executing SHM is given by x=10sin⁡(ωt+π3)x=10\sin\left(\omega t+\tfrac{\pi}{3}\right)x=10sin(ωt+3π​) m. The time period of motion is 3.14 s. The velocity of the particle at t=0t=0t=0 is ______ m/s.

Correct answer: 10

Step-by-step solution →
Q22·PhysicsNumerical
A bus moving along a straight highway with speed of 72 km/h is brought to halt within 4 s after applying the brakes. The distance travelled by the bus during this time (Assume the retardation is uniform) is ______ m.

Correct answer: 40

Step-by-step solution →
Q23·PhysicsNumerical
A parallel plate capacitor of capacitance 12.5 pF is charged by a battery connected between its plates to potential difference of 12.0 V. The battery is now disconnected and a dielectric slab (εr=6)(\varepsilon_r=6)(εr​=6) is inserted between the plates. The change in its potential energy after inserting the dielectric slab is ______ ×10−12\times10^{-12}×10−12 J.

Correct answer: 750

Step-by-step solution →
Q24·PhysicsNumerical
In a system two particles of masses m1=3m_1=3m1​=3 kg and m2=2m_2=2m2​=2 kg are placed at certain distance from each other. The particle of mass m1m_1m1​ is moved towards the center of mass of the system through a distance 2 cm. In order to keep the center of mass of the system at the original position, the particle of mass m2m_2m2​ should move towards the center of mass by the distance ______ cm.

Correct answer: 3

Step-by-step solution →
Q25·PhysicsNumerical
The disintegration energy Q for the nuclear fission of 235U→140Ce+94Zr+2n^{235}\text{U}\to{}^{140}\text{Ce}+{}^{94}\text{Zr}+2n235U→140Ce+94Zr+2n is ______ MeV. Given atomic masses are: 235U:235.0439 u^{235}\text{U}:235.0439\,u235U:235.0439u, 140Ce:139.9054 u^{140}\text{Ce}:139.9054\,u140Ce:139.9054u, 94Zr:93.9063 u^{94}\text{Zr}:93.9063\,u94Zr:93.9063u, n:1.00866 un:1.00866\,un:1.00866u. Value of c2=931 MeV/uc^2=931\ \text{MeV/u}c2=931 MeV/u.

Correct answer: 208

Step-by-step solution →
Q26·PhysicsNumerical
A light ray is incident on a glass slab of thickness 434\sqrt{3}43​ cm and refractive index 2\sqrt{2}2​. The angle of incidence is equal to the critical angle for the glass slab with air. The lateral displacement of ray after passing through glass slab is ______ cm. (Given sin⁡15∘=0.25\sin 15^{\circ}=0.25sin15∘=0.25)

Correct answer: 2

Step-by-step solution →
Q27·PhysicsNumerical
A rod of length 60 cm rotates with a uniform angular velocity 20 rad s−1^{-1}−1 about its perpendicular bisector, in a uniform magnetic field 0.5 T. The direction of magnetic field is parallel to the axis of rotation. The potential difference between the two ends of the rod is ______ V.

Correct answer: 0

Step-by-step solution →
Q28·PhysicsNumerical
Two wires A and B are made up of the same material and have the same mass. Wire A has radius of 2.0 mm and wire B has radius of 4.0 mm. The resistance of wire B is 2 Ω2\,\Omega2Ω. The resistance of wire A is ______ Ω\OmegaΩ.

Correct answer: 32

Step-by-step solution →
Q29·PhysicsNumerical
Two parallel long current carrying wire separated by a distance 2r2r2r are shown in the figure. The ratio of magnetic field at A to the magnetic field produced at C is x7\tfrac{x}{7}7x​. The value of xxx is ______.

Correct answer: 5

Step-by-step solution →
Q30·PhysicsNumerical
Mercury is filled in a tube of radius 2 cm up to a height of 30 cm. The force exerted by mercury on the bottom of the tube is ______ N. (given, atmospheric pressure =105 N/m2=10^5\ \text{N/m}^2=105 N/m2, density of mercury =13.6×103 kg/m3=13.6\times10^3\ \text{kg/m}^3=13.6×103 kg/m3, g=10 m/s2g=10\ \text{m/s}^2g=10 m/s2, π=227\pi=\tfrac{22}{7}π=722​)

Correct answer: 177

Step-by-step solution →

Chemistry — JEE Main 4 April 2024 Shift 2

Q31·ChemistrySingle correct
The equilibrium constant for the reaction SO3(g)⇌SO2(g)+12O2(g)\text{SO}_3(g)\rightleftharpoons\text{SO}_2(g)+\tfrac{1}{2}\text{O}_2(g)SO3​(g)⇌SO2​(g)+21​O2​(g) is KC=4.9×10−2K_C=4.9\times10^{-2}KC​=4.9×10−2. The value of KCK_CKC​ for the reaction 2SO2(g)+O2(g)⇌2SO3(g)2\text{SO}_2(g)+\text{O}_2(g)\rightleftharpoons 2\text{SO}_3(g)2SO2​(g)+O2​(g)⇌2SO3​(g) given below is
  1. (A)4.9
  2. (B)41.6
  3. (C)49
  4. (D)416

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Find out the major product formed from the following reaction (the substrate is shown in the figure, treated with Me2NH\text{Me}_2\text{NH}Me2​NH, 2 equivalents):
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
When MnO2\text{MnO}_2MnO2​ and H2SO4\text{H}_2\text{SO}_4H2​SO4​ is added to a salt (A), greenish yellow gas liberated as salt (A) is
  1. (A)NaBr\text{NaBr}NaBr
  2. (B)CaI2\text{CaI}_2CaI2​
  3. (C)KNO3\text{KNO}_3KNO3​
  4. (D)NH4Cl\text{NH}_4\text{Cl}NH4​Cl

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
The correct statement/s about Hydrogen bonding is/are: A. Hydrogen bonding exists when H is covalently bonded to the highly electro negative atom. B. Intermolecular H bonding is present in o-nitro phenol. C. Intramolecular H bonding is present in HF. D. The magnitude of H bonding depends on the physical state of the compound. E. H-bonding has powerful effect on the structure and properties of compounds. Choose the correct answer from the options given below:
  1. (A)A only
  2. (B)A, D, E only
  3. (C)A, B, D only
  4. (D)A, B, C only

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
In the chemical reaction sequence shown in the figure, the products 'A' and 'B' respectively are
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Common name of Benzene-1,2-diol is
  1. (A)quinol
  2. (B)resorcinol
  3. (C)catechol
  4. (D)o-cresol

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
CH3-CH2-CH2-Br\text{CH}_3\text{-CH}_2\text{-CH}_2\text{-Br}CH3​-CH2​-CH2​-Br on treatment with NaOH in C2H5OH\text{C}_2\text{H}_5\text{OH}C2​H5​OH gives product 'A'. 'A' with H2O/H+\text{H}_2\text{O}/\text{H}^+H2​O/H+ gives product 'B', and 'A' with diborane followed by H2O2/OH−\text{H}_2\text{O}_2/\text{OH}^-H2​O2​/OH− gives product 'C'. Identify product B and product C:
  1. (A)B = C = 2-Propanol
  2. (B)B = 2-Propanol, C = 1-Propanol
  3. (C)B = 1-Propanol, C = 2-Propanol
  4. (D)B = C = 1-Propanol

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
The adsorbent used in adsorption chromatography is/are: A. silica gel, B. alumina, C. quick lime, D. magnesia. Choose the most appropriate answer from the options given below:
  1. (A)B only
  2. (B)C and D only
  3. (C)A and B only
  4. (D)A only

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
Identify the major product 'P' formed when the compound shown in the figure is treated with alcoholic KOH and heat.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q40·Chemistry·Electronic Effects and StabilitySingle correct
The correct order of stability of the carbanions a, b, c and d (shown in the figure) is
  1. (A)c>b>d>ac>b>d>ac>b>d>a
  2. (B)a>b>c>da>b>c>da>b>c>d
  3. (C)d>c>b>ad>c>b>ad>c>b>a
  4. (D)d>c>a>bd>c>a>bd>c>a>b

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correct
The correct order of the first ionization enthalpy is
  1. (A)Al>Ga>Tl\text{Al}>\text{Ga}>\text{Tl}Al>Ga>Tl
  2. (B)Ga>Al>B\text{Ga}>\text{Al}>\text{B}Ga>Al>B
  3. (C)B>Al>Ga\text{B}>\text{Al}>\text{Ga}B>Al>Ga
  4. (D)Tl>Ga>Al\text{Tl}>\text{Ga}>\text{Al}Tl>Ga>Al

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
If an iron (III) complex with the formula [Fe(NH3)x(CN)y]\left[\text{Fe}(\text{NH}_3)_x(\text{CN})_y\right][Fe(NH3​)x​(CN)y​] has no electron in its ege_geg​ orbital, then the value of x+yx+yx+y is
  1. (A)5
  2. (B)6
  3. (C)3
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Fuel cell, using hydrogen and oxygen as fuels, A. has been used in spaceship, B. has an efficiency of 40% to produce electricity, C. uses aluminium as catalysts, D. is eco-friendly, E. is actually a type of Galvanic cell only. Choose the correct answer from the options given below:
  1. (A)A, B, C only
  2. (B)A, B, D only
  3. (C)A, B, D, E only
  4. (D)A, D, E only

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
Choose the Incorrect Statement about Dalton's Atomic Theory:
  1. (A)Compounds are formed when atoms of different elements combine in any ratio
  2. (B)All the atoms of a given element have identical properties including identical mass
  3. (C)Matter consists of indivisible atoms
  4. (D)Chemical reactions involve reorganization of atoms

Correct answer: (A)

Step-by-step solution →
Q45·ChemistrySingle correct
Match List-I (pairs of monosaccharides) with List-II (the type of relationship between them). Choose the correct answer from the options given below:
List-IList-II
A.α\alphaα-Glucose and α\alphaα-GalactoseI.Functional isomers
B.α\alphaα-Glucose and β\betaβ-GlucoseII.Homologous
C.α\alphaα-Glucose and α\alphaα-FructoseIII.Anomers
D.α\alphaα-Glucose and α\alphaα-RiboseIV.Epimers
  1. (A)A-III, B-IV, C-II, D-I
  2. (B)A-III, B-IV, C-I, D-II
  3. (C)A-IV, B-III, C-I, D-II
  4. (D)A-IV, B-III, C-II, D-I

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
Given below are two statements: Statement I: The correct order of first ionization enthalpy values of Li, Na, F and Cl is Na<Li<Cl<F\text{Na}<\text{Li}<\text{Cl}<\text{F}Na<Li<Cl<F. Statement II: The correct order of negative electron gain enthalpy values of Li, Na, F and Cl is Na<Li<F<Cl\text{Na}<\text{Li}<\text{F}<\text{Cl}Na<Li<F<Cl. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is false but Statement II is true
  4. (D)Statement I is true but Statement II is false

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
For a strong electrolyte, a plot of molar conductivity against (concentration)1/2^{1/2}1/2 is a straight line, with a negative slope, the correct unit for the slope is
  1. (A)S cm2 mol−3/2 L1/2\text{S cm}^2\,\text{mol}^{-3/2}\,\text{L}^{1/2}S cm2mol−3/2L1/2
  2. (B)S cm2 mol−1 L1/2\text{S cm}^2\,\text{mol}^{-1}\,\text{L}^{1/2}S cm2mol−1L1/2
  3. (C)S cm2 mol−3/2 L\text{S cm}^2\,\text{mol}^{-3/2}\,\text{L}S cm2mol−3/2L
  4. (D)S cm2 mol−3/2 L−1/2\text{S cm}^2\,\text{mol}^{-3/2}\,\text{L}^{-1/2}S cm2mol−3/2L−1/2

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
A first row transition metal in its +2+2+2 oxidation state has a spin-only magnetic moment value of 3.86 BM. The atomic number of the metal is
  1. (A)25
  2. (B)26
  3. (C)22
  4. (D)23

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
The number of unpaired d-electrons in [Co(H2O)6]3+\left[\text{Co}(\text{H}_2\text{O})_6\right]^{3+}[Co(H2​O)6​]3+ is
  1. (A)4
  2. (B)2
  3. (C)0
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q50·ChemistrySingle correct
The number of species from the following that have pyramidal geometry around the central atom is: S2O32−\text{S}_2\text{O}_3^{2-}S2​O32−​, SO42−\text{SO}_4^{2-}SO42−​, SO32−\text{SO}_3^{2-}SO32−​, S2O72−\text{S}_2\text{O}_7^{2-}S2​O72−​
  1. (A)4
  2. (B)3
  3. (C)1
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q51·ChemistryNumerical
The maximum number of orbitals which can be identified with n=4n=4n=4 and ml=0m_l=0ml​=0 is ______.

Correct answer: 4

Step-by-step solution →
Q52·ChemistryNumerical
Number of compounds/species from the following with non-zero dipole moment is ______: BeCl2\text{BeCl}_2BeCl2​, BCl3\text{BCl}_3BCl3​, NF3\text{NF}_3NF3​, XeF4\text{XeF}_4XeF4​, CCl4\text{CCl}_4CCl4​, H2O\text{H}_2\text{O}H2​O, H2S\text{H}_2\text{S}H2​S, HBr\text{HBr}HBr, CO2\text{CO}_2CO2​, H2\text{H}_2H2​, HCl\text{HCl}HCl.

Correct answer: 5

Step-by-step solution →
Q53·ChemistryNumerical
Three moles of an ideal gas are compressed isothermally from 60 L to 20 L using constant pressure of 5 atm. Heat exchange Q for the compression is ______ Lit. atm.

Correct answer: 200

Step-by-step solution →
Q54·ChemistryNumerical
From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ ×10−1\times10^{-1}×10−1 g.

Correct answer: 95

Step-by-step solution →
Q55·ChemistryNumerical
Consider the following reaction, the rate expression of which is given below A+B→CA+B\to CA+B→C, rate =k[A]1/2[B]1/2=k[A]^{1/2}[B]^{1/2}=k[A]1/2[B]1/2. The reaction is initiated by taking 1 M concentration A and B each. If the rate constant (k) is 4.6×10−2 s−14.6\times10^{-2}\ \text{s}^{-1}4.6×10−2 s−1, then the time taken for A to become 0.1 M is ______ sec. (nearest integer)

Correct answer: 50

Step-by-step solution →
Q56·ChemistryNumerical
Phthalimide is made to undergo the following sequence of reactions: Phthalimide reacts with (i) KOH then (ii) Benzyl chloride to give product 'P'. Total number of π\piπ bonds present in product 'P' is/are ______.

Correct answer: 8

Step-by-step solution →
Q57·ChemistryNumerical
The total number of 'sigma' and 'pi' bonds in 2-oxohex-4-ynoic acid is ______.

Correct answer: 18

Step-by-step solution →
Q58·ChemistryNumerical
A first row transition metal with highest enthalpy of atomisation, upon reaction with oxygen at high temperature forms oxides of formula M2On\text{M}_2\text{O}_nM2​On​ (where n=3,4,5n=3,4,5n=3,4,5). The 'spin-only' magnetic moment value of the amphoteric oxide from the above metal is ______ BM (nearest integer).

Correct answer: 0

Step-by-step solution →
Q59·ChemistryNumerical
2.7 kg of each of water and acetic acid are mixed. The freezing point of the solution will be −x ∘-x\ ^{\circ}−x ∘C. Consider the acetic acid does not dimerise in water, nor dissociates in water; x=x=x= ______ (nearest integer). [Given: Molar mass of water =18 g mol−1=18\ \text{g mol}^{-1}=18 g mol−1, acetic acid =60 g mol−1=60\ \text{g mol}^{-1}=60 g mol−1, KfK_fKf​ of water =1.86 ∘C/m=1.86\ ^{\circ}\text{C/m}=1.86 ∘C/m, acetic acid =3.90 K/m=3.90\ \text{K/m}=3.90 K/m; freezing point: H2O=273\text{H}_2\text{O}=273H2​O=273 K, acetic acid =290=290=290 K]

Correct answer: 31

Step-by-step solution →
Q60·ChemistryNumerical
Vanillin compound obtained from vanilla beans, has total sum of oxygen atoms and π\piπ electrons is ______.

Correct answer: 11

Step-by-step solution →

Mathematics — JEE Main 4 April 2024 Shift 2

Q61·MathematicsSingle correct
Let f(x)=72x−9x−8x+12−1+cos⁡xf(x)=\dfrac{72^x-9^x-8^x+1}{\sqrt{2}-\sqrt{1+\cos x}}f(x)=2​−1+cosx​72x−9x−8x+1​ for x≠0x\ne 0x=0, and f(0)=a log⁡e2 log⁡e3f(0)=a\,\log_e 2\,\log_e 3f(0)=aloge​2loge​3. If fff is continuous at x=0x=0x=0, then the value of a2a^2a2 is equal to
  1. (A)768
  2. (B)1152
  3. (C)746
  4. (D)1250

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
If λ>0\lambda>0λ>0, let θ\thetaθ be the angle between the vectors a⃗=i^+λj^−3k^\vec{a}=\hat{i}+\lambda\hat{j}-3\hat{k}a=i^+λj^​−3k^ and b⃗=3i^−j^+2k^\vec{b}=3\hat{i}-\hat{j}+2\hat{k}b=3i^−j^​+2k^. If the vectors a⃗+b⃗\vec{a}+\vec{b}a+b and a⃗−b⃗\vec{a}-\vec{b}a−b are mutually perpendicular, then the value of (14cos⁡θ)2(14\cos\theta)^2(14cosθ)2 is equal to
  1. (A)25
  2. (B)20
  3. (C)50
  4. (D)40

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
Let C be a circle with radius 10\sqrt{10}10​ units and centre at the origin. Let the line x+y=2x+y=2x+y=2 intersect the circle C at the points P and Q. Let MN be a chord of C of length 2 unit and slope −1-1−1. Then, a distance (in units) between the chord PQ and the chord MN is
  1. (A)2−32-\sqrt{3}2−3​
  2. (B)3−23-\sqrt{2}3−2​
  3. (C)2−1\sqrt{2}-12​−1
  4. (D)2+1\sqrt{2}+12​+1

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Let a relation R on N×N\mathbb{N}\times\mathbb{N}N×N be defined as (x1,y1) R (x2,y2)(x_1,y_1)\,R\,(x_2,y_2)(x1​,y1​)R(x2​,y2​) if and only if x1≤x2x_1\le x_2x1​≤x2​ or y1≤y2y_1\le y_2y1​≤y2​. Consider the two statements: (I) R is reflexive but not symmetric. (II) R is transitive. Then which one of the following is true?
  1. (A)Only (II) is correct.
  2. (B)Only (I) is correct.
  3. (C)Both (I) and (II) are correct.
  4. (D)Neither (I) nor (II) is correct.

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let three real numbers aaa, bbb, ccc be in arithmetic progression and a+1a+1a+1, bbb, c+3c+3c+3 be in geometric progression. If a>10a>10a>10 and the arithmetic mean of aaa, bbb and ccc is 8, then the cube of the geometric mean of aaa, bbb and ccc is
  1. (A)120
  2. (B)312
  3. (C)316
  4. (D)128

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let A=[1201]A=\begin{bmatrix}1&2\\0&1\end{bmatrix}A=[10​21​] and B=I+adj⁡(A)+(adj⁡A)2+…+(adj⁡A)10B=I+\operatorname{adj}(A)+(\operatorname{adj}A)^2+\ldots+(\operatorname{adj}A)^{10}B=I+adj(A)+(adjA)2+…+(adjA)10. Then, the sum of all the elements of the matrix B is
  1. (A)−110-110−110
  2. (B)222222
  3. (C)−88-88−88
  4. (D)−124-124−124

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
The value of 1⋅22+2⋅32+…+100⋅(101)212⋅2+22⋅3+…+1002⋅101\dfrac{1\cdot 2^2+2\cdot 3^2+\ldots+100\cdot(101)^2}{1^2\cdot 2+2^2\cdot 3+\ldots+100^2\cdot 101}12⋅2+22⋅3+…+1002⋅1011⋅22+2⋅32+…+100⋅(101)2​ is
  1. (A)306305\tfrac{306}{305}305306​
  2. (B)305301\tfrac{305}{301}301305​
  3. (C)3231\tfrac{32}{31}3132​
  4. (D)3130\tfrac{31}{30}3031​

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let f(x)=∫0x(t+sin⁡(1−et))dtf(x)=\displaystyle\int_0^x\left(t+\sin\left(1-e^t\right)\right)dtf(x)=∫0x​(t+sin(1−et))dt, x∈Rx\in\mathbb{R}x∈R. Then lim⁡x→0f(x)x3\displaystyle\lim_{x\to 0}\dfrac{f(x)}{x^3}x→0lim​x3f(x)​ is equal to
  1. (A)16\tfrac{1}{6}61​
  2. (B)−16-\tfrac{1}{6}−61​
  3. (C)−23-\tfrac{2}{3}−32​
  4. (D)23\tfrac{2}{3}32​

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
The area (in sq. units) of the region described by {(x,y):y2≤2x and y≥4x−1}\{(x,y):y^2\le 2x \text{ and } y\ge 4x-1\}{(x,y):y2≤2x and y≥4x−1} is
  1. (A)1132\tfrac{11}{32}3211​
  2. (B)83\tfrac{8}{3}38​
  3. (C)1112\tfrac{11}{12}1211​
  4. (D)932\tfrac{9}{32}329​

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
The area (in sq. units) of the region S={z=x+iy:∣z−1∣≤2,  (z+zˉ)+i(z−zˉ)≤2,  Im⁡(z)≥0}S=\{z=x+iy:|z-1|\le 2,\;(z+\bar{z})+i(z-\bar{z})\le 2,\;\operatorname{Im}(z)\ge 0\}S={z=x+iy:∣z−1∣≤2,(z+zˉ)+i(z−zˉ)≤2,Im(z)≥0} is
  1. (A)3π2\tfrac{3\pi}{2}23π​
  2. (B)3π3\pi3π
  3. (C)17π6\tfrac{17\pi}{6}617π​
  4. (D)7π4\tfrac{7\pi}{4}47π​

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
If the value of the integral ∫−11cos⁡αx1+3x dx\displaystyle\int_{-1}^{1}\dfrac{\cos\alpha x}{1+3^x}\,dx∫−11​1+3xcosαx​dx is 2π\dfrac{2}{\pi}π2​, then a value of α\alphaα is
  1. (A)π6\tfrac{\pi}{6}6π​
  2. (B)π2\tfrac{\pi}{2}2π​
  3. (C)π3\tfrac{\pi}{3}3π​
  4. (D)π4\tfrac{\pi}{4}4π​

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
Let f(x)=3x−2+4−xf(x)=3\sqrt{x-2}+\sqrt{4-x}f(x)=3x−2​+4−x​ be a real valued function. If α\alphaα and β\betaβ are respectively the minimum and the maximum values of fff, then α2+2β2\alpha^2+2\beta^2α2+2β2 is equal to
  1. (A)44
  2. (B)42
  3. (C)24
  4. (D)38

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
If the coefficients of x4x^4x4, x5x^5x5 and x6x^6x6 in the expansion of (1+x)n(1+x)^n(1+x)n are in the arithmetic progression, then the maximum value of nnn is
  1. (A)14
  2. (B)21
  3. (C)28
  4. (D)7

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
Consider the hyperbola H having centre at the origin and foci on the x-axis. Let C1C_1C1​ be the circle touching the hyperbola H and having the centre at the origin. Let C2C_2C2​ be the circle touching the hyperbola H at its vertex and having the centre at one of its foci. If areas (in sq. units) of C1C_1C1​ and C2C_2C2​ are 36π36\pi36π and 4π4\pi4π, respectively, then the length (in units) of latus rectum of H is
  1. (A)283\tfrac{28}{3}328​
  2. (B)143\tfrac{14}{3}314​
  3. (C)103\tfrac{10}{3}310​
  4. (D)113\tfrac{11}{3}311​

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
If the mean of the following probability distribution of a random variable X: (XXX: 0, 2, 4, 6, 8 with P(X)P(X)P(X): 2a2a2a, 3a3a3a, a+ba+ba+b, 2b2b2b, 3b3b3b respectively) is 469\dfrac{46}{9}946​, then the variance of the distribution is
  1. (A)58181\tfrac{581}{81}81581​
  2. (B)56681\tfrac{566}{81}81566​
  3. (C)17327\tfrac{173}{27}27173​
  4. (D)15127\tfrac{151}{27}27151​

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let PQ be a chord of the parabola y2=12xy^2=12xy2=12x and the midpoint of PQ be at (4,1)(4,1)(4,1). Then, which of the following point lies on the line passing through the points P and Q?
  1. (A)(3,−3)(3,-3)(3,−3)
  2. (B)(32,−16)\left(\tfrac{3}{2},-16\right)(23​,−16)
  3. (C)(2,−9)(2,-9)(2,−9)
  4. (D)(12,−20)\left(\tfrac{1}{2},-20\right)(21​,−20)

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
Given the inverse trigonometric function assumes principal values only. Let xxx, yyy be any two real numbers in [−1,1][-1,1][−1,1] such that cos⁡−1x−sin⁡−1y=α\cos^{-1}x-\sin^{-1}y=\alphacos−1x−sin−1y=α, −π2≤α≤π-\dfrac{\pi}{2}\le\alpha\le\pi−2π​≤α≤π. Then, the minimum value of x2+y2+2xysin⁡αx^2+y^2+2xy\sin\alphax2+y2+2xysinα is
  1. (A)−1-1−1
  2. (B)000
  3. (C)−12-\tfrac{1}{2}−21​
  4. (D)12\tfrac{1}{2}21​

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x2+4)2 dy+(2x3y+8xy−2) dx=0(x^2+4)^2\,dy+(2x^3y+8xy-2)\,dx=0(x2+4)2dy+(2x3y+8xy−2)dx=0. If y(0)=0y(0)=0y(0)=0, then y(2)y(2)y(2) is equal to
  1. (A)π8\tfrac{\pi}{8}8π​
  2. (B)π16\tfrac{\pi}{16}16π​
  3. (C)2π2\pi2π
  4. (D)π32\tfrac{\pi}{32}32π​

Correct answer: (D)

Step-by-step solution →
Q79·MathematicsSingle correct
Let a⃗=i^+j^+k^\vec{a}=\hat{i}+\hat{j}+\hat{k}a=i^+j^​+k^, b⃗=2i^+4j^−5k^\vec{b}=2\hat{i}+4\hat{j}-5\hat{k}b=2i^+4j^​−5k^ and c⃗=xi^+2j^+3k^\vec{c}=x\hat{i}+2\hat{j}+3\hat{k}c=xi^+2j^​+3k^, x∈Rx\in\mathbb{R}x∈R. If d⃗\vec{d}d is the unit vector in the direction of b⃗+c⃗\vec{b}+\vec{c}b+c such that a⃗⋅d⃗=1\vec{a}\cdot\vec{d}=1a⋅d=1, then (a⃗×b⃗)⋅c⃗(\vec{a}\times\vec{b})\cdot\vec{c}(a×b)⋅c is equal to
  1. (A)9
  2. (B)6
  3. (C)3
  4. (D)11

Correct answer: (D)

Step-by-step solution →
Q80·MathematicsSingle correct
Let P be the point of intersection of the lines x−21=y−45=z−22\dfrac{x-2}{1}=\dfrac{y-4}{5}=\dfrac{z-2}{2}1x−2​=5y−4​=2z−2​ and x−32=y−23=z−33\dfrac{x-3}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{3}2x−3​=3y−2​=3z−3​. Then the shortest distance of P from the line 4x=2y=z4x=2y=z4x=2y=z is
  1. (A)5147\tfrac{5\sqrt{14}}{7}7514​​
  2. (B)147\tfrac{\sqrt{14}}{7}714​​
  3. (C)3147\tfrac{3\sqrt{14}}{7}7314​​
  4. (D)6147\tfrac{6\sqrt{14}}{7}7614​​

Correct answer: (C)

Step-by-step solution →
Q81·MathematicsNumerical
Let S={sin⁡22θ:(sin⁡4θ+cos⁡4θ)x2+(sin⁡2θ)x+(sin⁡6θ+cos⁡6θ)=0 has real roots}S=\{\sin^2 2\theta:(\sin^4\theta+\cos^4\theta)x^2+(\sin 2\theta)x+(\sin^6\theta+\cos^6\theta)=0 \text{ has real roots}\}S={sin22θ:(sin4θ+cos4θ)x2+(sin2θ)x+(sin6θ+cos6θ)=0 has real roots}. If α\alphaα and β\betaβ be the smallest and largest elements of the set S, respectively, then 3((α−2)2+(β−1)2)3\left((\alpha-2)^2+(\beta-1)^2\right)3((α−2)2+(β−1)2) equals

Correct answer: 4

Step-by-step solution →
Q82·MathematicsNumerical
If ∫cosec⁡5x dx=αcot⁡x cosec⁡x(cosec⁡2x+32)+βlog⁡e∣tan⁡x2∣+C\displaystyle\int\operatorname{cosec}^5 x\,dx=\alpha\cot x\,\operatorname{cosec} x\left(\operatorname{cosec}^2 x+\tfrac{3}{2}\right)+\beta\log_e\left|\tan\tfrac{x}{2}\right|+C∫cosec5xdx=αcotxcosecx(cosec2x+23​)+βloge​​tan2x​​+C, where α,β∈R\alpha,\beta\in\mathbb{R}α,β∈R and C is constant of integration, then the value of 8(α+β)8(\alpha+\beta)8(α+β) equals

Correct answer: 1

Step-by-step solution →
Q83·MathematicsNumerical
Let f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R be a thrice differentiable function such that f(0)=0f(0)=0f(0)=0, f(1)=1f(1)=1f(1)=1, f(2)=−1f(2)=-1f(2)=−1, f(3)=2f(3)=2f(3)=2 and f(4)=−2f(4)=-2f(4)=−2. Then, the minimum number of zeros of (3f′f′′+ff′′′)(x)\left(3f'f''+ff'''\right)(x)(3f′f′′+ff′′′)(x) is

Correct answer: 5

Step-by-step solution →
Q84·MathematicsNumerical
Consider the function f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R defined by f(x)=2x1+9x2f(x)=\dfrac{2x}{\sqrt{1+9x^2}}f(x)=1+9x2​2x​. If the composition of fff, (f∘f∘f∘…∘f)⏟10 times(x)=210x1+9αx2\underbrace{(f\circ f\circ f\circ\ldots\circ f)}_{10\text{ times}}(x)=\dfrac{2^{10}x}{\sqrt{1+9\alpha x^2}}10 times(f∘f∘f∘…∘f)​​(x)=1+9αx2​210x​, then the value of 3α+1\sqrt{3\alpha+1}3α+1​ is equal to

Correct answer: 1024

Step-by-step solution →
Q85·MathematicsNumerical
Let A be a 2×22\times 22×2 symmetric matrix such that A[11]=[37]A\begin{bmatrix}1\\1\end{bmatrix}=\begin{bmatrix}3\\7\end{bmatrix}A[11​]=[37​] and the determinant of A be 1. If A−1=αA+βIA^{-1}=\alpha A+\beta IA−1=αA+βI, where I is an identity matrix of order 2×22\times 22×2, then α+β\alpha+\betaα+β equals

Correct answer: 5

Step-by-step solution →
Q86·MathematicsNumerical
There are 4 men and 5 women in Group A, and 5 men and 4 women in Group B. If 4 persons are selected from each group, then the number of ways of selecting 4 men and 4 women is

Correct answer: 5626

Step-by-step solution →
Q87·MathematicsNumerical
In a tournament, a team plays 10 matches with probabilities of winning and losing each match as 13\dfrac{1}{3}31​ and 23\dfrac{2}{3}32​ respectively. Let xxx be the number of matches that the team wins, and yyy be the number of matches that team loses. If the probability P(∣x−y∣≤2)P(|x-y|\le 2)P(∣x−y∣≤2) is ppp, then 39p3^9 p39p equals

Correct answer: 8288

Step-by-step solution →
Q88·MathematicsNumerical
Consider a triangle ABC having the vertices A(1,2)A(1,2)A(1,2), B(α,β)B(\alpha,\beta)B(α,β) and C(γ,δ)C(\gamma,\delta)C(γ,δ) and angles ∠ABC=π6\angle ABC=\dfrac{\pi}{6}∠ABC=6π​ and ∠BAC=2π3\angle BAC=\dfrac{2\pi}{3}∠BAC=32π​. If the points B and C lie on the line y=x+4y=x+4y=x+4, then α2+γ2\alpha^2+\gamma^2α2+γ2 is equal to

Correct answer: 14

Step-by-step solution →
Q89·MathematicsNumerical
Consider a line L passing through the points P(1,2,1)P(1,2,1)P(1,2,1) and Q(2,1,−1)Q(2,1,-1)Q(2,1,−1). If the mirror image of the point A(2,2,2)A(2,2,2)A(2,2,2) in the line L is (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ), then α+β+6γ\alpha+\beta+6\gammaα+β+6γ is equal to

Correct answer: 6

Step-by-step solution →
Q90·MathematicsNumerical
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x+y+2)2 dx=dy(x+y+2)^2\,dx=dy(x+y+2)2dx=dy, y(0)=−2y(0)=-2y(0)=−2. Let the maximum and minimum values of the function y=y(x)y=y(x)y=y(x) in [0,π3]\left[0,\dfrac{\pi}{3}\right][0,3π​] be α\alphaα and β\betaβ, respectively. If (3α+π)2+β2=γ+δ3(3\alpha+\pi)^2+\beta^2=\gamma+\delta\sqrt{3}(3α+π)2+β2=γ+δ3​, γ,δ∈Z\gamma,\delta\in\mathbb{Z}γ,δ∈Z, then γ+δ\gamma+\deltaγ+δ equals

Correct answer: 31

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Differentiability 91/186
  • Inverse Trigonometric Functions 93/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Indefinite Integration 66/186
  • Magnetism and Matter 50/186
  • IUPAC Nomenclature 37/186
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