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JEE Main 24 January 2026 Shift 2 Question Paper with Answers

24 January 2026 · January session · 72 questions

72 of the 75 questions from the JEE Main 24 January 2026 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

3 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
24
Chemistry
25
Mathematics
23

Physics — JEE Main 24 January 2026 Shift 2

Q1·PhysicsSingle correct
The reading of the ammeter (A) in steady state in the following circuit (assuming negligible internal resistance of the ammeter) is _______ A.
  1. (A)2
  2. (B)1
  3. (C)1/2
  4. (D)0

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division =0.05= 0.05=0.05 mm, then the least count of the vernier callipers is ______ mm.
  1. (A)0.002
  2. (B)0.05
  3. (C)0.02
  4. (D)0.005

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Five persons P1P_1P1​, P2P_2P2​, P3P_3P3​, P4P_4P4​ and P5P_5P5​ recorded object distance (u) and image distance (v) using same convex lens having power +5D+5D+5D as (25,96), (30,62), (35,37), (45,35) and (50,32) respectively. Identify correct statement
  1. (A)Readings recorded by all persons are correct
  2. (B)Reading recorded by P3P_3P3​ persons are incorrect
  3. (C)Reading recorded by P3P_3P3​ and P2P_2P2​ persons are incorrect
  4. (D)Reading recorded by P4P_4P4​ and P5P_5P5​ persons are incorrect

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A regular hexagon is formed by six wires each of resistance r Ω\OmegaΩ and the corners are joined to centre by wires of same resistance. If the current enters at one corner and leaves at the opposite corner, the equivalent resistance of the hexagon between the two opposite corners will be
  1. (A)45r\frac{4}{5}r54​r
  2. (B)58r\frac{5}{8}r85​r
  3. (C)34r\frac{3}{4}r43​r
  4. (D)35r\frac{3}{5}r53​r

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
In case of vertical circular motion of a particle by a thread of length r if the tension in the thread is zero at an angle 30∘30^\circ30∘ shown in figure, the velocity at the bottom point (A) of the circular path is (g = gravitational acceleration)
  1. (A)5gr\sqrt{5gr}5gr​
  2. (B)72gr\sqrt{\frac{7}{2}gr}27​gr​
  3. (C)4gr\sqrt{4gr}4gr​
  4. (D)52gr\sqrt{\frac{5}{2}gr}25​gr​

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
A thin uniform rod (X) of mass M and length L is pivoted at a height (L3)\left(\frac{L}{3}\right)(3L​) as shown in the figure. The rod is allowed to fall from a vertical position and lie horizontally on the table. The angular velocity of this rod when it hits the table top, is________. (g = gravitational acceleration)
  1. (A)32gL\sqrt{\frac{3}{2}\frac{g}{L}}23​Lg​​
  2. (B)32gL\frac{3}{\sqrt{2}}\sqrt{\frac{g}{L}}2​3​Lg​​
  3. (C)12gL\frac{1}{\sqrt{2}}\sqrt{\frac{g}{L}}2​1​Lg​​
  4. (D)3gL\sqrt{\frac{3g}{L}}L3g​​

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
Two identical circular loops P and Q each of radius r are lying in parallel planes such that they have common axis. The current through P and Q are I and 4I respectively in clockwise direction as seen from O. The net magnetic field at O is:
  1. (A)3μoI42r\frac{3\mu_o I}{4\sqrt{2}r}42​r3μo​I​ toward P
  2. (B)μoI42r\frac{\mu_o I}{4\sqrt{2}r}42​rμo​I​ toward P
  3. (C)μoI42r\frac{\mu_o I}{4\sqrt{2}r}42​rμo​I​ towards Q
  4. (D)3μoI42r\frac{3\mu_o I}{4\sqrt{2}r}42​r3μo​I​ towards Q

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
When a light of a given wavelength falls on a metallic surface the stopping potential for photoelectrons is 3.2 V. If a second light having wavelength twice of first light is used, the stopping potential drops to 0.7 V. The wavelength of first light is__________m. (h=6.63×10−34 J.s,e=1.6×10−19 C,c=3×108 m/s)(h = 6.63 \times 10^{-34}\,\text{J.s}, e = 1.6 \times 10^{-19}\,\text{C}, c = 3 \times 10^{8}\,\text{m/s})(h=6.63×10−34J.s,e=1.6×10−19C,c=3×108m/s)
  1. (A)2.9×10−82.9 \times 10^{-8}2.9×10−8
  2. (B)2.2×10−82.2 \times 10^{-8}2.2×10−8
  3. (C)3.1×10−73.1 \times 10^{-7}3.1×10−7
  4. (D)2.5×10−72.5 \times 10^{-7}2.5×10−7

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
The fifth harmonic of a closed organ pipe is found to be in unison with the first harmonic of an open pipe. The ratio of lengths of closed pipe to that of the open pipe is 5/x5/x5/x. The value of x is_______.
  1. (A)4
  2. (B)2
  3. (C)1
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
Three parallel plate capacitors each with area A and separation d are filled with two dielectric (k1k_1k1​ and k2k_2k2​) in the following fashion. Which of the following is true? (k1>k2k_1 > k_2k1​>k2​)
  1. (A)CB>CC>CAC_B > C_C > C_ACB​>CC​>CA​
  2. (B)CC>CB>CAC_C > C_B > C_ACC​>CB​>CA​
  3. (C)CC>CA>CBC_C > C_A > C_BCC​>CA​>CB​
  4. (D)CA>CC>CBC_A > C_C > C_BCA​>CC​>CB​

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
The binding energy for the following nuclear reactions are expressed in MeV. 2He3+0n1→2He4+20_2\text{He}^3 + _0\text{n}^1 \rightarrow _2\text{He}^4 + 202​He3+0​n1→2​He4+20 MeV 2He4+0n1→2He5−0.9_2\text{He}^4 + _0\text{n}^1 \rightarrow _2\text{He}^5 - 0.92​He4+0​n1→2​He5−0.9 MeV If X3X_3X3​, X4X_4X4​, X5X_5X5​ denote the stability of 2He3_2\text{He}^32​He3, 2He4_2\text{He}^42​He4 and 2He5_2\text{He}^52​He5, respectively, then the correct order is :
  1. (A)X4>X5>X3X_4 > X_5 > X_3X4​>X5​>X3​
  2. (B)X4=X5=X3X_4 = X_5 = X_3X4​=X5​=X3​
  3. (C)X4>X5<X3X_4 > X_5 < X_3X4​>X5​<X3​
  4. (D)X4<X5<X3X_4 < X_5 < X_3X4​<X5​<X3​

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
A cubical block of density ρb=600\rho_b = 600ρb​=600 kg/m3^33 floats in a liquid of density ρe=900\rho_e = 900ρe​=900 kg/m3^33. If the height of block is H=8.0H = 8.0H=8.0 cm then height of the submerged part is ______ cm.
  1. (A)7.3
  2. (B)4.3
  3. (C)6.3
  4. (D)5.3

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
A moving coil galvanometer of resistance 100 Ω\OmegaΩ shows a full scale deflection for a current of 1 mA. The value of resistance required to convert this galvanometer into an ammeter, showing full scale deflection for a current of 5 mA, is ______ Ω\OmegaΩ
  1. (A)25
  2. (B)10
  3. (C)0.5
  4. (D)2.5

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
Identify the correct truth table of the given logical circuit.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
A flexible chain of mass mmm hangs between two fixed points at the same level. The inclination of the chain with the horizontal at the two points of support is 30∘30^\circ30∘. Considering the equilibrium of each half of the chain, the tension of the chain at the lowest point is _____.
  1. (A)32mg\frac{\sqrt{3}}{2}mg23​​mg
  2. (B)12mg\frac{1}{2}mg21​mg
  3. (C)mgmgmg
  4. (D)3 mg\sqrt{3}\,mg3​mg

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
A point source is kept at the center of a spherically enclosed detector. If the volume of the detector increased by 8 times, the intensity will
  1. (A)increase by 8 times
  2. (B)increase by 64 times
  3. (C)decrease by 8 times
  4. (D)decrease by 4 times

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
In the Young's double slit experiment the intensity produced by each one of the individual slits is I0I_0I0​. The distance between two slits is 2 mm. The distance of screen from slits is 10 m. The wavelength of light is 6000 A˚\text{\AA}A˚. The intensity of light on the screen in front of one of the slits is _____.
  1. (A)2I02I_02I0​
  2. (B)I0I_0I0​
  3. (C)I02\frac{I_0}{2}2I0​​
  4. (D)4I04I_04I0​

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P1\text{P}_1P1​ to P2\text{P}_2P2​ is α\alphaα Joule (P1=21.7\text{P}_1 = 21.7P1​=21.7 Pa and P2=30\text{P}_2 = 30P2​=30 Pa, Cv=21\text{C}_\text{v} = 21Cv​=21 J/K.mol, R=8.3R = 8.3R=8.3 J/mol.K). The value of α\alphaα is _____.
  1. (A)24
  2. (B)15
  3. (C)21
  4. (D)28

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
The velocity (v) – Distance (x) graph is shown in figure. Which graph represents acceleration (a) versus distance (x) variation of this system?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
Distance between an object and three times magnified real image is 40 cm. The focal length of the mirror used is _____ cm.
  1. (A)−15/2-15/2−15/2
  2. (B)−10-10−10
  3. (C)−20-20−20
  4. (D)−15-15−15

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
A point charge q = 1 μ\muμC is located at a distance 2 cm from one end of a thin insulating wire of length 10 cm having a charge QQQ = 24 μ\muμC, distributed uniformly along its length, as shown in figure. Force between q and wire is ____ N. (Use 14πϵ0=9×109 N.m2/C2\frac{1}{4\pi\epsilon_0} = 9\times10^{9}\,\text{N.m}^{2}/\text{C}^{2}4πϵ0​1​=9×109N.m2/C2)

Correct answer: 90

Step-by-step solution →
Q22·PhysicsNumerical
In a meter bridge experiment to determine the value of unknown resistance, first the resistances 2 Ω\OmegaΩ and 3 Ω\OmegaΩ are connected in the left and right gaps of the bridge and the null point is obtained at a distance lll cm from the left. Now when an unknown resistance x Ω\OmegaΩ is connected in parallel to 3 Ω\OmegaΩ resistance, the null point is shifted by 10 cm to the right of wire. The value of unknown resistance x is ___ Ω\OmegaΩ.

Correct answer: 6

Step-by-step solution →
Q23·PhysicsNumerical
A uniform solid cylinder of length LLL and radius RRR has moment of inertia about its axis equal to I1I_1I1​. A small co-centric cylinder of length L/2L/2L/2 and radius R/3 carved from this cylinder has moment of inertia about its axis equals to I2I_2I2​. The ratio I1/I2I_1/I_2I1​/I2​ is _____.

Correct answer: 162

Step-by-step solution →
Q24·PhysicsNumerical
A soap bubble of surface tension 0.04 N/m is blown to a diameter of 7 cm. If (15000−x)(15000 - x)(15000−x) μ\muμJ of work is done in blowing it further to make its diameter 14 cm, then the value of x is ____. (π=22/7\pi = 22/7π=22/7)

Correct answer: 11304

Step-by-step solution →

Chemistry — JEE Main 24 January 2026 Shift 2

Q25·ChemistrySingle correct
Choose the INCORRECT statement
  1. (A)Among the isotopes of carbon, 13C^{13}\text{C}13C is a radioactive isotope.
  2. (B)Carbon exhibits negative oxidation states along with +4 and +2.
  3. (C)Carbon cannot exceed its covalency more than four.
  4. (D)CO2\text{CO}_{2}CO2​ is the most acidic oxide among the dioxides of group of 14 elements.

Correct answer: (A)

Step-by-step solution →
Q26·ChemistrySingle correct
The unsaturated ether on acidic hydrolysis produces carbonyl compounds as shown below:- CH3−CH=CH−O−CH=CH2\text{CH}_{3}-\text{CH}=\text{CH}-\text{O}-\text{CH}=\text{CH}_{2}CH3​−CH=CH−O−CH=CH2​ ↓H3O(+)\downarrow \text{H}_{3}\text{O}^{(+)}↓H3​O(+) CH3−CH2−CH=O\text{CH}_{3}-\text{CH}_{2}-\text{CH}=\text{O}CH3​−CH2​−CH=O and O=CH−CH3\text{O}=\text{CH}-\text{CH}_{3}O=CH−CH3​ Based on this, predict the solution / reagent that will help to distinguish “P” and “Q” obtained in the following reaction. CH3−CH=CH−O−C∣CH3=CH2→ΔH3O(+)P+Q\text{CH}_{3}-\text{CH}=\text{CH}-\text{O}-\overset{\overset{\text{CH}_{3}}{|}}{\text{C}}=\text{CH}_{2} \xrightarrow[\Delta]{\text{H}_{3}\text{O}^{(+)}} \text{P} + \text{Q}CH3​−CH=CH−O−C∣CH3​​=CH2​H3​O(+)Δ​P+Q
  1. (A)Lucas reagent
  2. (B)2,4-DNP reagent
  3. (C)Saturated NaHSO3\text{NaHSO}_{3}NaHSO3​ solution
  4. (D)Fehling solution

Correct answer: (D)

Step-by-step solution →
Q27·ChemistrySingle correct
The number of possible tripeptides formed involving alanine (ala), glycine (gly) and valine (val), where no amino acid has been used more than once is :
  1. (A)6
  2. (B)3
  3. (C)4
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correct
Two liquids A and B form an ideal solution at temperature T K. At T K , the vapour pressures of pure A and B are 55 and 15 kNm−2\text{kNm}^{-2}kNm−2 respectively. What is the mole fraction of A in solution of A and B in equilibrium with a vapour in which the mole fraction of A is 0.8 ?
  1. (A)0.5217
  2. (B)0.480
  3. (C)0.663
  4. (D)0.340

Correct answer: (A)

Step-by-step solution →
Q29·ChemistrySingle correct
Consider the following gaseous equilibrium in a closed container of volume “V” at T(K). P2(g)+Q2(g)⇌2PQ(g)\text{P}_{2}(\text{g}) + \text{Q}_{2}(\text{g}) \rightleftharpoons 2\text{PQ}(\text{g})P2​(g)+Q2​(g)⇌2PQ(g) 2 moles each of P2(g)\text{P}_{2}(\text{g})P2​(g), Q2(g)\text{Q}_{2}(\text{g})Q2​(g) and PQ (g) are present at equilibrium. Now one mole each of ‘P2\text{P}_{2}P2​’ and ‘Q2\text{Q}_{2}Q2​’ are added to the equilibrium keeping the temperature at T(K). The number of moles of P2\text{P}_{2}P2​, Q2\text{Q}_{2}Q2​ and PQ at the new equilibrium, respectively , are -
  1. (A)2.67, 2.67, 2.67
  2. (B)1.21, 2.24, 1.56
  3. (C)1.66, 1.66, 1.66
  4. (D)2.56, 1.62, 2.24

Correct answer: (A)

Step-by-step solution →
Q30·ChemistrySingle correct
Pair of species among the following having same bond order as well as paramagnetic character will be-
  1. (A)O2+,N22−\text{O}_{2}^{+}, \text{N}_{2}^{2-}O2+​,N22−​
  2. (B)O2−,N2+\text{O}_{2}^{-}, \text{N}_{2}^{+}O2−​,N2+​
  3. (C)O2+,N2−\text{O}_{2}^{+}, \text{N}_{2}^{-}O2+​,N2−​
  4. (D)O2−,N2−\text{O}_{2}^{-}, \text{N}_{2}^{-}O2−​,N2−​

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
The wavelength of light absorbed for the following complexes are in the order. [Co(NH3)6]3+\text{[Co(NH}_{3}\text{)}_{6}\text{]}^{3+}[Co(NH3​)6​]3+ (I) ; [Co(H2O)6]3+\text{[Co(H}_{2}\text{O)}_{6}\text{]}^{3+}[Co(H2​O)6​]3+ (II) ; [Co(CN)6]3−\text{[Co(CN)}_{6}\text{]}^{3-}[Co(CN)6​]3− (III) ; [Co(NH3)5(H2O)]3+\text{[Co(NH}_{3}\text{)}_{5}\text{(H}_{2}\text{O)]}^{3+}[Co(NH3​)5​(H2​O)]3+ (IV) ; [CoF6]3−\text{[CoF}_{6}\text{]}^{3-}[CoF6​]3− (V)
  1. (A)III < I < II < IV < V
  2. (B)III < I < IV < V < II
  3. (C)III < IV < I < II < V
  4. (D)III < I < IV < II < V

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
One mole of Cl2\text{Cl}_{2}Cl2​ (g) was passed into 2 L of cold 2M KOH solution. After the reaction, the concentrations of Cl−\text{Cl}^{-}Cl−, ClO−\text{ClO}^{-}ClO− and OH−\text{OH}^{-}OH− are respectively (assume volume remains constant)
  1. (A)0.75 M , 0.75 M , 1 M
  2. (B)0.5 M , 0.5 M , 0.5 M
  3. (C)0.5 M , 0.5 M , 1 M
  4. (D)1 M , 1M , 1 M

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
A student has planned to prepare acetanilide from aniline using acetic anhydride. The student has started from 9.3g of aniline. However, the student has managed to obtain 11 g of dry acetanilide. The % yield of this reaction is :-
  1. (A)81.5%
  2. (B)97.5%
  3. (C)59.5%
  4. (D)72.5%

Correct answer: (A)

Step-by-step solution →
Q34·Chemistry·Electronic Effects and StabilitySingle correct
Find out the statements which are not true. A. Resonating structure with more number of covalent bonds and lesser charge separation are more stable. B. In electromeric effect, an unsaturated system shows + E effect with nucleophile and –E effect with electrophile. C. Inductive effect is responsible for high melting point, boiling point and dipole moment of polar compounds. D. The greater the number of alkyl groups attached to the doubly bonded carbon atoms, higher is the heat of hydrogenation. E. Stability of carbanion increases with the increase in s-character of the carbon carrying the negative charge. Choose the correct answer from the options given below.
  1. (A)A, D & E only
  2. (B)B, D & E only
  3. (C)A, C & D only
  4. (D)B & D only

Correct answer: (D)

Step-by-step solution →
Q35·ChemistrySingle correct
The correct order of C, N, O and F in terms of second ionisation potential is
  1. (A)F < N < C < O
  2. (B)C < O < N < F
  3. (C)C < N < F < O
  4. (D)C < F < N < O

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
In the Group analysis of cations , Ba2+\text{Ba}^{2+}Ba2+ & Ca2+\text{Ca}^{2+}Ca2+ are precipitated respectively as
  1. (A)sulphide & sulphide
  2. (B)hydroxide & carbonate
  3. (C)carbonate & carbonate
  4. (D)chromate & sulphide

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
The wavelength of spectral line obtained in the spectrum of LI2+\text{LI}^{2+}LI2+ ion, when the transition takes place between two levels whose sum is 4 and difference is 2, is
  1. (A)2.28×10−72.28 \times 10^{-7}2.28×10−7 cm
  2. (B)2.28×10−62.28 \times 10^{-6}2.28×10−6 cm
  3. (C)1.14×10−71.14 \times 10^{-7}1.14×10−7 cm
  4. (D)1.14×10−61.14 \times 10^{-6}1.14×10−6 cm

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
Given below are two statements : Statement I : Cross aldol condensation between two different aldehydes will always produce four different products. Statement II : When semicarbazide reacts with a mixture of benzaldehyde and acetophenone under optimum pH, it forms a condensation product with acetophenone only. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is false but Statement II is true
  3. (C)Both Statement I and Statement II are true
  4. (D)Statement I is true but Statement II is false

Correct answer: (A)

Step-by-step solution →
Q39·Chemistry·AminesSingle correct
Given below are two statements : Statement I : The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce R−C∥O−OH\text{R}-\overset{\text{O}}{\overset{\|}{\text{C}}}-\text{OH}R−C∥O−OH . Statement II : R-CN hydrolyses under acidic medium to produce a compound which on treatment with SOCl2\text{SOCl}_{2}SOCl2​, followed by the addition of NH3\text{NH}_{3}NH3​ gives another compound(x). This compound (x) on treatment with NaOCl/NaOH\text{NaOCl}/\text{NaOH}NaOCl/NaOH gives a product, that on treatment with CHCl3/KOH/Δ\text{CHCl}_{3}/\text{KOH}/\DeltaCHCl3​/KOH/Δ produces R-NC In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q40·Chemistry·Alcohols and EthersSingle correct
From the following, how many compounds contain at least one secondary alcohol ? Choose the correct answer from the options given below :
  1. (A)Five
  2. (B)Three
  3. (C)Four
  4. (D)two

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
The heat of atomisation of methane and ethane are 'x' kJ mol−1\text{kJ mol}^{-1}kJ mol−1 and 'y' kJ mol−1\text{kJ mol}^{-1}kJ mol−1 respectively. The longest wavelength (λ\lambdaλ) of light capable of breaking the C-C bond can be expressed in SI unit as :
  1. (A)hc1000(y−6x4)−1\frac{\text{hc}}{1000}\left(\frac{\text{y}-6\text{x}}{4}\right)^{-1}1000hc​(4y−6x​)−1
  2. (B)NAhc250(4y−6x)\frac{\text{N}_{\text{A}}\text{hc}}{250(4\text{y}-6\text{x})}250(4y−6x)NA​hc​
  3. (C)NAhc250(y−6x)\frac{\text{N}_{\text{A}}\text{hc}}{250(\text{y}-6\text{x})}250(y−6x)NA​hc​
  4. (D)NAhc(y−6x4)−1\text{N}_{\text{A}}\text{hc}\left(\text{y}-\frac{6\text{x}}{4}\right)^{-1}NA​hc(y−46x​)−1

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
At 298 K, the mole percentage of N2(g)\text{N}_{2}(\text{g})N2​(g) in air is 80%. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of N2(g)\text{N}_{2}(\text{g})N2​(g) in water at 298 K ? (KH\text{K}_{\text{H}}KH​ for N2\text{N}_{2}N2​ is 6.5×1076.5 \times 10^{7}6.5×107 mm Hg )
  1. (A)1.23×10−71.23 \times 10^{-7}1.23×10−7
  2. (B)1.17×10−41.17 \times 10^{-4}1.17×10−4
  3. (C)9.35×1059.35 \times 10^{5}9.35×105
  4. (D)9.35×10−59.35 \times 10^{-5}9.35×10−5

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
"X" is an oxoanion of the lightest element of group 7 (in the periodic table). The metal is in +6 oxidation state in "X". The color of the potassium salt of X is
  1. (A)green
  2. (B)purple
  3. (C)yellow
  4. (D)orange

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
Given below are two statements : Statement I : There are several conformers for n-butane. Out of those conformers, (X) is the least stable and most stable conformer is (Y) Statement II : As the dihedral angle increases, torsional strain decreases from (X) to (Y). In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is false but Statement II is true
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are true

Correct answer: (D)

Step-by-step solution →
Q45·ChemistryNumerical
0.25 g of an organic compound "A" containing carbon, hydrogen and oxygen was analysed using the combustion method. There was an increase in mass of CaCl2\text{CaCl}_{2}CaCl2​ tube and potash tube at the end of the experiment. The amount was found to be 0.15 g and 0.1837 g, respectively. The percentage of oxygen in compound A is _______ %. (Nearest integer) (Given : molar mass in g mol−1\text{g mol}^{-1}g mol−1 H : 1, C : 12, O : 16)

Correct answer: 73

Step-by-step solution →
Q46·ChemistryNumerical
The half-life of 65Zn^{65}\text{Zn}65Zn is 245 days. After x days, 75% of original activity remained. The value of x in days is _______ . (Nearest integer) (Given : log 3 = 0.4771 and log 2 = 0.3010)

Correct answer: 102

Step-by-step solution →
Q47·ChemistryNumerical
A chromium complex with a formula CrCl3.6H2O\text{CrCl}_{3}.6\text{H}_{2}\text{O}CrCl3​.6H2​O has a spin only magnetic moment value of 3.87 BM and its solution conductivity corresponds to 1 : 2 electrolyte. 2.75 g of the complex solution was initially passed through a cation exchanger. The solution obtained after the process was reacted with excess of AgNO3\text{AgNO}_{3}AgNO3​. The amount of AgCl formed in the above process is _______ g. (Nearest integer) [Given : Molar mass in g mol−1\text{g mol}^{-1}g mol−1 Cr : 52; Cl : 35.5, Ag : 108, O : 16, H : 1]

Correct answer: 3

Step-by-step solution →
Q48·ChemistryNumerical
Molar conductivity of a weak acid HQ of concentration 0.18 M was found to be 1/30 of the molar conductivity of another weak acid HZ with concentration of 0.02 of M. If λQ−0\lambda^{0}_{\text{Q}^{-}}λQ−0​ happened to be equal with λZ−0\lambda^{0}_{\text{Z}^{-}}λZ−0​, then the difference of the pKa\text{pK}_{\text{a}}pKa​ values of the two weak acids (pKa(HQ)−pKa(HZ)\text{pK}_{\text{a}}(\text{HQ})-\text{pK}_{\text{a}}(\text{HZ})pKa​(HQ)−pKa​(HZ)) is _______ (Nearest integer). [Given : degree of dissociation (α\alphaα) << 1 for both weak acids, λ∘\lambda^{\circ}λ∘ : limiting molar conductivity of ions]

Correct answer: 2

Step-by-step solution →
Q49·Chemistry·Carboxylic Acids and DerivativesNumerical
Grignard reagent RMgBr(P) reacts with water and forms a gas (Q). One gram of Q occupies 1.4 dm3\text{dm}^{3}dm3 at STP. (P) on reaction with dry ice in dry ether followed by H3O+\text{H}_{3}\text{O}^{+}H3​O+ forms a compound (Z). 0.1 mole of (Z) will weigh _______ g. (Nearest integer)

Correct answer: 6

Step-by-step solution →

Mathematics — JEE Main 24 January 2026 Shift 2

Q50·MathematicsSingle correct
Let f(x)=∫7x10+9x8(1+x2+2x9)2dxf(x) = \int \frac{7x^{10} + 9x^{8}}{(1 + x^{2} + 2x^{9})^{2}}dxf(x)=∫(1+x2+2x9)27x10+9x8​dx, x>0x > 0x>0, lim⁡x→0f(x)=0\lim_{x \to 0} f(x) = 0limx→0​f(x)=0 and f(1)=14f(1) = \frac{1}{4}f(1)=41​. If A=[00114f′(1)1α241]A = \begin{bmatrix} 0 & 0 & 1 \\ \frac{1}{4} & f'(1) & 1 \\ \alpha^{2} & 4 & 1 \end{bmatrix}A=​041​α2​0f′(1)4​111​​ and B = adj(adj A) be such that ∣B∣=81|B| = 81∣B∣=81, then α2\alpha^{2}α2 is equal to
  1. (A)2
  2. (B)3
  3. (C)1
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q51·MathematicsSingle correct
Let the length of the latus rectum of an ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1a2x2​+b2y2​=1, (a>b)(a > b)(a>b), be 30. If its eccentricity is the maximum value of the function f(t)=−34+2t−t2f(t) = -\frac{3}{4} + 2t - t^{2}f(t)=−43​+2t−t2, then (a2+b2)(a^{2} + b^{2})(a2+b2) is equal to -
  1. (A)516
  2. (B)256
  3. (C)496
  4. (D)276

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correct
Let the angles made with the positive x-axis by two straight lines drawn from the point P(2, 3) and meeting the line x+y=6x + y = 6x+y=6 at a distance 23\sqrt{\frac{2}{3}}32​​ from the point P be θ1\theta_{1}θ1​ and θ2\theta_{2}θ2​. Then the value of (θ1+θ2)(\theta_{1} + \theta_{2})(θ1​+θ2​) is :
  1. (A)π12\frac{\pi}{12}12π​
  2. (B)π6\frac{\pi}{6}6π​
  3. (C)π2\frac{\pi}{2}2π​
  4. (D)π3\frac{\pi}{3}3π​

Correct answer: (C)

Step-by-step solution →
Q53·MathematicsSingle correct
Let the image of parabola x2=4yx^{2} = 4yx2=4y, in the line x−y=1x - y = 1x−y=1 be (y+α)2=b(x−c)(y + \alpha)^{2} = b(x - c)(y+α)2=b(x−c), a, b, c ∈ ℕ. Then a+b+ca + b + ca+b+c is equal to
  1. (A)12
  2. (B)4
  3. (C)6
  4. (D)8

Correct answer: (C)

Step-by-step solution →
Q54·MathematicsSingle correct
(13+47)+(132+13×47+4272)+(133+132×47+13×4272+4373)\left(\frac{1}{3} + \frac{4}{7}\right) + \left(\frac{1}{3^{2}} + \frac{1}{3} \times \frac{4}{7} + \frac{4^{2}}{7^{2}}\right) + \left(\frac{1}{3^{3}} + \frac{1}{3^{2}} \times \frac{4}{7} + \frac{1}{3} \times \frac{4^{2}}{7^{2}} + \frac{4^{3}}{7^{3}}\right)(31​+74​)+(321​+31​×74​+7242​)+(331​+321​×74​+31​×7242​+7343​) + ...... upto infinite terms is equal to -
  1. (A)52\frac{5}{2}25​
  2. (B)74\frac{7}{4}47​
  3. (C)43\frac{4}{3}34​
  4. (D)65\frac{6}{5}56​

Correct answer: (A)

Step-by-step solution →
Q55·MathematicsSingle correct
Let P=[pij]P = [p_{ij}]P=[pij​] and Q=[qij]Q = [q_{ij}]Q=[qij​] be two square matrices of order 3 such that qij=2(i+j−1)pijq_{ij} = 2^{(i + j - 1)} p_{ij}qij​=2(i+j−1)pij​ and det⁡(Q)=210\det(Q) = 2^{10}det(Q)=210. Then the value of det(adj(adj P)) is :
  1. (A)32
  2. (B)16
  3. (C)81
  4. (D)124

Correct answer: (B)

Step-by-step solution →
Q56·MathematicsSingle correct
The letters of the word "UDAYPUR" are written in all possible ways with or without meaning and these words are arranged as in a dictionary. The rank of the word "UDAYPUR" is :
  1. (A)1580
  2. (B)1578
  3. (C)1579
  4. (D)1581

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correct
The largest value of n, for which 40n40^{n}40n divides 60!, is
  1. (A)13
  2. (B)11
  3. (C)12
  4. (D)14

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsSingle correct
The sum of all values of α\alphaα, for which the shortest distance between the lines x+1α=y−2−1=z−4−α\frac{x+1}{\alpha} = \frac{y-2}{-1} = \frac{z-4}{-\alpha}αx+1​=−1y−2​=−αz−4​ and xα=y−12=z−12α\frac{x}{\alpha} = \frac{y-1}{2} = \frac{z-1}{2\alpha}αx​=2y−1​=2αz−1​ is 2\sqrt{2}2​, is
  1. (A)8
  2. (B)−6
  3. (C)6
  4. (D)−8

Correct answer: (B)

Step-by-step solution →
Q59·MathematicsSingle correct
Let f(α)f(\alpha)f(α) denote the area of the region in the first quadrant bounded by x=0x = 0x=0, x=1x = 1x=1, y2=xy^{2} = xy2=x and y=∣αx−5∣−∣1−αx∣+αx2y = |\alpha x - 5| - |1 - \alpha x| + \alpha x^{2}y=∣αx−5∣−∣1−αx∣+αx2. Then (f(0)+f(1))(f(0) + f(1))(f(0)+f(1)) is equal to
  1. (A)9
  2. (B)14
  3. (C)7
  4. (D)12

Correct answer: (C)

Step-by-step solution →
Q60·MathematicsSingle correct
If the domain of the function f(x)=sin⁡−1(1x2−2x−2)f(x) = \sin^{-1}\left(\frac{1}{x^{2} - 2x - 2}\right)f(x)=sin−1(x2−2x−21​), is (−∞,α]∪[β,γ]∪[δ,∞)(-\infty, \alpha] \cup [\beta, \gamma] \cup [\delta, \infty)(−∞,α]∪[β,γ]∪[δ,∞), then α+β+γ+δ\alpha + \beta + \gamma + \deltaα+β+γ+δ is equal to
  1. (A)2
  2. (B)4
  3. (C)3
  4. (D)5

Correct answer: (B)

Step-by-step solution →
Q61·MathematicsSingle correct
Let X={x∈N:1≤x≤19}X = \{x \in \mathbb{N} : 1 \le x \le 19\}X={x∈N:1≤x≤19} and for some a, b ∈R\in \mathbb{R}∈R, Y={ax+b:x∈X}Y = \{ax + b : x \in X\}Y={ax+b:x∈X}. If the mean and variance of the elements of Y are 30 and 750, respectively, then the sum of all possible values of b is
  1. (A)20
  2. (B)80
  3. (C)100
  4. (D)60

Correct answer: (D)

Step-by-step solution →
Q62·Mathematics·Application of DerivativesSingle correct
Consider the following three statements for the function f:(0,∞)→Rf : (0, \infty) \to \mathbb{R}f:(0,∞)→R defined by f(x)=∣log⁡ex∣−∣x−1∣f(x) = |\log_{e} x| - |x - 1|f(x)=∣loge​x∣−∣x−1∣ : (I) f is differentiable at all x>0x > 0x>0. (II) f is increasing in (0, 1). (III) f is decreasing in (1,∞)(1, \infty)(1,∞). Then.
  1. (A)All (I), (II) and (III) are TRUE.
  2. (B)Only (I) is TRUE.
  3. (C)Only (II) and (III) are TRUE.
  4. (D)Only (I) and (III) are TRUE.

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be a differentiable function in the interval (0,∞)(0, \infty)(0,∞) such that y(1)=2y(1) = 2y(1)=2. and lim⁡t→x(t2y(x)−x2y(t)x−t)=3\lim\limits_{t \to x} \left( \dfrac{t^{2} y(x) - x^{2} y(t)}{x - t} \right) = 3t→xlim​(x−tt2y(x)−x2y(t)​)=3 for each x>0x > 0x>0. Then 2y(2)2y(2)2y(2) is equal to
  1. (A)18
  2. (B)23
  3. (C)27
  4. (D)12

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Let f be a function such that 3f(x)+2f(m19x)=5x3f(x) + 2f\left( \dfrac{m}{19x} \right) = 5x3f(x)+2f(19xm​)=5x, x≠0x \ne 0x=0, where m=∑i=19(i)2m = \sum\limits_{i=1}^{9} (i)^{2}m=i=1∑9​(i)2. Then f(5)−f(2)f(5) - f(2)f(5)−f(2) is equal to
  1. (A)−9-9−9
  2. (B)36
  3. (C)18
  4. (D)9

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
The smallest positive integral value of a, for which all the roots of x4−ax2+9=0x^{4} - ax^{2} + 9 = 0x4−ax2+9=0 are real and distinct, is equal to
  1. (A)9
  2. (B)3
  3. (C)4
  4. (D)7

Correct answer: (D)

Step-by-step solution →
Q66·MathematicsSingle correct
Let a⃗=2i^−5j^+5k\vec{a} = 2\hat{i} - 5\hat{j} + 5ka=2i^−5j^​+5k and b⃗=i^−j^+3k\vec{b} = \hat{i} - \hat{j} + 3kb=i^−j^​+3k. If c⃗\vec{c}c is a vector such that 2(a⃗×c⃗)+3(b⃗×c⃗)=0⃗2(\vec{a} \times \vec{c}) + 3(\vec{b} \times \vec{c}) = \vec{0}2(a×c)+3(b×c)=0 and (a⃗−b⃗)⋅c⃗=−97(\vec{a} - \vec{b}) \cdot \vec{c} = -97(a−b)⋅c=−97, then ∣c⃗×k∣2\left| \vec{c} \times k \right|^{2}∣c×k∣2 is equal to
  1. (A)193
  2. (B)233
  3. (C)218
  4. (D)205

Correct answer: (C)

Step-by-step solution →
Q67·Mathematics·Limits and ContinuitySingle correct
Let [t] denote the greatest integer less than or equal to t. If the function f(x)={b2sin⁡(π2[π2(cos⁡x+sin⁡x)cos⁡x]),x<0sin⁡x−12sin⁡2xx3,x>0a,x=0f(x) = \begin{cases} b^{2} \sin\left( \dfrac{\pi}{2} \left[ \dfrac{\pi}{2} (\cos x + \sin x) \cos x \right] \right) & , x < 0 \\ \dfrac{\sin x - \dfrac{1}{2}\sin 2x}{x^{3}} & , x > 0 \\ a & , x = 0 \end{cases}f(x)=⎩⎨⎧​b2sin(2π​[2π​(cosx+sinx)cosx])x3sinx−21​sin2x​a​,x<0,x>0,x=0​ is continuous at x=0x = 0x=0, then a2+b2a^{2} + b^{2}a2+b2 is equal to
  1. (A)58\dfrac{5}{8}85​
  2. (B)916\dfrac{9}{16}169​
  3. (C)34\dfrac{3}{4}43​
  4. (D)12\dfrac{1}{2}21​

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsNumerical
If f(x) satisfies the relation f(x)=ex+∫01(y+xex)f(y) dyf(x) = e^{x} + \int\limits_{0}^{1} (y + xe^{x}) f(y)\, dyf(x)=ex+0∫1​(y+xex)f(y)dy, then e+f(0)e + f(0)e+f(0) is equal to ________.

Correct answer: 2

Step-by-step solution →
Q69·MathematicsNumerical
Let (h, k) lie on the circle C:x2+y2=4C : x^{2} + y^{2} = 4C:x2+y2=4 and the point (2h+1,3k+2)(2h + 1, 3k + 2)(2h+1,3k+2) lie on an ellipse with eccentricity e. Then the value of 5e2\dfrac{5}{e^{2}}e25​ is equal to ________.

Correct answer: 9

Step-by-step solution →
Q70·MathematicsNumerical
Let z=(1+i)(1+2i)(1+3i)…(1+ni)z = (1 + i)(1 + 2i)(1 + 3i) \ldots (1 + ni)z=(1+i)(1+2i)(1+3i)…(1+ni), where i=−1i = \sqrt{-1}i=−1​. If ∣z∣2=44200|z|^{2} = 44200∣z∣2=44200, then n is equal to −-−

Correct answer: 5

Step-by-step solution →
Q71·MathematicsNumerical
Let S be a set of 5 elements and P(S) denote the power set of S. Let E be an event of choosing an ordered pair (A, B) from the set P(S)×P(S)P(S) \times P(S)P(S)×P(S) such that A∩B=∅A \cap B = \varnothingA∩B=∅. If the probability of the event E is 3p2q\dfrac{3^{p}}{2^{q}}2q3p​, where p, q ∈N\in \mathbb{N}∈N, then p+qp + qp+q is equal to

Correct answer: 15

Step-by-step solution →
Q72·MathematicsNumerical
The number of elements in the set {x∈[0,180∘]:tan⁡(x+100∘)=tan⁡(x+50∘)tan⁡xtan⁡(x−50∘)}\{x \in [0, 180^{\circ}] : \tan(x + 100^{\circ}) = \tan(x + 50^{\circ}) \tan x \tan(x - 50^{\circ})\}{x∈[0,180∘]:tan(x+100∘)=tan(x+50∘)tanxtan(x−50∘)} is ________.

Correct answer: 4

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
  • Carboxylic Acids and Derivatives 54/186
  • Principles of Qualitative Analysis 58/186
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